WEBVTT

00:00:00.000 --> 00:00:02.640 align:middle line:84%
The following content is
provided under a Creative

00:00:02.640 --> 00:00:04.000 align:middle line:90%
Commons license.

00:00:04.000 --> 00:00:06.400 align:middle line:84%
Your support will help
MIT OpenCourseWare

00:00:06.400 --> 00:00:10.080 align:middle line:84%
continue to offer high quality
educational resources for free.

00:00:10.080 --> 00:00:13.320 align:middle line:84%
To make a donation or
view additional materials

00:00:13.320 --> 00:00:17.280 align:middle line:84%
from hundreds of MIT courses,
visit MIT OpenCourseWare

00:00:17.280 --> 00:00:21.000 align:middle line:90%
at ocw.mit.edu.

00:00:21.000 --> 00:00:22.660 align:middle line:84%
PROFESSOR: So for
the next two days,

00:00:22.660 --> 00:00:25.680 align:middle line:84%
I'm going to talk about
marine sediments, which

00:00:25.680 --> 00:00:27.680 align:middle line:90%
is the field that I work in.

00:00:27.680 --> 00:00:33.680 align:middle line:84%
And I think of it as a forgotten
corner of chemical oceanography.

00:00:33.680 --> 00:00:37.640 align:middle line:84%
And so I start out these two
lectures admitting right off

00:00:37.640 --> 00:00:39.160 align:middle line:84%
that I'm not going
to make anybody

00:00:39.160 --> 00:00:41.620 align:middle line:84%
a sediment geochemist
in two lectures.

00:00:41.620 --> 00:00:43.840 align:middle line:90%
So I have two real simple goals.

00:00:43.840 --> 00:00:47.200 align:middle line:84%
The first one is
to make sure you

00:00:47.200 --> 00:00:50.920 align:middle line:84%
remember that the ocean
does have a bottom--

00:00:50.920 --> 00:00:55.560 align:middle line:84%
JGOFS aside, where they
eliminated the sea floor--

00:00:55.560 --> 00:00:57.560 align:middle line:84%
there really is a
bottom to the ocean.

00:00:57.560 --> 00:01:02.553 align:middle line:84%
And second is that it has
some important effects,

00:01:02.553 --> 00:01:04.470 align:middle line:84%
that reactions in the
surface of the sediments

00:01:04.470 --> 00:01:05.650 align:middle line:90%
have some important effects.

00:01:05.650 --> 00:01:07.710 align:middle line:84%
And I'd like you to look
at surface sediments

00:01:07.710 --> 00:01:10.925 align:middle line:84%
in the same way you look
at the air/sea boundary

00:01:10.925 --> 00:01:12.550 align:middle line:84%
as the interface
between the atmosphere

00:01:12.550 --> 00:01:15.410 align:middle line:84%
is the ocean, same way
as you look at estuaries

00:01:15.410 --> 00:01:17.870 align:middle line:84%
as the interface between
rivers and the ocean,

00:01:17.870 --> 00:01:20.710 align:middle line:84%
or as hydrothermal vent
systems as the interface

00:01:20.710 --> 00:01:22.590 align:middle line:84%
between the deep
Earth and the ocean.

00:01:22.590 --> 00:01:24.510 align:middle line:84%
The sediments are the
interface between--

00:01:24.510 --> 00:01:27.510 align:middle line:84%
the sediment-water interface is
the interface between the water

00:01:27.510 --> 00:01:30.890 align:middle line:84%
column and the
accumulating sediments.

00:01:30.890 --> 00:01:34.530 align:middle line:84%
So with that in mind
I'm going to ask,

00:01:34.530 --> 00:01:36.330 align:middle line:84%
why would we study
this part of the ocean?

00:01:36.330 --> 00:01:38.122 align:middle line:84%
After all, the ocean
is a huge thing that's

00:01:38.122 --> 00:01:39.750 align:middle line:90%
several kilometers thick.

00:01:39.750 --> 00:01:44.430 align:middle line:84%
And the region that I focus on
is about 10 to 20 centimeters

00:01:44.430 --> 00:01:45.010 align:middle line:90%
thick.

00:01:45.010 --> 00:01:46.990 align:middle line:90%
So it's a very small piece.

00:01:46.990 --> 00:01:49.030 align:middle line:90%
But it does have some--

00:01:49.030 --> 00:01:50.610 align:middle line:84%
the reactions there
are important.

00:01:50.610 --> 00:01:53.290 align:middle line:84%
And if we look at it in
the way I've shown here,

00:01:53.290 --> 00:01:54.750 align:middle line:84%
where the inputs
for the reactions

00:01:54.750 --> 00:01:57.030 align:middle line:84%
are the particle flux
to the sea floor,

00:01:57.030 --> 00:01:59.050 align:middle line:84%
you can think of the
surface of the sediments

00:01:59.050 --> 00:02:02.370 align:middle line:84%
as being a layer in
which reactions occur.

00:02:02.370 --> 00:02:03.810 align:middle line:84%
Those reactions
can have a couple

00:02:03.810 --> 00:02:05.570 align:middle line:90%
of important consequences.

00:02:05.570 --> 00:02:08.970 align:middle line:84%
The first is that
they both use up

00:02:08.970 --> 00:02:11.410 align:middle line:84%
solutes that are
present in bottom water.

00:02:11.410 --> 00:02:15.210 align:middle line:84%
And they produce solutes that
can be returned to bottom water.

00:02:15.210 --> 00:02:17.450 align:middle line:84%
So that solute exchange
between the surface

00:02:17.450 --> 00:02:21.550 align:middle line:84%
of the sediments and the deep
ocean, and the water column,

00:02:21.550 --> 00:02:24.010 align:middle line:84%
be it deep or coastal ocean,
can have important effects

00:02:24.010 --> 00:02:26.490 align:middle line:90%
on ocean chemistry.

00:02:26.490 --> 00:02:29.130 align:middle line:84%
The second way it
matters is that, say

00:02:29.130 --> 00:02:31.087 align:middle line:84%
you're a paleoceanographer,
and you're

00:02:31.087 --> 00:02:33.170 align:middle line:84%
interested in studying the
record that's preserved

00:02:33.170 --> 00:02:34.970 align:middle line:90%
in accumulating sediments.

00:02:34.970 --> 00:02:37.770 align:middle line:84%
Well, then the particle
flux to the sea floor

00:02:37.770 --> 00:02:41.330 align:middle line:84%
has to pass through this
layer where lots of reactions

00:02:41.330 --> 00:02:45.090 align:middle line:84%
occur before those
particles become part

00:02:45.090 --> 00:02:46.890 align:middle line:90%
of the accumulating sediments.

00:02:46.890 --> 00:02:49.090 align:middle line:84%
And as we'll see,
the composition

00:02:49.090 --> 00:02:51.050 align:middle line:84%
of accumulating
sediments is very

00:02:51.050 --> 00:02:53.490 align:middle line:84%
different from the composition
of the particle flux

00:02:53.490 --> 00:02:54.745 align:middle line:90%
to the sea floor.

00:02:54.745 --> 00:02:56.370 align:middle line:84%
So if you're interested
in interpreting

00:02:56.370 --> 00:02:59.280 align:middle line:84%
the sedimentary
record, it's important

00:02:59.280 --> 00:03:02.320 align:middle line:84%
not to forget that there's this
layer at the sediment surface

00:03:02.320 --> 00:03:04.140 align:middle line:84%
that the particles
have to pass through.

00:03:04.140 --> 00:03:08.756 align:middle line:90%


00:03:08.756 --> 00:03:14.000 align:middle line:84%
So with that little preamble
in mind, we're going to start--

00:03:14.000 --> 00:03:16.080 align:middle line:84%
which I hope ties
in with what you've

00:03:16.080 --> 00:03:20.360 align:middle line:84%
been doing up to this point--
with a brief discussion

00:03:20.360 --> 00:03:23.960 align:middle line:84%
of the composition of the
particle flux to the sea floor.

00:03:23.960 --> 00:03:27.580 align:middle line:84%
After that, we'll talk
about the preservation--

00:03:27.580 --> 00:03:29.680 align:middle line:84%
we're going to focus on
the biogenic components

00:03:29.680 --> 00:03:31.200 align:middle line:90%
of the particle flux.

00:03:31.200 --> 00:03:34.120 align:middle line:84%
After that, we'll talk
about the preservation rates

00:03:34.120 --> 00:03:38.840 align:middle line:84%
in a general way of biogenic
components of the particle flux.

00:03:38.840 --> 00:03:40.680 align:middle line:84%
Once we've done
that, I'll remind you

00:03:40.680 --> 00:03:43.600 align:middle line:84%
of a couple of the consequences
of early diagenesis, which

00:03:43.600 --> 00:03:45.800 align:middle line:84%
we're not going to talk
about in any detail,

00:03:45.800 --> 00:03:50.960 align:middle line:84%
but I stick them in here as
a motivation for the things

00:03:50.960 --> 00:03:52.640 align:middle line:90%
I'm going to talk about later.

00:03:52.640 --> 00:03:54.740 align:middle line:84%
And after we get
through those preambles,

00:03:54.740 --> 00:03:57.240 align:middle line:84%
we're going to get a
little bit more specific,

00:03:57.240 --> 00:04:00.740 align:middle line:84%
and I'll talk in
turn about reactions

00:04:00.740 --> 00:04:03.820 align:middle line:84%
that organic matter undergoes
in the surface sediments.

00:04:03.820 --> 00:04:05.580 align:middle line:84%
That will take up
the rest of today.

00:04:05.580 --> 00:04:07.620 align:middle line:84%
Then in the lecture
on Tuesday, I'll

00:04:07.620 --> 00:04:11.620 align:middle line:84%
talk about calcium carbonate and
biogenic silica, the other two

00:04:11.620 --> 00:04:14.123 align:middle line:84%
biogenic components
of the particle flux.

00:04:14.123 --> 00:04:15.540 align:middle line:84%
And for each of
those, we'll first

00:04:15.540 --> 00:04:19.860 align:middle line:84%
talk about mechanism for
decomposition or dissolution

00:04:19.860 --> 00:04:20.980 align:middle line:90%
of the phase.

00:04:20.980 --> 00:04:26.060 align:middle line:84%
And then we'll talk about
what sort of measurements

00:04:26.060 --> 00:04:27.980 align:middle line:84%
we make to quantify
the reactions

00:04:27.980 --> 00:04:31.640 align:middle line:84%
and to support our
descriptions of the mechanisms.

00:04:31.640 --> 00:04:34.480 align:middle line:90%


00:04:34.480 --> 00:04:37.180 align:middle line:84%
So first, the particle
flux to the sea floor.

00:04:37.180 --> 00:04:42.900 align:middle line:84%
And this is just a
very brief overview.

00:04:42.900 --> 00:04:46.420 align:middle line:84%
On the left-hand side, these
are all-- on the left-hand side

00:04:46.420 --> 00:04:51.060 align:middle line:84%
are fluxes calculated
from sediment trap data

00:04:51.060 --> 00:04:54.330 align:middle line:84%
in milligrams per
meter squared per day.

00:04:54.330 --> 00:04:58.730 align:middle line:84%
On the very left-hand side
is the total mass flux.

00:04:58.730 --> 00:05:01.170 align:middle line:84%
And this range of
total mass fluxes

00:05:01.170 --> 00:05:06.610 align:middle line:84%
from about 50 to 250
milligrams of material

00:05:06.610 --> 00:05:08.770 align:middle line:84%
per square meter of
sediment surface per day

00:05:08.770 --> 00:05:10.370 align:middle line:84%
is about representative
of what you'll

00:05:10.370 --> 00:05:14.016 align:middle line:90%
see over most of the ocean.

00:05:14.016 --> 00:05:17.530 align:middle line:84%
To the right of that,
the flux is broken down

00:05:17.530 --> 00:05:18.670 align:middle line:90%
into four components.

00:05:18.670 --> 00:05:21.150 align:middle line:84%
The first three, calcium
carbonate, organic matter,

00:05:21.150 --> 00:05:24.450 align:middle line:84%
and opal are the biogenic
components of the particle flux.

00:05:24.450 --> 00:05:27.810 align:middle line:84%
And the fourth one on the far
right-hand side in this picture

00:05:27.810 --> 00:05:30.090 align:middle line:90%
is the lithogenic component.

00:05:30.090 --> 00:05:33.170 align:middle line:84%
So that's the
terrestrial material,

00:05:33.170 --> 00:05:37.290 align:middle line:84%
which has a lithogenic origin,
that falls to the sea floor.

00:05:37.290 --> 00:05:40.050 align:middle line:84%
I want you to notice
a couple of things.

00:05:40.050 --> 00:05:45.065 align:middle line:84%
First, in the Atlantic Ocean,
which is the top-- well,

00:05:45.065 --> 00:05:47.690 align:middle line:84%
before I get into that, on the
right-hand side is the same data

00:05:47.690 --> 00:05:50.910 align:middle line:84%
but plotted in
composition terms.

00:05:50.910 --> 00:05:54.070 align:middle line:84%
So it as weight percent of
the different components

00:05:54.070 --> 00:05:56.950 align:middle line:90%
of the flux.

00:05:56.950 --> 00:06:01.910 align:middle line:84%
So if we look now at the
right-hand side, the thing--

00:06:01.910 --> 00:06:04.030 align:middle line:84%
first, if you compare
the Atlantic Ocean

00:06:04.030 --> 00:06:06.130 align:middle line:84%
to the central
equatorial Pacific Ocean,

00:06:06.130 --> 00:06:09.327 align:middle line:84%
you can see that the lithogenic
component of the flux

00:06:09.327 --> 00:06:10.910 align:middle line:84%
is much more important
in the Atlantic

00:06:10.910 --> 00:06:13.630 align:middle line:84%
Ocean than the Pacific,
which is what you'd expect,

00:06:13.630 --> 00:06:16.350 align:middle line:84%
because the central equatorial
Pacific is far removed

00:06:16.350 --> 00:06:20.190 align:middle line:84%
from any continental
sources of material.

00:06:20.190 --> 00:06:24.190 align:middle line:84%
Again, looking at the
lithogenic component,

00:06:24.190 --> 00:06:27.650 align:middle line:84%
you'll see that this one marked
eastern equatorial Atlantic,

00:06:27.650 --> 00:06:30.242 align:middle line:84%
the lithogenic component is
considerably bigger than the one

00:06:30.242 --> 00:06:31.450 align:middle line:90%
that's marked North Atlantic.

00:06:31.450 --> 00:06:36.150 align:middle line:84%
That's because this eastern
equatorial Atlantic site is just

00:06:36.150 --> 00:06:38.470 align:middle line:90%
west of the Sahara desert.

00:06:38.470 --> 00:06:42.990 align:middle line:84%
And so there is a lot of input
of Saharan dust at this site.

00:06:42.990 --> 00:06:45.950 align:middle line:84%
And so the general
take-home message

00:06:45.950 --> 00:06:47.695 align:middle line:84%
is that lithogenic
components of the flux

00:06:47.695 --> 00:06:49.070 align:middle line:84%
are more important
the closer you

00:06:49.070 --> 00:06:52.460 align:middle line:84%
are to the continental sources
of the lithogenic material.

00:06:52.460 --> 00:06:54.980 align:middle line:84%
The second thing to
notice from all of this

00:06:54.980 --> 00:06:57.940 align:middle line:84%
is that in the deep
ocean, the majority

00:06:57.940 --> 00:07:00.260 align:middle line:84%
of the flux of particles
to the seafloor

00:07:00.260 --> 00:07:03.100 align:middle line:84%
is made up of biogenic
components of the flux.

00:07:03.100 --> 00:07:09.100 align:middle line:84%
And on a mass basis, the
most important component

00:07:09.100 --> 00:07:14.380 align:middle line:84%
of the biogenic flux
is calcium carbonate.

00:07:14.380 --> 00:07:17.060 align:middle line:84%
Where calcium carbonate
in these three examples

00:07:17.060 --> 00:07:22.620 align:middle line:84%
makes up 50% to 60% of the
mass flux to the seafloor,

00:07:22.620 --> 00:07:25.320 align:middle line:84%
organic matter and
biogenic silica are opal.

00:07:25.320 --> 00:07:29.240 align:middle line:84%
Each make up about 10%,
or a little bit more.

00:07:29.240 --> 00:07:35.660 align:middle line:90%


00:07:35.660 --> 00:07:39.460 align:middle line:84%
But I want to show you
one more set of data.

00:07:39.460 --> 00:07:42.380 align:middle line:84%
And the reason to show you this
is so that you don't go away

00:07:42.380 --> 00:07:44.240 align:middle line:84%
thinking that
everywhere in the ocean,

00:07:44.240 --> 00:07:46.060 align:middle line:84%
calcium carbonate is
the dominant component

00:07:46.060 --> 00:07:48.180 align:middle line:84%
of the particle flux
to the seafloor.

00:07:48.180 --> 00:07:52.170 align:middle line:84%
And the counterexample
is in the Southern Ocean,

00:07:52.170 --> 00:07:53.730 align:middle line:84%
where you may have
studied already

00:07:53.730 --> 00:07:56.290 align:middle line:84%
that south of the
polar front, going

00:07:56.290 --> 00:07:59.890 align:middle line:84%
towards the Antarctic
continent, surface

00:07:59.890 --> 00:08:03.070 align:middle line:84%
ocean productivity is dominated
by diatom productivity.

00:08:03.070 --> 00:08:07.970 align:middle line:84%
And as a result of that, close
to the Antarctic continent,

00:08:07.970 --> 00:08:09.690 align:middle line:84%
the flux to the sea
floor is dominated

00:08:09.690 --> 00:08:12.850 align:middle line:84%
not by calcium carbonate,
but by biogenic silica.

00:08:12.850 --> 00:08:15.610 align:middle line:84%
And what I've shown
here are some data

00:08:15.610 --> 00:08:20.630 align:middle line:84%
collected by Sus Honjo
on the AESOPS transect,

00:08:20.630 --> 00:08:23.570 align:middle line:84%
which went along
170 degrees west

00:08:23.570 --> 00:08:27.250 align:middle line:84%
from the Antarctic continent,
across the polar front,

00:08:27.250 --> 00:08:30.330 align:middle line:84%
and north into the
part of the Southern

00:08:30.330 --> 00:08:32.210 align:middle line:84%
Ocean that's north
of the polar front.

00:08:32.210 --> 00:08:37.610 align:middle line:84%
And this site, MS-5
here, corresponds

00:08:37.610 --> 00:08:40.070 align:middle line:84%
to this left-hand
point on the graph.

00:08:40.070 --> 00:08:41.450 align:middle line:90%
It's south of the polar front.

00:08:41.450 --> 00:08:43.289 align:middle line:84%
And you can see that
in this graph, which

00:08:43.289 --> 00:08:48.170 align:middle line:84%
shows the components of the
particle flux to the sea floor,

00:08:48.170 --> 00:08:50.810 align:middle line:84%
it's greatly dominated
by biogenic silica.

00:08:50.810 --> 00:08:53.510 align:middle line:84%
But as you move further
north, and eventually cross

00:08:53.510 --> 00:08:56.070 align:middle line:84%
the polar front,
the biogenic silica

00:08:56.070 --> 00:08:58.890 align:middle line:84%
is essentially displaced
by calcium carbonate.

00:08:58.890 --> 00:09:01.470 align:middle line:84%
And calcium carbonate becomes
the dominant component,

00:09:01.470 --> 00:09:04.190 align:middle line:84%
as it is over much
of the sea floor.

00:09:04.190 --> 00:09:07.550 align:middle line:84%
So the main messages
from this are

00:09:07.550 --> 00:09:13.110 align:middle line:84%
that in the deep ocean,
away from the continents,

00:09:13.110 --> 00:09:15.350 align:middle line:84%
the majority of the
flux to the seafloor

00:09:15.350 --> 00:09:17.390 align:middle line:84%
is made up of
biogenic materials.

00:09:17.390 --> 00:09:20.550 align:middle line:84%
And that over much of the
ocean, with the exception

00:09:20.550 --> 00:09:23.150 align:middle line:84%
of the Southern Ocean,
the dominant component

00:09:23.150 --> 00:09:26.230 align:middle line:84%
of the biogenic flux to the
seafloor on a mass basis

00:09:26.230 --> 00:09:29.090 align:middle line:90%
is calcium carbonate.

00:09:29.090 --> 00:09:33.830 align:middle line:84%
So I'm just going to summarize
here the preservation

00:09:33.830 --> 00:09:35.290 align:middle line:90%
rates of biogenic components.

00:09:35.290 --> 00:09:38.790 align:middle line:84%
So if you go around and
measure the accumulation

00:09:38.790 --> 00:09:41.490 align:middle line:84%
rate of biogenic
components in sediments,

00:09:41.490 --> 00:09:45.270 align:middle line:84%
and compare that to the rain
rate to the seafloor and divide

00:09:45.270 --> 00:09:46.550 align:middle line:90%
the--

00:09:46.550 --> 00:09:49.740 align:middle line:84%
well, then you can use those
two measurements to calculate

00:09:49.740 --> 00:09:52.700 align:middle line:84%
what fraction of the flux to the
sea floor for a given component

00:09:52.700 --> 00:09:55.220 align:middle line:84%
is recycled, and what
fraction is actually

00:09:55.220 --> 00:09:56.720 align:middle line:90%
buried in the sediments.

00:09:56.720 --> 00:10:03.180 align:middle line:84%
And what you find is that for
organic matter in the deep sea,

00:10:03.180 --> 00:10:08.140 align:middle line:84%
preservation rates are always
less than 3%, and in many cases,

00:10:08.140 --> 00:10:09.620 align:middle line:90%
are 1%.

00:10:09.620 --> 00:10:12.740 align:middle line:84%
So the organic matter that
falls to the sea floor

00:10:12.740 --> 00:10:15.560 align:middle line:90%
is almost all remineralized.

00:10:15.560 --> 00:10:19.820 align:middle line:84%
It's almost all recycled, with
the carbon returned to the water

00:10:19.820 --> 00:10:21.020 align:middle line:90%
column as CO2.

00:10:21.020 --> 00:10:25.180 align:middle line:90%


00:10:25.180 --> 00:10:28.820 align:middle line:84%
Sticking with organic
matter for a minute,

00:10:28.820 --> 00:10:32.820 align:middle line:84%
the fraction recycled can
become somewhat smaller

00:10:32.820 --> 00:10:35.380 align:middle line:84%
on continent and continental
margin sediments,

00:10:35.380 --> 00:10:38.540 align:middle line:84%
where the burial
rates are faster.

00:10:38.540 --> 00:10:45.300 align:middle line:84%
But in most instances,
the recycling rates still

00:10:45.300 --> 00:10:48.700 align:middle line:84%
are up in the 90% range,
but in some cases,

00:10:48.700 --> 00:10:51.920 align:middle line:84%
which are pretty rare, they can
be less than-- the recycling

00:10:51.920 --> 00:10:54.000 align:middle line:90%
rate can be less than 50%.

00:10:54.000 --> 00:10:56.058 align:middle line:84%
But the overall message
still stays the same,

00:10:56.058 --> 00:10:57.600 align:middle line:84%
is that almost all
the organic matter

00:10:57.600 --> 00:11:00.480 align:middle line:84%
that falls to the seafloor
is recycled rather than being

00:11:00.480 --> 00:11:02.360 align:middle line:90%
preserved in the sediments.

00:11:02.360 --> 00:11:06.400 align:middle line:84%
For calcium carbonate, as
we'll talk about on Tuesday,

00:11:06.400 --> 00:11:08.780 align:middle line:84%
the picture is a little
more complicated,

00:11:08.780 --> 00:11:14.320 align:middle line:84%
where there's a depth
in the ocean above which

00:11:14.320 --> 00:11:16.780 align:middle line:84%
the predominant calcium
carbonate mineral in the ocean,

00:11:16.780 --> 00:11:18.920 align:middle line:90%
which is calcite, is preserved.

00:11:18.920 --> 00:11:23.360 align:middle line:84%
And below that depth, the water
is undersaturated with respect

00:11:23.360 --> 00:11:24.340 align:middle line:90%
to calcite.

00:11:24.340 --> 00:11:26.080 align:middle line:84%
And at those depths,
calcium carbonate

00:11:26.080 --> 00:11:28.640 align:middle line:90%
tends to be remineralized.

00:11:28.640 --> 00:11:31.640 align:middle line:84%
And that depth is called the
calcite saturation horizon.

00:11:31.640 --> 00:11:33.900 align:middle line:84%
So above the calcite
saturation horizon,

00:11:33.900 --> 00:11:36.720 align:middle line:84%
preservation rates of calcium
carbonate in the sediment

00:11:36.720 --> 00:11:40.440 align:middle line:84%
range from about 30% to 90% of
the flux of calcium carbonate

00:11:40.440 --> 00:11:41.800 align:middle line:90%
to the seafloor.

00:11:41.800 --> 00:11:45.060 align:middle line:84%
Below the calcite saturation
horizon, as you might expect,

00:11:45.060 --> 00:11:48.990 align:middle line:84%
the preservation
rate drops to zero.

00:11:48.990 --> 00:11:50.770 align:middle line:84%
So that's a picture
for calcium carbonate.

00:11:50.770 --> 00:11:55.350 align:middle line:84%
For biogenic silica, the
median preservation rate

00:11:55.350 --> 00:11:58.070 align:middle line:84%
throughout the oceans-- so
if you compare the burial

00:11:58.070 --> 00:12:02.390 align:middle line:84%
rate to the flux to the sea
floor-- is only about 10%.

00:12:02.390 --> 00:12:05.250 align:middle line:84%
In 80% of the areas where
mass balances have been made,

00:12:05.250 --> 00:12:08.470 align:middle line:84%
the preservation rate
is less than 15%.

00:12:08.470 --> 00:12:12.990 align:middle line:84%
And so throughout the
oceans, the preservation rate

00:12:12.990 --> 00:12:15.190 align:middle line:90%
of biogenic silica is very low.

00:12:15.190 --> 00:12:19.030 align:middle line:84%
And so the recycling
rate is very high.

00:12:19.030 --> 00:12:22.870 align:middle line:84%
And so the overall
message here is

00:12:22.870 --> 00:12:26.390 align:middle line:84%
that the biogenic components
of the flux to the sea floor

00:12:26.390 --> 00:12:30.590 align:middle line:84%
are, to a large
extent, recycled back.

00:12:30.590 --> 00:12:33.110 align:middle line:84%
So only a relatively
small fraction

00:12:33.110 --> 00:12:36.230 align:middle line:84%
of the biogenic flux of
particles to the sea floor

00:12:36.230 --> 00:12:39.470 align:middle line:90%
is preserved in the sediments.

00:12:39.470 --> 00:12:43.430 align:middle line:84%
Now, I have one
specific example,

00:12:43.430 --> 00:12:45.210 align:middle line:84%
just to show the
sorts of measurements

00:12:45.210 --> 00:12:48.170 align:middle line:84%
that are made to make these
mass balance calculations.

00:12:48.170 --> 00:12:50.010 align:middle line:84%
And this is from
a study that was

00:12:50.010 --> 00:12:53.930 align:middle line:84%
part of the JGOFS project in
the central equatorial Pacific.

00:12:53.930 --> 00:12:57.850 align:middle line:84%
And as part of this study, they
measured sediment accumulation

00:12:57.850 --> 00:13:02.610 align:middle line:84%
rates and the accumulation
rate of biogenic components

00:13:02.610 --> 00:13:04.490 align:middle line:90%
of the sediments.

00:13:04.490 --> 00:13:07.530 align:middle line:84%
They also measured
remineralization rates

00:13:07.530 --> 00:13:12.090 align:middle line:84%
by measuring fluxes of
dissolved reactants and products

00:13:12.090 --> 00:13:14.570 align:middle line:84%
of decomposition and
dissolution reactions

00:13:14.570 --> 00:13:16.850 align:middle line:84%
across the
sediment-water interface.

00:13:16.850 --> 00:13:19.890 align:middle line:84%
So for instance, if calcium
carbonate is dissolved,

00:13:19.890 --> 00:13:22.530 align:middle line:84%
that results in a flux of
CO2 out of the sediments

00:13:22.530 --> 00:13:23.670 align:middle line:90%
into the water column.

00:13:23.670 --> 00:13:25.410 align:middle line:84%
So if you measure
that flux, you can

00:13:25.410 --> 00:13:28.610 align:middle line:84%
calculate the rate of recycling
of the calcium carbonate

00:13:28.610 --> 00:13:29.490 align:middle line:90%
at the seafloor.

00:13:29.490 --> 00:13:32.130 align:middle line:84%
And the same sorts of arguments
go for biogenic silica

00:13:32.130 --> 00:13:33.410 align:middle line:90%
and organic matter.

00:13:33.410 --> 00:13:36.830 align:middle line:84%
So you can measure burial,
remineralization rate,

00:13:36.830 --> 00:13:38.970 align:middle line:84%
and they also measured the
rain rates of particles

00:13:38.970 --> 00:13:42.170 align:middle line:84%
to the seafloor
using sediment traps.

00:13:42.170 --> 00:13:45.480 align:middle line:84%
So if the system's in
steady state, where

00:13:45.480 --> 00:13:48.040 align:middle line:84%
the input to the
sea floor equals

00:13:48.040 --> 00:13:52.040 align:middle line:84%
the sum of the remineralization
rate and the burial rate,

00:13:52.040 --> 00:13:54.920 align:middle line:84%
then the remineralization
rate plus the burial rate

00:13:54.920 --> 00:13:57.592 align:middle line:84%
should be equal to the
rain rate to the sea floor,

00:13:57.592 --> 00:13:59.800 align:middle line:84%
because only when that's
true will the concentrations

00:13:59.800 --> 00:14:01.633 align:middle line:84%
in the sediments-- or
the accumulation rates

00:14:01.633 --> 00:14:03.160 align:middle line:90%
in the sediments be constant.

00:14:03.160 --> 00:14:08.560 align:middle line:84%
AUDIENCE: So how do you
measure like a carbonate flux

00:14:08.560 --> 00:14:10.040 align:middle line:90%
in the sediments?

00:14:10.040 --> 00:14:10.560 align:middle line:90%
Just--

00:14:10.560 --> 00:14:12.300 align:middle line:90%
PROFESSOR: Which flux?

00:14:12.300 --> 00:14:13.280 align:middle line:90%
The burial rate or--

00:14:13.280 --> 00:14:15.560 align:middle line:84%
AUDIENCE: Now, how do you--
the remineralization rate.

00:14:15.560 --> 00:14:18.420 align:middle line:84%
PROFESSOR: It's a
little bit complicated.

00:14:18.420 --> 00:14:20.638 align:middle line:84%
What you would do
is measure the--

00:14:20.638 --> 00:14:22.180 align:middle line:84%
there's a few things
you can measure.

00:14:22.180 --> 00:14:23.620 align:middle line:84%
We'll actually talk
about this more later.

00:14:23.620 --> 00:14:23.960 align:middle line:90%
AUDIENCE: Oh, OK.

00:14:23.960 --> 00:14:24.627 align:middle line:90%
No, that's fine.

00:14:24.627 --> 00:14:28.320 align:middle line:84%
PROFESSOR: But just when
calcium carbonate dissolves,

00:14:28.320 --> 00:14:31.640 align:middle line:84%
it releases total CO2 into
the water and alkalinity

00:14:31.640 --> 00:14:32.720 align:middle line:90%
into the water.

00:14:32.720 --> 00:14:36.400 align:middle line:84%
You can measure the flux of
those two across the interface

00:14:36.400 --> 00:14:39.680 align:middle line:84%
and calculate the dissolution
rate of calcium carbonate

00:14:39.680 --> 00:14:40.720 align:middle line:90%
in the sediments.

00:14:40.720 --> 00:14:43.130 align:middle line:84%
We'll talk about
that more on Tuesday.

00:14:43.130 --> 00:14:46.796 align:middle line:90%


00:14:46.796 --> 00:14:50.150 align:middle line:84%
And so these guys, this
group of investigators,

00:14:50.150 --> 00:14:52.870 align:middle line:84%
measured burial rates
for organic carbon

00:14:52.870 --> 00:14:57.470 align:middle line:84%
in the black, calcium
carbonate in the hatched bars,

00:14:57.470 --> 00:15:00.390 align:middle line:84%
and opal in the--
or biogenic silica

00:15:00.390 --> 00:15:04.190 align:middle line:90%
in the unfilled bars here.

00:15:04.190 --> 00:15:06.430 align:middle line:84%
For burial rates, the burial
rate of organic carbon

00:15:06.430 --> 00:15:09.030 align:middle line:84%
was so small that it doesn't
show up on this scale.

00:15:09.030 --> 00:15:12.670 align:middle line:84%
And so what they did was they
had separate measurements

00:15:12.670 --> 00:15:14.870 align:middle line:84%
of burial,
remineralization, and rain,

00:15:14.870 --> 00:15:18.750 align:middle line:84%
and they added together the
burial and the remineralization

00:15:18.750 --> 00:15:22.110 align:middle line:84%
rate, and said in steady state,
that should equal the rain rate.

00:15:22.110 --> 00:15:24.590 align:middle line:84%
And what they
found was a balance

00:15:24.590 --> 00:15:28.270 align:middle line:84%
for organic carbon
and biogenic silica.

00:15:28.270 --> 00:15:30.970 align:middle line:84%
And from this, they conclude
that-- what I said before,

00:15:30.970 --> 00:15:33.910 align:middle line:84%
which is that these components
of the particles' flux

00:15:33.910 --> 00:15:36.710 align:middle line:84%
are very nearly totally
remineralized in the surface

00:15:36.710 --> 00:15:37.890 align:middle line:90%
sediments is true.

00:15:37.890 --> 00:15:39.430 align:middle line:90%
It held at this site.

00:15:39.430 --> 00:15:44.330 align:middle line:84%
And for calcium carbonate, they
actually measured a larger flux

00:15:44.330 --> 00:15:47.130 align:middle line:84%
from dissolution of
calcium carbonate

00:15:47.130 --> 00:15:49.530 align:middle line:84%
than they measured a rain
rate of calcium carbonate

00:15:49.530 --> 00:15:52.290 align:middle line:90%
to the sea floor.

00:15:52.290 --> 00:15:54.390 align:middle line:84%
You can say two
things from this,

00:15:54.390 --> 00:15:56.477 align:middle line:84%
and I'd say the
community is split.

00:15:56.477 --> 00:15:58.310 align:middle line:84%
One is to say, well,
these are close enough,

00:15:58.310 --> 00:16:01.090 align:middle line:84%
and actually, they show that
calcium carbonate is basically

00:16:01.090 --> 00:16:03.410 align:middle line:84%
totally remineralized
at this site.

00:16:03.410 --> 00:16:05.457 align:middle line:84%
Or you can take it at
face value and say,

00:16:05.457 --> 00:16:07.290 align:middle line:84%
what this means is that
the sediments aren't

00:16:07.290 --> 00:16:08.270 align:middle line:90%
in steady state.

00:16:08.270 --> 00:16:10.610 align:middle line:84%
And more calcium carbonate
is dissolving now

00:16:10.610 --> 00:16:12.350 align:middle line:84%
than it's falling to
the sea floor now.

00:16:12.350 --> 00:16:16.230 align:middle line:90%


00:16:16.230 --> 00:16:18.570 align:middle line:84%
But anyway, I include
this just to give you

00:16:18.570 --> 00:16:21.317 align:middle line:84%
an example of a specific case in
which these mass balances were

00:16:21.317 --> 00:16:23.650 align:middle line:84%
calculated, and tell you how
the measurements were made,

00:16:23.650 --> 00:16:25.910 align:middle line:84%
and the sorts of
comparisons that are done.

00:16:25.910 --> 00:16:31.250 align:middle line:90%


00:16:31.250 --> 00:16:38.010 align:middle line:84%
Now, as I've said
over and over again,

00:16:38.010 --> 00:16:41.080 align:middle line:84%
the remineralization rate
of these biogenic components

00:16:41.080 --> 00:16:42.840 align:middle line:84%
of the particle flux
to the sea floor

00:16:42.840 --> 00:16:45.960 align:middle line:84%
tend to be very much greater
than their burial rates.

00:16:45.960 --> 00:16:48.460 align:middle line:84%
And the question
is, should we care?

00:16:48.460 --> 00:16:50.040 align:middle line:90%
Is that important to us?

00:16:50.040 --> 00:16:52.960 align:middle line:84%
And to answer that
question, I've

00:16:52.960 --> 00:16:56.000 align:middle line:84%
said, well, suppose that
you're a paleoceanographer,

00:16:56.000 --> 00:16:58.103 align:middle line:84%
and you want to measure
accumulation rates

00:16:58.103 --> 00:16:59.520 align:middle line:84%
of some component
of the sediments

00:16:59.520 --> 00:17:03.040 align:middle line:84%
in the past and use that to
infer rain rates to the sea

00:17:03.040 --> 00:17:05.000 align:middle line:90%
floor in the past.

00:17:05.000 --> 00:17:08.560 align:middle line:84%
So in order to look
at the problem,

00:17:08.560 --> 00:17:10.500 align:middle line:90%
we'll assume steady state.

00:17:10.500 --> 00:17:12.280 align:middle line:84%
And I put a star there
because obviously,

00:17:12.280 --> 00:17:16.073 align:middle line:84%
if we're looking about changes
in accumulation rates over time,

00:17:16.073 --> 00:17:18.240 align:middle line:84%
the flux to the sea floor,
or the accumulation rate,

00:17:18.240 --> 00:17:19.700 align:middle line:90%
isn't constant over time.

00:17:19.700 --> 00:17:22.240 align:middle line:84%
So by assuming steady
state, what we mean

00:17:22.240 --> 00:17:26.359 align:middle line:84%
is that the flux is constant
over a long enough time

00:17:26.359 --> 00:17:31.080 align:middle line:84%
for the sediments to come into a
steady state for that flux rate

00:17:31.080 --> 00:17:32.440 align:middle line:90%
to the sea floor.

00:17:32.440 --> 00:17:34.300 align:middle line:84%
And once that steady
state has been reached,

00:17:34.300 --> 00:17:35.760 align:middle line:84%
then the flux
could change again,

00:17:35.760 --> 00:17:38.080 align:middle line:84%
and the system would
reach a new steady state.

00:17:38.080 --> 00:17:42.397 align:middle line:84%
But we're talking about one of
those periods of constant flux,

00:17:42.397 --> 00:17:43.980 align:middle line:84%
which is long enough
for the sediments

00:17:43.980 --> 00:17:45.320 align:middle line:90%
to reach a steady state.

00:17:45.320 --> 00:17:49.540 align:middle line:84%
So if that's true, if the system
is in steady state for a given

00:17:49.540 --> 00:17:52.940 align:middle line:84%
component of the particle flux,
the rain rate to the sea floor

00:17:52.940 --> 00:17:55.020 align:middle line:84%
must equal the sum
of the accumulation

00:17:55.020 --> 00:17:59.740 align:middle line:84%
rate in the sediments plus the
rate at which the component is

00:17:59.740 --> 00:18:00.880 align:middle line:90%
remineralized.

00:18:00.880 --> 00:18:05.140 align:middle line:84%
So if you write that in
symbols, R, the rain rate,

00:18:05.140 --> 00:18:07.760 align:middle line:84%
equals A, the
accumulation rate, plus D,

00:18:07.760 --> 00:18:10.540 align:middle line:84%
which I've called the
diagenetic reaction rate.

00:18:10.540 --> 00:18:13.380 align:middle line:84%
If you divide this
equation through by R,

00:18:13.380 --> 00:18:16.260 align:middle line:84%
and then rearrange
it, you get rain rate

00:18:16.260 --> 00:18:20.620 align:middle line:84%
equals some quantity multiplied
by the accumulation rate.

00:18:20.620 --> 00:18:24.500 align:middle line:84%
So the way you might use this is
if you're measuring accumulation

00:18:24.500 --> 00:18:27.860 align:middle line:84%
rates at times in
the past, and you

00:18:27.860 --> 00:18:30.470 align:middle line:84%
want to infer past
rain rates from that.

00:18:30.470 --> 00:18:32.220 align:middle line:84%
You will need to
multiply the accumulation

00:18:32.220 --> 00:18:35.660 align:middle line:84%
rate by this quantity
that's in the brackets here.

00:18:35.660 --> 00:18:39.810 align:middle line:84%
So in order to make that
inference of rain rates

00:18:39.810 --> 00:18:41.370 align:middle line:84%
from accumulation
rates, you need

00:18:41.370 --> 00:18:45.010 align:middle line:84%
to know the quantity
that's in the brackets.

00:18:45.010 --> 00:18:46.970 align:middle line:84%
So in looking at
this equation, I've

00:18:46.970 --> 00:18:48.690 align:middle line:90%
divided it into three cases.

00:18:48.690 --> 00:18:53.330 align:middle line:84%
First is suppose that the
recycling rate is very much

00:18:53.330 --> 00:18:54.890 align:middle line:90%
smaller than the rain rate.

00:18:54.890 --> 00:18:57.590 align:middle line:84%
This would be true, say,
for the lithogenic flux,

00:18:57.590 --> 00:18:59.810 align:middle line:84%
which is essentially
completely preserved.

00:18:59.810 --> 00:19:01.490 align:middle line:84%
It essentially doesn't
undergo reactions

00:19:01.490 --> 00:19:02.930 align:middle line:90%
in the surface sediments.

00:19:02.930 --> 00:19:08.747 align:middle line:84%
So in that case, this D/R
term would be very small,

00:19:08.747 --> 00:19:10.330 align:middle line:84%
and the rain rate
would be essentially

00:19:10.330 --> 00:19:13.130 align:middle line:90%
equal to the accumulation rate.

00:19:13.130 --> 00:19:16.490 align:middle line:84%
If this D/R term
were very small,

00:19:16.490 --> 00:19:18.410 align:middle line:84%
then still, this
quantity in the brackets

00:19:18.410 --> 00:19:20.270 align:middle line:90%
would be essentially equal to 1.

00:19:20.270 --> 00:19:23.970 align:middle line:84%
And you could make an easy
inference of rain rate

00:19:23.970 --> 00:19:26.210 align:middle line:84%
from your measured
accumulation rates.

00:19:26.210 --> 00:19:31.290 align:middle line:84%
The second simple case is if
this recycling rate were not

00:19:31.290 --> 00:19:34.290 align:middle line:84%
insignificant compared to the
rain rate, but it's constant.

00:19:34.290 --> 00:19:36.880 align:middle line:84%
If that's true, then
you could measure

00:19:36.880 --> 00:19:40.902 align:middle line:84%
the ratio of the recycling
rate to the rain rate, which

00:19:40.902 --> 00:19:43.360 align:middle line:84%
would be a constant, and then
this quantity in the brackets

00:19:43.360 --> 00:19:44.380 align:middle line:90%
would be a constant.

00:19:44.380 --> 00:19:46.480 align:middle line:84%
And it would again
be easy to infer

00:19:46.480 --> 00:19:48.500 align:middle line:84%
rain rates from measured
accumulation rates.

00:19:48.500 --> 00:19:51.080 align:middle line:84%
But what if you
have a case, which

00:19:51.080 --> 00:19:52.560 align:middle line:84%
is the one that
seems to hold over

00:19:52.560 --> 00:19:55.880 align:middle line:84%
much of the oceans for these
biogenic components of the flux,

00:19:55.880 --> 00:19:59.640 align:middle line:84%
where the recycling rate is very
nearly equal to the rain rate?

00:19:59.640 --> 00:20:03.600 align:middle line:84%
If that's the case, then small
changes in this recycling

00:20:03.600 --> 00:20:07.240 align:middle line:84%
efficiency, or the ratio
of D/R in this equation,

00:20:07.240 --> 00:20:10.000 align:middle line:84%
would lead to large
changes in the rain rate

00:20:10.000 --> 00:20:13.800 align:middle line:84%
that you'd infer from
the accumulation rate

00:20:13.800 --> 00:20:17.320 align:middle line:84%
independent of any changes
in the accumulation rate.

00:20:17.320 --> 00:20:20.160 align:middle line:84%
And so changes in this
quantity in the brackets

00:20:20.160 --> 00:20:24.120 align:middle line:84%
could mask changes in
accumulation rates.

00:20:24.120 --> 00:20:27.000 align:middle line:84%
I've just shown that
graphically here,

00:20:27.000 --> 00:20:29.560 align:middle line:84%
where I've plotted the
quantity in the brackets

00:20:29.560 --> 00:20:33.080 align:middle line:84%
on the vertical axis, and
the ratio of the recycling

00:20:33.080 --> 00:20:37.020 align:middle line:84%
rate to the rain rate to the sea
floor on the horizontal axis,

00:20:37.020 --> 00:20:39.460 align:middle line:90%
going from the simple--

00:20:39.460 --> 00:20:42.300 align:middle line:84%
what I called case 1, where
not much of the material

00:20:42.300 --> 00:20:43.540 align:middle line:90%
is recycled.

00:20:43.540 --> 00:20:48.840 align:middle line:84%
And then, in that case, this
quantity varies a little bit,

00:20:48.840 --> 00:20:49.600 align:middle line:90%
but not too much.

00:20:49.600 --> 00:20:51.780 align:middle line:84%
So you're pretty safe
inferring rain rates

00:20:51.780 --> 00:20:52.880 align:middle line:90%
from accumulation rates.

00:20:52.880 --> 00:20:59.580 align:middle line:84%
But if you get to the case where
the recycling efficiency, D/R,

00:20:59.580 --> 00:21:04.180 align:middle line:84%
exceeds 80% then
small changes in D/R

00:21:04.180 --> 00:21:07.440 align:middle line:84%
lead to very large changes in
the inferred accumulation rate.

00:21:07.440 --> 00:21:11.140 align:middle line:84%
So this curve
becomes very steep.

00:21:11.140 --> 00:21:13.780 align:middle line:84%
And so if you're a
paleoceanographer,

00:21:13.780 --> 00:21:16.300 align:middle line:84%
it's probably a
good idea to find

00:21:16.300 --> 00:21:19.460 align:middle line:84%
some proxy for the biogenic
components of the flux

00:21:19.460 --> 00:21:21.940 align:middle line:84%
to the sea floor, because
measuring those components

00:21:21.940 --> 00:21:24.020 align:middle line:90%
directly is--

00:21:24.020 --> 00:21:25.580 align:middle line:84%
measurements of
accumulation rates

00:21:25.580 --> 00:21:27.340 align:middle line:84%
of those biogenic
components directly

00:21:27.340 --> 00:21:29.200 align:middle line:84%
are going to be
difficult to interpret.

00:21:29.200 --> 00:21:35.080 align:middle line:90%


00:21:35.080 --> 00:21:40.650 align:middle line:84%
Now, some motivations for
not pulling the plug on me

00:21:40.650 --> 00:21:43.050 align:middle line:84%
now, and listening
for a little bit

00:21:43.050 --> 00:21:46.190 align:middle line:84%
longer, consequences
of early diagenesis.

00:21:46.190 --> 00:21:48.410 align:middle line:84%
First, we talked
about-- we've just

00:21:48.410 --> 00:21:50.130 align:middle line:84%
talked about low
rates of preservation

00:21:50.130 --> 00:21:53.930 align:middle line:84%
of biogenic components and what
that means for interpreting

00:21:53.930 --> 00:21:56.410 align:middle line:90%
the sedimentary record.

00:21:56.410 --> 00:21:58.790 align:middle line:84%
Second, another long
timescale-- in fact,

00:21:58.790 --> 00:22:01.010 align:middle line:90%
a very long timescale process--

00:22:01.010 --> 00:22:04.370 align:middle line:84%
is how early diagenesis
in marine sediments

00:22:04.370 --> 00:22:06.970 align:middle line:84%
affects the atmospheric
oxygen level.

00:22:06.970 --> 00:22:12.170 align:middle line:84%
And here, it's a
simple enough picture.

00:22:12.170 --> 00:22:16.530 align:middle line:84%
Oxygen is consumed on the
continents by weathering.

00:22:16.530 --> 00:22:19.190 align:middle line:84%
If the oxygen level in the
atmosphere is to be constant,

00:22:19.190 --> 00:22:21.350 align:middle line:84%
then the excess
of photosynthesis,

00:22:21.350 --> 00:22:23.810 align:middle line:84%
which releases oxygen
to the atmosphere,

00:22:23.810 --> 00:22:27.650 align:middle line:84%
over respiration,
which removes oxygen,

00:22:27.650 --> 00:22:32.230 align:middle line:84%
must balance that consumption of
the oxygen from the atmosphere

00:22:32.230 --> 00:22:33.170 align:middle line:90%
by weathering.

00:22:33.170 --> 00:22:36.330 align:middle line:90%


00:22:36.330 --> 00:22:39.710 align:middle line:90%
Did I say that clearly enough?

00:22:39.710 --> 00:22:42.150 align:middle line:84%
For the oxygen level to be
constant in the atmosphere,

00:22:42.150 --> 00:22:44.390 align:middle line:84%
processes which
consume oxygen have

00:22:44.390 --> 00:22:45.870 align:middle line:84%
to be balanced by
processes which

00:22:45.870 --> 00:22:48.390 align:middle line:84%
produce oxygen.
Oxygen is produced

00:22:48.390 --> 00:22:52.650 align:middle line:84%
by the excess of photosynthesis
over respiration.

00:22:52.650 --> 00:22:54.730 align:middle line:84%
It's consumed by
weathering processes.

00:22:54.730 --> 00:22:56.430 align:middle line:90%
So those need to be equal.

00:22:56.430 --> 00:23:01.430 align:middle line:84%
In the ocean, photosynthesis
occurs in the surface ocean.

00:23:01.430 --> 00:23:03.790 align:middle line:84%
Much of the organic matter--
most of the organic matter

00:23:03.790 --> 00:23:07.310 align:middle line:84%
that's produced is
respired, is consumed

00:23:07.310 --> 00:23:08.770 align:middle line:84%
by respiration in
the water column,

00:23:08.770 --> 00:23:11.747 align:middle line:84%
but a little bit is left over
to accumulate in the sediments.

00:23:11.747 --> 00:23:13.830 align:middle line:84%
And the fraction that
accumulates in the sediments

00:23:13.830 --> 00:23:17.990 align:middle line:84%
is determined, to some
extent, by processes

00:23:17.990 --> 00:23:21.130 align:middle line:84%
that recycle organic
matter in the sediments.

00:23:21.130 --> 00:23:26.310 align:middle line:84%
And in addition to that,
once oxygen is used up

00:23:26.310 --> 00:23:28.630 align:middle line:84%
in the sediments, then
other electron acceptors

00:23:28.630 --> 00:23:29.690 align:middle line:90%
become important.

00:23:29.690 --> 00:23:33.820 align:middle line:84%
And two of those, the most
important, are sulfate and iron.

00:23:33.820 --> 00:23:36.740 align:middle line:84%
When sulfate and iron are
used to oxidize organic matter

00:23:36.740 --> 00:23:39.420 align:middle line:84%
anaerobically in sediments,
then the products

00:23:39.420 --> 00:23:41.700 align:middle line:84%
are reduced iron
and reduced sulfur.

00:23:41.700 --> 00:23:43.460 align:middle line:84%
Some of that reduced
iron and sulfur

00:23:43.460 --> 00:23:46.180 align:middle line:84%
is buried as pyrite,
as iron sulfides.

00:23:46.180 --> 00:23:48.000 align:middle line:84%
To the extent that
those are buried,

00:23:48.000 --> 00:23:52.380 align:middle line:84%
it represents a source of
oxygen to the atmosphere

00:23:52.380 --> 00:23:55.180 align:middle line:84%
in the same way that
photosynthesis does.

00:23:55.180 --> 00:23:58.820 align:middle line:84%
So processes in sediments,
the burial of organic matter

00:23:58.820 --> 00:24:01.120 align:middle line:84%
and the burial of
reduced iron and sulfur,

00:24:01.120 --> 00:24:04.060 align:middle line:84%
which are produced by
sedimentary processes,

00:24:04.060 --> 00:24:07.260 align:middle line:84%
are significant components in
the long term atmospheric oxygen

00:24:07.260 --> 00:24:08.860 align:middle line:90%
cycle.

00:24:08.860 --> 00:24:10.860 align:middle line:84%
If we move from these
longtime scale things

00:24:10.860 --> 00:24:13.260 align:middle line:84%
to the contemporary
ocean, there have

00:24:13.260 --> 00:24:19.140 align:middle line:84%
been studies of deep water
oxygen consumption done.

00:24:19.140 --> 00:24:22.740 align:middle line:84%
And when measurements of oxygen
consumption in the sediments are

00:24:22.740 --> 00:24:26.740 align:middle line:84%
included in those studies, what
they show is that about half

00:24:26.740 --> 00:24:29.640 align:middle line:84%
of the oxygen consumption
below 1,000 meters in the ocean

00:24:29.640 --> 00:24:33.240 align:middle line:84%
actually occurs in the sediments
rather than in the water column.

00:24:33.240 --> 00:24:34.880 align:middle line:84%
So sedimentary
oxygen consumption

00:24:34.880 --> 00:24:38.840 align:middle line:84%
is an important piece of the
deep water oxygen balance.

00:24:38.840 --> 00:24:42.360 align:middle line:84%
And then the topic that
has been of most interest

00:24:42.360 --> 00:24:48.160 align:middle line:84%
to people in the last few
years is that about half

00:24:48.160 --> 00:24:52.240 align:middle line:84%
of the denitrification that
occurs in the oceans today--

00:24:52.240 --> 00:24:54.400 align:middle line:84%
or actually more
than half, even--

00:24:54.400 --> 00:24:56.180 align:middle line:90%
occurs in sediments.

00:24:56.180 --> 00:25:00.080 align:middle line:84%
So you might ask
yourself why that's true.

00:25:00.080 --> 00:25:03.960 align:middle line:84%
What condition has to hold in
the ocean for denitrification

00:25:03.960 --> 00:25:06.960 align:middle line:90%
to occur?

00:25:06.960 --> 00:25:09.300 align:middle line:84%
What has to be
true of the water?

00:25:09.300 --> 00:25:12.440 align:middle line:90%


00:25:12.440 --> 00:25:14.100 align:middle line:84%
I bet you've studied
this already.

00:25:14.100 --> 00:25:16.473 align:middle line:90%
AUDIENCE: [INAUDIBLE] anaerobic?

00:25:16.473 --> 00:25:17.140 align:middle line:90%
PROFESSOR: Yeah.

00:25:17.140 --> 00:25:18.438 align:middle line:90%
The oxygen has to be gone.

00:25:18.438 --> 00:25:20.480 align:middle line:84%
So where in the ocean--
where in the water column

00:25:20.480 --> 00:25:23.720 align:middle line:84%
does denitrification occur
throughout the oceans?

00:25:23.720 --> 00:25:25.238 align:middle line:90%
AUDIENCE: Oxygen minimum zones.

00:25:25.238 --> 00:25:26.280 align:middle line:90%
PROFESSOR: OK, which are?

00:25:26.280 --> 00:25:27.790 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:25:27.790 --> 00:25:32.070 align:middle line:84%
PROFESSOR: OK, but there's only
a very small number of places

00:25:32.070 --> 00:25:34.670 align:middle line:84%
where the oxygen minimum is
intense enough to actually have

00:25:34.670 --> 00:25:38.830 align:middle line:90%
an anoxic water column.

00:25:38.830 --> 00:25:40.510 align:middle line:90%
OK, I'll tell you.

00:25:40.510 --> 00:25:43.990 align:middle line:84%
The Arabian Sea and the Eastern
Tropical Pacific north and south

00:25:43.990 --> 00:25:44.850 align:middle line:90%
of the equator.

00:25:44.850 --> 00:25:48.750 align:middle line:84%
So there's a very limited
number of very limited in extent

00:25:48.750 --> 00:25:53.230 align:middle line:84%
places where denitrification
can occur in the water column.

00:25:53.230 --> 00:25:56.230 align:middle line:84%
So why are sediments a better
place for denitrification

00:25:56.230 --> 00:25:57.590 align:middle line:90%
to occur?

00:25:57.590 --> 00:26:03.790 align:middle line:84%
And what I've shown here
is a picture, on the left,

00:26:03.790 --> 00:26:06.070 align:middle line:84%
a profile of a
continental margin.

00:26:06.070 --> 00:26:11.250 align:middle line:84%
And continental margin
has a continental shelf,

00:26:11.250 --> 00:26:13.110 align:middle line:90%
which is very shallow and flat.

00:26:13.110 --> 00:26:16.270 align:middle line:84%
And seaward of the continental
shelf, the continental margin

00:26:16.270 --> 00:26:20.850 align:middle line:84%
slopes relatively rapidly
down to the abyssal plain.

00:26:20.850 --> 00:26:25.260 align:middle line:84%
So it goes from a depth of about
100 meters to a depth of about

00:26:25.260 --> 00:26:34.500 align:middle line:84%
4,000 meters over a horizontal
scale of maybe 100 kilometers.

00:26:34.500 --> 00:26:37.460 align:middle line:84%
So that's a region where
the depth of the sea floor

00:26:37.460 --> 00:26:39.200 align:middle line:90%
is changing a lot very fast.

00:26:39.200 --> 00:26:41.620 align:middle line:84%
And what I've shown
on the right is a plot

00:26:41.620 --> 00:26:45.420 align:middle line:84%
of the oxygen penetration depth
in the sediments as a function

00:26:45.420 --> 00:26:47.540 align:middle line:90%
of water column depth.

00:26:47.540 --> 00:26:50.740 align:middle line:84%
So the thickness of the water
column overlying the sediments.

00:26:50.740 --> 00:26:53.300 align:middle line:84%
And I've done it for
two continental margins.

00:26:53.300 --> 00:26:57.820 align:middle line:84%
In the open symbols are
the continental margins

00:26:57.820 --> 00:27:01.180 align:middle line:84%
in the eastern and western
North Atlantic Ocean.

00:27:01.180 --> 00:27:05.540 align:middle line:84%
And the filled triangles are
along the continental margin

00:27:05.540 --> 00:27:10.340 align:middle line:84%
in the Eastern Pacific Ocean,
the Northeast Pacific Ocean.

00:27:10.340 --> 00:27:13.660 align:middle line:84%
So the first thing to notice
is that this oxygen penetration

00:27:13.660 --> 00:27:15.660 align:middle line:90%
depth scale is in millimeters.

00:27:15.660 --> 00:27:22.740 align:middle line:84%
And so say, at a water depth
of 2,000 meters in the Atlantic

00:27:22.740 --> 00:27:25.260 align:middle line:84%
Ocean-- so if you're a spot
in this picture on the left,

00:27:25.260 --> 00:27:27.267 align:middle line:84%
which is about where
my arrow is there,

00:27:27.267 --> 00:27:29.600 align:middle line:84%
if you go ahead and measure
the oxygen penetration depth

00:27:29.600 --> 00:27:32.700 align:middle line:84%
in the sediments, oxygen
penetrates to a depth of about 5

00:27:32.700 --> 00:27:33.680 align:middle line:90%
centimeters.

00:27:33.680 --> 00:27:36.960 align:middle line:84%
As you go up the slope, if
you measure oxygen penetration

00:27:36.960 --> 00:27:39.640 align:middle line:84%
depths in the sediments, it
gets shallower and shallower,

00:27:39.640 --> 00:27:42.400 align:middle line:84%
until when you get
to about 400 meters,

00:27:42.400 --> 00:27:44.280 align:middle line:84%
oxygen penetration
depth in the sediments

00:27:44.280 --> 00:27:46.640 align:middle line:90%
is less than a centimeter.

00:27:46.640 --> 00:27:49.440 align:middle line:84%
So that means only the top--
this much of the sediments

00:27:49.440 --> 00:27:51.700 align:middle line:84%
actually have oxygen
in the pore waters.

00:27:51.700 --> 00:27:54.920 align:middle line:84%
If you do the same thing
in the Pacific Ocean,

00:27:54.920 --> 00:27:57.740 align:middle line:84%
you find oxygen penetration
depths are much shallower.

00:27:57.740 --> 00:27:59.840 align:middle line:84%
So why would oxygen
penetration depths

00:27:59.840 --> 00:28:02.800 align:middle line:84%
be shallower in sediments
on the continental margin

00:28:02.800 --> 00:28:04.020 align:middle line:90%
in the Pacific ocean?

00:28:04.020 --> 00:28:07.520 align:middle line:90%


00:28:07.520 --> 00:28:09.000 align:middle line:90%
In the Eastern Pacific--

00:28:09.000 --> 00:28:10.300 align:middle line:90%
Northeastern Pacific?

00:28:10.300 --> 00:28:12.880 align:middle line:90%


00:28:12.880 --> 00:28:15.300 align:middle line:84%
This has to be stuck in
your brain somewhere,

00:28:15.300 --> 00:28:16.660 align:middle line:90%
just waiting to come out.

00:28:16.660 --> 00:28:19.600 align:middle line:90%


00:28:19.600 --> 00:28:21.320 align:middle line:84%
What are the oxygen
concentrations

00:28:21.320 --> 00:28:23.830 align:middle line:84%
in the oxygen minimum
in the Atlantic

00:28:23.830 --> 00:28:25.210 align:middle line:90%
compared to in the Pacific?

00:28:25.210 --> 00:28:27.950 align:middle line:90%


00:28:27.950 --> 00:28:30.070 align:middle line:90%
They're much higher.

00:28:30.070 --> 00:28:33.670 align:middle line:84%
So oxygen concentrations in
bottom waters at these Pacific

00:28:33.670 --> 00:28:36.550 align:middle line:84%
sites are much lower than they
are at corresponding depths

00:28:36.550 --> 00:28:38.110 align:middle line:90%
in the Atlantic Ocean.

00:28:38.110 --> 00:28:43.162 align:middle line:84%
So oxygen penetration depths in
the sediments are much smaller.

00:28:43.162 --> 00:28:44.870 align:middle line:84%
So if you go along
the continental margin

00:28:44.870 --> 00:28:47.870 align:middle line:84%
in the Pacific Ocean, oxygen
penetration depths vary from

00:28:47.870 --> 00:28:52.990 align:middle line:84%
about 2 centimeters at a depth
of 4,000 meters and decrease

00:28:52.990 --> 00:28:58.030 align:middle line:84%
in the oxygen minimum to a depth
of about half a centimeter.

00:28:58.030 --> 00:28:59.710 align:middle line:90%
So this means in--

00:28:59.710 --> 00:29:01.910 align:middle line:84%
remember, in the
water column, there's

00:29:01.910 --> 00:29:04.670 align:middle line:84%
three places in the ocean
where oxygen concentrations

00:29:04.670 --> 00:29:07.670 align:middle line:84%
in the water get low enough
for denitrification to occur.

00:29:07.670 --> 00:29:11.070 align:middle line:84%
In the sediments, oxygen
penetration depths

00:29:11.070 --> 00:29:13.630 align:middle line:84%
along all of the
continental margins

00:29:13.630 --> 00:29:17.390 align:middle line:84%
are ranged from 5 to
half a centimeter.

00:29:17.390 --> 00:29:20.670 align:middle line:84%
So there's this region very
close to the water column that's

00:29:20.670 --> 00:29:22.210 align:middle line:90%
anoxic.

00:29:22.210 --> 00:29:25.130 align:middle line:84%
And as long as the flux of
organic matter to the sediments

00:29:25.130 --> 00:29:27.610 align:middle line:84%
is high enough, denitrification
can occur there.

00:29:27.610 --> 00:29:30.490 align:middle line:84%
And the result of that is that
over half the denitrification

00:29:30.490 --> 00:29:32.730 align:middle line:84%
in the oceans occurs
in the sediments.

00:29:32.730 --> 00:29:36.450 align:middle line:84%
So if you're interested in
oceanic nitrogen balances,

00:29:36.450 --> 00:29:38.270 align:middle line:84%
you shouldn't forget
about the sediments.

00:29:38.270 --> 00:29:44.810 align:middle line:90%


00:29:44.810 --> 00:29:48.447 align:middle line:84%
So now that we've talked
in general about reactions

00:29:48.447 --> 00:29:50.530 align:middle line:84%
in the sediments, we'll
get a little more specific

00:29:50.530 --> 00:29:54.050 align:middle line:84%
and focus on, for
the rest of today,

00:29:54.050 --> 00:29:57.130 align:middle line:84%
the oxidation of organic
matter in the sediments.

00:29:57.130 --> 00:29:59.850 align:middle line:84%
So you might ask how
sedimentary processes

00:29:59.850 --> 00:30:01.710 align:middle line:84%
are different from
water column processes.

00:30:01.710 --> 00:30:04.090 align:middle line:90%
Well, they must be different.

00:30:04.090 --> 00:30:08.110 align:middle line:84%
Remember that-- I'm sure
you've studied this--

00:30:08.110 --> 00:30:12.250 align:middle line:84%
that most of the organic matter
that's fixed by photosynthesis

00:30:12.250 --> 00:30:15.530 align:middle line:84%
in the surface ocean,
something like--

00:30:15.530 --> 00:30:20.170 align:middle line:84%
well, well over 90%, is respired
in the upper 1,000 meters

00:30:20.170 --> 00:30:21.383 align:middle line:90%
of the water column.

00:30:21.383 --> 00:30:23.800 align:middle line:84%
So relatively little gets to
the seafloor, and what's left

00:30:23.800 --> 00:30:27.298 align:middle line:84%
is presumably the relatively
unreactive components.

00:30:27.298 --> 00:30:28.840 align:middle line:84%
So the question is--
and I've already

00:30:28.840 --> 00:30:31.920 align:middle line:84%
told you that these are almost
completely remineralized

00:30:31.920 --> 00:30:33.310 align:middle line:90%
in the sediments.

00:30:33.310 --> 00:30:35.060 align:middle line:84%
So they're unreactive
in the water column,

00:30:35.060 --> 00:30:37.560 align:middle line:84%
but they hit the seafloor
and conditions have

00:30:37.560 --> 00:30:39.780 align:middle line:90%
changed so that they'll react.

00:30:39.780 --> 00:30:43.500 align:middle line:84%
So how are processes in
the sediments different?

00:30:43.500 --> 00:30:47.160 align:middle line:84%
First is the really
obvious one, that there's

00:30:47.160 --> 00:30:48.680 align:middle line:84%
a lot more particles
in sediments

00:30:48.680 --> 00:30:50.240 align:middle line:84%
than there are in
the water column.

00:30:50.240 --> 00:30:53.120 align:middle line:84%
So the concentration of
particles in the water column

00:30:53.120 --> 00:30:55.180 align:middle line:84%
is on the order of a
milligram per liter,

00:30:55.180 --> 00:30:59.480 align:middle line:84%
but surface sediments are 40%
to 70% particles by weight.

00:30:59.480 --> 00:31:04.540 align:middle line:84%
So they're 30% to 60%
water, 40% to 70% particles.

00:31:04.540 --> 00:31:06.080 align:middle line:90%
So there's a lot more particles.

00:31:06.080 --> 00:31:08.880 align:middle line:84%
And along with those particles
are a lot more bacteria.

00:31:08.880 --> 00:31:12.720 align:middle line:84%
So it's a great place
for reactions to occur.

00:31:12.720 --> 00:31:15.280 align:middle line:84%
The second is a
question of time.

00:31:15.280 --> 00:31:19.660 align:middle line:84%
So if you consider a water
column that's about 3,500 meters

00:31:19.660 --> 00:31:22.880 align:middle line:84%
long, and if you consider
the large particle flux,

00:31:22.880 --> 00:31:25.620 align:middle line:84%
which falls at a rate of
something like 50 meters a day,

00:31:25.620 --> 00:31:28.340 align:middle line:84%
then those particles will reside
in the water column for about 70

00:31:28.340 --> 00:31:29.420 align:middle line:90%
days.

00:31:29.420 --> 00:31:32.580 align:middle line:84%
Now, if you consider the
surface sediments, and here,

00:31:32.580 --> 00:31:37.220 align:middle line:84%
I've taken as the layer of the
sediments in which these "rapid"

00:31:37.220 --> 00:31:40.380 align:middle line:84%
reactions occur--
"rapid" in quotes--

00:31:40.380 --> 00:31:42.460 align:middle line:84%
to be what we call
the mixed layer, which

00:31:42.460 --> 00:31:45.140 align:middle line:84%
is the layer at the surface
of that live in the sediments,

00:31:45.140 --> 00:31:49.220 align:middle line:84%
in the deep sea, in the pelagic
ocean, away from the continents,

00:31:49.220 --> 00:31:52.300 align:middle line:84%
the depth of the mixed layer
is about 8 centimeters.

00:31:52.300 --> 00:31:55.140 align:middle line:84%
And in the open ocean,
sedimentation rates are about

00:31:55.140 --> 00:31:57.060 align:middle line:90%
a centimeter per 1,000 years.

00:31:57.060 --> 00:32:00.540 align:middle line:84%
So a particle will reside in
that mixed layer where reactions

00:32:00.540 --> 00:32:02.660 align:middle line:90%
occur for about 8,000 years.

00:32:02.660 --> 00:32:06.220 align:middle line:84%
In the coastal ocean,
mixed layers are thicker,

00:32:06.220 --> 00:32:07.560 align:middle line:90%
say 20 centimeters.

00:32:07.560 --> 00:32:09.860 align:middle line:84%
Sedimentation rates
are faster, say a tenth

00:32:09.860 --> 00:32:11.620 align:middle line:90%
of a centimeter per year.

00:32:11.620 --> 00:32:13.660 align:middle line:84%
So a particle will reside
in that mixed layer

00:32:13.660 --> 00:32:15.660 align:middle line:90%
for about 200 years.

00:32:15.660 --> 00:32:18.570 align:middle line:84%
So whereas a particle
resides in the water column

00:32:18.570 --> 00:32:22.730 align:middle line:84%
for on the order of months, it
resides in that surface layer

00:32:22.730 --> 00:32:25.910 align:middle line:84%
of the sediments for hundreds
to thousands of years,

00:32:25.910 --> 00:32:29.437 align:middle line:84%
so there's a lot longer for
reactions to occur there.

00:32:29.437 --> 00:32:31.770 align:middle line:84%
Reactions that are too slow
to occur in the water column

00:32:31.770 --> 00:32:35.650 align:middle line:84%
have plenty of time to
happen in the sediments.

00:32:35.650 --> 00:32:38.050 align:middle line:84%
And a final way,
and this is actually

00:32:38.050 --> 00:32:41.330 align:middle line:84%
a key to the occurrence of
denitrification in sediments,

00:32:41.330 --> 00:32:46.090 align:middle line:84%
is that the reactants
for the processes that

00:32:46.090 --> 00:32:48.730 align:middle line:84%
occur in the sediments
are supplied from above.

00:32:48.730 --> 00:32:50.832 align:middle line:84%
So the particles fall
to the sediment surface.

00:32:50.832 --> 00:32:53.290 align:middle line:84%
Once they fall there, they can
be mixed through the surface

00:32:53.290 --> 00:32:53.910 align:middle line:90%
sediments.

00:32:53.910 --> 00:32:55.970 align:middle line:84%
But they arrive at
the sediment surface

00:32:55.970 --> 00:32:59.715 align:middle line:84%
and they react with solutes,
and in particular, you

00:32:59.715 --> 00:33:02.250 align:middle line:84%
can think of oxygen, that
diffuse from the water column

00:33:02.250 --> 00:33:03.930 align:middle line:90%
into the sediments.

00:33:03.930 --> 00:33:08.290 align:middle line:90%
So you can see that reactions--

00:33:08.290 --> 00:33:10.970 align:middle line:84%
there tends to be
a layered structure

00:33:10.970 --> 00:33:16.310 align:middle line:84%
to zones of reactions that occur
in sediments, where first--

00:33:16.310 --> 00:33:18.840 align:middle line:90%


00:33:18.840 --> 00:33:21.880 align:middle line:90%
that's as far as--

00:33:21.880 --> 00:33:24.920 align:middle line:84%
reactants are
supplied from above,

00:33:24.920 --> 00:33:27.280 align:middle line:84%
and the sequence of
reactions that occurs

00:33:27.280 --> 00:33:29.480 align:middle line:84%
tends to make a sort
of layered structure

00:33:29.480 --> 00:33:32.960 align:middle line:84%
in the sediment column--
to a first approximation.

00:33:32.960 --> 00:33:36.200 align:middle line:90%
So why is that important?

00:33:36.200 --> 00:33:38.940 align:middle line:84%
When you think about how
organic matter is oxidized,

00:33:38.940 --> 00:33:42.080 align:middle line:84%
and in writing the
equation in this funny way,

00:33:42.080 --> 00:33:44.240 align:middle line:84%
I've assumed that you've
already written out

00:33:44.240 --> 00:33:47.680 align:middle line:84%
equations for the
oxidation of organic matter

00:33:47.680 --> 00:33:53.720 align:middle line:90%
by oxygen, nitrogen, by nitrate.

00:33:53.720 --> 00:33:55.860 align:middle line:84%
AUDIENCE: Only
[INAUDIBLE] respiration.

00:33:55.860 --> 00:33:57.240 align:middle line:90%
PROFESSOR: OK.

00:33:57.240 --> 00:33:57.920 align:middle line:90%
Well, then--

00:33:57.920 --> 00:34:00.360 align:middle line:84%
AUDIENCE: Carrying sea
nitrate per [INAUDIBLE]

00:34:00.360 --> 00:34:01.983 align:middle line:90%
comes after [INAUDIBLE].

00:34:01.983 --> 00:34:04.400 align:middle line:84%
PROFESSOR: Well, then this
equation will look a little odd

00:34:04.400 --> 00:34:07.400 align:middle line:90%
to you, but it's--

00:34:07.400 --> 00:34:10.840 align:middle line:84%
AUDIENCE: But it'll be very
useful for your homework.

00:34:10.840 --> 00:34:13.960 align:middle line:84%
PROFESSOR: And anticipating
that you've already seen these,

00:34:13.960 --> 00:34:16.340 align:middle line:84%
I didn't include any
stoichiometric information

00:34:16.340 --> 00:34:16.840 align:middle line:90%
at all.

00:34:16.840 --> 00:34:18.465 align:middle line:84%
So you're going to
have to go somewhere

00:34:18.465 --> 00:34:20.480 align:middle line:84%
else to get stoichiometry
of these reactions.

00:34:20.480 --> 00:34:23.940 align:middle line:84%
But what I've done is
written the reactants

00:34:23.940 --> 00:34:27.460 align:middle line:84%
on the left-hand side here, and
products on the right-hand side,

00:34:27.460 --> 00:34:30.620 align:middle line:84%
where the reactant
obviously is organic matter.

00:34:30.620 --> 00:34:33.420 align:middle line:90%
And that can react with oxygen.

00:34:33.420 --> 00:34:35.440 align:middle line:84%
When organic matter
reacts with oxygen,

00:34:35.440 --> 00:34:37.780 align:middle line:84%
the nitrogen in
the organic matter

00:34:37.780 --> 00:34:40.739 align:middle line:84%
is-- the carbon is
oxidized to CO2.

00:34:40.739 --> 00:34:42.739 align:middle line:84%
The nitrogen is
oxidized to nitrate.

00:34:42.739 --> 00:34:46.780 align:middle line:90%


00:34:46.780 --> 00:34:50.219 align:middle line:84%
And just to give
one more example,

00:34:50.219 --> 00:34:53.620 align:middle line:84%
the reason I'm going through
this will become clear, I hope.

00:34:53.620 --> 00:34:56.900 align:middle line:84%
If organic matter is
oxidized by nitrate,

00:34:56.900 --> 00:35:02.020 align:middle line:84%
then the nitrogen in the
organic matter ends up as N2.

00:35:02.020 --> 00:35:05.180 align:middle line:90%
And the same for the nitrate--

00:35:05.180 --> 00:35:06.700 align:middle line:84%
for the electrons--
nitrate that's

00:35:06.700 --> 00:35:10.920 align:middle line:84%
used as an electron
acceptor, it ends up as N2.

00:35:10.920 --> 00:35:15.010 align:middle line:84%
When manganese,
iron, and sulfate

00:35:15.010 --> 00:35:18.610 align:middle line:84%
are used as electron acceptors
by anaerobic bacteria

00:35:18.610 --> 00:35:21.450 align:middle line:84%
for organic matter
oxidation, then the nitrogen

00:35:21.450 --> 00:35:24.190 align:middle line:84%
in the organic matter
is released as ammonia.

00:35:24.190 --> 00:35:26.530 align:middle line:90%
It's not further oxidized.

00:35:26.530 --> 00:35:28.730 align:middle line:84%
And in addition,
the manganese oxides

00:35:28.730 --> 00:35:32.110 align:middle line:84%
are released to the water
as dissolved manganese.

00:35:32.110 --> 00:35:33.770 align:middle line:90%
Iron is dissolved iron.

00:35:33.770 --> 00:35:36.850 align:middle line:84%
And the sulfur is
released as sulfide.

00:35:36.850 --> 00:35:40.050 align:middle line:84%
And the reason for
going through this

00:35:40.050 --> 00:35:45.170 align:middle line:84%
is that you can use measurements
of solutes in pore waters

00:35:45.170 --> 00:35:47.850 align:middle line:84%
to tell you which
of these reactions

00:35:47.850 --> 00:35:50.370 align:middle line:84%
is occurring where in
the sediment column.

00:35:50.370 --> 00:35:53.610 align:middle line:84%
You can measure oxygen
profiles to tell you

00:35:53.610 --> 00:35:56.750 align:middle line:84%
the rate of consumption of
organic matter by oxygen,

00:35:56.750 --> 00:35:58.730 align:middle line:84%
and to tell you where
in the sediment column

00:35:58.730 --> 00:36:00.570 align:middle line:90%
oxygen is being used.

00:36:00.570 --> 00:36:05.610 align:middle line:84%
You can use nitrate as an
indicator of oxic respiration

00:36:05.610 --> 00:36:08.210 align:middle line:84%
because nitrate is produced,
and a denitrification

00:36:08.210 --> 00:36:12.430 align:middle line:84%
because nitrate is consumed,
and so on down the list.

00:36:12.430 --> 00:36:14.150 align:middle line:84%
And the one thing
I'll point out is

00:36:14.150 --> 00:36:16.750 align:middle line:84%
you can use ammonia
profiles in sediments

00:36:16.750 --> 00:36:21.510 align:middle line:84%
as an indicator of the
combined effect of oxidation

00:36:21.510 --> 00:36:24.970 align:middle line:84%
of organic matter by
manganese and iron oxides,

00:36:24.970 --> 00:36:27.150 align:middle line:84%
and by sulfate
sulfur, because it's

00:36:27.150 --> 00:36:29.790 align:middle line:84%
a product of each
of those reactions.

00:36:29.790 --> 00:36:33.150 align:middle line:90%


00:36:33.150 --> 00:36:36.450 align:middle line:84%
Now, I've written a very
simple-- well, simple.

00:36:36.450 --> 00:36:38.810 align:middle line:84%
If I wrote out one of
these equations on its own,

00:36:38.810 --> 00:36:42.990 align:middle line:84%
it would be a simple picture of
a reaction with organic matter

00:36:42.990 --> 00:36:46.950 align:middle line:84%
plus electron acceptor
equals oxidized products.

00:36:46.950 --> 00:36:49.790 align:middle line:84%
But in reality, you
have to be aware

00:36:49.790 --> 00:36:51.710 align:middle line:84%
that the true mechanisms
for these reactions

00:36:51.710 --> 00:36:53.590 align:middle line:90%
are much more complicated.

00:36:53.590 --> 00:36:58.930 align:middle line:84%
Bacteria don't bite off pieces
of particulate organic matter.

00:36:58.930 --> 00:37:03.110 align:middle line:84%
Instead, they
release enzymes which

00:37:03.110 --> 00:37:05.270 align:middle line:84%
break down the organic
matter into pieces

00:37:05.270 --> 00:37:08.390 align:middle line:84%
that are small enough for them
to incorporate in their cells.

00:37:08.390 --> 00:37:14.140 align:middle line:84%
And anaerobic bacteria, at
least, can't take organic matter

00:37:14.140 --> 00:37:16.340 align:middle line:84%
and oxidize it all
the way to CO2.

00:37:16.340 --> 00:37:18.273 align:middle line:84%
So it's not a single
bacterium that's

00:37:18.273 --> 00:37:19.940 align:middle line:84%
carrying out the whole
process, but it's

00:37:19.940 --> 00:37:21.980 align:middle line:90%
a consortium of bacteria.

00:37:21.980 --> 00:37:26.140 align:middle line:84%
But the overall effect is
these overall reactions

00:37:26.140 --> 00:37:28.380 align:middle line:84%
with organic matter
plus electron acceptor

00:37:28.380 --> 00:37:30.080 align:middle line:90%
goes to oxidized products.

00:37:30.080 --> 00:37:32.660 align:middle line:84%
And the reason for
writing them in that way

00:37:32.660 --> 00:37:36.500 align:middle line:84%
is that writing
them that way allows

00:37:36.500 --> 00:37:40.500 align:middle line:84%
you to calculate the free energy
yield of each of the reactions.

00:37:40.500 --> 00:37:44.380 align:middle line:84%
And what you find is that the
order in which these reactions

00:37:44.380 --> 00:37:48.580 align:middle line:84%
occur is the order of
decreasing free energy yield

00:37:48.580 --> 00:37:50.520 align:middle line:90%
for this overall reaction.

00:37:50.520 --> 00:37:55.677 align:middle line:84%
And I was assuming you had done
this already, but you haven't.

00:37:55.677 --> 00:37:57.260 align:middle line:84%
But if you do this
calculation, you'll

00:37:57.260 --> 00:38:00.940 align:middle line:84%
find that the free energy
yield for the oxidation

00:38:00.940 --> 00:38:08.660 align:middle line:84%
of organic matter by oxygen,
to CO2 plus nitrate--

00:38:08.660 --> 00:38:12.560 align:middle line:84%
to CO2 plus nitrate has a
higher free energy yield

00:38:12.560 --> 00:38:14.200 align:middle line:84%
than for the reaction
of organic matter

00:38:14.200 --> 00:38:17.840 align:middle line:84%
with nitrate, which in turn
has a higher free energy

00:38:17.840 --> 00:38:22.080 align:middle line:84%
yield than that of organic
matter with manganese oxides,

00:38:22.080 --> 00:38:27.100 align:middle line:84%
and so on, going down the ladder
to iron oxides and sulfate.

00:38:27.100 --> 00:38:31.680 align:middle line:84%
So the order of reactions
that you would predict based

00:38:31.680 --> 00:38:34.120 align:middle line:84%
on the free energy
yield of the reactions

00:38:34.120 --> 00:38:40.220 align:middle line:84%
is oxygen first, nitrate second,
manganese oxides, iron oxides,

00:38:40.220 --> 00:38:41.280 align:middle line:90%
sulfate.

00:38:41.280 --> 00:38:44.560 align:middle line:84%
And if all those electron
acceptors are used up

00:38:44.560 --> 00:38:47.720 align:middle line:84%
and there's nothing left but
smaller organic molecules,

00:38:47.720 --> 00:38:51.640 align:middle line:90%
then organic matter--

00:38:51.640 --> 00:38:53.400 align:middle line:84%
carbon reacts with
organic carbon

00:38:53.400 --> 00:38:55.660 align:middle line:90%
and produces methane, actually.

00:38:55.660 --> 00:38:59.330 align:middle line:90%


00:38:59.330 --> 00:39:03.280 align:middle line:84%
So I've essentially
asserted that that's

00:39:03.280 --> 00:39:05.180 align:middle line:84%
the order in which
these reactions occur.

00:39:05.180 --> 00:39:06.800 align:middle line:90%
So how do we know?

00:39:06.800 --> 00:39:09.350 align:middle line:84%
We can find out the
rates of these reactions

00:39:09.350 --> 00:39:11.710 align:middle line:84%
and where in the sediment
column each of the reactions

00:39:11.710 --> 00:39:14.710 align:middle line:84%
occurs by measuring
benthic fluxes, so

00:39:14.710 --> 00:39:18.210 align:middle line:84%
exchanges across the
sediment-water interface

00:39:18.210 --> 00:39:20.510 align:middle line:84%
of dissolved
reactants and products

00:39:20.510 --> 00:39:22.190 align:middle line:90%
of these different processes.

00:39:22.190 --> 00:39:27.550 align:middle line:84%
And we can measure pore water
profiles of both reactants,

00:39:27.550 --> 00:39:31.310 align:middle line:84%
those being oxygen and
nitrate and sulfate,

00:39:31.310 --> 00:39:37.350 align:middle line:84%
and products of the
reaction, which can be CO2.

00:39:37.350 --> 00:39:41.870 align:middle line:90%
They can be nitrate or ammonia.

00:39:41.870 --> 00:39:45.470 align:middle line:84%
And we can also measure the
reduced electron acceptors,

00:39:45.470 --> 00:39:49.790 align:middle line:84%
especially manganese,
iron, and sulfide.

00:39:49.790 --> 00:39:52.070 align:middle line:84%
Don't use solid phase
measurements as a rule

00:39:52.070 --> 00:39:57.910 align:middle line:84%
to determine these reactions,
because, one, they're--

00:39:57.910 --> 00:40:00.750 align:middle line:84%
concentrations in the solid
phase tend to be quite high.

00:40:00.750 --> 00:40:03.750 align:middle line:84%
So solid phase profiles are very
insensitive to the occurrence

00:40:03.750 --> 00:40:05.190 align:middle line:90%
of these reactions.

00:40:05.190 --> 00:40:07.550 align:middle line:84%
And second is that
solids are mixed

00:40:07.550 --> 00:40:10.600 align:middle line:84%
by very complicated
particle mixing processes,

00:40:10.600 --> 00:40:13.000 align:middle line:84%
so it's very difficult to
interpret the profiles.

00:40:13.000 --> 00:40:15.860 align:middle line:84%
So we measure solute profiles
as sensitive indicators

00:40:15.860 --> 00:40:18.320 align:middle line:84%
of these reactions'
occurrence and their rates.

00:40:18.320 --> 00:40:21.620 align:middle line:90%


00:40:21.620 --> 00:40:26.020 align:middle line:84%
So what do these pore
water profiles look like?

00:40:26.020 --> 00:40:31.100 align:middle line:84%
What I've shown here is pore
water dissolved oxygen profiles

00:40:31.100 --> 00:40:34.700 align:middle line:84%
at three places in
the ocean, which

00:40:34.700 --> 00:40:38.500 align:middle line:84%
were intended to show the
range of oxygen profiles

00:40:38.500 --> 00:40:39.980 align:middle line:90%
that you would observe.

00:40:39.980 --> 00:40:43.060 align:middle line:84%
And all these measurements were
done by in-situ microelectrode

00:40:43.060 --> 00:40:44.140 align:middle line:90%
profiling.

00:40:44.140 --> 00:40:46.700 align:middle line:84%
These in-situ
instruments measure

00:40:46.700 --> 00:40:48.200 align:middle line:90%
oxygen electrochemically.

00:40:48.200 --> 00:40:50.380 align:middle line:84%
So you have an
oxygen-sensitive electrode

00:40:50.380 --> 00:40:54.780 align:middle line:84%
that's mounted on an instrument
that sits on the sea floor

00:40:54.780 --> 00:40:57.020 align:middle line:84%
and has a plate that
lowers down by very

00:40:57.020 --> 00:41:02.500 align:middle line:84%
small and well-controlled
steps into the sediments.

00:41:02.500 --> 00:41:05.420 align:middle line:84%
So you can use the electrode
that's attached to that plate

00:41:05.420 --> 00:41:08.520 align:middle line:84%
to measure dissolved oxygen
profile in the pore waters

00:41:08.520 --> 00:41:12.360 align:middle line:84%
on a very, very fine
depth scale of millimeters

00:41:12.360 --> 00:41:15.920 align:middle line:90%
or even less than millimeters.

00:41:15.920 --> 00:41:19.660 align:middle line:84%
So I've shown pore water oxygen
profiles at three locations.

00:41:19.660 --> 00:41:21.640 align:middle line:90%
One is an open ocean place.

00:41:21.640 --> 00:41:23.320 align:middle line:84%
It happens to be
in the Atlantic,

00:41:23.320 --> 00:41:25.680 align:middle line:84%
at a water depth
of 3,200 meters,

00:41:25.680 --> 00:41:28.980 align:middle line:84%
where the total organic
matter oxidation rate,

00:41:28.980 --> 00:41:31.720 align:middle line:84%
which is essentially equal to
the rain rate of organic matter

00:41:31.720 --> 00:41:34.600 align:middle line:84%
to the sea floor, was 14
micromoles per centimeter

00:41:34.600 --> 00:41:36.080 align:middle line:90%
squared per year.

00:41:36.080 --> 00:41:38.280 align:middle line:84%
And under these
conditions, you can

00:41:38.280 --> 00:41:41.480 align:middle line:84%
see that over a depth
of 7 centimeters

00:41:41.480 --> 00:41:44.960 align:middle line:84%
in the sediment column, oxygen
dropped from its bottom water

00:41:44.960 --> 00:41:48.660 align:middle line:84%
value of about 250
micromolar, down to about 100.

00:41:48.660 --> 00:41:50.960 align:middle line:84%
So there was lots
of oxygen left even

00:41:50.960 --> 00:41:53.480 align:middle line:84%
at a depth of 7 centimeters
in the sediments,

00:41:53.480 --> 00:41:58.580 align:middle line:84%
these are what we would call
deep sea oxic sediments.

00:41:58.580 --> 00:42:01.120 align:middle line:84%
The next one,
moving to the right,

00:42:01.120 --> 00:42:04.480 align:middle line:84%
is at a water depth of 600
meters on the Northwest Atlantic

00:42:04.480 --> 00:42:05.890 align:middle line:90%
continental margin.

00:42:05.890 --> 00:42:08.550 align:middle line:84%
And here, the rain rate of
organic matter to the sea floor

00:42:08.550 --> 00:42:11.850 align:middle line:84%
was about three times what it
was at that deep water site,

00:42:11.850 --> 00:42:15.110 align:middle line:84%
about 45 micromoles per
centimeter squared per year.

00:42:15.110 --> 00:42:17.590 align:middle line:84%
And here again, this
is an oxygen profile

00:42:17.590 --> 00:42:20.470 align:middle line:84%
measured with an in-situ
microelectrode profiler.

00:42:20.470 --> 00:42:21.967 align:middle line:84%
Starting in bottom
water, hitting

00:42:21.967 --> 00:42:23.550 align:middle line:84%
the sediment-water
interface, and then

00:42:23.550 --> 00:42:26.870 align:middle line:84%
the oxygen concentration in the
pore waters of the sediments

00:42:26.870 --> 00:42:30.310 align:middle line:84%
drops off to zero at a
depth of a little less

00:42:30.310 --> 00:42:31.990 align:middle line:90%
than 2 centimeters.

00:42:31.990 --> 00:42:33.990 align:middle line:84%
So now, with three
times the flux

00:42:33.990 --> 00:42:35.650 align:middle line:84%
of organic matter
to the seafloor,

00:42:35.650 --> 00:42:38.910 align:middle line:84%
there's enough organic matter
so that the oxygen is completely

00:42:38.910 --> 00:42:43.870 align:middle line:84%
consumed by a depth of about 1.5
centimeters in the sediments.

00:42:43.870 --> 00:42:46.470 align:middle line:84%
This would be the
oxygen penetration depth

00:42:46.470 --> 00:42:49.110 align:middle line:84%
that I showed on
that earlier plot.

00:42:49.110 --> 00:42:54.430 align:middle line:84%
And if we go to a more extreme
case of a shallow water

00:42:54.430 --> 00:42:56.870 align:middle line:84%
coastal sediment, where
the organic matter

00:42:56.870 --> 00:43:00.790 align:middle line:90%
flux to the seafloor is about--

00:43:00.790 --> 00:43:03.530 align:middle line:84%
well, 10 times what it
was at the margin site.

00:43:03.530 --> 00:43:06.970 align:middle line:84%
So now, 350 micromoles per
centimeter squared per year.

00:43:06.970 --> 00:43:10.510 align:middle line:84%
This is another in-situ
microelectrode oxygen profile.

00:43:10.510 --> 00:43:14.350 align:middle line:84%
The oxygen penetration depth
is about 2.5 millimeters.

00:43:14.350 --> 00:43:17.610 align:middle line:84%
So here, the sediments
become anoxic very close

00:43:17.610 --> 00:43:19.290 align:middle line:84%
to the interface,
because there's

00:43:19.290 --> 00:43:22.070 align:middle line:84%
a very large flux of organic
matter to the seafloor.

00:43:22.070 --> 00:43:27.530 align:middle line:90%


00:43:27.530 --> 00:43:34.050 align:middle line:84%
So that's what pore water
profiles in general look like.

00:43:34.050 --> 00:43:36.940 align:middle line:84%
So that you have a measurement
of the solute concentration

00:43:36.940 --> 00:43:39.190 align:middle line:84%
in the pore waters that are
included in the sediments,

00:43:39.190 --> 00:43:41.890 align:middle line:84%
and the concentration
changes with depth

00:43:41.890 --> 00:43:46.210 align:middle line:84%
going from the sediment-water
interface down.

00:43:46.210 --> 00:43:48.650 align:middle line:84%
How do you interpret
profiles like that?

00:43:48.650 --> 00:43:50.450 align:middle line:84%
First, we'll talk
a little bit about

00:43:50.450 --> 00:43:52.410 align:middle line:90%
a qualitative interpretation.

00:43:52.410 --> 00:43:54.950 align:middle line:84%
If we assume that the
system is in steady state,

00:43:54.950 --> 00:43:56.370 align:middle line:84%
so that the
concentration profile

00:43:56.370 --> 00:44:00.970 align:middle line:84%
is not changing
over time, then--

00:44:00.970 --> 00:44:04.380 align:middle line:84%
well, also assume constant
porosity and diffusivity,

00:44:04.380 --> 00:44:06.840 align:middle line:90%
but we won't worry about that.

00:44:06.840 --> 00:44:08.640 align:middle line:84%
So what I've shown
on the left-hand side

00:44:08.640 --> 00:44:11.760 align:middle line:84%
is a hypothetical solute
profile of a solute that

00:44:11.760 --> 00:44:13.360 align:middle line:84%
happens to be
increasing with depth

00:44:13.360 --> 00:44:15.480 align:middle line:84%
below the sediment-water
interface.

00:44:15.480 --> 00:44:22.720 align:middle line:84%
And we'll consider what happens
between depth XA and depth XB.

00:44:22.720 --> 00:44:27.640 align:middle line:84%
If we draw a straight line
between the concentration points

00:44:27.640 --> 00:44:30.160 align:middle line:84%
corresponding to
those two depths--

00:44:30.160 --> 00:44:32.320 align:middle line:84%
it's shown in the
dashed line here.

00:44:32.320 --> 00:44:36.860 align:middle line:84%
And what you can see is that at
every depth over that interval,

00:44:36.860 --> 00:44:38.920 align:middle line:84%
the actual concentration
of the solute

00:44:38.920 --> 00:44:42.600 align:middle line:84%
is greater than
the concentration

00:44:42.600 --> 00:44:44.520 align:middle line:90%
along that straight line.

00:44:44.520 --> 00:44:46.560 align:middle line:84%
Now, the concentration
along that straight line

00:44:46.560 --> 00:44:49.680 align:middle line:84%
is what you'd get if you
just mixed water from point A

00:44:49.680 --> 00:44:53.920 align:middle line:84%
and from point B. The fact that
the concentration is higher

00:44:53.920 --> 00:44:56.520 align:middle line:84%
at every point tells you
that over this interval,

00:44:56.520 --> 00:44:59.560 align:middle line:84%
the solute is being added to
the pore waters over that depth

00:44:59.560 --> 00:45:00.800 align:middle line:90%
interval.

00:45:00.800 --> 00:45:05.060 align:middle line:84%
If we take the opposite
case, and here,

00:45:05.060 --> 00:45:06.900 align:middle line:84%
a solute that happens
to be decreasing

00:45:06.900 --> 00:45:09.340 align:middle line:84%
with depth below the
sediment-water interface.

00:45:09.340 --> 00:45:14.060 align:middle line:84%
Again, point A,
depth A to depth B.

00:45:14.060 --> 00:45:17.980 align:middle line:84%
And if we connect the points on
the concentration versus depth

00:45:17.980 --> 00:45:20.540 align:middle line:84%
profile by a straight
line, we find

00:45:20.540 --> 00:45:24.260 align:middle line:84%
that the concentration of this
solute is less at every depth

00:45:24.260 --> 00:45:26.320 align:middle line:84%
than it would be along
that straight line.

00:45:26.320 --> 00:45:28.340 align:middle line:84%
The straight line
is the mixing line,

00:45:28.340 --> 00:45:31.460 align:middle line:84%
which is the line that you
would get if the water were

00:45:31.460 --> 00:45:33.820 align:middle line:90%
being mixed with no reaction.

00:45:33.820 --> 00:45:36.140 align:middle line:84%
And since the concentration
of this solute

00:45:36.140 --> 00:45:40.260 align:middle line:84%
is less at every depth
than the concentration

00:45:40.260 --> 00:45:42.740 align:middle line:84%
along this mixing
line, then the solute

00:45:42.740 --> 00:45:47.640 align:middle line:84%
must be removed from pore
waters over this depth interval.

00:45:47.640 --> 00:45:52.260 align:middle line:84%
The reason for going through
of complicated picture,

00:45:52.260 --> 00:45:55.240 align:middle line:84%
rather than just saying, oh, the
solute is increasing with depth,

00:45:55.240 --> 00:45:56.860 align:middle line:84%
therefore, it must
be produced, is

00:45:56.860 --> 00:46:00.290 align:middle line:84%
because you can have situations
where the solute is increasing,

00:46:00.290 --> 00:46:02.590 align:middle line:84%
but over some depth
range in its profile,

00:46:02.590 --> 00:46:04.070 align:middle line:90%
it's actually being consumed.

00:46:04.070 --> 00:46:08.650 align:middle line:84%
And in that case, you could
apply this same criterion.

00:46:08.650 --> 00:46:11.810 align:middle line:84%
Draw a straight line between
the points bounding the interval

00:46:11.810 --> 00:46:13.090 align:middle line:90%
you're interested in.

00:46:13.090 --> 00:46:16.890 align:middle line:84%
If the concentration profile
falls above that straight line,

00:46:16.890 --> 00:46:18.950 align:middle line:84%
then the solute must be
added over the interval.

00:46:18.950 --> 00:46:20.550 align:middle line:84%
If it falls below
that straight line,

00:46:20.550 --> 00:46:22.650 align:middle line:84%
then it must be consumed
over the interval.

00:46:22.650 --> 00:46:25.210 align:middle line:84%
So that's the basis for
qualitative interpretations

00:46:25.210 --> 00:46:28.250 align:middle line:90%
of pore water profiles.

00:46:28.250 --> 00:46:29.570 align:middle line:90%
Why are these useful?

00:46:29.570 --> 00:46:32.850 align:middle line:84%
Well, I've shown you what pore
water oxygen profiles look like.

00:46:32.850 --> 00:46:36.210 align:middle line:84%
Here's a hypothetical picture
of what some other solutes might

00:46:36.210 --> 00:46:37.770 align:middle line:90%
look like as well.

00:46:37.770 --> 00:46:42.530 align:middle line:84%
So in the dashed line up here is
a hypothetical pore water oxygen

00:46:42.530 --> 00:46:44.050 align:middle line:90%
profile.

00:46:44.050 --> 00:46:47.290 align:middle line:84%
And over the whole
range of this profile,

00:46:47.290 --> 00:46:49.730 align:middle line:84%
if you apply that
straight-line test,

00:46:49.730 --> 00:46:52.370 align:middle line:84%
you'll find that oxygen is
consumed over that interval.

00:46:52.370 --> 00:46:55.730 align:middle line:84%
Over this interval where
oxygen is consumed,

00:46:55.730 --> 00:46:58.210 align:middle line:84%
if you apply that same
straight-line test

00:46:58.210 --> 00:47:00.520 align:middle line:84%
to the nitrate
profile, you'll find

00:47:00.520 --> 00:47:02.700 align:middle line:84%
that in the region where
oxygen is being consumed,

00:47:02.700 --> 00:47:04.440 align:middle line:90%
nitrate is produced.

00:47:04.440 --> 00:47:07.560 align:middle line:84%
Remember that I said that when
oxygen is used as an electron

00:47:07.560 --> 00:47:09.840 align:middle line:84%
acceptor for organic
matter oxidation,

00:47:09.840 --> 00:47:13.360 align:middle line:84%
the organic nitrogen is
oxidized all the way to nitrate.

00:47:13.360 --> 00:47:16.000 align:middle line:90%
So nitrate is produced.

00:47:16.000 --> 00:47:19.720 align:middle line:84%
Below this interval, the
nitrate profile in this case

00:47:19.720 --> 00:47:22.000 align:middle line:90%
has a straight line component.

00:47:22.000 --> 00:47:24.140 align:middle line:84%
That means that over
that depth interval,

00:47:24.140 --> 00:47:27.080 align:middle line:84%
the nitrate would be neither
consumed nor produced.

00:47:27.080 --> 00:47:30.640 align:middle line:90%
It's just diffusing down.

00:47:30.640 --> 00:47:35.000 align:middle line:84%
It shows manganese profile where
if you apply the same tests,

00:47:35.000 --> 00:47:40.460 align:middle line:84%
manganese is produced over a
depth region in the sediments.

00:47:40.460 --> 00:47:42.763 align:middle line:84%
But at the very
top of the profile,

00:47:42.763 --> 00:47:44.680 align:middle line:84%
you note that manganese
doesn't go all the way

00:47:44.680 --> 00:47:45.980 align:middle line:90%
to the sediment-water interface.

00:47:45.980 --> 00:47:48.355 align:middle line:84%
Instead, there's a region at
the top of the profile where

00:47:48.355 --> 00:47:50.840 align:middle line:84%
the manganese that's
diffusing up from below

00:47:50.840 --> 00:47:54.440 align:middle line:84%
is removed from the pore waters
by oxidation to manganese

00:47:54.440 --> 00:47:55.180 align:middle line:90%
oxides.

00:47:55.180 --> 00:47:59.100 align:middle line:84%
And you can apply
these same tests.

00:47:59.100 --> 00:48:00.980 align:middle line:84%
But the main point
of this is that you

00:48:00.980 --> 00:48:03.700 align:middle line:84%
can look at a suite of
pore water profiles,

00:48:03.700 --> 00:48:09.020 align:middle line:84%
analyze the depth intervals over
which the solutes are either

00:48:09.020 --> 00:48:11.740 align:middle line:84%
produced or consumed,
and use that to infer

00:48:11.740 --> 00:48:14.740 align:middle line:84%
the depth in the sediments over
which the reactions that either

00:48:14.740 --> 00:48:17.000 align:middle line:84%
produce or consume
those solutes occur.

00:48:17.000 --> 00:48:19.900 align:middle line:90%


00:48:19.900 --> 00:48:23.220 align:middle line:90%
So if we go on from that--

00:48:23.220 --> 00:48:24.920 align:middle line:84%
we're going to do
that in just a minute.

00:48:24.920 --> 00:48:27.060 align:middle line:84%
But before we do,
you should know

00:48:27.060 --> 00:48:30.120 align:middle line:84%
that people don't just look at
them and infer reaction zones.

00:48:30.120 --> 00:48:33.780 align:middle line:84%
They also use pore water
profiles of solutes

00:48:33.780 --> 00:48:35.860 align:middle line:90%
to calculate reaction rates.

00:48:35.860 --> 00:48:38.820 align:middle line:84%
And they do that by
calculating fluxes.

00:48:38.820 --> 00:48:43.900 align:middle line:84%
And in this case, we've assumed
it's a simple sediment where

00:48:43.900 --> 00:48:46.260 align:middle line:84%
the transport
process is diffusion

00:48:46.260 --> 00:48:48.200 align:middle line:90%
of solutes in the pore waters.

00:48:48.200 --> 00:48:51.020 align:middle line:84%
And the diffusion
occurs perpendicular

00:48:51.020 --> 00:48:52.400 align:middle line:90%
to the sediment water interface.

00:48:52.400 --> 00:48:56.490 align:middle line:90%
So it occurs up and down

00:48:56.490 --> 00:49:01.490 align:middle line:84%
Now, you probably haven't
seen Fick's first law.

00:49:01.490 --> 00:49:04.310 align:middle line:84%
So this is how you
calculate a diffusive flux.

00:49:04.310 --> 00:49:07.250 align:middle line:90%


00:49:07.250 --> 00:49:09.170 align:middle line:84%
There is a diffusive
flux if there

00:49:09.170 --> 00:49:12.250 align:middle line:90%
is a concentration gradient.

00:49:12.250 --> 00:49:14.170 align:middle line:84%
So in this case, the
concentration gradient

00:49:14.170 --> 00:49:19.370 align:middle line:84%
is the change in
concentration with depth.

00:49:19.370 --> 00:49:21.770 align:middle line:84%
And there's a
proportionality constant

00:49:21.770 --> 00:49:25.930 align:middle line:84%
that you multiply that gradient
by to calculate the flux,

00:49:25.930 --> 00:49:28.130 align:middle line:84%
and that's the
diffusion coefficient.

00:49:28.130 --> 00:49:32.330 align:middle line:84%
So the diffusive flux in water
equals diffusion coefficient

00:49:32.330 --> 00:49:35.010 align:middle line:84%
multiplied by the
concentration gradient.

00:49:35.010 --> 00:49:39.890 align:middle line:84%
And this minus sign means that
the diffusive transport is down

00:49:39.890 --> 00:49:41.350 align:middle line:90%
the concentration gradient.

00:49:41.350 --> 00:49:44.810 align:middle line:84%
So for instance, if you look at
this profile, from that point

00:49:44.810 --> 00:49:47.810 align:middle line:84%
there is this point
here, the concentration

00:49:47.810 --> 00:49:50.230 align:middle line:84%
decreases going toward the
sediment-water interface.

00:49:50.230 --> 00:49:52.050 align:middle line:84%
That means the
diffusive flux is toward

00:49:52.050 --> 00:49:54.570 align:middle line:90%
the sediment-water interface.

00:49:54.570 --> 00:49:56.070 align:middle line:84%
There's an additional
thing you have

00:49:56.070 --> 00:49:57.790 align:middle line:84%
to worry about in
sediments, which

00:49:57.790 --> 00:50:02.070 align:middle line:84%
is, How much of the area
actually of sediments

00:50:02.070 --> 00:50:05.170 align:middle line:84%
is water compared to
how much is solids?

00:50:05.170 --> 00:50:09.110 align:middle line:84%
which are sediment grains,
because the solutes are only

00:50:09.110 --> 00:50:12.110 align:middle line:90%
diffusing through the water.

00:50:12.110 --> 00:50:14.750 align:middle line:84%
There's a factor
called the porosity

00:50:14.750 --> 00:50:17.870 align:middle line:84%
that you have to multiply this
flux by to account for the fact

00:50:17.870 --> 00:50:21.590 align:middle line:84%
that part of the path is
blocked by sediment grains.

00:50:21.590 --> 00:50:23.830 align:middle line:84%
So the solutes that are
diffusing through the water

00:50:23.830 --> 00:50:27.670 align:middle line:84%
can only diffuse through part
of the cross-sectional area.

00:50:27.670 --> 00:50:28.670 align:middle line:90%
Is that clear?

00:50:28.670 --> 00:50:31.430 align:middle line:84%
So the diffusive flux
of a solute in sediments

00:50:31.430 --> 00:50:35.270 align:middle line:84%
is equal to the porosity, which
is the volume fraction of water

00:50:35.270 --> 00:50:38.270 align:middle line:84%
in the sediments multiplied
by diffusion coefficient

00:50:38.270 --> 00:50:44.723 align:middle line:84%
for the solute multiplied by
the concentration gradient.

00:50:44.723 --> 00:50:49.470 align:middle line:84%
And to take this just
one step further,

00:50:49.470 --> 00:50:51.750 align:middle line:84%
this is actually
a typical profile

00:50:51.750 --> 00:50:57.180 align:middle line:84%
for the nitrate concentration
in sediments, where,

00:50:57.180 --> 00:51:02.340 align:middle line:84%
in the surface of the sediment,
organic matter is oxidized

00:51:02.340 --> 00:51:05.780 align:middle line:84%
by oxygen, and it continues to
be oxidized by oxygen until all

00:51:05.780 --> 00:51:08.340 align:middle line:90%
the oxygen is used up.

00:51:08.340 --> 00:51:10.780 align:middle line:84%
When the organic matter
is oxidized by oxygen,

00:51:10.780 --> 00:51:13.160 align:middle line:84%
nitrate is released
into the pore waters.

00:51:13.160 --> 00:51:16.580 align:middle line:84%
So if you first do that
quantitative interpretation

00:51:16.580 --> 00:51:21.860 align:middle line:84%
I talked about, you find
that this dashed line here

00:51:21.860 --> 00:51:26.163 align:middle line:84%
is the layer in the sediments in
which nitrate is being produced.

00:51:26.163 --> 00:51:27.580 align:middle line:84%
It's actually
important to realize

00:51:27.580 --> 00:51:31.580 align:middle line:84%
that it goes a little bit
below the nitrate maximum.

00:51:31.580 --> 00:51:34.260 align:middle line:84%
And the layer below that is
the layer in which nitrate

00:51:34.260 --> 00:51:36.500 align:middle line:90%
is consumed by denitrification.

00:51:36.500 --> 00:51:40.380 align:middle line:84%
We can calculate the
rate at which nitrate

00:51:40.380 --> 00:51:46.220 align:middle line:84%
is produced in this oxic layer
by using a mass balance, where

00:51:46.220 --> 00:51:48.900 align:middle line:84%
we say the rate of
production in the layer

00:51:48.900 --> 00:51:52.720 align:middle line:84%
has to be equal to the
net flux out of the layer.

00:51:52.720 --> 00:51:56.040 align:middle line:84%
If the concentration is constant
within that sediment layer,

00:51:56.040 --> 00:51:58.480 align:middle line:84%
then the fluxes out
have to be exactly

00:51:58.480 --> 00:52:00.860 align:middle line:84%
equal to the rate at which
the solute is produced.

00:52:00.860 --> 00:52:05.080 align:middle line:84%
So if we calculate the
diffusive flux up out

00:52:05.080 --> 00:52:08.480 align:middle line:84%
of the sediments at
point 1, we calculate

00:52:08.480 --> 00:52:12.560 align:middle line:84%
the rate at which nitrate is
consumed by denitrification

00:52:12.560 --> 00:52:15.995 align:middle line:84%
at point 2, then the sum of--
the absolute values of those two

00:52:15.995 --> 00:52:18.120 align:middle line:84%
fluxes has to be equal to
the rate at which nitrate

00:52:18.120 --> 00:52:20.720 align:middle line:90%
is produced in this oxic layer.

00:52:20.720 --> 00:52:24.880 align:middle line:84%
And we can use stoichiometry
from that calculated nitrate

00:52:24.880 --> 00:52:27.280 align:middle line:84%
flux to tell us the rate
of organic matter oxidation

00:52:27.280 --> 00:52:32.520 align:middle line:84%
by oxygen But the point of
this is just to show you

00:52:32.520 --> 00:52:33.560 align:middle line:90%
how it's done.

00:52:33.560 --> 00:52:35.160 align:middle line:84%
And if you're
really lucky, Scott

00:52:35.160 --> 00:52:39.470 align:middle line:84%
will come up with a problem
that makes you do it.

00:52:39.470 --> 00:52:41.220 align:middle line:84%
AUDIENCE: [INAUDIBLE]
on your own problem.

00:52:41.220 --> 00:52:45.150 align:middle line:90%


00:52:45.150 --> 00:52:47.520 align:middle line:84%
PROFESSOR: So I've
essentially asserted

00:52:47.520 --> 00:52:50.950 align:middle line:84%
that the order in which electron
acceptors are used for oxidation

00:52:50.950 --> 00:52:52.550 align:middle line:84%
processes in the
sediments is oxygen

00:52:52.550 --> 00:52:57.270 align:middle line:84%
first, nitrate
second, and manganese,

00:52:57.270 --> 00:53:00.070 align:middle line:90%
then iron, then sulfate.

00:53:00.070 --> 00:53:03.615 align:middle line:84%
So is there evidence that this
sequence is actually followed?

00:53:03.615 --> 00:53:05.990 align:middle line:84%
First, you have to go to a
place where the organic matter

00:53:05.990 --> 00:53:09.830 align:middle line:84%
flux is large enough so that
the oxygen is completely

00:53:09.830 --> 00:53:11.330 align:middle line:90%
consumed in the sediments.

00:53:11.330 --> 00:53:13.387 align:middle line:84%
That's the first thing
that you have to do.

00:53:13.387 --> 00:53:15.470 align:middle line:84%
If you go to such a place
with a large enough flux

00:53:15.470 --> 00:53:19.590 align:middle line:84%
of organic matter, you could
measure an oxygen profile,

00:53:19.590 --> 00:53:22.790 align:middle line:84%
like here, and you
find that the oxygen

00:53:22.790 --> 00:53:24.710 align:middle line:84%
decreases from its
bottom water value

00:53:24.710 --> 00:53:27.750 align:middle line:84%
and goes to zero at
about 1 centimeter depth.

00:53:27.750 --> 00:53:30.670 align:middle line:84%
If, at the same place, you
measure a pore water nitrate

00:53:30.670 --> 00:53:34.030 align:middle line:84%
profile, and here, zero is
the sediment-water interface.

00:53:34.030 --> 00:53:35.750 align:middle line:84%
And that's measuring
the concentration

00:53:35.750 --> 00:53:38.990 align:middle line:84%
of nitrate in the pore waters as
you go down into the sediments.

00:53:38.990 --> 00:53:43.310 align:middle line:84%
And the depth scale here
is from 0 to 5 centimeters.

00:53:43.310 --> 00:53:47.950 align:middle line:84%
See that nitrate is produced
in this upper layer,

00:53:47.950 --> 00:53:51.260 align:middle line:84%
and then immediately below
that layer in which nitrate

00:53:51.260 --> 00:53:53.820 align:middle line:84%
is produced, the
profile shape tells

00:53:53.820 --> 00:53:55.560 align:middle line:90%
you nitrate is being consumed.

00:53:55.560 --> 00:53:58.460 align:middle line:84%
So just below this oxic
layer of the sediments

00:53:58.460 --> 00:54:01.940 align:middle line:84%
is a layer in which nitrate
is used by denitrification

00:54:01.940 --> 00:54:03.660 align:middle line:90%
to oxidize organic matter.

00:54:03.660 --> 00:54:07.660 align:middle line:84%
If you go a little bit
deeper, and here the indicator

00:54:07.660 --> 00:54:11.620 align:middle line:84%
is pore water dissolved ammonia
concentrations-- remember,

00:54:11.620 --> 00:54:13.660 align:middle line:84%
ammonia is a product
of the oxidation

00:54:13.660 --> 00:54:18.840 align:middle line:84%
of organic matter by
manganese, iron, and sulfate.

00:54:18.840 --> 00:54:22.940 align:middle line:84%
You see that the pore
water ammonia profile

00:54:22.940 --> 00:54:24.780 align:middle line:84%
shows that ammonia
is actually consumed

00:54:24.780 --> 00:54:29.060 align:middle line:84%
in the sediments above a depth
of about, oh, 3 centimeters

00:54:29.060 --> 00:54:29.860 align:middle line:90%
or so.

00:54:29.860 --> 00:54:31.500 align:middle line:84%
But below that,
the profile shape

00:54:31.500 --> 00:54:33.237 align:middle line:84%
tells you that
ammonia is produced.

00:54:33.237 --> 00:54:35.320 align:middle line:84%
If you look at where nitrate
goes to zero up here,

00:54:35.320 --> 00:54:37.340 align:middle line:84%
it's right about
at 3 centimeters.

00:54:37.340 --> 00:54:40.140 align:middle line:84%
So you have a pretty
distinct sequence

00:54:40.140 --> 00:54:43.900 align:middle line:84%
where oxygen is consumed first,
then nitrate is consumed,

00:54:43.900 --> 00:54:46.940 align:middle line:84%
then reactions which release
ammonia into the pore water

00:54:46.940 --> 00:54:47.560 align:middle line:90%
occur.

00:54:47.560 --> 00:54:51.720 align:middle line:84%
So that's some evidence for
the sequence of reactions

00:54:51.720 --> 00:54:54.920 align:middle line:90%
which I asserted earlier.

00:54:54.920 --> 00:54:59.720 align:middle line:84%
And for completeness sake, I'll
show you an extreme example

00:54:59.720 --> 00:55:01.240 align:middle line:90%
of a coastal sediment.

00:55:01.240 --> 00:55:05.620 align:middle line:84%
Now, remember the rates of
organic matter oxidation,

00:55:05.620 --> 00:55:07.720 align:middle line:84%
or the flux of organic
matter to the seafloor,

00:55:07.720 --> 00:55:11.520 align:middle line:84%
at a deep sea site, is something
like 15 micromoles of carbon

00:55:11.520 --> 00:55:13.400 align:middle line:90%
per square centimeter per year.

00:55:13.400 --> 00:55:16.520 align:middle line:84%
On a continental margin site,
it might be as much as 50.

00:55:16.520 --> 00:55:19.960 align:middle line:84%
But here, these are results
from a site which is actually

00:55:19.960 --> 00:55:23.000 align:middle line:84%
in Boston Harbor,
where the rain rate

00:55:23.000 --> 00:55:25.880 align:middle line:84%
of organic matter
to the sediments

00:55:25.880 --> 00:55:28.880 align:middle line:84%
is about 850
micromoles of carbon.

00:55:28.880 --> 00:55:32.200 align:middle line:84%
So the oxygen penetration
depth at this site

00:55:32.200 --> 00:55:34.420 align:middle line:84%
is on the order
of 2 millimeters.

00:55:34.420 --> 00:55:36.120 align:middle line:90%
It's very shallow.

00:55:36.120 --> 00:55:39.120 align:middle line:84%
Below that, there's
essentially no nitrate visible,

00:55:39.120 --> 00:55:41.180 align:middle line:84%
because first, this is
a very shallow water.

00:55:41.180 --> 00:55:43.200 align:middle line:84%
It's in about 5
meters water depth.

00:55:43.200 --> 00:55:45.160 align:middle line:84%
So there's very little
nitrate present there,

00:55:45.160 --> 00:55:46.880 align:middle line:84%
because it's in
the euphotic zone.

00:55:46.880 --> 00:55:50.390 align:middle line:84%
And second, because
denitrification is so fast

00:55:50.390 --> 00:55:53.230 align:middle line:84%
that the nitrate that's
produced by oxic organic matter

00:55:53.230 --> 00:55:56.410 align:middle line:84%
decomposition is essentially
immediately used up.

00:55:56.410 --> 00:56:01.870 align:middle line:84%
And so you go right into
the use of manganese

00:56:01.870 --> 00:56:03.330 align:middle line:90%
as an electron acceptor.

00:56:03.330 --> 00:56:04.950 align:middle line:90%
And you can see that manganese--

00:56:04.950 --> 00:56:06.750 align:middle line:90%
there's the bottom water value.

00:56:06.750 --> 00:56:10.950 align:middle line:84%
If my arrow wouldn't keep
going away, I'd show it to you.

00:56:10.950 --> 00:56:14.310 align:middle line:84%
The bottom water value
is very close to zero.

00:56:14.310 --> 00:56:16.590 align:middle line:84%
And right away, in the
first pore water sample,

00:56:16.590 --> 00:56:18.730 align:middle line:84%
there's dissolved
manganese present.

00:56:18.730 --> 00:56:20.750 align:middle line:84%
So manganese is used
as an electron acceptor

00:56:20.750 --> 00:56:23.030 align:middle line:84%
right near the
sediment-water interface.

00:56:23.030 --> 00:56:26.310 align:middle line:84%
If you look closely
at this iron profile,

00:56:26.310 --> 00:56:29.245 align:middle line:84%
see there's a very thin
layer-- it's very hard to see.

00:56:29.245 --> 00:56:30.870 align:middle line:84%
But if I expanded
it, you'd see there's

00:56:30.870 --> 00:56:34.470 align:middle line:84%
very thin layer where iron is
consumed, diffuses up, and is

00:56:34.470 --> 00:56:35.530 align:middle line:90%
oxidized.

00:56:35.530 --> 00:56:38.990 align:middle line:90%
It can be oxidized by manganese.

00:56:38.990 --> 00:56:42.190 align:middle line:84%
And below that, iron is
released into the pore waters

00:56:42.190 --> 00:56:47.290 align:middle line:84%
by decomposition of organic
matter using iron oxides.

00:56:47.290 --> 00:56:50.628 align:middle line:84%
One point of interest, if you're
used to looking at water column

00:56:50.628 --> 00:56:52.170 align:middle line:84%
data, you think of
manganese and iron

00:56:52.170 --> 00:56:56.270 align:middle line:84%
as trace metals with
nanomolar concentrations.

00:56:56.270 --> 00:56:59.010 align:middle line:84%
If you look at these
reducing sediments,

00:56:59.010 --> 00:57:01.570 align:middle line:84%
manganese concentrations are
in the tens of micromoles

00:57:01.570 --> 00:57:04.810 align:middle line:84%
per liter, and iron actually
reaches very nearly millimolar

00:57:04.810 --> 00:57:05.710 align:middle line:90%
concentrations.

00:57:05.710 --> 00:57:11.050 align:middle line:84%
So they're not trace metals in
these sedimentary pore waters.

00:57:11.050 --> 00:57:14.670 align:middle line:84%
We go down here and look
at the sulfate profile--

00:57:14.670 --> 00:57:16.150 align:middle line:90%
don't look at the open circles.

00:57:16.150 --> 00:57:17.530 align:middle line:90%
That's a different place.

00:57:17.530 --> 00:57:19.950 align:middle line:84%
If you look at these
triangles, see,

00:57:19.950 --> 00:57:24.810 align:middle line:84%
sulfate reduction begins at a
depth of about 2 and 1/2 or 3

00:57:24.810 --> 00:57:28.530 align:middle line:84%
centimeters, which
is right about there.

00:57:28.530 --> 00:57:31.090 align:middle line:84%
So sulfate reduction and
iron reduction actually

00:57:31.090 --> 00:57:35.610 align:middle line:84%
occur in overlapping regions of
the sediments, which is actually

00:57:35.610 --> 00:57:39.210 align:middle line:84%
what you would predict if
you calculate the free energy

00:57:39.210 --> 00:57:42.830 align:middle line:90%
yield of the reactions.

00:57:42.830 --> 00:57:44.600 align:middle line:84%
And you see an
interesting thing--

00:57:44.600 --> 00:57:46.480 align:middle line:84%
so again, the
sequence is followed,

00:57:46.480 --> 00:57:49.360 align:middle line:84%
where you have
oxic decomposition,

00:57:49.360 --> 00:57:51.440 align:middle line:84%
nitrate's not
important here-- then

00:57:51.440 --> 00:57:54.320 align:middle line:84%
decomposition using manganese
oxides and iron oxides

00:57:54.320 --> 00:57:55.340 align:middle line:90%
and sulfate.

00:57:55.340 --> 00:57:57.880 align:middle line:84%
But you see an
interesting thing,

00:57:57.880 --> 00:58:01.260 align:middle line:84%
if you look at pore water
dissolved sulfide profiles,

00:58:01.260 --> 00:58:03.480 align:middle line:84%
where I've said that
sulfide is the reduced

00:58:03.480 --> 00:58:06.440 align:middle line:90%
product of sulfate reduction.

00:58:06.440 --> 00:58:09.320 align:middle line:84%
But if you look at this, you
see sulfide concentrations

00:58:09.320 --> 00:58:13.600 align:middle line:84%
are pegged at zero until
the depth at which the iron

00:58:13.600 --> 00:58:15.480 align:middle line:90%
disappears from pore waters.

00:58:15.480 --> 00:58:20.240 align:middle line:84%
And then sulfide concentrations
increase pretty dramatically.

00:58:20.240 --> 00:58:23.960 align:middle line:84%
The reason for that is that
sulfate reduction and iron

00:58:23.960 --> 00:58:27.520 align:middle line:84%
reduction occur over pretty
much the same interval

00:58:27.520 --> 00:58:28.760 align:middle line:90%
in these sediments.

00:58:28.760 --> 00:58:33.760 align:middle line:84%
And that iron, reduced iron,
has very insoluble sulfides.

00:58:33.760 --> 00:58:36.720 align:middle line:84%
And so the sulfide is
produced by sulfate reduction

00:58:36.720 --> 00:58:38.760 align:middle line:84%
reacts with the iron
and precipitates out

00:58:38.760 --> 00:58:42.240 align:middle line:84%
as iron sulfides until
all the iron is gone.

00:58:42.240 --> 00:58:46.270 align:middle line:84%
And then sulfide starts to be
released into the pore waters.

00:58:46.270 --> 00:58:48.770 align:middle line:84%
Anyway, this is an example--
so I've shown you two examples.

00:58:48.770 --> 00:58:55.230 align:middle line:84%
One continental margin site and
one extreme coastal sediment

00:58:55.230 --> 00:58:58.890 align:middle line:84%
example, showing you the range
of conditions you'd observe.

00:58:58.890 --> 00:59:02.550 align:middle line:84%
And if you remember back to
the very first oxygen profile,

00:59:02.550 --> 00:59:05.030 align:middle line:84%
I showed you an oxygen
profile in an oxic sediment

00:59:05.030 --> 00:59:07.290 align:middle line:84%
where it never even got
close to going to zero.

00:59:07.290 --> 00:59:09.050 align:middle line:90%
That's a deep sea condition.

00:59:09.050 --> 00:59:14.470 align:middle line:90%


00:59:14.470 --> 00:59:17.190 align:middle line:84%
To summarize this little section
about electron acceptors that

00:59:17.190 --> 00:59:19.630 align:middle line:84%
are used for organic
matter oxidation,

00:59:19.630 --> 00:59:26.270 align:middle line:84%
I've put together a table which
shows, for, first, this table up

00:59:26.270 --> 00:59:30.032 align:middle line:84%
here, electron acceptors
in pelagic sediments.

00:59:30.032 --> 00:59:31.990 align:middle line:84%
So those are away from
the continental margins,

00:59:31.990 --> 00:59:33.350 align:middle line:90%
out in the open ocean.

00:59:33.350 --> 00:59:36.830 align:middle line:84%
And these are all
examples from the top tour

00:59:36.830 --> 00:59:40.110 align:middle line:84%
from the equatorial
Pacific and the last ones

00:59:40.110 --> 00:59:44.170 align:middle line:84%
from the equatorial Atlantic,
with organic matter oxidation

00:59:44.170 --> 00:59:48.160 align:middle line:84%
rates that are pretty
low, 12 to 20 micromoles

00:59:48.160 --> 00:59:49.910 align:middle line:84%
of carbon per centimeter
squared per year.

00:59:49.910 --> 00:59:52.170 align:middle line:84%
So those are typical
values for the deep sea.

00:59:52.170 --> 00:59:54.650 align:middle line:84%
And you find that
under these conditions,

00:59:54.650 --> 00:59:56.370 align:middle line:84%
essentially all
the organic matter

00:59:56.370 --> 00:59:59.930 align:middle line:84%
oxidation occurs using oxygen
as an electron acceptor.

00:59:59.930 --> 01:00:01.770 align:middle line:90%
It's the first one used.

01:00:01.770 --> 01:00:03.970 align:middle line:84%
There's plenty of it
in the bottom water

01:00:03.970 --> 01:00:05.570 align:middle line:90%
in all these locations.

01:00:05.570 --> 01:00:09.290 align:middle line:84%
And essentially, what happens
is the supply of organic matter

01:00:09.290 --> 01:00:11.990 align:middle line:84%
runs out before the
oxygen runs out.

01:00:11.990 --> 01:00:15.370 align:middle line:84%
So nearly all the organic
matter decomposition

01:00:15.370 --> 01:00:17.590 align:middle line:84%
uses oxygen as an
electron acceptor,

01:00:17.590 --> 01:00:19.370 align:middle line:90%
just like in the water column.

01:00:19.370 --> 01:00:22.090 align:middle line:84%
But if you go to places
on continental margins

01:00:22.090 --> 01:00:25.290 align:middle line:84%
where the supply of organic
matter to the seafloor

01:00:25.290 --> 01:00:28.250 align:middle line:84%
is great enough so that
all the oxygen is used up,

01:00:28.250 --> 01:00:30.410 align:middle line:84%
then you get a little
bit different story.

01:00:30.410 --> 01:00:33.890 align:middle line:84%
And here, I've got examples
from the North Atlantic Ocean

01:00:33.890 --> 01:00:36.050 align:middle line:84%
and from the North
Pacific Ocean.

01:00:36.050 --> 01:00:39.250 align:middle line:84%
In the North Atlantic
Ocean, oxygen still

01:00:39.250 --> 01:00:43.440 align:middle line:84%
accounts for 70% to 95%
of all the organic matter

01:00:43.440 --> 01:00:45.520 align:middle line:90%
oxidation in the sediments.

01:00:45.520 --> 01:00:49.280 align:middle line:84%
Nitrate accounts for a little
bit, and of the remainder,

01:00:49.280 --> 01:00:52.080 align:middle line:84%
most of it is accounted
for by sulfate reduction.

01:00:52.080 --> 01:00:54.120 align:middle line:84%
So under these continental
margin conditions

01:00:54.120 --> 01:00:57.360 align:middle line:84%
in the Atlantic, oxygen is the
main most important electron

01:00:57.360 --> 01:01:00.040 align:middle line:90%
acceptor, followed by nitrate.

01:01:00.040 --> 01:01:02.340 align:middle line:84%
Manganese and iron have a
very limited importance,

01:01:02.340 --> 01:01:04.780 align:middle line:84%
but sulfate reduction
can be significant.

01:01:04.780 --> 01:01:09.880 align:middle line:84%
If you go to the
Northeast Pacific Ocean,

01:01:09.880 --> 01:01:14.080 align:middle line:84%
the story is a little
bit different because--

01:01:14.080 --> 01:01:15.300 align:middle line:90%
why would it be different?

01:01:15.300 --> 01:01:17.192 align:middle line:90%
AUDIENCE: [INAUDIBLE]

01:01:17.192 --> 01:01:17.457 align:middle line:90%


01:01:17.457 --> 01:01:19.040 align:middle line:84%
PROFESSOR: I didn't
hear you, but I'll

01:01:19.040 --> 01:01:21.000 align:middle line:84%
bet you said because
oxygen concentrations

01:01:21.000 --> 01:01:23.700 align:middle line:84%
in the bottom water are much
lower in the Northeast Pacific.

01:01:23.700 --> 01:01:26.280 align:middle line:84%
And in fact, there's an
intense oxygen minimum.

01:01:26.280 --> 01:01:28.805 align:middle line:90%
And so in the oxygen minimum--

01:01:28.805 --> 01:01:30.680 align:middle line:84%
that's what's shown in
this line in the table

01:01:30.680 --> 01:01:35.120 align:middle line:84%
here-- oxygen only
accounts for 5% to 50%

01:01:35.120 --> 01:01:37.840 align:middle line:84%
and nitrate accounts
for most of the rest.

01:01:37.840 --> 01:01:40.280 align:middle line:84%
Iron and manganese again
are not very important,

01:01:40.280 --> 01:01:42.660 align:middle line:84%
but sulfate reduction
is significant.

01:01:42.660 --> 01:01:46.480 align:middle line:84%
The Northeast Pacific deeper
than the oxygen minimum,

01:01:46.480 --> 01:01:49.740 align:middle line:84%
you get a picture that's
much more like the Atlantic.

01:01:49.740 --> 01:01:51.500 align:middle line:90%
Oxygen is the most important.

01:01:51.500 --> 01:01:54.300 align:middle line:84%
In this case, nitrate is
second, and sulfate reduction

01:01:54.300 --> 01:01:55.820 align:middle line:90%
can also be important.

01:01:55.820 --> 01:01:58.620 align:middle line:84%
So why would nitrate be more
important under these conditions

01:01:58.620 --> 01:02:00.400 align:middle line:84%
in the Pacific
than the Atlantic?

01:02:00.400 --> 01:02:03.100 align:middle line:90%


01:02:03.100 --> 01:02:05.580 align:middle line:90%
AUDIENCE: [INAUDIBLE]

01:02:05.580 --> 01:02:09.940 align:middle line:84%
PROFESSOR: What else is
there in the bottom waters?

01:02:09.940 --> 01:02:11.780 align:middle line:90%
There's more nitrate.

01:02:11.780 --> 01:02:14.760 align:middle line:84%
So nitrate can diffuse in
from the bottom waters.

01:02:14.760 --> 01:02:15.900 align:middle line:90%
Actually, if you look at--

01:02:15.900 --> 01:02:18.060 align:middle line:84%
I showed you a nitrate
profile from the Atlantic

01:02:18.060 --> 01:02:20.620 align:middle line:84%
earlier, where there's
actually a nitrate maximum

01:02:20.620 --> 01:02:23.300 align:middle line:84%
in the sediments, meaning that
some of the nitrate that's

01:02:23.300 --> 01:02:25.860 align:middle line:84%
produced by oxic organic
matter decomposition

01:02:25.860 --> 01:02:29.300 align:middle line:84%
leaves the sediments and isn't
used for denitrification.

01:02:29.300 --> 01:02:32.660 align:middle line:84%
If you look at nitrate pore
water profiles in the Pacific,

01:02:32.660 --> 01:02:35.180 align:middle line:84%
you see there is no
subsurface maximum.

01:02:35.180 --> 01:02:37.800 align:middle line:84%
Concentration decreases
right from the interface,

01:02:37.800 --> 01:02:39.490 align:middle line:84%
which means that
bottom water nitrate is

01:02:39.490 --> 01:02:40.870 align:middle line:90%
diffusing into the sediments.

01:02:40.870 --> 01:02:43.130 align:middle line:84%
So that's an added
source of nitrate.

01:02:43.130 --> 01:02:47.130 align:middle line:84%
So nitrate is a little bit
more important in the Pacific.

01:02:47.130 --> 01:02:51.750 align:middle line:84%
But anyway, all these deep ocean
and continental margin sites,

01:02:51.750 --> 01:02:53.770 align:middle line:84%
oxygen is the most
important electron acceptor,

01:02:53.770 --> 01:02:57.130 align:middle line:84%
except in the oxygen minimum,
followed by nitrate and sulfate.

01:02:57.130 --> 01:03:01.210 align:middle line:84%
Now, in coastal sediments,
very shallow water sediments,

01:03:01.210 --> 01:03:03.570 align:middle line:84%
is a different story where
the dominant electron

01:03:03.570 --> 01:03:07.130 align:middle line:90%
acceptors are iron and sulfur.

01:03:07.130 --> 01:03:08.610 align:middle line:90%
But there's a catch.

01:03:08.610 --> 01:03:12.590 align:middle line:84%
And the catch is that
the reduced products--

01:03:12.590 --> 01:03:15.610 align:middle line:90%
so reduced iron sulfides--

01:03:15.610 --> 01:03:18.627 align:middle line:84%
can be mixed back up to
the sediment surface.

01:03:18.627 --> 01:03:20.710 align:middle line:84%
And at the sediment surface,
what happens to them?

01:03:20.710 --> 01:03:22.330 align:middle line:90%
They're oxidized by oxygen.

01:03:22.330 --> 01:03:26.570 align:middle line:84%
So even though the pathway for
organic matter decomposition

01:03:26.570 --> 01:03:29.530 align:middle line:84%
is mostly anaerobic,
where iron and sulfate

01:03:29.530 --> 01:03:31.950 align:middle line:84%
are the electron acceptors
used by the bacteria,

01:03:31.950 --> 01:03:35.570 align:middle line:84%
actually the ultimate electron
acceptor is still oxygen,

01:03:35.570 --> 01:03:37.270 align:middle line:84%
because very little
of the reduced iron

01:03:37.270 --> 01:03:38.650 align:middle line:90%
and sulfur are buried.

01:03:38.650 --> 01:03:41.730 align:middle line:84%
They're mostly mixed back to
the surface to be re-oxidized.

01:03:41.730 --> 01:03:43.330 align:middle line:84%
So they're used
over and over again.

01:03:43.330 --> 01:03:45.610 align:middle line:84%
And oxygen is the ultimate
electron acceptor.

01:03:45.610 --> 01:03:53.610 align:middle line:90%


01:03:53.610 --> 01:03:55.150 align:middle line:84%
Now you've heard
more than you ever

01:03:55.150 --> 01:03:57.210 align:middle line:84%
wanted to know about
pore water profiles.

01:03:57.210 --> 01:03:59.910 align:middle line:84%
So we'll talk for a minute
about organic carbon

01:03:59.910 --> 01:04:01.790 align:middle line:90%
burial in marine sediments.

01:04:01.790 --> 01:04:05.470 align:middle line:84%
I said way back
at the beginning,

01:04:05.470 --> 01:04:08.070 align:middle line:84%
what the long-term importance
of organic matter burial

01:04:08.070 --> 01:04:14.470 align:middle line:84%
in sediments is, and that's
that it represents the net--

01:04:14.470 --> 01:04:17.690 align:middle line:84%
the excess of photosynthesis
over respiration in the ocean.

01:04:17.690 --> 01:04:20.375 align:middle line:84%
And so it's a part of the
long-term oxygen balance.

01:04:20.375 --> 01:04:22.750 align:middle line:84%
So there's good reason for
studying organic carbon burial

01:04:22.750 --> 01:04:26.110 align:middle line:84%
in marine sediments,
and to understand

01:04:26.110 --> 01:04:29.030 align:middle line:84%
what makes it change
from place to place,

01:04:29.030 --> 01:04:30.990 align:middle line:84%
and what may make
it change over time.

01:04:30.990 --> 01:04:39.140 align:middle line:84%
So what's written in this
table are three summaries

01:04:39.140 --> 01:04:41.347 align:middle line:84%
of organic matter burial
in marine sediments.

01:04:41.347 --> 01:04:43.180 align:middle line:84%
The first one is an old
one, and it actually

01:04:43.180 --> 01:04:44.420 align:middle line:90%
doesn't tell you much.

01:04:44.420 --> 01:04:48.340 align:middle line:84%
The second one,
the point of these

01:04:48.340 --> 01:04:52.380 align:middle line:84%
is to show you that of the
total organic carbon that's

01:04:52.380 --> 01:04:55.860 align:middle line:84%
buried in sediments, by
far, the majority of it

01:04:55.860 --> 01:05:01.140 align:middle line:84%
is buried in the
Berner compilation

01:05:01.140 --> 01:05:03.580 align:middle line:84%
terrigenous deltaic
shelf sediments.

01:05:03.580 --> 01:05:09.140 align:middle line:84%
And when those were broken
down by Hedges and Keil

01:05:09.140 --> 01:05:12.660 align:middle line:84%
into deltaic sediments plus
sediments on the upper shelves

01:05:12.660 --> 01:05:13.780 align:middle line:90%
and slopes.

01:05:13.780 --> 01:05:15.580 align:middle line:84%
So what that tells
you, if you want

01:05:15.580 --> 01:05:19.137 align:middle line:84%
to understand organic carbon
burial in marine sediments

01:05:19.137 --> 01:05:21.220 align:middle line:84%
in the locations that are
most important, you need

01:05:21.220 --> 01:05:23.940 align:middle line:84%
to understand organic carbon
burial in continental margin

01:05:23.940 --> 01:05:26.580 align:middle line:84%
sediments, because that's where
most of the organic matter

01:05:26.580 --> 01:05:27.720 align:middle line:90%
burial occurs.

01:05:27.720 --> 01:05:30.900 align:middle line:90%


01:05:30.900 --> 01:05:37.650 align:middle line:84%
So you could ask yourself, what
determines the organic carbon

01:05:37.650 --> 01:05:40.250 align:middle line:90%
accumulation rate in sediments?

01:05:40.250 --> 01:05:45.350 align:middle line:84%
And way back when,
two camps arose.

01:05:45.350 --> 01:05:47.990 align:middle line:84%
One camp said, well,
what determined--

01:05:47.990 --> 01:05:49.790 align:middle line:84%
I think of these as
the wishful thinkers--

01:05:49.790 --> 01:05:54.410 align:middle line:84%
that what determines the organic
matter burial rate in sediments

01:05:54.410 --> 01:05:56.810 align:middle line:84%
is the productivity of
the overlying waters.

01:05:56.810 --> 01:05:59.550 align:middle line:84%
So if you measure organic carbon
burial rates in sediments,

01:05:59.550 --> 01:06:02.730 align:middle line:84%
that'll give you a picture of
productivity in the overlying

01:06:02.730 --> 01:06:04.530 align:middle line:90%
waters.

01:06:04.530 --> 01:06:07.690 align:middle line:84%
The others say, no,
that's not true.

01:06:07.690 --> 01:06:10.810 align:middle line:84%
And they go back to what
I discussed earlier, which

01:06:10.810 --> 01:06:14.042 align:middle line:84%
is the fact that in
marine sediments,

01:06:14.042 --> 01:06:16.250 align:middle line:84%
most of the organic matter
that falls to the seafloor

01:06:16.250 --> 01:06:17.730 align:middle line:90%
is remineralized.

01:06:17.730 --> 01:06:22.250 align:middle line:84%
So variations in
the inputs can be

01:06:22.250 --> 01:06:25.490 align:middle line:84%
masked by variations in
the remineralization rate,

01:06:25.490 --> 01:06:28.650 align:middle line:84%
or the recycling efficiency
of the organic matter.

01:06:28.650 --> 01:06:33.670 align:middle line:84%
So how did these two camps, one
that says local productivity

01:06:33.670 --> 01:06:36.230 align:middle line:84%
determines organic carbon
accumulation in sediments,

01:06:36.230 --> 01:06:40.470 align:middle line:84%
and one that says
variable preservation

01:06:40.470 --> 01:06:44.510 align:middle line:84%
determines variations in
organic carbon accumulation.

01:06:44.510 --> 01:06:46.550 align:middle line:84%
And there's actually
an important piece

01:06:46.550 --> 01:06:50.190 align:middle line:84%
to the variable
preservation story.

01:06:50.190 --> 01:06:53.150 align:middle line:84%
And that is that when
this argument first arose,

01:06:53.150 --> 01:06:56.030 align:middle line:84%
the variable preservation
was attributed entirely

01:06:56.030 --> 01:06:59.110 align:middle line:84%
to variations in bottom
water oxygen concentration.

01:06:59.110 --> 01:07:01.610 align:middle line:84%
They said that if the
bottom waters are anoxic,

01:07:01.610 --> 01:07:04.150 align:middle line:84%
organic matter is preserved
to a much greater extent

01:07:04.150 --> 01:07:06.030 align:middle line:90%
than if bottom waters are oxic.

01:07:06.030 --> 01:07:08.590 align:middle line:90%


01:07:08.590 --> 01:07:10.230 align:middle line:84%
So you could simplify
this discussion

01:07:10.230 --> 01:07:11.790 align:middle line:90%
into pictures like this.

01:07:11.790 --> 01:07:16.750 align:middle line:84%
The top one is a picture of the
organic carbon concentration

01:07:16.750 --> 01:07:19.850 align:middle line:84%
in sediments around the world,
where the darker the color,

01:07:19.850 --> 01:07:22.430 align:middle line:84%
the higher the organic
matter concentration.

01:07:22.430 --> 01:07:25.510 align:middle line:84%
I put a star there because,
remember, up until now,

01:07:25.510 --> 01:07:27.910 align:middle line:84%
I've talked about organic
matter accumulation rates.

01:07:27.910 --> 01:07:32.457 align:middle line:90%


01:07:32.457 --> 01:07:34.040 align:middle line:84%
And that's what I
really want to know.

01:07:34.040 --> 01:07:35.820 align:middle line:84%
I want to know the
accumulation rate.

01:07:35.820 --> 01:07:37.340 align:middle line:84%
It turns out that
if you're looking

01:07:37.340 --> 01:07:40.860 align:middle line:84%
at gross large-scale features,
the concentration variations

01:07:40.860 --> 01:07:45.860 align:middle line:84%
give you a reasonable picture
of accumulation rate variations.

01:07:45.860 --> 01:07:50.660 align:middle line:84%
But there's a catch, and
you can see the catch

01:07:50.660 --> 01:07:54.540 align:middle line:84%
if you look at these
areas of lightly hatched

01:07:54.540 --> 01:07:56.680 align:middle line:84%
low organic carbon
concentration.

01:07:56.680 --> 01:07:59.540 align:middle line:90%


01:07:59.540 --> 01:08:02.560 align:middle line:84%
Have you had your
hydrothermal lecture yet?

01:08:02.560 --> 01:08:08.140 align:middle line:84%
So you know that those follow
mid-ocean ridge system.

01:08:08.140 --> 01:08:11.260 align:middle line:84%
Those are all shallow
places in the water.

01:08:11.260 --> 01:08:14.300 align:middle line:84%
And as we'll see later,
those are places where

01:08:14.300 --> 01:08:16.420 align:middle line:90%
calcium carbonate accumulates.

01:08:16.420 --> 01:08:21.700 align:middle line:84%
And so what these low organic
carbon concentrations tell you

01:08:21.700 --> 01:08:23.779 align:middle line:84%
is that the organic
matter is being diluted

01:08:23.779 --> 01:08:25.032 align:middle line:90%
by a lot of calcium carbonate.

01:08:25.032 --> 01:08:26.740 align:middle line:84%
It doesn't tell you
that the accumulation

01:08:26.740 --> 01:08:28.479 align:middle line:84%
rate of organic
matter is lower there.

01:08:28.479 --> 01:08:29.819 align:middle line:90%
That's an aside.

01:08:29.819 --> 01:08:31.960 align:middle line:84%
The main point here that
I want you to be aware of,

01:08:31.960 --> 01:08:34.040 align:middle line:84%
because I don't want
you to get trapped

01:08:34.040 --> 01:08:37.819 align:middle line:84%
into equating concentrations
and accumulation rates.

01:08:37.819 --> 01:08:41.399 align:middle line:90%
You can run into problems.

01:08:41.399 --> 01:08:47.120 align:middle line:84%
And I used to be an economist
and mixing stocks and flows

01:08:47.120 --> 01:08:51.359 align:middle line:84%
was grounds to get you failed
out of all your classes.

01:08:51.359 --> 01:08:53.680 align:middle line:90%
So I don't want you to do that.

01:08:53.680 --> 01:08:55.880 align:middle line:84%
But having said, that I'm
going to proceed to mix

01:08:55.880 --> 01:08:58.340 align:middle line:90%
stocks and flows.

01:08:58.340 --> 01:08:59.160 align:middle line:90%
So these regions--

01:08:59.160 --> 01:09:01.040 align:middle line:84%
AUDIENCE: You can still do
that in fisheries research.

01:09:01.040 --> 01:09:01.998 align:middle line:90%
PROFESSOR: Oh, can you?

01:09:01.998 --> 01:09:04.279 align:middle line:90%
[LAUGHTER]

01:09:04.279 --> 01:09:07.180 align:middle line:84%
So anyway, the point here
is that the black spots,

01:09:07.180 --> 01:09:09.779 align:middle line:84%
the black ones, which are high
organic carbon concentrations,

01:09:09.779 --> 01:09:11.380 align:middle line:84%
are along the
continental margins.

01:09:11.380 --> 01:09:13.200 align:middle line:84%
And I've highlighted
three spots.

01:09:13.200 --> 01:09:15.120 align:middle line:90%
Number one is the Arabian Sea.

01:09:15.120 --> 01:09:17.680 align:middle line:84%
Number two is the
Eastern Tropical Pacific.

01:09:17.680 --> 01:09:21.080 align:middle line:84%
And number three is
the West African Coast.

01:09:21.080 --> 01:09:23.279 align:middle line:84%
What's shown in
the next plot down

01:09:23.279 --> 01:09:27.840 align:middle line:84%
is a map of oxygen
concentrations at the oxygen

01:09:27.840 --> 01:09:30.830 align:middle line:84%
minimum in the water column,
where the black ones are

01:09:30.830 --> 01:09:32.609 align:middle line:90%
very low oxygen concentrations.

01:09:32.609 --> 01:09:36.770 align:middle line:84%
And you see that I've labeled
the same spots, the Arabian Sea,

01:09:36.770 --> 01:09:42.050 align:middle line:84%
the West African Coast, and
the Eastern Tropical Pacific.

01:09:42.050 --> 01:09:44.149 align:middle line:84%
And they're not only areas
of high organic carbon

01:09:44.149 --> 01:09:45.790 align:middle line:84%
concentration and
accumulation rates,

01:09:45.790 --> 01:09:49.590 align:middle line:84%
they're also areas of low bottom
water oxygen concentration.

01:09:49.590 --> 01:09:52.830 align:middle line:84%
Well, it turns out that if
you take this one step further

01:09:52.830 --> 01:09:55.430 align:middle line:84%
and look at a map of
primary productivity--

01:09:55.430 --> 01:09:59.530 align:middle line:84%
this is an ancient map, which
I'm sure will make Scott cringe,

01:09:59.530 --> 01:10:02.310 align:middle line:90%
but it does the purpose here--

01:10:02.310 --> 01:10:04.150 align:middle line:84%
see that those
same spots labeled

01:10:04.150 --> 01:10:09.310 align:middle line:84%
1, 2, and 3 are also areas
of high primary productivity.

01:10:09.310 --> 01:10:12.008 align:middle line:84%
And so what you see is there's
a correspondence between regions

01:10:12.008 --> 01:10:13.550 align:middle line:84%
of high productivity
and high percent

01:10:13.550 --> 01:10:15.550 align:middle line:90%
organic carbon in sediments.

01:10:15.550 --> 01:10:18.850 align:middle line:84%
So that bolsters the argument
of the overlying water

01:10:18.850 --> 01:10:20.450 align:middle line:90%
Productivity is what counts.

01:10:20.450 --> 01:10:24.950 align:middle line:84%
But those are also regions
of low bottom water oxygen.

01:10:24.950 --> 01:10:26.790 align:middle line:84%
And so that also
bolstered the argument

01:10:26.790 --> 01:10:30.250 align:middle line:84%
of the variable
preservation rate camp.

01:10:30.250 --> 01:10:33.090 align:middle line:84%
And in addition, it's been
shown by a number of studies

01:10:33.090 --> 01:10:35.010 align:middle line:84%
that some naturally
occurring molecules

01:10:35.010 --> 01:10:37.570 align:middle line:84%
require oxygen
for decomposition.

01:10:37.570 --> 01:10:39.930 align:middle line:84%
And so you might
reasonably ask yourself,

01:10:39.930 --> 01:10:42.410 align:middle line:84%
does the sedimentary
organic matter accumulation

01:10:42.410 --> 01:10:44.730 align:middle line:90%
rate actually depend--

01:10:44.730 --> 01:10:46.290 align:middle line:84%
the variations,
are they determined

01:10:46.290 --> 01:10:50.010 align:middle line:84%
by variations in overlying
water productivity

01:10:50.010 --> 01:10:52.250 align:middle line:84%
or variations in the
preservation rate

01:10:52.250 --> 01:10:55.610 align:middle line:90%
of the organic matter, or both?

01:10:55.610 --> 01:10:58.510 align:middle line:84%
What I'm going to show is not
an answer to that question.

01:10:58.510 --> 01:11:01.590 align:middle line:84%
I think I've already made clear
where I stand on the issue.

01:11:01.590 --> 01:11:03.610 align:middle line:84%
I think preservation
is important.

01:11:03.610 --> 01:11:12.730 align:middle line:84%
But is actually a recent--
well, fairly recent improvement

01:11:12.730 --> 01:11:16.650 align:middle line:84%
of the argument of how bottom
water oxygen concentrations

01:11:16.650 --> 01:11:20.250 align:middle line:84%
affect organic
matter preservation

01:11:20.250 --> 01:11:26.560 align:middle line:84%
in the sediments, where it used
to be just oxic versus anoxic.

01:11:26.560 --> 01:11:29.120 align:middle line:84%
This reaches a middle
ground, this interpretation

01:11:29.120 --> 01:11:30.180 align:middle line:90%
that I'm going to show.

01:11:30.180 --> 01:11:35.503 align:middle line:84%
And what these people
did was study--

01:11:35.503 --> 01:11:36.920 align:middle line:84%
was come up with
an idea that they

01:11:36.920 --> 01:11:39.360 align:middle line:90%
called oxygen exposure time.

01:11:39.360 --> 01:11:42.660 align:middle line:84%
And in their original
work on this,

01:11:42.660 --> 01:11:45.400 align:middle line:84%
they studied two areas,
which were actually

01:11:45.400 --> 01:11:46.840 align:middle line:84%
very good for this
purpose because

01:11:46.840 --> 01:11:48.540 align:middle line:90%
of their contrasting properties.

01:11:48.540 --> 01:11:50.720 align:middle line:84%
They studied the
Washington margin,

01:11:50.720 --> 01:11:53.200 align:middle line:84%
so that's in the
Northeastern Pacific

01:11:53.200 --> 01:11:55.440 align:middle line:90%
off the coast of Washington.

01:11:55.440 --> 01:11:57.280 align:middle line:84%
And the Mexico
margin, so that's,

01:11:57.280 --> 01:12:00.720 align:middle line:84%
again, Northeast Pacific,
but off the coast of Mexico.

01:12:00.720 --> 01:12:04.040 align:middle line:84%
If you compare
these two regions,

01:12:04.040 --> 01:12:05.640 align:middle line:84%
the Washington
margin, which is shown

01:12:05.640 --> 01:12:09.040 align:middle line:84%
by the squares in these plots
that I've shown below it,

01:12:09.040 --> 01:12:10.760 align:middle line:84%
is a region that has
higher productivity

01:12:10.760 --> 01:12:15.240 align:middle line:84%
than the Mexico margin, but a
less intense oxygen minimum.

01:12:15.240 --> 01:12:16.760 align:middle line:84%
The Mexico margin,
which is shown

01:12:16.760 --> 01:12:20.020 align:middle line:84%
by the circles in these
plots, has lower productivity,

01:12:20.020 --> 01:12:22.060 align:middle line:84%
but a very intense
oxygen minimum.

01:12:22.060 --> 01:12:28.390 align:middle line:84%
So on the left here is a plot of
profile of oxygen in the water

01:12:28.390 --> 01:12:31.170 align:middle line:84%
column in these regions,
where the Washington margin,

01:12:31.170 --> 01:12:32.750 align:middle line:84%
there is an oxygen
minimum, but it's

01:12:32.750 --> 01:12:39.390 align:middle line:84%
deeper and not as intense
in this region from zero

01:12:39.390 --> 01:12:43.370 align:middle line:84%
to 600 or 700 meters as it
is in the Mexico margin,

01:12:43.370 --> 01:12:46.470 align:middle line:84%
where the water
column is anoxic.

01:12:46.470 --> 01:12:50.390 align:middle line:84%
What's shown on the right are
concentrations of organic carbon

01:12:50.390 --> 01:12:51.930 align:middle line:90%
in the sediments.

01:12:51.930 --> 01:12:56.390 align:middle line:84%
So on the Washington margin, the
organic carbon concentrations

01:12:56.390 --> 01:12:58.190 align:middle line:90%
are around 2%.

01:12:58.190 --> 01:13:00.790 align:middle line:84%
In the Mexico margin,
the concentrations

01:13:00.790 --> 01:13:04.470 align:middle line:84%
of organic matter in the
sediment run around 10%.

01:13:04.470 --> 01:13:06.710 align:middle line:84%
So you can already see
where this argument

01:13:06.710 --> 01:13:10.070 align:middle line:84%
is going in the simple
productivity versus preservation

01:13:10.070 --> 01:13:15.110 align:middle line:84%
discussion, where the site
that has an intense oxygen

01:13:15.110 --> 01:13:18.057 align:middle line:84%
minimum, but lower productivity
has a much higher oxygen

01:13:18.057 --> 01:13:20.390 align:middle line:84%
concentration in the sediments
than the site with higher

01:13:20.390 --> 01:13:23.150 align:middle line:84%
productivity, but a less
intense oxygen minimum,

01:13:23.150 --> 01:13:26.090 align:middle line:84%
saying that preservation
rate is a key in determining

01:13:26.090 --> 01:13:27.830 align:middle line:90%
organic carbon distributions.

01:13:27.830 --> 01:13:32.330 align:middle line:90%


01:13:32.330 --> 01:13:34.930 align:middle line:84%
What these guys did was,
in addition to measuring

01:13:34.930 --> 01:13:37.310 align:middle line:84%
organic carbon concentrations
in the sediments,

01:13:37.310 --> 01:13:40.050 align:middle line:84%
they also measured
oxygen profiles

01:13:40.050 --> 01:13:42.010 align:middle line:90%
in the sediment pore waters.

01:13:42.010 --> 01:13:44.310 align:middle line:84%
And with each of
those oxygen profiles,

01:13:44.310 --> 01:13:47.090 align:middle line:84%
they determined the depth below
the sediment-water interface

01:13:47.090 --> 01:13:49.290 align:middle line:84%
at which the oxygen
goes to zero.

01:13:49.290 --> 01:13:52.370 align:middle line:84%
And they called that depth
the oxygen penetration depth.

01:13:52.370 --> 01:13:54.370 align:middle line:84%
What they were
interested in doing

01:13:54.370 --> 01:13:57.210 align:middle line:84%
was calculating how long
a particular particle

01:13:57.210 --> 01:14:00.810 align:middle line:84%
would be exposed to oxygen
after it reaches the sea floor.

01:14:00.810 --> 01:14:02.850 align:middle line:84%
And they did that
by also measuring

01:14:02.850 --> 01:14:06.330 align:middle line:84%
the sediment accumulation
rate at all these places,

01:14:06.330 --> 01:14:10.010 align:middle line:84%
and dividing this
oxygen penetration depth

01:14:10.010 --> 01:14:11.287 align:middle line:90%
by the sedimentation rate.

01:14:11.287 --> 01:14:12.870 align:middle line:84%
And the result of
that would give you,

01:14:12.870 --> 01:14:15.090 align:middle line:84%
on average, how long
a particle spends

01:14:15.090 --> 01:14:18.450 align:middle line:84%
in the oxic part of
the sediment column.

01:14:18.450 --> 01:14:21.970 align:middle line:84%
And they called that quantity
the oxygen exposure time.

01:14:21.970 --> 01:14:24.440 align:middle line:84%
So the longer the
oxygen exposure time,

01:14:24.440 --> 01:14:27.640 align:middle line:84%
the longer a sediment
particle, or a bit

01:14:27.640 --> 01:14:29.480 align:middle line:84%
of sedimentary
organic matter, is

01:14:29.480 --> 01:14:32.480 align:middle line:84%
in a region where it's
exposed to dissolved oxygen.

01:14:32.480 --> 01:14:36.980 align:middle line:84%
And once they made
these calculations,

01:14:36.980 --> 01:14:41.320 align:middle line:84%
they compared the oxygen
exposure time for particles

01:14:41.320 --> 01:14:44.440 align:middle line:84%
at a given site to the
organic carbon burial

01:14:44.440 --> 01:14:46.040 align:middle line:90%
efficiency at that site.

01:14:46.040 --> 01:14:48.080 align:middle line:84%
And the burial
efficiency is here

01:14:48.080 --> 01:14:51.320 align:middle line:84%
equal to the burial rate
divided by the rain rate.

01:14:51.320 --> 01:14:57.320 align:middle line:84%
And the prediction would
be that if oxygen matters--

01:14:57.320 --> 01:15:01.040 align:middle line:84%
so if organic matter is
oxidized more readily by oxygen

01:15:01.040 --> 01:15:03.160 align:middle line:84%
than by other
electron acceptors,

01:15:03.160 --> 01:15:05.480 align:middle line:84%
then the longer the
oxygen exposure time,

01:15:05.480 --> 01:15:10.506 align:middle line:84%
the lower the organic carbon
burial efficiency will be.

01:15:10.506 --> 01:15:13.560 align:middle line:84%
And they came up
with a compilation

01:15:13.560 --> 01:15:16.360 align:middle line:84%
of data that looked
like this, where

01:15:16.360 --> 01:15:19.300 align:middle line:84%
they plotted organic
carbon burial efficiency.

01:15:19.300 --> 01:15:28.340 align:middle line:84%
And here the range is from 0 to
60% versus oxygen exposure time.

01:15:28.340 --> 01:15:30.200 align:middle line:84%
The vertical axis
is linear scale.

01:15:30.200 --> 01:15:32.580 align:middle line:84%
So burial efficiency
is on a linear scale.

01:15:32.580 --> 01:15:35.220 align:middle line:84%
Oxygen exposure time
is on a log scale.

01:15:35.220 --> 01:15:38.220 align:middle line:84%
And a very important
piece of their conclusion

01:15:38.220 --> 01:15:42.580 align:middle line:84%
is that they measured oxygen
exposure time over a five

01:15:42.580 --> 01:15:44.260 align:middle line:90%
order of magnitude range.

01:15:44.260 --> 01:15:46.718 align:middle line:84%
And it's safe to
say they wouldn't

01:15:46.718 --> 01:15:48.260 align:middle line:84%
have come to any
conclusion if they'd

01:15:48.260 --> 01:15:50.220 align:middle line:90%
measured a much smaller range.

01:15:50.220 --> 01:15:52.340 align:middle line:84%
They're actually very
upfront about that, because

01:15:52.340 --> 01:15:56.740 align:middle line:84%
in this inset here, they
plot both on linear scales,

01:15:56.740 --> 01:15:59.980 align:middle line:84%
and you see that all their
data fall in a big clump.

01:15:59.980 --> 01:16:01.860 align:middle line:84%
They don't start to
separate out and let

01:16:01.860 --> 01:16:04.740 align:middle line:84%
you see a pattern until
you plot it on a log scale

01:16:04.740 --> 01:16:08.180 align:middle line:84%
and look at this very large
scale, this very large change

01:16:08.180 --> 01:16:10.700 align:middle line:90%
in oxygen exposure time.

01:16:10.700 --> 01:16:13.300 align:middle line:84%
What you see, if you look
at this overall picture,

01:16:13.300 --> 01:16:18.020 align:middle line:84%
is that there is indeed, over
this large range of oxygen

01:16:18.020 --> 01:16:22.130 align:middle line:84%
exposure times, a decrease on
average in organic carbon burial

01:16:22.130 --> 01:16:26.970 align:middle line:84%
efficiency the longer the
oxygen exposure time is

01:16:26.970 --> 01:16:30.330 align:middle line:84%
But if you look at
any particular spot,

01:16:30.330 --> 01:16:32.730 align:middle line:90%
the variations are really big.

01:16:32.730 --> 01:16:35.730 align:middle line:84%
So my conclusion from
this was that it's

01:16:35.730 --> 01:16:39.030 align:middle line:84%
a promising idea that
oxygen does matter,

01:16:39.030 --> 01:16:41.730 align:middle line:84%
and that you can determine how
much it matters by measuring

01:16:41.730 --> 01:16:46.467 align:middle line:84%
this oxygen exposure time
thing, but that you really

01:16:46.467 --> 01:16:48.050 align:middle line:84%
need more information,
because there's

01:16:48.050 --> 01:16:49.508 align:middle line:84%
a lot of variability
in the results

01:16:49.508 --> 01:16:51.930 align:middle line:84%
that isn't explained
by this simple model.

01:16:51.930 --> 01:16:54.770 align:middle line:84%
And in fact, they've gone
on in subsequent years

01:16:54.770 --> 01:16:56.430 align:middle line:84%
to make it a lot
more complicated.

01:16:56.430 --> 01:16:59.010 align:middle line:90%


01:16:59.010 --> 01:17:01.530 align:middle line:84%
One interesting note
is that this actually

01:17:01.530 --> 01:17:04.410 align:middle line:84%
provides a feedback
between atmospheric oxygen

01:17:04.410 --> 01:17:07.133 align:middle line:84%
levels and the organic
carbon burial rate.

01:17:07.133 --> 01:17:08.550 align:middle line:84%
When you get into
these arguments,

01:17:08.550 --> 01:17:10.810 align:middle line:84%
they're very
hand-wavy, but they're

01:17:10.810 --> 01:17:13.250 align:middle line:90%
interesting to think about.

01:17:13.250 --> 01:17:16.490 align:middle line:84%
If you suppose oxygen
exposure time matters,

01:17:16.490 --> 01:17:18.710 align:middle line:84%
and, say, there's an
increase in weathering

01:17:18.710 --> 01:17:21.410 align:middle line:84%
rates on the continent, or
something that increases--

01:17:21.410 --> 01:17:25.213 align:middle line:84%
that tends to decrease the level
of oxygen in the atmosphere,

01:17:25.213 --> 01:17:27.630 align:middle line:84%
the level of oxygen in the
atmosphere decreases, then less

01:17:27.630 --> 01:17:29.630 align:middle line:84%
will be mixed down
into the deep ocean.

01:17:29.630 --> 01:17:32.990 align:middle line:84%
So the bottom water
oxygen will have lower--

01:17:32.990 --> 01:17:35.470 align:middle line:84%
bottom water will have
lower oxygen concentration.

01:17:35.470 --> 01:17:37.990 align:middle line:84%
And other things being
equal, the penetration depth

01:17:37.990 --> 01:17:40.470 align:middle line:84%
of oxygen in the
sediments will be smaller.

01:17:40.470 --> 01:17:43.410 align:middle line:84%
If that's true, and if
this argument is true,

01:17:43.410 --> 01:17:45.950 align:middle line:84%
then oxygen exposure
times will be smaller.

01:17:45.950 --> 01:17:48.150 align:middle line:84%
So the preservation
rate of organic matter

01:17:48.150 --> 01:17:53.710 align:middle line:84%
will increase, which,
remember, means a larger

01:17:53.710 --> 01:17:55.890 align:middle line:84%
excess of photosynthesis
over respiration,

01:17:55.890 --> 01:17:58.510 align:middle line:84%
which tends to increase the
atmospheric oxygen level.

01:17:58.510 --> 01:18:03.070 align:middle line:84%
So there's a feedback between
these inorganic carbon burial

01:18:03.070 --> 01:18:05.090 align:middle line:90%
and continental weathering.

01:18:05.090 --> 01:18:08.870 align:middle line:90%


01:18:08.870 --> 01:18:15.390 align:middle line:84%
So with that, I'll quit my
discussion of organic matter

01:18:15.390 --> 01:18:19.140 align:middle line:90%
decomposition in sediments.