WEBVTT

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CHRISTINE BREINER: Welcome
back to recitation.

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In this video I'd like
us to do two things.

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The first thing we're going to
do is we're going to graph the

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curve, r equals 1 plus cosine
theta over 2 for theta between

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0 and 4 pi and we're going to
graph it in the x, y plane.

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And then after we've done that,
we're going to take a

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look at some components of that
curve and we're going to

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calculate the area of some
components that close up.

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So what I'd like you to do first
is get a good picture of

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this curve in the x, y plane.

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I'll give you a little
while to do that.

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So why don't you pause the
video, get a good picture of

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that curve, then come back when
you're ready and I'll

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show you how I graph it, and
then we'll get into these area

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problems.

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OK.

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Welcome back.

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So the goal, again, was to
graph a certain curve

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described by r and theta,
but in the x, y plane.

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And for theta between
0 and pi over 4.

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And when I do these problems,
we want to make sure that we

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understand how r depends
on theta.

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That's sort of the main goal
to graph this curve.

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So what I do, actually, is I
look at this not in the x, y

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plane, which was what I said
to do in the problem, but I

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first look at it in what we
see as the r, theta plane.

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And what we mean by that is
we're going to graph this just

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like we would if this variable
was x and this variable was y.

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So we move out of what we know
about how r relates to x and

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y, and how theta relates to x
and y, and we just look at how

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r relates to theta.

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So let me draw that first and
we'll see if we can sort of

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understand what I mean by that,
and then we'll put that,

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use that curve to put that
into the x, y plane.

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OK.

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So, the first thing we do is I'm
going to let this be the

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theta-axis and this
be the r-axis.

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And let's look at--I want to
write down over here what the

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equation is so I don't have
to keep turning around.

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So again, this is not, I don't
want to think about this as

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the x, y plane.

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Because in the x, y plane, theta
has certain values at

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each point that are fixed
based on the angle.

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But now I'm letting theta vary
in this direction, and r is

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varying in this direction.

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And my theta, I said, was
between 0 and pi over 4--

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I'm sorry, not pi over 4.

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4 pi.

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0 and 4 pi.

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pi over 4 would be a very small
component of this that

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I'm interested in.

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And let's think about what
happens, what kind of

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transformations have been done
to the normal cosine function.

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So if I took the normal cosine
function and I take it instead

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of cosine theta, I look it
cosine theta over 2, what

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that's doing is that's
stretching it

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horizontally out.

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So think about the period
of the cosine function

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usually is 2 pi.

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But notice what happens when I
put in 2 pi for theta, I'm

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getting cosine of pi.

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If I want to get cosine of 2 pi,
I have to let theta go to

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4 pi, which is why I'm letting
theta be between 0 and 4 pi.

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So dividing the input value
by 2 doubles your period.

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So the period is now 4 pi.

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So to get all the way through,
I'm going to have

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to go up to 4 pi.

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So let me just make a 2
pi here, and this is

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about a 4 pi here.

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So here's around 3 pi,
and here's around pi.

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So that now, instead of the
usual cosine function, it's

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going to take twice as long to
get all the way through.

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That's one thing we know.

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What else have we done to the
usual cosine function?

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We've moved it up by 1.

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And so instead of starting out
when your input is 0, starting

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out at height 1, when you're
input is 0, you start out at

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height 1 plus 1.

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You start out at height 2.

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So in fact, this function, let
me point out, it's going to

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start at 2, which
means it also is

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going to end over here.

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Because it's periodic it's
going to end at 2.

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And let's think about
what else we know.

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We know that the usual
cosine function goes

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down to negative 1.

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But I've added 1 to it, so now
it only goes down to 0.

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OK?

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Hopefully that makes sense.

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Maybe I should even--

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hmm.

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I don't want to draw the actual
cosine function again

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right on here.

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But let me draw the regular
cosine function here.

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So we have it, the regular
cosine function--

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because I keep talking
about it--

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does something like this.

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It goes at 1 here, and
it's at 1 again here.

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And so it's at minus 1 at pi.

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And so, very roughly, it looks
something like this.

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Right?

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So I keep referencing the cosine
function, so this is

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the part I'm referencing.

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So we have to stretch it by 2,
and then shift it up by 1.

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And so we see what was at pi,
negative 1, I'm now going to

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be at 2 pi, 0.

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And then where do
these points go?

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This was pi over 2.

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The x value is going
to be doubled.

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I'm going to be at pi,
and the y value is

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going to go up by 1.

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So I'm at pi, 1 and 3, pi 1.

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And so the curve will look
something like this.

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I'm not an expert here, but
hopefully that looks something

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like the cosine time function.

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But with a stretch
and a shift.

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So that is the curve, r equals
1 plus cosine theta over 2 in

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what we consider the
r, theta plane.

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So theta is varying in this
direction and r is varying in

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this direction.

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But how do I transfer that
to the x, y plane?

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That's the real point
that I want to

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make about this problem.

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So let's look at what's
happening in the x, y plane.

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So this will be x and
this will be y.

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Let's pick some points
and try to

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figure out what's happening.

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So where is this point?

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This is the point
zero comma two.

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When theta is 0, r equals 2.

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Where is theta equal to
0 in this picture?

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It's in the x direction.

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Right?

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That's theta equals 0, and
also 2 pi and 4 pi.

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Any multiple of 2 pi, theta is
pointing in this direction.

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And r equals 2 there.

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So in a strange twist,
this is the point, 2,

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0 on the x, y plane.

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But that's no going to, that's
just a coincidence, OK?

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Don't think, oh, I'm just
going to flip the values

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everywhere.

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That's not going to happen.

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OK?

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Actually, and also, before I
make a mistake, I'm going to

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make this a little bit bigger.

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I want it to be bigger.

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So I don't want this to be 2.

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I want this to be 1.

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I'm going to make this 2, 0.

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I want to have a little
bigger picture.

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OK.

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So it's going to be 2, 0 at
theta equals 0 and r equal 2.

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Is it ever hit this
point again?

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Well, it is.

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And it's going to hit that
point again because it's

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periodic and I've gone
out to 4 pi.

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If I rotate all the way around,
I'm at 2 pi for theta.

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If I rotate all the way around
again I'm at 4 pi for theta,

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and my radius there
is 2, also.

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So this 2, 0 happens again
when I have this point.

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So it's going to close up.

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OK.

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And then what else happens?

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Well, as theta is rotating,
let's take theta

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between 0 and pi.

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theta rotates from 0 to
pi going like this.

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Notice what's happening
to the r value.

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The r value is going
from 2 down to 1.

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Now, I'm not going to be
totally exact, but--

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here's minus 1, OK,
in the x, y plane.

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I'm not going to be totally
exactly, but this curve is

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going to look something like--

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there's 2--

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it's going to look
something like--

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oops, I over-shot, we'll
make that negative 1--

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something like this.

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And what's the point?

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The point is that I start at
radius 2, and by the time I

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get to theta equals
pi I've gone down.

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And so my radius is 1.

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This has radius 1
and angle pi.

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So that represents this
part of the curve.

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That's this part of the curve.

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Now, what's nice about this
drawing is that we know this

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part of the curve and this part
of the curve should look

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exactly the same.

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So once I've drawn half of
this, I'm going to know

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everything.

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Once I've gone from
0 to 2 pi, I can

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just reflect it, basically.

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We'll see what I mean by reflect
in this case, but the

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same radii are happening
again and some sort

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of symmetric fashion.

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OK.

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So we've got 0 to pi.

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Now what happens between
pi and 2 pi?

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Notice pi to 2 pi in the theta
direction on the x, y plane is

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I start in this direction--

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I don't know if you can
see that, let me come

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over to this side--

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I start in this direction
for pi, and I'm

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going to rotate down.

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This is 3 pi over 2,
and this is 2 pi.

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Those are my angles.

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So what are my radii?

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Well, I start at radius 1 and
I'm going to radius 0.

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And so what happens is I'm
coming through this negative 1

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and I'm coming around, and
then by the time I get--

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it's going to be something like
this-- by the time I get

00:09:42.310 --> 00:09:45.260
to 2 pi, my radius is 0.

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Now just to make sure this curve
makes sense to you, you

00:09:48.430 --> 00:09:53.440
could pick a place, an angle,
maybe like right here.

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I don't know if that's easy to
see, but maybe that angle

00:09:55.430 --> 00:09:56.210
right there.

00:09:56.210 --> 00:09:59.480
That angle is between 3
pi over 2 and 2 pi.

00:09:59.480 --> 00:10:01.280
Is there positive
radius there?

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Yeah, there is positive
radius there.

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So in fact, this curve does come
into this fourth quadrant

00:10:06.540 --> 00:10:09.090
here and then curve back in.

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OK?

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It does curve back in.

00:10:11.550 --> 00:10:11.850
All right.

00:10:11.850 --> 00:10:16.020
So then what happens between
2 pi and 3 pi?

00:10:16.020 --> 00:10:16.150
OK.

00:10:16.150 --> 00:10:18.310
Hopefully this picture
is clear so far.

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I'm going to come back
to the other side.

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OK.

00:10:20.460 --> 00:10:22.390
What happens between
2 pi and 3 pi?

00:10:22.390 --> 00:10:24.020
2 pi, we're here.

00:10:24.020 --> 00:10:26.720
And 3 pi, we're back
over here again.

00:10:26.720 --> 00:10:30.490
And notice that the radius is
going to be doing the same

00:10:30.490 --> 00:10:33.200
kind of growth that it did
between 2 pi and 3 pi as it

00:10:33.200 --> 00:10:36.632
did decay from pi to 2 pi.

00:10:36.632 --> 00:10:37.500
OK?

00:10:37.500 --> 00:10:40.680
Because the radii now, there's
a symmetry with how the radii

00:10:40.680 --> 00:10:46.340
behave. So from 2 pi to 3 pi, I
start off with radius 0 and

00:10:46.340 --> 00:10:48.120
I have a small radius.

00:10:48.120 --> 00:10:53.870
And then once I get to 3 pi over
here, I'm going to have

00:10:53.870 --> 00:10:55.070
radius 1 again.

00:10:55.070 --> 00:10:56.940
I'm going to be at radius 1,
which is going to correspond

00:10:56.940 --> 00:10:57.840
to this point.

00:10:57.840 --> 00:11:00.580
So I'm going to have exactly
the same picture, which is

00:11:00.580 --> 00:11:03.265
dangerous because I probably
would do it wrong.

00:11:03.265 --> 00:11:06.840
But I'll try and draw it this
way and then talk about it.

00:11:06.840 --> 00:11:09.480
Hopefully that looks
about the same.

00:11:09.480 --> 00:11:13.570
So this curve coming through
here was from pi to 2 pi.

00:11:13.570 --> 00:11:17.750
This curve coming through here
was from to 2 pi to 3 pi.

00:11:17.750 --> 00:11:20.240
And then to finish it off, 3
pi to 4 pi is going to look

00:11:20.240 --> 00:11:22.310
like this curve here.

00:11:22.310 --> 00:11:24.260
So I come through--

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ooh, this is where it starts to
get really dangerous, but

00:11:27.440 --> 00:11:29.980
let's say that's
pretty close--

00:11:29.980 --> 00:11:33.160
so there's my 3 pi to 4 pi.

00:11:33.160 --> 00:11:36.410
It's again, the same growth
the way it was decaying

00:11:36.410 --> 00:11:38.260
between 0 and pi.

00:11:38.260 --> 00:11:43.940
So this is your picture in the
x, y plane of the curve, r

00:11:43.940 --> 00:11:47.150
equals 1 plus cosine
theta over 2.

00:11:47.150 --> 00:11:50.900
Now, we haven't calculated
any area problems, yet.

00:11:50.900 --> 00:11:54.210
So what I'd like us to do is
I'm going to shade two

00:11:54.210 --> 00:12:00.430
regions, and I want us to just
write down the integral form

00:12:00.430 --> 00:12:04.070
to find the area for each
of these regions.

00:12:04.070 --> 00:12:09.600
So the first region of interest
is the pink region.

00:12:09.600 --> 00:12:12.750
I'm going to ask us to find the
area of the pink region,

00:12:12.750 --> 00:12:16.420
and then I'm going to ask us to
find the area of everything

00:12:16.420 --> 00:12:17.670
else, the blue region.

00:12:20.450 --> 00:12:24.560
So let's think about
how to do that.

00:12:24.560 --> 00:12:26.980
And I think I'm going to have to
come over to the other side

00:12:26.980 --> 00:12:28.890
to write down the integrals,
but I'll be

00:12:28.890 --> 00:12:30.440
coming back and forth.

00:12:30.440 --> 00:12:35.700
So just to remind you, what you
saw in lecture was that dA

00:12:35.700 --> 00:12:40.550
is equal to r squared
over 2 d theta.

00:12:40.550 --> 00:12:42.740
That's what dA is.

00:12:42.740 --> 00:12:46.450
And so this is going to be an
integral in theta, and we know

00:12:46.450 --> 00:12:48.650
what r is as a function
of theta.

00:12:48.650 --> 00:12:52.890
And so if I want to find--
actually, I should even use my

00:12:52.890 --> 00:12:54.330
colors appropriately.

00:12:54.330 --> 00:12:59.890
I should say, the pink
area is going to

00:12:59.890 --> 00:13:01.860
be equal to an integral.

00:13:01.860 --> 00:13:03.780
And I'm going to write
the r squared.

00:13:03.780 --> 00:13:05.010
I know what r squared is.

00:13:05.010 --> 00:13:10.320
It's 1 plus cosine theta
over 2 squared, and

00:13:10.320 --> 00:13:12.560
then an over 2 d theta.

00:13:12.560 --> 00:13:14.810
And then what is important
about this?

00:13:14.810 --> 00:13:15.910
It's our bounds.

00:13:15.910 --> 00:13:16.090
Right?

00:13:16.090 --> 00:13:17.800
Our bounds are what's
important.

00:13:17.800 --> 00:13:21.760
And so let's go back and let's
look at our picture.

00:13:21.760 --> 00:13:25.680
What are the bounds on theta
for the pink region?

00:13:25.680 --> 00:13:28.540
So where does that pink
region start and stop?

00:13:28.540 --> 00:13:32.530
And maybe we even need to look
at this top graph, also.

00:13:32.530 --> 00:13:36.750
So if we think about it, we went
from 0 to pi to get this

00:13:36.750 --> 00:13:38.120
outer curve.

00:13:38.120 --> 00:13:39.440
So how do we get the
inner curve?

00:13:39.440 --> 00:13:44.070
The inner curve started at theta
equals pi, went to here,

00:13:44.070 --> 00:13:45.390
went to here--

00:13:45.390 --> 00:13:47.900
that was theta equals 3 pi.

00:13:47.900 --> 00:13:52.160
So it went all the way
from pi to 3 pi.

00:13:52.160 --> 00:13:55.410
Now, if you're paying good
attention, you can say, well,

00:13:55.410 --> 00:13:59.550
Christine, we know that this
region is totally symmetric.

00:13:59.550 --> 00:14:02.860
So why don't I just take the
area from pi to 2 pi and

00:14:02.860 --> 00:14:04.470
multiply it by 2?

00:14:04.470 --> 00:14:05.340
And you can.

00:14:05.340 --> 00:14:06.910
You can do it either way.

00:14:06.910 --> 00:14:09.900
So you can either take the
integral from all the way from

00:14:09.900 --> 00:14:13.880
pi to 3 pi, which corresponds
to starting at this angle,

00:14:13.880 --> 00:14:16.880
going all the way around, and
coming back to there, which

00:14:16.880 --> 00:14:18.240
takes you all the way
around this curve.

00:14:18.240 --> 00:14:21.780
Or you can go from pi to 2 pi
and multiply that by 2.

00:14:21.780 --> 00:14:25.470
So let me come back and let
me write that down.

00:14:25.470 --> 00:14:31.970
It's either pi to 3 pi, this,
or you just write it as

00:14:31.970 --> 00:14:34.310
integral from pi to 2 pi.

00:14:34.310 --> 00:14:38.430
And if I multiply this by
2, the 2 drops out.

00:14:38.430 --> 00:14:40.477
The 2 in the denominator
drops out.

00:14:44.680 --> 00:14:46.720
I'm not going to solve this
problem for you, but I do want

00:14:46.720 --> 00:14:48.850
to point out the kinds of terms
you would have. You

00:14:48.850 --> 00:14:51.060
would have a constant term
when you square this.

00:14:51.060 --> 00:14:54.370
You would have a term that was
2 cosine theta over 2, which

00:14:54.370 --> 00:14:56.980
is easy to integrate by
a u-substitution.

00:14:56.980 --> 00:14:59.990
And then you would have a cosine
squared theta over 2,

00:14:59.990 --> 00:15:03.160
which you'd want to use the
double angle formula or the

00:15:03.160 --> 00:15:06.310
half angle formula that you've
seen used to manipulate these

00:15:06.310 --> 00:15:08.040
integrals that involve
just a cosine

00:15:08.040 --> 00:15:09.680
squared or a sine squared.

00:15:09.680 --> 00:15:11.600
So that would be
your strategy.

00:15:11.600 --> 00:15:13.175
OK, now let's look
at the blue area.

00:15:13.175 --> 00:15:14.425
OK.

00:15:19.090 --> 00:15:22.110
So to find the blue area, again,
I know all that matters

00:15:22.110 --> 00:15:24.520
is really the bounds.

00:15:24.520 --> 00:15:26.515
We're going to see we have to
do a little extra work.

00:15:29.600 --> 00:15:31.000
But this is our first setup.

00:15:31.000 --> 00:15:33.090
And now let's go look
at the bounds.

00:15:33.090 --> 00:15:33.360
OK.

00:15:33.360 --> 00:15:35.880
So we go back to the curve.

00:15:35.880 --> 00:15:37.020
All right.

00:15:37.020 --> 00:15:38.000
What is the blue area?

00:15:38.000 --> 00:15:41.730
Well, the blue area, that's
a little harder.

00:15:41.730 --> 00:15:43.680
So let's see what happens.

00:15:43.680 --> 00:15:49.490
If I were to take theta from
0 to pi, what would happen?

00:15:49.490 --> 00:15:52.370
I would not only pick up the
blue area, but I'd pick up

00:15:52.370 --> 00:15:54.100
this pink stuff inside.

00:15:54.100 --> 00:15:55.640
But I don't want
the pink stuff.

00:15:55.640 --> 00:15:57.290
I just want the blue stuff.

00:15:57.290 --> 00:16:00.020
So what am I going to have to do
to find the blue area just,

00:16:00.020 --> 00:16:01.980
say, from 0 up to pi?

00:16:01.980 --> 00:16:05.080
I'm going to have to find the
area from 0 to pi, and then

00:16:05.080 --> 00:16:06.520
I'm going to have to
subtract off the

00:16:06.520 --> 00:16:07.722
area of this component.

00:16:07.722 --> 00:16:09.210
OK?

00:16:09.210 --> 00:16:10.660
But we know, actually,
how to find the

00:16:10.660 --> 00:16:12.490
area of this component.

00:16:12.490 --> 00:16:12.790
OK.

00:16:12.790 --> 00:16:14.120
So hopefully this makes sense.

00:16:14.120 --> 00:16:16.350
Because let's think about, when
I'm finding area, I'm

00:16:16.350 --> 00:16:18.420
going from the origin and I'm
coming out and I have the

00:16:18.420 --> 00:16:20.020
radius out there.

00:16:20.020 --> 00:16:24.930
So when I integrate this dA from
0 to pi for theta, I'm

00:16:24.930 --> 00:16:28.800
picking up pieces taht come out,
little sectors that come

00:16:28.800 --> 00:16:31.880
out like this between
pi over 2 and pi.

00:16:31.880 --> 00:16:34.960
So I'm getting more area than I
want if I just let theta go

00:16:34.960 --> 00:16:36.740
between 0 and pi.

00:16:36.740 --> 00:16:39.670
So I have to calculate all of
it, and then I have to take

00:16:39.670 --> 00:16:41.970
away the extra stuff.

00:16:41.970 --> 00:16:42.250
OK.

00:16:42.250 --> 00:16:45.410
So the blue area is actually
the bigger area subtracting

00:16:45.410 --> 00:16:47.180
the smaller area.

00:16:47.180 --> 00:16:48.890
And so how am I going
to write this?

00:16:48.890 --> 00:16:51.380
If we come back over, I'm just
going to take 2 times this

00:16:51.380 --> 00:16:52.440
whole thing.

00:16:52.440 --> 00:16:54.220
So I'm going to take
2 times this.

00:16:54.220 --> 00:16:57.580
And I know I have to integrate
it from 0 to pi.

00:16:57.580 --> 00:17:00.850
And I'm taking 2 times because
it's symmetric, remember.

00:17:00.850 --> 00:17:04.310
And then I'm going to subtract
track off this one that's 2

00:17:04.310 --> 00:17:06.360
times the thing from
pi to 2 pi.

00:17:06.360 --> 00:17:08.610
Now, you might say, well,
Christine, the pink stuff I'm

00:17:08.610 --> 00:17:13.780
interested in between 0 and pi
is actually theta between not

00:17:13.780 --> 00:17:15.830
pi and 2 pi, but
2 pi and 3 pi.

00:17:15.830 --> 00:17:17.880
But again, there's all this
symmetry in the problem.

00:17:17.880 --> 00:17:20.270
So it doesn't really matter.

00:17:20.270 --> 00:17:23.360
But if you're a stickler, I
guess I'll even write it this

00:17:23.360 --> 00:17:24.790
way just to make sure.

00:17:24.790 --> 00:17:27.200
So I'll write it as 2
pi to 3 pi so that

00:17:27.200 --> 00:17:28.129
everyone's very happy.

00:17:28.129 --> 00:17:29.379
OK?

00:17:34.920 --> 00:17:38.240
So again, what do we do?

00:17:38.240 --> 00:17:39.460
These 2's divide out.

00:17:39.460 --> 00:17:43.370
So from 0 to pi of r squared d
theta, that's going to give me

00:17:43.370 --> 00:17:46.890
the area of the blue
plus the pink.

00:17:46.890 --> 00:17:51.010
And then 2 pi to 3 pi of 1 plus
cosine over theta over 2

00:17:51.010 --> 00:17:54.510
squared d theta is going to give
me the area of the pink.

00:17:54.510 --> 00:17:58.600
So the blue plus the pink is
over here, and then the pink

00:17:58.600 --> 00:17:59.320
is over here.

00:17:59.320 --> 00:18:02.280
So when I subtract that off
I just get the blue.

00:18:02.280 --> 00:18:03.030
OK.

00:18:03.030 --> 00:18:06.220
Let me, again, just go back one
more time and point out

00:18:06.220 --> 00:18:08.190
what we did at the very
beginning to remind us what

00:18:08.190 --> 00:18:10.540
was happening.

00:18:10.540 --> 00:18:11.540
And then I will finish.

00:18:11.540 --> 00:18:13.700
So let's come back over here.

00:18:13.700 --> 00:18:18.190
So the idea was to graph this
curve that was in r is a

00:18:18.190 --> 00:18:19.620
function of theta.

00:18:19.620 --> 00:18:21.620
And I was supposed to understand
what that looked

00:18:21.620 --> 00:18:24.140
like in the x, y plane.

00:18:24.140 --> 00:18:30.680
And so my trick was to take the
relationship between r and

00:18:30.680 --> 00:18:33.050
theta and graph that explicitly

00:18:33.050 --> 00:18:35.160
in an r theta plane--

00:18:35.160 --> 00:18:37.370
so I let theta vary in the
horizontal direction and r

00:18:37.370 --> 00:18:39.090
vary in the vertical
direction--

00:18:39.090 --> 00:18:41.160
and I can do that very easily.

00:18:41.160 --> 00:18:44.830
And then translate that
into the x, y plane.

00:18:44.830 --> 00:18:49.380
So my curve, again, went the
big part, the little part

00:18:49.380 --> 00:18:52.390
here, little part here,
big part here.

00:18:52.390 --> 00:18:53.760
That was the order.

00:18:53.760 --> 00:18:58.045
So if you need arrows on
it, this was the order.

00:19:00.820 --> 00:19:04.890
And then once I had that, the
problem was about areas.

00:19:04.890 --> 00:19:08.340
And there was a lot of symmetry
in this problem, but

00:19:08.340 --> 00:19:13.560
the main point I wanted to show
was just knowing where

00:19:13.560 --> 00:19:16.570
your theta starts and stops is
not enough to determine an

00:19:16.570 --> 00:19:20.520
area of a region if that region
is excluding some part

00:19:20.520 --> 00:19:22.780
that would be potentially
counted twice.

00:19:22.780 --> 00:19:25.720
So that was the reason I wanted
you to calculate not

00:19:25.720 --> 00:19:30.190
just the pink area, but also see
that the blue is not from

00:19:30.190 --> 00:19:33.510
theta from 0 to pi, but you
have to subtract off this

00:19:33.510 --> 00:19:36.230
extra stuff that you counted.

00:19:36.230 --> 00:19:39.270
And I guess that is
where I will stop.