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CASEY RODRIGUEZ: All right.

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So last lecture, we
concluded our discussion

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about measurable functions,
I mean, measurable sets.

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And remember our
original motivation was

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that we're trying to build an
integral that somehow surpasses

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the properties of that of
the Riemann integral in that,

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hopefully, this larger
class of functions

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that are integral with
respect to this integral

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form a Banach space as opposed
to Riemann integral functions.

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And we started off by
asking the question,

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how would we integrate the
simplest types of functions,

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which are just one on a
set and zero off of it.

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And that led us to
how to define measure.

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And so then we define
Lebesgue measurable sets,

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proved that they form this
special type of collection

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of sets called
the sigma algebra,

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and that they contain
a lot of sets,

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a lot of interesting sets,
open, closed, unions,

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countable unions of closed,
which are not necessarily

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closed, countable
intersections of opens,

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which are not necessarily
open, and so on.

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Now not every set is
Lebesgue measurable.

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We will not go through
that construction

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of a nonmeasurable set.

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The construction of the
set or how one obtains it

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also would provide a
proof that we could not

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build a measure that's defined
on all subsets of real numbers

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having these three properties
that is translation invariant.

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The measure of an interval is
the length of the interval.

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And the measure of
a disjoint union

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is the sum of the measures.

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But this is a functional
analysis class.

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Our goal is to build up a Banach
space of integral functions

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so we needed to define a
better notion of integral

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than Riemann.

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I imagine in a
measured theory class,

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you would see such
a construction

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but we won't cover that here.

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So in some sense, if
we've built up measure,

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we kind of know,
roughly speaking,

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how we would
integrate the simplest

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type of function, which
is one on a measurable set

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and zero off of it.

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Now what about what
would be a method

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of trying to integrate
more general functions?

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So this is, I think--

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so now we're going to be
talking about measurable--

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this is how it's spelled--

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measurable functions.

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So to motivate the definition
of a measurable function,

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let me just give a
few minutes of why

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we introduced this definition,
what's really behind it.

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So historically,
when Lebesgue thought

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of his theory of integration,
if we had a function on a closed

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interval, AB--

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and let me draw it.

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Let's say it's just increasing.

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So what Riemann does, of
course, is you partition up ab.

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And then you form,
essentially, these boxes

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that have width given
by how you've chopped up

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ab and height given by f,
the function f, evaluated

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at some point in
those subintervals.

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Right.

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And you form a Riemann
sum and you take a limit.

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Yeah.

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And that gives you
the Riemann integral.

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And so what Lebesgue thought
of doing was, instead of

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chopping up the domain,
chopping up the range.

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So let's imagine-- so this
function is only this height.

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So what he would do, or what
one would do, is let's--

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and let's say we're just
interested in integrating

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non-negative things--

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chop up the range and so
on up to some finite point.

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And now how do you form
your boxes, if you like,

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that you're going
to take the size of?

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Well, you look at
the piece of f that's

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in between a given partition.

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And this portion of f will--

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OK.

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In this picture, we'll
call this point c.

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So then you take this
portion of f that's in here.

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And then ac would be given
by is the set f inverse of,

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in this picture--

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and I'm just going to
write it in this way--

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yi, y, yi minus 1, yi.

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And you could build
up a box by now

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taking it to be
the lower value y2

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and having width
given by a to c.

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And I can actually
do this because this

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is an increasing function so
this will be an actual box.

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Now what am I getting at?

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And then you would
say something like we

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would like to define the
integral of f over ab.

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So this is all motivation,
informal discussion.

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Don't take this
to heart too much.

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Then we would like to
define the integral from ab

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to f to be somehow this limit.

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And I'm not even going
to write as something

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goes to zero or infinity
you can think of

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as partitions get smaller of
a sum now where I'm summing

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from i equals 1 to n of y
minus 1, so the lower part,

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times now the length of,
at least for this picture--

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so this would be the length
of the interval given

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by f inverse of yi minus 1, yi.

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OK?

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So this would be kind of
an analogous procedure

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to what Reimann
does on the domain

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except now focusing
on the range.

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Now I wrote length
here because this

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function I drew is increasing
so the inverse image of one

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of these intervals is going
to be another interval.

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So the length is meaningful.

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But if f is more
general, f inverse

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doesn't need to be of yi minus
1, yi, need not be an interval.

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And so taking its length would
not be a meaningful thing.

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But remember we now have
this notion of measure, which

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should be the substitute
for length for more

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general sets, measurable sets.

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So this procedure
could still work

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if, instead of this requiring
that this is an interval,

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requiring that this is a
Lebesgue measurable set.

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And then perhaps one
could define the integral

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in this way.

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And there these kind of things
would no longer be boxes.

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So that should
motivate why perhaps we

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should look at functions
so that the inverse image

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of closed intervals is a
measurable set so that we can

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take its measure and maybe
do this procedure of defining

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an integral.

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Now all of that is a bit--

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again, this is all
informal discussion

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just meant to be motivation.

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In fact, in how we'll define
the Lebesgue integral,

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we're not going to
define it in this way,

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because what this way
of doing it suffers

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is it's not clear that
this is independent of how

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I partitioned up the range.

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So maybe if I take a limit
as the partitions get smaller

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along some sequence
of partitions,

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I get a different
number from the others

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so that would have
to be checked.

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But as we'll see when we
do define the Lebesgue

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integral, this number,
you can compute it

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by essentially this
procedure I gave here

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where you chop up the range
of f and take approximations

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to f that are more general
than just step functions, which

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is what this is.

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It's a function that's a
given value off on an interval

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and then zero outside.

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And that'll be a way of seeing
that this motivation connects

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to actually how we define
the Lebesgue integral.

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But again, the whole point
of what I'm saying is that--

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we're trying to motivate
is that we should,

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and at least
historically this is

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why one considers these
things, consider functions

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so that the inverse image of
closed intervals is measurable.

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OK.

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And that's the motivation
for measurable functions.

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Now, as we saw when
we were discussing

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what sets are measurable,
we didn't exactly

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conclude directly that closed
intervals were measurable.

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We started with something
a little more basic,

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which was half
infinite intervals,

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proved those were
measurable, and then

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concluded that close
intervals are measurable.

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Any interval is measurable.

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And so when we actually
define measurable functions,

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we'll be using as input more of
these half infinite intervals

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being measurable
rather than this.

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So let's get to it.

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Let's define
measurable function.

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So now just this comes
with the territory.

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But we're going
to be considering

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extended real valued
functions in what we do.

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So I shouldn't have
written that down.

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I should have written down
extended real numbers.

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What does this mean?

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This just means the
set of real numbers

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along with plus
and minus infinity.

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So when I write the
interval minus infinity,

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infinity, this is our union,
the two symbols plus or minus

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infinity.

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Now we're going to
have expressions

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where we allow a function to
take on the value plus infinity

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or minus infinity.

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So we should set down what
we mean when we multiply

00:13:34.560 --> 00:13:37.925 align:middle line:90%
some of these things together.

00:13:37.925 --> 00:13:49.720 align:middle line:90%


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So sums are defined
as x plus or minus

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infinity equals plus or minus
infinity for all x in r.

00:13:59.050 --> 00:14:06.070 align:middle line:84%
So if I have two functions
whose values could

00:14:06.070 --> 00:14:09.520 align:middle line:84%
be in the extended real numbers
and I have one is finite

00:14:09.520 --> 00:14:11.920 align:middle line:84%
and the other is
infinite, then I just,

00:14:11.920 --> 00:14:17.350 align:middle line:84%
by convention, their sum is
defined to be plus infinity.

00:14:17.350 --> 00:14:21.650 align:middle line:90%


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But I'm not allowed
to take infinity

00:14:24.530 --> 00:14:29.490 align:middle line:84%
minus infinity or infinity
plus minus infinity.

00:14:29.490 --> 00:14:47.030 align:middle line:84%
So this and products are defined
as we take the convention

00:14:47.030 --> 00:14:53.144 align:middle line:84%
that zero times plus or
minus infinity equals zero.

00:14:53.144 --> 00:14:55.810 align:middle line:90%


00:14:55.810 --> 00:15:00.460 align:middle line:84%
And we won't come
up against this

00:15:00.460 --> 00:15:02.950 align:middle line:84%
until we discuss
the integral, why

00:15:02.950 --> 00:15:04.450 align:middle line:90%
we would need such expressions.

00:15:04.450 --> 00:15:08.110 align:middle line:84%
But you could have a
function that's, let's say,

00:15:08.110 --> 00:15:10.750 align:middle line:84%
identically equal to
infinity, identically gives

00:15:10.750 --> 00:15:12.490 align:middle line:90%
this symbol plus infinity.

00:15:12.490 --> 00:15:16.000 align:middle line:84%
If I multiply that function by
zero, then I should get zero.

00:15:16.000 --> 00:15:19.270 align:middle line:84%
This has nothing to do with
limiting processes though.

00:15:19.270 --> 00:15:21.623 align:middle line:84%
These are purely
algebraic expressions

00:15:21.623 --> 00:15:22.540 align:middle line:90%
we'll be dealing with.

00:15:22.540 --> 00:15:25.090 align:middle line:84%
I'm not saying that
everything you learned

00:15:25.090 --> 00:15:28.330 align:middle line:84%
in 18100 Real Analysis
about being careful when

00:15:28.330 --> 00:15:32.530 align:middle line:84%
you have infinity over infinity
or zero times infinity is--

00:15:32.530 --> 00:15:34.810 align:middle line:90%
I'm not saying throw that away.

00:15:34.810 --> 00:15:39.400 align:middle line:84%
I'm just saying when we have
certain algebraic expressions,

00:15:39.400 --> 00:15:42.490 align:middle line:84%
these are the conventions
that we adopt.

00:15:42.490 --> 00:15:47.280 align:middle line:84%
And x times plus
or minus infinity

00:15:47.280 --> 00:15:54.746 align:middle line:84%
equals plus or minus infinity
for all x in R take away zero.

00:15:54.746 --> 00:15:56.660 align:middle line:90%
OK.

00:15:56.660 --> 00:16:01.135 align:middle line:84%
And let me just recall for
you what it means for--

00:16:01.135 --> 00:16:07.190 align:middle line:90%


00:16:07.190 --> 00:16:09.830 align:middle line:84%
we'll be making some
limiting statements

00:16:09.830 --> 00:16:13.500 align:middle line:84%
about certain numbers
approaching other numbers.

00:16:13.500 --> 00:16:16.130 align:middle line:84%
So what would it mean
for a sequence of numbers

00:16:16.130 --> 00:16:19.850 align:middle line:84%
to approach plus infinity
or minus infinity?

00:16:19.850 --> 00:16:33.230 align:middle line:84%
I want you to recall that a
sequence a n of real numbers

00:16:33.230 --> 00:16:36.800 align:middle line:90%
converges to infinity.

00:16:36.800 --> 00:16:40.250 align:middle line:84%
And then you can make a similar
definition for minus infinity

00:16:40.250 --> 00:16:50.440 align:middle line:84%
if, for every R positive, there
exists a natural number N such

00:16:50.440 --> 00:16:54.460 align:middle line:84%
that for all N bigger
than or equal to N

00:16:54.460 --> 00:16:58.914 align:middle line:90%
a sub n is bigger than R. OK.

00:16:58.914 --> 00:17:03.190 align:middle line:90%


00:17:03.190 --> 00:17:03.690 align:middle line:90%
OK.

00:17:03.690 --> 00:17:06.329 align:middle line:84%
And I mean I've been using
something equals infinity

00:17:06.329 --> 00:17:08.910 align:middle line:84%
already when we've
been just discussing

00:17:08.910 --> 00:17:10.710 align:middle line:84%
measure, the outer
measure of something

00:17:10.710 --> 00:17:12.750 align:middle line:90%
being equal to infinity.

00:17:12.750 --> 00:17:14.700 align:middle line:84%
In what follows, we'll
be having expressions

00:17:14.700 --> 00:17:16.980 align:middle line:84%
where we allow something
to equal infinity.

00:17:16.980 --> 00:17:21.069 align:middle line:84%
And we'll have algebraic
expressions of this type

00:17:21.069 --> 00:17:23.160 align:middle line:84%
so I just need to
set down convention

00:17:23.160 --> 00:17:24.990 align:middle line:84%
that if I have a real
number plus or minus

00:17:24.990 --> 00:17:28.740 align:middle line:84%
infinity, that is by definition
equal to plus or minus

00:17:28.740 --> 00:17:29.310 align:middle line:90%
infinity.

00:17:29.310 --> 00:17:31.980 align:middle line:84%
If I have zero
times something that

00:17:31.980 --> 00:17:35.490 align:middle line:84%
equals plus or minus infinity,
then that is by convention

00:17:35.490 --> 00:17:40.990 align:middle line:90%
equal to zero and so on.

00:17:40.990 --> 00:17:41.590 align:middle line:90%
All right.

00:17:41.590 --> 00:17:50.880 align:middle line:84%
So measurable
functions I said should

00:17:50.880 --> 00:17:54.900 align:middle line:84%
be those functions
at least motivated

00:17:54.900 --> 00:17:56.610 align:middle line:90%
by this discussion before.

00:17:56.610 --> 00:18:00.690 align:middle line:84%
Those functions or the
functions we're interested in

00:18:00.690 --> 00:18:02.832 align:middle line:84%
are those functions so
that the inverse image

00:18:02.832 --> 00:18:04.290 align:middle line:84%
of closed intervals
are measurable.

00:18:04.290 --> 00:18:07.965 align:middle line:84%
So that's how we'll define
measurable functions almost.

00:18:07.965 --> 00:18:11.323 align:middle line:90%


00:18:11.323 --> 00:18:13.490 align:middle line:84%
And the equivalent way,
which is a little bit easier

00:18:13.490 --> 00:18:15.990 align:middle line:90%
to work with, is the following.

00:18:15.990 --> 00:18:30.440 align:middle line:84%
So let E be a measurable set and
f from E to the extended reels.

00:18:30.440 --> 00:18:35.880 align:middle line:90%


00:18:35.880 --> 00:18:46.350 align:middle line:84%
You say f is
Lebesgue measurable--

00:18:46.350 --> 00:18:54.960 align:middle line:84%
that's new terminology--
if, for all alpha in R,

00:18:54.960 --> 00:19:02.360 align:middle line:84%
if I take the inverse image
of the half infinite interval,

00:19:02.360 --> 00:19:12.130 align:middle line:84%
alpha to infinity, this is
measurable I should say.

00:19:12.130 --> 00:19:15.010 align:middle line:84%
We had some notation
last time, the script

00:19:15.010 --> 00:19:19.315 align:middle line:84%
M being the collection
of measurable sets, i.e.

00:19:19.315 --> 00:19:22.100 align:middle line:90%


00:19:22.100 --> 00:19:24.320 align:middle line:90%
is Lebesgue measurable.

00:19:24.320 --> 00:19:24.820 align:middle line:90%
OK.

00:19:24.820 --> 00:19:29.210 align:middle line:90%


00:19:29.210 --> 00:19:31.930 align:middle line:84%
As we'll see in a minute, this
is an equivalent definition

00:19:31.930 --> 00:19:35.710 align:middle line:84%
really of requiring
that the inverse image

00:19:35.710 --> 00:19:42.340 align:middle line:84%
of a closed and bounded
interval is measurable,

00:19:42.340 --> 00:19:43.938 align:middle line:84%
or at least we'll
see one direction

00:19:43.938 --> 00:19:44.980 align:middle line:90%
of why that's equivalent.

00:19:44.980 --> 00:19:48.250 align:middle line:84%
And then in your own
time, you can figure out

00:19:48.250 --> 00:19:50.620 align:middle line:90%
why it's actually equivalent.

00:19:50.620 --> 00:19:58.480 align:middle line:90%
So now why not include alpha?

00:19:58.480 --> 00:20:01.090 align:middle line:84%
Why do I have to look at the
inverse image of this half

00:20:01.090 --> 00:20:03.040 align:middle line:90%
open interval?

00:20:03.040 --> 00:20:06.250 align:middle line:84%
And why am I going from
alpha to infinity and not,

00:20:06.250 --> 00:20:10.270 align:middle line:84%
say, alpha to minus infinity
or include alpha there?

00:20:10.270 --> 00:20:11.650 align:middle line:90%
Why this specific kind?

00:20:11.650 --> 00:20:14.020 align:middle line:84%
And then so what I
want to first tell you

00:20:14.020 --> 00:20:20.180 align:middle line:84%
is that looking at
those types of sets

00:20:20.180 --> 00:20:21.740 align:middle line:84%
and seeing if those
are measurable

00:20:21.740 --> 00:20:24.270 align:middle line:84%
is equivalent to this
definition that I'm giving here.

00:20:24.270 --> 00:20:34.130 align:middle line:90%


00:20:34.130 --> 00:20:37.030 align:middle line:84%
So let's take a function
from a measurable set E,

00:20:37.030 --> 00:20:41.495 align:middle line:84%
a subset of R to
the extended reals.

00:20:41.495 --> 00:20:50.560 align:middle line:90%


00:20:50.560 --> 00:20:55.960 align:middle line:84%
Then the following
are equivalent.

00:20:55.960 --> 00:20:58.780 align:middle line:90%


00:20:58.780 --> 00:21:07.100 align:middle line:84%
One is kind of the
property that's

00:21:07.100 --> 00:21:08.750 align:middle line:84%
in the definition
of being measurable.

00:21:08.750 --> 00:21:19.460 align:middle line:84%
For all alpha in R, f inverse
of alpha infinity is measurable.

00:21:19.460 --> 00:21:20.480 align:middle line:90%
Two.

00:21:20.480 --> 00:21:32.030 align:middle line:84%
For all alpha in R, f inverse
including alpha is measurable.

00:21:32.030 --> 00:21:34.810 align:middle line:90%


00:21:34.810 --> 00:21:36.280 align:middle line:90%
Three.

00:21:36.280 --> 00:21:44.160 align:middle line:84%
All alpha in R, the
inverse image of minus

00:21:44.160 --> 00:21:48.000 align:middle line:90%
infinity to alpha is measurable.

00:21:48.000 --> 00:21:54.310 align:middle line:90%


00:21:54.310 --> 00:22:01.880 align:middle line:84%
And the last condition
is, for all alpha in R,

00:22:01.880 --> 00:22:11.240 align:middle line:84%
the inverse image of now
include alpha is measurable.

00:22:11.240 --> 00:22:17.510 align:middle line:84%
So to check what
you get from this,

00:22:17.510 --> 00:22:19.740 align:middle line:84%
to check that a function
is Lebesgue measurable,

00:22:19.740 --> 00:22:26.380 align:middle line:84%
it suffices not to just
solely prove this property

00:22:26.380 --> 00:22:27.920 align:middle line:90%
or check this property.

00:22:27.920 --> 00:22:30.460 align:middle line:84%
You can check it on
other types of sets.

00:22:30.460 --> 00:22:33.310 align:middle line:84%
It suffices to only check
it-- it suffices to check it

00:22:33.310 --> 00:22:36.370 align:middle line:84%
on either these types of
sets, or these types of sets,

00:22:36.370 --> 00:22:38.260 align:middle line:90%
or these types of sets.

00:22:38.260 --> 00:22:44.650 align:middle line:84%
So if you can prove that for
all alpha, this type of set

00:22:44.650 --> 00:22:47.320 align:middle line:84%
or the inverse image of
these types of intervals

00:22:47.320 --> 00:22:50.050 align:middle line:84%
are measurable, then
it's equivalent to saying

00:22:50.050 --> 00:22:51.488 align:middle line:90%
that f is Lebesgue measurable.

00:22:51.488 --> 00:22:51.988 align:middle line:90%
OK.

00:22:51.988 --> 00:22:56.740 align:middle line:90%


00:22:56.740 --> 00:22:57.240 align:middle line:90%
OK.

00:22:57.240 --> 00:23:00.610 align:middle line:90%


00:23:00.610 --> 00:23:02.710 align:middle line:84%
Now the proof is not
hard based on what

00:23:02.710 --> 00:23:05.500 align:middle line:84%
we know about Lebesgue
measurable sets

00:23:05.500 --> 00:23:08.480 align:middle line:84%
which, again, we proved last
time that they form a sigma

00:23:08.480 --> 00:23:08.980 align:middle line:90%
algebra.

00:23:08.980 --> 00:23:11.120 align:middle line:84%
They're closed under
taking countable unions,

00:23:11.120 --> 00:23:13.670 align:middle line:84%
intersections, and
complements, and so on.

00:23:13.670 --> 00:23:19.980 align:middle line:84%
So let's first prove
that one implies two.

00:23:19.980 --> 00:23:22.500 align:middle line:84%
So I'm saying they're all
equivalent, which means they

00:23:22.500 --> 00:23:24.040 align:middle line:90%
should all imply each other.

00:23:24.040 --> 00:23:28.130 align:middle line:84%
So let's first prove
one implies two.

00:23:28.130 --> 00:23:41.360 align:middle line:84%
So suppose one holds,
then for all alpha in R,

00:23:41.360 --> 00:23:44.090 align:middle line:84%
now I want to check
that two holds.

00:23:44.090 --> 00:23:50.630 align:middle line:84%
I can write alpha to
infinity as the intersection

00:23:50.630 --> 00:23:55.130 align:middle line:84%
over natural numbers
n of alpha minus 1

00:23:55.130 --> 00:24:00.320 align:middle line:84%
over n infinity, which implies
the great thing about taking

00:24:00.320 --> 00:24:10.190 align:middle line:84%
inverse images is that they
respect all operations you

00:24:10.190 --> 00:24:11.000 align:middle line:90%
can do on set.

00:24:11.000 --> 00:24:13.790 align:middle line:84%
So the inverse image of
any type of intersection

00:24:13.790 --> 00:24:15.665 align:middle line:84%
is the intersection
of the inverse images.

00:24:15.665 --> 00:24:24.460 align:middle line:90%


00:24:24.460 --> 00:24:34.310 align:middle line:84%
And if I'm assuming each of
these is measurable by 1,

00:24:34.310 --> 00:24:37.070 align:middle line:84%
then this is a
countable intersection

00:24:37.070 --> 00:24:39.770 align:middle line:90%
of Lebesgue measurable sets.

00:24:39.770 --> 00:24:42.770 align:middle line:84%
Again, when I say what is
the Lebesgue measurable sets,

00:24:42.770 --> 00:24:46.040 align:middle line:84%
I'm talking about the inverse
image of this set, not

00:24:46.040 --> 00:24:47.630 align:middle line:90%
this set in here.

00:24:47.630 --> 00:24:50.790 align:middle line:84%
I'm talking about the inverse
image of this interval.

00:24:50.790 --> 00:24:53.120 align:middle line:84%
So each of those is
a Lebesgue measurable

00:24:53.120 --> 00:24:58.260 align:middle line:84%
set so their intersection
is Lebesgue measurable.

00:24:58.260 --> 00:25:00.210 align:middle line:90%
OK.

00:25:00.210 --> 00:25:02.430 align:middle line:84%
And therefore for
every alpha in R,

00:25:02.430 --> 00:25:05.340 align:middle line:84%
the inverse image of
these closed intervals

00:25:05.340 --> 00:25:09.660 align:middle line:90%
are measurable.

00:25:09.660 --> 00:25:13.380 align:middle line:84%
And how do I show
two implies one?

00:25:13.380 --> 00:25:15.675 align:middle line:90%
By a similar game.

00:25:15.675 --> 00:25:18.970 align:middle line:90%


00:25:18.970 --> 00:25:19.870 align:middle line:90%
Suppose two holds.

00:25:19.870 --> 00:25:22.470 align:middle line:90%


00:25:22.470 --> 00:25:31.780 align:middle line:84%
Then for all alpha in R,
the half open interval now

00:25:31.780 --> 00:25:38.070 align:middle line:84%
I can write as the union
over n alpha plus 1 over n

00:25:38.070 --> 00:25:39.000 align:middle line:90%
to infinity.

00:25:39.000 --> 00:25:42.710 align:middle line:90%


00:25:42.710 --> 00:25:48.220 align:middle line:84%
And therefore the inverse
image of alpha to infinity

00:25:48.220 --> 00:25:52.420 align:middle line:84%
is equal to the union of the
inverse images of these sets.

00:25:52.420 --> 00:25:58.800 align:middle line:90%


00:25:58.800 --> 00:26:03.000 align:middle line:84%
And again, if I'm assuming two,
then I'm assuming each of these

00:26:03.000 --> 00:26:06.090 align:middle line:84%
for each n is a
Lebesgue measurable set.

00:26:06.090 --> 00:26:09.210 align:middle line:84%
And we know countable unions
of Lebesgue measurable sets

00:26:09.210 --> 00:26:10.620 align:middle line:90%
are again Lebesgue measurable.

00:26:10.620 --> 00:26:14.760 align:middle line:90%
So this is Lebesgue measurable.

00:26:14.760 --> 00:26:15.390 align:middle line:90%
OK.

00:26:15.390 --> 00:26:20.540 align:middle line:84%
So that proves one and
two are equivalent.

00:26:20.540 --> 00:26:31.610 align:middle line:90%


00:26:31.610 --> 00:26:33.290 align:middle line:90%
OK.

00:26:33.290 --> 00:26:39.520 align:middle line:90%
And we get three and four.

00:26:39.520 --> 00:26:46.170 align:middle line:84%
So first off, two is
equivalent to three

00:26:46.170 --> 00:26:50.850 align:middle line:90%
simply because if I take--

00:26:50.850 --> 00:26:55.750 align:middle line:84%
let's see-- minus
infinity to alpha,

00:26:55.750 --> 00:27:04.710 align:middle line:84%
this is equal to alpha
infinity complement.

00:27:04.710 --> 00:27:06.900 align:middle line:84%
And therefore again, when
I take inverse images,

00:27:06.900 --> 00:27:10.140 align:middle line:84%
and knowing that that the
complement of a Lebesgue

00:27:10.140 --> 00:27:12.690 align:middle line:84%
measurable set is
Lebesgue measurable,

00:27:12.690 --> 00:27:20.180 align:middle line:84%
I get that two is
equivalent to three and one

00:27:20.180 --> 00:27:23.080 align:middle line:90%
is equivalent to four.

00:27:23.080 --> 00:27:27.820 align:middle line:84%
Again, since I have
this last type of set,

00:27:27.820 --> 00:27:31.510 align:middle line:84%
minus infinity to alpha,
this is equal to-- so this

00:27:31.510 --> 00:27:37.940 align:middle line:84%
is for all alpha in R
since for all alpha in R,

00:27:37.940 --> 00:27:43.080 align:middle line:90%
this is equal to complement.

00:27:43.080 --> 00:27:47.300 align:middle line:84%
So again, if I take the
inverse image of this set,

00:27:47.300 --> 00:27:50.990 align:middle line:84%
I will get the complement of
the inverse image of this set.

00:27:50.990 --> 00:27:53.983 align:middle line:84%
And if that's measurable, that
inverse image is measurable,

00:27:53.983 --> 00:27:55.400 align:middle line:84%
then its complement
is measurable,

00:27:55.400 --> 00:27:57.680 align:middle line:90%
implying that's measurable.

00:27:57.680 --> 00:28:02.510 align:middle line:84%
So it's a simple game or it's
a simple proof just based

00:28:02.510 --> 00:28:06.170 align:middle line:84%
on the fact that we know
that Lebesgue measurable

00:28:06.170 --> 00:28:08.430 align:middle line:84%
sets are closed undertaking
countable unions,

00:28:08.430 --> 00:28:10.955 align:middle line:90%
intersections, and complements.

00:28:10.955 --> 00:28:11.455 align:middle line:90%
OK.

00:28:11.455 --> 00:28:18.420 align:middle line:90%


00:28:18.420 --> 00:28:21.270 align:middle line:84%
So then we get the
following theorem

00:28:21.270 --> 00:28:29.730 align:middle line:84%
that, if E is measurable, so E
is a subset of R is measurable,

00:28:29.730 --> 00:28:39.030 align:middle line:84%
and f from E to R is a
measurable function--

00:28:39.030 --> 00:28:46.055 align:middle line:90%


00:28:46.055 --> 00:28:47.680 align:middle line:84%
in the future, I will
probably just say

00:28:47.680 --> 00:28:50.650 align:middle line:84%
f is measurable, not a
measurable function--

00:28:50.650 --> 00:28:55.410 align:middle line:90%


00:28:55.410 --> 00:29:12.930 align:middle line:84%
then for all f in the Borel
sigma algebra, f inverse of F

00:29:12.930 --> 00:29:13.680 align:middle line:90%
is measurable.

00:29:13.680 --> 00:29:18.120 align:middle line:84%
The inverse image
of f is measurable.

00:29:18.120 --> 00:29:18.840 align:middle line:90%
OK.

00:29:18.840 --> 00:29:23.275 align:middle line:90%
So what's the proof?

00:29:23.275 --> 00:29:33.120 align:middle line:90%


00:29:33.120 --> 00:29:41.560 align:middle line:84%
f measurable implies
that, for all ab, a less

00:29:41.560 --> 00:29:49.040 align:middle line:84%
b, f inverse of the
open interval ab, which

00:29:49.040 --> 00:30:06.910 align:middle line:84%
is equal to the f inverse
of the two intersect equals

00:30:06.910 --> 00:30:08.050 align:middle line:90%
f inverse of--

00:30:08.050 --> 00:30:18.610 align:middle line:90%


00:30:18.610 --> 00:30:23.050 align:middle line:84%
So if I take the inverse image
of this open interval ab,

00:30:23.050 --> 00:30:26.282 align:middle line:84%
then it's equal to the inverse
image of this intersection,

00:30:26.282 --> 00:30:28.240 align:middle line:84%
which is equal to the
intersection of these two

00:30:28.240 --> 00:30:29.360 align:middle line:90%
inverse images.

00:30:29.360 --> 00:30:31.700 align:middle line:84%
And if I'm assuming
f is measurable,

00:30:31.700 --> 00:30:34.150 align:middle line:90%
then each of these sets--

00:30:34.150 --> 00:30:37.600 align:middle line:84%
each of these pre-images
are measurable

00:30:37.600 --> 00:30:43.920 align:middle line:84%
by the previous theorem
that I just proved

00:30:43.920 --> 00:30:48.730 align:middle line:90%
and therefore that's measurable.

00:30:48.730 --> 00:31:01.500 align:middle line:84%
So I've shown that open
intervals are measurable.

00:31:01.500 --> 00:31:08.650 align:middle line:90%


00:31:08.650 --> 00:31:15.820 align:middle line:84%
And similar to how we concluded
that open sets are measurable,

00:31:15.820 --> 00:31:17.140 align:middle line:90%
you can then--

00:31:17.140 --> 00:31:19.780 align:middle line:84%
we use the fact that
every open set, which

00:31:19.780 --> 00:31:23.140 align:middle line:84%
you proved in assignment 3, that
every open set can be written

00:31:23.140 --> 00:31:31.790 align:middle line:84%
as a countable union of
disjoint open intervals,

00:31:31.790 --> 00:31:43.650 align:middle line:84%
thus f inverse of u is
measurable for all open sets,

00:31:43.650 --> 00:31:47.920 align:middle line:90%
subsets of R. OK.

00:31:47.920 --> 00:31:50.440 align:middle line:90%


00:31:50.440 --> 00:31:56.180 align:middle line:90%
And since the set--

00:31:56.180 --> 00:32:02.390 align:middle line:84%
let's call it A, which
is the set of all F such

00:32:02.390 --> 00:32:09.860 align:middle line:90%
that this is a--

00:32:09.860 --> 00:32:12.350 align:middle line:84%
so you're also proving
in the assignment

00:32:12.350 --> 00:32:16.670 align:middle line:84%
this collection of sets, such
that the inverse images are

00:32:16.670 --> 00:32:30.610 align:middle line:84%
Lebesgue measurable, this is
a sigma algebra containing--

00:32:30.610 --> 00:32:37.780 align:middle line:84%
since we've now proved that
all open sets are in the set,

00:32:37.780 --> 00:32:43.040 align:middle line:84%
this implies that the Borel
sigma algebra, which is, again,

00:32:43.040 --> 00:32:46.760 align:middle line:84%
the smallest sigma algebra
containing all open sets,

00:32:46.760 --> 00:32:52.550 align:middle line:84%
is a subset of
this here, which is

00:32:52.550 --> 00:32:54.268 align:middle line:90%
the statement of the theorem.

00:32:54.268 --> 00:32:54.768 align:middle line:90%
OK.

00:32:54.768 --> 00:33:00.210 align:middle line:90%


00:33:00.210 --> 00:33:01.550 align:middle line:90%
All right.

00:33:01.550 --> 00:33:10.590 align:middle line:84%
And so let me just add on
here another thing that--

00:33:10.590 --> 00:33:11.090 align:middle line:90%
OK.

00:33:11.090 --> 00:33:15.110 align:middle line:84%
So now we know that if we
have a measurable function,

00:33:15.110 --> 00:33:21.460 align:middle line:84%
it takes the inverse
image of Borel sets.

00:33:21.460 --> 00:33:24.760 align:middle line:84%
So sets that belong in the Borel
sigma algebra are measurable.

00:33:24.760 --> 00:33:26.155 align:middle line:90%
This includes all open sets.

00:33:26.155 --> 00:33:28.870 align:middle line:90%


00:33:28.870 --> 00:33:34.220 align:middle line:84%
What about throwing plus or
minus infinity into the mix?

00:33:34.220 --> 00:33:47.120 align:middle line:84%
So if f goes from one measurable
set E to R is measurable,

00:33:47.120 --> 00:33:59.110 align:middle line:90%
then the sets--

00:33:59.110 --> 00:34:00.470 align:middle line:90%
well, let me write it this way.

00:34:00.470 --> 00:34:11.670 align:middle line:84%
The inverse image of where
f is infinite or equal

00:34:11.670 --> 00:34:16.020 align:middle line:84%
to minus infinity, these
are measurable as well.

00:34:16.020 --> 00:34:19.429 align:middle line:90%
And how does one prove that?

00:34:19.429 --> 00:34:20.134 align:middle line:90%
So proof.

00:34:20.134 --> 00:34:24.530 align:middle line:90%


00:34:24.530 --> 00:34:27.380 align:middle line:84%
Again, we could just use the
definition of how this works

00:34:27.380 --> 00:34:30.409 align:middle line:84%
and the fact that we know
Lebesgue measurable functions,

00:34:30.409 --> 00:34:33.530 align:middle line:84%
or Lebesgue measurable
sets, are closed

00:34:33.530 --> 00:34:36.469 align:middle line:84%
undertaking countable
intersections, unions,

00:34:36.469 --> 00:34:37.520 align:middle line:90%
and complements.

00:34:37.520 --> 00:34:42.909 align:middle line:90%


00:34:42.909 --> 00:34:49.050 align:middle line:84%
We have that f
inverse of infinity,

00:34:49.050 --> 00:34:52.500 align:middle line:84%
this is equal to the
intersection overall n

00:34:52.500 --> 00:35:01.270 align:middle line:84%
of f inverse, the inverse
image of n to infinity.

00:35:01.270 --> 00:35:03.780 align:middle line:90%


00:35:03.780 --> 00:35:08.120 align:middle line:84%
And if I'm assuming f is
measurable, then each of these

00:35:08.120 --> 00:35:09.920 align:middle line:90%
is a measurable set.

00:35:09.920 --> 00:35:13.010 align:middle line:84%
The inverse image of n to
infinity is a measurable set.

00:35:13.010 --> 00:35:17.580 align:middle line:84%
I will often use inverse
image or pre-image.

00:35:17.580 --> 00:35:23.610 align:middle line:84%
These are meant to be taken
as saying the same thing.

00:35:23.610 --> 00:35:25.140 align:middle line:84%
Each of these is
a measurable set

00:35:25.140 --> 00:35:28.920 align:middle line:84%
so it's the countable
intersection of measurable sets

00:35:28.920 --> 00:35:30.670 align:middle line:90%
is measurable.

00:35:30.670 --> 00:35:34.880 align:middle line:90%
So that's measurable.

00:35:34.880 --> 00:35:39.950 align:middle line:84%
And similarly, if
I look at the set

00:35:39.950 --> 00:35:41.690 align:middle line:84%
where it's equal
to minus infinity,

00:35:41.690 --> 00:35:43.730 align:middle line:84%
this is equal to
the intersection

00:35:43.730 --> 00:35:47.270 align:middle line:84%
of the inverse image
of minus infinity to n.

00:35:47.270 --> 00:35:52.250 align:middle line:90%


00:35:52.250 --> 00:35:56.030 align:middle line:84%
Let's take these positives,
so then I'll put minus n here.

00:35:56.030 --> 00:35:59.960 align:middle line:84%
And by this theorem that we
just proved a minute ago,

00:35:59.960 --> 00:36:02.040 align:middle line:90%
each of these--

00:36:02.040 --> 00:36:07.460 align:middle line:84%
well, I mean we just proved that
the inverse image of Borel sets

00:36:07.460 --> 00:36:10.370 align:middle line:90%
are Lebesgue measurable so--

00:36:10.370 --> 00:36:12.030 align:middle line:90%
well, that won't apply.

00:36:12.030 --> 00:36:12.530 align:middle line:90%
Never mind.

00:36:12.530 --> 00:36:13.790 align:middle line:90%
Forget what I just said.

00:36:13.790 --> 00:36:15.440 align:middle line:84%
The theorem we just
proved a minute ago

00:36:15.440 --> 00:36:19.490 align:middle line:84%
that Lebesgue measurable
functions take

00:36:19.490 --> 00:36:24.140 align:middle line:84%
sets of this type to
Lebesgue measurable sets

00:36:24.140 --> 00:36:27.950 align:middle line:84%
implies that each of these
is Lebesgue measurable

00:36:27.950 --> 00:36:32.820 align:middle line:84%
and therefore it's a union
of Lebesgue measurable sets,

00:36:32.820 --> 00:36:38.360 align:middle line:84%
so for all n, so
that's measurable.

00:36:38.360 --> 00:36:43.060 align:middle line:90%


00:36:43.060 --> 00:36:45.670 align:middle line:84%
So if I have an
extended real value

00:36:45.670 --> 00:36:52.770 align:middle line:84%
function, and the inverse
image of every Borel set--

00:36:52.770 --> 00:36:57.800 align:middle line:84%
you can even toss in the
two infinities if you like.

00:36:57.800 --> 00:37:01.190 align:middle line:84%
The inverse image of those
sets is Lebesgue measurable.

00:37:01.190 --> 00:37:04.820 align:middle line:84%
So in particular, we conclude
that the inverse images

00:37:04.820 --> 00:37:09.680 align:middle line:84%
of closed and bounded intervals
is Lebesgue measurable

00:37:09.680 --> 00:37:12.560 align:middle line:90%
for measurable functions.

00:37:12.560 --> 00:37:13.060 align:middle line:90%
OK.

00:37:13.060 --> 00:37:16.270 align:middle line:90%
Now what are the simplest types?

00:37:16.270 --> 00:37:17.990 align:middle line:90%
Again, you see a definition.

00:37:17.990 --> 00:37:19.730 align:middle line:90%
You should ask for an example.

00:37:19.730 --> 00:37:23.920 align:middle line:84%
What are the simplest types
of measurable functions?

00:37:23.920 --> 00:37:37.560 align:middle line:84%
So if f from R to
R is continuous,

00:37:37.560 --> 00:37:43.270 align:middle line:84%
then that implies
that f is measurable.

00:37:43.270 --> 00:37:46.760 align:middle line:84%
So in the end when we build
our definition of the Lebesgue

00:37:46.760 --> 00:37:52.110 align:middle line:84%
integral, we should encompass
Reimann integration as well.

00:37:52.110 --> 00:37:55.670 align:middle line:84%
In other words, we should
be able to also integrate

00:37:55.670 --> 00:37:57.500 align:middle line:90%
continuous functions.

00:37:57.500 --> 00:38:00.620 align:middle line:84%
And later we'll see, and
something that we want as well,

00:38:00.620 --> 00:38:03.260 align:middle line:84%
is that the Lebesgue integral
of a continuous function

00:38:03.260 --> 00:38:05.990 align:middle line:84%
should reduce down to
the Reimann integral

00:38:05.990 --> 00:38:08.940 align:middle line:90%
of a continuous function.

00:38:08.940 --> 00:38:12.770 align:middle line:84%
So at a minimum, when we're
building these concepts,

00:38:12.770 --> 00:38:15.260 align:middle line:84%
we should check as a
kind of sanity check

00:38:15.260 --> 00:38:17.840 align:middle line:84%
that we are including
continuous functions

00:38:17.840 --> 00:38:22.350 align:middle line:84%
in these possible functions
which we will integrate.

00:38:22.350 --> 00:38:26.610 align:middle line:84%
So if f is continuous, f
is measurable, why is this?

00:38:26.610 --> 00:38:29.120 align:middle line:84%
This is because
for all alpha in R,

00:38:29.120 --> 00:38:36.390 align:middle line:84%
if I look at the inverse
image of alpha infinity--

00:38:36.390 --> 00:38:42.510 align:middle line:84%
so first off, this
is equal to this set.

00:38:42.510 --> 00:38:49.750 align:middle line:84%
And this is an open
set so this is open.

00:38:49.750 --> 00:38:54.130 align:middle line:90%


00:38:54.130 --> 00:38:57.910 align:middle line:84%
So the inverse image of an open
set for a continuous function

00:38:57.910 --> 00:38:58.990 align:middle line:90%
is open.

00:38:58.990 --> 00:39:03.165 align:middle line:90%
And therefore it's measurable.

00:39:03.165 --> 00:39:03.665 align:middle line:90%
Right?

00:39:03.665 --> 00:39:08.590 align:middle line:90%


00:39:08.590 --> 00:39:09.090 align:middle line:90%
OK.

00:39:09.090 --> 00:39:16.180 align:middle line:90%


00:39:16.180 --> 00:39:18.880 align:middle line:84%
So how about a
different example?

00:39:18.880 --> 00:39:27.990 align:middle line:90%


00:39:27.990 --> 00:39:32.640 align:middle line:84%
Let's take a measurable
subset E of R.

00:39:32.640 --> 00:39:39.640 align:middle line:84%
Let F be another
measurable subset.

00:39:39.640 --> 00:39:47.660 align:middle line:90%


00:39:47.660 --> 00:39:51.410 align:middle line:84%
And define the
indicator function

00:39:51.410 --> 00:40:07.530 align:middle line:84%
chi of F of x to be 1 if x is
in F, 0 if x is not in F. Then

00:40:07.530 --> 00:40:08.850 align:middle line:90%
this function chi F--

00:40:08.850 --> 00:40:11.890 align:middle line:90%


00:40:11.890 --> 00:40:21.240 align:middle line:84%
now if I think of it as
being a function from E to R,

00:40:21.240 --> 00:40:24.740 align:middle line:90%
this is measurable.

00:40:24.740 --> 00:40:25.607 align:middle line:90%
Now, why is that?

00:40:25.607 --> 00:40:26.690 align:middle line:90%
Well, we can just compute.

00:40:26.690 --> 00:40:31.400 align:middle line:90%


00:40:31.400 --> 00:40:38.150 align:middle line:84%
If alpha is in R, if I look
at the inverse image of alpha

00:40:38.150 --> 00:40:43.370 align:middle line:84%
to infinity, this is equal
to one of three things.

00:40:43.370 --> 00:40:47.930 align:middle line:84%
Since chi takes on only the
values 1 and 0, if alpha

00:40:47.930 --> 00:40:50.550 align:middle line:84%
is bigger than 1,
this is the empty set,

00:40:50.550 --> 00:40:56.970 align:middle line:84%
which is measurable if alpha's
bigger than or equal to 1

00:40:56.970 --> 00:40:58.770 align:middle line:84%
since this set
does not include--

00:40:58.770 --> 00:41:01.480 align:middle line:90%
would not include 1.

00:41:01.480 --> 00:41:07.400 align:middle line:84%
If alpha is between
0 and less than 1,

00:41:07.400 --> 00:41:11.580 align:middle line:84%
then the inverse image of this
set is equal to E intersect

00:41:11.580 --> 00:41:13.820 align:middle line:90%
F. E is measurable.

00:41:13.820 --> 00:41:14.820 align:middle line:90%
F is measurable.

00:41:14.820 --> 00:41:17.360 align:middle line:84%
So their intersection
is measurable.

00:41:17.360 --> 00:41:24.230 align:middle line:84%
And if alpha's less than 0, then
the inverse image of this set--

00:41:24.230 --> 00:41:27.640 align:middle line:84%
in other words,
what sets map into--

00:41:27.640 --> 00:41:30.190 align:middle line:84%
from one negative number
to infinity-- well,

00:41:30.190 --> 00:41:31.910 align:middle line:90%
both 1 and 0 map into there.

00:41:31.910 --> 00:41:42.370 align:middle line:84%
And that's the entire set
E. And so whatever you--

00:41:42.370 --> 00:41:47.470 align:middle line:84%
no matter what alpha is,
the inverse image of these--

00:41:47.470 --> 00:41:49.090 align:middle line:90%
of that set is measurable.

00:41:49.090 --> 00:42:02.150 align:middle line:90%


00:42:02.150 --> 00:42:05.720 align:middle line:84%
So these are basic properties
of measurable functions.

00:42:05.720 --> 00:42:13.590 align:middle line:84%
Let's continue what
would we like more--

00:42:13.590 --> 00:42:15.930 align:middle line:84%
so what other properties of
measurable functions, again,

00:42:15.930 --> 00:42:18.300 align:middle line:84%
which we would hope
to integrate or we

00:42:18.300 --> 00:42:22.200 align:middle line:84%
will be integrating at least
a class of these in the end

00:42:22.200 --> 00:42:23.070 align:middle line:90%
to satisfy.

00:42:23.070 --> 00:42:25.830 align:middle line:84%
Well, we would like
them to be closed,

00:42:25.830 --> 00:42:32.300 align:middle line:84%
undertaking linear
combinations, and also products,

00:42:32.300 --> 00:42:34.520 align:middle line:84%
because in the end, we'll
have LP spaces, which

00:42:34.520 --> 00:42:37.460 align:middle line:90%
is products of--

00:42:37.460 --> 00:42:40.640 align:middle line:84%
integrals of products
of integral functions.

00:42:40.640 --> 00:42:43.520 align:middle line:90%


00:42:43.520 --> 00:42:44.920 align:middle line:84%
So we have the
following theorem.

00:42:44.920 --> 00:42:53.470 align:middle line:90%


00:42:53.470 --> 00:43:00.020 align:middle line:84%
So let's suppose
E is measurable.

00:43:00.020 --> 00:43:02.360 align:middle line:84%
And I have two
functions going from E

00:43:02.360 --> 00:43:06.640 align:middle line:90%
to R that are measurable.

00:43:06.640 --> 00:43:11.190 align:middle line:90%


00:43:11.190 --> 00:43:25.470 align:middle line:84%
And I have a scalar in
R. Then c times f, f

00:43:25.470 --> 00:43:31.480 align:middle line:90%
plus g, and f times g--

00:43:31.480 --> 00:43:33.550 align:middle line:84%
so these are now all
functions from E to R--

00:43:33.550 --> 00:43:36.830 align:middle line:90%


00:43:36.830 --> 00:43:40.100 align:middle line:84%
are measurable, are
measurable functions.

00:43:40.100 --> 00:43:43.010 align:middle line:90%


00:43:43.010 --> 00:43:46.040 align:middle line:90%
So what's the proof?

00:43:46.040 --> 00:43:51.170 align:middle line:84%
Let's start with
scalar multiplication.

00:43:51.170 --> 00:43:53.240 align:middle line:90%
This equals 0.

00:43:53.240 --> 00:43:57.958 align:middle line:84%
And c times f equals 0, which
is a continuous function.

00:43:57.958 --> 00:43:59.000 align:middle line:90%
It's a constant function.

00:43:59.000 --> 00:44:11.460 align:middle line:84%
0 is continuous,
hence measurable.

00:44:11.460 --> 00:44:13.300 align:middle line:90%
So let's suppose c is non-zero.

00:44:13.300 --> 00:44:15.520 align:middle line:84%
So the-- we're out
of the silly case.

00:44:15.520 --> 00:44:20.730 align:middle line:90%


00:44:20.730 --> 00:44:26.250 align:middle line:84%
If c does not equal
0 and alpha is

00:44:26.250 --> 00:44:33.360 align:middle line:84%
an element of R, then c times
f of x greater than alpha--

00:44:33.360 --> 00:44:39.840 align:middle line:84%
this is equivalent to f of x
is greater than alpha over c.

00:44:39.840 --> 00:44:47.380 align:middle line:84%
So this implies that if I want
the inverse image, if I look

00:44:47.380 --> 00:44:51.370 align:middle line:84%
at c times f and I look at
the inverse image of alpha

00:44:51.370 --> 00:44:59.310 align:middle line:84%
to infinity, this is equal to
the inverse image of-- by f

00:44:59.310 --> 00:45:04.560 align:middle line:84%
of the set alpha
over c infinity.

00:45:04.560 --> 00:45:08.860 align:middle line:90%


00:45:08.860 --> 00:45:11.300 align:middle line:84%
And now if I'm assuming
f is measurable,

00:45:11.300 --> 00:45:14.900 align:middle line:84%
then the inverse image of
this set is measurable.

00:45:14.900 --> 00:45:17.800 align:middle line:90%
So that's a measurable set.

00:45:17.800 --> 00:45:22.010 align:middle line:84%
And therefore, c times f
is a measurable function.

00:45:22.010 --> 00:45:25.270 align:middle line:90%


00:45:25.270 --> 00:45:29.220 align:middle line:84%
So now, let's look at
the function f plus g.

00:45:29.220 --> 00:45:34.260 align:middle line:90%


00:45:34.260 --> 00:45:41.540 align:middle line:84%
Suppose alpha's in R. Then
let's do something similar.

00:45:41.540 --> 00:45:51.380 align:middle line:84%
Then f of x plus g of x
is greater than alpha.

00:45:51.380 --> 00:45:57.050 align:middle line:84%
This is if and only if f
of x is greater than alpha

00:45:57.050 --> 00:46:00.520 align:middle line:90%
minus g of x.

00:46:00.520 --> 00:46:02.600 align:middle line:90%
So I didn't say this.

00:46:02.600 --> 00:46:04.780 align:middle line:84%
But when I'm looking
at such a condition,

00:46:04.780 --> 00:46:08.450 align:middle line:84%
I'm looking at those x's that
will be in this inverse image.

00:46:08.450 --> 00:46:10.930 align:middle line:84%
So I'm just trying to
figure out an equivalent

00:46:10.930 --> 00:46:13.570 align:middle line:84%
way of expressing
this condition, which

00:46:13.570 --> 00:46:14.870 align:middle line:90%
we saw was this condition.

00:46:14.870 --> 00:46:16.960 align:middle line:84%
So what I'm really
looking at is those

00:46:16.960 --> 00:46:20.630 align:middle line:84%
x's which would lie in
the-- this pre-image here.

00:46:20.630 --> 00:46:22.420 align:middle line:84%
And what I did a minute
ago was show it's

00:46:22.420 --> 00:46:25.010 align:middle line:90%
equal to this pre-image here.

00:46:25.010 --> 00:46:29.410 align:middle line:84%
So this is why I'm considering
f of x plus g of x plus alpha.

00:46:29.410 --> 00:46:30.790 align:middle line:90%
This is the condition that--

00:46:30.790 --> 00:46:34.000 align:middle line:90%


00:46:34.000 --> 00:46:42.390 align:middle line:84%
so maybe I'll just
write this out.

00:46:42.390 --> 00:46:46.010 align:middle line:84%
Then x is in this set if and
only if f of x plus g of x

00:46:46.010 --> 00:46:49.280 align:middle line:84%
is bigger than alpha, which
is equivalent to f of x plus--

00:46:49.280 --> 00:46:52.280 align:middle line:84%
f of x is greater than
alpha minus g of x.

00:46:52.280 --> 00:46:59.680 align:middle line:90%
Now, you learned in 18.100--

00:46:59.680 --> 00:47:03.550 align:middle line:90%
A, B, P, Q, whatever--

00:47:03.550 --> 00:47:07.778 align:middle line:84%
that if I have any two
real numbers, one bigger

00:47:07.778 --> 00:47:09.820 align:middle line:84%
than the other, then I
can find a rational number

00:47:09.820 --> 00:47:11.650 align:middle line:90%
in between them.

00:47:11.650 --> 00:47:15.650 align:middle line:84%
So if this number is
bigger than this number,

00:47:15.650 --> 00:47:21.830 align:middle line:84%
there exists a rational
number, r, such that f of x

00:47:21.830 --> 00:47:28.100 align:middle line:84%
is greater than r is greater
than alpha minus g of x.

00:47:28.100 --> 00:47:31.100 align:middle line:84%
So this-- assuming
this does imply this.

00:47:31.100 --> 00:47:34.550 align:middle line:84%
And of course, this condition
also implies this condition.

00:47:34.550 --> 00:47:36.950 align:middle line:84%
If there exists a rational
number so that f of x

00:47:36.950 --> 00:47:39.260 align:middle line:84%
is bigger than r is bigger
than alpha minus g of x,

00:47:39.260 --> 00:47:42.380 align:middle line:84%
then, of course, f of x is
bigger than alpha minus g of x.

00:47:42.380 --> 00:47:44.720 align:middle line:84%
So these two conditions
are equivalent.

00:47:44.720 --> 00:47:48.450 align:middle line:90%


00:47:48.450 --> 00:47:56.110 align:middle line:84%
So this is equivalent to saying
there exists an r in Q such

00:47:56.110 --> 00:48:08.090 align:middle line:84%
that x is in the inverse image
of f r to infinity intersect

00:48:08.090 --> 00:48:14.400 align:middle line:84%
and r is bigger than alpha
minus g of x, which one can

00:48:14.400 --> 00:48:20.520 align:middle line:84%
state as x is in the inverse
image of alpha minus r

00:48:20.520 --> 00:48:21.540 align:middle line:90%
to infinity.

00:48:21.540 --> 00:48:28.980 align:middle line:90%


00:48:28.980 --> 00:48:40.020 align:middle line:84%
So this last expression here--
so let me come over here

00:48:40.020 --> 00:48:46.235 align:middle line:90%
and started erasing.

00:48:46.235 --> 00:48:51.670 align:middle line:90%


00:48:51.670 --> 00:48:58.430 align:middle line:84%
So we've shown that x is in the
inverse image of this set, f

00:48:58.430 --> 00:49:01.360 align:middle line:84%
plus g, the inverse image
by f plus g of this set,

00:49:01.360 --> 00:49:04.510 align:middle line:84%
if and only if there exists
a rational number so that x

00:49:04.510 --> 00:49:06.610 align:middle line:84%
is in the intersection of
these two types of sets,

00:49:06.610 --> 00:49:08.920 align:middle line:90%
which we know are measurable.

00:49:08.920 --> 00:49:14.420 align:middle line:84%
So we can express
this, or summarizing

00:49:14.420 --> 00:49:17.510 align:middle line:90%
what we just found--

00:49:17.510 --> 00:49:26.090 align:middle line:84%
that f plus g inverse
image of alpha infinity--

00:49:26.090 --> 00:49:29.840 align:middle line:84%
this is equal to the union
over rational numbers

00:49:29.840 --> 00:49:33.200 align:middle line:90%
Q, r and Q, such that--

00:49:33.200 --> 00:49:36.680 align:middle line:84%
or the inverse image of f
inverse or the inverse image

00:49:36.680 --> 00:49:51.980 align:middle line:84%
of r infinity intersect
alpha minus r infinity--

00:49:51.980 --> 00:49:55.290 align:middle line:90%


00:49:55.290 --> 00:49:58.020 align:middle line:84%
so that's just,
again, expressing

00:49:58.020 --> 00:50:00.260 align:middle line:90%
what we did over there.

00:50:00.260 --> 00:50:02.180 align:middle line:90%
And now what do we know?

00:50:02.180 --> 00:50:04.350 align:middle line:84%
If we're assuming
f is measurable,

00:50:04.350 --> 00:50:07.660 align:middle line:84%
then this whole
set is measurable.

00:50:07.660 --> 00:50:09.520 align:middle line:84%
And we're assuming
g is measurable.

00:50:09.520 --> 00:50:11.890 align:middle line:90%
So this whole set is measurable.

00:50:11.890 --> 00:50:15.670 align:middle line:84%
And therefore, this
intersection of these two sets

00:50:15.670 --> 00:50:17.020 align:middle line:90%
is measurable.

00:50:17.020 --> 00:50:19.282 align:middle line:84%
And now I have countable
union because, again,

00:50:19.282 --> 00:50:20.740 align:middle line:84%
the rational numbers
are countable.

00:50:20.740 --> 00:50:23.620 align:middle line:84%
One of the first things
you prove in analysis

00:50:23.620 --> 00:50:27.430 align:middle line:84%
is that the set of rational
numbers is countable.

00:50:27.430 --> 00:50:30.910 align:middle line:84%
This is a countable
union of measurable sets.

00:50:30.910 --> 00:50:32.110 align:middle line:90%
So that's measurable.

00:50:32.110 --> 00:50:49.600 align:middle line:90%


00:50:49.600 --> 00:50:50.950 align:middle line:90%
Now, what about f times g?

00:50:50.950 --> 00:50:53.095 align:middle line:90%
Here, we'll pull a little trick.

00:50:53.095 --> 00:50:58.530 align:middle line:90%


00:50:58.530 --> 00:51:01.870 align:middle line:84%
So we'll prove that
if f is measurable,

00:51:01.870 --> 00:51:03.120 align:middle line:90%
then its square is measurable.

00:51:03.120 --> 00:51:06.000 align:middle line:84%
And then we'll use
a simple identity

00:51:06.000 --> 00:51:08.760 align:middle line:84%
to conclude that f
times g is measurable.

00:51:08.760 --> 00:51:12.160 align:middle line:90%


00:51:12.160 --> 00:51:19.400 align:middle line:84%
So now I claim that f
squared is measurable.

00:51:19.400 --> 00:51:22.590 align:middle line:90%


00:51:22.590 --> 00:51:26.460 align:middle line:84%
Let alpha be a
subset of R. If alpha

00:51:26.460 --> 00:51:32.590 align:middle line:84%
is bigger than or equal to 0,
well, let's do this stupid case

00:51:32.590 --> 00:51:33.090 align:middle line:90%
first.

00:51:33.090 --> 00:51:40.980 align:middle line:84%
If alpha is less than
0, then f squared--

00:51:40.980 --> 00:51:43.780 align:middle line:90%
this is a non-negative function.

00:51:43.780 --> 00:51:48.730 align:middle line:84%
So if I take the inverse
image of alpha to infinity,

00:51:48.730 --> 00:51:55.740 align:middle line:84%
this is just equal to the
domain E. So this is measurable.

00:51:55.740 --> 00:51:59.130 align:middle line:84%
Remember, this is a
set of all x's that

00:51:59.130 --> 00:52:02.140 align:middle line:84%
get mapped by f squared
to alpha to infinity.

00:52:02.140 --> 00:52:06.660 align:middle line:84%
And if alpha is negative,
then no matter what x is in E,

00:52:06.660 --> 00:52:10.110 align:middle line:84%
f squared of x is going to be
in alpha to infinity, again,

00:52:10.110 --> 00:52:11.490 align:middle line:90%
for alpha less than 0.

00:52:11.490 --> 00:52:15.730 align:middle line:84%
So this inverse
image equals E, which

00:52:15.730 --> 00:52:17.110 align:middle line:90%
is measurable by assumption.

00:52:17.110 --> 00:52:20.460 align:middle line:90%


00:52:20.460 --> 00:52:23.670 align:middle line:84%
And then the other
less trivial case

00:52:23.670 --> 00:52:30.330 align:middle line:84%
is if alpha is bigger
than or equal to 0, then f

00:52:30.330 --> 00:52:34.980 align:middle line:84%
squared of x is bigger
than alpha if and only

00:52:34.980 --> 00:52:39.390 align:middle line:90%
if either what?

00:52:39.390 --> 00:52:46.390 align:middle line:84%
f of x is bigger than the
square root of alpha or f

00:52:46.390 --> 00:52:49.660 align:middle line:84%
of x is less than minus
square root of alpha.

00:52:49.660 --> 00:52:59.232 align:middle line:84%
And therefore-- so, again,
this expression here is--

00:52:59.232 --> 00:53:00.870 align:middle line:90%
this expression is expressing.

00:53:00.870 --> 00:53:03.600 align:middle line:84%
But this relation
here is expressing

00:53:03.600 --> 00:53:07.570 align:middle line:84%
x is in the inverse image
of alpha to infinity.

00:53:07.570 --> 00:53:16.720 align:middle line:84%
So this says that the inverse
image of alpha to infinity

00:53:16.720 --> 00:53:19.720 align:middle line:84%
is equal to the set
of all x's satisfying

00:53:19.720 --> 00:53:22.600 align:middle line:84%
this condition on the right
of this, if and only if,

00:53:22.600 --> 00:53:25.050 align:middle line:90%
which is--

00:53:25.050 --> 00:53:28.540 align:middle line:84%
can be written as x is
in the inverse image of--

00:53:28.540 --> 00:53:37.570 align:middle line:90%


00:53:37.570 --> 00:53:41.110 align:middle line:84%
f is bigger than square
root of alpha, union,

00:53:41.110 --> 00:53:44.950 align:middle line:84%
again, coming from
the or, f inverse of--

00:53:44.950 --> 00:53:50.940 align:middle line:90%


00:53:50.940 --> 00:53:53.070 align:middle line:84%
and again, if we have
a measurable function,

00:53:53.070 --> 00:53:56.370 align:middle line:84%
then not only are these
types of the pre-images

00:53:56.370 --> 00:53:58.590 align:middle line:84%
of these types of
sets measurable,

00:53:58.590 --> 00:54:00.540 align:middle line:84%
but the pre-images of
these types of sets

00:54:00.540 --> 00:54:01.613 align:middle line:90%
are also measurable.

00:54:01.613 --> 00:54:03.030 align:middle line:84%
That was the first
thing we prove.

00:54:03.030 --> 00:54:06.990 align:middle line:84%
And so since each of these
pre-images are measurable,

00:54:06.990 --> 00:54:08.560 align:middle line:90%
their union is measurable.

00:54:08.560 --> 00:54:10.890 align:middle line:90%
So that's measurable.

00:54:10.890 --> 00:54:14.540 align:middle line:90%


00:54:14.540 --> 00:54:17.880 align:middle line:84%
So we proved that f
squared is measurable.

00:54:17.880 --> 00:54:19.880 align:middle line:84%
And now we conclude
that f times g

00:54:19.880 --> 00:54:31.140 align:middle line:84%
is measurable by a simple
identity that f times g--

00:54:31.140 --> 00:54:37.860 align:middle line:84%
this is equal to
1/4 f plus g squared

00:54:37.860 --> 00:54:41.595 align:middle line:90%
minus f minus g squared.

00:54:41.595 --> 00:54:45.330 align:middle line:90%


00:54:45.330 --> 00:54:48.980 align:middle line:84%
So f times g is equal to
this function squared.

00:54:48.980 --> 00:54:51.980 align:middle line:84%
If f and g are measurable,
their sum is measurable.

00:54:51.980 --> 00:54:53.720 align:middle line:84%
And therefore, by
what we just proved,

00:54:53.720 --> 00:54:55.520 align:middle line:90%
the square is measurable.

00:54:55.520 --> 00:54:58.430 align:middle line:84%
And again, over here, this
is going to be measurable.

00:54:58.430 --> 00:55:02.510 align:middle line:84%
And by scalar multiple of minus
1, that thing's measurable.

00:55:02.510 --> 00:55:06.540 align:middle line:84%
Scalar multiple of 1/4 on
the outside is fine as well.

00:55:06.540 --> 00:55:13.320 align:middle line:84%
So we conclude that
this thing is measurable

00:55:13.320 --> 00:55:16.830 align:middle line:84%
because every operation
in this expression

00:55:16.830 --> 00:55:18.870 align:middle line:84%
preserves the function
being measurable,

00:55:18.870 --> 00:55:23.610 align:middle line:84%
as we proved before
this expression.

00:55:23.610 --> 00:55:25.480 align:middle line:84%
And that's-- that
concludes the proof.

00:55:25.480 --> 00:55:32.980 align:middle line:84%
So the sum of two measurable
functions is measurable.

00:55:32.980 --> 00:55:34.660 align:middle line:90%
Scalar products are measurable.

00:55:34.660 --> 00:55:43.490 align:middle line:84%
Products are measurable-- big
deal because as far as Riemann

00:55:43.490 --> 00:55:52.997 align:middle line:90%
integration goes, that's--

00:55:52.997 --> 00:55:55.739 align:middle line:90%


00:55:55.739 --> 00:55:57.880 align:middle line:90%
that still holds.

00:55:57.880 --> 00:56:01.500 align:middle line:84%
So what's something
that sets apart

00:56:01.500 --> 00:56:09.130 align:middle line:84%
a function being measurable and,
eventually, Lebesgue integrable

00:56:09.130 --> 00:56:14.040 align:middle line:90%
is that it has better--

00:56:14.040 --> 00:56:18.160 align:middle line:84%
it's closed under taking
limits as opposed to being

00:56:18.160 --> 00:56:21.050 align:middle line:90%
Riemann integrable.

00:56:21.050 --> 00:56:25.000 align:middle line:84%
So this is the
following theorem.

00:56:25.000 --> 00:56:31.110 align:middle line:90%


00:56:31.110 --> 00:56:38.130 align:middle line:84%
If I have a measurable
set and then I

00:56:38.130 --> 00:56:46.250 align:middle line:84%
have a sequence of functions,
fn, going from minus infinity

00:56:46.250 --> 00:56:48.380 align:middle line:90%
to infinity--

00:56:48.380 --> 00:56:53.510 align:middle line:84%
oh, and so I should
have said a minute ago--

00:56:53.510 --> 00:56:56.450 align:middle line:90%
I'm just catching myself.

00:56:56.450 --> 00:56:56.950 align:middle line:90%
Oh, no.

00:56:56.950 --> 00:56:57.700 align:middle line:90%
Everything's fine.

00:56:57.700 --> 00:57:02.980 align:middle line:84%
So I just wanted to make sure I
had gone to R because f plus g

00:57:02.980 --> 00:57:07.840 align:middle line:84%
is only defined
going from E to R.

00:57:07.840 --> 00:57:10.480 align:middle line:84%
But again, if I have
one function that

00:57:10.480 --> 00:57:13.360 align:middle line:84%
is finite everywhere and
another function that's

00:57:13.360 --> 00:57:15.170 align:middle line:84%
an extended
real-valued function,

00:57:15.170 --> 00:57:17.320 align:middle line:84%
you can check that
f plus g is then

00:57:17.320 --> 00:57:21.790 align:middle line:90%
going to be measurable as well.

00:57:21.790 --> 00:57:24.880 align:middle line:84%
I can't make sense
of the sum of two

00:57:24.880 --> 00:57:27.310 align:middle line:84%
extended real-valued
functions because I

00:57:27.310 --> 00:57:31.510 align:middle line:84%
might be in a situation where
I have plus infinity minus

00:57:31.510 --> 00:57:36.180 align:middle line:84%
infinity, which is an
undefined expression.

00:57:36.180 --> 00:57:44.430 align:middle line:84%
But what I'm saying
is I can take a--

00:57:44.430 --> 00:57:48.630 align:middle line:84%
for all of this, for one of
them to be extended real-valued

00:57:48.630 --> 00:57:49.350 align:middle line:90%
is fine.

00:57:49.350 --> 00:57:51.840 align:middle line:84%
And also, the product
of extended real-valued

00:57:51.840 --> 00:57:54.120 align:middle line:84%
is fine, although I left it
out of the list of rules,

00:57:54.120 --> 00:57:56.760 align:middle line:84%
plus infinity times
minus infinity

00:57:56.760 --> 00:58:02.325 align:middle line:84%
is defined to be minus infinity,
and with the usual sign rules.

00:58:02.325 --> 00:58:05.720 align:middle line:90%


00:58:05.720 --> 00:58:09.170 align:middle line:84%
So back to the theorem-- if I
have a sequence of measurable

00:58:09.170 --> 00:58:12.460 align:middle line:90%
functions--

00:58:12.460 --> 00:58:25.240 align:middle line:84%
so then some other
functions are measurable.

00:58:25.240 --> 00:58:33.630 align:middle line:84%
Then the function g1 of x
equal to sup n fn of x--

00:58:33.630 --> 00:58:36.510 align:middle line:84%
so that's now a function defined
on E. This is also measurable.

00:58:36.510 --> 00:58:39.193 align:middle line:90%


00:58:39.193 --> 00:58:40.860 align:middle line:84%
So I'll just list the
functions and then

00:58:40.860 --> 00:58:42.180 align:middle line:90%
say they're all measurable.

00:58:42.180 --> 00:58:46.100 align:middle line:90%


00:58:46.100 --> 00:58:52.860 align:middle line:84%
g2 of x equals the
inf over n fn of x.

00:58:52.860 --> 00:58:56.290 align:middle line:90%


00:58:56.290 --> 00:59:02.420 align:middle line:84%
3 x equals limsup as
n goes to infinity

00:59:02.420 --> 00:59:07.640 align:middle line:84%
of fn of x, which we'll recall
the definition you can write

00:59:07.640 --> 00:59:19.780 align:middle line:84%
as the inf over all n of
the sup over all k bigger

00:59:19.780 --> 00:59:22.660 align:middle line:90%
than or equal to n fk of x.

00:59:22.660 --> 00:59:26.200 align:middle line:90%


00:59:26.200 --> 00:59:33.340 align:middle line:84%
And 4-- so I don't know why
I'm double-labeling them.

00:59:33.340 --> 00:59:34.450 align:middle line:90%
I have 1, 2, 3, and 4.

00:59:34.450 --> 00:59:37.900 align:middle line:84%
But I also have 1,
2, 3, and 4 here.

00:59:37.900 --> 00:59:39.850 align:middle line:90%
And the liminf of--

00:59:39.850 --> 00:59:45.560 align:middle line:84%
the point-wise liminf
of these functions,

00:59:45.560 --> 00:59:51.387 align:middle line:84%
which I will recall is equal
to the sup over m of inf--

00:59:51.387 --> 00:59:57.240 align:middle line:90%


00:59:57.240 --> 00:59:59.100 align:middle line:84%
these are all
measurable functions.

00:59:59.100 --> 01:00:24.390 align:middle line:90%


01:00:24.390 --> 01:00:29.450 align:middle line:90%
So let's prove this.

01:00:29.450 --> 01:00:35.950 align:middle line:84%
So the proof is
not too difficult.

01:00:35.950 --> 01:00:37.710 align:middle line:84%
So let's start
with the first one.

01:00:37.710 --> 01:00:39.180 align:middle line:84%
Actually, the third
and the fourth

01:00:39.180 --> 01:00:42.480 align:middle line:84%
follow from the
first and the second.

01:00:42.480 --> 01:00:55.480 align:middle line:84%
But so x is in the
inverse image by g1 alpha

01:00:55.480 --> 01:01:10.150 align:middle line:84%
to infinity if and only if,
of course, sup n fn of x

01:01:10.150 --> 01:01:11.320 align:middle line:90%
is greater than alpha.

01:01:11.320 --> 01:01:14.110 align:middle line:84%
And this is
equivalent to the sup

01:01:14.110 --> 01:01:17.290 align:middle line:84%
over all n of fn of x
is bigger than alpha

01:01:17.290 --> 01:01:21.490 align:middle line:84%
if and only if there exists
some n so that fn of x is bigger

01:01:21.490 --> 01:01:22.930 align:middle line:90%
than alpha.

01:01:22.930 --> 01:01:26.920 align:middle line:84%
If all the fns stay below
alpha when evaluated at x, then

01:01:26.920 --> 01:01:29.620 align:middle line:84%
the sup is less than
or equal to alpha.

01:01:29.620 --> 01:01:33.920 align:middle line:84%
So since the sup is
the least upper bound--

01:01:33.920 --> 01:01:40.165 align:middle line:84%
so if and only if there
exists an n such that--

01:01:40.165 --> 01:01:49.180 align:middle line:90%


01:01:49.180 --> 01:01:54.625 align:middle line:84%
if and only if there exists an n
so that x is in fn inverse of--

01:01:54.625 --> 01:02:00.010 align:middle line:90%


01:02:00.010 --> 01:02:06.970 align:middle line:84%
and therefore, we've proven
that the inverse image

01:02:06.970 --> 01:02:10.960 align:middle line:84%
of the set by g1 is
equal to the union

01:02:10.960 --> 01:02:16.330 align:middle line:84%
over all n of f inverse f sub
n inverse the inverse image

01:02:16.330 --> 01:02:23.300 align:middle line:90%
of alpha to infinity.

01:02:23.300 --> 01:02:25.900 align:middle line:84%
And now we're assuming the
fn's are all measurable.

01:02:25.900 --> 01:02:28.210 align:middle line:90%
So each of these is measurable.

01:02:28.210 --> 01:02:30.820 align:middle line:84%
It's a countable union
of measurable sets.

01:02:30.820 --> 01:02:33.355 align:middle line:84%
So it's, again,
a measurable set.

01:02:33.355 --> 01:02:39.390 align:middle line:90%


01:02:39.390 --> 01:02:42.570 align:middle line:84%
So we've proven
that for all alpha,

01:02:42.570 --> 01:02:43.890 align:middle line:90%
this is a measurable set.

01:02:43.890 --> 01:02:45.390 align:middle line:90%
So g1 is measurable.

01:02:45.390 --> 01:02:49.820 align:middle line:90%


01:02:49.820 --> 01:02:54.860 align:middle line:84%
Now, if we go on to g2,
it's the same thing.

01:02:54.860 --> 01:02:59.220 align:middle line:84%
I can prove that the
inverse image of--

01:02:59.220 --> 01:02:59.720 align:middle line:90%
let's see.

01:02:59.720 --> 01:03:00.470 align:middle line:90%
What do I do here?

01:03:00.470 --> 01:03:06.420 align:middle line:90%


01:03:06.420 --> 01:03:09.750 align:middle line:84%
Now I'm going to
include alpha here.

01:03:09.750 --> 01:03:13.450 align:middle line:84%
The inverse image of
alpha to infinity--

01:03:13.450 --> 01:03:15.810 align:middle line:84%
so this is equal
to the requiring

01:03:15.810 --> 01:03:22.230 align:middle line:84%
that the inf over fn of x is
bigger than or equal to alpha.

01:03:22.230 --> 01:03:24.840 align:middle line:84%
This is equivalent
to the intersection

01:03:24.840 --> 01:03:36.850 align:middle line:90%
now of f inverse of these guys.

01:03:36.850 --> 01:03:42.630 align:middle line:84%
Now, each of these is, again,
measurable by assumption.

01:03:42.630 --> 01:03:46.260 align:middle line:90%
And therefore, it's countable.

01:03:46.260 --> 01:03:48.090 align:middle line:90%
Intersection is measurable.

01:03:48.090 --> 01:04:02.450 align:middle line:90%


01:04:02.450 --> 01:04:06.860 align:middle line:84%
So we've proven that taking
sups and infs of sequences

01:04:06.860 --> 01:04:08.450 align:middle line:90%
of functions are measurable.

01:04:08.450 --> 01:04:15.970 align:middle line:90%


01:04:15.970 --> 01:04:22.010 align:middle line:84%
But by how the limsup
and liminf are defined--

01:04:22.010 --> 01:04:24.070 align:middle line:84%
so now we've proven
that for any sequence

01:04:24.070 --> 01:04:27.130 align:middle line:84%
of measurable functions,
the sup and the infs

01:04:27.130 --> 01:04:29.380 align:middle line:90%
are measurable functions.

01:04:29.380 --> 01:04:31.750 align:middle line:90%
But the limsup is the sup--

01:04:31.750 --> 01:04:34.840 align:middle line:84%
is this sup first,
followed by an inf.

01:04:34.840 --> 01:04:37.060 align:middle line:84%
Now, if all of the
f's are measurable,

01:04:37.060 --> 01:04:42.660 align:middle line:84%
this sup is
measurable for all n.

01:04:42.660 --> 01:04:45.336 align:middle line:84%
And therefore, this
inf is measurable.

01:04:45.336 --> 01:04:50.520 align:middle line:84%
So g3 being measurable
follows immediately

01:04:50.520 --> 01:04:55.380 align:middle line:84%
from proving that sups and
infs of measurable functions

01:04:55.380 --> 01:04:58.260 align:middle line:84%
are measurable, and the
same thing with the liminf.

01:04:58.260 --> 01:05:00.690 align:middle line:84%
If f sub k is
measurable for all k,

01:05:00.690 --> 01:05:04.080 align:middle line:84%
then we've already proven
that the infs over the k's--

01:05:04.080 --> 01:05:07.230 align:middle line:84%
bigger than or equal
to n doesn't matter--

01:05:07.230 --> 01:05:10.830 align:middle line:84%
is measurable, a
measurable function.

01:05:10.830 --> 01:05:12.630 align:middle line:84%
And therefore, the
sup over the n's

01:05:12.630 --> 01:05:15.120 align:middle line:84%
of all these
measurable functions

01:05:15.120 --> 01:05:16.470 align:middle line:90%
are, again, measurable.

01:05:16.470 --> 01:05:31.350 align:middle line:84%
So the fact that g3
and g4 are measurable

01:05:31.350 --> 01:05:41.060 align:middle line:84%
follow from the
expressions for--

01:05:41.060 --> 01:05:48.040 align:middle line:90%


01:05:48.040 --> 01:05:57.140 align:middle line:84%
and the previous
two cases, meaning

01:05:57.140 --> 01:06:00.410 align:middle line:84%
that we proved infs and
sups of measurable functions

01:06:00.410 --> 01:06:01.760 align:middle line:90%
are measurable functions.

01:06:01.760 --> 01:06:06.530 align:middle line:90%


01:06:06.530 --> 01:06:08.360 align:middle line:90%
Now, what do we get from this?

01:06:08.360 --> 01:06:12.970 align:middle line:90%


01:06:12.970 --> 01:06:15.990 align:middle line:84%
So an immediate theorem
is the following.

01:06:15.990 --> 01:06:22.620 align:middle line:90%


01:06:22.620 --> 01:06:26.910 align:middle line:84%
If E is measurable,
fn goes from--

01:06:26.910 --> 01:06:36.180 align:middle line:90%


01:06:36.180 --> 01:06:41.520 align:middle line:90%
and fn is measurable for all n.

01:06:41.520 --> 01:06:44.610 align:middle line:90%


01:06:44.610 --> 01:06:51.875 align:middle line:84%
And they converge pointwise
to some function f of x.

01:06:51.875 --> 01:06:58.710 align:middle line:90%


01:06:58.710 --> 01:07:05.720 align:middle line:90%
Then f is measurable.

01:07:05.720 --> 01:07:07.983 align:middle line:90%


01:07:07.983 --> 01:07:09.400 align:middle line:84%
I shouldn't write
it as a theorem.

01:07:09.400 --> 01:07:10.630 align:middle line:84%
I should write it
as a corollary.

01:07:10.630 --> 01:07:11.130 align:middle line:90%
Why?

01:07:11.130 --> 01:07:16.490 align:middle line:84%
Because if these converge,
then f is equal to the limsup.

01:07:16.490 --> 01:07:17.780 align:middle line:90%
It's also equal to the liminf.

01:07:17.780 --> 01:07:21.220 align:middle line:90%
But f is equal to the limsup.

01:07:21.220 --> 01:07:31.010 align:middle line:90%
So f-- so the proof is one line.

01:07:31.010 --> 01:07:44.290 align:middle line:84%
For all x in E, f of x is
equal to limsup of fn of x.

01:07:44.290 --> 01:07:52.850 align:middle line:84%
And it's also
equal to the liminf

01:07:52.850 --> 01:07:55.643 align:middle line:90%
if the fns are converging to f.

01:07:55.643 --> 01:08:01.330 align:middle line:90%


01:08:01.330 --> 01:08:04.000 align:middle line:90%
You covered this in 18.100.

01:08:04.000 --> 01:08:07.480 align:middle line:84%
You have a limit of a
sequence if and only

01:08:07.480 --> 01:08:09.940 align:middle line:90%
if the limsup equals the liminf.

01:08:09.940 --> 01:08:13.600 align:middle line:84%
And this also holds if I
include plus or minus infinity

01:08:13.600 --> 01:08:17.649 align:middle line:84%
as being possible elements
of the extended real numbers

01:08:17.649 --> 01:08:20.154 align:middle line:84%
that are in the sequence
or the possible limit.

01:08:20.154 --> 01:08:24.920 align:middle line:90%


01:08:24.920 --> 01:08:27.290 align:middle line:84%
Since this is measurable
by the previous theorem,

01:08:27.290 --> 01:08:28.550 align:middle line:90%
f is measurable.

01:08:28.550 --> 01:08:32.220 align:middle line:90%


01:08:32.220 --> 01:08:39.250 align:middle line:84%
So this says something that
is an indicator that we're

01:08:39.250 --> 01:08:42.670 align:middle line:84%
doing something that's
or we're building

01:08:42.670 --> 01:08:46.479 align:middle line:84%
something that's stronger
than being Riemann integrable.

01:08:46.479 --> 01:08:50.770 align:middle line:84%
As I've said, the functions
which we will define a Lebesgue

01:08:50.770 --> 01:08:57.529 align:middle line:84%
integral for will be a certain
subset of measurable functions.

01:08:57.529 --> 01:09:00.090 align:middle line:90%


01:09:00.090 --> 01:09:11.120 align:middle line:84%
And so taking them as
our possible candidates,

01:09:11.120 --> 01:09:16.160 align:middle line:84%
let me just make the following
remark, which now separates

01:09:16.160 --> 01:09:18.620 align:middle line:84%
measurable functions,
which are-- again,

01:09:18.620 --> 01:09:20.029 align:middle line:84%
are candidates
for being Lebesgue

01:09:20.029 --> 01:09:23.029 align:middle line:84%
integrable from
Riemann integrable

01:09:23.029 --> 01:09:26.930 align:middle line:84%
is that this fails if
I replace measurable

01:09:26.930 --> 01:09:28.939 align:middle line:90%
by Riemann integrable.

01:09:28.939 --> 01:09:35.399 align:middle line:90%


01:09:35.399 --> 01:09:40.510 align:middle line:84%
If fn-- let's go
from a, b to even R--

01:09:40.510 --> 01:09:44.600 align:middle line:90%
is Riemann integrable.

01:09:44.600 --> 01:09:50.029 align:middle line:90%


01:09:50.029 --> 01:09:56.890 align:middle line:84%
And fns converge to f pointwise,
which just means this.

01:09:56.890 --> 01:10:00.520 align:middle line:84%
For all x in a, b, limit
as n goes to infinity

01:10:00.520 --> 01:10:05.540 align:middle line:90%
of fn of x equals f of x.

01:10:05.540 --> 01:10:16.890 align:middle line:84%
Then f need not be
Riemann integrable.

01:10:16.890 --> 01:10:20.650 align:middle line:84%
In other words, when I look at
Riemann integrable functions,

01:10:20.650 --> 01:10:24.100 align:middle line:84%
they're not closed under
taking pointwise limits.

01:10:24.100 --> 01:10:26.950 align:middle line:90%


01:10:26.950 --> 01:10:33.340 align:middle line:84%
So yet for the
Lebesgue integral,

01:10:33.340 --> 01:10:37.450 align:middle line:84%
at least for our candidates of
Lebesgue measurable functions,

01:10:37.450 --> 01:10:41.350 align:middle line:84%
those are closed under
taking pointwise limits,

01:10:41.350 --> 01:10:42.460 align:middle line:90%
as we just proved.

01:10:42.460 --> 01:10:47.080 align:middle line:84%
Now-- which says that we're
on track to proving something

01:10:47.080 --> 01:10:49.768 align:middle line:90%
that's a--

01:10:49.768 --> 01:10:52.620 align:middle line:84%
that has better qualities
than the Riemann integral.

01:10:52.620 --> 01:10:56.610 align:middle line:84%
Now, as it turns out,
the pointwise limit

01:10:56.610 --> 01:10:59.950 align:middle line:84%
of Lebesgue integrable
functions need not

01:10:59.950 --> 01:11:01.010 align:middle line:90%
be Lebesgue integrable.

01:11:01.010 --> 01:11:04.720 align:middle line:84%
But if you add another
very minor condition,

01:11:04.720 --> 01:11:08.500 align:middle line:84%
the answer is, yes, it
is Lebesgue integrable.

01:11:08.500 --> 01:11:13.570 align:middle line:84%
But at the very least, we
would like for our candidates--

01:11:13.570 --> 01:11:15.820 align:middle line:84%
again, Lebesgue
measurable functions--

01:11:15.820 --> 01:11:19.270 align:middle line:84%
to be closed under
taking pointwise limits

01:11:19.270 --> 01:11:22.600 align:middle line:84%
or, at least, that should
indicate to us that we're

01:11:22.600 --> 01:11:26.260 align:middle line:84%
doing something that will have
better properties than Riemann

01:11:26.260 --> 01:11:27.520 align:middle line:90%
integrable functions.

01:11:27.520 --> 01:11:28.840 align:middle line:90%
So why is this?

01:11:28.840 --> 01:11:33.220 align:middle line:84%
What's a sequence of functions
that are Riemann integrable,

01:11:33.220 --> 01:11:34.630 align:middle line:90%
but not--

01:11:34.630 --> 01:11:38.480 align:middle line:84%
but their pointwise limit
is not Riemann integrable?

01:11:38.480 --> 01:11:47.530 align:middle line:84%
So for example, you could
take the function fn to be--

01:11:47.530 --> 01:11:50.730 align:middle line:90%
so you know what?

01:11:50.730 --> 01:11:54.540 align:middle line:84%
I'm actually going to add
this to the assignment.

01:11:54.540 --> 01:11:55.830 align:middle line:90%
And it won't be--

01:11:55.830 --> 01:11:56.580 align:middle line:90%
no.

01:11:56.580 --> 01:12:00.360 align:middle line:84%
So I'll go ahead and say
why this is the case.

01:12:00.360 --> 01:12:03.770 align:middle line:90%


01:12:03.770 --> 01:12:11.360 align:middle line:84%
Let's write-- so the
rational numbers Q and--

01:12:11.360 --> 01:12:16.200 align:middle line:90%
let's say intersect 0, 1--

01:12:16.200 --> 01:12:18.497 align:middle line:90%
this is a countable set.

01:12:18.497 --> 01:12:20.080 align:middle line:84%
It's a subset of the
rational numbers.

01:12:20.080 --> 01:12:21.122 align:middle line:90%
So this is countable set.

01:12:21.122 --> 01:12:22.290 align:middle line:90%
So we can list them.

01:12:22.290 --> 01:12:26.580 align:middle line:84%
This is equal to
r1, r2, and so on.

01:12:26.580 --> 01:12:29.830 align:middle line:90%


01:12:29.830 --> 01:12:43.380 align:middle line:84%
If I define fn of x to be 1
if x is in r1 up to rn and 0

01:12:43.380 --> 01:12:50.540 align:middle line:84%
otherwise, now
this is a function

01:12:50.540 --> 01:12:53.510 align:middle line:84%
which is piecewise
continuous on 0, 1.

01:12:53.510 --> 01:12:55.400 align:middle line:90%
So it's Riemann integrable.

01:12:55.400 --> 01:13:03.560 align:middle line:90%


01:13:03.560 --> 01:13:07.630 align:middle line:84%
But what happens as I
take n goes to infinity?

01:13:07.630 --> 01:13:11.640 align:middle line:90%


01:13:11.640 --> 01:13:22.020 align:middle line:84%
The pointwise limit of
these functions converges

01:13:22.020 --> 01:13:25.920 align:middle line:84%
to the indicator function
of the rational numbers--

01:13:25.920 --> 01:13:27.480 align:middle line:90%
intersect 0, 1.

01:13:27.480 --> 01:13:29.580 align:middle line:84%
And hopefully,
this was something

01:13:29.580 --> 01:13:32.940 align:middle line:84%
that you checked
when you learned

01:13:32.940 --> 01:13:34.260 align:middle line:90%
about Riemann integration.

01:13:34.260 --> 01:13:36.720 align:middle line:84%
If you just learned
about the Riemann

01:13:36.720 --> 01:13:38.460 align:middle line:84%
integral of continuous
functions, then

01:13:38.460 --> 01:13:39.390 align:middle line:90%
that's fine, too.

01:13:39.390 --> 01:13:46.010 align:middle line:84%
But anyways, this function
is 1 on the rationals and 0

01:13:46.010 --> 01:13:46.880 align:middle line:90%
elsewhere.

01:13:46.880 --> 01:13:52.340 align:middle line:84%
And-- which is a function which
is discontinuous everywhere,

01:13:52.340 --> 01:13:54.910 align:middle line:90%
or--

01:13:54.910 --> 01:13:59.910 align:middle line:84%
let's see-- not everywhere,
or-- yeah, everywhere.

01:13:59.910 --> 01:14:02.100 align:middle line:84%
And you can convince
yourself that that's

01:14:02.100 --> 01:14:04.740 align:middle line:84%
too crazy of a function
to be Riemann integrable

01:14:04.740 --> 01:14:08.820 align:middle line:84%
if all you knew was that
continuous functions are

01:14:08.820 --> 01:14:09.640 align:middle line:90%
Riemann integrable.

01:14:09.640 --> 01:14:12.240 align:middle line:84%
But if you learned more
about the Riemann integral,

01:14:12.240 --> 01:14:14.190 align:middle line:84%
then one of the things
that you learned

01:14:14.190 --> 01:14:16.350 align:middle line:84%
was that this function is
not Riemann integrable.

01:14:16.350 --> 01:14:23.140 align:middle line:90%


01:14:23.140 --> 01:14:28.840 align:middle line:84%
So taking the pointwise limit
of Riemann integrable functions

01:14:28.840 --> 01:14:31.360 align:middle line:90%
may not be Riemann integrable.

01:14:31.360 --> 01:14:35.770 align:middle line:84%
However, what we've proven is
that the candidates for being

01:14:35.770 --> 01:14:38.860 align:middle line:84%
Lebesgue integrable-- namely,
those measurable functions--

01:14:38.860 --> 01:14:41.560 align:middle line:84%
are closed under taking
pointwise limits, which

01:14:41.560 --> 01:14:50.510 align:middle line:84%
is, like I said, an
indication that this theory

01:14:50.510 --> 01:14:53.630 align:middle line:84%
of the integral that
we're building up

01:14:53.630 --> 01:14:56.150 align:middle line:84%
is going to be a stronger
theory in the sense

01:14:56.150 --> 01:15:02.210 align:middle line:84%
that we can prove more
things than that of Riemann.

01:15:02.210 --> 01:15:04.910 align:middle line:84%
And one of those
things we'll prove

01:15:04.910 --> 01:15:11.250 align:middle line:90%
is that the space of Riemann--

01:15:11.250 --> 01:15:15.840 align:middle line:84%
I mean, Lebesgue integrable
functions with a norm

01:15:15.840 --> 01:15:17.760 align:middle line:84%
being the integral
of the absolute value

01:15:17.760 --> 01:15:19.655 align:middle line:84%
is, in fact, a Banach
space as opposed

01:15:19.655 --> 01:15:20.655 align:middle line:90%
to the Riemann integral.

01:15:20.655 --> 01:15:32.770 align:middle line:90%


01:15:32.770 --> 01:15:37.590 align:middle line:84%
So now let me just make a
couple of final statements.

01:15:37.590 --> 01:15:40.740 align:middle line:84%
And then we'll call it
a day for this lecture.

01:15:40.740 --> 01:15:43.430 align:middle line:90%


01:15:43.430 --> 01:15:52.910 align:middle line:84%
So this is just really
some terminology

01:15:52.910 --> 01:16:10.410 align:middle line:84%
that when I make a statement P
of x and I say that with x to--

01:16:10.410 --> 01:16:14.100 align:middle line:84%
an element of a
measurable set E--

01:16:14.100 --> 01:16:30.340 align:middle line:84%
If I say this statement
holds almost everywhere on E,

01:16:30.340 --> 01:16:32.860 align:middle line:90%
and I'll usually say--

01:16:32.860 --> 01:16:38.820 align:middle line:84%
I'll shorten that to
just "ae" on E or just

01:16:38.820 --> 01:16:47.710 align:middle line:84%
"ae" if I'm deleting even
more from what I write--

01:16:47.710 --> 01:16:55.610 align:middle line:84%
this holds almost everywhere
if the set where it doesn't--

01:16:55.610 --> 01:17:09.590 align:middle line:84%
where it's-- doesn't
hold has measure 0.

01:17:09.590 --> 01:17:13.340 align:middle line:84%
So I'm saying-- you may think
I'm saying two things here,

01:17:13.340 --> 01:17:15.560 align:middle line:84%
that this set is measurable
and its measure is 0.

01:17:15.560 --> 01:17:20.880 align:middle line:84%
But remember, when we developed
the theory of measure,

01:17:20.880 --> 01:17:23.250 align:middle line:84%
first thing we learned
about measurable sets

01:17:23.250 --> 01:17:26.580 align:middle line:84%
is that if it has outer
measure equal to 0, then

01:17:26.580 --> 01:17:27.570 align:middle line:90%
it's measurable.

01:17:27.570 --> 01:17:30.957 align:middle line:84%
And remember, the outer-- the
measure of a measurable set

01:17:30.957 --> 01:17:32.040 align:middle line:90%
is just its outer measure.

01:17:32.040 --> 01:17:36.820 align:middle line:90%
So perhaps I'll say with--

01:17:36.820 --> 01:17:38.020 align:middle line:90%
in parentheses--

01:17:38.020 --> 01:17:43.650 align:middle line:90%


01:17:43.650 --> 01:17:46.200 align:middle line:84%
So a statement holds
almost everywhere

01:17:46.200 --> 01:17:53.510 align:middle line:84%
if the set where it doesn't hold
has a Lebesgue measure 0, which

01:17:53.510 --> 01:17:55.940 align:middle line:84%
is equivalent to saying it
has outer measure equal to 0

01:17:55.940 --> 01:17:59.240 align:middle line:84%
because we proved that sets that
have outer measure equal to 0

01:17:59.240 --> 01:18:00.440 align:middle line:90%
are Lebesgue measurable.

01:18:00.440 --> 01:18:04.680 align:middle line:90%


01:18:04.680 --> 01:18:09.120 align:middle line:84%
And so the final theorem that
we'll prove today is that if I

01:18:09.120 --> 01:18:11.640 align:middle line:84%
have two functions--
one measurable,

01:18:11.640 --> 01:18:15.370 align:middle line:84%
the other differing by that
measurable function off a--

01:18:15.370 --> 01:18:19.830 align:middle line:84%
on a set of measure 0--
then the second function

01:18:19.830 --> 01:18:22.200 align:middle line:90%
is also measurable.

01:18:22.200 --> 01:18:27.060 align:middle line:84%
So somehow, sets of
measure 0 don't affect

01:18:27.060 --> 01:18:29.320 align:middle line:90%
being a measurable function.

01:18:29.320 --> 01:18:34.530 align:middle line:84%
So if fg go from
a measurable set E

01:18:34.530 --> 01:18:43.800 align:middle line:84%
to the extended real
numbers, f is measurable.

01:18:43.800 --> 01:18:50.960 align:middle line:84%
And f equals g almost
everywhere on E,

01:18:50.960 --> 01:18:53.360 align:middle line:84%
meaning the set of
x's where f does not

01:18:53.360 --> 01:19:04.610 align:middle line:84%
equal g is a set of measures
0 in E. Then g is measurable.

01:19:04.610 --> 01:19:09.110 align:middle line:90%


01:19:09.110 --> 01:19:11.020 align:middle line:84%
So if you take a
measurable function f,

01:19:11.020 --> 01:19:13.840 align:middle line:84%
change it on a set of
Lebesgue measure 0,

01:19:13.840 --> 01:19:16.060 align:middle line:84%
you still get a
measurable function.

01:19:16.060 --> 01:19:19.320 align:middle line:90%


01:19:19.320 --> 01:19:21.070 align:middle line:84%
And again, this just
follows from the fact

01:19:21.070 --> 01:19:23.950 align:middle line:84%
that all sets of
Lebesgue measure

01:19:23.950 --> 01:19:28.900 align:middle line:84%
0 or outer measure equal to
0 are Lebesgue measurable.

01:19:28.900 --> 01:19:31.270 align:middle line:84%
And then, again, the fact
that we know measurable sets

01:19:31.270 --> 01:19:36.460 align:middle line:84%
are closed under taking
unions and complements--

01:19:36.460 --> 01:19:43.000 align:middle line:84%
so let n be the set of
x's in E such that f of x

01:19:43.000 --> 01:19:44.305 align:middle line:90%
does not equal g of x.

01:19:44.305 --> 01:19:47.550 align:middle line:90%


01:19:47.550 --> 01:19:51.960 align:middle line:84%
Then this is a set
of outer measures 0.

01:19:51.960 --> 01:19:53.880 align:middle line:84%
And therefore, it's
Lebesgue measurable.

01:19:53.880 --> 01:20:06.300 align:middle line:90%


01:20:06.300 --> 01:20:15.750 align:middle line:84%
So now if I take an alpha in
R and define another set--

01:20:15.750 --> 01:20:23.610 align:middle line:84%
call it N sub alpha--
to be the set of all

01:20:23.610 --> 01:20:32.230 align:middle line:84%
x's in N such that g of
x is greater than alpha,

01:20:32.230 --> 01:20:39.940 align:middle line:84%
this is a subset of
N just by definition.

01:20:39.940 --> 01:20:42.460 align:middle line:90%


01:20:42.460 --> 01:20:44.670 align:middle line:84%
So this is how I'm
defining this set.

01:20:44.670 --> 01:20:54.080 align:middle line:90%


01:20:54.080 --> 01:20:56.390 align:middle line:84%
So it has outer
measure equal to 0.

01:20:56.390 --> 01:21:02.815 align:middle line:84%
And therefore, it's measurable
because N has outer measure 0.

01:21:02.815 --> 01:21:12.420 align:middle line:90%


01:21:12.420 --> 01:21:20.870 align:middle line:84%
Then if I take the inverse
image of alpha to infinity,

01:21:20.870 --> 01:21:27.820 align:middle line:84%
this is equal to
the inverse image

01:21:27.820 --> 01:21:32.720 align:middle line:84%
by f of alpha to
infinity intersect,

01:21:32.720 --> 01:21:34.400 align:middle line:90%
where they equal each other.

01:21:34.400 --> 01:21:40.930 align:middle line:84%
So we'll intersect the
complement of N union this set,

01:21:40.930 --> 01:21:41.665 align:middle line:90%
N sub alpha.

01:21:41.665 --> 01:21:45.540 align:middle line:90%


01:21:45.540 --> 01:21:50.480 align:middle line:90%
Now N has outer measure 0.

01:21:50.480 --> 01:21:52.160 align:middle line:90%
So it's Lebesgue measurable.

01:21:52.160 --> 01:21:54.590 align:middle line:84%
And therefore, its
complement is measurable.

01:21:54.590 --> 01:21:57.380 align:middle line:84%
This is measurable
by assumption.

01:21:57.380 --> 01:22:00.280 align:middle line:84%
And therefore, this
intersection is measurable.

01:22:00.280 --> 01:22:02.330 align:middle line:90%
And this set here is measurable.

01:22:02.330 --> 01:22:05.710 align:middle line:84%
So the union of this measurable
set with this measurable set

01:22:05.710 --> 01:22:07.120 align:middle line:90%
is, again, measurable.

01:22:07.120 --> 01:22:11.420 align:middle line:84%
And we conclude that
this is measurable.

01:22:11.420 --> 01:22:22.300 align:middle line:84%
So we have defined measurable
extended real-valued functions

01:22:22.300 --> 01:22:25.510 align:middle line:84%
and proven some
properties of them,

01:22:25.510 --> 01:22:28.660 align:middle line:84%
the most striking of which
being that being measurable

01:22:28.660 --> 01:22:32.610 align:middle line:84%
is closed under taking
pointwise limits

01:22:32.610 --> 01:22:37.920 align:middle line:84%
and that you can change a
function on a set of measure 0

01:22:37.920 --> 01:22:40.440 align:middle line:90%
and still be measurable.

01:22:40.440 --> 01:22:44.070 align:middle line:84%
Next time, we'll extend
this notion in a trivial way

01:22:44.070 --> 01:22:48.180 align:middle line:84%
to functions which
take on complex values,

01:22:48.180 --> 01:22:54.160 align:middle line:84%
not extended, just
finite complex numbers,

01:22:54.160 --> 01:22:56.950 align:middle line:90%
not including the--

01:22:56.950 --> 01:23:00.990 align:middle line:90%
pointed at infinity.

01:23:00.990 --> 01:23:12.710 align:middle line:84%
And then we will
move on to defining--

01:23:12.710 --> 01:23:14.105 align:middle line:90%
so once we have these--

01:23:14.105 --> 01:23:18.220 align:middle line:90%
so here's the game plan.

01:23:18.220 --> 01:23:20.530 align:middle line:84%
So we'll extend
this notion of being

01:23:20.530 --> 01:23:24.030 align:middle line:84%
measurable to
complex-valued functions.

01:23:24.030 --> 01:23:32.770 align:middle line:84%
And then we'll show that there's
a particular class of functions

01:23:32.770 --> 01:23:36.100 align:middle line:84%
called simple functions
which, again, are simplest

01:23:36.100 --> 01:23:39.910 align:middle line:84%
in the sense that they just
take on finitely many values,

01:23:39.910 --> 01:23:44.410 align:middle line:84%
and show that those are the
universal measurable functions.

01:23:44.410 --> 01:23:48.100 align:middle line:84%
And from there, we will then
define the Lebesgue integral

01:23:48.100 --> 01:23:52.710 align:middle line:84%
of a non-negative
measurable function

01:23:52.710 --> 01:23:56.380 align:middle line:84%
and prove some
properties of that.

01:23:56.380 --> 01:23:59.260 align:middle line:90%
And then once we've done that--

01:23:59.260 --> 01:24:00.950 align:middle line:90%
so you can define the--

01:24:00.950 --> 01:24:04.080 align:middle line:84%
an integral of a non-negative--
an arbitrary non-negative

01:24:04.080 --> 01:24:05.220 align:middle line:90%
measurable function.

01:24:05.220 --> 01:24:07.020 align:middle line:84%
We will then restrict
to those functions

01:24:07.020 --> 01:24:13.950 align:middle line:84%
which we call Lebesgue
integrable, which now can--

01:24:13.950 --> 01:24:20.820 align:middle line:84%
not necessarily non-negative,
but will have finite Lebesgue

01:24:20.820 --> 01:24:24.748 align:middle line:84%
integral, and then
prove those are--

01:24:24.748 --> 01:24:26.790 align:middle line:84%
and then prove some
properties of that, including

01:24:26.790 --> 01:24:31.140 align:middle line:84%
the big convergence
theorems, and then close out

01:24:31.140 --> 01:24:34.980 align:middle line:84%
our section on or chapter
on measure and integration

01:24:34.980 --> 01:24:39.600 align:middle line:84%
by proving that the Lebesgue
integrable functions form

01:24:39.600 --> 01:24:42.930 align:middle line:84%
a Banach space with
a natural norm put

01:24:42.930 --> 01:24:48.040 align:middle line:84%
on it as opposed to Riemann
integrable functions.

01:24:48.040 --> 01:24:49.910 align:middle line:90%
We'll stop there.

01:24:49.910 --> 01:24:57.000 align:middle line:90%