WEBVTT

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[RUSTLING]

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[CLICKING]

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PROFESSOR: OK, so
we're going to complete

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our discussion of Lebesgue
measure and integration

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by discussing the
big Lp spaces, which

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was kind of the whole point
of this endeavor, which

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was to find, in some
sense, the complete space

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of integratable functions,
whatever integratable means--

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I mean, we had to
define an integral--

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containing the space
of continuous functions

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with norm given by, let's say,
the integral of the p-th power

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of the continuous function.

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OK, so at the end of--
so at last lecture,

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we introduced the general
Lebesgue integratable--

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I mean the class of
Lebesgue-integratable functions

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and the Lebesgue integral.

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And we proved that--

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we proved the dominated
convergence theorem,

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and one consequence
of that was the fact

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that if I have a
continuous function

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on a closed and
bounded interval a,

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b, then the Lebesgue integral
of that continuous function

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equals the Riemann integral
of that continuous function.

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So you know how to
compute integrals--

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or the Lebesgue integral
for every function

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that how to compute the
Riemann integral for,

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which are mostly
continuous functions.

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Now this can be strengthened.

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One can show that, in fact--

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so we're not going to
cover it in this class.

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You'll see it in another class
that is devoted maybe just

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solely to measure theory
for a longer bit, of time

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but one can show using the
dominated convergence theorem

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that, in fact, every
Riemann-integratable function--

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not just continuous, but every
Riemann-integratable function

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on a closed and bounded interval
is Lebesgue-integratable,

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and that the Riemann
integral equals the Lebesgue

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integral, even just
for more general

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Riemann-integratable functions.

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And you can also, now using the
machinery that we built up--

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I don't know, maybe I'll
put this in the assignment

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maybe not.

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That you can completely
characterize those functions

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which are Riemann-integratable.

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And the statement is that
a function-- a measurable

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function, say, is
Riemann-integratable if

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and only if it is continuous
almost everywhere.

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I'm not saying that it's
equal to a continuous function

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almost everywhere.

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I'm saying that it's
continuous at almost

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every point in the interval.

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OK.

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Now let's move on to analogs
of the little Lp spaces

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that we saw earlier
in the lectures

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and on the assignments.

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So these are usually referred
to as the big Lp spaces.

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And so to define
these, let me first

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define what will be,
in the end, a norm.

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So if f from a measurable subset
of R to the complex numbers

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is measurable,
and 1 is less than

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or equal to p is
less than infinity,

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then we define the
following possibly--

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or the following extended
non-negative real number,

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norm Lp of E. This is defined
to be the integral over E

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of f raised to the absolute
value raised to the p to the 1

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over p.

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Now this is meaningful
because no matter what f--

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how f has behaved,
because the absolute value

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of f raised to the p, this
is a non-negative measurable

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function.

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So we can always define what
the Lebesgue integral is.

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So this may be either
infinite or finite,

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but it's a non-negative
number, extended real number.

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And so maybe you
ask, what's going on?

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Why did I leave out
p equals infinity?

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We have a different definition
for equals infinity,

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just like we had a
different definition

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for the little l infinity.

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We define this
quantity here, which

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I'm going to go ahead and start
referring to as the Lp and L

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infinity norms even though
I haven't proved their--

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a norm yet on what space either.

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This is defined to be the
infimum over M positive such

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that the measure of the set
x and E such that f of x

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is bigger than m equals 0.

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So what does it mean
for m to be in this set?

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This means that f of x
is less than or equal

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to m almost everywhere.

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And then I take the
minimum of all such--

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almost everywhere upper bounds.

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And this is usually
referred to as--

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what is called the essential
supremum of f of x.

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So just a little mini theorem
about this L infinity norm

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here, what you'll see--

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well, I guess you'll be
seeing these lectures

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after the first exam.

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So you saw this guy
actually on the exam,

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and you proved one
of these facts.

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The other I will put
on a future assignment.

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If f from E to C is measurable,
then the absolute value

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of f of x is less than
or equal to gL infinity

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almost everywhere on E.

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And another fact, if f--

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if E is equal to a, b and
f it is continuous on a, b,

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then this essential supremum
is equal to, in fact,

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just the usual what we call
the L infinity norm which,

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remember, was the sup over x and
a, b absolute value of f of x.

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So why do I state this?

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Because the L infinity
norm bounds f from above

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for almost every
x in the same way

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that the little l infinity
norm for sequences bounded,

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the sequence-- every entry in
the sequence-- for every entry

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in the sequence.

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But now for the
essential supremum,

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we have just an almost
everywhere statement.

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But this norm is the same
as the L infinity norm

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or the infinity norm for
continuous functions.

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So it shouldn't be
something that's too crazy.

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OK.

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So now I'm just going to
state a couple of theorems

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because you already
gave the proof--

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the proofs, I should
say, when you did--

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I think it was probably
the first assignment, when

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you did the corresponding
statements for little lp

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spaces, except now
you replace the--

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for those, you replace
an integral with a sum.

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I mean, you should always
think of an integral as a sum.

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So we have the following two
theorems, two inequalities.

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We have Holder's inequality.

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If one is between p--

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if p is between 1 and infinity
and q is the dual exponent

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to p, meaning 1 over p
plus 1 over q equals 1,

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and you have f as an Lp
of E and g is an Lp of E,

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then f times g
integrated over E--

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well I haven't
even said-- sorry.

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Getting way ahead of myself.

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So-- and if f and g are two
measurable functions, then

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the integral over E of f
times g absolute value,

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this is less than or
equal to the Lp norm of f

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times the Lp norm of g.

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Now of course, this
inequality is only interesting

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if the right
hand-side is finite.

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If this is infinite, then
this is all vacuously true.

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So this is the analog of
the Holder's inequality

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which you proved for sequences
where we had a sum here

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instead of the integral
and where we had a sum here

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instead of the integral.

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And it's proven
essentially the same way.

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You just replace a
sigma with a little s.

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And so from Holder's
inequality, you

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obtained Minkowski's inequality.

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If p is between 1
and infinity, and f,

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g are two measurable
functions, then by--

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take the Lp norm
of f plus g, this

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is less than or equal to
the Lp norm of f plus the Lp

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norm of E. And again,
you proved this exactly

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the same way as you did
for the little Lp spaces

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using Holder's inequality.

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Of course, that requires a
slightly different argument

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for p equals infinity you know
for this essential supremum,

00:12:30.400 --> 00:12:33.220 align:middle line:84%
but in fact, that's
what you did in the exam

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you took a few days ago.

00:12:35.890 --> 00:12:40.270 align:middle line:90%


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So I've been
calling these things

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a norm even though I haven't
proved their norm yet

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and on what space
are they a norm,

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so now I'm going to do that.

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So when it's clear-- also
let me make a small remark.

00:12:57.620 --> 00:13:10.740 align:middle line:90%


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I'll denote this thing just
by shorthand with just a p.

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And it should be clear
from the context what

00:13:23.610 --> 00:13:27.810 align:middle line:90%
set I'm taking this norm over.

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Or what set am I
taking this integral

00:13:30.240 --> 00:13:33.720 align:middle line:90%
that defines this norm over.

00:13:33.720 --> 00:13:35.670 align:middle line:84%
OK, so now let me
define the actual space

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that this will be a norm on.

00:13:40.430 --> 00:13:44.840 align:middle line:84%
And it involves a slight abuse
of terminology and notation

00:13:44.840 --> 00:13:48.890 align:middle line:84%
in the end, which
is just tradition,

00:13:48.890 --> 00:13:50.720 align:middle line:90%
not just in this subject, but--

00:13:50.720 --> 00:13:57.720 align:middle line:84%
I mean, abuse of notation
is tradition in all of math.

00:13:57.720 --> 00:14:07.520 align:middle line:84%
So for 1-- for p
between 1 and infinity,

00:14:07.520 --> 00:14:16.310 align:middle line:84%
we define the space Lp of
E-- so E here is know--

00:14:16.310 --> 00:14:18.560 align:middle line:84%
if I don't say it, it's
always a measurable subset

00:14:18.560 --> 00:14:24.490 align:middle line:84%
of R. This is the set of
all functions from E to C,

00:14:24.490 --> 00:14:34.400 align:middle line:84%
which are measurable,
that have finite Lp norm.

00:14:34.400 --> 00:14:40.430 align:middle line:90%


00:14:40.430 --> 00:14:51.270 align:middle line:84%
Now let me make a second
caveat to this space.

00:14:51.270 --> 00:14:55.767 align:middle line:84%
So as I've written it down
now, it's a space of functions.

00:14:55.767 --> 00:14:58.350 align:middle line:84%
And I'm going to keep referring
to it as a space of functions.

00:14:58.350 --> 00:15:02.500 align:middle line:84%
I'm going to keep referring to
elements of it as functions.

00:15:02.500 --> 00:15:07.010 align:middle line:84%
But the actual space itself
is not a space of functions,

00:15:07.010 --> 00:15:08.920 align:middle line:84%
it's a space of
equivalence classes

00:15:08.920 --> 00:15:12.610 align:middle line:84%
in order for this quantity,
which I keep calling a norm,

00:15:12.610 --> 00:15:15.260 align:middle line:84%
to actually be a
norm on this space.

00:15:15.260 --> 00:15:16.330 align:middle line:90%
So let me add here--

00:15:16.330 --> 00:15:27.076 align:middle line:90%


00:15:27.076 --> 00:15:32.695 align:middle line:84%
if we consider two
elements of this set, the--

00:15:32.695 --> 00:15:37.940 align:middle line:90%


00:15:37.940 --> 00:15:43.045 align:middle line:84%
I shouldn't say equal, but
to be the same element--

00:15:43.045 --> 00:15:47.270 align:middle line:90%


00:15:47.270 --> 00:15:54.360 align:middle line:84%
and let me give
two elements, say f

00:15:54.360 --> 00:16:05.160 align:middle line:84%
and g in Lp, to be the
same element if f equals g

00:16:05.160 --> 00:16:07.480 align:middle line:90%
almost everywhere.

00:16:07.480 --> 00:16:10.920 align:middle line:84%
So as I've written
it down, Lp of E

00:16:10.920 --> 00:16:15.360 align:middle line:84%
consists of all measurable
functions with finite Lp norm,

00:16:15.360 --> 00:16:22.250 align:middle line:84%
and now I'm saying that I
will consider two elements

00:16:22.250 --> 00:16:23.840 align:middle line:90%
in this space to be the same--

00:16:23.840 --> 00:16:27.410 align:middle line:84%
to be the same element if
they equal each other almost

00:16:27.410 --> 00:16:28.460 align:middle line:90%
everywhere.

00:16:28.460 --> 00:16:34.572 align:middle line:90%


00:16:34.572 --> 00:16:36.905 align:middle line:84%
So strictly speaking, let me
just make this as a remark.

00:16:36.905 --> 00:16:47.070 align:middle line:90%


00:16:47.070 --> 00:17:12.819 align:middle line:84%
This means an element of Lp
of E is an equivalence class

00:17:12.819 --> 00:17:15.160 align:middle line:90%
of the form--

00:17:15.160 --> 00:17:18.190 align:middle line:84%
so little brackets f to
indicate the equivalence class.

00:17:18.190 --> 00:17:20.800 align:middle line:84%
I haven't told you what the
equivalence relation is,

00:17:20.800 --> 00:17:24.440 align:middle line:84%
so I'll explain that as I
describe the equivalence class.

00:17:24.440 --> 00:17:27.220 align:middle line:84%
So the equivalence class
of f is equal to the set

00:17:27.220 --> 00:17:31.540 align:middle line:84%
of all function g,
which are measurable.

00:17:31.540 --> 00:17:43.860 align:middle line:90%


00:17:43.860 --> 00:17:48.990 align:middle line:84%
So Lp of E is really a
set of all equivalents--

00:17:48.990 --> 00:17:52.620 align:middle line:84%
is a set of equivalence
classes of measurable functions

00:17:52.620 --> 00:17:57.600 align:middle line:84%
with finite Lp norm where
two equivalence classes are

00:17:57.600 --> 00:18:03.300 align:middle line:84%
equal if and only if
the representative

00:18:03.300 --> 00:18:05.040 align:middle line:84%
from the first
equivalent class equals

00:18:05.040 --> 00:18:07.500 align:middle line:84%
the representative of the
second equivalent class

00:18:07.500 --> 00:18:09.310 align:middle line:90%
almost everywhere.

00:18:09.310 --> 00:18:15.800 align:middle line:90%
So this is what Lp of E is.

00:18:15.800 --> 00:18:19.400 align:middle line:90%
Now why am I making this--

00:18:19.400 --> 00:18:22.910 align:middle line:84%
why am I adding
this caveat that you

00:18:22.910 --> 00:18:27.800 align:middle line:84%
have to consider two elements
to be equal almost everywhere?

00:18:27.800 --> 00:18:32.570 align:middle line:84%
Because this is what
allows me to put--

00:18:32.570 --> 00:18:35.540 align:middle line:84%
or say this Lp norm
is an actual norm.

00:18:35.540 --> 00:18:39.770 align:middle line:84%
Otherwise it is just a semi-norm
if I really consider Lp of E

00:18:39.770 --> 00:18:42.990 align:middle line:84%
to be this space of
actual functions.

00:18:42.990 --> 00:18:49.760 align:middle line:84%
So again, this is a
small point, that Lp of E

00:18:49.760 --> 00:18:54.200 align:middle line:84%
is, in fact, a set of
equivalence classes

00:18:54.200 --> 00:18:58.190 align:middle line:84%
where two functions are two
equivalence classes or equal if

00:18:58.190 --> 00:19:00.890 align:middle line:84%
and only if the representative
functions equal--

00:19:00.890 --> 00:19:04.970 align:middle line:90%
are equal almost everywhere.

00:19:04.970 --> 00:19:07.700 align:middle line:84%
But now that I've
explained all of that

00:19:07.700 --> 00:19:10.610 align:middle line:84%
and carefully told
you what Lp of E is,

00:19:10.610 --> 00:19:14.420 align:middle line:84%
it is customary to never refer
to them as equivalence classes

00:19:14.420 --> 00:19:17.540 align:middle line:84%
or elements of Lp of E
as an equivalence class.

00:19:17.540 --> 00:19:20.570 align:middle line:84%
We usually still just
refer to them as functions.

00:19:20.570 --> 00:19:22.085 align:middle line:90%
Let me make that point clear.

00:19:22.085 --> 00:19:48.840 align:middle line:90%


00:19:48.840 --> 00:19:52.470 align:middle line:84%
So rather than speaking of an
equivalence class or elements

00:19:52.470 --> 00:19:54.450 align:middle line:84%
of Lp of E as an
equivalence class,

00:19:54.450 --> 00:19:56.430 align:middle line:84%
I will just refer
to them as functions

00:19:56.430 --> 00:20:03.660 align:middle line:84%
with the understanding that
two functions in Lp of E

00:20:03.660 --> 00:20:07.320 align:middle line:84%
are considered to be the same
function, the same element

00:20:07.320 --> 00:20:11.310 align:middle line:84%
if they equal each
other almost everywhere.

00:20:11.310 --> 00:20:18.450 align:middle line:84%
Now maybe you think
this is a little weird,

00:20:18.450 --> 00:20:20.200 align:middle line:84%
but you've been doing
this your whole life

00:20:20.200 --> 00:20:25.780 align:middle line:84%
already, because the rational
numbers themselves are defined,

00:20:25.780 --> 00:20:29.587 align:middle line:84%
if you look back into algebra
or if you're taking algebra now,

00:20:29.587 --> 00:20:32.170 align:middle line:84%
when you actually sit down and
construct the rational numbers,

00:20:32.170 --> 00:20:35.170 align:middle line:84%
they're constructed
as equivalence classes

00:20:35.170 --> 00:20:37.450 align:middle line:90%
of pairs of integers.

00:20:37.450 --> 00:20:40.270 align:middle line:84%
But you don't think
of them as that,

00:20:40.270 --> 00:20:44.260 align:middle line:90%
you think of them as 3 over 2.

00:20:44.260 --> 00:20:48.520 align:middle line:84%
Not the equivalence
class of 3, 2.

00:20:48.520 --> 00:20:53.600 align:middle line:84%
So again, two elements
in Lp of E. I mean,

00:20:53.600 --> 00:20:58.820 align:middle line:84%
we think of Lp of E as a set of
functions with finite Lp norm,

00:20:58.820 --> 00:21:01.370 align:middle line:84%
and with the caveat
that two functions--

00:21:01.370 --> 00:21:04.610 align:middle line:90%
or two elements of Lp and E--

00:21:04.610 --> 00:21:06.800 align:middle line:90%
Lp of E are equal--

00:21:06.800 --> 00:21:09.650 align:middle line:84%
are the same element
if the two functions

00:21:09.650 --> 00:21:13.350 align:middle line:90%
agree almost everywhere.

00:21:13.350 --> 00:21:18.640 align:middle line:84%
OK, now with that minor
detail out of the way,

00:21:18.640 --> 00:21:19.950 align:middle line:90%
let's move on to--

00:21:19.950 --> 00:21:24.710 align:middle line:90%
let me state the theorem that--

00:21:24.710 --> 00:21:33.480 align:middle line:90%


00:21:33.480 --> 00:21:41.120 align:middle line:84%
so Lp with the natural
scalar multiplication

00:21:41.120 --> 00:21:44.870 align:middle line:84%
where you just multiply-- the
scalar multiple of an element

00:21:44.870 --> 00:21:48.520 align:middle line:84%
as just multiplying the
function by a scalar.

00:21:48.520 --> 00:21:50.800 align:middle line:84%
And the sum of two elements
is just the pointwise

00:21:50.800 --> 00:21:54.800 align:middle line:90%
why some of the two functions.

00:21:54.800 --> 00:21:59.080 align:middle line:84%
So with the obvious definitions
of scalar multiplication

00:21:59.080 --> 00:21:59.815 align:middle line:90%
and addition.

00:21:59.815 --> 00:22:03.810 align:middle line:90%


00:22:03.810 --> 00:22:08.955 align:middle line:90%
Operations is a vector space.

00:22:08.955 --> 00:22:14.380 align:middle line:90%


00:22:14.380 --> 00:22:17.830 align:middle line:84%
Moreover, this
function which I've

00:22:17.830 --> 00:22:27.350 align:middle line:84%
been referring to as a norm
is actually a norm on Lp.

00:22:27.350 --> 00:22:30.950 align:middle line:90%


00:22:30.950 --> 00:22:32.210 align:middle line:90%
Now I'm not going to--

00:22:32.210 --> 00:22:38.640 align:middle line:84%
I'm only going to
prove part of this

00:22:38.640 --> 00:22:41.850 align:middle line:84%
because to verify something
as a vector space,

00:22:41.850 --> 00:22:44.460 align:middle line:84%
you have to verify
the operations are--

00:22:44.460 --> 00:22:49.800 align:middle line:90%
satisfy certain properties.

00:22:49.800 --> 00:22:53.070 align:middle line:84%
And when I state the--
or give the proof of what

00:22:53.070 --> 00:22:55.290 align:middle line:84%
I'm going to prove
out of this theorem,

00:22:55.290 --> 00:22:56.880 align:middle line:84%
this will be the
last time I actually

00:22:56.880 --> 00:23:00.030 align:middle line:84%
refer to the fact that these
are equivalence glasses and not

00:23:00.030 --> 00:23:04.200 align:middle line:84%
functions, but just
to make a point.

00:23:04.200 --> 00:23:10.390 align:middle line:90%


00:23:10.390 --> 00:23:12.630 align:middle line:84%
Again, this space,
strictly speaking,

00:23:12.630 --> 00:23:15.310 align:middle line:90%
is a set of equivalence classes.

00:23:15.310 --> 00:23:18.450 align:middle line:84%
So one would have to check
that addition and scalar

00:23:18.450 --> 00:23:21.960 align:middle line:84%
multiplication are
well-defined on this set,

00:23:21.960 --> 00:23:25.320 align:middle line:84%
meaning if I have
two representatives

00:23:25.320 --> 00:23:28.020 align:middle line:84%
of the same equivalence
class and I multiply one

00:23:28.020 --> 00:23:31.020 align:middle line:84%
by a scalar and the
other by a scalar,

00:23:31.020 --> 00:23:35.527 align:middle line:84%
then I get the same equivalence
class in the end, which

00:23:35.527 --> 00:23:37.360 align:middle line:84%
is easy to check, and
the same for addition.

00:23:37.360 --> 00:23:50.530 align:middle line:84%
So again, in a strictly
speaking sense,

00:23:50.530 --> 00:23:53.440 align:middle line:84%
that Lp is a set of
equivalence classes,

00:23:53.440 --> 00:23:57.070 align:middle line:84%
these things are well-defined,
scalar multiplication

00:23:57.070 --> 00:23:59.800 align:middle line:90%
and addition.

00:23:59.800 --> 00:24:05.350 align:middle line:90%
So let's check that Lp--

00:24:05.350 --> 00:24:07.750 align:middle line:84%
or that this quantity
here is a norm.

00:24:07.750 --> 00:24:11.080 align:middle line:90%
And I'm just going to--

00:24:11.080 --> 00:24:16.540 align:middle line:84%
So first off, note that taking
the Lp norm of an element of Lp

00:24:16.540 --> 00:24:17.890 align:middle line:90%
is actually well-defined.

00:24:17.890 --> 00:24:21.400 align:middle line:84%
Remember, so this is going
to be the only theorem

00:24:21.400 --> 00:24:24.160 align:middle line:84%
and proof where I
actually refer to the fact

00:24:24.160 --> 00:24:27.430 align:middle line:84%
that Lp is actually a set
of equivalence classes,

00:24:27.430 --> 00:24:30.760 align:middle line:84%
and then after that we
just won't do that anymore

00:24:30.760 --> 00:24:33.190 align:middle line:84%
and we'll just think of
Lp as a set of functions

00:24:33.190 --> 00:24:35.770 align:middle line:84%
where two functions are the
same element if they equal

00:24:35.770 --> 00:24:37.060 align:middle line:90%
each other almost everywhere.

00:24:37.060 --> 00:24:41.890 align:middle line:84%
But first thing to note
is that this is actually

00:24:41.890 --> 00:24:46.670 align:middle line:84%
well-defined on this set
of equivalence classes.

00:24:46.670 --> 00:24:55.780 align:middle line:84%
So note, if I have
two representatives

00:24:55.780 --> 00:25:06.310 align:middle line:84%
of an equivalence class,
then by what we developed

00:25:06.310 --> 00:25:08.240 align:middle line:90%
for the Lebesgue integral--

00:25:08.240 --> 00:25:10.900 align:middle line:84%
So f, take the absolute
value raised to the p

00:25:10.900 --> 00:25:13.743 align:middle line:84%
is also going to be equal to g
absolute value rates of the p

00:25:13.743 --> 00:25:15.910 align:middle line:84%
almost everywhere, and
therefore these two integrals

00:25:15.910 --> 00:25:18.550 align:middle line:90%
are going to equal each other.

00:25:18.550 --> 00:25:20.120 align:middle line:84%
These integrals
are real numbers.

00:25:20.120 --> 00:25:22.120 align:middle line:84%
They're not equivalence
classes of real numbers,

00:25:22.120 --> 00:25:26.230 align:middle line:84%
this is a real number, a
non-negative real number.

00:25:26.230 --> 00:25:38.220 align:middle line:84%
And therefore, if in the
notation I had before,

00:25:38.220 --> 00:25:41.370 align:middle line:84%
if I have an
equivalence class and I

00:25:41.370 --> 00:25:43.140 align:middle line:84%
have two different
representatives of this

00:25:43.140 --> 00:25:48.840 align:middle line:84%
and I define the Lp norm
of this equivalence class

00:25:48.840 --> 00:25:51.390 align:middle line:84%
to be the integral of
the representative,

00:25:51.390 --> 00:25:55.590 align:middle line:84%
I get the same number
regardless of the representative

00:25:55.590 --> 00:25:56.715 align:middle line:90%
for that equivalence class.

00:25:56.715 --> 00:26:25.420 align:middle line:90%


00:26:25.420 --> 00:26:35.785 align:middle line:90%
I.e.-- OK?

00:26:35.785 --> 00:26:40.450 align:middle line:90%
So this function is defined by--

00:26:40.450 --> 00:26:43.030 align:middle line:84%
if I take that Lp norm
of an equivalence class

00:26:43.030 --> 00:26:45.370 align:middle line:84%
given by just the integral
of the representative,

00:26:45.370 --> 00:26:46.643 align:middle line:90%
this is well-defined.

00:26:46.643 --> 00:26:48.310 align:middle line:84%
If I take two different
representatives,

00:26:48.310 --> 00:26:49.570 align:middle line:90%
I get the same number out.

00:26:49.570 --> 00:26:54.620 align:middle line:90%


00:26:54.620 --> 00:27:05.240 align:middle line:84%
Now this quantity here
equals 0 if and only if--

00:27:05.240 --> 00:27:09.320 align:middle line:84%
by what we've developed in
our theory of integration,

00:27:09.320 --> 00:27:13.610 align:middle line:90%
f equals 0 almost everywhere.

00:27:13.610 --> 00:27:16.820 align:middle line:90%
So the Lp norm or the--

00:27:16.820 --> 00:27:22.730 align:middle line:84%
so I should say this equals
0 almost everywhere-- i.e.,

00:27:22.730 --> 00:27:24.620 align:middle line:90%
f equals 0 almost everywhere.

00:27:24.620 --> 00:27:27.130 align:middle line:90%


00:27:27.130 --> 00:27:28.990 align:middle line:90%
But possibly not everywhere.

00:27:28.990 --> 00:27:33.990 align:middle line:90%


00:27:33.990 --> 00:27:35.610 align:middle line:84%
The equivalence class
of this function

00:27:35.610 --> 00:27:38.350 align:middle line:90%
is equal to the 0 element.

00:27:38.350 --> 00:27:41.190 align:middle line:84%
So this was the
whole reason why I

00:27:41.190 --> 00:27:46.315 align:middle line:84%
went through this trouble of
actually explaining to you why,

00:27:46.315 --> 00:27:50.850 align:middle line:84%
strictly speaking, the most
rigorous way of defining Lp

00:27:50.850 --> 00:27:52.680 align:middle line:84%
is as a space of
equivalence classes,

00:27:52.680 --> 00:27:55.140 align:middle line:84%
even though we won't
think about them that way

00:27:55.140 --> 00:27:57.690 align:middle line:84%
or talk about them that
way in the future, that's,

00:27:57.690 --> 00:27:59.700 align:middle line:90%
in fact, what they are.

00:27:59.700 --> 00:28:03.510 align:middle line:84%
Because then, this
quantity here, this Lp norm

00:28:03.510 --> 00:28:04.740 align:middle line:90%
is, in fact, a norm.

00:28:04.740 --> 00:28:11.775 align:middle line:84%
If the Lp norm is 0, then
that element is the 0 element.

00:28:11.775 --> 00:28:18.550 align:middle line:90%


00:28:18.550 --> 00:28:19.090 align:middle line:90%
OK.

00:28:19.090 --> 00:28:23.380 align:middle line:84%
So that's about the
last time I'm ever

00:28:23.380 --> 00:28:28.480 align:middle line:84%
going to refer to the elements
of Lp as equivalence classes.

00:28:28.480 --> 00:28:32.470 align:middle line:84%
I will now be referring
to them as functions.

00:28:32.470 --> 00:28:44.990 align:middle line:84%
But homogeneity and the triangle
inequality for the Lp norm,

00:28:44.990 --> 00:28:51.480 align:middle line:84%
then follow, simply
from the definition,

00:28:51.480 --> 00:28:55.560 align:middle line:84%
for homogeneity, the
fact that a scalar--

00:28:55.560 --> 00:28:57.720 align:middle line:84%
that the Lp norm of a
scalar multiple of f

00:28:57.720 --> 00:29:01.770 align:middle line:84%
is equal to the absolute
value of the scalar times

00:29:01.770 --> 00:29:03.990 align:middle line:84%
the Lp norm of f, and
the triangle inequality

00:29:03.990 --> 00:29:15.830 align:middle line:84%
follow from the definition
and Minkowski's inequality.

00:29:15.830 --> 00:29:26.460 align:middle line:90%


00:29:26.460 --> 00:29:27.270 align:middle line:90%
OK.

00:29:27.270 --> 00:29:35.020 align:middle line:84%
So Lp is the space of measurable
functions with finite Lp norms.

00:29:35.020 --> 00:29:35.520 align:middle line:90%
See?

00:29:35.520 --> 00:29:38.020 align:middle line:84%
I'm Already not going to refer
to it ever again as the space

00:29:38.020 --> 00:29:39.210 align:middle line:90%
of equivalence classes.

00:29:39.210 --> 00:29:41.460 align:middle line:84%
You should think of
them as space functions,

00:29:41.460 --> 00:29:45.600 align:middle line:84%
just with two elements equal
if these functions equal

00:29:45.600 --> 00:29:50.010 align:middle line:84%
each other almost
everywhere pointwise on E.

00:29:50.010 --> 00:29:54.140 align:middle line:90%
Now we come to the big question.

00:29:54.140 --> 00:29:58.640 align:middle line:84%
We now have this norm
space Lp of E corresponding

00:29:58.640 --> 00:30:03.095 align:middle line:84%
to all these functions
that have finite Lp norm.

00:30:03.095 --> 00:30:06.080 align:middle line:90%


00:30:06.080 --> 00:30:09.260 align:middle line:90%
First off, is this non-empty?

00:30:09.260 --> 00:30:14.470 align:middle line:84%
Let's maybe give you
the simplest example.

00:30:14.470 --> 00:30:17.730 align:middle line:84%
In fact, let me prove the
following simple theorem.

00:30:17.730 --> 00:30:21.830 align:middle line:90%


00:30:21.830 --> 00:30:24.290 align:middle line:90%
So-- which is the following.

00:30:24.290 --> 00:30:27.530 align:middle line:90%


00:30:27.530 --> 00:30:39.220 align:middle line:84%
Let E be measurable,
then f is an Lp of E

00:30:39.220 --> 00:30:50.760 align:middle line:84%
if and only if the limit as
R goes to infinity over--

00:30:50.760 --> 00:30:54.990 align:middle line:84%
of the integral of
minus R to R intersect E

00:30:54.990 --> 00:31:00.080 align:middle line:90%
of f raised to the p is finite.

00:31:00.080 --> 00:31:02.960 align:middle line:84%
Notice, as R going
to plus infinity--

00:31:02.960 --> 00:31:05.580 align:middle line:90%


00:31:05.580 --> 00:31:09.140 align:middle line:84%
so maybe let's not
make it R. We can

00:31:09.140 --> 00:31:10.895 align:middle line:84%
make it n we're in
as a natural number.

00:31:10.895 --> 00:31:17.720 align:middle line:90%


00:31:17.720 --> 00:31:20.550 align:middle line:84%
Then this is an increasing
sequence of numbers.

00:31:20.550 --> 00:31:25.190 align:middle line:84%
So let's give the
proof real quick.

00:31:25.190 --> 00:31:40.580 align:middle line:84%
Let's assume f is in Lp
implies that this quantity here

00:31:40.580 --> 00:31:41.090 align:middle line:90%
is finite.

00:31:41.090 --> 00:31:44.130 align:middle line:90%


00:31:44.130 --> 00:31:53.208 align:middle line:84%
Since the sequence of integrals
over minus n to n intersect E

00:31:53.208 --> 00:31:59.370 align:middle line:84%
f raised to the p, this
is an increasing sequence.

00:31:59.370 --> 00:32:03.030 align:middle line:84%
Because at each
step, at each entry,

00:32:03.030 --> 00:32:05.310 align:middle line:84%
I'm taking the integral of
this non-negative quantity

00:32:05.310 --> 00:32:09.030 align:middle line:90%
over a bigger set.

00:32:09.030 --> 00:32:10.770 align:middle line:84%
So this is an
increasing sequence.

00:32:10.770 --> 00:32:23.560 align:middle line:90%


00:32:23.560 --> 00:32:26.710 align:middle line:84%
So, in fact, this
limit always exists,

00:32:26.710 --> 00:32:29.070 align:middle line:84%
so it was meaningful to
actually refer to this limit.

00:32:29.070 --> 00:32:36.180 align:middle line:90%


00:32:36.180 --> 00:32:43.020 align:middle line:84%
Since this is an increasing
sequence, limit as n

00:32:43.020 --> 00:32:52.330 align:middle line:84%
goes to infinity minus n
intersect E actually exists

00:32:52.330 --> 00:32:56.515 align:middle line:84%
as a possibly
extended real number.

00:32:56.515 --> 00:33:03.270 align:middle line:90%


00:33:03.270 --> 00:33:06.500 align:middle line:84%
Now since for all n, we
have that the integral

00:33:06.500 --> 00:33:13.850 align:middle line:84%
of minus n to n intersect
E raised to the p

00:33:13.850 --> 00:33:15.770 align:middle line:90%
is less than or equal to--

00:33:15.770 --> 00:33:24.680 align:middle line:84%
well, in fact, I'm being
a little inefficient here.

00:33:24.680 --> 00:33:30.755 align:middle line:90%
Let's just erase one bit here.

00:33:30.755 --> 00:33:40.650 align:middle line:90%


00:33:40.650 --> 00:33:41.670 align:middle line:90%
OK.

00:33:41.670 --> 00:33:43.700 align:middle line:90%
Yeah, let's do it this way.

00:33:43.700 --> 00:33:44.700 align:middle line:90%
We'll do it much faster.

00:33:44.700 --> 00:33:48.600 align:middle line:90%


00:33:48.600 --> 00:34:00.910 align:middle line:84%
Now note that intersect
E f raised to the p,

00:34:00.910 --> 00:34:05.460 align:middle line:84%
this is equal to integral
over E chi minus n

00:34:05.460 --> 00:34:08.290 align:middle line:90%
to n f raised to the p.

00:34:08.290 --> 00:34:11.889 align:middle line:90%
So I can think of this as--

00:34:11.889 --> 00:34:14.380 align:middle line:84%
I can think of what's
here in the integrand

00:34:14.380 --> 00:34:16.480 align:middle line:90%
as a function for each n.

00:34:16.480 --> 00:34:41.060 align:middle line:84%
So since this is a sequence
that is pointwise increasing,

00:34:41.060 --> 00:34:47.449 align:middle line:84%
and for all x in
E, we have limit

00:34:47.449 --> 00:34:55.196 align:middle line:84%
as n goes to infinity
of chi minus n to n,

00:34:55.196 --> 00:35:03.810 align:middle line:84%
f of x raised to the p equals
f of x raised of the p.

00:35:03.810 --> 00:35:12.630 align:middle line:84%
This-- by the monotone
convergence theorem,

00:35:12.630 --> 00:35:15.280 align:middle line:84%
the integral of the limit
as n goes to infinity,

00:35:15.280 --> 00:35:22.050 align:middle line:84%
which is just f raised to
the p, is equal to the limit

00:35:22.050 --> 00:35:30.030 align:middle line:84%
as n goes to infinity of the
integral of this quantity

00:35:30.030 --> 00:35:32.910 align:middle line:84%
here over E, which is, again,
the interval over minus n

00:35:32.910 --> 00:35:36.890 align:middle line:84%
to n intersect E
raised to the p.

00:35:36.890 --> 00:35:39.230 align:middle line:84%
And therefore,
this quantity here

00:35:39.230 --> 00:35:43.790 align:middle line:84%
is finite if and only if
this quantity here is finite.

00:35:43.790 --> 00:35:46.310 align:middle line:84%
And therefore, f is
an Lp if and only

00:35:46.310 --> 00:35:51.100 align:middle line:84%
if this quantity here
is finite, and in fact,

00:35:51.100 --> 00:35:52.150 align:middle line:90%
they equal each other.

00:35:52.150 --> 00:36:01.180 align:middle line:90%


00:36:01.180 --> 00:36:10.230 align:middle line:84%
So using that theorem, if
you like, you can prove--

00:36:10.230 --> 00:36:20.310 align:middle line:84%
and I'll leave it to you-- that
if f from, let's say, R to C

00:36:20.310 --> 00:36:35.000 align:middle line:84%
is measurable and there exists
a constant non negative and q

00:36:35.000 --> 00:36:45.700 align:middle line:84%
bigger than 1 such that
for almost every x in R,

00:36:45.700 --> 00:36:49.610 align:middle line:84%
f of x is less than or
equal to a constant times 1

00:36:49.610 --> 00:37:07.490 align:middle line:84%
plus x raised to the minus
q, then f is an Lp of R

00:37:07.490 --> 00:37:09.350 align:middle line:84%
for all p bigger
than or equal to 1.

00:37:09.350 --> 00:37:13.610 align:middle line:90%


00:37:13.610 --> 00:37:16.530 align:middle line:90%
So how do you do that?

00:37:16.530 --> 00:37:23.840 align:middle line:84%
So OK, maybe I'll just indicate
why we use the previous theorem

00:37:23.840 --> 00:37:26.980 align:middle line:84%
and look at the
integral from minus n

00:37:26.980 --> 00:37:35.520 align:middle line:84%
to n intersect R. So this
here, by this estimate,

00:37:35.520 --> 00:37:37.410 align:middle line:84%
is less than or
equal to the integral

00:37:37.410 --> 00:37:49.325 align:middle line:84%
from minus n to n times constant
1 plus x to the minus q.

00:37:49.325 --> 00:37:53.020 align:middle line:84%
Now this is a continuous
function over a compact--

00:37:53.020 --> 00:37:56.380 align:middle line:84%
or closed and bounded
interval, so this is

00:37:56.380 --> 00:37:57.655 align:middle line:90%
equal to its Riemann integral.

00:37:57.655 --> 00:38:05.490 align:middle line:90%


00:38:05.490 --> 00:38:10.350 align:middle line:84%
I will often, on exams and
so on, right the Lebesgue

00:38:10.350 --> 00:38:12.540 align:middle line:84%
integral also in
this form, though.

00:38:12.540 --> 00:38:15.362 align:middle line:84%
So I don't want to
say that I'm just--

00:38:15.362 --> 00:38:17.070 align:middle line:84%
you're going to use
this kind of notation

00:38:17.070 --> 00:38:20.270 align:middle line:90%
for the Riemann integral.

00:38:20.270 --> 00:38:22.580 align:middle line:90%
But anyways.

00:38:22.580 --> 00:38:25.760 align:middle line:84%
And I leave it to you
to show that as long

00:38:25.760 --> 00:38:30.470 align:middle line:84%
as q is bigger than 1, this is
less than or equal to-- so I

00:38:30.470 --> 00:38:34.020 align:middle line:90%
should put p times q.

00:38:34.020 --> 00:38:35.640 align:middle line:90%
p times q.

00:38:35.640 --> 00:38:46.900 align:middle line:84%
That as long as q
is bigger than 1,

00:38:46.900 --> 00:38:53.620 align:middle line:84%
this integral here is less
than or equal to some constant

00:38:53.620 --> 00:38:54.640 align:middle line:90%
depending on p.

00:38:54.640 --> 00:39:06.990 align:middle line:90%


00:39:06.990 --> 00:39:08.700 align:middle line:90%
OK.

00:39:08.700 --> 00:39:18.420 align:middle line:84%
So there's many functions that
are in Lp, so it's not exactly

00:39:18.420 --> 00:39:19.680 align:middle line:90%
a trivial space.

00:39:19.680 --> 00:39:22.770 align:middle line:90%


00:39:22.770 --> 00:39:24.690 align:middle line:90%
But what kind of space is it?

00:39:24.690 --> 00:39:28.730 align:middle line:90%
Now let me state the following.

00:39:28.730 --> 00:39:34.370 align:middle line:84%
That, in fact, this is what you
proved in the assignment right

00:39:34.370 --> 00:39:38.970 align:middle line:84%
before -- or the assignment I at
least assigned before the exam,

00:39:38.970 --> 00:39:40.410 align:middle line:90%
which was following.

00:39:40.410 --> 00:39:44.645 align:middle line:90%
Let a less than b-- less than b.

00:39:44.645 --> 00:39:48.420 align:middle line:90%


00:39:48.420 --> 00:39:51.610 align:middle line:90%
And p between 1 and infinity.

00:39:51.610 --> 00:39:55.170 align:middle line:84%
So in fact, you did it
for L1, but the same proof

00:39:55.170 --> 00:39:56.220 align:middle line:90%
carries over for Lp.

00:39:56.220 --> 00:39:59.040 align:middle line:90%


00:39:59.040 --> 00:40:02.775 align:middle line:90%
fE in Lp of a, b.

00:40:02.775 --> 00:40:07.310 align:middle line:90%


00:40:07.310 --> 00:40:11.600 align:middle line:84%
So I keep adding stuff and
epsilon would be positive.

00:40:11.600 --> 00:40:15.610 align:middle line:90%


00:40:15.610 --> 00:40:20.670 align:middle line:84%
Then there exists a
continuous function

00:40:20.670 --> 00:40:31.410 align:middle line:84%
in a, b, which I can also impose
vanishes at the end points

00:40:31.410 --> 00:40:36.300 align:middle line:90%
and is close to f and Lp norm.

00:40:36.300 --> 00:40:42.310 align:middle line:90%


00:40:42.310 --> 00:40:50.710 align:middle line:84%
So what this states is that the
space of continuous functions

00:40:50.710 --> 00:40:59.065 align:middle line:90%
is dense an Lp of a, b.

00:40:59.065 --> 00:41:02.460 align:middle line:90%


00:41:02.460 --> 00:41:06.870 align:middle line:84%
And it's a proper
subset of Lp of a, b.

00:41:06.870 --> 00:41:14.560 align:middle line:84%
I can find elements in Lp that
are not continuous or even not

00:41:14.560 --> 00:41:17.480 align:middle line:84%
equal to a continuous
function almost everywhere.

00:41:17.480 --> 00:41:20.845 align:middle line:90%
So it is dense and also proper.

00:41:20.845 --> 00:41:25.010 align:middle line:90%


00:41:25.010 --> 00:41:29.030 align:middle line:84%
And now the final theorem
will prove about integration

00:41:29.030 --> 00:41:33.540 align:middle line:84%
in Lp spaces is
that Lp is complete.

00:41:33.540 --> 00:41:38.920 align:middle line:90%
So this is due to Reece and--

00:41:38.920 --> 00:41:39.420 align:middle line:90%
let's see.

00:41:39.420 --> 00:41:42.000 align:middle line:84%
Does this have a
C or is it just--

00:41:42.000 --> 00:41:48.550 align:middle line:84%
yeah, it does have a C.
This is a Banach space.

00:41:48.550 --> 00:41:52.130 align:middle line:90%


00:41:52.130 --> 00:41:54.422 align:middle line:90%
For p between 1 and infinity.

00:41:54.422 --> 00:41:57.380 align:middle line:90%


00:41:57.380 --> 00:41:58.970 align:middle line:90%
Including 1 and infinity.

00:41:58.970 --> 00:42:05.050 align:middle line:84%
Now I'll give the proof
for p between strictly

00:42:05.050 --> 00:42:06.020 align:middle line:90%
less than infinity.

00:42:06.020 --> 00:42:10.990 align:middle line:90%
So p equals infinity.

00:42:10.990 --> 00:42:19.030 align:middle line:84%
This will appear
in an assignment.

00:42:19.030 --> 00:42:26.280 align:middle line:84%
So we'll do the case of
p between 1 and infinity.

00:42:26.280 --> 00:42:32.920 align:middle line:90%


00:42:32.920 --> 00:42:34.520 align:middle line:90%
So how are we going to do this?

00:42:34.520 --> 00:42:38.470 align:middle line:84%
We are going to, in
fact, use that criterion

00:42:38.470 --> 00:42:43.390 align:middle line:84%
from several weeks ago
about when is a norm space

00:42:43.390 --> 00:42:44.350 align:middle line:90%
a Banach space?

00:42:44.350 --> 00:42:47.440 align:middle line:84%
So we proved this equivalent
criterion-- so remember,

00:42:47.440 --> 00:42:50.390 align:middle line:84%
a Banach space is a norm space
that's complete with respect

00:42:50.390 --> 00:42:50.890 align:middle line:90%
to the norm.

00:42:50.890 --> 00:42:53.410 align:middle line:84%
So you would have to check
that all Cauchy sequences

00:42:53.410 --> 00:42:56.410 align:middle line:84%
in the space converge to
something in the space.

00:42:56.410 --> 00:43:01.450 align:middle line:90%


00:43:01.450 --> 00:43:08.990 align:middle line:84%
But now we came up with
this other criterion--

00:43:08.990 --> 00:43:10.040 align:middle line:90%
I shouldn't say we did.

00:43:10.040 --> 00:43:12.200 align:middle line:84%
Somebody did, and then
I showed it to you,

00:43:12.200 --> 00:43:15.620 align:middle line:84%
that an equivalent
way to prove that is

00:43:15.620 --> 00:43:20.150 align:middle line:84%
to prove that all absolutely
summable series in the norm

00:43:20.150 --> 00:43:23.180 align:middle line:90%
space are summable.

00:43:23.180 --> 00:43:25.850 align:middle line:84%
Remember, absolutely summable
means that some of the norms

00:43:25.850 --> 00:43:26.660 align:middle line:90%
is finite.

00:43:26.660 --> 00:43:28.340 align:middle line:84%
So that's what
we're going to use--

00:43:28.340 --> 00:43:29.715 align:middle line:84%
or that's what
we're going to do.

00:43:29.715 --> 00:43:34.480 align:middle line:90%


00:43:34.480 --> 00:43:54.750 align:middle line:84%
We will show that every
absolutely summable series

00:43:54.750 --> 00:43:55.250 align:middle line:90%
is summable.

00:43:55.250 --> 00:43:59.120 align:middle line:90%


00:43:59.120 --> 00:44:11.910 align:middle line:84%
So, suppose I have a sequence
in Lk, it's a sequence in--

00:44:11.910 --> 00:44:14.550 align:middle line:90%
f is an Lp, not Lk.

00:44:14.550 --> 00:44:19.700 align:middle line:90%


00:44:19.700 --> 00:44:23.310 align:middle line:84%
That form an absolutely
seminal series.

00:44:23.310 --> 00:44:29.360 align:middle line:84%
So such that sum over k of--
if I take the LP norm of fk.

00:44:29.360 --> 00:44:33.500 align:middle line:84%
So this is now a series
of non-negative numbers,

00:44:33.500 --> 00:44:35.420 align:middle line:84%
let's assume this
converges, meaning

00:44:35.420 --> 00:44:41.425 align:middle line:84%
this I'm writing it
as this is finite.

00:44:41.425 --> 00:44:45.740 align:middle line:90%


00:44:45.740 --> 00:44:48.230 align:middle line:90%
So, in fact, this equals a--

00:44:48.230 --> 00:44:52.070 align:middle line:84%
let me call this a
convergence series something.

00:44:52.070 --> 00:44:54.005 align:middle line:84%
Call it m, which
is a finite number.

00:44:54.005 --> 00:44:59.056 align:middle line:90%


00:44:59.056 --> 00:45:06.580 align:middle line:84%
All right, so we have this
absolutely summable series,

00:45:06.580 --> 00:45:15.850 align:middle line:84%
and we want to prove that
now the series, sum of fk's,

00:45:15.850 --> 00:45:20.350 align:middle line:90%
converge to something in Lp.

00:45:20.350 --> 00:45:30.640 align:middle line:90%


00:45:30.640 --> 00:45:32.260 align:middle line:90%
And what do we want to show now?

00:45:32.260 --> 00:45:35.440 align:middle line:84%
So let me just-- so that
that's clear ahead of time,

00:45:35.440 --> 00:45:43.910 align:middle line:84%
we want to show there
exists a function in Lp

00:45:43.910 --> 00:45:53.320 align:middle line:90%
such that k equals 1 to n.

00:45:53.320 --> 00:45:56.380 align:middle line:84%
The partial sums
converts to f as n

00:45:56.380 --> 00:46:03.168 align:middle line:90%
goes to infinity and Lp of eie.

00:46:03.168 --> 00:46:07.980 align:middle line:84%
Equivalent way of writing
that is that the limit as n

00:46:07.980 --> 00:46:12.730 align:middle line:84%
goes to infinity of the
norm, some k equals 1 to n

00:46:12.730 --> 00:46:17.670 align:middle line:90%
of fk minus fp equals 0.

00:46:17.670 --> 00:46:21.290 align:middle line:90%


00:46:21.290 --> 00:46:24.680 align:middle line:84%
That will show that every
summable series is--

00:46:24.680 --> 00:46:26.720 align:middle line:84%
absolutely summable
series is summable.

00:46:26.720 --> 00:46:29.820 align:middle line:90%


00:46:29.820 --> 00:46:33.960 align:middle line:84%
So we have to identify
a candidate f and then

00:46:33.960 --> 00:46:37.530 align:middle line:90%
show that the norm of--

00:46:37.530 --> 00:46:43.901 align:middle line:84%
that this norm here goes
to 0 as n goes to infinity.

00:46:43.901 --> 00:46:52.030 align:middle line:90%
OK, so define gn from E to--

00:46:52.030 --> 00:46:55.960 align:middle line:90%


00:46:55.960 --> 00:46:58.240 align:middle line:84%
so it's a non-negative
number-- or it's a non-negative

00:46:58.240 --> 00:47:00.770 align:middle line:90%
function--

00:47:00.770 --> 00:47:09.320 align:middle line:84%
by gn of x equals sum
from k equals 1 to n

00:47:09.320 --> 00:47:11.540 align:middle line:84%
of the absolute
value of fk of x.

00:47:11.540 --> 00:47:16.140 align:middle line:90%


00:47:16.140 --> 00:47:17.990 align:middle line:84%
This is, again, a
measurable function

00:47:17.990 --> 00:47:20.390 align:middle line:84%
because it's the sum of
measurable functions.

00:47:20.390 --> 00:47:22.873 align:middle line:90%


00:47:22.873 --> 00:47:23.665 align:middle line:90%
So what do we know?

00:47:23.665 --> 00:47:27.170 align:middle line:90%


00:47:27.170 --> 00:47:29.210 align:middle line:84%
By the triangle
inequality, we know

00:47:29.210 --> 00:47:40.340 align:middle line:84%
that if I take the Lp norm of
gn, which is this finite sum--

00:47:40.340 --> 00:47:48.030 align:middle line:90%


00:47:48.030 --> 00:47:50.360 align:middle line:84%
so by the triangle
inequality for the Lp norm,

00:47:50.360 --> 00:47:54.800 align:middle line:84%
this is less than or equal
to sum from k equals 1 to n

00:47:54.800 --> 00:47:58.700 align:middle line:90%
of the Lp norms of the fk's.

00:47:58.700 --> 00:48:02.450 align:middle line:84%
And this is a partial
sum corresponding

00:48:02.450 --> 00:48:07.160 align:middle line:84%
to the series of the norms
of fk's which sum to M.

00:48:07.160 --> 00:48:12.340 align:middle line:84%
So this is always less
than or equal to M,

00:48:12.340 --> 00:48:14.635 align:middle line:84%
which we're assuming,
again, is a finite number.

00:48:14.635 --> 00:48:17.810 align:middle line:90%


00:48:17.810 --> 00:48:34.400 align:middle line:84%
And therefore, which
implies by Fatou's lemma

00:48:34.400 --> 00:48:41.360 align:middle line:84%
that the liminf as n
goes to infinity of g sub

00:48:41.360 --> 00:48:52.170 align:middle line:90%
n over E, which is equal to--

00:48:52.170 --> 00:48:56.596 align:middle line:90%
Now for each x, this--

00:48:56.596 --> 00:48:59.140 align:middle line:90%


00:48:59.140 --> 00:49:03.110 align:middle line:84%
so as n goes to infinity-- for
each x as n goes to infinity,

00:49:03.110 --> 00:49:04.570 align:middle line:90%
this converges to something.

00:49:04.570 --> 00:49:07.490 align:middle line:84%
It's either finite
or equal to infinity,

00:49:07.490 --> 00:49:08.480 align:middle line:90%
so it always converges.

00:49:08.480 --> 00:49:15.000 align:middle line:84%
So this is equal to
the infinite sum.

00:49:15.000 --> 00:49:18.440 align:middle line:84%
I should say, let's
raise this to the p.

00:49:18.440 --> 00:49:21.860 align:middle line:90%


00:49:21.860 --> 00:49:22.865 align:middle line:90%
Which is equal to--

00:49:22.865 --> 00:49:38.470 align:middle line:90%


00:49:38.470 --> 00:49:42.640 align:middle line:84%
so-- OK, I kind of
got this backwards.

00:49:42.640 --> 00:49:44.750 align:middle line:84%
I should have said
this is equal to this.

00:49:44.750 --> 00:49:47.950 align:middle line:90%
But anyways, by Fatou's lemma--

00:49:47.950 --> 00:49:50.650 align:middle line:90%
so let me reverse these things.

00:49:50.650 --> 00:50:02.590 align:middle line:90%


00:50:02.590 --> 00:50:06.000 align:middle line:84%
So by Fatou's lemma, so
I have this is equal to--

00:50:06.000 --> 00:50:08.700 align:middle line:90%
so this does not used Fatou.

00:50:08.700 --> 00:50:12.515 align:middle line:84%
It just uses the
definition of gn.

00:50:12.515 --> 00:50:15.950 align:middle line:90%


00:50:15.950 --> 00:50:19.260 align:middle line:90%
This is less than or equal to--

00:50:19.260 --> 00:50:22.550 align:middle line:90%
now I'm using Fatou's lemma.

00:50:22.550 --> 00:50:27.920 align:middle line:84%
Integral over E gn
raised to the p.

00:50:27.920 --> 00:50:32.420 align:middle line:84%
And now I use that bound
which I have right here--

00:50:32.420 --> 00:50:35.480 align:middle line:84%
this is always less
than or equal to--

00:50:35.480 --> 00:50:38.390 align:middle line:84%
remember, the Lp
norm of g sub n was

00:50:38.390 --> 00:50:41.840 align:middle line:84%
less than or equal to M. So
raising that to the p power,

00:50:41.840 --> 00:50:44.210 align:middle line:84%
I have this is less than
or equal to M to the p.

00:50:44.210 --> 00:50:50.780 align:middle line:84%
So I started off
with the integral

00:50:50.780 --> 00:50:53.270 align:middle line:84%
of this non-negative
measurable function, which

00:50:53.270 --> 00:50:57.410 align:middle line:84%
is the series of f
sub k raised to the p,

00:50:57.410 --> 00:51:00.005 align:middle line:84%
and showed that that
integral is finite.

00:51:00.005 --> 00:51:02.560 align:middle line:90%


00:51:02.560 --> 00:51:06.530 align:middle line:84%
Thus-- so by another
theorem that we

00:51:06.530 --> 00:51:09.110 align:middle line:84%
proved from integration, if I
have a non-negative measurable

00:51:09.110 --> 00:51:11.360 align:middle line:84%
function that has
finite integral,

00:51:11.360 --> 00:51:13.760 align:middle line:84%
then that measurable
function has

00:51:13.760 --> 00:51:17.900 align:middle line:90%
to be finite almost everywhere.

00:51:17.900 --> 00:51:25.190 align:middle line:84%
So thus, this quantity
has to converge

00:51:25.190 --> 00:51:38.280 align:middle line:84%
or is finite for
almost every x in E.

00:51:38.280 --> 00:51:42.195 align:middle line:84%
So, what I get is
that for almost--

00:51:42.195 --> 00:51:44.220 align:middle line:90%
let me include an x in here.

00:51:44.220 --> 00:51:53.190 align:middle line:90%


00:51:53.190 --> 00:51:58.818 align:middle line:84%
So I've proven for
almost every x in E,

00:51:58.818 --> 00:52:02.920 align:middle line:84%
fk of x is absolutely
convergent.

00:52:02.920 --> 00:52:04.860 align:middle line:84%
So this series is
absolutely convergent.

00:52:04.860 --> 00:52:07.740 align:middle line:84%
And therefore, it converges
for almost every x in E.

00:52:07.740 --> 00:52:10.500 align:middle line:84%
And I'll define my
function away, right?

00:52:10.500 --> 00:52:12.150 align:middle line:84%
Because in the end,
remember, we're

00:52:12.150 --> 00:52:16.020 align:middle line:84%
trying to find a function f
so that These partial sums

00:52:16.020 --> 00:52:17.640 align:middle line:90%
converge to f and Lp.

00:52:17.640 --> 00:52:22.560 align:middle line:84%
So if we can define f at
somehow as the almost everywhere

00:52:22.560 --> 00:52:24.600 align:middle line:84%
pointwise limit of
s sub k, maybe we

00:52:24.600 --> 00:52:26.340 align:middle line:84%
can use the dominated
convergence theorem

00:52:26.340 --> 00:52:30.860 align:middle line:84%
in some way, and
that'll be what we do.

00:52:30.860 --> 00:52:45.000 align:middle line:84%
So define f of x to
be exactly what I

00:52:45.000 --> 00:52:49.390 align:middle line:84%
get from this convergent series
when it converges, absolutely.

00:52:49.390 --> 00:52:57.820 align:middle line:90%
So if-- 0 or otherwise.

00:52:57.820 --> 00:53:02.780 align:middle line:90%


00:53:02.780 --> 00:53:10.030 align:middle line:84%
And I'm going to define g of
x to be, again, if you like,

00:53:10.030 --> 00:53:13.460 align:middle line:84%
it's when the g
sub n's converge.

00:53:13.460 --> 00:53:23.240 align:middle line:84%
So if this is finite,
and 0 otherwise.

00:53:23.240 --> 00:53:27.520 align:middle line:90%


00:53:27.520 --> 00:53:31.350 align:middle line:84%
So now I have these two
measurable real value

00:53:31.350 --> 00:53:33.920 align:middle line:90%
functions.

00:53:33.920 --> 00:53:38.930 align:middle line:84%
And this guy will end up being
what the fk's converged to.

00:53:38.930 --> 00:53:44.130 align:middle line:90%


00:53:44.130 --> 00:53:47.070 align:middle line:84%
So then we have a
couple of things.

00:53:47.070 --> 00:53:54.350 align:middle line:84%
Then limit as n goes to infinity
of sum from k equals 1 to n,

00:53:54.350 --> 00:53:55.800 align:middle line:90%
fk of x--

00:53:55.800 --> 00:53:58.550 align:middle line:90%


00:53:58.550 --> 00:54:02.920 align:middle line:90%
you can put a minus f of x--

00:54:02.920 --> 00:54:07.450 align:middle line:84%
equals 0 almost everywhere
on E. Why is that?

00:54:07.450 --> 00:54:10.060 align:middle line:84%
This is just because
f of x is simply

00:54:10.060 --> 00:54:13.750 align:middle line:84%
defined to be the infinite
sum when the sum is absolutely

00:54:13.750 --> 00:54:16.540 align:middle line:84%
convergent, which is almost
everywhere by what we've done.

00:54:16.540 --> 00:54:20.710 align:middle line:90%


00:54:20.710 --> 00:54:21.535 align:middle line:90%
What else?

00:54:21.535 --> 00:54:26.520 align:middle line:90%


00:54:26.520 --> 00:54:31.020 align:middle line:84%
If I-- so this is
one crucial thing.

00:54:31.020 --> 00:54:36.250 align:middle line:90%


00:54:36.250 --> 00:54:51.570 align:middle line:84%
And minus f of x, this is
less than or equal to g of x--

00:54:51.570 --> 00:55:00.430 align:middle line:84%
so it's the p raised the p
almost everywhere on E. OK,

00:55:00.430 --> 00:55:02.800 align:middle line:90%
why is this?

00:55:02.800 --> 00:55:05.380 align:middle line:84%
Holds, for example,
when the series

00:55:05.380 --> 00:55:07.270 align:middle line:90%
is absolutely convergent.

00:55:07.270 --> 00:55:11.435 align:middle line:84%
Because then f of x is equal
to the infinite sum of the fk's

00:55:11.435 --> 00:55:11.935 align:middle line:90%
of x.

00:55:11.935 --> 00:55:14.605 align:middle line:90%


00:55:14.605 --> 00:55:16.448 align:middle line:84%
And so by the
triangle inequality,

00:55:16.448 --> 00:55:17.990 align:middle line:84%
the absolute value
of that difference

00:55:17.990 --> 00:55:20.480 align:middle line:84%
is going to be less
than or equal to the sum

00:55:20.480 --> 00:55:22.250 align:middle line:90%
of the absolute values.

00:55:22.250 --> 00:55:27.590 align:middle line:84%
That's by definition equal
to g sub n or g sub n plus 1.

00:55:27.590 --> 00:55:31.460 align:middle line:84%
g is the limit of the g
sub n, so the g sub n's

00:55:31.460 --> 00:55:32.390 align:middle line:90%
are increasing.

00:55:32.390 --> 00:55:34.685 align:middle line:84%
So that always
sits below g of x.

00:55:34.685 --> 00:55:49.930 align:middle line:90%


00:55:49.930 --> 00:55:59.500 align:middle line:84%
Now, by-- I should say, by this,
I don't want to pull it up.

00:55:59.500 --> 00:56:17.620 align:middle line:84%
So let's just say, since we
proved that the Lp norm of this

00:56:17.620 --> 00:56:23.280 align:middle line:84%
is less than or equal
to M, which this here

00:56:23.280 --> 00:56:27.870 align:middle line:84%
is equal to g almost
everywhere, this

00:56:27.870 --> 00:56:36.940 align:middle line:84%
implies that the LP norm of
g is equal to this Lp norm,

00:56:36.940 --> 00:56:38.800 align:middle line:84%
and therefore is less
than or equal to M

00:56:38.800 --> 00:56:49.985 align:middle line:84%
And therefore, that means the
Lp norm raised the PE is finite.

00:56:49.985 --> 00:56:57.600 align:middle line:90%


00:56:57.600 --> 00:57:00.465 align:middle line:84%
Moreover, what
else do we deduce?

00:57:00.465 --> 00:57:02.970 align:middle line:90%


00:57:02.970 --> 00:57:09.180 align:middle line:84%
We also deduce from
this that f, which

00:57:09.180 --> 00:57:13.560 align:middle line:84%
is bounded above by almost
everywhere by this quantity,

00:57:13.560 --> 00:57:17.140 align:middle line:90%
this is less than or equal to--

00:57:17.140 --> 00:57:19.330 align:middle line:84%
which is equal to g
almost everywhere,

00:57:19.330 --> 00:57:21.900 align:middle line:84%
the Lp form of f is less
than or equal to the Lp

00:57:21.900 --> 00:57:25.710 align:middle line:84%
norm of g, which, as we said,
is less than or equal to M--

00:57:25.710 --> 00:57:31.770 align:middle line:90%
i.e., f is an Lp of E.

00:57:31.770 --> 00:57:33.840 align:middle line:84%
So again, almost
everywhere we have

00:57:33.840 --> 00:57:37.680 align:middle line:84%
that f which is equal to the
sum without the absolute values.

00:57:37.680 --> 00:57:40.980 align:middle line:84%
That's always less than or
equal to an absolute value.

00:57:40.980 --> 00:57:42.780 align:middle line:90%
The sum from k equals--

00:57:42.780 --> 00:57:45.742 align:middle line:84%
the sum over k with
absolute values inside.

00:57:45.742 --> 00:57:47.700 align:middle line:84%
And we know that the Lp
form of this is finite,

00:57:47.700 --> 00:57:50.850 align:middle line:84%
we proved that earlier, which
tells me that the Lp norm of g

00:57:50.850 --> 00:57:53.700 align:middle line:84%
is finite, because g is
equal to this quantity

00:57:53.700 --> 00:57:54.450 align:middle line:90%
almost everywhere.

00:57:54.450 --> 00:57:57.630 align:middle line:84%
It's 0 on a set of measure
0, which we just threw

00:57:57.630 --> 00:58:00.610 align:middle line:90%
in there to make it finite.

00:58:00.610 --> 00:58:08.700 align:middle line:84%
So we have f is an Lp,
we have g is an Lp.

00:58:08.700 --> 00:58:11.950 align:middle line:84%
So at least this can be
a possible candidate.

00:58:11.950 --> 00:58:15.330 align:middle line:84%
And we have these
two facts here.

00:58:15.330 --> 00:58:22.670 align:middle line:84%
Now we apply the dominated
convergence theorem

00:58:22.670 --> 00:58:24.680 align:middle line:90%
using this fact, this--

00:58:24.680 --> 00:58:29.240 align:middle line:84%
we have converging to 0
almost everywhere on E.

00:58:29.240 --> 00:58:32.750 align:middle line:84%
And since that's true,
I can put, if you like,

00:58:32.750 --> 00:58:34.700 align:middle line:90%
raised to the p.

00:58:34.700 --> 00:58:36.680 align:middle line:84%
So this quantity here
is converging to 0

00:58:36.680 --> 00:58:38.060 align:middle line:90%
almost everywhere.

00:58:38.060 --> 00:58:42.950 align:middle line:84%
This quantity is also bounded
above by this quantity here

00:58:42.950 --> 00:58:44.810 align:middle line:84%
on the right, which
is integrable.

00:58:44.810 --> 00:58:47.780 align:middle line:84%
It has the integral of
g to the p is finite.

00:58:47.780 --> 00:58:50.900 align:middle line:84%
So by the dominated
convergence theorem,

00:58:50.900 --> 00:58:55.220 align:middle line:84%
I can conclude
that the limit as n

00:58:55.220 --> 00:59:02.930 align:middle line:84%
goes to infinity of sum from k
equals 1 to n of the fk's minus

00:59:02.930 --> 00:59:08.750 align:middle line:84%
f raised to the p over E,
this equals the integral

00:59:08.750 --> 00:59:10.790 align:middle line:84%
of the limit, which,
remember, is 0.

00:59:10.790 --> 00:59:15.350 align:middle line:90%


00:59:15.350 --> 00:59:16.805 align:middle line:90%
I.e., we've shown that.

00:59:16.805 --> 00:59:32.275 align:middle line:90%


00:59:32.275 --> 00:59:33.650 align:middle line:84%
Which is what we
wanted to prove.

00:59:33.650 --> 00:59:37.807 align:middle line:90%


00:59:37.807 --> 00:59:39.890 align:middle line:84%
Now of course, you need a
different argument for p

00:59:39.890 --> 00:59:42.905 align:middle line:84%
equals infinity, and it's
a little bit simpler.

00:59:42.905 --> 00:59:47.310 align:middle line:90%


00:59:47.310 --> 00:59:52.420 align:middle line:84%
So we've proved that
Lp is a Banach space.

00:59:52.420 --> 00:59:57.300 align:middle line:84%
And notice, we used a lot of
different tools and things

00:59:57.300 --> 01:00:02.670 align:middle line:84%
that we had developed
over the course of this--

01:00:02.670 --> 01:00:05.475 align:middle line:84%
over the course of
this course so far.

01:00:05.475 --> 01:00:10.330 align:middle line:90%


01:00:10.330 --> 01:00:12.370 align:middle line:84%
I keep using this word
completion even though we

01:00:12.370 --> 01:00:13.900 align:middle line:90%
haven't really talked about it.

01:00:13.900 --> 01:00:15.940 align:middle line:84%
I kind of left it out
of the first chapter

01:00:15.940 --> 01:00:18.340 align:middle line:84%
because I wasn't going
to use the second chapter

01:00:18.340 --> 01:00:24.980 align:middle line:84%
from the lecture notes that are
usually used for this course.

01:00:24.980 --> 01:00:29.268 align:middle line:90%
But from this fact--

01:00:29.268 --> 01:00:30.810 align:middle line:84%
so you should think
of the completion

01:00:30.810 --> 01:00:36.470 align:middle line:84%
as the smallest Banach space
containing a certain norm

01:00:36.470 --> 01:00:36.970 align:middle line:90%
space.

01:00:36.970 --> 01:00:40.900 align:middle line:84%
But what this statement
here along with the theorem

01:00:40.900 --> 01:00:43.960 align:middle line:84%
due to Riesz and Fischer
is that the completion

01:00:43.960 --> 01:00:46.930 align:middle line:84%
of continuous functions
over a, b with norm

01:00:46.930 --> 01:00:49.640 align:middle line:84%
given by the Lp norm,
which is, in fact,

01:00:49.640 --> 01:00:51.550 align:middle line:84%
a norm on continuous
functions because if

01:00:51.550 --> 01:00:54.040 align:middle line:84%
a continuous function is
equal to 0 almost everywhere,

01:00:54.040 --> 01:00:56.380 align:middle line:90%
it has to be 0.

01:00:56.380 --> 01:00:58.750 align:middle line:84%
So what this proves
is that the completion

01:00:58.750 --> 01:01:01.900 align:middle line:84%
of the continuous
functions with this norm

01:01:01.900 --> 01:01:03.810 align:middle line:90%
is equal to the space Lp.

01:01:03.810 --> 01:01:14.970 align:middle line:90%


01:01:14.970 --> 01:01:20.230 align:middle line:84%
So now we're going
to move on back

01:01:20.230 --> 01:01:23.650 align:middle line:84%
to some more general theory
of functional analysis.

01:01:23.650 --> 01:01:29.727 align:middle line:84%
This was specific to
measure and integration

01:01:29.727 --> 01:01:30.560 align:middle line:90%
on the real numbers.

01:01:30.560 --> 01:01:41.500 align:middle line:84%
Now we're going to go to more
general topics and probably

01:01:41.500 --> 01:01:54.350 align:middle line:84%
more intuitive topics because
a lot of it has analogs.

01:01:54.350 --> 01:01:58.130 align:middle line:84%
I mean, a lot of
functional analysis has--

01:01:58.130 --> 01:02:01.820 align:middle line:84%
it's supposed to be in
some way analogous to stuff

01:02:01.820 --> 01:02:05.270 align:middle line:90%
you've seen in linear algebra.

01:02:05.270 --> 01:02:06.635 align:middle line:90%
Some of it definitely is not.

01:02:06.635 --> 01:02:12.490 align:middle line:90%


01:02:12.490 --> 01:02:14.640 align:middle line:84%
For example, in one
of the assignments,

01:02:14.640 --> 01:02:19.770 align:middle line:84%
you proved that the
unit ball and little Lp

01:02:19.770 --> 01:02:21.030 align:middle line:90%
is not compact for--

01:02:21.030 --> 01:02:23.640 align:middle line:90%


01:02:23.640 --> 01:02:25.980 align:middle line:84%
over the natural
numbers, the set

01:02:25.980 --> 01:02:29.160 align:middle line:84%
of sequences that have
little-- finite little Lp norm.

01:02:29.160 --> 01:02:30.390 align:middle line:90%
That that's not compact.

01:02:30.390 --> 01:02:41.660 align:middle line:84%
While from calculus, that in
Rn, the unit ball is compact.

01:02:41.660 --> 01:02:46.040 align:middle line:84%
That's the Burrill theorem or
Bolzano-Weierstrass depending

01:02:46.040 --> 01:02:52.730 align:middle line:84%
on if you take as your starting
definition of compactness

01:02:52.730 --> 01:02:55.400 align:middle line:84%
in terms of open sets or in
terms of sequences having

01:02:55.400 --> 01:03:00.620 align:middle line:84%
a convergent subsequence, which
are equivalent for metric--

01:03:00.620 --> 01:03:01.790 align:middle line:90%
at least in a metric space.

01:03:01.790 --> 01:03:05.190 align:middle line:90%


01:03:05.190 --> 01:03:05.760 align:middle line:90%
OK.

01:03:05.760 --> 01:03:11.750 align:middle line:84%
Now here we're going to move on
to the topic of Hilbert spaces.

01:03:11.750 --> 01:03:25.450 align:middle line:84%
So these are
special in the sense

01:03:25.450 --> 01:03:28.653 align:middle line:84%
that the norm comes from
an inner product-- maybe

01:03:28.653 --> 01:03:30.445 align:middle line:84%
you saw an inner product
in linear algebra.

01:03:30.445 --> 01:03:33.460 align:middle line:90%


01:03:33.460 --> 01:03:35.830 align:middle line:90%
Or you should have at least.

01:03:35.830 --> 01:03:38.050 align:middle line:84%
And therefore, you have
notions of being orthogonal,

01:03:38.050 --> 01:03:40.210 align:middle line:84%
you have notions of
projections, and these--

01:03:40.210 --> 01:03:45.727 align:middle line:84%
we saw things that
have that flavor when

01:03:45.727 --> 01:03:47.560 align:middle line:84%
we're talking about
Banach spaces in general

01:03:47.560 --> 01:03:52.940 align:middle line:84%
and we were talking about
modding out by a subspace,

01:03:52.940 --> 01:03:55.960 align:middle line:84%
and you can think of the
equivalence class corresponding

01:03:55.960 --> 01:04:00.640 align:middle line:84%
to an element as the
projection onto the complement

01:04:00.640 --> 01:04:07.100 align:middle line:84%
of that subspace, but it
wasn't an exact analogy.

01:04:07.100 --> 01:04:09.020 align:middle line:84%
But a lot of exact
analogies will now

01:04:09.020 --> 01:04:10.550 align:middle line:84%
occur for Hilbert
spaces, and then

01:04:10.550 --> 01:04:13.430 align:middle line:84%
certain operators
on Hilbert spaces

01:04:13.430 --> 01:04:22.460 align:middle line:84%
will be very analogous
to self-adjoint matrices

01:04:22.460 --> 01:04:28.490 align:middle line:84%
or symmetric matrices which
you saw in linear algebra.

01:04:28.490 --> 01:04:31.520 align:middle line:84%
And of course, from a
applied standpoint--

01:04:31.520 --> 01:04:33.410 align:middle line:90%
I should say applied--

01:04:33.410 --> 01:04:36.980 align:middle line:84%
Hilbert spaces, this
is where the action--

01:04:36.980 --> 01:04:39.978 align:middle line:90%


01:04:39.978 --> 01:04:42.020 align:middle line:84%
this is where-- the setting
of quantum mechanics.

01:04:42.020 --> 01:04:47.470 align:middle line:84%
Quantum mechanics takes
place in a Hilbert space.

01:04:47.470 --> 01:04:50.570 align:middle line:84%
The elements are
square integrable,

01:04:50.570 --> 01:04:54.633 align:middle line:84%
now that we've dealt with
that, functions over R3,

01:04:54.633 --> 01:04:56.300 align:middle line:84%
if we're in three
dimensions or if we're

01:04:56.300 --> 01:05:03.230 align:middle line:84%
on the line R, that
have L2 norm equal to 1,

01:05:03.230 --> 01:05:05.150 align:middle line:84%
along with the
Schrodinger equation.

01:05:05.150 --> 01:05:08.592 align:middle line:84%
So Hilbert spaces
are very important.

01:05:08.592 --> 01:05:10.175 align:middle line:84%
They arise naturally
in many problems.

01:05:10.175 --> 01:05:12.770 align:middle line:90%


01:05:12.770 --> 01:05:16.640 align:middle line:84%
And because of this
additional structure of them--

01:05:16.640 --> 01:05:20.550 align:middle line:84%
of the norm coming
from an inner product,

01:05:20.550 --> 01:05:25.260 align:middle line:84%
you can say a lot more
things about them.

01:05:25.260 --> 01:05:29.000 align:middle line:90%


01:05:29.000 --> 01:05:34.060 align:middle line:84%
So before we get
to Hilbert spaces,

01:05:34.060 --> 01:05:39.620 align:middle line:90%
let me add a "pre" before that.

01:05:39.620 --> 01:05:41.400 align:middle line:90%
So pre-Hilbert spaces.

01:05:41.400 --> 01:05:43.220 align:middle line:84%
So I said that
Hilbert spaces are

01:05:43.220 --> 01:05:46.310 align:middle line:84%
going to be Banach spaces
that come from a norm.

01:05:46.310 --> 01:05:47.750 align:middle line:84%
Pre-Hilbert spaces,
these are just

01:05:47.750 --> 01:05:50.400 align:middle line:84%
norm spaces that come
from an inner product.

01:05:50.400 --> 01:05:53.180 align:middle line:84%
So make the
following definition.

01:05:53.180 --> 01:05:58.860 align:middle line:90%


01:05:58.860 --> 01:06:07.850 align:middle line:84%
A pre-Hilbert space H,
this is a vector space.

01:06:07.850 --> 01:06:11.010 align:middle line:90%


01:06:11.010 --> 01:06:13.920 align:middle line:84%
Typically over C, but
you can also just take it

01:06:13.920 --> 01:06:17.290 align:middle line:90%
over R, that's fine as well.

01:06:17.290 --> 01:06:19.357 align:middle line:84%
But I'll just for
definiteness say over

01:06:19.357 --> 01:06:32.765 align:middle line:84%
C. With a Hermitian
inner product.

01:06:32.765 --> 01:06:35.730 align:middle line:90%


01:06:35.730 --> 01:06:38.250 align:middle line:84%
So this is new
terminology, maybe this

01:06:38.250 --> 01:06:44.460 align:middle line:84%
is new terminology, too, so let
me write out what it means--

01:06:44.460 --> 01:06:46.330 align:middle line:84%
what is a Hermitian
inner product.

01:06:46.330 --> 01:06:55.310 align:middle line:84%
So this is, i.e., a
map, usually denoted

01:06:55.310 --> 01:07:01.010 align:middle line:84%
using brackets from H-cross-H
into the complex numbers.

01:07:01.010 --> 01:07:06.120 align:middle line:84%
Satisfying certain
properties-- so such that--

01:07:06.120 --> 01:07:25.700 align:middle line:84%
so one, it is linear
and the first variable--

01:07:25.700 --> 01:07:29.940 align:middle line:84%
so for all lambda
1, lambda 2, v1, v2,

01:07:29.940 --> 01:07:35.370 align:middle line:84%
if I look at the inner product
of v1, lambda 1 times v1

01:07:35.370 --> 01:07:41.040 align:middle line:84%
plus lambda 2 times v2 with w,
this is equal to lambda 1 times

01:07:41.040 --> 01:07:47.230 align:middle line:84%
v1 times the inner product
with w plus lambda 2 v2

01:07:47.230 --> 01:07:48.190 align:middle line:90%
inner product with w.

01:07:48.190 --> 01:07:56.580 align:middle line:90%


01:07:56.580 --> 01:07:59.340 align:middle line:90%
For all V, w, and--

01:07:59.340 --> 01:08:01.290 align:middle line:84%
I wrote capital
V, I should have--

01:08:01.290 --> 01:08:02.790 align:middle line:90%
written H a minute ago.

01:08:02.790 --> 01:08:07.020 align:middle line:90%


01:08:07.020 --> 01:08:09.690 align:middle line:84%
Now we're in Hilbert
spaces, pre-Hilbert spaces.

01:08:09.690 --> 01:08:13.200 align:middle line:84%
For all v and w, the
inner product of v and w

01:08:13.200 --> 01:08:18.750 align:middle line:84%
is equal to the complex
conjugate of the inner product

01:08:18.750 --> 01:08:28.200 align:middle line:90%
of w with v.

01:08:28.200 --> 01:08:31.830 align:middle line:84%
And the following, which
is positive definiteness

01:08:31.830 --> 01:08:37.335 align:middle line:84%
of the inner product, if to
call it that, for all v and H,

01:08:37.335 --> 01:08:42.640 align:middle line:84%
m the inner product
would be with itself,

01:08:42.640 --> 01:08:45.670 align:middle line:84%
this is bigger than or equal
to 0, so it's a real number

01:08:45.670 --> 01:08:48.250 align:middle line:90%
and it's non-negative.

01:08:48.250 --> 01:08:56.050 align:middle line:84%
And this one, it equals 0 if
and only if v is a zero element.

01:08:56.050 --> 01:09:06.229 align:middle line:90%


01:09:06.229 --> 01:09:07.970 align:middle line:90%
OK.

01:09:07.970 --> 01:09:14.729 align:middle line:84%
So let me make a
couple of remarks.

01:09:14.729 --> 01:09:19.474 align:middle line:84%
First off, let's say
this is remark 1.

01:09:19.474 --> 01:09:23.180 align:middle line:90%


01:09:23.180 --> 01:09:25.390 align:middle line:84%
The third quantity does
imply that the only thing

01:09:25.390 --> 01:09:28.040 align:middle line:84%
orthogonal to everything in
the space is a zero element.

01:09:28.040 --> 01:09:35.609 align:middle line:84%
So v is in H and v is
orthogonal to everything--

01:09:35.609 --> 01:09:37.800 align:middle line:84%
I keep using the
word orthogonal.

01:09:37.800 --> 01:09:40.500 align:middle line:84%
I should just the inner
product with zero.

01:09:40.500 --> 01:09:53.069 align:middle line:84%
It gives me 0 for every element,
this implies that v equals 0,

01:09:53.069 --> 01:09:54.990 align:middle line:84%
and of course, the
converse applies, too,

01:09:54.990 --> 01:09:58.500 align:middle line:84%
that v is equal to 0, then
the inner product with 0

01:09:58.500 --> 01:10:02.430 align:middle line:84%
and every element is
0 just by linearity.

01:10:02.430 --> 01:10:09.930 align:middle line:84%
Two is that if I have two
elements v and w and a scalar

01:10:09.930 --> 01:10:16.890 align:middle line:84%
lambda, then this is equal to
the complex conjugate of lambda

01:10:16.890 --> 01:10:27.080 align:middle line:84%
times w with v, and by the first
property, the lambda pops out,

01:10:27.080 --> 01:10:29.930 align:middle line:90%
and therefore, if I--

01:10:29.930 --> 01:10:31.910 align:middle line:84%
complex conjugate of
a product is a product

01:10:31.910 --> 01:10:33.260 align:middle line:90%
of the complex conjugates.

01:10:33.260 --> 01:10:38.000 align:middle line:84%
And then if I undo
this, I can get this.

01:10:38.000 --> 01:10:42.650 align:middle line:84%
So it's linear in
the first entry,

01:10:42.650 --> 01:10:44.570 align:middle line:84%
meaning the constants
just come out.

01:10:44.570 --> 01:10:46.610 align:middle line:84%
But if I have a
constant in the second--

01:10:46.610 --> 01:10:50.600 align:middle line:84%
or a scalar multiple
in the second entry,

01:10:50.600 --> 01:10:53.840 align:middle line:84%
then that comes out as well,
but with a complex conjugate

01:10:53.840 --> 01:10:54.930 align:middle line:90%
over it.

01:10:54.930 --> 01:10:56.270 align:middle line:90%
That's all I wanted to say.

01:10:56.270 --> 01:11:00.150 align:middle line:90%


01:11:00.150 --> 01:11:04.830 align:middle line:84%
So I said that pre
Hilbert spaces are--

01:11:04.830 --> 01:11:08.540 align:middle line:84%
you naturally think of them
as norm spaces where the norm

01:11:08.540 --> 01:11:10.400 align:middle line:90%
comes from the inner product.

01:11:10.400 --> 01:11:12.170 align:middle line:90%
Here, we have in a product.

01:11:12.170 --> 01:11:13.010 align:middle line:90%
Where's the norm?

01:11:13.010 --> 01:11:16.910 align:middle line:90%


01:11:16.910 --> 01:11:18.200 align:middle line:90%
So definition.

01:11:18.200 --> 01:11:29.420 align:middle line:84%
If H is a pre-Hilbert space
with inner product denoted

01:11:29.420 --> 01:11:42.810 align:middle line:84%
as before, we
define using this--

01:11:42.810 --> 01:11:44.350 align:middle line:84%
So I'm not calling
it a norm yet.

01:11:44.350 --> 01:11:48.510 align:middle line:84%
I'm just saying we
define this function on H

01:11:48.510 --> 01:11:54.990 align:middle line:84%
to be in a product v with
itself raised to the 1/2 power.

01:11:54.990 --> 01:11:56.670 align:middle line:84%
In the end or in a
minute we'll show

01:11:56.670 --> 01:11:58.140 align:middle line:90%
that this is, in fact, a norm.

01:11:58.140 --> 01:12:02.900 align:middle line:90%


01:12:02.900 --> 01:12:09.020 align:middle line:84%
But for now I'm just going
to call it this function on H

01:12:09.020 --> 01:12:18.650 align:middle line:84%
or possible norm on
H. All right, so we

01:12:18.650 --> 01:12:21.140 align:middle line:90%
have the following theorem.

01:12:21.140 --> 01:12:23.450 align:middle line:84%
So this is valid in
any pre-Hilbert space.

01:12:23.450 --> 01:12:27.230 align:middle line:90%


01:12:27.230 --> 01:12:30.590 align:middle line:84%
For all u, v, and H
of pre-Hilbert space,

01:12:30.590 --> 01:12:36.770 align:middle line:84%
if I take the absolute value of
the inner product of u and v,

01:12:36.770 --> 01:12:46.070 align:middle line:84%
this is less than or equal
to this norm-looking thing

01:12:46.070 --> 01:12:51.850 align:middle line:84%
of u times the
norm-looking thing of v.

01:12:51.850 --> 01:13:01.230 align:middle line:84%
So this shouldn't come
as a complete surprise.

01:13:01.230 --> 01:13:05.350 align:middle line:84%
Right down-- if we
took H to be Rn,

01:13:05.350 --> 01:13:10.860 align:middle line:84%
and so then now this is
a vector space over R,

01:13:10.860 --> 01:13:13.980 align:middle line:84%
then and the inner product
would just be the dot product.

01:13:13.980 --> 01:13:17.610 align:middle line:84%
This is stating the
Cauchy-Schwarz inequality

01:13:17.610 --> 01:13:20.080 align:middle line:84%
that you know and
love from before.

01:13:20.080 --> 01:13:23.760 align:middle line:90%
So what's the proof?

01:13:23.760 --> 01:13:37.800 align:middle line:84%
Let's let f of t be the
norm of u plus t times v.

01:13:37.800 --> 01:13:40.510 align:middle line:84%
So I said norm, but I haven't
proved it's a norm yet,

01:13:40.510 --> 01:13:42.802 align:middle line:84%
so you're going to have to
forgive if I keep calling it

01:13:42.802 --> 01:13:45.570 align:middle line:90%
a norm, but in the end it is.

01:13:45.570 --> 01:13:50.700 align:middle line:84%
Let f of t be this thing
squared, which, we note,

01:13:50.700 --> 01:13:52.380 align:middle line:90%
it's a non-negative number.

01:13:52.380 --> 01:13:56.040 align:middle line:84%
Because the product of v with v
is a non-negative number taking

01:13:56.040 --> 01:14:04.310 align:middle line:84%
that to the 1/2 power, so this
is u plus tv inner product u

01:14:04.310 --> 01:14:10.570 align:middle line:90%
plus tv which is non-negative.

01:14:10.570 --> 01:14:20.910 align:middle line:84%
Now if we compute all this out
using how the linearity works

01:14:20.910 --> 01:14:25.090 align:middle line:90%
for inner products, this--

01:14:25.090 --> 01:14:30.060 align:middle line:84%
I get u inner product
u plus t squared

01:14:30.060 --> 01:14:35.100 align:middle line:84%
v inner product v plus
t times u inner product

01:14:35.100 --> 01:14:40.820 align:middle line:84%
v plus t times inner
product of v with u.

01:14:40.820 --> 01:14:43.690 align:middle line:90%


01:14:43.690 --> 01:14:46.120 align:middle line:84%
And this is the
complex conjugate

01:14:46.120 --> 01:14:48.410 align:middle line:90%
of this complex number.

01:14:48.410 --> 01:14:54.250 align:middle line:84%
So let me just rewrite this--
u squared plus t squared or v

01:14:54.250 --> 01:14:56.530 align:middle line:90%
squared plus--

01:14:56.530 --> 01:14:59.530 align:middle line:84%
so again, this number
is the complex conjugate

01:14:59.530 --> 01:15:00.430 align:middle line:90%
of this number.

01:15:00.430 --> 01:15:03.910 align:middle line:84%
And when I add a complex number
to its complex conjugate,

01:15:03.910 --> 01:15:06.920 align:middle line:90%
I get twice times the real part.

01:15:06.920 --> 01:15:20.390 align:middle line:90%
2t real part of u and v.

01:15:20.390 --> 01:15:25.670 align:middle line:84%
Now, this is just a polynomial
with a non-negative thing

01:15:25.670 --> 01:15:26.940 align:middle line:90%
out in front of t squared.

01:15:26.940 --> 01:15:28.340 align:middle line:90%
So it has a minimum somewhere.

01:15:28.340 --> 01:15:30.470 align:middle line:84%
And this minimum has
to be non-negative

01:15:30.470 --> 01:15:32.765 align:middle line:84%
since this function is
greater than or equal to 0.

01:15:32.765 --> 01:15:42.390 align:middle line:90%


01:15:42.390 --> 01:15:47.890 align:middle line:84%
Is greater than or equal to 0, I
should say, just as a sentence.

01:15:47.890 --> 01:15:59.980 align:middle line:90%


01:15:59.980 --> 01:16:01.810 align:middle line:84%
Now, where does
this minimum occur?

01:16:01.810 --> 01:16:05.380 align:middle line:84%
It occurs where the
derivative is equal to 0.

01:16:05.380 --> 01:16:11.920 align:middle line:84%
Now f prime of t then
equals 0 implies--

01:16:11.920 --> 01:16:18.040 align:middle line:84%
or if and only if t min is
equal to minus the real part.

01:16:18.040 --> 01:16:21.310 align:middle line:84%
So I will leave this
calculus to you.

01:16:21.310 --> 01:16:26.420 align:middle line:90%


01:16:26.420 --> 01:16:27.860 align:middle line:84%
I mean, this is
just a polynomial.

01:16:27.860 --> 01:16:29.402 align:middle line:84%
Take the derivative
with respect to t

01:16:29.402 --> 01:16:32.150 align:middle line:84%
and solve for when
that's equal to 0.

01:16:32.150 --> 01:16:36.590 align:middle line:84%
And therefore, I get
that this minimum--

01:16:36.590 --> 01:16:39.420 align:middle line:84%
so f evaluated at this
point is non-negative,

01:16:39.420 --> 01:16:45.530 align:middle line:84%
so 0 is less than or equal
to f of t min, which,

01:16:45.530 --> 01:16:48.950 align:middle line:84%
when you stick that
into this here,

01:16:48.950 --> 01:16:58.580 align:middle line:84%
you get norm of u squared
minus real part of u v squared

01:16:58.580 --> 01:17:03.540 align:middle line:90%
over norm of v squared.

01:17:03.540 --> 01:17:12.310 align:middle line:84%
And therefore, the real part
of u, v absolute value--

01:17:12.310 --> 01:17:15.750 align:middle line:84%
so this-- all of this is
bigger than or equal to 0.

01:17:15.750 --> 01:17:17.685 align:middle line:84%
So if I move this
over to that side

01:17:17.685 --> 01:17:20.790 align:middle line:84%
and multiplied by norm
squared, take the square root,

01:17:20.790 --> 01:17:24.780 align:middle line:84%
I get that this is
less than or equal to--

01:17:24.780 --> 01:17:25.410 align:middle line:90%
le me put a--

01:17:25.410 --> 01:17:29.290 align:middle line:90%


01:17:29.290 --> 01:17:31.690 align:middle line:90%
u times norm v.

01:17:31.690 --> 01:17:34.490 align:middle line:90%
So this is almost what I want.

01:17:34.490 --> 01:17:40.570 align:middle line:84%
I want the absolute value of the
inner product with u and v. But

01:17:40.570 --> 01:17:47.030 align:middle line:84%
all I have is the real part
of inner product with u and v.

01:17:47.030 --> 01:17:49.970 align:middle line:84%
So of course, if the inner
product of u and v is 0,

01:17:49.970 --> 01:17:54.380 align:middle line:84%
this inequality I want
to prove is automatic.

01:17:54.380 --> 01:17:59.420 align:middle line:84%
Also, if u or v is 0, then this
inequality I wanted to prove

01:17:59.420 --> 01:18:00.180 align:middle line:90%
is automatic.

01:18:00.180 --> 01:18:02.180 align:middle line:84%
So that's why I'm
actually just dealing

01:18:02.180 --> 01:18:03.780 align:middle line:90%
with the non-trivial case.

01:18:03.780 --> 01:18:11.450 align:middle line:84%
So if this inner
product is 0, then we're

01:18:11.450 --> 01:18:13.250 align:middle line:84%
already done because
the right-hand side

01:18:13.250 --> 01:18:14.210 align:middle line:90%
is non-negative.

01:18:14.210 --> 01:18:25.250 align:middle line:84%
So suppose this is non-zero, but
lambda be this complex number

01:18:25.250 --> 01:18:29.210 align:middle line:84%
u, v inner product
complex conjugate

01:18:29.210 --> 01:18:39.480 align:middle line:84%
over the absolute value,
then the absolute value

01:18:39.480 --> 01:18:41.880 align:middle line:84%
of this complex
number is equal to 1

01:18:41.880 --> 01:18:44.820 align:middle line:84%
because the absolute
value of the conjugate

01:18:44.820 --> 01:18:48.045 align:middle line:84%
is equal to the absolute value
of the original complex number.

01:18:48.045 --> 01:18:51.590 align:middle line:90%


01:18:51.590 --> 01:19:03.560 align:middle line:84%
And lambda times u, v,
which is equal to lambda.

01:19:03.560 --> 01:19:18.000 align:middle line:84%
So I should say u, v, this is
equal to lambda times u, v,

01:19:18.000 --> 01:19:23.010 align:middle line:84%
which is equal to
lambda u times v.

01:19:23.010 --> 01:19:26.910 align:middle line:84%
Now this is equal to
this, and therefore, it's

01:19:26.910 --> 01:19:29.010 align:middle line:90%
equal to the real part of it.

01:19:29.010 --> 01:19:32.490 align:middle line:84%
So this is equal
to a real number,

01:19:32.490 --> 01:19:36.055 align:middle line:84%
and therefore it's
equal to its real part.

01:19:36.055 --> 01:19:37.430 align:middle line:84%
We pulled a similar
trick when we

01:19:37.430 --> 01:19:39.180 align:middle line:84%
were talking about the
triangle inequality

01:19:39.180 --> 01:19:43.520 align:middle line:84%
for integral functions
that now take

01:19:43.520 --> 01:19:45.050 align:middle line:90%
values and the complex number--

01:19:45.050 --> 01:19:46.020 align:middle line:90%
complex numbers.

01:19:46.020 --> 01:19:48.320 align:middle line:84%
So this is equal to the
real part of this, which

01:19:48.320 --> 01:19:49.460 align:middle line:90%
is less than or equal to--

01:19:49.460 --> 01:19:52.960 align:middle line:90%


01:19:52.960 --> 01:19:55.120 align:middle line:84%
by what we've done
here, we've already

01:19:55.120 --> 01:19:57.940 align:middle line:84%
proven this inequality
holds for every u and v,

01:19:57.940 --> 01:20:06.350 align:middle line:84%
so it also holds for lambda
times u times v. And now--

01:20:06.350 --> 01:20:11.780 align:middle line:84%
so simple off to the side,
that if I take lambda u,

01:20:11.780 --> 01:20:13.460 align:middle line:84%
an inner product
with lambda u, if I

01:20:13.460 --> 01:20:16.010 align:middle line:84%
take the 1/2 power of that,
that gives me this quantity.

01:20:16.010 --> 01:20:17.420 align:middle line:90%
But let me just compute this.

01:20:17.420 --> 01:20:18.710 align:middle line:90%
This is equal to--

01:20:18.710 --> 01:20:20.780 align:middle line:90%
lambda comes out from here.

01:20:20.780 --> 01:20:26.040 align:middle line:84%
And then complex conjugate of
lambda comes out from there,

01:20:26.040 --> 01:20:27.320 align:middle line:90%
and this is equal to--

01:20:27.320 --> 01:20:32.410 align:middle line:90%


01:20:32.410 --> 01:20:35.550 align:middle line:90%
but this is equal to 1.

01:20:35.550 --> 01:20:43.670 align:middle line:84%
So we see that this is equal
to this, and therefore,

01:20:43.670 --> 01:20:47.030 align:middle line:84%
raising it to the 1/2
power is equal to--

01:20:47.030 --> 01:20:49.910 align:middle line:90%


01:20:49.910 --> 01:20:52.220 align:middle line:84%
this quantity here is
equal to this quantity.

01:20:52.220 --> 01:20:53.990 align:middle line:84%
And we proven what
we wanted to do.

01:20:53.990 --> 01:20:57.490 align:middle line:90%


01:20:57.490 --> 01:20:59.440 align:middle line:90%
OK.

01:20:59.440 --> 01:21:04.220 align:middle line:84%
And so this was a
Cauchy-Schwarz inequality

01:21:04.220 --> 01:21:07.450 align:middle line:84%
and a general pre-Hilbert
space with this quantity

01:21:07.450 --> 01:21:09.340 align:middle line:84%
that I referred
to as a norm but I

01:21:09.340 --> 01:21:11.200 align:middle line:90%
haven't proved it's a norm yet.

01:21:11.200 --> 01:21:14.680 align:middle line:84%
Next time we will use the
Cauchy-Schwarz inequality

01:21:14.680 --> 01:21:19.300 align:middle line:84%
to prove that, in fact, this
thing that I'm masquerading

01:21:19.300 --> 01:21:22.070 align:middle line:84%
around in a norm
notation is, in fact,

01:21:22.070 --> 01:21:25.210 align:middle line:90%
a norm on a pre-Hilbert space.

01:21:25.210 --> 01:21:28.450 align:middle line:90%


01:21:28.450 --> 01:21:34.140 align:middle line:84%
And from there, we'll
introduce Hilbert spaces

01:21:34.140 --> 01:21:39.090 align:middle line:84%
which are those pre-Hilbert
spaces with this norm that

01:21:39.090 --> 01:21:42.400 align:middle line:90%
are actually complete.

01:21:42.400 --> 01:21:46.170 align:middle line:90%
And really, for any kind of--

01:21:46.170 --> 01:21:53.730 align:middle line:84%
so for-- and we'll prove
this at some point,

01:21:53.730 --> 01:21:58.890 align:middle line:84%
there's really only two types
of reasonable Hilbert spaces.

01:21:58.890 --> 01:22:01.630 align:middle line:90%


01:22:01.630 --> 01:22:04.220 align:middle line:84%
And I mean this in
a very strong sense,

01:22:04.220 --> 01:22:10.180 align:middle line:84%
not in a loose sense,
that the first type is

01:22:10.180 --> 01:22:13.150 align:middle line:84%
just finite-dimensional-- so
think of C raised to the n.

01:22:13.150 --> 01:22:17.350 align:middle line:84%
So n tuples of complex numbers
where the inner product

01:22:17.350 --> 01:22:21.650 align:middle line:90%
is definable in a natural way.

01:22:21.650 --> 01:22:28.970 align:middle line:90%
Or a little L2 which is these--

01:22:28.970 --> 01:22:36.400 align:middle line:84%
this set of sequences that
have finite little L2 norm.

01:22:36.400 --> 01:22:39.520 align:middle line:84%
This is basically the only
other type of Hilbert space

01:22:39.520 --> 01:22:43.780 align:middle line:84%
that there is, and I'll
say what I mean by that.

01:22:43.780 --> 01:22:46.590 align:middle line:84%
How it'll work is
we'll basically

01:22:46.590 --> 01:22:50.910 align:middle line:84%
show that every separable
Hilbert space, which

01:22:50.910 --> 01:22:57.330 align:middle line:84%
is what I mean by
reasonable, that it's

01:22:57.330 --> 01:23:02.370 align:middle line:84%
the most reasonable spaces
we work with are separable,

01:23:02.370 --> 01:23:04.770 align:middle line:84%
meaning they have
countable dense subset,

01:23:04.770 --> 01:23:09.420 align:middle line:84%
has a countable orthogonal
basis, which is what--

01:23:09.420 --> 01:23:11.730 align:middle line:84%
Orthonormal basis
I haven't defined.

01:23:11.730 --> 01:23:17.250 align:middle line:84%
It's not a Hamel basis, but
it serves the same purpose,

01:23:17.250 --> 01:23:19.590 align:middle line:84%
meaning you can't
write every element

01:23:19.590 --> 01:23:22.470 align:middle line:84%
as a finite linear combination
of orthonormal basis,

01:23:22.470 --> 01:23:25.230 align:middle line:84%
but you can write it as
an infinite expansion

01:23:25.230 --> 01:23:26.620 align:middle line:90%
in orthonormal basis.

01:23:26.620 --> 01:23:31.600 align:middle line:90%
Think Fourier series.

01:23:31.600 --> 01:23:34.230 align:middle line:84%
And this is what provides
this identification

01:23:34.230 --> 01:23:41.100 align:middle line:84%
of a separable Hilbert space
with either a C to the n

01:23:41.100 --> 01:23:44.670 align:middle line:84%
if this or orthonormal basis
is finite, or little L2

01:23:44.670 --> 01:23:48.120 align:middle line:84%
if this or orthonormal
basis is countably infinite.

01:23:48.120 --> 01:23:52.850 align:middle line:84%
And we'll get to that possibly
by the end of next lecture.

01:23:52.850 --> 01:23:58.000 align:middle line:90%