WEBVTT

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TOBIAS COLDING: Last
time, we talked about--

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one of the things we talked
about last time was series.

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So we'll continue on that today.

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So series is that
you have a sequence.

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You're starting with a sequence.

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So a n is a sequence.

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And then you form
a new sequence.

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So you form a new sequence.

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A new sequence from
a n as follows.

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So the new sequence, let's call
that Sn, and S1 is just a1,

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S2 is a1 plus a2, S3 is a1
plus a2 plus a3, and so on.

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So this is the sum of
the first n elements.

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And you typically write a Sn.

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You write Sn as
the sum here from--

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and then, in this case,
I'm starting at 1.

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But you could start at something
else, i equal to 1, to n of ai.

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And so to say that's the--

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so and you write the series.

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You also write-- so this is
slight abuse of notation,

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that you write this infinite
sum, sorry, as the series.

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So you think about this as--

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you think about this thing here.

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When you write this
thing here, you really

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think about the sequence Sn.

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So write this for
the sequence Sn.

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And so the series converge.

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This means that the
sequence Sn converges.

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And so the most--

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so remember that a sequence
converges-- so recall,

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by the Cauchy
convergence theorem--

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so recall by the Cauchy
convergence theorem

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that Sn converge if and only
if Sn is a Cauchy sequence.

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And a Cauchy sequence just means
that if you go sufficiently far

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out and you're looking
at this difference here,

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then this here is
small, provided

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that m and n are larger
than some capital

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N, where this here is
chosen depending on epsilon.

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That's what it means to
be a Cauchy sequence.

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So in particular, of course,
if you take-- so in particular,

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if you take m to be n plus 1--

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sorry.

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Let me say m to be n minus 1.

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Doesn't matter.

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So if I take it like
this, then Sn minus Sm.

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Well, this here is some
of the first n elements,

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and from that we
have to subtract

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the sum of the first
n minus 1 elements.

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So this here-- just
leave this here.

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Cancel out all of these.

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And so you're just
left with a n.

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So this means that if it is
converging, then in particular,

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a n here has to go to 0
as n goes to infinity.

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Because in fact,
this whole difference

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here, as long as m and n
are sufficiently large,

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has to be as small as you want.

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And so in a particularly
special case

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where this here is
the one prior to that,

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then you see that the a
n will have to go to 0.

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So again, if you see a
series, the first thing--

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you do don't apply any tests.

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The first thing that you check
is that this element here

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goes to 0.

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Now what are the most
important series?

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So the most important
is the geometric series.

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And the reason it's
the most important

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is that it can be
used to determine--

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it's easy to determine whether
it's converging or not.

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And it can be used to
determine using the test

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whether other series converge.

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And so the geometric series
is that you take a sum.

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Typically, here, you start at 0.

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You don't have to start at 0.

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But of course, the limit.

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The limit.

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If you take a series, then,
to say that it's converging,

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meaning that the
sequence Sn converges,

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and the limit of
these here is also.

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And that's where there's
this abuse of notation.

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It's denoted by the same thing.

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So this thing here is playing
the role of the sequence,

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but it's also
denoting the limit.

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That's just a standard thing.

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So in this case, I
was starting from 1.

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So now your matrix
series is where

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you take some number, c, and
then you multiply it by itself.

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This is some real number, and
you multiply it with itself

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i times, where i runs
from 0 to infinity.

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And when i is zero,
this is meant to be 1.

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And the reason why I
want to do it here at 0

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is that it's probably worth
remembering that this here, it's

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easy to deduce.

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But it's such a standard fact
that this here is converging.

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So the geometric
series converges,

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provided that the absolute
value of c is less than 1.

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And when it is, this
here is the limit.

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So then you can
ask if c here is 1,

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so if c is actually equal to 1.

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Not just the absolute value,
but if c is actually equal to 1,

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then it's just 1 times
itself a number of times.

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But that does not go to 0.

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So that's clearly diverging.

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And if it's minus 1 multiply
itself by a number of times,

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then it just alternates
between 1 and negative 1.

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So it doesn't go to 0.

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So it's divergent here.

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And in fact, as long as c
here is bigger or equal to--

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the absolute value is
bigger or equal to 1,

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because you take this
number and multiply it

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by itself a number of times,
if the absolute value of c

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is bigger than 1, then it
actually is even blowing up.

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It becomes larger and
larger in absolute value.

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So it's divergent here
and it's convergent.

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So that was kind of easy.

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And it was easy to
determine why we did--

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this little trick will
determine what this limit was.

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And this is a trick that
goes back, I think, certainly

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to the ancient Greeks,
I mean, this idea.

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And you can do this with various
other things, these things

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about adding things in
different order kind of stuff,

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or multiplying by something.

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So that was the most important.

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And again, we'll come back to
why it is the most important,

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but it's because it can
be used to determine

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whether other series
converge or not.

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Another classical, but that
sits inside a family of series

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is the harmonic series.

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So this is an
example of a series.

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It's one series that sits inside
a larger family of series.

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And so the harmonic series
is when you take 1 over n

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and you're summing
here like that.

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This series here, and we saw
that last time, is divergent.

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And in fact, the larger series
that is sitting inside is the--

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sits inside a larger family.

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And that larger
family is where you're

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summing from 1 to infinity
of 1 over n to the alpha.

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And here, alpha is taken
to be bigger or equal to 1.

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And so in the case where
alpha is equal to 1,

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that's a harmonic series.

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These ones diverge.

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But if alpha-- and so this
here is for alpha equal to 1.

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It's diverged because
it's the harmonic series.

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And when alpha is strictly
bigger than 1, what we

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just-- last time, we
just saw one example

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of this when alpha
was equal to 2,

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and we saw that that converged.

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But in fact, you can prove that
for any alpha strictly bigger

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than 1, it does converge.

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And the typical thing
to use there is--

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and we'll talk about that
at some later lecture

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is what's called
the integral test.

00:12:02.210 --> 00:12:09.680 align:middle line:90%


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Now there is-- when you have a
series, then most, but not all--

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00:12:25.280 --> 00:12:30.800 align:middle line:84%
most tests, but again,
not all, determine really

00:12:30.800 --> 00:12:35.520 align:middle line:84%
whether the series is what's
called absolutely convergent.

00:12:35.520 --> 00:12:36.968 align:middle line:84%
So what is absolutely
convergent?

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We talked about that last time.

00:12:38.260 --> 00:12:41.480 align:middle line:90%
But let me remind you.

00:12:41.480 --> 00:12:44.180 align:middle line:90%
Absolute convergence.

00:12:44.180 --> 00:12:48.900 align:middle line:90%


00:12:48.900 --> 00:12:56.100 align:middle line:84%
So if you take a
series here, then here

00:12:56.100 --> 00:12:59.100 align:middle line:90%
is absolutely convergent.

00:12:59.100 --> 00:13:00.880 align:middle line:90%
Is absolutely convergent.

00:13:00.880 --> 00:13:09.140 align:middle line:90%


00:13:09.140 --> 00:13:17.380 align:middle line:84%
This just means-- it means that
the series where you're slapping

00:13:17.380 --> 00:13:22.180 align:middle line:84%
on absolute value,
so this thing here,

00:13:22.180 --> 00:13:24.520 align:middle line:84%
means that this series
here is convergent.

00:13:24.520 --> 00:13:29.980 align:middle line:90%


00:13:29.980 --> 00:13:32.360 align:middle line:90%
And so it's easy to see.

00:13:32.360 --> 00:13:37.700 align:middle line:90%
So easy to see.

00:13:37.700 --> 00:13:41.020 align:middle line:90%
And we saw this last time.

00:13:41.020 --> 00:13:43.610 align:middle line:84%
And it was just from the
Cauchy convergence theorem.

00:13:43.610 --> 00:13:52.350 align:middle line:90%


00:13:52.350 --> 00:14:05.750 align:middle line:84%
It is easy to see that absolute
convergence implies convergence,

00:14:05.750 --> 00:14:07.750 align:middle line:90%
but not the other way around.

00:14:07.750 --> 00:14:12.430 align:middle line:84%
So Cauchy convergence theorem
gives you this implication.

00:14:12.430 --> 00:14:17.350 align:middle line:84%
Why it's not the case that
you have the other way around?

00:14:17.350 --> 00:14:25.670 align:middle line:84%
And that is because what's
called the alternating series.

00:14:25.670 --> 00:14:29.550 align:middle line:90%
So the alternating series.

00:14:29.550 --> 00:14:30.570 align:middle line:90%
Alternating.

00:14:30.570 --> 00:14:34.550 align:middle line:90%


00:14:34.550 --> 00:14:38.270 align:middle line:84%
And there's something called
the alternating series test.

00:14:38.270 --> 00:14:41.810 align:middle line:84%
But let me just
explain to you in words

00:14:41.810 --> 00:14:44.530 align:middle line:84%
why the alternating
series converge.

00:14:44.530 --> 00:14:46.580 align:middle line:84%
So the alternating
harmonic series.

00:14:46.580 --> 00:14:54.330 align:middle line:90%


00:14:54.330 --> 00:15:01.330 align:middle line:84%
So if you take this series
here minus 1 to the n times--

00:15:01.330 --> 00:15:07.410 align:middle line:84%
over n and you sum
here from 0 to--

00:15:07.410 --> 00:15:11.490 align:middle line:84%
sorry, not 0, because you're
dividing by 0, so from 1

00:15:11.490 --> 00:15:16.090 align:middle line:84%
to infinity, this here is
called the alternating series.

00:15:16.090 --> 00:15:18.930 align:middle line:90%
Alternating harmonic series.

00:15:18.930 --> 00:15:22.290 align:middle line:84%
If you were slapping an
absolute value sign on it,

00:15:22.290 --> 00:15:28.850 align:middle line:84%
this means that a n here is
minus 1 to the power n over n.

00:15:28.850 --> 00:15:34.930 align:middle line:84%
So if you take the
absolute value sign of a n,

00:15:34.930 --> 00:15:37.410 align:middle line:90%
then this here is just 1.

00:15:37.410 --> 00:15:39.370 align:middle line:90%
So this is 1 over n.

00:15:39.370 --> 00:15:43.270 align:middle line:84%
So this here is the
corresponding series when

00:15:43.270 --> 00:15:45.070 align:middle line:90%
you're slapping absolute value.

00:15:45.070 --> 00:15:46.640 align:middle line:90%
And this is the harmonic series.

00:15:46.640 --> 00:15:51.910 align:middle line:90%


00:15:51.910 --> 00:15:55.170 align:middle line:90%
And this is divergent.

00:15:55.170 --> 00:15:57.830 align:middle line:90%
That was what we just discussed.

00:15:57.830 --> 00:16:00.722 align:middle line:84%
Now why is this series
here convergent?

00:16:00.722 --> 00:16:04.590 align:middle line:84%
We'll probably come back to that
in a later lecture in a more

00:16:04.590 --> 00:16:08.060 align:middle line:84%
general setting, but let
me just explain this.

00:16:08.060 --> 00:16:11.910 align:middle line:90%


00:16:11.910 --> 00:16:21.030 align:middle line:84%
And so the idea is that
before you start summing,

00:16:21.030 --> 00:16:25.030 align:middle line:84%
imagine that you have here--
before you start your sum,

00:16:25.030 --> 00:16:28.642 align:middle line:84%
then you are in a neutral
position, which is 1.

00:16:28.642 --> 00:16:30.030 align:middle line:90%
0, sorry.

00:16:30.030 --> 00:16:35.350 align:middle line:90%
And then you do the first thing.

00:16:35.350 --> 00:16:38.210 align:middle line:90%
You're looking at S1.

00:16:38.210 --> 00:16:43.280 align:middle line:84%
But S1 will bring
you down, because S1

00:16:43.280 --> 00:16:47.740 align:middle line:84%
is just equal to minus
1 to the power 1.

00:16:47.740 --> 00:16:49.060 align:middle line:90%
But that's minus 1.

00:16:49.060 --> 00:16:51.280 align:middle line:90%
So it's minus 1 over n.

00:16:51.280 --> 00:16:53.800 align:middle line:90%
This is the first element.

00:16:53.800 --> 00:16:56.040 align:middle line:84%
So that's going
to bring you down.

00:16:56.040 --> 00:16:59.720 align:middle line:84%
Let me just
exaggerate the picture

00:16:59.720 --> 00:17:04.359 align:middle line:84%
and bring you down
here to minus 1 over n.

00:17:04.359 --> 00:17:08.180 align:middle line:90%
Minus 1 over-- n is equal to 1.

00:17:08.180 --> 00:17:11.160 align:middle line:90%
So this is minus 1.

00:17:11.160 --> 00:17:15.000 align:middle line:90%
This is how the series starts.

00:17:15.000 --> 00:17:18.680 align:middle line:90%
And so the next element is S2.

00:17:18.680 --> 00:17:21.020 align:middle line:90%
But S2 is minus 1.

00:17:21.020 --> 00:17:22.760 align:middle line:90%
That was the first element.

00:17:22.760 --> 00:17:30.480 align:middle line:84%
And then plus and then
minus 1 squared over 2.

00:17:30.480 --> 00:17:33.920 align:middle line:84%
So this is-- and you would
be tempted, but it's not--

00:17:33.920 --> 00:17:36.300 align:middle line:90%
don't add them at this stage.

00:17:36.300 --> 00:17:40.610 align:middle line:84%
But just looking
at it like this.

00:17:40.610 --> 00:17:48.460 align:middle line:84%
So the next-- so
this here is S1.

00:17:48.460 --> 00:17:50.700 align:middle line:90%
Let me just write it down here.

00:17:50.700 --> 00:17:52.580 align:middle line:90%
This is S1.

00:17:52.580 --> 00:17:57.780 align:middle line:84%
When you're looking at S2, then
you're coming back towards 0.

00:17:57.780 --> 00:18:02.440 align:middle line:84%
But you don't go as far
up as you went down,

00:18:02.440 --> 00:18:05.580 align:middle line:90%
because it's 1 over 2.

00:18:05.580 --> 00:18:06.080 align:middle line:90%
Right.

00:18:06.080 --> 00:18:08.740 align:middle line:90%
So this here is S2.

00:18:08.740 --> 00:18:12.300 align:middle line:84%
And then you see
the next one is--

00:18:12.300 --> 00:18:13.360 align:middle line:90%
the next one.

00:18:13.360 --> 00:18:18.500 align:middle line:84%
If you start here, then you
are supposed to-- so for S3,

00:18:18.500 --> 00:18:26.220 align:middle line:84%
it's really S2 plus minus
1 to the power 3 over 3.

00:18:26.220 --> 00:18:32.100 align:middle line:84%
So this is S2 minus, because
minus 1 to the power 3

00:18:32.100 --> 00:18:35.400 align:middle line:90%
is a negative sign like that.

00:18:35.400 --> 00:18:38.800 align:middle line:90%
So the next one here--

00:18:38.800 --> 00:18:42.460 align:middle line:84%
so you're starting here before
you have done any summation.

00:18:42.460 --> 00:18:44.000 align:middle line:90%
You're starting at 0.

00:18:44.000 --> 00:18:45.440 align:middle line:90%
You're brought down here.

00:18:45.440 --> 00:18:47.960 align:middle line:90%
You come up here.

00:18:47.960 --> 00:18:50.300 align:middle line:84%
But then in S3,
you're going down,

00:18:50.300 --> 00:18:53.600 align:middle line:84%
but you don't go as far
down as the previous one.

00:18:53.600 --> 00:18:55.320 align:middle line:90%
So you're going down here.

00:18:55.320 --> 00:18:58.220 align:middle line:84%
And so you're really
continuing this process.

00:18:58.220 --> 00:19:01.000 align:middle line:84%
And you see that this interval
gets smaller and smaller,

00:19:01.000 --> 00:19:03.380 align:middle line:84%
and it just goes down,
and then it come up.

00:19:03.380 --> 00:19:07.200 align:middle line:84%
But it doesn't go as far
up as you were before,

00:19:07.200 --> 00:19:08.700 align:middle line:90%
and then so on and so forth.

00:19:08.700 --> 00:19:11.500 align:middle line:84%
And so you could make
this more precise.

00:19:11.500 --> 00:19:13.000 align:middle line:90%
It's quite easy.

00:19:13.000 --> 00:19:16.460 align:middle line:84%
And this shows you that
this series is converging.

00:19:16.460 --> 00:19:20.680 align:middle line:84%
And in fact, this is the basis
for this alternating series

00:19:20.680 --> 00:19:21.180 align:middle line:90%
test.

00:19:21.180 --> 00:19:24.440 align:middle line:84%
And it works as long as
you have alternating--

00:19:24.440 --> 00:19:27.800 align:middle line:84%
where the sign of the
a n's are alternating

00:19:27.800 --> 00:19:30.240 align:middle line:84%
and the absolute
value goes to 0.

00:19:30.240 --> 00:19:32.840 align:middle line:84%
Then this here, that's
your alternating series.

00:19:32.840 --> 00:19:35.970 align:middle line:84%
So I'll probably come back
to that at some later stage.

00:19:35.970 --> 00:19:44.050 align:middle line:84%
But this just shows you that
if you take a series, then--

00:19:44.050 --> 00:19:46.770 align:middle line:84%
So the absolute
convergence means

00:19:46.770 --> 00:19:48.990 align:middle line:84%
that if you slap
absolute value sign,

00:19:48.990 --> 00:19:51.930 align:middle line:84%
then that new series
also converges.

00:19:51.930 --> 00:19:55.065 align:middle line:84%
Absolute convergence
implies convergence, but not

00:19:55.065 --> 00:19:55.940 align:middle line:90%
the other way around.

00:19:55.940 --> 00:19:58.750 align:middle line:90%


00:19:58.750 --> 00:20:03.910 align:middle line:90%
So now the next thing is that--

00:20:03.910 --> 00:20:07.200 align:middle line:84%
so the next thing is that
if you take a series--

00:20:07.200 --> 00:20:11.370 align:middle line:90%


00:20:11.370 --> 00:20:16.730 align:middle line:84%
suppose you take a series and
suppose that you knew that--

00:20:16.730 --> 00:20:24.610 align:middle line:84%
so suppose you have a series
like this and you knew that

00:20:24.610 --> 00:20:26.470 align:middle line:90%
a n here--

00:20:26.470 --> 00:20:29.750 align:middle line:84%
all of the a n's were
non-negative for all n.

00:20:29.750 --> 00:20:33.590 align:middle line:90%


00:20:33.590 --> 00:20:35.950 align:middle line:90%
Then convergence here.

00:20:35.950 --> 00:20:36.950 align:middle line:90%
Convergence.

00:20:36.950 --> 00:20:41.110 align:middle line:90%


00:20:41.110 --> 00:20:42.370 align:middle line:90%
Just implied, right?

00:20:42.370 --> 00:20:47.550 align:middle line:84%
So convergence is-- because
the Sn is now the sum here

00:20:47.550 --> 00:20:48.890 align:middle line:90%
of these guys here.

00:20:48.890 --> 00:20:51.470 align:middle line:90%


00:20:51.470 --> 00:20:53.830 align:middle line:90%
That's Sn.

00:20:53.830 --> 00:20:55.850 align:middle line:84%
And you see that
this is, of course,

00:20:55.850 --> 00:20:58.150 align:middle line:84%
less than or equal to--
because all of these guys

00:20:58.150 --> 00:21:03.030 align:middle line:84%
are non-negative, it's less than
or equal to where you summing.

00:21:03.030 --> 00:21:08.710 align:middle line:84%
Not just up to n, but one more,
because this is non-negative.

00:21:08.710 --> 00:21:11.190 align:middle line:90%
And so this is Sn plus 1.

00:21:11.190 --> 00:21:14.910 align:middle line:84%
So you see that if the
elements are non-negative,

00:21:14.910 --> 00:21:18.610 align:middle line:90%
then the sequence Sn is--

00:21:18.610 --> 00:21:24.210 align:middle line:84%
so Sn is monotone
non-decreasing sequence.

00:21:24.210 --> 00:21:27.870 align:middle line:84%
And so to say-- by the
monotone convergence theorem,

00:21:27.870 --> 00:21:31.510 align:middle line:84%
to say that this sequence,
Sn, is convergent,

00:21:31.510 --> 00:21:33.950 align:middle line:90%
is equivalent to saying that.

00:21:33.950 --> 00:21:47.500 align:middle line:84%
So Sn converges if and only
if Sn is bounded from above.

00:21:47.500 --> 00:21:58.290 align:middle line:90%


00:21:58.290 --> 00:21:58.790 align:middle line:90%
OK.

00:21:58.790 --> 00:22:03.890 align:middle line:84%
So now when you have a
series and you have already

00:22:03.890 --> 00:22:08.730 align:middle line:84%
checked that a n goes
to 0, and you are then

00:22:08.730 --> 00:22:13.590 align:middle line:84%
asked to determine whether the
series is convergent or not,

00:22:13.590 --> 00:22:15.830 align:middle line:84%
then there are these
number of tests.

00:22:15.830 --> 00:22:18.150 align:middle line:90%
And so there's a bunch of tests.

00:22:18.150 --> 00:22:24.750 align:middle line:90%
So tests for convergence.

00:22:24.750 --> 00:22:30.090 align:middle line:90%


00:22:30.090 --> 00:22:32.220 align:middle line:90%
And so there's a bunch of them.

00:22:32.220 --> 00:22:35.340 align:middle line:90%
And let me talk about--

00:22:35.340 --> 00:22:37.870 align:middle line:84%
in this lecture, I'll just
talk about the comparison test.

00:22:37.870 --> 00:22:40.740 align:middle line:90%


00:22:40.740 --> 00:22:46.040 align:middle line:84%
And I mentioned them
very briefly last time,

00:22:46.040 --> 00:22:48.020 align:middle line:84%
but I'll talk a little
bit more about them.

00:22:48.020 --> 00:22:49.570 align:middle line:90%
And then there's the ratio test.

00:22:49.570 --> 00:22:56.980 align:middle line:90%


00:22:56.980 --> 00:22:59.120 align:middle line:90%
And then there's the root test.

00:22:59.120 --> 00:23:01.180 align:middle line:90%
So I'll talk about those three.

00:23:01.180 --> 00:23:02.740 align:middle line:90%
But there are other tests.

00:23:02.740 --> 00:23:03.590 align:middle line:90%
So root test.

00:23:03.590 --> 00:23:14.500 align:middle line:90%


00:23:14.500 --> 00:23:20.140 align:middle line:84%
So now let's start with
the comparison test.

00:23:20.140 --> 00:23:22.850 align:middle line:84%
And there are two
versions of this.

00:23:22.850 --> 00:23:27.060 align:middle line:90%


00:23:27.060 --> 00:23:30.660 align:middle line:90%
One version is the following.

00:23:30.660 --> 00:23:40.460 align:middle line:84%
Let's suppose that you have--
so comparison test version one.

00:23:40.460 --> 00:23:46.240 align:middle line:90%


00:23:46.240 --> 00:23:49.640 align:middle line:84%
And so the first version
of the comparison test

00:23:49.640 --> 00:23:50.780 align:middle line:90%
is the following.

00:23:50.780 --> 00:23:56.460 align:middle line:84%
Imagine that you have two
series here, a n, and again,

00:23:56.460 --> 00:23:58.220 align:middle line:90%
we talked about this last time.

00:23:58.220 --> 00:24:02.880 align:middle line:84%
But let me just say a few more
words, that you have this series

00:24:02.880 --> 00:24:04.840 align:middle line:90%
and you have that series.

00:24:04.840 --> 00:24:11.080 align:middle line:84%
And I'm assuming here
that a n and the bn

00:24:11.080 --> 00:24:12.540 align:middle line:90%
are non-negative numbers.

00:24:12.540 --> 00:24:17.800 align:middle line:84%
And in fact, I'm assuming that
bn is larger or equal to a n.

00:24:17.800 --> 00:24:20.460 align:middle line:84%
In the comparison
test, this version,

00:24:20.460 --> 00:24:28.460 align:middle line:84%
the simple version of the
comparison test is this here.

00:24:28.460 --> 00:24:38.780 align:middle line:84%
If the series based on
the bn is convergent,

00:24:38.780 --> 00:24:47.160 align:middle line:84%
then the series of the a
n's is also convergent.

00:24:47.160 --> 00:24:52.860 align:middle line:90%


00:24:52.860 --> 00:24:57.660 align:middle line:84%
And so this version
of the comparison test

00:24:57.660 --> 00:25:00.820 align:middle line:84%
is used both in this
way, but it's also

00:25:00.820 --> 00:25:05.720 align:middle line:84%
used sometimes where you know
that this series is divergent.

00:25:05.720 --> 00:25:08.380 align:middle line:84%
And from that, you conclude
that this one is just

00:25:08.380 --> 00:25:09.960 align:middle line:90%
a negation of this statement.

00:25:09.960 --> 00:25:14.420 align:middle line:90%


00:25:14.420 --> 00:25:18.100 align:middle line:90%
So let's see.

00:25:18.100 --> 00:25:24.900 align:middle line:84%
So the proof here of
that is actually easy.

00:25:24.900 --> 00:25:28.390 align:middle line:90%
So why is this the case?

00:25:28.390 --> 00:25:38.670 align:middle line:84%
Well, the thing is that you
know by the Cauchy convergence

00:25:38.670 --> 00:25:39.170 align:middle line:90%
theorem.

00:25:39.170 --> 00:25:46.790 align:middle line:90%


00:25:46.790 --> 00:25:51.790 align:middle line:84%
And we know that to
determine whether--

00:25:51.790 --> 00:25:56.110 align:middle line:84%
all we need to check to
determine whether this sequence

00:25:56.110 --> 00:25:57.870 align:middle line:90%
here is convergent--

00:25:57.870 --> 00:26:08.230 align:middle line:84%
all we need to figure out is
if it is a Cauchy sequence.

00:26:08.230 --> 00:26:12.310 align:middle line:84%
So this means that
you want to say that--

00:26:12.310 --> 00:26:23.110 align:middle line:84%
so suppose you're looking at
the sequence defined from a.

00:26:23.110 --> 00:26:28.010 align:middle line:84%
And so this is just where
I'm now summing the first n

00:26:28.010 --> 00:26:32.250 align:middle line:90%
elements in a.

00:26:32.250 --> 00:26:35.630 align:middle line:90%
And I just want to--

00:26:35.630 --> 00:26:40.490 align:middle line:84%
so I'm using the
superscript a just

00:26:40.490 --> 00:26:44.250 align:middle line:84%
to denote that it's coming
from the sequence a n.

00:26:44.250 --> 00:26:48.670 align:middle line:84%
So if you're looking at
this, and so likewise,

00:26:48.670 --> 00:26:50.450 align:middle line:90%
I look at this thing here.

00:26:50.450 --> 00:26:55.130 align:middle line:90%


00:26:55.130 --> 00:26:58.210 align:middle line:84%
Now, of course, you
have that suppose you're

00:26:58.210 --> 00:27:02.650 align:middle line:90%
looking at Sna minus Sma.

00:27:02.650 --> 00:27:05.570 align:middle line:90%


00:27:05.570 --> 00:27:08.730 align:middle line:84%
You want to show
that this here--

00:27:08.730 --> 00:27:11.630 align:middle line:84%
you want to show that this
here is a Cauchy sequence.

00:27:11.630 --> 00:27:15.010 align:middle line:84%
So you're looking at
this difference here.

00:27:15.010 --> 00:27:19.570 align:middle line:84%
But this thing here is
just this here difference.

00:27:19.570 --> 00:27:23.810 align:middle line:84%
I'm assuming that
m is less than n.

00:27:23.810 --> 00:27:25.710 align:middle line:90%
Strictly less than m.

00:27:25.710 --> 00:27:27.030 align:middle line:90%
n, sorry.

00:27:27.030 --> 00:27:30.510 align:middle line:84%
This just means that
this difference here

00:27:30.510 --> 00:27:35.250 align:middle line:84%
is just where you're
coming from m plus 1.

00:27:35.250 --> 00:27:42.416 align:middle line:84%
So this is just the
a m plus 1 up to a n.

00:27:42.416 --> 00:27:45.630 align:middle line:90%
This is just this one.

00:27:45.630 --> 00:27:46.710 align:middle line:90%
Yeah?

00:27:46.710 --> 00:27:50.730 align:middle line:84%
AUDIENCE: When we're proving
convergence, there's now--

00:27:50.730 --> 00:27:52.870 align:middle line:84%
just to give some
motivation, is the reason

00:27:52.870 --> 00:27:55.613 align:middle line:84%
that we're using
Cauchy sequences?

00:27:55.613 --> 00:27:57.030 align:middle line:84%
TOBIAS COLDING:
At this stage, you

00:27:57.030 --> 00:27:59.770 align:middle line:84%
could either use Cauchy
sequence, that's what I started.

00:27:59.770 --> 00:28:02.810 align:middle line:84%
You could also have used the
monotone convergence theorem.

00:28:02.810 --> 00:28:04.394 align:middle line:90%
Maybe that would be--

00:28:04.394 --> 00:28:04.936 align:middle line:90%
AUDIENCE: OK.

00:28:04.936 --> 00:28:05.550 align:middle line:84%
Because I was just
going to say, back

00:28:05.550 --> 00:28:07.633 align:middle line:84%
to the definition of
convergence that we initially

00:28:07.633 --> 00:28:10.252 align:middle line:84%
had where we had the absolute
value of a of n minus some--

00:28:10.252 --> 00:28:11.710 align:middle line:84%
TOBIAS COLDING:
Yeah, that's right.

00:28:11.710 --> 00:28:13.690 align:middle line:84%
AUDIENCE: Is it
just like-- is it--

00:28:13.690 --> 00:28:16.150 align:middle line:84%
TOBIAS COLDING: So if
you went all the way back

00:28:16.150 --> 00:28:18.350 align:middle line:84%
to the definition,
then you would

00:28:18.350 --> 00:28:20.640 align:middle line:84%
have to determine
what the limit was.

00:28:20.640 --> 00:28:21.430 align:middle line:84%
AUDIENCE: Right,
which we don't want.

00:28:21.430 --> 00:28:23.763 align:middle line:84%
TOBIAS COLDING: And we don't
want because we don't know.

00:28:23.763 --> 00:28:26.160 align:middle line:84%
But just because we may
know what the limit of b--

00:28:26.160 --> 00:28:28.980 align:middle line:90%
of the sequence based on b is.

00:28:28.980 --> 00:28:31.160 align:middle line:84%
But this doesn't mean that
you can figure out what

00:28:31.160 --> 00:28:32.120 align:middle line:90%
the limit of the a--

00:28:32.120 --> 00:28:34.920 align:middle line:84%
AUDIENCE: So does that
motivate why the sequences are

00:28:34.920 --> 00:28:35.940 align:middle line:90%
more useful in general?

00:28:35.940 --> 00:28:36.580 align:middle line:84%
TOBIAS COLDING:
Yeah, that's right.

00:28:36.580 --> 00:28:36.940 align:middle line:90%
That's right.

00:28:36.940 --> 00:28:37.482 align:middle line:90%
That's right.

00:28:37.482 --> 00:28:38.460 align:middle line:90%
Exactly, that's right.

00:28:38.460 --> 00:28:39.002 align:middle line:90%
That's right.

00:28:39.002 --> 00:28:41.080 align:middle line:84%
So the advantage
with Cauchy sequence

00:28:41.080 --> 00:28:44.340 align:middle line:84%
is that you don't have to
figure out what the limit is.

00:28:44.340 --> 00:28:48.060 align:middle line:84%
And it's often-- I mean, like
in this case, you have no idea.

00:28:48.060 --> 00:28:51.980 align:middle line:84%
I mean, it's not in terms
of anything from the b's.

00:28:51.980 --> 00:28:56.240 align:middle line:84%
And I should-- but let me just
continue doing it like this.

00:28:56.240 --> 00:28:59.320 align:middle line:84%
But just now when you
asked, I should probably

00:28:59.320 --> 00:29:02.880 align:middle line:84%
have done it using the
monotone convergence theorem.

00:29:02.880 --> 00:29:04.700 align:middle line:84%
But you can do that
as an exercise.

00:29:04.700 --> 00:29:07.240 align:middle line:90%
But it doesn't matter.

00:29:07.240 --> 00:29:11.980 align:middle line:90%
So the difference here is--

00:29:11.980 --> 00:29:14.320 align:middle line:90%
this is what the difference is.

00:29:14.320 --> 00:29:17.040 align:middle line:84%
The absolute value signs
are really irrelevant,

00:29:17.040 --> 00:29:19.140 align:middle line:84%
because these are all
non-negative numbers.

00:29:19.140 --> 00:29:23.685 align:middle line:84%
So I don't have to have
the absolute value sign.

00:29:23.685 --> 00:29:27.200 align:middle line:84%
And now this thing here
is, of course, less than.

00:29:27.200 --> 00:29:29.950 align:middle line:84%
But this here is less than
the corresponding b's.

00:29:29.950 --> 00:29:34.420 align:middle line:90%


00:29:34.420 --> 00:29:39.660 align:middle line:84%
And this is less than the
corresponding b here like that.

00:29:39.660 --> 00:29:48.500 align:middle line:84%
But this here is exactly
Sn, the one based on bSm.

00:29:48.500 --> 00:29:50.060 align:middle line:90%
Based on b.

00:29:50.060 --> 00:29:53.760 align:middle line:84%
And this here, as long as n
and m are sufficiently large,

00:29:53.760 --> 00:29:55.820 align:middle line:84%
we can make this as
small as we want.

00:29:55.820 --> 00:29:58.150 align:middle line:84%
So therefore, this here
was the smallest one.

00:29:58.150 --> 00:30:01.700 align:middle line:90%


00:30:01.700 --> 00:30:03.380 align:middle line:84%
You could also have
done it-- maybe

00:30:03.380 --> 00:30:05.540 align:middle line:84%
let's just say
that you could also

00:30:05.540 --> 00:30:10.040 align:middle line:84%
have done it using the monotone
convergence, because now,

00:30:10.040 --> 00:30:15.060 align:middle line:90%
of course, you have that.

00:30:15.060 --> 00:30:16.900 align:middle line:90%
Again, the same of thing.

00:30:16.900 --> 00:30:21.780 align:middle line:84%
Say that if you take
the Sn based on the a's.

00:30:21.780 --> 00:30:27.320 align:middle line:84%
So that's a1 up to a
n sum of these guys.

00:30:27.320 --> 00:30:31.110 align:middle line:84%
But this individually is less
than the corresponding b's.

00:30:31.110 --> 00:30:34.560 align:middle line:90%


00:30:34.560 --> 00:30:41.040 align:middle line:84%
And this here is just the
sequence Sn based on the b's.

00:30:41.040 --> 00:30:45.360 align:middle line:90%
But these here converge.

00:30:45.360 --> 00:30:48.480 align:middle line:84%
This is equivalent to saying
that they are bounded.

00:30:48.480 --> 00:30:49.920 align:middle line:90%
They are less than some c--

00:30:49.920 --> 00:30:51.920 align:middle line:90%
some real number c.

00:30:51.920 --> 00:30:53.660 align:middle line:90%
And this here is for all a.

00:30:53.660 --> 00:30:57.040 align:middle line:90%


00:30:57.040 --> 00:30:59.120 align:middle line:90%
For all n, sorry.

00:30:59.120 --> 00:31:01.560 align:middle line:84%
But this means, of course,
that those things here

00:31:01.560 --> 00:31:05.260 align:middle line:90%
are bounded for all n.

00:31:05.260 --> 00:31:10.760 align:middle line:84%
And this here is also a monotone
sequence-- monotone increasing

00:31:10.760 --> 00:31:13.880 align:middle line:84%
sequence that is not
bounded from above.

00:31:13.880 --> 00:31:16.360 align:middle line:90%
So therefore, it converges.

00:31:16.360 --> 00:31:19.690 align:middle line:84%
So you can do it either
of those two ways.

00:31:19.690 --> 00:31:22.530 align:middle line:90%
So that's really easy to check.

00:31:22.530 --> 00:31:26.340 align:middle line:84%
Let's see an example where
we are using this test here.

00:31:26.340 --> 00:31:34.490 align:middle line:90%


00:31:34.490 --> 00:31:43.170 align:middle line:84%
And so this could be that you're
looking at something like--

00:31:43.170 --> 00:31:45.880 align:middle line:84%
you're looking at--
so here's an example.

00:31:45.880 --> 00:31:50.530 align:middle line:90%


00:31:50.530 --> 00:31:54.890 align:middle line:84%
You're looking at a series
that is true to the minus n

00:31:54.890 --> 00:32:00.550 align:middle line:84%
over n, n equal
to 1 to infinity.

00:32:00.550 --> 00:32:04.050 align:middle line:90%


00:32:04.050 --> 00:32:08.090 align:middle line:84%
And you want to show--
you're being asked,

00:32:08.090 --> 00:32:14.210 align:middle line:90%
is this series converging?

00:32:14.210 --> 00:32:17.170 align:middle line:90%


00:32:17.170 --> 00:32:22.750 align:middle line:84%
So this is typically
how it works.

00:32:22.750 --> 00:32:24.950 align:middle line:84%
And so, of course,
in this case, you

00:32:24.950 --> 00:32:30.830 align:middle line:84%
should think about that
this here is a sequence a n.

00:32:30.830 --> 00:32:33.750 align:middle line:90%
And so you have to find the bn.

00:32:33.750 --> 00:32:37.430 align:middle line:84%
But in this case, we just
say-- so we're setting a.

00:32:37.430 --> 00:32:49.230 align:middle line:84%
So answer set a n equal
to 2 to minus n over 2

00:32:49.230 --> 00:32:53.930 align:middle line:84%
and bn equal to
2 to the minus n.

00:32:53.930 --> 00:32:58.683 align:middle line:90%


00:32:58.683 --> 00:33:05.760 align:middle line:84%
Then you have that a n bigger or
equal to 0 is smaller than bn.

00:33:05.760 --> 00:33:09.350 align:middle line:90%


00:33:09.350 --> 00:33:17.130 align:middle line:84%
And the sequence
here based on the bn

00:33:17.130 --> 00:33:23.520 align:middle line:84%
is a convergent
geometric series.

00:33:23.520 --> 00:33:28.970 align:middle line:90%


00:33:28.970 --> 00:33:34.830 align:middle line:84%
It's convergent between--
because c here, in this case,

00:33:34.830 --> 00:33:36.570 align:middle line:90%
is 1 over 2.

00:33:36.570 --> 00:33:38.690 align:middle line:90%
It's 1 over 2.

00:33:38.690 --> 00:33:41.170 align:middle line:90%
So it's just 1 over 2.

00:33:41.170 --> 00:33:44.230 align:middle line:84%
1.5 is the same as
2 to the minus 1.

00:33:44.230 --> 00:33:47.450 align:middle line:90%


00:33:47.450 --> 00:33:49.550 align:middle line:90%
And so this is convergent.

00:33:49.550 --> 00:33:52.910 align:middle line:90%


00:33:52.910 --> 00:33:55.490 align:middle line:90%
So this is just so--

00:33:55.490 --> 00:33:58.570 align:middle line:84%
so typically, this could
be used to-- that you're

00:33:58.570 --> 00:34:00.690 align:middle line:84%
given a sequence and
you're being asked,

00:34:00.690 --> 00:34:02.690 align:middle line:90%
is convergent or not?

00:34:02.690 --> 00:34:06.170 align:middle line:84%
And so you have to
find the sequence

00:34:06.170 --> 00:34:09.330 align:middle line:84%
and you're being asked whether
it's convergent or not.

00:34:09.330 --> 00:34:14.489 align:middle line:84%
And you have to find
the comparison series.

00:34:14.489 --> 00:34:24.460 align:middle line:84%
And then, in this case, say that
this thing here is convergent.

00:34:24.460 --> 00:34:27.500 align:middle line:84%
And so therefore,
the sequence a n

00:34:27.500 --> 00:34:34.460 align:middle line:84%
that was squeezed between that
and 0 was also convergent.

00:34:34.460 --> 00:34:40.580 align:middle line:84%
So this was the first version
of the comparison test.

00:34:40.580 --> 00:34:47.300 align:middle line:84%
Here is another more fancy
version of comparing,

00:34:47.300 --> 00:34:50.089 align:middle line:84%
where you're
comparing two series.

00:34:50.089 --> 00:34:53.260 align:middle line:90%


00:34:53.260 --> 00:34:57.500 align:middle line:84%
In fact, it's pretty much like
that, except for this stuff

00:34:57.500 --> 00:34:59.540 align:middle line:90%
we talked about.

00:34:59.540 --> 00:35:05.620 align:middle line:84%
I mean, typically the tests
are where you're comparing it

00:35:05.620 --> 00:35:09.060 align:middle line:90%
with some other series.

00:35:09.060 --> 00:35:11.580 align:middle line:90%
So here is version two.

00:35:11.580 --> 00:35:19.500 align:middle line:90%
So comparison version two.

00:35:19.500 --> 00:35:26.225 align:middle line:90%


00:35:26.225 --> 00:35:31.480 align:middle line:84%
And so you have,
again, two series, a n.

00:35:31.480 --> 00:35:33.840 align:middle line:90%
And again, it doesn't matter--

00:35:33.840 --> 00:35:36.580 align:middle line:84%
what the sum is matters
where you're starting,

00:35:36.580 --> 00:35:41.320 align:middle line:84%
but whether or not it converges
doesn't matter where you start.

00:35:41.320 --> 00:35:45.120 align:middle line:84%
So suppose that you have this
series and you have this series

00:35:45.120 --> 00:35:45.620 align:middle line:90%
here.

00:35:45.620 --> 00:35:48.840 align:middle line:90%


00:35:48.840 --> 00:36:00.200 align:middle line:84%
And suppose that you know that
the none of the bn's are 0.

00:36:00.200 --> 00:36:06.160 align:middle line:84%
And you know that the
a n divided by bn,

00:36:06.160 --> 00:36:11.080 align:middle line:84%
that this ratio here,
as n goes to infinity,

00:36:11.080 --> 00:36:17.140 align:middle line:84%
converges to some
L. And L here is--

00:36:17.140 --> 00:36:22.980 align:middle line:84%
L here is not 0 and
is not infinity.

00:36:22.980 --> 00:36:29.060 align:middle line:84%
I mean that it really
is a limit, like that.

00:36:29.060 --> 00:36:32.610 align:middle line:84%
So if that's the case,
then the series--

00:36:32.610 --> 00:36:39.380 align:middle line:90%


00:36:39.380 --> 00:36:52.810 align:middle line:84%
then let's-- then let's have
these as non-negative numbers.

00:36:52.810 --> 00:37:01.660 align:middle line:90%


00:37:01.660 --> 00:37:19.430 align:middle line:84%
Then the series a n converges
if and only if the series bn

00:37:19.430 --> 00:37:20.250 align:middle line:90%
converges.

00:37:20.250 --> 00:37:30.270 align:middle line:90%


00:37:30.270 --> 00:37:33.270 align:middle line:90%
And so an example of this--

00:37:33.270 --> 00:37:36.790 align:middle line:84%
so a typical example
of this is where

00:37:36.790 --> 00:37:45.110 align:middle line:84%
you're looking at the series
1 over n squared minus 1.

00:37:45.110 --> 00:37:46.990 align:middle line:90%
Suppose you're looking at this.

00:37:46.990 --> 00:37:48.910 align:middle line:84%
And now, just to
make it so that--

00:37:48.910 --> 00:37:53.070 align:middle line:84%
make sure that it makes sense
that you're not dividing by 0,

00:37:53.070 --> 00:37:56.590 align:middle line:84%
you're looking at
this thing here.

00:37:56.590 --> 00:38:02.270 align:middle line:84%
Suppose that this is the
series that you're given.

00:38:02.270 --> 00:38:04.490 align:middle line:90%
Well, this here is--

00:38:04.490 --> 00:38:07.050 align:middle line:84%
so you wouldn't use
the first comparison,

00:38:07.050 --> 00:38:08.770 align:middle line:84%
although you could
have used the first.

00:38:08.770 --> 00:38:11.855 align:middle line:84%
But then it would be a
little bit more complicated.

00:38:11.855 --> 00:38:14.230 align:middle line:84%
Not super complicated, but a
little bit more complicated,

00:38:14.230 --> 00:38:17.870 align:middle line:84%
because this thing
here this is--

00:38:17.870 --> 00:38:20.230 align:middle line:84%
so the first thing you observe
is that this, of course,

00:38:20.230 --> 00:38:21.570 align:middle line:90%
goes to 0.

00:38:21.570 --> 00:38:22.810 align:middle line:90%
This goes to 0.

00:38:22.810 --> 00:38:26.250 align:middle line:84%
But the second thing is that
it's very close to a series

00:38:26.250 --> 00:38:28.250 align:middle line:90%
that you know something about.

00:38:28.250 --> 00:38:32.610 align:middle line:84%
It's very close to
this series here.

00:38:32.610 --> 00:38:34.050 align:middle line:84%
But again, it
doesn't matter where

00:38:34.050 --> 00:38:38.250 align:middle line:84%
I'm starting when you're asking
whether it's converging or not.

00:38:38.250 --> 00:38:40.570 align:middle line:84%
So it's very close
to this series.

00:38:40.570 --> 00:38:44.850 align:middle line:90%
But of course, this thing here--

00:38:44.850 --> 00:38:47.650 align:middle line:84%
this thing here is
a smaller number.

00:38:47.650 --> 00:38:53.730 align:middle line:84%
So this is actually bigger
than 1 over n squared.

00:38:53.730 --> 00:38:57.510 align:middle line:84%
This here is a
convergent series.

00:38:57.510 --> 00:38:59.870 align:middle line:90%
So this does not help you.

00:38:59.870 --> 00:39:03.570 align:middle line:84%
This is not great for
using the first test.

00:39:03.570 --> 00:39:05.170 align:middle line:90%
You could have done it.

00:39:05.170 --> 00:39:07.110 align:middle line:84%
You could still
use the first test.

00:39:07.110 --> 00:39:09.830 align:middle line:84%
But then you have to build
a slightly more clever.

00:39:09.830 --> 00:39:16.910 align:middle line:84%
So instead of that you
can use this second test.

00:39:16.910 --> 00:39:22.430 align:middle line:84%
And so in the second test
you, set a n equal to 1 over n

00:39:22.430 --> 00:39:24.110 align:middle line:90%
squared minus 1.

00:39:24.110 --> 00:39:28.390 align:middle line:84%
And you set bn equal
to 1 over n squared.

00:39:28.390 --> 00:39:33.190 align:middle line:84%
And then you have that
a n divided by bn.

00:39:33.190 --> 00:39:42.950 align:middle line:84%
But this is just 1 over n
squared minus 1 over n squared.

00:39:42.950 --> 00:39:44.390 align:middle line:90%
Or 1 over n squared, sorry.

00:39:44.390 --> 00:39:47.270 align:middle line:90%


00:39:47.270 --> 00:39:56.470 align:middle line:84%
And so this here is the same as
n squared minus 1, like that.

00:39:56.470 --> 00:40:00.070 align:middle line:84%
And now you can divide by
n squared in both numerator

00:40:00.070 --> 00:40:01.130 align:middle line:90%
and denominator.

00:40:01.130 --> 00:40:07.070 align:middle line:84%
So you're getting 1
minus 1 over n squared.

00:40:07.070 --> 00:40:11.780 align:middle line:84%
And now you just use the usual
algebraic rules for limits.

00:40:11.780 --> 00:40:13.820 align:middle line:90%
This here converts to 0.

00:40:13.820 --> 00:40:16.840 align:middle line:84%
So it means that the
denominator converts to 1.

00:40:16.840 --> 00:40:22.600 align:middle line:84%
So this means that this
ratio here converts to 1.

00:40:22.600 --> 00:40:27.360 align:middle line:84%
And so you see that the ratios
are converging to something that

00:40:27.360 --> 00:40:30.840 align:middle line:90%
is neither zero nor infinity.

00:40:30.840 --> 00:40:35.160 align:middle line:84%
And this means that this
series here is convergent if

00:40:35.160 --> 00:40:37.020 align:middle line:90%
and only if this convergent.

00:40:37.020 --> 00:40:39.420 align:middle line:84%
You already know that
this is convergent.

00:40:39.420 --> 00:40:41.800 align:middle line:84%
So we conclude that
this is convergent.

00:40:41.800 --> 00:40:44.530 align:middle line:84%
So that's how it's
typically used.

00:40:44.530 --> 00:40:53.300 align:middle line:90%


00:40:53.300 --> 00:41:01.620 align:middle line:84%
So now the next test I want to
talk about is the ratio test.

00:41:01.620 --> 00:41:04.560 align:middle line:90%
And so this is--

00:41:04.560 --> 00:41:08.900 align:middle line:84%
I mean, the comparison
tests are typically almost

00:41:08.900 --> 00:41:11.740 align:middle line:90%
the easiest tests.

00:41:11.740 --> 00:41:14.430 align:middle line:84%
But this one here
is extremely useful.

00:41:14.430 --> 00:41:18.220 align:middle line:90%


00:41:18.220 --> 00:41:23.820 align:middle line:84%
And so the next two
tests, the ratio test--

00:41:23.820 --> 00:41:40.140 align:middle line:84%
both the ratio
test and root test,

00:41:40.140 --> 00:41:55.300 align:middle line:84%
are based on comparison
with the geometric series.

00:41:55.300 --> 00:42:00.580 align:middle line:84%
And so this is explaining
why the geometric series

00:42:00.580 --> 00:42:02.620 align:middle line:90%
is so crucial.

00:42:02.620 --> 00:42:05.230 align:middle line:90%
So what is the ratio test?

00:42:05.230 --> 00:42:08.350 align:middle line:84%
Well, the ratio test
is simply the test

00:42:08.350 --> 00:42:12.670 align:middle line:90%
that if you're looking at--

00:42:12.670 --> 00:42:14.290 align:middle line:90%
so if you have a series.

00:42:14.290 --> 00:42:16.930 align:middle line:84%
You don't have to look
at any other series.

00:42:16.930 --> 00:42:21.510 align:middle line:84%
Like in the comparison test,
you had to find another series.

00:42:21.510 --> 00:42:23.730 align:middle line:90%
But in the ratio test--

00:42:23.730 --> 00:42:25.080 align:middle line:90%
so this is the ratio test.

00:42:25.080 --> 00:42:31.070 align:middle line:90%


00:42:31.070 --> 00:42:34.680 align:middle line:84%
So you're looking at
a series like this.

00:42:34.680 --> 00:42:38.870 align:middle line:90%


00:42:38.870 --> 00:42:48.190 align:middle line:84%
And the ratio test is that
you're looking at a n plus 1

00:42:48.190 --> 00:42:49.130 align:middle line:90%
over n.

00:42:49.130 --> 00:42:55.310 align:middle line:84%
So you are looking at the ratio
between two consecutive elements

00:42:55.310 --> 00:42:57.510 align:middle line:90%
of the a n's.

00:42:57.510 --> 00:43:01.710 align:middle line:84%
So you're looking at
this and you're looking

00:43:01.710 --> 00:43:04.690 align:middle line:90%
at the absolute value of this.

00:43:04.690 --> 00:43:09.010 align:middle line:84%
And you're asking
if the limit here--

00:43:09.010 --> 00:43:14.330 align:middle line:84%
as n goes to infinity,
suppose that the limit exists.

00:43:14.330 --> 00:43:17.770 align:middle line:84%
And let's say that
the limit is a.

00:43:17.770 --> 00:43:24.690 align:middle line:90%
So it's asking you if this--

00:43:24.690 --> 00:43:26.610 align:middle line:90%
somehow the test here--

00:43:26.610 --> 00:43:31.010 align:middle line:84%
this form of the ratio test,
it requires that the ratio here

00:43:31.010 --> 00:43:33.450 align:middle line:90%
has a limit.

00:43:33.450 --> 00:43:40.450 align:middle line:84%
So the ratio test then
says that if a here is--

00:43:40.450 --> 00:43:41.640 align:middle line:90%
if a here is--

00:43:41.640 --> 00:43:46.090 align:middle line:90%


00:43:46.090 --> 00:43:46.890 align:middle line:90%
sorry.

00:43:46.890 --> 00:43:54.090 align:middle line:84%
If a here is less than 1,
then the series is-- so let

00:43:54.090 --> 00:43:55.190 align:middle line:90%
me write it like this.

00:43:55.190 --> 00:43:57.970 align:middle line:90%


00:43:57.970 --> 00:44:04.190 align:middle line:84%
So a less than 1,
this here means

00:44:04.190 --> 00:44:05.970 align:middle line:90%
that the series is convergent.

00:44:05.970 --> 00:44:13.270 align:middle line:90%


00:44:13.270 --> 00:44:17.230 align:middle line:84%
Two, if this a here
is bigger than 1,

00:44:17.230 --> 00:44:22.250 align:middle line:84%
this implies that the
series is divergent.

00:44:22.250 --> 00:44:26.150 align:middle line:90%


00:44:26.150 --> 00:44:30.950 align:middle line:84%
And three is that
if this a here is 1,

00:44:30.950 --> 00:44:36.256 align:middle line:90%
then the test is inconclusive.

00:44:36.256 --> 00:44:40.150 align:middle line:90%


00:44:40.150 --> 00:44:44.470 align:middle line:84%
But it's important to
remember that it is possible

00:44:44.470 --> 00:44:46.610 align:middle line:84%
that you don't get
anything out of the test

00:44:46.610 --> 00:44:51.570 align:middle line:84%
if you are in the unlucky
case where this limit is 1.

00:44:51.570 --> 00:44:54.580 align:middle line:90%


00:44:54.580 --> 00:45:02.560 align:middle line:84%
And I should also emphasize that
it is crucial to have a limit.

00:45:02.560 --> 00:45:07.050 align:middle line:84%
So the test here, in this form,
it's crucial to have a limit.

00:45:07.050 --> 00:45:18.136 align:middle line:90%


00:45:18.136 --> 00:45:22.640 align:middle line:84%
And we'll talk a little bit
and we'll come back to that.

00:45:22.640 --> 00:45:23.900 align:middle line:90%
We'll come back to this.

00:45:23.900 --> 00:45:27.760 align:middle line:90%


00:45:27.760 --> 00:45:37.440 align:middle line:84%
So now let me try to
explain why you have--

00:45:37.440 --> 00:45:41.540 align:middle line:84%
well, in conclusion, I don't
really need to explain anything.

00:45:41.540 --> 00:45:44.740 align:middle line:90%
But why in the case--

00:45:44.740 --> 00:45:46.140 align:middle line:90%
so proof of case one.

00:45:46.140 --> 00:45:52.320 align:middle line:90%


00:45:52.320 --> 00:45:55.680 align:middle line:84%
So this means that
I have to show--

00:45:55.680 --> 00:46:08.940 align:middle line:84%
so I need to show that
if this limit here--

00:46:08.940 --> 00:46:16.220 align:middle line:84%
if this limit of a
n plus 1 over a n,

00:46:16.220 --> 00:46:22.480 align:middle line:84%
if this here is less than 1,
then the series is convergent.

00:46:22.480 --> 00:46:31.540 align:middle line:90%


00:46:31.540 --> 00:46:37.260 align:middle line:84%
And I'll just sketch the proof,
because we're going to do--

00:46:37.260 --> 00:46:37.780 align:middle line:90%
yeah.

00:46:37.780 --> 00:46:39.760 align:middle line:90%
I will just sketch the proof.

00:46:39.760 --> 00:46:41.980 align:middle line:84%
We;ll come back, in
a way, to the proof,

00:46:41.980 --> 00:46:45.620 align:middle line:84%
because it's very close to
the same proof that is used

00:46:45.620 --> 00:46:47.090 align:middle line:90%
in the case of the root test.

00:46:47.090 --> 00:46:50.180 align:middle line:90%


00:46:50.180 --> 00:46:54.040 align:middle line:90%
So that's what I need.

00:46:54.040 --> 00:46:56.570 align:middle line:90%
So I have that there exists--

00:46:56.570 --> 00:47:01.560 align:middle line:90%


00:47:01.560 --> 00:47:09.360 align:middle line:90%
so given a0 less than 1.

00:47:09.360 --> 00:47:12.860 align:middle line:90%
So given a0 with--

00:47:12.860 --> 00:47:17.680 align:middle line:90%


00:47:17.680 --> 00:47:23.460 align:middle line:84%
a0 bigger than this
a and less than 1.

00:47:23.460 --> 00:47:26.600 align:middle line:84%
So if you pick an
a0 that is strictly

00:47:26.600 --> 00:47:30.480 align:middle line:84%
bigger than a and
still less than 1,

00:47:30.480 --> 00:47:40.400 align:middle line:84%
then we know that
there exists an n such

00:47:40.400 --> 00:47:51.040 align:middle line:84%
that if little n is bigger
than this capital N,

00:47:51.040 --> 00:47:58.850 align:middle line:90%
then a n plus 1 over a n--

00:47:58.850 --> 00:48:03.610 align:middle line:84%
and really, I should have
absolute value here on this.

00:48:03.610 --> 00:48:09.530 align:middle line:84%
Then we have that this
thing here is less than--

00:48:09.530 --> 00:48:12.150 align:middle line:90%
it's less than a0.

00:48:12.150 --> 00:48:16.370 align:middle line:84%
Because if you're very
far out, then this here

00:48:16.370 --> 00:48:19.490 align:middle line:84%
is-- this ratio is going
to be very close to this.

00:48:19.490 --> 00:48:21.830 align:middle line:84%
But this is strictly
less than that.

00:48:21.830 --> 00:48:24.090 align:middle line:90%
So we have this.

00:48:24.090 --> 00:48:26.650 align:middle line:84%
So this means that--
maybe I shouldn't

00:48:26.650 --> 00:48:30.890 align:middle line:84%
call it a0 because
there's too many a's now.

00:48:30.890 --> 00:48:32.710 align:middle line:90%
Let's call it something else.

00:48:32.710 --> 00:48:36.380 align:middle line:84%
Let's call it alpha to make it
just look much more distinct.

00:48:36.380 --> 00:48:41.392 align:middle line:90%


00:48:41.392 --> 00:48:43.270 align:middle line:90%
So this means that--

00:48:43.270 --> 00:48:49.050 align:middle line:84%
so you see that if--
so in other words,

00:48:49.050 --> 00:48:52.810 align:middle line:84%
If n here is bigger
than this capital N then

00:48:52.810 --> 00:48:57.830 align:middle line:84%
you have-- just multiplying
over, you have that a n plus 1

00:48:57.830 --> 00:49:01.620 align:middle line:84%
is less than alpha
times a n, like that.

00:49:01.620 --> 00:49:04.214 align:middle line:90%


00:49:04.214 --> 00:49:06.610 align:middle line:84%
In the ratio test, I
should have said that.

00:49:06.610 --> 00:49:10.790 align:middle line:84%
But obviously, you are assuming
that these a n's are not 0.

00:49:10.790 --> 00:49:12.450 align:middle line:90%
So you can divide by them.

00:49:12.450 --> 00:49:17.230 align:middle line:90%


00:49:17.230 --> 00:49:19.150 align:middle line:90%
So you have this.

00:49:19.150 --> 00:49:20.910 align:middle line:84%
If you are far
out, you have this,

00:49:20.910 --> 00:49:25.390 align:middle line:84%
that the next one is a
fraction of the previous one.

00:49:25.390 --> 00:49:30.530 align:middle line:84%
But this means, of
course, that if you take--

00:49:30.530 --> 00:49:37.310 align:middle line:84%
if you're looking at n is bigger
or equal to this capital N,

00:49:37.310 --> 00:49:44.790 align:middle line:84%
well, you have that
a capital N plus 1.

00:49:44.790 --> 00:49:52.070 align:middle line:84%
If you're using this a
capital N as little n,

00:49:52.070 --> 00:49:57.682 align:middle line:84%
then you have that this
thing here, this is now the--

00:49:57.682 --> 00:49:59.450 align:middle line:90%
this here is now-- sorry.

00:49:59.450 --> 00:50:08.890 align:middle line:84%
If you're using-- if you first
pick n equal to capital N, then

00:50:08.890 --> 00:50:10.990 align:middle line:84%
what does this
inequality tell you?

00:50:10.990 --> 00:50:15.770 align:middle line:84%
It tells you that a capital N
plus 1 is less than or equal

00:50:15.770 --> 00:50:23.890 align:middle line:84%
to alpha a capital N. Now apply
this inequality here for n --

00:50:23.890 --> 00:50:24.650 align:middle line:90%
plus--

00:50:24.650 --> 00:50:27.090 align:middle line:90%
capital n plus 1.

00:50:27.090 --> 00:50:33.650 align:middle line:84%
So then you have that a capital
N plus true absolute value

00:50:33.650 --> 00:50:40.570 align:middle line:84%
is less than or equal to
alpha a n plus 1 like that.

00:50:40.570 --> 00:50:44.890 align:middle line:84%
But you already proven
that this thing here--

00:50:44.890 --> 00:50:46.350 align:middle line:90%
forget about the alpha here.

00:50:46.350 --> 00:50:47.830 align:middle line:84%
But you've proven
this inequality.

00:50:47.830 --> 00:50:51.650 align:middle line:84%
So filling in that inequality,
I have this alpha here.

00:50:51.650 --> 00:50:56.600 align:middle line:84%
But then I have another alpha
that is this and then like this.

00:50:56.600 --> 00:51:01.300 align:middle line:90%


00:51:01.300 --> 00:51:03.800 align:middle line:84%
And so now, you can
continue this way.

00:51:03.800 --> 00:51:09.540 align:middle line:84%
So this here is like alpha
squared times a capital N.

00:51:09.540 --> 00:51:12.300 align:middle line:84%
And so now you see
that you can continue.

00:51:12.300 --> 00:51:14.480 align:middle line:90%
So if you're looking at--

00:51:14.480 --> 00:51:20.740 align:middle line:84%
so if you continue
like this, then

00:51:20.740 --> 00:51:26.780 align:middle line:84%
you see that a capital
N plus some little n

00:51:26.780 --> 00:51:31.820 align:middle line:84%
is less than or equal to
alpha to the power m times

00:51:31.820 --> 00:51:35.540 align:middle line:90%
a to the absolute value of a n.

00:51:35.540 --> 00:51:37.700 align:middle line:84%
This here, the
previous line, was just

00:51:37.700 --> 00:51:40.420 align:middle line:90%
where m was equal to true.

00:51:40.420 --> 00:51:42.840 align:middle line:84%
But you really get
it for all integers.

00:51:42.840 --> 00:51:45.940 align:middle line:90%


00:51:45.940 --> 00:51:49.780 align:middle line:84%
And so this says that at least
the tail of this sequence here,

00:51:49.780 --> 00:51:53.160 align:middle line:84%
the tail of the a n
sequence, this is just

00:51:53.160 --> 00:51:54.540 align:middle line:90%
some fixed constant.

00:51:54.540 --> 00:51:57.840 align:middle line:84%
This here is a convergent
geometric series.

00:51:57.840 --> 00:52:02.120 align:middle line:84%
So the tail is bounded by a
convergent geometric series.

00:52:02.120 --> 00:52:06.920 align:middle line:84%
So you can just apply
the first comparison test

00:52:06.920 --> 00:52:11.040 align:middle line:84%
to prove that the
sequence-- the series a n

00:52:11.040 --> 00:52:12.400 align:middle line:90%
is actually convergent.

00:52:12.400 --> 00:52:16.640 align:middle line:90%


00:52:16.640 --> 00:52:23.120 align:middle line:84%
So the ratio test,
again, was to compare

00:52:23.120 --> 00:52:28.040 align:middle line:84%
it, use the first comparison
test where the comparison was

00:52:28.040 --> 00:52:29.090 align:middle line:90%
the geometric series.

00:52:29.090 --> 00:52:36.520 align:middle line:90%


00:52:36.520 --> 00:52:39.560 align:middle line:90%
And so of course, if the--

00:52:39.560 --> 00:52:45.920 align:middle line:90%
so this proves one, two here.

00:52:45.920 --> 00:52:49.080 align:middle line:84%
But two is kind of
really the same.

00:52:49.080 --> 00:52:53.140 align:middle line:90%
Because if this alpha here--

00:52:53.140 --> 00:52:56.980 align:middle line:90%
so to show the second part.

00:52:56.980 --> 00:52:59.980 align:middle line:84%
Again, the third one, to
prove it's inconclusive,

00:52:59.980 --> 00:53:01.980 align:middle line:84%
there's nothing to
prove, because it

00:53:01.980 --> 00:53:05.220 align:middle line:90%
leaves open any possibility.

00:53:05.220 --> 00:53:08.940 align:middle line:84%
But you want to show that if
this limit here-- so if this

00:53:08.940 --> 00:53:11.000 align:middle line:90%
limit-- so proof of two.

00:53:11.000 --> 00:53:16.300 align:middle line:90%


00:53:16.300 --> 00:53:22.180 align:middle line:84%
So you want-- so we're assuming
that a here is bigger than 1.

00:53:22.180 --> 00:53:24.200 align:middle line:84%
But this means
that there exists--

00:53:24.200 --> 00:53:26.820 align:middle line:90%
so if you take alpha--

00:53:26.820 --> 00:53:41.020 align:middle line:84%
so this time, choose alpha such
that alpha is bigger than 1,

00:53:41.020 --> 00:53:44.860 align:middle line:90%
but it's smaller than a.

00:53:44.860 --> 00:53:48.080 align:middle line:90%
But then you have that for--

00:53:48.080 --> 00:53:53.030 align:middle line:84%
since this ratio is
converging for little n

00:53:53.030 --> 00:53:55.470 align:middle line:84%
bigger than-- there
exists some capital N, so

00:53:55.470 --> 00:53:58.990 align:middle line:84%
that if this little n is
bigger than capital N, then

00:53:58.990 --> 00:54:06.870 align:middle line:84%
you have that a n plus 1 over
a n, that this thing here,

00:54:06.870 --> 00:54:09.690 align:middle line:84%
if it's far enough out,
it's going to converge here.

00:54:09.690 --> 00:54:11.390 align:middle line:84%
But at least far
enough out, it's

00:54:11.390 --> 00:54:14.830 align:middle line:90%
going to be bigger than alpha.

00:54:14.830 --> 00:54:22.150 align:middle line:84%
Multiplying over again
means that a n plus 1

00:54:22.150 --> 00:54:28.590 align:middle line:90%
is bigger than alpha times a n.

00:54:28.590 --> 00:54:31.270 align:middle line:90%
This here is now bigger than 1.

00:54:31.270 --> 00:54:33.410 align:middle line:84%
And so in the same
way as before,

00:54:33.410 --> 00:54:36.870 align:middle line:84%
you see that if
you're far enough out,

00:54:36.870 --> 00:54:42.070 align:middle line:84%
then the next element
is some multiple,

00:54:42.070 --> 00:54:48.850 align:middle line:84%
some big number, at least bigger
than 1, times the previous one.

00:54:48.850 --> 00:54:52.290 align:middle line:84%
But this means that they're
getting larger and larger.

00:54:52.290 --> 00:54:57.290 align:middle line:84%
From some fixed stage on
and outwards, the a n's are

00:54:57.290 --> 00:54:59.310 align:middle line:90%
getting larger and larger.

00:54:59.310 --> 00:55:03.170 align:middle line:84%
So they don't converge to
0 as they were supposed to.

00:55:03.170 --> 00:55:05.858 align:middle line:90%
So this is proving true.

00:55:05.858 --> 00:55:07.650 align:middle line:84%
And three, again,
there's nothing to prove,

00:55:07.650 --> 00:55:10.190 align:middle line:84%
because it leaves open
both possibilities.

00:55:10.190 --> 00:55:18.067 align:middle line:90%


00:55:18.067 --> 00:55:20.150 align:middle line:84%
AUDIENCE: I have a question
about the first group.

00:55:20.150 --> 00:55:21.025 align:middle line:90%
TOBIAS COLDING: Yeah.

00:55:21.025 --> 00:55:23.970 align:middle line:84%
AUDIENCE: Does that assume that
the series is monotonically

00:55:23.970 --> 00:55:26.810 align:middle line:90%
decreasing?

00:55:26.810 --> 00:55:29.330 align:middle line:90%
TOBIAS COLDING: Sorry?

00:55:29.330 --> 00:55:32.230 align:middle line:84%
AUDIENCE: I guess just looking
at it from a high level,

00:55:32.230 --> 00:55:34.625 align:middle line:84%
we're saying that a of
n plus 1 over a of n--

00:55:34.625 --> 00:55:35.750 align:middle line:90%
TOBIAS COLDING: Wait, wait.

00:55:35.750 --> 00:55:38.968 align:middle line:84%
So you're asking--
what are you asking?

00:55:38.968 --> 00:55:41.510 align:middle line:84%
AUDIENCE: So for part one, when
we say that a is less than 1,

00:55:41.510 --> 00:55:45.690 align:middle line:84%
that implies that it
converges, is that only

00:55:45.690 --> 00:55:47.590 align:middle line:84%
going to work for
monotonically decreasing?

00:55:47.590 --> 00:55:48.715 align:middle line:90%
TOBIAS COLDING: No, no, no.

00:55:48.715 --> 00:55:54.530 align:middle line:84%
So there's no assumption here on
whether the sequence is right.

00:55:54.530 --> 00:55:56.810 align:middle line:90%
I mean, so 1--

00:55:56.810 --> 00:55:57.310 align:middle line:90%
yeah.

00:55:57.310 --> 00:56:04.950 align:middle line:84%
So 1 implies that the absolute
value is going down, as you say.

00:56:04.950 --> 00:56:07.850 align:middle line:84%
But I could alternate
signs and things like that.

00:56:07.850 --> 00:56:08.990 align:middle line:90%
Yeah.

00:56:08.990 --> 00:56:10.430 align:middle line:90%
But it is-- yeah.

00:56:10.430 --> 00:56:13.370 align:middle line:84%
And so just because
you're comparing it with--

00:56:13.370 --> 00:56:17.030 align:middle line:84%
you're going to compare it with
a convergent geometric series.

00:56:17.030 --> 00:56:19.510 align:middle line:84%
In a convergent
geometric series,

00:56:19.510 --> 00:56:25.850 align:middle line:84%
the next element is some fixed
fraction of the previous one.

00:56:25.850 --> 00:56:26.350 align:middle line:90%
Yeah.

00:56:26.350 --> 00:56:29.030 align:middle line:90%


00:56:29.030 --> 00:56:33.430 align:middle line:84%
So you're right that in
order for the ratio test

00:56:33.430 --> 00:56:37.750 align:middle line:84%
to give you
convergence, then it's

00:56:37.750 --> 00:56:41.350 align:middle line:84%
going to require that
sufficiently far out,

00:56:41.350 --> 00:56:46.960 align:middle line:84%
the absolute value of the
a n element has gone down.

00:56:46.960 --> 00:56:57.920 align:middle line:90%


00:56:57.920 --> 00:57:01.800 align:middle line:84%
And this, in a way, addresses
that point you're making there.

00:57:01.800 --> 00:57:08.760 align:middle line:84%
So the other test that is
also based on comparing it

00:57:08.760 --> 00:57:11.440 align:middle line:90%
with the geometric series.

00:57:11.440 --> 00:57:15.080 align:middle line:84%
But this does not compare
consecutive elements.

00:57:15.080 --> 00:57:19.720 align:middle line:84%
So it's leaving the possibility
that the next element could

00:57:19.720 --> 00:57:22.250 align:middle line:90%
be larger than the previous.

00:57:22.250 --> 00:57:25.760 align:middle line:90%


00:57:25.760 --> 00:57:27.880 align:middle line:90%
And so this is the root test.

00:57:27.880 --> 00:57:31.800 align:middle line:84%
But of course, it
cannot be that--

00:57:31.800 --> 00:57:35.420 align:middle line:84%
you cannot keep having the
next element larger than

00:57:35.420 --> 00:57:35.980 align:middle line:90%
the previous.

00:57:35.980 --> 00:57:39.480 align:middle line:84%
But you could have-- there
could be somewhere where

00:57:39.480 --> 00:57:41.760 align:middle line:90%
the next one actually went up.

00:57:41.760 --> 00:57:44.580 align:middle line:84%
But then presumably,
after that, they're

00:57:44.580 --> 00:57:46.403 align:middle line:84%
going down, at least
for a long time.

00:57:46.403 --> 00:57:47.820 align:middle line:84%
And then maybe
there's another one

00:57:47.820 --> 00:57:50.920 align:middle line:84%
that jumps up, but not
very much, et cetera.

00:57:50.920 --> 00:57:57.380 align:middle line:84%
And the root test is OK with
that, whereas that test wasn't

00:57:57.380 --> 00:57:58.380 align:middle line:90%
OK with that.

00:57:58.380 --> 00:58:00.420 align:middle line:90%
So the root test.

00:58:00.420 --> 00:58:05.020 align:middle line:84%
So you have a series,
again, like this.

00:58:05.020 --> 00:58:08.780 align:middle line:84%
And the root test is
that you're looking

00:58:08.780 --> 00:58:13.860 align:middle line:84%
at-- you're taking the
absolute value of this

00:58:13.860 --> 00:58:16.700 align:middle line:84%
and then you're
taking the n-th root.

00:58:16.700 --> 00:58:20.540 align:middle line:84%
So this means-- this is
the same as saying a n

00:58:20.540 --> 00:58:26.180 align:middle line:84%
absolute value, if you want to
write it like this, 1 over n.

00:58:26.180 --> 00:58:31.340 align:middle line:90%
So it's dealing with this.

00:58:31.340 --> 00:58:43.360 align:middle line:84%
And the root test is saying that
suppose that when you form this

00:58:43.360 --> 00:58:46.360 align:middle line:90%
here, that this has a limit.

00:58:46.360 --> 00:58:47.970 align:middle line:90%
Suppose that this n-th root--

00:58:47.970 --> 00:58:50.800 align:middle line:90%


00:58:50.800 --> 00:58:53.640 align:middle line:84%
suppose that this
here has a limit.

00:58:53.640 --> 00:58:56.720 align:middle line:90%
And let's call this limit c.

00:58:56.720 --> 00:59:00.080 align:middle line:90%
Suppose that you have this.

00:59:00.080 --> 00:59:06.950 align:middle line:84%
Then it has the same three
parts here as in the previous.

00:59:06.950 --> 00:59:15.600 align:middle line:90%


00:59:15.600 --> 00:59:19.320 align:middle line:90%
And so this is--

00:59:19.320 --> 00:59:21.640 align:middle line:90%
so there's three possibilities.

00:59:21.640 --> 00:59:25.720 align:middle line:84%
Where c here is less
than 1, then this

00:59:25.720 --> 00:59:27.860 align:middle line:84%
implies that the
series is convergent.

00:59:27.860 --> 00:59:34.240 align:middle line:90%


00:59:34.240 --> 00:59:41.420 align:middle line:84%
Two, c is bigger than 1 implies
that the series is divergent.

00:59:41.420 --> 00:59:46.330 align:middle line:90%


00:59:46.330 --> 00:59:52.530 align:middle line:84%
And again, the case where c here
is equal to 1, in conclusion.

00:59:52.530 --> 00:59:53.950 align:middle line:90%
Test is in conclusion.

00:59:53.950 --> 01:00:01.690 align:middle line:90%


01:00:01.690 --> 01:00:04.330 align:middle line:84%
And again, we're
going to compare

01:00:04.330 --> 01:00:05.750 align:middle line:90%
with the geometric series.

01:00:05.750 --> 01:00:07.160 align:middle line:84%
So let's see how
the proof works.

01:00:07.160 --> 01:00:20.990 align:middle line:90%


01:00:20.990 --> 01:00:21.490 align:middle line:90%
OK.

01:00:21.490 --> 01:00:23.300 align:middle line:90%
So now let's prove one.

01:00:23.300 --> 01:00:26.050 align:middle line:90%


01:00:26.050 --> 01:00:28.530 align:middle line:90%
Proof of one.

01:00:28.530 --> 01:00:30.570 align:middle line:84%
So again, we are in
a situation where

01:00:30.570 --> 01:00:37.290 align:middle line:84%
we have that the n-th root
of the absolute value here

01:00:37.290 --> 01:00:43.070 align:middle line:84%
as n goes to infinity
is equal to some c,

01:00:43.070 --> 01:00:47.270 align:middle line:84%
and we're assuming that
the c is less than 1.

01:00:47.270 --> 01:00:53.390 align:middle line:84%
So now I'm again
choosing something

01:00:53.390 --> 01:00:57.490 align:middle line:90%
that is between c and 1.

01:00:57.490 --> 01:01:08.140 align:middle line:84%
So choose c-- let's
call it c0 with a--

01:01:08.140 --> 01:01:12.270 align:middle line:90%


01:01:12.270 --> 01:01:16.790 align:middle line:90%
c0 less than 1.

01:01:16.790 --> 01:01:20.390 align:middle line:84%
And now we know that--
because we have this limit,

01:01:20.390 --> 01:01:28.790 align:middle line:84%
we know that there
exists capital N such

01:01:28.790 --> 01:01:38.730 align:middle line:84%
that if little n is
bigger than capital N,

01:01:38.730 --> 01:01:43.330 align:middle line:84%
then the n-th root of
this absolute value sign

01:01:43.330 --> 01:01:47.930 align:middle line:84%
is actually less
than or equal to c0.

01:01:47.930 --> 01:01:53.650 align:middle line:84%
This is just because c0
was strictly bigger than c.

01:01:53.650 --> 01:01:54.850 align:middle line:90%
So we have that.

01:01:54.850 --> 01:01:58.790 align:middle line:84%
So now we just check the
n-th power on both sides.

01:01:58.790 --> 01:02:12.570 align:middle line:84%
So this implies by
taking the n-th power,

01:02:12.570 --> 01:02:22.450 align:middle line:84%
we get that absolute value
of a n is less or equal to c0

01:02:22.450 --> 01:02:23.410 align:middle line:90%
to the power n.

01:02:23.410 --> 01:02:27.850 align:middle line:90%


01:02:27.850 --> 01:02:32.970 align:middle line:84%
But that's already great,
because this means that you have

01:02:32.970 --> 01:02:37.290 align:middle line:84%
compared-- at least from a
certain stage and an outward,

01:02:37.290 --> 01:02:40.320 align:middle line:90%
you have compared the a n with--

01:02:40.320 --> 01:02:46.220 align:middle line:84%
if you're thinking that this
thing here is like the b n,

01:02:46.220 --> 01:02:50.020 align:middle line:84%
then you have compared
these guys here

01:02:50.020 --> 01:02:53.900 align:middle line:84%
with this series here
based on these, at least

01:02:53.900 --> 01:02:57.060 align:middle line:84%
from this capital
N and outwards.

01:02:57.060 --> 01:03:00.300 align:middle line:84%
And this is a geometric
series because it's

01:03:00.300 --> 01:03:03.220 align:middle line:84%
just some number
strictly smaller than 1

01:03:03.220 --> 01:03:05.800 align:middle line:90%
multiplied by itself n times.

01:03:05.800 --> 01:03:09.290 align:middle line:84%
So again, by the first
comparison test--

01:03:09.290 --> 01:03:20.140 align:middle line:90%


01:03:20.140 --> 01:03:39.140 align:middle line:84%
so by the first comparison
test, the a n is convergent.

01:03:39.140 --> 01:03:42.760 align:middle line:84%
And note here that what
you're proving is--

01:03:42.760 --> 01:03:47.680 align:middle line:84%
you're actually proving that
this series is convergent.

01:03:47.680 --> 01:03:50.280 align:middle line:84%
Because you're comparing
this series here

01:03:50.280 --> 01:03:52.200 align:middle line:90%
with the geometric series.

01:03:52.200 --> 01:03:53.800 align:middle line:90%
But this here is just--

01:03:53.800 --> 01:04:01.520 align:middle line:84%
this just means-- sorry, means
that the original series here

01:04:01.520 --> 01:04:03.300 align:middle line:90%
was absolutely convergent.

01:04:03.300 --> 01:04:09.440 align:middle line:90%


01:04:09.440 --> 01:04:13.960 align:middle line:84%
But absolute convergence
implies convergence.

01:04:13.960 --> 01:04:18.860 align:middle line:84%
So you're actually proving
absolute convergence.

01:04:18.860 --> 01:04:22.826 align:middle line:90%


01:04:22.826 --> 01:04:27.020 align:middle line:84%
Now let's try to-- again,
there's three parts to it.

01:04:27.020 --> 01:04:30.900 align:middle line:84%
But the last one leaves
open any possibility,

01:04:30.900 --> 01:04:32.460 align:middle line:90%
so there's nothing to prove.

01:04:32.460 --> 01:04:35.900 align:middle line:84%
So let's just prove
the second part here.

01:04:35.900 --> 01:04:39.220 align:middle line:90%
And that just goes similarly.

01:04:39.220 --> 01:04:43.900 align:middle line:84%
And again, it fails
dramatically to be convergent,

01:04:43.900 --> 01:04:47.260 align:middle line:84%
because the a n,
as you will see,

01:04:47.260 --> 01:04:49.820 align:middle line:90%
does not actually goes to 0.

01:04:49.820 --> 01:04:52.160 align:middle line:90%
So proof of two.

01:04:52.160 --> 01:04:56.220 align:middle line:90%


01:04:56.220 --> 01:04:58.820 align:middle line:90%
So we have that this--

01:04:58.820 --> 01:05:04.380 align:middle line:84%
so we're assuming that
this thing here, this

01:05:04.380 --> 01:05:11.180 align:middle line:84%
should converge to some c here,
which is now bigger than 1.

01:05:11.180 --> 01:05:13.460 align:middle line:84%
So this means that
there exists--

01:05:13.460 --> 01:05:23.660 align:middle line:84%
so this means that there
exists capital N such that

01:05:23.660 --> 01:05:28.080 align:middle line:84%
if little n is bigger than
this capital N-- sorry.

01:05:28.080 --> 01:05:31.260 align:middle line:90%
So we have this thing here.

01:05:31.260 --> 01:05:35.710 align:middle line:84%
And what I should before I
do this, I should choose my--

01:05:35.710 --> 01:05:44.910 align:middle line:84%
just like before, I
should choose my c0 such

01:05:44.910 --> 01:05:53.330 align:middle line:84%
that c0 is strictly
bigger than 1,

01:05:53.330 --> 01:05:55.463 align:middle line:84%
but yet is strictly
smaller than c.

01:05:55.463 --> 01:05:58.790 align:middle line:90%


01:05:58.790 --> 01:06:00.050 align:middle line:90%
So you choose this.

01:06:00.050 --> 01:06:03.390 align:middle line:84%
And now using this,
we have-- because we

01:06:03.390 --> 01:06:06.130 align:middle line:84%
have that this limit
here, it converts to c.

01:06:06.130 --> 01:06:09.790 align:middle line:84%
So it converts to something
that is strictly above this c0.

01:06:09.790 --> 01:06:16.950 align:middle line:84%
This means that there
exists capital N such

01:06:16.950 --> 01:06:22.630 align:middle line:84%
that if little n is
bigger than capital N,

01:06:22.630 --> 01:06:35.115 align:middle line:84%
then the n-th root
here is bigger than c0.

01:06:35.115 --> 01:06:38.370 align:middle line:90%


01:06:38.370 --> 01:06:41.770 align:middle line:84%
But now, again, taking the
n-th power on both sides,

01:06:41.770 --> 01:06:47.530 align:middle line:84%
then you have that
a n is bigger than--

01:06:47.530 --> 01:06:53.410 align:middle line:84%
strictly bigger than, in
fact, c0 to the n-th power.

01:06:53.410 --> 01:06:56.710 align:middle line:90%
But you see these guys here?

01:06:56.710 --> 01:06:58.950 align:middle line:90%
c0 is strictly bigger than 1.

01:06:58.950 --> 01:07:02.470 align:middle line:84%
So this here actually
even goes to infinity.

01:07:02.470 --> 01:07:04.100 align:middle line:90%
So this here does not go to 0.

01:07:04.100 --> 01:07:08.714 align:middle line:90%


01:07:08.714 --> 01:07:13.130 align:middle line:84%
So this proves, again,
that it's divergent.

01:07:13.130 --> 01:07:14.170 align:middle line:90%
So this proved true.

01:07:14.170 --> 01:07:17.210 align:middle line:90%


01:07:17.210 --> 01:07:19.570 align:middle line:90%
Now the next thing--

01:07:19.570 --> 01:07:22.400 align:middle line:84%
the next thing we want to
talk about is power series.

01:07:22.400 --> 01:07:35.550 align:middle line:90%


01:07:35.550 --> 01:07:40.550 align:middle line:84%
So remember that-- so the
first example of a power series

01:07:40.550 --> 01:07:44.510 align:middle line:84%
is something we already
looked at, more or less.

01:07:44.510 --> 01:07:47.230 align:middle line:90%
So suppose you take--

01:07:47.230 --> 01:07:51.790 align:middle line:84%
suppose that you're looking
at the series, some number,

01:07:51.790 --> 01:07:57.590 align:middle line:84%
I'll call it x now instead of c,
to the power n, and n equal to 0

01:07:57.590 --> 01:07:59.390 align:middle line:90%
to infinity.

01:07:59.390 --> 01:08:00.644 align:middle line:90%
Yeah?

01:08:00.644 --> 01:08:03.488 align:middle line:90%
AUDIENCE: [INAUDIBLE]

01:08:03.488 --> 01:08:05.390 align:middle line:90%


01:08:05.390 --> 01:08:07.550 align:middle line:84%
TOBIAS COLDING: So
what we proved--

01:08:07.550 --> 01:08:12.430 align:middle line:84%
so in the root test here,
we proved that the series

01:08:12.430 --> 01:08:15.490 align:middle line:90%
is absolutely convergent.

01:08:15.490 --> 01:08:19.510 align:middle line:90%


01:08:19.510 --> 01:08:23.069 align:middle line:90%
Here we proved it's divergent.

01:08:23.069 --> 01:08:27.229 align:middle line:84%
And what we actually proved
is we proved that a n--

01:08:27.229 --> 01:08:33.040 align:middle line:84%
in fact, this here
a n that is here

01:08:33.040 --> 01:08:40.000 align:middle line:84%
allows me to write that it
goes to infinity like this.

01:08:40.000 --> 01:08:43.840 align:middle line:84%
They were supposed to go to
0, but we actually write--

01:08:43.840 --> 01:08:48.680 align:middle line:84%
if the series was converging,
the most elementary thing

01:08:48.680 --> 01:08:53.200 align:middle line:84%
is, the most basic thing is
that the a n has to go to 0.

01:08:53.200 --> 01:08:55.319 align:middle line:84%
Otherwise, it's not
going to converge.

01:08:55.319 --> 01:08:58.560 align:middle line:84%
But in fact, not only
do they not go to 0,

01:08:58.560 --> 01:09:01.580 align:middle line:84%
they actually, in absolute
value, go to infinity.

01:09:01.580 --> 01:09:04.479 align:middle line:84%
So it's very, very far
from being convergent.

01:09:04.479 --> 01:09:12.720 align:middle line:90%


01:09:12.720 --> 01:09:16.479 align:middle line:84%
So suppose we looked at
the geometric series.

01:09:16.479 --> 01:09:20.040 align:middle line:84%
If you think about x just
representing any number,

01:09:20.040 --> 01:09:21.819 align:middle line:84%
you can look at
this series here.

01:09:21.819 --> 01:09:25.240 align:middle line:90%
This is the geometric series.

01:09:25.240 --> 01:09:27.520 align:middle line:84%
And we know that
it's convergent.

01:09:27.520 --> 01:09:29.840 align:middle line:84%
So we know that this
has convergence.

01:09:29.840 --> 01:09:34.180 align:middle line:90%


01:09:34.180 --> 01:09:39.200 align:middle line:84%
It's convergent if the
absolute value is less than 1.

01:09:39.200 --> 01:09:45.979 align:middle line:84%
And in that case, the sum here
is just this familiar function.

01:09:45.979 --> 01:09:54.560 align:middle line:84%
But in general, you
may have a sequence.

01:09:54.560 --> 01:10:04.460 align:middle line:84%
So in general, if
a n is a sequence,

01:10:04.460 --> 01:10:07.860 align:middle line:84%
then you can form
a power series.

01:10:07.860 --> 01:10:11.500 align:middle line:84%
And the power
series is like that,

01:10:11.500 --> 01:10:13.740 align:middle line:90%
where this is the coefficient.

01:10:13.740 --> 01:10:19.980 align:middle line:84%
The a n is now the coefficient
to the x to the power n.

01:10:19.980 --> 01:10:26.120 align:middle line:84%
So if you will, this is
like an infinite polynomial,

01:10:26.120 --> 01:10:29.680 align:middle line:84%
a polynomial of infinite
degree because the sum

01:10:29.680 --> 01:10:33.500 align:middle line:90%
of all these polynomials.

01:10:33.500 --> 01:10:34.940 align:middle line:84%
And this is called
a power series.

01:10:34.940 --> 01:10:37.047 align:middle line:90%
So this is a power series.

01:10:37.047 --> 01:10:38.130 align:middle line:90%
So this is a power series.

01:10:38.130 --> 01:10:41.600 align:middle line:90%


01:10:41.600 --> 01:10:44.960 align:middle line:90%
And the question is then--

01:10:44.960 --> 01:10:50.240 align:middle line:84%
the question, which turned
out to be quite subtle, is--

01:10:50.240 --> 01:10:53.360 align:middle line:84%
so a lot of the
basic functions can

01:10:53.360 --> 01:10:56.000 align:middle line:90%
be represented by power series.

01:10:56.000 --> 01:10:59.480 align:middle line:90%
This here was one example.

01:10:59.480 --> 01:11:04.640 align:middle line:84%
Another example is--
so another example of--

01:11:04.640 --> 01:11:07.200 align:middle line:84%
if you're looking at the
exponential function-- and we'll

01:11:07.200 --> 01:11:09.320 align:middle line:90%
come back and discuss this more.

01:11:09.320 --> 01:11:12.640 align:middle line:84%
But the exponential function
has a nice power series

01:11:12.640 --> 01:11:14.520 align:middle line:90%
representation.

01:11:14.520 --> 01:11:17.860 align:middle line:84%
And this is the
exponential function,

01:11:17.860 --> 01:11:22.760 align:middle line:84%
the power series representation
of the exponential function.

01:11:22.760 --> 01:11:26.170 align:middle line:90%
And also the sine and cosine.

01:11:26.170 --> 01:11:33.010 align:middle line:84%
So cosine x, this also has a
power series representation.

01:11:33.010 --> 01:11:38.210 align:middle line:84%
And the power series is minus 1
to the power n x to the power 2n

01:11:38.210 --> 01:11:45.210 align:middle line:84%
divided by 2n factorial,
where you're summing from 0

01:11:45.210 --> 01:11:46.930 align:middle line:90%
to infinity.

01:11:46.930 --> 01:11:50.170 align:middle line:90%
And sine has a similar one.

01:11:50.170 --> 01:11:54.730 align:middle line:84%
So sine x has a similar
one where you're

01:11:54.730 --> 01:11:57.170 align:middle line:90%
summing from 0 to infinity.

01:11:57.170 --> 01:12:05.810 align:middle line:84%
And then it's minus 1 to power n
x to the power 2n plus 1 over 2n

01:12:05.810 --> 01:12:08.270 align:middle line:90%
plus 1 factorial.

01:12:08.270 --> 01:12:11.202 align:middle line:90%


01:12:11.202 --> 01:12:16.970 align:middle line:84%
And lots of functions have a
power series representation.

01:12:16.970 --> 01:12:19.470 align:middle line:90%
But it's not every function.

01:12:19.470 --> 01:12:23.250 align:middle line:84%
If I write down a
function, then--

01:12:23.250 --> 01:12:26.990 align:middle line:84%
so in fact, it's easy to write
a function that doesn't have.

01:12:26.990 --> 01:12:30.230 align:middle line:84%
So if you have-- but I'm not
going to prove to you that it

01:12:30.230 --> 01:12:30.870 align:middle line:90%
doesn't.

01:12:30.870 --> 01:12:33.910 align:middle line:84%
So if I take the
function that starts off

01:12:33.910 --> 01:12:39.170 align:middle line:84%
being dead zero and now
it's becoming interesting.

01:12:39.170 --> 01:12:43.050 align:middle line:84%
So this function here, this one
does not have a power series.

01:12:43.050 --> 01:12:45.990 align:middle line:84%
Even locally does not
have a power series.

01:12:45.990 --> 01:12:51.190 align:middle line:84%
And the thing is
that a power series

01:12:51.190 --> 01:12:52.870 align:middle line:84%
is an example of
something that's

01:12:52.870 --> 01:12:55.030 align:middle line:90%
called an analytic function.

01:12:55.030 --> 01:12:57.850 align:middle line:84%
And this here is not
an analytic function.

01:12:57.850 --> 01:13:00.070 align:middle line:84%
So that's why I know
that it definitely

01:13:00.070 --> 01:13:01.350 align:middle line:90%
doesn't have a power series.

01:13:01.350 --> 01:13:01.850 align:middle line:90%
But anyway.

01:13:01.850 --> 01:13:11.390 align:middle line:90%


01:13:11.390 --> 01:13:16.510 align:middle line:84%
So the question is if
you take a power series--

01:13:16.510 --> 01:13:23.550 align:middle line:84%
so suppose you take a sequence,
a n, and you write it down.

01:13:23.550 --> 01:13:28.370 align:middle line:84%
Suppose you take a sequence
a n and then you write down

01:13:28.370 --> 01:13:32.730 align:middle line:90%
a power series based on it.

01:13:32.730 --> 01:13:35.130 align:middle line:84%
Then the first question
that comes to mind

01:13:35.130 --> 01:13:41.770 align:middle line:84%
is, when does this-- for which
x does this series converge?

01:13:41.770 --> 01:13:51.140 align:middle line:84%
So for which x does
the series converge?

01:13:51.140 --> 01:13:57.810 align:middle line:90%


01:13:57.810 --> 01:14:01.250 align:middle line:84%
So this is like the
most basic thing.

01:14:01.250 --> 01:14:04.360 align:middle line:90%
And let's look at some examples.

01:14:04.360 --> 01:14:13.370 align:middle line:90%


01:14:13.370 --> 01:14:21.250 align:middle line:84%
Of course, if you
look at the-- so

01:14:21.250 --> 01:14:27.840 align:middle line:84%
the first example is what
we already talked about.

01:14:27.840 --> 01:14:31.540 align:middle line:84%
Suppose I'm looking
at this thing here.

01:14:31.540 --> 01:14:33.900 align:middle line:90%
Well, this here is x.

01:14:33.900 --> 01:14:35.960 align:middle line:84%
If you think about
x as being fixed,

01:14:35.960 --> 01:14:38.060 align:middle line:90%
this is a geometric series.

01:14:38.060 --> 01:14:39.740 align:middle line:90%
And we already know--

01:14:39.740 --> 01:14:52.050 align:middle line:84%
so this is for each fixed x,
this is the geometric series.

01:14:52.050 --> 01:14:58.340 align:middle line:90%


01:14:58.340 --> 01:15:01.160 align:middle line:84%
So we already know that
this thing here converges.

01:15:01.160 --> 01:15:09.480 align:middle line:84%
So converges as long as
the absolute value sign--

01:15:09.480 --> 01:15:12.300 align:middle line:84%
absolute value of
x is less than 1.

01:15:12.300 --> 01:15:21.320 align:middle line:84%
And we also know that n diverges
otherwise, because we've already

01:15:21.320 --> 01:15:22.260 align:middle line:90%
determined that.

01:15:22.260 --> 01:15:26.560 align:middle line:90%


01:15:26.560 --> 01:15:33.440 align:middle line:84%
Now you see-- the next example I
want to look at is the one power

01:15:33.440 --> 01:15:36.520 align:middle line:90%
series that represents--

01:15:36.520 --> 01:15:38.180 align:middle line:90%
but we haven't proven that yet.

01:15:38.180 --> 01:15:40.840 align:middle line:84%
But we'll talk about
that next time.

01:15:40.840 --> 01:15:42.820 align:middle line:90%
It's the exponential function.

01:15:42.820 --> 01:15:48.880 align:middle line:84%
If I'm looking at this power
series here, then I have--

01:15:48.880 --> 01:15:54.200 align:middle line:84%
then I'm interested
in for what x--

01:15:54.200 --> 01:16:01.570 align:middle line:90%
for what x does this converge?

01:16:01.570 --> 01:16:09.400 align:middle line:90%


01:16:09.400 --> 01:16:13.620 align:middle line:84%
And so it's natural here to
try to apply one of the tests.

01:16:13.620 --> 01:16:16.320 align:middle line:84%
So you just think
about x as being fixed

01:16:16.320 --> 01:16:19.100 align:middle line:84%
and you just apply
one of the tests.

01:16:19.100 --> 01:16:23.180 align:middle line:84%
And the natural one is either
the root test or the ratio test.

01:16:23.180 --> 01:16:24.550 align:middle line:90%
Let's do the ratio test.

01:16:24.550 --> 01:16:27.180 align:middle line:90%


01:16:27.180 --> 01:16:32.080 align:middle line:84%
So x is fixed, and I'm not
interested in x equal to 0.

01:16:32.080 --> 01:16:36.840 align:middle line:84%
I'm assuming that x is not
equal to 0, because when x is 0,

01:16:36.840 --> 01:16:38.420 align:middle line:90%
this here is just--

01:16:38.420 --> 01:16:44.780 align:middle line:84%
it's only for-- x to the power
of 0 is by definition one.

01:16:44.780 --> 01:16:50.540 align:middle line:84%
And all the other things,
all the other terms, are 0.

01:16:50.540 --> 01:16:53.380 align:middle line:84%
So this here is-- it's
definitely converging

01:16:53.380 --> 01:16:55.360 align:middle line:90%
when x is equal to 0.

01:16:55.360 --> 01:16:58.425 align:middle line:90%
So let's not look at that.

01:16:58.425 --> 01:17:00.300 align:middle line:84%
And then-- because if
you don't look at that,

01:17:00.300 --> 01:17:02.900 align:middle line:84%
you can look at-- you
can think about a n.

01:17:02.900 --> 01:17:08.660 align:middle line:84%
You can now think about,
sorry, as the series

01:17:08.660 --> 01:17:14.780 align:middle line:84%
where bn is x to the
power n over n factorial.

01:17:14.780 --> 01:17:17.180 align:middle line:84%
If you think about
this thing here,

01:17:17.180 --> 01:17:19.950 align:middle line:84%
and you think about
the series as now bn,

01:17:19.950 --> 01:17:23.590 align:middle line:84%
then the ratio test
tells you that if you're

01:17:23.590 --> 01:17:29.280 align:middle line:84%
looking at the ratio
of bn plus 1 over bn--

01:17:29.280 --> 01:17:35.270 align:middle line:90%


01:17:35.270 --> 01:17:40.510 align:middle line:84%
so if you're looking
at bn plus 1 over bn,

01:17:40.510 --> 01:17:43.070 align:middle line:84%
you take the absolute
value of this here.

01:17:43.070 --> 01:17:47.630 align:middle line:84%
Well, this is just
x to the power n

01:17:47.630 --> 01:17:52.650 align:middle line:90%
plus 1 over n plus 1 factorial.

01:17:52.650 --> 01:17:57.190 align:middle line:84%
And then you have to
divide it by x to the power

01:17:57.190 --> 01:18:00.070 align:middle line:90%
n over n factorial.

01:18:00.070 --> 01:18:05.630 align:middle line:84%
But if you do that, this
here flips upside down,

01:18:05.630 --> 01:18:10.510 align:middle line:84%
and you're getting x to
the power n plus 1 times

01:18:10.510 --> 01:18:12.430 align:middle line:90%
n factorial.

01:18:12.430 --> 01:18:18.170 align:middle line:84%
And then you're getting x to
the n times n plus 1 factorial.

01:18:18.170 --> 01:18:21.330 align:middle line:90%
So this is what it's equal to.

01:18:21.330 --> 01:18:24.410 align:middle line:84%
And now, of course,
here, there are

01:18:24.410 --> 01:18:27.930 align:middle line:90%
x times itself n plus 1 times.

01:18:27.930 --> 01:18:31.750 align:middle line:84%
The n of those is
canceling out with this.

01:18:31.750 --> 01:18:34.890 align:middle line:90%
So this is x.

01:18:34.890 --> 01:18:41.170 align:middle line:84%
And here, you see here
the n plus 1 factorial.

01:18:41.170 --> 01:18:45.890 align:middle line:84%
You can write as n
plus 1 and then times

01:18:45.890 --> 01:18:48.130 align:middle line:90%
n times n minus 1 cetera.

01:18:48.130 --> 01:18:50.610 align:middle line:90%
But that's just n factorial.

01:18:50.610 --> 01:18:52.250 align:middle line:90%
So you can write it like that.

01:18:52.250 --> 01:18:56.050 align:middle line:84%
And so you see that
this here cancels that.

01:18:56.050 --> 01:18:59.250 align:middle line:90%
So you're left with n plus 1.

01:18:59.250 --> 01:19:06.130 align:middle line:84%
Remember, if x is fixed as n
goes to infinity, this here--

01:19:06.130 --> 01:19:10.390 align:middle line:84%
for each fixed x,
this just goes to 0.

01:19:10.390 --> 01:19:15.430 align:middle line:84%
So now you have, from the
ratio test, if that limit--

01:19:15.430 --> 01:19:18.270 align:middle line:84%
if it has a limit--
it does have a limit.

01:19:18.270 --> 01:19:23.890 align:middle line:84%
If that limit is strictly less
than 1, but it's actually 0.

01:19:23.890 --> 01:19:26.530 align:middle line:84%
So it's definitely
fallen under 1.

01:19:26.530 --> 01:19:28.670 align:middle line:90%
So it's convergent.

01:19:28.670 --> 01:19:32.990 align:middle line:90%
So the ratio test tells you--

01:19:32.990 --> 01:19:39.890 align:middle line:84%
so by the ratio test,
this is convergent.

01:19:39.890 --> 01:19:46.694 align:middle line:90%


01:19:46.694 --> 01:19:49.350 align:middle line:90%
And so we'll finish here.

01:19:49.350 --> 01:19:50.550 align:middle line:90%
There's a little bit more.

01:19:50.550 --> 01:19:54.110 align:middle line:84%
I posted already
my lecture notes.

01:19:54.110 --> 01:19:56.270 align:middle line:90%
There's a little bit more.

01:19:56.270 --> 01:19:59.750 align:middle line:84%
And I'll probably talk
about that next time.

01:19:59.750 --> 01:20:02.070 align:middle line:84%
I'll just start with just
talking about the stuff I

01:20:02.070 --> 01:20:02.910 align:middle line:90%
didn't get to.

01:20:02.910 --> 01:20:05.390 align:middle line:90%
The stuff I didn't get to was--

01:20:05.390 --> 01:20:08.190 align:middle line:84%
and we touched
upon that earlier--

01:20:08.190 --> 01:20:10.534 align:middle line:90%
is lim sup and lim inf.

01:20:10.534 --> 01:20:13.150 align:middle line:90%


01:20:13.150 --> 01:20:16.760 align:middle line:84%
And the reason why
we're covering it here

01:20:16.760 --> 01:20:19.840 align:middle line:90%
is that what if the ratio--

01:20:19.840 --> 01:20:22.800 align:middle line:84%
what if these things-- what
if the n-th roots-- so you're

01:20:22.800 --> 01:20:26.240 align:middle line:84%
asking for either the
ratio or the n-th root

01:20:26.240 --> 01:20:28.760 align:middle line:90%
of something to have a limit.

01:20:28.760 --> 01:20:31.520 align:middle line:84%
But what if it
doesn't have a limit?

01:20:31.520 --> 01:20:33.620 align:middle line:84%
And so it's dealing
with that case.

01:20:33.620 --> 01:20:35.560 align:middle line:90%
OK.

01:20:35.560 --> 01:20:36.320 align:middle line:90%
All right.

01:20:36.320 --> 01:20:37.520 align:middle line:90%
Any questions?

01:20:37.520 --> 01:20:39.793 align:middle line:84%
AUDIENCE: That means for
all x, right, you're saying?

01:20:39.793 --> 01:20:41.210 align:middle line:84%
TOBIAS COLDING:
This is for all x.

01:20:41.210 --> 01:20:44.240 align:middle line:84%
But think about
x as being fixed.

01:20:44.240 --> 01:20:46.320 align:middle line:90%
Think about x.

01:20:46.320 --> 01:20:48.860 align:middle line:84%
You're just asking
for one particular x,

01:20:48.860 --> 01:20:50.300 align:middle line:90%
but it holds for all x.

01:20:50.300 --> 01:20:54.400 align:middle line:84%
But don't think about x also
as being variable right.

01:20:54.400 --> 01:20:58.240 align:middle line:84%
Because you think about x as
being fixed, and then you let n

01:20:58.240 --> 01:21:00.033 align:middle line:90%
go to infinity.

01:21:00.033 --> 01:21:00.700 align:middle line:90%
AUDIENCE: Right.

01:21:00.700 --> 01:21:01.960 align:middle line:90%
And then after, you generalize.

01:21:01.960 --> 01:21:02.480 align:middle line:90%
TOBIAS COLDING: Yeah, yeah.

01:21:02.480 --> 01:21:03.022 align:middle line:90%
That's right.

01:21:03.022 --> 01:21:07.280 align:middle line:84%
And so you have for all
x, this makes sense.

01:21:07.280 --> 01:21:09.460 align:middle line:84%
Then you can ask, how
does it vary in x?

01:21:09.460 --> 01:21:11.710 align:middle line:90%
But that's a different story.

01:21:11.710 --> 01:21:14.000 align:middle line:90%