WEBVTT

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[RUSTLING]

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[CLICKING]

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TOBIAS COLDING: Last
time, we started

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looking at what's called
the Riemann integrals.

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For the Riemann integrals,
we have a function,

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f, that is defined on some
interval from a to b into R.

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And this function is bounded.

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And then we have P here is a
partition of this interval.

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And so this means that we have
a number of dividing points,

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where a is the first,
and then we have x1, x0.

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That's a, x1, x2, and
so on, up to, say, xn.

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And that is the final point,
end point, of the interval.

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So this here is a partition.

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These are the dividing points.

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Then we look at the length of
each of these subintervals.

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So we have the subintervals
from xi minus 1 to xi.

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And the length of one
of these subintervals

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we denote by delta xi.

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And so this is xi
minus xi minus 1.

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And then we look at--

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so here, if you have
the function here,

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this is the function f.

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And here, we have the
integral from a to b.

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And so this here is the
first dividing point.

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This is the last dividing point.

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And then we have these other
dividing points in between.

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And this is maybe like that.

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Then we look at the function
on one of these subintervals.

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So we look at--

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we look at the function.

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And we restrict it to one
of these subintervals.

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And then remember the
function is bounded.

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And so we're looking
at it on one of these.

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And we defined capital
Mi to be the sup

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of f over this subinterval.

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Likewise, we defined
little mi to be the inf.

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And this makes sense,
the finite number,

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because the function is bounded.

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And then we look at the
upper and the lower sum.

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So the upper sum.

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So the upper sum is that we
have this given partition.

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And we look at the sum here
of the Mi times delta xi.

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And we're summing.

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This is from 1 to n.

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So this is the upper sum of the
function for this partition.

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And likewise, we look
at the lower sum.

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This is where we
sum the infimum.

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And we weight them by the
length of the intervals.

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So we look at mi and then
delta xi and i equal to 1 to n.

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And this is the lower
sum for this partition.

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And then just using--

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then just using that--

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so of course, for these
mi, like these here,

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it's the inf and sum
on the same interval.

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So little mi is less than
or equal to capital Mi.

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But this also means that
these weights are the same.

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If this here is
less than that, it

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means that the lower sum is less
than or equal to the upper sum.

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Now, the second thing
we looked at is--

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so again, we looked at--

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so again, we have
this partition P.

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And we looked at P1
as a subpartition--

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subpartition or a refinement.

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This is if P1 has the
same dividing points as P

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and then presumably some--

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then-- I mean, then some more.

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But I mean, you
could have that-- you

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could have that the true
partition was exactly the same.

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And you would still say that
one is a trivial subpartition

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of the other.

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But in general, a subpartition
would have more dividing points.

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And so then the thing is that if
you're looking at-- so let's say

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that--

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so that P here, again,
has the partitions.

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This is the partition that
comes from P. And let's

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say that P1 here--

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let me illustrate it as
if P1 had one additional.

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So here, you have
x0, which is a.

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Here, you have xn, which is b.

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And then you have two other.

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Say this is x1 maybe.

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And this here is xk.

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Then you have a bunch of other.

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This is the partition p.

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And then p1, let's say, have
one more dividing point.

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It could have many
more dividing points.

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But if you're looking at--

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so you have here xi minus 1.

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And then you have xi and then
maybe the P1, this partition,

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have an additional dividing
point, which is called that one.

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Well, then the contribution
that you get from--

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to the lower and upper sum--

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so the contribution
that you get from this

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or that for P, you can
think about that as mi.

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This is the contribution
from the lowest sum.

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And here, you have the
contribution from the upper sum.

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But now you see that for
the subpartition, then

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you have that--

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so the intervals for
the subpartition--

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this here is the interval
for the original partition P.

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But for the
subpartition, this is now

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divided into two intervals,
this here and that here.

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And so you have that.

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So this thing here, this is,
in this case, split into two.

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And one of them is
y minus xi minus 1.

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And the other is xi minus 1.

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If you're looking at the--

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say, the lower sum
for this subpartition,

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so this thing here,
so the contribution

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that you get from this
here, where you have-- now

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you have two intervals.

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And so you're getting a--

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you're getting a contribution,
which is the inf on this thing

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here, on this
little interval here

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of f, times y minus xi minus 1.

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And then you get a
second contribution,

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which is inf on this interval
here, from y to xi of f.

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And then it's xi minus y.

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So this is the contribution that
you get from this interval here.

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But this thing here is
smaller or equal to the--

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it's actually-- sorry.

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This here is larger
or equal to the inf

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where you take the inf over
the larger interval that goes

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from this point to that point.

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So you have that this is
larger than y minus xi minus 1.

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This thing here is also
larger than this little mi.

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And then it's xi minus y.

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And now you can just factor
out-- so you're getting mi.

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And then when you add
these two together,

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then you see that this gives
you exactly xi minus xi minus 1.

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So this is little
mi times delta xi.

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So this means that if you--

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so you see that the
contribution that you

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get on this little
interval for this

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is larger than the contribution
that you get from this--

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larger, equal to.

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And so when you're summing
over all intervals,

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then you get that if P1 is a
refinement or subpartition, then

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this lower here, the
lower sum, go up.

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So this lower sum go up.

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And if you do it now,
if you do the same stuff

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for the upper sum,
then this here

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would-- instead of being inf,
it would have to be the sup.

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This here would
have to be the sup.

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But the sup on the
smaller interval

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is now then the-- this
inequality would reverse.

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It's less than or equal to.

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And then it would come to
sup on the larger interval.

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This here remains the same.

00:12:14.840 --> 00:12:18.200 align:middle line:84%
This here again
becomes a larger one.

00:12:18.200 --> 00:12:22.180 align:middle line:84%
So this here becomes
less than this.

00:12:22.180 --> 00:12:25.520 align:middle line:84%
This here becomes
less than this.

00:12:25.520 --> 00:12:30.980 align:middle line:84%
And so what you see is
that the sup here go down.

00:12:30.980 --> 00:12:36.360 align:middle line:90%
So the lower sum go up.

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And if you're looking at the
upper sum, this here, decrease.

00:12:46.580 --> 00:12:48.940 align:middle line:90%
So you have that.

00:12:48.940 --> 00:12:54.220 align:middle line:84%
And so putting
this together, you

00:12:54.220 --> 00:12:59.300 align:middle line:84%
have that the lower
sum for the partition P

00:12:59.300 --> 00:13:05.100 align:middle line:84%
is less than the lower sum
for this subpartition, which

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is less than the upper sum for
the subpartition, which is less

00:13:11.380 --> 00:13:17.140 align:middle line:90%
than the original upper sum.

00:13:17.140 --> 00:13:20.780 align:middle line:90%
So you have that.

00:13:20.780 --> 00:13:24.460 align:middle line:90%
And so this is like a key fact.

00:13:24.460 --> 00:13:28.130 align:middle line:84%
It's an obvious fact,
but it's a key fact.

00:13:28.130 --> 00:13:32.140 align:middle line:90%


00:13:32.140 --> 00:13:39.110 align:middle line:84%
So that was the
upper and lower sum.

00:13:39.110 --> 00:13:47.510 align:middle line:84%
So now we define the
upper and lower integrals.

00:13:47.510 --> 00:13:59.130 align:middle line:84%
So we define the upper and
lower Riemann integrals.

00:13:59.130 --> 00:14:07.390 align:middle line:90%


00:14:07.390 --> 00:14:14.390 align:middle line:84%
You define them as
follows, that the upper one

00:14:14.390 --> 00:14:15.580 align:middle line:90%
we denote like this.

00:14:15.580 --> 00:14:18.190 align:middle line:90%


00:14:18.190 --> 00:14:26.010 align:middle line:84%
And this here is now the inf of
all partitions of the upper sum.

00:14:26.010 --> 00:14:30.030 align:middle line:90%


00:14:30.030 --> 00:14:34.390 align:middle line:84%
And likewise, we define
the lower Riemann integral

00:14:34.390 --> 00:14:39.090 align:middle line:84%
of this function,
this bounded function,

00:14:39.090 --> 00:14:47.250 align:middle line:84%
to be the sup of the
lower sums, like that.

00:14:47.250 --> 00:14:49.690 align:middle line:90%
So sup of all partitions.

00:14:49.690 --> 00:14:52.690 align:middle line:84%
So that is the upper
and lower sums--

00:14:52.690 --> 00:14:55.210 align:middle line:90%
Riemann integrals.

00:14:55.210 --> 00:15:02.770 align:middle line:84%
And so now we say that the
function, this bounded function

00:15:02.770 --> 00:15:05.830 align:middle line:90%
f, is Riemann integrable.

00:15:05.830 --> 00:15:14.450 align:middle line:90%


00:15:14.450 --> 00:15:26.350 align:middle line:84%
So f here-- so f is said
to be a Riemann integrable.

00:15:26.350 --> 00:15:34.050 align:middle line:90%


00:15:34.050 --> 00:15:41.470 align:middle line:84%
And we write that f
here is like this.

00:15:41.470 --> 00:15:45.650 align:middle line:84%
So it means that it's
Riemann integrable.

00:15:45.650 --> 00:15:56.898 align:middle line:84%
If the following is the case,
so if this lower integral here

00:15:56.898 --> 00:16:04.970 align:middle line:84%
is equal to the upper integral,
and if this is the case,

00:16:04.970 --> 00:16:06.510 align:middle line:90%
then we just write--

00:16:06.510 --> 00:16:23.590 align:middle line:84%
and then the Riemann integral
of f is then denoted by--

00:16:23.590 --> 00:16:25.510 align:middle line:90%
just like that.

00:16:25.510 --> 00:16:30.350 align:middle line:90%


00:16:30.350 --> 00:16:34.850 align:middle line:84%
And so this is so
this is Riemann's way

00:16:34.850 --> 00:16:36.890 align:middle line:90%
of defining integrals.

00:16:36.890 --> 00:16:39.690 align:middle line:84%
There are other
ways, but this is--

00:16:39.690 --> 00:16:49.890 align:middle line:84%
I think this was the first way
where you have a definition that

00:16:49.890 --> 00:16:50.740 align:middle line:90%
really made sense.

00:16:50.740 --> 00:16:54.130 align:middle line:90%


00:16:54.130 --> 00:16:59.890 align:middle line:84%
So now the first thing
I want to observe

00:16:59.890 --> 00:17:07.650 align:middle line:84%
is that for a general
function, you always have--

00:17:07.650 --> 00:17:16.609 align:middle line:84%
so in general, so we always
have-- whether the function is

00:17:16.609 --> 00:17:19.290 align:middle line:84%
Riemann integrable
or not, we always

00:17:19.290 --> 00:17:26.290 align:middle line:84%
have that the lower integral
here, the lower Riemann integral

00:17:26.290 --> 00:17:28.710 align:middle line:84%
is less than or
equal to the upper.

00:17:28.710 --> 00:17:33.990 align:middle line:90%


00:17:33.990 --> 00:17:36.790 align:middle line:90%
And so why is that the case?

00:17:36.790 --> 00:17:38.180 align:middle line:90%
So this is because--

00:17:38.180 --> 00:17:44.330 align:middle line:90%


00:17:44.330 --> 00:17:44.830 align:middle line:90%
why?

00:17:44.830 --> 00:17:48.730 align:middle line:84%
This is because if
you take a partition--

00:17:48.730 --> 00:17:54.870 align:middle line:90%


00:17:54.870 --> 00:17:56.690 align:middle line:90%
so fix a partition.

00:17:56.690 --> 00:18:04.710 align:middle line:90%


00:18:04.710 --> 00:18:12.830 align:middle line:84%
Then you have that
the lower sum here

00:18:12.830 --> 00:18:19.630 align:middle line:84%
is, of course, less than
or equal to this thing

00:18:19.630 --> 00:18:28.430 align:middle line:84%
here, because this here was
the sup of all partitions.

00:18:28.430 --> 00:18:31.570 align:middle line:90%
So you have that.

00:18:31.570 --> 00:18:35.190 align:middle line:84%
But in fact, what you
also have, that you--

00:18:35.190 --> 00:18:52.810 align:middle line:84%
but more importantly, you
have that this L of f here,

00:18:52.810 --> 00:19:08.450 align:middle line:84%
I claim that this is a less
than or equal to the upper sum

00:19:08.450 --> 00:19:16.310 align:middle line:84%
for any other partition,
for any partition.

00:19:16.310 --> 00:19:21.490 align:middle line:90%


00:19:21.490 --> 00:19:23.550 align:middle line:84%
So I claim that you
always have this here.

00:19:23.550 --> 00:19:27.370 align:middle line:84%
If you take two
partition P and P star,

00:19:27.370 --> 00:19:29.790 align:middle line:84%
then the lower sum
for one is less than

00:19:29.790 --> 00:19:31.930 align:middle line:84%
or equal to the upper
sum for the other.

00:19:31.930 --> 00:19:33.550 align:middle line:90%
Why is that the case?

00:19:33.550 --> 00:19:35.810 align:middle line:84%
This just uses that
inequality over there.

00:19:35.810 --> 00:19:39.150 align:middle line:90%


00:19:39.150 --> 00:19:42.890 align:middle line:84%
It uses that together
with this inequality.

00:19:42.890 --> 00:19:46.150 align:middle line:90%
So let's see.

00:19:46.150 --> 00:19:47.360 align:middle line:90%
So if you take--

00:19:47.360 --> 00:19:51.950 align:middle line:90%


00:19:51.950 --> 00:20:02.830 align:middle line:84%
if P here is a partition
and P star is a partition,

00:20:02.830 --> 00:20:05.830 align:middle line:84%
then you could
take a partition--

00:20:05.830 --> 00:20:16.310 align:middle line:84%
so let P bar be
the partition that

00:20:16.310 --> 00:20:41.460 align:middle line:84%
has all the dividing points of P
and all the dividing points of P

00:20:41.460 --> 00:20:41.960 align:middle line:90%
star.

00:20:41.960 --> 00:20:44.610 align:middle line:90%


00:20:44.610 --> 00:20:47.250 align:middle line:84%
So the dividing
point of P bar is

00:20:47.250 --> 00:20:51.950 align:middle line:84%
the union of the dividing
points of the two partitions.

00:20:51.950 --> 00:20:59.810 align:middle line:84%
But this means that P bar here--
so P bar here is a refinement.

00:20:59.810 --> 00:21:14.850 align:middle line:84%
It's a refinement of
subpartition of both P and P

00:21:14.850 --> 00:21:20.146 align:middle line:84%
star, because it has all of
the dividing points of either.

00:21:20.146 --> 00:21:22.450 align:middle line:90%
But this means that--

00:21:22.450 --> 00:21:26.630 align:middle line:90%
remember that the lower sum--

00:21:26.630 --> 00:21:28.870 align:middle line:90%
so if you're looking at this--

00:21:28.870 --> 00:21:35.230 align:middle line:84%
the lower sum, if you take a
subpartition, that goes up.

00:21:35.230 --> 00:21:41.390 align:middle line:84%
So if you take a subpartition,
the lower sum will go up.

00:21:41.390 --> 00:21:44.450 align:middle line:84%
But the lower sum
is always less than

00:21:44.450 --> 00:21:48.710 align:middle line:84%
or equal to the upper sum
for a given partition.

00:21:48.710 --> 00:21:53.910 align:middle line:84%
But this here is now a
refinement of P star.

00:21:53.910 --> 00:21:56.350 align:middle line:90%
So the upper sum goes down.

00:21:56.350 --> 00:22:02.530 align:middle line:84%
So this is less than or
equal to U f of P star.

00:22:02.530 --> 00:22:05.190 align:middle line:84%
And so there you have it, that
this thing here, the lower

00:22:05.190 --> 00:22:09.350 align:middle line:84%
sum for one partition, is always
smaller than the upper sum

00:22:09.350 --> 00:22:12.070 align:middle line:90%
for the other.

00:22:12.070 --> 00:22:15.930 align:middle line:84%
And so this means that if
you now take a partition--

00:22:15.930 --> 00:22:26.210 align:middle line:90%


00:22:26.210 --> 00:22:37.330 align:middle line:84%
so now it means that for
a fixed partition P--

00:22:37.330 --> 00:22:41.110 align:middle line:84%
so if we have that this
thing here is less than

00:22:41.110 --> 00:22:47.790 align:middle line:84%
or equal to this thing
about P as being fixed,

00:22:47.790 --> 00:22:49.690 align:middle line:90%
but this is now for all other--

00:22:49.690 --> 00:22:52.270 align:middle line:90%
for all partitions P star.

00:22:52.270 --> 00:22:56.970 align:middle line:90%
So this is for all P star.

00:22:56.970 --> 00:23:00.010 align:middle line:84%
But if it holds
for all, this is--

00:23:00.010 --> 00:23:02.730 align:middle line:84%
sorry-- is less
than or equal to.

00:23:02.730 --> 00:23:06.710 align:middle line:84%
If it holds for all, then
it-- also, this inequality,

00:23:06.710 --> 00:23:08.170 align:middle line:90%
this is a fixed number.

00:23:08.170 --> 00:23:13.210 align:middle line:84%
This means that this here is
a lower bound for this family.

00:23:13.210 --> 00:23:22.490 align:middle line:84%
So this means that L f of P is
less than or equal to the inf

00:23:22.490 --> 00:23:23.360 align:middle line:90%
of those guys.

00:23:23.360 --> 00:23:30.270 align:middle line:90%


00:23:30.270 --> 00:23:32.870 align:middle line:84%
It's less than or
equal to the inf.

00:23:32.870 --> 00:23:35.350 align:middle line:90%
But that here is just the--

00:23:35.350 --> 00:23:41.430 align:middle line:84%
this here is by definition
the upper Riemann sum--

00:23:41.430 --> 00:23:42.800 align:middle line:90%
or, rather, Riemann integral.

00:23:42.800 --> 00:23:47.570 align:middle line:90%


00:23:47.570 --> 00:23:48.890 align:middle line:90%
But this is for each.

00:23:48.890 --> 00:23:51.210 align:middle line:84%
So now you forget
about the P star.

00:23:51.210 --> 00:23:54.190 align:middle line:84%
You have that this thing here
is less than that number.

00:23:54.190 --> 00:23:56.230 align:middle line:84%
So this means that
this number here

00:23:56.230 --> 00:24:00.716 align:middle line:84%
is an upper bound for
this whole family.

00:24:00.716 --> 00:24:04.750 align:middle line:84%
So this means that also the
sup, the smallest upper bound,

00:24:04.750 --> 00:24:06.990 align:middle line:90%
must be less than that.

00:24:06.990 --> 00:24:15.150 align:middle line:84%
So this means that
the sup of L of f, p

00:24:15.150 --> 00:24:18.450 align:middle line:84%
must be less than or
equal to this thing here.

00:24:18.450 --> 00:24:21.810 align:middle line:90%


00:24:21.810 --> 00:24:25.580 align:middle line:84%
But the sup is by definition
the lower integral.

00:24:25.580 --> 00:24:29.770 align:middle line:90%


00:24:29.770 --> 00:24:31.530 align:middle line:90%
So you always have--

00:24:31.530 --> 00:24:33.550 align:middle line:90%
and this claim over here.

00:24:33.550 --> 00:24:38.290 align:middle line:90%


00:24:38.290 --> 00:24:44.890 align:middle line:90%
So that's the first.

00:24:44.890 --> 00:24:53.450 align:middle line:84%
So let's look at a
function that is--

00:24:53.450 --> 00:24:57.670 align:middle line:84%
I added just a little bit,
if you find it interesting.

00:24:57.670 --> 00:24:59.290 align:middle line:84%
I find it interesting,
but maybe you

00:24:59.290 --> 00:25:04.330 align:middle line:84%
don't, but a little bit
about Riemann, that he died

00:25:04.330 --> 00:25:08.290 align:middle line:90%
rather young of tuberculosis.

00:25:08.290 --> 00:25:12.413 align:middle line:90%
But he had an incredible impact.

00:25:12.413 --> 00:25:13.330 align:middle line:90%
He had an incredible--

00:25:13.330 --> 00:25:15.730 align:middle line:84%
I mean, this is one
of his contributions.

00:25:15.730 --> 00:25:20.350 align:middle line:84%
His first contribution
is he was a student

00:25:20.350 --> 00:25:26.750 align:middle line:84%
of another really famous
mathematician, perhaps

00:25:26.750 --> 00:25:28.290 align:middle line:90%
the most famous of all time--

00:25:28.290 --> 00:25:29.390 align:middle line:90%
Gauss.

00:25:29.390 --> 00:25:35.550 align:middle line:84%
And so at those times,
when you wrote your thesis,

00:25:35.550 --> 00:25:38.250 align:middle line:84%
then you had like six
months to write your thesis.

00:25:38.250 --> 00:25:46.950 align:middle line:90%


00:25:46.950 --> 00:25:49.450 align:middle line:84%
Formally, you couldn't
choose your subject,

00:25:49.450 --> 00:25:51.510 align:middle line:90%
but it was always--

00:25:51.510 --> 00:25:54.130 align:middle line:84%
anyway, you always got
permission to choose it.

00:25:54.130 --> 00:25:57.350 align:middle line:84%
You had to give three
suggestions for something

00:25:57.350 --> 00:25:59.710 align:middle line:90%
you would write your thesis on.

00:25:59.710 --> 00:26:01.350 align:middle line:90%
But it was always--

00:26:01.350 --> 00:26:05.390 align:middle line:84%
it was a unspoken rule
that your advisor always

00:26:05.390 --> 00:26:06.430 align:middle line:90%
picked number one.

00:26:06.430 --> 00:26:07.570 align:middle line:90%
And that's what you wanted.

00:26:07.570 --> 00:26:09.990 align:middle line:84%
And then you could add
some other crazy stuff

00:26:09.990 --> 00:26:12.670 align:middle line:90%
as two other suggestions.

00:26:12.670 --> 00:26:15.830 align:middle line:84%
So Riemann had
three suggestions.

00:26:15.830 --> 00:26:21.330 align:middle line:84%
And the third one, which he
had absolutely no idea about,

00:26:21.330 --> 00:26:27.010 align:middle line:84%
was to make sense of
curvature in higher dimension.

00:26:27.010 --> 00:26:30.110 align:middle line:90%
And so he just put it in there.

00:26:30.110 --> 00:26:33.130 align:middle line:84%
He knew it wasn't
going to be selected.

00:26:33.130 --> 00:26:35.330 align:middle line:84%
But actually, at
the time, this was

00:26:35.330 --> 00:26:37.250 align:middle line:90%
what Gauss was interested in.

00:26:37.250 --> 00:26:39.430 align:middle line:84%
And so Gauss said, to
hell with the rules.

00:26:39.430 --> 00:26:41.010 align:middle line:90%
I'll pick number three.

00:26:41.010 --> 00:26:44.150 align:middle line:84%
And so he had six months, and
nobody had figured this out.

00:26:44.150 --> 00:26:47.210 align:middle line:84%
So Gauss is considered
by many the greatest

00:26:47.210 --> 00:26:50.370 align:middle line:90%
mathematician of all time.

00:26:50.370 --> 00:26:53.010 align:middle line:84%
But after six months,
actually, so Riemann

00:26:53.010 --> 00:26:55.930 align:middle line:84%
came up with something
called the curvature tensor,

00:26:55.930 --> 00:26:59.290 align:middle line:84%
which is this objects
in all dimensions.

00:26:59.290 --> 00:27:02.090 align:middle line:84%
And that generalized
Gauss's work.

00:27:02.090 --> 00:27:06.090 align:middle line:84%
And this lay the foundation
for general relativity

00:27:06.090 --> 00:27:14.770 align:middle line:84%
that came many years later,
70 years or so later.

00:27:14.770 --> 00:27:16.970 align:middle line:90%
So that was the Riemann's first.

00:27:16.970 --> 00:27:20.230 align:middle line:84%
This is one of Riemann's
other contributions.

00:27:20.230 --> 00:27:23.990 align:middle line:84%
And there are other things that
was only published a long time

00:27:23.990 --> 00:27:29.110 align:middle line:84%
after his death that have
had a tremendous contribution

00:27:29.110 --> 00:27:31.070 align:middle line:90%
in other areas.

00:27:31.070 --> 00:27:33.070 align:middle line:90%
Anyway, so this is--

00:27:33.070 --> 00:27:36.450 align:middle line:84%
so this was Riemann's way
of defining the integrals.

00:27:36.450 --> 00:27:44.830 align:middle line:90%


00:27:44.830 --> 00:27:48.312 align:middle line:90%
Let me look at a function.

00:27:48.312 --> 00:27:49.770 align:middle line:84%
So we talk about
that a little bit.

00:27:49.770 --> 00:27:52.770 align:middle line:84%
But we didn't
actually define it.

00:27:52.770 --> 00:27:56.870 align:middle line:84%
So here's an example
of a function

00:27:56.870 --> 00:27:59.870 align:middle line:90%
that is not Riemann integrable.

00:27:59.870 --> 00:28:04.750 align:middle line:84%
So it's a function defined
on the interval from 0 to 1,

00:28:04.750 --> 00:28:07.790 align:middle line:90%
so it's bounded.

00:28:07.790 --> 00:28:18.970 align:middle line:84%
And so the function is
f of x is equal to 1

00:28:18.970 --> 00:28:21.600 align:middle line:90%
if x here is rational.

00:28:21.600 --> 00:28:25.650 align:middle line:90%


00:28:25.650 --> 00:28:28.190 align:middle line:90%
And it's 0 otherwise.

00:28:28.190 --> 00:28:35.258 align:middle line:90%


00:28:35.258 --> 00:28:39.510 align:middle line:84%
And so of course, this function
here is always between 0 and 1.

00:28:39.510 --> 00:28:42.610 align:middle line:90%
So it's definitely bounded.

00:28:42.610 --> 00:28:45.190 align:middle line:84%
But if you take
now any interval--

00:28:45.190 --> 00:28:50.530 align:middle line:90%


00:28:50.530 --> 00:29:03.950 align:middle line:84%
so this here, so I claim here
f is not Riemann integrable.

00:29:03.950 --> 00:29:13.290 align:middle line:90%


00:29:13.290 --> 00:29:15.620 align:middle line:84%
And so the thing is
that if you take--

00:29:15.620 --> 00:29:19.070 align:middle line:90%


00:29:19.070 --> 00:29:25.070 align:middle line:84%
if you take a interval
like this and you

00:29:25.070 --> 00:29:34.610 align:middle line:84%
take a subpartition like
that, and now you have that--

00:29:34.610 --> 00:29:39.070 align:middle line:84%
and now you're looking
at one of these mi.

00:29:39.070 --> 00:29:41.770 align:middle line:90%
So here, you have xi minus 1.

00:29:41.770 --> 00:29:44.910 align:middle line:90%
And here you have xi.

00:29:44.910 --> 00:29:48.670 align:middle line:90%
And so you're looking at mi.

00:29:48.670 --> 00:29:51.830 align:middle line:84%
So this is some little
interval like this.

00:29:51.830 --> 00:29:55.070 align:middle line:84%
But on any kind
of small interval,

00:29:55.070 --> 00:29:57.010 align:middle line:84%
if it's really a
proper integral,

00:29:57.010 --> 00:29:58.510 align:middle line:84%
if it's not just
a point but it's

00:29:58.510 --> 00:30:01.950 align:middle line:84%
a proper integral--
interval, then there's

00:30:01.950 --> 00:30:04.790 align:middle line:84%
always points that are
rational and always points

00:30:04.790 --> 00:30:06.150 align:middle line:90%
that are not rational.

00:30:06.150 --> 00:30:10.950 align:middle line:84%
So this means that this here,
this here, the sup here,

00:30:10.950 --> 00:30:17.930 align:middle line:84%
would have to be 1, but
the inf here would be 0.

00:30:17.930 --> 00:30:20.080 align:middle line:90%
And so this means that for the--

00:30:20.080 --> 00:30:22.030 align:middle line:90%
so this is just any partition.

00:30:22.030 --> 00:30:24.250 align:middle line:90%
And so this means that for--

00:30:24.250 --> 00:30:29.610 align:middle line:84%
if you're looking at
the upper sum here,

00:30:29.610 --> 00:30:34.290 align:middle line:84%
but it's now the sum of
these capital Mi delta xi.

00:30:34.290 --> 00:30:35.730 align:middle line:90%
This here is 1.

00:30:35.730 --> 00:30:39.450 align:middle line:84%
So it's just the sum of the
length of the small interval.

00:30:39.450 --> 00:30:43.730 align:middle line:84%
But that's just one because the
whole interval is from 0 to 1.

00:30:43.730 --> 00:30:48.650 align:middle line:84%
And likewise, for the
lower interval, lower sum,

00:30:48.650 --> 00:30:55.450 align:middle line:84%
this is the sum here of
this small mi delta xi.

00:30:55.450 --> 00:30:56.970 align:middle line:90%
These here are 0.

00:30:56.970 --> 00:30:58.790 align:middle line:90%
So this whole thing here is 0.

00:30:58.790 --> 00:31:01.730 align:middle line:90%


00:31:01.730 --> 00:31:08.370 align:middle line:84%
So you see that if you--
this is for all partitions.

00:31:08.370 --> 00:31:11.170 align:middle line:84%
So this means that if you
take the infimum of this,

00:31:11.170 --> 00:31:12.290 align:middle line:90%
you still get 1.

00:31:12.290 --> 00:31:15.510 align:middle line:84%
And if you take the sup
of these still get 0.

00:31:15.510 --> 00:31:18.530 align:middle line:84%
So those two numbers
are not the same.

00:31:18.530 --> 00:31:22.870 align:middle line:84%
The lower and the upper Riemann
integrals are not the same.

00:31:22.870 --> 00:31:25.170 align:middle line:84%
So the function is not
Riemann integrable.

00:31:25.170 --> 00:31:32.430 align:middle line:90%


00:31:32.430 --> 00:31:34.920 align:middle line:90%
So now the next thing is--

00:31:34.920 --> 00:31:38.390 align:middle line:90%


00:31:38.390 --> 00:31:42.630 align:middle line:84%
the next thing is-- so we
want to know which functions

00:31:42.630 --> 00:31:45.710 align:middle line:90%
are Riemann integrable.

00:31:45.710 --> 00:31:49.950 align:middle line:84%
And so here's a useful
little criteria.

00:31:49.950 --> 00:31:56.220 align:middle line:84%
So lemma-- so you have a
function again that is bounded.

00:31:56.220 --> 00:32:00.990 align:middle line:90%


00:32:00.990 --> 00:32:08.170 align:middle line:90%
Then f is Riemann integrable.

00:32:08.170 --> 00:32:11.210 align:middle line:84%
And again, we
write it like this.

00:32:11.210 --> 00:32:20.770 align:middle line:84%
So it's Riemann integrable if
for all epsilon greater than 0,

00:32:20.770 --> 00:32:40.850 align:middle line:84%
there exists a partition P
so that the upper integral--

00:32:40.850 --> 00:32:46.390 align:middle line:84%
upper sum-- sorry-- so that the
upper sum minus the lower sum--

00:32:46.390 --> 00:32:51.050 align:middle line:84%
remember that this is always
bigger than the lower sum

00:32:51.050 --> 00:32:55.410 align:middle line:84%
if this here is
less than epsilon.

00:32:55.410 --> 00:32:59.130 align:middle line:84%
So if we want to check that a
function is Riemann integrable,

00:32:59.130 --> 00:33:01.890 align:middle line:84%
then we just need to check
that for all epsilon,

00:33:01.890 --> 00:33:09.390 align:middle line:84%
we can find a partition
with this property.

00:33:09.390 --> 00:33:13.830 align:middle line:84%
And so this is a statement that
is if and only if-- so I should

00:33:13.830 --> 00:33:15.410 align:middle line:90%
say if and only if--

00:33:15.410 --> 00:33:18.430 align:middle line:90%


00:33:18.430 --> 00:33:21.650 align:middle line:90%
if and only if.

00:33:21.650 --> 00:33:35.310 align:middle line:90%


00:33:35.310 --> 00:33:37.030 align:middle line:90%
So just try to prove that.

00:33:37.030 --> 00:33:40.790 align:middle line:84%
And then we're going
to use this later on

00:33:40.790 --> 00:33:45.770 align:middle line:84%
to prove that a lot of functions
are Riemann integrable.

00:33:45.770 --> 00:33:50.190 align:middle line:90%


00:33:50.190 --> 00:33:59.250 align:middle line:90%
So suppose that f--

00:33:59.250 --> 00:34:03.530 align:middle line:84%
so if f here is
Riemann integrable--

00:34:03.530 --> 00:34:11.889 align:middle line:90%


00:34:11.889 --> 00:34:14.290 align:middle line:84%
so if it is Riemann
integrable, then we

00:34:14.290 --> 00:34:20.138 align:middle line:84%
know that this lower
Riemann integral

00:34:20.138 --> 00:34:23.099 align:middle line:84%
is equal to the upper
Riemann integral.

00:34:23.099 --> 00:34:29.170 align:middle line:90%


00:34:29.170 --> 00:34:32.210 align:middle line:84%
This here was the sup
of all-- this here

00:34:32.210 --> 00:34:39.050 align:middle line:84%
was the sup of all lower sums
for all-- over all partitions.

00:34:39.050 --> 00:34:48.170 align:middle line:84%
And this here was the
inf of all upper sum,

00:34:48.170 --> 00:34:50.989 align:middle line:90%
like that, over all partitions.

00:34:50.989 --> 00:34:57.930 align:middle line:90%


00:34:57.930 --> 00:35:08.550 align:middle line:84%
So therefore, given
epsilon greater than 0,

00:35:08.550 --> 00:35:20.350 align:middle line:90%
there exists a partition P1.

00:35:20.350 --> 00:35:20.850 align:middle line:90%
Why?

00:35:20.850 --> 00:35:23.050 align:middle line:84%
Because this here has a
sup over all partitions.

00:35:23.050 --> 00:35:31.870 align:middle line:84%
So it means that there exists
a partition so that this lower

00:35:31.870 --> 00:35:46.010 align:middle line:84%
sum here is bigger or equal to
this here minus epsilon over 2.

00:35:46.010 --> 00:35:49.010 align:middle line:84%
It's just because it's a
sup of all these numbers.

00:35:49.010 --> 00:35:54.220 align:middle line:84%
So there must exist one that
comes this close to the sup.

00:35:54.220 --> 00:36:11.330 align:middle line:90%


00:36:11.330 --> 00:36:24.410 align:middle line:84%
Likewise, there exists
a partition P2--

00:36:24.410 --> 00:36:26.930 align:middle line:90%
sorry-- this here should be P1.

00:36:26.930 --> 00:36:29.370 align:middle line:90%
This is the sup over-- sorry.

00:36:29.370 --> 00:36:33.990 align:middle line:84%
So there exists a
partition P2 so that the--

00:36:33.990 --> 00:36:39.290 align:middle line:84%
so that for that, this is
one where this value here

00:36:39.290 --> 00:36:40.270 align:middle line:90%
is really small.

00:36:40.270 --> 00:36:43.670 align:middle line:84%
So this is not too
much larger than this.

00:36:43.670 --> 00:36:54.370 align:middle line:84%
So this means that this for
P2 is smaller or equal to this

00:36:54.370 --> 00:37:02.870 align:middle line:84%
here, upper Riemann integral
plus epsilon over 2.

00:37:02.870 --> 00:37:09.470 align:middle line:90%


00:37:09.470 --> 00:37:32.750 align:middle line:84%
So now let P be the partition
with all the dividing points

00:37:32.750 --> 00:37:40.130 align:middle line:90%
of both P1 and P2.

00:37:40.130 --> 00:37:43.470 align:middle line:84%
So it has all of the
dividing points from P1

00:37:43.470 --> 00:37:46.936 align:middle line:84%
together with all of the
dividing points from P2.

00:37:46.936 --> 00:37:50.910 align:middle line:84%
But now for this
partition, we have that--

00:37:50.910 --> 00:37:55.310 align:middle line:84%
well, for-- this is
a refinement of P1.

00:37:55.310 --> 00:37:58.610 align:middle line:84%
So if it's refinement,
the value here goes up.

00:37:58.610 --> 00:38:03.330 align:middle line:90%


00:38:03.330 --> 00:38:06.370 align:middle line:90%
And this thing here is--

00:38:06.370 --> 00:38:11.730 align:middle line:84%
so this is less than the
upper for the same thing.

00:38:11.730 --> 00:38:15.610 align:middle line:84%
And since it's a
refinement also of P2,

00:38:15.610 --> 00:38:20.150 align:middle line:84%
we have that it is less
than the upper sum for P2.

00:38:20.150 --> 00:38:23.530 align:middle line:90%


00:38:23.530 --> 00:38:28.210 align:middle line:84%
But now you see that
this thing here--

00:38:28.210 --> 00:38:32.750 align:middle line:84%
so L-- so the difference
between these two--

00:38:32.750 --> 00:38:35.330 align:middle line:84%
the difference between
these two numbers--

00:38:35.330 --> 00:38:37.470 align:middle line:90%
so this is the difference here.

00:38:37.470 --> 00:38:45.610 align:middle line:90%
So U f P minus U f P-- sorry--

00:38:45.610 --> 00:38:51.870 align:middle line:84%
L f P, this difference here,
this is bigger than that.

00:38:51.870 --> 00:38:54.050 align:middle line:84%
So if you take this
and subtract this,

00:38:54.050 --> 00:38:56.210 align:middle line:84%
you're getting
something non-negative.

00:38:56.210 --> 00:38:59.190 align:middle line:84%
And this, the spread
between these two,

00:38:59.190 --> 00:39:02.110 align:middle line:84%
is smaller than the
spread between these.

00:39:02.110 --> 00:39:10.520 align:middle line:84%
So this is less than U
of f P2 minus L of f P1.

00:39:10.520 --> 00:39:13.030 align:middle line:90%


00:39:13.030 --> 00:39:16.750 align:middle line:90%
But this thing here is--

00:39:16.750 --> 00:39:25.590 align:middle line:84%
this thing here is less than U
f P2 minus this upper integral

00:39:25.590 --> 00:39:26.090 align:middle line:90%
here.

00:39:26.090 --> 00:39:30.190 align:middle line:90%


00:39:30.190 --> 00:39:31.890 align:middle line:84%
Assuming that it's
Riemann integral,

00:39:31.890 --> 00:39:34.230 align:middle line:84%
so the upper and
lower are the same.

00:39:34.230 --> 00:39:47.870 align:middle line:84%
So this thing here we can write
it as this plus minus L f P1

00:39:47.870 --> 00:39:56.730 align:middle line:84%
minus the integral
here, like that.

00:39:56.730 --> 00:40:02.920 align:middle line:84%
I'm just subtracting and then
adding back the same thing.

00:40:02.920 --> 00:40:06.320 align:middle line:84%
And this one here, we
already found that this here

00:40:06.320 --> 00:40:10.780 align:middle line:90%
was bounded by epsilon over 2.

00:40:10.780 --> 00:40:12.880 align:middle line:84%
This here is--
remember, we're assuming

00:40:12.880 --> 00:40:15.020 align:middle line:90%
that it's Riemann integrable.

00:40:15.020 --> 00:40:20.640 align:middle line:84%
So this here is the same thing
as when you have the upper one.

00:40:20.640 --> 00:40:24.000 align:middle line:90%
And this thing here is--

00:40:24.000 --> 00:40:29.180 align:middle line:84%
this here is also bounded
by-- this is actually right.

00:40:29.180 --> 00:40:33.700 align:middle line:90%
This is negative, but it's--

00:40:33.700 --> 00:40:40.680 align:middle line:84%
so this thing here is
bigger or equal to--

00:40:40.680 --> 00:40:42.070 align:middle line:90%
maybe I should write it as--

00:40:42.070 --> 00:40:45.600 align:middle line:90%


00:40:45.600 --> 00:40:48.280 align:middle line:84%
well, let me write
it like this-- plus.

00:40:48.280 --> 00:40:51.680 align:middle line:84%
And then I can write it
as the integral from a

00:40:51.680 --> 00:40:59.820 align:middle line:84%
to b of f of x dx
minus L f of P1.

00:40:59.820 --> 00:41:04.420 align:middle line:84%
But this thing here was
bounded by epsilon over 2 also.

00:41:04.420 --> 00:41:08.020 align:middle line:84%
So epsilon over 2
plus epsilon over 2.

00:41:08.020 --> 00:41:10.900 align:middle line:90%
So this is equal to epsilon.

00:41:10.900 --> 00:41:15.940 align:middle line:90%


00:41:15.940 --> 00:41:21.460 align:middle line:84%
So again, if you want to test
that a function is Riemann

00:41:21.460 --> 00:41:24.560 align:middle line:84%
integral, you just need
to find-- for a given,

00:41:24.560 --> 00:41:26.620 align:middle line:84%
for any given epsilon,
you need to be

00:41:26.620 --> 00:41:32.740 align:middle line:84%
able to find a partition so that
the upper sum for that partition

00:41:32.740 --> 00:41:37.540 align:middle line:84%
is minus the lower sum
for the same partition

00:41:37.540 --> 00:41:38.680 align:middle line:90%
is less than epsilon.

00:41:38.680 --> 00:41:42.495 align:middle line:90%


00:41:42.495 --> 00:41:47.740 align:middle line:84%
And so now this leads
us to the next theorem.

00:41:47.740 --> 00:41:52.920 align:middle line:84%
So the next theorem is that
any continuous function

00:41:52.920 --> 00:41:54.580 align:middle line:90%
is Riemann integrable.

00:41:54.580 --> 00:42:07.280 align:middle line:90%


00:42:07.280 --> 00:42:09.240 align:middle line:90%
So any Riemann sum--

00:42:09.240 --> 00:42:10.840 align:middle line:90%
so any continuous function--

00:42:10.840 --> 00:42:20.480 align:middle line:90%


00:42:20.480 --> 00:42:26.600 align:middle line:84%
any continuous function on an
integral like this-- this is--

00:42:26.600 --> 00:42:30.235 align:middle line:90%
a and b are real numbers--

00:42:30.235 --> 00:42:33.180 align:middle line:90%
it is Riemann integrable.

00:42:33.180 --> 00:42:41.800 align:middle line:90%


00:42:41.800 --> 00:42:45.480 align:middle line:84%
So this is the next theorem
that we want to prove.

00:42:45.480 --> 00:42:48.720 align:middle line:84%
But in order to prove
that, we need a tool.

00:42:48.720 --> 00:42:52.800 align:middle line:84%
And so this is what's
called uniformly continuous.

00:42:52.800 --> 00:42:56.620 align:middle line:90%


00:42:56.620 --> 00:42:59.260 align:middle line:84%
So just to show this,
we need the notion

00:42:59.260 --> 00:43:03.420 align:middle line:90%
of being uniformly continuous.

00:43:03.420 --> 00:43:06.500 align:middle line:90%
So what is that?

00:43:06.500 --> 00:43:30.600 align:middle line:84%
So in the proof, we need the
notion of uniformly continuous.

00:43:30.600 --> 00:43:39.820 align:middle line:90%


00:43:39.820 --> 00:43:42.260 align:middle line:90%
So that's the following.

00:43:42.260 --> 00:43:47.060 align:middle line:84%
And you have a function
defined on some interval, say.

00:43:47.060 --> 00:43:51.720 align:middle line:84%
It could be all of
R, for that matter.

00:43:51.720 --> 00:43:54.440 align:middle line:84%
So you have a
function like this.

00:43:54.440 --> 00:43:58.200 align:middle line:90%
And f is said to be--

00:43:58.200 --> 00:44:21.480 align:middle line:84%
is said to be uniformly
continuous if for all epsilon

00:44:21.480 --> 00:44:31.000 align:middle line:84%
greater than 0, there
exists delta greater than 0

00:44:31.000 --> 00:44:39.200 align:middle line:84%
such that as long as x and
y are less than delta, then

00:44:39.200 --> 00:44:48.344 align:middle line:84%
their images is
less than epsilon.

00:44:48.344 --> 00:44:52.120 align:middle line:84%
So what is the difference
between this and continuity?

00:44:52.120 --> 00:44:54.940 align:middle line:84%
For continuity,
you're always-- you're

00:44:54.940 --> 00:44:57.440 align:middle line:84%
looking at-- a
function's continuous

00:44:57.440 --> 00:45:00.160 align:middle line:84%
if it's continuous
at all points.

00:45:00.160 --> 00:45:02.100 align:middle line:84%
And so it's
continuous at a point.

00:45:02.100 --> 00:45:05.220 align:middle line:90%


00:45:05.220 --> 00:45:06.620 align:middle line:84%
To be continuous
at a point, it's

00:45:06.620 --> 00:45:08.940 align:middle line:84%
like you're fixing
one of these two.

00:45:08.940 --> 00:45:11.300 align:middle line:90%
So it's like x is fixed.

00:45:11.300 --> 00:45:15.220 align:middle line:84%
And then you're looking at if
y is sufficiently close, then

00:45:15.220 --> 00:45:16.620 align:middle line:90%
the value--

00:45:16.620 --> 00:45:20.020 align:middle line:84%
the difference between
the value at x and y

00:45:20.020 --> 00:45:21.660 align:middle line:90%
is smaller than epsilon.

00:45:21.660 --> 00:45:26.880 align:middle line:84%
But here, it's like that the
same delta works for all x.

00:45:26.880 --> 00:45:30.380 align:middle line:84%
You don't have to fix
one of the two points.

00:45:30.380 --> 00:45:31.800 align:middle line:90%
The same delta work.

00:45:31.800 --> 00:45:38.100 align:middle line:84%
So let's see where
this is not the case.

00:45:38.100 --> 00:45:41.340 align:middle line:90%
So let me look at two examples.

00:45:41.340 --> 00:45:43.360 align:middle line:84%
So just to understand
the difference--

00:45:43.360 --> 00:45:46.200 align:middle line:84%
so to understand
the difference--

00:45:46.200 --> 00:45:51.200 align:middle line:90%


00:45:51.200 --> 00:46:05.740 align:middle line:84%
the difference between
continuity and uniform

00:46:05.740 --> 00:46:07.400 align:middle line:90%
continuity.

00:46:07.400 --> 00:46:14.380 align:middle line:84%
Uniform, again, refer to
that x is not fixed, or x0.

00:46:14.380 --> 00:46:16.680 align:middle line:90%
Usually, we call it x0 and x.

00:46:16.680 --> 00:46:20.500 align:middle line:84%
So one of the two
points was fixed.

00:46:20.500 --> 00:46:23.340 align:middle line:84%
And uniform means that
you don't need to fix.

00:46:23.340 --> 00:46:28.080 align:middle line:84%
It's like the same delta
works for all x0's.

00:46:28.080 --> 00:46:33.880 align:middle line:90%


00:46:33.880 --> 00:46:41.160 align:middle line:84%
And so here is an example that
suppose you take the function f

00:46:41.160 --> 00:46:42.820 align:middle line:90%
of x equal to x squared.

00:46:42.820 --> 00:46:48.780 align:middle line:84%
This is now on R.
Well, we already

00:46:48.780 --> 00:46:51.420 align:middle line:84%
know that this
function is continuous.

00:46:51.420 --> 00:47:04.500 align:middle line:84%
And so if it was uniformly so,
if f was uniformly continuous,

00:47:04.500 --> 00:47:12.820 align:middle line:84%
then for a given
epsilon greater than 0,

00:47:12.820 --> 00:47:18.460 align:middle line:84%
there would exist a delta
so that the value at x

00:47:18.460 --> 00:47:26.020 align:middle line:84%
and the value where
you, say, added delta,

00:47:26.020 --> 00:47:29.460 align:middle line:84%
this difference here
would have to be

00:47:29.460 --> 00:47:33.040 align:middle line:84%
less than if you want--
if you don't like it,

00:47:33.040 --> 00:47:36.860 align:middle line:84%
you could say delta over 2
if you want it to be strictly

00:47:36.860 --> 00:47:38.188 align:middle line:90%
the difference between.

00:47:38.188 --> 00:47:39.480 align:middle line:90%
But that doesn't really matter.

00:47:39.480 --> 00:47:42.100 align:middle line:90%
I'll just say like that.

00:47:42.100 --> 00:47:44.920 align:middle line:84%
This here would
have to be the case.

00:47:44.920 --> 00:47:47.940 align:middle line:84%
And this here would have
to be the case for all x.

00:47:47.940 --> 00:47:52.160 align:middle line:90%


00:47:52.160 --> 00:47:54.080 align:middle line:90%
But what is this here?

00:47:54.080 --> 00:47:58.620 align:middle line:84%
This here is x
plus delta squared.

00:47:58.620 --> 00:48:01.560 align:middle line:84%
That's the value of
the function in this.

00:48:01.560 --> 00:48:04.300 align:middle line:84%
And this is the value
of the function in x.

00:48:04.300 --> 00:48:07.380 align:middle line:90%


00:48:07.380 --> 00:48:09.760 align:middle line:84%
But this thing here,
it's a squaring out.

00:48:09.760 --> 00:48:17.880 align:middle line:84%
It gives you x squared plus
delta squared plus 2x delta.

00:48:17.880 --> 00:48:22.090 align:middle line:84%
And this thing here would
have to be less than epsilon.

00:48:22.090 --> 00:48:25.704 align:middle line:90%


00:48:25.704 --> 00:48:29.840 align:middle line:90%
Delta is positive.

00:48:29.840 --> 00:48:30.400 align:middle line:90%
Sorry.

00:48:30.400 --> 00:48:33.680 align:middle line:84%
This here, minus x
squared, would have

00:48:33.680 --> 00:48:35.160 align:middle line:90%
to be less than delta epsilon.

00:48:35.160 --> 00:48:38.760 align:middle line:90%


00:48:38.760 --> 00:48:43.500 align:middle line:90%
And so you get rid of these two.

00:48:43.500 --> 00:48:45.660 align:middle line:90%
Delta is positive.

00:48:45.660 --> 00:48:50.440 align:middle line:84%
So if you have this, you would
definitely also have that

00:48:50.440 --> 00:48:53.580 align:middle line:84%
so this would imply
that-- or delta--

00:48:53.580 --> 00:48:56.460 align:middle line:84%
this here, delta square, I
guess, is positive regardless.

00:48:56.460 --> 00:49:01.020 align:middle line:84%
But you would have
that 2x delta here,

00:49:01.020 --> 00:49:03.710 align:middle line:84%
would have to be
less than epsilon.

00:49:03.710 --> 00:49:06.900 align:middle line:90%


00:49:06.900 --> 00:49:09.120 align:middle line:84%
Now I'm using the
delta is positive.

00:49:09.120 --> 00:49:12.120 align:middle line:84%
So this here would have
to be the case for all x.

00:49:12.120 --> 00:49:14.780 align:middle line:90%


00:49:14.780 --> 00:49:19.220 align:middle line:84%
But if you just let x be
delta is now supposed to be--

00:49:19.220 --> 00:49:21.700 align:middle line:84%
you're supposed to
find some delta so that

00:49:21.700 --> 00:49:23.120 align:middle line:90%
this here works for all x.

00:49:23.120 --> 00:49:25.500 align:middle line:84%
So this means that
delta is fixed.

00:49:25.500 --> 00:49:28.580 align:middle line:84%
But if now delta x becomes
incredibly large, then

00:49:28.580 --> 00:49:31.920 align:middle line:84%
of course, you don't have
this inequality anymore.

00:49:31.920 --> 00:49:36.340 align:middle line:84%
So this function is
not uniform continuous.

00:49:36.340 --> 00:49:37.100 align:middle line:90%
Yeah?

00:49:37.100 --> 00:49:38.300 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:49:38.300 --> 00:49:41.160 align:middle line:84%
TOBIAS COLDING: Because
it only helps us.

00:49:41.160 --> 00:49:47.260 align:middle line:84%
So if this here is less
than that, this is positive.

00:49:47.260 --> 00:49:52.612 align:middle line:84%
This means that this here surely
is also less than epsilon.

00:49:52.612 --> 00:49:53.950 align:middle line:90%
So that's one example.

00:49:53.950 --> 00:49:58.440 align:middle line:90%


00:49:58.440 --> 00:50:02.440 align:middle line:90%
The other example is--

00:50:02.440 --> 00:50:08.160 align:middle line:84%
and actually, let me draw a
picture to just illustrate it.

00:50:08.160 --> 00:50:10.540 align:middle line:90%
So if you take.

00:50:10.540 --> 00:50:13.840 align:middle line:84%
So again the function
roughly looks like this.

00:50:13.840 --> 00:50:16.830 align:middle line:84%
This is f of x
equal to x squared.

00:50:16.830 --> 00:50:20.920 align:middle line:90%


00:50:20.920 --> 00:50:26.360 align:middle line:84%
This meaning of that it's
uniform continuous means that

00:50:26.360 --> 00:50:32.640 align:middle line:84%
if you take some epsilon
for any given epsilon,

00:50:32.640 --> 00:50:38.240 align:middle line:84%
so if you're looking at a
interval over on the y-axis

00:50:38.240 --> 00:50:42.580 align:middle line:90%
here, so this is between--

00:50:42.580 --> 00:50:46.340 align:middle line:84%
this here is like
a epsilon interval.

00:50:46.340 --> 00:50:48.500 align:middle line:90%
And you're looking at--

00:50:48.500 --> 00:50:51.740 align:middle line:84%
so if you're looking
at some point here,

00:50:51.740 --> 00:50:54.260 align:middle line:90%
this here is this point here--

00:50:54.260 --> 00:50:57.220 align:middle line:90%
is taken to this here.

00:50:57.220 --> 00:51:01.240 align:middle line:84%
And now you want to look
at some small interval.

00:51:01.240 --> 00:51:03.560 align:middle line:84%
So that you end up
in that interval.

00:51:03.560 --> 00:51:06.940 align:middle line:84%
And the thing is that as you're
moving further and further

00:51:06.940 --> 00:51:09.780 align:middle line:84%
out this-- the length
of that interval

00:51:09.780 --> 00:51:12.200 align:middle line:84%
would have to be
smaller and smaller.

00:51:12.200 --> 00:51:14.320 align:middle line:84%
But you can't use the
same uniform size.

00:51:14.320 --> 00:51:19.300 align:middle line:84%
So that's why it's not
uniformly continuous.

00:51:19.300 --> 00:51:23.740 align:middle line:84%
The other example
I want to look at

00:51:23.740 --> 00:51:26.300 align:middle line:90%
is where you take a function--

00:51:26.300 --> 00:51:29.730 align:middle line:90%


00:51:29.730 --> 00:51:34.700 align:middle line:84%
where you're taking f of
x equal to 1 over x, and x

00:51:34.700 --> 00:51:40.800 align:middle line:84%
here is now in the
interval, from 0 to 1.

00:51:40.800 --> 00:51:45.120 align:middle line:90%
1 is included, but 0 is not.

00:51:45.120 --> 00:51:52.120 align:middle line:84%
And so there, the picture is
that this here is the function.

00:51:52.120 --> 00:51:57.680 align:middle line:84%
And so you see that as you're
getting closer, here is 1.

00:51:57.680 --> 00:52:00.800 align:middle line:84%
And as you're looking
at things closer

00:52:00.800 --> 00:52:06.460 align:middle line:84%
to 0, then even a really
small interval, the functions,

00:52:06.460 --> 00:52:10.160 align:middle line:84%
the value of the function
would deviate a lot

00:52:10.160 --> 00:52:12.700 align:middle line:90%
on even a very small interval.

00:52:12.700 --> 00:52:17.120 align:middle line:84%
So you couldn't use
the same interval size

00:52:17.120 --> 00:52:21.040 align:middle line:84%
to say that the
value of the function

00:52:21.040 --> 00:52:22.700 align:middle line:90%
is smaller than some epsilon.

00:52:22.700 --> 00:52:25.480 align:middle line:90%
So just make that precise.

00:52:25.480 --> 00:52:34.480 align:middle line:84%
If you take a sequence xn equal
to 1 over n and yn equal to 1

00:52:34.480 --> 00:52:37.820 align:middle line:90%
over 2n, then--

00:52:37.820 --> 00:52:39.010 align:middle line:90%
and you're looking at--

00:52:39.010 --> 00:52:43.900 align:middle line:90%


00:52:43.900 --> 00:52:46.340 align:middle line:84%
you're looking at
the difference,

00:52:46.340 --> 00:52:55.012 align:middle line:84%
so if you're looking at xn
minus 1, here, you have--

00:52:55.012 --> 00:52:56.720 align:middle line:84%
we don't even need to
calculate anything.

00:52:56.720 --> 00:52:58.860 align:middle line:84%
For the first thing
here, you have xn.

00:52:58.860 --> 00:53:01.220 align:middle line:90%
Here, you have yn.

00:53:01.220 --> 00:53:03.820 align:middle line:84%
So this means that the
difference between these two

00:53:03.820 --> 00:53:06.980 align:middle line:84%
is certainly bounded
by this here.

00:53:06.980 --> 00:53:09.300 align:middle line:90%
So of course, you always have--

00:53:09.300 --> 00:53:11.040 align:middle line:84%
you have actually
something much better.

00:53:11.040 --> 00:53:13.440 align:middle line:84%
But this is actually
smaller than 1 over n.

00:53:13.440 --> 00:53:16.260 align:middle line:90%


00:53:16.260 --> 00:53:21.860 align:middle line:84%
And if you're now looking at
the value of the function,

00:53:21.860 --> 00:53:25.540 align:middle line:90%
this thing here is 1 over xn.

00:53:25.540 --> 00:53:27.780 align:middle line:90%
So that's n.

00:53:27.780 --> 00:53:34.500 align:middle line:90%
And f of yn is 1 over 2n.

00:53:34.500 --> 00:53:36.280 align:middle line:90%
So this is 2n.

00:53:36.280 --> 00:53:44.680 align:middle line:84%
So this means that f of
xn minus f of yn here,

00:53:44.680 --> 00:53:50.905 align:middle line:84%
this here is equal to this
difference here, is equal to 2n.

00:53:50.905 --> 00:53:54.760 align:middle line:90%


00:53:54.760 --> 00:53:58.088 align:middle line:84%
And so you see
that you couldn't--

00:53:58.088 --> 00:54:02.440 align:middle line:84%
it's not like-- it's not--
for any given epsilon,

00:54:02.440 --> 00:54:06.560 align:middle line:84%
it doesn't work that if
these two points are,

00:54:06.560 --> 00:54:09.000 align:middle line:84%
doesn't exist a delta
so that if these two

00:54:09.000 --> 00:54:15.420 align:middle line:84%
points are delta closed, then
the images is at most epsilon.

00:54:15.420 --> 00:54:15.920 align:middle line:90%
Yeah?

00:54:15.920 --> 00:54:16.800 align:middle line:84%
AUDIENCE: I don't know
if this is too broad

00:54:16.800 --> 00:54:19.467 align:middle line:84%
of a generalization, but is that
essentially just the same thing

00:54:19.467 --> 00:54:21.558 align:middle line:84%
as saying that the
slope is bounded.

00:54:21.558 --> 00:54:23.100 align:middle line:84%
TOBIAS COLDING:
Yeah, it's like that.

00:54:23.100 --> 00:54:24.740 align:middle line:90%
I mean, it's sort of like that.

00:54:24.740 --> 00:54:25.640 align:middle line:90%
I mean, it's not--

00:54:25.640 --> 00:54:31.240 align:middle line:84%
I mean, uniform continuity
doesn't require--

00:54:31.240 --> 00:54:35.566 align:middle line:84%
I mean, sort of like that but
not exactly, because uniformly--

00:54:35.566 --> 00:54:39.760 align:middle line:84%
slope is something about
being differentiable,

00:54:39.760 --> 00:54:44.020 align:middle line:84%
and you can have a uniformly
continuous function

00:54:44.020 --> 00:54:45.480 align:middle line:90%
that is not differentiable.

00:54:45.480 --> 00:54:48.180 align:middle line:90%


00:54:48.180 --> 00:54:50.080 align:middle line:90%
But it's definitely related.

00:54:50.080 --> 00:54:50.580 align:middle line:90%
Yeah.

00:54:50.580 --> 00:54:54.680 align:middle line:90%


00:54:54.680 --> 00:54:59.860 align:middle line:84%
So anyway, so uniform again
means that for a given delta--

00:54:59.860 --> 00:55:05.300 align:middle line:84%
for a given epsilon, you
can use the same delta for--

00:55:05.300 --> 00:55:06.920 align:middle line:90%
at all points.

00:55:06.920 --> 00:55:09.060 align:middle line:84%
Otherwise, for
continuity, you are always

00:55:09.060 --> 00:55:10.280 align:middle line:90%
fixing one of the points.

00:55:10.280 --> 00:55:13.580 align:middle line:84%
And then you were
looking at other points

00:55:13.580 --> 00:55:14.650 align:middle line:90%
close to that point.

00:55:14.650 --> 00:55:17.680 align:middle line:90%


00:55:17.680 --> 00:55:22.420 align:middle line:84%
So now the first thing
that we want to prove is--

00:55:22.420 --> 00:55:24.980 align:middle line:84%
so we want to prove
that-- so we want--

00:55:24.980 --> 00:55:28.600 align:middle line:84%
our goal here is to
prove this theorem.

00:55:28.600 --> 00:55:34.800 align:middle line:84%
Let's say that if you have a
continuous function on a closed

00:55:34.800 --> 00:55:38.520 align:middle line:84%
interval-- so a closed bounded
interval, compact interval,

00:55:38.520 --> 00:55:43.420 align:middle line:84%
from a to b, then the function
is actually Riemann integrable.

00:55:43.420 --> 00:55:46.280 align:middle line:90%


00:55:46.280 --> 00:55:49.840 align:middle line:84%
And to prove that, we
need again this notion

00:55:49.840 --> 00:55:52.280 align:middle line:90%
of uniformly continuous.

00:55:52.280 --> 00:55:54.000 align:middle line:84%
And so the first
thing we want to prove

00:55:54.000 --> 00:56:00.720 align:middle line:84%
is we want to upgrade continuity
to uniform continuity.

00:56:00.720 --> 00:56:02.440 align:middle line:90%
So what does that mean?

00:56:02.440 --> 00:56:08.280 align:middle line:84%
So it means that if you take a
function on a compact interval

00:56:08.280 --> 00:56:10.360 align:middle line:90%
like this--

00:56:10.360 --> 00:56:17.560 align:middle line:84%
so if you have a
continuous function,

00:56:17.560 --> 00:56:24.140 align:middle line:90%
then f is uniformly continuous.

00:56:24.140 --> 00:56:31.780 align:middle line:90%


00:56:31.780 --> 00:56:35.540 align:middle line:84%
So if the interval
actually is compact,

00:56:35.540 --> 00:56:37.940 align:middle line:84%
then the-- and then
a continuous function

00:56:37.940 --> 00:56:39.740 align:middle line:90%
is uniformly continuous.

00:56:39.740 --> 00:56:42.380 align:middle line:84%
Let's just look at the
two examples we had.

00:56:42.380 --> 00:56:44.180 align:middle line:90%
We had two examples.

00:56:44.180 --> 00:56:49.100 align:middle line:84%
In the first one, f of x
was equal to x squared.

00:56:49.100 --> 00:56:51.140 align:middle line:90%
But it was defined on all of--

00:56:51.140 --> 00:56:52.980 align:middle line:90%
it was continuous of course.

00:56:52.980 --> 00:56:56.520 align:middle line:84%
But the thing is it wasn't
on a compact interval.

00:56:56.520 --> 00:56:58.020 align:middle line:90%
It was on all of R.

00:56:58.020 --> 00:57:02.260 align:middle line:84%
In the second, this function
here is also continuous,

00:57:02.260 --> 00:57:06.240 align:middle line:84%
but it's not a compact interval,
because 0 is not included.

00:57:06.240 --> 00:57:07.740 align:middle line:90%
Yeah?

00:57:07.740 --> 00:57:11.900 align:middle line:84%
AUDIENCE: Compact in
the sense of the before?

00:57:11.900 --> 00:57:16.140 align:middle line:84%
TOBIAS COLDING:
So remember that--

00:57:16.140 --> 00:57:24.300 align:middle line:84%
so compact, you can
either think about it as--

00:57:24.300 --> 00:57:28.560 align:middle line:84%
we talked about compact
metric spaces or compact sets.

00:57:28.560 --> 00:57:35.880 align:middle line:84%
But for a subset
of the real line,

00:57:35.880 --> 00:57:41.720 align:middle line:84%
compact is the same as saying
that it's bounded and closed.

00:57:41.720 --> 00:57:46.760 align:middle line:84%
And so this thing here, when I'm
writing it like this, a and b

00:57:46.760 --> 00:57:48.160 align:middle line:90%
are real numbers.

00:57:48.160 --> 00:57:49.620 align:middle line:90%
And they are both included.

00:57:49.620 --> 00:57:54.520 align:middle line:84%
And again, if it was this here,
then one end point is included,

00:57:54.520 --> 00:57:55.700 align:middle line:90%
but the other one is not.

00:57:55.700 --> 00:57:57.500 align:middle line:90%
So it's not actually compact.

00:57:57.500 --> 00:58:00.306 align:middle line:90%


00:58:00.306 --> 00:58:04.460 align:middle line:84%
And so if the function
here is continuous,

00:58:04.460 --> 00:58:06.100 align:middle line:90%
then it's uniformly continuous.

00:58:06.100 --> 00:58:09.120 align:middle line:90%
So that's what we want to prove.

00:58:09.120 --> 00:58:16.160 align:middle line:84%
Again, if the interval is
compact, then actually,

00:58:16.160 --> 00:58:19.760 align:middle line:90%
you get the stronger continuity.

00:58:19.760 --> 00:58:21.500 align:middle line:90%
So now let's try to prove that.

00:58:21.500 --> 00:58:24.200 align:middle line:90%


00:58:24.200 --> 00:58:24.950 align:middle line:90%
Suppose not.

00:58:24.950 --> 00:58:30.060 align:middle line:90%


00:58:30.060 --> 00:58:33.020 align:middle line:84%
If this here was not
the case, then it

00:58:33.020 --> 00:58:36.260 align:middle line:84%
meant that-- so we take the
negation of the definition

00:58:36.260 --> 00:58:38.180 align:middle line:90%
of uniform continuity.

00:58:38.180 --> 00:58:41.460 align:middle line:84%
So this means that
there exists an epsilon.

00:58:41.460 --> 00:58:43.140 align:middle line:90%
So suppose not.

00:58:43.140 --> 00:58:52.580 align:middle line:84%
Then there exists
epsilon greater than 0

00:58:52.580 --> 00:59:02.260 align:middle line:84%
such that no delta would
work, such that for all delta

00:59:02.260 --> 00:59:07.300 align:middle line:84%
greater than 0,
there exists x comma

00:59:07.300 --> 00:59:19.060 align:middle line:84%
y so that the difference between
these two is less than delta

00:59:19.060 --> 00:59:29.880 align:middle line:84%
and the images is bigger
or equal to epsilon.

00:59:29.880 --> 00:59:33.880 align:middle line:84%
That's just the negation
of the statement.

00:59:33.880 --> 00:59:37.380 align:middle line:84%
But now we choose a
sequence of delta.

00:59:37.380 --> 00:59:39.340 align:middle line:90%
And so we do this--

00:59:39.340 --> 00:59:41.120 align:middle line:90%
so this is for all delta.

00:59:41.120 --> 00:59:43.800 align:middle line:84%
So we should take
advantage of that.

00:59:43.800 --> 00:59:48.080 align:middle line:84%
We look at a sequence
of such delta.

00:59:48.080 --> 00:59:51.820 align:middle line:84%
So we look at a
sequence of delta.

00:59:51.820 --> 01:00:03.280 align:middle line:84%
And this is where we use this
for delta equal to 1 over n.

01:00:03.280 --> 01:00:12.200 align:middle line:84%
So n here is, again, a positive
natural number, like that.

01:00:12.200 --> 01:00:21.120 align:middle line:84%
So this means that we-- for each
n, you have xn, and you have yn.

01:00:21.120 --> 01:00:25.020 align:middle line:84%
They're both in the
interval from a to b.

01:00:25.020 --> 01:00:31.120 align:middle line:84%
And you have that xn minus
yn is less than 1 over n.

01:00:31.120 --> 01:00:39.820 align:middle line:84%
And you have that the
images f of xn minus f of yn

01:00:39.820 --> 01:00:42.380 align:middle line:90%
is bigger or equal to epsilon.

01:00:42.380 --> 01:00:44.960 align:middle line:84%
Epsilon was positive,
strictly positive.

01:00:44.960 --> 01:00:47.860 align:middle line:90%


01:00:47.860 --> 01:00:51.100 align:middle line:84%
But this means--
so now we have xn.

01:00:51.100 --> 01:00:53.540 align:middle line:90%
So these are in this interval.

01:00:53.540 --> 01:00:57.440 align:middle line:84%
So this means that we can find
a subsequence by compactness.

01:00:57.440 --> 01:01:02.620 align:middle line:84%
We can find of the
Bolzano-Weierstrass theorem.

01:01:02.620 --> 01:01:07.900 align:middle line:84%
We have a subsequence
that converges to some x.

01:01:07.900 --> 01:01:12.780 align:middle line:84%
This is just a
subsequence of these xn's.

01:01:12.780 --> 01:01:16.420 align:middle line:90%
But now you can just look at--

01:01:16.420 --> 01:01:19.700 align:middle line:84%
so now, if you're looking at
the corresponding subsequence

01:01:19.700 --> 01:01:29.120 align:middle line:84%
of the yn's, so you
have that yn k minus x,

01:01:29.120 --> 01:01:32.160 align:middle line:84%
this thing here is
less than or equal to--

01:01:32.160 --> 01:01:35.400 align:middle line:84%
by the triangle inequality,
this is less than or equal

01:01:35.400 --> 01:01:46.600 align:middle line:84%
to yn k minus xn k
plus xn k minus x.

01:01:46.600 --> 01:01:50.240 align:middle line:90%


01:01:50.240 --> 01:01:54.840 align:middle line:84%
And we have that this thing
here, this here, was less than 1

01:01:54.840 --> 01:01:56.400 align:middle line:90%
over n.

01:01:56.400 --> 01:02:01.320 align:middle line:90%
And we have plus this here.

01:02:01.320 --> 01:02:03.680 align:middle line:84%
But this thing here
is actually over nk.

01:02:03.680 --> 01:02:04.455 align:middle line:90%
Sorry.

01:02:04.455 --> 01:02:04.955 align:middle line:90%
nk.

01:02:04.955 --> 01:02:08.560 align:middle line:90%


01:02:08.560 --> 01:02:12.080 align:middle line:84%
But you have that this
thing here, this here,

01:02:12.080 --> 01:02:13.940 align:middle line:90%
this subsequence go to x.

01:02:13.940 --> 01:02:15.880 align:middle line:90%
So this here goes to 0.

01:02:15.880 --> 01:02:18.280 align:middle line:90%
And this here goes to 0.

01:02:18.280 --> 01:02:25.020 align:middle line:84%
So this means that these yn k
actually also converge to x.

01:02:25.020 --> 01:02:29.740 align:middle line:90%


01:02:29.740 --> 01:02:31.500 align:middle line:90%
But now you have--

01:02:31.500 --> 01:02:38.620 align:middle line:84%
so you have this, and you
have that yn k converge to x.

01:02:38.620 --> 01:02:42.220 align:middle line:84%
So now this here together
with that the function

01:02:42.220 --> 01:02:52.740 align:middle line:84%
is continuous means that f
xn k converges to f of x.

01:02:52.740 --> 01:03:02.660 align:middle line:84%
And you have that f yn k
converge to also f of x.

01:03:02.660 --> 01:03:08.800 align:middle line:84%
This is just because
since f is continuous.

01:03:08.800 --> 01:03:14.860 align:middle line:90%


01:03:14.860 --> 01:03:18.760 align:middle line:90%
But now you just look at--

01:03:18.760 --> 01:03:22.460 align:middle line:90%
now you just look at the--

01:03:22.460 --> 01:03:24.600 align:middle line:90%
so now you have that--

01:03:24.600 --> 01:03:31.360 align:middle line:84%
so again, f xn k
converges to f of x.

01:03:31.360 --> 01:03:39.360 align:middle line:84%
And this here
converges to f of x.

01:03:39.360 --> 01:03:46.820 align:middle line:84%
But I claim that this here-- but
we also have that f xn k minus f

01:03:46.820 --> 01:03:49.640 align:middle line:90%
yn k--

01:03:49.640 --> 01:03:55.920 align:middle line:84%
we have that this thing here
is bigger or equal to epsilon.

01:03:55.920 --> 01:03:58.680 align:middle line:84%
But then you can't
have-- if this here--

01:03:58.680 --> 01:04:00.880 align:middle line:84%
this here is clearly
a contradiction,

01:04:00.880 --> 01:04:03.080 align:middle line:84%
because if this
converges to that,

01:04:03.080 --> 01:04:05.040 align:middle line:84%
this here converges
to the same thing.

01:04:05.040 --> 01:04:09.080 align:middle line:84%
Then these two things here must
get closer and closer together.

01:04:09.080 --> 01:04:12.240 align:middle line:84%
But they're saying that they
are some fixed thing apart.

01:04:12.240 --> 01:04:16.400 align:middle line:84%
So that's clearly
a contradiction.

01:04:16.400 --> 01:04:19.400 align:middle line:84%
So this proof that
if it is continuous,

01:04:19.400 --> 01:04:21.480 align:middle line:90%
it's also uniformly continuous.

01:04:21.480 --> 01:04:24.712 align:middle line:90%


01:04:24.712 --> 01:04:32.500 align:middle line:84%
So now let's use this to prove
that if you take a function-- so

01:04:32.500 --> 01:04:35.980 align:middle line:84%
now we are ready to get
back to the theorem that

01:04:35.980 --> 01:04:39.280 align:middle line:90%
was our main interest.

01:04:39.280 --> 01:04:41.420 align:middle line:84%
So you see also in
the two examples

01:04:41.420 --> 01:04:45.820 align:middle line:84%
I had, it was no accident,
again, that in the first one,

01:04:45.820 --> 01:04:47.900 align:middle line:90%
the interval was unbounded.

01:04:47.900 --> 01:04:50.980 align:middle line:84%
In the second one, the
interval was bounded,

01:04:50.980 --> 01:04:52.800 align:middle line:90%
but it was not closed.

01:04:52.800 --> 01:04:55.660 align:middle line:84%
And so either case, it
failed to be compact.

01:04:55.660 --> 01:04:58.460 align:middle line:84%
And that was why you could
have a continuous function that

01:04:58.460 --> 01:05:02.100 align:middle line:90%
wasn't uniformly continuous.

01:05:02.100 --> 01:05:05.580 align:middle line:84%
And so now we get
back to this theorem.

01:05:05.580 --> 01:05:07.840 align:middle line:90%
And so the theorem again is--

01:05:07.840 --> 01:05:10.100 align:middle line:84%
the theorem gives you
this nice criterion

01:05:10.100 --> 01:05:12.960 align:middle line:84%
for when a function
is Riemann integrable.

01:05:12.960 --> 01:05:26.100 align:middle line:84%
So if f here is continuous, then
f here is Riemann integrable.

01:05:26.100 --> 01:05:29.640 align:middle line:90%


01:05:29.640 --> 01:05:31.680 align:middle line:84%
And again, this here
should be-- it's

01:05:31.680 --> 01:05:37.120 align:middle line:84%
understood that it's
f here is defined

01:05:37.120 --> 01:05:40.510 align:middle line:84%
on an integral
like this integral.

01:05:40.510 --> 01:05:46.264 align:middle line:90%


01:05:46.264 --> 01:05:48.420 align:middle line:84%
And so now the
proof is like this.

01:05:48.420 --> 01:05:55.880 align:middle line:90%


01:05:55.880 --> 01:06:06.480 align:middle line:90%
We showed earlier that we only--

01:06:06.480 --> 01:06:22.700 align:middle line:84%
that we need only show that a
given epsilon greater than 0,

01:06:22.700 --> 01:06:32.060 align:middle line:84%
there exists a
partition so that if--

01:06:32.060 --> 01:06:42.620 align:middle line:84%
such that the upper sum minus
the lower sum for this partition

01:06:42.620 --> 01:06:45.160 align:middle line:84%
is less than epsilon,
that's all we need.

01:06:45.160 --> 01:06:48.840 align:middle line:84%
We need to prove that
for each epsilon,

01:06:48.840 --> 01:06:53.140 align:middle line:84%
there exists a partition so
that the upper and the lower sum

01:06:53.140 --> 01:06:54.820 align:middle line:84%
are within epsilon
of each other.

01:06:54.820 --> 01:07:04.740 align:middle line:90%


01:07:04.740 --> 01:07:07.010 align:middle line:90%
So now using that--

01:07:07.010 --> 01:07:10.300 align:middle line:90%


01:07:10.300 --> 01:07:18.510 align:middle line:84%
so now-- so given
epsilon greater than 0--

01:07:18.510 --> 01:07:25.090 align:middle line:84%
since f is uniformly
continuous--

01:07:25.090 --> 01:07:26.790 align:middle line:84%
so actually, we're
proving that f

01:07:26.790 --> 01:07:29.970 align:middle line:84%
is continuous on this
compact interval.

01:07:29.970 --> 01:07:31.890 align:middle line:90%
It's also uniformly continuous.

01:07:31.890 --> 01:07:36.830 align:middle line:90%


01:07:36.830 --> 01:07:40.750 align:middle line:84%
Since f is uniformly
continuous, it

01:07:40.750 --> 01:07:48.710 align:middle line:84%
means that there exists
delta greater than 0 such

01:07:48.710 --> 01:08:03.790 align:middle line:84%
that if x minus y is
less than delta, then--

01:08:03.790 --> 01:08:06.860 align:middle line:84%
let's say delta is, let's
say, less than 2 delta.

01:08:06.860 --> 01:08:13.290 align:middle line:90%


01:08:13.290 --> 01:08:23.980 align:middle line:84%
Then the images-- then f of
x minus f of y is now smaller

01:08:23.980 --> 01:08:24.480 align:middle line:90%
than--

01:08:24.480 --> 01:08:27.330 align:middle line:90%


01:08:27.330 --> 01:08:30.649 align:middle line:84%
and then instead of epsilon,
I'm using epsilon divided

01:08:30.649 --> 01:08:32.630 align:middle line:90%
by the length of the interval.

01:08:32.630 --> 01:08:33.130 align:middle line:90%
Sorry.

01:08:33.130 --> 01:08:34.739 align:middle line:90%
And this would be strictly less.

01:08:34.739 --> 01:08:40.409 align:middle line:90%


01:08:40.409 --> 01:08:55.010 align:middle line:84%
So now we let P here
be a partition where

01:08:55.010 --> 01:09:03.529 align:middle line:84%
each delta xi, each
little interval here,

01:09:03.529 --> 01:09:07.330 align:middle line:90%
is equal to delta.

01:09:07.330 --> 01:09:11.050 align:middle line:84%
You just have to be, say,
less than or equal to delta,

01:09:11.050 --> 01:09:12.820 align:middle line:84%
but couldn't make
it equal to delta.

01:09:12.820 --> 01:09:19.750 align:middle line:90%


01:09:19.750 --> 01:09:22.470 align:middle line:90%
So now if this is the case--

01:09:22.470 --> 01:09:25.470 align:middle line:90%
but then we have--

01:09:25.470 --> 01:09:28.529 align:middle line:84%
so now if we're looking at one
of these small intervals here--

01:09:28.529 --> 01:09:37.630 align:middle line:90%


01:09:37.630 --> 01:09:40.670 align:middle line:84%
so now, if you're looking at one
of these small intervals here,

01:09:40.670 --> 01:09:43.350 align:middle line:90%
here, you have xi minus 1.

01:09:43.350 --> 01:09:45.750 align:middle line:90%
And here, you have xi.

01:09:45.750 --> 01:09:50.330 align:middle line:84%
So if you're now looking at
one of these small interval,

01:09:50.330 --> 01:09:54.630 align:middle line:84%
then you have that the
function is continuous here.

01:09:54.630 --> 01:10:00.950 align:middle line:84%
So if you're looking at
the sup of this interval--

01:10:00.950 --> 01:10:07.170 align:middle line:84%
so the sup on this
interval, this

01:10:07.170 --> 01:10:11.410 align:middle line:84%
is the sup of one of these
intervals here, of f.

01:10:11.410 --> 01:10:15.290 align:middle line:84%
The sup here, this is--
it's actually achieved

01:10:15.290 --> 01:10:16.970 align:middle line:90%
by the extreme value theorem.

01:10:16.970 --> 01:10:23.610 align:middle line:84%
This is achieved at
some point if, say, ya--

01:10:23.610 --> 01:10:26.436 align:middle line:90%


01:10:26.436 --> 01:10:28.650 align:middle line:90%
y and maybe this--

01:10:28.650 --> 01:10:33.570 align:middle line:90%
my-- let's just say y.

01:10:33.570 --> 01:10:37.810 align:middle line:84%
And likewise, on
this little interval,

01:10:37.810 --> 01:10:41.940 align:middle line:90%
the inf here is also achieved.

01:10:41.940 --> 01:10:45.050 align:middle line:90%


01:10:45.050 --> 01:10:47.160 align:middle line:90%
And let's call that y star.

01:10:47.160 --> 01:10:51.290 align:middle line:90%


01:10:51.290 --> 01:10:53.470 align:middle line:90%
So the infimum is also achieved.

01:10:53.470 --> 01:10:58.450 align:middle line:84%
And that's achieved
at some y star.

01:10:58.450 --> 01:11:01.110 align:middle line:84%
But now this interval
here have length.

01:11:01.110 --> 01:11:09.150 align:middle line:90%
This here is at most delta.

01:11:09.150 --> 01:11:11.230 align:middle line:84%
So this means that
the difference

01:11:11.230 --> 01:11:14.320 align:middle line:84%
in the value of
any such two points

01:11:14.320 --> 01:11:17.850 align:middle line:84%
so they are actually less--
strictly less than 2 delta.

01:11:17.850 --> 01:11:23.350 align:middle line:84%
So that means that the value
differ at most like this.

01:11:23.350 --> 01:11:28.150 align:middle line:84%
So it means that f of y,
which is actually the sup--

01:11:28.150 --> 01:11:31.510 align:middle line:84%
so this here-- so
since it's a sup,

01:11:31.510 --> 01:11:32.710 align:middle line:90%
I don't even need this here.

01:11:32.710 --> 01:11:33.650 align:middle line:90%
It's larger than that.

01:11:33.650 --> 01:11:36.410 align:middle line:84%
So I don't need to even take
absolute value sign on it.

01:11:36.410 --> 01:11:42.230 align:middle line:84%
But it means that the difference
here is now less than epsilon

01:11:42.230 --> 01:11:43.530 align:middle line:90%
over b minus a.

01:11:43.530 --> 01:11:48.038 align:middle line:90%


01:11:48.038 --> 01:11:54.710 align:middle line:84%
And so this here again is M
of i minus m of i, like that.

01:11:54.710 --> 01:11:57.550 align:middle line:90%


01:11:57.550 --> 01:12:01.850 align:middle line:84%
And so now you see that-- so now
let's look at the contribution.

01:12:01.850 --> 01:12:08.530 align:middle line:84%
So for the upper sum, we have
that this here is this capital

01:12:08.530 --> 01:12:11.850 align:middle line:90%
Mi and then delta xi.

01:12:11.850 --> 01:12:18.890 align:middle line:84%
For the lower sum, we have that
this is the sum of the small mi

01:12:18.890 --> 01:12:19.810 align:middle line:90%
delta xi.

01:12:19.810 --> 01:12:22.330 align:middle line:90%


01:12:22.330 --> 01:12:26.890 align:middle line:84%
And so now let's look at the
difference between these two.

01:12:26.890 --> 01:12:31.450 align:middle line:84%
That's the one we need to prove
is strictly less than epsilon.

01:12:31.450 --> 01:12:40.850 align:middle line:84%
So if you're looking at
this U f of P minus L f P,

01:12:40.850 --> 01:12:43.650 align:middle line:90%
this here is now the sum here.

01:12:43.650 --> 01:12:46.530 align:middle line:84%
And then it's-- so
you're summing--

01:12:46.530 --> 01:12:47.830 align:middle line:90%
this thing is the same.

01:12:47.830 --> 01:12:50.690 align:middle line:84%
So you can write the sum
here-- the difference.

01:12:50.690 --> 01:12:53.090 align:middle line:90%
Well, let's just write it first.

01:12:53.090 --> 01:12:55.730 align:middle line:90%
Just write it out like this.

01:12:55.730 --> 01:12:57.090 align:middle line:90%
But then now I can--

01:12:57.090 --> 01:12:59.450 align:middle line:84%
once I have written
it out like this,

01:12:59.450 --> 01:13:05.230 align:middle line:84%
see that I can write this thing
here is the sum of capital Mi

01:13:05.230 --> 01:13:09.070 align:middle line:90%
minus little mi times delta xi.

01:13:09.070 --> 01:13:12.470 align:middle line:90%


01:13:12.470 --> 01:13:15.350 align:middle line:84%
And this thing here
I already figured--

01:13:15.350 --> 01:13:16.730 align:middle line:90%
I already have a bound.

01:13:16.730 --> 01:13:19.350 align:middle line:84%
So this is each of
these is less than this.

01:13:19.350 --> 01:13:21.290 align:middle line:90%
So I just write in that bound.

01:13:21.290 --> 01:13:24.470 align:middle line:90%
So this here is less than--

01:13:24.470 --> 01:13:29.110 align:middle line:84%
and then the sum here,
epsilon over b minus a--

01:13:29.110 --> 01:13:32.990 align:middle line:90%
and then like this.

01:13:32.990 --> 01:13:34.770 align:middle line:90%
But now this is just a constant.

01:13:34.770 --> 01:13:37.820 align:middle line:84%
So this just-- I can just take
this out of the summation sign.

01:13:37.820 --> 01:13:41.230 align:middle line:90%


01:13:41.230 --> 01:13:42.990 align:middle line:90%
And so I get this thing.

01:13:42.990 --> 01:13:45.570 align:middle line:84%
So this is the sum of
the small interval.

01:13:45.570 --> 01:13:49.070 align:middle line:84%
But the sum of the small
interval is the whole interval.

01:13:49.070 --> 01:13:54.890 align:middle line:84%
So this is epsilon b
minus a times b minus a.

01:13:54.890 --> 01:13:58.030 align:middle line:90%
And so this here is epsilon.

01:13:58.030 --> 01:13:59.950 align:middle line:90%
And so you have exactly--

01:13:59.950 --> 01:14:06.510 align:middle line:84%
it's a-- this difference here
is strictly bounded by epsilon.

01:14:06.510 --> 01:14:13.230 align:middle line:84%
So let's prove that if the
function is continuous,

01:14:13.230 --> 01:14:16.090 align:middle line:84%
then it is on a
compact interval.

01:14:16.090 --> 01:14:19.090 align:middle line:90%
Then it is Riemann integral.

01:14:19.090 --> 01:14:23.330 align:middle line:84%
And now let me at least state
some of the basic formulas

01:14:23.330 --> 01:14:25.990 align:middle line:90%
for Riemann integrals.

01:14:25.990 --> 01:14:29.410 align:middle line:90%


01:14:29.410 --> 01:14:33.320 align:middle line:84%
And so maybe we might prove
some of these next time.

01:14:33.320 --> 01:14:42.610 align:middle line:90%


01:14:42.610 --> 01:14:47.190 align:middle line:84%
So the first one is
that if you take--

01:14:47.190 --> 01:14:49.670 align:middle line:90%
so you have this theorem here.

01:14:49.670 --> 01:14:52.970 align:middle line:90%


01:14:52.970 --> 01:14:54.770 align:middle line:84%
The first one is--
so suppose you

01:14:54.770 --> 01:14:58.450 align:middle line:84%
take a function that
is Riemann integrable

01:14:58.450 --> 01:15:01.910 align:middle line:90%
on some integral like this.

01:15:01.910 --> 01:15:04.630 align:middle line:90%
And c here is constant.

01:15:04.630 --> 01:15:07.350 align:middle line:90%
It's a real number.

01:15:07.350 --> 01:15:13.210 align:middle line:84%
Then this constant times f
is also Riemann integrable.

01:15:13.210 --> 01:15:16.910 align:middle line:90%


01:15:16.910 --> 01:15:20.470 align:middle line:84%
And the integral
of this function

01:15:20.470 --> 01:15:29.310 align:middle line:84%
here is equal to c times the
integral, Riemann integral,

01:15:29.310 --> 01:15:30.670 align:middle line:90%
like that.

01:15:30.670 --> 01:15:31.970 align:middle line:90%
So that's the first one.

01:15:31.970 --> 01:15:34.950 align:middle line:90%


01:15:34.950 --> 01:15:45.270 align:middle line:84%
The next one is that if you
take two functions, f and g.

01:15:45.270 --> 01:15:52.390 align:middle line:84%
Suppose you take two
functions, f and g,

01:15:52.390 --> 01:15:53.520 align:middle line:90%
that are Riemann integral.

01:15:53.520 --> 01:15:59.090 align:middle line:90%


01:15:59.090 --> 01:16:02.770 align:middle line:84%
And now let's look
at the function that

01:16:02.770 --> 01:16:05.090 align:middle line:90%
is the sum of these two.

01:16:05.090 --> 01:16:07.050 align:middle line:90%
So this is a new function.

01:16:07.050 --> 01:16:10.870 align:middle line:84%
And the claim is that this here
is also Riemann integrable.

01:16:10.870 --> 01:16:15.170 align:middle line:90%


01:16:15.170 --> 01:16:26.910 align:middle line:84%
And the integral of the sum
is the sum of the integrals.

01:16:26.910 --> 01:16:27.410 align:middle line:90%
Oops.

01:16:27.410 --> 01:16:37.330 align:middle line:90%


01:16:37.330 --> 01:16:40.650 align:middle line:90%
That's the second one.

01:16:40.650 --> 01:16:43.930 align:middle line:90%
And the third one is that--

01:16:43.930 --> 01:16:51.130 align:middle line:84%
so the third one is that if you
take a function-- two functions,

01:16:51.130 --> 01:16:53.630 align:middle line:84%
again, they are both
Riemann integrable.

01:16:53.630 --> 01:16:56.150 align:middle line:90%


01:16:56.150 --> 01:17:00.590 align:middle line:84%
And you have that f here
is less than or equal to g.

01:17:00.590 --> 01:17:05.710 align:middle line:84%
Then the Riemann
integral of f is

01:17:05.710 --> 01:17:12.470 align:middle line:84%
less than or equal to the
Riemann integral of g,

01:17:12.470 --> 01:17:13.090 align:middle line:90%
like that.

01:17:13.090 --> 01:17:15.790 align:middle line:90%


01:17:15.790 --> 01:17:21.710 align:middle line:90%
And the fourth rule is that--

01:17:21.710 --> 01:17:23.990 align:middle line:84%
the fourth rule is a
little bit different.

01:17:23.990 --> 01:17:28.170 align:middle line:84%
So this is if you
split the integral.

01:17:28.170 --> 01:17:31.394 align:middle line:90%


01:17:31.394 --> 01:17:35.810 align:middle line:90%
So the fourth rule is like this.

01:17:35.810 --> 01:17:38.650 align:middle line:84%
Again, I will prove some
of them, not all of them,

01:17:38.650 --> 01:17:42.490 align:middle line:84%
but I'll prove some of them
next time but not all of them.

01:17:42.490 --> 01:17:45.190 align:middle line:84%
I won't prove the
first one for sure.

01:17:45.190 --> 01:17:48.610 align:middle line:84%
So the fourth is
that if you take--

01:17:48.610 --> 01:17:53.670 align:middle line:84%
so imagine-- so you have this
integral here from a to b.

01:17:53.670 --> 01:17:56.902 align:middle line:84%
But imagine that--
so here, you have a.

01:17:56.902 --> 01:17:59.010 align:middle line:90%
Here, you have b.

01:17:59.010 --> 01:18:04.650 align:middle line:84%
Imagine that c is somewhere
in between a and b.

01:18:04.650 --> 01:18:08.450 align:middle line:84%
And suppose that you have
a function that is Riemann

01:18:08.450 --> 01:18:13.010 align:middle line:90%
integrable on this interval.

01:18:13.010 --> 01:18:18.010 align:middle line:84%
Then the claim is that then,
if you take the function

01:18:18.010 --> 01:18:23.730 align:middle line:84%
and you restrict it to either of
this interval or that interval,

01:18:23.730 --> 01:18:25.510 align:middle line:90%
it's still Riemann integrable.

01:18:25.510 --> 01:18:31.610 align:middle line:90%


01:18:31.610 --> 01:18:36.050 align:middle line:90%
And f here is also in--

01:18:36.050 --> 01:18:37.350 align:middle line:90%
from c to b.

01:18:37.350 --> 01:18:40.130 align:middle line:90%


01:18:40.130 --> 01:18:45.330 align:middle line:84%
And the claim is that
the Riemann integral

01:18:45.330 --> 01:18:56.790 align:middle line:84%
on the original integral is the
sum of the Riemann integral,

01:18:56.790 --> 01:18:58.775 align:middle line:90%
like that.

01:18:58.775 --> 01:19:03.390 align:middle line:84%
And so if you think about it in
terms of area below the graph,

01:19:03.390 --> 01:19:06.510 align:middle line:84%
if you take a
function like this,

01:19:06.510 --> 01:19:10.270 align:middle line:84%
if this here was-- if
this here was c, then

01:19:10.270 --> 01:19:14.150 align:middle line:84%
the area below the
graph here, I guess

01:19:14.150 --> 01:19:16.490 align:middle line:84%
this here would be sign
area below the graph.

01:19:16.490 --> 01:19:19.190 align:middle line:84%
But if you just took the
area below the function

01:19:19.190 --> 01:19:22.390 align:middle line:84%
was actually positive and
you think about the Riemann

01:19:22.390 --> 01:19:26.565 align:middle line:84%
integral as the area below
the graph, if this here is c,

01:19:26.565 --> 01:19:31.990 align:middle line:84%
this here is a, this here
is b, then this area here

01:19:31.990 --> 01:19:33.990 align:middle line:90%
plus this area is--

01:19:33.990 --> 01:19:38.370 align:middle line:84%
the sum of these two is the
sum underneath the whole graph.

01:19:38.370 --> 01:19:40.020 align:middle line:90%
So it makes sense.

01:19:40.020 --> 01:19:43.430 align:middle line:90%


01:19:43.430 --> 01:19:44.610 align:middle line:90%
Any questions?

01:19:44.610 --> 01:19:47.190 align:middle line:90%


01:19:47.190 --> 01:19:47.850 align:middle line:90%
OK, great.

01:19:47.850 --> 01:19:49.980 align:middle line:90%
See you next time.

01:19:49.980 --> 01:19:52.000 align:middle line:90%