WEBVTT

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[SQUEAKING]

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[RUSTLING]

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[CLICKING]

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CASEY RODRIGUEZ: OK, so let's
continue with our discussion

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of Hilbert spaces.

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And so last time, we finished
with Riesz representation

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theorem, the only representation
theory I remember,

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Riesz representation
theorem, which

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states that if you have
a Hilbert space, then

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for all f in the dual space--

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which remember, this is a
set of bounded linear maps

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from H to complex numbers--

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there exists a unique
v in H such that f of u

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is equal to u inner product
v for all v, for all u and H.

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So every continuous linear
functional on a Hilbert space

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can be realized as an inner
product with a fixed vector.

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So using this, we can
revisit the subject

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which you touched upon in
the assignment of adjoints.

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So let me just state
this as a theorem.

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Let H be a Hilbert space
and A going from H to H

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be a bounded linear operator.

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The conclusion is
then, there exists

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a unique bounded linear
operator A star from H

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to H, which we call
the adjoint of A such

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that A star satisfies
the following property--

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for all u, v in H,
A u inner product

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v is equal to u inner
product A star v.

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And moreover, the operator
norm of the adjoint

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equals the operator norm of A.

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So again, the same way we
proved uniqueness for the Riesz

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representation
theorem, you can prove

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that such a linear
operator satisfying

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this identity for all u
and v has to be unique.

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So I'll just state
here that uniqueness

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of such an operator
A star follows

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from the identity it satisfies,
just like the vector v, which

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spits out f of u when you
take the inner product with u

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with it.

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Just like that vector
is unique regardless

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of how you chose to define it--

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I mean, how you created it
based on that identity--

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the same thing holds
for the adjoint.

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So it's just the same
argument is what I mean.

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So how do we define
this operator?

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Well, we basically define
it by this relation.

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So let v be in H.
Define a map f sub v

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from H to C via f sub v of u
is equal to A u inner product

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with v.

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Now, this is clearly
a linear map.

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Maybe I shouldn't check
this, maybe I should,

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but let's check it anyways.

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If I take f of v of lambda
1 times u1 plus lambda 2 u2,

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this is equal to A times
lambda 1 u1 plus lambda 2 u2 v.

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And now, we use the fact
that A is a linear operator

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so that it acts on the linear
combination by linearity.

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So then I get lambda
1 A u1 plus lambda 2

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A applied to u2 inner product
v. And because the inner product

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is linear in the first entry--

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it's conjugate linear
in the second entry,

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but it's linear in
the first entry--

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this is equal to lambda 1 times
A u v plus lambda 2 A u2 v,

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and which is lambda 1 f v of
u1 plus lambda 2 f v of u2.

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So this thing is a linear map.

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I claim it's also
continuous, i.e.,

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it's an element of the dual.

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And we just check.

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If the norm of u
equals 1, then if I

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take the absolute value
of f sub v applied to u,

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this is, by definition, A u v,
which is less than or equal to

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by the Cauchy-Schwarz
inequality,

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the norm of A u times the
norm of v. And the norm of A u

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is less than or equal
to the norm of A,

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since is a bounded linear
operator, times the norm of v.

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So this holds for all
u and norm u equals 1.

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And therefore, norm
of this operator

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is less than or equal to
norm of A times norm of v.

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So that proves that
it's an element.

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So thus, f sub v is an
element of the dual.

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And now we use the Riesz
representation theorem.

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So by the Riesz
representation theorem,

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there exists a unique element,
which we denote A star v,

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in H such that for all u in H,
f v of u equals u inner product

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with A star v. I.e.,
for all u in H A u v--

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because that's the definition
of this guy on the left--

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is equal to u A star v.

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So this just defines, for each
v, an element A star v in H.

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So now let's prove that
this map v to A star v

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is a bounded linear operator.

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That then defines the adjoint.

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So first, we claim v,
which maps to A star v--

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the element that
satisfies this identity--

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is linear.

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So let lambda 1, let v1 v2
be in H, lambda 1, lambda 2

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be complex numbers.

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Then for all u in
H, we have what?

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If I take-- let's see,
how did I spell this out--

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u inner product with the element
A star lambda 1 v1 plus lambda

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2 v2--

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so remember, this is the element
or this is the element such

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that this inner
product is defined by--

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this is equal to A
u plus inner product

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with lambda 1 v1
plus lambda 2 v2.

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And this is equal to--

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so first off, the inner
product is conjugate linear

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in the second entry.

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So this is equal to
lambda 1 complex conjugate

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A u v1 plus lambda 2
complex conjugate A u v2.

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Now, how A star--

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how this symbol, if
you like-- is defined

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is that it's equal
to this quantity

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here is equal to lambda
1 times A u A star v1

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plus lambda 2 bar u A star v2.

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And pulling the complex
numbers back in,

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this is equal to u
lambda 1 A star v1

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plus lambda 2 A star v2.

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Now, this holds for
all u in H, i.e.,

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the inner product of u with this
minus this is 0 for all u in H.

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And the only thing
orthogonal to everything in H

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is the zero vector.

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So we conclude that this
element is equal to--

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so this element corresponding
to this linear combination

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is a linear combination
of these elements.

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Thus, the map v that's
mapped to A star v is linear.

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And so we denote this
map now simply by A star.

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It acts on a vector v by
operating by A star v,

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by multiplying by A star.

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So now, A star is
a linear operator.

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When I write A star here, I mean
the map that takes v to A star

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v. So now I want to check
that this linear operator is

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a bounded linear operator.

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I need to check that
it's continuous.

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And in the process, we'll end up
showing that the norm of A star

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equals the norm of A.

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Now, suppose norm of v equals 1.

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So I want to bound
A star applied

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to v. So if A star v equals
0, then clearly, A star

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v is less than or equal to the
norm of A. This, in the end,

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is what I will show.

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But I'm kind of dealing
with the stupid case, which

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is when this thing on
the left-hand side is 0.

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So suppose A star v is non-zero.

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Then, if I take the norm
of A star v squared,

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this is equal to A star
v inner product A star

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v. Now, by the definition
of the inner product,

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this is equal to A times A
star v, v, taking this A star

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and moving it over here.

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And by Cauchy-Schwarz-- well,
first off, all of these numbers

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are real so it makes sense
to actually write less than

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or equal to.

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But by Cauchy-Schwarz, this
is equal to, or less than

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or equal to, A times A
star v norm times norm

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of v, which equals 1.

00:16:24.550 --> 00:16:29.190 align:middle line:90%


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Now, this equals 1.

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And the norm of A
applied to A star v,

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that's bounded by
the norm of A times

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the norm of the input, which
is A star v. And therefore--

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so we started off with A
star v squared less than

00:16:52.990 --> 00:16:56.800 align:middle line:84%
or equal to the norm of A times
the norm of A star v. This

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is non-zero.

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So I can divide
by it and conclude

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that A star v norm of that
is less than or equal to norm

00:17:11.950 --> 00:17:16.119 align:middle line:84%
of A. Now remember,
the norm of an operator

00:17:16.119 --> 00:17:19.390 align:middle line:84%
or a linear operator
is the sup of this

00:17:19.390 --> 00:17:22.839 align:middle line:90%
for all v which have linked 1.

00:17:22.839 --> 00:17:28.540 align:middle line:84%
And since this is bounded
above by the norm of A,

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that implies that norm
of A star is less than

00:17:33.310 --> 00:17:38.680 align:middle line:90%
or equal to the norm of A.

00:17:38.680 --> 00:17:44.020 align:middle line:84%
So we've shown that basically
all of this theorem,

00:17:44.020 --> 00:17:47.890 align:middle line:84%
with the exception of
equality of the norms.

00:17:47.890 --> 00:17:50.830 align:middle line:84%
So every bounded
linear operator has

00:17:50.830 --> 00:17:55.660 align:middle line:84%
an adjoint which is a bounded
linear operator and satisfies--

00:17:55.660 --> 00:17:57.610 align:middle line:84%
and it's a unique
linear operator

00:17:57.610 --> 00:18:02.770 align:middle line:84%
satisfying that identity
up there for A star.

00:18:02.770 --> 00:18:08.070 align:middle line:90%


00:18:08.070 --> 00:18:20.020 align:middle line:84%
Now, note that for
all u, v, and H,

00:18:20.020 --> 00:18:24.790 align:middle line:84%
if I look at A star
u inner product v,

00:18:24.790 --> 00:18:31.120 align:middle line:84%
this is equal to the complex
conjugate of v inner product

00:18:31.120 --> 00:18:40.780 align:middle line:84%
A star u, which is equal to,
by the definition of A star,

00:18:40.780 --> 00:18:44.080 align:middle line:90%
moves over to A v u.

00:18:44.080 --> 00:18:46.570 align:middle line:84%
And again, applying
the complex conjugate

00:18:46.570 --> 00:18:49.310 align:middle line:84%
switches the order
of the entries.

00:18:49.310 --> 00:18:52.600 align:middle line:90%
So this is equal to u A v.

00:18:52.600 --> 00:18:54.550 align:middle line:90%
So what have we shown?

00:18:54.550 --> 00:18:59.350 align:middle line:84%
We've shown that the
adjoint of the adjoint--

00:18:59.350 --> 00:19:07.540 align:middle line:84%
that is equal to A. So
we've shown that A star u

00:19:07.540 --> 00:19:14.800 align:middle line:84%
v is equal to u
times A v. And recall

00:19:14.800 --> 00:19:21.670 align:middle line:84%
this is supposed to be equal to
u A star A star, so the adjoint

00:19:21.670 --> 00:19:23.950 align:middle line:90%
of the adjoint.

00:19:23.950 --> 00:19:25.990 align:middle line:84%
And we've shown that
this quantity is

00:19:25.990 --> 00:19:30.670 align:middle line:84%
equal to this quantity
for all u and v.

00:19:30.670 --> 00:19:37.090 align:middle line:84%
And therefore, the
adjoint of the adjoint

00:19:37.090 --> 00:19:38.650 align:middle line:90%
is equal to the operator again.

00:19:38.650 --> 00:19:43.420 align:middle line:90%


00:19:43.420 --> 00:19:50.870 align:middle line:84%
Thus, by what we've
done previously--

00:19:50.870 --> 00:19:52.490 align:middle line:84%
the previous argument,
if you like--

00:19:52.490 --> 00:19:58.910 align:middle line:84%
applied now where A is replaced
by A star, the norm of A,

00:19:58.910 --> 00:20:04.100 align:middle line:84%
which is equal to
the norm of A--

00:20:04.100 --> 00:20:07.520 align:middle line:84%
the adjoint of the adjoint
because this operator

00:20:07.520 --> 00:20:09.230 align:middle line:90%
is equal to A--

00:20:09.230 --> 00:20:11.900 align:middle line:84%
by what we've done, we've shown
that the norm of the adjoint

00:20:11.900 --> 00:20:14.000 align:middle line:84%
is always less than or equal
to the norm of the thing you're

00:20:14.000 --> 00:20:15.050 align:middle line:90%
taking the adjoint of.

00:20:15.050 --> 00:20:26.010 align:middle line:84%
So this is less than or equal to
norm of A. And so we have this.

00:20:26.010 --> 00:20:34.970 align:middle line:84%
And we have this, which
implies norm of the adjoint

00:20:34.970 --> 00:20:40.650 align:middle line:84%
is equal to the norm
of the operator.

00:20:40.650 --> 00:20:46.810 align:middle line:90%


00:20:46.810 --> 00:20:53.750 align:middle line:84%
So I mean, what is this
creature in practice?

00:20:53.750 --> 00:21:00.170 align:middle line:84%
So let's take maybe a
second simplest example.

00:21:00.170 --> 00:21:06.980 align:middle line:84%
The simplest example would be
if you're on C n and R n-- well,

00:21:06.980 --> 00:21:09.840 align:middle line:90%
so let's talk about that.

00:21:09.840 --> 00:21:11.240 align:middle line:90%
Suppose now we have a matrix.

00:21:11.240 --> 00:21:20.480 align:middle line:90%
So u is equal to u1, u n.

00:21:20.480 --> 00:21:22.670 align:middle line:90%
And this is in C n.

00:21:22.670 --> 00:21:31.010 align:middle line:84%
And A applied to u, if I want
the i-th coordinate of that,

00:21:31.010 --> 00:21:37.800 align:middle line:84%
is given by sum
of j equals 1 to n

00:21:37.800 --> 00:21:42.720 align:middle line:84%
of u j, where these
are just complex

00:21:42.720 --> 00:21:47.325 align:middle line:84%
numbers, some fixed
complex numbers.

00:21:47.325 --> 00:21:50.010 align:middle line:90%


00:21:50.010 --> 00:21:53.186 align:middle line:90%
So A is just a matrix.

00:21:53.186 --> 00:21:55.850 align:middle line:84%
A linear transformation
on C n is always

00:21:55.850 --> 00:21:58.590 align:middle line:90%
represented by a matrix.

00:21:58.590 --> 00:22:02.300 align:middle line:84%
And here, I'm writing u in
terms of the standard basis

00:22:02.300 --> 00:22:04.250 align:middle line:90%
vectors 1, 0, and so on.

00:22:04.250 --> 00:22:09.040 align:middle line:90%


00:22:09.040 --> 00:22:11.890 align:middle line:84%
Then, to determine
what the adjoint is,

00:22:11.890 --> 00:22:15.580 align:middle line:84%
we figure out what's
the operator that

00:22:15.580 --> 00:22:19.690 align:middle line:84%
satisfies the identity the
adjoint has to satisfy.

00:22:19.690 --> 00:22:27.590 align:middle line:84%
So if we take A u and
take its inner product,

00:22:27.590 --> 00:22:30.970 align:middle line:84%
we want to write this-- so
let me write this in a box--

00:22:30.970 --> 00:22:36.250 align:middle line:84%
we want to be able to write
this as u with some operator B

00:22:36.250 --> 00:22:38.950 align:middle line:84%
applied to v. And
then this would be--

00:22:38.950 --> 00:22:41.230 align:middle line:84%
and therefore, that
would be the adjoint.

00:22:41.230 --> 00:22:44.200 align:middle line:84%
So if we write A
u inner product v,

00:22:44.200 --> 00:22:58.230 align:middle line:84%
this is equal to sum i equals 1
to n of v i complex conjugate.

00:22:58.230 --> 00:23:01.260 align:middle line:84%
And this is, by
definition, equal to--

00:23:01.260 --> 00:23:03.300 align:middle line:84%
I'm just going to
write sum over i

00:23:03.300 --> 00:23:06.540 align:middle line:84%
and j, i and j are
going from 1 to n,

00:23:06.540 --> 00:23:18.890 align:middle line:84%
of A i, j, u i v j
complex conjugate.

00:23:18.890 --> 00:23:26.990 align:middle line:84%
And if I now switch
this over and sum first

00:23:26.990 --> 00:23:30.560 align:middle line:84%
with respect to i and
then with respect to j,

00:23:30.560 --> 00:23:35.570 align:middle line:84%
I can write this as u
j sum i equals 1 to n

00:23:35.570 --> 00:23:46.178 align:middle line:84%
of A i j applied to v
i complex conjugate,

00:23:46.178 --> 00:23:47.345 align:middle line:90%
the complex conjugate there.

00:23:47.345 --> 00:23:53.180 align:middle line:90%


00:23:53.180 --> 00:23:56.035 align:middle line:90%
And so this tells me that--

00:23:56.035 --> 00:24:00.700 align:middle line:90%


00:24:00.700 --> 00:24:04.870 align:middle line:84%
so this is equal
to sum j equals 1

00:24:04.870 --> 00:24:19.890 align:middle line:84%
to n u j and times what I'll
call the adjoint applied to v j

00:24:19.890 --> 00:24:20.460 align:middle line:90%
where--

00:24:20.460 --> 00:24:22.290 align:middle line:90%
what is the adjoint?

00:24:22.290 --> 00:24:28.080 align:middle line:84%
Or how does the adjoint
operate on an element v?

00:24:28.080 --> 00:24:35.440 align:middle line:90%


00:24:35.440 --> 00:24:39.145 align:middle line:90%
This is equal to sum from--

00:24:39.145 --> 00:24:41.680 align:middle line:90%


00:24:41.680 --> 00:24:44.290 align:middle line:84%
let's say I want the
i-th member now--

00:24:44.290 --> 00:24:52.720 align:middle line:84%
this is sum from j equals 1 to n
A j i complex conjugate applied

00:24:52.720 --> 00:24:59.060 align:middle line:90%
to v j.

00:24:59.060 --> 00:25:03.400 align:middle line:90%


00:25:03.400 --> 00:25:09.160 align:middle line:84%
So for matrices-- again,
this should be review--

00:25:09.160 --> 00:25:12.980 align:middle line:90%


00:25:12.980 --> 00:25:21.570 align:middle line:84%
if A is represented
by the matrix,

00:25:21.570 --> 00:25:27.560 align:middle line:84%
then the adjoint, which is
also representable by a matrix,

00:25:27.560 --> 00:25:30.300 align:middle line:90%
is representable by the matrix.

00:25:30.300 --> 00:25:34.520 align:middle line:84%
So I should say the
matrix for the adjoint

00:25:34.520 --> 00:25:41.060 align:middle line:84%
A i j is equal to A j
i complex conjugate.

00:25:41.060 --> 00:25:50.450 align:middle line:90%


00:25:50.450 --> 00:25:52.400 align:middle line:90%
So we did this for C n.

00:25:52.400 --> 00:25:57.937 align:middle line:84%
There's no reason we can't do
it for, let's say, little l2 now

00:25:57.937 --> 00:25:59.520 align:middle line:84%
and make it a little
more interesting.

00:25:59.520 --> 00:26:12.250 align:middle line:84%
So suppose now I have now
infinitely many numbers

00:26:12.250 --> 00:26:26.200 align:middle line:84%
A i j, so a double
sequence in C n,

00:26:26.200 --> 00:26:35.110 align:middle line:84%
such that sum i j, sum
A i j squared, which

00:26:35.110 --> 00:26:45.340 align:middle line:84%
is linked as n goes to infinity,
of sum of i equals 1 to n,

00:26:45.340 --> 00:26:54.055 align:middle line:90%
j equals 1 to n, is finite.

00:26:54.055 --> 00:27:04.830 align:middle line:90%


00:27:04.830 --> 00:27:18.350 align:middle line:84%
Now, let's define A now from
little l 2 to little l 2 via A

00:27:18.350 --> 00:27:22.290 align:middle line:84%
applied to a sequence, which
I put an underline underneath,

00:27:22.290 --> 00:27:25.550 align:middle line:90%
or let's make it u.

00:27:25.550 --> 00:27:31.790 align:middle line:84%
OK, we've been using A's
for elements in little l p

00:27:31.790 --> 00:27:41.810 align:middle line:84%
as sum j equals 1 to
infinity A i j A j.

00:27:41.810 --> 00:27:49.670 align:middle line:84%
And here, this is for
A equals A little l 2.

00:27:49.670 --> 00:27:51.350 align:middle line:84%
Now, by the
Cauchy-Schwarz inequality,

00:27:51.350 --> 00:27:54.860 align:middle line:84%
you can check that if this
condition is satisfied, then

00:27:54.860 --> 00:27:57.860 align:middle line:84%
this is a bounded
linear operator.

00:27:57.860 --> 00:28:00.620 align:middle line:84%
The absolute value
of this thing will

00:28:00.620 --> 00:28:05.060 align:middle line:84%
be less than or equal to the sum
j equals 1 to infinity of A i j

00:28:05.060 --> 00:28:11.900 align:middle line:84%
sum of j squared, square
root times the l 2 norm of A.

00:28:11.900 --> 00:28:15.210 align:middle line:84%
And therefore, I
can sum that using--

00:28:15.210 --> 00:28:21.150 align:middle line:84%
that's l 2 summable using
the fact that this is finite.

00:28:21.150 --> 00:28:24.600 align:middle line:84%
Don't worry about
the fact that I'm

00:28:24.600 --> 00:28:28.590 align:middle line:84%
summing this double
sum in a certain way

00:28:28.590 --> 00:28:32.100 align:middle line:84%
by j going from 1 to
n, i going from 1 to n.

00:28:32.100 --> 00:28:36.703 align:middle line:84%
In fact, if it's absolutely
summable in this, which

00:28:36.703 --> 00:28:38.620 align:middle line:84%
it is-- it's the sum of
non-negative numbers--

00:28:38.620 --> 00:28:42.940 align:middle line:84%
this sum doesn't depend on how
I'm summing it in this way.

00:28:42.940 --> 00:28:45.790 align:middle line:90%


00:28:45.790 --> 00:28:50.650 align:middle line:84%
So then this is a
bounded linear operator.

00:28:50.650 --> 00:28:57.130 align:middle line:90%


00:28:57.130 --> 00:28:58.150 align:middle line:90%
And what's its adjoint?

00:28:58.150 --> 00:29:01.300 align:middle line:84%
Its adjoint is going to
be of the same flavor

00:29:01.300 --> 00:29:07.090 align:middle line:84%
as what we got for the
finite dimensional case.

00:29:07.090 --> 00:29:15.130 align:middle line:84%
And for all A B and little l
2, if I take the inner product

00:29:15.130 --> 00:29:21.280 align:middle line:84%
of A applied to u,
A, B, and little l 2,

00:29:21.280 --> 00:29:25.540 align:middle line:90%
this is equal to sum over i--

00:29:25.540 --> 00:29:28.090 align:middle line:84%
I mean, the same proof
applies, essentially--

00:29:28.090 --> 00:29:35.060 align:middle line:84%
sum i j A i B i
complex conjugate,

00:29:35.060 --> 00:29:46.420 align:middle line:84%
which is equal to sum j A j i
A i j B i complex conjugate,

00:29:46.420 --> 00:29:59.830 align:middle line:84%
complex conjugate, which is
equal to inner product with A

00:29:59.830 --> 00:30:10.805 align:middle line:84%
star B, where A star
B is defined via sum--

00:30:10.805 --> 00:30:15.650 align:middle line:90%


00:30:15.650 --> 00:30:18.140 align:middle line:84%
so I should have said
this is the i-th entry

00:30:18.140 --> 00:30:24.140 align:middle line:90%
in this new sequence in l 2.

00:30:24.140 --> 00:30:30.110 align:middle line:84%
And so here, the i-th entry
in this new sequence in l 2

00:30:30.110 --> 00:30:35.540 align:middle line:84%
is defined to be j equals
1 to infinity A j i

00:30:35.540 --> 00:30:39.230 align:middle line:90%
complex conjugate B j.

00:30:39.230 --> 00:30:44.040 align:middle line:90%


00:30:44.040 --> 00:30:47.730 align:middle line:84%
So just like in the
finite dimensional case,

00:30:47.730 --> 00:30:52.620 align:middle line:84%
for this case, if I switch
the variables of this A--

00:30:52.620 --> 00:30:59.970 align:middle line:84%
if you'd like a double
infinite matrix, if you

00:30:59.970 --> 00:31:01.810 align:middle line:90%
want to think of it that way--

00:31:01.810 --> 00:31:05.280 align:middle line:84%
it's the same as in the
finite dimensional case.

00:31:05.280 --> 00:31:07.810 align:middle line:90%
Let's do one last example.

00:31:07.810 --> 00:31:11.010 align:middle line:84%
So I'm not going to go through
again the computations, which

00:31:11.010 --> 00:31:14.130 align:middle line:90%
are very similar.

00:31:14.130 --> 00:31:16.650 align:middle line:84%
Here, we're having
kind of finite sums.

00:31:16.650 --> 00:31:18.563 align:middle line:84%
If you can do
something with sums,

00:31:18.563 --> 00:31:19.980 align:middle line:84%
you should consider
whether or not

00:31:19.980 --> 00:31:22.180 align:middle line:90%
you can do it for integrals.

00:31:22.180 --> 00:31:28.080 align:middle line:84%
So let's suppose K is
a continuous function

00:31:28.080 --> 00:31:29.940 align:middle line:90%
on 0, 1 cross 0, 1.

00:31:29.940 --> 00:31:33.630 align:middle line:90%


00:31:33.630 --> 00:31:48.000 align:middle line:84%
And we define a map A which
we can show goes from L 2

00:31:48.000 --> 00:31:53.970 align:middle line:84%
to L 2 via A f of x is
equal to the integral from 0

00:31:53.970 --> 00:32:00.660 align:middle line:90%
to 1 of K of x, y, f of y dy.

00:32:00.660 --> 00:32:04.722 align:middle line:90%


00:32:04.722 --> 00:32:12.480 align:middle line:84%
In fact, this is for
each f in L 2, A f--

00:32:12.480 --> 00:32:14.910 align:middle line:84%
this thing is, in fact,
a continuous function.

00:32:14.910 --> 00:32:16.570 align:middle line:90%
It's more than just in L2.

00:32:16.570 --> 00:32:18.070 align:middle line:84%
It's in fact, a
continuous function.

00:32:18.070 --> 00:32:22.850 align:middle line:84%
But continuous functions on 0,
1 are elements of L2 on 0, 1.

00:32:22.850 --> 00:32:25.570 align:middle line:90%


00:32:25.570 --> 00:32:28.270 align:middle line:84%
Then you can check,
just as we've

00:32:28.270 --> 00:32:36.100 align:middle line:84%
done in these two other
examples, that the adjoint of f

00:32:36.100 --> 00:32:38.320 align:middle line:90%
is equal to--

00:32:38.320 --> 00:32:40.600 align:middle line:90%
or let's make this different--

00:32:40.600 --> 00:32:44.440 align:middle line:84%
say adjoint applied to g
is equal to the integral

00:32:44.440 --> 00:32:54.370 align:middle line:84%
from 0 to 1 K y, x complex
conjugate g of y dy.

00:32:54.370 --> 00:32:56.770 align:middle line:84%
So again, it's like
flipping the indices

00:32:56.770 --> 00:32:58.330 align:middle line:84%
and taking the
complex conjugate.

00:32:58.330 --> 00:33:08.460 align:middle line:90%


00:33:08.460 --> 00:33:11.620 align:middle line:84%
I said at the end of last class
that you can tell something

00:33:11.620 --> 00:33:20.330 align:middle line:84%
about the solvability
of equations

00:33:20.330 --> 00:33:23.930 align:middle line:90%
based on how the adjoint--

00:33:23.930 --> 00:33:25.355 align:middle line:90%
on properties of the adjoint.

00:33:25.355 --> 00:33:34.290 align:middle line:90%


00:33:34.290 --> 00:33:41.470 align:middle line:84%
We'll see another way
this is manifested later.

00:33:41.470 --> 00:33:46.030 align:middle line:90%
That's kind of the simplest way.

00:33:46.030 --> 00:33:56.625 align:middle line:84%
And so suppose H
is a Hilbert space.

00:33:56.625 --> 00:34:05.470 align:middle line:90%


00:34:05.470 --> 00:34:10.239 align:middle line:84%
And A from H to H is a
bounded linear operator.

00:34:10.239 --> 00:34:18.489 align:middle line:90%


00:34:18.489 --> 00:34:28.750 align:middle line:84%
Then-- I used Ran
in the assignments,

00:34:28.750 --> 00:34:31.150 align:middle line:90%
so I'll use it this way here--

00:34:31.150 --> 00:34:34.250 align:middle line:84%
the range of A,
orthogonal complement--

00:34:34.250 --> 00:34:41.550 align:middle line:84%
so the range you can show is
a subspace of H. In fact, I

00:34:41.550 --> 00:34:44.440 align:middle line:84%
think that was in one of
the earlier assignments.

00:34:44.440 --> 00:34:47.380 align:middle line:84%
If you take the orthogonal
complement of that,

00:34:47.380 --> 00:35:02.450 align:middle line:84%
that is equal to the null
space of the adjoint.

00:35:02.450 --> 00:35:06.780 align:middle line:90%


00:35:06.780 --> 00:35:16.150 align:middle line:84%
So here, let me recall that
range of an operator B--

00:35:16.150 --> 00:35:17.350 align:middle line:90%
this is exactly what it is.

00:35:17.350 --> 00:35:22.960 align:middle line:84%
This is a set of all
vectors B u where u is in H

00:35:22.960 --> 00:35:27.810 align:middle line:90%
and null space of B--

00:35:27.810 --> 00:35:32.730 align:middle line:84%
I might have called
it the kernel,

00:35:32.730 --> 00:35:37.290 align:middle line:84%
might have labeled it
as the kernel of B,

00:35:37.290 --> 00:35:39.400 align:middle line:90%
but both mean the same set.

00:35:39.400 --> 00:35:45.540 align:middle line:84%
This is a set of all u in
H such that B u equals 0.

00:35:45.540 --> 00:35:51.600 align:middle line:90%


00:35:51.600 --> 00:35:56.400 align:middle line:84%
So in particular, if we know
that we have an operator A such

00:35:56.400 --> 00:36:03.810 align:middle line:84%
that the range is a closed
subspace, then being

00:36:03.810 --> 00:36:06.420 align:middle line:84%
able to solve the
equation A u equals

00:36:06.420 --> 00:36:12.390 align:middle line:84%
v is equivalent to showing that
the null space of the adjoint

00:36:12.390 --> 00:36:13.965 align:middle line:90%
is simply 0.

00:36:13.965 --> 00:36:17.940 align:middle line:90%


00:36:17.940 --> 00:36:19.380 align:middle line:90%
So let me make that as a remark.

00:36:19.380 --> 00:36:26.460 align:middle line:90%


00:36:26.460 --> 00:36:35.790 align:middle line:84%
Suppose that the
range of A is closed.

00:36:35.790 --> 00:36:47.320 align:middle line:84%
Then A from H to H is
surjective if and only

00:36:47.320 --> 00:36:58.330 align:middle line:84%
if the adjoint is
injective, meaning

00:36:58.330 --> 00:37:02.680 align:middle line:84%
the only thing that gets
set to 0 is the zero vector.

00:37:02.680 --> 00:37:07.360 align:middle line:84%
Because if the null space is
equal to the 0-- so first off,

00:37:07.360 --> 00:37:11.680 align:middle line:84%
it's easy to see if the
range of A is equal to H,

00:37:11.680 --> 00:37:14.980 align:middle line:84%
then the orthogonal complement
of H is the zero vector.

00:37:14.980 --> 00:37:19.870 align:middle line:84%
So null space of the
adjoint is just a set

00:37:19.870 --> 00:37:21.550 align:middle line:90%
containing the zero vector.

00:37:21.550 --> 00:37:27.360 align:middle line:84%
Now, if the null
phase of the adjoint

00:37:27.360 --> 00:37:31.170 align:middle line:84%
is just a zero
vector, then taking

00:37:31.170 --> 00:37:33.540 align:middle line:84%
the orthogonal
complements of both sides,

00:37:33.540 --> 00:37:35.970 align:middle line:84%
and using the fact that
the range is closed

00:37:35.970 --> 00:37:37.650 align:middle line:84%
so that the
orthogonal complement

00:37:37.650 --> 00:37:40.470 align:middle line:84%
of the orthogonal complement
gives me back the set,

00:37:40.470 --> 00:37:42.480 align:middle line:84%
I conclude that the
range of A equals

00:37:42.480 --> 00:37:45.570 align:middle line:84%
the orthogonal complement
of the zero vector, which

00:37:45.570 --> 00:37:47.505 align:middle line:90%
is H, the entire space.

00:37:47.505 --> 00:37:50.050 align:middle line:90%


00:37:50.050 --> 00:37:54.670 align:middle line:84%
So we know that we
have an operator which

00:37:54.670 --> 00:37:55.780 align:middle line:90%
has closed range.

00:37:55.780 --> 00:37:58.870 align:middle line:84%
Then being surjective is
equivalent to the adjoint

00:37:58.870 --> 00:37:59.850 align:middle line:90%
being injective.

00:37:59.850 --> 00:38:13.650 align:middle line:90%


00:38:13.650 --> 00:38:15.885 align:middle line:84%
So the proof of this,
though, is pretty easy.

00:38:15.885 --> 00:38:20.680 align:middle line:90%


00:38:20.680 --> 00:38:30.210 align:middle line:84%
So B is in the null
space of A star

00:38:30.210 --> 00:38:42.570 align:middle line:84%
if and only if u A star B
equals 0 for all u in H.

00:38:42.570 --> 00:38:47.100 align:middle line:84%
A star v equals 0 if and only
if this holds for all u in H.

00:38:47.100 --> 00:38:53.340 align:middle line:84%
And this is equivalent to, by
the property of the adjoint,

00:38:53.340 --> 00:38:57.240 align:middle line:84%
u inner product of A star
v is equal to A times u

00:38:57.240 --> 00:39:05.910 align:middle line:84%
inner product v, so A u,
v equals 0 for all u in H.

00:39:05.910 --> 00:39:08.810 align:middle line:90%
So v is a fixed thing.

00:39:08.810 --> 00:39:12.680 align:middle line:84%
So this says that v
is orthogonal to all

00:39:12.680 --> 00:39:15.230 align:middle line:84%
of the elements of H
of the form A times u.

00:39:15.230 --> 00:39:18.950 align:middle line:84%
But that's just
the range of A. So

00:39:18.950 --> 00:39:27.740 align:middle line:84%
this is equivalent to B is
in the orthogonal complement

00:39:27.740 --> 00:40:01.770 align:middle line:90%
of the range of A.

00:40:01.770 --> 00:40:05.160 align:middle line:84%
So we're soon going to
get into the realm of more

00:40:05.160 --> 00:40:08.220 align:middle line:84%
refined things we
can say about solving

00:40:08.220 --> 00:40:11.850 align:middle line:84%
certain equations
involving operators,

00:40:11.850 --> 00:40:16.840 align:middle line:84%
meaning when can you solve
A u equals v and so on.

00:40:16.840 --> 00:40:28.650 align:middle line:84%
But now, the best theorem about
that you should know or maybe

00:40:28.650 --> 00:40:31.560 align:middle line:84%
heard at some point from linear
algebra is the rank-nullity

00:40:31.560 --> 00:40:38.040 align:middle line:84%
theorem, that says the dimension
of the range plus the dimension

00:40:38.040 --> 00:40:40.800 align:middle line:84%
of the null space equals
the dimension of the--

00:40:40.800 --> 00:40:44.370 align:middle line:84%
let's say you're going from
spaces with the same dimension,

00:40:44.370 --> 00:40:49.860 align:middle line:84%
then the dimension of the
range plus the dimension

00:40:49.860 --> 00:40:52.318 align:middle line:90%
of the kernel--

00:40:52.318 --> 00:40:53.860 align:middle line:84%
I may be actually
getting this wrong;

00:40:53.860 --> 00:40:56.793 align:middle line:84%
it's the end of a day; it's
the end of a long day--

00:40:56.793 --> 00:40:58.460 align:middle line:84%
equals the dimension
of the whole space.

00:40:58.460 --> 00:41:09.980 align:middle line:84%
So what this says
is that in essence,

00:41:09.980 --> 00:41:13.410 align:middle line:84%
in order to be able to
solve a given equation,

00:41:13.410 --> 00:41:18.230 align:middle line:84%
your input has to satisfy
finitely many linear relations.

00:41:18.230 --> 00:41:20.660 align:middle line:84%
And the solution
of that equation

00:41:20.660 --> 00:41:25.010 align:middle line:90%
is unique up to finally many--

00:41:25.010 --> 00:41:26.615 align:middle line:84%
or a finite
dimensional subspace.

00:41:26.615 --> 00:41:31.770 align:middle line:90%


00:41:31.770 --> 00:41:35.690 align:middle line:84%
Now this is the best
thing you can say.

00:41:35.690 --> 00:41:40.730 align:middle line:84%
Input has to satisfy finitely
many linear relations

00:41:40.730 --> 00:41:43.020 align:middle line:90%
and unique.

00:41:43.020 --> 00:41:46.700 align:middle line:84%
So that existence is
predicated upon your data

00:41:46.700 --> 00:41:50.390 align:middle line:84%
satisfying finitely
many linear conditions,

00:41:50.390 --> 00:41:58.700 align:middle line:84%
and you have uniqueness up to
a finite dimensional subspace,

00:41:58.700 --> 00:42:00.360 align:middle line:90%
meaning the null space.

00:42:00.360 --> 00:42:03.260 align:middle line:84%
Now, this is from finite
dimensional linear algebra.

00:42:03.260 --> 00:42:06.590 align:middle line:84%
It would be great if we could
do the same thing for infinite

00:42:06.590 --> 00:42:08.990 align:middle line:84%
dimensions, not just
because it would be fun,

00:42:08.990 --> 00:42:12.950 align:middle line:84%
but in the end because we
need to do these things,

00:42:12.950 --> 00:42:19.167 align:middle line:84%
or I should say need to, but not
in the sense that an airplane

00:42:19.167 --> 00:42:20.750 align:middle line:84%
wing is going to
fall off if we don't.

00:42:20.750 --> 00:42:29.100 align:middle line:84%
But in order to learn more about
certain problems that arise,

00:42:29.100 --> 00:42:31.440 align:middle line:84%
it would be great to be
able to do these things.

00:42:31.440 --> 00:42:35.220 align:middle line:84%
And we'll be able to do them
for certain operators, which

00:42:35.220 --> 00:42:38.170 align:middle line:90%
are in some way--

00:42:38.170 --> 00:42:42.010 align:middle line:84%
these aren't the only operators,
but for certain operators

00:42:42.010 --> 00:42:45.595 align:middle line:84%
that are close to being
matrices in a certain sense.

00:42:45.595 --> 00:42:46.970 align:middle line:84%
So we'll get to
that in a minute.

00:42:46.970 --> 00:42:58.560 align:middle line:84%
Now, these operators
that we will eventually

00:42:58.560 --> 00:43:02.490 align:middle line:84%
study the solvability
properties of

00:43:02.490 --> 00:43:10.980 align:middle line:84%
have a very special
nature or property on how

00:43:10.980 --> 00:43:14.420 align:middle line:90%
it acts on bounded sequences.

00:43:14.420 --> 00:43:17.390 align:middle line:84%
Now, something that you
take for granted in R n

00:43:17.390 --> 00:43:19.490 align:middle line:84%
is that if I have
a linear operator

00:43:19.490 --> 00:43:23.120 align:middle line:84%
and I have a bounded
sequence of vectors, then

00:43:23.120 --> 00:43:25.670 align:middle line:84%
A maps that to a bounded
sequence of vectors

00:43:25.670 --> 00:43:28.350 align:middle line:84%
because a matrix is a
bounded linear operator.

00:43:28.350 --> 00:43:30.260 align:middle line:84%
It takes bounded
sets of bounded sets.

00:43:30.260 --> 00:43:37.430 align:middle line:84%
And therefore, by the
Heine-Borel theorem,

00:43:37.430 --> 00:43:42.130 align:middle line:84%
there will be a subsequence of
the images of these vectors,

00:43:42.130 --> 00:43:43.150 align:middle line:90%
which converges.

00:43:43.150 --> 00:43:46.100 align:middle line:90%


00:43:46.100 --> 00:43:51.470 align:middle line:84%
So there's some
compactness hidden in what

00:43:51.470 --> 00:43:53.840 align:middle line:90%
you're doing on R n and C n.

00:43:53.840 --> 00:43:56.900 align:middle line:90%
And why am I rambling right now?

00:43:56.900 --> 00:43:59.180 align:middle line:84%
I'm getting to the
final point that we

00:43:59.180 --> 00:44:05.390 align:middle line:84%
need to study a little bit about
compactness and Hilbert spaces

00:44:05.390 --> 00:44:08.720 align:middle line:84%
to eventually get to the
place where we can say more

00:44:08.720 --> 00:44:10.880 align:middle line:84%
about being able to
solve equations involving

00:44:10.880 --> 00:44:13.400 align:middle line:84%
bounded linear operators,
now in infinite dimensions.

00:44:13.400 --> 00:44:16.410 align:middle line:90%


00:44:16.410 --> 00:44:19.590 align:middle line:84%
So with that rambling
build-up, hopefully, I

00:44:19.590 --> 00:44:21.630 align:middle line:84%
convinced you that we
should study a little bit

00:44:21.630 --> 00:44:30.320 align:middle line:84%
about what it means for sets to
be compact in a Hilbert space.

00:44:30.320 --> 00:44:41.200 align:middle line:84%
So let's look at compactness
in Hilbert space.

00:44:41.200 --> 00:44:46.080 align:middle line:84%
So let me recall for
you what it means

00:44:46.080 --> 00:44:51.306 align:middle line:84%
for a set to be compact
in a metric space.

00:44:51.306 --> 00:45:05.770 align:middle line:84%
If X is a metric space,
We say a subset K in X

00:45:05.770 --> 00:45:22.940 align:middle line:84%
is compact if every
sequence of elements in K

00:45:22.940 --> 00:45:40.120 align:middle line:84%
has a subsequence converging
to an element in K.

00:45:40.120 --> 00:45:48.480 align:middle line:84%
So a set is compact if every
sequence of elements in the set

00:45:48.480 --> 00:45:50.070 align:middle line:84%
has a subsequence
which converges

00:45:50.070 --> 00:45:51.390 align:middle line:90%
to an element in the set.

00:45:51.390 --> 00:45:55.020 align:middle line:84%
So the simplest on Earth
types of compact sets

00:45:55.020 --> 00:45:55.920 align:middle line:90%
are finite sets.

00:45:55.920 --> 00:45:58.390 align:middle line:90%


00:45:58.390 --> 00:46:00.390 align:middle line:84%
This just follows from
the pigeonhole principle,

00:46:00.390 --> 00:46:01.140 align:middle line:90%
basically.

00:46:01.140 --> 00:46:03.930 align:middle line:90%


00:46:03.930 --> 00:46:07.320 align:middle line:84%
So the simplest
example are finite sets

00:46:07.320 --> 00:46:11.415 align:middle line:84%
of finite subsets of a metric
space, of any metric space.

00:46:11.415 --> 00:46:25.420 align:middle line:90%


00:46:25.420 --> 00:46:31.880 align:middle line:84%
Now, we have this very cool
theorem from Intro Analysis,

00:46:31.880 --> 00:46:39.090 align:middle line:84%
which goes by the
name of Heine-Borel,

00:46:39.090 --> 00:46:44.630 align:middle line:90%
that says a subset K in R--

00:46:44.630 --> 00:46:47.720 align:middle line:84%
you can replace R by
R n or C n, but this

00:46:47.720 --> 00:46:49.760 align:middle line:84%
follows from the
one-dimensional case,

00:46:49.760 --> 00:47:02.270 align:middle line:84%
essentially-- a subset K of R
is compact if and only if K is

00:47:02.270 --> 00:47:07.265 align:middle line:90%
closed subset of R and bounded.

00:47:07.265 --> 00:47:09.990 align:middle line:90%


00:47:09.990 --> 00:47:12.170 align:middle line:84%
So for example, the closed
and bounded intervals

00:47:12.170 --> 00:47:13.700 align:middle line:84%
a, b-- those are
all compact sets.

00:47:13.700 --> 00:47:19.620 align:middle line:90%


00:47:19.620 --> 00:47:26.720 align:middle line:84%
a, b, the set
consisting of 1 over n,

00:47:26.720 --> 00:47:31.340 align:middle line:84%
n a natural number,
union the element 0.

00:47:31.340 --> 00:47:33.020 align:middle line:90%
That's also a compact set.

00:47:33.020 --> 00:47:34.235 align:middle line:90%
It's closed and it's bounded.

00:47:34.235 --> 00:47:38.980 align:middle line:90%


00:47:38.980 --> 00:47:43.320 align:middle line:84%
Now, this is a
theorem about elements

00:47:43.320 --> 00:47:51.570 align:middle line:84%
of compact subsets of R. One can
build off of the proof of this,

00:47:51.570 --> 00:47:56.160 align:middle line:84%
really, to get the
result for R n and C n.

00:47:56.160 --> 00:47:59.370 align:middle line:84%
The metric properties of
C n are the same as R 2n,

00:47:59.370 --> 00:48:03.600 align:middle line:84%
so let's say just R n-- that
a subset of R n is compact if

00:48:03.600 --> 00:48:06.640 align:middle line:84%
and only if it's
closed and bounded.

00:48:06.640 --> 00:48:13.350 align:middle line:84%
Now, does that hold for
arbitrary metric spaces?

00:48:13.350 --> 00:48:14.640 align:middle line:90%
No.

00:48:14.640 --> 00:48:16.750 align:middle line:90%
Does it hold for Banach spaces?

00:48:16.750 --> 00:48:17.250 align:middle line:90%
No.

00:48:17.250 --> 00:48:19.583 align:middle line:84%
You did an example on one of
the assignments that proved

00:48:19.583 --> 00:48:22.560 align:middle line:90%
that little l p is not compact.

00:48:22.560 --> 00:48:24.840 align:middle line:84%
What about if we specialize
the Hilbert spaces?

00:48:24.840 --> 00:48:25.860 align:middle line:90%
The answer is still no.

00:48:25.860 --> 00:48:30.360 align:middle line:84%
So let's make this a
non example, since we

00:48:30.360 --> 00:48:32.080 align:middle line:90%
did examples a minute ago.

00:48:32.080 --> 00:48:37.230 align:middle line:84%
So all of these, as subsets
of R, these are all compact.

00:48:37.230 --> 00:49:08.010 align:middle line:84%
So let's suppose H is a
infinite-dimensional Hilbert

00:49:08.010 --> 00:49:10.290 align:middle line:90%
space.

00:49:10.290 --> 00:49:20.520 align:middle line:84%
Then the closed ball B
equals the set of u and H--

00:49:20.520 --> 00:49:21.285 align:middle line:90%
let's make it F--

00:49:21.285 --> 00:49:25.110 align:middle line:90%


00:49:25.110 --> 00:49:28.650 align:middle line:84%
such that length of u is
less than or equal to 1.

00:49:28.650 --> 00:49:31.450 align:middle line:84%
This is a closed
and bounded set.

00:49:31.450 --> 00:49:34.140 align:middle line:90%
You can check that.

00:49:34.140 --> 00:49:40.530 align:middle line:90%
This is not compact.

00:49:40.530 --> 00:49:43.730 align:middle line:90%
Let's get back to compactness.

00:49:43.730 --> 00:49:46.580 align:middle line:84%
So let's suppose H is a
infinite-dimensional--

00:49:46.580 --> 00:49:53.680 align:middle line:84%
let's even make it separable,
as all good Hilbert spaces are.

00:49:53.680 --> 00:49:59.380 align:middle line:84%
Then the closed unit
ball is not compact.

00:49:59.380 --> 00:50:00.430 align:middle line:90%
So why is this?

00:50:00.430 --> 00:50:04.430 align:middle line:90%


00:50:04.430 --> 00:50:11.410 align:middle line:84%
Let e n equals 1
to infinity b n--

00:50:11.410 --> 00:50:18.110 align:middle line:84%
or in fact, it doesn't
have to be separable.

00:50:18.110 --> 00:50:21.950 align:middle line:84%
In fact, if you just take any
infinite-dimensional Hilbert

00:50:21.950 --> 00:50:23.480 align:middle line:90%
space, you can find by the--

00:50:23.480 --> 00:50:26.730 align:middle line:90%


00:50:26.730 --> 00:50:29.910 align:middle line:84%
we don't need to
make it separable.

00:50:29.910 --> 00:50:34.020 align:middle line:84%
You can always find an
orthonormal, countably infinite

00:50:34.020 --> 00:50:37.593 align:middle line:90%
orthonormal, subset of H.

00:50:37.593 --> 00:50:39.510 align:middle line:84%
Now, in the separable
case, we could choose it

00:50:39.510 --> 00:50:40.948 align:middle line:84%
so that it's a
orthonormal basis.

00:50:40.948 --> 00:50:42.240 align:middle line:90%
But that really doesn't matter.

00:50:42.240 --> 00:50:44.970 align:middle line:84%
Just the fact that H is an
infinite-dimensional Hilbert

00:50:44.970 --> 00:51:00.410 align:middle line:84%
space, we can find
a countable subset.

00:51:00.410 --> 00:51:02.590 align:middle line:84%
So we can find a
countably infinite subset

00:51:02.590 --> 00:51:04.690 align:middle line:90%
of orthonormal vectors.

00:51:04.690 --> 00:51:05.350 align:middle line:90%
Why is this?

00:51:05.350 --> 00:51:08.980 align:middle line:84%
Because we can find a countable
set of linearly independent

00:51:08.980 --> 00:51:11.300 align:middle line:90%
vectors--

00:51:11.300 --> 00:51:14.350 align:middle line:84%
an infinite-dimensional
Hilbert space

00:51:14.350 --> 00:51:18.100 align:middle line:84%
or infinite-dimensional
vector space.

00:51:18.100 --> 00:51:21.040 align:middle line:84%
And then we can make them
orthonormal by applying

00:51:21.040 --> 00:51:25.300 align:middle line:84%
the Gram-Schmidt process
to that collection,

00:51:25.300 --> 00:51:29.830 align:middle line:84%
and come up with countably
infinite orthonormal subset.

00:51:29.830 --> 00:51:34.270 align:middle line:84%
Then, for all n
not equal to k, we

00:51:34.270 --> 00:51:40.120 align:middle line:84%
get that e n norm
minus e k squared--

00:51:40.120 --> 00:51:45.130 align:middle line:84%
this is equal to, again,
using the parallelogram law--

00:51:45.130 --> 00:51:49.457 align:middle line:90%


00:51:49.457 --> 00:51:51.540 align:middle line:84%
well, I don't need to apply
the parallelogram law.

00:51:51.540 --> 00:51:53.370 align:middle line:90%
I can just apply what this is.

00:51:53.370 --> 00:52:00.230 align:middle line:84%
This is equal to norm n squared
plus norm e k squared plus 2

00:52:00.230 --> 00:52:04.140 align:middle line:90%
real part e n e k.

00:52:04.140 --> 00:52:07.110 align:middle line:84%
And since they're
orthogonal, this is 0.

00:52:07.110 --> 00:52:10.440 align:middle line:84%
And since they're normalized
to 1, this is equal to 2.

00:52:10.440 --> 00:52:17.220 align:middle line:84%
So for any two distinct
elements in the sequence,

00:52:17.220 --> 00:52:22.620 align:middle line:84%
the distance between the
two of them is equal to 2.

00:52:22.620 --> 00:52:26.880 align:middle line:84%
So there's no way the sequence
of these orthonormal vectors

00:52:26.880 --> 00:52:29.550 align:middle line:84%
can have a convergent
subsequence.

00:52:29.550 --> 00:52:31.290 align:middle line:84%
Because a convergent
subsequence would

00:52:31.290 --> 00:52:35.610 align:middle line:84%
mean that if I go
along the subsequence,

00:52:35.610 --> 00:52:37.320 align:middle line:84%
or this subsequence
has to be Cauchy

00:52:37.320 --> 00:52:41.640 align:middle line:84%
so that the difference between
vectors has to get small.

00:52:41.640 --> 00:52:42.692 align:middle line:90%
But it's never small.

00:52:42.692 --> 00:52:44.400 align:middle line:84%
It's always at least
bigger than or equal

00:52:44.400 --> 00:52:49.095 align:middle line:84%
to 2, at least the length
squared or distance squared.

00:52:49.095 --> 00:52:52.130 align:middle line:90%


00:52:52.130 --> 00:52:59.120 align:middle line:84%
So this is a closed and bounded
subset which is not compact.

00:52:59.120 --> 00:53:04.470 align:middle line:90%


00:53:04.470 --> 00:53:07.680 align:middle line:84%
There exist sequences
which have no--

00:53:07.680 --> 00:53:11.580 align:middle line:84%
or this sequence has no
convergent subsequence.

00:53:11.580 --> 00:53:15.570 align:middle line:84%
So the question is, what's
the additional condition

00:53:15.570 --> 00:53:26.280 align:middle line:84%
I need to conclude that a subset
of a metric space is compact?

00:53:26.280 --> 00:53:34.720 align:middle line:84%
From Real Analysis 18.100, every
compact set has to be closed

00:53:34.720 --> 00:53:36.370 align:middle line:90%
and bounded.

00:53:36.370 --> 00:53:40.220 align:middle line:84%
One implication is that
if something is compact,

00:53:40.220 --> 00:53:42.280 align:middle line:90%
it's closed and it's bounded.

00:53:42.280 --> 00:53:46.090 align:middle line:84%
What additional condition
on the set-- so being

00:53:46.090 --> 00:53:48.370 align:middle line:84%
closed and bounded is
a necessity of the set.

00:53:48.370 --> 00:53:52.240 align:middle line:84%
What additional condition
guarantees that it's compact?

00:53:52.240 --> 00:53:53.860 align:middle line:84%
Maybe not if and
only if, like we

00:53:53.860 --> 00:53:58.660 align:middle line:84%
have for the Heine-Borel,
but at least something simple

00:53:58.660 --> 00:54:06.580 align:middle line:84%
to verify so that the subset of
the Hilbert space is compact.

00:54:06.580 --> 00:54:12.350 align:middle line:84%
Now, if you didn't see this
in 18.100, that's fine.

00:54:12.350 --> 00:54:19.750 align:middle line:84%
But this question can or
could have been already asked

00:54:19.750 --> 00:54:25.870 align:middle line:84%
in a different
context in 18.100.

00:54:25.870 --> 00:54:30.370 align:middle line:84%
And at least when I
taught it, 100B, it

00:54:30.370 --> 00:54:36.160 align:middle line:84%
was that you can ask the
same question about subsets

00:54:36.160 --> 00:54:40.060 align:middle line:90%
of continuous functions.

00:54:40.060 --> 00:54:43.900 align:middle line:84%
So definition of a compact
set is with respect

00:54:43.900 --> 00:54:45.400 align:middle line:90%
to a metric space.

00:54:45.400 --> 00:54:47.150 align:middle line:84%
Doesn't have to be an
inner product space.

00:54:47.150 --> 00:54:51.400 align:middle line:84%
So the space of continuous
functions on, say, 0, 1--

00:54:51.400 --> 00:54:54.760 align:middle line:84%
that's a perfectly good metric
space with the infinity norm.

00:54:54.760 --> 00:55:00.130 align:middle line:84%
You could ask, what are the
conditions on a set to ensure

00:55:00.130 --> 00:55:04.000 align:middle line:90%
that the set is compact?

00:55:04.000 --> 00:55:07.210 align:middle line:84%
And the three conditions
are closed, bounded--

00:55:07.210 --> 00:55:10.960 align:middle line:84%
because these are necessary
if the set is to be compact--

00:55:10.960 --> 00:55:14.150 align:middle line:84%
and what's called
"equicontinuous."

00:55:14.150 --> 00:55:21.500 align:middle line:84%
So for subsets of the space
of continuous functions,

00:55:21.500 --> 00:55:23.990 align:middle line:84%
if the subset is
closed, bounded,

00:55:23.990 --> 00:55:25.970 align:middle line:84%
and what's called
equicontinuous,

00:55:25.970 --> 00:55:28.310 align:middle line:90%
then the subset is compact.

00:55:28.310 --> 00:55:30.380 align:middle line:84%
This is the famous
Arzela-Ascoli theorem.

00:55:30.380 --> 00:55:33.290 align:middle line:90%


00:55:33.290 --> 00:55:39.560 align:middle line:84%
And that extra condition,
equicontinuity,

00:55:39.560 --> 00:55:48.250 align:middle line:84%
is in some sense what
allows you to reduce

00:55:48.250 --> 00:55:51.820 align:middle line:84%
your problem of
showing your space is

00:55:51.820 --> 00:55:55.810 align:middle line:84%
compact to the
finite-dimensional case.

00:55:55.810 --> 00:55:59.770 align:middle line:84%
It takes care of the
infinite dimensions

00:55:59.770 --> 00:56:06.890 align:middle line:84%
or it takes care of the
infinite part, in a sense.

00:56:06.890 --> 00:56:09.310 align:middle line:84%
That's not very
specific, but it's

00:56:09.310 --> 00:56:14.980 align:middle line:84%
needed to control all
but finitely many things,

00:56:14.980 --> 00:56:16.160 align:middle line:90%
in some sense.

00:56:16.160 --> 00:56:18.760 align:middle line:84%
Equicontinuity in
Arzela-Ascoli is

00:56:18.760 --> 00:56:22.150 align:middle line:84%
what helps you control all
but finitely many things.

00:56:22.150 --> 00:56:33.590 align:middle line:84%
Now, there is a similar
theorem that you can prove, now

00:56:33.590 --> 00:56:34.445 align:middle line:90%
in Hilbert spaces.

00:56:34.445 --> 00:56:43.092 align:middle line:90%


00:56:43.092 --> 00:56:44.300 align:middle line:90%
Let's just state the theorem.

00:56:44.300 --> 00:56:46.700 align:middle line:84%
Part of the theorem will be
a definition, unfortunately,

00:56:46.700 --> 00:56:54.445 align:middle line:90%
but let H be a Hilbert space.

00:56:54.445 --> 00:57:03.190 align:middle line:90%


00:57:03.190 --> 00:57:07.618 align:middle line:84%
Well, we're not going
to prove the theorem

00:57:07.618 --> 00:57:08.660 align:middle line:90%
I want to prove just yet.

00:57:08.660 --> 00:57:09.827 align:middle line:90%
I just skipped ahead by one.

00:57:09.827 --> 00:57:16.600 align:middle line:90%


00:57:16.600 --> 00:57:19.010 align:middle line:84%
So we'll motivate a
certain condition.

00:57:19.010 --> 00:57:24.850 align:middle line:84%
So I got ahead of myself just
a minute by just one theorem.

00:57:24.850 --> 00:57:27.850 align:middle line:84%
But let me introduce
the definition.

00:57:27.850 --> 00:57:30.550 align:middle line:90%


00:57:30.550 --> 00:57:43.995 align:middle line:90%
So let H be a Hilbert space.

00:57:43.995 --> 00:57:50.040 align:middle line:90%


00:57:50.040 --> 00:58:10.180 align:middle line:84%
A subset K of H sets has
equismall tails with respect

00:58:10.180 --> 00:58:25.150 align:middle line:84%
to a countable
orthonormal subset.

00:58:25.150 --> 00:58:34.990 align:middle line:84%
So the new bit of terminology
is "equismall tails--" e n if--

00:58:34.990 --> 00:58:38.970 align:middle line:90%


00:58:38.970 --> 00:58:39.980 align:middle line:90%
let's make this K--

00:58:39.980 --> 00:58:52.280 align:middle line:90%


00:58:52.280 --> 00:59:02.236 align:middle line:84%
in some sense-- so by
Bessel's inequality,

00:59:02.236 --> 00:59:06.380 align:middle line:84%
the sum of the, if you like,
Fourier coefficients or the sum

00:59:06.380 --> 00:59:07.940 align:middle line:84%
of the squares of
the inner product

00:59:07.940 --> 00:59:09.800 align:middle line:84%
e K with a fixed
vector-- this is always

00:59:09.800 --> 00:59:12.770 align:middle line:84%
bounded by the norm
of the vector squared.

00:59:12.770 --> 00:59:16.790 align:middle line:84%
And therefore, it
always converges.

00:59:16.790 --> 00:59:21.860 align:middle line:84%
So equismall tails means that
somehow, that series converges,

00:59:21.860 --> 00:59:24.800 align:middle line:84%
or the tail end of
that series converges,

00:59:24.800 --> 00:59:30.020 align:middle line:84%
uniformly with respect to
this orthonormal subset.

00:59:30.020 --> 00:59:35.040 align:middle line:84%
So in other words, for
all epsilon positive,

00:59:35.040 --> 00:59:41.300 align:middle line:84%
there exists a natural
number N such that

00:59:41.300 --> 00:59:53.950 align:middle line:84%
for all v in the set K,
if I look at the tail,

00:59:53.950 --> 00:59:56.250 align:middle line:84%
this is less than
epsilon squared.

00:59:56.250 --> 00:59:59.200 align:middle line:90%


00:59:59.200 --> 01:00:01.870 align:middle line:84%
So somehow, given
epsilon, I can always

01:00:01.870 --> 01:00:06.490 align:middle line:84%
choose an N which is
independent of the element in K

01:00:06.490 --> 01:00:11.890 align:middle line:84%
so that the tail end of, if
you like, the Fourier series

01:00:11.890 --> 01:00:14.290 align:middle line:90%
is small.

01:00:14.290 --> 01:00:16.570 align:middle line:84%
And this N can be
chosen independent

01:00:16.570 --> 01:00:20.530 align:middle line:90%
of the element in K.

01:00:20.530 --> 01:00:34.910 align:middle line:84%
So I leave it to you to verify
if K is simply a finite set,

01:00:34.910 --> 01:00:48.920 align:middle line:84%
this implies K has
equismall tails with respect

01:00:48.920 --> 01:01:00.735 align:middle line:90%
to any orthonormal subset.

01:01:00.735 --> 01:01:11.150 align:middle line:90%


01:01:11.150 --> 01:01:14.720 align:middle line:84%
So what's the motivation
for this definition

01:01:14.720 --> 01:01:21.860 align:middle line:84%
is that the next simplest
type of set which is compact.

01:01:21.860 --> 01:01:28.510 align:middle line:84%
So like I said, any finite
subset of a metric space

01:01:28.510 --> 01:01:29.440 align:middle line:90%
is compact.

01:01:29.440 --> 01:01:34.150 align:middle line:84%
Now, I'll give an
example of another,

01:01:34.150 --> 01:01:36.610 align:middle line:90%
more interesting compact set.

01:01:36.610 --> 01:01:39.760 align:middle line:84%
But that compact set also
satisfies this property,

01:01:39.760 --> 01:01:41.770 align:middle line:84%
that it has equismall
tails with respect

01:01:41.770 --> 01:01:46.510 align:middle line:84%
to any countable
orthonormal subset.

01:01:46.510 --> 01:01:51.220 align:middle line:84%
And so then, we should hope
that if a set is closed,

01:01:51.220 --> 01:01:54.460 align:middle line:84%
bounded, and has the
property that, with respect

01:01:54.460 --> 01:01:58.990 align:middle line:84%
to an orthonormal basis it has
equismall tails, then that set

01:01:58.990 --> 01:01:59.560 align:middle line:90%
is compact.

01:01:59.560 --> 01:02:00.820 align:middle line:84%
And that's eventually
what will prove,

01:02:00.820 --> 01:02:02.500 align:middle line:84%
but I don't think
we'll get to it today.

01:02:02.500 --> 01:02:08.590 align:middle line:84%
But so one more
bit of motivation

01:02:08.590 --> 01:02:12.610 align:middle line:84%
on why this might be the
right extra condition

01:02:12.610 --> 01:02:17.350 align:middle line:84%
to add to closed and bounded
to produce compact sets

01:02:17.350 --> 01:02:18.890 align:middle line:90%
is provided by the following.

01:02:18.890 --> 01:02:28.490 align:middle line:84%
So again, let H
be a Hilbert space

01:02:28.490 --> 01:02:36.530 align:middle line:90%
and be in a convergent sequence.

01:02:36.530 --> 01:02:44.590 align:middle line:90%


01:02:44.590 --> 01:02:49.720 align:middle line:84%
Now let e K be some
arbitrary orthonormal,

01:02:49.720 --> 01:02:51.070 align:middle line:90%
countable orthonormal subset.

01:02:51.070 --> 01:03:00.020 align:middle line:90%


01:03:00.020 --> 01:03:02.120 align:middle line:90%
So then two things hold--

01:03:02.120 --> 01:03:11.540 align:middle line:84%
one is that the set K
equals a set of elements v N

01:03:11.540 --> 01:03:14.750 align:middle line:90%
union the limit.

01:03:14.750 --> 01:03:15.530 align:middle line:90%
This is compact.

01:03:15.530 --> 01:03:21.940 align:middle line:90%


01:03:21.940 --> 01:03:25.770 align:middle line:84%
The proof is given in
[? Mel ?] [? Rose's ?] notes,

01:03:25.770 --> 01:03:28.270 align:middle line:84%
and I'm going to leave it to
you to look up or work your way

01:03:28.270 --> 01:03:28.770 align:middle line:90%
through.

01:03:28.770 --> 01:03:32.380 align:middle line:84%
It's not that difficult
to work your way through.

01:03:32.380 --> 01:03:48.240 align:middle line:84%
And K has equismall tails
with respect to e K.

01:03:48.240 --> 01:03:54.880 align:middle line:84%
So this subset consisting
of a convergent sequence

01:03:54.880 --> 01:03:56.950 align:middle line:84%
along with this
limit is compact.

01:03:56.950 --> 01:03:59.170 align:middle line:84%
And it has equismall
details with respect

01:03:59.170 --> 01:04:01.225 align:middle line:84%
to any countable
orthonormal subset.

01:04:01.225 --> 01:04:06.820 align:middle line:90%


01:04:06.820 --> 01:04:12.100 align:middle line:84%
So like I said, I'm going
to leave one for you.

01:04:12.100 --> 01:04:14.560 align:middle line:90%
2 we will prove.

01:04:14.560 --> 01:04:15.580 align:middle line:90%
How much time do I got?

01:04:15.580 --> 01:04:20.440 align:middle line:84%
I don't have much
time left, but we

01:04:20.440 --> 01:04:23.770 align:middle line:90%
should be able to finish this.

01:04:23.770 --> 01:04:27.170 align:middle line:84%
We have to verify
this definition.

01:04:27.170 --> 01:04:28.900 align:middle line:90%
So let epsilon be positive.

01:04:28.900 --> 01:04:32.260 align:middle line:90%


01:04:32.260 --> 01:04:35.370 align:middle line:90%
So why should we--

01:04:35.370 --> 01:04:38.490 align:middle line:84%
what's the thinking on why
we expect this set to have

01:04:38.490 --> 01:04:40.860 align:middle line:90%
equismall tails?

01:04:40.860 --> 01:04:43.260 align:middle line:84%
So I have to check that I can
find a large enough integer

01:04:43.260 --> 01:04:47.590 align:middle line:84%
that all the squares of
these coefficients is small.

01:04:47.590 --> 01:04:50.190 align:middle line:84%
Now, the point is
that the v N's are

01:04:50.190 --> 01:04:56.100 align:middle line:84%
essentially very close to being
v, at least for N very large.

01:04:56.100 --> 01:04:59.220 align:middle line:84%
And for a fixed v, I can
always choose a capital N

01:04:59.220 --> 01:05:01.780 align:middle line:90%
so that this holds.

01:05:01.780 --> 01:05:04.770 align:middle line:84%
And so that N will take
care of infinitely many,

01:05:04.770 --> 01:05:08.130 align:middle line:84%
and then I just need to
choose N big enough for v,

01:05:08.130 --> 01:05:12.900 align:middle line:84%
and also the finitely many
that are not very close--

01:05:12.900 --> 01:05:14.830 align:middle line:84%
finitely many elements
of this sequence

01:05:14.830 --> 01:05:18.510 align:middle line:84%
which are not close to v.
That's essentially the argument.

01:05:18.510 --> 01:05:34.210 align:middle line:84%
So since v N converges to v,
there exists a natural number

01:05:34.210 --> 01:05:42.670 align:middle line:84%
M such that all N bigger than or
equal to M, I have v N minus v,

01:05:42.670 --> 01:05:45.760 align:middle line:84%
and norm is less
than epsilon over 2.

01:05:45.760 --> 01:05:52.610 align:middle line:90%


01:05:52.610 --> 01:06:02.650 align:middle line:84%
Now, choose natural
number N so large

01:06:02.650 --> 01:06:17.240 align:middle line:84%
so that sum k bigger
than N of v v k--

01:06:17.240 --> 01:06:19.850 align:middle line:84%
this is small, so
here, v is fixed.

01:06:19.850 --> 01:06:22.820 align:middle line:84%
And we always have that
this whole sum converges

01:06:22.820 --> 01:06:24.350 align:middle line:90%
by Bessel's inequality.

01:06:24.350 --> 01:06:26.120 align:middle line:84%
And therefore, we can
always choose an N

01:06:26.120 --> 01:06:27.740 align:middle line:90%
so that the tail is small.

01:06:27.740 --> 01:06:30.530 align:middle line:84%
And we can do the
same for the first M

01:06:30.530 --> 01:06:50.610 align:middle line:84%
minus 1 elements of the
sequence, so plus max of 1,

01:06:50.610 --> 01:06:55.470 align:middle line:84%
so that this is all less
than epsilon squared over 4.

01:06:55.470 --> 01:06:59.250 align:middle line:84%
So for each v N, I
can find a capital--

01:06:59.250 --> 01:07:03.690 align:middle line:84%
so for v1, I can find an N1 so
that this is less than epsilon

01:07:03.690 --> 01:07:07.350 align:middle line:90%
squared over 8, say.

01:07:07.350 --> 01:07:11.070 align:middle line:84%
And then for N
equals 2, N equals 3,

01:07:11.070 --> 01:07:16.350 align:middle line:84%
all the way up to N minus 1,
I can find a capital N sub n.

01:07:16.350 --> 01:07:18.240 align:middle line:84%
I then take capital
N to be the maximum

01:07:18.240 --> 01:07:24.720 align:middle line:84%
of those finitely many capital
N sub n's along with the N

01:07:24.720 --> 01:07:26.610 align:middle line:90%
that I need for this.

01:07:26.610 --> 01:07:29.970 align:middle line:84%
So that's the argument on why
I can find such a capital N.

01:07:29.970 --> 01:07:32.470 align:middle line:84%
I just have finitely many
things I need to make small,

01:07:32.470 --> 01:07:33.945 align:middle line:90%
which I individually can.

01:07:33.945 --> 01:07:46.160 align:middle line:90%


01:07:46.160 --> 01:07:48.000 align:middle line:84%
Now, I claim this
capital N works.

01:07:48.000 --> 01:07:52.850 align:middle line:84%
So I have to show that if I
take any element in K, then

01:07:52.850 --> 01:07:54.320 align:middle line:90%
it has a small tail.

01:07:54.320 --> 01:07:58.070 align:middle line:90%


01:07:58.070 --> 01:08:09.180 align:middle line:84%
Then I have that, by
how I've chosen N,

01:08:09.180 --> 01:08:15.330 align:middle line:84%
sum over k bigger than
N of v e k squared--

01:08:15.330 --> 01:08:18.750 align:middle line:84%
this is less than
epsilon squared over 4,

01:08:18.750 --> 01:08:21.189 align:middle line:84%
which is less than
epsilon squared.

01:08:21.189 --> 01:08:28.979 align:middle line:84%
And for all 1 less than
or equal to n is less than

01:08:28.979 --> 01:08:30.780 align:middle line:84%
or equal to n minus
1, the same bound.

01:08:30.780 --> 01:08:41.720 align:middle line:90%


01:08:41.720 --> 01:08:45.590 align:middle line:84%
So I just need to check
now that this is small

01:08:45.590 --> 01:08:50.950 align:middle line:84%
when n is bigger
than or equal to M.

01:08:50.950 --> 01:09:02.130 align:middle line:84%
Now, if n is bigger than
or equal to M, by Bessel's

01:09:02.130 --> 01:09:11.250 align:middle line:84%
inequality, we have that
some K bigger than our N v n

01:09:11.250 --> 01:09:17.069 align:middle line:84%
e K squared, if I can
take the 1/2 power

01:09:17.069 --> 01:09:19.630 align:middle line:84%
and show that's
less than epsilon.

01:09:19.630 --> 01:09:35.529 align:middle line:84%
So this is equal to K bigger
than N of v N minus v plus v.

01:09:35.529 --> 01:09:43.340 align:middle line:90%
So I can-- e K plus--

01:09:43.340 --> 01:09:45.080 align:middle line:90%
so let's write it this way.

01:09:45.080 --> 01:09:59.360 align:middle line:90%


01:09:59.360 --> 01:10:04.940 align:middle line:84%
Now, this is the little l2 norm
of a sum of two sequences in K,

01:10:04.940 --> 01:10:08.960 align:middle line:84%
not N, but in K. So by
the triangle inequality

01:10:08.960 --> 01:10:12.380 align:middle line:84%
for sequences in little l2,
this is less than or equal

01:10:12.380 --> 01:10:27.990 align:middle line:84%
to sum K bigger than N of v N
minus v e K 1/2 plus sum from K

01:10:27.990 --> 01:10:38.630 align:middle line:84%
bigger than N of v e
K to the 1/2 power.

01:10:38.630 --> 01:10:42.890 align:middle line:84%
Now, this quantity I
already have control over.

01:10:42.890 --> 01:10:46.610 align:middle line:90%
That's less than epsilon over 2.

01:10:46.610 --> 01:10:48.950 align:middle line:90%
I'm taking the 1/2 power here.

01:10:48.950 --> 01:10:51.300 align:middle line:84%
And I can bound this
by Bessel's inequality.

01:10:51.300 --> 01:10:56.990 align:middle line:84%
This is less than or equal
to norm of v N minus v plus--

01:10:56.990 --> 01:10:59.600 align:middle line:84%
and then using the
bound for this--

01:10:59.600 --> 01:11:01.100 align:middle line:90%
epsilon over 2.

01:11:01.100 --> 01:11:05.210 align:middle line:84%
And now remember, how
is capital M chosen?

01:11:05.210 --> 01:11:08.905 align:middle line:84%
Capital M is chosen to
ensure that this is less

01:11:08.905 --> 01:11:10.280 align:middle line:84%
than epsilon over
2, which we can

01:11:10.280 --> 01:11:12.440 align:middle line:84%
do since the v N's
are converging to v.

01:11:12.440 --> 01:11:17.930 align:middle line:84%
So this is less than epsilon
over 2 plus epsilon over 2

01:11:17.930 --> 01:11:23.600 align:middle line:84%
equals epsilon, proving
that this set consisting

01:11:23.600 --> 01:11:28.610 align:middle line:84%
of the elements of a convergent
sequence along with the limit,

01:11:28.610 --> 01:11:32.190 align:middle line:84%
has equismall tails with respect
to an arbitrary orthonormal

01:11:32.190 --> 01:11:32.690 align:middle line:90%
subset.

01:11:32.690 --> 01:11:34.940 align:middle line:84%
So next time, we
will prove that if we

01:11:34.940 --> 01:11:40.970 align:middle line:84%
have a subset of a separable
Hilbert space which is closed,

01:11:40.970 --> 01:11:43.940 align:middle line:84%
bounded, and has equismall
details with respect

01:11:43.940 --> 01:11:47.930 align:middle line:84%
to A orthonormal
basis, which exists

01:11:47.930 --> 01:11:54.540 align:middle line:84%
because it's a separable Hilbert
space, then the set is compact.

01:11:54.540 --> 01:11:56.850 align:middle line:84%
And then, we'll rephrase
that in a way that

01:11:56.850 --> 01:12:02.157 align:middle line:84%
doesn't involve Hilbert
spaces, and go from there,

01:12:02.157 --> 01:12:03.990 align:middle line:84%
and start looking at
some of these operators

01:12:03.990 --> 01:12:08.210 align:middle line:84%
I said, which are
close to matrices.

01:12:08.210 --> 01:12:10.480 align:middle line:90%
All right, we'll stop there.

01:12:10.480 --> 01:12:17.000 align:middle line:90%