WEBVTT

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[SQUEAKING]

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[RUSTLING]

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[CLICKING]

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PROFESSOR: OK, so last time,
we discussed orthonormal bases.

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And then we considered
the concrete question

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of the complex exponentials
being an orthonormal basis

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for L2 of minus pi to pi,
that Fourier series actually

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converge to an L2
function in the L2 norm.

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So now, we're going to go
back to a general discussion

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of Hilbert space.

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This is kind of the way
the rest of the course,

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will be some general
theory followed

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by some concrete
applications scattered in,

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concrete in the
sense that it just

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won't be about general Hilbert
spaces, but about maybe

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specific operators, specific
problems we're trying to solve.

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Now, we're going to
discuss length minimizers.

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And what do I mean by that?

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I mean by the
following, is if I have

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a closed subspace of a Hilbert
space, then I could define--

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of course, so way back
when, we could then

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define a norm on H modulo,
this closed Hilbert

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space, and the norm on that is
the infimum of the norm of v

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minus w, where w, little w, is
in the linear subspace capital

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W.

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Now, a natural question
is, is that infimum,

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is that minimum, that minimal
distance actually achieved

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by some element in the subspace?

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Now, the answer
is, in fact, yes.

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And it's, in fact,
true for a larger

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class of subsets of Hilbert
spaces than closed subspaces.

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So we have the following--

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suppose C is a subset
of a Hilbert space--

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of a Hilbert space H such
that three conditions hold.

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The silliest-- C is
non-empty, C is closed.

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And the final is that C
is what's called convex.

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This means the following,
that if v1 and v2 are

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in the subset C and t
is in 0, 1, then tv 1

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plus 1 minus tv2 is in C.
So another way of stating

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this last condition is that
for any two elements in C,

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the line segment from v1
to v2 is contained in C.

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So this is nothing but
an element on the line

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segment joining v1 to v2.

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So here, we have what would
look like a convex set C.

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And for every v1,
v2, it's convex,

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meaning the line segment
joining them is in there.

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So you wouldn't have--

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let's say you wouldn't have--

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so this is convex.

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And so for example, something
like this picture is not convex

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because I could take
two elements-- v1, v2--

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here and the line segment
does not stay in the set C.

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All right, so if we assume that
we have a non-empty, closed,

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and convex subset of
a Hilbert space H,

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then there exists a unique
element v in C such that--

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or I should say--

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yeah, v in C such that v
is equal to the minimum

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of the length of u in C.

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Now, we'll see, when
we apply this theorem,

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how such C's pop up.

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One of them is, like I
said a minute ago, that--

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OK, I didn't exactly
say it this way,

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but C being a vector plus a--

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so C could be some fixed
vector plus a subspace,

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meaning the set of all
vectors of the form v

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plus w, where w is
in some subspace.

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But that's not necessarily the
only kind we'll come across.

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OK, so if we have a closed,
convex, non-empty subset

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of a Hilbert space, then there
exists a unique minimizer

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in this subspace.

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So of course, I encourage
you to think about

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if I drop either
of these conditions

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whether or not this
theorem remains true.

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So it's clear you cannot
drop C being closed.

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So for example, this just remark
you cannot drop the condition C

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closed.

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For example, let's say you
have an open ball in R2 now.

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And you take just any
point outside the ball.

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Then the minimum--
now, let's see.

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I've got this backwards.

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Let's take C to be
everything outside the ball.

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So it's neither
closed nor convex.

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Then of course, this will not
have a minimum length because--

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or this subset will
not have a vector

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that has minimum length
because the minimum length will

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want to be on this--

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let's say that's radius 1--
on this circle of radius

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1, which is not
included in the set C.

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So that one's taken
away both conditions--

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that C is closed and convex.

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Of course, you can do something
where it's just convex,

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but not closed-- for example,
take a square now in R2.

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Then let's say
this is minus 1, 1.

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This is corners at 1, 1.

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And there's the origin.

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Then the vector
of minimum length

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will want to be right
here at the point 0, 1.

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But that's not in
C. So you can also

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show that for C given by this
rectangle missing a spot,

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it will not have a minimizer.

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And then you can play
with this and find

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a closed subset that is
not convex that doesn't

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have a unique minimizer.

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So these conditions are
necessary for this theorem

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to hold.

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It's not just me
giving you a lesser--

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or a theorem that's with
assumptions that are

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much stronger than you need.

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OK, so what's the proof?

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So this infimum-- so let me
recall just real quick that--

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so something, let's say a, is
equal to the infiumum of a set

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S, where S is a subset of
the real numbers if and only

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if two things--

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a is a lower bound for S
and there exists a sequence

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Sn in S such that
Sn converged to a.

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So this should have
been covered in 18.100.

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So let's call this number d.

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So let d be the
infimum of u, which

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we know exists because norms
are bounded below by 0.

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So this set of norms
where u ranges over C

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is bounded below by 0,
so the infimum exists.

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OK, so let d be that.

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Then there exists a
sequence un of elements

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in C such that the norms of
these un's converge to d.

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So I now make the claim
that this sequence--

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so what we're trying
to do is come up

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with some element in C
that achieves this d,

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so that the norm of
v is equal to this d.

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So I now claim that this
sequence is, in fact, Cauchy.

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And you'll see how we use the
Hilbert space structure of--

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or the inner product
structure that

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comes with the Hilbert space.

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So we'll just do this
the old fashioned way.

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Let epsilon be positive.

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We now need to
find a capital N so

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that the difference
between un and um

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less than epsilon
in norm for all n

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and m bigger than or
equal to capital N.

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So since the norm of
un is converging to d,

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there exists a
natural number N such

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that for all n bigger than or
equal to N, I have that 2 un

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squared is less than 2 d squared
plus epsilon squared over 2.

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So this thing here is
converging to 2 times

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d squared as n goes to infinity.

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So if I perturb 2 d
squared by a little bit,

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then since this is
converging to 2 d squared,

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that will be less than this
for insufficiently large.

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Now, I claim this
capital N works.

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And for all nm bigger
than or equal to capital

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N, if I take the norm--

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now, I'm going to use
this parallelogram law

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that I have for norms, which
crucially relies on the Hilbert

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space property.

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So this I can write
as 2 norm u squared

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plus 2 norm um squared minus
4 times un plus um over 2

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squared.

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Now, what's the point?

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Now, un plus um
divided by 2, that's,

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if you like, t equals
1/2 in condition C. Now,

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since un and um are in C, un
plus um over 2 is in C as well,

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right?

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So this thing is in C.

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And therefore, its norm
squared is bigger than

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or equal to d squared.

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So when it gets hit
with a negative,

00:14:18.690 --> 00:14:20.110 align:middle line:90%
that switches the inequality.

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This norm squared is
less than or equal to--

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or minus 4 this norm squared is
less than or equal to minus 4

00:14:27.300 --> 00:14:28.860 align:middle line:90%
d squared.

00:14:28.860 --> 00:14:34.440 align:middle line:84%
So this is less than or
equal to 2 un squared

00:14:34.440 --> 00:14:41.130 align:middle line:84%
plus 2 um squared minus
4 d squared-- again,

00:14:41.130 --> 00:14:46.710 align:middle line:84%
because d is a lower bound for
the norms of all elements in C

00:14:46.710 --> 00:14:51.600 align:middle line:84%
and this element is in C.
And this minus sign flips,

00:14:51.600 --> 00:14:52.440 align:middle line:90%
all right?

00:14:52.440 --> 00:14:55.620 align:middle line:84%
And now, based on how
we've chosen capital N,

00:14:55.620 --> 00:15:00.400 align:middle line:84%
we've chosen it so that we
have this inequality here.

00:15:00.400 --> 00:15:05.730 align:middle line:84%
I get this is less than 2 d
squared plus epsilon squared

00:15:05.730 --> 00:15:09.540 align:middle line:84%
over 2 from the
first one plus 2 d

00:15:09.540 --> 00:15:13.770 align:middle line:84%
squared plus epsilon squared
over 2 from the second one,

00:15:13.770 --> 00:15:17.790 align:middle line:84%
and then minus d squared
from this last one.

00:15:17.790 --> 00:15:20.830 align:middle line:90%
And that equals epsilon squared.

00:15:20.830 --> 00:15:23.760 align:middle line:84%
So for all nm bigger than
or equal to capital N,

00:15:23.760 --> 00:15:28.900 align:middle line:84%
the norm squared of un minus um
is less than epsilon squared.

00:15:28.900 --> 00:15:31.142 align:middle line:84%
And therefore, that
proves the claim

00:15:31.142 --> 00:15:32.350 align:middle line:90%
that this sequence is Cauchy.

00:15:32.350 --> 00:15:37.120 align:middle line:90%


00:15:37.120 --> 00:15:39.190 align:middle line:84%
Now, since this
sequence is Cauchy

00:15:39.190 --> 00:15:44.680 align:middle line:84%
and we're in a Hilbert space,
a complete inner product space,

00:15:44.680 --> 00:15:57.880 align:middle line:84%
there's a limit such that
un converges to v. Now,

00:15:57.880 --> 00:15:58.750 align:middle line:90%
C is closed.

00:15:58.750 --> 00:16:07.570 align:middle line:84%
So v is also in H.
Since C is closed,

00:16:07.570 --> 00:16:11.510 align:middle line:84%
it contains all limits,
all subsequential limits.

00:16:11.510 --> 00:16:15.580 align:middle line:84%
So C is closed is equivalent to
for every sequence converging

00:16:15.580 --> 00:16:18.760 align:middle line:84%
to something, that something
has to be in the set.

00:16:18.760 --> 00:16:24.880 align:middle line:90%
v is in C.

00:16:24.880 --> 00:16:28.540 align:middle line:84%
Finally, since the
un's converge to v,

00:16:28.540 --> 00:16:33.880 align:middle line:84%
we have v norm is equal to the
limit as n goes to infinity

00:16:33.880 --> 00:16:35.770 align:middle line:90%
of the norms of the un's.

00:16:35.770 --> 00:16:38.620 align:middle line:84%
And remember, where did we
come up with these un's?

00:16:38.620 --> 00:16:40.450 align:middle line:84%
They are supposed to
be-- their norms are

00:16:40.450 --> 00:16:43.480 align:middle line:90%
supposed to be converging to d.

00:16:43.480 --> 00:16:51.823 align:middle line:84%
So v is an element in C
whose norm gives me d.

00:16:51.823 --> 00:16:53.740 align:middle line:84%
Now, there's one last
statement in the theorem

00:16:53.740 --> 00:16:54.940 align:middle line:90%
that v is unique.

00:16:54.940 --> 00:16:56.300 align:middle line:90%
There can't be two of them.

00:16:56.300 --> 00:17:00.020 align:middle line:84%
And it follows from a similar
argument that we made here.

00:17:00.020 --> 00:17:05.020 align:middle line:84%
So what we've shown so
far is that there exists

00:17:05.020 --> 00:17:11.359 align:middle line:90%
a v in C whose norm gives me d.

00:17:11.359 --> 00:17:16.010 align:middle line:84%
Now, we claim that there
can't be more than one.

00:17:16.010 --> 00:17:24.119 align:middle line:84%
Suppose v and v-bar are in
C and both of their norms

00:17:24.119 --> 00:17:29.730 align:middle line:84%
give me d, this infimum
of norms over C. Now,

00:17:29.730 --> 00:17:32.820 align:middle line:84%
I use the parallelogram
law again.

00:17:32.820 --> 00:17:36.960 align:middle line:84%
I get that norm of v
minus v-bar squared,

00:17:36.960 --> 00:17:44.640 align:middle line:84%
this is equal 2 norm squared
of v plus norm of v-bar squared

00:17:44.640 --> 00:17:46.590 align:middle line:90%
with a 2--

00:17:46.590 --> 00:17:55.725 align:middle line:84%
plus 2-- minus 4 norm
v plus v-bar squared.

00:17:55.725 --> 00:17:58.970 align:middle line:90%


00:17:58.970 --> 00:18:01.640 align:middle line:90%
Now, this equals d squared.

00:18:01.640 --> 00:18:03.030 align:middle line:90%
This equals d squared.

00:18:03.030 --> 00:18:10.410 align:middle line:84%
So this combines and gives me 4
d squared minus the same thing.

00:18:10.410 --> 00:18:16.340 align:middle line:84%
And again, since C is convex
in both v and v-bar are in C--

00:18:16.340 --> 00:18:18.740 align:middle line:84%
v-bar does not mean
complex conjugate.

00:18:18.740 --> 00:18:21.200 align:middle line:84%
It just means
something other than v.

00:18:21.200 --> 00:18:24.830 align:middle line:84%
So since both of these elements
are in C, their midpoint, which

00:18:24.830 --> 00:18:28.520 align:middle line:84%
is, again t equals 1/2
if you like in condition

00:18:28.520 --> 00:18:31.580 align:middle line:84%
C for this theorem,
this is also in C.

00:18:31.580 --> 00:18:35.810 align:middle line:84%
And since d is the
smallest of all the norms,

00:18:35.810 --> 00:18:38.330 align:middle line:84%
the norm of the norm
squared has to be bigger

00:18:38.330 --> 00:18:40.380 align:middle line:90%
than or equal to d squared.

00:18:40.380 --> 00:18:43.350 align:middle line:84%
And when I hit a minus sign,
that flips the inequality.

00:18:43.350 --> 00:18:47.510 align:middle line:84%
So that's less than or
equal to 4 d squared minus 4

00:18:47.510 --> 00:18:49.910 align:middle line:90%
d squared equals 0.

00:18:49.910 --> 00:18:55.460 align:middle line:84%
And therefore, this norm
squared has to be 0, i.e.

00:18:55.460 --> 00:18:56.180 align:middle line:90%
v equals v-bar.

00:18:56.180 --> 00:18:59.020 align:middle line:90%


00:18:59.020 --> 00:19:04.480 align:middle line:84%
Now, this simple theorem has
important consequences which

00:19:04.480 --> 00:19:06.640 align:middle line:90%
we're going to obtain from it.

00:19:06.640 --> 00:19:13.880 align:middle line:90%


00:19:13.880 --> 00:19:20.690 align:middle line:84%
So the first application of
this theorem is going to be to--

00:19:20.690 --> 00:19:24.830 align:middle line:84%
a way to always
decompose a Hilbert space

00:19:24.830 --> 00:19:29.450 align:middle line:84%
if we're given a closed
linear subspace, which you're

00:19:29.450 --> 00:19:36.070 align:middle line:84%
kind of used to if, you're
working in Rn or Cn,

00:19:36.070 --> 00:19:38.560 align:middle line:84%
but we haven't touched on
yet for Hilbert spaces.

00:19:38.560 --> 00:19:41.950 align:middle line:84%
And there's a reason, because we
didn't have the technology yet.

00:19:41.950 --> 00:19:49.820 align:middle line:84%
But now, let's discuss
orthocomplements.

00:19:49.820 --> 00:19:55.630 align:middle line:90%


00:19:55.630 --> 00:19:56.680 align:middle line:90%
So let's see.

00:19:56.680 --> 00:19:58.300 align:middle line:84%
OK, I actually
spelled it correctly.

00:19:58.300 --> 00:20:02.920 align:middle line:90%


00:20:02.920 --> 00:20:05.290 align:middle line:84%
When I was at the
University of Chicago,

00:20:05.290 --> 00:20:09.970 align:middle line:90%
I sent my thesis to my advisor.

00:20:09.970 --> 00:20:19.790 align:middle line:84%
And he had some questions
about math points of the thesis

00:20:19.790 --> 00:20:21.740 align:middle line:84%
that I needed to make
a little bit clearer.

00:20:21.740 --> 00:20:24.950 align:middle line:84%
These weren't big
deals math-wise.

00:20:24.950 --> 00:20:28.640 align:middle line:84%
But of course, every time I
got an email from my advisor

00:20:28.640 --> 00:20:34.135 align:middle line:84%
with a question about my thesis,
it struck the fear of God

00:20:34.135 --> 00:20:34.635 align:middle line:90%
in me.

00:20:34.635 --> 00:20:37.140 align:middle line:90%


00:20:37.140 --> 00:20:38.460 align:middle line:90%
But everything was fine.

00:20:38.460 --> 00:20:39.485 align:middle line:90%
Everything was fixable.

00:20:39.485 --> 00:20:40.860 align:middle line:84%
And then the last
comment he made

00:20:40.860 --> 00:20:44.520 align:middle line:84%
was there was like 50
times throughout the paper

00:20:44.520 --> 00:20:46.560 align:middle line:90%
that I needed to--

00:20:46.560 --> 00:20:48.810 align:middle line:84%
or the thesis that
I needed to change

00:20:48.810 --> 00:20:50.940 align:middle line:84%
complement because
I kept spelling

00:20:50.940 --> 00:20:57.630 align:middle line:84%
it compliment with
an I, so complement

00:20:57.630 --> 00:21:00.270 align:middle line:90%
meaning what's not in there.

00:21:00.270 --> 00:21:02.520 align:middle line:84%
Compliment is
something nice you say.

00:21:02.520 --> 00:21:06.240 align:middle line:84%
And so mistakes
get made sometimes.

00:21:06.240 --> 00:21:09.330 align:middle line:90%


00:21:09.330 --> 00:21:15.550 align:middle line:84%
So for the complements
we're interested in,

00:21:15.550 --> 00:21:16.480 align:middle line:90%
we have the following.

00:21:16.480 --> 00:21:27.280 align:middle line:84%
If H is a Hilbert space
and W is a linear--

00:21:27.280 --> 00:21:33.910 align:middle line:90%


00:21:33.910 --> 00:21:44.720 align:middle line:84%
is a subspace, then
the following set,

00:21:44.720 --> 00:21:51.230 align:middle line:84%
W-perp which is equal to the
set of all u in H which are

00:21:51.230 --> 00:21:53.600 align:middle line:90%
orthogonal to everything in W--

00:21:53.600 --> 00:22:00.800 align:middle line:84%
so u inner product w
equals 0 for all w in W--

00:22:00.800 --> 00:22:15.455 align:middle line:84%
this is a closed linear subspace
of H. So that's the first part.

00:22:15.455 --> 00:22:19.840 align:middle line:90%


00:22:19.840 --> 00:22:28.980 align:middle line:84%
If the subspace we started with,
W, is closed then, in fact,

00:22:28.980 --> 00:22:34.490 align:middle line:84%
we can write H as the
direct product of--

00:22:34.490 --> 00:22:36.950 align:middle line:84%
or the direct sum,
I'm sorry, of W

00:22:36.950 --> 00:22:39.357 align:middle line:90%
and the orthogonal complement.

00:22:39.357 --> 00:22:40.190 align:middle line:90%
What does this mean?

00:22:40.190 --> 00:22:43.280 align:middle line:84%
Again, I'll recall from linear
algebra what this means, i.e.--

00:22:43.280 --> 00:22:50.618 align:middle line:90%


00:22:50.618 --> 00:22:54.190 align:middle line:84%
let me make sure I don't
leave anything out.

00:22:54.190 --> 00:22:54.690 align:middle line:90%
i.e.

00:22:54.690 --> 00:23:07.022 align:middle line:84%
for all u in H, there
exists a unique w in W,

00:23:07.022 --> 00:23:15.270 align:middle line:84%
w-perp in W-perp,
little w, such that u

00:23:15.270 --> 00:23:18.000 align:middle line:90%
is equal to w plus w-perp.

00:23:18.000 --> 00:23:40.060 align:middle line:90%


00:23:40.060 --> 00:23:44.860 align:middle line:90%
So it's simple to show that--

00:23:44.860 --> 00:24:02.940 align:middle line:84%
so to see that W-perp
is a subspace of H. What

00:24:02.940 --> 00:24:06.210 align:middle line:84%
I have to check is that linear
combinations of elements

00:24:06.210 --> 00:24:08.290 align:middle line:90%
of W-perp remain in W-perp.

00:24:08.290 --> 00:24:09.450 align:middle line:90%
But this is kind of clear.

00:24:09.450 --> 00:24:16.890 align:middle line:84%
If u inner product w1 is equal
to 0 for all u in capital W--

00:24:16.890 --> 00:24:18.270 align:middle line:90%
no, no, no, backwards.

00:24:18.270 --> 00:24:21.630 align:middle line:84%
If u1 inner product
w is equal to 0

00:24:21.630 --> 00:24:26.160 align:middle line:84%
for all w in capital W
and u2 inner product w

00:24:26.160 --> 00:24:29.310 align:middle line:84%
is equal to 0 for
all w in capital W,

00:24:29.310 --> 00:24:33.720 align:middle line:84%
then the linear
combination of u1 and u2

00:24:33.720 --> 00:24:38.070 align:middle line:84%
will be orthogonal to w for
all little w in capital W.

00:24:38.070 --> 00:24:41.670 align:middle line:84%
So that's pretty easy to
see why it's a subspace.

00:24:41.670 --> 00:24:53.040 align:middle line:84%
And the only thing these
two subspaces have in common

00:24:53.040 --> 00:24:58.650 align:middle line:84%
is the zero vector because if I
have something in W and W-perp,

00:24:58.650 --> 00:25:03.010 align:middle line:84%
then it must be
orthogonal to itself.

00:25:03.010 --> 00:25:05.818 align:middle line:84%
And one of the conditions that
we have for an inner product

00:25:05.818 --> 00:25:07.110 align:middle line:90%
is that it's positive definite.

00:25:07.110 --> 00:25:09.070 align:middle line:84%
If I have something
orthogonal to itself,

00:25:09.070 --> 00:25:11.110 align:middle line:90%
it has to be the zero vector.

00:25:11.110 --> 00:25:15.240 align:middle line:84%
So that's why we get
these fairly quickly.

00:25:15.240 --> 00:25:21.470 align:middle line:84%
Why is W-perp--
why is this closed?

00:25:21.470 --> 00:25:24.150 align:middle line:84%
This follows from the
continuity of the inner product.

00:25:24.150 --> 00:25:41.780 align:middle line:84%
So to show the
W-perp is closed, let

00:25:41.780 --> 00:25:55.240 align:middle line:84%
un be a sequence in
W-perp and u in H

00:25:55.240 --> 00:25:58.140 align:middle line:90%
such that un converges to u.

00:25:58.140 --> 00:26:03.050 align:middle line:84%
So W-perp is closed if we show
that u is, in fact, in W-perp.

00:26:03.050 --> 00:26:06.350 align:middle line:84%
That's the condition of a
subset of a metric space being

00:26:06.350 --> 00:26:07.040 align:middle line:90%
closed, right?

00:26:07.040 --> 00:26:07.700 align:middle line:90%
It's closed.

00:26:07.700 --> 00:26:09.950 align:middle line:84%
I mean, there's several
different ways to phrase this.

00:26:09.950 --> 00:26:14.000 align:middle line:84%
But the most useful one is
often that a subset is closed if

00:26:14.000 --> 00:26:16.940 align:middle line:84%
and only if it's
closed undertaking

00:26:16.940 --> 00:26:17.870 align:middle line:90%
subsequential limits.

00:26:17.870 --> 00:26:22.160 align:middle line:84%
Every limit of a sequence
is contained in the set.

00:26:22.160 --> 00:26:25.430 align:middle line:90%


00:26:25.430 --> 00:26:28.160 align:middle line:84%
So we need to verify that if
I have a sequence of elements

00:26:28.160 --> 00:26:30.500 align:middle line:84%
in W-perp converging
to something, then

00:26:30.500 --> 00:26:35.140 align:middle line:90%
that something has to be in C.

00:26:35.140 --> 00:26:40.390 align:middle line:84%
Now, let little w be
in capital W. Then

00:26:40.390 --> 00:26:43.660 align:middle line:84%
the inner product of
this limit, u with w,

00:26:43.660 --> 00:26:47.680 align:middle line:84%
by continuity of
the inner product,

00:26:47.680 --> 00:26:49.930 align:middle line:84%
since the un's are
converging to u,

00:26:49.930 --> 00:26:51.700 align:middle line:84%
this is equal to the
inner product of un

00:26:51.700 --> 00:26:54.400 align:middle line:90%
with w, taking the limit.

00:26:54.400 --> 00:26:58.060 align:middle line:84%
And all of these
are 0 for all n.

00:26:58.060 --> 00:27:01.500 align:middle line:90%
So this equals 0 .

00:27:01.500 --> 00:27:04.050 align:middle line:84%
And therefore,
this inner product

00:27:04.050 --> 00:27:08.850 align:middle line:84%
is 0 for all w in capital
W. But this is the condition

00:27:08.850 --> 00:27:12.350 align:middle line:90%
that u is in W-perp.

00:27:12.350 --> 00:27:13.280 align:middle line:90%
Thus, u is closed.

00:27:13.280 --> 00:27:23.440 align:middle line:90%


00:27:23.440 --> 00:27:28.025 align:middle line:90%
Now, let's do the second part.

00:27:28.025 --> 00:27:29.650 align:middle line:84%
So maybe I should
have numbered these--

00:27:29.650 --> 00:27:32.530 align:middle line:90%
1, 2.

00:27:32.530 --> 00:27:35.020 align:middle line:90%
So this is a proof of 1.

00:27:35.020 --> 00:27:37.960 align:middle line:84%
So now, we're onto proof
of the statement 2.

00:27:37.960 --> 00:27:42.310 align:middle line:84%
If W is closed, then H is
equal to the direct product

00:27:42.310 --> 00:27:43.150 align:middle line:90%
of W and W-perp.

00:27:43.150 --> 00:27:46.300 align:middle line:90%


00:27:46.300 --> 00:27:49.440 align:middle line:90%
So now, suppose W is closed.

00:27:49.440 --> 00:27:55.930 align:middle line:90%


00:27:55.930 --> 00:28:00.880 align:middle line:84%
If W is just the
entire Hilbert space,

00:28:00.880 --> 00:28:09.730 align:middle line:84%
then clearly the only thing
orthogonal to everything

00:28:09.730 --> 00:28:11.020 align:middle line:90%
is the zero vector.

00:28:11.020 --> 00:28:13.670 align:middle line:90%


00:28:13.670 --> 00:28:24.690 align:middle line:84%
And we have the
decomposition as trivially.

00:28:24.690 --> 00:28:29.880 align:middle line:90%


00:28:29.880 --> 00:28:34.410 align:middle line:84%
So let's assume w
is not the entire--

00:28:34.410 --> 00:28:35.520 align:middle line:90%
is not the entire space.

00:28:35.520 --> 00:28:50.150 align:middle line:90%


00:28:50.150 --> 00:28:52.880 align:middle line:84%
So now, we actually
have something to check.

00:28:52.880 --> 00:29:00.383 align:middle line:84%
Let u be in H take
away W. I can't

00:29:00.383 --> 00:29:02.550 align:middle line:84%
remember if the backslash
goes that way or that way.

00:29:02.550 --> 00:29:12.720 align:middle line:84%
I don't mean H modulo W. I
mean H take away the set W.

00:29:12.720 --> 00:29:18.520 align:middle line:84%
And let's define
set C seems to be--

00:29:18.520 --> 00:29:21.550 align:middle line:90%


00:29:21.550 --> 00:29:23.950 align:middle line:84%
OK, so maybe it
looks like I'm just

00:29:23.950 --> 00:29:29.140 align:middle line:84%
lying to you about not
having to deal with H mod W.

00:29:29.140 --> 00:29:36.460 align:middle line:84%
But in any case, the actual set
u plus capital W, meaning set u

00:29:36.460 --> 00:29:43.880 align:middle line:84%
plus little w, little w
in capital W. All right?

00:29:43.880 --> 00:29:44.755 align:middle line:90%
So just this set.

00:29:44.755 --> 00:29:53.350 align:middle line:90%


00:29:53.350 --> 00:29:55.780 align:middle line:84%
Now, I claim that C
is-- so first off,

00:29:55.780 --> 00:29:57.010 align:middle line:90%
C is clearly non-empty.

00:29:57.010 --> 00:29:58.360 align:middle line:90%
It contains u.

00:29:58.360 --> 00:30:10.010 align:middle line:90%


00:30:10.010 --> 00:30:12.320 align:middle line:90%
So it's non-empty.

00:30:12.320 --> 00:30:16.193 align:middle line:90%
I claim it's also closed.

00:30:16.193 --> 00:30:18.485 align:middle line:84%
Well, first, let's do the
easier bit, that it's convex.

00:30:18.485 --> 00:30:24.794 align:middle line:90%


00:30:24.794 --> 00:30:38.440 align:middle line:84%
It's convex since if u plus
w1 is in C, u plus w2 is in C.

00:30:38.440 --> 00:30:41.080 align:middle line:84%
So these are two
elements now in C.

00:30:41.080 --> 00:30:44.800 align:middle line:84%
They're of the form u plus
an element of capital W--

00:30:44.800 --> 00:30:47.510 align:middle line:90%


00:30:47.510 --> 00:30:55.370 align:middle line:84%
w1, w2 are in capital W
and t is between 0 and 1--

00:30:55.370 --> 00:31:12.090 align:middle line:84%
then t times u plus w1 plus
1 minus t times u plus w2,

00:31:12.090 --> 00:31:15.990 align:middle line:84%
this equals t times u
plus 1 minus t times u

00:31:15.990 --> 00:31:23.430 align:middle line:84%
just gives me back u plus
t w1 plus 1 minus t w2.

00:31:23.430 --> 00:31:29.640 align:middle line:84%
And now, you note that w1
and w2, they're part of a--

00:31:29.640 --> 00:31:31.440 align:middle line:84%
they're elements in
a subspace capital

00:31:31.440 --> 00:31:34.110 align:middle line:84%
W. And therefore, this
linear combination of them

00:31:34.110 --> 00:31:40.990 align:middle line:84%
is also in W. So therefore,
u plus this element

00:31:40.990 --> 00:31:46.090 align:middle line:84%
is in C, which is all
elements of the form u

00:31:46.090 --> 00:31:49.780 align:middle line:90%
plus w for w in capital W.

00:31:49.780 --> 00:31:50.980 align:middle line:90%
So C is convex.

00:31:50.980 --> 00:31:54.130 align:middle line:84%
Now, let's just
show C is closed.

00:31:54.130 --> 00:32:03.350 align:middle line:90%


00:32:03.350 --> 00:32:08.140 align:middle line:90%
Now, why is C closed?

00:32:08.140 --> 00:32:15.700 align:middle line:90%
So suppose u plus wn--

00:32:15.700 --> 00:32:20.230 align:middle line:84%
so this is the sequence of
elements in C. So each of these

00:32:20.230 --> 00:32:21.700 align:middle line:90%
is in C--

00:32:21.700 --> 00:32:24.760 align:middle line:90%
converges to an element--

00:32:24.760 --> 00:32:32.700 align:middle line:84%
let's call it v in H. We
want to show that v is in C.

00:32:32.700 --> 00:32:36.340 align:middle line:90%
We want to show v is in C.

00:32:36.340 --> 00:32:43.900 align:middle line:84%
Now, u plus wn
converging to v implies

00:32:43.900 --> 00:32:48.745 align:middle line:90%
that wn converges to v minus u.

00:32:48.745 --> 00:32:54.580 align:middle line:90%


00:32:54.580 --> 00:33:00.015 align:middle line:84%
And since wn is coming from
a closed subspace-- remember,

00:33:00.015 --> 00:33:01.390 align:middle line:84%
this is actually
what we're using

00:33:01.390 --> 00:33:03.160 align:middle line:90%
the fact that W is closed.

00:33:03.160 --> 00:33:19.570 align:middle line:84%
So this implies since W is
closed v minus u is in W.

00:33:19.570 --> 00:33:23.560 align:middle line:90%
And since v is in--

00:33:23.560 --> 00:33:28.690 align:middle line:84%
since v minus u is
in W, this implies

00:33:28.690 --> 00:33:36.040 align:middle line:84%
that v is equal to u
plus some element w

00:33:36.040 --> 00:33:39.820 align:middle line:90%
with w in capital W, i.e.

00:33:39.820 --> 00:33:43.540 align:middle line:84%
v is in C. Again,
capital C is the set

00:33:43.540 --> 00:33:45.970 align:middle line:84%
of all elements of
the form little u

00:33:45.970 --> 00:33:50.740 align:middle line:84%
plus something from
capital W. So we've

00:33:50.740 --> 00:33:53.560 align:middle line:84%
shown that if we have a sequence
converging to an element in H,

00:33:53.560 --> 00:33:55.750 align:middle line:84%
then that limit
must be in the set.

00:33:55.750 --> 00:33:59.050 align:middle line:90%
So C is closed.

00:33:59.050 --> 00:34:02.840 align:middle line:84%
All right, so let me draw a
picture now of what's going on.

00:34:02.840 --> 00:34:06.325 align:middle line:84%
Let's imagine that W,
the subspace W, is--

00:34:06.325 --> 00:34:13.210 align:middle line:90%


00:34:13.210 --> 00:34:21.070 align:middle line:84%
so imagine H is R2 and
W is just the x-axis.

00:34:21.070 --> 00:34:29.110 align:middle line:90%
And u is this vector here.

00:34:29.110 --> 00:34:32.650 align:middle line:84%
u plus w is now
the horizontal line

00:34:32.650 --> 00:34:33.984 align:middle line:90%
that goes through this point.

00:34:33.984 --> 00:34:37.330 align:middle line:90%


00:34:37.330 --> 00:34:39.390 align:middle line:90%
This is u plus w.

00:34:39.390 --> 00:34:49.150 align:middle line:84%
This is-- let's just
let's just call it C.

00:34:49.150 --> 00:34:52.120 align:middle line:84%
Now, we have the
set C. We have W.

00:34:52.120 --> 00:34:58.420 align:middle line:84%
We would like to break up u into
an element which is parallel

00:34:58.420 --> 00:35:03.640 align:middle line:84%
to W and something that's
perpendicular to w, right?

00:35:03.640 --> 00:35:09.280 align:middle line:90%


00:35:09.280 --> 00:35:14.440 align:middle line:84%
Now, based on this
picture, what is--

00:35:14.440 --> 00:35:18.950 align:middle line:84%
let's call this element v. This
is not the same v from before,

00:35:18.950 --> 00:35:31.740 align:middle line:90%
so new v.

00:35:31.740 --> 00:35:35.880 align:middle line:84%
We would like for this v
to be perpendicular to C.

00:35:35.880 --> 00:35:38.400 align:middle line:84%
And based on this picture,
what would it satisfy?

00:35:38.400 --> 00:35:42.360 align:middle line:84%
It would be the element
of C of minimal length.

00:35:42.360 --> 00:35:45.920 align:middle line:90%


00:35:45.920 --> 00:35:49.580 align:middle line:84%
So that's how we'll
define v. Or if you like,

00:35:49.580 --> 00:35:51.890 align:middle line:84%
that's the element
that's the W-perp.

00:35:51.890 --> 00:35:53.660 align:middle line:84%
It'll end up being the
perpendicular part.

00:35:53.660 --> 00:35:56.780 align:middle line:90%


00:35:56.780 --> 00:36:13.850 align:middle line:84%
So since C is closed and convex,
there exists a unique element v

00:36:13.850 --> 00:36:21.540 align:middle line:84%
in C such that the
norm of v equals

00:36:21.540 --> 00:36:26.270 align:middle line:84%
the infimum of all elements--
the norms of the elements

00:36:26.270 --> 00:36:29.000 align:middle line:84%
and C. but I'll write it a
slightly different way, w

00:36:29.000 --> 00:36:33.800 align:middle line:84%
in capital W of norm of
u plus w because this

00:36:33.800 --> 00:36:36.360 align:middle line:84%
is all of the elements
in C come in this way.

00:36:36.360 --> 00:36:39.322 align:middle line:84%
So this is the way
this norm of v is--

00:36:39.322 --> 00:36:42.040 align:middle line:90%


00:36:42.040 --> 00:36:43.840 align:middle line:84%
or the way this
infimum can be written.

00:36:43.840 --> 00:36:47.840 align:middle line:90%


00:36:47.840 --> 00:36:52.580 align:middle line:84%
So I've identified a
candidate for the part

00:36:52.580 --> 00:36:54.270 align:middle line:90%
that will be orthogonal.

00:36:54.270 --> 00:36:59.390 align:middle line:84%
And then simply, u minus v
will be the part that's in C,

00:36:59.390 --> 00:37:00.140 align:middle line:90%
hopefully.

00:37:00.140 --> 00:37:02.820 align:middle line:90%


00:37:02.820 --> 00:37:04.680 align:middle line:90%
And let's check this.

00:37:04.680 --> 00:37:05.310 align:middle line:90%
So claim.

00:37:05.310 --> 00:37:22.380 align:middle line:90%


00:37:22.380 --> 00:37:30.860 align:middle line:84%
So first off, let's note a
simple thing, note that v in C

00:37:30.860 --> 00:37:37.310 align:middle line:84%
implies that u
minus v is in W. v

00:37:37.310 --> 00:37:39.290 align:middle line:90%
is of the form u plus little w.

00:37:39.290 --> 00:37:43.730 align:middle line:84%
So u minus that has
to be an element of W.

00:37:43.730 --> 00:37:51.620 align:middle line:84%
And we have that u is
equal to u minus v plus v.

00:37:51.620 --> 00:37:55.550 align:middle line:84%
So this would be
the element of w.

00:37:55.550 --> 00:37:58.550 align:middle line:84%
And we hope to show that
this element is in W-perp.

00:37:58.550 --> 00:38:05.010 align:middle line:90%


00:38:05.010 --> 00:38:20.480 align:middle line:84%
OK, so now, we claim little
w is in capital W-perp.

00:38:20.480 --> 00:38:22.520 align:middle line:84%
Now, how we do this
is what's called,

00:38:22.520 --> 00:38:28.040 align:middle line:84%
I guess, a variational argument
or Euler-Lagrange equations

00:38:28.040 --> 00:38:28.740 align:middle line:90%
argument.

00:38:28.740 --> 00:38:31.940 align:middle line:84%
But in any case,
something is the infimum

00:38:31.940 --> 00:38:38.330 align:middle line:84%
of this if and only if v
satisfies certain equations--

00:38:38.330 --> 00:38:41.840 align:middle line:84%
or not if not only if, but
v being the infimum of this

00:38:41.840 --> 00:38:44.870 align:middle line:84%
implies that v satisfies
certain equations.

00:38:44.870 --> 00:38:48.050 align:middle line:84%
If you've taken
classical mechanics,

00:38:48.050 --> 00:38:51.620 align:middle line:84%
those equations end up being
the Euler-Lagrange equations.

00:38:51.620 --> 00:38:56.570 align:middle line:84%
But anyways, I claim
v is in W-perp.

00:38:56.570 --> 00:39:02.600 align:middle line:84%
So let w be in capital
W. We want to show

00:39:02.600 --> 00:39:06.500 align:middle line:90%
v inner product w equals 0.

00:39:06.500 --> 00:39:10.295 align:middle line:90%
Let f of t be the norm of u--

00:39:10.295 --> 00:39:13.340 align:middle line:90%


00:39:13.340 --> 00:39:18.830 align:middle line:84%
norm of, sorry, v
plus tw squared, which

00:39:18.830 --> 00:39:21.110 align:middle line:90%
this is just a polynomial in t.

00:39:21.110 --> 00:39:25.880 align:middle line:84%
This is equal to
norm v squared plus t

00:39:25.880 --> 00:39:37.550 align:middle line:84%
squared norm w squared plus 2
real part of 2t real part vw.

00:39:37.550 --> 00:39:39.000 align:middle line:90%
So it's just a polynomial.

00:39:39.000 --> 00:39:42.180 align:middle line:90%
Now, what do we know?

00:39:42.180 --> 00:39:57.450 align:middle line:84%
So then f of t has a minimum at
t equals 0 because for each t,

00:39:57.450 --> 00:40:02.970 align:middle line:84%
this is an element of capital
C. And the norm of everything

00:40:02.970 --> 00:40:05.910 align:middle line:84%
in capital C is
minimized exactly

00:40:05.910 --> 00:40:09.600 align:middle line:90%
at v, which is t equals 0.

00:40:09.600 --> 00:40:12.060 align:middle line:84%
So this has a
minimum at t equals

00:40:12.060 --> 00:40:18.630 align:middle line:84%
0, which implies f-prime
evaluated at t equals 0 is 0.

00:40:18.630 --> 00:40:22.920 align:middle line:84%
And therefore, if I take
the derivative of f-prime

00:40:22.920 --> 00:40:25.680 align:middle line:84%
of t and set t equal
to 0, then I just

00:40:25.680 --> 00:40:30.000 align:middle line:84%
pick up twice the real
part of vw equaling 0.

00:40:30.000 --> 00:40:35.340 align:middle line:84%
And therefore, I get the
real part of vw equals 0.

00:40:35.340 --> 00:40:39.170 align:middle line:90%


00:40:39.170 --> 00:40:43.610 align:middle line:84%
So I got that the real part
of the inner product is 0.

00:40:43.610 --> 00:40:49.780 align:middle line:84%
Now, it's not--
so what we can do

00:40:49.780 --> 00:41:05.560 align:middle line:84%
is then repeat the previous
argument with iw, i times w

00:41:05.560 --> 00:41:16.910 align:middle line:84%
in place of w to get that the
real part of v inner product

00:41:16.910 --> 00:41:23.210 align:middle line:84%
iw, which is equal to, in
fact, the imaginary part of vw,

00:41:23.210 --> 00:41:24.950 align:middle line:90%
equals 0.

00:41:24.950 --> 00:41:29.180 align:middle line:84%
And therefore, the inner
product of v with w

00:41:29.180 --> 00:41:33.470 align:middle line:84%
is 0, since its real part
and imaginary part equals 0.

00:41:33.470 --> 00:41:43.030 align:middle line:84%
And therefore, vw
equals 0 and v is

00:41:43.030 --> 00:41:45.848 align:middle line:90%
in the orthogonal complement.

00:41:45.848 --> 00:41:49.440 align:middle line:90%


00:41:49.440 --> 00:41:53.580 align:middle line:84%
And so v is in the
orthogonal complement

00:41:53.580 --> 00:41:55.680 align:middle line:84%
and u can be
written as something

00:41:55.680 --> 00:42:00.070 align:middle line:90%
in W plus something in W-perp.

00:42:00.070 --> 00:42:06.430 align:middle line:90%


00:42:06.430 --> 00:42:09.520 align:middle line:90%
Now, why is this?

00:42:09.520 --> 00:42:13.270 align:middle line:84%
So let's take just
two seconds to say why

00:42:13.270 --> 00:42:15.730 align:middle line:90%
this decomposition is unique.

00:42:15.730 --> 00:42:20.290 align:middle line:84%
It's unique because the only
thing the two subspaces have

00:42:20.290 --> 00:42:22.000 align:middle line:90%
in common is the zero vector.

00:42:22.000 --> 00:42:25.094 align:middle line:90%


00:42:25.094 --> 00:42:35.180 align:middle line:84%
OK, so if I have u is equal to
two different decompositions--

00:42:35.180 --> 00:42:42.500 align:middle line:84%
w1 plus w1-perp equals
w2 plus w2-perp,

00:42:42.500 --> 00:42:44.780 align:middle line:84%
where each of these
is in capital W,

00:42:44.780 --> 00:42:47.120 align:middle line:84%
each of these is in the
orthogonal complement

00:42:47.120 --> 00:42:49.610 align:middle line:90%
of capital W--

00:42:49.610 --> 00:42:54.860 align:middle line:84%
I didn't say-- actually, that's
the terminology I'm using,

00:42:54.860 --> 00:43:00.260 align:middle line:84%
but w-perp I'll call the
orthogonal complement--

00:43:00.260 --> 00:43:05.240 align:middle line:84%
then this implies
that w2 minus w1 is

00:43:05.240 --> 00:43:08.810 align:middle line:90%
equal to w1-perp minus w2-perp.

00:43:08.810 --> 00:43:14.060 align:middle line:84%
And this is in W.
This is in W-perp.

00:43:14.060 --> 00:43:19.100 align:middle line:84%
And therefore, since the only
thing in W and W-perp is 0,

00:43:19.100 --> 00:43:22.820 align:middle line:84%
that implies that the left
and right side have to be 0.

00:43:22.820 --> 00:43:26.290 align:middle line:90%
And therefore, w equals w1.

00:43:26.290 --> 00:43:29.260 align:middle line:90%
w1-perp equals w2-perp.

00:43:29.260 --> 00:43:34.120 align:middle line:84%
And that gives us the
uniqueness of the decomposition.

00:43:34.120 --> 00:43:49.610 align:middle line:90%


00:43:49.610 --> 00:43:51.110 align:middle line:90%
So it's in the assignment--

00:43:51.110 --> 00:43:54.098 align:middle line:90%


00:43:54.098 --> 00:43:55.640 align:middle line:84%
I should say the
optional assignment.

00:43:55.640 --> 00:44:10.450 align:middle line:90%
But this subspace, then--

00:44:10.450 --> 00:44:15.190 align:middle line:84%
so I have a subspace W. I can
take its orthogonal complement.

00:44:15.190 --> 00:44:18.130 align:middle line:84%
If it's closed, then H is
equal to w plus w-perp.

00:44:18.130 --> 00:44:21.148 align:middle line:84%
But if I just have
an arbitrary subspace

00:44:21.148 --> 00:44:22.690 align:middle line:84%
and I take its
orthogonal complement,

00:44:22.690 --> 00:44:24.773 align:middle line:84%
I can then take the
orthogonal complement of that.

00:44:24.773 --> 00:44:25.850 align:middle line:90%
What do I get?

00:44:25.850 --> 00:44:29.530 align:middle line:84%
Well, the orthogonal complement
of a set is always closed.

00:44:29.530 --> 00:44:33.250 align:middle line:84%
So I may not get back the
actual subspace again.

00:44:33.250 --> 00:44:35.050 align:middle line:90%
But I will get back its closure.

00:44:35.050 --> 00:44:37.330 align:middle line:84%
So the closure of
W, which you can

00:44:37.330 --> 00:44:40.660 align:middle line:84%
check is, again, a
subspace, is equal

00:44:40.660 --> 00:44:43.540 align:middle line:84%
to the orthogonal complement
of the orthogonal complement.

00:44:43.540 --> 00:44:45.920 align:middle line:84%
So in particular,
if W is closed,

00:44:45.920 --> 00:44:49.150 align:middle line:84%
then the orthogonal complement
of the orthogonal complement

00:44:49.150 --> 00:44:51.680 align:middle line:90%
is the set again.

00:44:51.680 --> 00:44:55.290 align:middle line:84%
So this is in the
optional subspace--

00:44:55.290 --> 00:44:58.050 align:middle line:90%


00:44:58.050 --> 00:45:04.000 align:middle line:84%
in the optional assignment
from the last week.

00:45:04.000 --> 00:45:08.700 align:middle line:90%


00:45:08.700 --> 00:45:15.090 align:middle line:84%
All right, now, given a
closed linear subspace,

00:45:15.090 --> 00:45:18.450 align:middle line:90%
I can define an operator--

00:45:18.450 --> 00:45:21.660 align:middle line:84%
maybe it's-- so let's just
call it a map for now--

00:45:21.660 --> 00:45:30.040 align:middle line:84%
that takes a vector
u and spits out--

00:45:30.040 --> 00:45:35.830 align:middle line:84%
let's say the part that's
in capital W. It's W-part.

00:45:35.830 --> 00:45:37.420 align:middle line:84%
Now, what kind of
operator is that?

00:45:37.420 --> 00:45:39.850 align:middle line:84%
Or I could have said,
it takes an element u

00:45:39.850 --> 00:45:46.030 align:middle line:84%
and spits out the part that's
in the orthogonal complement

00:45:46.030 --> 00:45:49.630 align:middle line:84%
of capital W. What kind
of map is that part?

00:45:49.630 --> 00:45:50.600 align:middle line:90%
Or is that?

00:45:50.600 --> 00:45:53.755 align:middle line:84%
So there's a very
special name for that.

00:45:53.755 --> 00:45:59.500 align:middle line:90%


00:45:59.500 --> 00:46:05.625 align:middle line:84%
So of course, in R2, if
I have an element u--

00:46:05.625 --> 00:46:08.240 align:middle line:90%


00:46:08.240 --> 00:46:15.090 align:middle line:90%
so let's say W is the x-axis.

00:46:15.090 --> 00:46:17.290 align:middle line:90%
W-perp would then be the y-axis.

00:46:17.290 --> 00:46:25.970 align:middle line:84%
And then this would
be the part that's

00:46:25.970 --> 00:46:32.040 align:middle line:84%
in W. This vector would be
the part that's in W-perp.

00:46:32.040 --> 00:46:36.690 align:middle line:84%
Now, what exactly is this
usually called, at least going

00:46:36.690 --> 00:46:38.535 align:middle line:90%
back to your calculus days?

00:46:38.535 --> 00:46:40.650 align:middle line:84%
You usually refer to
it as the projection

00:46:40.650 --> 00:46:44.220 align:middle line:84%
of u onto the,
let's say, x-axis.

00:46:44.220 --> 00:46:46.760 align:middle line:90%


00:46:46.760 --> 00:46:49.020 align:middle line:90%
But that name has--

00:46:49.020 --> 00:46:51.650 align:middle line:84%
or that word has a
very specific meaning.

00:46:51.650 --> 00:46:54.770 align:middle line:90%


00:46:54.770 --> 00:46:58.820 align:middle line:84%
And then we'll show that
what I was just discussing--

00:46:58.820 --> 00:47:02.210 align:middle line:84%
taking u to it's W part
or it's W-perp part--

00:47:02.210 --> 00:47:04.670 align:middle line:90%
is, in fact, a projection.

00:47:04.670 --> 00:47:25.820 align:middle line:84%
So a founded linear
operator P going from H to H

00:47:25.820 --> 00:47:45.460 align:middle line:84%
is a projection if p
squared equals P. So this is

00:47:45.460 --> 00:47:47.090 align:middle line:90%
a new bit of terminology.

00:47:47.090 --> 00:47:51.310 align:middle line:84%
So for example, it doesn't
have to exactly look like this

00:47:51.310 --> 00:47:55.900 align:middle line:84%
or come from this way I
was describing of obtaining

00:47:55.900 --> 00:47:59.080 align:middle line:90%
a map from H to W or W-perp.

00:47:59.080 --> 00:48:01.730 align:middle line:84%
That's not the definition
of a projection.

00:48:01.730 --> 00:48:03.490 align:middle line:84%
The definition of a
projection is this.

00:48:03.490 --> 00:48:05.740 align:middle line:84%
So for example,
taking everything to 0

00:48:05.740 --> 00:48:10.430 align:middle line:84%
is certainly a
projection, which I

00:48:10.430 --> 00:48:12.110 align:middle line:84%
guess you could think
of as projecting

00:48:12.110 --> 00:48:15.740 align:middle line:84%
onto the subspace
consisting only of 0.

00:48:15.740 --> 00:48:23.460 align:middle line:84%
But what I want to
say is that, in fact,

00:48:23.460 --> 00:48:26.850 align:middle line:84%
the map that I just
outlined is, in fact,

00:48:26.850 --> 00:48:29.220 align:middle line:90%
a projection as defined here.

00:48:29.220 --> 00:48:52.420 align:middle line:84%
So let H be a Hilbert space,
as usual; W, a closed subspace.

00:48:52.420 --> 00:48:57.032 align:middle line:90%


00:48:57.032 --> 00:48:58.490 align:middle line:84%
So then by the
previous theorem, we

00:48:58.490 --> 00:49:02.870 align:middle line:84%
have H is equal to
the direct sum of W

00:49:02.870 --> 00:49:04.700 align:middle line:90%
and its orthogonal complement.

00:49:04.700 --> 00:49:09.980 align:middle line:90%


00:49:09.980 --> 00:49:16.475 align:middle line:84%
The map pi sub W going
from H to H given by--

00:49:16.475 --> 00:49:25.260 align:middle line:90%


00:49:25.260 --> 00:49:33.140 align:middle line:84%
defined by the following-- if
v is equal to w plus w-perp--

00:49:33.140 --> 00:49:36.530 align:middle line:84%
so I take an element
in the Hilbert space,

00:49:36.530 --> 00:49:38.900 align:middle line:84%
decompose it as a
part that's in W

00:49:38.900 --> 00:49:40.640 align:middle line:90%
and as a part that's in W-perp.

00:49:40.640 --> 00:49:51.435 align:middle line:84%
Then the definition of this
map evaluated on v is just w.

00:49:51.435 --> 00:49:54.050 align:middle line:90%


00:49:54.050 --> 00:49:58.360 align:middle line:90%
This map is a projection.

00:49:58.360 --> 00:50:06.890 align:middle line:90%


00:50:06.890 --> 00:50:10.430 align:middle line:84%
So we need to show that it
is a bounded linear operator

00:50:10.430 --> 00:50:14.450 align:middle line:84%
and its square gives you
back the original map.

00:50:14.450 --> 00:50:39.540 align:middle line:90%


00:50:39.540 --> 00:50:43.905 align:middle line:84%
So first, let's show
this map is linear.

00:50:43.905 --> 00:50:47.890 align:middle line:90%


00:50:47.890 --> 00:50:51.305 align:middle line:84%
So the first claim
is that pi is linear.

00:50:51.305 --> 00:51:07.590 align:middle line:90%


00:51:07.590 --> 00:51:15.450 align:middle line:84%
So if I have v1 is equal
to w1 plus w1-perp,

00:51:15.450 --> 00:51:22.260 align:middle line:84%
v2 is equal to w2 plus w2-perp,
and I have two scalars--

00:51:22.260 --> 00:51:26.385 align:middle line:84%
lambda 1, lambda 2,
complex numbers--

00:51:26.385 --> 00:51:28.990 align:middle line:90%


00:51:28.990 --> 00:51:35.650 align:middle line:84%
then lambda 1 times v1 plus
lambda 2 v2, this is equal to--

00:51:35.650 --> 00:51:41.480 align:middle line:84%
multiplying out
and combining, this

00:51:41.480 --> 00:51:50.000 align:middle line:84%
is equal to lambda 2 w2
plus lambda 1 w1-perp plus

00:51:50.000 --> 00:51:54.800 align:middle line:90%
lambda 2 times w2-perp.

00:51:54.800 --> 00:52:02.840 align:middle line:84%
Now, since w1 and w2 are in W,
this linear combination of them

00:52:02.840 --> 00:52:10.650 align:middle line:84%
is also in W. And
this part also,

00:52:10.650 --> 00:52:14.460 align:middle line:84%
since that's in the
orthogonal complement of W

00:52:14.460 --> 00:52:16.620 align:middle line:84%
and so is that, their
linear combination is also

00:52:16.620 --> 00:52:18.970 align:middle line:90%
in the orthogonal complement.

00:52:18.970 --> 00:52:27.030 align:middle line:84%
So the decomposition of this
linear combination of v1 and v2

00:52:27.030 --> 00:52:32.100 align:middle line:84%
is a linear combination
of the decompositions.

00:52:32.100 --> 00:52:41.680 align:middle line:84%
And therefore, by how
we define this map

00:52:41.680 --> 00:52:44.320 align:middle line:84%
as the part that's in W,
this is equal to lambda

00:52:44.320 --> 00:52:48.280 align:middle line:90%
1 w1 plus lambda 2 w2.

00:52:48.280 --> 00:52:52.055 align:middle line:84%
And w1, that's just pi sub W.
That's just the projection--

00:52:52.055 --> 00:52:53.680 align:middle line:84%
I'm calling it a
projection, although I

00:52:53.680 --> 00:52:56.680 align:middle line:90%
haven't proved that yet--

00:52:56.680 --> 00:53:00.070 align:middle line:84%
this thing applied to
v1 and w2 is this thing

00:53:00.070 --> 00:53:03.160 align:middle line:90%
applied to v2 by definition.

00:53:03.160 --> 00:53:05.825 align:middle line:90%
This is pi.

00:53:05.825 --> 00:53:08.680 align:middle line:90%


00:53:08.680 --> 00:53:14.550 align:middle line:90%
w2 is pi by definition.

00:53:14.550 --> 00:53:25.678 align:middle line:84%
So this is equal to lambda
1 v1 plus lambda 2 v2.

00:53:25.678 --> 00:53:27.095 align:middle line:84%
And therefore,
this map is linear.

00:53:27.095 --> 00:53:47.050 align:middle line:90%


00:53:47.050 --> 00:53:48.670 align:middle line:90%
OK, so it's linear.

00:53:48.670 --> 00:53:49.585 align:middle line:90%
Why is it bounded?

00:53:49.585 --> 00:53:52.830 align:middle line:90%


00:53:52.830 --> 00:54:06.660 align:middle line:84%
So now, pi is bounded to v
is equal to w plus w-perp.

00:54:06.660 --> 00:54:13.890 align:middle line:84%
w is, again, equal to pi of v.
Then because these two things

00:54:13.890 --> 00:54:17.850 align:middle line:84%
are orthogonal, I get
that norm of v squared

00:54:17.850 --> 00:54:22.960 align:middle line:84%
is equal to norm of w
plus w-perp squared.

00:54:22.960 --> 00:54:24.270 align:middle line:90%
And now, what do I pick up?

00:54:24.270 --> 00:54:34.981 align:middle line:84%
I pick up the norm of w squared
plus norm of w-perp squared

00:54:34.981 --> 00:54:38.225 align:middle line:84%
plus 2 times the real part
of the inner product of w

00:54:38.225 --> 00:54:38.970 align:middle line:90%
with w-perp.

00:54:38.970 --> 00:54:50.090 align:middle line:84%
But that's 0, so I just
get the sum of the norms.

00:54:50.090 --> 00:54:52.090 align:middle line:84%
And that's bigger
than or equal--

00:54:52.090 --> 00:54:55.090 align:middle line:84%
or since it's a sum of
two non-negative things,

00:54:55.090 --> 00:54:58.030 align:middle line:84%
that's bigger than
or equal to one

00:54:58.030 --> 00:55:00.010 align:middle line:90%
of them, which is w squared.

00:55:00.010 --> 00:55:10.030 align:middle line:84%
Or rephrasing, since w is
equal to pi applied to v,

00:55:10.030 --> 00:55:13.030 align:middle line:84%
I've said that this is less
than or equal to the norm of v

00:55:13.030 --> 00:55:19.130 align:middle line:84%
so that pi is a bounded
linear operator.

00:55:19.130 --> 00:55:28.430 align:middle line:90%


00:55:28.430 --> 00:55:30.260 align:middle line:84%
In fact, what we've
shown is that its norm

00:55:30.260 --> 00:55:33.300 align:middle line:90%
is less than or equal to 1.

00:55:33.300 --> 00:55:36.900 align:middle line:84%
OK, and finally, so the last
piece that we need to check

00:55:36.900 --> 00:55:38.730 align:middle line:90%
is that pi squared equals pi.

00:55:38.730 --> 00:55:40.410 align:middle line:90%
But that's pretty easy to check.

00:55:40.410 --> 00:55:46.524 align:middle line:90%


00:55:46.524 --> 00:56:00.080 align:middle line:84%
We simply note that if v is
equal to w plus w-perp, then

00:56:00.080 --> 00:56:03.890 align:middle line:84%
I need to check that
I get pi w of v again.

00:56:03.890 --> 00:56:10.070 align:middle line:84%
So this is equal to the
part of this that's in w.

00:56:10.070 --> 00:56:14.480 align:middle line:84%
Now, this is equal
to w, little w.

00:56:14.480 --> 00:56:19.310 align:middle line:84%
And again, this picks out the
part of the element in here

00:56:19.310 --> 00:56:22.490 align:middle line:84%
that's in capital W. But
this is in capital W.

00:56:22.490 --> 00:56:25.820 align:middle line:90%
So this is just equal to w.

00:56:25.820 --> 00:56:32.330 align:middle line:84%
And this is, by definition
again, equal to pi of v

00:56:32.330 --> 00:56:52.750 align:middle line:84%
So we've shown that pi
squared of v equals pi of v.

00:56:52.750 --> 00:56:55.850 align:middle line:84%
OK, so one last
application we'll

00:56:55.850 --> 00:56:59.810 align:middle line:84%
do of minimizers,
which is probably

00:56:59.810 --> 00:57:04.070 align:middle line:84%
the most important
application, which

00:57:04.070 --> 00:57:06.680 align:middle line:84%
one could prove for
separable Hilbert spaces

00:57:06.680 --> 00:57:12.290 align:middle line:84%
based on what we know
and have done so far.

00:57:12.290 --> 00:57:22.110 align:middle line:84%
But this proof works also for
non-separable Hilbert spaces.

00:57:22.110 --> 00:57:25.070 align:middle line:84%
And OK, so what is this
theorem I'm referring to?

00:57:25.070 --> 00:57:27.860 align:middle line:84%
It's probably one of the
most important theorems

00:57:27.860 --> 00:57:29.180 align:middle line:90%
in all of this business.

00:57:29.180 --> 00:57:31.025 align:middle line:84%
It's the Riesz
representation theorem.

00:57:31.025 --> 00:57:41.450 align:middle line:90%


00:57:41.450 --> 00:57:43.710 align:middle line:84%
OK, so the only
category theory I know

00:57:43.710 --> 00:57:45.030 align:middle line:90%
is the Baire category theorem.

00:57:45.030 --> 00:57:46.890 align:middle line:84%
The only representation
theory I remember

00:57:46.890 --> 00:57:52.020 align:middle line:84%
is the Riesz representation
theorem, which tells us we

00:57:52.020 --> 00:57:55.860 align:middle line:84%
can identify a Hilbert space,
the dual of a Hilbert space

00:57:55.860 --> 00:57:58.960 align:middle line:90%
with the Hilbert space itself.

00:57:58.960 --> 00:58:20.820 align:middle line:84%
So if H is a Hilbert space,
then for all f in the dual,

00:58:20.820 --> 00:58:32.713 align:middle line:84%
there exists a unique element
v in H such that f of u--

00:58:32.713 --> 00:58:34.130 align:middle line:84%
so this is an
element in the dual,

00:58:34.130 --> 00:58:37.190 align:middle line:84%
meaning it takes u
to a complex number--

00:58:37.190 --> 00:58:39.320 align:middle line:84%
and is linear in
u, you can write it

00:58:39.320 --> 00:58:48.780 align:middle line:84%
as u inner product with
this element v All right,

00:58:48.780 --> 00:58:55.260 align:middle line:84%
so every element
of the dual can be

00:58:55.260 --> 00:59:01.210 align:middle line:84%
realized as the inner
product with a vector.

00:59:01.210 --> 00:59:04.793 align:middle line:84%
Now, we saw this in a
certain form already in,

00:59:04.793 --> 00:59:06.960 align:middle line:84%
I think, it was maybe the
first or second assignment

00:59:06.960 --> 00:59:09.240 align:middle line:90%
when you computed the--

00:59:09.240 --> 00:59:12.540 align:middle line:84%
or proved that the
dual space of little lp

00:59:12.540 --> 00:59:16.620 align:middle line:84%
is a little lq, where 1 over
p plus 1 over q equals 1.

00:59:16.620 --> 00:59:20.040 align:middle line:90%
When p equals 2, q is 2.

00:59:20.040 --> 00:59:25.830 align:middle line:84%
So you saw that the dual space
could be identified with itself

00:59:25.830 --> 00:59:30.720 align:middle line:84%
when we're looking at little l2,
which is the only Hilbert space

00:59:30.720 --> 00:59:34.290 align:middle line:90%
out of all the little lp's.

00:59:34.290 --> 00:59:39.810 align:middle line:84%
And remember, how we proved that
little lq was dual to little lp

00:59:39.810 --> 00:59:45.030 align:middle line:84%
was via pairing between
the two, which specifically

00:59:45.030 --> 00:59:49.155 align:middle line:84%
was the sum of the sequences
multiplied entry by entry.

00:59:49.155 --> 00:59:52.960 align:middle line:90%


00:59:52.960 --> 00:59:55.880 align:middle line:84%
And now, so this theorem
says that wasn't a fluke.

00:59:55.880 --> 00:59:57.880 align:middle line:84%
This is, in fact, true
for every Hilbert space,

00:59:57.880 --> 01:00:01.540 align:middle line:84%
that the dual can be identified
with the space itself

01:00:01.540 --> 01:00:06.280 align:middle line:84%
in this canonical way, where
every element of the dual

01:00:06.280 --> 01:00:08.950 align:middle line:84%
can be realized as taking the
inner product with a vector.

01:00:08.950 --> 01:00:16.490 align:middle line:90%


01:00:16.490 --> 01:00:17.380 align:middle line:90%
So for the proof--

01:00:17.380 --> 01:00:24.010 align:middle line:90%


01:00:24.010 --> 01:00:32.020 align:middle line:84%
so first off, we note
that v is unique.

01:00:32.020 --> 01:00:40.140 align:middle line:84%
If such a v exists, it's unique,
since if f of u is equal to u,

01:00:40.140 --> 01:00:48.820 align:middle line:84%
inner product v is equal to u,
inner product v-tilde for all u

01:00:48.820 --> 01:00:55.300 align:middle line:84%
implies that u inner
product v minus v-tilde

01:00:55.300 --> 01:01:02.740 align:middle line:84%
equals 0 for all u in
H, which, by setting

01:01:02.740 --> 01:01:10.330 align:middle line:84%
u equal to v minus v-tilde,
tells me v equals v-tilde.

01:01:10.330 --> 01:01:13.120 align:middle line:84%
All right, so all we need
to do is come up with--

01:01:13.120 --> 01:01:16.810 align:middle line:84%
given an element of the
dual, come up with a vector

01:01:16.810 --> 01:01:23.325 align:middle line:84%
that whenever I stick a
u into the dual vector,

01:01:23.325 --> 01:01:24.700 align:middle line:84%
it's equal to this
inner product.

01:01:24.700 --> 01:01:27.380 align:middle line:90%


01:01:27.380 --> 01:01:30.835 align:middle line:84%
OK, so the easiest case to deal
with is, of course, f equals 0.

01:01:30.835 --> 01:01:33.700 align:middle line:90%


01:01:33.700 --> 01:01:37.480 align:middle line:84%
In other words, it maps u
to 0 no matter what u is.

01:01:37.480 --> 01:01:41.440 align:middle line:84%
We just choose
this vector that--

01:01:41.440 --> 01:01:43.300 align:middle line:84%
we just choose this
vector v to be 0.

01:01:43.300 --> 01:01:48.130 align:middle line:84%
Then we'll always have f of
u equal to u inner product

01:01:48.130 --> 01:01:49.045 align:middle line:90%
with the 0 vector.

01:01:49.045 --> 01:01:54.280 align:middle line:90%


01:01:54.280 --> 01:02:05.835 align:middle line:84%
So suppose now f
does not equal 0.

01:02:05.835 --> 01:02:08.530 align:middle line:90%


01:02:08.530 --> 01:02:18.400 align:middle line:84%
Then there exists, let's say,
a u1 in H such that f of u1

01:02:18.400 --> 01:02:21.160 align:middle line:90%
does not equal 0.

01:02:21.160 --> 01:02:30.200 align:middle line:84%
Then if I take u0 to
be u1 over f of u1,

01:02:30.200 --> 01:02:34.730 align:middle line:84%
this implies that
f of u0 equals 1.

01:02:34.730 --> 01:02:40.960 align:middle line:90%


01:02:40.960 --> 01:02:52.270 align:middle line:84%
OK, so now, let C b e
the set of all elements

01:02:52.270 --> 01:03:01.108 align:middle line:84%
u in H which give me 1 when
I stick it into F. Now,

01:03:01.108 --> 01:03:02.650 align:middle line:84%
this set is non-empty,
because I just

01:03:02.650 --> 01:03:06.910 align:middle line:84%
gave you an element that when
I stick it into f gives me 1.

01:03:06.910 --> 01:03:09.500 align:middle line:90%
So this is non-empty.

01:03:09.500 --> 01:03:11.050 align:middle line:90%
And what is this?

01:03:11.050 --> 01:03:14.830 align:middle line:84%
Actually, this is
the inverse image

01:03:14.830 --> 01:03:21.820 align:middle line:84%
of the singleton in the
set of complex numbers.

01:03:21.820 --> 01:03:23.980 align:middle line:84%
Now, a singleton
is a closed set.

01:03:23.980 --> 01:03:26.290 align:middle line:84%
f is a continuous
function, right?

01:03:26.290 --> 01:03:28.720 align:middle line:84%
An element of the dual
is a bounded linear map--

01:03:28.720 --> 01:03:33.930 align:middle line:84%
or bounded linear map
from the Hilbert space

01:03:33.930 --> 01:03:34.958 align:middle line:90%
to the complex numbers.

01:03:34.958 --> 01:03:36.250 align:middle line:90%
And therefore, it's continuous.

01:03:36.250 --> 01:03:39.960 align:middle line:84%
So the inverse image by
a continuous function

01:03:39.960 --> 01:03:41.490 align:middle line:90%
of a closed set is closed.

01:03:41.490 --> 01:03:42.615 align:middle line:90%
So this is also closed.

01:03:42.615 --> 01:03:46.710 align:middle line:90%


01:03:46.710 --> 01:04:01.507 align:middle line:84%
So C is that, which is a
non-empty closed subset of H.

01:04:01.507 --> 01:04:02.840 align:middle line:90%
You can see where this is going.

01:04:02.840 --> 01:04:07.640 align:middle line:84%
Now, let's check
that C is convex.

01:04:07.640 --> 01:04:11.320 align:middle line:90%
That writing is a bit skewed.

01:04:11.320 --> 01:04:19.350 align:middle line:84%
Now, if u1, u2 are
in C, t is in 0, 1,

01:04:19.350 --> 01:04:28.770 align:middle line:84%
then f of t times u1 plus 1
minus t u2, this is equal to--

01:04:28.770 --> 01:04:30.040 align:middle line:90%
now, f is linear.

01:04:30.040 --> 01:04:38.610 align:middle line:84%
So this is equal to t times f
of u1 plus 1 minus t f of u2.

01:04:38.610 --> 01:04:41.220 align:middle line:90%
Now, this is equal to 1.

01:04:41.220 --> 01:04:44.420 align:middle line:90%
That's equal to 1.

01:04:44.420 --> 01:04:45.110 align:middle line:90%
So I get 1.

01:04:45.110 --> 01:04:46.370 align:middle line:90%
So C is also convex.

01:04:46.370 --> 01:04:58.380 align:middle line:90%


01:04:58.380 --> 01:05:01.370 align:middle line:84%
Now, you can see how
the proof is going.

01:05:01.370 --> 01:05:06.540 align:middle line:90%
But we might guess that--

01:05:06.540 --> 01:05:09.910 align:middle line:84%
if you're just looking at the
proof, why am I doing this?

01:05:09.910 --> 01:05:13.915 align:middle line:84%
Well, in fact, almost
the minimum vector,

01:05:13.915 --> 01:05:15.540 align:middle line:84%
or the vector with
the smallest length,

01:05:15.540 --> 01:05:20.680 align:middle line:84%
will be the vector that
satisfies that inequality.

01:05:20.680 --> 01:05:27.990 align:middle line:84%
So since C is a closed,
convex, non-empty set,

01:05:27.990 --> 01:05:39.180 align:middle line:84%
there exists a v0 in C such
that v0 is equal to the inf

01:05:39.180 --> 01:05:46.960 align:middle line:84%
of, let's say, u
in C such that--

01:05:46.960 --> 01:05:48.780 align:middle line:84%
so we're looking
at the norm of u.

01:05:48.780 --> 01:05:54.120 align:middle line:90%


01:05:54.120 --> 01:06:05.810 align:middle line:84%
So let v equal norm of v0
over norm squared of v0.

01:06:05.810 --> 01:06:10.070 align:middle line:84%
So first off, note that
v0 cannot be 0, right?

01:06:10.070 --> 01:06:13.280 align:middle line:84%
If v0 is 0, then f
of v0 is equal to 0.

01:06:13.280 --> 01:06:17.300 align:middle line:84%
But v0 is in C. f
of v0 has to be 1.

01:06:17.300 --> 01:06:18.170 align:middle line:90%
So v0 is non-zero.

01:06:18.170 --> 01:06:23.140 align:middle line:90%


01:06:23.140 --> 01:06:24.865 align:middle line:90%
And I claim this v does a job.

01:06:24.865 --> 01:06:33.570 align:middle line:90%


01:06:33.570 --> 01:06:37.410 align:middle line:84%
For all-- OK, I was using
u's to denote elements in C.

01:06:37.410 --> 01:06:39.420 align:middle line:90%
But claim--

01:06:39.420 --> 01:06:42.930 align:middle line:90%
I'll just write does a job--

01:06:42.930 --> 01:06:46.690 align:middle line:90%


01:06:46.690 --> 01:06:50.170 align:middle line:84%
i.e. for all u in
capital H, f of u

01:06:50.170 --> 01:06:55.857 align:middle line:84%
is equal to u inner
product with v.

01:06:55.857 --> 01:07:06.910 align:middle line:84%
All right, to see that,
let N be the null space

01:07:06.910 --> 01:07:11.530 align:middle line:84%
of f, the set of all vectors
that get sent to the number 0.

01:07:11.530 --> 01:07:19.360 align:middle line:84%
So this is a set of all w in
H such that f of w equals 0.

01:07:19.360 --> 01:07:24.520 align:middle line:84%
This is a closed
linear subspace of N--

01:07:24.520 --> 01:07:25.295 align:middle line:90%
I mean of h.

01:07:25.295 --> 01:07:28.380 align:middle line:90%


01:07:28.380 --> 01:07:31.920 align:middle line:84%
Then it's not too difficult
to convince yourself

01:07:31.920 --> 01:07:38.490 align:middle line:84%
that I can write C as,
in fact, v0 plus w, where

01:07:38.490 --> 01:07:41.625 align:middle line:90%
w is in this subspace.

01:07:41.625 --> 01:07:45.030 align:middle line:90%


01:07:45.030 --> 01:07:45.780 align:middle line:90%
And what is v0?

01:07:45.780 --> 01:07:50.980 align:middle line:84%
Again, v0 is the infimum of
the norms of all of these guys.

01:07:50.980 --> 01:08:00.230 align:middle line:84%
So it's equal to
the infimum over,

01:08:00.230 --> 01:08:08.770 align:middle line:84%
if I'm writing C in that
way, w in N norm v0 plus w.

01:08:08.770 --> 01:08:12.330 align:middle line:90%


01:08:12.330 --> 01:08:15.300 align:middle line:90%
All right, why am I doing this?

01:08:15.300 --> 01:08:17.609 align:middle line:84%
Because of the argument
we gave a minute ago,

01:08:17.609 --> 01:08:23.399 align:middle line:84%
I can conclude that v0 is
orthogonal to everything in n.

01:08:23.399 --> 01:08:27.359 align:middle line:84%
So by the previous argument,
I mean, look back at--

01:08:27.359 --> 01:08:28.859 align:middle line:90%
is it up there or--

01:08:28.859 --> 01:08:31.380 align:middle line:84%
no, it was on this
board and I erased it.

01:08:31.380 --> 01:08:35.250 align:middle line:84%
But where we define
this function

01:08:35.250 --> 01:08:37.970 align:middle line:84%
f of t equal to--
in this case, it

01:08:37.970 --> 01:08:40.890 align:middle line:90%
would be v0 plus t w squared.

01:08:40.890 --> 01:08:43.109 align:middle line:84%
Since that has a
minimum at t equals 0,

01:08:43.109 --> 01:08:46.410 align:middle line:84%
we conclude that v0
is orthogonal to W.

01:08:46.410 --> 01:08:55.420 align:middle line:84%
So by previous
argument for when we

01:08:55.420 --> 01:08:58.779 align:middle line:84%
showed that H can be written
as W plus its orthogonal--

01:08:58.779 --> 01:09:01.490 align:middle line:84%
the direct sum of a
closed linear subspace

01:09:01.490 --> 01:09:02.740 align:middle line:90%
and its orthogonal complement.

01:09:02.740 --> 01:09:07.720 align:middle line:84%
So by the previous
argument from that proof,

01:09:07.720 --> 01:09:12.250 align:middle line:84%
we can show that
v0 is an element

01:09:12.250 --> 01:09:15.370 align:middle line:84%
of the orthogonal
complement of N,

01:09:15.370 --> 01:09:17.875 align:middle line:84%
the set of all vectors
that get sent to 0.

01:09:17.875 --> 01:09:24.887 align:middle line:90%


01:09:24.887 --> 01:09:25.845 align:middle line:90%
Now, we're almost done.

01:09:25.845 --> 01:09:30.060 align:middle line:90%


01:09:30.060 --> 01:09:36.240 align:middle line:84%
So let u be in H. I
want to show that f of u

01:09:36.240 --> 01:09:40.625 align:middle line:90%
is equal to v inner product u.

01:09:40.625 --> 01:09:47.340 align:middle line:84%
I just needed that
little bit of fact there.

01:09:47.340 --> 01:09:57.280 align:middle line:84%
So remember, then if I look
at f of u minus f of u v0,

01:09:57.280 --> 01:09:59.590 align:middle line:84%
this is equal to-- so
f is linear, remember?

01:09:59.590 --> 01:10:00.880 align:middle line:90%
So scalars pop out.

01:10:00.880 --> 01:10:03.740 align:middle line:90%
This is just a complex number.

01:10:03.740 --> 01:10:11.020 align:middle line:84%
So this is equal to f of
u minus f of u f of v0.

01:10:11.020 --> 01:10:12.430 align:middle line:90%
This equals 0, right?

01:10:12.430 --> 01:10:19.700 align:middle line:90%


01:10:19.700 --> 01:10:29.530 align:middle line:84%
And therefore, u, which is
equal to u minus f of u v0

01:10:29.530 --> 01:10:32.590 align:middle line:90%
plus f of u v0--

01:10:32.590 --> 01:10:38.170 align:middle line:84%
now, this thing here, because
f applied to it gives me 0,

01:10:38.170 --> 01:10:45.010 align:middle line:84%
this is in N. And
this is in, again

01:10:45.010 --> 01:10:48.008 align:middle line:84%
remember, N-perp,
although I'm not

01:10:48.008 --> 01:10:49.300 align:middle line:90%
going to use that specifically.

01:10:49.300 --> 01:10:51.700 align:middle line:84%
I'm going to use the fact
that v0 inner product

01:10:51.700 --> 01:10:56.790 align:middle line:90%
with everything from N is 0.

01:10:56.790 --> 01:10:59.810 align:middle line:90%


01:10:59.810 --> 01:11:06.290 align:middle line:84%
And therefore, if I take the
inner product of u with v--

01:11:06.290 --> 01:11:11.120 align:middle line:84%
remember, v was v0
over v0 squared--

01:11:11.120 --> 01:11:21.580 align:middle line:84%
this is equal to u 1 over v0
squared inner product u v0.

01:11:21.580 --> 01:11:26.180 align:middle line:84%
This is equal to 1
over norm v0 squared.

01:11:26.180 --> 01:11:32.200 align:middle line:84%
Now, again, this
element is in N.

01:11:32.200 --> 01:11:35.380 align:middle line:84%
So when I take the inner
product of this line

01:11:35.380 --> 01:11:41.410 align:middle line:84%
with v0, when v0 hits this,
I get 0 because it's in N.

01:11:41.410 --> 01:11:49.900 align:middle line:84%
So if you like, call this--
so call this thing w,

01:11:49.900 --> 01:12:00.330 align:middle line:84%
which is in N. So this is equal
to w inner product v0 plus f

01:12:00.330 --> 01:12:05.820 align:middle line:90%
of u v0 inner product v0.

01:12:05.820 --> 01:12:09.270 align:middle line:84%
And again, this
thing is in N. v0

01:12:09.270 --> 01:12:14.826 align:middle line:84%
is in the orthogonal
complement of N.

01:12:14.826 --> 01:12:25.480 align:middle line:84%
So this inner product
is 0 times f of u times

01:12:25.480 --> 01:12:30.010 align:middle line:84%
v0 inner product with
itself is the norm squared.

01:12:30.010 --> 01:12:31.120 align:middle line:90%
And I get f of u.

01:12:31.120 --> 01:12:34.720 align:middle line:90%


01:12:34.720 --> 01:12:41.020 align:middle line:84%
So I have found a vector,
namely this certain minimizer

01:12:41.020 --> 01:12:43.810 align:middle line:84%
over its length
squared so that f of u

01:12:43.810 --> 01:12:47.500 align:middle line:84%
is equal to u inner product
with this vector for all u in H.

01:12:47.500 --> 01:12:49.910 align:middle line:84%
And that completes the proof
of the Riesz representation

01:12:49.910 --> 01:12:50.410 align:middle line:90%
theorem.

01:12:50.410 --> 01:12:54.440 align:middle line:90%


01:12:54.440 --> 01:12:58.700 align:middle line:84%
Now, next time, we'll
talk about adjoints,

01:12:58.700 --> 01:13:03.050 align:middle line:84%
which you had on an
assignment at one point

01:13:03.050 --> 01:13:05.510 align:middle line:90%
when we were talking about--

01:13:05.510 --> 01:13:08.165 align:middle line:84%
I think I defined the adjoint
for a general Banach space.

01:13:08.165 --> 01:13:11.870 align:middle line:90%


01:13:11.870 --> 01:13:17.530 align:middle line:84%
So if you have a map, let's say,
from a Banach space to itself,

01:13:17.530 --> 01:13:21.140 align:middle line:84%
then we define the
adjoint, in a certain way,

01:13:21.140 --> 01:13:24.740 align:middle line:84%
to be now a linear map that
goes from the dual space

01:13:24.740 --> 01:13:27.140 align:middle line:90%
to the dual space.

01:13:27.140 --> 01:13:28.940 align:middle line:84%
Now, in the case
of a Hilbert space,

01:13:28.940 --> 01:13:31.770 align:middle line:84%
the dual space is equal
to the space itself.

01:13:31.770 --> 01:13:33.800 align:middle line:84%
So the adjoint for
a Hilbert space

01:13:33.800 --> 01:13:37.550 align:middle line:84%
will be a map, again,
from the space to itself.

01:13:37.550 --> 01:13:42.900 align:middle line:84%
And it will satisfy
a certain identity.

01:13:42.900 --> 01:13:48.910 align:middle line:84%
And we will see the
connection between adjoints

01:13:48.910 --> 01:14:01.880 align:middle line:84%
and what this has to
do with when a map is--

01:14:01.880 --> 01:14:03.800 align:middle line:84%
or a bounded linear
operator is onto.

01:14:03.800 --> 01:14:08.240 align:middle line:84%
So adjoints pop up now when
we're trying to solve equations

01:14:08.240 --> 01:14:10.010 align:middle line:90%
on Hilbert spaces.

01:14:10.010 --> 01:14:11.960 align:middle line:84%
The properties of the
adjoint can tell us

01:14:11.960 --> 01:14:15.260 align:middle line:84%
when we can always
solve our equation.

01:14:15.260 --> 01:14:19.430 align:middle line:84%
And not only that,
they're going to end up--

01:14:19.430 --> 01:14:25.480 align:middle line:84%
they're the analog of the
transpose that hopefully you

01:14:25.480 --> 01:14:25.980 align:middle line:90%
saw.

01:14:25.980 --> 01:14:30.340 align:middle line:84%
Maybe it was also referred to
the adjoint in linear algebra

01:14:30.340 --> 01:14:31.680 align:middle line:90%
on finite dimensions.

01:14:31.680 --> 01:14:34.780 align:middle line:90%


01:14:34.780 --> 01:14:38.570 align:middle line:90%
And so this is way ahead.

01:14:38.570 --> 01:14:42.050 align:middle line:84%
But hopefully, what you
proved in linear algebra

01:14:42.050 --> 01:14:44.370 align:middle line:84%
and finite dimensions
was the spectral theorem,

01:14:44.370 --> 01:14:57.162 align:middle line:84%
which that if you have a matrix
that is equal to its adjoint--

01:14:57.162 --> 01:14:58.870 align:middle line:84%
more generally, that
it's normal, that it

01:14:58.870 --> 01:15:00.130 align:middle line:90%
commutes with this adjoint--

01:15:00.130 --> 01:15:04.840 align:middle line:84%
then-- and for
finite dimensions,

01:15:04.840 --> 01:15:07.900 align:middle line:84%
the adjoint of a matrix
was switched the entries,

01:15:07.900 --> 01:15:10.300 align:middle line:84%
switch i and j and take
the complex conjugate.

01:15:10.300 --> 01:15:12.910 align:middle line:84%
If that's equal to
the matrix again,

01:15:12.910 --> 01:15:18.110 align:middle line:84%
then what you can
conclude, the statement

01:15:18.110 --> 01:15:19.760 align:middle line:84%
of the spectral
theorem is that you

01:15:19.760 --> 01:15:26.210 align:middle line:84%
can find an orthonormal
basis of Cn, say, or Rn,

01:15:26.210 --> 01:15:30.830 align:middle line:90%
that diagonalizes the matrix.

01:15:30.830 --> 01:15:37.950 align:middle line:84%
And we'll see something like
that also holds in the Hilbert

01:15:37.950 --> 01:15:42.350 align:middle line:84%
space setting, but
it's not so simple

01:15:42.350 --> 01:15:46.100 align:middle line:84%
as the eigenvalues--
as diagonalizing just

01:15:46.100 --> 01:15:48.560 align:middle line:84%
does not mean finitely
many eigenvalues.

01:15:48.560 --> 01:15:53.180 align:middle line:90%
And we'll go over more of--

01:15:53.180 --> 01:15:55.790 align:middle line:84%
I'll go more into that
when we get to it.

01:15:55.790 --> 01:15:58.300 align:middle line:84%
All right, we'll
stop there for now.

01:15:58.300 --> 01:16:04.000 align:middle line:90%