]> 0.4 Stirling Numbers of the Second Kind

0.4 Stirling Numbers of the Second Kind

OK but I knew all these things already.

Here is a slight but useful modification. In D5 instead of the instruction above put '=d$1*d4+c4', and copy that into a huge rectangle. The dollar sign, $, will cause the index that follows it to remain constant. Thus when you copy this into other rows and columns, d$1 will be the element of that column in the first row.

When you again put 1 in c4 you get numbers called "The Stirling numbers of the second kind" .

Binomial coefficients count the number of subsets of an n element set having k elements in them. The Stirling number for arguments n and k here counts the number of partitions of a set of n elements into k disjoint blocks.

Exercises:

0.6 Set this up on your own machine. Solution

0.7 Binomial coefficients count the number of subsets of an n element set having k elements in them. The Stirling number here counts the number of partitions of a set of n elements into k disjoint blocks. Prove these two statements. Solution

0.8 Invent a good question for this spot.