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GIAN PAOLO BERETTA: OK.

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Good morning.

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It will take us a
couple of lectures,

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I guess, to cover
this in some details.

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And it is-- we want to extend
what we know about heat transfer

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to heat and mass transfer
and charge transfer.

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And we want to do it
in a way that exhibits

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the logic of the construction.

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So this is why I am
going to restart--

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I mean, start again from
what we have already seen

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because it already
contains that logic.

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Actually, parallel
logic between what

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we've done in chemical
kinetics and what

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we've done in our simple review
of the heat transfer basics.

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And because this contains
what we want to develop item

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by item with some care and
in other details in the rest

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of this lecture or two.

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So in chemical
kinetics, let's start

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with-- because we did
this first, so let's

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start with this first.

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When we considered
the closed systems,

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we considered the
energy balance.

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It was implicit that the
energy remains constant

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if the system is isolated.

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And this is the
entropy balance that

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says that the rate
of entropy change

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is equal to the entropy
produced by irreversibility.

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Then we-- this is not
a balance of particles,

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but you could view the
proportionality relations

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as sort of a
balance in the sense

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that they account for
the rate of change

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of the number of
particles in your mixture.

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And so that is
another ingredient.

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Plus, we have assumed
something about equilibrium--

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the near-equilibrium
situation in which we--

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if it weren't for the
chemical reactions that

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are changing the composition,
our system in our model,

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so far, is very close
to what it would

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be if it were in equilibrium--
a stable equilibrium

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state without the reactions on.

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And that allows us--
so this relation here

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allows us to evaluate
the rate of change

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of the entropy which is needed
for the entropy balance.

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So we've to evaluate that.

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And when we do that rate of
change, since this depends--

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the only thing that
is changing here

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is n through the
proportionality relation--

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so you have to take
the partial of S

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with respect to n times
the rate of change of n.

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And then you keep going
and you single out

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the affinities of
the reaction, and you

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bring in the reaction rates.

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So you combine them,
this balance equation,

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with the energy balance,
which is trivial in this case,

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and you obtain an expression
for the entropy produced

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by irreversibility, which
is this product of rates

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and affinities
that we interpreted

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as degrees of disequilibrium.

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And then we assumed a law
that relates how the rates--

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relates the rates
to the affinities.

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And this law is a
nonlinear law, but

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in the near-equilibrium
limit, we have linearized it.

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And here's the parallel
structure and parallel logic

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that we followed
when we derived--

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when we did the
heat transfer basis.

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We write the energy balance.

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It takes this form.

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We will return to why
it takes this form.

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For the moment, just believe it.

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So that's the energy balance.

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This is the entropy balance.

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Also, of course, we
will return on this.

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There is-- we are talking
about a solid, a pure solid,

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there is no change
in composition,

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so the rate of change
of composition is 0.

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Then we assume,
like we did here,

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we assume something about
the local equilibrium.

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We assume local equilibrium.

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So that there is a
fundamental relation,

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we can write the Gibbs relation
between the properties.

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And this is a way to write the
Gibbs relation in order to--

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we will also see this
in more detail later.

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This is-- in order to
get rid of the pressure

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here and push the pressure in
the Gibbs-Duhem independent

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equation.

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The Gibbs relation can be used
to combine the left-hand sides

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of the balance equations.

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So you substitute the
various balance equations

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into this Gibbs relation.

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And obtain an
expression, like here,

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for the entropy produced
by irreversibility.

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Of course, we will
do the details.

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Also, because here, I've
changed the notation a bit,

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but as you know,
for a heat transfer,

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the energy flux is
just q double prime,

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and the entropy flux is
q double prime over T.

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That's the heat interaction.

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And when we do
these substitutions,

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you can rewrite the divergence
of JS as the sum of two terms.

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The first one
cancels with the one

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that comes from the
divergence of the energy flux.

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And you are left with this
final result that says that

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the entropy produced by
irreversibility-- and here,

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we are talking about entropy
produced per unit volume--

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is equal to the heat
flux times the gradient

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in the inverse
temperature, which

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we can interpret as the degree
of disequilibrium for the heat

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transfer.

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And then if we assume a linear
law, then we get Fourier.

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In other words, if you-- by
looking at this expression here,

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if--

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and knowing that the entropy
produced by irreversibility must

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be non-negative, the simple
way is to assume that q is--

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that the flux is
proportional to the gradient

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through a positive constant
of proportionality, which

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could end-- actually,
since it is a vector,

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the most general linear
relation between two vectors

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is through a tensor.

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So we take a positive
tensor in between here,

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which assures that the sigma
is going to be non-negative.

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And then-- so we
get Fourier law.

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And also, we have seen that if
we accept Onsager's reciprocity

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theorem, that tensor
not only needs

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to be positive definite--
or non-negative definite,

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but it also needs
to be symmetric.

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You can also invert it.

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And therefore, the
entropy production

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becomes a quadratic form in
the degrees of disequilibrium,

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or equivalently, a quadratic
form in the fluxes.

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OK.

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So the ingredients are
write the energy balance,

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do something about
the Gibbs relation--

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or write the Gibbs
relation in this form

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so that you can combine these
balances in a proper way.

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Make an assumption about
the kind of interaction

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that is occurring between
the various parcels

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or elements of your continuum.

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And then assume-- if you
want to be near equilibrium,

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you can assume a
linear relation.

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And if you want to discuss
more non-equilibrium--

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I mean, not near-equilibrium--
far from equilibrium,

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then you need to develop
some more elaborate theories.

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And also, here,
there is space, as we

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have seen for the Cattaneo
correction to Fourier law,

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there is space to account--

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or to solve some of the
problems of the Fourier

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law, the infinite speed
of propagation that

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is implied by this expression.

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So let's start.

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We take them one by one.

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So we have to be
patient, but this

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will give us also
some opportunity

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to highlight a few
of the details.

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This procedure that
I am describing

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varies depending on the
field of application.

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In particular, I
need to mention,

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but I'm not going to
follow precisely or--

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but there is strong connections
with a famous procedure called--

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under the names of
Coleman and Noll,

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which is used more by the
community of solid mechanics

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people that study
plasticity, viscoelasticity.

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For example, not to go too far,
if you go to Professor Lallit

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Anand in this department,
he has written books

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and he is renowned
for that procedure.

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I am more inclined,
since I have studied

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with people in the
fluid mechanics area,

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I am more inclined to
describe the procedure that

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applies for fluid mechanics
kind of applications.

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But the logics are very similar.

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Except when it comes to this
generalization of the heat

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interaction, that,
instead, is peculiar,

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of course, of our course
here because also,

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the definition of heat is
peculiar to our course.

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Not yet very
widespread in textbooks

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or other scientific papers.

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OK, so let's start
with this simple.

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Take a piece of
material, fluid element.

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So already, the fact
that I call it fluid

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means it shows you
my inclination.

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And as you know,
this department has

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had very influential
professors in fluid mechanics.

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And heat transfer.

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So Rosenow, Shapiro, Sonin,
just to mention a few.

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So I have these
one-dimensional piece of fluid.

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And it's subjected to
interactions on one side

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and on the other side.

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And when we did
heat transfer, we

00:14:35.340 --> 00:14:39.660 align:middle line:84%
were considering only
energy and entropy.

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Now here, we're going
to introduce also

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a flux of particles.

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And also, here,
you have the flux.

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And this is a component-- the
x-component because we are

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one-dimensional--

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of the flux, and
it changes as you

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move from the face at x
and the face at x plus dx.

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And the area of exchange
between the adjacent--

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between these fluid element
and the one to its right is A.

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And also, the area on the other
side, of course, is, again, A.

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We want to make a
general energy balance,

00:15:38.855 --> 00:15:40.605 align:middle line:84%
so we're not going to
assume steady state.

00:15:40.605 --> 00:15:45.420 align:middle line:90%


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So we call the energy of the
fluid in this lamina delta

00:15:56.300 --> 00:15:58.290 align:middle line:90%
E. Why delta?

00:15:58.290 --> 00:16:01.650 align:middle line:90%
Because it's infinitesimal.

00:16:01.650 --> 00:16:03.820 align:middle line:84%
Since the thickness
is infinitesimal,

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it's from x to x plus dx.

00:16:06.690 --> 00:16:12.510 align:middle line:84%
So that is an infinitesimal
amount of energy.

00:16:12.510 --> 00:16:15.630 align:middle line:84%
Related to the fact that it
has an infinitesimal amount

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of volume, which is given
by the area times dx.

00:16:19.230 --> 00:16:22.390 align:middle line:90%


00:16:22.390 --> 00:16:27.810 align:middle line:84%
And the specific
energy per unit volume,

00:16:27.810 --> 00:16:32.130 align:middle line:84%
you can write it, as we
know, like rho times u,

00:16:32.130 --> 00:16:36.630 align:middle line:84%
and u here is really
u star, what we

00:16:36.630 --> 00:16:38.990 align:middle line:90%
call the energy per unit mass.

00:16:38.990 --> 00:16:42.990 align:middle line:90%


00:16:42.990 --> 00:16:43.980 align:middle line:90%
All right.

00:16:43.980 --> 00:16:47.140 align:middle line:84%
So you write it--
you need volume,

00:16:47.140 --> 00:16:53.350 align:middle line:84%
and then we can also substitute
the volume for A times dx.

00:16:53.350 --> 00:17:01.710 align:middle line:84%
The same-- I mean, this
system has also entropy.

00:17:01.710 --> 00:17:03.540 align:middle line:90%
And here's the entropy.

00:17:03.540 --> 00:17:07.349 align:middle line:84%
Also infinitesimal because
it's an infinitesimal amount

00:17:07.349 --> 00:17:09.690 align:middle line:90%
of material.

00:17:09.690 --> 00:17:12.550 align:middle line:90%
And it stays like that.

00:17:12.550 --> 00:17:17.640 align:middle line:84%
So it's the volume times
the specific entropy

00:17:17.640 --> 00:17:20.449 align:middle line:84%
per unit volume, which
is rho times s star.

00:17:20.449 --> 00:17:24.760 align:middle line:90%


00:17:24.760 --> 00:17:29.650 align:middle line:84%
And also the amounts,
they are infinitesimal.

00:17:29.650 --> 00:17:36.340 align:middle line:84%
And the amount per unit
volume is the concentration.

00:17:36.340 --> 00:17:40.990 align:middle line:84%
So you can write that as
concentration times the volume.

00:17:40.990 --> 00:17:43.465 align:middle line:90%
OK.

00:17:43.465 --> 00:17:53.400 align:middle line:84%
Now inside these element, we
have also some volume effects.

00:17:53.400 --> 00:17:57.060 align:middle line:84%
For example, chemical reactions
that are occurring inside--

00:17:57.060 --> 00:18:00.340 align:middle line:90%
in the interior.

00:18:00.340 --> 00:18:05.440 align:middle line:84%
And therefore, the
proportionality relations

00:18:05.440 --> 00:18:09.830 align:middle line:84%
are governed by
this epsilon dot,

00:18:09.830 --> 00:18:13.180 align:middle line:84%
which are the rates
of advancement

00:18:13.180 --> 00:18:16.770 align:middle line:90%
of the reaction coordinates.

00:18:16.770 --> 00:18:21.690 align:middle line:84%
We can write also that as
the volume times the reaction

00:18:21.690 --> 00:18:24.420 align:middle line:84%
rate per unit volume,
which is typically

00:18:24.420 --> 00:18:28.030 align:middle line:90%
called r without the dot.

00:18:28.030 --> 00:18:30.940 align:middle line:90%


00:18:30.940 --> 00:18:34.210 align:middle line:84%
And then the other is
the entropy production

00:18:34.210 --> 00:18:41.050 align:middle line:84%
due to irreversibility, which
occurs throughout the volume

00:18:41.050 --> 00:18:44.330 align:middle line:90%
of this system.

00:18:44.330 --> 00:18:49.380 align:middle line:84%
And that, too, we like to write
in terms of per-unit volume.

00:18:49.380 --> 00:18:55.200 align:middle line:84%
So we have defined this symbol s
dot rate of entropy production.

00:18:55.200 --> 00:19:00.440 align:middle line:84%
Triple means per unit
volume, and soon, we

00:19:00.440 --> 00:19:03.940 align:middle line:84%
have already started
calling this thing sigma.

00:19:03.940 --> 00:19:07.730 align:middle line:90%


00:19:07.730 --> 00:19:08.950 align:middle line:90%
All right.

00:19:08.950 --> 00:19:13.760 align:middle line:90%
So here is the energy balance.

00:19:13.760 --> 00:19:19.760 align:middle line:84%
It says the rate of change
of the energy of our system

00:19:19.760 --> 00:19:26.990 align:middle line:84%
is equal to the net
energy it exchanges

00:19:26.990 --> 00:19:30.140 align:middle line:90%
through the interactions.

00:19:30.140 --> 00:19:35.610 align:middle line:84%
And here, it has interactions
on the left and on the right.

00:19:35.610 --> 00:19:39.150 align:middle line:90%
And the net is the difference.

00:19:39.150 --> 00:19:45.120 align:middle line:84%
And you have to take it with
a minus sign if it goes out.

00:19:45.120 --> 00:19:49.470 align:middle line:84%
So if this one is
greater than that one,

00:19:49.470 --> 00:19:53.940 align:middle line:84%
the difference is
this term here.

00:19:53.940 --> 00:19:55.660 align:middle line:90%
And that is per unit area.

00:19:55.660 --> 00:19:58.865 align:middle line:84%
And then you have to
multiply by the area.

00:19:58.865 --> 00:20:03.940 align:middle line:90%


00:20:03.940 --> 00:20:06.890 align:middle line:84%
And that is it, because
energy is conserved.

00:20:06.890 --> 00:20:09.500 align:middle line:90%


00:20:09.500 --> 00:20:10.940 align:middle line:90%
Let's go to entropy.

00:20:10.940 --> 00:20:12.860 align:middle line:84%
The entropy balance
says the rate

00:20:12.860 --> 00:20:15.920 align:middle line:84%
of change of the entropy
of our fluid element

00:20:15.920 --> 00:20:24.550 align:middle line:84%
is equal to the net entropy
flux, via interaction.

00:20:24.550 --> 00:20:28.330 align:middle line:84%
So here, I have,
again, left and right.

00:20:28.330 --> 00:20:34.700 align:middle line:84%
The difference is
this term here.

00:20:34.700 --> 00:20:39.340 align:middle line:84%
And with the negative sign
because if it is positive,

00:20:39.340 --> 00:20:43.180 align:middle line:84%
you have more entropy
going out than coming in,

00:20:43.180 --> 00:20:45.450 align:middle line:90%
and that's this term here.

00:20:45.450 --> 00:20:48.110 align:middle line:90%


00:20:48.110 --> 00:20:55.700 align:middle line:84%
I think there is an error here
because I need also an area.

00:20:55.700 --> 00:20:57.200 align:middle line:90%
Like here.

00:20:57.200 --> 00:21:01.830 align:middle line:84%
I need to multiply by A.
I need to correct that.

00:21:01.830 --> 00:21:06.020 align:middle line:90%


00:21:06.020 --> 00:21:08.880 align:middle line:84%
That doesn't finish
the entropy balance

00:21:08.880 --> 00:21:12.500 align:middle line:84%
because you also have to account
for the entropy generation

00:21:12.500 --> 00:21:17.930 align:middle line:84%
inside the element due
to irreversibility.

00:21:17.930 --> 00:21:19.870 align:middle line:90%
Now what do we do?

00:21:19.870 --> 00:21:29.210 align:middle line:84%
We simply divide by the
volume delta V left and right

00:21:29.210 --> 00:21:32.620 align:middle line:84%
of these equations, and
here is what you get.

00:21:32.620 --> 00:21:40.160 align:middle line:90%


00:21:40.160 --> 00:21:42.180 align:middle line:84%
So these are the
balance equations.

00:21:42.180 --> 00:21:45.070 align:middle line:90%


00:21:45.070 --> 00:21:56.180 align:middle line:84%
Now I want to open a little
digression that is nevertheless

00:21:56.180 --> 00:22:04.930 align:middle line:84%
important regarding
how we describe

00:22:04.930 --> 00:22:07.700 align:middle line:84%
the properties of a
continuum-- in particular,

00:22:07.700 --> 00:22:12.140 align:middle line:84%
the extensive
properties like energy,

00:22:12.140 --> 00:22:17.680 align:middle line:84%
mass, entropy, and
a bunch of others

00:22:17.680 --> 00:22:22.360 align:middle line:84%
that I'll have in
a summary table.

00:22:22.360 --> 00:22:33.110 align:middle line:84%
So let's consider, like we
typically do in fluid mechanics,

00:22:33.110 --> 00:22:37.990 align:middle line:90%
we consider a volume.

00:22:37.990 --> 00:22:41.120 align:middle line:84%
Call it sigma M. So
it's a material volume.

00:22:41.120 --> 00:22:44.880 align:middle line:84%
So I select at a
certain instant of time

00:22:44.880 --> 00:22:51.830 align:middle line:84%
a certain bunch of particles
contained inside this volume.

00:22:51.830 --> 00:23:02.150 align:middle line:84%
And I denote the surface of
that as partial of sigma M. M

00:23:02.150 --> 00:23:03.823 align:middle line:90%
stands for material.

00:23:03.823 --> 00:23:07.180 align:middle line:90%


00:23:07.180 --> 00:23:16.230 align:middle line:84%
Of course, when the fluid
moves, you need to--

00:23:16.230 --> 00:23:19.320 align:middle line:84%
if you want to follow the
material volume in all

00:23:19.320 --> 00:23:25.710 align:middle line:84%
this problem, is that you need
to track all the particles that

00:23:25.710 --> 00:23:29.610 align:middle line:84%
are inside here
at time, say, t1.

00:23:29.610 --> 00:23:34.140 align:middle line:84%
And then at time t2, you need
to see where all those particles

00:23:34.140 --> 00:23:37.140 align:middle line:84%
have gone and consider
another volume that

00:23:37.140 --> 00:23:40.270 align:middle line:90%
contains only those particles.

00:23:40.270 --> 00:23:43.180 align:middle line:90%


00:23:43.180 --> 00:23:47.930 align:middle line:84%
And so these would be a
Lagrangian point of view,

00:23:47.930 --> 00:23:52.480 align:middle line:84%
and it's complicated, so
that's why in fluid mechanics,

00:23:52.480 --> 00:23:58.290 align:middle line:84%
you introduce control volumes
and the Eulerian point of view.

00:23:58.290 --> 00:24:03.340 align:middle line:84%
But that's not-- we're not
doing control volumes here.

00:24:03.340 --> 00:24:05.260 align:middle line:90%
They do them in fluid mechanics.

00:24:05.260 --> 00:24:10.240 align:middle line:84%
But what I'm doing here is
just the balance equations,

00:24:10.240 --> 00:24:15.960 align:middle line:84%
and in particular, I want
to obtain from the balance

00:24:15.960 --> 00:24:20.490 align:middle line:84%
equation written for the
material volume, the balance

00:24:20.490 --> 00:24:24.720 align:middle line:84%
equation written for the
infinitesimal element

00:24:24.720 --> 00:24:25.540 align:middle line:90%
of that volume.

00:24:25.540 --> 00:24:28.050 align:middle line:90%
So in other words, something--

00:24:28.050 --> 00:24:33.300 align:middle line:84%
what we usually call
the indefinite balance

00:24:33.300 --> 00:24:42.430 align:middle line:84%
equations that are what holds
point by point in our continuum.

00:24:42.430 --> 00:24:46.190 align:middle line:90%


00:24:46.190 --> 00:24:50.210 align:middle line:84%
So first of all, let's call
the generic property-- think

00:24:50.210 --> 00:24:53.930 align:middle line:84%
of energy, but then it could be
also entropy, let's call it A,

00:24:53.930 --> 00:24:56.440 align:middle line:90%
capital A. Or even mass.

00:24:56.440 --> 00:24:59.870 align:middle line:90%


00:24:59.870 --> 00:25:00.730 align:middle line:90%
Even volume.

00:25:00.730 --> 00:25:03.280 align:middle line:90%


00:25:03.280 --> 00:25:08.515 align:middle line:84%
And we call it extensive
if you can say--

00:25:08.515 --> 00:25:16.140 align:middle line:84%
if you can assign to that
property a local field little a.

00:25:16.140 --> 00:25:20.617 align:middle line:84%
And field means it's defined
at every point in space.

00:25:20.617 --> 00:25:24.840 align:middle line:90%
x is x, y, z, and t is time.

00:25:24.840 --> 00:25:27.900 align:middle line:90%
So this is the field.

00:25:27.900 --> 00:25:28.760 align:middle line:90%
Like density.

00:25:28.760 --> 00:25:33.010 align:middle line:90%


00:25:33.010 --> 00:25:35.830 align:middle line:84%
So you want to--
you are assuming

00:25:35.830 --> 00:25:44.080 align:middle line:84%
that you can define a density
field as a function of position

00:25:44.080 --> 00:25:46.660 align:middle line:90%
and time.

00:25:46.660 --> 00:25:52.120 align:middle line:84%
So that you can write
the overall property

00:25:52.120 --> 00:25:58.240 align:middle line:84%
for the material volume as
the sum of contributions

00:25:58.240 --> 00:26:00.160 align:middle line:90%
for all the parts.

00:26:00.160 --> 00:26:06.670 align:middle line:84%
So in other words, the integral
of that property per unit volume

00:26:06.670 --> 00:26:10.130 align:middle line:90%
times the volume.

00:26:10.130 --> 00:26:15.895 align:middle line:84%
OK, so rho times a is
property A per unit volume.

00:26:15.895 --> 00:26:20.790 align:middle line:90%


00:26:20.790 --> 00:26:22.895 align:middle line:90%
OK.

00:26:22.895 --> 00:26:28.220 align:middle line:84%
Once you have that, you have
seen in the balance equations--

00:26:28.220 --> 00:26:30.460 align:middle line:84%
for example, the left-hand
side of the energy balance

00:26:30.460 --> 00:26:35.200 align:middle line:84%
or the entropy balance, you
need to take the rate of change

00:26:35.200 --> 00:26:41.480 align:middle line:84%
of the energy of your system or
of the entropy of your system.

00:26:41.480 --> 00:26:45.200 align:middle line:84%
So we need to take the
rate of change, d by dt,

00:26:45.200 --> 00:26:52.200 align:middle line:84%
of this integral to compute the
left-hand side of the balance

00:26:52.200 --> 00:26:54.800 align:middle line:90%
equations.

00:26:54.800 --> 00:27:04.170 align:middle line:84%
And since the
material volume moves,

00:27:04.170 --> 00:27:09.420 align:middle line:84%
you cannot just take the
derivative inside the integral.

00:27:09.420 --> 00:27:15.370 align:middle line:84%
Yes, you can, that does
part of the contribution.

00:27:15.370 --> 00:27:18.070 align:middle line:84%
But there is another part
which is due to the fact

00:27:18.070 --> 00:27:20.260 align:middle line:84%
that the limits of
integration, namely

00:27:20.260 --> 00:27:25.970 align:middle line:84%
this surface that follows the
particles as they move, moves.

00:27:25.970 --> 00:27:32.150 align:middle line:84%
And therefore, you have to
write a surface integral--

00:27:32.150 --> 00:27:34.840 align:middle line:84%
so an integral
over the surface--

00:27:34.840 --> 00:27:38.560 align:middle line:90%
of-- that takes into account--

00:27:38.560 --> 00:27:45.180 align:middle line:84%
for each of these
surface positions,

00:27:45.180 --> 00:27:47.700 align:middle line:90%
you have to take into account--

00:27:47.700 --> 00:27:54.700 align:middle line:84%
first of all, you
assign a unit vector.

00:27:54.700 --> 00:27:58.900 align:middle line:84%
And by convention,
usually I typically

00:27:58.900 --> 00:28:01.770 align:middle line:90%
choose positive outward.

00:28:01.770 --> 00:28:04.530 align:middle line:90%


00:28:04.530 --> 00:28:10.920 align:middle line:84%
And then I have to see how
the molecules on this point

00:28:10.920 --> 00:28:13.640 align:middle line:90%
of the surface move.

00:28:13.640 --> 00:28:19.040 align:middle line:84%
And that I call the
velocity, v sub m.

00:28:19.040 --> 00:28:23.370 align:middle line:90%


00:28:23.370 --> 00:28:28.466 align:middle line:84%
Which we will call soon
the barycentric velocity.

00:28:28.466 --> 00:28:35.800 align:middle line:90%


00:28:35.800 --> 00:28:39.580 align:middle line:84%
Because, in fact, before
I call it v sub m,

00:28:39.580 --> 00:28:44.370 align:middle line:84%
it simply should be the
velocity assigned to the surface

00:28:44.370 --> 00:28:47.140 align:middle line:90%
of the material volume.

00:28:47.140 --> 00:28:50.470 align:middle line:84%
And then it turns out that since
the volume is a material volume,

00:28:50.470 --> 00:28:55.380 align:middle line:84%
so it's made of particles,
that part of the surface

00:28:55.380 --> 00:28:59.570 align:middle line:84%
moves with the velocity of
the particles that are there.

00:28:59.570 --> 00:29:02.450 align:middle line:84%
And the velocity of
the particles is vm.

00:29:02.450 --> 00:29:08.000 align:middle line:90%


00:29:08.000 --> 00:29:13.640 align:middle line:84%
So the net-- so since the
velocity may have a different

00:29:13.640 --> 00:29:17.060 align:middle line:84%
direction than the
normal to the surface,

00:29:17.060 --> 00:29:27.830 align:middle line:84%
what brings the particles,
say, out of this volume

00:29:27.830 --> 00:29:31.580 align:middle line:84%
and contribute to that
surface integral--

00:29:31.580 --> 00:29:34.850 align:middle line:84%
or contribute to changing
the surface integral

00:29:34.850 --> 00:29:38.460 align:middle line:84%
is only the component that is
in the direction of the normal.

00:29:38.460 --> 00:29:42.680 align:middle line:84%
So that's why you take the
scalar product of v and n

00:29:42.680 --> 00:29:50.210 align:middle line:84%
to get the normal component that
contributes to moving stuff out

00:29:50.210 --> 00:29:52.510 align:middle line:90%
of that--

00:29:52.510 --> 00:29:54.805 align:middle line:90%
say energy out of that surface.

00:29:54.805 --> 00:29:58.200 align:middle line:90%


00:29:58.200 --> 00:30:03.370 align:middle line:84%
And then you convert
by using the divergence

00:30:03.370 --> 00:30:08.830 align:middle line:84%
theorem, a surface integral
of this form something,

00:30:08.830 --> 00:30:15.590 align:middle line:84%
dotted into n, is equal to
the integral of the volume--

00:30:15.590 --> 00:30:17.890 align:middle line:84%
the volume integral
of the divergence

00:30:17.890 --> 00:30:22.300 align:middle line:90%
of whatever is dotted into n.

00:30:22.300 --> 00:30:23.325 align:middle line:90%
And so you get this.

00:30:23.325 --> 00:30:31.790 align:middle line:90%


00:30:31.790 --> 00:30:34.700 align:middle line:84%
So we transformed this,
the rate of change

00:30:34.700 --> 00:30:40.230 align:middle line:84%
in an integral-- in a volume
integral of two contributions,

00:30:40.230 --> 00:30:48.370 align:middle line:84%
the partial with respect to t
and the divergence of rho a vm.

00:30:48.370 --> 00:30:55.575 align:middle line:84%
These will be called the
convective flux in a moment.

00:30:55.575 --> 00:31:02.240 align:middle line:90%


00:31:02.240 --> 00:31:07.346 align:middle line:84%
Because that property
that is exchanged--

00:31:07.346 --> 00:31:10.185 align:middle line:90%


00:31:10.185 --> 00:31:10.685 align:middle line:90%
OK.

00:31:10.685 --> 00:31:15.200 align:middle line:90%


00:31:15.200 --> 00:31:20.100 align:middle line:84%
OK, we are talking about
property A. So property A,

00:31:20.100 --> 00:31:23.930 align:middle line:90%
like, say, heat--

00:31:23.930 --> 00:31:31.500 align:middle line:84%
I mean energy, if you have
a heat interaction happening

00:31:31.500 --> 00:31:35.910 align:middle line:84%
on the surface of
this control volume--

00:31:35.910 --> 00:31:42.530 align:middle line:84%
so you have, say,
another vector here,

00:31:42.530 --> 00:31:51.880 align:middle line:84%
which would be q double prime,
that is important in your energy

00:31:51.880 --> 00:31:58.390 align:middle line:84%
balance because even if it is
true that the surface follows

00:31:58.390 --> 00:32:01.155 align:middle line:84%
the particles-- so the
particles don't go out.

00:32:01.155 --> 00:32:05.480 align:middle line:90%


00:32:05.480 --> 00:32:09.230 align:middle line:84%
But if there is a
heat interaction

00:32:09.230 --> 00:32:11.990 align:middle line:84%
between those particles
inside your material

00:32:11.990 --> 00:32:14.000 align:middle line:84%
volume and those
outside, then there

00:32:14.000 --> 00:32:15.780 align:middle line:84%
is energy transfer
between the two,

00:32:15.780 --> 00:32:19.890 align:middle line:84%
and the energy transfer is
represented by this vector here.

00:32:19.890 --> 00:32:28.860 align:middle line:84%
And there is also, of
course, an entropy transfer

00:32:28.860 --> 00:32:31.840 align:middle line:84%
in the same direction if
it is a heat interaction.

00:32:31.840 --> 00:32:40.480 align:middle line:90%


00:32:40.480 --> 00:32:46.940 align:middle line:90%
So what we define as flux--

00:32:46.940 --> 00:32:49.200 align:middle line:90%
because these are fluxes.

00:32:49.200 --> 00:32:55.610 align:middle line:84%
So it's energy per unit
area per unit time.

00:32:55.610 --> 00:33:02.240 align:middle line:84%
Energy exchanged per
unit area per unit time.

00:33:02.240 --> 00:33:04.970 align:middle line:90%
And we give that--

00:33:04.970 --> 00:33:08.570 align:middle line:90%
the genetic symbol J sub A--

00:33:08.570 --> 00:33:20.930 align:middle line:84%
or actually, J 0 sub A.
And it's defined this way.

00:33:20.930 --> 00:33:25.010 align:middle line:84%
And once I have defined
that, I can also

00:33:25.010 --> 00:33:31.360 align:middle line:84%
assign a velocity of
transfer of that quantity.

00:33:31.360 --> 00:33:36.980 align:middle line:90%


00:33:36.980 --> 00:33:41.070 align:middle line:84%
So I have the flux,
to which is assigned

00:33:41.070 --> 00:33:45.680 align:middle line:84%
the velocity of transfer,
by dividing the flux

00:33:45.680 --> 00:33:49.050 align:middle line:90%
by the property per unit volume.

00:33:49.050 --> 00:33:53.240 align:middle line:84%
So if I take q double prime
and divide it by rho u--

00:33:53.240 --> 00:34:03.640 align:middle line:84%
q double prime divided by rho
u, that gives me a velocity.

00:34:03.640 --> 00:34:10.050 align:middle line:84%
We could call that
velocity the transport--

00:34:10.050 --> 00:34:12.070 align:middle line:90%
the heat transport velocity.

00:34:12.070 --> 00:34:14.770 align:middle line:90%


00:34:14.770 --> 00:34:19.389 align:middle line:84%
And also, you could
have q double prime

00:34:19.389 --> 00:34:24.130 align:middle line:84%
over T, which is the
entropy divided by rho S,

00:34:24.130 --> 00:34:33.790 align:middle line:84%
And that would be the
transport velocity for entropy.

00:34:33.790 --> 00:34:41.969 align:middle line:90%


00:34:41.969 --> 00:34:47.090 align:middle line:84%
The transport velocity for
momentum (I meant, mass)

00:34:47.090 --> 00:34:51.920 align:middle line:84%
is the barycentric velocity,
the velocity that you typically

00:34:51.920 --> 00:34:53.810 align:middle line:90%
use in fluid mechanics.

00:34:53.810 --> 00:34:58.160 align:middle line:84%
If you say, the fluid
has a velocity field v,

00:34:58.160 --> 00:35:05.420 align:middle line:84%
you mean this velocity is
the mass transport velocity.

00:35:05.420 --> 00:35:24.940 align:middle line:84%
So it's Jm, which is the
flux of mass, divided by rho,

00:35:24.940 --> 00:35:29.410 align:middle line:84%
because rho is the
mass per unit volume,

00:35:29.410 --> 00:35:35.030 align:middle line:84%
and that is the barycentric
velocity of fluid mechanics.

00:35:35.030 --> 00:35:51.980 align:middle line:90%


00:35:51.980 --> 00:35:53.684 align:middle line:90%
OK.

00:35:53.684 --> 00:36:03.150 align:middle line:84%
Now-- so this velocity-- this
flux with the 0 on top is,

00:36:03.150 --> 00:36:09.320 align:middle line:90%
in terms of a reference frame--

00:36:09.320 --> 00:36:12.610 align:middle line:90%


00:36:12.610 --> 00:36:13.570 align:middle line:90%
yeah.

00:36:13.570 --> 00:36:14.070 align:middle line:90%
OK.

00:36:14.070 --> 00:36:17.020 align:middle line:84%
Reference frame the
laboratory reference frame

00:36:17.020 --> 00:36:19.090 align:middle line:84%
with respect to which
you measure velocity

00:36:19.090 --> 00:36:21.340 align:middle line:90%
of your fluid elements.

00:36:21.340 --> 00:36:28.360 align:middle line:84%
However, you could also
consider a local reference frame

00:36:28.360 --> 00:36:34.150 align:middle line:84%
to your fluid element that
moves with the velocity vm.

00:36:34.150 --> 00:36:36.840 align:middle line:90%


00:36:36.840 --> 00:36:40.430 align:middle line:84%
So you move with
your fluid element.

00:36:40.430 --> 00:36:43.790 align:middle line:90%


00:36:43.790 --> 00:36:48.600 align:middle line:84%
Well actually, the fluid element
is made up of many particles.

00:36:48.600 --> 00:36:51.770 align:middle line:84%
So you have-- you're not
moving with the velocity of one

00:36:51.770 --> 00:36:55.610 align:middle line:84%
particular particle, but
with a weighted average

00:36:55.610 --> 00:36:59.910 align:middle line:84%
of the velocity, which is
the barycentric velocity

00:36:59.910 --> 00:37:01.180 align:middle line:90%
of those particles.

00:37:01.180 --> 00:37:07.250 align:middle line:90%


00:37:07.250 --> 00:37:13.340 align:middle line:84%
So relative to that, if I
take the velocity of transport

00:37:13.340 --> 00:37:21.240 align:middle line:84%
of this property, and I view
it from that reference frame--

00:37:21.240 --> 00:37:24.140 align:middle line:84%
so the relative
velocity is vA minus vm.

00:37:24.140 --> 00:37:26.710 align:middle line:90%


00:37:26.710 --> 00:37:30.030 align:middle line:90%
So I define these flux.

00:37:30.030 --> 00:37:34.520 align:middle line:90%


00:37:34.520 --> 00:37:39.510 align:middle line:90%
And we call it diffusive flux.

00:37:39.510 --> 00:37:42.710 align:middle line:90%


00:37:42.710 --> 00:37:47.660 align:middle line:84%
So it's the flux relative to
the local barycentric velocity.

00:37:47.660 --> 00:37:53.560 align:middle line:84%
This is the most
practically used

00:37:53.560 --> 00:37:57.830 align:middle line:84%
and what appears typically
in the balance equations,

00:37:57.830 --> 00:38:00.380 align:middle line:84%
but also, this
other one appears.

00:38:00.380 --> 00:38:03.850 align:middle line:84%
So you have to be careful
if you are in this business

00:38:03.850 --> 00:38:12.690 align:middle line:84%
and you see balance equations,
you have to be careful whether--

00:38:12.690 --> 00:38:15.330 align:middle line:84%
because sometimes people
don't put the naught.

00:38:15.330 --> 00:38:19.960 align:middle line:84%
Actually, almost never
put the distinction.

00:38:19.960 --> 00:38:24.360 align:middle line:84%
They just pick one way
of describing fluxes

00:38:24.360 --> 00:38:27.780 align:middle line:84%
and then keep going,
and presume that

00:38:27.780 --> 00:38:33.600 align:middle line:84%
from the context of the paper,
you can understand which one--

00:38:33.600 --> 00:38:35.730 align:middle line:90%
which is what.

00:38:35.730 --> 00:38:40.875 align:middle line:84%
Now the same concept of flux
applies also, as you know,

00:38:40.875 --> 00:38:42.130 align:middle line:90%
to vectors.

00:38:42.130 --> 00:38:43.535 align:middle line:90%
So you can transfer momentum.

00:38:43.535 --> 00:38:46.430 align:middle line:90%


00:38:46.430 --> 00:38:55.390 align:middle line:84%
And so if you define
the diffusive flux where

00:38:55.390 --> 00:38:59.770 align:middle line:90%
the property A is momentum--

00:38:59.770 --> 00:39:05.637 align:middle line:84%
actually-- so little a is the
barycentric velocity itself.

00:39:05.637 --> 00:39:10.390 align:middle line:90%


00:39:10.390 --> 00:39:15.970 align:middle line:90%
Then you obtain the diffusion--

00:39:15.970 --> 00:39:21.340 align:middle line:84%
momentum diffusion flux, which
is the negative of the stress

00:39:21.340 --> 00:39:21.840 align:middle line:90%
tensor.

00:39:21.840 --> 00:39:25.480 align:middle line:90%


00:39:25.480 --> 00:39:26.985 align:middle line:90%
Also called the pressure tensor.

00:39:26.985 --> 00:39:33.060 align:middle line:90%


00:39:33.060 --> 00:39:37.300 align:middle line:84%
And typically, the
stress tensor is

00:39:37.300 --> 00:39:43.546 align:middle line:84%
split into two parts,
an isotropic part with--

00:39:43.546 --> 00:39:48.180 align:middle line:90%


00:39:48.180 --> 00:39:52.110 align:middle line:84%
delta is like a
tensor isotropic.

00:39:52.110 --> 00:39:55.210 align:middle line:84%
So 1, 1, 1 on the diagonal
and 0 off the diagonal.

00:39:55.210 --> 00:40:02.096 align:middle line:84%
And that-- this
is the trace of--

00:40:02.096 --> 00:40:09.340 align:middle line:90%


00:40:09.340 --> 00:40:12.910 align:middle line:84%
pm is the trace of
the stress tensor--

00:40:12.910 --> 00:40:16.280 align:middle line:84%
I'm sorry, of the pressure
tensor, and divided by 3,

00:40:16.280 --> 00:40:20.330 align:middle line:84%
and it is called the
mechanical energy (I meant,

00:40:20.330 --> 00:40:22.480 align:middle line:84%
mechanical pressure),
which is not

00:40:22.480 --> 00:40:29.025 align:middle line:84%
necessarily equal to the
thermodynamic pressure.

00:40:29.025 --> 00:40:38.100 align:middle line:90%


00:40:38.100 --> 00:40:40.338 align:middle line:90%
OK.

00:40:40.338 --> 00:40:50.240 align:middle line:84%
So what we instead
call convective flux

00:40:50.240 --> 00:40:52.970 align:middle line:84%
is the flux of
that property which

00:40:52.970 --> 00:40:57.620 align:middle line:84%
is transported by the
simple translation

00:40:57.620 --> 00:40:59.330 align:middle line:90%
of the fluid element.

00:40:59.330 --> 00:41:07.610 align:middle line:90%


00:41:07.610 --> 00:41:12.590 align:middle line:84%
The fact that the
fluid element moves,

00:41:12.590 --> 00:41:16.650 align:middle line:84%
it brings with itself the
properties that it has inside.

00:41:16.650 --> 00:41:20.550 align:middle line:84%
So that produces a flux
movement of the property.

00:41:20.550 --> 00:41:25.830 align:middle line:84%
If there is energy in that
box and you move the box,

00:41:25.830 --> 00:41:27.460 align:middle line:90%
you're moving energy.

00:41:27.460 --> 00:41:30.170 align:middle line:90%
So that is convection.

00:41:30.170 --> 00:41:40.050 align:middle line:84%
And it's the difference
between this and the diffusive.

00:41:40.050 --> 00:41:44.050 align:middle line:90%


00:41:44.050 --> 00:41:50.030 align:middle line:84%
Or, if you want, you can
write the flux with respect

00:41:50.030 --> 00:41:55.880 align:middle line:84%
to the reference frame
as a sum of the diffusive

00:41:55.880 --> 00:41:57.805 align:middle line:90%
plus the convective flux.

00:41:57.805 --> 00:42:03.430 align:middle line:90%


00:42:03.430 --> 00:42:04.906 align:middle line:90%
OK.

00:42:04.906 --> 00:42:17.020 align:middle line:84%
So the convective
momentum flux is the fact

00:42:17.020 --> 00:42:23.790 align:middle line:84%
that this fluid element, since
it's moving, it has momentum.

00:42:23.790 --> 00:42:26.070 align:middle line:84%
And the momentum
per unit volume is

00:42:26.070 --> 00:42:29.910 align:middle line:84%
rho v. And since it's
moving with velocity v,

00:42:29.910 --> 00:42:35.250 align:middle line:84%
you're transporting
momentum by simple motion.

00:42:35.250 --> 00:42:38.810 align:middle line:84%
So it's not diffusion,
it's just due to the fact

00:42:38.810 --> 00:42:43.610 align:middle line:84%
that the thing is moving, and
that is convective momentum

00:42:43.610 --> 00:42:44.590 align:middle line:90%
transport.

00:42:44.590 --> 00:43:05.120 align:middle line:90%


00:43:05.120 --> 00:43:14.080 align:middle line:84%
Now inside your material volume,
inside that fluid element,

00:43:14.080 --> 00:43:18.140 align:middle line:84%
there are certain
things that happen.

00:43:18.140 --> 00:43:20.210 align:middle line:84%
For example, per unit
volume-- for example,

00:43:20.210 --> 00:43:22.030 align:middle line:84%
the entropy produced
by irreversibility

00:43:22.030 --> 00:43:23.840 align:middle line:90%
is locally produced.

00:43:23.840 --> 00:43:33.450 align:middle line:84%
So it's something that when
you want to account for it,

00:43:33.450 --> 00:43:38.300 align:middle line:84%
you have to take it,
multiply it by the volume,

00:43:38.300 --> 00:43:41.910 align:middle line:90%
and then integrate.

00:43:41.910 --> 00:43:45.310 align:middle line:84%
So this you can view
it as a source term.

00:43:45.310 --> 00:43:47.500 align:middle line:84%
I mean, for the entropy
balance, it's a source term.

00:43:47.500 --> 00:43:51.090 align:middle line:84%
It cannot be a sink because
it would violate the principle

00:43:51.090 --> 00:43:53.970 align:middle line:90%
of entropy non-decrease.

00:43:53.970 --> 00:44:05.250 align:middle line:84%
But in other models, for
example, often in heat transfer,

00:44:05.250 --> 00:44:09.930 align:middle line:90%
you use terms like--

00:44:09.930 --> 00:44:12.700 align:middle line:84%
you add a term to
the balance equation,

00:44:12.700 --> 00:44:15.000 align:middle line:90%
you call it triple prime q.

00:44:15.000 --> 00:44:18.210 align:middle line:90%
It's the entropy--

00:44:18.210 --> 00:44:21.660 align:middle line:90%
I'm sorry, the energy--

00:44:21.660 --> 00:44:25.780 align:middle line:84%
internal energy deposited
locally, for example,

00:44:25.780 --> 00:44:26.620 align:middle line:90%
by joule effect.

00:44:26.620 --> 00:44:29.520 align:middle line:90%
If you have a conductor--

00:44:29.520 --> 00:44:31.690 align:middle line:84%
electricity conductor,
by joule effect,

00:44:31.690 --> 00:44:36.180 align:middle line:84%
that dissipates
electrical energy

00:44:36.180 --> 00:44:38.800 align:middle line:84%
and transforms it
into internal energy.

00:44:38.800 --> 00:44:42.220 align:middle line:84%
So if you make a balance
of internal energy,

00:44:42.220 --> 00:44:45.780 align:middle line:84%
you will find a source
term, and that source term

00:44:45.780 --> 00:44:52.460 align:middle line:84%
is a source-per-unit volume,
so it's like a sigma of energy.

00:44:52.460 --> 00:44:55.140 align:middle line:90%


00:44:55.140 --> 00:44:57.780 align:middle line:84%
And usually you can
distinguish between those

00:44:57.780 --> 00:45:03.820 align:middle line:84%
that are produced
by local effects--

00:45:03.820 --> 00:45:06.190 align:middle line:84%
like the joule effect
is a local effect.

00:45:06.190 --> 00:45:19.030 align:middle line:84%
Or a collision-produced effects,
including chemical reactions,

00:45:19.030 --> 00:45:23.430 align:middle line:84%
that essentially,
chemical reactions,

00:45:23.430 --> 00:45:28.190 align:middle line:84%
you can consider it as
a source of products

00:45:28.190 --> 00:45:32.330 align:middle line:84%
of the reaction and the
sink for the reactants

00:45:32.330 --> 00:45:40.150 align:middle line:84%
of the reaction, which occurs
locally in your volume.

00:45:40.150 --> 00:45:43.810 align:middle line:84%
And so these-- you would
call it with a superscript i.

00:45:43.810 --> 00:45:47.660 align:middle line:84%
To be distinguished with
the externally generated--

00:45:47.660 --> 00:45:55.210 align:middle line:84%
for example, if this
fluid element lives

00:45:55.210 --> 00:46:03.280 align:middle line:90%
in a gravitational field g.

00:46:03.280 --> 00:46:06.880 align:middle line:90%
And, of course, it has mass.

00:46:06.880 --> 00:46:09.520 align:middle line:84%
So it also has a
potential energy.

00:46:09.520 --> 00:46:17.650 align:middle line:84%
And the fact that it moves makes
that potential energy change.

00:46:17.650 --> 00:46:20.150 align:middle line:84%
And that's not due
to a local effect.

00:46:20.150 --> 00:46:22.820 align:middle line:84%
It's due to an
externally applied field.

00:46:22.820 --> 00:46:25.450 align:middle line:84%
The same, if you
had charges there

00:46:25.450 --> 00:46:30.970 align:middle line:84%
and you had an electric
field, say, an electric field

00:46:30.970 --> 00:46:33.350 align:middle line:90%
like this.

00:46:33.350 --> 00:46:41.040 align:middle line:90%


00:46:41.040 --> 00:46:42.420 align:middle line:90%
And then you move the charges--

00:46:42.420 --> 00:46:45.310 align:middle line:90%


00:46:45.310 --> 00:46:49.260 align:middle line:84%
so the electrical-- the
electrostatic energy

00:46:49.260 --> 00:46:55.920 align:middle line:84%
of your fluid element
changes, and that

00:46:55.920 --> 00:46:59.070 align:middle line:90%
gets into this volume term.

00:46:59.070 --> 00:47:03.245 align:middle line:84%
It could be up or down, so it
could be a sink or a source.

00:47:03.245 --> 00:47:06.070 align:middle line:90%


00:47:06.070 --> 00:47:08.830 align:middle line:84%
So these in principle
for various properties,

00:47:08.830 --> 00:47:12.000 align:middle line:90%
could be positive or negative.

00:47:12.000 --> 00:47:13.920 align:middle line:84%
It's only for the
entropy production

00:47:13.920 --> 00:47:18.590 align:middle line:84%
that you know precisely
which sign it must have.

00:47:18.590 --> 00:47:22.350 align:middle line:90%


00:47:22.350 --> 00:47:27.780 align:middle line:84%
So finally, with all
those ingredients,

00:47:27.780 --> 00:47:29.930 align:middle line:84%
you can write the
balance equations

00:47:29.930 --> 00:47:33.140 align:middle line:84%
for this extensive
property A. And it

00:47:33.140 --> 00:47:40.860 align:middle line:84%
says the rate of change of the
property inside your material

00:47:40.860 --> 00:47:45.490 align:middle line:84%
volume is equal
to the amount of--

00:47:45.490 --> 00:47:53.160 align:middle line:84%
the amount of-- the contribution
of these sink source terms

00:47:53.160 --> 00:47:55.155 align:middle line:84%
integrated, of course,
over the volume.

00:47:55.155 --> 00:48:00.230 align:middle line:90%


00:48:00.230 --> 00:48:03.550 align:middle line:84%
Minus the amount that leaves
the volume through the surface.

00:48:03.550 --> 00:48:07.640 align:middle line:90%


00:48:07.640 --> 00:48:10.340 align:middle line:84%
And so that amount
that leaves is

00:48:10.340 --> 00:48:16.280 align:middle line:84%
equal to the velocity associated
with the flux of that property

00:48:16.280 --> 00:48:29.665 align:middle line:84%
relative to the velocity of the
surface of your material volume.

00:48:29.665 --> 00:48:33.225 align:middle line:90%


00:48:33.225 --> 00:48:33.725 align:middle line:90%
OK.

00:48:33.725 --> 00:48:39.660 align:middle line:90%


00:48:39.660 --> 00:48:44.040 align:middle line:84%
Times the property
per unit volume.

00:48:44.040 --> 00:48:48.300 align:middle line:84%
And also here, you see
something dotted into n

00:48:48.300 --> 00:48:50.310 align:middle line:84%
and integrated
over a surface, you

00:48:50.310 --> 00:48:54.180 align:middle line:84%
can use the divergence
theorem and transform it

00:48:54.180 --> 00:49:02.200 align:middle line:84%
into the divergence
of whatever is

00:49:02.200 --> 00:49:06.830 align:middle line:84%
dotted into the outward
normal to the surface.

00:49:06.830 --> 00:49:14.340 align:middle line:84%
And you may recognize here that
since this velocity is vm--

00:49:14.340 --> 00:49:23.010 align:middle line:84%
vA minus vm dot n times rho a is
the diffusive flux we defined it

00:49:23.010 --> 00:49:24.810 align:middle line:90%
in the previous slide.

00:49:24.810 --> 00:49:26.800 align:middle line:90%
That's why I get that.

00:49:26.800 --> 00:49:32.360 align:middle line:90%


00:49:32.360 --> 00:49:40.880 align:middle line:84%
So this is, the right-hand
side of the balance equation.

00:49:40.880 --> 00:49:46.420 align:middle line:90%


00:49:46.420 --> 00:49:49.240 align:middle line:84%
And the left-hand
side we already wrote

00:49:49.240 --> 00:49:53.090 align:middle line:90%
in a couple of slides ago.

00:49:53.090 --> 00:49:54.445 align:middle line:90%
We wrote it in this form.

00:49:54.445 --> 00:49:57.790 align:middle line:90%


00:49:57.790 --> 00:50:03.620 align:middle line:84%
So this is the general form of
a balance equation for property

00:50:03.620 --> 00:50:07.760 align:middle line:84%
A. For an extensive
property A. And I

00:50:07.760 --> 00:50:11.420 align:middle line:84%
think I'll repeat
it in the next slide

00:50:11.420 --> 00:50:13.195 align:middle line:90%
because we need to-- here it is.

00:50:13.195 --> 00:50:15.810 align:middle line:90%


00:50:15.810 --> 00:50:17.482 align:middle line:90%
OK.

00:50:17.482 --> 00:50:25.300 align:middle line:84%
Now, since that equation--
balance equation

00:50:25.300 --> 00:50:31.930 align:middle line:84%
must hold for whatever
material volume, large, small,

00:50:31.930 --> 00:50:35.680 align:middle line:84%
and so on, arbitrary,
the only way

00:50:35.680 --> 00:50:40.450 align:middle line:84%
that this equation can
hold for arbitrary volumes

00:50:40.450 --> 00:50:44.380 align:middle line:84%
is that the arguments of
the integrals be equal,

00:50:44.380 --> 00:50:50.800 align:middle line:84%
and therefore, you can
cross away the integrals

00:50:50.800 --> 00:50:54.440 align:middle line:84%
and keep the equality
between the integrands,

00:50:54.440 --> 00:51:10.280 align:middle line:84%
and that's your indefinite
balance equation for property A.

00:51:10.280 --> 00:51:16.800 align:middle line:84%
Remember that we said
that the diffusive flux is

00:51:16.800 --> 00:51:20.370 align:middle line:84%
the Lagrangian flux
minus the convective flux

00:51:20.370 --> 00:51:21.930 align:middle line:90%
of that property.

00:51:21.930 --> 00:51:31.100 align:middle line:84%
So we can combine
these two equations,

00:51:31.100 --> 00:51:36.540 align:middle line:84%
and therefore, rewrite it in
either this form or that form.

00:51:36.540 --> 00:51:39.985 align:middle line:84%
These are two equivalent ways
to write the balance equation.

00:51:39.985 --> 00:51:42.670 align:middle line:90%


00:51:42.670 --> 00:51:47.710 align:middle line:84%
But the important thing is
that in this left-hand side,

00:51:47.710 --> 00:51:54.710 align:middle line:84%
you get J 0, whereas
here, you get J.

00:51:54.710 --> 00:51:58.640 align:middle line:84%
And these combination
of partial derivative

00:51:58.640 --> 00:52:02.750 align:middle line:84%
and the barycentric velocity
times the gradient of property

00:52:02.750 --> 00:52:05.240 align:middle line:84%
A, which comes in when
you substitute these

00:52:05.240 --> 00:52:11.740 align:middle line:84%
into there, as you know, it's
called the material derivative.

00:52:11.740 --> 00:52:14.540 align:middle line:90%


00:52:14.540 --> 00:52:20.050 align:middle line:84%
And it represents how things
change as a function of time

00:52:20.050 --> 00:52:26.080 align:middle line:84%
as viewed from the fluid
element by moving together

00:52:26.080 --> 00:52:29.000 align:middle line:84%
with the fluid element at
the barycentric velocity.

00:52:29.000 --> 00:52:31.950 align:middle line:90%


00:52:31.950 --> 00:52:34.110 align:middle line:84%
And following, therefore,
the fluid element.

00:52:34.110 --> 00:52:38.160 align:middle line:84%
That's why it follows
the trajectory that

00:52:38.160 --> 00:52:41.500 align:middle line:84%
is called the path line
in fluid mechanics.

00:52:41.500 --> 00:52:46.600 align:middle line:90%


00:52:46.600 --> 00:52:48.310 align:middle line:90%
OK.

00:52:48.310 --> 00:52:50.230 align:middle line:84%
So these are the
balance equations.

00:52:50.230 --> 00:52:53.170 align:middle line:90%
We are going to--

00:52:53.170 --> 00:52:56.760 align:middle line:90%
I think we are going to use--

00:52:56.760 --> 00:52:58.680 align:middle line:90%
well, either one.

00:52:58.680 --> 00:53:00.200 align:middle line:90%
Probably more this one.

00:53:00.200 --> 00:53:09.610 align:middle line:90%


00:53:09.610 --> 00:53:13.480 align:middle line:84%
So if you do that, what we have
done for the one-dimensional

00:53:13.480 --> 00:53:16.750 align:middle line:84%
problem, if you do it for
the three-dimensional--

00:53:16.750 --> 00:53:24.310 align:middle line:84%
I mean for the
full-dimensional stuff,

00:53:24.310 --> 00:53:28.275 align:middle line:84%
you can write the mass
balance equation in this way.

00:53:28.275 --> 00:53:31.490 align:middle line:90%


00:53:31.490 --> 00:53:37.370 align:middle line:84%
You can write the energy
balance in this way in terms

00:53:37.370 --> 00:53:40.760 align:middle line:90%
of the diffusive fluxes.

00:53:40.760 --> 00:53:41.920 align:middle line:90%
The entropy balance.

00:53:41.920 --> 00:53:45.750 align:middle line:90%


00:53:45.750 --> 00:53:50.250 align:middle line:84%
But also, you can write
the momentum balance.

00:53:50.250 --> 00:53:52.396 align:middle line:90%
And, of course, the material--

00:53:52.396 --> 00:53:55.610 align:middle line:90%


00:53:55.610 --> 00:54:03.115 align:middle line:84%
actually, these two are
related to one another.

00:54:03.115 --> 00:54:06.310 align:middle line:90%


00:54:06.310 --> 00:54:08.680 align:middle line:84%
Because what you
would need to do

00:54:08.680 --> 00:54:11.900 align:middle line:84%
is to write a balance equation
for each kind of particle,

00:54:11.900 --> 00:54:12.730 align:middle line:90%
each type--

00:54:12.730 --> 00:54:14.980 align:middle line:90%
like each i.

00:54:14.980 --> 00:54:17.800 align:middle line:84%
And then once you have
it, you can express it

00:54:17.800 --> 00:54:22.490 align:middle line:84%
in terms of mole-specific
or mass-specific and so on.

00:54:22.490 --> 00:54:24.020 align:middle line:90%
And you can write it--

00:54:24.020 --> 00:54:33.310 align:middle line:84%
for example, here, this symbol
xi is the mass fraction.

00:54:33.310 --> 00:54:36.730 align:middle line:84%
In other places-- actually,
probably in the next slide,

00:54:36.730 --> 00:54:40.365 align:middle line:84%
I call that same mass
fraction with the symbol x.

00:54:40.365 --> 00:54:44.900 align:middle line:90%


00:54:44.900 --> 00:54:47.330 align:middle line:84%
So here is the definition
of the barycentric velocity

00:54:47.330 --> 00:54:53.150 align:middle line:84%
that I mentioned, and here is
the expression for the flux of--

00:54:53.150 --> 00:55:01.990 align:middle line:84%
the mass flux in
laboratory frame.

00:55:01.990 --> 00:55:08.170 align:middle line:84%
It's rho times v. And it
is related to the mass

00:55:08.170 --> 00:55:10.440 align:middle line:84%
and to the velocities of
the various (constituents)

00:55:10.440 --> 00:55:14.560 align:middle line:84%
and this table, I'm
not describing it,

00:55:14.560 --> 00:55:16.210 align:middle line:90%
but simply is there.

00:55:16.210 --> 00:55:19.770 align:middle line:84%
It's useful just to mention how
many different ways you have

00:55:19.770 --> 00:55:22.800 align:middle line:84%
to do the accounting,
and depending

00:55:22.800 --> 00:55:26.790 align:middle line:84%
on what your application or
depending on your community,

00:55:26.790 --> 00:55:36.480 align:middle line:84%
people use mole fractions,
mass fractions, concentrations,

00:55:36.480 --> 00:55:37.480 align:middle line:90%
and so on.

00:55:37.480 --> 00:55:39.990 align:middle line:84%
And so these are
the interrelations

00:55:39.990 --> 00:55:47.990 align:middle line:84%
that intercur between
these various properties.

00:55:47.990 --> 00:55:50.600 align:middle line:84%
So I'll leave it there
just for reference.

00:55:50.600 --> 00:55:57.830 align:middle line:84%
And also, this slide
provides a list of examples--

00:55:57.830 --> 00:56:02.620 align:middle line:84%
the main examples for
those extensive properties

00:56:02.620 --> 00:56:07.140 align:middle line:84%
that we have written the
balance equations for.

00:56:07.140 --> 00:56:11.450 align:middle line:84%
And for which we can define
convective fluxes and diffusive

00:56:11.450 --> 00:56:13.610 align:middle line:90%
fluxes.

00:56:13.610 --> 00:56:17.540 align:middle line:84%
And so the number of
moles, the total mole,

00:56:17.540 --> 00:56:26.150 align:middle line:84%
the mass of particles of a
certain type, the total mass,

00:56:26.150 --> 00:56:31.200 align:middle line:84%
the charge of particles of a
certain type, the total charge,

00:56:31.200 --> 00:56:35.340 align:middle line:84%
the energy, the entropy,
the kinetic energy,

00:56:35.340 --> 00:56:37.200 align:middle line:84%
the potential
gravitational energy,

00:56:37.200 --> 00:56:42.040 align:middle line:84%
the potential electrical
energy, and momentum.

00:56:42.040 --> 00:56:45.550 align:middle line:84%
For each one of
these, you can write

00:56:45.550 --> 00:56:48.430 align:middle line:90%
balance equations of the form--

00:56:48.430 --> 00:56:52.590 align:middle line:84%
of the generic form
that we have discussed.

00:56:52.590 --> 00:56:56.670 align:middle line:90%


00:56:56.670 --> 00:56:58.020 align:middle line:90%
OK.

00:56:58.020 --> 00:57:02.860 align:middle line:90%
So that is the balance equation.

00:57:02.860 --> 00:57:08.830 align:middle line:84%
Now, just a small
digression about the fact

00:57:08.830 --> 00:57:11.810 align:middle line:84%
that we are dealing,
in this model

00:57:11.810 --> 00:57:15.490 align:middle line:84%
so far, and all
that we have done,

00:57:15.490 --> 00:57:18.280 align:middle line:84%
we are dealing with the
idea of a continuum.

00:57:18.280 --> 00:57:25.990 align:middle line:84%
The fact that you can assign to
a position in space and time a--

00:57:25.990 --> 00:57:32.080 align:middle line:84%
for example, a density,
it means that you

00:57:32.080 --> 00:57:42.890 align:middle line:84%
have enough particles in
your volume so that you can--

00:57:42.890 --> 00:57:46.320 align:middle line:90%


00:57:46.320 --> 00:57:50.590 align:middle line:84%
so that you can assume that
all the particles are--

00:57:50.590 --> 00:57:53.650 align:middle line:90%


00:57:53.650 --> 00:57:57.220 align:middle line:84%
so that you can take the mass
of the particles and consider

00:57:57.220 --> 00:58:02.740 align:middle line:84%
it as uniformly
spread in that volume.

00:58:02.740 --> 00:58:04.603 align:middle line:90%
And that you can do only--

00:58:04.603 --> 00:58:08.330 align:middle line:90%


00:58:08.330 --> 00:58:13.530 align:middle line:84%
of course, that is a limit of
the traditional fluid mechanics.

00:58:13.530 --> 00:58:16.150 align:middle line:90%


00:58:16.150 --> 00:58:22.200 align:middle line:84%
And you can do it only
if the Knudsen number--

00:58:22.200 --> 00:58:29.540 align:middle line:84%
the Knudsen number is the ratio
between the mean-free path--

00:58:29.540 --> 00:58:36.190 align:middle line:84%
mean-free path is
the travel distance

00:58:36.190 --> 00:58:44.520 align:middle line:84%
that, on average, particles
travel between one

00:58:44.520 --> 00:58:45.515 align:middle line:90%
collision and the next.

00:58:45.515 --> 00:58:48.830 align:middle line:90%


00:58:48.830 --> 00:58:50.690 align:middle line:90%
So that is lambda.

00:58:50.690 --> 00:58:56.030 align:middle line:84%
And in the denominator is
L. L is the typical size

00:58:56.030 --> 00:58:58.610 align:middle line:90%
of your fluid mechanics--

00:58:58.610 --> 00:59:04.280 align:middle line:84%
it's the length scale of
your fluid mechanics problem.

00:59:04.280 --> 00:59:07.970 align:middle line:84%
Could be the boundary
layer thickness

00:59:07.970 --> 00:59:13.230 align:middle line:84%
or could be the diameter of your
pipe if you are in a pipe flow.

00:59:13.230 --> 00:59:15.830 align:middle line:90%


00:59:15.830 --> 00:59:28.760 align:middle line:84%
So not always the Knudsen
number is smaller than 1.

00:59:28.760 --> 00:59:32.390 align:middle line:84%
Smaller than-- much
smaller than 1.

00:59:32.390 --> 00:59:39.860 align:middle line:84%
So typically, one would say,
if it is less than 1%, then

00:59:39.860 --> 00:59:43.950 align:middle line:84%
you can apply the
continuum hypothesis.

00:59:43.950 --> 00:59:47.750 align:middle line:84%
If it is not, then
you have to be careful

00:59:47.750 --> 00:59:50.000 align:middle line:84%
because the results
that you are obtaining

00:59:50.000 --> 00:59:53.730 align:middle line:84%
may not correspond to
the physical reality.

00:59:53.730 --> 00:59:56.270 align:middle line:84%
So you can always do
that in the model,

00:59:56.270 --> 00:59:59.870 align:middle line:84%
but the results
are not providing

00:59:59.870 --> 01:00:05.720 align:middle line:90%
valid descriptions of reality.

01:00:05.720 --> 01:00:09.340 align:middle line:84%
For example, this
table gives for air.

01:00:09.340 --> 01:00:14.600 align:middle line:84%
At sea level for dry air
at 25 C, 1 atmosphere.

01:00:14.600 --> 01:00:24.606 align:middle line:84%
The mean-free path, it's
about 67 nanometers.

01:00:24.606 --> 01:00:31.890 align:middle line:90%


01:00:31.890 --> 01:00:36.580 align:middle line:84%
So this condition is guaranteed
when you see the green.

01:00:36.580 --> 01:00:43.110 align:middle line:84%
So if I have a device
that is a large, small--

01:00:43.110 --> 01:00:51.370 align:middle line:84%
even pretty small, like 70
microns, it's pretty small,

01:00:51.370 --> 01:00:55.090 align:middle line:84%
you still can apply
fluid mechanics.

01:00:55.090 --> 01:00:59.530 align:middle line:90%
When your device gets smaller--

01:00:59.530 --> 01:01:03.710 align:middle line:84%
see, the denominator
of the Knudsen number

01:01:03.710 --> 01:01:07.400 align:middle line:84%
gets smaller, so the Knudsen
number becomes larger.

01:01:07.400 --> 01:01:14.120 align:middle line:84%
And so for small
devices, you cannot--

01:01:14.120 --> 01:01:22.030 align:middle line:84%
we cannot use fluid mechanics
or the continuum assumption.

01:01:22.030 --> 01:01:27.480 align:middle line:84%
But even for air, if
you go at this position,

01:01:27.480 --> 01:01:31.460 align:middle line:84%
100 kilometers altitude--
it's called the Karman line,

01:01:31.460 --> 01:01:36.500 align:middle line:84%
there, the temperature
is minus 80 degrees C

01:01:36.500 --> 01:01:41.480 align:middle line:84%
and the pressure is
hundreds of atmosphere.

01:01:41.480 --> 01:01:46.173 align:middle line:90%
The mean-free path is about--

01:01:46.173 --> 01:01:49.640 align:middle line:90%


01:01:49.640 --> 01:01:50.870 align:middle line:90%
what is it?

01:01:50.870 --> 01:01:57.945 align:middle line:84%
100 times-- 50 times
larger than at sea level.

01:01:57.945 --> 01:02:01.840 align:middle line:90%


01:02:01.840 --> 01:02:08.150 align:middle line:84%
So there, it's the
lambda that is high.

01:02:08.150 --> 01:02:10.990 align:middle line:90%
So even for standard devices--

01:02:10.990 --> 01:02:18.940 align:middle line:84%
for example, a typical problem
where the Knudsen number fails

01:02:18.940 --> 01:02:20.740 align:middle line:84%
and you cannot apply
fluid mechanics,

01:02:20.740 --> 01:02:28.420 align:middle line:84%
it's in the boundary layer of
the space vehicles that have

01:02:28.420 --> 01:02:32.590 align:middle line:84%
to come back to the
atmosphere, in the upper layers

01:02:32.590 --> 01:02:38.380 align:middle line:84%
of the atmosphere, the
lambda is so small (I meant,

01:02:38.380 --> 01:02:46.720 align:middle line:84%
large) that the Knudsen
number is of the order, say,

01:02:46.720 --> 01:02:58.080 align:middle line:84%
1 even for relatively
large thicknesses.

01:02:58.080 --> 01:03:03.450 align:middle line:84%
And therefore, that was, in
fact, one of the problems

01:03:03.450 --> 01:03:08.220 align:middle line:84%
when they were studying the
reentry problem of the Space

01:03:08.220 --> 01:03:10.290 align:middle line:90%
Shuttle.

01:03:10.290 --> 01:03:12.395 align:middle line:90%
And not only-- also the--

01:03:12.395 --> 01:03:17.070 align:middle line:90%


01:03:17.070 --> 01:03:22.130 align:middle line:84%
the other vehicles that have
re-enter through the atmosphere.

01:03:22.130 --> 01:03:23.994 align:middle line:90%
OK.

01:03:23.994 --> 01:03:30.140 align:middle line:84%
So remember that what we are
doing refers to a continuum,

01:03:30.140 --> 01:03:32.340 align:middle line:84%
so there are
limitations to this.

01:03:32.340 --> 01:03:37.980 align:middle line:90%


01:03:37.980 --> 01:03:40.410 align:middle line:84%
At the end, one of
the final lectures

01:03:40.410 --> 01:03:45.005 align:middle line:84%
we'll mention what we need
to do when this fails.

01:03:45.005 --> 01:03:51.300 align:middle line:90%


01:03:51.300 --> 01:03:52.512 align:middle line:90%
OK.

01:03:52.512 --> 01:03:57.020 align:middle line:84%
Now we are in the
part that we have

01:03:57.020 --> 01:04:00.090 align:middle line:84%
to-- in order to assemble
the energy balance,

01:04:00.090 --> 01:04:02.340 align:middle line:84%
entropy balance,
constituents' balance,

01:04:02.340 --> 01:04:09.430 align:middle line:84%
we need to use a Gibbs
relation to combine them, which

01:04:09.430 --> 01:04:14.770 align:middle line:84%
is an assumption of local
equilibrium, which goes together

01:04:14.770 --> 01:04:17.090 align:middle line:90%
with the continuum assumption.

01:04:17.090 --> 01:04:20.370 align:middle line:90%


01:04:20.370 --> 01:04:25.510 align:middle line:84%
So remember, you have
the Gibbs relation.

01:04:25.510 --> 01:04:29.720 align:middle line:84%
We are talking about
large number of particles,

01:04:29.720 --> 01:04:35.260 align:middle line:84%
so we assume the Euler
relation, and also from the two,

01:04:35.260 --> 01:04:36.780 align:middle line:90%
we get the Gibbs-Duhem relation.

01:04:36.780 --> 01:04:41.330 align:middle line:90%


01:04:41.330 --> 01:04:43.550 align:middle line:84%
Now here, there
are a couple of--

01:04:43.550 --> 01:04:47.680 align:middle line:90%
OK, so that is the basics.

01:04:47.680 --> 01:04:51.700 align:middle line:84%
Then, of course,
we need to remember

01:04:51.700 --> 01:04:54.796 align:middle line:84%
what the definitions
are, chemical potentials.

01:04:54.796 --> 01:04:58.000 align:middle line:90%


01:04:58.000 --> 01:04:59.660 align:middle line:90%
We've seen it so many times.

01:04:59.660 --> 01:05:03.500 align:middle line:84%
The differential of
the chemical potential,

01:05:03.500 --> 01:05:06.810 align:middle line:84%
if you remember when we
started doing mixtures,

01:05:06.810 --> 01:05:08.335 align:middle line:90%
we wrote this expression here.

01:05:08.335 --> 01:05:11.010 align:middle line:90%


01:05:11.010 --> 01:05:17.330 align:middle line:84%
A new way that is used
often is this one.

01:05:17.330 --> 01:05:20.220 align:middle line:90%


01:05:20.220 --> 01:05:24.990 align:middle line:84%
You collect the part of the
differential that is not related

01:05:24.990 --> 01:05:27.780 align:middle line:90%
to changes in temperature.

01:05:27.780 --> 01:05:33.400 align:middle line:84%
And instead of writing it
all the times explicitly,

01:05:33.400 --> 01:05:37.800 align:middle line:84%
you write it as
the differential--

01:05:37.800 --> 01:05:39.960 align:middle line:84%
the part of the
differential of mu

01:05:39.960 --> 01:05:43.320 align:middle line:84%
that would survive if
you keep the temperature

01:05:43.320 --> 01:05:45.990 align:middle line:90%
constant with this symbol here.

01:05:45.990 --> 01:05:50.160 align:middle line:84%
So you change the
chemical potential

01:05:50.160 --> 01:05:53.690 align:middle line:90%
by changing the temperature.

01:05:53.690 --> 01:05:55.430 align:middle line:90%
And so the specific--

01:05:55.430 --> 01:06:01.980 align:middle line:84%
I'm sorry, the partial
entropy appears here.

01:06:01.980 --> 01:06:08.180 align:middle line:84%
And you call the
rest, which relates

01:06:08.180 --> 01:06:12.460 align:middle line:84%
to changing pressure
and composition,

01:06:12.460 --> 01:06:13.980 align:middle line:90%
you put it together in here.

01:06:13.980 --> 01:06:18.400 align:middle line:90%


01:06:18.400 --> 01:06:24.300 align:middle line:84%
Then, another item that we
do because we are making

01:06:24.300 --> 01:06:27.270 align:middle line:84%
balances, for
example, of energy--

01:06:27.270 --> 01:06:29.440 align:middle line:90%
not of internal energy.

01:06:29.440 --> 01:06:31.900 align:middle line:84%
Yes, we could also make a
balance of internal energy,

01:06:31.900 --> 01:06:37.060 align:middle line:84%
but usually, the meaningful
one is the energy balance.

01:06:37.060 --> 01:06:40.710 align:middle line:84%
And so in the energy
balance, we typically

01:06:40.710 --> 01:06:47.040 align:middle line:84%
use this bulk
flow-like expression

01:06:47.040 --> 01:06:50.850 align:middle line:84%
of the energy in which we
recognize an internal energy,

01:06:50.850 --> 01:06:56.200 align:middle line:84%
and then some
mechanical addenda that

01:06:56.200 --> 01:07:02.020 align:middle line:84%
bring in the kinetic energy, the
gravitational potential energy,

01:07:02.020 --> 01:07:09.490 align:middle line:84%
the electrostatic
potential energy, and even

01:07:09.490 --> 01:07:12.550 align:middle line:84%
the centrifugal potential
energy with the negative sign

01:07:12.550 --> 01:07:18.010 align:middle line:84%
that we have seen when we
did the stratification.

01:07:18.010 --> 01:07:22.000 align:middle line:84%
And you remember that,
therefore, the chemical

01:07:22.000 --> 01:07:27.550 align:middle line:90%
potential gets in--

01:07:27.550 --> 01:07:29.512 align:middle line:84%
it's only a part
of the expression

01:07:29.512 --> 01:07:31.220 align:middle line:84%
of the partial of the
energy with respect

01:07:31.220 --> 01:07:34.200 align:middle line:84%
to the amounts, which we have
called the total potential.

01:07:34.200 --> 01:07:36.200 align:middle line:84%
And there are these
other contributions

01:07:36.200 --> 01:07:39.175 align:middle line:90%
that need to be taken care of.

01:07:39.175 --> 01:07:42.310 align:middle line:90%


01:07:42.310 --> 01:07:46.110 align:middle line:84%
There is some--
there is some fishy--

01:07:46.110 --> 01:07:54.285 align:middle line:84%
this dq-- this dq
shouldn't be here.

01:07:54.285 --> 01:07:56.830 align:middle line:90%


01:07:56.830 --> 01:08:01.240 align:middle line:84%
Yeah, it's from cut and
paste from this expression

01:08:01.240 --> 01:08:08.240 align:middle line:84%
where I take this one, I
take the differential here,

01:08:08.240 --> 01:08:14.620 align:middle line:84%
and then you take the
total potential is

01:08:14.620 --> 01:08:15.970 align:middle line:90%
the partial of the energy.

01:08:15.970 --> 01:08:19.270 align:middle line:84%
While you keep fixed
the entropy, the volume,

01:08:19.270 --> 01:08:22.240 align:middle line:84%
the other amounts,
and then you have

01:08:22.240 --> 01:08:27.109 align:middle line:84%
to keep fixed, for example,
the barycentric velocity,

01:08:27.109 --> 01:08:32.620 align:middle line:84%
the height in the potential,
the value of the gravitational--

01:08:32.620 --> 01:08:40.060 align:middle line:84%
I'm sorry, of the electrostatic
field, the angular speed,

01:08:40.060 --> 01:08:43.750 align:middle line:90%
and the location.

01:08:43.750 --> 01:08:50.170 align:middle line:84%
So you keep all these fixed
and change only the amount

01:08:50.170 --> 01:08:51.819 align:middle line:84%
of that particular
constituent in order

01:08:51.819 --> 01:08:53.960 align:middle line:90%
to get the total potential.

01:08:53.960 --> 01:08:57.399 align:middle line:90%


01:08:57.399 --> 01:09:00.640 align:middle line:84%
And these last lines are
just a summary of the fact

01:09:00.640 --> 01:09:04.420 align:middle line:90%
that you can write properties--

01:09:04.420 --> 01:09:10.540 align:middle line:84%
specific properties per mole,
per unit mass with the star,

01:09:10.540 --> 01:09:14.140 align:middle line:90%
or per unit volume.

01:09:14.140 --> 01:09:16.779 align:middle line:84%
Per unit volume, you could
write it as rho u star,

01:09:16.779 --> 01:09:19.380 align:middle line:90%
or also c times u.

01:09:19.380 --> 01:09:23.350 align:middle line:90%


01:09:23.350 --> 01:09:30.200 align:middle line:84%
So this is a summary
of what's needed.

01:09:30.200 --> 01:09:37.926 align:middle line:84%
So we have worked so far using
molar specific properties.

01:09:37.926 --> 01:09:41.779 align:middle line:90%


01:09:41.779 --> 01:09:48.229 align:middle line:84%
And the Gibbs-Duhem relation has
been always written this way.

01:09:48.229 --> 01:09:52.760 align:middle line:84%
And with this new notation
of the differential

01:09:52.760 --> 01:09:56.870 align:middle line:84%
of the chemical potential
at fixed temperature,

01:09:56.870 --> 01:09:58.465 align:middle line:90%
it takes this form.

01:09:58.465 --> 01:10:01.400 align:middle line:90%


01:10:01.400 --> 01:10:06.500 align:middle line:84%
And since that differential
means any changes

01:10:06.500 --> 01:10:11.720 align:middle line:84%
of the property-- if you change
only the property by moving

01:10:11.720 --> 01:10:17.950 align:middle line:84%
in space at a given instant
of time, that becomes--

01:10:17.950 --> 01:10:21.715 align:middle line:84%
you can substitute, essentially,
the d with the nabla,

01:10:21.715 --> 01:10:22.465 align:middle line:90%
with the gradient.

01:10:22.465 --> 01:10:25.120 align:middle line:90%


01:10:25.120 --> 01:10:26.950 align:middle line:84%
And so you have
an expression here

01:10:26.950 --> 01:10:31.570 align:middle line:84%
that comes from the
Gibbs-Duhem and gives you

01:10:31.570 --> 01:10:33.580 align:middle line:84%
the gradient in
pressure and how it

01:10:33.580 --> 01:10:38.256 align:middle line:84%
is related to the gradients
in the chemical potentials.

01:10:38.256 --> 01:10:42.280 align:middle line:90%


01:10:42.280 --> 01:10:45.680 align:middle line:90%
So they are not independent.

01:10:45.680 --> 01:10:51.900 align:middle line:84%
It's just another face
of the Gibbs phase rule.

01:10:51.900 --> 01:10:56.920 align:middle line:84%
You may also write it in terms
of mass-specific properties.

01:10:56.920 --> 01:10:59.320 align:middle line:84%
I'm not staying
too much on this.

01:10:59.320 --> 01:11:01.680 align:middle line:84%
You can just-- but
I'm staying more

01:11:01.680 --> 01:11:07.640 align:middle line:84%
on this other one,
volume-specific properties.

01:11:07.640 --> 01:11:12.620 align:middle line:84%
Because if I write the Gibbs
relation, the Euler relation,

01:11:12.620 --> 01:11:14.420 align:middle line:84%
and the Gibbs-Duhem
relation in terms

01:11:14.420 --> 01:11:25.200 align:middle line:84%
of these volume-specific
properties, what I already said

01:11:25.200 --> 01:11:32.670 align:middle line:84%
is that you can show that
the pressure disappears

01:11:32.670 --> 01:11:36.390 align:middle line:90%
from the Gibbs relation.

01:11:36.390 --> 01:11:41.340 align:middle line:84%
Not that you get rid
of it, but in terms

01:11:41.340 --> 01:11:43.180 align:middle line:84%
of these volume-specific
properties,

01:11:43.180 --> 01:11:49.240 align:middle line:84%
you decouple the Gibbs relation
from the Gibbs-Duhem relation.

01:11:49.240 --> 01:11:52.360 align:middle line:84%
And you can so forget
about pressure,

01:11:52.360 --> 01:11:55.320 align:middle line:84%
and then when you need it, you
can use the Gibbs-Duhem relation

01:11:55.320 --> 01:12:02.700 align:middle line:84%
as an additional
independent equation that

01:12:02.700 --> 01:12:07.050 align:middle line:90%
gives you the pressure.

01:12:07.050 --> 01:12:11.460 align:middle line:84%
So the gradient in pressure
is the weighted sum

01:12:11.460 --> 01:12:13.990 align:middle line:84%
of the gradients in the
chemical potentials,

01:12:13.990 --> 01:12:20.250 align:middle line:84%
the constant temperature part,
weighted on the concentrations

01:12:20.250 --> 01:12:21.230 align:middle line:90%
of the various things.

01:12:21.230 --> 01:12:27.690 align:middle line:90%


01:12:27.690 --> 01:12:36.070 align:middle line:84%
So this Gibbs relation,
you can write it--

01:12:36.070 --> 01:12:39.700 align:middle line:84%
this time, we are interested
in the change with respect

01:12:39.700 --> 01:12:48.460 align:middle line:84%
to the time variable while
keeping the position variables

01:12:48.460 --> 01:12:50.450 align:middle line:90%
of these fields constant.

01:12:50.450 --> 01:12:54.440 align:middle line:84%
So you may substitute the d with
the partial with respect to t.

01:12:54.440 --> 01:12:57.130 align:middle line:90%


01:12:57.130 --> 01:13:02.770 align:middle line:84%
So that Gibbs relation
becomes this one.

01:13:02.770 --> 01:13:05.560 align:middle line:84%
Or gives this relation
between the partial properties

01:13:05.560 --> 01:13:07.130 align:middle line:90%
(I meant, partial derivatives).

01:13:07.130 --> 01:13:11.680 align:middle line:84%
And as you notice, these
are the left-hand sides

01:13:11.680 --> 01:13:13.990 align:middle line:90%
of the balance equations.

01:13:13.990 --> 01:13:16.410 align:middle line:84%
This is the left-hand side
of the energy balance,

01:13:16.410 --> 01:13:18.430 align:middle line:84%
left-hand side of
the entropy balance,

01:13:18.430 --> 01:13:21.935 align:middle line:84%
left-hand side of the
constituent's balance.

01:13:21.935 --> 01:13:32.590 align:middle line:90%


01:13:32.590 --> 01:13:45.540 align:middle line:84%
Now we need to generalize
the idea of heat interaction.

01:13:45.540 --> 01:13:55.540 align:middle line:90%


01:13:55.540 --> 01:14:00.580 align:middle line:84%
And we do it in a way
similar to the way we

01:14:00.580 --> 01:14:04.030 align:middle line:90%
have done the heat interaction.

01:14:04.030 --> 01:14:11.020 align:middle line:84%
So simply here, it's
drawn in a different way.

01:14:11.020 --> 01:14:14.340 align:middle line:84%
Remember, we took
two systems that

01:14:14.340 --> 01:14:17.520 align:middle line:84%
are at different
temperature, and we

01:14:17.520 --> 01:14:20.200 align:middle line:84%
allow them to exchange
energy and entropy,

01:14:20.200 --> 01:14:24.210 align:middle line:90%
and then we run a test.

01:14:24.210 --> 01:14:30.330 align:middle line:84%
Can we identify part of that
energy that is transferred

01:14:30.330 --> 01:14:34.420 align:middle line:90%
between the two as work?

01:14:34.420 --> 01:14:37.240 align:middle line:90%
If yes, we don't call it heat.

01:14:37.240 --> 01:14:43.510 align:middle line:84%
If no, yes, that's the condition
for a heat interaction.

01:14:43.510 --> 01:14:46.340 align:middle line:84%
So in order to
analyze this problem,

01:14:46.340 --> 01:14:49.360 align:middle line:84%
you run an energy balance
and entropy balance

01:14:49.360 --> 01:14:56.990 align:middle line:84%
for system A. Same for system
B. Same for the machinery here.

01:14:56.990 --> 01:14:59.770 align:middle line:90%


01:14:59.770 --> 01:15:03.550 align:middle line:84%
We use the Gibbs
relation for system A.

01:15:03.550 --> 01:15:11.830 align:middle line:84%
We use the Gibbs
relation for system B.

01:15:11.830 --> 01:15:14.320 align:middle line:90%
And outcomes that the work--

01:15:14.320 --> 01:15:18.460 align:middle line:84%
the maximum work-- so we set
the entropy generation equal

01:15:18.460 --> 01:15:20.260 align:middle line:84%
to 0-- the maximum
work you can get

01:15:20.260 --> 01:15:26.080 align:middle line:84%
is given by the Caront
coefficient multiplied

01:15:26.080 --> 01:15:30.290 align:middle line:84%
by the energy that
is being transferred.

01:15:30.290 --> 01:15:36.230 align:middle line:84%
And so that says that, yes, a
good fraction of that energy

01:15:36.230 --> 01:15:41.000 align:middle line:84%
can be recognized as work
unless the Carnot coefficient is

01:15:41.000 --> 01:15:42.150 align:middle line:90%
equal to 0.

01:15:42.150 --> 01:15:45.140 align:middle line:84%
And that is why we
define heat only

01:15:45.140 --> 01:15:49.220 align:middle line:84%
when the two temperatures,
TA and TB, are--

01:15:49.220 --> 01:15:53.230 align:middle line:84%
their difference vanishes, so
they are approaching each other.

01:15:53.230 --> 01:15:55.860 align:middle line:90%


01:15:55.860 --> 01:16:00.250 align:middle line:84%
And also, in addition
to this result,

01:16:00.250 --> 01:16:05.380 align:middle line:84%
you remember that we get
a set of inequalities that

01:16:05.380 --> 01:16:10.210 align:middle line:84%
says that the entropy
exchanged is bound,

01:16:10.210 --> 01:16:12.940 align:middle line:84%
has an upper bound
and a lower bound

01:16:12.940 --> 01:16:16.040 align:middle line:84%
related to the initial
temperatures of the two objects,

01:16:16.040 --> 01:16:20.380 align:middle line:84%
and only in the limit in
which the two temperatures are

01:16:20.380 --> 01:16:26.620 align:middle line:84%
equal to one another, that
range of values results

01:16:26.620 --> 01:16:34.240 align:middle line:84%
in a single definite relation
between the entropy transfer

01:16:34.240 --> 01:16:35.460 align:middle line:90%
and the energy transfer.

01:16:35.460 --> 01:16:39.670 align:middle line:90%


01:16:39.670 --> 01:16:43.020 align:middle line:90%
Which is this relation--

01:16:43.020 --> 01:16:50.530 align:middle line:84%
q, or delta q, because
then we call that heat,

01:16:50.530 --> 01:16:55.240 align:middle line:84%
is equal to T times
the entropy exchanged.

01:16:55.240 --> 01:17:07.290 align:middle line:84%
Now if we divide by the area
of contact between the two

01:17:07.290 --> 01:17:09.190 align:middle line:90%
objects--

01:17:09.190 --> 01:17:12.850 align:middle line:84%
so A here represents the
area, not the system A,

01:17:12.850 --> 01:17:20.620 align:middle line:84%
and dt is the amount of time
that the interaction occurred,

01:17:20.620 --> 01:17:23.680 align:middle line:90%
you obtain the flux.

01:17:23.680 --> 01:17:26.230 align:middle line:84%
So you may rewrite
this expression

01:17:26.230 --> 01:17:29.140 align:middle line:84%
as saying that for
a heat interaction,

01:17:29.140 --> 01:17:32.140 align:middle line:84%
the energy flux and
the entropy flux

01:17:32.140 --> 01:17:38.020 align:middle line:84%
are related by the temperature,
which is this, this expression

01:17:38.020 --> 01:17:40.310 align:middle line:90%
here.

01:17:40.310 --> 01:17:42.960 align:middle line:84%
And actually, for
this particular one,

01:17:42.960 --> 01:17:46.530 align:middle line:84%
we could even write
q double prime,

01:17:46.530 --> 01:17:49.720 align:middle line:84%
the symbol q double
prime for heat.

01:17:49.720 --> 01:17:50.540 align:middle line:90%
OK.

01:17:50.540 --> 01:18:02.290 align:middle line:84%
Now I do the same, but with a
new fact that the two systems,

01:18:02.290 --> 01:18:06.430 align:middle line:84%
the two-- think of them as
the adjacent fluid elements

01:18:06.430 --> 01:18:09.560 align:middle line:84%
that for which we
are making a balance.

01:18:09.560 --> 01:18:12.850 align:middle line:84%
But in general,
these two systems

01:18:12.850 --> 01:18:18.490 align:middle line:84%
exchange not only energy and
entropy, but also a given amount

01:18:18.490 --> 01:18:21.230 align:middle line:90%
of each of the constituents.

01:18:21.230 --> 01:18:24.674 align:middle line:90%


01:18:24.674 --> 01:18:27.162 align:middle line:90%
The procedure is the same.

01:18:27.162 --> 01:18:31.180 align:middle line:84%
You have to write energy and
entropy balances for system A,

01:18:31.180 --> 01:18:35.540 align:middle line:84%
for system B, and for
the machinery here.

01:18:35.540 --> 01:18:38.330 align:middle line:84%
And you need to use the
Gibbs relation for system A

01:18:38.330 --> 01:18:40.310 align:middle line:84%
and the Gibbs
relation for system

01:18:40.310 --> 01:19:01.310 align:middle line:84%
B. It's a bit improper
how I'm doing it here

01:19:01.310 --> 01:19:04.985 align:middle line:90%
because the pressure--

01:19:04.985 --> 01:19:13.430 align:middle line:84%
there should be a pressure
term there if we are not using

01:19:13.430 --> 01:19:15.170 align:middle line:90%
properties per unit volume.

01:19:15.170 --> 01:19:22.620 align:middle line:84%
But anyway, the
idea is still OK.

01:19:22.620 --> 01:19:25.860 align:middle line:84%
And then as a result of
these balance equations,

01:19:25.860 --> 01:19:30.890 align:middle line:90%
you get this expression.

01:19:30.890 --> 01:19:33.620 align:middle line:84%
So the question is
always the same.

01:19:33.620 --> 01:19:38.270 align:middle line:84%
Can we recognize as part of the
energy that is being exchanged

01:19:38.270 --> 01:19:40.830 align:middle line:90%
here, part is work?

01:19:40.830 --> 01:19:44.530 align:middle line:84%
Well now, we have two
ways in which we could.

01:19:44.530 --> 01:19:47.080 align:middle line:90%


01:19:47.080 --> 01:19:49.870 align:middle line:84%
If the Carnot coefficient
is different than 0,

01:19:49.870 --> 01:19:53.560 align:middle line:84%
then a good fraction,
yes, could be work.

01:19:53.560 --> 01:20:01.620 align:middle line:84%
But also, if these
other coefficients--

01:20:01.620 --> 01:20:07.240 align:middle line:84%
I don't know what the name is,
but if it is different than 0,

01:20:07.240 --> 01:20:12.430 align:middle line:84%
then even if the
temperatures are equal,

01:20:12.430 --> 01:20:15.180 align:middle line:90%
you could have some work.

01:20:15.180 --> 01:20:18.980 align:middle line:90%
So in order to have--

01:20:18.980 --> 01:20:21.270 align:middle line:84%
to extend the idea
of heat interaction--

01:20:21.270 --> 01:20:23.780 align:middle line:84%
and we are going to call
this new interaction heat

01:20:23.780 --> 01:20:31.070 align:middle line:84%
and diffusion interaction with
the ampersand that joins them--

01:20:31.070 --> 01:20:37.010 align:middle line:84%
for lack of better names, we
call it heat and diffusion,

01:20:37.010 --> 01:20:42.540 align:middle line:84%
you need the limit that
the temperatures be equal,

01:20:42.540 --> 01:20:44.240 align:middle line:84%
but also the chemical
potentials of each

01:20:44.240 --> 01:20:48.085 align:middle line:84%
of the constituents of the two
interacting systems be equal.

01:20:48.085 --> 01:20:52.640 align:middle line:90%


01:20:52.640 --> 01:20:58.530 align:middle line:84%
And of course, by the same way
that we prove that inequality,

01:20:58.530 --> 01:21:00.350 align:middle line:84%
you could prove this
inequality here,

01:21:00.350 --> 01:21:06.260 align:middle line:84%
that the entropy exchanged
is, again, limited by two--

01:21:06.260 --> 01:21:17.070 align:middle line:84%
an upper bound and a lower
bound, which, in that limit,

01:21:17.070 --> 01:21:19.415 align:middle line:84%
become the same value,
and in that limit--

01:21:19.415 --> 01:21:22.560 align:middle line:90%


01:21:22.560 --> 01:21:24.880 align:middle line:84%
so for a heat and
diffusion interaction,

01:21:24.880 --> 01:21:27.780 align:middle line:84%
you have a definite relation
between the energy that

01:21:27.780 --> 01:21:30.340 align:middle line:84%
is transferred, the entropy
that is transferred,

01:21:30.340 --> 01:21:33.190 align:middle line:84%
and the amounts of constituents
that are transferred.

01:21:33.190 --> 01:21:40.350 align:middle line:90%


01:21:40.350 --> 01:21:47.380 align:middle line:84%
And if you divide by dt and the
area, the various transfers,

01:21:47.380 --> 01:21:49.650 align:middle line:90%
you get the fluxes.

01:21:49.650 --> 01:21:53.790 align:middle line:84%
So it's the transfer per
unit area per unit time.

01:21:53.790 --> 01:21:57.960 align:middle line:84%
And so this is the relation
that characterizes--

01:21:57.960 --> 01:22:04.890 align:middle line:84%
it's the equivalent of q
over T, but you see here

01:22:04.890 --> 01:22:07.680 align:middle line:90%
that it contains also this part.

01:22:07.680 --> 01:22:10.550 align:middle line:90%


01:22:10.550 --> 01:22:18.680 align:middle line:84%
So this is a very important
new independent equation

01:22:18.680 --> 01:22:21.500 align:middle line:90%
that we need in order to--

01:22:21.500 --> 01:22:23.780 align:middle line:84%
like we needed the
q over T in order

01:22:23.780 --> 01:22:26.745 align:middle line:84%
to combine the energy
and entropy balances.

01:22:26.745 --> 01:22:32.530 align:middle line:90%


01:22:32.530 --> 01:22:34.550 align:middle line:90%
Here it is.

01:22:34.550 --> 01:22:37.000 align:middle line:90%
So we start from that.

01:22:37.000 --> 01:22:40.560 align:middle line:90%
The question now is--

01:22:40.560 --> 01:22:45.300 align:middle line:84%
I see something fishy with
this slide, but in any case,

01:22:45.300 --> 01:22:46.535 align:middle line:90%
the question is--

01:22:46.535 --> 01:22:50.130 align:middle line:90%


01:22:50.130 --> 01:22:53.020 align:middle line:90%
I'm sorry.

01:22:53.020 --> 01:23:00.360 align:middle line:84%
The question is, can
we still call heat

01:23:00.360 --> 01:23:04.380 align:middle line:84%
the energy that is transferred
in a heat and diffusion

01:23:04.380 --> 01:23:05.790 align:middle line:90%
interaction?

01:23:05.790 --> 01:23:07.290 align:middle line:90%
The answer is no.

01:23:07.290 --> 01:23:11.735 align:middle line:84%
Only part of the energy
transfer can be called heat.

01:23:11.735 --> 01:23:15.380 align:middle line:90%


01:23:15.380 --> 01:23:18.562 align:middle line:90%
How do we identify that?

01:23:18.562 --> 01:23:22.130 align:middle line:84%
OK, remember-- OK, we
start from this relation

01:23:22.130 --> 01:23:26.870 align:middle line:84%
between the fluxes that
characterizes the heat

01:23:26.870 --> 01:23:30.160 align:middle line:90%
and diffusion interaction.

01:23:30.160 --> 01:23:32.480 align:middle line:84%
The chemical potential
appears in it.

01:23:32.480 --> 01:23:34.750 align:middle line:84%
Remember that the chemical
potential can always

01:23:34.750 --> 01:23:41.520 align:middle line:84%
be written as the
partial enthalpy minus T

01:23:41.520 --> 01:23:46.390 align:middle line:84%
times the partial entropy
for each of the constituents.

01:23:46.390 --> 01:23:47.400 align:middle line:90%
This is general.

01:23:47.400 --> 01:23:50.380 align:middle line:90%


01:23:50.380 --> 01:23:53.090 align:middle line:90%
So substitute that.

01:23:53.090 --> 01:23:56.900 align:middle line:84%
And then take, on
the left-hand side,

01:23:56.900 --> 01:23:59.000 align:middle line:84%
the stuff that is
not multiplied by T,

01:23:59.000 --> 01:24:03.580 align:middle line:84%
and on the right-hand side, the
stuff that is multiplied by T.

01:24:03.580 --> 01:24:08.560 align:middle line:84%
So now you have found some
part of the energy transfer

01:24:08.560 --> 01:24:09.660 align:middle line:90%
of the energy flux--

01:24:09.660 --> 01:24:12.390 align:middle line:90%


01:24:12.390 --> 01:24:14.940 align:middle line:90%
the total minus this part--

01:24:14.940 --> 01:24:20.130 align:middle line:84%
which is related to a
part of the entropy flux,

01:24:20.130 --> 01:24:21.340 align:middle line:90%
via the temperature.

01:24:21.340 --> 01:24:24.150 align:middle line:90%


01:24:24.150 --> 01:24:29.440 align:middle line:84%
So we are going to call
that part of the energy flux

01:24:29.440 --> 01:24:31.420 align:middle line:90%
q double prime.

01:24:31.420 --> 01:24:35.450 align:middle line:84%
That is what we
call the heat flux.

01:24:35.450 --> 01:24:41.900 align:middle line:84%
So we call heat, only the
difference between this

01:24:41.900 --> 01:24:50.520 align:middle line:84%
and the flux of
constituents, each multiplied

01:24:50.520 --> 01:24:52.303 align:middle line:90%
by the partial enthalpy.

01:24:52.303 --> 01:24:55.620 align:middle line:90%


01:24:55.620 --> 01:25:01.050 align:middle line:84%
You can think of this term
that we are subtracting away

01:25:01.050 --> 01:25:08.520 align:middle line:84%
as the energy that is
carried by the particles that

01:25:08.520 --> 01:25:13.440 align:middle line:84%
diffuse because Jn is
the diffusion (flux)

01:25:13.440 --> 01:25:17.650 align:middle line:90%
of particles of type i.

01:25:17.650 --> 01:25:26.860 align:middle line:84%
These particles diffuse, and
therefore, carry with them--

01:25:26.860 --> 01:25:31.900 align:middle line:84%
like in their backpack, they
have the partial enthalpy

01:25:31.900 --> 01:25:34.060 align:middle line:84%
and the partial
enthalpy-- they actually

01:25:34.060 --> 01:25:39.576 align:middle line:84%
have the partial energy
and the partial entropy.

01:25:39.576 --> 01:25:43.696 align:middle line:90%
But in order to overcome--

01:25:43.696 --> 01:25:48.940 align:middle line:84%
to move in a pressure
field, they have to--

01:25:48.940 --> 01:25:52.135 align:middle line:84%
that's why get the enthalpy
and not the energy,

01:25:52.135 --> 01:25:56.860 align:middle line:84%
it's like in bulk flow,
you have the pulsion work.

01:25:56.860 --> 01:26:00.140 align:middle line:84%
This is pulsion work against
the partial pressure,

01:26:00.140 --> 01:26:03.910 align:middle line:84%
but it's still
something that takes you

01:26:03.910 --> 01:26:10.550 align:middle line:84%
from the energy
plus the work that

01:26:10.550 --> 01:26:15.080 align:middle line:90%
is needed to overcome this--

01:26:15.080 --> 01:26:16.610 align:middle line:90%
the pulsion work.

01:26:16.610 --> 01:26:18.668 align:middle line:90%
The partial pulsion work.

01:26:18.668 --> 01:26:24.329 align:middle line:90%


01:26:24.329 --> 01:26:29.120 align:middle line:84%
So the overall energy
flux is, therefore,

01:26:29.120 --> 01:26:33.290 align:middle line:84%
now given by this that
we will call heat,

01:26:33.290 --> 01:26:43.250 align:middle line:84%
plus this transported enthalpy
due to the flux of particles.

01:26:43.250 --> 01:26:49.750 align:middle line:84%
And also, the entropy flux
is given by q over T. So

01:26:49.750 --> 01:26:52.240 align:middle line:90%
that's proper of a heat--

01:26:52.240 --> 01:26:54.970 align:middle line:84%
characteristic of
the heat interaction.

01:26:54.970 --> 01:26:58.630 align:middle line:84%
Plus the entropy that is
carried in the backpack by these

01:26:58.630 --> 01:27:01.750 align:middle line:90%
particles that are diffused.

01:27:01.750 --> 01:27:06.910 align:middle line:84%
So in other words, by
calling this q double prime,

01:27:06.910 --> 01:27:13.770 align:middle line:84%
essentially we are transforming
this single equation

01:27:13.770 --> 01:27:18.570 align:middle line:84%
into two equations with
the q double prime in it.

01:27:18.570 --> 01:27:20.045 align:middle line:90%
And so we have these two sets.

01:27:20.045 --> 01:27:23.540 align:middle line:90%


01:27:23.540 --> 01:27:27.425 align:middle line:84%
In heat transfer, we
call it q double prime.

01:27:27.425 --> 01:27:33.880 align:middle line:84%
In this typical business of
non-equilibrium thermodynamics,

01:27:33.880 --> 01:27:38.490 align:middle line:84%
this is called the measurable
heat flux, particularly

01:27:38.490 --> 01:27:44.020 align:middle line:84%
introduced by this famous
bible of the subject,

01:27:44.020 --> 01:27:47.090 align:middle line:84%
which is the book by
De Groot and Mazur.

01:27:47.090 --> 01:28:01.450 align:middle line:90%


01:28:01.450 --> 01:28:07.870 align:middle line:84%
If the particles
carry also charge,

01:28:07.870 --> 01:28:11.380 align:middle line:90%
then we do exactly the same.

01:28:11.380 --> 01:28:23.650 align:middle line:84%
So the relation that defines the
heat and diffusion interaction

01:28:23.650 --> 01:28:26.960 align:middle line:84%
is like this,
except that you have

01:28:26.960 --> 01:28:29.900 align:middle line:84%
to substitute the
chemical potential

01:28:29.900 --> 01:28:34.990 align:middle line:84%
with the total potential,
so it becomes this one.

01:28:34.990 --> 01:28:37.300 align:middle line:84%
And remember that the total
potential when you have

01:28:37.300 --> 01:28:40.510 align:middle line:90%
particles is given by this.

01:28:40.510 --> 01:28:44.710 align:middle line:84%
It's the chemical potential,
plus the electrostatic potential

01:28:44.710 --> 01:28:48.760 align:middle line:90%
times the charge of--

01:28:48.760 --> 01:28:53.540 align:middle line:84%
the unit charge
of your particles.

01:28:53.540 --> 01:28:56.940 align:middle line:90%


01:28:56.940 --> 01:28:59.370 align:middle line:90%
So you can write it this way.

01:28:59.370 --> 01:29:01.270 align:middle line:84%
Still in terms of the
chemical potential.

01:29:01.270 --> 01:29:07.880 align:middle line:84%
So now you can
still use the fact

01:29:07.880 --> 01:29:12.240 align:middle line:84%
that the chemical
potential is hi minus Tsi.

01:29:12.240 --> 01:29:14.830 align:middle line:90%
And then you can also--

01:29:14.830 --> 01:29:19.850 align:middle line:90%
remember that-- or define.

01:29:19.850 --> 01:29:23.600 align:middle line:84%
If you take the flux of
particles-- and these particles

01:29:23.600 --> 01:29:26.190 align:middle line:90%
carry this much charge.

01:29:26.190 --> 01:29:32.780 align:middle line:84%
This flux of charge is what
we call current density--

01:29:32.780 --> 01:29:38.785 align:middle line:84%
charge current or electrical
charge current density.

01:29:38.785 --> 01:29:43.460 align:middle line:90%


01:29:43.460 --> 01:29:51.020 align:middle line:84%
So take this one or this one and
substitute as before and-- not

01:29:51.020 --> 01:29:55.010 align:middle line:84%
substitute-- and move left-hand
side the stuff that is not

01:29:55.010 --> 01:29:57.890 align:middle line:84%
multiplied by T and on the
right-hand side the stuff that

01:29:57.890 --> 01:30:01.116 align:middle line:84%
is multiplied by T,
then you recognize--

01:30:01.116 --> 01:30:03.650 align:middle line:90%


01:30:03.650 --> 01:30:09.920 align:middle line:84%
then you call-- define q double
prime, the measurable heat flux,

01:30:09.920 --> 01:30:15.970 align:middle line:84%
as this term here, and
you get two equations.

01:30:15.970 --> 01:30:19.860 align:middle line:84%
So now, the energy
flux is due to heat.

01:30:19.860 --> 01:30:23.100 align:middle line:84%
The energy transported by
the diffusion of particles

01:30:23.100 --> 01:30:26.820 align:middle line:84%
through the enthalpy, the
internal energy plus the pulsion

01:30:26.820 --> 01:30:36.920 align:middle line:84%
work, and the electrical energy
carried by the charge carriers.

01:30:36.920 --> 01:30:41.030 align:middle line:84%
And for the entropy
flux, the same.

01:30:41.030 --> 01:30:46.310 align:middle line:84%
There is no contribution by
the electric charge current.

01:30:46.310 --> 01:30:49.798 align:middle line:90%


01:30:49.798 --> 01:30:52.460 align:middle line:90%
So with these ingredients--

01:30:52.460 --> 01:30:55.200 align:middle line:90%


01:30:55.200 --> 01:31:00.755 align:middle line:84%
Yeah we're almost out of
time, but yeah, we can--

01:31:00.755 --> 01:31:08.270 align:middle line:90%


01:31:08.270 --> 01:31:14.010 align:middle line:84%
well, yeah, one--
let me just say--

01:31:14.010 --> 01:31:16.190 align:middle line:84%
one thing from which
we will start next time

01:31:16.190 --> 01:31:19.490 align:middle line:84%
is that you can rewrite
that expression that

01:31:19.490 --> 01:31:25.520 align:middle line:84%
defines the relation
between energy, entropy,

01:31:25.520 --> 01:31:34.010 align:middle line:84%
and materials flux in an entropy
form instead of an energy form

01:31:34.010 --> 01:31:37.460 align:middle line:84%
in terms of new variables, like
the inverse of the temperature

01:31:37.460 --> 01:31:40.340 align:middle line:84%
and the chemical potential,
the total potential divided

01:31:40.340 --> 01:31:42.700 align:middle line:90%
by the temperature.

01:31:42.700 --> 01:31:47.190 align:middle line:84%
But let's do that next time
because we're out of time now.

01:31:47.190 --> 01:31:51.000 align:middle line:90%