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PAIGE BRIGHT: So
today, in case you

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were thinking that there wasn't
enough theorems on Tuesday,

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we're going to
prove a lot of them

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today on the general
metrics based theory.

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I like this notion of
a theory of the spaces.

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This is a notation that Dr.
Casey Rodriguez taught me,

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loosely speaking,
where you're just

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trying to encapsulate what
are all the things we can say

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about the most fundamental
objects in the space

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that you're considering?

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And essentially, a number of
the theorems that we'll prove

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are essentially the same as what
we would picture in Euclidean

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space, but we have to
be slightly more careful

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sometimes.

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And all of this theory is
going to be building up

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to understanding something
that you probably

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haven't seen before
if you haven't done

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100B, known as compact sets.

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So we're going to be building up
to talking about compact sets.

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But first, we have
to understand what

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are the fundamental
tools in our tool

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belt with metrics based theory?

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And I do want to note one thing.

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Even though last
time, I said we can

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put a metric on every
set, which is true,

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not every set has a
nice metric on it.

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Have any of y'all
taken topology before?

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No worries if not.

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It's a class that usually
comes after real analysis,

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but in topology talk, not
every topological space

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is metrizable-- i.e. there's not
necessarily a metric on it that

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will make the topology nice.

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And we'll talk about what
topology is a little bit today.

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So in case you're interested
in what that statement is,

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we'll come to it,
but the basic idea

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is even though we can put
a metric on every set,

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sometimes the trivial one
is not that interesting.

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So all right.

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Let's go ahead and jump into the
metrics based theory for today.

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So first off, we're
going to be talking

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about convergent sequences,
just like we did in RN.

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So throughout
this, let xn and yn

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be the sequences
we're considering.

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In the first statement theorem,
suppose xn converges to x.

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What should we expect about
the point that it converges to?

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Well, in Euclidean space, we
knew that this limit point

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had to be unique.

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And in fact, we can prove
that this must be the case.

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So then x is unique.

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To prove a statement like this,
we choose a different point y

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in our set to consider.

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So what we're going to show now
is that convergent sequences

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have unique limit points.

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So proof.

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Suppose there exists a y
in your metric space x--

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or I should say sequences
in your metric space xd,

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so metric x with metric d.

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And suppose that
there exists a y

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and x such that
xn converges to y.

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Our end goal is to show then
that x must be equal to y,

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in fact.

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Now, to do this, what do we
know about equality for points?

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Well, by the axioms of what
we're defining a metric space

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to be, two points are
going to be the same

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if the distance is precisely 0.

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It's an if and
only if statement.

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So that's what we want to prove.

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We want to prove that the
distance between x and y is 0.

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So how can we do that?

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Well, firstly, let's
write down what

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the definitions of them
converging to x and y

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is respectively.

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So xn converges to x.

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Means that for all
epsilon bigger than 0,

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there exists an n in
the natural numbers

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such that for all n bigger
than or equal to n--

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and I'll call this n1--

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we have that the distance from
xn to x is less than epsilon.

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This is the definition
of convergent sequence

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that we're dealing with.

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And similarly, xn converges
to y if there exists

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an n2 in the natural numbers
for this epsilon such

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that for n bigger
than or equal to n2,

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the distance from xn to
y is less than epsilon.

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So now, what do we want to do?

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We want to use this to show that
the distance between x and y

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is small.

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And to do this, we
will apply the triangle

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inequality to understand
the distance from x to y.

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So by the triangle
inequality, this

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is less than or equal
to the distance from xn

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to x plus the
distance from xn to y,

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where here I'm applying
symmetry so that I can

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move the terms around, right?

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And we know that for all
epsilon bigger than 0,

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there exists an
n-- let's say this

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is equal to the maximum of n1
and n2 in the natural numbers

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such that both of these terms
are now less than epsilon.

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In fact, you know what?

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To make it nicer, I'll make
this epsilon over 2 both spots.

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So then this is less
than epsilon over 2

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plus epsilon over 2,
which is equal to epsilon.

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Now, does this imply immediately
that the distance between them

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is 0?

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Essentially, we have
to note one more

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thing, which is that distances
are positive definite.

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So this is going to be
bigger than or equal to 0.

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So what this tells you is that
because the distance between x

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and y gets arbitrarily
small and arbitrarily

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small and close to
0, it has to be 0.

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This is from the real number
theory that we already know.

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So this implies that the
distance from x to y is 0.

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And therefore, x is
equal to y, which

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is what we wanted to prove.

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So notice that a lot of
this used all of the axioms

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that we were talking about.

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At one point, we use symmetry,
which wasn't too important,

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but was useful to
note so that we

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can swap xn and x around and
apply the triangle inequality.

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We applied the
triangle inequality,

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and we had to use
positive definiteness.

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So these are the bare
bones of what we really

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need in the theory.

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All right.

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So now what we're
going to do is show

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that not only do limit
points exist nicely,

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but the distances between
limit points act nicely.

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So to state that more
clearly, theorem--

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let y be an x and
xn converge to x.

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Then my claim is that
the distance from xn to y

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will converge from the
distance from x to y,

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which makes relative sense.

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But notice here the statement
is slightly different.

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Before, we were purely
dealing with sequences

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of a metric space.

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And so we had to deal
with the metric d itself.

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But when we're saying that
this converges to d xy,

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what space am I considering
these distances in?

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Anyone?

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No worries.

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We're looking at it in r, right?

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Because for every single n,
this is just a real number.

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And so when I say
the distance from xn

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to y converges to the
distance from x to y,

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I mean that this happens
in Euclidean space.

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And in fact, you can likely--

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I don't want to
state explicitly,

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but I'm pretty
certain can prove this

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as well in a general setting,
so between two metric spaces.

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OK, so let's prove this.

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To do this, ultimately,
we want to show

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that for all epsilon
bigger than 0,

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there exists an n in
the natural numbers

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such that the distance from
xn to y minus the distance

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from x to y is less than
epsilon in absolute values.

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And to do so, we can
just find an upper

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and lower bound on the
distance from xn to y.

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So let's do that.

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The first direction is nice.

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The distance from
xn to y is less than

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or equal to, by the triangle
inequality, the distance

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from xn to x plus the
distance from x to y.

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And we can make this
term arbitrarily small.

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So I'm just going
to choose the same n

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to be the one for this
convergent sequence.

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So this is less than epsilon
plus the distance from x to y.

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So this gives us the upper
bound that we're wanting

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on the distance from xn to y.

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Let's prove the lower bound.

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And the lower bound
is very similar,

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but it's just a slightly
different manipulation, where

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what we're then going to do--

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so the distance from xn to y--

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or actually, I'll look at
the distance from x to y.

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This is less than or
equal to the distance

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from x to xn plus the
distance from x to y.

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And then what we can do
is subtract these terms.

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So specifically, we'll get
that the distance from x

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to y minus the distance
from x to xn is less than

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or equal to the
distance from x to y.

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And we can make this
term arbitrarily small.

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So this is less
than the distance

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from x to y minus epsilon.

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And notice that this
implies the result

00:09:48.290 --> 00:09:53.120 align:middle line:84%
because then we have that the
distance from xn to y is less--

00:09:53.120 --> 00:09:55.530 align:middle line:90%
oh, shoot.

00:09:55.530 --> 00:09:56.550 align:middle line:90%
Did I get this wrong?

00:09:56.550 --> 00:09:58.960 align:middle line:90%


00:09:58.960 --> 00:09:59.460 align:middle line:90%
No, no.

00:09:59.460 --> 00:10:00.030 align:middle line:90%
OK, yeah.

00:10:00.030 --> 00:10:06.080 align:middle line:84%
So then the distance
from xn y is less than--

00:10:06.080 --> 00:10:08.510 align:middle line:84%
sorry, this should be
the distance from x to y.

00:10:08.510 --> 00:10:09.740 align:middle line:90%
There we go.

00:10:09.740 --> 00:10:12.358 align:middle line:90%
The distance from xn to--

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let me double-check this.

00:10:13.400 --> 00:10:20.300 align:middle line:84%
Distance from xn
to y plus xn to y.

00:10:20.300 --> 00:10:21.542 align:middle line:90%
There we go.

00:10:21.542 --> 00:10:22.250 align:middle line:90%
Sorry about that.

00:10:22.250 --> 00:10:25.480 align:middle line:84%
I mixed up what they
were converging to.

00:10:25.480 --> 00:10:28.900 align:middle line:84%
So what this tells us is
that the distance from xn

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to y minus the
distance from x to y

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gets arbitrarily small, right?

00:10:34.420 --> 00:10:36.770 align:middle line:84%
I can write that out,
if y'all would prefer,

00:10:36.770 --> 00:10:38.020 align:middle line:90%
but that's just the next step.

00:10:38.020 --> 00:10:40.760 align:middle line:84%
You write it in terms
of the absolute values.

00:10:40.760 --> 00:10:41.980 align:middle line:90%
OK?

00:10:41.980 --> 00:10:44.840 align:middle line:90%
Any questions?

00:10:44.840 --> 00:10:49.760 align:middle line:84%
So not only are
limit points unique,

00:10:49.760 --> 00:10:51.367 align:middle line:84%
but the distances
between limit points

00:10:51.367 --> 00:10:53.700 align:middle line:84%
are also going to be unique,
at least in the real number

00:10:53.700 --> 00:10:56.150 align:middle line:90%
sense, which is pretty nice.

00:10:56.150 --> 00:10:57.020 align:middle line:90%
I'll remark.

00:10:57.020 --> 00:11:00.510 align:middle line:84%
One proposition, which
is pretty interesting--

00:11:00.510 --> 00:11:03.020 align:middle line:84%
you can study this for two
convergent sequences at once.

00:11:03.020 --> 00:11:08.000 align:middle line:90%


00:11:08.000 --> 00:11:09.290 align:middle line:90%
I'll state this in two parts.

00:11:09.290 --> 00:11:15.660 align:middle line:84%
Suppose xn converges to
x and yn converges to y.

00:11:15.660 --> 00:11:20.960 align:middle line:84%
Then the distance from
xn to yn converges

00:11:20.960 --> 00:11:24.470 align:middle line:90%
to the distance from x to y.

00:11:24.470 --> 00:11:27.230 align:middle line:84%
This relatively makes
sense, but we can also

00:11:27.230 --> 00:11:29.570 align:middle line:84%
state this slightly
differently, or a different type

00:11:29.570 --> 00:11:30.360 align:middle line:90%
of this theorem.

00:11:30.360 --> 00:11:36.590 align:middle line:90%
Suppose xn and yn are Cauchy.

00:11:36.590 --> 00:11:37.935 align:middle line:90%
So they're Cauchy sequences.

00:11:37.935 --> 00:11:39.560 align:middle line:84%
So they get arbitrarily
close together,

00:11:39.560 --> 00:11:44.370 align:middle line:84%
but don't necessarily
have a limit point.

00:11:44.370 --> 00:11:49.580 align:middle line:84%
Then we know that the distance
from x to yn converges.

00:11:49.580 --> 00:11:52.800 align:middle line:90%


00:11:52.800 --> 00:11:55.530 align:middle line:84%
Notice that I'm not saying
what it converges to.

00:11:55.530 --> 00:11:58.200 align:middle line:84%
I don't know that Cauchy
sequences have limit points

00:11:58.200 --> 00:12:00.455 align:middle line:90%
in my metric space.

00:12:00.455 --> 00:12:02.080 align:middle line:84%
And we'll get back
to that in a moment.

00:12:02.080 --> 00:12:05.130 align:middle line:84%
But nonetheless, the sequence
itself in the real numbers

00:12:05.130 --> 00:12:06.120 align:middle line:90%
will converge.

00:12:06.120 --> 00:12:08.880 align:middle line:84%
And that uses the fact that
the real numbers is Cauchy

00:12:08.880 --> 00:12:10.347 align:middle line:90%
complete.

00:12:10.347 --> 00:12:12.180 align:middle line:84%
Now, I'm not going to
prove these two facts.

00:12:12.180 --> 00:12:15.127 align:middle line:84%
These are facts that
are on your problem set,

00:12:15.127 --> 00:12:17.460 align:middle line:84%
but I do want to point out--
because this happened a lot

00:12:17.460 --> 00:12:18.103 align:middle line:90%
last year--

00:12:18.103 --> 00:12:20.520 align:middle line:84%
you cannot assume that the
limit points in the second part

00:12:20.520 --> 00:12:21.600 align:middle line:90%
exist.

00:12:21.600 --> 00:12:25.290 align:middle line:84%
You can note that this
implication implies the top one

00:12:25.290 --> 00:12:29.130 align:middle line:84%
by uniqueness because convergent
sequences are Cauchy, as we're

00:12:29.130 --> 00:12:31.180 align:middle line:90%
going to prove right now.

00:12:31.180 --> 00:12:32.730 align:middle line:84%
So if you prove the
second one first,

00:12:32.730 --> 00:12:34.325 align:middle line:84%
then you can make
a small remark.

00:12:34.325 --> 00:12:35.700 align:middle line:84%
You have to explain
why the limit

00:12:35.700 --> 00:12:38.860 align:middle line:84%
point is the distance from x
to y, but that's not too bad.

00:12:38.860 --> 00:12:44.282 align:middle line:90%
So let's prove that theorem.

00:12:44.282 --> 00:12:45.990 align:middle line:84%
Is that the next
theorem I wanted to say?

00:12:45.990 --> 00:12:52.690 align:middle line:90%


00:12:52.690 --> 00:12:55.850 align:middle line:90%
Yeah, I'll do that one now.

00:12:55.850 --> 00:13:01.700 align:middle line:90%
Cauchy sequences-- ope, sorry.

00:13:01.700 --> 00:13:11.510 align:middle line:84%
Convergent sequences
are Cauchy sequences.

00:13:11.510 --> 00:13:17.220 align:middle line:90%


00:13:17.220 --> 00:13:21.450 align:middle line:84%
Suppose xn is the convergent
sequence we're considering,

00:13:21.450 --> 00:13:24.550 align:middle line:90%
and that xn converges to x.

00:13:24.550 --> 00:13:26.293 align:middle line:90%
Then we know that--

00:13:26.293 --> 00:13:28.210 align:middle line:84%
and I'm going to say
this over and over again,

00:13:28.210 --> 00:13:29.600 align:middle line:84%
just like we do
in real analysis,

00:13:29.600 --> 00:13:32.980 align:middle line:84%
but at a certain point, it just
becomes second-hand nature--

00:13:32.980 --> 00:13:35.380 align:middle line:84%
so therefore, for all
epsilon bigger than 0,

00:13:35.380 --> 00:13:38.860 align:middle line:84%
there exists n in
the natural numbers

00:13:38.860 --> 00:13:47.260 align:middle line:84%
such that for all n
bigger than or equal to n,

00:13:47.260 --> 00:13:51.800 align:middle line:84%
the distance from xn to
x is less than epsilon.

00:13:51.800 --> 00:13:53.690 align:middle line:90%
So what does this tell us?

00:13:53.690 --> 00:13:56.320 align:middle line:84%
Well, what we're
ultimately interested in

00:13:56.320 --> 00:14:00.460 align:middle line:84%
is the distance from
xn to xm, right?

00:14:00.460 --> 00:14:04.840 align:middle line:84%
Let m be bigger
than or equal to n.

00:14:04.840 --> 00:14:07.240 align:middle line:84%
What we're interested in
is the distance from xn

00:14:07.240 --> 00:14:10.220 align:middle line:84%
to xm to state that
it's a Cauchy sequence.

00:14:10.220 --> 00:14:12.765 align:middle line:90%
So what can we do?

00:14:12.765 --> 00:14:13.265 align:middle line:90%
Anyone?

00:14:13.265 --> 00:14:18.516 align:middle line:90%


00:14:18.516 --> 00:14:22.098 align:middle line:84%
Want y'all to think about it
because we want to bound this

00:14:22.098 --> 00:14:23.765 align:middle line:84%
and show that this
is less than epsilon.

00:14:23.765 --> 00:14:27.560 align:middle line:90%


00:14:27.560 --> 00:14:28.810 align:middle line:90%
AUDIENCE: Triangle inequality.

00:14:28.810 --> 00:14:29.727 align:middle line:90%
PAIGE BRIGHT: Exactly.

00:14:29.727 --> 00:14:30.740 align:middle line:90%
The triangle inequality.

00:14:30.740 --> 00:14:32.823 align:middle line:84%
This is less than or equal
to the distance from xn

00:14:32.823 --> 00:14:40.720 align:middle line:84%
to x plus the
distance from x to xm.

00:14:40.720 --> 00:14:42.925 align:middle line:84%
And we can make both of
these less than epsilon.

00:14:42.925 --> 00:14:45.397 align:middle line:90%


00:14:45.397 --> 00:14:47.980 align:middle line:84%
Now, if I was really careful, I
could have made these epsilons

00:14:47.980 --> 00:14:48.970 align:middle line:90%
over 2.

00:14:48.970 --> 00:14:50.887 align:middle line:84%
And then this would have
been exactly epsilon.

00:14:50.887 --> 00:14:53.428 align:middle line:84%
Most of the time, if you show
it's less than a constant times

00:14:53.428 --> 00:14:54.310 align:middle line:90%
epsilon, you're good.

00:14:54.310 --> 00:14:55.893 align:middle line:84%
You would just have
to relabel things.

00:14:55.893 --> 00:14:57.670 align:middle line:90%
So all good things here.

00:14:57.670 --> 00:14:58.510 align:middle line:90%
But yeah, exactly.

00:14:58.510 --> 00:15:01.190 align:middle line:84%
You apply the
triangle inequality.

00:15:01.190 --> 00:15:01.690 align:middle line:90%
Oh.

00:15:01.690 --> 00:15:03.400 align:middle line:84%
And then this is
precisely what we want

00:15:03.400 --> 00:15:04.600 align:middle line:90%
for Cauchy sequence, right?

00:15:04.600 --> 00:15:09.150 align:middle line:84%
This implies that it is,
in fact, a Cauchy sequence.

00:15:09.150 --> 00:15:11.670 align:middle line:90%
So we're done.

00:15:11.670 --> 00:15:14.780 align:middle line:84%
Now, the real question is, if
Cauchy sequences are convergent

00:15:14.780 --> 00:15:19.100 align:middle line:84%
sequences-- and as we know
from the real numbers,

00:15:19.100 --> 00:15:21.470 align:middle line:84%
from the real numbers, we
know that there it's Cauchy

00:15:21.470 --> 00:15:23.067 align:middle line:90%
complete, but here we don't.

00:15:23.067 --> 00:15:24.650 align:middle line:84%
And what do I mean
by Cauchy complete,

00:15:24.650 --> 00:15:26.570 align:middle line:90%
which I've stated a few times?

00:15:26.570 --> 00:15:39.680 align:middle line:84%
Definition-- a space is Cauchy
complete if and only if-- i.e.

00:15:39.680 --> 00:15:48.010 align:middle line:84%
the definition-- the Cauchy
sequences are convergent.

00:15:48.010 --> 00:15:53.313 align:middle line:90%


00:15:53.313 --> 00:15:55.730 align:middle line:84%
So this is the definition of
what Cauchy complete actually

00:15:55.730 --> 00:15:56.420 align:middle line:90%
means.

00:15:56.420 --> 00:15:58.460 align:middle line:84%
And this is a very
powerful fact, right?

00:15:58.460 --> 00:16:01.970 align:middle line:84%
We use Cauchy completeness
everywhere in real analysis

00:16:01.970 --> 00:16:03.620 align:middle line:84%
to state that
limit points exist,

00:16:03.620 --> 00:16:05.600 align:middle line:84%
to state that
differentiability was nice.

00:16:05.600 --> 00:16:08.450 align:middle line:84%
Things like that-- we needed
Cauchy completeness there.

00:16:08.450 --> 00:16:11.060 align:middle line:84%
Now, not every space is Cauchy
complete, unfortunately,

00:16:11.060 --> 00:16:14.510 align:middle line:84%
but the ones that we really
want them to be are, in fact.

00:16:14.510 --> 00:16:19.070 align:middle line:84%
So proposition-- this
is on your homework--

00:16:19.070 --> 00:16:27.260 align:middle line:84%
we have that yeah, the set of
continuous functions on 0 to 1

00:16:27.260 --> 00:16:28.160 align:middle line:90%
is Cauchy complete.

00:16:28.160 --> 00:16:34.360 align:middle line:90%


00:16:34.360 --> 00:16:36.970 align:middle line:84%
This is a statement
on your homework

00:16:36.970 --> 00:16:39.110 align:middle line:84%
that I've broken up
into individual steps.

00:16:39.110 --> 00:16:41.950 align:middle line:84%
So this should be
a little bit nicer.

00:16:41.950 --> 00:16:45.775 align:middle line:84%
But yeah, a very useful
proposition to show.

00:16:45.775 --> 00:16:47.170 align:middle line:90%
OK.

00:16:47.170 --> 00:16:51.000 align:middle line:84%
Now, let me go back to what I
meant to do slightly earlier.

00:16:51.000 --> 00:16:51.990 align:middle line:90%
OK.

00:16:51.990 --> 00:16:55.560 align:middle line:84%
We have a few more things to
say about convergent sequences.

00:16:55.560 --> 00:16:57.570 align:middle line:84%
And to do so, I'm going
to define what it means

00:16:57.570 --> 00:16:59.010 align:middle line:90%
for a set to be bounded, right?

00:16:59.010 --> 00:17:00.660 align:middle line:84%
When we are looking
at real analysis,

00:17:00.660 --> 00:17:03.090 align:middle line:84%
one of the most useful theorems
we had in our tool belt

00:17:03.090 --> 00:17:05.085 align:middle line:84%
was the Bolzano-Weierstrass
theorem.

00:17:05.085 --> 00:17:06.960 align:middle line:84%
Now, we're not going to
have an analog of it,

00:17:06.960 --> 00:17:09.030 align:middle line:84%
but we still have some
statements akin to it

00:17:09.030 --> 00:17:10.499 align:middle line:90%
that we want to show.

00:17:10.499 --> 00:17:12.180 align:middle line:84%
And this will be
especially important

00:17:12.180 --> 00:17:14.790 align:middle line:90%
as we build up to compact sets.

00:17:14.790 --> 00:17:27.060 align:middle line:84%
So definition-- a sequence
xn is bounded by, let's say,

00:17:27.060 --> 00:17:33.850 align:middle line:84%
b bigger than 0 if, for all
n in the natural numbers--

00:17:33.850 --> 00:17:37.990 align:middle line:90%


00:17:37.990 --> 00:17:38.490 align:middle line:90%
oh, sorry.

00:17:38.490 --> 00:17:44.970 align:middle line:84%
I should say if there exists
a point p in your metrics

00:17:44.970 --> 00:17:50.250 align:middle line:84%
base such that for all
n in the natural numbers

00:17:50.250 --> 00:17:54.360 align:middle line:84%
the distance from xn
to p is less than B--

00:17:54.360 --> 00:17:55.690 align:middle line:90%
which is what we would expect.

00:17:55.690 --> 00:17:59.880 align:middle line:84%
We want the sequence
itself to be--

00:17:59.880 --> 00:18:03.690 align:middle line:84%
the distance between the
point and your sequence

00:18:03.690 --> 00:18:04.650 align:middle line:90%
to be bounded.

00:18:04.650 --> 00:18:07.380 align:middle line:84%
That's what it means for
a sequence to be bounded.

00:18:07.380 --> 00:18:10.500 align:middle line:84%
And if you want to
picture this, I always

00:18:10.500 --> 00:18:12.960 align:middle line:84%
like to draw little pictures
in my notes about this.

00:18:12.960 --> 00:18:16.230 align:middle line:84%
If this is our metric space
x, here's our point p.

00:18:16.230 --> 00:18:18.480 align:middle line:84%
And what this is
stating is that there

00:18:18.480 --> 00:18:26.640 align:middle line:84%
exists a radius large enough
of radius B such that it

00:18:26.640 --> 00:18:29.210 align:middle line:90%
completely contains x.

00:18:29.210 --> 00:18:31.760 align:middle line:84%
Now, granted, what does it mean
to have stuff outside of x?

00:18:31.760 --> 00:18:32.510 align:middle line:90%
Nothing, really.

00:18:32.510 --> 00:18:36.740 align:middle line:84%
So really, we just mean
the region in the middle

00:18:36.740 --> 00:18:39.860 align:middle line:84%
is contained in the
ball of radius B.

00:18:39.860 --> 00:18:42.470 align:middle line:84%
But that's a nice
picture, if you prefer.

00:18:42.470 --> 00:18:47.610 align:middle line:84%
And not only can we say this
about sequences in general,

00:18:47.610 --> 00:18:50.405 align:middle line:84%
we can also define what
this means for a set.

00:18:50.405 --> 00:19:09.740 align:middle line:84%
A set A in x is bounded
by B if, for all p in x--

00:19:09.740 --> 00:19:10.240 align:middle line:90%
oh, sorry.

00:19:10.240 --> 00:19:15.040 align:middle line:84%
If there exists a p in
x such that for all A

00:19:15.040 --> 00:19:20.650 align:middle line:84%
in A the distance
from A to p is less

00:19:20.650 --> 00:19:25.485 align:middle line:84%
than B. Does the set
theory notation that I'm

00:19:25.485 --> 00:19:26.610 align:middle line:90%
using make sense, everyone?

00:19:26.610 --> 00:19:28.740 align:middle line:90%
There exists, and for all?

00:19:28.740 --> 00:19:29.560 align:middle line:90%
Cool.

00:19:29.560 --> 00:19:31.560 align:middle line:84%
So this is what it means
for a sequence in a set

00:19:31.560 --> 00:19:32.247 align:middle line:90%
to be bounded.

00:19:32.247 --> 00:19:33.330 align:middle line:90%
Why would I bring this up?

00:19:33.330 --> 00:19:36.270 align:middle line:84%
Because convergent sequences
are bounded sequences.

00:19:36.270 --> 00:19:38.130 align:middle line:90%
We have this from real analysis.

00:19:38.130 --> 00:19:41.430 align:middle line:84%
But I'm going to prove
it now in metric spaces.

00:19:41.430 --> 00:19:48.690 align:middle line:84%
So proposition-- or
I'll just write it

00:19:48.690 --> 00:19:50.670 align:middle line:84%
out how I've been writing
out the other ones.

00:19:50.670 --> 00:19:58.185 align:middle line:84%
If xn converges to x, then
xn is the bounded sequence.

00:19:58.185 --> 00:20:02.960 align:middle line:90%


00:20:02.960 --> 00:20:04.472 align:middle line:90%
OK.

00:20:04.472 --> 00:20:06.680 align:middle line:84%
Let's start off with the
proof, which will start off,

00:20:06.680 --> 00:20:08.720 align:middle line:84%
as all of our
statements have so far,

00:20:08.720 --> 00:20:12.898 align:middle line:84%
with the statement of
what convergence means.

00:20:12.898 --> 00:20:14.690 align:middle line:84%
In the statement of
what convergence means,

00:20:14.690 --> 00:20:15.680 align:middle line:84%
we're going to
choose the epsilon

00:20:15.680 --> 00:20:17.138 align:middle line:84%
that I want so that
I'm not dealing

00:20:17.138 --> 00:20:18.600 align:middle line:90%
with all the possible epsilons.

00:20:18.600 --> 00:20:25.310 align:middle line:84%
So I'm going to note for epsilon
equal to 1 bigger than 0,

00:20:25.310 --> 00:20:28.550 align:middle line:84%
we know that there exists
an n in the natural numbers

00:20:28.550 --> 00:20:36.800 align:middle line:84%
such that for all n
bigger than or equal to n,

00:20:36.800 --> 00:20:42.570 align:middle line:84%
the distance from xn to
x is less than epsilon,

00:20:42.570 --> 00:20:45.060 align:middle line:90%
which again, I'm assuming is 1.

00:20:45.060 --> 00:20:47.620 align:middle line:84%
Now, does this
complete our statement?

00:20:47.620 --> 00:20:49.170 align:middle line:90%
The answer is no.

00:20:49.170 --> 00:20:52.650 align:middle line:84%
Here we only have that this
is true for all n bigger than

00:20:52.650 --> 00:20:55.350 align:middle line:90%
or equal to capital N, right?

00:20:55.350 --> 00:20:58.650 align:middle line:84%
But what we want
for our statement is

00:20:58.650 --> 00:21:01.110 align:middle line:84%
to show that for every
single natural number,

00:21:01.110 --> 00:21:02.580 align:middle line:90%
this sequence is bounded.

00:21:02.580 --> 00:21:06.270 align:middle line:84%
But this isn't an issue
because what we can note

00:21:06.270 --> 00:21:09.330 align:middle line:84%
is that there are finitely
many terms less than n

00:21:09.330 --> 00:21:11.700 align:middle line:90%
in the natural numbers, right?

00:21:11.700 --> 00:21:17.610 align:middle line:84%
So what we can do is
that B be the maximum

00:21:17.610 --> 00:21:22.080 align:middle line:84%
of the finitely many
terms of the distance

00:21:22.080 --> 00:21:34.830 align:middle line:84%
from xi to x, or, let's
say, 1 for i between 1

00:21:34.830 --> 00:21:38.010 align:middle line:84%
and capital N. So
what I'm doing here

00:21:38.010 --> 00:21:41.460 align:middle line:84%
is I'm noting that here I
have my convergent sequence.

00:21:41.460 --> 00:21:44.500 align:middle line:90%


00:21:44.500 --> 00:21:46.450 align:middle line:90%
I know that most of them--

00:21:46.450 --> 00:21:48.520 align:middle line:84%
in fact, infinitely
many of them--

00:21:48.520 --> 00:21:54.320 align:middle line:84%
are contained in a
ball of radius 1.

00:21:54.320 --> 00:21:58.962 align:middle line:84%
And I only have finitely many
terms outside of that ball.

00:21:58.962 --> 00:22:00.920 align:middle line:84%
So what I'm doing is I'm
saying, OK, well, it's

00:22:00.920 --> 00:22:05.690 align:middle line:84%
either in this ball, or in
the next one, or the next one,

00:22:05.690 --> 00:22:07.520 align:middle line:90%
or so on and so forth.

00:22:07.520 --> 00:22:10.700 align:middle line:84%
This is what the statement
is that we wanted to show.

00:22:10.700 --> 00:22:13.880 align:middle line:84%
And we know that this
is, in fact, finite,

00:22:13.880 --> 00:22:16.050 align:middle line:84%
as there is only
finitely many terms.

00:22:16.050 --> 00:22:19.202 align:middle line:84%
So this is the B
that it's bounded by.

00:22:19.202 --> 00:22:21.410 align:middle line:84%
I can write that out some
more if y'all would prefer,

00:22:21.410 --> 00:22:24.510 align:middle line:84%
but this is essentially
the statement.

00:22:24.510 --> 00:22:26.480 align:middle line:90%
Cool.

00:22:26.480 --> 00:22:29.803 align:middle line:90%
So I think that's mostly--

00:22:29.803 --> 00:22:31.220 align:middle line:84%
oh, there's one
more thing we want

00:22:31.220 --> 00:22:34.550 align:middle line:84%
to say about convergent
sequences, which

00:22:34.550 --> 00:22:37.010 align:middle line:84%
is that their
subsequences act nicely,

00:22:37.010 --> 00:22:40.290 align:middle line:84%
which will be essentially
how we want it to be.

00:22:40.290 --> 00:22:52.096 align:middle line:84%
So proposition-- let xn
converge to x and xnk

00:22:52.096 --> 00:22:58.320 align:middle line:90%
be a subsequence of xn.

00:22:58.320 --> 00:23:01.370 align:middle line:90%


00:23:01.370 --> 00:23:08.420 align:middle line:84%
Then my claim is that
xnk is convergent.

00:23:08.420 --> 00:23:12.890 align:middle line:90%


00:23:12.890 --> 00:23:14.738 align:middle line:84%
And in fact, to show
that it's convergent,

00:23:14.738 --> 00:23:16.280 align:middle line:84%
we're going to show
that it converges

00:23:16.280 --> 00:23:19.820 align:middle line:84%
to x, which is what we should
expect of a subsequence.

00:23:19.820 --> 00:23:22.010 align:middle line:84%
Does everyone here know
what a subsequence is?

00:23:22.010 --> 00:23:25.420 align:middle line:90%
Happy to redefine.

00:23:25.420 --> 00:23:27.610 align:middle line:90%
Cool.

00:23:27.610 --> 00:23:29.660 align:middle line:90%
So let's go with this statement.

00:23:29.660 --> 00:23:33.393 align:middle line:84%
So proof-- notice that my
subsequence here is arbitrary.

00:23:33.393 --> 00:23:34.810 align:middle line:84%
I'm not going to
rewrite that out,

00:23:34.810 --> 00:23:37.630 align:middle line:84%
but we could choose any
subsequence of our sequence.

00:23:37.630 --> 00:23:42.970 align:middle line:84%
And what we're interested in is
we want to show for all epsilon

00:23:42.970 --> 00:23:47.170 align:middle line:84%
bigger than 0, there exists
an n in the natural numbers

00:23:47.170 --> 00:23:54.200 align:middle line:84%
such that for all nk now
bigger than or equal to n,

00:23:54.200 --> 00:23:58.880 align:middle line:84%
the distance from xnk to
x is less than epsilon.

00:23:58.880 --> 00:24:01.480 align:middle line:90%


00:24:01.480 --> 00:24:05.490 align:middle line:84%
And now, again, any guesses
as to what we should do?

00:24:05.490 --> 00:24:06.330 align:middle line:90%
Triangle inequality.

00:24:06.330 --> 00:24:07.290 align:middle line:90%
Precisely.

00:24:07.290 --> 00:24:07.860 align:middle line:90%
Yeah.

00:24:07.860 --> 00:24:12.240 align:middle line:84%
So we're considering the
distance from xnk to x.

00:24:12.240 --> 00:24:15.000 align:middle line:84%
What we can do is apply the fact
that we know that convergent

00:24:15.000 --> 00:24:17.640 align:middle line:90%
sequences are Cauchy.

00:24:17.640 --> 00:24:21.240 align:middle line:84%
So we can write
this as less than

00:24:21.240 --> 00:24:24.210 align:middle line:84%
or equal to the
distance from xnk,

00:24:24.210 --> 00:24:31.830 align:middle line:84%
let's say, to xm for m
bigger than or equal to n

00:24:31.830 --> 00:24:37.020 align:middle line:90%
plus the distance from xm to x.

00:24:37.020 --> 00:24:39.630 align:middle line:84%
And now, I can choose a larger
natural number, if necessary,

00:24:39.630 --> 00:24:42.420 align:middle line:84%
such that this term gets
less than epsilon over 2.

00:24:42.420 --> 00:24:45.720 align:middle line:84%
And this term, because it's
Cauchy, is less than epsilon

00:24:45.720 --> 00:24:46.920 align:middle line:90%
over 2.

00:24:46.920 --> 00:24:49.110 align:middle line:84%
So without writing
all those steps,

00:24:49.110 --> 00:24:50.295 align:middle line:90%
this is less than epsilon.

00:24:50.295 --> 00:24:53.260 align:middle line:90%


00:24:53.260 --> 00:24:55.620 align:middle line:84%
So this shows that the
distance from xnk to x

00:24:55.620 --> 00:24:57.100 align:middle line:90%
gets arbitrarily small.

00:24:57.100 --> 00:24:58.410 align:middle line:90%
So therefore, it's convergent.

00:24:58.410 --> 00:25:01.300 align:middle line:90%


00:25:01.300 --> 00:25:03.220 align:middle line:90%
Yeah.

00:25:03.220 --> 00:25:07.150 align:middle line:90%
This is fairly important.

00:25:07.150 --> 00:25:08.740 align:middle line:84%
And it highlights
one of the many ways

00:25:08.740 --> 00:25:11.530 align:middle line:84%
in which Cauchy sequences are
deeply important, as we'll

00:25:11.530 --> 00:25:14.560 align:middle line:84%
talk about in the fifth
lecture in the specific module

00:25:14.560 --> 00:25:16.540 align:middle line:90%
of this class.

00:25:16.540 --> 00:25:18.495 align:middle line:84%
Having things be Cauchy
complete-- really,

00:25:18.495 --> 00:25:19.120 align:middle line:90%
really helpful.

00:25:19.120 --> 00:25:23.400 align:middle line:90%


00:25:23.400 --> 00:25:24.930 align:middle line:90%
OK.

00:25:24.930 --> 00:25:25.950 align:middle line:90%
Oh, one more note.

00:25:25.950 --> 00:25:29.070 align:middle line:84%
This is something that I
vaguely noted on Tuesday,

00:25:29.070 --> 00:25:33.240 align:middle line:84%
but these are all of the major
theorems and propositions

00:25:33.240 --> 00:25:35.610 align:middle line:84%
that we're going to need
for convergent sequences.

00:25:35.610 --> 00:25:37.830 align:middle line:84%
You might be wondering
why there aren't more.

00:25:37.830 --> 00:25:39.760 align:middle line:84%
We had a ton more
in real analysis.

00:25:39.760 --> 00:25:42.260 align:middle line:84%
In fact, it took a
month of our time.

00:25:42.260 --> 00:25:44.940 align:middle line:84%
The reason we don't have more
is because the real numbers

00:25:44.940 --> 00:25:46.238 align:middle line:90%
are a vector space.

00:25:46.238 --> 00:25:48.280 align:middle line:84%
I can add two real numbers
and get a real number.

00:25:48.280 --> 00:25:50.130 align:middle line:84%
I can multiply them
and get a real number.

00:25:50.130 --> 00:25:53.290 align:middle line:84%
Everything there was nicer,
and we had addition defined.

00:25:53.290 --> 00:25:56.220 align:middle line:84%
So one thing we could
state in real analysis

00:25:56.220 --> 00:25:59.430 align:middle line:84%
is that for instance, the sum
of two convergent sequences

00:25:59.430 --> 00:26:00.480 align:middle line:90%
is convergent.

00:26:00.480 --> 00:26:02.295 align:middle line:84%
Here that doesn't make
sense, necessarily.

00:26:02.295 --> 00:26:05.520 align:middle line:84%
You can't always add two
points in a metric space

00:26:05.520 --> 00:26:07.500 align:middle line:84%
and get a point in
your metric space,

00:26:07.500 --> 00:26:10.590 align:middle line:84%
let alone have addition
be well defined.

00:26:10.590 --> 00:26:13.290 align:middle line:84%
Similarly, we have the squeeze
theorem in real analysis.

00:26:13.290 --> 00:26:16.620 align:middle line:84%
We have a version of it
based off of distances,

00:26:16.620 --> 00:26:20.100 align:middle line:84%
but we don't have a
squeeze theorem for points

00:26:20.100 --> 00:26:22.630 align:middle line:84%
because we don't necessarily
have an ordering on our set,

00:26:22.630 --> 00:26:23.130 align:middle line:90%
right?

00:26:23.130 --> 00:26:24.810 align:middle line:84%
You can picture the
complex numbers.

00:26:24.810 --> 00:26:28.482 align:middle line:84%
The complex numbers don't
have an ordering on them.

00:26:28.482 --> 00:26:30.690 align:middle line:84%
You don't have a sense in
which one complex number is

00:26:30.690 --> 00:26:32.880 align:middle line:90%
bigger than the other.

00:26:32.880 --> 00:26:34.797 align:middle line:84%
Yeah, I'm just going
to leave it there.

00:26:34.797 --> 00:26:36.630 align:middle line:84%
If you've done complex
analysis, then you'll

00:26:36.630 --> 00:26:39.210 align:middle line:90%
know what I'm talking about.

00:26:39.210 --> 00:26:40.410 align:middle line:90%
But yeah.

00:26:40.410 --> 00:26:43.180 align:middle line:84%
So that's why we don't have
more theorems as we used to.

00:26:43.180 --> 00:26:45.840 align:middle line:84%
So now, we're going to move
on to the next major theorem

00:26:45.840 --> 00:26:48.450 align:middle line:84%
that I've talked about, or the
next major definition that I've

00:26:48.450 --> 00:26:48.930 align:middle line:90%
talked about.

00:26:48.930 --> 00:26:50.610 align:middle line:84%
We've talked about
convergent sequences.

00:26:50.610 --> 00:26:53.010 align:middle line:84%
We've talked a little bit
about Cauchy sequences.

00:26:53.010 --> 00:26:55.740 align:middle line:84%
Cauchy sequences are helpful,
but in terms of a metric space,

00:26:55.740 --> 00:26:59.280 align:middle line:84%
we've mostly stated what we
need for the moment being.

00:26:59.280 --> 00:27:01.023 align:middle line:84%
Now, we're going to
move on to open sets.

00:27:01.023 --> 00:27:02.940 align:middle line:84%
So I'm going to recall
what this definition is

00:27:02.940 --> 00:27:05.670 align:middle line:84%
because it's the one that can
be a little bit the weirdest.

00:27:05.670 --> 00:27:19.440 align:middle line:84%
So recall-- a set A contained
in your metric space x is open

00:27:19.440 --> 00:27:24.720 align:middle line:84%
if, for every single point
in A, there exists an epsilon

00:27:24.720 --> 00:27:28.890 align:middle line:84%
bigger than 0 such that the
ball of radius epsilon around A

00:27:28.890 --> 00:27:31.530 align:middle line:84%
is completely
contained in your set.

00:27:31.530 --> 00:27:36.120 align:middle line:84%
And this is the set of y
in your metric space such

00:27:36.120 --> 00:27:41.707 align:middle line:84%
that the distance from y
to A is less than epsilon.

00:27:41.707 --> 00:27:43.290 align:middle line:84%
Just to bring it up
because sometimes,

00:27:43.290 --> 00:27:45.720 align:middle line:84%
the notation comes
up, this is also

00:27:45.720 --> 00:27:50.310 align:middle line:84%
sometimes denoted the ball
around A of radius epsilon.

00:27:50.310 --> 00:27:54.210 align:middle line:84%
So use whichever
notation you prefer.

00:27:54.210 --> 00:27:56.320 align:middle line:84%
Here-- I can lift
it a little bit up.

00:27:56.320 --> 00:27:59.100 align:middle line:84%
So use whichever
notation you prefer.

00:27:59.100 --> 00:28:02.130 align:middle line:84%
I prefer this one
just because it means

00:28:02.130 --> 00:28:05.880 align:middle line:90%
less commas, but whichever.

00:28:05.880 --> 00:28:07.560 align:middle line:90%
OK.

00:28:07.560 --> 00:28:11.760 align:middle line:84%
So open sets are going
to have a huge connection

00:28:11.760 --> 00:28:14.430 align:middle line:84%
between topology,
and continuity,

00:28:14.430 --> 00:28:17.823 align:middle line:84%
and other definitions
that are important.

00:28:17.823 --> 00:28:19.740 align:middle line:84%
Now, the first thing
that we're going to prove

00:28:19.740 --> 00:28:22.480 align:middle line:84%
is topological
properties of open sets.

00:28:22.480 --> 00:28:25.180 align:middle line:84%
So because y'all haven't taken
topology, this is, in fact,

00:28:25.180 --> 00:28:26.200 align:middle line:90%
really, really helpful.

00:28:26.200 --> 00:28:29.310 align:middle line:84%
We're going to show three
major properties of open sets

00:28:29.310 --> 00:28:31.090 align:middle line:90%
in metric spaces.

00:28:31.090 --> 00:28:37.660 align:middle line:84%
So a theorem-- and you can call
this topological properties,

00:28:37.660 --> 00:28:40.120 align:middle line:90%
if you want.

00:28:40.120 --> 00:28:41.590 align:middle line:90%
Or I'll write it out because--

00:28:41.590 --> 00:28:49.955 align:middle line:84%
topological properties
of open sets.

00:28:49.955 --> 00:28:54.495 align:middle line:90%


00:28:54.495 --> 00:28:54.995 align:middle line:90%
OK.

00:28:54.995 --> 00:28:58.130 align:middle line:84%
Firstly, we have
that the empty set

00:28:58.130 --> 00:29:01.685 align:middle line:84%
and the entire metric
space itself are open.

00:29:01.685 --> 00:29:04.950 align:middle line:90%


00:29:04.950 --> 00:29:19.700 align:middle line:84%
Two, given Ai are open sets,
then the union of all of these

00:29:19.700 --> 00:29:23.030 align:middle line:84%
sets from i equals, let's
say, 1 to infinity--

00:29:23.030 --> 00:29:25.090 align:middle line:90%
or I'll just use 0, why not--

00:29:25.090 --> 00:29:26.210 align:middle line:90%
is open.

00:29:26.210 --> 00:29:31.610 align:middle line:84%
So in other words, the arbitrary
union of open sets is open.

00:29:31.610 --> 00:29:45.900 align:middle line:84%
And finally, the finite
intersections of open sets

00:29:45.900 --> 00:29:46.400 align:middle line:90%
are open.

00:29:46.400 --> 00:29:51.260 align:middle line:90%


00:29:51.260 --> 00:29:54.260 align:middle line:84%
In other words, if
I intersect from i

00:29:54.260 --> 00:30:01.270 align:middle line:84%
equals 0 to capital M of
Ai, then this is open.

00:30:01.270 --> 00:30:04.030 align:middle line:84%
The fact that we can't intersect
infinitely many of them

00:30:04.030 --> 00:30:06.650 align:middle line:84%
will become apparent
in the proof.

00:30:06.650 --> 00:30:08.680 align:middle line:84%
So in the proof of
these three properties,

00:30:08.680 --> 00:30:10.180 align:middle line:84%
it will become
apparent why we can't

00:30:10.180 --> 00:30:12.520 align:middle line:90%
do infinitely many of them.

00:30:12.520 --> 00:30:13.330 align:middle line:90%
But let's see this.

00:30:13.330 --> 00:30:18.670 align:middle line:90%


00:30:18.670 --> 00:30:21.970 align:middle line:90%
One, so consider the empty set.

00:30:21.970 --> 00:30:24.040 align:middle line:84%
How do we know that
the empty set is open?

00:30:24.040 --> 00:30:26.620 align:middle line:90%
Well, it's vacuously true.

00:30:26.620 --> 00:30:28.990 align:middle line:84%
It's true all the time
because for every single point

00:30:28.990 --> 00:30:31.430 align:middle line:84%
in the empty set, there are
no points in the empty set.

00:30:31.430 --> 00:30:33.490 align:middle line:84%
So as soon as that
statement's false,

00:30:33.490 --> 00:30:36.370 align:middle line:84%
we have that the
empty set is open.

00:30:36.370 --> 00:30:38.620 align:middle line:90%
So this is open vacuously.

00:30:38.620 --> 00:30:41.500 align:middle line:90%


00:30:41.500 --> 00:30:43.840 align:middle line:90%
Two, let's consider the set x.

00:30:43.840 --> 00:30:47.740 align:middle line:90%
Well, for all epsilon--

00:30:47.740 --> 00:30:50.320 align:middle line:84%
or sorry, for every
single point x

00:30:50.320 --> 00:30:54.250 align:middle line:84%
in x, does there exist
a ball around x in x?

00:30:54.250 --> 00:30:59.500 align:middle line:84%
Yes, there is because just pick
your favorite epsilon bigger

00:30:59.500 --> 00:31:00.580 align:middle line:90%
than 0.

00:31:00.580 --> 00:31:03.550 align:middle line:84%
And then the ball of radius
epsilon around that point

00:31:03.550 --> 00:31:07.570 align:middle line:84%
x is, by definition, a subset
of your metric space, right?

00:31:07.570 --> 00:31:10.870 align:middle line:84%
Because the definition of
a ball of radius epsilon

00:31:10.870 --> 00:31:12.117 align:middle line:90%
is only the point in x.

00:31:12.117 --> 00:31:14.200 align:middle line:84%
So we're not going to end
up with some weird thing

00:31:14.200 --> 00:31:16.660 align:middle line:90%
outside of x.

00:31:16.660 --> 00:31:21.040 align:middle line:84%
So this shows that
x itself is open.

00:31:21.040 --> 00:31:24.100 align:middle line:84%
Two, we want to show that the
union of open sets is open.

00:31:24.100 --> 00:31:25.060 align:middle line:90%
How do we do that?

00:31:25.060 --> 00:31:28.250 align:middle line:90%


00:31:28.250 --> 00:31:33.210 align:middle line:90%
i equals 0 to infinity is open.

00:31:33.210 --> 00:31:36.330 align:middle line:90%
This is what we want to show.

00:31:36.330 --> 00:31:38.533 align:middle line:84%
Well, as with the
definition, we're

00:31:38.533 --> 00:31:40.200 align:middle line:84%
just going to pick a
point in the union.

00:31:40.200 --> 00:31:45.420 align:middle line:84%
So pick arbitrary
x in the union--

00:31:45.420 --> 00:31:49.038 align:middle line:90%
equals 0 to infinity of Ai.

00:31:49.038 --> 00:31:50.580 align:middle line:84%
And we want to show
that there exists

00:31:50.580 --> 00:31:54.900 align:middle line:84%
a ball of radius epsilon around
x that's contained in the set.

00:31:54.900 --> 00:31:56.730 align:middle line:84%
Well, because it's
in the union, there

00:31:56.730 --> 00:31:59.970 align:middle line:84%
has to exist at least
1 Ai that contains x.

00:31:59.970 --> 00:32:05.880 align:middle line:84%
So therefore, there exists an
Aj in your set of open sets

00:32:05.880 --> 00:32:11.850 align:middle line:90%
Ai such that x is in Aj.

00:32:11.850 --> 00:32:15.420 align:middle line:84%
And then we apply the fact
that Aj itself is open.

00:32:15.420 --> 00:32:19.710 align:middle line:84%
So therefore, there exists
an epsilon bigger than 0 such

00:32:19.710 --> 00:32:28.680 align:middle line:84%
that the ball of radius epsilon
around x is contained in Aj,

00:32:28.680 --> 00:32:30.780 align:middle line:84%
but this is a
subset of the union.

00:32:30.780 --> 00:32:34.175 align:middle line:90%


00:32:34.175 --> 00:32:36.050 align:middle line:84%
So this shows that the
ball of radius epsilon

00:32:36.050 --> 00:32:38.750 align:middle line:84%
is contained in the infinite
union, or potentially

00:32:38.750 --> 00:32:39.860 align:middle line:90%
infinite union.

00:32:39.860 --> 00:32:42.800 align:middle line:84%
This also works if
it's finite, notice.

00:32:42.800 --> 00:32:46.060 align:middle line:90%
But that's just a subcase.

00:32:46.060 --> 00:32:47.380 align:middle line:90%
OK.

00:32:47.380 --> 00:32:50.110 align:middle line:90%
And can I squeeze it in here?

00:32:50.110 --> 00:32:50.740 align:middle line:90%
No, I cannot.

00:32:50.740 --> 00:32:54.500 align:middle line:90%
So I will move over here.

00:32:54.500 --> 00:32:55.810 align:middle line:90%
Any questions so far?

00:32:55.810 --> 00:32:57.250 align:middle line:90%
Actually, let me move this.

00:32:57.250 --> 00:32:58.210 align:middle line:90%
Any questions?

00:32:58.210 --> 00:33:01.760 align:middle line:90%


00:33:01.760 --> 00:33:06.130 align:middle line:84%
Open sets are weird
in that when we

00:33:06.130 --> 00:33:07.940 align:middle line:84%
learn about them
in real analysis,

00:33:07.940 --> 00:33:11.380 align:middle line:84%
I feel like they're pretty
unintuitively important.

00:33:11.380 --> 00:33:16.740 align:middle line:84%
Everyone says that they're
important, but I never got why.

00:33:16.740 --> 00:33:21.690 align:middle line:84%
And I'll explain why they
are just in a moment.

00:33:21.690 --> 00:33:24.810 align:middle line:84%
But yeah, open sets are deeply
important in real analysis

00:33:24.810 --> 00:33:26.610 align:middle line:90%
and topology.

00:33:26.610 --> 00:33:29.040 align:middle line:84%
And we're going to prove
some more statements

00:33:29.040 --> 00:33:31.890 align:middle line:84%
besides these topological
properties that

00:33:31.890 --> 00:33:37.020 align:middle line:84%
will be important and will
relate to the major definitions

00:33:37.020 --> 00:33:37.840 align:middle line:90%
in our toolbox.

00:33:37.840 --> 00:33:41.724 align:middle line:90%


00:33:41.724 --> 00:33:43.660 align:middle line:90%
OK.

00:33:43.660 --> 00:33:48.460 align:middle line:84%
So now, we're interested
in the third case,

00:33:48.460 --> 00:33:52.590 align:middle line:84%
the intersection from i
equals 0 to m of the Ai.

00:33:52.590 --> 00:33:56.140 align:middle line:84%
Well, we're going to do
exactly as we did before.

00:33:56.140 --> 00:34:00.690 align:middle line:84%
If I have some x in the
intersection of the Ai from i

00:34:00.690 --> 00:34:04.380 align:middle line:84%
equals 0 to m, then
what do I know?

00:34:04.380 --> 00:34:07.140 align:middle line:84%
Before, we knew that it
was in any of the Ai's.

00:34:07.140 --> 00:34:09.389 align:middle line:84%
But here we know even
more information.

00:34:09.389 --> 00:34:17.389 align:middle line:84%
Here we know that x is
in Ai for every single i.

00:34:17.389 --> 00:34:18.600 align:middle line:90%
So what can we do?

00:34:18.600 --> 00:34:23.449 align:middle line:84%
Well, we know that therefore,
because each Ai is open,

00:34:23.449 --> 00:34:27.920 align:middle line:84%
there exists an epsilon
i bigger than 0 such

00:34:27.920 --> 00:34:35.190 align:middle line:84%
that the ball of radius epsilon
i around x is contained in Ai.

00:34:35.190 --> 00:34:38.010 align:middle line:84%
The issue is that
the entirety of Ai

00:34:38.010 --> 00:34:39.820 align:middle line:84%
might not be in
the intersection.

00:34:39.820 --> 00:34:41.040 align:middle line:90%
So what can we do?

00:34:41.040 --> 00:34:43.350 align:middle line:90%
We have this for every single i.

00:34:43.350 --> 00:34:44.880 align:middle line:84%
And we have finitely
many of them.

00:34:44.880 --> 00:34:53.889 align:middle line:84%
So choose epsilon to be equal
to the minimum of the epsilon

00:34:53.889 --> 00:35:00.600 align:middle line:90%
i's from i equals 0 or 0 to M--

00:35:00.600 --> 00:35:04.380 align:middle line:84%
capital M. This is
bigger than 0, right?

00:35:04.380 --> 00:35:06.820 align:middle line:84%
Because we're only
choosing finite many.

00:35:06.820 --> 00:35:10.260 align:middle line:84%
This is where we're using
the fact that there's

00:35:10.260 --> 00:35:11.640 align:middle line:90%
the finite intersection.

00:35:11.640 --> 00:35:14.130 align:middle line:84%
If you had an
infinite intersection,

00:35:14.130 --> 00:35:18.420 align:middle line:84%
you can picture taking more
and more, smaller and smaller

00:35:18.420 --> 00:35:22.470 align:middle line:84%
epsilon i's such that
this infimum is 0.

00:35:22.470 --> 00:35:24.810 align:middle line:84%
And that's an issue, but
if it's finitely many,

00:35:24.810 --> 00:35:27.900 align:middle line:90%
we can take the minimum of them.

00:35:27.900 --> 00:35:30.270 align:middle line:84%
And then what we know is
that the ball of radius

00:35:30.270 --> 00:35:35.250 align:middle line:84%
epsilon around x is a
subset of Ai for all i

00:35:35.250 --> 00:35:38.946 align:middle line:84%
because it's contained in
the ball of radius epsilon i.

00:35:38.946 --> 00:35:40.950 align:middle line:84%
Or I guess I should say
that this is contained

00:35:40.950 --> 00:35:46.800 align:middle line:84%
in the ball of radius epsilon
i of x, which is contained

00:35:46.800 --> 00:35:50.910 align:middle line:84%
in Ai for all i, which implies
that the ball of radius

00:35:50.910 --> 00:35:57.610 align:middle line:84%
epsilon around x is a subset
of the finite intersection.

00:35:57.610 --> 00:35:58.780 align:middle line:90%
All right?

00:35:58.780 --> 00:36:01.030 align:middle line:84%
So why is this called the
topological properties

00:36:01.030 --> 00:36:02.260 align:middle line:90%
of open sets?

00:36:02.260 --> 00:36:04.102 align:middle line:84%
Because if you
were to take 18901,

00:36:04.102 --> 00:36:06.310 align:middle line:84%
which is a class that I
would highly suggest you take

00:36:06.310 --> 00:36:08.268 align:middle line:84%
at some point if you're
interested in this sort

00:36:08.268 --> 00:36:11.260 align:middle line:84%
of analysis, as
we're going to see,

00:36:11.260 --> 00:36:13.960 align:middle line:84%
open sets allow us to state
things about continuity.

00:36:13.960 --> 00:36:16.300 align:middle line:84%
You can define continuity
in terms of open sets.

00:36:16.300 --> 00:36:17.950 align:middle line:84%
You can define
convergent sequences

00:36:17.950 --> 00:36:19.390 align:middle line:90%
in terms of open sets.

00:36:19.390 --> 00:36:23.110 align:middle line:84%
Basically, everything we can
redo in terms of open sets.

00:36:23.110 --> 00:36:25.090 align:middle line:90%
And that is a topology.

00:36:25.090 --> 00:36:28.570 align:middle line:84%
If I have a set of subsets
such that these three

00:36:28.570 --> 00:36:31.330 align:middle line:84%
properties hold, that's
known as a topology.

00:36:31.330 --> 00:36:34.930 align:middle line:84%
And in 18901, that's the basic
toolbox that you're given.

00:36:34.930 --> 00:36:38.810 align:middle line:84%
And then you go from there in
terms of redefining everything.

00:36:38.810 --> 00:36:42.790 align:middle line:84%
So this is just an example
of a more general thing

00:36:42.790 --> 00:36:45.400 align:middle line:90%
than metric spaces.

00:36:45.400 --> 00:36:47.170 align:middle line:84%
I'm going to talk a
little bit about that

00:36:47.170 --> 00:36:49.960 align:middle line:84%
in the final lecture,
where I talk about where

00:36:49.960 --> 00:36:51.260 align:middle line:90%
things go from here.

00:36:51.260 --> 00:36:55.340 align:middle line:84%
But for now, this
is the basic idea.

00:36:55.340 --> 00:36:55.840 align:middle line:90%
All right.

00:36:55.840 --> 00:36:58.960 align:middle line:90%


00:36:58.960 --> 00:37:01.750 align:middle line:84%
Now what I'm going to state is
some facts about closed sets.

00:37:01.750 --> 00:37:05.590 align:middle line:84%
But what is a closed set,
which I haven't defined before?

00:37:05.590 --> 00:37:07.160 align:middle line:90%
So this is useful to know.

00:37:07.160 --> 00:37:19.040 align:middle line:84%
A subset A in x is closed
if the complement of A,

00:37:19.040 --> 00:37:25.460 align:middle line:84%
which is known as the metric
space x minus A, is open.

00:37:25.460 --> 00:37:28.780 align:middle line:90%


00:37:28.780 --> 00:37:34.600 align:middle line:84%
Now, if a set is closed, does
that imply that it's not open?

00:37:34.600 --> 00:37:35.140 align:middle line:90%
Yeah.

00:37:35.140 --> 00:37:36.280 align:middle line:90%
The answer is no.

00:37:36.280 --> 00:37:37.893 align:middle line:90%
How can we see that?

00:37:37.893 --> 00:37:40.060 align:middle line:84%
Well, let's consider the
real numbers as an example.

00:37:40.060 --> 00:37:43.810 align:middle line:90%


00:37:43.810 --> 00:37:47.042 align:middle line:84%
Notice-- what's the
complement of the empty set

00:37:47.042 --> 00:37:47.875 align:middle line:90%
in the real numbers?

00:37:47.875 --> 00:37:50.970 align:middle line:90%


00:37:50.970 --> 00:37:53.268 align:middle line:90%
Anyone?

00:37:53.268 --> 00:37:55.060 align:middle line:84%
It's a good exercise
in thinking about what

00:37:55.060 --> 00:37:57.320 align:middle line:90%
the complement means.

00:37:57.320 --> 00:37:59.940 align:middle line:84%
It's the real numbers
minus the empty set.

00:37:59.940 --> 00:38:03.780 align:middle line:84%
So it's just going to be
all of the real numbers.

00:38:03.780 --> 00:38:06.920 align:middle line:84%
But this, as we've stated
before in our first topological

00:38:06.920 --> 00:38:07.910 align:middle line:90%
property--

00:38:07.910 --> 00:38:10.880 align:middle line:90%
this is open.

00:38:10.880 --> 00:38:16.730 align:middle line:84%
So therefore, the empty set
is closed by definition.

00:38:16.730 --> 00:38:20.810 align:middle line:84%
But we also know, by our
topological properties, again,

00:38:20.810 --> 00:38:22.100 align:middle line:90%
that the empty set is open.

00:38:22.100 --> 00:38:25.700 align:middle line:90%


00:38:25.700 --> 00:38:27.050 align:middle line:90%
What the heck?

00:38:27.050 --> 00:38:29.210 align:middle line:84%
Well, this is just one of
those things in topology.

00:38:29.210 --> 00:38:30.590 align:middle line:90%
It's weird.

00:38:30.590 --> 00:38:33.260 align:middle line:84%
Open sets-- you can prove
properties of closed sets

00:38:33.260 --> 00:38:36.710 align:middle line:90%
instead, and everything's fine.

00:38:36.710 --> 00:38:48.210 align:middle line:84%
I'll note-- there's a notion
called connectedness, which

00:38:48.210 --> 00:38:50.610 align:middle line:84%
I'll briefly define,
but ultimately will be

00:38:50.610 --> 00:38:52.660 align:middle line:90%
more of a problem set problem.

00:38:52.660 --> 00:38:56.340 align:middle line:84%
But if your metric
space is connected--

00:38:56.340 --> 00:38:59.420 align:middle line:90%
let me state it that way.

00:38:59.420 --> 00:39:03.920 align:middle line:84%
If your metric space
x is connected,

00:39:03.920 --> 00:39:10.430 align:middle line:84%
which I'll define in a moment,
this is true if and only

00:39:10.430 --> 00:39:18.650 align:middle line:84%
if the only open
and closed sets--

00:39:18.650 --> 00:39:22.040 align:middle line:84%
so sets that are both
open and closed--

00:39:22.040 --> 00:39:26.818 align:middle line:84%
are the empty set and
the metric space itself.

00:39:26.818 --> 00:39:29.360 align:middle line:84%
Now, what does it mean for your
metric space to be connected?

00:39:29.360 --> 00:39:31.068 align:middle line:84%
We have a nice picture
of it in our heads

00:39:31.068 --> 00:39:33.470 align:middle line:84%
because connected is
a pretty visual thing,

00:39:33.470 --> 00:39:35.600 align:middle line:90%
but this is one definition.

00:39:35.600 --> 00:39:38.400 align:middle line:84%
Once you prove this,
this is a definition.

00:39:38.400 --> 00:39:39.380 align:middle line:90%
How do you prove this?

00:39:39.380 --> 00:39:42.020 align:middle line:84%
Well, you prove it based off of
the definition of disconnected.

00:39:42.020 --> 00:39:50.630 align:middle line:84%
So definition-- x is
disconnected by definition

00:39:50.630 --> 00:39:58.220 align:middle line:84%
if there exist two open sets,
U1 and U2, that are disjoint--

00:39:58.220 --> 00:40:02.150 align:middle line:90%


00:40:02.150 --> 00:40:17.070 align:middle line:84%
disjoint-- and nonempty
such that the union of them

00:40:17.070 --> 00:40:18.270 align:middle line:90%
is exactly x.

00:40:18.270 --> 00:40:22.300 align:middle line:84%
This is what it means for
your space to be disconnected.

00:40:22.300 --> 00:40:26.310 align:middle line:84%
And from here a set is connected
if it is not disconnected.

00:40:26.310 --> 00:40:28.290 align:middle line:90%
So it's circular reasoning.

00:40:28.290 --> 00:40:29.790 align:middle line:84%
And then once you
have that, you can

00:40:29.790 --> 00:40:33.687 align:middle line:84%
prove this note, which I'll put
in the third problem set, which

00:40:33.687 --> 00:40:34.770 align:middle line:90%
is an interesting problem.

00:40:34.770 --> 00:40:38.040 align:middle line:90%


00:40:38.040 --> 00:40:40.200 align:middle line:84%
But I just want
to note-- showing

00:40:40.200 --> 00:40:41.970 align:middle line:84%
something is closed
does not necessarily

00:40:41.970 --> 00:40:45.060 align:middle line:90%
imply that it's open.

00:40:45.060 --> 00:40:47.640 align:middle line:84%
I'll give one short example
of why this is true.

00:40:47.640 --> 00:40:51.450 align:middle line:84%
And then I'll move on to
more properties of open sets.

00:40:51.450 --> 00:40:53.750 align:middle line:90%
Anyone have questions?

00:40:53.750 --> 00:40:55.800 align:middle line:90%
Cool.

00:40:55.800 --> 00:40:58.490 align:middle line:84%
Feel free to shout out questions
if you have any, or interrupt.

00:40:58.490 --> 00:41:00.650 align:middle line:84%
I'm more than happy
to be interrupted.

00:41:00.650 --> 00:41:13.777 align:middle line:90%


00:41:13.777 --> 00:41:16.570 align:middle line:84%
OK, so I'm just going to give
one example of a metric space

00:41:16.570 --> 00:41:19.420 align:middle line:84%
that is disconnected, which is
one that makes relative sense,

00:41:19.420 --> 00:41:21.880 align:middle line:90%
at least on the face of it.

00:41:21.880 --> 00:41:28.660 align:middle line:84%
Example-- I can take a
unit of two open intervals,

00:41:28.660 --> 00:41:44.390 align:middle line:84%
CR to 1 and 1 to 2, and give
it the usual metric on R.

00:41:44.390 --> 00:41:45.950 align:middle line:90%
What do I mean by usual metric?

00:41:45.950 --> 00:41:48.650 align:middle line:84%
I mean the distance between
two points in the set

00:41:48.650 --> 00:41:50.840 align:middle line:84%
is just the distance
normally in R--

00:41:50.840 --> 00:41:52.610 align:middle line:90%
absolute values.

00:41:52.610 --> 00:41:55.040 align:middle line:84%
This is an example of one
that's disconnected, right?

00:41:55.040 --> 00:41:58.280 align:middle line:90%


00:41:58.280 --> 00:42:02.870 align:middle line:84%
It is the union of two open
sets that are disjoint.

00:42:02.870 --> 00:42:05.930 align:middle line:84%
And you can notice
here the interval 0,

00:42:05.930 --> 00:42:12.310 align:middle line:84%
1 is both open and closed
because the complement of it

00:42:12.310 --> 00:42:14.540 align:middle line:90%
is just 1, 2, and that's open.

00:42:14.540 --> 00:42:16.970 align:middle line:84%
So this is an interesting
example to think through.

00:42:16.970 --> 00:42:19.880 align:middle line:84%
This is known as
the subspace metric

00:42:19.880 --> 00:42:23.000 align:middle line:84%
or the subspace
topology, technically.

00:42:23.000 --> 00:42:24.510 align:middle line:90%
But yeah.

00:42:24.510 --> 00:42:25.740 align:middle line:90%
OK.

00:42:25.740 --> 00:42:28.110 align:middle line:84%
Let's go back to proving
things about the general theory

00:42:28.110 --> 00:42:30.420 align:middle line:90%
of open sets.

00:42:30.420 --> 00:42:34.140 align:middle line:84%
Proposition-- I'm first going to
point out that closed sets are

00:42:34.140 --> 00:42:36.960 align:middle line:90%
very similar to open sets.

00:42:36.960 --> 00:42:38.880 align:middle line:84%
In fact, we can
define everything

00:42:38.880 --> 00:42:41.817 align:middle line:84%
in terms of closed
sets, if we wanted to.

00:42:41.817 --> 00:42:42.900 align:middle line:90%
Properties of closed sets.

00:42:42.900 --> 00:42:49.510 align:middle line:90%


00:42:49.510 --> 00:42:53.140 align:middle line:84%
Here we have that the
empty set in x are closed.

00:42:53.140 --> 00:42:55.810 align:middle line:90%


00:42:55.810 --> 00:43:04.390 align:middle line:84%
Two, the potentially infinite
intersection of closed sets,

00:43:04.390 --> 00:43:08.950 align:middle line:90%
Ai closed, is closed.

00:43:08.950 --> 00:43:13.350 align:middle line:90%


00:43:13.350 --> 00:43:23.800 align:middle line:84%
And three, the finite union
of closed sets is closed.

00:43:23.800 --> 00:43:27.390 align:middle line:90%


00:43:27.390 --> 00:43:29.910 align:middle line:84%
Nearly identical to the
topological properties

00:43:29.910 --> 00:43:31.320 align:middle line:90%
of open sets.

00:43:31.320 --> 00:43:32.850 align:middle line:90%
How do we prove this?

00:43:32.850 --> 00:43:33.837 align:middle line:90%
It's not too bad.

00:43:33.837 --> 00:43:35.170 align:middle line:90%
I'm not going to actually do it.

00:43:35.170 --> 00:43:37.320 align:middle line:84%
The fact that the empty
set and x are closed

00:43:37.320 --> 00:43:40.680 align:middle line:84%
is just the proof that I
did above for R, right?

00:43:40.680 --> 00:43:44.470 align:middle line:84%
You can replace R with
just any metric space.

00:43:44.470 --> 00:43:46.720 align:middle line:84%
And we have that this
first property holds.

00:43:46.720 --> 00:43:48.130 align:middle line:90%
How about the other two?

00:43:48.130 --> 00:43:49.930 align:middle line:84%
Well, for the
other two, I'm just

00:43:49.930 --> 00:43:52.660 align:middle line:84%
going to quickly note what
are known as De Morgan's laws.

00:43:52.660 --> 00:43:56.710 align:middle line:90%


00:43:56.710 --> 00:44:01.270 align:middle line:84%
So this is a nice
lemma from set theory.

00:44:01.270 --> 00:44:02.905 align:middle line:84%
These are known as
De Morgan's laws.

00:44:02.905 --> 00:44:08.510 align:middle line:90%


00:44:08.510 --> 00:44:10.260 align:middle line:84%
I'm going to switch
which chalk I'm using.

00:44:10.260 --> 00:44:13.440 align:middle line:90%


00:44:13.440 --> 00:44:21.210 align:middle line:84%
This states that the
complement of a union

00:44:21.210 --> 00:44:25.380 align:middle line:84%
is the intersection
of the complements--

00:44:25.380 --> 00:44:35.900 align:middle line:84%
so i am A. And similarly, the
complement of an intersection--

00:44:35.900 --> 00:44:40.310 align:middle line:90%
Ui complement i and A--

00:44:40.310 --> 00:44:42.650 align:middle line:84%
is equal to the union
of the complements.

00:44:42.650 --> 00:44:46.070 align:middle line:90%


00:44:46.070 --> 00:44:47.720 align:middle line:84%
These are known as
De Morgan's laws.

00:44:47.720 --> 00:44:48.820 align:middle line:90%
They make relative sense?

00:44:48.820 --> 00:44:50.570 align:middle line:84%
You can prove them for
two sets as opposed

00:44:50.570 --> 00:44:52.260 align:middle line:90%
to infinitely many of them.

00:44:52.260 --> 00:44:54.380 align:middle line:84%
But once you have
these two properties,

00:44:54.380 --> 00:44:56.480 align:middle line:84%
then you can rewrite
these two properties

00:44:56.480 --> 00:44:58.040 align:middle line:90%
in terms of open sets.

00:44:58.040 --> 00:45:00.200 align:middle line:84%
That's why there's
this duality, right?

00:45:00.200 --> 00:45:02.090 align:middle line:84%
I can write the
intersection of closed sets

00:45:02.090 --> 00:45:03.455 align:middle line:90%
as the union of open sets.

00:45:03.455 --> 00:45:07.300 align:middle line:90%


00:45:07.300 --> 00:45:08.948 align:middle line:84%
That's how you apply
De Morgan's laws.

00:45:08.948 --> 00:45:10.740 align:middle line:84%
And I'm not going to
prove that, or I'm not

00:45:10.740 --> 00:45:12.330 align:middle line:84%
going to prove these
topological properties.

00:45:12.330 --> 00:45:13.980 align:middle line:84%
This is in the
lecture notes, but I

00:45:13.980 --> 00:45:15.750 align:middle line:84%
do want to note-- you
could do everything

00:45:15.750 --> 00:45:18.600 align:middle line:84%
in terms of closed sets if
you really truly wanted to.

00:45:18.600 --> 00:45:23.280 align:middle line:84%
We just don't because
open sets are nice.

00:45:23.280 --> 00:45:24.210 align:middle line:90%
OK.

00:45:24.210 --> 00:45:28.392 align:middle line:84%
We'll show why some of those
things are actually nice.

00:45:28.392 --> 00:45:29.850 align:middle line:84%
What more things
do I want to note?

00:45:29.850 --> 00:45:30.480 align:middle line:90%
OK, cool.

00:45:30.480 --> 00:45:33.170 align:middle line:90%


00:45:33.170 --> 00:45:36.380 align:middle line:84%
Now, I want to state some
specific examples of open sets

00:45:36.380 --> 00:45:41.320 align:middle line:84%
in metric spaces, which we
can already do quite a bit of.

00:45:41.320 --> 00:45:45.698 align:middle line:84%
Example-- did I
erase it already?

00:45:45.698 --> 00:45:46.240 align:middle line:90%
Oh, wait, no.

00:45:46.240 --> 00:45:46.960 align:middle line:90%
I did it here.

00:45:46.960 --> 00:45:49.930 align:middle line:90%


00:45:49.930 --> 00:45:50.680 align:middle line:90%
Where did I do it?

00:45:50.680 --> 00:45:52.570 align:middle line:90%
Oh, I did at the very top.

00:45:52.570 --> 00:45:54.310 align:middle line:84%
The ball of radius
epsilon around A

00:45:54.310 --> 00:45:57.010 align:middle line:84%
is sometimes referred
to as an open ball,

00:45:57.010 --> 00:46:00.100 align:middle line:84%
but you should prove that the
ball is, in fact, open, which

00:46:00.100 --> 00:46:02.360 align:middle line:90%
will be our first example.

00:46:02.360 --> 00:46:07.270 align:middle line:84%
So given some point x
in your metric space

00:46:07.270 --> 00:46:11.850 align:middle line:84%
x and epsilon bigger
than 0, we have

00:46:11.850 --> 00:46:15.465 align:middle line:84%
that the ball of radius
epsilon around x is open.

00:46:15.465 --> 00:46:18.040 align:middle line:90%


00:46:18.040 --> 00:46:18.950 align:middle line:90%
How do we do this?

00:46:18.950 --> 00:46:20.440 align:middle line:84%
Well, we choose
an arbitrary point

00:46:20.440 --> 00:46:23.760 align:middle line:84%
in your ball of
radius epsilon, right?

00:46:23.760 --> 00:46:33.250 align:middle line:84%
So proof-- choose
some y in the ball

00:46:33.250 --> 00:46:36.040 align:middle line:90%
of radius epsilon around x.

00:46:36.040 --> 00:46:38.080 align:middle line:84%
We want to find a ball
of radius, let's say,

00:46:38.080 --> 00:46:42.130 align:middle line:84%
delta around y contained in the
ball of radius epsilon round x.

00:46:42.130 --> 00:46:45.940 align:middle line:84%
That's the definition
of open set.

00:46:45.940 --> 00:46:50.920 align:middle line:84%
Well, notice that the
distance from x to y

00:46:50.920 --> 00:46:53.500 align:middle line:84%
is less than epsilon
by definition, right?

00:46:53.500 --> 00:46:55.180 align:middle line:84%
Because we're assuming
that the distance

00:46:55.180 --> 00:46:58.610 align:middle line:84%
between points in our
ball is less than epsilon.

00:46:58.610 --> 00:47:08.350 align:middle line:84%
So let delta be the
distance from x to y over 2.

00:47:08.350 --> 00:47:09.470 align:middle line:90%
Why does this work?

00:47:09.470 --> 00:47:12.700 align:middle line:84%
Because then we'll
notice that the ball

00:47:12.700 --> 00:47:16.030 align:middle line:84%
of radius delta
around y has to be

00:47:16.030 --> 00:47:19.180 align:middle line:84%
contained in the ball of
radius epsilon around x.

00:47:19.180 --> 00:47:20.590 align:middle line:90%
Why is this true?

00:47:20.590 --> 00:47:23.140 align:middle line:84%
Essentially, the triangle
inequality, right?

00:47:23.140 --> 00:47:30.310 align:middle line:84%
We have a ball of radius
epsilon centered at x.

00:47:30.310 --> 00:47:33.560 align:middle line:90%
We have a point y here.

00:47:33.560 --> 00:47:35.840 align:middle line:84%
And I'm noting that the
distance from here to here

00:47:35.840 --> 00:47:41.250 align:middle line:84%
is less than epsilon,
by definition.

00:47:41.250 --> 00:47:44.420 align:middle line:84%
And I'm just choosing
a ball around y

00:47:44.420 --> 00:47:46.823 align:middle line:90%
to be 1/2 of that distance.

00:47:46.823 --> 00:47:48.740 align:middle line:84%
And then you can apply
the triangle inequality

00:47:48.740 --> 00:47:50.600 align:middle line:84%
to show that this
ball must actually

00:47:50.600 --> 00:47:52.900 align:middle line:90%
be contained in the bigger one.

00:47:52.900 --> 00:47:54.400 align:middle line:84%
Anyone want me to
work through that?

00:47:54.400 --> 00:47:55.220 align:middle line:90%
I'm happy to.

00:47:55.220 --> 00:48:00.020 align:middle line:90%


00:48:00.020 --> 00:48:01.050 align:middle line:90%
Oh, wait a moment.

00:48:01.050 --> 00:48:08.660 align:middle line:90%


00:48:08.660 --> 00:48:10.912 align:middle line:90%
Let me write it up.

00:48:10.912 --> 00:48:11.495 align:middle line:90%
You know what?

00:48:11.495 --> 00:48:13.990 align:middle line:84%
I'll write it out
on the back board.

00:48:13.990 --> 00:48:21.770 align:middle line:84%
So let z be in the ball
of radius delta around y.

00:48:21.770 --> 00:48:26.290 align:middle line:84%
Then we have that the
distance from x to z

00:48:26.290 --> 00:48:29.630 align:middle line:84%
is less than or equal to,
by the triangle inequality,

00:48:29.630 --> 00:48:36.160 align:middle line:84%
the distance from x to y plus
the distance from y to z--

00:48:36.160 --> 00:48:39.430 align:middle line:90%
distance from x to y.

00:48:39.430 --> 00:48:42.040 align:middle line:84%
And the distance from y to
z is less than the distance

00:48:42.040 --> 00:48:43.240 align:middle line:90%
from x to y over 2.

00:48:43.240 --> 00:48:49.070 align:middle line:90%


00:48:49.070 --> 00:48:50.450 align:middle line:90%
Is this what I wanted to do?

00:48:50.450 --> 00:48:56.710 align:middle line:90%


00:48:56.710 --> 00:48:58.450 align:middle line:90%
Oh, I should say, no.

00:48:58.450 --> 00:49:01.690 align:middle line:90%
This is not what I wanted to do.

00:49:01.690 --> 00:49:10.900 align:middle line:84%
Let R be the distance
from x to y minus epsilon.

00:49:10.900 --> 00:49:13.510 align:middle line:84%
Then what we know is that
the distance from y to z

00:49:13.510 --> 00:49:19.750 align:middle line:84%
is less than R. What
am I trying to say?

00:49:19.750 --> 00:49:22.840 align:middle line:84%
Distance from y to
z is less than--

00:49:22.840 --> 00:49:25.210 align:middle line:84%
or sorry, this should be
epsilon minus the distance.

00:49:25.210 --> 00:49:25.930 align:middle line:90%
There we go.

00:49:25.930 --> 00:49:28.280 align:middle line:84%
And this is then
less than epsilon.

00:49:28.280 --> 00:49:29.650 align:middle line:90%
So this is in the lecture notes.

00:49:29.650 --> 00:49:31.690 align:middle line:84%
I would highly suggest
drawing up the picture

00:49:31.690 --> 00:49:34.150 align:middle line:84%
and working through
it separately.

00:49:34.150 --> 00:49:36.762 align:middle line:84%
But loosely speaking,
it's just this diagram

00:49:36.762 --> 00:49:37.720 align:middle line:90%
on the right-hand side.

00:49:37.720 --> 00:49:41.680 align:middle line:84%
It's an application of
the triangle inequality.

00:49:41.680 --> 00:49:42.180 align:middle line:90%
OK.

00:49:42.180 --> 00:49:45.150 align:middle line:84%
So the ball of radius
epsilon is an open ball.

00:49:45.150 --> 00:49:48.840 align:middle line:84%
In fact, you can state
much more than this.

00:49:48.840 --> 00:49:53.150 align:middle line:84%
This is an optional problem
on your second problem set.

00:49:53.150 --> 00:49:58.933 align:middle line:84%
And for the record, I do suggest
y'all look at the optional

00:49:58.933 --> 00:50:01.100 align:middle line:84%
problems because they will
potentially give you more

00:50:01.100 --> 00:50:02.900 align:middle line:84%
intuition, even if
you don't solve them.

00:50:02.900 --> 00:50:06.310 align:middle line:90%


00:50:06.310 --> 00:50:10.420 align:middle line:84%
But yeah, this is just one
of those cases where this

00:50:10.420 --> 00:50:13.360 align:middle line:84%
isn't a topology class, so I'm
not going to ask that y'all do

00:50:13.360 --> 00:50:18.240 align:middle line:84%
a bunch of topology,
but it's pretty nice.

00:50:18.240 --> 00:50:19.630 align:middle line:90%
OK.

00:50:19.630 --> 00:50:21.280 align:middle line:90%
So just a small note.

00:50:21.280 --> 00:50:25.420 align:middle line:90%


00:50:25.420 --> 00:50:33.550 align:middle line:84%
Any open set U contained
in your metric space

00:50:33.550 --> 00:50:44.770 align:middle line:84%
can be written as a union, a
potentially infinite union,

00:50:44.770 --> 00:50:45.640 align:middle line:90%
of open balls.

00:50:45.640 --> 00:50:51.490 align:middle line:90%


00:50:51.490 --> 00:50:53.660 align:middle line:84%
I'll outline briefly how
to do this right now.

00:50:53.660 --> 00:50:56.360 align:middle line:84%
So if y'all want to do
it later, you can do it.

00:50:56.360 --> 00:50:59.470 align:middle line:84%
But the idea is that for any
single point in your open set,

00:50:59.470 --> 00:51:02.578 align:middle line:84%
there exists a ball of radius
epsilon around that point.

00:51:02.578 --> 00:51:04.870 align:middle line:84%
And then you can just take
the union of all those balls

00:51:04.870 --> 00:51:05.870 align:middle line:90%
of radius epsilon.

00:51:05.870 --> 00:51:07.870 align:middle line:84%
The epsilon might change
for every single point,

00:51:07.870 --> 00:51:09.162 align:middle line:90%
but that doesn't matter, right?

00:51:09.162 --> 00:51:10.660 align:middle line:90%
Because it's an infinite union.

00:51:10.660 --> 00:51:13.780 align:middle line:84%
So I'll let y'all work
through those details,

00:51:13.780 --> 00:51:17.995 align:middle line:84%
but this is just a
proposition you can show.

00:51:17.995 --> 00:51:20.070 align:middle line:84%
OK, let's also just
prove an example

00:51:20.070 --> 00:51:25.313 align:middle line:84%
of a closed set, which will
come important for next time.

00:51:25.313 --> 00:51:25.980 align:middle line:90%
Just an example.

00:51:25.980 --> 00:51:28.870 align:middle line:90%


00:51:28.870 --> 00:51:29.370 align:middle line:90%
Oh, sorry.

00:51:29.370 --> 00:51:35.850 align:middle line:84%
I should say let x be a
point in your metric space.

00:51:35.850 --> 00:51:40.680 align:middle line:90%
Then the set x is closed.

00:51:40.680 --> 00:51:44.910 align:middle line:84%
So this is just a singular
point in your metric space.

00:51:44.910 --> 00:51:46.210 align:middle line:90%
How are we going to prove this?

00:51:46.210 --> 00:51:48.060 align:middle line:84%
Well, we only have one
definition of closed.

00:51:48.060 --> 00:51:53.790 align:middle line:84%
We have that the
complement is open, right?

00:51:53.790 --> 00:52:01.020 align:middle line:84%
So proof-- consider
the complement

00:52:01.020 --> 00:52:15.330 align:middle line:84%
of x, which is x not including
x, and let y be a point here.

00:52:15.330 --> 00:52:17.520 align:middle line:84%
What we want to
show is that there's

00:52:17.520 --> 00:52:19.180 align:middle line:90%
a ball of radius epsilon--

00:52:19.180 --> 00:52:23.130 align:middle line:90%
want to show-- around y--

00:52:23.130 --> 00:52:28.520 align:middle line:84%
or not in-- a subset
of x not including x.

00:52:28.520 --> 00:52:31.020 align:middle line:84%
Let's draw a picture of what
this should actually look like,

00:52:31.020 --> 00:52:33.650 align:middle line:90%
right?

00:52:33.650 --> 00:52:35.650 align:middle line:90%
Well, I didn't want to do that.

00:52:35.650 --> 00:52:38.530 align:middle line:90%
Here's our metric space.

00:52:38.530 --> 00:52:40.600 align:middle line:90%
Here's our singular point x.

00:52:40.600 --> 00:52:43.420 align:middle line:84%
And here's our
point, let's say, y.

00:52:43.420 --> 00:52:48.940 align:middle line:84%
We want to choose a ball around
y that doesn't contain x.

00:52:48.940 --> 00:52:49.750 align:middle line:90%
How can we do it?

00:52:49.750 --> 00:52:52.990 align:middle line:90%


00:52:52.990 --> 00:52:53.628 align:middle line:90%
Anyone?

00:52:53.628 --> 00:52:55.420 align:middle line:84%
You could choose whatever
epsilon you want,

00:52:55.420 --> 00:52:57.670 align:middle line:84%
so it's a question of what
epsilon you want to choose.

00:52:57.670 --> 00:53:00.570 align:middle line:90%


00:53:00.570 --> 00:53:04.158 align:middle line:84%
We can choose epsilon to be 1/2
the distance between x and y.

00:53:04.158 --> 00:53:06.450 align:middle line:84%
I think that's what I was
mixing up on the other proof,

00:53:06.450 --> 00:53:08.970 align:middle line:84%
but it's in the lecture notes,
so I'll let y'all do the other

00:53:08.970 --> 00:53:09.470 align:middle line:90%
one.

00:53:09.470 --> 00:53:20.220 align:middle line:84%
But choose epsilon to be the
distance from x to y over 2.

00:53:20.220 --> 00:53:24.120 align:middle line:84%
And then pictorially, we
have the rest of the problem,

00:53:24.120 --> 00:53:26.810 align:middle line:84%
but let's actually work
through the details.

00:53:26.810 --> 00:53:32.850 align:middle line:84%
So then let z be in your ball
of radius epsilon around y.

00:53:32.850 --> 00:53:38.930 align:middle line:84%
Then we want to show that
z cannot be x, right?

00:53:38.930 --> 00:53:45.210 align:middle line:84%
Well, notice-- this implies
that the distance from y to z

00:53:45.210 --> 00:53:50.160 align:middle line:84%
has to be less than
epsilon, right?

00:53:50.160 --> 00:53:55.050 align:middle line:84%
This is by construction, but can
we get a lower bound on this?

00:53:55.050 --> 00:53:56.376 align:middle line:90%
We can.

00:53:56.376 --> 00:53:59.468 align:middle line:84%
We can note that
the distance from--

00:53:59.468 --> 00:54:01.260 align:middle line:84%
I want to make sure
I'm getting this right.

00:54:01.260 --> 00:54:10.330 align:middle line:90%


00:54:10.330 --> 00:54:11.330 align:middle line:90%
Actually, you know what?

00:54:11.330 --> 00:54:13.663 align:middle line:84%
I'll do this directly, or
I'll do this by contradiction.

00:54:13.663 --> 00:54:16.480 align:middle line:90%


00:54:16.480 --> 00:54:19.770 align:middle line:84%
Suppose, for the sake
of contradiction,

00:54:19.770 --> 00:54:22.540 align:middle line:84%
x was in the ball of
radius epsilon around y.

00:54:22.540 --> 00:54:26.130 align:middle line:84%
Then this would imply that
the distance from x to y

00:54:26.130 --> 00:54:29.820 align:middle line:84%
is less than epsilon, but
this can't be the case

00:54:29.820 --> 00:54:35.760 align:middle line:84%
because again, we're
assuming that epsilon

00:54:35.760 --> 00:54:38.470 align:middle line:84%
is the distance
from x to y over 2.

00:54:38.470 --> 00:54:40.470 align:middle line:84%
And the distance from x
to y cannot be less than

00:54:40.470 --> 00:54:42.780 align:middle line:90%
the distance from x to y over 2.

00:54:42.780 --> 00:54:44.926 align:middle line:90%
So that is our contradiction.

00:54:44.926 --> 00:54:49.890 align:middle line:90%


00:54:49.890 --> 00:54:51.880 align:middle line:84%
I'll make one more
small note here,

00:54:51.880 --> 00:54:55.080 align:middle line:84%
which will become important for
Tuesday, which is, as opposed

00:54:55.080 --> 00:54:56.940 align:middle line:84%
to looking at a
singular point, you

00:54:56.940 --> 00:55:01.218 align:middle line:84%
can do this with a finite
union of points, right?

00:55:01.218 --> 00:55:02.760 align:middle line:84%
And the argument
would be essentially

00:55:02.760 --> 00:55:05.130 align:middle line:84%
the same as our finite
intersection of open sets

00:55:05.130 --> 00:55:06.060 align:middle line:90%
argument.

00:55:06.060 --> 00:55:09.430 align:middle line:84%
You have a finite
Union of open sets--

00:55:09.430 --> 00:55:11.180 align:middle line:84%
or sorry, a finite
union of closed things.

00:55:11.180 --> 00:55:12.220 align:middle line:90%
So it should be closed.

00:55:12.220 --> 00:55:14.840 align:middle line:84%
In fact, you could use that
to prove it immediately.

00:55:14.840 --> 00:55:18.972 align:middle line:84%
But you can also prove
it directly, like this.

00:55:18.972 --> 00:55:21.555 align:middle line:90%
OK.

00:55:21.555 --> 00:55:22.930 align:middle line:84%
So now, what we're
going to do is

00:55:22.930 --> 00:55:26.950 align:middle line:84%
talk about how this
definition of open sets

00:55:26.950 --> 00:55:34.960 align:middle line:84%
relates to convergent
sequences and to continuity.

00:55:34.960 --> 00:55:40.155 align:middle line:90%
Proposition-- let xn--

00:55:40.155 --> 00:55:42.280 align:middle line:84%
to do this, I'm going to
do it in the real numbers,

00:55:42.280 --> 00:55:44.697 align:middle line:84%
but note that everything can
be done in your metric space.

00:55:44.697 --> 00:55:48.170 align:middle line:84%
I just want to use the
notation from the real numbers.

00:55:48.170 --> 00:55:52.390 align:middle line:90%
Let xn be a sequence--

00:55:52.390 --> 00:55:53.530 align:middle line:90%
am I writing it backwards?

00:55:53.530 --> 00:56:01.140 align:middle line:90%
I am-- in R that converges to x.

00:56:01.140 --> 00:56:04.260 align:middle line:90%


00:56:04.260 --> 00:56:06.750 align:middle line:84%
So then this is true,
I claim, if and only

00:56:06.750 --> 00:56:24.210 align:middle line:84%
if, for all epsilon bigger than
0, all but finitely many xi

00:56:24.210 --> 00:56:32.030 align:middle line:84%
are in x minus epsilon
to x plus epsilon.

00:56:32.030 --> 00:56:36.100 align:middle line:84%
So this is the ball of radius
epsilon around x, right?

00:56:36.100 --> 00:56:38.350 align:middle line:84%
How do we prove
this if and only if?

00:56:38.350 --> 00:56:41.230 align:middle line:90%
Proof-- well, OK.

00:56:41.230 --> 00:56:44.500 align:middle line:84%
I should say
convergent sequence.

00:56:44.500 --> 00:56:46.220 align:middle line:84%
Let's prove the forward
direction first.

00:56:46.220 --> 00:56:54.070 align:middle line:84%
So if xn is convergent, then
for all epsilon bigger than 0,

00:56:54.070 --> 00:56:59.680 align:middle line:84%
there exists n in the natural
numbers such that the ball

00:56:59.680 --> 00:57:00.985 align:middle line:90%
of radius epsilon around x--

00:57:00.985 --> 00:57:04.090 align:middle line:90%


00:57:04.090 --> 00:57:11.710 align:middle line:84%
I should say such that for all
n bigger than or equal to n,

00:57:11.710 --> 00:57:20.860 align:middle line:84%
xn is in the ball of radius
epsilon, x plus epsilon.

00:57:20.860 --> 00:57:24.280 align:middle line:84%
This is true because the
distance from xn to x

00:57:24.280 --> 00:57:25.400 align:middle line:90%
is less than epsilon.

00:57:25.400 --> 00:57:29.050 align:middle line:84%
This is just the open set
way to view it, right?

00:57:29.050 --> 00:57:30.550 align:middle line:90%
And this capital N--

00:57:30.550 --> 00:57:32.920 align:middle line:84%
notice that there are only
finitely many terms less

00:57:32.920 --> 00:57:33.550 align:middle line:90%
than it.

00:57:33.550 --> 00:57:35.560 align:middle line:84%
So this shows that
infinitely many of the terms

00:57:35.560 --> 00:57:36.820 align:middle line:90%
are in this open set.

00:57:36.820 --> 00:57:39.730 align:middle line:84%
And in fact, only finitely
many are outside of it.

00:57:39.730 --> 00:57:41.620 align:middle line:84%
So that proves the
forward direction.

00:57:41.620 --> 00:57:43.240 align:middle line:84%
Let's prove the
opposite direction.

00:57:43.240 --> 00:57:52.140 align:middle line:90%


00:57:52.140 --> 00:58:00.464 align:middle line:84%
I should write-- suppose, for
all epsilon bigger than 0,

00:58:00.464 --> 00:58:14.680 align:middle line:84%
all but finitely many xi
are in x minus epsilon

00:58:14.680 --> 00:58:17.440 align:middle line:90%
to x plus epsilon.

00:58:17.440 --> 00:58:22.970 align:middle line:84%
I want to choose a sequence that
will converge to x then, right?

00:58:22.970 --> 00:58:25.170 align:middle line:90%
Well, how can we do that?

00:58:25.170 --> 00:58:28.430 align:middle line:84%
We can construct a subsequence
that is going to be convergent.

00:58:28.430 --> 00:58:32.240 align:middle line:84%
And remember, a subsequence,
if it's convergent,

00:58:32.240 --> 00:58:36.212 align:middle line:84%
converges to what the original
sequence converges to, right?

00:58:36.212 --> 00:58:37.670 align:middle line:84%
So this is where
we're using a fact

00:58:37.670 --> 00:58:40.390 align:middle line:90%
from earlier that we proved.

00:58:40.390 --> 00:58:41.320 align:middle line:90%
OK.

00:58:41.320 --> 00:58:46.750 align:middle line:84%
So suppose epsilon is 1 over n
for n in the natural numbers,

00:58:46.750 --> 00:58:49.840 align:middle line:90%
or I'll say m.

00:58:49.840 --> 00:59:00.680 align:middle line:84%
Then choose x and m in the
ball of radius epsilon--

00:59:00.680 --> 00:59:05.600 align:middle line:90%
so 1 over m to x plus 1 over m.

00:59:05.600 --> 00:59:06.980 align:middle line:90%
What does this tell us?

00:59:06.980 --> 00:59:12.050 align:middle line:84%
I claim that this convergent
sequence converges to x.

00:59:12.050 --> 00:59:18.020 align:middle line:84%
Well, to show that, we need
to write down the definition.

00:59:18.020 --> 00:59:25.010 align:middle line:90%


00:59:25.010 --> 00:59:27.530 align:middle line:84%
When Professor Rodriguez
was erasing the board,

00:59:27.530 --> 00:59:30.170 align:middle line:84%
he'd always tell some joke,
but I don't have any jokes

00:59:30.170 --> 00:59:31.700 align:middle line:90%
right now, unfortunately.

00:59:31.700 --> 00:59:35.100 align:middle line:90%


00:59:35.100 --> 00:59:36.850 align:middle line:84%
Though he would do
them two at a time-- so

00:59:36.850 --> 00:59:38.642 align:middle line:84%
he could actually have
time to actually say

00:59:38.642 --> 00:59:40.894 align:middle line:90%
the joke before he finished.

00:59:40.894 --> 00:59:41.760 align:middle line:90%
OK.

00:59:41.760 --> 00:59:45.702 align:middle line:84%
So we want to show that x
and m converges to x, right?

00:59:45.702 --> 00:59:49.510 align:middle line:84%
Proof-- for all
epsilon bigger than 0,

00:59:49.510 --> 00:59:55.165 align:middle line:90%
we can choose M large enough--

00:59:55.165 --> 00:59:59.750 align:middle line:90%


00:59:59.750 --> 01:00:02.210 align:middle line:90%
or I should say capital M--

01:00:02.210 --> 01:00:08.170 align:middle line:84%
such that for all nm
bigger than or equal to M,

01:00:08.170 --> 01:00:16.000 align:middle line:84%
we have that 1 over nm is
less than epsilon, right?

01:00:16.000 --> 01:00:17.680 align:middle line:84%
Because epsilon
is bigger than 0,

01:00:17.680 --> 01:00:19.810 align:middle line:84%
I can find a large enough
natural number such

01:00:19.810 --> 01:00:22.480 align:middle line:84%
that 1 over that natural
number is less than epsilon.

01:00:22.480 --> 01:00:26.870 align:middle line:84%
That's a fact from
real analysis.

01:00:26.870 --> 01:00:34.360 align:middle line:84%
So what this tells us
is that we know, then,

01:00:34.360 --> 01:00:46.160 align:middle line:84%
that x and M is in x minus
epsilon to x plus epsilon

01:00:46.160 --> 01:00:53.690 align:middle line:84%
because this is from x over 1
over nm to x plus 1 over nm,

01:00:53.690 --> 01:00:56.960 align:middle line:84%
which is a subset of the
ball of radius epsilon,

01:00:56.960 --> 01:00:59.180 align:middle line:90%
by construction, right?

01:00:59.180 --> 01:01:01.290 align:middle line:84%
Because 1 over nm is
less than epsilon.

01:01:01.290 --> 01:01:06.440 align:middle line:84%
So what this tells you is that
the distance from x nm minus x

01:01:06.440 --> 01:01:08.510 align:middle line:84%
is less than epsilon,
which implies

01:01:08.510 --> 01:01:11.480 align:middle line:84%
that the convergent sequence
or the convergent subsequence

01:01:11.480 --> 01:01:12.830 align:middle line:90%
converges to x.

01:01:12.830 --> 01:01:14.780 align:middle line:84%
So to reiterate how
the proof went--

01:01:14.780 --> 01:01:16.310 align:middle line:90%
we had a convergent sequence.

01:01:16.310 --> 01:01:19.190 align:middle line:84%
We had a subsequence that
we showed converges to x.

01:01:19.190 --> 01:01:21.327 align:middle line:84%
And by what we showed
earlier, x must

01:01:21.327 --> 01:01:23.660 align:middle line:84%
be the limit point of the
original convergence sequence,

01:01:23.660 --> 01:01:24.410 align:middle line:90%
then.

01:01:24.410 --> 01:01:25.310 align:middle line:90%
So we're done.

01:01:25.310 --> 01:01:29.140 align:middle line:90%


01:01:29.140 --> 01:01:31.070 align:middle line:90%
All right.

01:01:31.070 --> 01:01:34.010 align:middle line:84%
I won't write out the analogous
statement for metric spaces.

01:01:34.010 --> 01:01:35.900 align:middle line:84%
You just change x
minus epsilon to x

01:01:35.900 --> 01:01:38.750 align:middle line:84%
plus epsilon with the
ball of radius epsilon.

01:01:38.750 --> 01:01:42.740 align:middle line:84%
I just stated it in
real numbers because I

01:01:42.740 --> 01:01:44.930 align:middle line:84%
prefer the interval
notation to think about it.

01:01:44.930 --> 01:01:47.108 align:middle line:84%
And it's a fact that
not everyone fully

01:01:47.108 --> 01:01:49.400 align:middle line:84%
sees in real analysis because
sometimes, you don't know

01:01:49.400 --> 01:01:51.650 align:middle line:90%
what an open set is in 100A.

01:01:51.650 --> 01:01:54.940 align:middle line:84%
It depends on who's
teaching it, realistically.

01:01:54.940 --> 01:01:56.050 align:middle line:90%
OK.

01:01:56.050 --> 01:01:58.660 align:middle line:90%
We're going to prove one more--

01:01:58.660 --> 01:01:59.160 align:middle line:90%
oh, wait.

01:01:59.160 --> 01:02:00.077 align:middle line:90%
What do I want to say?

01:02:00.077 --> 01:02:03.870 align:middle line:90%


01:02:03.870 --> 01:02:05.063 align:middle line:90%
Yeah, OK.

01:02:05.063 --> 01:02:07.230 align:middle line:84%
This was just how I wanted
to show that it's related

01:02:07.230 --> 01:02:09.570 align:middle line:90%
to convergent sequences.

01:02:09.570 --> 01:02:11.370 align:middle line:84%
Now, what I'm
going to do is show

01:02:11.370 --> 01:02:14.422 align:middle line:84%
that it's related to
continuous functions.

01:02:14.422 --> 01:02:16.380 align:middle line:84%
And I'm going to recall
what that definition is

01:02:16.380 --> 01:02:18.047 align:middle line:84%
because that can,
again, be a little bit

01:02:18.047 --> 01:02:20.260 align:middle line:90%
weird between metric spaces.

01:02:20.260 --> 01:02:22.770 align:middle line:84%
So a function f
from a metric space

01:02:22.770 --> 01:02:28.890 align:middle line:84%
x to a metric space y, let's
say, with metric dx and dy,

01:02:28.890 --> 01:02:37.430 align:middle line:84%
is continuous if, for all
epsilon bigger than 0,

01:02:37.430 --> 01:02:41.510 align:middle line:84%
there exists a delta
bigger than 0 such

01:02:41.510 --> 01:02:46.550 align:middle line:84%
that if the distance
between two points x and y

01:02:46.550 --> 01:02:49.790 align:middle line:84%
is less than delta, then the
distance in the metric space

01:02:49.790 --> 01:02:55.520 align:middle line:84%
y of the images of x and
y is less than epsilon.

01:02:55.520 --> 01:02:58.450 align:middle line:84%
This is the definition of
continuous in the metric space

01:02:58.450 --> 01:03:00.430 align:middle line:90%
setting.

01:03:00.430 --> 01:03:01.950 align:middle line:84%
And so now what
we're going to do

01:03:01.950 --> 01:03:05.310 align:middle line:84%
is prove a statement akin
to convergent sequences,

01:03:05.310 --> 01:03:06.390 align:middle line:90%
but for continuity.

01:03:06.390 --> 01:03:08.670 align:middle line:84%
We can write the
definition of continuity

01:03:08.670 --> 01:03:10.200 align:middle line:90%
in terms of open sets.

01:03:10.200 --> 01:03:13.350 align:middle line:84%
And not only can we do that, we
can write continuity in terms

01:03:13.350 --> 01:03:14.997 align:middle line:90%
of convergence of sequences.

01:03:14.997 --> 01:03:16.080 align:middle line:90%
So I'll do that right now.

01:03:16.080 --> 01:03:19.580 align:middle line:90%


01:03:19.580 --> 01:03:24.110 align:middle line:84%
Theorem-- under all the
same assumptions here

01:03:24.110 --> 01:03:27.230 align:middle line:84%
I'm going to let x and y be
metric spaces with distances dx

01:03:27.230 --> 01:03:29.060 align:middle line:90%
and dy.

01:03:29.060 --> 01:03:33.360 align:middle line:90%
And yeah, OK.

01:03:33.360 --> 01:03:37.950 align:middle line:90%


01:03:37.950 --> 01:03:43.530 align:middle line:84%
Claim-- f from x to y
is continuous at a point

01:03:43.530 --> 01:04:01.440 align:middle line:84%
c in x if and only if xn is a
sequence that converges to x.

01:04:01.440 --> 01:04:06.090 align:middle line:84%
Then f of xn
converges to f of x.

01:04:06.090 --> 01:04:08.970 align:middle line:90%
This is my statement.

01:04:08.970 --> 01:04:12.030 align:middle line:84%
When I say continuous
at the point c,

01:04:12.030 --> 01:04:16.410 align:middle line:84%
I mean just replace
y with c here.

01:04:16.410 --> 01:04:21.540 align:middle line:84%
That means that this is
continuous at every point,

01:04:21.540 --> 01:04:24.810 align:middle line:90%
continuous at x in x.

01:04:24.810 --> 01:04:28.328 align:middle line:84%
And it's continuous if it's
continuous everywhere, right?

01:04:28.328 --> 01:04:29.870 align:middle line:84%
This is the same as
in real analysis.

01:04:29.870 --> 01:04:32.570 align:middle line:84%
We had continuity at a point
and continuity everywhere.

01:04:32.570 --> 01:04:35.450 align:middle line:84%
This is just
continuity at a point.

01:04:35.450 --> 01:04:36.410 align:middle line:90%
OK.

01:04:36.410 --> 01:04:43.100 align:middle line:84%
Proof-- I always prefer going
the downwards direction first.

01:04:43.100 --> 01:04:50.695 align:middle line:90%
So let f be continuous at c.

01:04:50.695 --> 01:04:56.620 align:middle line:90%


01:04:56.620 --> 01:04:59.380 align:middle line:84%
Then by definition, for
all epsilon bigger than 0,

01:04:59.380 --> 01:05:02.860 align:middle line:84%
there exists a delta such
that this implication holds.

01:05:02.860 --> 01:05:05.050 align:middle line:90%
What does this actually tell us?

01:05:05.050 --> 01:05:13.570 align:middle line:84%
Well, I'm going to suppose the
thing in the second hypothesis.

01:05:13.570 --> 01:05:20.440 align:middle line:84%
Suppose xn is a sequence
in x that converges to x.

01:05:20.440 --> 01:05:22.190 align:middle line:90%
Then what can I say?

01:05:22.190 --> 01:05:25.473 align:middle line:84%
Well, we know that
there exists--

01:05:25.473 --> 01:05:26.640 align:middle line:90%
or sorry, I should say to c.

01:05:26.640 --> 01:05:29.930 align:middle line:90%


01:05:29.930 --> 01:05:32.790 align:middle line:84%
Then by definition of
convergent sequence,

01:05:32.790 --> 01:05:35.930 align:middle line:84%
we know that for all
epsilon bigger than 0,

01:05:35.930 --> 01:05:39.230 align:middle line:84%
there exists an n in
the natural numbers

01:05:39.230 --> 01:05:44.420 align:middle line:84%
such that for all n
bigger than or equal to n,

01:05:44.420 --> 01:05:48.660 align:middle line:84%
the distance from xn to
c is less than epsilon.

01:05:48.660 --> 01:05:57.880 align:middle line:84%
But we know that for all epsilon
bigger than 0, furthermore,

01:05:57.880 --> 01:06:00.490 align:middle line:84%
there exists a delta
bigger than 0 such

01:06:00.490 --> 01:06:07.240 align:middle line:84%
that the distance from f of xn
to f of c is less than delta

01:06:07.240 --> 01:06:08.170 align:middle line:90%
over 2--

01:06:08.170 --> 01:06:11.560 align:middle line:84%
or sorry, not delta
over 2, just delta.

01:06:11.560 --> 01:06:13.112 align:middle line:90%
No.

01:06:13.112 --> 01:06:14.320 align:middle line:90%
I should have relabeled this.

01:06:14.320 --> 01:06:16.278 align:middle line:84%
I should have said for
all delta bigger than 0,

01:06:16.278 --> 01:06:18.640 align:middle line:84%
there exists one such that
this is less than delta.

01:06:18.640 --> 01:06:22.520 align:middle line:84%
And then there exists an epsilon
bigger than 0 such that--

01:06:22.520 --> 01:06:23.020 align:middle line:90%
no, no.

01:06:23.020 --> 01:06:25.280 align:middle line:90%
I said it right the first time.

01:06:25.280 --> 01:06:28.100 align:middle line:84%
For all epsiolon bigger than
0, there exists a delta bigger

01:06:28.100 --> 01:06:30.590 align:middle line:84%
than 0 such that this
term is less than delta.

01:06:30.590 --> 01:06:34.100 align:middle line:84%
And furthermore, the
distance between the images

01:06:34.100 --> 01:06:35.190 align:middle line:90%
is less than epsilon.

01:06:35.190 --> 01:06:35.700 align:middle line:90%
There we go.

01:06:35.700 --> 01:06:37.160 align:middle line:90%
That's what I meant to say.

01:06:37.160 --> 01:06:39.620 align:middle line:84%
And so what this tells
you is that f of xn

01:06:39.620 --> 01:06:41.870 align:middle line:90%
must converge to f of c, right?

01:06:41.870 --> 01:06:43.970 align:middle line:84%
Because there exists an
n in the natural numbers

01:06:43.970 --> 01:06:45.980 align:middle line:84%
such that the distance
between the two points

01:06:45.980 --> 01:06:48.260 align:middle line:84%
is less than epsilon,
which is the definition

01:06:48.260 --> 01:06:50.780 align:middle line:90%
of convergent sequence.

01:06:50.780 --> 01:06:53.360 align:middle line:84%
And then to prove
the other direction,

01:06:53.360 --> 01:06:54.980 align:middle line:84%
I'm just going to
state it because--

01:06:54.980 --> 01:06:56.210 align:middle line:90%
are we running out of time?

01:06:56.210 --> 01:06:58.193 align:middle line:90%
No, I'll write it out.

01:06:58.193 --> 01:06:59.360 align:middle line:90%
I'll write it out over here.

01:06:59.360 --> 01:07:03.052 align:middle line:90%


01:07:03.052 --> 01:07:04.510 align:middle line:84%
To prove the other
direction, we're

01:07:04.510 --> 01:07:07.180 align:middle line:84%
going to use it
by contradiction.

01:07:07.180 --> 01:07:10.750 align:middle line:84%
We're going to assume that
it's not continuous at c,

01:07:10.750 --> 01:07:17.230 align:middle line:84%
and then choose a sequence
that doesn't converge,

01:07:17.230 --> 01:07:18.880 align:middle line:84%
or such that the
images don't converge.

01:07:18.880 --> 01:07:27.150 align:middle line:90%


01:07:27.150 --> 01:07:29.180 align:middle line:90%
OK.

01:07:29.180 --> 01:07:31.070 align:middle line:90%
If and only if.

01:07:31.070 --> 01:07:38.060 align:middle line:90%
Suppose f is not continuous.

01:07:38.060 --> 01:07:42.530 align:middle line:84%
This is the proof of
the upwards direction.

01:07:42.530 --> 01:07:45.920 align:middle line:84%
Suppose it's not
continuous at c.

01:07:45.920 --> 01:07:47.480 align:middle line:90%
What does this tell you?

01:07:47.480 --> 01:07:50.570 align:middle line:84%
Well, saying something is not
continuous this is a little bit

01:07:50.570 --> 01:07:53.090 align:middle line:84%
weird, but I'll state out
what that definition means.

01:07:53.090 --> 01:07:58.640 align:middle line:84%
Given some epsilon
bigger than 0,

01:07:58.640 --> 01:08:06.890 align:middle line:84%
we know that there exists
an xn in the sequence

01:08:06.890 --> 01:08:13.220 align:middle line:84%
such that the distance
from xn to c gets small.

01:08:13.220 --> 01:08:16.270 align:middle line:90%


01:08:16.270 --> 01:08:17.270 align:middle line:90%
Do I want to say over n?

01:08:17.270 --> 01:08:22.127 align:middle line:90%
No, I'll just say less than--

01:08:22.127 --> 01:08:24.460 align:middle line:84%
given epsilon bigger than 0,
there exists a delta bigger

01:08:24.460 --> 01:08:27.790 align:middle line:84%
than 0 in an xn in your sequence
such that the distances get

01:08:27.790 --> 01:08:28.490 align:middle line:90%
small--

01:08:28.490 --> 01:08:31.819 align:middle line:90%
so let's say 1 over n.

01:08:31.819 --> 01:08:38.630 align:middle line:84%
But the distances between
the images of them, f of c,

01:08:38.630 --> 01:08:41.319 align:middle line:90%
is bigger than epsilon, right?

01:08:41.319 --> 01:08:47.020 align:middle line:84%
Because the opposite would
be if this was less than

01:08:47.020 --> 01:08:50.439 align:middle line:90%
or equal to epsilon, right?

01:08:50.439 --> 01:08:56.260 align:middle line:84%
And so then what you can
show is that therefore, xn

01:08:56.260 --> 01:09:04.960 align:middle line:84%
converges to c, but f of xn
does not converge to f of c.

01:09:04.960 --> 01:09:07.600 align:middle line:84%
How do we know that it
doesn't converge to f of c?

01:09:07.600 --> 01:09:12.640 align:middle line:84%
Because we just proved up
here that if a sequence is

01:09:12.640 --> 01:09:15.490 align:middle line:84%
to converge all but
finitely many of them, i.e.

01:09:15.490 --> 01:09:17.170 align:middle line:90%
infinitely many of them--

01:09:17.170 --> 01:09:20.050 align:middle line:84%
or that's not quite the same--
but all but finitely many

01:09:20.050 --> 01:09:24.850 align:middle line:84%
of them must exist in any
ball of radius epsilon, right?

01:09:24.850 --> 01:09:27.590 align:middle line:84%
And we just showed here
that there are, in fact,

01:09:27.590 --> 01:09:32.420 align:middle line:84%
infinitely many that don't exist
in a ball of radius epsilon.

01:09:32.420 --> 01:09:35.950 align:middle line:84%
So that proves the
other direction.

01:09:35.950 --> 01:09:39.069 align:middle line:90%


01:09:39.069 --> 01:09:41.430 align:middle line:84%
This is known as sequential
continuity, sometimes.

01:09:41.430 --> 01:09:44.970 align:middle line:84%
If you want to study this in
more generality, as opposed

01:09:44.970 --> 01:09:48.630 align:middle line:84%
to assuming continuous, you
can assume this definition

01:09:48.630 --> 01:09:50.560 align:middle line:90%
on a topological space.

01:09:50.560 --> 01:09:52.359 align:middle line:90%
And that's slightly different.

01:09:52.359 --> 01:09:54.180 align:middle line:84%
But for metric spaces,
the two definitions

01:09:54.180 --> 01:09:57.210 align:middle line:84%
are the same, which will be
the case a lot of the time.

01:09:57.210 --> 01:09:59.880 align:middle line:84%
A lot of the time in this
class, a definition that's

01:09:59.880 --> 01:10:01.770 align:middle line:84%
specific to metric
spaces will imply

01:10:01.770 --> 01:10:04.860 align:middle line:84%
other very useful
definitions that might not

01:10:04.860 --> 01:10:06.960 align:middle line:90%
hold in more generality.

01:10:06.960 --> 01:10:08.825 align:middle line:90%
OK.

01:10:08.825 --> 01:10:10.450 align:middle line:84%
I just have one more
statement to show,

01:10:10.450 --> 01:10:15.420 align:middle line:84%
which is how continuity
relates to open sets.

01:10:15.420 --> 01:10:18.570 align:middle line:84%
Let me write out what
this lemma will be.

01:10:18.570 --> 01:10:20.610 align:middle line:90%
Oh, sorry.

01:10:20.610 --> 01:10:22.110 align:middle line:90%
This is poor board manners.

01:10:22.110 --> 01:10:27.510 align:middle line:84%
I should have raised
this and lowered this.

01:10:27.510 --> 01:10:30.190 align:middle line:90%
OK, OK.

01:10:30.190 --> 01:10:33.197 align:middle line:90%


01:10:33.197 --> 01:10:34.030 align:middle line:90%
Just one more lemma.

01:10:34.030 --> 01:10:40.390 align:middle line:90%


01:10:40.390 --> 01:10:47.950 align:middle line:84%
f is continuous at
c if and only if--

01:10:47.950 --> 01:10:50.020 align:middle line:84%
oh, I need to state
a definition first.

01:10:50.020 --> 01:10:52.030 align:middle line:90%
I'll state it over here.

01:10:52.030 --> 01:11:10.360 align:middle line:84%
Definition-- a neighborhood of
a point y is simply an open set

01:11:10.360 --> 01:11:11.230 align:middle line:90%
that contains y--

01:11:11.230 --> 01:11:16.240 align:middle line:90%


01:11:16.240 --> 01:11:17.200 align:middle line:90%
containing y.

01:11:17.200 --> 01:11:21.027 align:middle line:90%


01:11:21.027 --> 01:11:22.610 align:middle line:84%
For our purposes,
though, you can just

01:11:22.610 --> 01:11:24.652 align:middle line:84%
think of this open
neighborhood as a ball, right?

01:11:24.652 --> 01:11:27.020 align:middle line:84%
Because I've stated
that every open set

01:11:27.020 --> 01:11:31.230 align:middle line:84%
can be written as a union
of infinitely many balls.

01:11:31.230 --> 01:11:34.065 align:middle line:84%
So this is what a definition
of a neighborhood is,

01:11:34.065 --> 01:11:35.690 align:middle line:84%
and that lets us
state the lemma, which

01:11:35.690 --> 01:11:49.670 align:middle line:84%
is for every open
neighborhood of f of c--

01:11:49.670 --> 01:11:50.585 align:middle line:90%
this will be our y--

01:11:50.585 --> 01:11:54.080 align:middle line:90%


01:11:54.080 --> 01:11:59.030 align:middle line:84%
then we have that the
inverse image, f inverse of--

01:11:59.030 --> 01:11:59.530 align:middle line:90%
oh, sorry.

01:11:59.530 --> 01:12:01.420 align:middle line:84%
I should say every
open neighborhood

01:12:01.420 --> 01:12:12.655 align:middle line:84%
U of f of c, f inverse of U
is an open neighborhood of f

01:12:12.655 --> 01:12:16.370 align:middle line:84%
of c-- oh, sorry, of c because
we're in the inverse image.

01:12:16.370 --> 01:12:17.050 align:middle line:90%
OK.

01:12:17.050 --> 01:12:21.890 align:middle line:84%
Has anyone seen this definition
before regarding open sets?

01:12:21.890 --> 01:12:23.780 align:middle line:90%
Yeah.

01:12:23.780 --> 01:12:26.030 align:middle line:84%
It doesn't come up all
the time because it

01:12:26.030 --> 01:12:27.145 align:middle line:90%
is essentially topology.

01:12:27.145 --> 01:12:28.520 align:middle line:84%
If you take a
topology class, you

01:12:28.520 --> 01:12:30.470 align:middle line:90%
would see this definition of--

01:12:30.470 --> 01:12:32.720 align:middle line:84%
this would be the
definition of continuity

01:12:32.720 --> 01:12:35.430 align:middle line:90%
in a topological class.

01:12:35.430 --> 01:12:38.000 align:middle line:84%
But here we're going to actually
prove it for a metric space.

01:12:38.000 --> 01:12:40.042 align:middle line:84%
And because not all of
y'all have seen it before,

01:12:40.042 --> 01:12:41.690 align:middle line:84%
we'll just go
through that proof.

01:12:41.690 --> 01:12:48.880 align:middle line:84%
So proof-- we'll prove
the downwards direction.

01:12:48.880 --> 01:12:54.780 align:middle line:84%
So we have that f
is continuous at c.

01:12:54.780 --> 01:13:09.920 align:middle line:84%
And I'm going to let U be an
open neighborhood of f of c.

01:13:09.920 --> 01:13:13.670 align:middle line:84%
And so then I want to
show that f inverse of c--

01:13:13.670 --> 01:13:15.320 align:middle line:90%
oh, sorry, f inverse of U--

01:13:15.320 --> 01:13:19.730 align:middle line:84%
is an open set of c, open
neighborhood of c, right?

01:13:19.730 --> 01:13:22.532 align:middle line:90%
What I'm going to do instead--

01:13:22.532 --> 01:13:24.740 align:middle line:84%
instead of considering this
entire open neighborhood,

01:13:24.740 --> 01:13:29.780 align:middle line:84%
I'm going to consider a ball of
radius epsilon around f of c.

01:13:29.780 --> 01:13:34.280 align:middle line:84%
So because U is open, we know
that there exists an epsilon

01:13:34.280 --> 01:13:38.180 align:middle line:84%
bigger than 0 such
that the ball of radius

01:13:38.180 --> 01:13:47.930 align:middle line:84%
epsilon with metric dy around f
of c is contained in U, right?

01:13:47.930 --> 01:13:50.900 align:middle line:84%
We can find a ball around f of
c such that is contained in U

01:13:50.900 --> 01:13:52.760 align:middle line:90%
because it's open.

01:13:52.760 --> 01:13:53.760 align:middle line:90%
What does this tell you?

01:13:53.760 --> 01:13:59.280 align:middle line:84%
Well, by continuity,
furthermore, there

01:13:59.280 --> 01:14:01.980 align:middle line:84%
exists a delta
bigger than 0 such

01:14:01.980 --> 01:14:14.370 align:middle line:84%
that if the distance from
x to c is less than delta,

01:14:14.370 --> 01:14:21.450 align:middle line:84%
then the distance of f of x to
f of c is less than epsilon.

01:14:21.450 --> 01:14:23.290 align:middle line:90%
What does this tell you?

01:14:23.290 --> 01:14:26.070 align:middle line:84%
Well, this tells
you that the image

01:14:26.070 --> 01:14:31.200 align:middle line:84%
of the ball of
radius delta around c

01:14:31.200 --> 01:14:39.190 align:middle line:84%
is contained in the ball of
radius epsilon around f of c,

01:14:39.190 --> 01:14:39.690 align:middle line:90%
right?

01:14:39.690 --> 01:14:42.340 align:middle line:84%
Because if I look at the
images of these points,

01:14:42.340 --> 01:14:44.700 align:middle line:84%
I'm going to get that the
distance is less than epsilon

01:14:44.700 --> 01:14:46.490 align:middle line:90%
around f of c.

01:14:46.490 --> 01:14:47.490 align:middle line:90%
And what you can check--

01:14:47.490 --> 01:14:50.400 align:middle line:84%
I won't state this right
now, or I won't prove it--

01:14:50.400 --> 01:14:53.130 align:middle line:84%
but you can check that
if I do f inverse here,

01:14:53.130 --> 01:14:56.460 align:middle line:84%
it's going to be contained
in f inverse here.

01:14:56.460 --> 01:14:57.810 align:middle line:90%
Why is this helpful?

01:14:57.810 --> 01:15:02.610 align:middle line:84%
Because this is a subset
of f inverse of U.

01:15:02.610 --> 01:15:06.115 align:middle line:84%
So what we've done is we've gone
from an open neighborhood of f

01:15:06.115 --> 01:15:09.990 align:middle line:84%
of c to an open
neighborhood of c, which is

01:15:09.990 --> 01:15:11.910 align:middle line:90%
what we wanted to show, right?

01:15:11.910 --> 01:15:15.020 align:middle line:84%
We wanted to show
that f inverse of U

01:15:15.020 --> 01:15:17.682 align:middle line:90%
is an open neighborhood of c.

01:15:17.682 --> 01:15:19.570 align:middle line:90%
OK.

01:15:19.570 --> 01:15:21.905 align:middle line:84%
So we now need to prove the
other direction, which is

01:15:21.905 --> 01:15:23.155 align:middle line:90%
sometimes a little bit harder.

01:15:23.155 --> 01:15:31.500 align:middle line:90%


01:15:31.500 --> 01:15:34.710 align:middle line:84%
Only a little bit
harder, but should

01:15:34.710 --> 01:15:35.820 align:middle line:90%
be able to fit right here.

01:15:35.820 --> 01:15:40.266 align:middle line:90%


01:15:40.266 --> 01:15:45.640 align:middle line:84%
OK, so now we're going to
suppose that let epsilon

01:15:45.640 --> 01:15:47.980 align:middle line:90%
be bigger than 0.

01:15:47.980 --> 01:15:50.740 align:middle line:84%
And consider the open
neighborhood of f of c

01:15:50.740 --> 01:15:54.080 align:middle line:90%
given by the ball--

01:15:54.080 --> 01:16:01.640 align:middle line:84%
and consider the ball of
radius epsilon around f of c.

01:16:01.640 --> 01:16:04.240 align:middle line:90%


01:16:04.240 --> 01:16:07.570 align:middle line:84%
Then we know, by
assumption, that

01:16:07.570 --> 01:16:13.510 align:middle line:84%
f inverse of this ball of
radius epsilon of f of c--

01:16:13.510 --> 01:16:22.390 align:middle line:84%
1, 2, 3-- is an open
neighborhood of c.

01:16:22.390 --> 01:16:25.630 align:middle line:84%
But because this is
an open set around c,

01:16:25.630 --> 01:16:29.560 align:middle line:84%
there exists a delta
bigger than 0 such

01:16:29.560 --> 01:16:35.150 align:middle line:84%
that the ball of
radius delta around c

01:16:35.150 --> 01:16:39.560 align:middle line:84%
is contained in f inverse of
the ball of radius epsilon of f

01:16:39.560 --> 01:16:42.883 align:middle line:90%
of c, right?

01:16:42.883 --> 01:16:44.050 align:middle line:90%
Because this is an open set.

01:16:44.050 --> 01:16:47.290 align:middle line:84%
And therefore, we know that
there exists a radius such

01:16:47.290 --> 01:16:49.900 align:middle line:84%
that the ball of radius
delta of that radius

01:16:49.900 --> 01:16:51.655 align:middle line:90%
is contained in the open set.

01:16:51.655 --> 01:16:52.780 align:middle line:90%
And then we're done, right?

01:16:52.780 --> 01:16:54.670 align:middle line:84%
Because then we can
apply f to both sides.

01:16:54.670 --> 01:16:57.130 align:middle line:84%
And we get that f is a
ball of radius delta around

01:16:57.130 --> 01:17:01.577 align:middle line:84%
c is contained in the ball
of radius epsilon of f

01:17:01.577 --> 01:17:05.350 align:middle line:84%
of c, which is exactly the
statement of continuity.

01:17:05.350 --> 01:17:08.290 align:middle line:84%
You can just write this out in
terms of the metrics, right?

01:17:08.290 --> 01:17:13.210 align:middle line:84%
Because then the distance from
x to c being less than delta

01:17:13.210 --> 01:17:18.460 align:middle line:84%
implies that the distance
from f of x to f of c

01:17:18.460 --> 01:17:19.640 align:middle line:90%
is less than epsilon.

01:17:19.640 --> 01:17:21.590 align:middle line:90%
So this concludes the proof.

01:17:21.590 --> 01:17:22.570 align:middle line:90%
OK.

01:17:22.570 --> 01:17:25.270 align:middle line:84%
This was the general
theory of metric spaces.

01:17:25.270 --> 01:17:27.070 align:middle line:84%
We've talked about
convergent sequences,

01:17:27.070 --> 01:17:29.500 align:middle line:84%
which was essentially just
like the real numbers.

01:17:29.500 --> 01:17:32.110 align:middle line:84%
We talked about open
sets-- specifically,

01:17:32.110 --> 01:17:34.550 align:middle line:84%
the topological
properties of them,

01:17:34.550 --> 01:17:36.410 align:middle line:90%
which is important for topology.

01:17:36.410 --> 01:17:41.680 align:middle line:84%
And then we related those two
concepts to continuity, right?

01:17:41.680 --> 01:17:43.870 align:middle line:84%
We talked about how
continuity is sequentially

01:17:43.870 --> 01:17:47.650 align:middle line:84%
continuous at a point c if it's
continuous on the metric space.

01:17:47.650 --> 01:17:50.020 align:middle line:84%
And we've talked about how
continuity can be defined

01:17:50.020 --> 01:17:51.610 align:middle line:90%
in terms of these open sets.

01:17:51.610 --> 01:17:54.160 align:middle line:84%
This is by no means
a simple connection.

01:17:54.160 --> 01:17:56.810 align:middle line:84%
It can take a while to feel
comfortable with these ideas,

01:17:56.810 --> 01:18:00.160 align:middle line:84%
but I highly suggest, if you're
finding this a little bit

01:18:00.160 --> 01:18:02.800 align:middle line:84%
confusing, to try and
draw out the pictures.

01:18:02.800 --> 01:18:05.590 align:middle line:90%
Why does this conclusion hold?

01:18:05.590 --> 01:18:08.180 align:middle line:84%
Why can I apply f to both sides
and have things to be fine?

01:18:08.180 --> 01:18:09.970 align:middle line:84%
It's just a practice
in set theory,

01:18:09.970 --> 01:18:12.660 align:middle line:84%
but it is helpful
to do at some point.

01:18:12.660 --> 01:18:13.540 align:middle line:90%
OK?

01:18:13.540 --> 01:18:14.770 align:middle line:84%
Starting next time,
we're going to start

01:18:14.770 --> 01:18:16.312 align:middle line:84%
talking about
something you might not

01:18:16.312 --> 01:18:18.550 align:middle line:84%
have seen before at all
known as compact sets.

01:18:18.550 --> 01:18:20.530 align:middle line:90%
Until then have a great weekend.

01:18:20.530 --> 01:18:24.810 align:middle line:84%
Remember that the p set
is due on the 13th, OK?

01:18:24.810 --> 01:18:27.890 align:middle line:90%
All right, have a great day.

01:18:27.890 --> 01:18:34.000 align:middle line:90%