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GIAN PAOLO BERETTA:
Good afternoon.

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So we've been studying
properties of stable equilibrium

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states, relations
that can be extracted

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from the fundamental
relation of any system

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and, therefore,
if the system is,

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for example, a substance
of a pure substance

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or mixtures of substances.

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And yes, it is a lot of math
and mathematical manipulations.

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And today we will have
a little more of that.

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And then we'll stop about
the mathematics, at least

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for this part.

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But I wanted to stress the
fact that we are extracting

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a lot of information
out of just the idea

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that there exists a fundamental
relation for stable equilibrium

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states from which we
can extract properties.

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And it's precisely the
mathematical manipulations

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that is not just
by itself but with

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proper physical interpretation.

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And that's the important aspect.

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It's not just the mathematics.

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It's also to interpret
the mathematics

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and see what the
useful part of it is.

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It's from these that you can
extract a lot of information.

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For example, in economics,
manipulations of this sort

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have earned the Nobel Prize
to Paul Samuelson, who

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was a professor here at MIT,
because he realized that,

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essentially also in economics--

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don't ask me what
part of economics--

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but in any case,
in economics, there

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are functions like that that
can be manipulated by the tools

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that we are
developing from which

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you can extract a
lot of information

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about economics in that case.

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So mathematics is
a powerful tool,

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a way that allows you
to think straight.

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So, right, we've done
the Legendre transform.

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And we have applied it to derive
the Helmholtz free energy,

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the Gibbs free energy,
the enthalpy, and also

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this Euler free energy
that we'll return to also

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today and the next time.

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Also we developed
this Maxwell relations

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coming from the reciprocity of
the second order derivatives

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of the various functions.

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Today I want to introduce
quickly, or review quickly

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if you've seen it already,
this other tool which

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is Jacobian determinants.

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So if you have a
system of two functions

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and you take the
matrix in which you

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put all the partial
derivatives in that fashion,

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the determinant of that
matrix is called the Jacobian

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determinant.

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The matrix is the Jacobian.

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And the determinant
of the Jacobian

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is we call it the Jacobian
anyway, just for short.

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And we use this symbol,
which resembles a partial

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because somehow it's a partial
of a vector of functions

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with respect to a vector
of independent variables.

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And it has these
properties, which

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you can infer easily by the
properties of determinants.

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You exchange row, exchange a
column, you change the sign,

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and so you can easily
prove these relations.

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You can also notice that
if one of the functions

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like, for example, g is the
simple function g equals y,

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then the second row
is just the derivative

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of y with respect to x.

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Since y and x are independent
variables, that's 0.

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And the derivative of y
with respect to y is 1.

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So that's 0 and 1, which
leaves for the determinant just

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this term here, which is
the partial derivative

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of f with respect to x.

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So this is a useful
identity because you

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can pass from partial
derivatives that

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might be want to evaluate
to an equivalent Jacobian.

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And then we will see that we
can manipulate that further.

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Of course, if also
f is equal to x,

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then this becomes simply
the identity, I mean 1.

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OK.

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The other theorem
about Jacobians

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is that if you consider a
function of a single variable

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and you invert the function so
you have f as a function of x,

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and you invert it as
x as a function of f,

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you know that the derivative
of this inverted function

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is equal to the inverse
of the derivative

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of the original function.

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And the equivalent for a
system of two functions of two

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variables is that the Jacobian
of the inverted system, when

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you solve the system,
this system of equations,

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to put in evidence x and y
as a function of x and g.

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So if you change the independent
variables, and so you invert--

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well, the Jacobian of
the inverted system

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is equal to the inverse of the
Jacobian of the original system.

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And that also shows
that if you prove--

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if you choose the
function g of y

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as before, g equals y as before,
you can prove by this relation

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the fact that the inverse--

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I mean the partial derivative
of the inverse with respect

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to f, at fixed y, is
equal to the inverse

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of the original
partial derivative.

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So formally, you see this
is x over y, at constant y.

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Let's read it loosely.

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Well, you can just put it--

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consider the x and the y.

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And consider it as a fraction
and put it under a denominator

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and you get this function.

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And it is fair.

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In other words,
this proves that you

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can do that easy manipulation.

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All right.

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And the other item
is that if you

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have a function f of x, so x
is your independent variable,

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but suppose you
want to represent

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your independent variable
in parametric form.

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So x is a function of another
variable, say a, x of a.

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So you substitute
in the function.

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And so you have a
function of a function.

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This a function of a.

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Now a has become the
independent variable.

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So the chain rule
for derivatives

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says for single variables
that the derivative

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of f with respect to
a is the derivative

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of f with respect to x times
the derivative of x with respect

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to a.

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The equivalent for our
system of two variables--

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so when you change
your system f and g,

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instead of as a
function of x and y,

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but as a function of a
and b, so the x and y

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are in turn
functions of a and b,

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then you have a situation
similar to that.

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And the derivative
actually, the Jacobian

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of f and g with respect
to the new variables,

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is equal to the
Jacobian with respect

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to the old variables times the
Jacobian of the old variables

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with respect to the new ones.

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Informally, you can
write this result--

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suppose you delete these two.

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So we view this result as simply
the Jacobian of f with respect

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to a.

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So you write it this way.

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And then you have
empty spaces here

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where you can put
anything that cancels out.

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So for example, you can put the
Jacobian of x, y with respect

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to x, y, which is equal
to 1, the identity.

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We just proved it before.

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And thus the formal
manipulation becomes easy

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now because then you interpret
this one as the Jacobian

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of f with respect to x, y.

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And this is the Jacobian
of x, y in respect to a, b.

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Let's give an example that
brings us to a useful relation

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useful identity for
two properties that

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are among the list that we
have seen are measurable.

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So take the Hess
determinant, the determinant

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of the Hess
relation-- of the Hess

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matrix of the fundamental
relation with respect

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to entropy and volume.

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So it's the matrix
of the second order

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derivatives of energy with
respect to entropy and volume.

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Now since this second
derivatives are derivatives of,

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for example, we remember
that the derivative

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of the first derivative
of E with respect to S

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is the temperature,
you can also write them

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in this way in terms of the
conjugate variables, temperature

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for entropy minus the
pressure for volume.

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OK.

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So this is just applying
those definitions.

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And then here you recognize
that, apart from the minus sign

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here that can be taken
outside of the determinant,

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this is just the Jacobian
of temperature and pressure

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versus with respect
to S and V. So now

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let's do this trick of
shifting the denominator,

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leaving the empty spaces.

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And let's put here
whatever we want.

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So I'll do it in two ways.

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I put S and p here and there.

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And then I notice that
I have chosen my--

00:12:03.590 --> 00:12:09.530 align:middle line:84%
made my choice so that in
each of these determinant--

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I mean Jacobian, there
is a repeated pressure

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above and below.

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So that is the derivative of T
with respect to S at constant p.

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And this other side has
S, which is repeated.

00:12:29.350 --> 00:12:37.910 align:middle line:84%
So that is the derivative of p
with respect to V at constant S.

00:12:37.910 --> 00:12:40.640 align:middle line:90%
But then if you look up--

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and let me remind it here.

00:12:45.290 --> 00:12:50.780 align:middle line:84%
We define the heat capacity
at constant pressure,

00:12:50.780 --> 00:12:52.640 align:middle line:90%
a few days ago.

00:12:52.640 --> 00:12:55.760 align:middle line:84%
And that was defined
as the derivative

00:12:55.760 --> 00:12:59.840 align:middle line:84%
of the enthalpy with
respect to temperature at p.

00:12:59.840 --> 00:13:05.810 align:middle line:84%
But if you look at how the
differential for the enthalpy

00:13:05.810 --> 00:13:13.340 align:middle line:84%
is, if you keep p and n
constant, dH is equal to TdS.

00:13:13.340 --> 00:13:16.070 align:middle line:84%
So you can substitute
the dH with the TdS

00:13:16.070 --> 00:13:19.910 align:middle line:90%
here at constant p and n.

00:13:19.910 --> 00:13:23.900 align:middle line:84%
So Cp, or actually, you see
here that the derivative

00:13:23.900 --> 00:13:26.360 align:middle line:84%
of S with respect
to T at constant p

00:13:26.360 --> 00:13:34.210 align:middle line:84%
is Cp over T. This derivative
is therefore the inverse of Cp

00:13:34.210 --> 00:13:36.850 align:middle line:90%
over T. Why the inverse?

00:13:36.850 --> 00:13:41.130 align:middle line:84%
Because we just proved
that these derivatives

00:13:41.130 --> 00:13:48.710 align:middle line:84%
here is equal to the inverse
of its reciprocal, so to speak.

00:13:48.710 --> 00:13:51.110 align:middle line:84%
Also this other one
we can recognize

00:13:51.110 --> 00:13:55.165 align:middle line:84%
as one of the properties that
we have defined or almost.

00:13:55.165 --> 00:14:01.700 align:middle line:90%


00:14:01.700 --> 00:14:04.040 align:middle line:84%
It's the derivative
of V with respect

00:14:04.040 --> 00:14:07.890 align:middle line:84%
to pressure with
the minus in front.

00:14:07.890 --> 00:14:11.450 align:middle line:90%
And so it's the compressibility.

00:14:11.450 --> 00:14:12.980 align:middle line:84%
Actually, the other
day, we defined

00:14:12.980 --> 00:14:14.960 align:middle line:84%
the isothermal
compressibility, so when

00:14:14.960 --> 00:14:18.200 align:middle line:84%
you compress a material
at constant temperature,

00:14:18.200 --> 00:14:21.020 align:middle line:84%
but you could also compress
it at constant entropy.

00:14:21.020 --> 00:14:25.230 align:middle line:84%
That defines the
isentropic compressibility.

00:14:25.230 --> 00:14:28.230 align:middle line:90%


00:14:28.230 --> 00:14:32.440 align:middle line:84%
And so here you
recognize the inverse

00:14:32.440 --> 00:14:35.700 align:middle line:84%
of the isentropic
compressibility.

00:14:35.700 --> 00:14:36.200 align:middle line:90%
OK.

00:14:36.200 --> 00:14:44.220 align:middle line:84%
So first result is that since
the determinant of the Hess

00:14:44.220 --> 00:14:48.650 align:middle line:84%
matrix has to be non-negative
by the conditions of stability

00:14:48.650 --> 00:14:54.950 align:middle line:84%
that we have already proved,
we have this inequality.

00:14:54.950 --> 00:14:58.930 align:middle line:84%
But that's not the
main object here.

00:14:58.930 --> 00:15:03.040 align:middle line:84%
I want to do now the
same but by substituting

00:15:03.040 --> 00:15:09.890 align:middle line:84%
here in the empty spaces,
another pair of variables, again

00:15:09.890 --> 00:15:15.350 align:middle line:84%
in such a way that numerator
and denominator have

00:15:15.350 --> 00:15:19.350 align:middle line:84%
one same variable like here the
temperature and here the volume.

00:15:19.350 --> 00:15:22.350 align:middle line:90%


00:15:22.350 --> 00:15:25.330 align:middle line:84%
Then this becomes the
partial of p with respect

00:15:25.330 --> 00:15:26.830 align:middle line:84%
to volume with
constant temperature.

00:15:26.830 --> 00:15:30.790 align:middle line:84%
And this becomes a partial of T
with respect to S at constant V.

00:15:30.790 --> 00:15:35.660 align:middle line:84%
And by the same definitions
that we just reviewed,

00:15:35.660 --> 00:15:40.650 align:middle line:84%
you can show that this is
equal to T over the heat

00:15:40.650 --> 00:15:44.610 align:middle line:84%
capacity at constant
volume and this other

00:15:44.610 --> 00:15:50.820 align:middle line:84%
is 1 over the volume times the
isothermal compressibility.

00:15:50.820 --> 00:15:54.815 align:middle line:84%
Also this group must be
greater than or equal to 0.

00:15:54.815 --> 00:15:57.820 align:middle line:90%


00:15:57.820 --> 00:16:03.870 align:middle line:84%
But since they came from the
manipulation of the same stuff,

00:16:03.870 --> 00:16:09.120 align:middle line:84%
these groups must also
be equal to one another.

00:16:09.120 --> 00:16:15.250 align:middle line:84%
And that by eliminating T and V,
which cancel if you equate that

00:16:15.250 --> 00:16:19.980 align:middle line:84%
to this, you obtain this result,
that the ratio of the heat

00:16:19.980 --> 00:16:24.030 align:middle line:84%
capacities, constant
pressure and volume,

00:16:24.030 --> 00:16:29.580 align:middle line:84%
is equal to the ratio of
the compressibilities,

00:16:29.580 --> 00:16:36.000 align:middle line:84%
at constant temperature
versus at constant entropy.

00:16:36.000 --> 00:16:42.160 align:middle line:84%
For example, if you
remember like for air

00:16:42.160 --> 00:16:53.140 align:middle line:84%
or for a diatomic gas,
how much is Cp over CV?

00:16:53.140 --> 00:16:54.350 align:middle line:90%
Anybody remembers?

00:16:54.350 --> 00:16:58.000 align:middle line:90%


00:16:58.000 --> 00:17:05.210 align:middle line:90%
For air, it's 1.4.

00:17:05.210 --> 00:17:11.700 align:middle line:90%
It is 7/5, 7 over 5.

00:17:11.700 --> 00:17:19.430 align:middle line:84%
So that means that also the
ratio of this compressibility

00:17:19.430 --> 00:17:21.475 align:middle line:90%
is 1 point 4.

00:17:21.475 --> 00:17:24.339 align:middle line:90%


00:17:24.339 --> 00:17:28.960 align:middle line:84%
We will see in a while
that this gives us--

00:17:28.960 --> 00:17:33.410 align:middle line:84%
this has some importance
in a practical application,

00:17:33.410 --> 00:17:41.710 align:middle line:84%
which is the air springs that
are used in many transport

00:17:41.710 --> 00:17:42.460 align:middle line:90%
devices--

00:17:42.460 --> 00:17:48.130 align:middle line:84%
I mean transport systems like
trains, trucks, cars, and so on,

00:17:48.130 --> 00:17:53.830 align:middle line:90%
even bicycles, air springs.

00:17:53.830 --> 00:18:00.580 align:middle line:84%
But before we get to that, let's
keep going with another relation

00:18:00.580 --> 00:18:06.110 align:middle line:84%
that we can prove
by, again, using

00:18:06.110 --> 00:18:08.930 align:middle line:90%
the properties of Jacobians.

00:18:08.930 --> 00:18:14.825 align:middle line:84%
And here is a situation in
which you have a surface.

00:18:14.825 --> 00:18:17.690 align:middle line:90%


00:18:17.690 --> 00:18:22.520 align:middle line:84%
For example, a function
of x, y, and z equals 0,

00:18:22.520 --> 00:18:25.640 align:middle line:84%
represents a surface
that you can represent

00:18:25.640 --> 00:18:27.840 align:middle line:90%
in three dimensions x, y, z.

00:18:27.840 --> 00:18:33.920 align:middle line:84%
So of course, you
can view that surface

00:18:33.920 --> 00:18:36.080 align:middle line:84%
from various points
of view by choosing

00:18:36.080 --> 00:18:38.540 align:middle line:84%
what your base
reference frame is

00:18:38.540 --> 00:18:40.320 align:middle line:84%
and what the
independent variable is.

00:18:40.320 --> 00:18:43.550 align:middle line:84%
So you can represent
that surface also

00:18:43.550 --> 00:18:49.210 align:middle line:84%
in these three alternative
ways, x as a function of x, y.

00:18:49.210 --> 00:18:50.080 align:middle line:90%
No.

00:18:50.080 --> 00:18:51.260 align:middle line:90%
You see what I'm saying?

00:18:51.260 --> 00:19:05.950 align:middle line:84%
If I have this surface here
which is f of x, y, z equals 0,

00:19:05.950 --> 00:19:07.780 align:middle line:90%
I can represent it.

00:19:07.780 --> 00:19:11.740 align:middle line:90%
Suppose this is x, y, and z.

00:19:11.740 --> 00:19:12.590 align:middle line:90%
OK.

00:19:12.590 --> 00:19:14.950 align:middle line:90%
So this is also--

00:19:14.950 --> 00:19:19.060 align:middle line:84%
For every x and y,
I have a value of z

00:19:19.060 --> 00:19:25.030 align:middle line:84%
so I can view it as a
function z of x and y.

00:19:25.030 --> 00:19:28.780 align:middle line:84%
But I can also view
it also from here.

00:19:28.780 --> 00:19:32.950 align:middle line:84%
I fix x, I fix z, and
that gives me a y.

00:19:32.950 --> 00:19:39.640 align:middle line:84%
So that's y function
of z and x and so on.

00:19:39.640 --> 00:19:43.300 align:middle line:84%
So these are alternative
ways of representing,

00:19:43.300 --> 00:19:48.040 align:middle line:84%
in thermodynamics, the typical
surface that is treated this way

00:19:48.040 --> 00:19:50.560 align:middle line:90%
is the pVT relation.

00:19:50.560 --> 00:19:53.630 align:middle line:90%
The equation of state.

00:19:53.630 --> 00:19:59.260 align:middle line:84%
That particular equation,
that, for a class of states,

00:19:59.260 --> 00:20:03.670 align:middle line:84%
like single phase
states, is equivalent

00:20:03.670 --> 00:20:07.900 align:middle line:90%
to the fundamental relation.

00:20:07.900 --> 00:20:12.220 align:middle line:84%
And so it's useful
because it's in terms

00:20:12.220 --> 00:20:16.030 align:middle line:84%
of easily measurable properties
like volume, temperature,

00:20:16.030 --> 00:20:16.610 align:middle line:90%
and pressure.

00:20:16.610 --> 00:20:24.700 align:middle line:90%


00:20:24.700 --> 00:20:26.470 align:middle line:90%
So here we do--

00:20:26.470 --> 00:20:28.140 align:middle line:90%
what do we do?

00:20:28.140 --> 00:20:35.440 align:middle line:84%
We take, essentially, ratios
of stuff that are equal to 1

00:20:35.440 --> 00:20:36.900 align:middle line:90%
or actually say minus 1.

00:20:36.900 --> 00:20:39.820 align:middle line:90%


00:20:39.820 --> 00:20:45.970 align:middle line:84%
So say x, z, and z,
x in the denominator.

00:20:45.970 --> 00:20:47.870 align:middle line:84%
By the properties
of determinants,

00:20:47.870 --> 00:20:49.510 align:middle line:90%
that's equal to minus 1.

00:20:49.510 --> 00:20:56.550 align:middle line:84%
If I switch one column,
it changes sign.

00:20:56.550 --> 00:21:00.460 align:middle line:84%
So I write this, which
are easy identities,

00:21:00.460 --> 00:21:04.180 align:middle line:84%
then I rearrange them in
a more interesting way

00:21:04.180 --> 00:21:11.280 align:middle line:84%
so that, again, I have the
same variable numerator

00:21:11.280 --> 00:21:12.450 align:middle line:90%
and denominator.

00:21:12.450 --> 00:21:15.210 align:middle line:84%
So for example, this is the
partial of x with respect

00:21:15.210 --> 00:21:17.160 align:middle line:90%
to y at constant z.

00:21:17.160 --> 00:21:19.660 align:middle line:84%
This is the partial
of x with respect--

00:21:19.660 --> 00:21:21.810 align:middle line:84%
I'm sorry, y respect
to z at constant x.

00:21:21.810 --> 00:21:23.700 align:middle line:84%
And this is partial
of z with respect

00:21:23.700 --> 00:21:28.710 align:middle line:84%
to x at constant y,
which is written here.

00:21:28.710 --> 00:21:32.880 align:middle line:84%
And if you multiply minus 1
three times, you get minus 1.

00:21:32.880 --> 00:21:36.450 align:middle line:84%
So this is called
the cyclic relation.

00:21:36.450 --> 00:21:42.330 align:middle line:84%
And if you apply it
to the pVT relation,

00:21:42.330 --> 00:21:44.645 align:middle line:84%
equation of state,
here is what you get.

00:21:44.645 --> 00:21:49.340 align:middle line:90%


00:21:49.340 --> 00:21:52.430 align:middle line:84%
And for example,
you could apply it--

00:21:52.430 --> 00:21:57.230 align:middle line:84%
remember that one of the
Maxwell relations that we said

00:21:57.230 --> 00:22:01.580 align:middle line:84%
could be useful to measure
entropy because it gives entropy

00:22:01.580 --> 00:22:06.150 align:middle line:84%
changes that you can
measure by measuring volume

00:22:06.150 --> 00:22:08.490 align:middle line:84%
changes, pressure
changes, temperature

00:22:08.490 --> 00:22:11.140 align:middle line:84%
changes at constant temperature
and constant volume.

00:22:11.140 --> 00:22:16.260 align:middle line:84%
So this is somehow the
basis of an instrument

00:22:16.260 --> 00:22:20.160 align:middle line:84%
that you could call
an entropy meter.

00:22:20.160 --> 00:22:24.460 align:middle line:84%
Well, by applying
this cyclic relation--

00:22:24.460 --> 00:22:29.030 align:middle line:84%
and I'm not going to the details
but I'll let you show that--

00:22:29.030 --> 00:22:31.840 align:middle line:90%


00:22:31.840 --> 00:22:34.990 align:middle line:84%
you prove that
this derivative is

00:22:34.990 --> 00:22:38.080 align:middle line:84%
equal to the ratio of
alpha p over kappa T.

00:22:38.080 --> 00:22:45.880 align:middle line:84%
So it's the isobaric
coefficient of expansion alpha

00:22:45.880 --> 00:22:48.310 align:middle line:84%
over the isothermal
compressibility

00:22:48.310 --> 00:22:51.460 align:middle line:90%
of your material.

00:22:51.460 --> 00:23:00.040 align:middle line:84%
For example, for a gas, I mean,
if I can write the ideal gas

00:23:00.040 --> 00:23:07.600 align:middle line:84%
relation, you can
view that as a V

00:23:07.600 --> 00:23:13.360 align:middle line:84%
as a function of
T, and p, and n.

00:23:13.360 --> 00:23:18.260 align:middle line:90%


00:23:18.260 --> 00:23:24.050 align:middle line:90%
So it's nRT over p.

00:23:24.050 --> 00:23:28.390 align:middle line:84%
So it's easy to compute,
for example, alpha p.

00:23:28.390 --> 00:23:33.250 align:middle line:84%
alpha p is 1 over V, the
derivative of V with respect

00:23:33.250 --> 00:23:37.430 align:middle line:90%
to T at constant pressure.

00:23:37.430 --> 00:23:44.390 align:middle line:84%
So it's how much the
expansion for a given

00:23:44.390 --> 00:23:46.610 align:middle line:90%
increase in temperature.

00:23:46.610 --> 00:23:47.310 align:middle line:90%
All right.

00:23:47.310 --> 00:23:53.600 align:middle line:84%
So it's 1 over V. The derivative
of V with respect to T is easy.

00:23:53.600 --> 00:23:58.260 align:middle line:90%
It's nR over p.

00:23:58.260 --> 00:24:15.080 align:middle line:84%
And if you use that again, this
is 1 over T. kappa T is minus 1

00:24:15.080 --> 00:24:19.880 align:middle line:84%
over V, the derivative of V
with respect to p at constant T.

00:24:19.880 --> 00:24:20.970 align:middle line:90%
All right.

00:24:20.970 --> 00:24:25.810 align:middle line:90%
We can also do that derivative.

00:24:25.810 --> 00:24:28.840 align:middle line:84%
The derivative of
this with respect to p

00:24:28.840 --> 00:24:34.480 align:middle line:90%
is minus nRT over p squared.

00:24:34.480 --> 00:24:39.100 align:middle line:90%


00:24:39.100 --> 00:24:42.440 align:middle line:90%
I apply that again.

00:24:42.440 --> 00:24:44.840 align:middle line:84%
And the minus goes
away with the minus.

00:24:44.840 --> 00:24:46.380 align:middle line:90%
One V goes away.

00:24:46.380 --> 00:24:47.820 align:middle line:90%
And I'm left with 1 over p.

00:24:47.820 --> 00:24:50.710 align:middle line:90%


00:24:50.710 --> 00:24:58.270 align:middle line:84%
So alpha and kappa for ideal
gases are relatively simple.

00:24:58.270 --> 00:25:06.220 align:middle line:84%
And so this gives that
the derivative here

00:25:06.220 --> 00:25:13.680 align:middle line:90%
is equal to p over T for a gas.

00:25:13.680 --> 00:25:20.610 align:middle line:90%


00:25:20.610 --> 00:25:24.000 align:middle line:84%
There is another
interesting relation

00:25:24.000 --> 00:25:32.750 align:middle line:84%
that you can prove not so easily
but relatively straightforward

00:25:32.750 --> 00:25:38.630 align:middle line:90%
by using the Jacobians.

00:25:38.630 --> 00:25:41.510 align:middle line:90%


00:25:41.510 --> 00:25:44.060 align:middle line:84%
It's the Mayer
relation which relates

00:25:44.060 --> 00:25:49.410 align:middle line:84%
Cp, CV, alpha p and kappa T,
and, of course, temperature

00:25:49.410 --> 00:25:51.940 align:middle line:90%
and volume.

00:25:51.940 --> 00:25:58.740 align:middle line:84%
And here you see this is
just the definition of Cp.

00:25:58.740 --> 00:26:02.310 align:middle line:84%
We write this derivative
in terms of a Jacobian

00:26:02.310 --> 00:26:06.030 align:middle line:84%
with the property
that is kept constant,

00:26:06.030 --> 00:26:08.950 align:middle line:84%
repeated numerator
and denominator.

00:26:08.950 --> 00:26:12.910 align:middle line:84%
Then we shift, leave the empty
space, and then we search.

00:26:12.910 --> 00:26:17.080 align:middle line:84%
And now the choice of what to
put there is sort of a smart--

00:26:17.080 --> 00:26:21.780 align:middle line:84%
you have to use just trial
and error or some experience

00:26:21.780 --> 00:26:24.180 align:middle line:90%
on how to choose it.

00:26:24.180 --> 00:26:30.660 align:middle line:84%
But here if you, for example,
we choose to select T and V,

00:26:30.660 --> 00:26:34.530 align:middle line:84%
the second one has a
repeated variable numerator

00:26:34.530 --> 00:26:37.140 align:middle line:84%
and denominator so it
is a partial derivative.

00:26:37.140 --> 00:26:41.390 align:middle line:84%
And again, we find that
it's related to kappa T.

00:26:41.390 --> 00:26:44.820 align:middle line:84%
The first determinant has
four different variables.

00:26:44.820 --> 00:26:50.520 align:middle line:84%
So we write it here in
terms of its definition.

00:26:50.520 --> 00:26:54.550 align:middle line:90%


00:26:54.550 --> 00:26:57.190 align:middle line:84%
And then these
various entries can be

00:26:57.190 --> 00:26:59.840 align:middle line:90%
recognized as those properties.

00:26:59.840 --> 00:27:06.540 align:middle line:84%
For example, this is CV
over T. This we just proved

00:27:06.540 --> 00:27:11.500 align:middle line:90%
is alpha over kappa T.

00:27:11.500 --> 00:27:17.500 align:middle line:84%
This is the same because of the
symmetry of the Hess determinant

00:27:17.500 --> 00:27:21.230 align:middle line:84%
or because of the Maxwell
relations, which is the same.

00:27:21.230 --> 00:27:25.380 align:middle line:84%
And this is one over kappa T. So
now we compute the determinant.

00:27:25.380 --> 00:27:26.660 align:middle line:90%
You get that.

00:27:26.660 --> 00:27:29.510 align:middle line:90%
You place it here.

00:27:29.510 --> 00:27:32.155 align:middle line:84%
And out comes the
Mayer relation.

00:27:32.155 --> 00:27:35.270 align:middle line:90%


00:27:35.270 --> 00:27:36.560 align:middle line:90%
OK.

00:27:36.560 --> 00:27:37.080 align:middle line:90%
Yeah.

00:27:37.080 --> 00:27:39.100 align:middle line:84%
So what's the Mayer
relation for a gas?

00:27:39.100 --> 00:27:43.900 align:middle line:90%


00:27:43.900 --> 00:27:52.215 align:middle line:84%
What's the relation between
Cp and CV for the ideal gas?

00:27:52.215 --> 00:27:56.045 align:middle line:90%


00:27:56.045 --> 00:27:56.545 align:middle line:90%
No?

00:27:56.545 --> 00:28:10.590 align:middle line:90%


00:28:10.590 --> 00:28:15.220 align:middle line:90%
How about R, the gas constant?

00:28:15.220 --> 00:28:20.450 align:middle line:84%
Usually, you don't
do heat capacities.

00:28:20.450 --> 00:28:24.330 align:middle line:90%
We do specific heats.

00:28:24.330 --> 00:28:26.060 align:middle line:90%
So that's CP.

00:28:26.060 --> 00:28:31.280 align:middle line:90%
Small c is capital C over n.

00:28:31.280 --> 00:28:36.410 align:middle line:90%
And cV, small c, heat capacity.

00:28:36.410 --> 00:28:41.580 align:middle line:84%
I'm sorry, specific
heat, is the CV over n.

00:28:41.580 --> 00:28:47.340 align:middle line:84%
And then the Meyer relation is
that CP equals CV plus the gas

00:28:47.340 --> 00:28:51.630 align:middle line:84%
constant, but let's
prove it because we

00:28:51.630 --> 00:28:54.840 align:middle line:90%
said that we have it there.

00:28:54.840 --> 00:28:58.610 align:middle line:90%
So we have to compute V--

00:28:58.610 --> 00:29:06.760 align:middle line:84%
what is it-- the VT alpha
squared over kappa T,

00:29:06.760 --> 00:29:11.260 align:middle line:84%
all right, which
is this term here,

00:29:11.260 --> 00:29:14.260 align:middle line:84%
which is the difference
between the two capacities.

00:29:14.260 --> 00:29:15.790 align:middle line:90%
So alpha.

00:29:15.790 --> 00:29:16.580 align:middle line:90%
So that's VT.

00:29:16.580 --> 00:29:19.380 align:middle line:90%


00:29:19.380 --> 00:29:23.240 align:middle line:84%
Alpha is 1 over T. So
we got T squared here.

00:29:23.240 --> 00:29:25.250 align:middle line:90%
And kappa is 1 over p.

00:29:25.250 --> 00:29:28.360 align:middle line:90%
So I've got the p there.

00:29:28.360 --> 00:29:31.310 align:middle line:90%
So that goes with that.

00:29:31.310 --> 00:29:38.510 align:middle line:84%
And hopefully, since pV is equal
to nRT, divided by T gives nR.

00:29:38.510 --> 00:29:44.640 align:middle line:90%


00:29:44.640 --> 00:29:51.900 align:middle line:84%
I see a lot of rust in your
mind about previous thermo.

00:29:51.900 --> 00:29:52.475 align:middle line:90%
That's OK.

00:29:52.475 --> 00:29:56.665 align:middle line:90%


00:29:56.665 --> 00:29:57.165 align:middle line:90%
All right.

00:29:57.165 --> 00:30:00.420 align:middle line:90%


00:30:00.420 --> 00:30:03.760 align:middle line:90%
So done with these properties.

00:30:03.760 --> 00:30:10.480 align:middle line:84%
I want to go back to the
subject of available energy.

00:30:10.480 --> 00:30:15.380 align:middle line:84%
You remember what
we've done I forget now

00:30:15.380 --> 00:30:17.525 align:middle line:84%
if it was the previous
lecture or the one before.

00:30:17.525 --> 00:30:24.410 align:middle line:90%


00:30:24.410 --> 00:30:27.090 align:middle line:90%
Available energy.

00:30:27.090 --> 00:30:31.650 align:middle line:84%
This is the setup in which I
have a system and the reservoir.

00:30:31.650 --> 00:30:35.340 align:middle line:84%
And they undergo
a weight process.

00:30:35.340 --> 00:30:38.160 align:middle line:84%
And we know that if the
process, the weight process

00:30:38.160 --> 00:30:49.390 align:middle line:84%
is reversible, we can extract
the maximum amount of energy

00:30:49.390 --> 00:30:52.630 align:middle line:84%
when the system ends
in a mutual equilibrium

00:30:52.630 --> 00:30:57.460 align:middle line:84%
state with the environment,
with the reservoir.

00:30:57.460 --> 00:30:59.620 align:middle line:84%
Here instead we
are going to adopt

00:30:59.620 --> 00:31:03.640 align:middle line:84%
two different states, two
arbitrary states, initial

00:31:03.640 --> 00:31:05.330 align:middle line:90%
and final.

00:31:05.330 --> 00:31:11.060 align:middle line:84%
And you ask yourself, well,
if my system has to go from A1

00:31:11.060 --> 00:31:17.330 align:middle line:84%
to A2, and it has available the
interaction with this thermal

00:31:17.330 --> 00:31:24.520 align:middle line:84%
reservoir, what is the maximum
weight lift that it can do,

00:31:24.520 --> 00:31:32.160 align:middle line:84%
or if it cannot lift the weight,
what is the minimum weight

00:31:32.160 --> 00:31:37.460 align:middle line:84%
lowering that is required so
as to achieve that change?

00:31:37.460 --> 00:31:42.840 align:middle line:90%


00:31:42.840 --> 00:31:45.045 align:middle line:90%
And we have seen that--

00:31:45.045 --> 00:31:47.630 align:middle line:90%


00:31:47.630 --> 00:31:51.440 align:middle line:84%
I mean this class of problems--
what's the maximum work,

00:31:51.440 --> 00:31:53.970 align:middle line:90%
what's the minimum work--

00:31:53.970 --> 00:31:57.240 align:middle line:84%
Are always solved
by writing an energy

00:31:57.240 --> 00:32:02.330 align:middle line:84%
balance, an entropy
balance, and also

00:32:02.330 --> 00:32:05.360 align:middle line:84%
inserting as much as we
know about the properties

00:32:05.360 --> 00:32:06.620 align:middle line:90%
of the systems involved.

00:32:06.620 --> 00:32:08.120 align:middle line:84%
In this case, we
have a reservoir

00:32:08.120 --> 00:32:10.460 align:middle line:84%
for which we know the
fundamental relation is

00:32:10.460 --> 00:32:12.850 align:middle line:84%
this linear relationship
between energy and entropy.

00:32:12.850 --> 00:32:15.680 align:middle line:90%


00:32:15.680 --> 00:32:20.660 align:middle line:90%
And by the way, usually in--

00:32:20.660 --> 00:32:24.420 align:middle line:90%


00:32:24.420 --> 00:32:30.510 align:middle line:84%
often, especially
in physics language,

00:32:30.510 --> 00:32:35.180 align:middle line:84%
what we call thermal reservoir
is called a heat bath.

00:32:35.180 --> 00:32:35.680 align:middle line:90%
OK.

00:32:35.680 --> 00:32:42.210 align:middle line:84%
Now you realize that we
defined the heat interaction

00:32:42.210 --> 00:32:57.980 align:middle line:84%
so that from heat from
A to B so that if you

00:32:57.980 --> 00:33:05.110 align:middle line:84%
want how much entropy
is transferred,

00:33:05.110 --> 00:33:09.790 align:middle line:84%
you get it because the ratio
between energy and entropy

00:33:09.790 --> 00:33:11.590 align:middle line:84%
transferred in a
heat interaction

00:33:11.590 --> 00:33:16.070 align:middle line:84%
is equal to the temperature
at which that transfer occurs.

00:33:16.070 --> 00:33:18.480 align:middle line:90%
OK.

00:33:18.480 --> 00:33:24.970 align:middle line:84%
Now the reservoir-- you can
write the fundamental relation

00:33:24.970 --> 00:33:29.140 align:middle line:90%
for the reservoir this way.

00:33:29.140 --> 00:33:38.140 align:middle line:90%


00:33:38.140 --> 00:33:42.190 align:middle line:84%
So you see why they
call it heat bath

00:33:42.190 --> 00:33:48.660 align:middle line:84%
because the heat reservoir
is ready to provide the heat

00:33:48.660 --> 00:33:49.720 align:middle line:90%
interaction.

00:33:49.720 --> 00:33:55.380 align:middle line:84%
If you extract energy
at its temperature,

00:33:55.380 --> 00:34:00.810 align:middle line:84%
then it provides also the
entropy and in the right

00:34:00.810 --> 00:34:03.840 align:middle line:84%
ratio so that you have a heat
interaction at the temperature

00:34:03.840 --> 00:34:06.170 align:middle line:90%
of the reservoir.

00:34:06.170 --> 00:34:12.350 align:middle line:84%
So it's a heat bath in the
sense that it can provide heat

00:34:12.350 --> 00:34:14.146 align:middle line:90%
so that at least justifies--

00:34:14.146 --> 00:34:16.650 align:middle line:90%


00:34:16.650 --> 00:34:18.929 align:middle line:90%
that's the reading of--

00:34:18.929 --> 00:34:22.659 align:middle line:84%
my justification
of that language.

00:34:22.659 --> 00:34:28.670 align:middle line:84%
It is not a reservoir of
heat, though in the sense

00:34:28.670 --> 00:34:35.100 align:middle line:84%
that heat is not
a form of energy.

00:34:35.100 --> 00:34:38.580 align:middle line:90%
It is a form of energy transfer.

00:34:38.580 --> 00:34:40.270 align:middle line:90%
You cannot store heat.

00:34:40.270 --> 00:34:42.360 align:middle line:90%
You store energy.

00:34:42.360 --> 00:34:42.860 align:middle line:90%
OK.

00:34:42.860 --> 00:34:45.810 align:middle line:84%
You transfer energy
in the form of heat

00:34:45.810 --> 00:34:49.159 align:middle line:84%
when you have an
interaction of that form.

00:34:49.159 --> 00:34:51.590 align:middle line:90%
So the language is important.

00:34:51.590 --> 00:34:55.380 align:middle line:84%
And loose language is OK if you
understand what you're doing.

00:34:55.380 --> 00:34:58.910 align:middle line:84%
If it is too loose
and if you assign

00:34:58.910 --> 00:35:02.910 align:middle line:84%
to this language too
popular a meaning,

00:35:02.910 --> 00:35:05.040 align:middle line:90%
then you get a lot of confusion.

00:35:05.040 --> 00:35:07.590 align:middle line:90%


00:35:07.590 --> 00:35:13.030 align:middle line:84%
This is why one
of our objectives

00:35:13.030 --> 00:35:17.565 align:middle line:84%
here is to try to be as careful
as possible with the language.

00:35:17.565 --> 00:35:21.800 align:middle line:90%


00:35:21.800 --> 00:35:29.060 align:middle line:84%
And by the way, my sincere
congratulations for how good

00:35:29.060 --> 00:35:31.440 align:middle line:90%
you're doing in your homeworks.

00:35:31.440 --> 00:35:36.587 align:middle line:90%


00:35:36.587 --> 00:35:37.087 align:middle line:90%
OK.

00:35:37.087 --> 00:35:39.769 align:middle line:90%


00:35:39.769 --> 00:35:46.450 align:middle line:90%
So the work that--

00:35:46.450 --> 00:35:48.710 align:middle line:84%
by solving this
system of equations,

00:35:48.710 --> 00:35:57.570 align:middle line:84%
we already said that we find an
expression for the work which

00:35:57.570 --> 00:36:00.150 align:middle line:84%
has a term related to
irreversibility-- entropy

00:36:00.150 --> 00:36:03.150 align:middle line:84%
produced by irreversibility,
which is not there

00:36:03.150 --> 00:36:04.870 align:middle line:90%
if the process is reversible.

00:36:04.870 --> 00:36:08.540 align:middle line:84%
And that's typically
the best you can do.

00:36:08.540 --> 00:36:18.500 align:middle line:84%
Whether you have to spend energy
or produce a mechanical energy,

00:36:18.500 --> 00:36:22.340 align:middle line:84%
you get the best always
when you do it reversibly.

00:36:22.340 --> 00:36:25.410 align:middle line:84%
So if you have to
extract energy,

00:36:25.410 --> 00:36:27.930 align:middle line:84%
if you can extract energy,
you extract the maximum

00:36:27.930 --> 00:36:29.700 align:middle line:84%
if you do the
reversible process.

00:36:29.700 --> 00:36:31.400 align:middle line:84%
If you have to spend
energy in order

00:36:31.400 --> 00:36:38.000 align:middle line:84%
to obtain a change of state, for
example, heating up some water,

00:36:38.000 --> 00:36:43.680 align:middle line:84%
that's a task that
requires spending energy,

00:36:43.680 --> 00:36:49.130 align:middle line:84%
you can ask yourself,
what is the minimum work

00:36:49.130 --> 00:36:58.190 align:middle line:84%
that you need to spend in
order to heat up that water.

00:36:58.190 --> 00:37:04.410 align:middle line:84%
And if you do that, maybe
when we do the next time

00:37:04.410 --> 00:37:13.300 align:middle line:84%
they review on
exergies, we'll see

00:37:13.300 --> 00:37:17.160 align:middle line:84%
how efficient are certain
ways we have to heat up water.

00:37:17.160 --> 00:37:22.790 align:middle line:90%


00:37:22.790 --> 00:37:24.848 align:middle line:90%
OK.

00:37:24.848 --> 00:37:26.870 align:middle line:84%
Now the maximum,
the reversible work,

00:37:26.870 --> 00:37:31.400 align:middle line:84%
is the difference between the
available energies of the two

00:37:31.400 --> 00:37:32.725 align:middle line:90%
states of your system.

00:37:32.725 --> 00:37:35.270 align:middle line:90%


00:37:35.270 --> 00:37:40.680 align:middle line:84%
It's also the difference in
this availability function gamma

00:37:40.680 --> 00:37:44.760 align:middle line:84%
that is energy minus entropy
multiplied by the temperature

00:37:44.760 --> 00:37:48.020 align:middle line:90%
of the reservoir.

00:37:48.020 --> 00:37:52.850 align:middle line:84%
We called it canonical
availability function.

00:37:52.850 --> 00:37:58.310 align:middle line:84%
And that we have seen that
if you try to represent it

00:37:58.310 --> 00:38:04.180 align:middle line:84%
graphically, it acquires
an absolute minimum

00:38:04.180 --> 00:38:05.880 align:middle line:84%
at the state in
which the system is

00:38:05.880 --> 00:38:09.270 align:middle line:84%
in mutual equilibrium
with the reservoir.

00:38:09.270 --> 00:38:17.080 align:middle line:84%
So by exploiting this idea
that this is a minimum,

00:38:17.080 --> 00:38:20.360 align:middle line:84%
we extract information
about, for example,

00:38:20.360 --> 00:38:31.710 align:middle line:84%
the concavity of the fundamental
relation by devising changes.

00:38:31.710 --> 00:38:34.690 align:middle line:84%
You start from this
mutual equilibrium state.

00:38:34.690 --> 00:38:39.840 align:middle line:84%
And you move
anywhere else in one

00:38:39.840 --> 00:38:44.850 align:middle line:84%
of the possible states of your
system A. Wherever you move,

00:38:44.850 --> 00:38:48.080 align:middle line:90%
gamma must increase.

00:38:48.080 --> 00:38:53.810 align:middle line:84%
And so, for example, we
chose a particular changes.

00:38:53.810 --> 00:38:57.830 align:middle line:84%
And we proved that with
those particular changes,

00:38:57.830 --> 00:39:02.840 align:middle line:84%
you can find that the
second differential

00:39:02.840 --> 00:39:14.030 align:middle line:84%
of the energy at fixed n and
V, second differential, so

00:39:14.030 --> 00:39:18.180 align:middle line:90%
the concavity here is positive.

00:39:18.180 --> 00:39:20.410 align:middle line:84%
You can view it also from
the other point of view.

00:39:20.410 --> 00:39:23.490 align:middle line:84%
So you find that the
second differential of S

00:39:23.490 --> 00:39:27.840 align:middle line:90%
at fixed V and n is negative.

00:39:27.840 --> 00:39:30.155 align:middle line:90%
OK.

00:39:30.155 --> 00:39:38.840 align:middle line:84%
Now, yeah, we also applied
that to prove that,

00:39:38.840 --> 00:39:40.790 align:middle line:90%
for example, the specific--

00:39:40.790 --> 00:39:45.036 align:middle line:84%
I mean the heat capacities
are non-negative.

00:39:45.036 --> 00:39:49.110 align:middle line:90%


00:39:49.110 --> 00:39:53.990 align:middle line:90%
And we proved the first part.

00:39:53.990 --> 00:39:57.140 align:middle line:84%
This is just the first
part of the theorem

00:39:57.140 --> 00:39:58.620 align:middle line:90%
by LeChatelier and Braun.

00:39:58.620 --> 00:40:01.960 align:middle line:90%


00:40:01.960 --> 00:40:06.230 align:middle line:84%
Today we'll do
also a second part,

00:40:06.230 --> 00:40:11.280 align:middle line:90%
which is even more interesting.

00:40:11.280 --> 00:40:16.620 align:middle line:84%
So the first part was,
anyway, that if you perturb

00:40:16.620 --> 00:40:19.710 align:middle line:84%
the state of your system,
which is initially

00:40:19.710 --> 00:40:21.990 align:middle line:84%
in mutual equilibrium
with the reservoir,

00:40:21.990 --> 00:40:25.080 align:middle line:84%
you put it off the
mutual equilibrium

00:40:25.080 --> 00:40:28.650 align:middle line:84%
by, for example, giving
energy, the system

00:40:28.650 --> 00:40:33.170 align:middle line:84%
will react by increasing
its temperature.

00:40:33.170 --> 00:40:36.560 align:middle line:84%
And the temperature, as we
know, is the escaping tendency

00:40:36.560 --> 00:40:37.290 align:middle line:90%
for energy.

00:40:37.290 --> 00:40:41.960 align:middle line:84%
So it increases its willingness
to give away energy.

00:40:41.960 --> 00:40:47.510 align:middle line:84%
And since the
reservoir is there,

00:40:47.510 --> 00:40:54.050 align:middle line:84%
the increasing in temperature
prepares for a heat interaction

00:40:54.050 --> 00:40:57.810 align:middle line:84%
in which the system gives
energy to the reservoir,

00:40:57.810 --> 00:41:03.810 align:middle line:84%
thereby contrasting the change
with which you took it away

00:41:03.810 --> 00:41:04.600 align:middle line:90%
from equilibrium.

00:41:04.600 --> 00:41:07.140 align:middle line:84%
It tries to spontaneously
return to equilibrium

00:41:07.140 --> 00:41:09.130 align:middle line:90%
by increasing its temperature.

00:41:09.130 --> 00:41:15.170 align:middle line:90%


00:41:15.170 --> 00:41:17.510 align:middle line:90%
So that's one thing.

00:41:17.510 --> 00:41:18.290 align:middle line:90%
All right.

00:41:18.290 --> 00:41:30.410 align:middle line:84%
So to see a little more, let's
broaden our class or category

00:41:30.410 --> 00:41:33.350 align:middle line:84%
of systems that we
call thermal reservoirs

00:41:33.350 --> 00:41:37.940 align:middle line:84%
or, say, heat baths
because, in practice,

00:41:37.940 --> 00:41:42.915 align:middle line:84%
we often have also reservoirs
that are variable volume.

00:41:42.915 --> 00:41:46.570 align:middle line:90%


00:41:46.570 --> 00:41:52.420 align:middle line:84%
Often, the atmosphere where
we live is the environment.

00:41:52.420 --> 00:41:55.860 align:middle line:84%
And it's something that would
accept a change in volume.

00:41:55.860 --> 00:42:01.060 align:middle line:90%


00:42:01.060 --> 00:42:04.810 align:middle line:84%
If the change in volume
is reasonably small

00:42:04.810 --> 00:42:09.880 align:middle line:84%
and also the changes in
energy are reasonably small,

00:42:09.880 --> 00:42:13.360 align:middle line:84%
you can add or subtract
the volume and energy

00:42:13.360 --> 00:42:15.910 align:middle line:84%
to the environment without
changing its temperature

00:42:15.910 --> 00:42:17.830 align:middle line:90%
and pressure.

00:42:17.830 --> 00:42:19.990 align:middle line:84%
So if the system
is large enough,

00:42:19.990 --> 00:42:25.630 align:middle line:84%
like the air in the
environment of a town,

00:42:25.630 --> 00:42:30.970 align:middle line:84%
or the water in the sea, or
in the lake, or in the river,

00:42:30.970 --> 00:42:33.230 align:middle line:90%
with respect to--

00:42:33.230 --> 00:42:34.900 align:middle line:84%
if it is large
enough with respect

00:42:34.900 --> 00:42:38.590 align:middle line:84%
to the amounts of energies,
entropies and volume

00:42:38.590 --> 00:42:42.250 align:middle line:84%
that you exchange, then
you may consider that

00:42:42.250 --> 00:42:46.630 align:middle line:84%
as a thermal
reservoir, so a system

00:42:46.630 --> 00:42:52.390 align:middle line:84%
that maintains fixed
values of the temperature

00:42:52.390 --> 00:42:53.290 align:middle line:90%
and the pressure.

00:42:53.290 --> 00:42:58.430 align:middle line:84%
In this case, we consider a
system which has variable volume

00:42:58.430 --> 00:43:02.260 align:middle line:90%
but still the amounts are fixed.

00:43:02.260 --> 00:43:07.270 align:middle line:84%
Then the fundamental
relation for a system

00:43:07.270 --> 00:43:15.850 align:middle line:90%
is also linear except that now--

00:43:15.850 --> 00:43:16.750 align:middle line:90%
OK.

00:43:16.750 --> 00:43:25.810 align:middle line:84%
Before we had energy, entropy,
and this is the temperature, TR.

00:43:25.810 --> 00:43:48.540 align:middle line:84%
Now we add volume as a
possibility to change then,

00:43:48.540 --> 00:43:59.880 align:middle line:84%
we have an equation of the
plane of which the slopes are

00:43:59.880 --> 00:44:05.430 align:middle line:84%
TR when you take the slope
at constant V and minus pR

00:44:05.430 --> 00:44:10.730 align:middle line:84%
when you take the
slope at constant S.

00:44:10.730 --> 00:44:13.080 align:middle line:84%
So this is the
equation of a plane.

00:44:13.080 --> 00:44:16.810 align:middle line:84%
And that's the
fundamental relation

00:44:16.810 --> 00:44:20.040 align:middle line:84%
for that thermal reservoir
at variable volume.

00:44:20.040 --> 00:44:25.600 align:middle line:90%


00:44:25.600 --> 00:44:27.210 align:middle line:90%
So we ask the same question now.

00:44:27.210 --> 00:44:27.730 align:middle line:90%
OK.

00:44:27.730 --> 00:44:33.960 align:middle line:84%
What if I'm changing
state for my system

00:44:33.960 --> 00:44:39.120 align:middle line:84%
but it exchanges volume
with the reservoir.

00:44:39.120 --> 00:44:42.800 align:middle line:84%
So maybe the system
changes also the volume.

00:44:42.800 --> 00:44:45.230 align:middle line:84%
And where does it
take that volume?

00:44:45.230 --> 00:44:48.530 align:middle line:90%
From the reservoir.

00:44:48.530 --> 00:44:49.760 align:middle line:90%
Or where does it give it?

00:44:49.760 --> 00:44:52.870 align:middle line:90%
To the reservoir.

00:44:52.870 --> 00:44:57.790 align:middle line:84%
You want to ask the maximum work
or the minimum work requirement

00:44:57.790 --> 00:44:59.590 align:middle line:90%
for doing that change.

00:44:59.590 --> 00:45:04.180 align:middle line:84%
Well, energy balance, entropy
balance, fundamental relation

00:45:04.180 --> 00:45:05.230 align:middle line:90%
for the reservoir.

00:45:05.230 --> 00:45:07.540 align:middle line:84%
And here you also have
to do a volume balance

00:45:07.540 --> 00:45:09.460 align:middle line:84%
because you have an
additional variable that

00:45:09.460 --> 00:45:15.450 align:middle line:84%
has to be kept fixed for
the composite system.

00:45:15.450 --> 00:45:19.870 align:middle line:84%
The overall volume
is conserved in order

00:45:19.870 --> 00:45:24.330 align:middle line:84%
to have no other external
effects like in a weight

00:45:24.330 --> 00:45:26.610 align:middle line:90%
process.

00:45:26.610 --> 00:45:29.250 align:middle line:90%
So when you do the--

00:45:29.250 --> 00:45:36.370 align:middle line:84%
when you solve this problem by
eliminating the variables that

00:45:36.370 --> 00:45:41.366 align:middle line:84%
relate to the reservoir,
here is the result.

00:45:41.366 --> 00:45:45.180 align:middle line:84%
It is almost like before
except that there is now

00:45:45.180 --> 00:45:50.160 align:middle line:84%
an extra term here, which is PR
times the difference in volume

00:45:50.160 --> 00:45:52.220 align:middle line:90%
of your system.

00:45:52.220 --> 00:45:56.180 align:middle line:84%
And again, it's
a reversible term

00:45:56.180 --> 00:46:01.470 align:middle line:84%
minus a term related
to irreversibility.

00:46:01.470 --> 00:46:06.850 align:middle line:90%


00:46:06.850 --> 00:46:09.340 align:middle line:84%
The reversible term can
be seen as the difference

00:46:09.340 --> 00:46:15.280 align:middle line:90%
in two properties.

00:46:15.280 --> 00:46:19.060 align:middle line:84%
You could consider this as a
definition of another property

00:46:19.060 --> 00:46:24.020 align:middle line:84%
that we still call,
for short of names,

00:46:24.020 --> 00:46:27.040 align:middle line:84%
available energy with respect
to that particular reservoir

00:46:27.040 --> 00:46:29.780 align:middle line:90%
at variable volume.

00:46:29.780 --> 00:46:36.350 align:middle line:84%
It's like the one before plus
this additional PR times delta

00:46:36.350 --> 00:46:40.340 align:middle line:84%
V. And also this
one, if you notice,

00:46:40.340 --> 00:46:46.160 align:middle line:84%
may be written as a difference
in an availability function

00:46:46.160 --> 00:46:53.300 align:middle line:84%
E minus TRS plus PRV, which
we are going to call just

00:46:53.300 --> 00:46:55.380 align:middle line:90%
with the name capital Psi.

00:46:55.380 --> 00:47:00.160 align:middle line:90%


00:47:00.160 --> 00:47:05.540 align:middle line:84%
And we may notice
that this is not--

00:47:05.540 --> 00:47:09.910 align:middle line:84%
that it looks like but it's
not the Gibbs free energy

00:47:09.910 --> 00:47:15.460 align:middle line:84%
except when the system is
in mutual equilibrium--

00:47:15.460 --> 00:47:16.960 align:middle line:84%
in the state of
mutual equilibrium

00:47:16.960 --> 00:47:18.530 align:middle line:90%
with the environment.

00:47:18.530 --> 00:47:24.770 align:middle line:84%
In that case, TR is also the
temperature of your system A

00:47:24.770 --> 00:47:27.410 align:middle line:84%
and therefore this is
the Gibbs free energy,

00:47:27.410 --> 00:47:36.680 align:middle line:84%
whereas in any other
state, this TR and this PR

00:47:36.680 --> 00:47:43.635 align:middle line:84%
may not be the temperature
of your system A.

00:47:43.635 --> 00:47:48.510 align:middle line:84%
And actually, if the state
is not an equilibrium state,

00:47:48.510 --> 00:47:52.790 align:middle line:84%
the system A might not even
have a temperature defined.

00:47:52.790 --> 00:47:56.570 align:middle line:84%
Actually, it does not if it
is not stable equilibrium.

00:47:56.570 --> 00:48:01.350 align:middle line:84%
Yet this availability
function is defined.

00:48:01.350 --> 00:48:05.160 align:middle line:84%
And it gives you these
answers to questions

00:48:05.160 --> 00:48:13.440 align:middle line:84%
of minimum or maximum
work to do or to obtain.

00:48:13.440 --> 00:48:20.320 align:middle line:90%


00:48:20.320 --> 00:48:21.870 align:middle line:90%
Yes.

00:48:21.870 --> 00:48:25.170 align:middle line:84%
Exactly with the same
procedure that we

00:48:25.170 --> 00:48:34.010 align:middle line:84%
have done to obtain these
conditions for the stability.

00:48:34.010 --> 00:48:36.200 align:middle line:90%
You can do it also here.

00:48:36.200 --> 00:48:41.710 align:middle line:84%
Now, since I have several
variables, it's not--

00:48:41.710 --> 00:48:42.210 align:middle line:90%
I'm sorry.

00:48:42.210 --> 00:48:44.060 align:middle line:90%
Let me go back one moment here.

00:48:44.060 --> 00:48:50.200 align:middle line:84%
So you should think
of a similar procedure

00:48:50.200 --> 00:48:54.100 align:middle line:84%
only in a
three-dimensional setup

00:48:54.100 --> 00:48:56.750 align:middle line:84%
in which you start from a
mutual equilibrium state

00:48:56.750 --> 00:49:01.800 align:middle line:90%
and you move away from it.

00:49:01.800 --> 00:49:04.050 align:middle line:84%
And then you apply the
condition that gamma

00:49:04.050 --> 00:49:07.820 align:middle line:90%
must increase if you move away.

00:49:07.820 --> 00:49:17.520 align:middle line:84%
Now whereas here you could
move away only on the S plane,

00:49:17.520 --> 00:49:25.240 align:middle line:84%
in the new setup, where also
the volume can be changed,

00:49:25.240 --> 00:49:31.210 align:middle line:84%
yes, you can move at
constant V or constant E,

00:49:31.210 --> 00:49:33.740 align:middle line:84%
but you can also move
in any other direction

00:49:33.740 --> 00:49:36.370 align:middle line:90%
so you have more choices.

00:49:36.370 --> 00:49:40.250 align:middle line:84%
And whatever choice
you make, you still

00:49:40.250 --> 00:49:46.325 align:middle line:84%
have to have this
property to increase.

00:49:46.325 --> 00:49:48.830 align:middle line:90%


00:49:48.830 --> 00:49:55.100 align:middle line:84%
So here, I'll let you, if you're
interested, watch the details.

00:49:55.100 --> 00:50:00.440 align:middle line:84%
I chose, for example,
to move by changing

00:50:00.440 --> 00:50:05.750 align:middle line:84%
the entropy and the volume,
keeping the n fixed.

00:50:05.750 --> 00:50:08.750 align:middle line:84%
And it turns out that when
you compute the change

00:50:08.750 --> 00:50:13.940 align:middle line:84%
in the variable Psi, it is
exactly equal to 1/2 the second

00:50:13.940 --> 00:50:21.120 align:middle line:84%
differential of E. And therefore
you prove that this is greater

00:50:21.120 --> 00:50:23.670 align:middle line:90%
than or equal to 0.

00:50:23.670 --> 00:50:27.180 align:middle line:84%
Or if I choose instead to
change the energy and the volume

00:50:27.180 --> 00:50:30.060 align:middle line:84%
and therefore-- and to move
along the stable equilibrium

00:50:30.060 --> 00:50:33.210 align:middle line:84%
state curve so that the
entropy is determined

00:50:33.210 --> 00:50:36.060 align:middle line:84%
by the fundamental
relation, then delta Psi

00:50:36.060 --> 00:50:39.420 align:middle line:84%
becomes equal to minus
the second differential

00:50:39.420 --> 00:50:41.810 align:middle line:90%
of the entropy.

00:50:41.810 --> 00:50:44.400 align:middle line:84%
And since that must
be greater than 0,

00:50:44.400 --> 00:50:53.140 align:middle line:84%
it gives again that the d2S
at fixed n (is negative).

00:50:53.140 --> 00:51:00.090 align:middle line:84%
Now this d2S if you
want to represent it,

00:51:00.090 --> 00:51:06.320 align:middle line:84%
it's not just the
second derivative

00:51:06.320 --> 00:51:14.070 align:middle line:84%
because you see when we have
d2S at constant V and n,

00:51:14.070 --> 00:51:18.600 align:middle line:84%
this was equal to the
second derivative of S

00:51:18.600 --> 00:51:23.670 align:middle line:84%
with respect to E
times dE squared.

00:51:23.670 --> 00:51:26.680 align:middle line:90%


00:51:26.680 --> 00:51:35.380 align:middle line:84%
But this other d2S at constant n
only, you can vary both E and V.

00:51:35.380 --> 00:51:40.330 align:middle line:84%
Then it's given by
d2S with respect

00:51:40.330 --> 00:51:50.470 align:middle line:84%
to E squared times dE squared
plus twice the second derivative

00:51:50.470 --> 00:51:54.970 align:middle line:84%
of S with respect to E and
with respect to V times

00:51:54.970 --> 00:52:01.090 align:middle line:84%
dE dV plus the
second with respect

00:52:01.090 --> 00:52:06.020 align:middle line:90%
to V twice times dV squared.

00:52:06.020 --> 00:52:09.850 align:middle line:84%
So it's a quadratic
form which you

00:52:09.850 --> 00:52:22.180 align:middle line:84%
can express also in this
form using matrices, dE dV.

00:52:22.180 --> 00:52:24.350 align:middle line:84%
Here, you put the
Hess determinant,

00:52:24.350 --> 00:52:28.610 align:middle line:84%
which is the determinant made
up of the second derivatives.

00:52:28.610 --> 00:52:37.665 align:middle line:90%


00:52:37.665 --> 00:52:41.260 align:middle line:90%
And this is equal.

00:52:41.260 --> 00:52:45.280 align:middle line:84%
And then you multiply this
by this other vector made up

00:52:45.280 --> 00:52:48.490 align:middle line:90%
of two elements dE and dV.

00:52:48.490 --> 00:52:51.550 align:middle line:84%
If you do matrix
multiplication of this--

00:52:51.550 --> 00:52:54.760 align:middle line:90%
let's be more elegant here--

00:52:54.760 --> 00:52:59.230 align:middle line:90%
you get the above result. OK.

00:52:59.230 --> 00:53:04.215 align:middle line:90%


00:53:04.215 --> 00:53:15.040 align:middle line:84%
And the fact that this has
to be negative for arbitrary

00:53:15.040 --> 00:53:22.590 align:middle line:84%
choice of your vector dE
dV, which means no matter

00:53:22.590 --> 00:53:27.930 align:middle line:84%
what direction you
want to move, this

00:53:27.930 --> 00:53:33.860 align:middle line:84%
has to be negative, that
requires that the matrix inside

00:53:33.860 --> 00:53:35.790 align:middle line:90%
be non-negative definite.

00:53:35.790 --> 00:53:39.470 align:middle line:90%


00:53:39.470 --> 00:53:44.220 align:middle line:84%
And the matrix is a
non-negative definite.

00:53:44.220 --> 00:53:44.720 align:middle line:90%
When?

00:53:44.720 --> 00:53:47.440 align:middle line:90%


00:53:47.440 --> 00:53:48.250 align:middle line:90%
Sorry.

00:53:48.250 --> 00:53:50.620 align:middle line:90%
Non-positive.

00:53:50.620 --> 00:53:53.880 align:middle line:90%
So it's negative semidefinite.

00:53:53.880 --> 00:53:55.660 align:middle line:90%
OK.

00:53:55.660 --> 00:53:56.515 align:middle line:90%
When is a matrix--

00:53:56.515 --> 00:54:01.420 align:middle line:90%


00:54:01.420 --> 00:54:02.630 align:middle line:90%
let's start with positive.

00:54:02.630 --> 00:54:05.009 align:middle line:84%
When is a matrix
positive definite?

00:54:05.009 --> 00:54:12.050 align:middle line:90%


00:54:12.050 --> 00:54:18.650 align:middle line:90%
I have a matrix a11, a12.

00:54:18.650 --> 00:54:20.790 align:middle line:90%
And let's make it symmetric.

00:54:20.790 --> 00:54:29.210 align:middle line:90%


00:54:29.210 --> 00:54:30.030 align:middle line:90%
OK.

00:54:30.030 --> 00:54:40.170 align:middle line:84%
So this, if it is
positive semi-definite,

00:54:40.170 --> 00:54:44.526 align:middle line:84%
the diagonal entries
must be non-negative.

00:54:44.526 --> 00:54:51.390 align:middle line:90%


00:54:51.390 --> 00:54:55.050 align:middle line:84%
The determinant must
be non-negative.

00:54:55.050 --> 00:55:01.650 align:middle line:84%
So a11 a22 minus a12
squared because it's

00:55:01.650 --> 00:55:05.930 align:middle line:84%
a symmetric must be
greater than or equal to 0.

00:55:05.930 --> 00:55:11.400 align:middle line:90%


00:55:11.400 --> 00:55:13.980 align:middle line:90%
You want to make it--

00:55:13.980 --> 00:55:18.050 align:middle line:84%
if the matrix, instead
of being positive

00:55:18.050 --> 00:55:20.800 align:middle line:84%
semi-definite is
negative semidefinite,

00:55:20.800 --> 00:55:28.580 align:middle line:84%
so this is less
than or equal to,

00:55:28.580 --> 00:55:38.190 align:middle line:84%
so the entries on the diagonal
should be non-positive.

00:55:38.190 --> 00:55:42.350 align:middle line:90%


00:55:42.350 --> 00:55:44.703 align:middle line:90%
How about the determinant?

00:55:44.703 --> 00:55:45.745 align:middle line:90%
Should I change the sign?

00:55:45.745 --> 00:55:50.190 align:middle line:90%


00:55:50.190 --> 00:55:58.980 align:middle line:84%
Not for a 2 by 2 matrix
because you see also,

00:55:58.980 --> 00:56:03.660 align:middle line:84%
the more fundamental
property of a non-negative--

00:56:03.660 --> 00:56:09.970 align:middle line:84%
of a non-positive-- of a
negative semi-definite matrix

00:56:09.970 --> 00:56:17.410 align:middle line:84%
is that its eigenvalues
are all negative.

00:56:17.410 --> 00:56:20.320 align:middle line:84%
So it means-- let's
call them lambda.

00:56:20.320 --> 00:56:23.980 align:middle line:90%
So lambda 1 is less than 0.

00:56:23.980 --> 00:56:25.905 align:middle line:90%
Lambda 2 is less than 0.

00:56:25.905 --> 00:56:33.110 align:middle line:90%


00:56:33.110 --> 00:56:37.670 align:middle line:84%
And for a 2 by 2
matrix, the determinant

00:56:37.670 --> 00:56:40.940 align:middle line:84%
is equal to the product
of the two eigenvalues.

00:56:40.940 --> 00:56:45.850 align:middle line:84%
So this is also equal to
lambda 1 times lambda 2.

00:56:45.850 --> 00:56:48.110 align:middle line:84%
So if you multiply
two negative numbers,

00:56:48.110 --> 00:56:49.370 align:middle line:90%
you get a positive number.

00:56:49.370 --> 00:56:54.620 align:middle line:84%
And so you get the determinant
is greater than zero.

00:56:54.620 --> 00:56:59.200 align:middle line:84%
If instead you had a 3
by 3 by 3 matrix, then

00:56:59.200 --> 00:57:01.900 align:middle line:84%
you have three
negative numbers that

00:57:01.900 --> 00:57:05.440 align:middle line:84%
multiply to give the
determinant in that case

00:57:05.440 --> 00:57:08.160 align:middle line:90%
with an odd number of entries.

00:57:08.160 --> 00:57:11.110 align:middle line:90%


00:57:11.110 --> 00:57:13.870 align:middle line:84%
Negative times negative times
negative makes negative.

00:57:13.870 --> 00:57:25.920 align:middle line:84%
So the determinant of a negative
semi-definite matrix is positive

00:57:25.920 --> 00:57:32.370 align:middle line:84%
for odd number of rows and
columns and negative for--

00:57:32.370 --> 00:57:33.660 align:middle line:90%
what did I say?

00:57:33.660 --> 00:57:37.930 align:middle line:84%
Positive for even number
and negative for odd number.

00:57:37.930 --> 00:57:38.430 align:middle line:90%
OK.

00:57:38.430 --> 00:57:45.110 align:middle line:90%


00:57:45.110 --> 00:57:47.770 align:middle line:84%
We'll need that
in a short while.

00:57:47.770 --> 00:57:52.380 align:middle line:90%


00:57:52.380 --> 00:57:53.890 align:middle line:90%
Here-- oh yeah.

00:57:53.890 --> 00:58:11.960 align:middle line:84%
Let me just go back to a
simple question about--

00:58:11.960 --> 00:58:15.910 align:middle line:90%


00:58:15.910 --> 00:58:16.410 align:middle line:90%
all right.

00:58:16.410 --> 00:58:22.530 align:middle line:90%
Suppose you have a vacuum.

00:58:22.530 --> 00:58:24.090 align:middle line:90%
So we have a piston.

00:58:24.090 --> 00:58:31.640 align:middle line:84%
You have a container in which
you manage to have nothing.

00:58:31.640 --> 00:58:32.150 align:middle line:90%
Vacuum.

00:58:32.150 --> 00:58:35.240 align:middle line:84%
Vacuum means no
particles, nothing.

00:58:35.240 --> 00:58:37.100 align:middle line:90%
OK.

00:58:37.100 --> 00:58:45.870 align:middle line:84%
So the question is,
is that a situation--

00:58:45.870 --> 00:58:51.270 align:middle line:84%
and this vacuum is in
an environment which

00:58:51.270 --> 00:59:01.130 align:middle line:84%
I can model as a reservoir at
pressure pR, also temperature TR

00:59:01.130 --> 00:59:05.970 align:middle line:84%
but the temperature doesn't
play much of a role here.

00:59:05.970 --> 00:59:10.110 align:middle line:84%
So it's like I have this
container in the environment

00:59:10.110 --> 00:59:11.250 align:middle line:90%
here.

00:59:11.250 --> 00:59:13.650 align:middle line:90%
I managed to make vacuum.

00:59:13.650 --> 00:59:17.240 align:middle line:84%
What's the minimum work
required to make that vacuum?

00:59:17.240 --> 00:59:19.980 align:middle line:90%


00:59:19.980 --> 00:59:23.770 align:middle line:84%
Or if I have that vacuum,
can I do something useful?

00:59:23.770 --> 00:59:25.410 align:middle line:90%
Can I lift a weight?

00:59:25.410 --> 00:59:27.755 align:middle line:90%
What's the maximum lift?

00:59:27.755 --> 00:59:33.820 align:middle line:90%


00:59:33.820 --> 00:59:37.800 align:middle line:84%
Well, let's apply
this formula here.

00:59:37.800 --> 00:59:43.250 align:middle line:90%


00:59:43.250 --> 00:59:46.830 align:middle line:84%
Assume that we do things
the best thermodynamic way.

00:59:46.830 --> 00:59:52.100 align:middle line:84%
So that means without generating
entropy by irreversibility.

00:59:52.100 --> 00:59:57.860 align:middle line:84%
And suppose I want my
initial state, state one.

00:59:57.860 --> 01:00:04.910 align:middle line:84%
So let me say that I started
with my piston down below here.

01:00:04.910 --> 01:00:13.620 align:middle line:84%
And this is my state 1 and
this is my state 2 and I pull.

01:00:13.620 --> 01:00:18.980 align:middle line:90%


01:00:18.980 --> 01:00:23.780 align:middle line:84%
Here I have the pressure
of the environment.

01:00:23.780 --> 01:00:29.620 align:middle line:84%
So if I pull, how much
work do I have to do?

01:00:29.620 --> 01:00:33.970 align:middle line:84%
I have to-- if you look
at the piston on one side,

01:00:33.970 --> 01:00:36.400 align:middle line:84%
you have zero pressure
because nothing here.

01:00:36.400 --> 01:00:37.805 align:middle line:90%
On the other side, you have PR.

01:00:37.805 --> 01:00:40.720 align:middle line:90%


01:00:40.720 --> 01:00:53.065 align:middle line:84%
So if the volume change is V2
minus V1, you can view that as--

01:00:53.065 --> 01:00:56.170 align:middle line:90%


01:00:56.170 --> 01:00:57.850 align:middle line:90%
let's call x this--

01:00:57.850 --> 01:01:00.470 align:middle line:90%


01:01:00.470 --> 01:01:00.970 align:middle line:90%
OK.

01:01:00.970 --> 01:01:05.350 align:middle line:84%
Let's go call z the
location of the weight--

01:01:05.350 --> 01:01:07.270 align:middle line:90%
I'm sorry, of the piston.

01:01:07.270 --> 01:01:11.445 align:middle line:84%
And let's call little a
the area of the piston.

01:01:11.445 --> 01:01:16.230 align:middle line:90%


01:01:16.230 --> 01:01:24.550 align:middle line:84%
So the force that
you have to apply

01:01:24.550 --> 01:01:28.630 align:middle line:90%
is equal to the pressure times--

01:01:28.630 --> 01:01:33.190 align:middle line:84%
which is force per unit
area times the area.

01:01:33.190 --> 01:01:36.860 align:middle line:90%
So that's the force.

01:01:36.860 --> 01:01:44.008 align:middle line:90%
The work is f times x.

01:01:44.008 --> 01:01:44.550 align:middle line:90%
I'm sorry. z.

01:01:44.550 --> 01:01:52.310 align:middle line:90%


01:01:52.310 --> 01:02:00.470 align:middle line:90%
So that's pR times a z.

01:02:00.470 --> 01:02:06.560 align:middle line:84%
But a z is the volume so that's
pR times V. But actually, it's

01:02:06.560 --> 01:02:13.270 align:middle line:84%
V2 minus V1 because
this is V2 and this is

01:02:13.270 --> 01:02:15.830 align:middle line:90%
V1 is equal to 0 in our case.

01:02:15.830 --> 01:02:25.300 align:middle line:84%
So it seems that
the work that you

01:02:25.300 --> 01:02:30.670 align:middle line:84%
need to spend in order to go
from 1 to 2 in a reversible way

01:02:30.670 --> 01:02:43.870 align:middle line:84%
is equal to that, which is
written here except that now it

01:02:43.870 --> 01:02:48.780 align:middle line:84%
has the wrong sign
because this represents

01:02:48.780 --> 01:02:54.330 align:middle line:84%
the work with the
arrow out instead

01:02:54.330 --> 01:02:56.680 align:middle line:84%
if we change the
direction of the arrow

01:02:56.680 --> 01:03:02.430 align:middle line:84%
so let's say that this is the
work that I need to spend.

01:03:02.430 --> 01:03:12.600 align:middle line:84%
And of course, this I could
also write the same thing

01:03:12.600 --> 01:03:14.040 align:middle line:90%
by changing the arrow.

01:03:14.040 --> 01:03:16.150 align:middle line:84%
If I change the arrow,
I change also the sign.

01:03:16.150 --> 01:03:21.120 align:middle line:90%


01:03:21.120 --> 01:03:26.010 align:middle line:84%
So essentially, the minimum work
required to produce the vacuum

01:03:26.010 --> 01:03:29.910 align:middle line:84%
is equal to the pressure of the
environment times the volume

01:03:29.910 --> 01:03:32.990 align:middle line:90%
of that vacuum.

01:03:32.990 --> 01:03:36.350 align:middle line:84%
That's an easy result.
We could have--

01:03:36.350 --> 01:03:38.750 align:middle line:84%
I mean, we actually
got to that result

01:03:38.750 --> 01:03:43.170 align:middle line:84%
without all the complicated
long story that we're telling.

01:03:43.170 --> 01:03:52.070 align:middle line:84%
But that's just to show the
consistency of this relation

01:03:52.070 --> 01:03:53.795 align:middle line:90%
with what we know.

01:03:53.795 --> 01:04:00.740 align:middle line:90%


01:04:00.740 --> 01:04:08.140 align:middle line:84%
So now let's think of
another kind of reservoir

01:04:08.140 --> 01:04:14.140 align:middle line:84%
which, again, can be
typically-- is a typical model

01:04:14.140 --> 01:04:21.696 align:middle line:84%
of the air in the environment
or some natural environment.

01:04:21.696 --> 01:04:24.990 align:middle line:90%


01:04:24.990 --> 01:04:27.030 align:middle line:84%
So here is a
particular reservoir

01:04:27.030 --> 01:04:31.240 align:middle line:84%
that can exchange through
a semi-permeable membrane

01:04:31.240 --> 01:04:35.270 align:middle line:84%
only one type of substance
with your system.

01:04:35.270 --> 01:04:41.000 align:middle line:84%
We may call it an osmotic
reservoir or a thermal reservoir

01:04:41.000 --> 01:04:47.670 align:middle line:84%
or we just don't give
any names but just

01:04:47.670 --> 01:04:52.600 align:middle line:90%
define it by just these words.

01:04:52.600 --> 01:04:54.510 align:middle line:90%
All right.

01:04:54.510 --> 01:04:57.190 align:middle line:84%
You run the same machinery,
energy balance, entropy,

01:04:57.190 --> 01:04:57.880 align:middle line:90%
balance.

01:04:57.880 --> 01:05:00.750 align:middle line:84%
Now you also have
to make a balance

01:05:00.750 --> 01:05:05.020 align:middle line:84%
for the amounts of constituents
of the kind of substance

01:05:05.020 --> 01:05:06.946 align:middle line:90%
that can be transferred.

01:05:06.946 --> 01:05:10.320 align:middle line:90%


01:05:10.320 --> 01:05:18.640 align:middle line:84%
For example, you may
be interested in--

01:05:18.640 --> 01:05:26.830 align:middle line:84%
some people are devising
methods or plans

01:05:26.830 --> 01:05:30.910 align:middle line:84%
that want to extract
CO2 from the atmosphere.

01:05:30.910 --> 01:05:31.410 align:middle line:90%
All right.

01:05:31.410 --> 01:05:35.450 align:middle line:84%
So you want to ask, well, what's
the minimum amount of work I

01:05:35.450 --> 01:05:43.500 align:middle line:84%
need to spend if I want to
extract CO2 from the atmosphere

01:05:43.500 --> 01:05:48.040 align:middle line:84%
because that minimum
defines the target.

01:05:48.040 --> 01:05:51.340 align:middle line:84%
Defines also the way
in which you determine

01:05:51.340 --> 01:05:54.880 align:middle line:84%
the efficiency, the
second law efficiency

01:05:54.880 --> 01:06:01.720 align:middle line:90%
of that particular equipment.

01:06:01.720 --> 01:06:04.360 align:middle line:84%
And it's a question
very similar to this one

01:06:04.360 --> 01:06:14.190 align:middle line:84%
because one way to do that, not
saying it's the reversible way,

01:06:14.190 --> 01:06:17.335 align:middle line:84%
but I'm saying that one way to
do it is first you do vacuum.

01:06:17.335 --> 01:06:20.100 align:middle line:90%


01:06:20.100 --> 01:06:27.400 align:middle line:84%
And then you open up the
permeability of the piston

01:06:27.400 --> 01:06:29.830 align:middle line:90%
to just CO2.

01:06:29.830 --> 01:06:34.370 align:middle line:84%
And so CO2 will
fill this region.

01:06:34.370 --> 01:06:39.490 align:middle line:84%
And you'll have just CO2
because the other parts,

01:06:39.490 --> 01:06:43.840 align:middle line:84%
oxygen and nitrogen, cannot
go through this particular

01:06:43.840 --> 01:06:45.650 align:middle line:90%
semi-permeable membrane.

01:06:45.650 --> 01:06:48.290 align:middle line:90%
And that way you have separated.

01:06:48.290 --> 01:06:51.630 align:middle line:90%
So one way is produce vacuum.

01:06:51.630 --> 01:06:54.893 align:middle line:84%
And we know how much
work it requires.

01:06:54.893 --> 01:06:57.430 align:middle line:90%


01:06:57.430 --> 01:07:02.970 align:middle line:84%
Use a semi-permeable membrane
and there you have your CO2.

01:07:02.970 --> 01:07:06.900 align:middle line:84%
Your CO2 eventually will
reach mutual equilibrium

01:07:06.900 --> 01:07:07.980 align:middle line:90%
with the reservoir.

01:07:07.980 --> 01:07:14.890 align:middle line:90%


01:07:14.890 --> 01:07:18.130 align:middle line:84%
At that stage, I have
blocked my piston.

01:07:18.130 --> 01:07:21.010 align:middle line:90%
Cannot go up and down.

01:07:21.010 --> 01:07:22.450 align:middle line:90%
And I change the reservoir.

01:07:22.450 --> 01:07:26.080 align:middle line:84%
Instead of having a
reservoir at variable volume,

01:07:26.080 --> 01:07:31.570 align:middle line:84%
I have a reservoir
that can exchange--

01:07:31.570 --> 01:07:37.110 align:middle line:84%
at constant chemical potential
of that substance, CO2.

01:07:37.110 --> 01:07:42.440 align:middle line:90%


01:07:42.440 --> 01:07:49.640 align:middle line:84%
The final state will be
that, instead of vacuum,

01:07:49.640 --> 01:07:52.710 align:middle line:90%
I will just have CO2 pure.

01:07:52.710 --> 01:07:56.950 align:middle line:84%
Let's say that this will
have a chemical potential

01:07:56.950 --> 01:08:01.920 align:middle line:90%
that we will call mu double i.

01:08:01.920 --> 01:08:05.010 align:middle line:84%
And it will have a
pressure that corresponds

01:08:05.010 --> 01:08:09.160 align:middle line:84%
to what we defined when they
are in mutual equilibrium,

01:08:09.160 --> 01:08:14.040 align:middle line:84%
equality of chemical potentials
defines the partial pressure.

01:08:14.040 --> 01:08:17.310 align:middle line:84%
So the CO2 will be at
the partial pressure

01:08:17.310 --> 01:08:23.850 align:middle line:84%
that it has in air
viewed as a mixture.

01:08:23.850 --> 01:08:24.350 align:middle line:90%
OK.

01:08:24.350 --> 01:08:27.000 align:middle line:90%


01:08:27.000 --> 01:08:31.830 align:middle line:84%
This second part of the process
from after I made the vacuum,

01:08:31.830 --> 01:08:36.380 align:middle line:84%
and I stopped the piston, and I
opened the pore, the second part

01:08:36.380 --> 01:08:43.399 align:middle line:84%
of the process is spontaneous
because, initially, you

01:08:43.399 --> 01:08:46.550 align:middle line:84%
are in a nonequilibrium
state because here you

01:08:46.550 --> 01:08:50.240 align:middle line:84%
have no CO2, whereas, in
order for equilibrium,

01:08:50.240 --> 01:08:52.830 align:middle line:84%
you need to have chemical
potentials to be equal.

01:08:52.830 --> 01:08:56.700 align:middle line:84%
So this is an
irreversible process.

01:08:56.700 --> 01:08:58.750 align:middle line:84%
There will be entropy
produced by reversibility.

01:08:58.750 --> 01:09:01.460 align:middle line:84%
So this is not the
best way to do it.

01:09:01.460 --> 01:09:05.640 align:middle line:84%
You could also evaluate
how much is the efficiency,

01:09:05.640 --> 01:09:10.220 align:middle line:84%
if you could compare it with
what's the minimum work that

01:09:10.220 --> 01:09:11.390 align:middle line:90%
is required.

01:09:11.390 --> 01:09:14.930 align:middle line:84%
And the minimum work
that is required

01:09:14.930 --> 01:09:18.609 align:middle line:84%
is given here by
this formula here.

01:09:18.609 --> 01:09:19.109 align:middle line:90%
I'm sorry.

01:09:19.109 --> 01:09:23.560 align:middle line:90%
By this formula here.

01:09:23.560 --> 01:09:30.950 align:middle line:84%
So there is, again, another
available energy function--

01:09:30.950 --> 01:09:35.520 align:middle line:84%
I'm sorry, available
energy property

01:09:35.520 --> 01:09:43.080 align:middle line:84%
for this particular kind
of osmotic reservoirs,

01:09:43.080 --> 01:09:45.479 align:middle line:84%
the difference of
which tells you

01:09:45.479 --> 01:09:51.800 align:middle line:84%
the minimum or the maximum works
for producing or exploiting

01:09:51.800 --> 01:09:53.160 align:middle line:90%
a situation.

01:09:53.160 --> 01:09:56.980 align:middle line:90%


01:09:56.980 --> 01:10:02.740 align:middle line:84%
So we will return later on to
this question of minimum work

01:10:02.740 --> 01:10:08.060 align:middle line:84%
for separating a substance
from, say, the atmosphere.

01:10:08.060 --> 01:10:12.240 align:middle line:90%


01:10:12.240 --> 01:10:16.350 align:middle line:84%
Here this combination
that appears

01:10:16.350 --> 01:10:21.330 align:middle line:84%
in the expression for this new
version of the available energy,

01:10:21.330 --> 01:10:26.550 align:middle line:84%
namely E minus TRS minus
the chemical potential times

01:10:26.550 --> 01:10:29.520 align:middle line:84%
the amount of that
substance that

01:10:29.520 --> 01:10:32.910 align:middle line:84%
can cross between the
system and the reservoir,

01:10:32.910 --> 01:10:39.570 align:middle line:84%
we may give it a name or not,
simply an availability function.

01:10:39.570 --> 01:10:42.630 align:middle line:84%
Maybe we could call it
osmotic availability function.

01:10:42.630 --> 01:10:46.620 align:middle line:84%
Maybe we could use this
letter or another letter.

01:10:46.620 --> 01:10:48.080 align:middle line:90%
It's just a matter of choice.

01:10:48.080 --> 01:10:54.210 align:middle line:90%


01:10:54.210 --> 01:10:59.830 align:middle line:84%
As for the other
availability functions,

01:10:59.830 --> 01:11:03.150 align:middle line:90%
there is also this minimum.

01:11:03.150 --> 01:11:10.200 align:middle line:84%
So also from this one, you
can derive by the same method

01:11:10.200 --> 01:11:15.380 align:middle line:84%
as before, same
procedure, conditions

01:11:15.380 --> 01:11:19.240 align:middle line:90%
for stability of equilibrium.

01:11:19.240 --> 01:11:21.470 align:middle line:84%
For the second
differential of the energy,

01:11:21.470 --> 01:11:27.560 align:middle line:84%
now it will be like
this but not with volume

01:11:27.560 --> 01:11:31.430 align:middle line:90%
but with n i that substitutes.

01:11:31.430 --> 01:11:38.610 align:middle line:84%
And that's the expression
for these second order

01:11:38.610 --> 01:11:39.760 align:middle line:90%
differentials.

01:11:39.760 --> 01:11:44.600 align:middle line:90%


01:11:44.600 --> 01:11:48.690 align:middle line:84%
And finally, we could
have a grand situation, so

01:11:48.690 --> 01:11:57.300 align:middle line:84%
a grand reservoir with
which your system can

01:11:57.300 --> 01:12:00.180 align:middle line:90%
exchange anything it wants--

01:12:00.180 --> 01:12:03.800 align:middle line:84%
amounts, volume,
energy, and entropy.

01:12:03.800 --> 01:12:06.387 align:middle line:90%


01:12:06.387 --> 01:12:06.887 align:middle line:90%
OK.

01:12:06.887 --> 01:12:09.869 align:middle line:90%


01:12:09.869 --> 01:12:12.660 align:middle line:84%
So you have to run again
the same machinery-- energy

01:12:12.660 --> 01:12:14.030 align:middle line:90%
balance, entropy, balance.

01:12:14.030 --> 01:12:17.060 align:middle line:84%
Fundamental relation
for the reservoir.

01:12:17.060 --> 01:12:19.230 align:middle line:84%
Notice that-- of course,
in the previous case,

01:12:19.230 --> 01:12:20.910 align:middle line:84%
maybe I didn't
emphasize it enough,

01:12:20.910 --> 01:12:24.590 align:middle line:84%
but what changes from
reservoir to reservoir

01:12:24.590 --> 01:12:28.460 align:middle line:84%
is the expression for the
fundamental relations.

01:12:28.460 --> 01:12:37.370 align:middle line:84%
These terms are new, peculiar
to this reservoir, that

01:12:37.370 --> 01:12:40.670 align:middle line:84%
acts as a reservoir not
only for exchanges of energy

01:12:40.670 --> 01:12:43.708 align:middle line:84%
and entropy but also for
if you change volume,

01:12:43.708 --> 01:12:45.000 align:middle line:90%
it doesn't change the pressure.

01:12:45.000 --> 01:12:46.790 align:middle line:84%
If you change the
amounts, it doesn't

01:12:46.790 --> 01:12:48.630 align:middle line:90%
change the chemical potentials.

01:12:48.630 --> 01:12:52.160 align:middle line:90%


01:12:52.160 --> 01:12:55.580 align:middle line:84%
And then you have
to remember also

01:12:55.580 --> 01:13:02.070 align:middle line:84%
to do the volume
balance and the balances

01:13:02.070 --> 01:13:06.820 align:middle line:84%
for all of the amounts of
the various constituents that

01:13:06.820 --> 01:13:08.690 align:middle line:90%
are conserved.

01:13:08.690 --> 01:13:10.045 align:middle line:90%
No chemical reactions here.

01:13:10.045 --> 01:13:14.600 align:middle line:90%


01:13:14.600 --> 01:13:22.470 align:middle line:84%
Again, eliminate the terms
that relate to the reservoir.

01:13:22.470 --> 01:13:24.380 align:middle line:84%
And you get this
expression, which

01:13:24.380 --> 01:13:29.560 align:middle line:84%
is another generalization of the
available energy with respect

01:13:29.560 --> 01:13:34.540 align:middle line:84%
to this completely
open reservoir.

01:13:34.540 --> 01:13:42.780 align:middle line:84%
And this is the available
energy, the expression,

01:13:42.780 --> 01:13:48.890 align:middle line:84%
which can also be written as
a difference in two values.

01:13:48.890 --> 01:13:51.920 align:middle line:84%
So the work, the maximum or
minimum, the reversible work

01:13:51.920 --> 01:13:56.630 align:middle line:84%
is the difference in the
values of this new availability

01:13:56.630 --> 01:13:59.570 align:middle line:84%
function, which I like to
call Euler availability

01:13:59.570 --> 01:14:01.400 align:middle line:84%
function for the
reason I already

01:14:01.400 --> 01:14:05.470 align:middle line:90%
explained the other time.

01:14:05.470 --> 01:14:11.120 align:middle line:84%
And that will be
also clear later on.

01:14:11.120 --> 01:14:16.800 align:middle line:84%
So this E minus TRS
plus PRV minus mu Rn.

01:14:16.800 --> 01:14:19.850 align:middle line:84%
This availability function
is defined for all states,

01:14:19.850 --> 01:14:22.080 align:middle line:90%
equilibrium and nonequilibrium.

01:14:22.080 --> 01:14:30.330 align:middle line:84%
When your system is
in mutual equilibrium,

01:14:30.330 --> 01:14:35.240 align:middle line:84%
so it is in the state at
temperature TR, pressure PR,

01:14:35.240 --> 01:14:38.620 align:middle line:84%
and with the chemical potential,
so complete equilibrium

01:14:38.620 --> 01:14:45.740 align:middle line:84%
between system and reservoir,
then this availability function

01:14:45.740 --> 01:14:48.920 align:middle line:84%
corresponds to that
characteristic function

01:14:48.920 --> 01:14:58.370 align:middle line:84%
that we call the Euler free
energy that I just reviewed

01:14:58.370 --> 01:15:01.190 align:middle line:90%
at the beginning of today.

01:15:01.190 --> 01:15:03.580 align:middle line:90%
OK.

01:15:03.580 --> 01:15:13.930 align:middle line:84%
And from this one, this also is
minimum at mutual equilibrium.

01:15:13.930 --> 01:15:17.480 align:middle line:90%


01:15:17.480 --> 01:15:25.830 align:middle line:84%
And you can do the
same again to extract

01:15:25.830 --> 01:15:29.930 align:middle line:90%
conditions for stability.

01:15:29.930 --> 01:15:36.850 align:middle line:84%
This time, this expression
d2E is with respect

01:15:36.850 --> 01:15:42.350 align:middle line:84%
not to just two
variables, so this matrix,

01:15:42.350 --> 01:15:44.970 align:middle line:84%
the Hess matrix will
not be just 2 by 2

01:15:44.970 --> 01:15:50.330 align:middle line:84%
but will be 2 plus r
because it also can

01:15:50.330 --> 01:15:51.980 align:middle line:90%
change all the constituents.

01:15:51.980 --> 01:15:57.830 align:middle line:84%
And if you have r constituents
is like 2 plus r by 2 plus r.

01:15:57.830 --> 01:16:04.570 align:middle line:84%
So it's this matrix that we have
already anticipated a while ago.

01:16:04.570 --> 01:16:09.690 align:middle line:90%
And this therefore proves--

01:16:09.690 --> 01:16:16.650 align:middle line:84%
I mean the details here
prove in more detail also

01:16:16.650 --> 01:16:18.886 align:middle line:84%
these expressions that
we had anticipated.

01:16:18.886 --> 01:16:22.730 align:middle line:90%


01:16:22.730 --> 01:16:23.920 align:middle line:90%
But you can also choose--

01:16:23.920 --> 01:16:27.270 align:middle line:90%


01:16:27.270 --> 01:16:33.450 align:middle line:84%
since now you-- think that you
are in a mutual equilibrium

01:16:33.450 --> 01:16:38.470 align:middle line:84%
state, and then you
can move your state

01:16:38.470 --> 01:16:41.680 align:middle line:90%
in various directions.

01:16:41.680 --> 01:16:53.610 align:middle line:84%
And one way is that you choose
another state that still

01:16:53.610 --> 01:16:56.770 align:middle line:84%
has the same temperature and
pressure of your reservoir

01:16:56.770 --> 01:16:59.940 align:middle line:90%
but you change the amounts.

01:16:59.940 --> 01:17:04.395 align:middle line:84%
So you choose to move away
from mutual equilibrium

01:17:04.395 --> 01:17:06.270 align:middle line:84%
because the conditions
for mutual equilibrium

01:17:06.270 --> 01:17:09.780 align:middle line:84%
with the reservoir not only
now that it can exchange not

01:17:09.780 --> 01:17:12.230 align:middle line:90%
only energy but also amounts.

01:17:12.230 --> 01:17:15.210 align:middle line:84%
It's not only the
temperature equality.

01:17:15.210 --> 01:17:17.610 align:middle line:84%
It's also the pressure
equality for the volume

01:17:17.610 --> 01:17:20.190 align:middle line:84%
change and the
chemical potentials,

01:17:20.190 --> 01:17:22.380 align:middle line:90%
all chemical potentials.

01:17:22.380 --> 01:17:26.250 align:middle line:84%
So I can move away
from mutual equilibrium

01:17:26.250 --> 01:17:29.460 align:middle line:84%
while keeping some of the
mutual equilibrium conditions

01:17:29.460 --> 01:17:32.760 align:middle line:84%
satisfied, like same
temperature and same pressure,

01:17:32.760 --> 01:17:34.760 align:middle line:90%
and moving only the amounts.

01:17:34.760 --> 01:17:37.690 align:middle line:90%


01:17:37.690 --> 01:17:43.240 align:middle line:84%
If you do that and move along
the stable equilibrium state

01:17:43.240 --> 01:17:50.820 align:middle line:84%
surface, constant
temperature and pressure,

01:17:50.820 --> 01:17:52.710 align:middle line:90%
the condition that delta--

01:17:52.710 --> 01:18:03.380 align:middle line:84%
that this Euler availability
function must increase along

01:18:03.380 --> 01:18:11.170 align:middle line:84%
that path turns out to be the
change in this variable Xi

01:18:11.170 --> 01:18:17.240 align:middle line:84%
is equal to the second
differential of the Gibbs

01:18:17.240 --> 01:18:17.910 align:middle line:90%
free energy.

01:18:17.910 --> 01:18:20.780 align:middle line:90%


01:18:20.780 --> 01:18:27.320 align:middle line:84%
You can prove it by remembering
that the Gibbs free energy is

01:18:27.320 --> 01:18:29.450 align:middle line:90%
E minus S minus TR.

01:18:29.450 --> 01:18:33.450 align:middle line:84%
And here TR and PR
remain constant.

01:18:33.450 --> 01:18:34.915 align:middle line:90%
So it remains defined.

01:18:34.915 --> 01:18:38.420 align:middle line:90%


01:18:38.420 --> 01:18:46.560 align:middle line:84%
So this proves that
the Gibbs free energy

01:18:46.560 --> 01:18:49.250 align:middle line:90%
has a minimum if you move--

01:18:49.250 --> 01:18:52.520 align:middle line:84%
so the second differential
is non-negative.

01:18:52.520 --> 01:18:53.020 align:middle line:90%
Yes.

01:18:53.020 --> 01:18:56.580 align:middle line:84%
It is non-negative if
you move at constant--

01:18:56.580 --> 01:19:06.370 align:middle line:84%
if you change the composition
at constant T and P.

01:19:06.370 --> 01:19:09.370 align:middle line:84%
If you keep only
temperature fixed

01:19:09.370 --> 01:19:13.460 align:middle line:84%
and change the volume instead of
keeping the pressure constant,

01:19:13.460 --> 01:19:16.190 align:middle line:90%
you get a similar relation.

01:19:16.190 --> 01:19:18.350 align:middle line:84%
This is not the
Gibbs free energy.

01:19:18.350 --> 01:19:30.460 align:middle line:84%
It's the Helmholtz free
energy at constant T.

01:19:30.460 --> 01:19:35.270 align:middle line:84%
So remember that
we have seen the--

01:19:35.270 --> 01:19:39.740 align:middle line:84%
that from these
conditions here, we

01:19:39.740 --> 01:19:43.730 align:middle line:84%
obtain a first part of the
LeChatelier-Braun principle.

01:19:43.730 --> 01:19:50.540 align:middle line:84%
Now, yes, another
little piece of math.

01:19:50.540 --> 01:19:51.655 align:middle line:90%
Sorry about that.

01:19:51.655 --> 01:19:55.470 align:middle line:90%


01:19:55.470 --> 01:19:57.960 align:middle line:84%
But that will get us to
the second part of the Le

01:19:57.960 --> 01:20:04.690 align:middle line:84%
Chatelier-Braun principle, which
is a more general statement

01:20:04.690 --> 01:20:14.695 align:middle line:84%
which requires a little brush
up or maybe first-time-you-see

01:20:14.695 --> 01:20:15.195 align:middle line:90%
math.

01:20:15.195 --> 01:20:22.050 align:middle line:90%


01:20:22.050 --> 01:20:27.400 align:middle line:84%
So let's say we have a
function of two variables.

01:20:27.400 --> 01:20:31.510 align:middle line:84%
I put also the other z here
just to say that the z's

01:20:31.510 --> 01:20:33.020 align:middle line:90%
are going to be constant.

01:20:33.020 --> 01:20:38.390 align:middle line:84%
So I have several variables but
I keep constant all except two

01:20:38.390 --> 01:20:40.990 align:middle line:90%
of them, which are x and y.

01:20:40.990 --> 01:20:45.510 align:middle line:90%


01:20:45.510 --> 01:20:47.410 align:middle line:84%
And then, for example,
I have that function.

01:20:47.410 --> 01:20:51.140 align:middle line:90%
I can write the differential.

01:20:51.140 --> 01:20:55.740 align:middle line:84%
So that's the partial of A
with respect to x times dx

01:20:55.740 --> 01:20:58.600 align:middle line:84%
plus the partial of A with
respect to y times dy.

01:20:58.600 --> 01:21:04.890 align:middle line:84%
I'm going to use the notation
comma x for partial with respect

01:21:04.890 --> 01:21:09.190 align:middle line:84%
to x, which is often
used in fluid mechanics

01:21:09.190 --> 01:21:12.830 align:middle line:84%
so maybe you've seen it
already or elsewhere.

01:21:12.830 --> 01:21:16.760 align:middle line:90%


01:21:16.760 --> 01:21:21.050 align:middle line:84%
And for example, comma double
x is the second derivative

01:21:21.050 --> 01:21:24.890 align:middle line:90%
with respect to x twice.

01:21:24.890 --> 01:21:28.520 align:middle line:84%
comma xy is the
derivative with respect

01:21:28.520 --> 01:21:30.660 align:middle line:90%
to x and with respect to y.

01:21:30.660 --> 01:21:34.660 align:middle line:90%


01:21:34.660 --> 01:21:36.720 align:middle line:90%
OK.

01:21:36.720 --> 01:21:41.130 align:middle line:84%
So this is the partial
derivative with respect to x.

01:21:41.130 --> 01:21:46.170 align:middle line:84%
And here is the full glory
of the representation

01:21:46.170 --> 01:21:50.680 align:middle line:84%
of the derivatives where these
subscripts, as you remember,

01:21:50.680 --> 01:21:56.630 align:middle line:84%
mean the other variables
of the original function

01:21:56.630 --> 01:21:59.980 align:middle line:84%
that you're taking the
partial derivative of.

01:21:59.980 --> 01:22:00.480 align:middle line:90%
OK.

01:22:00.480 --> 01:22:02.440 align:middle line:90%
Good.

01:22:02.440 --> 01:22:08.410 align:middle line:84%
Then we have, like we've
seen there for d2S,

01:22:08.410 --> 01:22:15.980 align:middle line:84%
here's d2 of this
variable A. Can think of S

01:22:15.980 --> 01:22:19.240 align:middle line:84%
but it could be also others
like the Gibbs free energy,

01:22:19.240 --> 01:22:22.080 align:middle line:84%
or the Helmholtz free
energy, or whatever you need.

01:22:22.080 --> 01:22:26.050 align:middle line:90%


01:22:26.050 --> 01:22:29.290 align:middle line:84%
And this is the
quadratic form that

01:22:29.290 --> 01:22:37.780 align:middle line:84%
represents the explicit form
of the second differential.

01:22:37.780 --> 01:22:38.390 align:middle line:90%
OK.

01:22:38.390 --> 01:22:41.980 align:middle line:84%
So now that we have
a quadratic form,

01:22:41.980 --> 01:22:48.040 align:middle line:84%
the trick is to put it in
the so-called canonical form

01:22:48.040 --> 01:22:53.480 align:middle line:84%
because, you see, this quadratic
form has a square here,

01:22:53.480 --> 01:22:58.060 align:middle line:84%
a square there, and then
it has a product dx dy.

01:22:58.060 --> 01:23:01.410 align:middle line:84%
This doesn't have
a definite sign.

01:23:01.410 --> 01:23:04.190 align:middle line:90%


01:23:04.190 --> 01:23:10.010 align:middle line:84%
But let's try to rewrite
this quadratic form

01:23:10.010 --> 01:23:15.000 align:middle line:84%
into a form in which you
have something squared

01:23:15.000 --> 01:23:18.020 align:middle line:90%
and dy squared.

01:23:18.020 --> 01:23:22.340 align:middle line:84%
So a combination of
dx and dy, if you

01:23:22.340 --> 01:23:25.880 align:middle line:84%
choose the proper
combination of dx and dy--

01:23:25.880 --> 01:23:27.680 align:middle line:84%
and this is the
proper combination.

01:23:27.680 --> 01:23:29.520 align:middle line:84%
I've already built
in the answer.

01:23:29.520 --> 01:23:33.070 align:middle line:84%
So if you want to check
it, you just substitute.

01:23:33.070 --> 01:23:37.510 align:middle line:84%
If you take this
expression and work it out,

01:23:37.510 --> 01:23:41.025 align:middle line:84%
you will prove to yourself that
it's equivalent to that one.

01:23:41.025 --> 01:23:44.960 align:middle line:90%


01:23:44.960 --> 01:23:46.910 align:middle line:84%
And this ratio, this
coefficient here

01:23:46.910 --> 01:23:51.140 align:middle line:84%
is the ratio of the
second derivative

01:23:51.140 --> 01:23:54.170 align:middle line:84%
with respect to xy divided
by the second derivative

01:23:54.170 --> 01:23:54.980 align:middle line:90%
with respect to xx.

01:23:54.980 --> 01:23:59.730 align:middle line:90%


01:23:59.730 --> 01:24:03.790 align:middle line:84%
And then if you
substitute, by comparison

01:24:03.790 --> 01:24:07.140 align:middle line:84%
you find that what you need to
put in front of the dy squared

01:24:07.140 --> 01:24:10.470 align:middle line:90%
is this lambda, which is not--

01:24:10.470 --> 01:24:12.550 align:middle line:90%
sorry that I used lambda here.

01:24:12.550 --> 01:24:13.686 align:middle line:90%
It's not the eigenvalues.

01:24:13.686 --> 01:24:17.660 align:middle line:90%


01:24:17.660 --> 01:24:23.400 align:middle line:84%
But this lambda is given
by this expression.

01:24:23.400 --> 01:24:27.450 align:middle line:90%
Again, in terms of the original.

01:24:27.450 --> 01:24:31.890 align:middle line:84%
You can do it in this way,
where in your summation,

01:24:31.890 --> 01:24:33.780 align:middle line:90%
you keep the square of--

01:24:33.780 --> 01:24:37.660 align:middle line:84%
dy squared, or you can do
it also in this other way.

01:24:37.660 --> 01:24:41.370 align:middle line:84%
This is another canonical form
in which you keep dx squared.

01:24:41.370 --> 01:24:45.910 align:middle line:90%
They are two equivalent ways.

01:24:45.910 --> 01:24:47.830 align:middle line:84%
Of course, here the
lambda is different

01:24:47.830 --> 01:24:49.785 align:middle line:84%
and the lambda x is
given by this one.

01:24:49.785 --> 01:24:52.760 align:middle line:90%


01:24:52.760 --> 01:24:54.444 align:middle line:90%
OK.

01:24:54.444 --> 01:25:00.520 align:middle line:90%
Now do I have more space?

01:25:00.520 --> 01:25:07.490 align:middle line:90%


01:25:07.490 --> 01:25:12.230 align:middle line:90%
Now let's look at--

01:25:12.230 --> 01:25:16.790 align:middle line:84%
suppose that our
function A is such

01:25:16.790 --> 01:25:23.040 align:middle line:84%
that its second differential
must be positive.

01:25:23.040 --> 01:25:26.020 align:middle line:90%
OK.

01:25:26.020 --> 01:25:34.810 align:middle line:84%
So positive means that this
matrix is positive definite

01:25:34.810 --> 01:25:38.500 align:middle line:90%
or semidefinite.

01:25:38.500 --> 01:25:40.960 align:middle line:90%
And as we remember--

01:25:40.960 --> 01:25:42.220 align:middle line:90%
yeah.

01:25:42.220 --> 01:25:44.290 align:middle line:90%
I took away the wrong.

01:25:44.290 --> 01:25:53.650 align:middle line:84%
So if we remember, positive
definite for a matrix

01:25:53.650 --> 01:25:59.460 align:middle line:84%
implies all these things are
positive or non-negative.

01:25:59.460 --> 01:26:07.620 align:middle line:90%


01:26:07.620 --> 01:26:14.110 align:middle line:84%
So we have to have that A
xx is greater than zero.

01:26:14.110 --> 01:26:16.280 align:middle line:84%
And in fact, here is
just what I have written.

01:26:16.280 --> 01:26:20.200 align:middle line:90%
A xx is greater than 0--

01:26:20.200 --> 01:26:22.990 align:middle line:84%
is greater than something
else and greater than zero.

01:26:22.990 --> 01:26:25.575 align:middle line:84%
And also A yy is
greater than zero.

01:26:25.575 --> 01:26:29.330 align:middle line:90%


01:26:29.330 --> 01:26:35.450 align:middle line:84%
But here we have written also
something more strong than that.

01:26:35.450 --> 01:26:43.400 align:middle line:84%
We have written that A xx or
A yy is greater than lambda.

01:26:43.400 --> 01:26:44.190 align:middle line:90%
Let's see.

01:26:44.190 --> 01:26:47.730 align:middle line:90%


01:26:47.730 --> 01:27:00.550 align:middle line:84%
The lambda-- for
example, lambda y--

01:27:00.550 --> 01:27:04.950 align:middle line:90%


01:27:04.950 --> 01:27:07.830 align:middle line:90%
let me rewrite it this way.

01:27:07.830 --> 01:27:22.650 align:middle line:84%
It has at the denominator A xx
squared and at the numerator

01:27:22.650 --> 01:27:34.290 align:middle line:84%
A xx times A yy
minus A xy squared.

01:27:34.290 --> 01:27:43.350 align:middle line:84%
That is the determinant of the
Hess matrix, that numerator.

01:27:43.350 --> 01:27:51.820 align:middle line:90%


01:27:51.820 --> 01:27:58.160 align:middle line:84%
So since the matrix is positive,
the numerator is positive,

01:27:58.160 --> 01:28:03.120 align:middle line:84%
the denominator is positive,
so this is also positive.

01:28:03.120 --> 01:28:03.620 align:middle line:90%
OK.

01:28:03.620 --> 01:28:06.870 align:middle line:90%


01:28:06.870 --> 01:28:08.680 align:middle line:90%
So this explains why lambda--

01:28:08.680 --> 01:28:12.140 align:middle line:90%


01:28:12.140 --> 01:28:16.710 align:middle line:84%
you can do that for
y, but also for x.

01:28:16.710 --> 01:28:22.310 align:middle line:84%
The lambdas are
also non-negative.

01:28:22.310 --> 01:28:28.010 align:middle line:84%
And now you can also
see here why lambda--

01:28:28.010 --> 01:28:35.970 align:middle line:84%
for example, lambda y is smaller
than A yy because look here.

01:28:35.970 --> 01:28:36.720 align:middle line:90%
This is lambda.

01:28:36.720 --> 01:28:40.820 align:middle line:84%
This is A. And then you
subtract something positive.

01:28:40.820 --> 01:28:44.310 align:middle line:84%
So if from A you subtract
something positive,

01:28:44.310 --> 01:28:50.940 align:middle line:84%
it means that lambda
is smaller than A yy.

01:28:50.940 --> 01:28:53.680 align:middle line:90%
OK.

01:28:53.680 --> 01:28:54.180 align:middle line:90%
All right.

01:28:54.180 --> 01:29:05.540 align:middle line:84%
So this is the mathematics
that stands behind the Le

01:29:05.540 --> 01:29:09.410 align:middle line:84%
Chatelier-Braun principle that
we are going to do in a second.

01:29:09.410 --> 01:29:11.810 align:middle line:84%
Of course, you can
do exactly the same

01:29:11.810 --> 01:29:16.360 align:middle line:84%
that I've done here for
positive semidefinite.

01:29:16.360 --> 01:29:19.740 align:middle line:84%
You can also do it for
negative semidefinite.

01:29:19.740 --> 01:29:23.660 align:middle line:90%


01:29:23.660 --> 01:29:24.160 align:middle line:90%
OK.

01:29:24.160 --> 01:29:46.336 align:middle line:90%


01:29:46.336 --> 01:29:56.140 align:middle line:84%
These steps help understanding
the various steps

01:29:56.140 --> 01:29:58.830 align:middle line:90%
on the previous slide.

01:29:58.830 --> 01:30:02.850 align:middle line:90%


01:30:02.850 --> 01:30:14.130 align:middle line:84%
And the bottom line is here, you
can rewrite that A double x--

01:30:14.130 --> 01:30:17.280 align:middle line:90%


01:30:17.280 --> 01:30:20.990 align:middle line:84%
this is equal to the partial
of A (with respect to)

01:30:20.990 --> 01:30:27.960 align:middle line:84%
x, which is the conjugate
potential to variable x.

01:30:27.960 --> 01:30:33.490 align:middle line:90%
So yeah.

01:30:33.490 --> 01:30:45.070 align:middle line:84%
So suppose our function is S.
And S is a function of energy.

01:30:45.070 --> 01:30:48.880 align:middle line:84%
And so S EE, which
is the equivalent--

01:30:48.880 --> 01:30:53.440 align:middle line:84%
so our function is the
entropy and the x variable

01:30:53.440 --> 01:30:54.610 align:middle line:90%
is the energy.

01:30:54.610 --> 01:31:00.940 align:middle line:84%
So S EE means partial of
S with respect to E twice.

01:31:00.940 --> 01:31:11.820 align:middle line:84%
But since the partial of S
with respect to E is 1 over T,

01:31:11.820 --> 01:31:13.740 align:middle line:90%
this is equivalent also to--

01:31:13.740 --> 01:31:20.040 align:middle line:84%
you can write it
as S comma E, which

01:31:20.040 --> 01:31:29.970 align:middle line:84%
is the inverse of the
temperature, again comma E.

01:31:29.970 --> 01:31:35.060 align:middle line:84%
And of course, you can do
also the other like that.

01:31:35.060 --> 01:31:39.980 align:middle line:84%
So this is the meaning of
partial of A comma x, again

01:31:39.980 --> 01:31:42.705 align:middle line:90%
comma x, done at constant y.

01:31:42.705 --> 01:31:46.710 align:middle line:90%


01:31:46.710 --> 01:31:57.740 align:middle line:84%
The point is that, by doing this
math here that I want to skip,

01:31:57.740 --> 01:32:02.040 align:middle line:84%
I prove that the lambda
also, the lambdas can

01:32:02.040 --> 01:32:08.640 align:middle line:84%
be written as partials
of these potentials--

01:32:08.640 --> 01:32:10.320 align:middle line:84%
so of the first
derivative with respect

01:32:10.320 --> 01:32:14.580 align:middle line:84%
to x but not while
keeping constant y

01:32:14.580 --> 01:32:22.790 align:middle line:84%
but while keeping constant the
other potential conjugated to y.

01:32:22.790 --> 01:32:29.600 align:middle line:84%
So what changes in these two
terms is what is kept constant.

01:32:29.600 --> 01:32:31.350 align:middle line:90%
Here I keep constant y.

01:32:31.350 --> 01:32:37.400 align:middle line:84%
Here I keep constant the
potential conjugated to y.

01:32:37.400 --> 01:32:52.130 align:middle line:84%
And that's the key to the
practical consequences

01:32:52.130 --> 01:32:54.200 align:middle line:90%
of this mathematics.

01:32:54.200 --> 01:33:00.130 align:middle line:84%
So for example, let's
change once more variables

01:33:00.130 --> 01:33:02.940 align:middle line:84%
so that we get
even more confused.

01:33:02.940 --> 01:33:07.260 align:middle line:84%
But we just have five
minutes so it's OK.

01:33:07.260 --> 01:33:13.390 align:middle line:84%
So we start from the function E
from this fundamental relation,

01:33:13.390 --> 01:33:16.710 align:middle line:84%
this form of the
fundamental relation.

01:33:16.710 --> 01:33:19.440 align:middle line:84%
Keep the n fixed
and look at what

01:33:19.440 --> 01:33:21.995 align:middle line:84%
happens by applying
what we've just seen.

01:33:21.995 --> 01:33:26.910 align:middle line:90%


01:33:26.910 --> 01:33:30.210 align:middle line:84%
This is the train
of inequalities

01:33:30.210 --> 01:33:35.300 align:middle line:84%
that is implied by one of
the forms, by this form,

01:33:35.300 --> 01:33:41.440 align:middle line:84%
and by the second
form is written here.

01:33:41.440 --> 01:33:44.480 align:middle line:90%
You can do the substitutions.

01:33:44.480 --> 01:33:47.110 align:middle line:84%
You see I put here what
the variable x and y

01:33:47.110 --> 01:33:51.460 align:middle line:84%
is, what A sub x, A sub y, the
temperature and the pressure

01:33:51.460 --> 01:33:52.990 align:middle line:90%
in our case.

01:33:52.990 --> 01:33:58.390 align:middle line:84%
And here is the result.
Now, by the way,

01:33:58.390 --> 01:34:02.430 align:middle line:84%
by looking at these derivatives,
you find old friends.

01:34:02.430 --> 01:34:06.180 align:middle line:84%
And you can see that, for
example, you can rewrite this

01:34:06.180 --> 01:34:11.070 align:middle line:84%
as CP is greater than
or equal to CV, which

01:34:11.070 --> 01:34:17.600 align:middle line:84%
is greater than or equal to 0,
or that one, the compressibility

01:34:17.600 --> 01:34:20.060 align:middle line:84%
at constant temperature is
greater than the compressibility

01:34:20.060 --> 01:34:22.940 align:middle line:90%
at constant entropy.

01:34:22.940 --> 01:34:29.745 align:middle line:84%
So what's the reading that
Le Chatelier-Brown does?

01:34:29.745 --> 01:34:32.880 align:middle line:90%


01:34:32.880 --> 01:34:38.370 align:middle line:84%
What's the difference here
between these two derivatives?

01:34:38.370 --> 01:34:43.080 align:middle line:90%
It is what is kept constant.

01:34:43.080 --> 01:34:49.830 align:middle line:84%
I change the entropy and measure
what temperature change occurs

01:34:49.830 --> 01:34:54.740 align:middle line:84%
when I keep volume or when
I keep pressure fixed.

01:34:54.740 --> 01:34:59.260 align:middle line:90%


01:34:59.260 --> 01:35:06.170 align:middle line:84%
You see, volume is
the original variable.

01:35:06.170 --> 01:35:11.330 align:middle line:84%
Pressure is the
conjugated potential.

01:35:11.330 --> 01:35:17.130 align:middle line:84%
It has to do with the tendency
to escape, to gain volume.

01:35:17.130 --> 01:35:19.375 align:middle line:84%
So minus pressure is the
tendency to yield volume.

01:35:19.375 --> 01:35:23.270 align:middle line:90%


01:35:23.270 --> 01:35:26.870 align:middle line:84%
So the idea is that
the interpretation

01:35:26.870 --> 01:35:28.700 align:middle line:84%
of these derivatives
being positive

01:35:28.700 --> 01:35:34.340 align:middle line:84%
is that the system reacts
if you move it away

01:35:34.340 --> 01:35:38.500 align:middle line:84%
from the mutual equilibrium
state of the environment.

01:35:38.500 --> 01:35:41.160 align:middle line:84%
If you add some
entropy, for example,

01:35:41.160 --> 01:35:44.150 align:middle line:84%
it will increase
its temperature--

01:35:44.150 --> 01:35:53.860 align:middle line:84%
this is positive-- so as
to increase its tendency

01:35:53.860 --> 01:36:00.520 align:middle line:84%
to return energy to contrast
your change by giving energy

01:36:00.520 --> 01:36:02.090 align:middle line:90%
away to your environment.

01:36:02.090 --> 01:36:07.030 align:middle line:84%
So the system responds by trying
to spontaneously reestablish

01:36:07.030 --> 01:36:08.940 align:middle line:90%
equilibrium.

01:36:08.940 --> 01:36:16.150 align:middle line:84%
But it does more so if you
do it at constant volume

01:36:16.150 --> 01:36:18.740 align:middle line:84%
than if you do it at
constant pressure.

01:36:18.740 --> 01:36:26.198 align:middle line:84%
So the reaction of the
system is stronger if what?

01:36:26.198 --> 01:36:27.240 align:middle line:90%
So what's the difference?

01:36:27.240 --> 01:36:31.970 align:middle line:84%
The difference is that, here,
the system has a smaller

01:36:31.970 --> 01:36:35.820 align:middle line:90%
reaction if you keep--

01:36:35.820 --> 01:36:41.670 align:middle line:84%
keeping the pressure constant
means keeping your system

01:36:41.670 --> 01:36:43.600 align:middle line:84%
in equilibrium
with your reservoir

01:36:43.600 --> 01:36:48.630 align:middle line:84%
at least as for the condition
that requires pressure equality.

01:36:48.630 --> 01:36:50.610 align:middle line:84%
So you're not touching
that condition

01:36:50.610 --> 01:36:51.570 align:middle line:90%
for mutual equilibrium.

01:36:51.570 --> 01:36:53.530 align:middle line:84%
You're touching
only something else.

01:36:53.530 --> 01:36:56.830 align:middle line:84%
So if you do it there,
the system says,

01:36:56.830 --> 01:37:00.780 align:middle line:84%
all right, well, after all,
you're moving me away but not so

01:37:00.780 --> 01:37:03.660 align:middle line:90%
much so its reaction is softer.

01:37:03.660 --> 01:37:07.500 align:middle line:84%
If you move it away so that
also its pressure changes

01:37:07.500 --> 01:37:11.520 align:middle line:84%
and therefore like you do when
you keep the volume constant,

01:37:11.520 --> 01:37:18.990 align:middle line:90%
then it will increase not only--

01:37:18.990 --> 01:37:22.830 align:middle line:84%
so essentially, you are
touching two conditions

01:37:22.830 --> 01:37:25.800 align:middle line:84%
of mutual equilibrium, touching
equality of temperature

01:37:25.800 --> 01:37:27.760 align:middle line:84%
and touching
equality of pressure.

01:37:27.760 --> 01:37:31.820 align:middle line:84%
And therefore the
system reacts stronger.

01:37:31.820 --> 01:37:35.490 align:middle line:84%
Wants more to come
back to equilibrium.

01:37:35.490 --> 01:37:38.270 align:middle line:90%


01:37:38.270 --> 01:37:44.830 align:middle line:90%
This is the-- this is the idea.

01:37:44.830 --> 01:37:48.120 align:middle line:90%
And since I wanted to--

01:37:48.120 --> 01:37:50.010 align:middle line:90%
give me two more minutes.

01:37:50.010 --> 01:37:56.330 align:middle line:84%
I wanted to show you
the application here.

01:37:56.330 --> 01:37:59.100 align:middle line:90%
This is an air spring.

01:37:59.100 --> 01:38:02.920 align:middle line:84%
So it's a piston
with air inside.

01:38:02.920 --> 01:38:06.940 align:middle line:84%
And it acts like a
standard mechanical spring.

01:38:06.940 --> 01:38:08.745 align:middle line:84%
You can compute the
spring constant.

01:38:08.745 --> 01:38:11.940 align:middle line:90%


01:38:11.940 --> 01:38:13.090 align:middle line:90%
Here are the details.

01:38:13.090 --> 01:38:17.735 align:middle line:84%
It's kind of easy mechanical
engineering, so to speak.

01:38:17.735 --> 01:38:22.350 align:middle line:90%


01:38:22.350 --> 01:38:28.740 align:middle line:84%
This k is the spring
constant that relates,

01:38:28.740 --> 01:38:34.650 align:middle line:84%
the increasing reaction
or force of your spring

01:38:34.650 --> 01:38:39.710 align:middle line:90%
to a change in its compression.

01:38:39.710 --> 01:38:42.410 align:middle line:90%


01:38:42.410 --> 01:38:45.650 align:middle line:84%
And this is also a
similar situation.

01:38:45.650 --> 01:38:48.480 align:middle line:90%
This acts as a spring.

01:38:48.480 --> 01:38:53.530 align:middle line:84%
And you can compute
the dF over dx.

01:38:53.530 --> 01:38:59.170 align:middle line:84%
And if you go down here, you
see it's related to how much

01:38:59.170 --> 01:39:03.950 align:middle line:84%
the area, little a, of
the piston, the volume.

01:39:03.950 --> 01:39:05.840 align:middle line:84%
And this thing at
the denominator

01:39:05.840 --> 01:39:07.380 align:middle line:90%
is the compressibility.

01:39:07.380 --> 01:39:10.500 align:middle line:90%


01:39:10.500 --> 01:39:12.240 align:middle line:90%
So you could have--

01:39:12.240 --> 01:39:17.590 align:middle line:84%
so if you act your
spring while keeping

01:39:17.590 --> 01:39:21.790 align:middle line:84%
the temperature constant--
so if your spring is

01:39:21.790 --> 01:39:26.630 align:middle line:84%
in contact with the thermal
reservoir and therefore,

01:39:26.630 --> 01:39:28.360 align:middle line:84%
it has the time
to exchange energy

01:39:28.360 --> 01:39:33.650 align:middle line:84%
to remain in mutual equilibrium,
which typically is when you

01:39:33.650 --> 01:39:37.790 align:middle line:84%
push it, but push it slow enough
so that the system has time

01:39:37.790 --> 01:39:41.150 align:middle line:84%
to exchange heat
with the environment

01:39:41.150 --> 01:39:49.310 align:middle line:84%
and remain in equilibrium, then
you get one spring constant.

01:39:49.310 --> 01:39:52.800 align:middle line:84%
If instead you push
the spring fast,

01:39:52.800 --> 01:40:01.160 align:middle line:84%
like when the car
goes on a bump,

01:40:01.160 --> 01:40:06.270 align:middle line:84%
the system doesn't have time
to exchange energy or heat

01:40:06.270 --> 01:40:09.730 align:middle line:84%
and the entropy
remains constant.

01:40:09.730 --> 01:40:12.850 align:middle line:84%
So that's the isothermal
compressibility--

01:40:12.850 --> 01:40:16.880 align:middle line:84%
I'm sorry, the isentropic
compressibility that appears.

01:40:16.880 --> 01:40:24.405 align:middle line:84%
And so you see that the ratio
of these two spring constants

01:40:24.405 --> 01:40:34.220 align:middle line:84%
is equal to CP over CV,
which for air is 1.4.

01:40:34.220 --> 01:40:36.520 align:middle line:90%
We just reviewed.

01:40:36.520 --> 01:40:41.380 align:middle line:84%
So that means that if you
act on the spring fast,

01:40:41.380 --> 01:40:46.060 align:middle line:84%
you get the spring constant
that is 40% higher than if you

01:40:46.060 --> 01:40:48.540 align:middle line:90%
act on the spring slow.

01:40:48.540 --> 01:40:53.460 align:middle line:84%
And these devices, if
you look up air springs,

01:40:53.460 --> 01:40:56.810 align:middle line:84%
you can see that it's
an enormous business

01:40:56.810 --> 01:41:04.880 align:middle line:84%
because, as I said, trains,
buses, bicycles, and cars use

01:41:04.880 --> 01:41:09.110 align:middle line:84%
spring constants combined
also with the damping system

01:41:09.110 --> 01:41:14.480 align:middle line:84%
to give you suspension
systems that

01:41:14.480 --> 01:41:22.620 align:middle line:84%
are allowed to absorb vibrations
and make it more comfortable.

01:41:22.620 --> 01:41:23.170 align:middle line:90%
OK.

01:41:23.170 --> 01:41:27.910 align:middle line:84%
So sorry if I went
a little bit late.

01:41:27.910 --> 01:41:32.000 align:middle line:90%