1 00:00:00 --> 00:00:01 2 00:00:01 --> 00:00:02 The following content is provided under a Creative 3 00:00:02 --> 00:00:03 Commons license. 4 00:00:03 --> 00:00:06 Your support will help MIT OpenCourseWare continue to 5 00:00:06 --> 00:00:10 offer high quality educational resources for free. 6 00:00:10 --> 00:00:13 To make a donation, or view additional materials from 7 00:00:13 --> 00:00:16 hundreds of MIT courses, visit MIT OpenCourseWare 8 00:00:16 --> 00:00:20 at ocw.mit.edu. 9 00:00:20 --> 00:00:23 PROFESSOR: So, the first thing that we did is look at a simple 10 00:00:23 --> 00:00:26 polymer model not too different from polymer models that 11 00:00:26 --> 00:00:27 we've seen before. 12 00:00:27 --> 00:00:29 That is, models for molecular configurations. 13 00:00:29 --> 00:00:32 The difference in the case that we treated last time, though, 14 00:00:32 --> 00:00:36 was that instead of having just a handful of possible 15 00:00:36 --> 00:00:40 configurations with their just, designated energies, we had 16 00:00:40 --> 00:00:42 essentially an infinite sequence of levels. 17 00:00:42 --> 00:00:45 All of evenly spaced energy. 18 00:00:45 --> 00:00:49 And we went through that and saw what the thermodynamics 19 00:00:49 --> 00:00:50 worked out to be. 20 00:00:50 --> 00:00:53 And also with the high and low temperature limits of 21 00:00:53 --> 00:00:55 the thermodynamics turned out to be. 22 00:00:55 --> 00:00:59 And the interesting consequence of that is that that particular 23 00:00:59 --> 00:01:03 choice of configurations and energies associated with them 24 00:01:03 --> 00:01:08 maps exactly onto the vibrational levels of 25 00:01:08 --> 00:01:10 an ordinary molecule. 26 00:01:10 --> 00:01:14 So, of course, when we do the statistical mechanics in the 27 00:01:14 --> 00:01:17 end, everything depends on the partition function. 28 00:01:17 --> 00:01:17 Right? 29 00:01:17 --> 00:01:22 So we're always writing some molecular partition function. 30 00:01:22 --> 00:01:30 And we've got a sum over our energies for all the states. 31 00:01:30 --> 00:01:34 And so the only input information we need to know 32 00:01:34 --> 00:01:37 is, what are the levels and what are their energies. 33 00:01:37 --> 00:01:40 So, although we started yesterday with a model of 34 00:01:40 --> 00:01:44 polymer confirmations, once we decided what the energies were, 35 00:01:44 --> 00:01:48 which was this sequence of energies starting at zero and 36 00:01:48 --> 00:01:55 going with E, and 2E, and 3E, I think we labeled them E0, and 37 00:01:55 --> 00:01:59 so on, that's all that mattered as far as the statistical 38 00:01:59 --> 00:02:00 mechanics was concerned. 39 00:02:00 --> 00:02:05 And so, since we started, We formulated this by imagining 40 00:02:05 --> 00:02:08 different confirmations for a polymer, but in fact these are 41 00:02:08 --> 00:02:11 the vibrational energies of any molecule too. 42 00:02:11 --> 00:02:13 Of any vibrational mode. 43 00:02:13 --> 00:02:16 So the results are very generally applicable. 44 00:02:16 --> 00:02:19 And so we saw what the thermodynamics 45 00:02:19 --> 00:02:20 worked out to be. 46 00:02:20 --> 00:02:22 And what the limiting cases were. 47 00:02:22 --> 00:02:25 And a couple of them, that I'll just review, are, one that's 48 00:02:25 --> 00:02:29 very important in lots of settings, is that the low 49 00:02:29 --> 00:02:32 temperature limit when you're down it basically zero degrees 50 00:02:32 --> 00:02:44 Kelvin, that's where you've got kT way down here. 51 00:02:44 --> 00:02:46 So there's not nearly enough thermal energy for anything 52 00:02:46 --> 00:02:48 to get out of even the lowest level. 53 00:02:48 --> 00:02:51 And so in that case, everything is in the ground state. 54 00:02:51 --> 00:02:55 And then the heat capacity, which is this often a very 55 00:02:55 --> 00:02:58 simple thing to measure, you change the temperature. 56 00:02:58 --> 00:03:00 And you see that there's no change in the total 57 00:03:00 --> 00:03:01 vibrational energy. 58 00:03:01 --> 00:03:03 In other words, the limiting low temperature heat 59 00:03:03 --> 00:03:06 capacity is zero. 60 00:03:06 --> 00:03:15 So we saw that for Cv for vibrations. 61 00:03:15 --> 00:03:20 And the limit that T goes to zero was zero. 62 00:03:20 --> 00:03:23 And that's because we were in this limit, where everything 63 00:03:23 --> 00:03:24 is in the ground state. 64 00:03:24 --> 00:03:30 Which is to say that u vibrational energy in 65 00:03:30 --> 00:03:35 that limit is zero. 66 00:03:35 --> 00:03:38 Unlike the case we treated earlier, where we had a 67 00:03:38 --> 00:03:39 limited number of levels. 68 00:03:39 --> 00:03:42 Because we treated a simple four-unit polymer with only 69 00:03:42 --> 00:03:46 four possible confirmations, in this case we have essentially 70 00:03:46 --> 00:03:47 an infinite number. 71 00:03:47 --> 00:03:52 So even in the high temperature limit, we don't have them, 72 00:03:52 --> 00:03:54 there's not a maximum total energy. 73 00:03:54 --> 00:03:55 If the temperature keeps going up, you'll get 74 00:03:55 --> 00:03:56 more and more energy. 75 00:03:56 --> 00:04:00 Because you can keep populating higher and higher levels. 76 00:04:00 --> 00:04:03 But the way that happens stops changing. 77 00:04:03 --> 00:04:06 Because the levels are all evenly spaced. 78 00:04:06 --> 00:04:09 So if the temperature, instead of being down here, is 79 00:04:09 --> 00:04:15 somewhere up here, now for sure if we change the 80 00:04:15 --> 00:04:18 temperature, the energy will continue to change. 81 00:04:18 --> 00:04:22 But what we've found is that in the high temperature limit, we 82 00:04:22 --> 00:04:26 had the equipartition of energy result. 83 00:04:26 --> 00:04:33 And that is, u vibrational in the high temperature 84 00:04:33 --> 00:04:40 limit, was just, for N molecules, it was NkT. 85 00:04:40 --> 00:04:44 1/2 kT for each kinetic energy degree of freedom. 86 00:04:44 --> 00:04:47 1/2 kT for each potential energy degree of freedom. 87 00:04:47 --> 00:04:51 And since vibrations have each of those, potential and kinetic 88 00:04:51 --> 00:04:54 energy, it's kT for each molecule, for each 89 00:04:54 --> 00:04:56 degree of freedom. 90 00:04:56 --> 00:04:58 That's an incredibly simple, useful thing. 91 00:04:58 --> 00:05:01 That means, if I've got a molecule in the gas phase and 92 00:05:01 --> 00:05:05 it's in the high temperature limit for translation, I know 93 00:05:05 --> 00:05:09 each translational degree of freedom will contribute 94 00:05:09 --> 00:05:12 for each molecule 1/2 kT. 95 00:05:12 --> 00:05:15 Or 3/2 kT, in all three dimensions. 96 00:05:15 --> 00:05:19 So I know the translational energy of a mole of molecules 97 00:05:19 --> 00:05:22 in the gas phase at room temperature without 98 00:05:22 --> 00:05:23 doing anything all. 99 00:05:23 --> 00:05:24 It's 3/2 NkT. 100 00:05:24 --> 00:05:28 Rotations, if it's a diatomic molecule, will be two 101 00:05:28 --> 00:05:30 different degrees of freedom. 102 00:05:30 --> 00:05:30 For rotation. 103 00:05:30 --> 00:05:32 In two orthogonal planes. 104 00:05:32 --> 00:05:35 And I'll have 1/2 kT for each. 105 00:05:35 --> 00:05:37 1/2 NkT for N molecules. 106 00:05:37 --> 00:05:40 For vibrations, if I'm in a high temperature limit, then 107 00:05:40 --> 00:05:42 it'll be kT for each vibrational mode. 108 00:05:42 --> 00:05:45 For molecules, the vibrational frequencies are usually high, 109 00:05:45 --> 00:05:47 so that you're not in the high temperature limit. 110 00:05:47 --> 00:05:52 But for materials where you have vibrations, acoustic 111 00:05:52 --> 00:05:54 vibrations, those are low frequency. 112 00:05:54 --> 00:05:55 You can be in the high temperature limit. 113 00:05:55 --> 00:05:57 And easily are. 114 00:05:57 --> 00:06:01 So the result for energy for vibrational energy in the high 115 00:06:01 --> 00:06:02 temperature limit, was NkT. 116 00:06:02 --> 00:06:08 And so that means that the heat capacity in that same limit at 117 00:06:08 --> 00:06:13 high temperature was just Nk, derivative with respect 118 00:06:13 --> 00:06:14 to temperature. 119 00:06:14 --> 00:06:17 Very simple thing to measure, again. 120 00:06:17 --> 00:06:20 So that's what we saw last time in the case of both the 121 00:06:20 --> 00:06:24 conformational model that we treated and the vibrational 122 00:06:24 --> 00:06:29 energies of molecules onto which that same model maps. 123 00:06:29 --> 00:06:32 Now what I want to do, is look a little further. 124 00:06:32 --> 00:06:35 And let me actually write the partition functions too. 125 00:06:35 --> 00:06:38 Also an important result was that the partition function 126 00:06:38 --> 00:06:46 itself, q vibrational, in the high temperature limit, 127 00:06:46 --> 00:06:50 was just kT over E0. 128 00:06:50 --> 00:06:57 Also very simple result. 129 00:06:57 --> 00:07:10 E0 is h nu 0 for vibrational mode with frequency nu 0. 130 00:07:10 --> 00:07:12 And of course, given the partition function you can 131 00:07:12 --> 00:07:13 calculate everything. 132 00:07:13 --> 00:07:15 So in the high temperature limit we can easily 133 00:07:15 --> 00:07:16 calculate things. 134 00:07:16 --> 00:07:18 In the low temperature limit, it's just one, right? 135 00:07:18 --> 00:07:21 There's only one allowed possible state in the 136 00:07:21 --> 00:07:22 low temperature limit. 137 00:07:22 --> 00:07:26 Everything is in the ground state when it's cold enough. 138 00:07:26 --> 00:07:30 So the sum of our states just gives us exactly one term 139 00:07:30 --> 00:07:32 that's of any reasonable value. 140 00:07:32 --> 00:07:35 That is, the term with this being the lowest energy. 141 00:07:35 --> 00:07:38 Everything else, the energy is much bigger than kT. 142 00:07:38 --> 00:07:45 This is a vanishingly small number then. 143 00:07:45 --> 00:07:50 So just write q, vibrational, in the low temperature 144 00:07:50 --> 00:07:53 limit, is just one. 145 00:07:53 --> 00:07:57 OK, that was the case for vibration. 146 00:07:57 --> 00:08:02 And remember, these low temperature limiting cases, 147 00:08:02 --> 00:08:04 that's a common case for nearly any degree of freedom. 148 00:08:04 --> 00:08:06 As long as it's quantized. 149 00:08:06 --> 00:08:08 At some point, you'll get this situation. 150 00:08:08 --> 00:08:11 Where the temperature is low compared to even the 151 00:08:11 --> 00:08:12 lowest excited level. 152 00:08:12 --> 00:08:15 Of course, what'll happen in the high temperature limit 153 00:08:15 --> 00:08:19 might vary, depending on the structure of the energy levels. 154 00:08:19 --> 00:08:22 In the case of vibrations, it's like this, it'll turn out 155 00:08:22 --> 00:08:23 rotations do the same thing. 156 00:08:23 --> 00:08:28 But it's not always as simple as this. 157 00:08:28 --> 00:08:34 OK, now what I want to do is just go through the next step 158 00:08:34 --> 00:08:37 of what we can treat, given the statistical 159 00:08:37 --> 00:08:38 mechanics that we know. 160 00:08:38 --> 00:08:40 Which is chemical equilibrium. 161 00:08:40 --> 00:08:43 Why can't we just calculate equilibrium constants based 162 00:08:43 --> 00:08:45 on what we've seen so far. 163 00:08:45 --> 00:08:48 If we can calculate the partition functions for 164 00:08:48 --> 00:08:51 molecules, and they undergo reactions and they're in 165 00:08:51 --> 00:08:54 equilibrium, we should be able to calculate the 166 00:08:54 --> 00:08:55 equilibrium constants. 167 00:08:55 --> 00:08:57 From first principles, just based on the statistical 168 00:08:57 --> 00:08:59 math we've seen so far. 169 00:08:59 --> 00:09:15 So let's try to do that. 170 00:09:15 --> 00:09:18 So it just means that, again, just as always, if we know all 171 00:09:18 --> 00:09:21 the energy levels and what all the possible states are, 172 00:09:21 --> 00:09:24 there's no reason we shouldn't be able to set our sights on a 173 00:09:24 --> 00:09:28 calculation of that sort. 174 00:09:28 --> 00:09:31 So let's just sketch out what the levels are going to 175 00:09:31 --> 00:09:34 look like for simple chemical events. 176 00:09:34 --> 00:09:43 So I just want to draw an energy diagram, here's energy. 177 00:09:43 --> 00:09:46 And, like we often do with chemical equilibria, I'm going 178 00:09:46 --> 00:09:50 to set the zero of energy at the separated atoms, and 179 00:09:50 --> 00:10:14 I'm imagining I've got reactants and products. 180 00:10:14 --> 00:10:20 So let's make this our products. 181 00:10:20 --> 00:10:23 Then over here we'll have our reactants and make 182 00:10:23 --> 00:10:32 the energies different. 183 00:10:32 --> 00:10:33 Alright. 184 00:10:33 --> 00:10:36 So there's some amount of binding energy, right? 185 00:10:36 --> 00:10:40 There's a bond dissociation energy going from the lowest 186 00:10:40 --> 00:10:44 available level in each molecule to the dissociation 187 00:10:44 --> 00:10:47 limit where we pulled the atoms apart. 188 00:10:47 --> 00:10:50 So now I'm going to draw vibrational energy levels 189 00:10:50 --> 00:10:51 inside the molecule. 190 00:10:51 --> 00:10:54 Let's imagine, it wouldn't need to be this, but let's imagine 191 00:10:54 --> 00:10:56 it's just diatomic molecules. 192 00:10:56 --> 00:10:59 So there's one vibrational mode in each. 193 00:10:59 --> 00:11:01 Just the stretching mode. 194 00:11:01 --> 00:11:06 And we've already seen the levels are evenly spaced. 195 00:11:06 --> 00:11:09 So there's going to be a bunch of evenly spaced levels. 196 00:11:09 --> 00:11:12 Actually, it stopped being quite evenly spaced once this 197 00:11:12 --> 00:11:16 stops being a simple harmonic oscillator, but for all the 198 00:11:16 --> 00:11:18 low lying levels it's pretty close to that. 199 00:11:18 --> 00:11:22 So those are the available levels. 200 00:11:22 --> 00:11:25 And there's a dissociation energy. 201 00:11:25 --> 00:11:36 So minus E, and I'll call this for the products, Ep. 202 00:11:36 --> 00:11:40 203 00:11:40 --> 00:11:45 And it's just minus D0 for the products. 204 00:11:45 --> 00:11:48 Right, in language, terminology that we've seen before. 205 00:11:48 --> 00:11:56 And it's the same thing for the reactants. 206 00:11:56 --> 00:12:00 And really, if this were more than a diatomic molecule, 207 00:12:00 --> 00:12:02 maybe there would be a bunch of vibrational modes. 208 00:12:02 --> 00:12:03 But it wouldn't matter. 209 00:12:03 --> 00:12:06 This would just represent all the vibrational energies. 210 00:12:06 --> 00:12:14 There's some lowest state available. 211 00:12:14 --> 00:12:18 So now we've got the dissociation energy 212 00:12:18 --> 00:12:23 for the reactants. 213 00:12:23 --> 00:12:26 So those are the energies it takes to separate the molecule. 214 00:12:26 --> 00:12:29 But those aren't the only states available to molecules. 215 00:12:29 --> 00:12:32 Of course, they could have extra vibrational energy. 216 00:12:32 --> 00:12:35 They're not always in their ground states. 217 00:12:35 --> 00:12:37 And we're going to calculate partition functions. 218 00:12:37 --> 00:12:41 In general we would sum over all the available states. 219 00:12:41 --> 00:12:43 And then just calculate the probability of 220 00:12:43 --> 00:12:46 being in the state. 221 00:12:46 --> 00:12:50 One way to look at this, since if there's chemical equilibrium 222 00:12:50 --> 00:12:54 between the species, it means the molecules can interconvert. 223 00:12:54 --> 00:12:57 What that really means is that any of the molecule has access 224 00:12:57 --> 00:13:00 to any of these states. 225 00:13:00 --> 00:13:03 Of course, we like to group all these states over here. 226 00:13:03 --> 00:13:06 Because they correspond to a particular chemical structure. 227 00:13:06 --> 00:13:08 And we like to group these states over here, because they 228 00:13:08 --> 00:13:12 correspond to this different chemical structure. 229 00:13:12 --> 00:13:15 From a statistical mechanics point of view, it's 230 00:13:15 --> 00:13:18 just states and levels. 231 00:13:18 --> 00:13:22 And we could just calculate the probability of any molecule 232 00:13:22 --> 00:13:25 being in any one of the states. 233 00:13:25 --> 00:13:28 But it's useful to keep them separated like this. 234 00:13:28 --> 00:13:31 So let's do that. 235 00:13:31 --> 00:13:37 And let's look at the difference here, the difference 236 00:13:37 --> 00:13:39 in dissociation energy. 237 00:13:39 --> 00:13:41 Delta D0. 238 00:13:41 --> 00:13:44 Let's not put a double arrow. 239 00:13:44 --> 00:13:49 Let's define the sign of it. 240 00:13:49 --> 00:13:54 This way, going from products to reactants. 241 00:13:54 --> 00:13:58 OK, now let's just look at how equilibrium should work. 242 00:13:58 --> 00:14:01 So now, let's just take a generic reaction. 243 00:14:01 --> 00:14:06 Little a, our number, our stoichiometric number, A plus 244 00:14:06 --> 00:14:12 b, and B goes to c C, d D. 245 00:14:12 --> 00:14:20 And we know that delta G0 is minus RT log of Kp. 246 00:14:20 --> 00:14:24 247 00:14:24 --> 00:14:28 And that delta G0 is just the free energy of the products 248 00:14:28 --> 00:14:30 minus the free energy of the reactants. 249 00:14:30 --> 00:14:43 So it's c times G C0 plus d G D0 minus a G A0 250 00:14:43 --> 00:14:47 minus b G equals B0. 251 00:14:47 --> 00:14:50 So we need to know the free energy of each 252 00:14:50 --> 00:14:53 one of the species. 253 00:14:53 --> 00:14:56 And now we know how to calculate that from first 254 00:14:56 --> 00:14:58 principles, through statistical mechanics. 255 00:14:58 --> 00:15:05 So we know that G is A plus pV. 256 00:15:05 --> 00:15:14 A is minus kT log of capital Q. 257 00:15:14 --> 00:15:18 And I'm going to assume that we're in the gas phase. 258 00:15:18 --> 00:15:21 And it's an ideal gas, so I'm going to replace pV by NkT. 259 00:15:21 --> 00:15:31 260 00:15:31 --> 00:15:33 And what's Q? 261 00:15:33 --> 00:15:37 Well, we know what Q is. 262 00:15:37 --> 00:15:45 It's q, little q, to the N power translational 263 00:15:45 --> 00:15:47 over N factorial. 264 00:15:47 --> 00:15:50 For atoms, this is all it would be. 265 00:15:50 --> 00:15:51 But we have molecules. 266 00:15:51 --> 00:15:54 So we have individual other degrees of freedom 267 00:15:54 --> 00:15:57 besides translation. 268 00:15:57 --> 00:16:04 So let me just label those internal, q internal. 269 00:16:04 --> 00:16:06 And that's also to the N power. 270 00:16:06 --> 00:16:09 And q internal, if you say, what are those degrees of 271 00:16:09 --> 00:16:12 freedom, well it's the electronic energy. it's 272 00:16:12 --> 00:16:13 the vibrational energy. 273 00:16:13 --> 00:16:14 It's the rotational energy. 274 00:16:14 --> 00:16:17 And we'll deal with those shortly, but let's just 275 00:16:17 --> 00:16:19 separate it this way for now. 276 00:16:19 --> 00:16:26 Just we can keep track of where the N factorial belongs. 277 00:16:26 --> 00:16:28 And now we're going to use Stirling's approximation 278 00:16:28 --> 00:16:32 for the N factorial. 279 00:16:32 --> 00:16:46 So our log of Q, which we need up here, is just N log of q 280 00:16:46 --> 00:17:05 trans q internal minus log of N factorial. 281 00:17:05 --> 00:17:14 And that's just equal to N log q trans q internal, 282 00:17:14 --> 00:17:19 minus N log N. 283 00:17:19 --> 00:17:22 Plus N. 284 00:17:22 --> 00:17:26 And of course, this I'm going to put down here momentarily. 285 00:17:26 --> 00:17:31 And now our expression for G is up there. 286 00:17:31 --> 00:17:36 So it's minus kT log of Q plus NkT. 287 00:17:36 --> 00:17:41 288 00:17:41 --> 00:17:47 So these factors of N are going to cancel. 289 00:17:47 --> 00:17:50 So when I take minus kT log of Q, that's going to 290 00:17:50 --> 00:17:52 be minus NkT over here. 291 00:17:52 --> 00:17:54 That's going to cancel the plus NkT here. 292 00:17:54 --> 00:17:57 So all I'm going to have left is this term and this term. 293 00:17:57 --> 00:18:01 Which I can combine. 294 00:18:01 --> 00:18:12 So it's just minus NkT log of q translational 295 00:18:12 --> 00:18:15 q internal over N. 296 00:18:15 --> 00:18:19 Now these, really, are just the same as q, it's just minus 297 00:18:19 --> 00:18:24 NkT log of little q over N. 298 00:18:24 --> 00:18:27 I didn't need to separate that into this product. 299 00:18:27 --> 00:18:29 I only wanted to do it to be clear where we were getting 300 00:18:29 --> 00:18:33 this factor of N factorial from. 301 00:18:33 --> 00:18:37 So now we have an expression for G. 302 00:18:37 --> 00:18:40 And if we know G for all the species involved in a chemical 303 00:18:40 --> 00:18:43 reaction, we should be able to calculate the chemical 304 00:18:43 --> 00:18:44 equilibrium. 305 00:18:44 --> 00:18:46 So let's do it. 306 00:18:46 --> 00:18:50 So now to do it, let's look a little more closely at what 307 00:18:50 --> 00:18:52 these internal degrees of freedom are. 308 00:18:52 --> 00:18:55 Because that's where these important details are 309 00:18:55 --> 00:18:56 going to come in. 310 00:18:56 --> 00:18:58 Obviously the equilibrium is going to depend 311 00:18:58 --> 00:18:59 on the energetics. 312 00:18:59 --> 00:19:02 How much different are the bonding energies or the 313 00:19:02 --> 00:19:05 dissociation energies and the molecules involved. 314 00:19:05 --> 00:19:08 And also, how much different or the other molecular 315 00:19:08 --> 00:19:09 energy levels. 316 00:19:09 --> 00:19:12 The vibrations, rotations, and so forth. 317 00:19:12 --> 00:19:27 So, q internal is the product of rotational, vibrational, and 318 00:19:27 --> 00:19:30 electronic partition functions. 319 00:19:30 --> 00:19:35 Remember how we saw that if you can write the energy as a sum 320 00:19:35 --> 00:19:38 of energies, then the partition functions are multiplied. 321 00:19:38 --> 00:19:44 Because, of course, if this is the sum of a rotational plus 322 00:19:44 --> 00:19:47 vibrational plus electronic energy, then of course I can 323 00:19:47 --> 00:19:49 just separate out these things. 324 00:19:49 --> 00:19:50 These are in the exponent. 325 00:19:50 --> 00:19:55 I can write it as a product. 326 00:19:55 --> 00:19:56 Same with translations. 327 00:19:56 --> 00:20:01 I already have separated that. 328 00:20:01 --> 00:20:05 So now let's look at how these things behave. 329 00:20:05 --> 00:20:13 Well, for the electronic case, there's really only one 330 00:20:13 --> 00:20:15 electronic state of interest in general. 331 00:20:15 --> 00:20:18 And that's the lowest state. 332 00:20:18 --> 00:20:20 In cases you're extremely familiar with, if it were the 333 00:20:20 --> 00:20:23 hydrogen atom, it would be down in the 1s orbital. 334 00:20:23 --> 00:20:26 And it would take a huge amount of energy to get up into 335 00:20:26 --> 00:20:28 the 2s or 2p orbital. 336 00:20:28 --> 00:20:31 At ordinary temperatures you never have that. 337 00:20:31 --> 00:20:34 All the atoms would be in the ground state. 338 00:20:34 --> 00:20:37 Now, for most molecules, it don't take as much energy 339 00:20:37 --> 00:20:39 as for the hydrogen atom. 340 00:20:39 --> 00:20:43 If you have benzene, for example, the ground electronic 341 00:20:43 --> 00:20:47 state, the lowest electronic state, is quite far below 342 00:20:47 --> 00:20:48 the first excited state. 343 00:20:48 --> 00:20:52 Not as much as the hydrogen atom going from 1s to 2s to 2p, 344 00:20:52 --> 00:20:55 but still by much more than ordinary thermal energies 345 00:20:55 --> 00:20:57 at room temperature. 346 00:20:57 --> 00:21:00 And what that means is, again, only the ground state 347 00:21:00 --> 00:21:04 term is going to matter. 348 00:21:04 --> 00:21:07 Now, sometimes we would define that is this as 349 00:21:07 --> 00:21:08 the zero of energy. 350 00:21:08 --> 00:21:09 But since we're doing chemical equilibria, the zero 351 00:21:09 --> 00:21:12 of energy is up here. 352 00:21:12 --> 00:21:18 So that epsilon, that energy term, is this amount. 353 00:21:18 --> 00:21:20 The dissociation energy. 354 00:21:20 --> 00:21:22 This is minus dissociation energy. 355 00:21:22 --> 00:21:24 So we're going to have a positive number there. 356 00:21:24 --> 00:21:37 So q electronic is just e to the D0 over kT. 357 00:21:37 --> 00:22:13 So that's easy enough. 358 00:22:13 --> 00:22:18 We also know what the vibrational partition 359 00:22:18 --> 00:22:19 function is. 360 00:22:19 --> 00:22:21 We saw it last time. 361 00:22:21 --> 00:22:24 It's this thing we could write as a simple form. 362 00:22:24 --> 00:22:27 One over one minus e to the minus E, I'll call 363 00:22:27 --> 00:22:31 it E vibe, over kT. 364 00:22:31 --> 00:22:41 It's h nu 0, where nu is the vibrational frequency. 365 00:22:41 --> 00:22:45 Again, in the case of many molecules, the vibrational 366 00:22:45 --> 00:22:47 energy is pretty high compared to kT. 367 00:22:47 --> 00:22:50 So even this often simplifies to be just one. 368 00:22:50 --> 00:22:54 In other words, all the molecules, in many cases, are 369 00:22:54 --> 00:22:57 basically all of them are in the ground vibrational 370 00:22:57 --> 00:23:00 state at room temperature. 371 00:23:00 --> 00:23:03 Certainly if you look at molecules of high frequencies, 372 00:23:03 --> 00:23:07 if you look at the hydrogen molecule, H2, the vibrational 373 00:23:07 --> 00:23:10 frequency is about 4,000 wave numbers. 374 00:23:10 --> 00:23:13 Remember I mentioned last time, kT at room temperature, 375 00:23:13 --> 00:23:15 T is 300 Kelvin. 376 00:23:15 --> 00:23:18 Then kT corresponds to 200 wave numbers. 377 00:23:18 --> 00:23:20 It's a factor of 2/3. 378 00:23:20 --> 00:23:23 Much less than 4 wave numbers. 379 00:23:23 --> 00:23:28 In other words, the vibrational energy is much lower than kT. 380 00:23:28 --> 00:23:31 So, again, everything would be in the lowest level. 381 00:23:31 --> 00:23:34 And this just simplifies to one. 382 00:23:34 --> 00:23:40 In many cases, it's reasonably close to one. 383 00:23:40 --> 00:23:54 For high vibrational frequencies, nu 0. 384 00:23:54 --> 00:24:03 Now, we haven't talked about rotation. 385 00:24:03 --> 00:24:08 But you probably have just an intuitive feeling that at 386 00:24:08 --> 00:24:12 ordinary temperatures, if I do this, if I wave my hand in the 387 00:24:12 --> 00:24:15 air, molecules that I happen to intersect are going to 388 00:24:15 --> 00:24:17 start spinning faster. 389 00:24:17 --> 00:24:20 In other words, ordinary thermal energies do populate 390 00:24:20 --> 00:24:26 some number of rotational levels of molecules. 391 00:24:26 --> 00:24:28 Molecules probably aren't going to start getting squished 392 00:24:28 --> 00:24:33 together and vibrate harder when I do something like this. 393 00:24:33 --> 00:24:36 So molecules might generally still be in the ground 394 00:24:36 --> 00:24:39 vibrational levels, thermal energy isn't enough to 395 00:24:39 --> 00:24:41 raise them in many cases. 396 00:24:41 --> 00:24:42 But rotation, for sure. 397 00:24:42 --> 00:24:45 They're not all in the lowest level. 398 00:24:45 --> 00:24:51 Turns out that, in fact, the energy separation between 399 00:24:51 --> 00:24:54 rotational levels is very small compared to kT 400 00:24:54 --> 00:24:55 at room temperature. 401 00:24:55 --> 00:25:00 So just like we saw for the high temperature limit for 402 00:25:00 --> 00:25:10 vibrations, it turns out that for q rotation in the high 403 00:25:10 --> 00:25:16 temperature limit, we have the same situation where we have 404 00:25:16 --> 00:25:23 kT over, now it's a rotational energy. 405 00:25:23 --> 00:25:26 And it's typically on the order of about one to ten wave 406 00:25:26 --> 00:25:32 numbers for small to medium sized molecules. 407 00:25:32 --> 00:25:35 Remember, too, last time when we talked about in the 408 00:25:35 --> 00:25:38 vibrational levels and said, well, if you're at kT and it's 409 00:25:38 --> 00:25:42 this big, it's basically telling you roughly how many 410 00:25:42 --> 00:25:46 levels do you have thermal access to. 411 00:25:46 --> 00:25:49 Because we saw the same results for vibrations. 412 00:25:49 --> 00:25:52 It's not so different for rotation. 413 00:25:52 --> 00:25:54 And it turns out that at ordinary temperatures, you 414 00:25:54 --> 00:25:58 might have access to a few tens to a few hundreds of rotational 415 00:25:58 --> 00:26:02 levels, depending on whether they're closer to one or ten 416 00:26:02 --> 00:26:03 wave numbers or a little higher. 417 00:26:03 --> 00:26:08 Again, room temperature is 200 wave numbers. 418 00:26:08 --> 00:26:13 So, that means that, remember q is a unitless number. 419 00:26:13 --> 00:26:15 You're counting the states, weighted by the energy. 420 00:26:15 --> 00:26:18 Weighted by the Boltzmann factor. 421 00:26:18 --> 00:26:21 And for rotations, it's a number that might be on 422 00:26:21 --> 00:26:34 the order of 100 or so. 423 00:26:34 --> 00:26:38 Order of magnitude estimate, that's all. 424 00:26:38 --> 00:26:44 And of course we've seen the translational partition 425 00:26:44 --> 00:26:54 function is on the order of 10 to the 30th, right? 426 00:26:54 --> 00:26:55 Enormous number. 427 00:26:55 --> 00:26:59 In other words, in the simple lattice model that we've use to 428 00:26:59 --> 00:27:02 describe translation, just breaking up the available 429 00:27:02 --> 00:27:04 volume into little pieces. 430 00:27:04 --> 00:27:04 Counting. 431 00:27:04 --> 00:27:07 Well, OK, you have something on the order of 10 to the 432 00:27:07 --> 00:27:09 30th possible locations. 433 00:27:09 --> 00:27:13 And if you treat this properly, quantum mechanically, for the 434 00:27:13 --> 00:27:15 translations, there's actually a magnitude of the 435 00:27:15 --> 00:27:19 number is similar. 436 00:27:19 --> 00:27:23 Now I just want to go through a very simple example. 437 00:27:23 --> 00:27:28 Just treating a particular generic reaction. 438 00:27:28 --> 00:27:30 And look at what the equilibrium constant is. 439 00:27:30 --> 00:27:33 Working it through, given what we've seen so far. 440 00:27:33 --> 00:27:37 So I just want to simplify it by having all the 441 00:27:37 --> 00:27:41 stoichiometric coefficients equal to one. 442 00:27:41 --> 00:27:45 It's not a great complication, if we don't do that. 443 00:27:45 --> 00:27:50 But it's a little bit simpler. 444 00:27:50 --> 00:27:56 So let's take a molecule that's A-B plus C-D. 445 00:27:56 --> 00:27:59 And now let's break bonds and reform them. 446 00:27:59 --> 00:28:05 So we get A-C plus B-D, right? 447 00:28:05 --> 00:28:08 So we're going to do something simple. 448 00:28:08 --> 00:28:11 And since I've got all the stoichiometric coefficients 449 00:28:11 --> 00:28:13 equal to one, we've got the same number of molecules as 450 00:28:13 --> 00:28:16 reactants and products, that'll make things 451 00:28:16 --> 00:28:18 a little bit easier. 452 00:28:18 --> 00:28:21 Just in the sense that if we look at the contribution of 453 00:28:21 --> 00:28:24 the translational energies at room temperature, they're 454 00:28:24 --> 00:28:25 going to be the same. 455 00:28:25 --> 00:28:27 For the reactants and the products. 456 00:28:27 --> 00:28:30 Any of the molecules is going to have a translational 457 00:28:30 --> 00:28:33 partition function on the order of 10 to the 30th, at room 458 00:28:33 --> 00:28:35 temperature and an ordinary volume. 459 00:28:35 --> 00:28:40 And nothing's going to change from reactants to products. 460 00:28:40 --> 00:28:44 And for vibrations, let's assume, as is often the 461 00:28:44 --> 00:28:48 case, that the vibrational frequencies are fairly high. 462 00:28:48 --> 00:28:51 So all the partition functions for the vibrations 463 00:28:51 --> 00:28:53 are equal to one. 464 00:28:53 --> 00:28:54 Like we've got written up there. 465 00:28:54 --> 00:28:56 For all four of the molecules. 466 00:28:56 --> 00:28:59 So then nothing is going to change in the vibrations. 467 00:28:59 --> 00:29:03 Going from reactants to products. 468 00:29:03 --> 00:29:05 Finally, the rotations. 469 00:29:05 --> 00:29:08 So, for the rotations our partition function is something 470 00:29:08 --> 00:29:13 on the order of, I think I meant to write 100, 471 00:29:13 --> 00:29:15 not ten here. 472 00:29:15 --> 00:29:17 As our order of magnitude. 473 00:29:17 --> 00:29:17 That's what it's going to be. 474 00:29:17 --> 00:29:21 It's a number on that order. 475 00:29:21 --> 00:29:25 And if we assume that the masses of the atoms involved 476 00:29:25 --> 00:29:28 are comparable, then we can cheat a little bit and say 477 00:29:28 --> 00:29:32 that's also, those numbers are also, going to be comparable 478 00:29:32 --> 00:29:35 for the reactants and the products. 479 00:29:35 --> 00:29:36 We don't have to do that. 480 00:29:36 --> 00:29:39 We could put it in, and rather easily calculate it. 481 00:29:39 --> 00:29:42 But I'm going to make life simple in this way and just 482 00:29:42 --> 00:29:46 work through how to carry through the calculation. 483 00:29:46 --> 00:29:51 And I think it'll be clear how to put in different partition 484 00:29:51 --> 00:29:53 functions for those quantities if they are different 485 00:29:53 --> 00:29:55 from each other. 486 00:29:55 --> 00:30:03 OK, so let's try it. 487 00:30:03 --> 00:30:16 Then, our delta G0, let's go back over here. 488 00:30:16 --> 00:30:23 Here's delta G, let me just put the relationship up. 489 00:30:23 --> 00:30:26 So we've got an expression for G. 490 00:30:26 --> 00:30:28 Which is, let's start from back there. 491 00:30:28 --> 00:30:35 It's minus. 492 00:30:35 --> 00:30:38 And now for each one of the substances, it's 493 00:30:38 --> 00:30:47 Ni kT log qi over Ni. 494 00:30:47 --> 00:30:49 I'm just going to put this in molar terms. 495 00:30:49 --> 00:30:55 So it's minus little ni RT. 496 00:30:55 --> 00:31:00 Log of qi over capital Ni. 497 00:31:00 --> 00:31:02 And I only want to do that because I want to express 498 00:31:02 --> 00:31:04 this in free energy. 499 00:31:04 --> 00:31:05 This is for substance i. 500 00:31:05 --> 00:31:08 Free energy per mole. 501 00:31:08 --> 00:31:15 So it's just minus RT log of qi over Ni. 502 00:31:15 --> 00:31:17 503 00:31:17 --> 00:31:19 That's G per mole. 504 00:31:19 --> 00:31:25 That's Gi naught per mole. 505 00:31:25 --> 00:31:30 Plus RT log pi over p0. 506 00:31:30 --> 00:31:33 Where p0 is an atmosphere, basically. 507 00:31:33 --> 00:31:39 One bar. 508 00:31:39 --> 00:31:45 So that means Gi0 bar is minus RT. 509 00:31:45 --> 00:31:49 And I'm going to take this minus this and combine them. 510 00:31:49 --> 00:31:57 So it's log of qi over Ni, that's this part. 511 00:31:57 --> 00:32:00 And now I've got log of pi over p, and I'm just going 512 00:32:00 --> 00:32:01 to use the ideal gas law. 513 00:32:01 --> 00:32:03 So I'm going to use pV is nRT. 514 00:32:03 --> 00:32:05 515 00:32:05 --> 00:32:23 So then I've got Ni kT over my factor of p0, times the volume. 516 00:32:23 --> 00:32:30 So that's Gi0 for each one of the substances. 517 00:32:30 --> 00:32:33 The Ni's cancel. 518 00:32:33 --> 00:32:47 And I've got minus RT log of qi kT over p0 times V. 519 00:32:47 --> 00:32:51 Now, qi is just the total molecular partition function. 520 00:32:51 --> 00:32:55 It's this product of q trans times q rotational times q 521 00:32:55 --> 00:33:00 vibrational times q electronic. 522 00:33:00 --> 00:33:08 And now I need delta G. 523 00:33:08 --> 00:33:16 So delta G0, is just minus RT. 524 00:33:16 --> 00:33:18 And now it's just, I'm going to take this for each one of the 525 00:33:18 --> 00:33:22 substances, for the products, minus the reactants. 526 00:33:22 --> 00:33:24 And I'm going to combine the log terms. 527 00:33:24 --> 00:33:26 This is the same, and I'm going to have this in every term. 528 00:33:26 --> 00:33:27 So what's going to happen? 529 00:33:27 --> 00:33:32 Well, all this stuff is going to cancel. 530 00:33:32 --> 00:33:34 Now, that doesn't necessarily happen. 531 00:33:34 --> 00:33:36 That happens because of the stoichiometric numbers 532 00:33:36 --> 00:33:37 being the same. 533 00:33:37 --> 00:33:40 Otherwise I'd have to take them to that the power of 534 00:33:40 --> 00:33:42 the stoichiometric number. 535 00:33:42 --> 00:33:45 But in this case they're just going to simply cancel. 536 00:33:45 --> 00:33:53 So I'm going to have left is the ratio of my partition 537 00:33:53 --> 00:33:56 function for molecule AC. 538 00:33:56 --> 00:34:00 Partition function for molecule BD. 539 00:34:00 --> 00:34:07 Partition function for molecule AB, and for molecule CD. 540 00:34:07 --> 00:34:11 Products, reactants. 541 00:34:11 --> 00:34:13 Pretty simple, because I know how to calculate 542 00:34:13 --> 00:34:15 all this stuff. 543 00:34:15 --> 00:34:19 And again I'd suggested some simplifying assumptions for 544 00:34:19 --> 00:34:20 what those partition functions are. 545 00:34:20 --> 00:34:23 But it wouldn't be hard to calculate each one of them 546 00:34:23 --> 00:34:27 if I just had all the relevant energy levels. 547 00:34:27 --> 00:34:29 To make this simple, we're going to assume that the 548 00:34:29 --> 00:34:33 rotational energies are the same for all the molecules. 549 00:34:33 --> 00:34:35 It wouldn't need to be, it wouldn't be hard, to plug 550 00:34:35 --> 00:34:36 in different values. 551 00:34:36 --> 00:34:39 We're going to assume we're in the low temperature 552 00:34:39 --> 00:34:40 limit for vibrations. 553 00:34:40 --> 00:34:42 So q vibrational for each one of these things 554 00:34:42 --> 00:34:46 is equal to one. 555 00:34:46 --> 00:34:49 The translational contributions, are 556 00:34:49 --> 00:34:51 equal for all of them. 557 00:34:51 --> 00:34:53 So the only thing that's different is the 558 00:34:53 --> 00:34:56 electronic contribution. 559 00:34:56 --> 00:34:57 And that's different. 560 00:34:57 --> 00:35:03 Because, of course, you have different electronic energies. 561 00:35:03 --> 00:35:06 The binding energies for the products and the reactants 562 00:35:06 --> 00:35:08 aren't in general going to be equal. 563 00:35:08 --> 00:35:13 And in most cases, it is the energetics that dominate 564 00:35:13 --> 00:35:15 the equilibrium constants. 565 00:35:15 --> 00:35:18 Of course, that is, it's the electronic energies 566 00:35:18 --> 00:35:19 that usually dominate. 567 00:35:19 --> 00:35:22 Of course, the other things do matter. 568 00:35:22 --> 00:35:23 But it's not unusual for the electronic 569 00:35:23 --> 00:35:26 energies to dominate. 570 00:35:26 --> 00:35:27 So here's delta G0. 571 00:35:27 --> 00:35:33 Of course, this is minus RT log of Kp. 572 00:35:33 --> 00:35:38 So there's our expression for our equilibrium constants. 573 00:35:38 --> 00:35:41 So it's just this product. 574 00:35:41 --> 00:35:44 So let's just put in the partition functions for 575 00:35:44 --> 00:35:45 the electronic part. 576 00:35:45 --> 00:35:53 It's e to the D0 over kT for molecule AC. 577 00:35:53 --> 00:36:11 Times e to the D0 for molecule BD over kT. 578 00:36:11 --> 00:36:21 Divided by e to the D0 for AB over kT, times e to the D0 579 00:36:21 --> 00:36:25 for molecule CD over kT. 580 00:36:25 --> 00:36:36 So the whole thing is just e to the D0 AC, plus D0 BD minus 581 00:36:36 --> 00:36:49 D0 AB minus D0 CD over kT. 582 00:36:49 --> 00:36:57 Or in other words, it's e to the delta D0 over kT. 583 00:36:57 --> 00:37:00 That's the whole story. 584 00:37:00 --> 00:37:06 So it's a super-simple calculation to execute. 585 00:37:06 --> 00:37:10 And for lots of molecules, we know the dissociation energies. 586 00:37:10 --> 00:37:13 These are measured, determined, either thermochemically or 587 00:37:13 --> 00:37:16 spectroscopically for a great many molecules. 588 00:37:16 --> 00:37:19 So in fact, we have the information we need to 589 00:37:19 --> 00:37:21 do that calculation. 590 00:37:21 --> 00:37:24 And if we want to worry about the vibrational and rotational 591 00:37:24 --> 00:37:26 levels, typically we have that information, too, 592 00:37:26 --> 00:37:28 spectroscopically. 593 00:37:28 --> 00:37:32 So we know what the relevant energy levels are to do 594 00:37:32 --> 00:37:33 the whole calculation. 595 00:37:33 --> 00:37:37 So what it means is, we can calculate equilibrium constants 596 00:37:37 --> 00:37:42 for ordinary chemical reactions just from first principles. 597 00:37:42 --> 00:37:45 Knowing the energy levels of the available states 598 00:37:45 --> 00:37:49 of the molecules. 599 00:37:49 --> 00:37:58 Any questions? 600 00:37:58 --> 00:38:03 In your notes I've included another example. 601 00:38:03 --> 00:38:06 It's a little bit of an extra example. 602 00:38:06 --> 00:38:08 You can go through it if you'd like. 603 00:38:08 --> 00:38:12 It turns out to have a kind of attractive 604 00:38:12 --> 00:38:13 closed form solution. 605 00:38:13 --> 00:38:18 Which is the case of a chemical reaction like an isomerization 606 00:38:18 --> 00:38:21 inside a crystalline solid. 607 00:38:21 --> 00:38:23 So you can imagine you've got a crystal of some molecule, 608 00:38:23 --> 00:38:27 many crystals, thermally over time, they might decompose. 609 00:38:27 --> 00:38:29 They might have reaction processes that can take place. 610 00:38:29 --> 00:38:31 So I've imagined you've got uni-molecular reactions 611 00:38:31 --> 00:38:32 that can occur. 612 00:38:32 --> 00:38:36 And in that case you start with a pure crystal of one species. 613 00:38:36 --> 00:38:37 And you end up with a mixture of some number of the 614 00:38:37 --> 00:38:40 original species, and some number of new species. 615 00:38:40 --> 00:38:42 And there's an equilibrium constant that'll say 616 00:38:42 --> 00:38:44 where that should be. 617 00:38:44 --> 00:38:48 So again, it'll depend on the energies. 618 00:38:48 --> 00:38:52 On the dissociation energies of the different species. 619 00:38:52 --> 00:38:55 And there's also a kind of mixing term, because 620 00:38:55 --> 00:38:59 effectively now you've got the different species located at 621 00:38:59 --> 00:39:00 different places in the crystal. 622 00:39:00 --> 00:39:04 Those are distinguishable states, in the solid. 623 00:39:04 --> 00:39:07 And you need to count those. 624 00:39:07 --> 00:39:13 But the one other example I want to work through is a 625 00:39:13 --> 00:39:15 little bit different from chemical equilibria. 626 00:39:15 --> 00:39:17 It's phase equilibria. 627 00:39:17 --> 00:39:22 Why shouldn't we be able to calculate phase diagrams? 628 00:39:22 --> 00:39:24 So in the earlier part of the course, you went through 629 00:39:24 --> 00:39:28 and saw the macroscopic thermodynamic treatment. 630 00:39:28 --> 00:39:31 The equilibrium constants and chemical equilibria. 631 00:39:31 --> 00:39:34 So of course you saw the whole delta G0 as minus 632 00:39:34 --> 00:39:37 RT log Kp and so forth. 633 00:39:37 --> 00:39:39 And you've seen now we can actually calculate all that 634 00:39:39 --> 00:39:42 from first principles. 635 00:39:42 --> 00:39:43 What about phase equilibria? 636 00:39:43 --> 00:39:47 What you saw before, we just drew phase diagrams. 637 00:39:47 --> 00:39:51 And they had boiling points or lines of boiling. 638 00:39:51 --> 00:39:54 Or in other words, liquid-solid and liquid-gas and 639 00:39:54 --> 00:39:56 solid-gas equilibria. 640 00:39:56 --> 00:40:02 And what we did is, given where those lines fell, 641 00:40:02 --> 00:40:05 you can calculate things. 642 00:40:05 --> 00:40:07 But where do the lines fall? 643 00:40:07 --> 00:40:10 What's the boiling point or the sublimation temperature 644 00:40:10 --> 00:40:13 of some material at a particular pressure? 645 00:40:13 --> 00:40:15 Well, we didn't offer any prescription for 646 00:40:15 --> 00:40:16 calculating that. 647 00:40:16 --> 00:40:19 You had to take that from measurement and then given 648 00:40:19 --> 00:40:22 that, you could use the Clausius-Clapeyron equation and 649 00:40:22 --> 00:40:26 so forth and look at the way things behaved if you moved 650 00:40:26 --> 00:40:28 along a line in a phase diagram. 651 00:40:28 --> 00:40:31 But there was no prescription offered to calculate where 652 00:40:31 --> 00:40:35 exactly would that line be on the phase diagram. 653 00:40:35 --> 00:40:38 But again, if you know all the energies of the possible 654 00:40:38 --> 00:40:43 states, in the solid, in the liquid and the gas, statistical 655 00:40:43 --> 00:40:46 mechanics shows us that we can calculate the equilibrium 656 00:40:46 --> 00:40:46 between those. 657 00:40:46 --> 00:40:49 Which is to say we know we can calculate where 658 00:40:49 --> 00:40:51 those lines belong. 659 00:40:51 --> 00:40:56 So I want to just go through maybe one of a couple of 660 00:40:56 --> 00:40:58 relatively simple cases. 661 00:40:58 --> 00:41:02 I want to go through the case of a solid-solid equilibrium. 662 00:41:02 --> 00:41:05 Let's imagine we have two solid phases and an equilibrium 663 00:41:05 --> 00:41:06 between them. 664 00:41:06 --> 00:41:08 And this problem was on the problem set. 665 00:41:08 --> 00:41:13 How many of you did it? 666 00:41:13 --> 00:41:15 Everybody did it. 667 00:41:15 --> 00:41:19 Did you all get to the end of it? 668 00:41:19 --> 00:41:23 Who got to the end of it? 669 00:41:23 --> 00:41:25 Some of you got to the end of it. 670 00:41:25 --> 00:41:29 If you did, congratulations, it's not so trivial to work 671 00:41:29 --> 00:41:31 on for the first time. 672 00:41:31 --> 00:41:36 So I'll just briefly go through that problem. 673 00:41:36 --> 00:41:37 And show how it works. 674 00:41:37 --> 00:41:43 So, it's similar, of course, to the case that we're doing now. 675 00:41:43 --> 00:41:46 To the case we just did, of chemical equilibria. 676 00:41:46 --> 00:41:49 The difference, though, is that it's cooperative. 677 00:41:49 --> 00:41:56 The solid, at least in the way I formulated that problem, you 678 00:41:56 --> 00:41:59 either have the crystal in phase one or phase alpha, 679 00:41:59 --> 00:41:59 or in phase beta. 680 00:41:59 --> 00:42:02 And there's nothing in between. 681 00:42:02 --> 00:42:03 There are lots of systems like that. 682 00:42:03 --> 00:42:09 Not just crystals, you could go from different forms of DNA. 683 00:42:09 --> 00:42:11 Act like that. 684 00:42:11 --> 00:42:15 Where you have super coiled DNA and regular DNA. 685 00:42:15 --> 00:42:19 And you actually can have some of the DNA in each. 686 00:42:19 --> 00:42:22 But it's actually very cooperative. 687 00:42:22 --> 00:42:26 So there's a huge tendency to either be all in one, 688 00:42:26 --> 00:42:26 or be all in the other. 689 00:42:26 --> 00:42:30 Or at least very very, large pieces of it like that. 690 00:42:30 --> 00:42:32 Lots of other systems act like that. 691 00:42:32 --> 00:42:36 In other words, unlike the case where we're thinking about 692 00:42:36 --> 00:42:39 chemical equilibrium among molecules in the gas phase, 693 00:42:39 --> 00:42:42 these two molecules over here crash into each other 694 00:42:42 --> 00:42:44 and they react. 695 00:42:44 --> 00:42:45 Nothing else cares. 696 00:42:45 --> 00:42:47 The other whole mole of molecules does whatever 697 00:42:47 --> 00:42:48 they were doing. 698 00:42:48 --> 00:42:51 And a little later some other pair of molecules happen to 699 00:42:51 --> 00:42:53 crash into each other and maybe react or maybe don't. 700 00:42:53 --> 00:42:56 In other words, there's no cooperativity at all. 701 00:42:56 --> 00:43:00 What happens to some pair of reactants and products, 702 00:43:00 --> 00:43:03 everything else is completely independent of it. 703 00:43:03 --> 00:43:05 That's not the case when you have, in many cases, 704 00:43:05 --> 00:43:06 a phase transition. 705 00:43:06 --> 00:43:08 You can see it by eye, often. 706 00:43:08 --> 00:43:13 If you do something like super cool water. 707 00:43:13 --> 00:43:14 This is a kind of fun experiment. 708 00:43:14 --> 00:43:18 If you take dry ice, and you've got a little bit of water. 709 00:43:18 --> 00:43:21 Right or a little pot of water. 710 00:43:21 --> 00:43:23 And you put some dry ice into it. 711 00:43:23 --> 00:43:26 So you can actually get the water to be below the 712 00:43:26 --> 00:43:28 freezing temperature and it won't freeze yet. 713 00:43:28 --> 00:43:33 Then you drop a crystal in there and boom, it all freezes. 714 00:43:33 --> 00:43:35 Very cooperatively. 715 00:43:35 --> 00:43:38 Lots of phase transitions behave like that. 716 00:43:38 --> 00:43:52 So let's just see how it works. 717 00:43:52 --> 00:44:04 In this case, it's really similar to what we just did. 718 00:44:04 --> 00:44:09 We can treat it, here's phase alpha. 719 00:44:09 --> 00:44:14 Here's phase beta. 720 00:44:14 --> 00:44:18 And the crystal, the interactions between molecules 721 00:44:18 --> 00:44:21 or the atoms in the crystal are different in the two phases. 722 00:44:21 --> 00:44:23 So effectively, the binding energy is different. 723 00:44:23 --> 00:44:26 In other words, if you say, now let's think of the energy it 724 00:44:26 --> 00:44:29 would take to evaporate all the atoms or molecules and let 725 00:44:29 --> 00:44:31 them loose in the gas phase. 726 00:44:31 --> 00:44:34 That's the analog of dissociation for the molecule. 727 00:44:34 --> 00:44:36 You're pulling everything apart from the crystal 728 00:44:36 --> 00:44:38 and separating them all. 729 00:44:38 --> 00:44:41 So that's what we'll call these energies. 730 00:44:41 --> 00:44:48 This'll be minus E alpha. 731 00:44:48 --> 00:44:55 And this will be minus E beta. 732 00:44:55 --> 00:44:58 And then there are vibrational energies. 733 00:44:58 --> 00:45:02 So the lattice has a bunch of vibrational energies. 734 00:45:02 --> 00:45:05 We can assume they're evenly spaced. 735 00:45:05 --> 00:45:07 And they're going to be different. 736 00:45:07 --> 00:45:10 They're not the same in the two different crystalline forms. 737 00:45:10 --> 00:45:11 That's typically the case. 738 00:45:11 --> 00:45:14 You have a phase transition from one crystal to another. 739 00:45:14 --> 00:45:16 The lattice vibrational frequencies aren't 740 00:45:16 --> 00:45:17 the same any more. 741 00:45:17 --> 00:45:18 Speed of sound is different. 742 00:45:18 --> 00:45:20 Things are different. 743 00:45:20 --> 00:45:21 And that's all. 744 00:45:21 --> 00:45:24 That's the only thing that's different. 745 00:45:24 --> 00:45:40 So these are binding energies per atom. 746 00:45:40 --> 00:45:45 So now, let's just try to calculate Q. 747 00:45:45 --> 00:45:51 And what we are supposed to get out of this is, what's the 748 00:45:51 --> 00:45:52 phase transition temperature? 749 00:45:52 --> 00:45:55 That's the thing that we didn't have any prescription 750 00:45:55 --> 00:45:57 for calculating before. 751 00:45:57 --> 00:45:58 We just said, here it is. 752 00:45:58 --> 00:46:00 Here's the boiling point. 753 00:46:00 --> 00:46:01 Here's the melting point, or whatever the phase 754 00:46:01 --> 00:46:02 transition was. 755 00:46:02 --> 00:46:05 Or if we drew a phase diagram, here's the line. 756 00:46:05 --> 00:46:07 But now we're going to try to calculate where that is. 757 00:46:07 --> 00:46:09 Or what those temperatures are. 758 00:46:09 --> 00:46:16 So, Q for either phase it's just e to the E over kT. 759 00:46:16 --> 00:46:18 Just like we saw before for the dissociation 760 00:46:18 --> 00:46:20 energies of molecules. 761 00:46:20 --> 00:46:22 To the Nth power. 762 00:46:22 --> 00:46:23 No N factorial any more. 763 00:46:23 --> 00:46:26 There's no translation. 764 00:46:26 --> 00:46:28 Times the vibrational part. 765 00:46:28 --> 00:46:32 This is the electronic partition function. 766 00:46:32 --> 00:46:34 And then there's the vibrational part. 767 00:46:34 --> 00:46:40 And that's one over one minus e to the minus h nu, what's 768 00:46:40 --> 00:46:44 called E over kT, for the lattice I'm assuming it's 769 00:46:44 --> 00:46:47 just one frequency. 770 00:46:47 --> 00:46:52 So this energy is h nu E. 771 00:46:52 --> 00:46:57 And of course, it's different for the alpha and beta phases. 772 00:46:57 --> 00:46:59 And I'm going to assume we're in the high temperature limit. 773 00:46:59 --> 00:47:02 Which is often the case for lattice vibrations. 774 00:47:02 --> 00:47:06 So it's e to the, little E over kT. 775 00:47:06 --> 00:47:09 For our electronic part, to the Nth power. 776 00:47:09 --> 00:47:11 And we've seen what the high temperature limit is. 777 00:47:11 --> 00:47:14 It's kT over h nu E. 778 00:47:14 --> 00:47:17 And that's also, that to the 3N power. 779 00:47:17 --> 00:47:19 I should have written this here. 780 00:47:19 --> 00:47:24 In other words if you say, how many vibrations are there in 781 00:47:24 --> 00:47:28 the lattice, well if there are N atoms, each atom in the gas 782 00:47:28 --> 00:47:30 phase would have three degrees of freedom. 783 00:47:30 --> 00:47:32 Translational degrees of freedom. 784 00:47:32 --> 00:47:35 In the crystal, it can't freely translate. 785 00:47:35 --> 00:47:36 But those degrees of freedom are still there. 786 00:47:36 --> 00:47:38 The atoms can all move. 787 00:47:38 --> 00:47:41 So now, those are the lattice vibrations. 788 00:47:41 --> 00:47:42 When the atoms try to move, they vibrate 789 00:47:42 --> 00:47:44 against each other. 790 00:47:44 --> 00:47:47 So how many different modes are there? 791 00:47:47 --> 00:47:48 They may be degenerate. 792 00:47:48 --> 00:47:50 They may all have the same energy. 793 00:47:50 --> 00:47:52 But those modes are all still there. 794 00:47:52 --> 00:47:55 Actually, they're the acoustic modes of the crystal. 795 00:47:55 --> 00:47:58 And there are 3N of them. 796 00:47:58 --> 00:48:01 One for each translational degree or freedom 797 00:48:01 --> 00:48:02 that each atom had. 798 00:48:02 --> 00:48:06 OK, so that's it. 799 00:48:06 --> 00:48:14 A, minus kT log of Q, so it's just minus NE, 800 00:48:14 --> 00:48:16 and the kT cancels. 801 00:48:16 --> 00:48:28 Minus 3NkT log of kT over h nu E. 802 00:48:28 --> 00:48:29 Second part. 803 00:48:29 --> 00:48:33 And then we can calculate the chemical potential. 804 00:48:33 --> 00:48:40 It's just the dA/dN, d constant T and V. 805 00:48:40 --> 00:48:41 So this goes away. 806 00:48:41 --> 00:48:43 It's just minus little E. 807 00:48:43 --> 00:48:52 This goes away, it's minus 3kT log of kT over h nu E. 808 00:48:52 --> 00:48:55 Well, basically we just finished. 809 00:48:55 --> 00:48:58 At the phase transition temperature for the two phases, 810 00:48:58 --> 00:49:02 those things have to be equal. 811 00:49:02 --> 00:49:03 And that's all there is to it. 812 00:49:03 --> 00:49:18 So, at, we'll call it Tc, the phase transition temperature, I 813 00:49:18 --> 00:49:26 guess I called it T1 here, mu alpha is equal to mu beta. 814 00:49:26 --> 00:49:30 So this stuff for alpha is equal to this for beta. 815 00:49:30 --> 00:49:32 That's it. 816 00:49:32 --> 00:49:33 So what does it say? 817 00:49:33 --> 00:49:44 It says E beta minus E alpha, these terms, equals 3kT1 log 818 00:49:44 --> 00:49:50 of nu E beta over nu E alpha. 819 00:49:50 --> 00:49:52 Solve for T1. 820 00:49:52 --> 00:49:54 That's it. 821 00:49:54 --> 00:50:03 It's E beta minus E alpha over 3k log nu E beta 822 00:50:03 --> 00:50:06 over nu E alpha. 823 00:50:06 --> 00:50:09 There is our phase transition temperature. 824 00:50:09 --> 00:50:11 That's the whole story. 825 00:50:11 --> 00:50:15 So if we know the electronic energy that binds the crystal 826 00:50:15 --> 00:50:18 together, usually something that can be measured easily, so 827 00:50:18 --> 00:50:21 it's known for many materials. 828 00:50:21 --> 00:50:23 And if we know the lattice vibrational frequency. 829 00:50:23 --> 00:50:29 Also something that's pretty routinely measured, we're done. 830 00:50:29 --> 00:50:34 So again, from a very simple first principles approach, we 831 00:50:34 --> 00:50:38 can calculate that phase transition temperature. 832 00:50:38 --> 00:50:42 We could do it for a solid-gas equilibria too, if we said OK, 833 00:50:42 --> 00:50:45 let's think of sublimation of the solid. 834 00:50:45 --> 00:50:48 And now we know how to calculate the chemical 835 00:50:48 --> 00:50:50 potential in the gas phase. 836 00:50:50 --> 00:50:51 We can have those be equal. 837 00:50:51 --> 00:50:53 That's actually worked through in your notes. 838 00:50:53 --> 00:50:55 Again, it's an extra problem. 839 00:50:55 --> 00:50:57 If you would like to take a look at it, it's a 840 00:50:57 --> 00:50:59 straightforward calculation. 841 00:50:59 --> 00:51:02 The point is, we can calculate those phase equilibria. 842 00:51:02 --> 00:51:03 Liquids, I will say, are harder. 843 00:51:03 --> 00:51:05 Just because it's harder to define and know all the 844 00:51:05 --> 00:51:07 energies available. 845 00:51:07 --> 00:51:10 Doable, approximately. 846 00:51:10 --> 00:51:13 But the point is, we can actually now locate all 847 00:51:13 --> 00:51:16 those lines that we sort of arbitrarily drew on 848 00:51:16 --> 00:51:17 the phase diagrams. 849 00:51:17 --> 00:51:21 And make sense of what the temperatures and what the 850 00:51:21 --> 00:51:26 pressures are, for that matter, where they occur. 851 00:51:26 --> 00:51:27 Any questions? 852 00:51:27 --> 00:51:30