| LANE | SAMPLE | LANE | SAMPLE |
|---|---|---|---|
| 1 | Group 1, U | 8 | Parent IPC |
| 2 | Group 1, D | 9 | BLANK |
| 3 | BLANK | 10 | Group 3, U |
| 4 | Group 3, D | 11 | Group 2, 8-12 |
| 5 | Group 2, D | 12 | BLANK |
| 6 | BLANK | 13 | Group 4, U |
| 7 | DNA Ladder | 14 | Group 4, D |
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Bacterial transformation. (Figure by MIT OpenCourseWare.)
Assuming all went well, your reaction tubes from last time contain mutagenized DNA that encodes mutant inverse pericam. However, the desired DNA plasmid is likely present at a low concentration, and moreover it is nicked rather than in intact circular form. What we would like to do now is repair and further amplify only the mutagenized product. Thankfully, we have E. coli bacteria to do this for us quite efficiently!
Bacteria can take up foreign DNA in a process called transformation, during which a single plasmid enters a bacterium and, once inside, replicates and expresses the genes it encodes. Most bacteria do not exist in a transformation-ready state, but can be made permeable to foreign DNA by chemical treatment or other means. Cells that are capable of transformation are referred to as competent. Competent cells are extremely fragile and should be handled gently, i.e., kept cold and not vortexed. Bacterial transformation is efficient enough for most lab purposes, resulting in as many as 109 transformed cells per microgram of DNA, but even with highly competent cells only 1 DNA molecule in about 10,000 is successfully transformed. Thus we need a way to identify transformed cells, which is usually accomplished with antiobiotics. For example, the plasmid carrying inverse pericam (called pRSET) also carries a gene that leads to ampicillin-resistance. Consequently, a transformed bacterium will grow on ampicillin-containing agar medium, while untransformed cells will die before they can form a colony (see figure above right). Given the low concentration and nicked structure of your DNA to begin with, you should perform your transformations today with great care.
Before setting up transformations, you will test your mutagenized DNA for the presence and approximate concentration of product, by running your mutagenesis reaction mixtures (both before and after DpnI digestion) through an agarose gel. Because the product is several Kbp long, a standard 1% agarose gel will serve us just fine. The long mutant plasmid DNA should be separated from the short digested fragments of parental DNA and thus can be identified. However, the bands may be very faint. (Note that the parental plasmid is originally present at a concentration too low to detect on a gel.) If you do not see a band at the expected size of the mutant plasmid, you might increase the amount of DNA used during the transformation procedure at the end of lab.
Using a 1% agarose gel prepared by the teaching faculty, you will run two samples and a reference lane containing standards of known molecular weight (also called a DNA ladder). Recall that You should always handle all gels and gel equipment with nitrile gloves.
| LANE | SAMPLE | LANE | SAMPLE |
|---|---|---|---|
| 1 | Group 1, U | 8 | Parent IPC |
| 2 | Group 1, D | 9 | BLANK |
| 3 | BLANK | 10 | Group 3, U |
| 4 | Group 3, D | 11 | Group 2, 8-12 |
| 5 | Group 2, D | 12 | BLANK |
| 6 | BLANK | 13 | Group 4, U |
| 7 | DNA Ladder | 14 | Group 4, D |
While the gel runs, you can label the tubes you will need later, work on your notebooks, start the FNT assignment, etc.
Be sure to pre-chill your 14 mL tubes on ice for at least a few min before adding competent cells to them.
You will transform competent cells called XL1-Blue with your X#Z mutagenesis reactions and plate them on ampicillin-containing Petri dishes. Tomorrow, two candidate colonies will be chosen from each group's plate. The efficiency of this mutagenesis protocol is reported to be ~80%. We will test two candidates per mutation to cover our bases, so to speak.
You will make your teaching faculty very happy if you contribute to their preparatory work. Please label 2 large glass test tubes with your team color and sample name (X#Z-1, X#Z-2). Mix 10 mL LB with 10 μL of ampicillin. Aliquot 2.5 mL of LB+Amp per tube. These will be used to set up liquid overnight cultures from your two colonies for next time.
A silent mutation can be introduced that results in a new PvuI site at the 341st-342nd residues of inverse pericam (ATT → ATC and TAC → GAC) , or approximately the 1020th basepair of IPC. When IPC is inserted into pRSET, its starting point is ~200bp into the pRSET plasmid. Thus, if the mutated pRSET-IPC plasmid is digested with PvuI, three linear fragments of DNA are the result: 470, 1050, and 2660 bp. To understand these calculations, see also the plasmid maps below. Make sure you can reproduce the numbers above before proceeding with your own samples.

Left: IPC plasmid map (Q1). Right: Mutant plasmid map (Q1)
For this assignment, you should plan restriction enzyme digests that allow you to distinguish parental and mutant pRSET-IPC for M124S and for your X#Z mutation. You are probably best off doing a single enzyme digest for this particular experiment. However, in other kinds of experiments (notably cloning) using two enzymes per digest can give more information. Note: the M124S primer information is now on the Day 2 Talk page.
(A) Use NEB's NEBuffer Activity Chart for Restriction Enzymes to determine the appropriate buffer and temperature for your reactions.
(B) In addition to giving the reaction conditions for each digest, you should explicitly show how the digest distinguishes between parent and mutant. In other words, what are the expected band sizes for each upon digestion?