WEBVTT

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[RUSTLING]

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[CLICKING]

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PROFESSOR: OK, so
we're going to continue

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with our discussion of the
spectrum of an operator,

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a bounded linear operator.

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So let me just recall from last
time the definition that if A--

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and throughout H
is a Hilbert space,

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if A is a bounded
linear operator,

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then the resolvent set of
A is the set of all lambdas

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and complex numbers
such that A minus

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lambda times the identity,
which I write as A minus lambda,

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is bijective, meaning
it's 1 to 1 and onto,

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which implies by the
open mapping theorem,

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that it has a bounded inverse
or is equivalent to it

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having a bounded inverse.

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And the spectrum of
A was the complement

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of the resolvent set within
the set of complex numbers.

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And so the spectrum is supposed
to be a generalization of,

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in finite dimensions, what
were called the eigenvalues.

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And so we just--

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recall we called lambda an
element of the spectrum,

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an eigenvalue if there exists
a u not equal to 0 such

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that A minus lambda
applied to u is 0.

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In other words, A minus
lambda is not injective.

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So the reason for lambda being
in the spectrum is that--

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so for a number to be
called an eigenvalue

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is that this operator,
A minus lambda,

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has non-trivial null space.

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In other words, it
has a non-zero u So

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that Au equals lambda u.

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And we call this
thing an eigenvector.

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And we saw last time
examples of an operator that

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has infinitely many eigenvalues
and eigenvectors and also

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an example of a bounded
linear operator, which

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has no eigenvalues and
eigenvectors unlike in the case

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in finite dimensions, where
the spectrum is exactly

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the set of eigenvalues
of an operator.

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Now, and we also proved
at the end of last time--

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so what we could say
about these two sets

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or what we could say
about the spectrum

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is that it's a closed set.

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And it's contained within
the ball of radius norm A

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in the complex numbers, which
means it's a compact set.

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And what we could say,
by taking complements

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about the resolvent
set, is that it's

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an open set that contains the
exterior to a ball of radius

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norm of A in the
complex numbers.

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And that's about all we can say
about the spectrum in general

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for now.

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But we can say quite a
lot about the spectrum

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of self-adjoint operators.

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And then we can give a
pretty complete picture

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about the spectrum for
compact operators--

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self-adjoint compact operators.

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But let's first look at
self-adjoint operators.

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So at the end of
last time, we proved

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that if I have a
self-adjoint-- and this is not

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related to the spectrum.

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If I have a self-adjoint bounded
linear operator on a Hilbert

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space, then for all u,
Au, u is a real number.

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And we could write the norm
of A as this quantity sup

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u equals 1 of the absolute
value of Au inner product u.

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All right, so now, we
have the following theorem

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about the spectrum for
self-adjoint bounded linear

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operators on a Hilbert space.

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So the first is that the
spectrum is contained

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in the real number line.

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So the spectrum of A is
contained in the real number

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line--

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norm A-- or in this interval,
minus norm A to norm A, which

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I'm viewing as a subset of
the complex numbers, so just

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the line segment
from minus norm A

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to norm A as a subset
of the complex numbers.

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And the second is that
one of these two endpoints

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has to be in the spectrum--
maybe both, but at least one.

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At least one of plus or minus
norm A is in the spectrum of A.

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OK, so to establish
one, we already know--

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since the spectrum
of A is contained

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in those complex numbers
with modulus less than

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or equal to the
norm of A, we just

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need to show that the spectrum
is contained in the real number

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line.

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Then it must be contained
in this interval,

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since it's contained here.

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OK, so we'll show that anything
off the real number line

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lies in the resolvent.

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That's how we'll go about this.

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So we'll show that if lambda
equals s plus it with t

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not equal to 0, then lambda
is in the resolvent set of A.

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Now, suppose lambda
has this form.

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Then A minus lambda is
equal to A minus s plus--

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or minus, sorry, it, which I
can write as A-tilde minus it

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with A-tilde, a bounded linear
operator given by A minus

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s, which is also
equal to the adjoint

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because s is a real number.

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So I should have said
t is not equal to 0

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and s, t, real numbers.

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So A minus lambda I can
write as A-tilde minus it,

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where A-tilde is A minus s,
again, a self-adjoint operator,

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all right?

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So if I can do an
argument for A-tilde

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and show that A-tilde
minus it is bijective,

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then I can conclude A minus
s minus it is bijective.

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Why am I doing this?

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Because then I can just focus
on the one case that s is 0.

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A minus it is
bijective if and only

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if A minus lambda is bijective.

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So we only need to consider-- so
I can just work on this thing.

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But instead of writing
A-tilde over and over again,

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I'll just switch
back to A. So I only

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really need to consider
the case s equals 0.

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So rather than do the
argument for A-tilde minus

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it, I'm just going
to set s equal to 0

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and start doing the
argument for A minus it.

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OK, so since by what we proved,
or the result from last time--

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so let me just set out
what we're going to prove.

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If A is self-adjoint,
then A minus t minus it

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is bijective for all
t not equal to 0.

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So once I've proven this
claim, then I've proven that--

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I've proven my first
part of the theorem.

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OK, now, since Au applied
to u is real, I get that--

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if I take the imaginary
part of A minus

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it applied to u, inner
product u, this is equal to--

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Au, u, taking the imaginary
part of that is just 0.

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So then I get minus
t norm u squared,

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which implies that
since t is non-zero--

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we're assuming t is non-zero--

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A minus it times u
equals 0 if and only

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if u equals 0 because if
this quantity here equals 0,

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then this thing here equals 0.

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And therefore, the norm of u
has to be 0 since t is non-zero.

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So the null space of A minus
it is just the zero vector.

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And therefore, it must--
it's injective, right?

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It is injective.

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It is 1 to 1.

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All right, now, we just want
to show it's bijective--

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or it's surjective.

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OK, so similarly, I can
prove that the adjoint

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of this operator, which is, in
fact, A plus it, is injective.

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And therefore, I get that
the orthogonal complement

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to the range of A minus it--
so I want to show this equals

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H to show it's surjective.

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So the orthogonal
complement of that,

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which is equal to the null
space of the adjoint, which is--

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equals-- so since
this equals 0, I

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conclude that the range of
A minus it closure, which

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is equal to the
range of A minus it

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taking the orthogonal complement
of the orthogonal complement.

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So that was part
of an assignment

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that if I have a subspace of
a Hilbert space and I take--

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or let me say it here-- and I
take the orthogonal complement

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of the orthogonal complement,
I don't get back to subspace.

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I get the closure
of the subspace.

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So this is equal to the
orthogonal complement

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of the zero vector,
which is H. So I'll

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be done showing that A minus
it is surjective if I can show

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that the range is
closed because then this

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will just be the range
of A minus it equals H.

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So we just need to show now
that the range of A minus it

00:14:43.595 --> 00:14:44.095 align:middle line:90%
is closed.

00:14:44.095 --> 00:14:50.570 align:middle line:90%


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So to show it's
closed, we have to show

00:14:52.970 --> 00:14:54.890 align:middle line:84%
that if we take a
sequence of elements

00:14:54.890 --> 00:14:57.470 align:middle line:84%
in here converging to
something, then that limit

00:14:57.470 --> 00:14:58.670 align:middle line:90%
is, in fact, in the set.

00:14:58.670 --> 00:15:08.460 align:middle line:84%
So suppose I have a
sequence of elements un such

00:15:08.460 --> 00:15:15.750 align:middle line:84%
that A minus it applied to un
converges to an element v. So

00:15:15.750 --> 00:15:19.920 align:middle line:84%
my goal is to show that v is
in the range of A minus it.

00:15:19.920 --> 00:15:23.880 align:middle line:90%


00:15:23.880 --> 00:15:28.035 align:middle line:84%
So we want to show
v is in the range.

00:15:28.035 --> 00:15:31.983 align:middle line:90%


00:15:31.983 --> 00:15:33.900 align:middle line:84%
And then we've shown
that the range is closed.

00:15:33.900 --> 00:15:37.155 align:middle line:84%
And we're done with
the first part.

00:15:37.155 --> 00:15:41.140 align:middle line:90%


00:15:41.140 --> 00:15:45.120 align:middle line:84%
So using this
argument here, we're

00:15:45.120 --> 00:15:48.780 align:middle line:84%
going to show that the
un's, which a priori

00:15:48.780 --> 00:15:50.280 align:middle line:84%
we don't know
converge-- all we know

00:15:50.280 --> 00:15:52.980 align:middle line:84%
is that the images
of the un's converge.

00:15:52.980 --> 00:15:55.650 align:middle line:84%
We are going to show that
the un's actually converge.

00:15:55.650 --> 00:15:57.780 align:middle line:84%
And then that will
essentially finish the proof.

00:15:57.780 --> 00:16:01.670 align:middle line:90%


00:16:01.670 --> 00:16:08.280 align:middle line:84%
Then we have that the
absolute value of t u minus um

00:16:08.280 --> 00:16:09.830 align:middle line:90%
norm squared--

00:16:09.830 --> 00:16:12.800 align:middle line:84%
this is, by this calculation
we did over here,

00:16:12.800 --> 00:16:16.490 align:middle line:84%
equal to the absolute
value of the image of--

00:16:16.490 --> 00:16:28.070 align:middle line:84%
I mean, the imaginary part
of A minus it un minus um un

00:16:28.070 --> 00:16:28.951 align:middle line:90%
minus um.

00:16:28.951 --> 00:16:31.897 align:middle line:90%


00:16:31.897 --> 00:16:35.790 align:middle line:90%
Take the value of all of that.

00:16:35.790 --> 00:16:38.870 align:middle line:84%
And now, this is
less than or equal

00:16:38.870 --> 00:16:41.870 align:middle line:84%
to-- so the absolute value
of the imaginary part

00:16:41.870 --> 00:16:45.830 align:middle line:84%
of a complex number is less than
or equal to the absolute value

00:16:45.830 --> 00:16:48.530 align:middle line:84%
of that complex number,
which by Cauchy-Schwarz I

00:16:48.530 --> 00:16:52.610 align:middle line:84%
can say is less than
or equal to A minus it

00:16:52.610 --> 00:16:55.400 align:middle line:90%
applied to un minus um.

00:16:55.400 --> 00:17:07.025 align:middle line:84%
But I'll write it as A minus it
times the norm of un minus um.

00:17:07.025 --> 00:17:11.960 align:middle line:84%
And I started off with
t, which is non-zero,

00:17:11.960 --> 00:17:14.640 align:middle line:84%
times the norm of
un minus um squared.

00:17:14.640 --> 00:17:16.939 align:middle line:90%
So I get that un minus um--

00:17:16.939 --> 00:17:20.869 align:middle line:90%


00:17:20.869 --> 00:17:22.880 align:middle line:84%
that this is less
than or equal to 1

00:17:22.880 --> 00:17:28.250 align:middle line:84%
over the absolute value
of t times the norm

00:17:28.250 --> 00:17:35.600 align:middle line:84%
A minus it applied to un minus
A minus it applied to um norm.

00:17:35.600 --> 00:17:40.830 align:middle line:90%


00:17:40.830 --> 00:17:43.500 align:middle line:90%
Now, this thing on the right--

00:17:43.500 --> 00:17:46.260 align:middle line:90%


00:17:46.260 --> 00:17:49.590 align:middle line:84%
or I should say A
minus it applied to un,

00:17:49.590 --> 00:17:52.110 align:middle line:90%
this is a convergent sequence.

00:17:52.110 --> 00:17:54.480 align:middle line:84%
In particular, it's
a Cauchy sequence.

00:17:54.480 --> 00:17:58.170 align:middle line:84%
So given epsilon, I
can find capital N

00:17:58.170 --> 00:18:01.470 align:middle line:84%
so that the norm of
this right-hand side

00:18:01.470 --> 00:18:05.940 align:middle line:84%
is less than epsilon
times the magnitude of t.

00:18:05.940 --> 00:18:09.060 align:middle line:84%
And therefore, for all capital
N bigger than or equal to--

00:18:09.060 --> 00:18:12.240 align:middle line:84%
or for all little n m bigger
than or equal to that capital

00:18:12.240 --> 00:18:15.630 align:middle line:84%
N, this in norm will
be less than epsilon.

00:18:15.630 --> 00:18:24.660 align:middle line:90%


00:18:24.660 --> 00:18:34.970 align:middle line:84%
Since this is Cauchy
because it's convergent,

00:18:34.970 --> 00:18:43.230 align:middle line:84%
the previous estimate implies
that the sequence un is Cauchy.

00:18:43.230 --> 00:18:45.600 align:middle line:84%
And since we're in a
Hilbert space, which

00:18:45.600 --> 00:18:50.170 align:middle line:84%
means it's complete, we can
find a limit of this un.

00:18:50.170 --> 00:18:57.360 align:middle line:84%
There exists a u in H such
that un converges to u.

00:18:57.360 --> 00:18:58.860 align:middle line:90%
And then we're done now.

00:18:58.860 --> 00:19:07.050 align:middle line:84%
Then since A is a bounded
linear operator, A minus it u--

00:19:07.050 --> 00:19:10.110 align:middle line:84%
or A minus it applied to u,
this is equal to the limit

00:19:10.110 --> 00:19:16.230 align:middle line:84%
as n goes to infinity of
A minus it applied to un.

00:19:16.230 --> 00:19:20.310 align:middle line:84%
But remember, we assumed that
this converges to some element

00:19:20.310 --> 00:19:27.270 align:middle line:84%
v. And therefore, v is equal
to something in the image

00:19:27.270 --> 00:19:28.995 align:middle line:90%
or in the range of A minus it.

00:19:28.995 --> 00:19:31.840 align:middle line:90%


00:19:31.840 --> 00:19:32.815 align:middle line:90%
v is in the range.

00:19:32.815 --> 00:19:38.760 align:middle line:90%


00:19:38.760 --> 00:19:41.980 align:middle line:84%
And thus, the range of
A minus it is closed.

00:19:41.980 --> 00:19:48.630 align:middle line:84%
And by this here, we conclude
that the range of A minus t

00:19:48.630 --> 00:19:51.870 align:middle line:84%
equals H. So A minus
it is bijective.

00:19:51.870 --> 00:20:00.590 align:middle line:90%


00:20:00.590 --> 00:20:03.470 align:middle line:84%
And that concludes the
proof of the first property

00:20:03.470 --> 00:20:04.490 align:middle line:90%
we wanted to do.

00:20:04.490 --> 00:20:13.440 align:middle line:90%


00:20:13.440 --> 00:20:19.680 align:middle line:84%
OK, so for the second
thing we wanted

00:20:19.680 --> 00:20:25.470 align:middle line:84%
to show, we wanted to
show that at least one

00:20:25.470 --> 00:20:37.050 align:middle line:84%
of plus or minus norm of A
is in the spectrum of A. Now,

00:20:37.050 --> 00:20:46.920 align:middle line:84%
since the norm of A is equal
to the sup over norm of u

00:20:46.920 --> 00:20:53.000 align:middle line:84%
equals 1 of the absolute
value of Au, u--

00:20:53.000 --> 00:20:55.040 align:middle line:84%
so a supremum is
always characterized

00:20:55.040 --> 00:21:00.530 align:middle line:84%
by being an upper bound and
also there existing a sequence

00:21:00.530 --> 00:21:02.630 align:middle line:84%
in the set of things
you're taking the supremum

00:21:02.630 --> 00:21:07.400 align:middle line:90%
of converging to that supremum.

00:21:07.400 --> 00:21:12.620 align:middle line:84%
So that implies that there
exists a sequence of unit

00:21:12.620 --> 00:21:22.650 align:middle line:84%
vectors so that Au inner
product u in absolute value

00:21:22.650 --> 00:21:24.810 align:middle line:84%
has to converge
to the norm of a.

00:21:24.810 --> 00:21:29.610 align:middle line:84%
So in particular,
Au applied to u

00:21:29.610 --> 00:21:41.132 align:middle line:84%
has to converge to the norm
of A or minus norm of A

00:21:41.132 --> 00:21:43.133 align:middle line:90%
as n goes to infinity.

00:21:43.133 --> 00:21:44.050 align:middle line:90%
And there's no n here.

00:21:44.050 --> 00:22:01.880 align:middle line:90%


00:22:01.880 --> 00:22:09.790 align:middle line:84%
All right, then what
does this imply?

00:22:09.790 --> 00:22:16.870 align:middle line:84%
Then this implies that, for
at least one of these choices,

00:22:16.870 --> 00:22:35.540 align:middle line:84%
then A plus or minus norm of A
applied to un inner product un

00:22:35.540 --> 00:22:38.970 align:middle line:84%
converges to 0 as
n goes to infinity,

00:22:38.970 --> 00:22:42.590 align:middle line:84%
where here the plus or
minus is chosen depending

00:22:42.590 --> 00:22:46.430 align:middle line:84%
on whether this goes to
plus or minus the norm of A.

00:22:46.430 --> 00:22:50.300 align:middle line:84%
So this sign here would be
the opposite of whichever sign

00:22:50.300 --> 00:22:52.010 align:middle line:90%
this sequence goes to.

00:22:52.010 --> 00:23:00.540 align:middle line:90%


00:23:00.540 --> 00:23:07.020 align:middle line:84%
I now claim that this property
here implies that whichever

00:23:07.020 --> 00:23:13.200 align:middle line:84%
sign we have that for, that this
operator appearing here cannot

00:23:13.200 --> 00:23:13.890 align:middle line:90%
be invertible.

00:23:13.890 --> 00:23:19.300 align:middle line:84%
And therefore, whichever sign
appeared here or the opposite

00:23:19.300 --> 00:23:23.020 align:middle line:84%
sign-- so let me,
in fact, stay--

00:23:23.020 --> 00:23:25.340 align:middle line:84%
so the minus corresponds
to the plus sign.

00:23:25.340 --> 00:23:28.110 align:middle line:84%
The plus sign corresponds
to the minus sign

00:23:28.110 --> 00:23:30.130 align:middle line:90%
if we have one of those.

00:23:30.130 --> 00:23:33.540 align:middle line:84%
So I claim that
this property here

00:23:33.540 --> 00:23:37.800 align:middle line:84%
implies that this operator
is not invertible.

00:23:37.800 --> 00:23:43.150 align:middle line:84%
And therefore, one of
those is in the spectrum.

00:23:43.150 --> 00:23:51.510 align:middle line:84%
So suppose instead that A
minus plus norm of a, whichever

00:23:51.510 --> 00:23:53.520 align:middle line:90%
one appeared, is invertible.

00:23:53.520 --> 00:23:57.110 align:middle line:90%


00:23:57.110 --> 00:24:01.610 align:middle line:84%
So whichever one does
satisfy this is invertible.

00:24:01.610 --> 00:24:04.400 align:middle line:90%


00:24:04.400 --> 00:24:08.930 align:middle line:90%
Then the un's all have norm 1.

00:24:08.930 --> 00:24:12.860 align:middle line:90%
So 1 is equal to the norm of un.

00:24:12.860 --> 00:24:19.130 align:middle line:84%
And I can write this as the
norm of A minus plus norm

00:24:19.130 --> 00:24:25.490 align:middle line:84%
A inverse applied to
A minus plus norm A,

00:24:25.490 --> 00:24:30.155 align:middle line:84%
because that's just the
identity, applied to un.

00:24:30.155 --> 00:24:32.420 align:middle line:84%
And this is less than
or equal to the norm

00:24:32.420 --> 00:24:42.810 align:middle line:84%
of the inverse times the
norm of this quantity.

00:24:42.810 --> 00:24:51.500 align:middle line:90%


00:24:51.500 --> 00:24:54.520 align:middle line:90%
And so this is a fixed number.

00:24:54.520 --> 00:24:56.440 align:middle line:84%
And this thing is
converging to 0.

00:24:56.440 --> 00:24:59.140 align:middle line:84%
So the right-hand side
converges to zero.

00:24:59.140 --> 00:25:01.900 align:middle line:90%
But that's 1, right?

00:25:01.900 --> 00:25:03.550 align:middle line:84%
I have 1 is less
than or equal to 0.

00:25:03.550 --> 00:25:06.310 align:middle line:90%
So that's a contradiction.

00:25:06.310 --> 00:25:13.990 align:middle line:84%
Thus, A minus or plus
the norm of A-- again,

00:25:13.990 --> 00:25:18.070 align:middle line:84%
the minus or plus corresponds to
which sign of the norm of A we

00:25:18.070 --> 00:25:19.585 align:middle line:84%
had that sequence
converging to--

00:25:19.585 --> 00:25:24.230 align:middle line:90%


00:25:24.230 --> 00:25:33.430 align:middle line:84%
is not invertible, which implies
that plus or minus at least one

00:25:33.430 --> 00:25:47.420 align:middle line:84%
of these is in
the spectrum of A.

00:25:47.420 --> 00:25:52.570 align:middle line:84%
OK, now, we can, in fact, do
a little bit better then--

00:25:52.570 --> 00:25:56.582 align:middle line:90%


00:25:56.582 --> 00:25:58.790 align:middle line:84%
based on this argument, we
can do a little bit better

00:25:58.790 --> 00:26:03.170 align:middle line:84%
in bounding the spectrum
of a self-adjoint operator

00:26:03.170 --> 00:26:09.190 align:middle line:84%
than just the bound that we have
coming from the general theory.

00:26:09.190 --> 00:26:13.130 align:middle line:90%


00:26:13.130 --> 00:26:16.240 align:middle line:90%
So what do I mean by that?

00:26:16.240 --> 00:26:24.340 align:middle line:90%


00:26:24.340 --> 00:26:38.830 align:middle line:84%
So if A is a self-adjoint
bounded operator

00:26:38.830 --> 00:26:45.760 align:middle line:84%
and a-minus is equal to the
infimum over all u equals

00:26:45.760 --> 00:27:01.330 align:middle line:84%
1 Au applied to u, a-plus
equals the sup Au applied to u,

00:27:01.330 --> 00:27:09.140 align:middle line:84%
then the spectrum
of A is contained.

00:27:09.140 --> 00:27:13.075 align:middle line:84%
So first off then, a couple
of things, two things--

00:27:13.075 --> 00:27:18.050 align:middle line:90%


00:27:18.050 --> 00:27:24.530 align:middle line:84%
then both of these numbers
are in the spectrum of A.

00:27:24.530 --> 00:27:28.905 align:middle line:84%
And the spectrum is contained
in this line segment.

00:27:28.905 --> 00:27:36.030 align:middle line:90%


00:27:36.030 --> 00:27:41.160 align:middle line:84%
So this is something of a
tighter bound because a-minus

00:27:41.160 --> 00:27:44.400 align:middle line:84%
is always bigger than or equal
to minus the norm of A just

00:27:44.400 --> 00:27:48.015 align:middle line:84%
by this always being bounded
below by the norm of A.

00:27:48.015 --> 00:27:51.180 align:middle line:84%
And a-plus is always bounded
above by the norm of A,

00:27:51.180 --> 00:27:53.400 align:middle line:84%
since this is always bounded
above by the norm of A.

00:27:53.400 --> 00:27:56.950 align:middle line:84%
So the sup will be
bounded above by that.

00:27:56.950 --> 00:28:01.200 align:middle line:84%
So this is a tighter estimate
than just the regular estimate

00:28:01.200 --> 00:28:04.320 align:middle line:84%
that says the spectrum
is contained inside

00:28:04.320 --> 00:28:09.290 align:middle line:84%
of the interval from
minus norm A to norm A.

00:28:09.290 --> 00:28:12.810 align:middle line:84%
And in fact, you get more
information, that not just one

00:28:12.810 --> 00:28:17.520 align:middle line:84%
of the endpoints have to be
in, but both of these endpoints

00:28:17.520 --> 00:28:18.420 align:middle line:90%
are in the spectrum.

00:28:18.420 --> 00:28:25.050 align:middle line:90%


00:28:25.050 --> 00:28:30.840 align:middle line:84%
So the proof of
this is just kind

00:28:30.840 --> 00:28:36.930 align:middle line:84%
of a trick of using
what we've done already.

00:28:36.930 --> 00:28:44.540 align:middle line:90%
So first, note that--

00:28:44.540 --> 00:28:50.010 align:middle line:84%
again, since the absolute
value of Au inner product

00:28:50.010 --> 00:29:02.140 align:middle line:84%
is always less than or
equal to the norm of A,

00:29:02.140 --> 00:29:07.540 align:middle line:84%
for all unit vectors, this
implies that this quantity here

00:29:07.540 --> 00:29:12.500 align:middle line:84%
is always bounded
below by norm of A

00:29:12.500 --> 00:29:19.150 align:middle line:84%
and bounded above by norm of
A. And therefore, the infimum

00:29:19.150 --> 00:29:22.990 align:middle line:84%
of this is always bounded
from-- so this is a lower bound

00:29:22.990 --> 00:29:25.010 align:middle line:90%
for this quantity here.

00:29:25.010 --> 00:29:26.920 align:middle line:84%
So this infimum
is bigger than it,

00:29:26.920 --> 00:29:30.460 align:middle line:84%
since it's the
greatest lower bound.

00:29:30.460 --> 00:29:34.540 align:middle line:84%
And the least upper
bound of these quantities

00:29:34.540 --> 00:29:36.910 align:middle line:84%
is always less than or
equal to the norm of A.

00:29:36.910 --> 00:29:44.280 align:middle line:84%
So these are actual
numbers for one.

00:29:44.280 --> 00:29:57.020 align:middle line:84%
OK, now, by the definition
of a-plus or minus,

00:29:57.020 --> 00:30:04.940 align:middle line:84%
there exists sequences of unit
vectors un-plus or minus such

00:30:04.940 --> 00:30:08.720 align:middle line:84%
that A applied to un-plus
or minus inner product

00:30:08.720 --> 00:30:15.140 align:middle line:84%
un-plus or minus converges
to a-plus or minus.

00:30:15.140 --> 00:30:21.380 align:middle line:84%
Now, by the argument we just
gave with a-plus or minus being

00:30:21.380 --> 00:30:23.750 align:middle line:90%
the norm of A--

00:30:23.750 --> 00:30:32.480 align:middle line:84%
but now, we have
this property, i.e.

00:30:32.480 --> 00:30:38.420 align:middle line:84%
A minus a-plus or minus applied
to un-plus or minus, un-plus

00:30:38.420 --> 00:30:42.650 align:middle line:90%
or minus converges to 0.

00:30:42.650 --> 00:30:46.370 align:middle line:84%
Since I have this property by
the previous argument I gave,

00:30:46.370 --> 00:30:49.700 align:middle line:84%
this implies that both
a-plus and a-minus

00:30:49.700 --> 00:30:53.770 align:middle line:84%
are in the spectrum
of A, since we

00:30:53.770 --> 00:30:57.760 align:middle line:84%
have for each choice of plus
or minus a sequence of unit

00:30:57.760 --> 00:31:00.910 align:middle line:84%
vectors so that this
quantity here goes to 0.

00:31:00.910 --> 00:31:03.160 align:middle line:84%
A minute ago, we could
just assert that there

00:31:03.160 --> 00:31:05.240 align:middle line:90%
was a sequence of unit vectors.

00:31:05.240 --> 00:31:09.070 align:middle line:84%
So for at least one choice of
plus or minus the norm of A,

00:31:09.070 --> 00:31:11.050 align:middle line:90%
we had this thing going to 0.

00:31:11.050 --> 00:31:15.700 align:middle line:84%
But for these two numbers,
because it's the inf

00:31:15.700 --> 00:31:21.000 align:middle line:84%
and because this is the sup,
we can always find unit vectors

00:31:21.000 --> 00:31:23.450 align:middle line:84%
so that this quantity is
converging to the sup, which

00:31:23.450 --> 00:31:25.152 align:middle line:84%
is a-plus; this
quantity is converging

00:31:25.152 --> 00:31:26.360 align:middle line:90%
to the inf, which is a-minus.

00:31:26.360 --> 00:31:29.630 align:middle line:90%


00:31:29.630 --> 00:31:37.640 align:middle line:84%
So by the previous
argument, we get

00:31:37.640 --> 00:31:45.538 align:middle line:84%
that both a-plus or minus are
in the spectrum of A. Again,

00:31:45.538 --> 00:31:46.580 align:middle line:90%
I just want to emphasize.

00:31:46.580 --> 00:31:51.710 align:middle line:84%
Before, we could just say that
one of the norms of A or plus

00:31:51.710 --> 00:31:52.580 align:middle line:90%
or--

00:31:52.580 --> 00:31:55.790 align:middle line:84%
at least one choice of
plus or minus the norm of A

00:31:55.790 --> 00:31:56.780 align:middle line:90%
is in the spectrum.

00:31:56.780 --> 00:32:00.120 align:middle line:84%
Here, we're saying both of these
numbers are in the spectrum.

00:32:00.120 --> 00:32:02.640 align:middle line:84%
So now, what remains is to
show that the spectrum is,

00:32:02.640 --> 00:32:05.662 align:middle line:84%
in fact, contained
in this interval

00:32:05.662 --> 00:32:06.620 align:middle line:90%
from a-minus to a-plus.

00:32:06.620 --> 00:32:13.790 align:middle line:90%


00:32:13.790 --> 00:32:20.200 align:middle line:84%
All right, so let b
be their midpoint.

00:32:20.200 --> 00:32:26.310 align:middle line:90%


00:32:26.310 --> 00:32:36.120 align:middle line:84%
And B equals A minus
b times I. Now,

00:32:36.120 --> 00:32:39.640 align:middle line:84%
B's a real number because
those are two real numbers.

00:32:39.640 --> 00:32:42.360 align:middle line:84%
So capital B is the
difference between A

00:32:42.360 --> 00:32:46.450 align:middle line:84%
and-- is A minus a real
number times the identity.

00:32:46.450 --> 00:32:58.600 align:middle line:84%
So B is self-adjoint and a
bounded linear operator on H.

00:32:58.600 --> 00:33:17.880 align:middle line:84%
So by the previous theorem,
we get that the spectrum of B,

00:33:17.880 --> 00:33:25.445 align:middle line:84%
well, is contained
in the norm of B--

00:33:25.445 --> 00:33:29.730 align:middle line:90%


00:33:29.730 --> 00:33:39.140 align:middle line:84%
so minus norm of B,
norm of B. And it

00:33:39.140 --> 00:33:43.670 align:middle line:84%
shouldn't take much
thought to realize

00:33:43.670 --> 00:33:48.260 align:middle line:84%
that if the spectrum of B, which
is a shift of a by little b,

00:33:48.260 --> 00:33:54.060 align:middle line:84%
is contained in this
interval, then the spec of A

00:33:54.060 --> 00:33:58.020 align:middle line:84%
is contained in minus
norm of B plus little

00:33:58.020 --> 00:34:01.800 align:middle line:90%
b, normal of B plus b.

00:34:01.800 --> 00:34:04.770 align:middle line:90%


00:34:04.770 --> 00:34:09.270 align:middle line:84%
So now, what's left is to
compute the norm B, all right?

00:34:09.270 --> 00:34:17.610 align:middle line:84%
But this is not too difficult.
We have that the norm of B--

00:34:17.610 --> 00:34:26.250 align:middle line:84%
this is equal to the sup of
u equals 1 Bu applied to u.

00:34:26.250 --> 00:34:34.560 align:middle line:84%
And now, I take the sup
over all u equals 1.

00:34:34.560 --> 00:34:37.050 align:middle line:84%
And let me plug in
what A is and B is.

00:34:37.050 --> 00:34:42.840 align:middle line:84%
And this is Au, u
minus a-plus minus--

00:34:42.840 --> 00:34:45.420 align:middle line:90%
or a-plus minus a-minus over 2.

00:34:45.420 --> 00:34:49.690 align:middle line:90%


00:34:49.690 --> 00:34:52.060 align:middle line:90%
Now, here's the picture.

00:34:52.060 --> 00:34:53.290 align:middle line:90%
Here's a-minus.

00:34:53.290 --> 00:34:55.230 align:middle line:90%
Here's a-plus.

00:34:55.230 --> 00:34:58.780 align:middle line:84%
a-plus is the sup over
all of these expressions

00:34:58.780 --> 00:35:01.150 align:middle line:90%
where u has unit length.

00:35:01.150 --> 00:35:03.850 align:middle line:84%
a-minus is the inf over
all these expressions,

00:35:03.850 --> 00:35:05.320 align:middle line:90%
where u has unit length.

00:35:05.320 --> 00:35:09.620 align:middle line:84%
a-plus plus a-minus is the point
right in the middle of them.

00:35:09.620 --> 00:35:12.880 align:middle line:84%
So what's the biggest
this-- or what's

00:35:12.880 --> 00:35:18.840 align:middle line:84%
the supremum of the difference
between these numbers

00:35:18.840 --> 00:35:19.930 align:middle line:90%
and the midpoint?

00:35:19.930 --> 00:35:26.030 align:middle line:84%
Well, it's the distance given
by the distance from a-plus

00:35:26.030 --> 00:35:28.530 align:middle line:84%
to the midpoint, which is equal
to the distance from a-minus

00:35:28.530 --> 00:35:37.080 align:middle line:84%
to the midpoint, which is
a-plus minus a-minus over 2.

00:35:37.080 --> 00:35:43.180 align:middle line:90%


00:35:43.180 --> 00:35:45.820 align:middle line:84%
And since that's the norm
of B, when we plug that

00:35:45.820 --> 00:35:51.330 align:middle line:84%
into what we had
a minute ago, we

00:35:51.330 --> 00:35:56.940 align:middle line:84%
conclude that the spectrum is
contained in a-minus, a-plus.

00:35:56.940 --> 00:36:12.240 align:middle line:90%


00:36:12.240 --> 00:36:16.213 align:middle line:84%
So as a simple corollary
of what we've done,

00:36:16.213 --> 00:36:17.630 align:middle line:84%
we have this nice
little statement

00:36:17.630 --> 00:36:22.220 align:middle line:84%
about when exactly a
self-adjoint bounded linear

00:36:22.220 --> 00:36:24.560 align:middle line:90%
operator is non-negative.

00:36:24.560 --> 00:36:34.080 align:middle line:84%
So let A be a self-adjoint
bounded linear operator

00:36:34.080 --> 00:36:36.360 align:middle line:90%
on a Hilbert space.

00:36:36.360 --> 00:36:46.440 align:middle line:84%
Then for all u,
Au inner product u

00:36:46.440 --> 00:36:53.380 align:middle line:84%
is bigger than or equal to 0 if
and only if the spectrum of A

00:36:53.380 --> 00:37:00.310 align:middle line:84%
is contained in the
non-negative numbers.

00:37:00.310 --> 00:37:08.750 align:middle line:90%


00:37:08.750 --> 00:37:11.692 align:middle line:84%
So I'm not even going
to write out the proof.

00:37:11.692 --> 00:37:13.400 align:middle line:84%
I'm just going to talk
my way through it.

00:37:13.400 --> 00:37:18.540 align:middle line:90%


00:37:18.540 --> 00:37:23.970 align:middle line:84%
So let's suppose that Au inner
product u is non-negative.

00:37:23.970 --> 00:37:28.520 align:middle line:84%
Then this number
a-minus is non-negative.

00:37:28.520 --> 00:37:32.300 align:middle line:84%
And therefore, the spectrum is
contained in a-minus, a-plus,

00:37:32.300 --> 00:37:34.805 align:middle line:84%
which is the subset of the
non-negative real numbers.

00:37:34.805 --> 00:37:37.530 align:middle line:90%


00:37:37.530 --> 00:37:39.710 align:middle line:84%
On the other hand, suppose
that the spectrum of A

00:37:39.710 --> 00:37:42.540 align:middle line:90%
is contained in here.

00:37:42.540 --> 00:37:46.530 align:middle line:84%
Then a-minus, which
is in the spectrum,

00:37:46.530 --> 00:37:50.040 align:middle line:84%
has to be in the set of
non-negative real numbers.

00:37:50.040 --> 00:37:52.110 align:middle line:84%
And therefore, Au
inner product u always

00:37:52.110 --> 00:37:54.060 align:middle line:84%
has to be non-negative,
since a-minus

00:37:54.060 --> 00:37:55.335 align:middle line:90%
is the inf over all of these.

00:37:55.335 --> 00:37:58.470 align:middle line:90%


00:37:58.470 --> 00:38:04.890 align:middle line:84%
So now, we're going to move on
to the spectral theory for not

00:38:04.890 --> 00:38:07.380 align:middle line:84%
just self-adjoint operators,
but self-adjoint operators

00:38:07.380 --> 00:38:08.370 align:middle line:90%
that are also compact.

00:38:08.370 --> 00:38:15.720 align:middle line:90%


00:38:15.720 --> 00:38:18.960 align:middle line:84%
Again, a natural
example is given

00:38:18.960 --> 00:38:24.210 align:middle line:84%
by the inverse of taking
the second derivative along

00:38:24.210 --> 00:38:27.450 align:middle line:84%
with requiring 0 at the
endpoints, this operator I

00:38:27.450 --> 00:38:29.700 align:middle line:90%
gave last time.

00:38:29.700 --> 00:38:32.205 align:middle line:90%
That is a bounded self-adjoint--

00:38:32.205 --> 00:38:35.950 align:middle line:84%
or a compact
self-adjoint operator.

00:38:35.950 --> 00:38:40.600 align:middle line:84%
So all the spectral theory we
developed for that applies.

00:38:40.600 --> 00:38:43.600 align:middle line:84%
And the spectrum for that
operator ends up being 1 over

00:38:43.600 --> 00:38:47.050 align:middle line:84%
the eigenvalues corresponding to
u-double prime equals lambda--

00:38:47.050 --> 00:38:50.830 align:middle line:84%
equals, say, mu times u
with 0 at the endpoint.

00:38:50.830 --> 00:38:53.950 align:middle line:90%


00:38:53.950 --> 00:38:55.600 align:middle line:84%
And you'll see that
in the assignment.

00:38:55.600 --> 00:38:57.500 align:middle line:84%
Or maybe I'll do
it as an example.

00:38:57.500 --> 00:39:12.940 align:middle line:84%
So now, we're moving on to
spectral theory for compact

00:39:12.940 --> 00:39:17.500 align:middle line:84%
self-adjoint operators, which
is one of the most, again,

00:39:17.500 --> 00:39:18.580 align:middle line:90%
complete things--

00:39:18.580 --> 00:39:24.130 align:middle line:84%
or class of operators we
can say the most about when

00:39:24.130 --> 00:39:25.930 align:middle line:90%
it comes to the spectrum.

00:39:25.930 --> 00:39:31.340 align:middle line:84%
And I'll go ahead and
give you a preview

00:39:31.340 --> 00:39:36.650 align:middle line:84%
of what we can say about the
spectrum for these operators,

00:39:36.650 --> 00:39:38.840 align:middle line:84%
that it essentially
consists of nothing

00:39:38.840 --> 00:39:48.350 align:middle line:84%
but eigenvalues with the
possible exception of 0

00:39:48.350 --> 00:39:51.870 align:middle line:84%
being an accumulation
point of the eigenvalues.

00:39:51.870 --> 00:39:54.410 align:middle line:84%
So what we'll prove
is that the spectrum

00:39:54.410 --> 00:39:56.510 align:middle line:84%
of a compact
self-adjoint operator

00:39:56.510 --> 00:40:01.920 align:middle line:84%
consists of the eigenvalues
of this operator

00:40:01.920 --> 00:40:04.485 align:middle line:90%
along with possibly 0.

00:40:04.485 --> 00:40:10.290 align:middle line:90%


00:40:10.290 --> 00:40:16.510 align:middle line:84%
And 0 may or may not
be an eigenvalue.

00:40:16.510 --> 00:40:18.760 align:middle line:84%
If it's not an
eigenvalue, then it's

00:40:18.760 --> 00:40:21.190 align:middle line:90%
the limit of the eigenvalues.

00:40:21.190 --> 00:40:26.020 align:middle line:84%
And in fact, implicit
in that statement

00:40:26.020 --> 00:40:29.380 align:middle line:84%
is that the spectrum
is, in fact, countable

00:40:29.380 --> 00:40:31.940 align:middle line:84%
for a compact
self-adjoint operator.

00:40:31.940 --> 00:40:36.900 align:middle line:90%
So why should we expect that?

00:40:36.900 --> 00:40:39.708 align:middle line:84%
Or why should we expect
such a complete picture?

00:40:39.708 --> 00:40:41.250 align:middle line:84%
In the end, we'll
also prove that you

00:40:41.250 --> 00:40:44.010 align:middle line:84%
can find a basis for
H consisting entirely

00:40:44.010 --> 00:40:50.320 align:middle line:84%
of eigenvectors of the
operator A, which is, again,

00:40:50.320 --> 00:40:56.870 align:middle line:84%
a generalization to infinite
dimensions of what hopefully

00:40:56.870 --> 00:40:58.215 align:middle line:90%
you saw in finite dimensions.

00:40:58.215 --> 00:40:59.840 align:middle line:84%
But if you didn't,
our proof will still

00:40:59.840 --> 00:41:01.220 align:middle line:90%
apply to finite dimensions.

00:41:01.220 --> 00:41:05.840 align:middle line:84%
So why should that then apply to
compact self-adjoint operators

00:41:05.840 --> 00:41:07.520 align:middle line:84%
if you believe it for
finite dimensions?

00:41:07.520 --> 00:41:10.970 align:middle line:84%
Well, it's because, again,
compact self-adjoint operators

00:41:10.970 --> 00:41:15.047 align:middle line:84%
are the norm limit of finite
rank operators, all right?

00:41:15.047 --> 00:41:16.880 align:middle line:84%
And finite rank operators,
again, these just

00:41:16.880 --> 00:41:18.530 align:middle line:84%
correspond to
basically matrices.

00:41:18.530 --> 00:41:22.850 align:middle line:84%
We know how to compute the
eigenvalues of matrices.

00:41:22.850 --> 00:41:24.920 align:middle line:84%
For finite rank
operators, they could

00:41:24.920 --> 00:41:33.200 align:middle line:84%
have a very large null space,
meaning the eigenvalue 0 could

00:41:33.200 --> 00:41:35.330 align:middle line:90%
have a very large eigenspace.

00:41:35.330 --> 00:41:39.560 align:middle line:84%
But that's the point
of why you expect maybe

00:41:39.560 --> 00:41:41.120 align:middle line:84%
things to carry
over to the setting

00:41:41.120 --> 00:41:42.890 align:middle line:84%
of compact
self-adjoint operators

00:41:42.890 --> 00:41:47.430 align:middle line:84%
from what you know
in finite dimensions.

00:41:47.430 --> 00:41:58.765 align:middle line:84%
OK, so this is not so much a
definition as just notation.

00:41:58.765 --> 00:42:04.200 align:middle line:90%


00:42:04.200 --> 00:42:09.320 align:middle line:84%
If A is a bounded
linear operator,

00:42:09.320 --> 00:42:18.630 align:middle line:84%
I will denote E lambda to be the
null space of A minus lambda--

00:42:18.630 --> 00:42:20.940 align:middle line:90%
in other words, the set of--

00:42:20.940 --> 00:42:26.280 align:middle line:84%
or the subspace of eigenvectors
with eigenvalue lambda, which,

00:42:26.280 --> 00:42:34.820 align:middle line:84%
again, is the set of u in H such
that A minus lambda u equals 0.

00:42:34.820 --> 00:42:41.130 align:middle line:90%


00:42:41.130 --> 00:42:52.710 align:middle line:84%
So first off, before we get
to classifying the spectral--

00:42:52.710 --> 00:42:55.140 align:middle line:84%
or the spectrum of a compact
self-adjoint operator

00:42:55.140 --> 00:42:59.400 align:middle line:84%
as basically consisting of
eigenvalues along with 0,

00:42:59.400 --> 00:43:04.530 align:middle line:84%
we'll first give some
kind of general properties

00:43:04.530 --> 00:43:10.930 align:middle line:84%
of eigenvalues in general for a
compact self-adjoint operator.

00:43:10.930 --> 00:43:23.610 align:middle line:84%
So we have the following
theorem that suppose A-star in A

00:43:23.610 --> 00:43:25.740 align:middle line:84%
is a compact
self-adjoint operator.

00:43:25.740 --> 00:43:35.120 align:middle line:90%


00:43:35.120 --> 00:43:38.195 align:middle line:90%
Then a few things--

00:43:38.195 --> 00:43:42.060 align:middle line:90%


00:43:42.060 --> 00:43:51.430 align:middle line:84%
if lambda not equal to
0 is an eigenvalue of A,

00:43:51.430 --> 00:43:57.330 align:middle line:84%
then the dimension of E
lambda, the eigenspace,

00:43:57.330 --> 00:43:59.890 align:middle line:84%
the linear subspace
of all vectors

00:43:59.890 --> 00:44:06.910 align:middle line:84%
that are eigenvectors
of A, this is finite.

00:44:06.910 --> 00:44:10.625 align:middle line:84%
So for a given eigenvalue, the
dimension of the eigenspace

00:44:10.625 --> 00:44:11.125 align:middle line:90%
is finite.

00:44:11.125 --> 00:44:15.770 align:middle line:90%


00:44:15.770 --> 00:44:21.290 align:middle line:84%
The second is that if I take
two different eigenvalues,

00:44:21.290 --> 00:44:24.650 align:middle line:84%
the corresponding
eigenspaces are

00:44:24.650 --> 00:44:26.150 align:middle line:90%
perpendicular to each other.

00:44:26.150 --> 00:44:30.510 align:middle line:90%


00:44:30.510 --> 00:44:32.230 align:middle line:84%
Lambda 1 does not
equal lambda 2.

00:44:32.230 --> 00:44:36.740 align:middle line:90%


00:44:36.740 --> 00:44:46.130 align:middle line:84%
For eigenvalues of
A, then E lambda 1,

00:44:46.130 --> 00:44:56.930 align:middle line:84%
E lambda 2 are orthogonal
or perpendicular.

00:44:56.930 --> 00:45:01.040 align:middle line:84%
Every element in E lambda 1
is orthogonal to every element

00:45:01.040 --> 00:45:02.810 align:middle line:90%
in E lambda 2 and vice versa.

00:45:02.810 --> 00:45:12.190 align:middle line:90%


00:45:12.190 --> 00:45:29.160 align:middle line:84%
And finally, the set of
non-zero eigenvalues of A

00:45:29.160 --> 00:45:36.420 align:middle line:90%
is either finite or countable.

00:45:36.420 --> 00:45:47.090 align:middle line:90%


00:45:47.090 --> 00:45:56.480 align:middle line:84%
If it is countable, i.e. it's
given by a sequence lambda n,

00:45:56.480 --> 00:46:01.330 align:middle line:90%
then these--

00:46:01.330 --> 00:46:04.180 align:middle line:84%
or if it is countably
infinite, I should say--

00:46:04.180 --> 00:46:08.720 align:middle line:90%


00:46:08.720 --> 00:46:11.405 align:middle line:84%
and I should have said
countably infinite here.

00:46:11.405 --> 00:46:17.090 align:middle line:90%


00:46:17.090 --> 00:46:24.050 align:middle line:84%
If it's countably infinite, then
the eigenvalues converge to 0.

00:46:24.050 --> 00:46:29.300 align:middle line:90%


00:46:29.300 --> 00:46:31.700 align:middle line:84%
In particular, this
implies that if I

00:46:31.700 --> 00:46:35.840 align:middle line:84%
have a compact
self-adjoint operator

00:46:35.840 --> 00:46:38.690 align:middle line:84%
with infinitely
many eigenvalues,

00:46:38.690 --> 00:46:44.090 align:middle line:84%
then 0 is in the
spectrum of this operator

00:46:44.090 --> 00:46:48.900 align:middle line:84%
because the spectrum
is a closed set.

00:46:48.900 --> 00:46:51.630 align:middle line:84%
So it's closed
undertaking limits.

00:46:51.630 --> 00:46:54.270 align:middle line:84%
And since, these
are in the spectrum,

00:46:54.270 --> 00:46:55.770 align:middle line:84%
the limit has to
be in the spectrum.

00:46:55.770 --> 00:47:05.330 align:middle line:90%


00:47:05.330 --> 00:47:13.190 align:middle line:90%
All right, so proof of 1--

00:47:13.190 --> 00:47:15.830 align:middle line:84%
suppose I have a
non-zero eigenvalue.

00:47:15.830 --> 00:47:22.580 align:middle line:84%
And towards the
contradiction, E lambda

00:47:22.580 --> 00:47:26.390 align:middle line:90%
is not finite dimensional.

00:47:26.390 --> 00:47:28.220 align:middle line:90%
Then what I can do--

00:47:28.220 --> 00:47:31.760 align:middle line:84%
by the Gram-Schmidt
process, then there

00:47:31.760 --> 00:47:45.270 align:middle line:84%
exists a sequence or a
countable collection un,

00:47:45.270 --> 00:47:54.580 align:middle line:84%
orthonormal elements
in E lambda.

00:47:54.580 --> 00:47:59.790 align:middle line:84%
So every element in the
sequence has unit length.

00:47:59.790 --> 00:48:02.790 align:middle line:84%
And it's orthogonal to any
other element in the sequence.

00:48:02.790 --> 00:48:09.270 align:middle line:90%


00:48:09.270 --> 00:48:23.810 align:middle line:84%
Now, since A is a compact
operator and all of these

00:48:23.810 --> 00:48:31.280 align:middle line:84%
have unit length, it
follows that A applied to un

00:48:31.280 --> 00:48:34.620 align:middle line:84%
is contained-- this is a
sequence in a compact set,

00:48:34.620 --> 00:48:35.120 align:middle line:90%
right?

00:48:35.120 --> 00:48:37.290 align:middle line:84%
So it has a convergent
subsequence--

00:48:37.290 --> 00:48:44.340 align:middle line:90%


00:48:44.340 --> 00:48:45.195 align:middle line:90%
Au nj, j.

00:48:45.195 --> 00:48:56.760 align:middle line:90%


00:48:56.760 --> 00:49:05.260 align:middle line:90%
Then Au nj is Cauchy.

00:49:05.260 --> 00:49:07.840 align:middle line:84%
But let's actually
look at what's

00:49:07.840 --> 00:49:17.240 align:middle line:84%
the difference between
two of these in norm.

00:49:17.240 --> 00:49:20.150 align:middle line:90%
Let's make it squared.

00:49:20.150 --> 00:49:27.470 align:middle line:84%
This is equal to norm of,
because these are eigenvalues,

00:49:27.470 --> 00:49:33.590 align:middle line:84%
lambda un j minus lambda un
k squared, which equals--

00:49:33.590 --> 00:49:39.270 align:middle line:90%


00:49:39.270 --> 00:49:43.178 align:middle line:84%
squared, which equals
2 lambda squared,

00:49:43.178 --> 00:49:45.720 align:middle line:84%
which is a fixed number that's
positive because lambda is not

00:49:45.720 --> 00:49:46.320 align:middle line:90%
equal to 0.

00:49:46.320 --> 00:49:51.360 align:middle line:90%


00:49:51.360 --> 00:49:54.300 align:middle line:90%
Oh, I left off a part of the--

00:49:54.300 --> 00:49:56.110 align:middle line:90%
OK, so what does this imply?

00:49:56.110 --> 00:50:00.390 align:middle line:84%
This implies that the distance
between any-- so this is--

00:50:00.390 --> 00:50:03.222 align:middle line:90%


00:50:03.222 --> 00:50:05.890 align:middle line:84%
if I take any two elements
in this subsequence,

00:50:05.890 --> 00:50:09.100 align:middle line:84%
their distance is a
constant equal to 2 times

00:50:09.100 --> 00:50:10.090 align:middle line:90%
lambda squared.

00:50:10.090 --> 00:50:11.660 align:middle line:84%
And therefore,
this is not Cauchy,

00:50:11.660 --> 00:50:12.760 align:middle line:90%
which is a contradiction.

00:50:12.760 --> 00:50:26.560 align:middle line:90%


00:50:26.560 --> 00:50:29.068 align:middle line:90%
Something I forgot to say--

00:50:29.068 --> 00:50:30.235 align:middle line:90%
restatement of the theorem--

00:50:30.235 --> 00:50:33.450 align:middle line:90%


00:50:33.450 --> 00:50:36.360 align:middle line:84%
forgive me, it's the
end of a long day--

00:50:36.360 --> 00:50:41.250 align:middle line:84%
is that eigenvalues
have to be real

00:50:41.250 --> 00:50:43.290 align:middle line:84%
for self-adjoint
compact operators,

00:50:43.290 --> 00:50:47.010 align:middle line:84%
or really for
self-adjoint operators.

00:50:47.010 --> 00:50:48.510 align:middle line:84%
So I could have
included it earlier.

00:50:48.510 --> 00:50:51.120 align:middle line:90%


00:50:51.120 --> 00:50:53.880 align:middle line:84%
So the eigenvalues of
a self-adjoint operator

00:50:53.880 --> 00:50:54.870 align:middle line:90%
have to be real.

00:50:54.870 --> 00:50:55.485 align:middle line:90%
Why is that?

00:50:55.485 --> 00:51:02.250 align:middle line:90%


00:51:02.250 --> 00:51:12.560 align:middle line:84%
Since if I have
something with norm 1--

00:51:12.560 --> 00:51:16.640 align:middle line:84%
so if lambda is
an eigenvalue, it

00:51:16.640 --> 00:51:19.700 align:middle line:84%
comes with an eigenvector
u with length 1

00:51:19.700 --> 00:51:21.170 align:middle line:90%
so that Au equals lambda u.

00:51:21.170 --> 00:51:23.030 align:middle line:84%
Of course, it just has
to be a non-zero u.

00:51:23.030 --> 00:51:28.190 align:middle line:84%
But I can normalize it by
dividing by its length.

00:51:28.190 --> 00:51:30.780 align:middle line:84%
And therefore, I
get that lambda,

00:51:30.780 --> 00:51:35.930 align:middle line:84%
which is equal to lambda
u inner product u--

00:51:35.930 --> 00:51:41.570 align:middle line:84%
this is norm of u squared,
which is 1 lambda u, u.

00:51:41.570 --> 00:51:47.420 align:middle line:84%
And this is equal to
complex conjugate--

00:51:47.420 --> 00:51:49.160 align:middle line:90%
or let's not do that.

00:51:49.160 --> 00:51:52.840 align:middle line:90%


00:51:52.840 --> 00:51:58.440 align:middle line:84%
This is equal to Au,
u which is equal to--

00:51:58.440 --> 00:52:00.780 align:middle line:84%
I take A and it
becomes A-star u.

00:52:00.780 --> 00:52:04.680 align:middle line:84%
But A-star is equal
to A, So I get u, Au,

00:52:04.680 --> 00:52:06.480 align:middle line:90%
since A is self-adjoint.

00:52:06.480 --> 00:52:09.990 align:middle line:84%
And this is equal
to u, lambda u.

00:52:09.990 --> 00:52:15.540 align:middle line:84%
And remember, inner products
are conjugate linear

00:52:15.540 --> 00:52:16.440 align:middle line:90%
in the second entry.

00:52:16.440 --> 00:52:19.930 align:middle line:84%
So this lambda pops out,
but now complex conjugate.

00:52:19.930 --> 00:52:29.010 align:middle line:84%
So lambda-- so we've shown
that the complex conjugate is

00:52:29.010 --> 00:52:31.958 align:middle line:90%
equal to the original number.

00:52:31.958 --> 00:52:33.375 align:middle line:84%
So lambda has to
be a real number.

00:52:33.375 --> 00:52:36.060 align:middle line:90%


00:52:36.060 --> 00:52:37.470 align:middle line:84%
All, right so that
proves part 1,

00:52:37.470 --> 00:52:40.740 align:middle line:84%
that the eigenvalues of
a self-adjoint operator

00:52:40.740 --> 00:52:42.460 align:middle line:90%
have to be real.

00:52:42.460 --> 00:52:48.030 align:middle line:84%
And the eigenspaces,
which is what I have just

00:52:48.030 --> 00:52:50.760 align:middle line:84%
started calling the E
lambdas, the eigenspace,

00:52:50.760 --> 00:52:53.640 align:middle line:84%
have to be finite dimensional
for a compact self-adjoint

00:52:53.640 --> 00:52:54.300 align:middle line:90%
operator.

00:52:54.300 --> 00:52:59.890 align:middle line:90%


00:52:59.890 --> 00:53:13.170 align:middle line:84%
OK, so now, let's show that
distinct eigenspaces have

00:53:13.170 --> 00:53:14.610 align:middle line:90%
to be orthogonal to each other.

00:53:14.610 --> 00:53:17.460 align:middle line:84%
Suppose lambda 1 does
not equal lambda 2.

00:53:17.460 --> 00:53:23.094 align:middle line:90%
u1 is in E lambda 1.

00:53:23.094 --> 00:53:26.230 align:middle line:90%
u2 is in E lambda 2.

00:53:26.230 --> 00:53:28.810 align:middle line:90%


00:53:28.810 --> 00:53:31.180 align:middle line:84%
So now, what I'd like to show
is that the inner product

00:53:31.180 --> 00:53:34.632 align:middle line:90%
of u1 with u2 is equal to 0.

00:53:34.632 --> 00:53:37.090 align:middle line:84%
And it's going to be a trick,
kind of like I just did here.

00:53:37.090 --> 00:53:46.660 align:middle line:84%
Lambda 1 times u1, u2, this
is equal to lambda 1 u1, u2.

00:53:46.660 --> 00:53:51.670 align:middle line:84%
This is equal to A
applied to u1, u2.

00:53:51.670 --> 00:53:56.740 align:middle line:84%
And now, I move A over to here
because A is self-adjoint.

00:53:56.740 --> 00:54:04.150 align:middle line:90%


00:54:04.150 --> 00:54:06.310 align:middle line:90%
And A applied to u2--

00:54:06.310 --> 00:54:09.070 align:middle line:84%
so u2 is in the
second eigenspace.

00:54:09.070 --> 00:54:13.630 align:middle line:84%
So this is equal
to u1 lambda 2 u2.

00:54:13.630 --> 00:54:17.980 align:middle line:84%
And because lambda 1 and lambda
2 have to be real numbers--

00:54:17.980 --> 00:54:20.530 align:middle line:84%
what we've done from
the first part--

00:54:20.530 --> 00:54:24.880 align:middle line:84%
this lambda 2 comes all the
way out and remains itself,

00:54:24.880 --> 00:54:26.440 align:middle line:84%
no complex conjugate
because it's

00:54:26.440 --> 00:54:29.020 align:middle line:90%
equal to its complex conjugate.

00:54:29.020 --> 00:54:32.920 align:middle line:84%
And so I started off with
lambda 1 times the inner product

00:54:32.920 --> 00:54:33.940 align:middle line:90%
of u1, u2.

00:54:33.940 --> 00:54:38.140 align:middle line:84%
And I've ended up with lambda
2 u1 inner product with u2.

00:54:38.140 --> 00:54:41.140 align:middle line:84%
And therefore, lambda
1 minus lambda 2

00:54:41.140 --> 00:54:44.560 align:middle line:84%
times the inner
product of u1 minus--

00:54:44.560 --> 00:54:47.590 align:middle line:84%
or the inner product
of u1 with u2 equals 0.

00:54:47.590 --> 00:54:50.350 align:middle line:90%


00:54:50.350 --> 00:54:53.800 align:middle line:84%
And lambda 1-- remember,
we're assuming lambda 1

00:54:53.800 --> 00:54:56.180 align:middle line:84%
and lambda 2 are
non-zero-- or not equal.

00:54:56.180 --> 00:54:58.310 align:middle line:84%
So this quantity
here is non-zero.

00:54:58.310 --> 00:55:04.120 align:middle line:90%
So I get that u1, u2 equals 0.

00:55:04.120 --> 00:55:07.460 align:middle line:84%
And that's the-- nope,
that's not the end.

00:55:07.460 --> 00:55:10.030 align:middle line:84%
That's the end of number
2, but not the end

00:55:10.030 --> 00:55:12.745 align:middle line:90%
of the proof of this theorem.

00:55:12.745 --> 00:55:15.237 align:middle line:90%


00:55:15.237 --> 00:55:17.320 align:middle line:84%
All right, so we're going
to prove the last thing,

00:55:17.320 --> 00:55:20.440 align:middle line:84%
that the set of
non-zero eigenvalues

00:55:20.440 --> 00:55:25.360 align:middle line:84%
is either finite or countable,
and that if I arrange them

00:55:25.360 --> 00:55:27.925 align:middle line:84%
in a sequence, then the
sequence converges to 0.

00:55:27.925 --> 00:55:37.360 align:middle line:90%


00:55:37.360 --> 00:55:41.095 align:middle line:84%
OK, so just to have some
notation running around--

00:55:41.095 --> 00:55:43.600 align:middle line:90%


00:55:43.600 --> 00:55:48.770 align:middle line:84%
capital lambda, let
me let this denote

00:55:48.770 --> 00:55:50.630 align:middle line:90%
those non-zero eigenvalues.

00:55:50.630 --> 00:56:10.660 align:middle line:90%


00:56:10.660 --> 00:56:14.230 align:middle line:84%
All right, so what
I'd like to claim--

00:56:14.230 --> 00:56:29.580 align:middle line:84%
or what I'm going to show is
that if lambda n is a sequence

00:56:29.580 --> 00:56:36.230 align:middle line:90%
of distinct elements--

00:56:36.230 --> 00:56:54.520 align:middle line:84%
or distinct eigenvalues,
non-zero eigenvalues of A,

00:56:54.520 --> 00:56:59.380 align:middle line:90%
then these converge to 0.

00:56:59.380 --> 00:57:03.020 align:middle line:90%
So this gives us--

00:57:03.020 --> 00:57:06.620 align:middle line:84%
of course, so the set
of non-zero eigenvalues

00:57:06.620 --> 00:57:08.150 align:middle line:90%
may be finite.

00:57:08.150 --> 00:57:08.840 align:middle line:90%
Fine.

00:57:08.840 --> 00:57:10.550 align:middle line:90%
Suppose it's not, OK?

00:57:10.550 --> 00:57:16.520 align:middle line:84%
Now, we're just in
the setting that A has

00:57:16.520 --> 00:57:20.510 align:middle line:90%
infinitely many eigenvalues.

00:57:20.510 --> 00:57:22.150 align:middle line:84%
If I can prove
this claim, then I

00:57:22.150 --> 00:57:23.620 align:middle line:90%
have proven two things at once.

00:57:23.620 --> 00:57:27.880 align:middle line:84%
I have proven both that the
set of non-zero eigenvalues

00:57:27.880 --> 00:57:31.480 align:middle line:84%
is countably infinite,
assuming it's infinite,

00:57:31.480 --> 00:57:34.630 align:middle line:90%
and they converge to zero.

00:57:34.630 --> 00:57:35.680 align:middle line:90%
So why does this--

00:57:35.680 --> 00:57:50.890 align:middle line:90%


00:57:50.890 --> 00:57:55.590 align:middle line:84%
So first off, if we can show
that this capital lambda is

00:57:55.590 --> 00:57:57.720 align:middle line:84%
countable, then this
claim then implies

00:57:57.720 --> 00:57:59.400 align:middle line:84%
that-- or countably
infinite, then

00:57:59.400 --> 00:58:02.790 align:middle line:84%
this claim tells me that the
eigenvalues converge to 0,

00:58:02.790 --> 00:58:04.660 align:middle line:90%
which is the last thing I want.

00:58:04.660 --> 00:58:08.670 align:middle line:84%
So all I really need to show
is that this is countable

00:58:08.670 --> 00:58:09.880 align:middle line:90%
using this claim.

00:58:09.880 --> 00:58:14.100 align:middle line:84%
Now, why does this show that
capital lambda is countable?

00:58:14.100 --> 00:58:19.140 align:middle line:84%
Since then if I define
lambda sub capital

00:58:19.140 --> 00:58:26.320 align:middle line:84%
N to be the set of
non-zero eigenvalues

00:58:26.320 --> 00:58:29.200 align:middle line:84%
which are, let's say, even
bigger than or equal to 1

00:58:29.200 --> 00:58:34.560 align:middle line:84%
over N, this has to be
a finite set, right?

00:58:34.560 --> 00:58:37.020 align:middle line:84%
If it was infinite,
then I could find

00:58:37.020 --> 00:58:46.090 align:middle line:84%
a sequence of distinct
elements in here and obtain--

00:58:46.090 --> 00:58:49.990 align:middle line:84%
or I should say, then I can
find a subsequence-- or hold on.

00:58:49.990 --> 00:58:51.970 align:middle line:90%
Let me stop for a minute.

00:58:51.970 --> 00:58:59.080 align:middle line:90%


00:58:59.080 --> 00:59:04.080 align:middle line:84%
So my claim is that this
is finite for all N, which

00:59:04.080 --> 00:59:06.585 align:middle line:84%
implies that lambda,
which is the union of--

00:59:06.585 --> 00:59:11.760 align:middle line:90%


00:59:11.760 --> 00:59:14.820 align:middle line:90%
is countable.

00:59:14.820 --> 00:59:21.060 align:middle line:84%
OK, so assuming this claim or
assuming what I wrote here,

00:59:21.060 --> 00:59:24.240 align:middle line:84%
that this is finite for all N,
this implies this is countable,

00:59:24.240 --> 00:59:25.060 align:middle line:90%
that's clear.

00:59:25.060 --> 00:59:27.930 align:middle line:84%
So why do I get this
as finite, this set

00:59:27.930 --> 00:59:30.790 align:middle line:90%
is finite assuming this claim?

00:59:30.790 --> 00:59:34.200 align:middle line:84%
Well, if this set
is infinite, then I

00:59:34.200 --> 00:59:37.890 align:middle line:84%
can pick out a sequence of
distinct elements in lambda sub

00:59:37.890 --> 00:59:40.590 align:middle line:90%
N that converges.

00:59:40.590 --> 00:59:42.630 align:middle line:84%
I could just take any
sequence, and then

00:59:42.630 --> 00:59:45.630 align:middle line:84%
take a convergent subsequence
because that sequence has

00:59:45.630 --> 00:59:50.820 align:middle line:84%
to be bounded between 1
over N and the norm of A.

00:59:50.820 --> 00:59:53.340 align:middle line:84%
But since they're all bigger
than or equal to 1 over N,

00:59:53.340 --> 00:59:56.730 align:middle line:84%
that sequence has to converge
to something that's non-zero.

00:59:56.730 --> 00:59:58.373 align:middle line:84%
But that would
contradict the claim--

00:59:58.373 --> 00:59:59.790 align:middle line:84%
again, assuming
the claim is true.

00:59:59.790 --> 01:00:01.470 align:middle line:84%
We haven't proved
it yet, all right?

01:00:01.470 --> 01:00:04.920 align:middle line:84%
So again, from this
claim, we can then

01:00:04.920 --> 01:00:10.200 align:middle line:84%
conclude that each of these
sets is finite for all N.

01:00:10.200 --> 01:00:13.530 align:middle line:84%
And therefore, the set
of non-zero eigenvalues

01:00:13.530 --> 01:00:16.770 align:middle line:90%
is countable.

01:00:16.770 --> 01:00:19.350 align:middle line:84%
And if it's countably infinite,
then, again, from this claim,

01:00:19.350 --> 01:00:23.310 align:middle line:84%
we conclude that the eigenvalues
must converge to 0 when

01:00:23.310 --> 01:00:25.990 align:middle line:90%
I line them up in a sequence.

01:00:25.990 --> 01:00:28.905 align:middle line:84%
So the whole proof is reduced
to just proving this claim.

01:00:28.905 --> 01:00:37.990 align:middle line:90%


01:00:37.990 --> 01:00:56.670 align:middle line:84%
OK, so to prove the claim, let
un be associated eigenvectors.

01:00:56.670 --> 01:01:11.260 align:middle line:90%


01:01:11.260 --> 01:01:15.070 align:middle line:90%
So these have unit lengths.

01:01:15.070 --> 01:01:21.670 align:middle line:84%
And for all n, A un
equals lambda n un, right?

01:01:21.670 --> 01:01:22.700 align:middle line:90%
We have eigenvalues.

01:01:22.700 --> 01:01:25.360 align:middle line:84%
So we can find eigenvectors
with unit length.

01:01:25.360 --> 01:01:31.440 align:middle line:90%


01:01:31.440 --> 01:01:40.850 align:middle line:84%
Now, then lambda n,
which is equal to--

01:01:40.850 --> 01:01:42.530 align:middle line:84%
or the absolute
value of lambda n

01:01:42.530 --> 01:01:46.460 align:middle line:84%
is equal to the absolute
value of lambda n--

01:01:46.460 --> 01:01:49.670 align:middle line:84%
or the norm of
lambda n applied to--

01:01:49.670 --> 01:01:54.710 align:middle line:84%
or times un, which is equal to
the norm of A applied to un.

01:01:54.710 --> 01:01:57.380 align:middle line:90%


01:01:57.380 --> 01:02:00.050 align:middle line:84%
So what I'm going
to show is that A

01:02:00.050 --> 01:02:02.210 align:middle line:90%
applied to un converges to 0.

01:02:02.210 --> 01:02:07.160 align:middle line:84%
So if you like, this is the
final claim that I need to.

01:02:07.160 --> 01:02:08.780 align:middle line:90%
Prove so this is claim 1.

01:02:08.780 --> 01:02:16.020 align:middle line:90%


01:02:16.020 --> 01:02:19.530 align:middle line:84%
Claim 1 will follow from claim
2 in this little computation

01:02:19.530 --> 01:02:25.800 align:middle line:84%
right here, where claim
2 is that the norm of A

01:02:25.800 --> 01:02:29.910 align:middle line:84%
applied to un-- again, un's are
eigenvectors with unit length

01:02:29.910 --> 01:02:32.040 align:middle line:84%
corresponding to the
lambda n's converge to 0.

01:02:32.040 --> 01:02:40.010 align:middle line:90%


01:02:40.010 --> 01:02:44.660 align:middle line:84%
So the fact that A applied to
these unit vectors converges

01:02:44.660 --> 01:02:51.070 align:middle line:84%
to 0 is not just
specific to eigenvectors

01:02:51.070 --> 01:02:53.050 align:middle line:90%
of distinct eigenvalues.

01:02:53.050 --> 01:02:56.980 align:middle line:84%
It's just a property of the
compactness of A and the fact

01:02:56.980 --> 01:03:00.250 align:middle line:84%
that the un's are in
orthonormal sequence.

01:03:00.250 --> 01:03:01.510 align:middle line:90%
They're all unit length.

01:03:01.510 --> 01:03:03.790 align:middle line:84%
And any one element
in the sequence

01:03:03.790 --> 01:03:07.750 align:middle line:84%
is orthogonal to a different
element in the sequence.

01:03:07.750 --> 01:03:08.890 align:middle line:90%
So suppose not.

01:03:08.890 --> 01:03:10.330 align:middle line:90%
Suppose claim 2 does not hold.

01:03:10.330 --> 01:03:16.160 align:middle line:90%


01:03:16.160 --> 01:03:21.260 align:middle line:84%
Then just negating the
definition of convergence,

01:03:21.260 --> 01:03:23.060 align:middle line:84%
there exists an
epsilon positive.

01:03:23.060 --> 01:03:27.020 align:middle line:90%


01:03:27.020 --> 01:03:45.500 align:middle line:84%
And we can find a subsequence
A unj such that for all j,

01:03:45.500 --> 01:03:49.940 align:middle line:84%
length of A unj is bigger
than or equal to epsilon 0.

01:03:49.940 --> 01:03:53.720 align:middle line:84%
If you look at the
definition of--

01:03:53.720 --> 01:03:55.910 align:middle line:84%
or the definition of
convergence to 0 and then

01:03:55.910 --> 01:04:00.050 align:middle line:84%
negate that, you can conclude
that you can find a subsequence

01:04:00.050 --> 01:04:01.070 align:middle line:90%
so that I have this.

01:04:01.070 --> 01:04:03.800 align:middle line:84%
So there is some bad epsilon
0 so that I have that.

01:04:03.800 --> 01:04:07.530 align:middle line:90%


01:04:07.530 --> 01:04:16.570 align:middle line:84%
All right, since A is
a compact operator,

01:04:16.570 --> 01:04:19.920 align:middle line:84%
there exists a
further subsequence.

01:04:19.920 --> 01:04:26.360 align:middle line:90%


01:04:26.360 --> 01:04:31.250 align:middle line:84%
And let me call it e sub k,
which is un sub j sub k--

01:04:31.250 --> 01:04:37.330 align:middle line:90%


01:04:37.330 --> 01:04:41.030 align:middle line:90%
unj-- such that--

01:04:41.030 --> 01:04:45.760 align:middle line:84%
so remember, A applied
to un sub j-- so un sub

01:04:45.760 --> 01:04:47.290 align:middle line:90%
j is a unit length vector.

01:04:47.290 --> 01:04:50.620 align:middle line:84%
And therefore, A applied to that
is contained in a compact set,

01:04:50.620 --> 01:04:52.490 align:middle line:84%
assuming A is a
compact operator.

01:04:52.490 --> 01:04:55.780 align:middle line:84%
So this must have a
convergent subsequence such

01:04:55.780 --> 01:05:09.000 align:middle line:84%
that A applied to
ek converges in H.

01:05:09.000 --> 01:05:16.800 align:middle line:84%
And note Aek, since this is just
a subsequence of this sequence,

01:05:16.800 --> 01:05:20.160 align:middle line:84%
is bigger than or equal
to epsilon 0 for all k.

01:05:20.160 --> 01:05:23.440 align:middle line:90%


01:05:23.440 --> 01:05:26.620 align:middle line:84%
Now, since the ek's
are a subsequence

01:05:26.620 --> 01:05:31.240 align:middle line:84%
of an orthonormal sequence, it's
still an orthonormal sequence.

01:05:31.240 --> 01:05:41.220 align:middle line:84%
So note, for all k not equal
to l inner product ek el,

01:05:41.220 --> 01:05:50.640 align:middle line:90%
which is unk unl equals 0.

01:05:50.640 --> 01:05:52.600 align:middle line:90%
And what I'm using here--

01:05:52.600 --> 01:05:54.720 align:middle line:84%
so of course, these
are all unit vectors.

01:05:54.720 --> 01:05:56.190 align:middle line:90%
Why are they orthogonal?

01:05:56.190 --> 01:06:00.300 align:middle line:84%
It's because they correspond
to distinct eigenvalues,

01:06:00.300 --> 01:06:02.340 align:middle line:90%
distinct non-zero eigenvalues.

01:06:02.340 --> 01:06:05.670 align:middle line:84%
And we proved that--
that was number 2, that--

01:06:05.670 --> 01:06:07.940 align:middle line:90%
was it number 2?

01:06:07.940 --> 01:06:12.200 align:middle line:84%
Yeah, that eigenvectors
for distinct eigenvalues

01:06:12.200 --> 01:06:15.760 align:middle line:90%
are orthogonal to each other.

01:06:15.760 --> 01:06:19.240 align:middle line:84%
So assuming the
negation of the claim 2,

01:06:19.240 --> 01:06:20.740 align:middle line:84%
which would prove
claim 1 and finish

01:06:20.740 --> 01:06:23.080 align:middle line:84%
the proof of this
whole theorem, I

01:06:23.080 --> 01:06:28.150 align:middle line:84%
conclude that there exists
a sequence of eigenvectors,

01:06:28.150 --> 01:06:34.770 align:middle line:84%
orthonormal eigenvectors of A
So that Aek is always bounded

01:06:34.770 --> 01:06:36.390 align:middle line:90%
below in norm by epsilon 0.

01:06:36.390 --> 01:06:43.980 align:middle line:90%


01:06:43.980 --> 01:06:46.780 align:middle line:90%
And this sequence converges.

01:06:46.780 --> 01:06:56.940 align:middle line:84%
So let f be the limit as
k goes to infinity of Aek.

01:06:56.940 --> 01:07:02.430 align:middle line:84%
Then norm of f, by
continuity of the norm,

01:07:02.430 --> 01:07:05.490 align:middle line:84%
is equal to the limit of
the norms of the ek's.

01:07:05.490 --> 01:07:08.010 align:middle line:90%
And all of these are above--

01:07:08.010 --> 01:07:11.310 align:middle line:84%
bigger than or
equal to epsilon 0.

01:07:11.310 --> 01:07:13.680 align:middle line:90%
So f is non-zero, right?

01:07:13.680 --> 01:07:22.482 align:middle line:90%


01:07:22.482 --> 01:07:24.065 align:middle line:84%
In fact, we can say
a little bit more.

01:07:24.065 --> 01:07:27.620 align:middle line:90%


01:07:27.620 --> 01:07:30.890 align:middle line:90%
Then in fact-- let's see.

01:07:30.890 --> 01:07:34.170 align:middle line:90%


01:07:34.170 --> 01:07:37.620 align:middle line:84%
So this is kind of useless
information I skipped.

01:07:37.620 --> 01:07:40.418 align:middle line:90%


01:07:40.418 --> 01:07:41.960 align:middle line:84%
I didn't write down
what I wanted to.

01:07:41.960 --> 01:07:46.280 align:middle line:84%
But then-- well no,
I still need that.

01:07:46.280 --> 01:07:49.530 align:middle line:90%
No, let me not get rid of that.

01:07:49.530 --> 01:07:50.940 align:middle line:90%
So that should still be there.

01:07:50.940 --> 01:07:53.630 align:middle line:84%
So the norm of f is bigger
than or equal to epsilon 0.

01:07:53.630 --> 01:07:56.360 align:middle line:84%
So norm of f squared
is bigger than or equal

01:07:56.360 --> 01:07:57.575 align:middle line:90%
to epsilon 0 squared.

01:07:57.575 --> 01:08:01.960 align:middle line:90%


01:08:01.960 --> 01:08:04.290 align:middle line:90%
So f inner product f--

01:08:04.290 --> 01:08:10.140 align:middle line:84%
and by continuity of the inner
product, that's equal to--

01:08:10.140 --> 01:08:14.940 align:middle line:84%
since the Aek's converts
to f, I will get f here.

01:08:14.940 --> 01:08:20.399 align:middle line:84%
And using the fact
that A is self-adjoint,

01:08:20.399 --> 01:08:22.124 align:middle line:90%
this is equal to ek, Af.

01:08:22.124 --> 01:08:27.830 align:middle line:90%


01:08:27.830 --> 01:08:39.310 align:middle line:84%
So I have that this limit
here is non-negative.

01:08:39.310 --> 01:08:40.540 align:middle line:90%
I mean, it's a real number.

01:08:40.540 --> 01:08:51.520 align:middle line:84%
And it's bigger than or
equal to epsilon 0 squared.

01:08:51.520 --> 01:08:53.310 align:middle line:90%
Now, here's the problem.

01:08:53.310 --> 01:08:57.090 align:middle line:84%
I have here a sequence of
orthonormal vectors, right?

01:08:57.090 --> 01:08:59.609 align:middle line:84%
And I know that the sum of
squares of these Fourier

01:08:59.609 --> 01:09:02.160 align:middle line:84%
coefficients, which are
Fourier coefficients for A

01:09:02.160 --> 01:09:05.160 align:middle line:90%
applied to f, are--

01:09:05.160 --> 01:09:06.840 align:middle line:90%
the sum of squares is finite.

01:09:06.840 --> 01:09:09.090 align:middle line:84%
And therefore, this
has to go to 0.

01:09:09.090 --> 01:09:12.580 align:middle line:84%
And that's the contradiction
to the epsilon 0 squared.

01:09:12.580 --> 01:09:19.920 align:middle line:84%
So by Bessel,
Bessel's inequality,

01:09:19.920 --> 01:09:27.450 align:middle line:84%
we get that sum over
k norm ek, Af squared,

01:09:27.450 --> 01:09:31.529 align:middle line:84%
this is less than or equal to
the norm of Af squared, which

01:09:31.529 --> 01:09:34.010 align:middle line:90%
is finite.

01:09:34.010 --> 01:09:37.970 align:middle line:84%
And since this is a
convergent series,

01:09:37.970 --> 01:09:40.460 align:middle line:84%
the individual terms
have to converge to 0.

01:09:40.460 --> 01:09:44.220 align:middle line:90%


01:09:44.220 --> 01:09:50.479 align:middle line:90%
And therefore, this equals 0.

01:09:50.479 --> 01:09:56.361 align:middle line:84%
But this and this
are a contradiction.

01:09:56.361 --> 01:10:04.550 align:middle line:90%


01:10:04.550 --> 01:10:16.780 align:middle line:84%
OK, so that finishes the
proof of this theorem

01:10:16.780 --> 01:10:22.330 align:middle line:84%
about the eigenvalues
and eigenspaces

01:10:22.330 --> 01:10:24.280 align:middle line:84%
for a compact
self-adjoint operator.

01:10:24.280 --> 01:10:38.910 align:middle line:90%


01:10:38.910 --> 01:10:43.960 align:middle line:84%
All right, so I think
we'll stop there.

01:10:43.960 --> 01:10:51.000 align:middle line:90%