WEBVTT

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PROFESSOR: OK, so ortho--

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today, we're going to be
discussing orthonormal bases

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of a Hilbert space.

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So let me just recall what we
did at the end of last time.

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We introduced maximal
orthonormal sets, so

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a collection of vectors in a--

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we could say a
pre-Hilbert space,

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but let's say in
a Hilbert space.

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So this is maximal
if u in H and u,

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e lambda equals 0 for
all lambda in the index

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implies that u equals 0.

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So a collection of--

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so I should say that a
collection of orthonormal--

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orthonormal vectors is
maximal if the only thing

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that's orthogonal to all
of them is the zero vector.

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And last time, we proved that--

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let H be a separable
Hilbert space,

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meaning it has a
countable dense subset .

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Most-- I mean, I think
all of the Hilbert spaces

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you've come into contact
with are separable.

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Cn, Rn, also little l2, big L2--

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this is what you're
doing in the assignment.

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That's also separable-- then
H has a countable maximal

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orthonormal subset, e sub n.

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So we proved this at
the end of last time

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via the Gram-Schmidt process.

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We took a countable
collection of--

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a countable collection of
elements in the Hilbert space,

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which were dense.

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And then we formed this
countable orthonormal subset.

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And I shouldn't
put N in, capital

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N because this could
be a finite collection

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or it could be countably
infinite collection.

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But then we applied the
Gram-Schmidt process

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to that collection
of dense elements

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and came up with this
maximal orthonormal subset.

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Now, we have a special name for
countable maximal orthonormal

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subsets for a good
reason as we'll see.

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So let H be a Hilbert space.

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An orthonormal basis of H is a
countable maximal orthonormal

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subset--

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I shouldn't say n and N again--

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of H. So an orthonormal
basis is just a special name

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that we give to those maximal
orthonormal subsets which

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are countable, meaning they can
be either finite or countably

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infinite.

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So again, all of the Hilbert
spaces we've encountered

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in practice-- for example,
Cn, little l2, big L2,

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which are all separable, meaning
they do have countable maximal

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orthonormal subset, meaning
they have an orthonormal basis--

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so they have these objects.

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Now, why do we call--

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why do we call a
countable orthonormal--

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or a countable maximal
orthonormal subset an

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all orthonormal basis?

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So a basis is supposed
to be something

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where you can write
every vector in the space

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as some sort of linear
combination of the elements

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of the basis, right?

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Now, we dealt with Hamel basis--

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or bases, which are you
can write every element

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as a finite linear combination
of the elements in this subset.

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Now, in this setting, in
what sense is this a basis?

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Or what is-- I shouldn't
say, is it a basis?

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But in what sense
does this connect

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to what we've encountered,
say, in finite dimensions?

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An orthonormal basis-- so as
stated in the next theorem,

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every element can
be written now as

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an infinite linear
combination of elements

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of an orthonormal basis,
not necessarily finite.

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So the statement
is the following--

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if en is an orthonormal
basis in the Hilbert space H,

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then for all u in H, if I
look at the partial sum, un

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inner product e sub n, e
sub n, this converges as n

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goes to infinity to the
element u in the space H.

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Written in shorter form is
that u is equal to sum from n

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equals 1 to infinity of u
inner product e sub n, e sub n.

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Sometimes, this is referred
to as a Fourier-Bessel series.

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So just like in
finite dimensions,

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if you have an orthonormal
basis consisting

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of only finitely many
vectors, then you

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can expand every vector in
that, say, Cn in this way.

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Now, the statement is,
in a Hilbert space,

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if you have an orthonormal
basis in this sense,

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meaning it's a countable
maximal or orthonormal subset,

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then you can expand
every element

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as an infinite linear
combination of these elements.

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OK, so to prove this, we
will use Bessel's inequality

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and the completeness
of H. This is

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where we're using the fact that
H is not a pre-Hilbert space,

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but a Hilbert space, all right?

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What we're going to do is we're
going to be able to show that

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the right-hand side
of this equality--

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so we're going to be able to
show that this series here

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converges in H.
That uses Bessel's

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inequality and the fact
that H is a Hilbert space

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converges to some element.

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And then we're going to use the
fact that this collection is

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maximal to show that the
inner product of whatever this

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defines with each
element e sub n is

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the same as the inner product of
this thing with each element e

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sub n, and then conclude that
this thing on the right side

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has to equal this thing.

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All right, so if
we first prove that

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the sequence of partial sums--

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so m is Cauchy.

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So let epsilon be positive.

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So by Bessel's inequality,
we have that the sum of n

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equals 1 to infinity
of u squared--

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this thing converges.

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So the only thing
we have to check

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is that, since this
is a series involving

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non-negative terms, that
this thing is bounded above.

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And we have by
Bessel's inequality

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that this is always bounded
above by the norm of u squared.

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So this sum, this series
converges to a finite number.

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In particular, the series--

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the partial sums
corresponding to this series

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is a Cauchy sequence
of real numbers,

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of non-negative real numbers.

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Thus, there exists an N natural
number such that for all--

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let's see-- all N bigger
than or equal to M,

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we have that the tail
is small, meaning n

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equals N plus 1 infinity
of less than epsilon.

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You can just look back into your
18.100 notes or whatever that

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if I have a series of
non-negative terms which

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converges, then
for every epsilon,

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I can find a capital
N so that the tail,

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so starting the sum at a large
enough entry, will be small.

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Then for all m greater than l
greater than this capital M,

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if I compute the norm
of n equals 1 to m u

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inner product e sub n, e sub
n minus N equals 1 to l u

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e sub n, e sub n squared.

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And let's make this a square.

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I can do that.

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This you can just compute.

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Expanding this out as the inner
product of this whole thing

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with itself, this gives you
sum from n equals l plus 1 to m

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of u en squared.

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And since l is bigger
than or equal to m,

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this is certainly less
than or equal to--

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well, I can put infinity
here. n equals l

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plus 1 u inner product
e sub n squared.

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And that's less
than-- since l is

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bigger than or equal to capital
M, we can use this inequality.

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And that's less than
epsilon squared.

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So we've shown that for n and l
bigger than or equal to capital

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M, the norm squared
of the difference

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is less than epsilon squared.

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And therefore, the
norm of the difference

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is less than epsilon,
proving that the sequence

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of partial sums is Cauchy.

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OK, so we've proven that
the sequence of partial sums

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is Cauchy.

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So since H is
complete, there exists

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an element u in H
such that u-bar is

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equal to limit as
n goes to infinity

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equals 1 m of these partial
sums, where this limit means

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that the norm of the
difference in H converges to 0.

00:14:47.705 --> 00:14:51.690 align:middle line:90%


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And so just in shorthand,
again, this means--

00:14:55.110 --> 00:15:02.140 align:middle line:90%


00:15:02.140 --> 00:15:06.310 align:middle line:84%
now, what I'd like to do is
show that u-bar equals u.

00:15:06.310 --> 00:15:07.750 align:middle line:90%
I don't mean complex conjugate.

00:15:07.750 --> 00:15:14.500 align:middle line:90%
I just mean an element of H.

00:15:14.500 --> 00:15:17.230 align:middle line:84%
And now, how we're
going to do that is show

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that the inner product
of u minus u-bar

00:15:21.400 --> 00:15:25.600 align:middle line:84%
against every element of this
maximal orthonormal subset

00:15:25.600 --> 00:15:29.650 align:middle line:84%
is 0, and therefore
conclude u equals u-bar.

00:15:29.650 --> 00:15:33.550 align:middle line:84%
Now, we have this result,
that the inner product

00:15:33.550 --> 00:15:38.450 align:middle line:84%
is continuous with
respect to the entry.

00:15:38.450 --> 00:15:43.250 align:middle line:84%
So by continuity of
the inner product,

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we have that the
inner product of u--

00:15:47.590 --> 00:15:51.670 align:middle line:84%
so let me-- so then for
all l natural number,

00:15:51.670 --> 00:15:57.820 align:middle line:84%
the inner product of
u minus u-bar with el,

00:15:57.820 --> 00:16:00.730 align:middle line:90%
this is equal to--

00:16:00.730 --> 00:16:02.620 align:middle line:84%
u-bar is equal to
the limit as m goes

00:16:02.620 --> 00:16:05.200 align:middle line:84%
to infinity of this
partial sum in H.

00:16:05.200 --> 00:16:09.580 align:middle line:84%
So this inner product
is equal to the limit

00:16:09.580 --> 00:16:17.580 align:middle line:84%
as m goes to infinity of u minus
sum from n equals 1 to m of u

00:16:17.580 --> 00:16:23.110 align:middle line:90%
en, en inner product el.

00:16:23.110 --> 00:16:26.140 align:middle line:90%
And this is also--

00:16:26.140 --> 00:16:28.140 align:middle line:84%
I mean, I'm sure you've
seen this at some point.

00:16:28.140 --> 00:16:30.350 align:middle line:84%
But this is also why the
coefficients appearing

00:16:30.350 --> 00:16:34.770 align:middle line:84%
in front of the en's
are the way they are.

00:16:34.770 --> 00:16:38.270 align:middle line:84%
So this is equal
to the limit as m

00:16:38.270 --> 00:16:45.860 align:middle line:84%
goes to infinity of u inner
product el minus the sum from n

00:16:45.860 --> 00:16:54.230 align:middle line:84%
equals 1 to m of u en,
en inner product el.

00:16:54.230 --> 00:16:58.440 align:middle line:90%


00:16:58.440 --> 00:17:02.280 align:middle line:84%
And when n does not
equal l-- so remember,

00:17:02.280 --> 00:17:04.230 align:middle line:90%
these are orthonormal.

00:17:04.230 --> 00:17:06.240 align:middle line:84%
When n does not
equal l, I get 0.

00:17:06.240 --> 00:17:08.010 align:middle line:90%
And when n equals l, I get 1.

00:17:08.010 --> 00:17:09.869 align:middle line:90%
So all I pick up is u--

00:17:09.869 --> 00:17:12.670 align:middle line:90%


00:17:12.670 --> 00:17:16.750 align:middle line:84%
this just reduces to u
inner product el, which

00:17:16.750 --> 00:17:18.326 align:middle line:90%
cancels with that one.

00:17:18.326 --> 00:17:19.284 align:middle line:90%
And therefore, I get 0.

00:17:19.284 --> 00:17:22.800 align:middle line:90%


00:17:22.800 --> 00:17:26.250 align:middle line:84%
All right, so I've shown
that for every l, u

00:17:26.250 --> 00:17:29.670 align:middle line:84%
minus u-bar inner
product with el is 0.

00:17:29.670 --> 00:17:46.350 align:middle line:84%
And since this collection
is maximal, anything

00:17:46.350 --> 00:17:48.780 align:middle line:90%
that inner product with--

00:17:48.780 --> 00:17:53.250 align:middle line:84%
so the only element that's
orthogonal to every element

00:17:53.250 --> 00:17:55.680 align:middle line:90%
in this collection is 0.

00:17:55.680 --> 00:17:59.490 align:middle line:84%
That implies that u
minus u-bar equals 0.

00:17:59.490 --> 00:18:04.410 align:middle line:84%
And therefore, u equals
u-bar, which means

00:18:04.410 --> 00:18:09.345 align:middle line:90%
u is equal to this series.

00:18:09.345 --> 00:18:21.300 align:middle line:90%


00:18:21.300 --> 00:18:35.420 align:middle line:84%
OK, so we've shown that
if a Hilbert space has

00:18:35.420 --> 00:18:38.750 align:middle line:84%
an orthonormal basis,
then every element

00:18:38.750 --> 00:18:42.800 align:middle line:84%
can be expanded in
what's typically

00:18:42.800 --> 00:18:46.520 align:middle line:84%
referred to as a Fourier-Bessel
series in this way,

00:18:46.520 --> 00:18:51.850 align:middle line:84%
in terms of the elements
of the orthonormal basis.

00:18:51.850 --> 00:19:05.420 align:middle line:84%
Now, let me just
tie one thing up.

00:19:05.420 --> 00:19:08.150 align:middle line:84%
So we know that every
separable Hilbert space

00:19:08.150 --> 00:19:12.788 align:middle line:84%
does have an orthonormal
basis, a countable maximal

00:19:12.788 --> 00:19:13.580 align:middle line:90%
orthonormal subset.

00:19:13.580 --> 00:19:17.120 align:middle line:90%


00:19:17.120 --> 00:19:20.000 align:middle line:84%
And so if H is
separable, that implies

00:19:20.000 --> 00:19:21.710 align:middle line:90%
H has an orthonormal basis.

00:19:21.710 --> 00:19:23.570 align:middle line:84%
Now, what this
theorem also proves

00:19:23.570 --> 00:19:27.710 align:middle line:84%
is that if H has a orthonormal
basis, then H is separable.

00:19:27.710 --> 00:19:32.390 align:middle line:84%
So let me just state that
as a simple theorem that

00:19:32.390 --> 00:19:33.290 align:middle line:90%
follows from this.

00:19:33.290 --> 00:19:35.840 align:middle line:90%


00:19:35.840 --> 00:19:37.520 align:middle line:90%
So we've shown that if H--

00:19:37.520 --> 00:19:39.770 align:middle line:84%
that was the first theorem
my stated at the beginning,

00:19:39.770 --> 00:19:43.340 align:middle line:84%
that if H is separable, then
it has an orthonormal basis.

00:19:43.340 --> 00:19:51.645 align:middle line:84%
If H has an orthonormal
basis, H is a Hilbert space.

00:19:51.645 --> 00:19:54.150 align:middle line:90%


00:19:54.150 --> 00:19:56.070 align:middle line:84%
So I should have said
that at the beginning.

00:19:56.070 --> 00:19:57.240 align:middle line:90%
But H is a Hilbert space.

00:19:57.240 --> 00:20:07.100 align:middle line:84%
Then H is separable,
meaning it has a countably--

00:20:07.100 --> 00:20:10.420 align:middle line:90%
a countable dense subset.

00:20:10.420 --> 00:20:12.045 align:middle line:84%
So what is this
countable dense subset?

00:20:12.045 --> 00:20:14.808 align:middle line:90%


00:20:14.808 --> 00:20:16.350 align:middle line:84%
I'm just going to
give you the subset

00:20:16.350 --> 00:20:27.570 align:middle line:84%
and then talk through
why this subset works.

00:20:27.570 --> 00:20:46.430 align:middle line:84%
So suppose en is an
orthonormal basis for H, again

00:20:46.430 --> 00:20:49.550 align:middle line:90%
a Hilbert space.

00:20:49.550 --> 00:20:56.120 align:middle line:84%
Then if I define S to
be the union over all,

00:20:56.120 --> 00:21:02.240 align:middle line:84%
lets say, m natural number of
elements of the form sum from n

00:21:02.240 --> 00:21:10.490 align:middle line:84%
equals 1 to m of
qn en where q1--

00:21:10.490 --> 00:21:15.930 align:middle line:90%
these are just rational numbers.

00:21:15.930 --> 00:21:27.080 align:middle line:84%
So first off, this is a
countable subset of H.

00:21:27.080 --> 00:21:28.050 align:middle line:90%
Why is that?

00:21:28.050 --> 00:21:37.300 align:middle line:84%
Well, each of these is in
one to one correspondence

00:21:37.300 --> 00:21:41.980 align:middle line:84%
with the m-fold
Cartesian product

00:21:41.980 --> 00:21:43.240 align:middle line:90%
of the rational numbers.

00:21:43.240 --> 00:21:45.970 align:middle line:84%
And now, the rational
numbers are countable.

00:21:45.970 --> 00:21:51.544 align:middle line:84%
And you proved back
in 18.100 that any--

00:21:51.544 --> 00:21:55.940 align:middle line:84%
in fact, well, any
Cartesian product,

00:21:55.940 --> 00:22:00.470 align:middle line:84%
finite Cartesian product
of a countable set

00:22:00.470 --> 00:22:01.820 align:middle line:90%
is, again, countable.

00:22:01.820 --> 00:22:03.560 align:middle line:84%
And then we're taking
a countable union.

00:22:03.560 --> 00:22:07.400 align:middle line:84%
Another thing you proved in
18.100 is that a countable

00:22:07.400 --> 00:22:09.410 align:middle line:84%
union of countable
subsets is countable.

00:22:09.410 --> 00:22:13.980 align:middle line:90%
So that's why S is countable.

00:22:13.980 --> 00:22:19.650 align:middle line:84%
And then so now, I'm
just going to state

00:22:19.650 --> 00:22:29.540 align:middle line:84%
by the previous theorem
S is dense in H.

00:22:29.540 --> 00:22:31.920 align:middle line:84%
And then I'm going to put
a box here and explain why.

00:22:31.920 --> 00:22:39.970 align:middle line:84%
So every element-- so if H
has an orthonormal basis,

00:22:39.970 --> 00:22:44.020 align:middle line:84%
by the theorem we proved, every
element can be expanded in one

00:22:44.020 --> 00:22:47.440 align:middle line:84%
of these Fourier-Bessel
series as coefficients times--

00:22:47.440 --> 00:22:49.090 align:middle line:84%
as an infinite
linear combination

00:22:49.090 --> 00:22:53.170 align:middle line:84%
of orthonormal vectors, of
these orthogonal vectors.

00:22:53.170 --> 00:22:56.160 align:middle line:90%


00:22:56.160 --> 00:22:59.990 align:middle line:84%
Now, this means the
partial sums are converging

00:22:59.990 --> 00:23:03.410 align:middle line:90%
to a given element u.

00:23:03.410 --> 00:23:06.200 align:middle line:84%
So what we have to
show for this thing

00:23:06.200 --> 00:23:08.670 align:middle line:84%
to be dense-- we have to
show for every epsilon,

00:23:08.670 --> 00:23:12.560 align:middle line:84%
there exists something from
this set within epsilon distance

00:23:12.560 --> 00:23:14.270 align:middle line:90%
of that given vector.

00:23:14.270 --> 00:23:17.480 align:middle line:90%
Now, give yourself a vector.

00:23:17.480 --> 00:23:20.270 align:middle line:84%
Its Fourier-Bessel
series converges to it.

00:23:20.270 --> 00:23:24.780 align:middle line:90%
So we can cut off a--

00:23:24.780 --> 00:23:26.940 align:middle line:84%
we can cut the series
off at a certain point

00:23:26.940 --> 00:23:31.260 align:middle line:84%
and still be within
epsilon over 2

00:23:31.260 --> 00:23:33.750 align:middle line:84%
to that element we're
trying to get close to.

00:23:33.750 --> 00:23:41.943 align:middle line:84%
Then that finite-- that finite
sum will be in one of these--

00:23:41.943 --> 00:23:43.360 align:middle line:84%
well, it won't be
in one of these.

00:23:43.360 --> 00:23:47.080 align:middle line:84%
But it will just be the sum
from n equals 1 to m of some

00:23:47.080 --> 00:23:49.000 align:middle line:90%
coefficients time the e sub n's.

00:23:49.000 --> 00:23:51.220 align:middle line:90%
Now, the rational numbers--

00:23:51.220 --> 00:23:58.490 align:middle line:84%
I should say-- there,
now that's correct.

00:23:58.490 --> 00:24:03.260 align:middle line:84%
Now, any complex number
here can be approximated

00:24:03.260 --> 00:24:07.670 align:middle line:84%
by a rational number here plus i
times the rational number here.

00:24:07.670 --> 00:24:14.370 align:middle line:84%
This is still in one to one
correspondence with q squared,

00:24:14.370 --> 00:24:17.130 align:middle line:84%
the Cartesian product
of with itself.

00:24:17.130 --> 00:24:18.900 align:middle line:84%
And therefore, this
is still countable--

00:24:18.900 --> 00:24:22.992 align:middle line:84%
and so I should
have said 2m here.

00:24:22.992 --> 00:24:24.450 align:middle line:84%
I was thinking
about real numbers--

00:24:24.450 --> 00:24:27.040 align:middle line:90%


00:24:27.040 --> 00:24:31.740 align:middle line:84%
so that you can get close
to the actual Fourier-Bessel

00:24:31.740 --> 00:24:34.080 align:middle line:84%
coefficients that
appear in that sum

00:24:34.080 --> 00:24:39.450 align:middle line:84%
by now just rational or
complex numbers with rational

00:24:39.450 --> 00:24:43.300 align:middle line:90%
real and imaginary part.

00:24:43.300 --> 00:24:45.000 align:middle line:84%
So I hope that
explanation was clear.

00:24:45.000 --> 00:24:46.650 align:middle line:84%
Maybe sit down,
and think about it,

00:24:46.650 --> 00:24:51.190 align:middle line:84%
and actually write down
carefully the epsilon argument.

00:24:51.190 --> 00:24:55.890 align:middle line:84%
But that's essentially
why this is true.

00:24:55.890 --> 00:25:01.800 align:middle line:84%
So what we've shown is that a
Hilbert space is separable if

00:25:01.800 --> 00:25:04.510 align:middle line:84%
and only if it has
an orthonormal basis.

00:25:04.510 --> 00:25:07.620 align:middle line:84%
So let me make a remark
that what we've shown up

00:25:07.620 --> 00:25:19.810 align:middle line:84%
to this point is that
if H is a Hilbert space,

00:25:19.810 --> 00:25:36.660 align:middle line:84%
then H is separable if and only
if H has an orthonormal basis.

00:25:36.660 --> 00:25:47.262 align:middle line:90%


00:25:47.262 --> 00:25:54.420 align:middle line:84%
All right, so we've proven
that, in the Hilbert space,

00:25:54.420 --> 00:25:56.760 align:middle line:84%
if a Hilbert space has
an orthonormal basis,

00:25:56.760 --> 00:25:58.470 align:middle line:84%
then every element
can be expanded

00:25:58.470 --> 00:26:00.750 align:middle line:84%
in this kind of infinite
series involving

00:26:00.750 --> 00:26:02.190 align:middle line:90%
or the orthonormal vectors.

00:26:02.190 --> 00:26:03.300 align:middle line:90%
I say infinite.

00:26:03.300 --> 00:26:08.220 align:middle line:84%
That's only if the orthonormal
basis is countably infinite.

00:26:08.220 --> 00:26:12.220 align:middle line:84%
If it was finite, then that's
actually not an infinite sum.

00:26:12.220 --> 00:26:13.020 align:middle line:90%
It's a finite sum.

00:26:13.020 --> 00:26:15.830 align:middle line:90%


00:26:15.830 --> 00:26:23.090 align:middle line:84%
Now, what follows
from that is that--

00:26:23.090 --> 00:26:24.890 align:middle line:84%
so we have Bessel's
inequality, which

00:26:24.890 --> 00:26:30.140 align:middle line:84%
says that the sum of squares
of the coefficients appearing

00:26:30.140 --> 00:26:33.345 align:middle line:84%
in this Fourier-Bessel
series is always less

00:26:33.345 --> 00:26:34.970 align:middle line:84%
than or equal to the
norm of u squared.

00:26:34.970 --> 00:26:39.050 align:middle line:84%
That's no matter what you assume
about the orthonormal subset.

00:26:39.050 --> 00:26:42.170 align:middle line:84%
That's for any
orthonormal subset.

00:26:42.170 --> 00:26:47.120 align:middle line:84%
But now, we have that if it's
an orthonormal basis, then,

00:26:47.120 --> 00:26:48.350 align:middle line:90%
in fact, we have equality.

00:26:48.350 --> 00:27:15.780 align:middle line:84%
So if H is the Hilbert space and
this is a countable orthonormal

00:27:15.780 --> 00:27:25.580 align:middle line:84%
basis, then for all u in H, we
have that the sum n equals 1--

00:27:25.580 --> 00:27:28.970 align:middle line:84%
I'll just put sum over n because
this may be a finite sum--

00:27:28.970 --> 00:27:33.858 align:middle line:84%
u en, which by
Bessel's inequality,

00:27:33.858 --> 00:27:35.900 align:middle line:84%
we always had less than
or equal to the norm of u

00:27:35.900 --> 00:27:38.900 align:middle line:84%
squared, in fact, equals
norm of u squared.

00:27:38.900 --> 00:27:42.260 align:middle line:84%
And this is sometimes referred
to as Parseval's identity.

00:27:42.260 --> 00:27:48.140 align:middle line:90%


00:27:48.140 --> 00:27:50.375 align:middle line:84%
All right, so what's
the proof of that?

00:27:50.375 --> 00:27:54.690 align:middle line:90%


00:27:54.690 --> 00:28:03.350 align:middle line:84%
We have that u equals
the sum of u, en en.

00:28:03.350 --> 00:28:09.780 align:middle line:84%
And therefore, immediately,
by the continuity

00:28:09.780 --> 00:28:17.580 align:middle line:84%
of the inner product, we can
write norm of u squared as--

00:28:17.580 --> 00:28:21.600 align:middle line:84%
so this is for the case that
we have countably infinite.

00:28:21.600 --> 00:28:24.608 align:middle line:84%
If it's finite, if it's a
finite orthonormal basis,

00:28:24.608 --> 00:28:25.650 align:middle line:90%
this follows immediately.

00:28:25.650 --> 00:28:28.680 align:middle line:90%
But sum from m equals--

00:28:28.680 --> 00:28:41.630 align:middle line:84%
or the sum as m goes to infinity
of n equals 1 to m u, en en sum

00:28:41.630 --> 00:28:51.260 align:middle line:84%
from, let's say, l
equals 1 to m u, el el.

00:28:51.260 --> 00:28:55.490 align:middle line:84%
And this is equal
to the limit as m

00:28:55.490 --> 00:29:00.720 align:middle line:84%
goes to infinity of
sum of n equals--

00:29:00.720 --> 00:29:06.440 align:middle line:90%
say nl equals 1 to m of u, en.

00:29:06.440 --> 00:29:08.390 align:middle line:84%
And now, this constant
here comes out

00:29:08.390 --> 00:29:10.190 align:middle line:90%
with a complex conjugate--

00:29:10.190 --> 00:29:16.400 align:middle line:90%
u, el times en inner product el.

00:29:16.400 --> 00:29:18.390 align:middle line:90%
And now, we only pick up--

00:29:18.390 --> 00:29:20.945 align:middle line:84%
so n and l are
going from 1 to m.

00:29:20.945 --> 00:29:23.860 align:middle line:90%


00:29:23.860 --> 00:29:26.470 align:middle line:84%
For a fixed n, we
only pick up the l

00:29:26.470 --> 00:29:31.720 align:middle line:84%
where l equals n because
these vectors are orthonormal.

00:29:31.720 --> 00:29:34.300 align:middle line:84%
And when n equals
l, this gives me 1.

00:29:34.300 --> 00:29:35.380 align:middle line:90%
So I only pick up--

00:29:35.380 --> 00:29:40.290 align:middle line:90%


00:29:40.290 --> 00:29:48.330 align:middle line:84%
when l equals n, I get u, en
times the complex conjugate

00:29:48.330 --> 00:29:53.190 align:middle line:84%
of u inner product en, which
is just the norm squared

00:29:53.190 --> 00:29:54.720 align:middle line:90%
when I multiply by that.

00:29:54.720 --> 00:29:57.190 align:middle line:84%
And I'm taking the limit
as m goes to infinity.

00:29:57.190 --> 00:30:06.080 align:middle line:84%
So I pick up the whole sum, the
infinite sum, if it's infinite.

00:30:06.080 --> 00:30:20.570 align:middle line:90%


00:30:20.570 --> 00:30:27.385 align:middle line:84%
All right, so we've seen a
couple of simple applications

00:30:27.385 --> 00:30:28.010 align:middle line:90%
of the theorem.

00:30:28.010 --> 00:30:35.270 align:middle line:84%
We proved that if I have
a normal basis, then

00:30:35.270 --> 00:30:38.510 align:middle line:84%
the Hilbert space
must be separable.

00:30:38.510 --> 00:30:43.050 align:middle line:84%
And also, we have equality in
Bessel's inequality for the--

00:30:43.050 --> 00:30:44.780 align:middle line:84%
in terms of the
orthonormal basis.

00:30:44.780 --> 00:30:50.380 align:middle line:90%


00:30:50.380 --> 00:30:53.950 align:middle line:84%
What's more is that the
previous actually gives us

00:30:53.950 --> 00:30:56.860 align:middle line:84%
a way to identify
every separable Hilbert

00:30:56.860 --> 00:30:59.320 align:middle line:84%
space with the one
you were introduced

00:30:59.320 --> 00:31:03.590 align:middle line:84%
to in the first week, although I
didn't call it a Hilbert space.

00:31:03.590 --> 00:31:11.230 align:middle line:84%
So this is the following
theorem, that if H--

00:31:11.230 --> 00:31:14.950 align:middle line:84%
so if H is a finite
dimensional Hilbert space,

00:31:14.950 --> 00:31:19.390 align:middle line:84%
that means I can find finitely
many orthonormal vectors that

00:31:19.390 --> 00:31:20.380 align:middle line:90%
span the space.

00:31:20.380 --> 00:31:24.910 align:middle line:84%
And it's quite easy to show that
then that is isomorphic to Cn

00:31:24.910 --> 00:31:26.600 align:middle line:90%
in an isometric way.

00:31:26.600 --> 00:31:30.340 align:middle line:84%
So I'm just going to state the
infinite dimensional version.

00:31:30.340 --> 00:31:52.130 align:middle line:84%
If H is an infinite dimensional
separable Hilbert space,

00:31:52.130 --> 00:31:54.350 align:middle line:84%
then H is isometrically
isomorphic--

00:31:54.350 --> 00:32:04.600 align:middle line:90%


00:32:04.600 --> 00:32:07.405 align:middle line:84%
and I'll spell out
what these words mean--

00:32:07.405 --> 00:32:12.030 align:middle line:90%


00:32:12.030 --> 00:32:15.750 align:middle line:90%
to l2, little l2, meaning what?

00:32:15.750 --> 00:32:24.250 align:middle line:84%
Meaning there exists
a bijective map

00:32:24.250 --> 00:32:28.780 align:middle line:90%
T going from H to little l2--

00:32:28.780 --> 00:32:31.000 align:middle line:90%
so it's one to on and on to--

00:32:31.000 --> 00:32:42.040 align:middle line:84%
so that for all u, v in H,
we have that the norm of Tu--

00:32:42.040 --> 00:32:53.080 align:middle line:84%
I should say bijective linear
map, bijective linear map.

00:32:53.080 --> 00:32:57.200 align:middle line:84%
Or I should even say, I mean,
bijective linear operator.

00:32:57.200 --> 00:33:00.520 align:middle line:84%
So it's going to be
a bounded linear map.

00:33:00.520 --> 00:33:02.290 align:middle line:84%
And this follows
immediately from what

00:33:02.290 --> 00:33:03.850 align:middle line:90%
I'm about to write down--

00:33:03.850 --> 00:33:06.760 align:middle line:84%
such that if I take the norm
of the image in little l2,

00:33:06.760 --> 00:33:12.730 align:middle line:84%
this is equal to the
norm of the vector in H.

00:33:12.730 --> 00:33:18.520 align:middle line:84%
So that's the
isometric part here,

00:33:18.520 --> 00:33:22.390 align:middle line:84%
is that the map is
not changing lengths.

00:33:22.390 --> 00:33:26.230 align:middle line:84%
And basically, if I
have two maps between--

00:33:26.230 --> 00:33:28.120 align:middle line:84%
or if I have a map
between two Hilbert spaces

00:33:28.120 --> 00:33:29.650 align:middle line:84%
that preserve the
lengths, then it

00:33:29.650 --> 00:33:31.240 align:middle line:84%
also preserves
inner products by--

00:33:31.240 --> 00:33:35.330 align:middle line:90%


00:33:35.330 --> 00:33:39.470 align:middle line:84%
not the parallelogram law,
it's the polarization identity,

00:33:39.470 --> 00:33:41.450 align:middle line:90%
which you see in the assignment.

00:33:41.450 --> 00:33:48.752 align:middle line:84%
But anyways-- and
also, we have Tu, Tv--

00:33:48.752 --> 00:33:51.210 align:middle line:84%
taking this inner product and
l2 because these are elements

00:33:51.210 --> 00:33:53.040 align:middle line:84%
now of little l2,
this is the same

00:33:53.040 --> 00:33:59.580 align:middle line:84%
as the inner product
in H of u and v.

00:33:59.580 --> 00:34:03.000 align:middle line:84%
And it really just follows
kind of immediately

00:34:03.000 --> 00:34:08.037 align:middle line:84%
from what we've done, once
I just write down the map.

00:34:08.037 --> 00:34:08.870 align:middle line:90%
So what's the proof?

00:34:08.870 --> 00:34:11.929 align:middle line:90%


00:34:11.929 --> 00:34:28.989 align:middle line:84%
So since H is a
separable Hilbert space,

00:34:28.989 --> 00:34:40.153 align:middle line:84%
it has an orthonormal
basis, en, which

00:34:40.153 --> 00:34:41.570 align:middle line:84%
is countably
infinite, since we're

00:34:41.570 --> 00:34:44.644 align:middle line:84%
in the infinite
dimensional setting.

00:34:44.644 --> 00:34:50.409 align:middle line:90%


00:34:50.409 --> 00:34:57.240 align:middle line:84%
And by the previous theorem,
we have for all u in H,

00:34:57.240 --> 00:35:01.510 align:middle line:84%
u is equal to sum
from n equals 1

00:35:01.510 --> 00:35:07.750 align:middle line:84%
to infinity u inner
product en, en.

00:35:07.750 --> 00:35:17.753 align:middle line:84%
And with the norm of
u squared equals--

00:35:17.753 --> 00:35:19.420 align:middle line:84%
if you'd like, let
me remove the squares

00:35:19.420 --> 00:35:22.810 align:middle line:84%
and I can write
this as sum from n

00:35:22.810 --> 00:35:32.610 align:middle line:84%
equals 1 to infinity of
u en norm squared 1/2.

00:35:32.610 --> 00:35:35.910 align:middle line:84%
So now, this should
just jump at you.

00:35:35.910 --> 00:35:42.950 align:middle line:84%
How do I define my map
from H to little l2?

00:35:42.950 --> 00:35:52.310 align:middle line:84%
Then I define T of u to simply
be the sequence of coefficients

00:35:52.310 --> 00:35:53.150 align:middle line:90%
appearing here.

00:35:53.150 --> 00:36:05.050 align:middle line:90%


00:36:05.050 --> 00:36:14.620 align:middle line:84%
And this is an element of
little l2 by this identity here,

00:36:14.620 --> 00:36:15.790 align:middle line:90%
Parseval's identity.

00:36:15.790 --> 00:36:22.990 align:middle line:90%


00:36:22.990 --> 00:36:30.115 align:middle line:90%
Then T does the job.

00:36:30.115 --> 00:36:33.870 align:middle line:90%


00:36:33.870 --> 00:36:37.680 align:middle line:84%
So I didn't go through and
check all the properties

00:36:37.680 --> 00:36:38.880 align:middle line:90%
that I needed to check.

00:36:38.880 --> 00:36:41.340 align:middle line:84%
I mean, it's clear that
it's going to be linear in u

00:36:41.340 --> 00:36:43.800 align:middle line:84%
because these coefficients
are linear in u.

00:36:43.800 --> 00:36:47.610 align:middle line:90%
And that's clear.

00:36:47.610 --> 00:36:49.140 align:middle line:90%
It's one to one.

00:36:49.140 --> 00:36:54.090 align:middle line:84%
It follows from the fact that
every u is expanded this way.

00:36:54.090 --> 00:36:56.730 align:middle line:84%
And therefore, if
the coefficients

00:36:56.730 --> 00:37:02.010 align:middle line:84%
are the same for two different
u's, then those two u's

00:37:02.010 --> 00:37:03.880 align:middle line:90%
have to be the same.

00:37:03.880 --> 00:37:06.780 align:middle line:90%
So that makes it injective.

00:37:06.780 --> 00:37:08.150 align:middle line:90%
The fact that it's surjective--

00:37:08.150 --> 00:37:11.480 align:middle line:90%


00:37:11.480 --> 00:37:13.820 align:middle line:84%
again, it doesn't take
too much to prove,

00:37:13.820 --> 00:37:21.680 align:middle line:84%
although you just show that
for every choice of sequence

00:37:21.680 --> 00:37:25.822 align:middle line:84%
in little l2, that
forming such a sum--

00:37:25.822 --> 00:37:27.930 align:middle line:90%
so let's label these Cn.

00:37:27.930 --> 00:37:32.400 align:middle line:84%
So now, you have just
the element of little l2.

00:37:32.400 --> 00:37:37.320 align:middle line:84%
Now, if I put Cn
here en, now, you

00:37:37.320 --> 00:37:40.560 align:middle line:84%
can argue, as we did before,
that this series is, in fact,

00:37:40.560 --> 00:37:43.980 align:middle line:84%
Cauchy in H and therefore
converges to some element in H.

00:37:43.980 --> 00:37:50.640 align:middle line:84%
And then you can prove that
T takes that element that you

00:37:50.640 --> 00:37:53.520 align:middle line:84%
have to the sequence
that you started with,

00:37:53.520 --> 00:37:56.610 align:middle line:90%
proving that T is surjective.

00:37:56.610 --> 00:37:59.110 align:middle line:84%
So I'm not going to go
through all the details.

00:37:59.110 --> 00:38:02.650 align:middle line:84%
But it should be kind
of clear that this--

00:38:02.650 --> 00:38:07.900 align:middle line:84%
at least based on this identity
here, what the map should be.

00:38:07.900 --> 00:38:28.170 align:middle line:90%


00:38:28.170 --> 00:38:30.360 align:middle line:84%
All right, so we've
seen some applications

00:38:30.360 --> 00:38:36.060 align:middle line:84%
of this general theory
of orthonormal bases

00:38:36.060 --> 00:38:43.030 align:middle line:84%
of countable maximal subsets in
the Hilbert space applications,

00:38:43.030 --> 00:38:47.040 align:middle line:84%
meaning if it has a
basis, orthonormal basis,

00:38:47.040 --> 00:38:50.100 align:middle line:84%
then the space has
to be separable.

00:38:50.100 --> 00:38:54.210 align:middle line:84%
Every separable infinite
dimensional Hilbert space

00:38:54.210 --> 00:38:55.420 align:middle line:90%
is basically the same.

00:38:55.420 --> 00:39:00.090 align:middle line:84%
They're all isometrically
isomorphic to little l2.

00:39:00.090 --> 00:39:03.870 align:middle line:84%
But how can we use this in a
more concrete setting, whatever

00:39:03.870 --> 00:39:04.830 align:middle line:90%
concrete means?

00:39:04.830 --> 00:39:07.410 align:middle line:84%
I mean, concrete
kind of is by taste.

00:39:07.410 --> 00:39:12.180 align:middle line:84%
So I thought we'd pause here on
the general theory for Hilbert

00:39:12.180 --> 00:39:14.400 align:middle line:84%
spaces that we've been
doing and do something

00:39:14.400 --> 00:39:20.430 align:middle line:84%
a little more specific and
look at Fourier series, which

00:39:20.430 --> 00:39:22.860 align:middle line:84%
will connect this general
stuff that we've been doing

00:39:22.860 --> 00:39:31.890 align:middle line:84%
with Hilbert spaces to more of
the concrete bit of producing

00:39:31.890 --> 00:39:35.720 align:middle line:84%
Lebesgue integration in these
big LP spaces, which we proved

00:39:35.720 --> 00:39:41.750 align:middle line:84%
are complete spaces
involving, in some sense,

00:39:41.750 --> 00:39:45.290 align:middle line:90%
integrable functions.

00:39:45.290 --> 00:39:58.620 align:middle line:84%
So let's take a pause
from general theory

00:39:58.620 --> 00:40:01.620 align:middle line:84%
and talk a little bit
about Fourier series.

00:40:01.620 --> 00:40:09.770 align:middle line:90%


00:40:09.770 --> 00:40:17.990 align:middle line:84%
OK, Fourier series,
which was the reason why

00:40:17.990 --> 00:40:20.690 align:middle line:84%
a lot of especially
the integration theory

00:40:20.690 --> 00:40:22.760 align:middle line:84%
was created in the
first place, was

00:40:22.760 --> 00:40:25.250 align:middle line:84%
to understand a
certain question, which

00:40:25.250 --> 00:40:28.320 align:middle line:90%
we'll get to in a minute.

00:40:28.320 --> 00:40:32.300 align:middle line:84%
Let me just start off with
a very simple theorem,

00:40:32.300 --> 00:40:47.380 align:middle line:84%
that the subset of functions,
e to the inx over root 2

00:40:47.380 --> 00:40:59.670 align:middle line:84%
pi in now an integer
is an orthonormal--

00:40:59.670 --> 00:41:10.830 align:middle line:84%
orthonormal subset
of l2 minus pi to pi.

00:41:10.830 --> 00:41:15.690 align:middle line:90%


00:41:15.690 --> 00:41:17.370 align:middle line:90%
And here, let me--

00:41:17.370 --> 00:41:23.700 align:middle line:84%
just for a quick refresher,
if t is a real number,

00:41:23.700 --> 00:41:25.740 align:middle line:84%
e to the it, this
is simply defined

00:41:25.740 --> 00:41:33.720 align:middle line:84%
to be the complex number
of cosine t plus i sine t.

00:41:33.720 --> 00:41:38.170 align:middle line:84%
And it satisfies all the
things that you know and love

00:41:38.170 --> 00:41:39.400 align:middle line:90%
about the exponential.

00:41:39.400 --> 00:41:42.800 align:middle line:90%


00:41:42.800 --> 00:41:45.420 align:middle line:84%
If I multiply e to the
it times e to the i tau,

00:41:45.420 --> 00:41:48.480 align:middle line:84%
that's equal to e to the it
plus tau just by referring

00:41:48.480 --> 00:41:56.810 align:middle line:84%
to the definition and using
angle sum formulas and so on.

00:41:56.810 --> 00:41:59.840 align:middle line:90%


00:41:59.840 --> 00:42:02.960 align:middle line:84%
All right, so this is not
too difficult to prove.

00:42:02.960 --> 00:42:04.970 align:middle line:90%
What's the proof of this?

00:42:04.970 --> 00:42:13.330 align:middle line:84%
If I take e to the inx and inner
product it with e to the inx,

00:42:13.330 --> 00:42:16.180 align:middle line:84%
now this inner
product is in big L2.

00:42:16.180 --> 00:42:19.450 align:middle line:84%
This is, by definition, equal
to the integral from minus pi

00:42:19.450 --> 00:42:27.250 align:middle line:84%
to pi e to the inx times e
to the imx complex conjugate.

00:42:27.250 --> 00:42:32.790 align:middle line:84%
And again, from the
definition, when

00:42:32.790 --> 00:42:36.590 align:middle line:84%
I take a complex conjugate,
that flips this i to a minus i.

00:42:36.590 --> 00:42:39.390 align:middle line:90%


00:42:39.390 --> 00:42:43.020 align:middle line:84%
And then I can take that
minus that sits out here

00:42:43.020 --> 00:42:45.840 align:middle line:84%
and put it in, and make this
a minus t here and a minus t

00:42:45.840 --> 00:42:48.750 align:middle line:84%
there, since cosine t is
even and sine t is odd.

00:42:48.750 --> 00:42:56.250 align:middle line:84%
So then this becomes e to the
inx e to the minus imx x dx.

00:42:56.250 --> 00:43:07.680 align:middle line:84%
And again, you can just go from
the definition of what this is.

00:43:07.680 --> 00:43:10.470 align:middle line:84%
You don't need any
fancy complex analysis.

00:43:10.470 --> 00:43:14.850 align:middle line:84%
This is i to the n
minus m times x dx.

00:43:14.850 --> 00:43:19.004 align:middle line:90%


00:43:19.004 --> 00:43:23.560 align:middle line:90%
Now, this quantity here--

00:43:23.560 --> 00:43:27.350 align:middle line:84%
when n equals m,
I just get 0 here.

00:43:27.350 --> 00:43:28.690 align:middle line:90%
And therefore, this is just 1.

00:43:28.690 --> 00:43:32.500 align:middle line:84%
And when I integrate
that, I get 2 pi.

00:43:32.500 --> 00:43:37.330 align:middle line:90%
So this equals 2 pi.

00:43:37.330 --> 00:43:40.960 align:middle line:84%
And now, when n
does not equal m,

00:43:40.960 --> 00:43:44.270 align:middle line:84%
this has an antiderivative
that you expect it to be.

00:43:44.270 --> 00:43:50.170 align:middle line:84%
And therefore, this is equal
to e to the i n minus m

00:43:50.170 --> 00:43:59.680 align:middle line:84%
x over n minus m times i
evaluated at pi n minus pi.

00:43:59.680 --> 00:44:04.170 align:middle line:84%
And this is if n equals
m, n does not equal m.

00:44:04.170 --> 00:44:09.060 align:middle line:90%


00:44:09.060 --> 00:44:14.040 align:middle line:84%
Now, what is it
about e to the it?

00:44:14.040 --> 00:44:16.980 align:middle line:90%
This thing is 2 pi periodic.

00:44:16.980 --> 00:44:18.930 align:middle line:84%
And it's the same
if I have an n here.

00:44:18.930 --> 00:44:24.310 align:middle line:84%
Then that's going to be
2 pi over n periodic.

00:44:24.310 --> 00:44:30.120 align:middle line:84%
So if I stick in pi
here, the value I get

00:44:30.120 --> 00:44:33.330 align:middle line:84%
is going to be the same as
when I stick in minus pi

00:44:33.330 --> 00:44:36.810 align:middle line:84%
here because the difference
between these two values is 2

00:44:36.810 --> 00:44:37.650 align:middle line:90%
pi.

00:44:37.650 --> 00:44:38.940 align:middle line:90%
This is 2 pi periodic.

00:44:38.940 --> 00:44:41.940 align:middle line:84%
And I'm sticking in two
numbers separated by 2 pi.

00:44:41.940 --> 00:44:45.480 align:middle line:84%
So this will be 0 when
n does not equal m.

00:44:45.480 --> 00:44:51.640 align:middle line:90%


00:44:51.640 --> 00:44:55.690 align:middle line:84%
And therefore, that
proves the claim

00:44:55.690 --> 00:44:57.190 align:middle line:84%
that this is an
orthonormal subset.

00:44:57.190 --> 00:44:59.020 align:middle line:84%
We divide by square
root of 2 pi so

00:44:59.020 --> 00:45:03.130 align:middle line:84%
that when I take the inner
product of this with itself

00:45:03.130 --> 00:45:05.050 align:middle line:84%
or the element with
itself, I get 1.

00:45:05.050 --> 00:45:07.630 align:middle line:84%
Here, I just did e to
the inx, so I got 2 pi.

00:45:07.630 --> 00:45:10.810 align:middle line:84%
So I divide by the
square root of that

00:45:10.810 --> 00:45:15.105 align:middle line:90%
to get the orthonormal thing.

00:45:15.105 --> 00:45:18.050 align:middle line:90%


00:45:18.050 --> 00:45:21.620 align:middle line:90%
So make a definition.

00:45:21.620 --> 00:45:24.480 align:middle line:90%


00:45:24.480 --> 00:45:30.335 align:middle line:84%
So let f be in l2
of minus pi to pi.

00:45:30.335 --> 00:45:35.310 align:middle line:90%


00:45:35.310 --> 00:45:41.870 align:middle line:90%
The n-th Fourier coefficient--

00:45:41.870 --> 00:45:44.210 align:middle line:84%
this is the new bit
of terminology--

00:45:44.210 --> 00:45:47.680 align:middle line:90%


00:45:47.680 --> 00:45:55.520 align:middle line:84%
of f is the complex number f-hat
of n equals 1 over 2 pi inner

00:45:55.520 --> 00:45:56.240 align:middle line:90%
product--

00:45:56.240 --> 00:45:57.830 align:middle line:84%
I mean-- inner
product-- integral

00:45:57.830 --> 00:46:07.370 align:middle line:84%
of minus pi to pi of f of
t e to the minus int dt.

00:46:07.370 --> 00:46:28.230 align:middle line:84%
And the N-th partial
Fourier sum of f

00:46:28.230 --> 00:46:34.830 align:middle line:84%
is denoted by capital
S sub N of f of x.

00:46:34.830 --> 00:46:39.750 align:middle line:84%
This is equal to the sum for
n in absolute value less than

00:46:39.750 --> 00:46:45.480 align:middle line:84%
or equal to capital N. So little
n is an integer of f-hat of n

00:46:45.480 --> 00:46:54.030 align:middle line:84%
times e to the
inx, which I can--

00:46:54.030 --> 00:47:01.415 align:middle line:84%
is the same as f inner
product with in--

00:47:01.415 --> 00:47:04.140 align:middle line:90%


00:47:04.140 --> 00:47:09.120 align:middle line:84%
let's say t over square
root of 2 pi e to the i.

00:47:09.120 --> 00:47:15.510 align:middle line:90%


00:47:15.510 --> 00:47:18.960 align:middle line:84%
All I did with my definition
of the Fourier coefficient

00:47:18.960 --> 00:47:21.240 align:middle line:84%
is I combined these two
square root of 2 pi's

00:47:21.240 --> 00:47:23.460 align:middle line:90%
in my definition of f-hat of n.

00:47:23.460 --> 00:47:30.240 align:middle line:84%
But this partial sum is just
equal to a partial sum in terms

00:47:30.240 --> 00:47:32.070 align:middle line:90%
of this orthonormal subset.

00:47:32.070 --> 00:47:45.292 align:middle line:90%


00:47:45.292 --> 00:47:59.850 align:middle line:84%
OK, and we also associate to
function f a formal object.

00:47:59.850 --> 00:48:24.430 align:middle line:84%
The Fourier series of
f is the formal series,

00:48:24.430 --> 00:48:27.520 align:middle line:84%
because we are not making any
claims about its convergence

00:48:27.520 --> 00:48:40.715 align:middle line:84%
at all, summed from n in
z f-hat of n e to the inx.

00:48:40.715 --> 00:48:46.220 align:middle line:90%


00:48:46.220 --> 00:48:58.190 align:middle line:84%
So the question that
we're going to answer--

00:48:58.190 --> 00:49:04.280 align:middle line:84%
and like I said, what motivated
all of this to begin with

00:49:04.280 --> 00:49:05.280 align:middle line:90%
is the following.

00:49:05.280 --> 00:49:10.220 align:middle line:84%
So back when Fourier was
studying heat conduction,

00:49:10.220 --> 00:49:12.080 align:middle line:84%
he made a claim that
every function can

00:49:12.080 --> 00:49:14.720 align:middle line:84%
be expanded in terms
of-- essentially,

00:49:14.720 --> 00:49:16.280 align:middle line:90%
he was doing cosines and sines.

00:49:16.280 --> 00:49:20.720 align:middle line:84%
But in terms of this,
he said every function

00:49:20.720 --> 00:49:23.850 align:middle line:90%
can be expanded--

00:49:23.850 --> 00:49:26.115 align:middle line:90%
is equal to its Fourier series.

00:49:26.115 --> 00:49:28.720 align:middle line:90%


00:49:28.720 --> 00:49:32.110 align:middle line:84%
Now, at the time, people
said, no, that's not the case.

00:49:32.110 --> 00:49:33.460 align:middle line:90%
Not every function is periodic.

00:49:33.460 --> 00:49:35.560 align:middle line:90%
And these are 2 pi--

00:49:35.560 --> 00:49:37.160 align:middle line:90%
each of these is 2 pi periodic.

00:49:37.160 --> 00:49:40.070 align:middle line:90%
So what are you talking about?

00:49:40.070 --> 00:49:43.540 align:middle line:84%
And then he said,
maybe if we restrict

00:49:43.540 --> 00:49:46.600 align:middle line:84%
to continuous
functions, maybe it's

00:49:46.600 --> 00:49:48.730 align:middle line:90%
equal to its Fourier series.

00:49:48.730 --> 00:49:49.600 align:middle line:90%
That's not true.

00:49:49.600 --> 00:49:52.240 align:middle line:84%
There's continuous
functions that have--

00:49:52.240 --> 00:49:58.000 align:middle line:84%
where the Fourier series
actually diverges at a point

00:49:58.000 --> 00:49:59.860 align:middle line:84%
and doesn't converge
back to the function.

00:49:59.860 --> 00:50:02.810 align:middle line:90%


00:50:02.810 --> 00:50:06.080 align:middle line:84%
But Fourier series,
now if you're

00:50:06.080 --> 00:50:09.500 align:middle line:84%
asking about
pointwise convergence,

00:50:09.500 --> 00:50:13.100 align:middle line:84%
that's a very tricky
and delicate issue.

00:50:13.100 --> 00:50:20.630 align:middle line:84%
But Fourier series has a very
nice and beautiful answer

00:50:20.630 --> 00:50:25.670 align:middle line:84%
when you look in terms of the
space that you're supposed to.

00:50:25.670 --> 00:50:27.710 align:middle line:84%
As I started off
this discussion,

00:50:27.710 --> 00:50:31.160 align:middle line:84%
I said these elements are
orthonormal with respect

00:50:31.160 --> 00:50:32.660 align:middle line:90%
to this inner product.

00:50:32.660 --> 00:50:36.620 align:middle line:84%
And this inner product lives,
as far as in a Hilbert space,

00:50:36.620 --> 00:50:38.780 align:middle line:90%
in the space big L2.

00:50:38.780 --> 00:50:42.140 align:middle line:84%
So the question that
one should ask then

00:50:42.140 --> 00:50:46.910 align:middle line:84%
is-- you have this or
the normal subset of L2.

00:50:46.910 --> 00:51:05.220 align:middle line:84%
So the question is, do we
have for all f in L2 f of x

00:51:05.220 --> 00:51:15.000 align:middle line:90%
equals f-hat of n e to the inx.

00:51:15.000 --> 00:51:17.100 align:middle line:90%
So this is an infinite sum.

00:51:17.100 --> 00:51:21.230 align:middle line:84%
So I should be talking about
in what sense is this series

00:51:21.230 --> 00:51:22.070 align:middle line:90%
converging.

00:51:22.070 --> 00:51:25.640 align:middle line:84%
And I mean in the
sense of in the space

00:51:25.640 --> 00:51:29.510 align:middle line:84%
that we're asking this
question, in L2, i.e.

00:51:29.510 --> 00:51:32.030 align:middle line:90%


00:51:32.030 --> 00:51:46.030 align:middle line:84%
do I have that the partial sums
converge to f in the L2 norm?

00:51:46.030 --> 00:51:54.210 align:middle line:90%


00:51:54.210 --> 00:51:57.165 align:middle line:84%
So I'm not going to
write the argument.

00:51:57.165 --> 00:51:58.380 align:middle line:90%
OK, maybe I will.

00:51:58.380 --> 00:52:05.700 align:middle line:90%


00:52:05.700 --> 00:52:09.550 align:middle line:90%
Does this equal-- does this--

00:52:09.550 --> 00:52:11.620 align:middle line:90%
OK, now, I'm butchering this.

00:52:11.620 --> 00:52:15.160 align:middle line:84%
Instead of writing
that limit, let's say,

00:52:15.160 --> 00:52:23.200 align:middle line:84%
does this norm converge to 0
as capital N goes to infinity?

00:52:23.200 --> 00:52:26.710 align:middle line:90%


00:52:26.710 --> 00:52:28.380 align:middle line:90%
So that's the question.

00:52:28.380 --> 00:52:33.130 align:middle line:84%
Do we have convergence
of this series,

00:52:33.130 --> 00:52:37.280 align:middle line:84%
meaning the partial sums, do
they converge to the function f

00:52:37.280 --> 00:52:39.020 align:middle line:90%
in the L2 norm?

00:52:39.020 --> 00:52:41.090 align:middle line:84%
So this is something
weaker than--

00:52:41.090 --> 00:52:44.210 align:middle line:84%
or maybe not even comparable
to pointwise convergence.

00:52:44.210 --> 00:52:47.120 align:middle line:84%
So sometimes, this is referred
to as convergence in the mean.

00:52:47.120 --> 00:52:49.860 align:middle line:90%


00:52:49.860 --> 00:52:55.410 align:middle line:84%
And so what is the way to
phrase this question based

00:52:55.410 --> 00:52:56.265 align:middle line:90%
on what we've done?

00:52:56.265 --> 00:53:00.090 align:middle line:90%


00:53:00.090 --> 00:53:16.900 align:middle line:84%
So this question is
equivalent to the question,

00:53:16.900 --> 00:53:37.424 align:middle line:84%
is this collection of
orthonormal elements in big L2

00:53:37.424 --> 00:53:45.000 align:middle line:90%
a maximal subset of big L2? i.e.

00:53:45.000 --> 00:53:52.620 align:middle line:84%
and so now, let's really put
this question into equivalence

00:53:52.620 --> 00:53:56.640 align:middle line:84%
with just a pure
statement-- i.e.

00:53:56.640 --> 00:54:09.260 align:middle line:84%
does the vanishing of all
the Fourier coefficients

00:54:09.260 --> 00:54:11.075 align:middle line:90%
imply that the function is 0?

00:54:11.075 --> 00:54:15.880 align:middle line:90%


00:54:15.880 --> 00:54:19.300 align:middle line:84%
So we proved that
this statement here

00:54:19.300 --> 00:54:26.770 align:middle line:84%
is equivalent to e to the inx
being an orthonormal basis.

00:54:26.770 --> 00:54:28.000 align:middle line:90%
So we proved one direction.

00:54:28.000 --> 00:54:30.130 align:middle line:84%
We proved that if
I have a collection

00:54:30.130 --> 00:54:34.750 align:middle line:84%
of orthonormal vectors, then
that's an orthonormal basis

00:54:34.750 --> 00:54:38.530 align:middle line:84%
implies that every
function can be expanded

00:54:38.530 --> 00:54:40.360 align:middle line:90%
in this infinite series.

00:54:40.360 --> 00:54:42.280 align:middle line:84%
But the converse
clearly holds, too.

00:54:42.280 --> 00:54:45.970 align:middle line:84%
If I can expand every
function in an infinite series

00:54:45.970 --> 00:54:47.740 align:middle line:84%
with those
coefficients, then that

00:54:47.740 --> 00:54:50.410 align:middle line:84%
implies that the subset
has to be ortho--

00:54:50.410 --> 00:54:53.590 align:middle line:84%
has to be maximal
because if something's

00:54:53.590 --> 00:54:56.705 align:middle line:84%
orthogonal to everything
in the collection,

00:54:56.705 --> 00:54:59.080 align:middle line:84%
then all those coefficients
appearing in the series are 0

00:54:59.080 --> 00:55:00.580 align:middle line:90%
and therefore the function is 0.

00:55:00.580 --> 00:55:05.860 align:middle line:84%
So this question here
is equivalent to asking

00:55:05.860 --> 00:55:08.890 align:middle line:84%
whether or not this
collection is maximal, which

00:55:08.890 --> 00:55:13.090 align:middle line:84%
means if I have an
element in L2 that

00:55:13.090 --> 00:55:16.450 align:middle line:84%
is orthogonal to
everything in here,

00:55:16.450 --> 00:55:19.810 align:middle line:84%
then it has to be 0, which
is this statement here.

00:55:19.810 --> 00:55:27.160 align:middle line:90%
So let me put a box around it.

00:55:27.160 --> 00:55:30.970 align:middle line:84%
Based on what we've done, of
the question of convergence

00:55:30.970 --> 00:55:35.020 align:middle line:90%
of Fourier series in big L2--

00:55:35.020 --> 00:55:38.200 align:middle line:84%
and what I'm using
here really as well

00:55:38.200 --> 00:55:40.510 align:middle line:84%
is the fact that
big L2 is complete.

00:55:40.510 --> 00:55:43.090 align:middle line:84%
This all only works
in a Hilbert space.

00:55:43.090 --> 00:55:46.120 align:middle line:84%
At certain points,
we relied on the fact

00:55:46.120 --> 00:55:49.690 align:middle line:84%
that Cauchy sequences converge
to something in this space.

00:55:49.690 --> 00:55:55.300 align:middle line:84%
So the fact that I can cleanly
reduce this question down

00:55:55.300 --> 00:55:57.820 align:middle line:84%
to what's in yellow
relies on the fact

00:55:57.820 --> 00:56:02.290 align:middle line:84%
that big L2 is complete,
which we did a lot of work

00:56:02.290 --> 00:56:06.250 align:middle line:90%
to show and to construct.

00:56:06.250 --> 00:56:19.810 align:middle line:90%


00:56:19.810 --> 00:56:24.190 align:middle line:84%
So this is the question that
we're going to try to answer.

00:56:24.190 --> 00:56:30.370 align:middle line:90%
And let me go ahead and answer--

00:56:30.370 --> 00:56:32.630 align:middle line:84%
I asked a question, so I
should give the answer.

00:56:32.630 --> 00:56:36.430 align:middle line:84%
The answer is yes, but it's
going to take some work.

00:56:36.430 --> 00:56:37.660 align:middle line:90%
This is a non-trivial matter.

00:56:37.660 --> 00:56:41.730 align:middle line:90%


00:56:41.730 --> 00:56:45.470 align:middle line:84%
So let's see, how
much time do I have?

00:56:45.470 --> 00:56:47.450 align:middle line:84%
OK, so how we're
going to proceed

00:56:47.450 --> 00:56:52.170 align:middle line:84%
is via what may be referred
to as Fejer's method.

00:56:52.170 --> 00:56:54.560 align:middle line:84%
So again, our goal
is to show this,

00:56:54.560 --> 00:56:57.710 align:middle line:84%
to answer the question about
convergence of Fourier series

00:56:57.710 --> 00:56:59.240 align:middle line:90%
in L2.

00:56:59.240 --> 00:57:00.050 align:middle line:90%
Why in L2?

00:57:00.050 --> 00:57:04.550 align:middle line:90%
Because that's the complete--

00:57:04.550 --> 00:57:12.540 align:middle line:84%
that's a complete Hilbert
space that we're working in,

00:57:12.540 --> 00:57:15.600 align:middle line:84%
that we're going to apply
our general framework to.

00:57:15.600 --> 00:57:25.000 align:middle line:84%
So let me start off with a
following simple calculation,

00:57:25.000 --> 00:57:40.870 align:middle line:84%
that for all f in L2 minus pi to
pi and for all natural numbers

00:57:40.870 --> 00:57:45.070 align:middle line:84%
n, including 0,
if I want to look

00:57:45.070 --> 00:57:53.760 align:middle line:84%
at the n-th partial
sum of f, I can

00:57:53.760 --> 00:57:55.980 align:middle line:84%
write this as the
integral from minus pi

00:57:55.980 --> 00:58:03.510 align:middle line:84%
to pi of a function
evaluated at x minus t times

00:58:03.510 --> 00:58:06.420 align:middle line:90%
f of t integrated dt.

00:58:06.420 --> 00:58:10.050 align:middle line:84%
And again, this should be
interpreted as a Lesbegue

00:58:10.050 --> 00:58:13.080 align:middle line:84%
integral, even though
I'm writing it using

00:58:13.080 --> 00:58:16.090 align:middle line:90%
the notation that you use--

00:58:16.090 --> 00:58:24.233 align:middle line:90%
Lord, sorry, that e was awful.

00:58:24.233 --> 00:58:25.650 align:middle line:84%
I just couldn't
let it stay there.

00:58:25.650 --> 00:58:29.350 align:middle line:90%


00:58:29.350 --> 00:58:32.590 align:middle line:84%
Even though I was using this
notation at one point to denote

00:58:32.590 --> 00:58:35.950 align:middle line:84%
the Riemann integral, I'm
now using this notation

00:58:35.950 --> 00:58:38.710 align:middle line:84%
for the Lebesgue integral
if the function's--

00:58:38.710 --> 00:58:41.980 align:middle line:84%
if I'm talking about
Lebesgue integration,

00:58:41.980 --> 00:58:43.740 align:middle line:84%
which is not such
an abuse of notation

00:58:43.740 --> 00:58:45.900 align:middle line:84%
because we found out
that the Lebesgue

00:58:45.900 --> 00:58:49.870 align:middle line:84%
integral of continuous functions
is the Riemann integral.

00:58:49.870 --> 00:58:51.340 align:middle line:90%
So let me finish the statement.

00:58:51.340 --> 00:58:56.070 align:middle line:84%
So we can write it as some
function of x minus t times

00:58:56.070 --> 00:59:07.960 align:middle line:84%
f of t integrate from minus
pi to pi where dn of x, this

00:59:07.960 --> 00:59:14.440 align:middle line:84%
is equal to the function, which
is 2n plus 1 over 2 pi when

00:59:14.440 --> 00:59:29.290 align:middle line:84%
x equals 0 and
sine of n plus 1/2

00:59:29.290 --> 00:59:40.360 align:middle line:84%
of x over 2 pi sine x over
2 when x does not equal 0.

00:59:40.360 --> 00:59:42.940 align:middle line:84%
And this function
here-- so first off,

00:59:42.940 --> 00:59:46.810 align:middle line:84%
note that this is a
continuous function.

00:59:46.810 --> 00:59:51.190 align:middle line:84%
As x converges to 0, using
L'Hopital's rule, if you like,

00:59:51.190 --> 00:59:53.967 align:middle line:84%
this thing converges
to 2n plus 1 over 2 pi.

00:59:53.967 --> 00:59:55.300 align:middle line:90%
In fact, it's a smooth function.

00:59:55.300 --> 00:59:57.830 align:middle line:90%


00:59:57.830 --> 01:00:00.845 align:middle line:84%
This function here is referred
to as the Dirichlet kernel.

01:00:00.845 --> 01:00:34.160 align:middle line:90%


01:00:34.160 --> 01:00:38.760 align:middle line:84%
As a first step, I said,
we're going to look at--

01:00:38.760 --> 01:00:41.850 align:middle line:84%
we're going to rewrite the
partial sums in this way.

01:00:41.850 --> 01:00:43.110 align:middle line:90%
I'll tell you why in a minute.

01:00:43.110 --> 01:00:46.560 align:middle line:90%


01:00:46.560 --> 01:00:49.760 align:middle line:84%
But let's just take this
as a warm-up calculation

01:00:49.760 --> 01:00:51.665 align:middle line:90%
of some calculations to come.

01:00:51.665 --> 01:01:13.720 align:middle line:90%


01:01:13.720 --> 01:01:16.010 align:middle line:90%
OK, so what's the proof?

01:01:16.010 --> 01:01:32.410 align:middle line:84%
We have that the n-th
partial Fourier sum of f,

01:01:32.410 --> 01:01:37.990 align:middle line:84%
this is equal to n less
than or equal to N of--

01:01:37.990 --> 01:01:42.490 align:middle line:84%
let me just write out here what
the Fourier coefficient is--

01:01:42.490 --> 01:01:52.960 align:middle line:84%
1 over 2 pi minus pi to pi of
e to the minus i of f of t, e

01:01:52.960 --> 01:02:00.040 align:middle line:84%
tot he minus int
dt e to the inx.

01:02:00.040 --> 01:02:02.990 align:middle line:90%
And this is just a finite sum.

01:02:02.990 --> 01:02:05.560 align:middle line:84%
So I can bring this
inside the integral

01:02:05.560 --> 01:02:06.700 align:middle line:90%
and combine everything.

01:02:06.700 --> 01:02:08.770 align:middle line:84%
And I get this is
equal to minus pi

01:02:08.770 --> 01:02:21.725 align:middle line:84%
to phi of f of t times dn
of x minus t, where dn of--

01:02:21.725 --> 01:02:26.100 align:middle line:90%


01:02:26.100 --> 01:02:30.150 align:middle line:84%
so in fact, let me--
let me not jump ahead.

01:02:30.150 --> 01:02:32.910 align:middle line:84%
I'll go ahead and
write this out.

01:02:32.910 --> 01:02:48.170 align:middle line:84%
This is equal to now sum times
e to the in x minus t dt.

01:02:48.170 --> 01:02:51.430 align:middle line:90%
So this is dn, all right?

01:02:51.430 --> 01:02:56.010 align:middle line:90%


01:02:56.010 --> 01:03:05.160 align:middle line:84%
So dn-- so call this
thing, dn of x minus t, x

01:03:05.160 --> 01:03:06.480 align:middle line:90%
minus t appearing there.

01:03:06.480 --> 01:03:13.420 align:middle line:90%


01:03:13.420 --> 01:03:17.410 align:middle line:90%
And now, let's compute dn of x.

01:03:17.410 --> 01:03:23.260 align:middle line:84%
So let me just rewrite what
it is, sum in less than

01:03:23.260 --> 01:03:24.880 align:middle line:90%
or equal to n e to the inx.

01:03:24.880 --> 01:03:28.010 align:middle line:90%


01:03:28.010 --> 01:03:28.720 align:middle line:90%
Where'd the t go?

01:03:28.720 --> 01:03:31.690 align:middle line:84%
Again, again this
is dn of x minus t.

01:03:31.690 --> 01:03:33.160 align:middle line:90%
So the argument's there.

01:03:33.160 --> 01:03:35.470 align:middle line:84%
So dn of x is--
there's the argument.

01:03:35.470 --> 01:03:37.930 align:middle line:84%
Maybe I should have put a
y or something like that,

01:03:37.930 --> 01:03:42.420 align:middle line:84%
but I didn't think
that far ahead.

01:03:42.420 --> 01:03:46.610 align:middle line:84%
So this is the d capital
N. And now, let's

01:03:46.610 --> 01:03:50.990 align:middle line:90%
just massage this a little bit.

01:03:50.990 --> 01:03:58.610 align:middle line:84%
We can write as e to the minus
inx times now the sum from n

01:03:58.610 --> 01:04:02.345 align:middle line:90%
equals 0 to 2n e to the inx.

01:04:02.345 --> 01:04:05.410 align:middle line:90%


01:04:05.410 --> 01:04:11.440 align:middle line:84%
This is a sum from, if you'd
like, n equals minus capital

01:04:11.440 --> 01:04:14.230 align:middle line:90%
N to n.

01:04:14.230 --> 01:04:17.140 align:middle line:84%
All right, so if I factor
out an e to the minus inx,

01:04:17.140 --> 01:04:19.110 align:middle line:84%
I can write this
sum as this sum.

01:04:19.110 --> 01:04:24.550 align:middle line:90%


01:04:24.550 --> 01:04:31.370 align:middle line:90%
Now, this is a geometric sum.

01:04:31.370 --> 01:04:33.680 align:middle line:84%
This e to the inx,
again, this is something

01:04:33.680 --> 01:04:35.600 align:middle line:84%
that you can just check
from the definition.

01:04:35.600 --> 01:04:41.330 align:middle line:84%
This is also equal to e to the
ix raised to the n-th power.

01:04:41.330 --> 01:04:44.390 align:middle line:84%
And I know how to sum things
that involves something being

01:04:44.390 --> 01:04:46.130 align:middle line:90%
raised to the n-th power--

01:04:46.130 --> 01:04:48.590 align:middle line:90%
finite sums, that is.

01:04:48.590 --> 01:04:51.260 align:middle line:84%
This is equal to 1
over 2 pi times e

01:04:51.260 --> 01:05:07.430 align:middle line:84%
to the minus inx times 1
minus e to the i 2n plus 1 x

01:05:07.430 --> 01:05:13.580 align:middle line:84%
over 1 minus e to the ix, the
thing that's appearing here.

01:05:13.580 --> 01:05:16.820 align:middle line:84%
2n plus 1 the thing that
appears on top plus 1.

01:05:16.820 --> 01:05:23.440 align:middle line:90%


01:05:23.440 --> 01:05:31.390 align:middle line:84%
Now, multiplying through by this
e to the inx, pulling out a 1/2

01:05:31.390 --> 01:05:34.090 align:middle line:84%
e to the ix over 2
and distributing that

01:05:34.090 --> 01:05:37.960 align:middle line:84%
to the bottom, we
get that the previous

01:05:37.960 --> 01:05:39.730 align:middle line:90%
is equal to 1 over 2 pi.

01:05:39.730 --> 01:05:43.800 align:middle line:90%


01:05:43.800 --> 01:05:48.250 align:middle line:84%
So first off, this is
valid only when x--

01:05:48.250 --> 01:05:49.530 align:middle line:90%
what?

01:05:49.530 --> 01:05:53.530 align:middle line:90%
When x is not equal to 0.

01:05:53.530 --> 01:05:58.480 align:middle line:84%
When x equals 0, I just get
1 here and I get 1 here.

01:05:58.480 --> 01:06:04.010 align:middle line:84%
And then I get the
sum from 0 to 2 n,

01:06:04.010 --> 01:06:05.630 align:middle line:90%
which is equal to 2n plus 1.

01:06:05.630 --> 01:06:07.940 align:middle line:84%
That's why I get what
I get when x equals 0.

01:06:07.940 --> 01:06:12.140 align:middle line:84%
So this is valid for
x not equal to 0.

01:06:12.140 --> 01:06:17.730 align:middle line:84%
And so I get e to
the in plus 1 x.

01:06:17.730 --> 01:06:20.310 align:middle line:90%


01:06:20.310 --> 01:06:24.210 align:middle line:84%
I should say, after
I've taken away

01:06:24.210 --> 01:06:28.110 align:middle line:84%
that 1/2 x that
appeared with this 1x

01:06:28.110 --> 01:06:39.770 align:middle line:84%
and distributed it down on
the bottom e to the ix over 2

01:06:39.770 --> 01:06:44.930 align:middle line:90%
minus e to the minus ix over 2.

01:06:44.930 --> 01:06:49.910 align:middle line:84%
Now, if I have e to
the i times something

01:06:49.910 --> 01:06:53.390 align:middle line:84%
minus e to the minus
i times that something

01:06:53.390 --> 01:06:57.380 align:middle line:84%
and I subtract those two,
I pick up 2i times sine

01:06:57.380 --> 01:06:59.060 align:middle line:90%
of whatever's in the--

01:06:59.060 --> 01:07:00.450 align:middle line:90%
whatever this real number is.

01:07:00.450 --> 01:07:12.620 align:middle line:84%
So I pick up 1 over 2 pi
times 2i sine of n plus 1/2 x

01:07:12.620 --> 01:07:18.230 align:middle line:90%
over 2i sine of x over 2.

01:07:18.230 --> 01:07:20.510 align:middle line:90%
And these 2i's cancel.

01:07:20.510 --> 01:07:31.010 align:middle line:84%
And that equals 1 over 2
pi sine of n plus 1/2 x

01:07:31.010 --> 01:07:35.420 align:middle line:84%
over sine x over 2,
which is what I wanted.

01:07:35.420 --> 01:07:49.660 align:middle line:90%


01:07:49.660 --> 01:07:59.020 align:middle line:84%
So what's the idea of
trying to prove this?

01:07:59.020 --> 01:08:03.760 align:middle line:84%
In the end-- I mean, in the
beginning, I should say,

01:08:03.760 --> 01:08:05.860 align:middle line:84%
we were asking about
the convergence

01:08:05.860 --> 01:08:08.740 align:middle line:84%
of the partial
Fourier sums to f.

01:08:08.740 --> 01:08:11.610 align:middle line:90%


01:08:11.610 --> 01:08:13.180 align:middle line:90%
And we don't know that going in.

01:08:13.180 --> 01:08:15.530 align:middle line:84%
That's what we're
trying to prove.

01:08:15.530 --> 01:08:19.149 align:middle line:84%
So maybe working
with the partial sums

01:08:19.149 --> 01:08:20.260 align:middle line:90%
is not the best thing.

01:08:20.260 --> 01:08:21.399 align:middle line:90%
What am I getting at here?

01:08:21.399 --> 01:08:25.330 align:middle line:84%
How about I introduce
the next bit, and then

01:08:25.330 --> 01:08:30.060 align:middle line:84%
I'll explain why we're
interested in it.

01:08:30.060 --> 01:08:37.520 align:middle line:84%
So if f is in l2
from minus pi to pi,

01:08:37.520 --> 01:09:00.410 align:middle line:84%
we define the N-th
Cesaro-Fourier mean of f--

01:09:00.410 --> 01:09:03.590 align:middle line:84%
so this is the new
bit of terminology--

01:09:03.590 --> 01:09:06.260 align:middle line:90%


01:09:06.260 --> 01:09:10.415 align:middle line:84%
to be the average of
the partial sums of f.

01:09:10.415 --> 01:09:15.060 align:middle line:90%


01:09:15.060 --> 01:09:18.270 align:middle line:84%
This we denote by
sigma n of f of x.

01:09:18.270 --> 01:09:32.859 align:middle line:84%
This is equal to the average of
the first n partial sums of f.

01:09:32.859 --> 01:09:44.080 align:middle line:90%


01:09:44.080 --> 01:09:48.370 align:middle line:84%
In the end, what
we'd like to do is

01:09:48.370 --> 01:09:54.620 align:middle line:84%
we're trying to establish that
this claim in the yellow box--

01:09:54.620 --> 01:09:58.020 align:middle line:84%
if the Fourier
coefficients are all zero,

01:09:58.020 --> 01:10:00.270 align:middle line:84%
then the function
has to be zero.

01:10:00.270 --> 01:10:04.980 align:middle line:84%
So you may think, well, let's
prove that the partial sums

01:10:04.980 --> 01:10:06.690 align:middle line:90%
converge to the function f.

01:10:06.690 --> 01:10:08.395 align:middle line:84%
And that would
give us immediately

01:10:08.395 --> 01:10:10.770 align:middle line:84%
that the function is 0 because
the partial sums would all

01:10:10.770 --> 01:10:13.680 align:middle line:84%
be 0 because they involve
the coefficients of f.

01:10:13.680 --> 01:10:17.610 align:middle line:84%
But that's ridiculous
because that's actually

01:10:17.610 --> 01:10:18.930 align:middle line:90%
what we're trying to prove.

01:10:18.930 --> 01:10:23.040 align:middle line:84%
That's equivalent to the
question that we're trying to--

01:10:23.040 --> 01:10:25.290 align:middle line:84%
that's equivalent to
what's in the yellow box.

01:10:25.290 --> 01:10:30.510 align:middle line:84%
We're not making our life
any easier by doing that.

01:10:30.510 --> 01:10:38.550 align:middle line:84%
So now, what one
can do instead is

01:10:38.550 --> 01:10:43.398 align:middle line:84%
instead of trying to prove
what's in the yellow box,

01:10:43.398 --> 01:10:44.940 align:middle line:84%
that if all the
coefficients are zero

01:10:44.940 --> 01:10:49.440 align:middle line:84%
the function is zero, what if we
can prove that this object now

01:10:49.440 --> 01:10:52.830 align:middle line:90%
converges to f?

01:10:52.830 --> 01:10:59.780 align:middle line:84%
This object here, which is this
mean of the partial sums maybe

01:10:59.780 --> 01:11:03.530 align:middle line:84%
has better properties
than the partial sums

01:11:03.530 --> 01:11:06.980 align:middle line:84%
originally that we
were trying to study.

01:11:06.980 --> 01:11:13.840 align:middle line:84%
Remember if you
look back to 18.100,

01:11:13.840 --> 01:11:17.350 align:middle line:84%
if you have just say a
sequence of real numbers which

01:11:17.350 --> 01:11:21.550 align:middle line:84%
converges, you can define
a Cesaro mean of that

01:11:21.550 --> 01:11:25.090 align:middle line:84%
by averaging the first n
terms, just like we did here.

01:11:25.090 --> 01:11:28.000 align:middle line:84%
There's an n plus 1 here
because we're starting at 0

01:11:28.000 --> 01:11:30.280 align:middle line:84%
and going up to n rather
than going from 1 to n.

01:11:30.280 --> 01:11:33.040 align:middle line:84%
But if you have a
sequence of real numbers,

01:11:33.040 --> 01:11:36.880 align:middle line:84%
you can look at its Cesaro
sums or Cesaro means.

01:11:36.880 --> 01:11:41.630 align:middle line:84%
And what's great about the
Cesaro means is that you

01:11:41.630 --> 01:11:44.080 align:middle line:90%
don't--

01:11:44.080 --> 01:11:47.950 align:middle line:84%
it kind of behaves a little
bit better than the sequence

01:11:47.950 --> 01:11:48.820 align:middle line:90%
you start with.

01:11:48.820 --> 01:11:50.480 align:middle line:84%
But you don't lose
any information.

01:11:50.480 --> 01:11:52.670 align:middle line:84%
So if the original
sequence converges,

01:11:52.670 --> 01:11:55.570 align:middle line:84%
then the Cesaro
mean also converges.

01:11:55.570 --> 01:12:00.910 align:middle line:84%
So if you're expecting the
partial sums to converge to f,

01:12:00.910 --> 01:12:04.480 align:middle line:84%
then the Cesaro means
should converge to f.

01:12:04.480 --> 01:12:10.750 align:middle line:84%
But the Cesaro means have
an even better quality.

01:12:10.750 --> 01:12:15.100 align:middle line:84%
Let's go back to
sequences of real numbers.

01:12:15.100 --> 01:12:18.520 align:middle line:84%
You could have sequences of
real numbers that don't converge

01:12:18.520 --> 01:12:20.770 align:middle line:90%
whose Cesaro means do converge.

01:12:20.770 --> 01:12:25.540 align:middle line:84%
So take the sequence 1, minus
1, 1 minus, 1, 1 minus 1,

01:12:25.540 --> 01:12:28.870 align:middle line:84%
and so on, that sequence
doesn't converge.

01:12:28.870 --> 01:12:31.120 align:middle line:84%
But the Cesaro
means do converge.

01:12:31.120 --> 01:12:41.910 align:middle line:84%
The Cesaro mean is 1, 0,
1/3, 0, 1/5, 0, 1/7, 0.

01:12:41.910 --> 01:12:43.710 align:middle line:84%
So the Cesaro means
converge to 0.

01:12:43.710 --> 01:12:48.700 align:middle line:84%
So all of that is to say
that this object here,

01:12:48.700 --> 01:12:51.570 align:middle line:84%
which is the average
of the partial sums,

01:12:51.570 --> 01:12:55.200 align:middle line:84%
we expect to behave
better than just

01:12:55.200 --> 01:12:56.670 align:middle line:90%
how the partial sums converge.

01:12:56.670 --> 01:13:03.650 align:middle line:84%
We expect it to have better
convergence properties.

01:13:03.650 --> 01:13:07.180 align:middle line:84%
And what does better
convergence properties mean?

01:13:07.180 --> 01:13:08.980 align:middle line:84%
Quite honestly,
it means we should

01:13:08.980 --> 01:13:13.090 align:middle line:84%
be able to show it
converges to f in hopefully

01:13:13.090 --> 01:13:14.740 align:middle line:90%
some straightforward way--

01:13:14.740 --> 01:13:16.690 align:middle line:84%
or maybe not straightforward
way, but in a--

01:13:16.690 --> 01:13:22.810 align:middle line:90%


01:13:22.810 --> 01:13:26.510 align:middle line:84%
yeah, I don't know
how to describe that.

01:13:26.510 --> 01:13:28.120 align:middle line:90%
And that's what we'll do.

01:13:28.120 --> 01:13:33.650 align:middle line:84%
That's the plan, is what we're
going to show is that for every

01:13:33.650 --> 01:13:39.500 align:middle line:84%
f in l2, the Cesaro means
converge to f in l2,

01:13:39.500 --> 01:13:41.870 align:middle line:84%
meaning the limit as
capital N-- so let me--

01:13:41.870 --> 01:13:44.930 align:middle line:90%


01:13:44.930 --> 01:13:49.970 align:middle line:84%
so what's the goal
that we'll show

01:13:49.970 --> 01:13:54.470 align:middle line:84%
is we'll show that
the Cesaro means--

01:13:54.470 --> 01:14:01.835 align:middle line:84%
Cesaro-Fourier means of
f converge to f in L2.

01:14:01.835 --> 01:14:06.670 align:middle line:90%


01:14:06.670 --> 01:14:12.340 align:middle line:84%
Now, if we can do this,
then we will have answered

01:14:12.340 --> 01:14:15.870 align:middle line:84%
and we will have shown
what's in the yellow box

01:14:15.870 --> 01:14:21.030 align:middle line:84%
because if you assume all of
the Fourier coefficients are 0,

01:14:21.030 --> 01:14:24.300 align:middle line:84%
then all of the
partial sums are 0.

01:14:24.300 --> 01:14:28.380 align:middle line:84%
And therefore, all the
Cesaro means are 0.

01:14:28.380 --> 01:14:31.980 align:middle line:84%
And by this thing that
we are hoping to prove,

01:14:31.980 --> 01:14:35.590 align:middle line:84%
this will prove that
0 converges to f.

01:14:35.590 --> 01:14:39.320 align:middle line:84%
And therefore, f is 0, which
is what we wanted to show.

01:14:39.320 --> 01:14:42.190 align:middle line:90%
So one more time--

01:14:42.190 --> 01:14:45.640 align:middle line:84%
we want to prove that if all
the Fourier coefficients are 0,

01:14:45.640 --> 01:14:47.920 align:middle line:90%
then the function has to be 0.

01:14:47.920 --> 01:14:49.960 align:middle line:84%
Now, if all the Fourier
coefficients are 0,

01:14:49.960 --> 01:14:51.430 align:middle line:90%
then all the partial sums are 0.

01:14:51.430 --> 01:14:54.010 align:middle line:84%
And therefore, all
the 0 means are 0.

01:14:54.010 --> 01:15:00.400 align:middle line:84%
And if we're able to prove
this holds for all f in l2,

01:15:00.400 --> 01:15:03.100 align:middle line:84%
then this would tell
us that 0, which

01:15:03.100 --> 01:15:06.250 align:middle line:84%
is what all of these
Cesaro-Fourier means are,

01:15:06.250 --> 01:15:09.200 align:middle line:90%
converges to f.

01:15:09.200 --> 01:15:13.970 align:middle line:84%
And therefore, f is 0,
our desired conclusion.

01:15:13.970 --> 01:15:19.550 align:middle line:84%
And from that, we conclude
that the collection

01:15:19.550 --> 01:15:22.370 align:middle line:84%
e to the inx over square
root of 2 pi is a maximal--

01:15:22.370 --> 01:15:24.320 align:middle line:90%
is a orthonormal basis for l2.

01:15:24.320 --> 01:15:26.600 align:middle line:84%
And therefore,
the Fourier series

01:15:26.600 --> 01:15:36.020 align:middle line:84%
of a given l2 function converges
to the function in l2, meaning

01:15:36.020 --> 01:15:39.140 align:middle line:84%
f minus the partial
sum converges to 0

01:15:39.140 --> 01:15:42.710 align:middle line:90%
as n goes to infinity.

01:15:42.710 --> 01:15:45.730 align:middle line:90%


01:15:45.730 --> 01:15:49.350 align:middle line:84%
All right, and so that'll
be what we do next time,

01:15:49.350 --> 01:15:54.800 align:middle line:90%
is prove this claim right here.

01:15:54.800 --> 01:16:01.000 align:middle line:90%