WEBVTT

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[SQUEAKING]

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[RUSTLING]

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[CLICKING]

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GIAN PAOLO BERETTA:
OK, good morning.

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So we started talking about
multi-component systems,

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mixtures.

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And our program is
that at the beginning,

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we try to see when
it is possible

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to infer the properties of a
mixture as much as possible

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from the properties of
the pure components.

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And so we are in the process of
defining some ideal situations

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in which this is possible,
which as we said,

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is a good start in
our modeling efforts.

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It's like a reference
simple situation

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in which we do not need to
add experimental data to model

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our mixtures.

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But then we will find that in
practice, the ideal situation

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is really only a
limiting situation, which

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is not fulfilled by any real
mixture, except in some limits.

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Nevertheless, we gain
a lot of information

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by just looking at
ideal situations.

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So we have defined
these partial properties

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that are derivatives or
functions of the chemical

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potentials.

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For example, the partial
entropy of the constituent

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in the mixture, which is
a function of T, p, and y.

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We will have to be careful
in distinguishing well

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between the partial entropy of
the constituent in the mixture

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and the s double i T p, which
is the specific property,

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the specific entropy,
of pure component

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i when at the same temperature
and pressure of the mixture.

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We will see that they
are somehow related

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and that the difference
is measurable.

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So we have to pay a lot of
attention to the subscripts.

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Like, so a single subscript
is a partial property

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for the mixture.

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Double subscript is a specific
property of the pure component.

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And then we define
the partial volume,

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which is another derivative
of the chemical potential,

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once we know the
chemical potentials

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as a function of temperature,
pressure, and composition.

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We define the partial energy.

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And also, we define
the partial enthalpy.

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And let me just stress this one.

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If you have the expression
for the chemical potential

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and you divide it
by the temperature,

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and take the derivative not with
respect to T, but with respect

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to the inverse of
the temperature,

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then you get the
partial enthalpy.

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This formula will come
out a while often.

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And also, this one, which I
better write here on the board,

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we can write it this way.

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OK, so we can say that--

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we can see that from
this relation here,

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we can see that the
chemical potential can be--

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of the component
in the mixture can

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be written as this linear
combination, enthalpy

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minus T s, which
essentially is also

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equal to the Gibbs free energy.

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So this is also equal to the
partial Gibbs free energy.

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And in fact, the derivative
of G with respect to ni,

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at fixed T and p, and
the other constituents,

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that's the definition of the
chemical potential in terms

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of the Gibbs free energy.

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But it's also-- you could
also call it by analogy

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with these definitions,
the partial Gibbs

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free energy of the
constituent in the mixture.

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So in other words, we're saying
that the chemical potential

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can be interpreted itself
as a partial property.

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It's the partial
Gibbs free energy

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of the constituent
in the mixture.

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And the reason why we call
these properties partial

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is because they
contribute to building up

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the property of the mixture
by simple multiplication

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with their amounts.

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And each-- and you can do this
for entropy, volume, energy,

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the free energies, the enthalpy.

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They are all-- they all
have the same structure.

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Of course, now, we are-- we
forget the small systems,

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and we focus on large systems.

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So this is the right-hand
side, the highlighted formulas,

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because for small
systems, we will

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have also to some
contributions that

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correct this expression in
terms of the Euler free energy.

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OK, so how do we measure
these partial properties?

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And here's the setup.

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We take a mixture with
a given composition,

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in stable equilibrium of course.

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I know I'm not repeating
it often enough,

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but we are concentrating
our attention now

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on the stable
equilibrium states.

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And so we take a mixture
with some given composition

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at a stable equilibrium state,
at temperature T and pressure p.

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And we put it in
mutual equilibrium

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with a thermal reservoir
of the kind that

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can exchange also volume.

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So you have also the
pressure equality

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as a condition for mutual
equilibrium between your mixture

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and the reservoir.

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Then we take a little
bit of pure component i,

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and we add it to the mixture.

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And we wait until the
mixture goes again

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to mutual equilibrium with
that thermal reservoir.

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OK, so this is a
mixing process in which

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we add a small amount of
one of the components.

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And then since we can measure
properties of systems,

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for example, let me
take the enthalpy.

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And so let me measure the
difference between the enthalpy

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of the mixture in
this final state

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and the enthalpy of the
composite system of the mixture

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plus the pure component
in the initial state.

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OK, so this is for the
mixture in the final state.

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The amounts are the same, but
the amount for the constituent i

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is n plus dn.

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This is the initial where in
the mixture, I just have ni

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and the dni is separate
from the mixture.

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So it contributes with its own--

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to the enthalpy of
the pure constituent

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through its specific property
of the pure component.

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And notice that usually, as I
said several times, enthalpy

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is not an additive property.

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But if you're looking at systems
that are at the same temp--

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pressure, then
enthalpy is additive.

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And therefore, the enthalpy
of the composite of these two

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subsystems is equal to the
sum of the two enthalpies,

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like we do here, the sum of
the enthalpy of the mixture,

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plus the enthalpy of
the pure component.

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OK, now if we take
this and divide it

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by the amount of
constituent i that we

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have added to the
mixture, that defines

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the change in the enthalpy due
to the addition of that amount--

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of a small amount
of that component.

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And of course, the n is
supposed to be small.

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So we're taking the
limit of this, which is--

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which can be viewed as an
incremental product, at least

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the part with the
capital H. It's

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the partial derivative of
capital H with respect to ni.

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And then there is this
additional contribution

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of the separate pure
component that we have added,

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which since I divided--

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I'm dividing by dni
adds, but with the minus

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sign, a contribution here.

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Now, we recognize
that this derivative

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is exactly what we defined
as the partial enthalpy

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of the constituent in the
mixture in the previous slide.

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So here, we have the difference
between the partial enthalpy

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and the specific enthalpy
of pure component

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at the same T and
p of the mixture.

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This is what we
call the enthalpy

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of isothermobaric mixing.

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Tp stands for
isothermal and isobaric

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because we are doing this
at fixed T and p imposed

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by the reservoir.

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This can be measured.

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Enthalpy in a process
like this is essentially,

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if you make the
energy balance, this

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is essentially
the heat exchanged

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with the thermal reservoir.

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So you measure it
with a calorimeter.

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So that means that since you can
measure this with a calorimeter

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and you know the properties
of the pure substances,

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then you have measured
the partial enthalpy

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of the component in the mixture.

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And this doesn't require
any particular assumptions

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about the mixture being
ideal or non-ideal.

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We actually haven't even
defined yet what ideal means.

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It's simply a tool, a
method, with which people

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measure properties of mixtures.

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And what we have done
here for the enthalpy

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can be repeated the same way.

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So I'm not repeating
it here, but to define

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the volume of mixing,
so it's the difference

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between the partial volume
and the specific volume

00:13:07.390 --> 00:13:10.180 align:middle line:84%
at the same T and p,
the energy of mixing

00:13:10.180 --> 00:13:12.060 align:middle line:90%
and the entropy of mixing.

00:13:12.060 --> 00:13:16.180 align:middle line:90%


00:13:16.180 --> 00:13:18.520 align:middle line:84%
And these are all things
that you can measure

00:13:18.520 --> 00:13:20.430 align:middle line:90%
by energy and entropy balances.

00:13:20.430 --> 00:13:25.040 align:middle line:90%


00:13:25.040 --> 00:13:28.460 align:middle line:84%
So these are ways in which
you can characterize.

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OK, this is a--

00:13:30.230 --> 00:13:31.970 align:middle line:90%
oops, sorry.

00:13:31.970 --> 00:13:38.460 align:middle line:84%
Yeah, there is an
extra character there.

00:13:38.460 --> 00:13:41.210 align:middle line:90%
OK.

00:13:41.210 --> 00:13:41.730 align:middle line:90%
All right.

00:13:41.730 --> 00:13:45.350 align:middle line:84%
So now, let's use
that equation, which

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I've written up
there on the board

00:13:48.920 --> 00:14:02.940 align:middle line:84%
and substitute the expression
of the partial enthalpy as hii,

00:14:02.940 --> 00:14:05.040 align:middle line:84%
the specific enthalpy
of the pure component,

00:14:05.040 --> 00:14:07.680 align:middle line:90%
plus the enthalpy of mixing.

00:14:07.680 --> 00:14:11.350 align:middle line:84%
And the same for the
entropy, s partial.

00:14:11.350 --> 00:14:17.610 align:middle line:84%
We can write it as s specific
of the pure component

00:14:17.610 --> 00:14:21.080 align:middle line:84%
plus the entropy of
isothermobaric mixing.

00:14:21.080 --> 00:14:23.930 align:middle line:90%


00:14:23.930 --> 00:14:27.860 align:middle line:84%
All right, so then,
we recognize that also

00:14:27.860 --> 00:14:36.410 align:middle line:84%
for the pure substance, h minus
Ts is the chemical potential.

00:14:36.410 --> 00:14:41.773 align:middle line:84%
So this gives us a relation
for the chemical potential

00:14:41.773 --> 00:14:44.660 align:middle line:84%
of the component in
the mixture in terms

00:14:44.660 --> 00:14:46.850 align:middle line:84%
of the chemical potential
of the pure component

00:14:46.850 --> 00:14:49.940 align:middle line:84%
at the same temperature and
pressure of the mixture,

00:14:49.940 --> 00:14:54.500 align:middle line:84%
plus the enthalpy
of mixing minus T

00:14:54.500 --> 00:14:58.310 align:middle line:90%
times the entropy of mixing.

00:14:58.310 --> 00:15:00.650 align:middle line:84%
And at this stage, we
should also remember that

00:15:00.650 --> 00:15:04.460 align:middle line:84%
by the definition of partial
pressures of components

00:15:04.460 --> 00:15:06.230 align:middle line:90%
in a mixture.

00:15:06.230 --> 00:15:12.410 align:middle line:84%
You recall that that is
defined by the condition

00:15:12.410 --> 00:15:17.720 align:middle line:84%
of mutual equilibrium across
a membrane, permeable only,

00:15:17.720 --> 00:15:19.460 align:middle line:90%
to constituent i.

00:15:19.460 --> 00:15:24.450 align:middle line:84%
So at that mutual equilibrium
across the membrane,

00:15:24.450 --> 00:15:27.950 align:middle line:84%
you have equality of
chemical potentials.

00:15:27.950 --> 00:15:31.370 align:middle line:84%
So the chemical potential of
a constituent in the mixture

00:15:31.370 --> 00:15:34.433 align:middle line:84%
is also equal to the
chemical potential.

00:15:34.433 --> 00:15:36.100 align:middle line:84%
And here, there is
also another mistake.

00:15:36.100 --> 00:15:38.810 align:middle line:90%
This should be a double i.

00:15:38.810 --> 00:15:42.200 align:middle line:84%
This is the chemical
potential of a pure component

00:15:42.200 --> 00:15:50.060 align:middle line:84%
on the other side of the
semi-permeable membrane.

00:15:50.060 --> 00:15:51.870 align:middle line:90%
And therefore, yes.

00:15:51.870 --> 00:15:53.970 align:middle line:84%
At the same temperature
of the mixture,

00:15:53.970 --> 00:15:58.595 align:middle line:84%
but at a pressure which is what
we call the partial pressure.

00:15:58.595 --> 00:16:02.820 align:middle line:90%


00:16:02.820 --> 00:16:07.080 align:middle line:90%
So again, here, I--

00:16:07.080 --> 00:16:12.720 align:middle line:84%
cut and paste, makes
errors propagate.

00:16:12.720 --> 00:16:17.130 align:middle line:84%
So these should be
double i and double i.

00:16:17.130 --> 00:16:25.080 align:middle line:84%
OK, so we are now taking
this last equality

00:16:25.080 --> 00:16:28.210 align:middle line:84%
and putting in evidence
the difference.

00:16:28.210 --> 00:16:34.080 align:middle line:84%
And so taking essentially this
term to the right-hand side.

00:16:34.080 --> 00:16:38.400 align:middle line:84%
So I have the chemical
potential difference

00:16:38.400 --> 00:16:41.370 align:middle line:84%
evaluated between the
pressure-- the partial pressure

00:16:41.370 --> 00:16:46.930 align:middle line:84%
and the pressure of the
mixture, pii minus p.

00:16:46.930 --> 00:16:50.330 align:middle line:90%


00:16:50.330 --> 00:17:02.330 align:middle line:84%
Now here, we have already
proved in a previous slide,

00:17:02.330 --> 00:17:05.240 align:middle line:84%
maybe we can just
remind ourselves

00:17:05.240 --> 00:17:10.670 align:middle line:90%
of how they got here, that--

00:17:10.670 --> 00:17:16.339 align:middle line:84%
so we are having that
mu double i at pii--

00:17:16.339 --> 00:17:25.270 align:middle line:84%
I'm sorry, at T and pii
minus mu double i at T p.

00:17:25.270 --> 00:17:28.130 align:middle line:90%


00:17:28.130 --> 00:17:39.580 align:middle line:84%
OK, you see, if I
have a function of x,

00:17:39.580 --> 00:17:43.000 align:middle line:84%
And the difference of
a function evaluated

00:17:43.000 --> 00:17:45.640 align:middle line:84%
at two different
points, I can always

00:17:45.640 --> 00:17:50.560 align:middle line:84%
write by the integral
calculus equation

00:17:50.560 --> 00:17:55.120 align:middle line:84%
that this is equal to
the integral from x2

00:17:55.120 --> 00:18:01.030 align:middle line:84%
to x1 of the derivative
of that function.

00:18:01.030 --> 00:18:01.815 align:middle line:90%
Let's call it--

00:18:01.815 --> 00:18:04.920 align:middle line:90%


00:18:04.920 --> 00:18:11.810 align:middle line:84%
And this x double prime is a
dummy variable of integration.

00:18:11.810 --> 00:18:15.480 align:middle line:84%
OK, so these, you can
write for any function.

00:18:15.480 --> 00:18:20.120 align:middle line:90%
So here, we apply this theorem.

00:18:20.120 --> 00:18:30.330 align:middle line:84%
So this x2 is p, x1 is
pii, and the derivative

00:18:30.330 --> 00:18:33.650 align:middle line:84%
we have to put here is the
partial derivative with respect

00:18:33.650 --> 00:18:38.771 align:middle line:90%
to p of what?

00:18:38.771 --> 00:18:42.820 align:middle line:84%
Of the chemical potential
of the pure component

00:18:42.820 --> 00:18:46.450 align:middle line:84%
while the other
variables are T p--

00:18:46.450 --> 00:18:56.920 align:middle line:84%
I'm sorry, T. And this
is to be evaluated

00:18:56.920 --> 00:19:03.550 align:middle line:84%
at the value of the dummy
variable, so at p double prime,

00:19:03.550 --> 00:19:07.720 align:middle line:84%
and integrated over
the dummy variable.

00:19:07.720 --> 00:19:14.050 align:middle line:84%
But if you look up
the many equations

00:19:14.050 --> 00:19:17.980 align:middle line:84%
that we have derived also
for the pure substance,

00:19:17.980 --> 00:19:23.025 align:middle line:84%
this derivative is
the specific volume.

00:19:23.025 --> 00:19:26.260 align:middle line:90%


00:19:26.260 --> 00:19:33.410 align:middle line:84%
So this becomes the specific
volume of the pure component

00:19:33.410 --> 00:19:37.790 align:middle line:84%
evaluated at temperature T
and at the dummy pressure p

00:19:37.790 --> 00:19:41.430 align:middle line:90%
of integration p double prime.

00:19:41.430 --> 00:19:44.070 align:middle line:90%
OK, all right.

00:19:44.070 --> 00:19:49.235 align:middle line:84%
So that explains
this integral here.

00:19:49.235 --> 00:19:52.210 align:middle line:90%


00:19:52.210 --> 00:19:55.810 align:middle line:84%
But above, we've seen that
this difference in chemical

00:19:55.810 --> 00:20:04.480 align:middle line:84%
potentials is equal to the delta
h mix minus T s delta s mix.

00:20:04.480 --> 00:20:12.970 align:middle line:90%
OK, now look at this volume.

00:20:12.970 --> 00:20:15.875 align:middle line:90%


00:20:15.875 --> 00:20:22.030 align:middle line:84%
If I have an ideal
gas, and if I can--

00:20:22.030 --> 00:20:27.970 align:middle line:84%
my substance i behaves according
to the ideal gas relation,

00:20:27.970 --> 00:20:35.230 align:middle line:84%
the specific volume can
be written as RT over p.

00:20:35.230 --> 00:20:39.980 align:middle line:84%
And the pressure that we should
evaluate is p that is here.

00:20:39.980 --> 00:20:43.480 align:middle line:90%
So it's p double prime.

00:20:43.480 --> 00:20:50.710 align:middle line:84%
And so when I do this
integral, RT goes outside

00:20:50.710 --> 00:20:53.890 align:middle line:84%
because I'm integrating
over p, p double prime.

00:20:53.890 --> 00:20:59.440 align:middle line:84%
And the integral of 1
over p is the logarithm.

00:20:59.440 --> 00:21:10.330 align:middle line:84%
So that gives me the formula
RT log of pii over p.

00:21:10.330 --> 00:21:12.340 align:middle line:90%
And that's for the gas.

00:21:12.340 --> 00:21:15.250 align:middle line:90%


00:21:15.250 --> 00:21:20.860 align:middle line:84%
If instead I have
a liquid and I can

00:21:20.860 --> 00:21:26.020 align:middle line:84%
use the incompressible
liquid model for which

00:21:26.020 --> 00:21:33.860 align:middle line:84%
the specific volume vii
is approximately constant,

00:21:33.860 --> 00:21:38.590 align:middle line:84%
meaning independent of
temperature and pressure,

00:21:38.590 --> 00:21:41.810 align:middle line:84%
well, if it is a constant,
it goes out of the integral.

00:21:41.810 --> 00:21:48.820 align:middle line:84%
And then this becomes
the specific volume times

00:21:48.820 --> 00:21:53.830 align:middle line:90%
pii minus p.

00:21:53.830 --> 00:21:59.380 align:middle line:84%
And here in the
slide, I just switched

00:21:59.380 --> 00:22:03.100 align:middle line:84%
because the pressure
is usually greater

00:22:03.100 --> 00:22:04.250 align:middle line:90%
than the partial pressure.

00:22:04.250 --> 00:22:07.660 align:middle line:84%
So I put this difference
in parentheses

00:22:07.660 --> 00:22:11.290 align:middle line:84%
and then I pick up a minus
sign on the other side.

00:22:11.290 --> 00:22:18.105 align:middle line:84%
OK, so this formula will
be useful in a moment.

00:22:18.105 --> 00:22:23.220 align:middle line:90%


00:22:23.220 --> 00:22:27.210 align:middle line:84%
And again, we see that
there is a relation

00:22:27.210 --> 00:22:37.745 align:middle line:84%
between the partial pressures,
very explicit relations in terms

00:22:37.745 --> 00:22:42.530 align:middle line:84%
of the enthalpy and the entropy
of isothermobaric mixing.

00:22:42.530 --> 00:22:48.250 align:middle line:84%
So this is a way in which you
can measure partial pressures

00:22:48.250 --> 00:22:50.770 align:middle line:84%
because you can
measure the properties

00:22:50.770 --> 00:22:52.095 align:middle line:90%
of isothermobaric mixing.

00:22:52.095 --> 00:23:01.230 align:middle line:90%


00:23:01.230 --> 00:23:12.000 align:middle line:84%
For example, here, I want
to point you to a couple

00:23:12.000 --> 00:23:20.300 align:middle line:84%
of references, which if you go
and take a look, and they'll--

00:23:20.300 --> 00:23:23.275 align:middle line:90%


00:23:23.275 --> 00:23:30.840 align:middle line:84%
a huge literature,
so a huge community

00:23:30.840 --> 00:23:36.840 align:middle line:84%
that over many
decades, or perhaps

00:23:36.840 --> 00:23:41.010 align:middle line:84%
over more than a
century, have been

00:23:41.010 --> 00:23:44.310 align:middle line:90%
measuring properties this way.

00:23:44.310 --> 00:23:47.640 align:middle line:84%
And they're still doing it
because the applications

00:23:47.640 --> 00:23:49.123 align:middle line:90%
are growing.

00:23:49.123 --> 00:23:52.820 align:middle line:90%


00:23:52.820 --> 00:23:58.250 align:middle line:84%
For example, this is
an experimental paper

00:23:58.250 --> 00:24:01.370 align:middle line:90%
where they collect--

00:24:01.370 --> 00:24:05.570 align:middle line:84%
they measure the enthalpy
of isothermobaric mixing

00:24:05.570 --> 00:24:07.970 align:middle line:90%
of liquids.

00:24:07.970 --> 00:24:16.330 align:middle line:84%
And these liquids are molten
salts that, as you may know,

00:24:16.330 --> 00:24:20.150 align:middle line:84%
are used in various
applications,

00:24:20.150 --> 00:24:30.170 align:middle line:84%
including solar thermal
applications in those collectors

00:24:30.170 --> 00:24:37.350 align:middle line:84%
with mirrors that want to
achieve high temperatures.

00:24:37.350 --> 00:24:41.660 align:middle line:84%
The molten salts
allow-- are stable

00:24:41.660 --> 00:24:43.440 align:middle line:90%
also at very high temperatures.

00:24:43.440 --> 00:24:52.910 align:middle line:84%
And therefore,
using these fluids,

00:24:52.910 --> 00:24:58.400 align:middle line:84%
you can collect solar
energy at high temperatures

00:24:58.400 --> 00:25:00.730 align:middle line:90%
up to maybe 600 Celsius.

00:25:00.730 --> 00:25:05.450 align:middle line:90%


00:25:05.450 --> 00:25:11.360 align:middle line:84%
But of course, molten salts are
used also in nuclear engineering

00:25:11.360 --> 00:25:21.170 align:middle line:84%
and in processing industries
for producing materials

00:25:21.170 --> 00:25:25.100 align:middle line:84%
that are useful for all
sorts of applications,

00:25:25.100 --> 00:25:30.310 align:middle line:90%
from electronics to magnets.

00:25:30.310 --> 00:25:33.200 align:middle line:90%


00:25:33.200 --> 00:25:36.860 align:middle line:84%
So this is a
reference in which you

00:25:36.860 --> 00:25:42.560 align:middle line:84%
can see how people measure
and then try to correlate.

00:25:42.560 --> 00:25:46.430 align:middle line:84%
So there is also a
number of correlations,

00:25:46.430 --> 00:25:52.910 align:middle line:84%
which go under the names of the
inventors of the correlations,

00:25:52.910 --> 00:26:01.670 align:middle line:84%
that do good jobs in
determining these effects.

00:26:01.670 --> 00:26:09.980 align:middle line:84%
You see, here, the gray
molecule, cesium ion,

00:26:09.980 --> 00:26:14.030 align:middle line:90%
is sort of the solvent.

00:26:14.030 --> 00:26:20.900 align:middle line:84%
It's like the prevailing,
or the common substance

00:26:20.900 --> 00:26:23.190 align:middle line:90%
of these mixtures.

00:26:23.190 --> 00:26:27.450 align:middle line:84%
And then they keep changing
the other substance.

00:26:27.450 --> 00:26:31.710 align:middle line:90%


00:26:31.710 --> 00:26:40.380 align:middle line:84%
So it's actually
not only for dilute,

00:26:40.380 --> 00:26:45.690 align:middle line:84%
it's for over the full range
of compositions from 0 to 1.

00:26:45.690 --> 00:26:52.220 align:middle line:84%
And you can see that you have a
behavior in which the enthalpy

00:26:52.220 --> 00:26:55.076 align:middle line:90%
of mixing is negative.

00:26:55.076 --> 00:27:01.710 align:middle line:90%


00:27:01.710 --> 00:27:06.210 align:middle line:90%
Meaning that the substance--

00:27:06.210 --> 00:27:12.430 align:middle line:84%
that when you mix the substance,
you have an exothermic reaction.

00:27:12.430 --> 00:27:17.590 align:middle line:84%
It's not really a reaction, but
it's a physical chemical effect,

00:27:17.590 --> 00:27:19.780 align:middle line:90%
which releases heat.

00:27:19.780 --> 00:27:21.390 align:middle line:90%
So in other words, you have to--

00:27:21.390 --> 00:27:24.670 align:middle line:84%
if you want to return to mutual
equilibrium with the reservoir,

00:27:24.670 --> 00:27:27.870 align:middle line:84%
you have to cool down
after the mixing.

00:27:27.870 --> 00:27:30.410 align:middle line:84%
You have to cool
down by this amount.

00:27:30.410 --> 00:27:34.410 align:middle line:90%


00:27:34.410 --> 00:27:38.070 align:middle line:84%
And that cooling
measures is exactly--

00:27:38.070 --> 00:27:40.620 align:middle line:84%
so we-- that's how
with a calorimeter,

00:27:40.620 --> 00:27:49.470 align:middle line:84%
you can measure that cooling,
and therefore this delta H.

00:27:49.470 --> 00:27:54.410 align:middle line:84%
You can also do
similar measurements

00:27:54.410 --> 00:27:58.800 align:middle line:90%
for the volume of mixing.

00:27:58.800 --> 00:28:07.320 align:middle line:90%
And here, I sketched the--

00:28:07.320 --> 00:28:12.120 align:middle line:84%
yeah, I think this line should
belong a little lower here

00:28:12.120 --> 00:28:14.250 align:middle line:90%
to the 0 level.

00:28:14.250 --> 00:28:18.870 align:middle line:84%
And I sketched--
this is just to show

00:28:18.870 --> 00:28:24.280 align:middle line:84%
that it's the volume of
mixing is not always positive.

00:28:24.280 --> 00:28:27.750 align:middle line:84%
It can be positive,
it can be negative,

00:28:27.750 --> 00:28:32.670 align:middle line:84%
it can be positive in one
range and become negative

00:28:32.670 --> 00:28:38.300 align:middle line:84%
in the other range,
depending on the composition.

00:28:38.300 --> 00:28:41.870 align:middle line:84%
And it all depends on what
kind of molecules you have,

00:28:41.870 --> 00:28:48.680 align:middle line:84%
and how the molecules
interact with each other.

00:28:48.680 --> 00:28:52.640 align:middle line:84%
And as you can see,
these two references

00:28:52.640 --> 00:28:57.920 align:middle line:84%
where you may want to take a
look to see experimental data,

00:28:57.920 --> 00:29:03.655 align:middle line:84%
and how they're treated, date
back to at least 40 years ago.

00:29:03.655 --> 00:29:11.130 align:middle line:90%


00:29:11.130 --> 00:29:19.600 align:middle line:84%
OK, now, this slide is
also just a parenthetical.

00:29:19.600 --> 00:29:22.475 align:middle line:90%
It just says, all right.

00:29:22.475 --> 00:29:25.230 align:middle line:90%


00:29:25.230 --> 00:29:27.480 align:middle line:84%
So we have seen
that in practice,

00:29:27.480 --> 00:29:33.660 align:middle line:84%
with those measurements, we can
infer the values of the chemical

00:29:33.660 --> 00:29:37.245 align:middle line:84%
potentials, and therefore
the partial properties.

00:29:37.245 --> 00:29:45.750 align:middle line:84%
So the question that we address
in this slide is, can we--

00:29:45.750 --> 00:29:48.360 align:middle line:84%
is the meaning of
partial that we

00:29:48.360 --> 00:29:54.570 align:middle line:84%
use in partial properties the
same as the meaning of partial

00:29:54.570 --> 00:29:57.330 align:middle line:90%
as we use in partial pressures?

00:29:57.330 --> 00:30:00.550 align:middle line:84%
And the answer is no because
the definition is different.

00:30:00.550 --> 00:30:05.100 align:middle line:84%
However, you can somehow
relate partial properties

00:30:05.100 --> 00:30:07.290 align:middle line:90%
in terms of partial pressures.

00:30:07.290 --> 00:30:14.850 align:middle line:84%
And here, here is
the way of doing it.

00:30:14.850 --> 00:30:18.520 align:middle line:90%


00:30:18.520 --> 00:30:22.160 align:middle line:84%
It's just a matter of writing
the chemical potential,

00:30:22.160 --> 00:30:24.520 align:middle line:90%
as we see here.

00:30:24.520 --> 00:30:28.130 align:middle line:84%
Again, as a function, as it
is of the partial pressure.

00:30:28.130 --> 00:30:33.310 align:middle line:84%
So if you take the
differential of this relation

00:30:33.310 --> 00:30:36.760 align:middle line:84%
here, which defines
the partial pressure,

00:30:36.760 --> 00:30:41.230 align:middle line:84%
and then remember that the
derivatives of the chemical

00:30:41.230 --> 00:30:43.130 align:middle line:84%
potential are the
partial properties,

00:30:43.130 --> 00:30:47.273 align:middle line:84%
then that is where that
relation comes about.

00:30:47.273 --> 00:30:50.670 align:middle line:90%


00:30:50.670 --> 00:30:52.000 align:middle line:90%
And here are the details.

00:30:52.000 --> 00:30:54.900 align:middle line:84%
So if you like to
take derivatives,

00:30:54.900 --> 00:30:58.800 align:middle line:90%
this is how you can practice it.

00:30:58.800 --> 00:31:05.330 align:middle line:84%
So I'm not going to
explain the details here.

00:31:05.330 --> 00:31:13.459 align:middle line:90%


00:31:13.459 --> 00:31:19.100 align:middle line:84%
At this stage, we need
to recall something

00:31:19.100 --> 00:31:25.220 align:middle line:84%
about what happens
when molecules

00:31:25.220 --> 00:31:27.595 align:middle line:90%
come close to one another.

00:31:27.595 --> 00:31:31.090 align:middle line:90%


00:31:31.090 --> 00:31:40.730 align:middle line:84%
And the Lennard-Jones
model gives you

00:31:40.730 --> 00:31:44.360 align:middle line:84%
the potential energy
of the interaction

00:31:44.360 --> 00:31:45.630 align:middle line:90%
between two molecules.

00:31:45.630 --> 00:31:49.850 align:middle line:84%
So suppose I have one
molecule and I stay in--

00:31:49.850 --> 00:31:52.580 align:middle line:84%
and I sit on that molecule
on the reference frame that

00:31:52.580 --> 00:31:55.850 align:middle line:84%
moves with that
molecule, and I see

00:31:55.850 --> 00:31:57.980 align:middle line:90%
another molecule approaching.

00:31:57.980 --> 00:32:04.560 align:middle line:84%
The Lennard-Jones model is a
pair-interaction kind of model.

00:32:04.560 --> 00:32:08.540 align:middle line:84%
It looks just what happens
between one molecule

00:32:08.540 --> 00:32:11.910 align:middle line:90%
and the other, not the fact--

00:32:11.910 --> 00:32:16.490 align:middle line:84%
it doesn't apply well if you
have to consider also the fact

00:32:16.490 --> 00:32:19.070 align:middle line:84%
that this molecule may
also, at the same time,

00:32:19.070 --> 00:32:27.005 align:middle line:84%
be interacting with a third
and maybe a fourth molecule,

00:32:27.005 --> 00:32:30.240 align:middle line:84%
which of course, is
important in liquids.

00:32:30.240 --> 00:32:32.850 align:middle line:90%
But OK, so here's the idea.

00:32:32.850 --> 00:32:34.580 align:middle line:84%
I'm sitting on that
molecule, and I see

00:32:34.580 --> 00:32:39.290 align:middle line:90%
another molecule approaching.

00:32:39.290 --> 00:32:43.760 align:middle line:84%
Now, because of the
electronic structure

00:32:43.760 --> 00:32:48.170 align:middle line:84%
of atoms and molecules,
the electrons

00:32:48.170 --> 00:32:51.570 align:middle line:84%
that are negatively
charged, yes,

00:32:51.570 --> 00:32:55.940 align:middle line:84%
are attracted by the nucleus
or the nuclei of the molecule,

00:32:55.940 --> 00:32:58.310 align:middle line:90%
or the atom.

00:32:58.310 --> 00:33:01.560 align:middle line:84%
But as they approach
other molecules,

00:33:01.560 --> 00:33:08.270 align:middle line:84%
they are also a bit attracted by
the nucleus of the other atom.

00:33:08.270 --> 00:33:14.630 align:middle line:84%
And that produces
these so-called van

00:33:14.630 --> 00:33:16.800 align:middle line:90%
der Waals attractive forces.

00:33:16.800 --> 00:33:20.760 align:middle line:84%
So the potential
going negative--

00:33:20.760 --> 00:33:23.120 align:middle line:84%
so if this is the
potential, remember

00:33:23.120 --> 00:33:28.040 align:middle line:84%
that I can calculate
the force by taking

00:33:28.040 --> 00:33:30.260 align:middle line:84%
the derivative of the
potential with respect

00:33:30.260 --> 00:33:33.560 align:middle line:90%
to distance minus sign.

00:33:33.560 --> 00:33:36.140 align:middle line:90%
So this force is a vector.

00:33:36.140 --> 00:33:44.100 align:middle line:84%
And ir is the vector that
points in the direction outward,

00:33:44.100 --> 00:33:48.770 align:middle line:84%
so further from the
molecule I am sitting on.

00:33:48.770 --> 00:33:53.570 align:middle line:84%
So it's like on
this axis, i sub r

00:33:53.570 --> 00:33:56.030 align:middle line:84%
is the unit vector
in the r direction,

00:33:56.030 --> 00:33:58.170 align:middle line:90%
in the right direction.

00:33:58.170 --> 00:34:01.660 align:middle line:90%


00:34:01.660 --> 00:34:03.910 align:middle line:84%
So the usefulness of
having a potential

00:34:03.910 --> 00:34:05.980 align:middle line:84%
is that then, you
can calculate forces

00:34:05.980 --> 00:34:08.270 align:middle line:84%
by taking the derivative
of the potential.

00:34:08.270 --> 00:34:10.360 align:middle line:84%
And as you see,
here is the force--

00:34:10.360 --> 00:34:12.896 align:middle line:90%
if the force is negative.

00:34:12.896 --> 00:34:16.860 align:middle line:90%


00:34:16.860 --> 00:34:23.969 align:middle line:84%
it means that its direction is
in the opposite sign of the unit

00:34:23.969 --> 00:34:26.050 align:middle line:90%
vector in the r direction.

00:34:26.050 --> 00:34:27.780 align:middle line:90%
So it points left.

00:34:27.780 --> 00:34:31.469 align:middle line:90%
So it's attractive.

00:34:31.469 --> 00:34:47.540 align:middle line:84%
Up to this point, which is
about here, the derivative of V

00:34:47.540 --> 00:34:48.739 align:middle line:90%
is positive.

00:34:48.739 --> 00:34:50.750 align:middle line:90%
So the force is negative.

00:34:50.750 --> 00:34:57.850 align:middle line:90%
And yeah.

00:34:57.850 --> 00:35:01.620 align:middle line:84%
Yeah, OK, up to this
point, where it is 0,

00:35:01.620 --> 00:35:07.100 align:middle line:84%
we get to the minimum,
it's attractive.

00:35:07.100 --> 00:35:10.850 align:middle line:84%
And from this point on,
it becomes repulsive.

00:35:10.850 --> 00:35:13.230 align:middle line:90%
The force becomes positive.

00:35:13.230 --> 00:35:16.280 align:middle line:90%


00:35:16.280 --> 00:35:18.890 align:middle line:84%
That repulsion is
due to the fact

00:35:18.890 --> 00:35:24.410 align:middle line:84%
that now, the nuclei, which
are positively charged,

00:35:24.410 --> 00:35:28.330 align:middle line:84%
begin to fill the positive
charge of the nuclei

00:35:28.330 --> 00:35:29.990 align:middle line:90%
of the particle I'm sitting on.

00:35:29.990 --> 00:35:31.493 align:middle line:90%
And therefore, that repels.

00:35:31.493 --> 00:35:38.140 align:middle line:90%


00:35:38.140 --> 00:35:48.530 align:middle line:84%
OK, so most of the
times, molecules

00:35:48.530 --> 00:35:55.160 align:middle line:84%
are running around in
their Brownian motion.

00:35:55.160 --> 00:36:01.440 align:middle line:84%
So in which they have
some kinetic energy

00:36:01.440 --> 00:36:04.050 align:middle line:90%
due to the velocity they have.

00:36:04.050 --> 00:36:06.520 align:middle line:84%
And they have also
this potential energy.

00:36:06.520 --> 00:36:12.480 align:middle line:84%
Some of that kinetic energy gets
transformed in potential energy.

00:36:12.480 --> 00:36:15.990 align:middle line:84%
Or actually when the
molecule approaches and gets

00:36:15.990 --> 00:36:21.520 align:middle line:84%
an attractive force, it
gains kinetic energy.

00:36:21.520 --> 00:36:25.330 align:middle line:84%
So it's accelerated
towards the particle.

00:36:25.330 --> 00:36:28.800 align:middle line:84%
So if the molecule is
coming from the right

00:36:28.800 --> 00:36:36.540 align:middle line:84%
and it's approaching, it's
accelerated towards the molecule

00:36:36.540 --> 00:36:38.950 align:middle line:90%
I'm sitting in.

00:36:38.950 --> 00:36:44.620 align:middle line:84%
But then, all of a sudden, it
finds also a repulsive force.

00:36:44.620 --> 00:36:47.710 align:middle line:90%
So that's decelerating.

00:36:47.710 --> 00:36:53.950 align:middle line:84%
Of course, if the
kinetic energy is enough,

00:36:53.950 --> 00:36:58.310 align:middle line:90%
this molecule can go and hit.

00:36:58.310 --> 00:37:00.910 align:middle line:90%
So make a collision.

00:37:00.910 --> 00:37:03.710 align:middle line:84%
Eventually, it will
make a collision

00:37:03.710 --> 00:37:07.370 align:middle line:84%
because the force is going
to become very large.

00:37:07.370 --> 00:37:09.170 align:middle line:84%
The repulsive force
becomes very large.

00:37:09.170 --> 00:37:13.350 align:middle line:84%
And therefore, the particle
is pushed away back.

00:37:13.350 --> 00:37:14.970 align:middle line:90%
That's a collision.

00:37:14.970 --> 00:37:17.730 align:middle line:84%
It's like a soft collision,
but it's a collision.

00:37:17.730 --> 00:37:22.880 align:middle line:90%


00:37:22.880 --> 00:37:30.370 align:middle line:84%
An even simpler model of this
would be the so-called hard

00:37:30.370 --> 00:37:37.840 align:middle line:84%
sphere model, in which the
potential is-- would be like--

00:37:37.840 --> 00:37:49.820 align:middle line:90%


00:37:49.820 --> 00:37:52.510 align:middle line:90%
will be like this.

00:37:52.510 --> 00:37:56.260 align:middle line:84%
A function, so V,
is a function which

00:37:56.260 --> 00:38:03.760 align:middle line:84%
goes to infinite at
this point, which is 1.

00:38:03.760 --> 00:38:08.650 align:middle line:84%
It's the distance-- 1 is
because we're normalizing these

00:38:08.650 --> 00:38:17.050 align:middle line:84%
to the diameter of these
molecules, of these spheres,

00:38:17.050 --> 00:38:19.480 align:middle line:90%
assuming they're equal.

00:38:19.480 --> 00:38:22.330 align:middle line:84%
Otherwise, it would be like
the-- have to normalize

00:38:22.330 --> 00:38:23.666 align:middle line:90%
to the average--

00:38:23.666 --> 00:38:27.260 align:middle line:90%


00:38:27.260 --> 00:38:30.740 align:middle line:84%
the sum of the radii
of the two molecules.

00:38:30.740 --> 00:38:32.670 align:middle line:90%
And it's 0 here.

00:38:32.670 --> 00:38:37.940 align:middle line:84%
So the hard sphere model
assumes no attractive force

00:38:37.940 --> 00:38:47.330 align:middle line:84%
until the sphere hits like
in a billiard ball situation.

00:38:47.330 --> 00:38:51.050 align:middle line:84%
It hits the other molecule
and it gets repelled

00:38:51.050 --> 00:38:56.146 align:middle line:90%
by some elastic collision.

00:38:56.146 --> 00:38:59.940 align:middle line:90%


00:38:59.940 --> 00:39:09.250 align:middle line:84%
OK, let's return to this
case here and now consider

00:39:09.250 --> 00:39:10.955 align:middle line:90%
two important regimes.

00:39:10.955 --> 00:39:13.480 align:middle line:90%


00:39:13.480 --> 00:39:20.980 align:middle line:84%
One regime is the ideal
gas, the gas regime.

00:39:20.980 --> 00:39:27.100 align:middle line:84%
So it's true that the
molecules of the gas

00:39:27.100 --> 00:39:40.200 align:middle line:84%
very often, billions of
collisions per second, we--

00:39:40.200 --> 00:39:47.580 align:middle line:84%
maybe we'll have a slide later
on that does that calculation,

00:39:47.580 --> 00:39:50.130 align:middle line:90%
do have experienced collisions.

00:39:50.130 --> 00:39:58.290 align:middle line:84%
So these molecules do get
to feel this potential when

00:39:58.290 --> 00:40:03.210 align:middle line:84%
they approach the other
molecules and have a collision.

00:40:03.210 --> 00:40:05.550 align:middle line:90%
That happens very often.

00:40:05.550 --> 00:40:09.090 align:middle line:84%
But if you look up, if
you make an average,

00:40:09.090 --> 00:40:17.580 align:middle line:84%
a time average, of how much
time this molecule spends

00:40:17.580 --> 00:40:23.970 align:middle line:84%
in this area, where the
Lennard-Jones potential is

00:40:23.970 --> 00:40:28.440 align:middle line:90%
negative, is very small.

00:40:28.440 --> 00:40:35.710 align:middle line:84%
Most of the times, on average,
the particles are far apart.

00:40:35.710 --> 00:40:45.241 align:middle line:84%
And therefore, on average,
they feel zero potential.

00:40:45.241 --> 00:40:50.960 align:middle line:84%
See, this is why when you try
to measure the properties,

00:40:50.960 --> 00:40:55.730 align:middle line:84%
you're actually measuring
the properties on average,

00:40:55.730 --> 00:40:59.460 align:middle line:84%
because remember that somehow,
the state of your system

00:40:59.460 --> 00:41:04.820 align:middle line:84%
is the probability
distribution of things.

00:41:04.820 --> 00:41:08.690 align:middle line:84%
For example, here is the
probability distribution

00:41:08.690 --> 00:41:13.160 align:middle line:84%
of finding the particle at
these various distances.

00:41:13.160 --> 00:41:20.130 align:middle line:84%
And that probability
for a gas is--

00:41:20.130 --> 00:41:25.620 align:middle line:84%
has this very small tail
here, and it peaks away.

00:41:25.620 --> 00:41:28.920 align:middle line:84%
So most of the
times, the particles

00:41:28.920 --> 00:41:32.220 align:middle line:84%
are far away from each
other even though they

00:41:32.220 --> 00:41:34.090 align:middle line:90%
experience a lot of collisions.

00:41:34.090 --> 00:41:39.260 align:middle line:90%


00:41:39.260 --> 00:41:41.660 align:middle line:84%
But that means that
when you're calculating

00:41:41.660 --> 00:41:43.820 align:middle line:84%
the stable equilibrium
properties, therefore,

00:41:43.820 --> 00:41:45.170 align:middle line:90%
the average--

00:41:45.170 --> 00:41:52.690 align:middle line:84%
time average properties,
this potential is irrelevant.

00:41:52.690 --> 00:41:59.930 align:middle line:84%
And that is what allows
you to, for example,

00:41:59.930 --> 00:42:03.400 align:middle line:84%
use the hard sphere
model because that's

00:42:03.400 --> 00:42:06.340 align:middle line:84%
totally equivalent if
the particles live far

00:42:06.340 --> 00:42:13.193 align:middle line:84%
away on average and the
details of the potential

00:42:13.193 --> 00:42:14.860 align:middle line:84%
of their interaction
when they are close

00:42:14.860 --> 00:42:20.890 align:middle line:84%
is not important, well, those
details, you can forget.

00:42:20.890 --> 00:42:22.420 align:middle line:84%
They don't enter
into determining

00:42:22.420 --> 00:42:25.300 align:middle line:90%
the properties of the mixtures.

00:42:25.300 --> 00:42:29.860 align:middle line:84%
So much that in the
ideal gas, and also,

00:42:29.860 --> 00:42:40.500 align:middle line:84%
we will hopefully have a slide
also on this, the ideal gas,

00:42:40.500 --> 00:42:46.050 align:middle line:84%
this relation here that
the volume is RT over p,

00:42:46.050 --> 00:42:51.210 align:middle line:84%
you can derive for a
particle, a single particle

00:42:51.210 --> 00:42:59.900 align:middle line:84%
in a box, which is a nice
illustration also of--

00:42:59.900 --> 00:43:02.050 align:middle line:84%
that's why I will
have a slide on this.

00:43:02.050 --> 00:43:05.330 align:middle line:90%


00:43:05.330 --> 00:43:08.750 align:middle line:84%
But in other words, this--
here in this context

00:43:08.750 --> 00:43:17.015 align:middle line:84%
is just to say that the
properties of an ideal gas, so

00:43:17.015 --> 00:43:23.465 align:middle line:84%
the origin of this ideal
gas equation of state

00:43:23.465 --> 00:43:27.230 align:middle line:84%
comes from the single particle
because the properties

00:43:27.230 --> 00:43:31.331 align:middle line:84%
at stable equilibrium
in this regime

00:43:31.331 --> 00:43:35.900 align:middle line:84%
are those of particles that
leave on average by themselves.

00:43:35.900 --> 00:43:40.080 align:middle line:84%
They don't feel the effects
of the other particles.

00:43:40.080 --> 00:43:44.590 align:middle line:90%


00:43:44.590 --> 00:43:49.340 align:middle line:84%
There is another case also,
which is the liquid case.

00:43:49.340 --> 00:43:54.940 align:middle line:84%
We will return to the liquid
in a while, maybe today.

00:43:54.940 --> 00:44:01.870 align:middle line:84%
But what's important is that
instead, the liquid particles

00:44:01.870 --> 00:44:03.890 align:middle line:90%
live very close to one another.

00:44:03.890 --> 00:44:05.670 align:middle line:90%
They live near this minimum.

00:44:05.670 --> 00:44:08.220 align:middle line:90%


00:44:08.220 --> 00:44:14.470 align:middle line:84%
So for them, this potential
is more important.

00:44:14.470 --> 00:44:31.760 align:middle line:90%


00:44:31.760 --> 00:44:40.610 align:middle line:84%
This-- the Lennard-Jones
potential formula can be

00:44:40.610 --> 00:44:41.150 align:middle line:90%
written--

00:44:41.150 --> 00:44:44.010 align:middle line:84%
is written in two
different ways here.

00:44:44.010 --> 00:44:48.920 align:middle line:84%
One is in terms of
the actual distance,

00:44:48.920 --> 00:44:53.030 align:middle line:84%
and one is in terms of
the distance normalized

00:44:53.030 --> 00:45:00.590 align:middle line:84%
to this minimum, to the distance
at which the minimum occurs.

00:45:00.590 --> 00:45:05.450 align:middle line:90%
Sigma, as I already said, is--

00:45:05.450 --> 00:45:07.650 align:middle line:90%
r is normalized here to sigma.

00:45:07.650 --> 00:45:14.720 align:middle line:84%
So it's 1 at the
distance where it

00:45:14.720 --> 00:45:17.070 align:middle line:84%
is equal to the diameter
of the two particles.

00:45:17.070 --> 00:45:21.530 align:middle line:84%
So where the particles
are colliding.

00:45:21.530 --> 00:45:27.650 align:middle line:84%
And here, we also in the
plot normalized the potential

00:45:27.650 --> 00:45:28.700 align:middle line:90%
to epsilon.

00:45:28.700 --> 00:45:36.450 align:middle line:84%
And epsilon is the
depth of this well here.

00:45:36.450 --> 00:45:38.110 align:middle line:90%
So it goes to minus 1.

00:45:38.110 --> 00:45:41.480 align:middle line:90%


00:45:41.480 --> 00:45:46.730 align:middle line:84%
So stronger
interactions will have--

00:45:46.730 --> 00:45:50.455 align:middle line:84%
would be characterized by
stronger values of this epsilon.

00:45:50.455 --> 00:45:55.630 align:middle line:90%


00:45:55.630 --> 00:46:03.430 align:middle line:84%
OK, so with this
introduction, let's

00:46:03.430 --> 00:46:10.660 align:middle line:84%
consider a first
ideal behavior, which

00:46:10.660 --> 00:46:14.950 align:middle line:84%
we will call Gibbs-Dalton
ideal behavior,

00:46:14.950 --> 00:46:21.580 align:middle line:84%
and which will be a very
good approximation for gases

00:46:21.580 --> 00:46:28.540 align:middle line:84%
in the gas phase,
because in practice, we

00:46:28.540 --> 00:46:33.820 align:middle line:84%
will assume that not only
particles of the same kind

00:46:33.820 --> 00:46:36.830 align:middle line:84%
like you would have
in a pure substance,

00:46:36.830 --> 00:46:43.450 align:middle line:84%
but also particles of different
kind like we have in a mixture,

00:46:43.450 --> 00:46:48.200 align:middle line:84%
they also live on average
far away from one another.

00:46:48.200 --> 00:46:51.430 align:middle line:84%
And therefore, we can
neglect the effect

00:46:51.430 --> 00:46:54.680 align:middle line:84%
of their intermolecular
interactions.

00:46:54.680 --> 00:47:03.050 align:middle line:90%


00:47:03.050 --> 00:47:03.550 align:middle line:90%
All right.

00:47:03.550 --> 00:47:08.800 align:middle line:84%
Formally, this is
how the story goes.

00:47:08.800 --> 00:47:12.330 align:middle line:84%
We will first define
ideal behavior.

00:47:12.330 --> 00:47:16.950 align:middle line:84%
And just so this will
be our-- this will be

00:47:16.950 --> 00:47:18.830 align:middle line:90%
the final result of this slide.

00:47:18.830 --> 00:47:21.930 align:middle line:90%


00:47:21.930 --> 00:47:25.680 align:middle line:90%
And the motivation is that--

00:47:25.680 --> 00:47:29.610 align:middle line:84%
of this definition that
we are going to do here--

00:47:29.610 --> 00:47:35.610 align:middle line:84%
is that we will find that
under this approximation,

00:47:35.610 --> 00:47:37.530 align:middle line:90%
or in this limit--

00:47:37.530 --> 00:47:43.650 align:middle line:84%
when these
assumptions are valid,

00:47:43.650 --> 00:47:46.800 align:middle line:84%
then we obtain a
famous result, which

00:47:46.800 --> 00:47:50.610 align:middle line:84%
is the Dalton law of
additive partial pressures.

00:47:50.610 --> 00:47:54.870 align:middle line:84%
So the pressure
of the mixture is

00:47:54.870 --> 00:47:57.420 align:middle line:84%
going to be equal to the
sum of the partial pressures

00:47:57.420 --> 00:48:02.320 align:middle line:84%
of the constituents
of the mixture.

00:48:02.320 --> 00:48:04.310 align:middle line:84%
But in general,
that is not true.

00:48:04.310 --> 00:48:07.770 align:middle line:84%
Not-- I mean, this is not
true for a non-ideal mixture.

00:48:07.770 --> 00:48:12.810 align:middle line:90%


00:48:12.810 --> 00:48:14.680 align:middle line:84%
So the derivation
goes as follows.

00:48:14.680 --> 00:48:19.940 align:middle line:84%
We start from the Euler relation
written for the mixture.

00:48:19.940 --> 00:48:22.880 align:middle line:90%


00:48:22.880 --> 00:48:28.816 align:middle line:84%
We write also the Euler relation
for the pure components.

00:48:28.816 --> 00:48:32.070 align:middle line:90%


00:48:32.070 --> 00:48:35.130 align:middle line:84%
And when-- and here,
I'm going to write it

00:48:35.130 --> 00:48:39.570 align:middle line:84%
for the pure components
at just on the other side

00:48:39.570 --> 00:48:44.370 align:middle line:84%
of the semi-permeable
membrane so they

00:48:44.370 --> 00:48:46.990 align:middle line:84%
are at the same
temperature of the mixture,

00:48:46.990 --> 00:48:49.680 align:middle line:90%
but at the partial pressure.

00:48:49.680 --> 00:48:56.860 align:middle line:84%
So these uii here, I'm not
writing the explicit dependence,

00:48:56.860 --> 00:49:03.960 align:middle line:84%
but I'm doing it here,
are to be evaluated at T

00:49:03.960 --> 00:49:08.070 align:middle line:90%
and at the partial pressure.

00:49:08.070 --> 00:49:16.050 align:middle line:84%
Then I take these
individual pure constituent

00:49:16.050 --> 00:49:18.220 align:middle line:90%
Euler relations, we multiply--

00:49:18.220 --> 00:49:24.660 align:middle line:84%
I multiply them by the amount ni
with which that constituent is

00:49:24.660 --> 00:49:29.010 align:middle line:84%
present in the mixture and
sum over all components.

00:49:29.010 --> 00:49:32.230 align:middle line:84%
And then I take this
summation, subtract it

00:49:32.230 --> 00:49:39.190 align:middle line:84%
from the Euler relation for the
mixture, and here is the result.

00:49:39.190 --> 00:49:43.030 align:middle line:84%
So you can still identify
here the Euler relation

00:49:43.030 --> 00:49:45.340 align:middle line:84%
for the mixture is
given by this term.

00:49:45.340 --> 00:49:52.210 align:middle line:90%
This TS minus pV plus mui ni.

00:49:52.210 --> 00:49:57.190 align:middle line:84%
And what I subtracted is
the summation of the ni's

00:49:57.190 --> 00:49:58.285 align:middle line:90%
with which--

00:49:58.285 --> 00:50:01.150 align:middle line:84%
that are the amounts
in the mixture

00:50:01.150 --> 00:50:08.080 align:middle line:84%
times the single component,
pure component, Euler relation.

00:50:08.080 --> 00:50:20.850 align:middle line:84%
uii minus T sii plus pii
vii and plus the mu's.

00:50:20.850 --> 00:50:29.170 align:middle line:90%


00:50:29.170 --> 00:50:34.400 align:middle line:84%
Actually, there's a
mistake here because there

00:50:34.400 --> 00:50:35.730 align:middle line:90%
shouldn't be a summation here.

00:50:35.730 --> 00:50:37.430 align:middle line:84%
This is, again, a
cut-and-paste problem.

00:50:37.430 --> 00:50:41.450 align:middle line:84%
This should be-- I hope I'll
remember all these things

00:50:41.450 --> 00:50:44.210 align:middle line:90%
to correct in the viewgraph.

00:50:44.210 --> 00:50:48.330 align:middle line:84%
Yeah, so for the pure
component, there's only one.

00:50:48.330 --> 00:50:49.650 align:middle line:90%
And so there is no summation.

00:50:49.650 --> 00:50:53.620 align:middle line:90%


00:50:53.620 --> 00:51:02.590 align:middle line:84%
OK, now, look at these
elements of the last summation.

00:51:02.590 --> 00:51:05.410 align:middle line:84%
They are identically 0
because of the condition

00:51:05.410 --> 00:51:08.620 align:middle line:84%
for mutual equilibrium
that the chemical potential

00:51:08.620 --> 00:51:12.550 align:middle line:84%
of component i in the mixture is
equal to the chemical potential

00:51:12.550 --> 00:51:14.830 align:middle line:84%
of the pure component
when evaluated

00:51:14.830 --> 00:51:16.370 align:middle line:90%
at the partial pressure.

00:51:16.370 --> 00:51:19.270 align:middle line:90%
So these are 0.

00:51:19.270 --> 00:51:23.080 align:middle line:84%
And then I get a relation here,
which contains the pressure

00:51:23.080 --> 00:51:25.030 align:middle line:84%
and contains the
partial pressures,

00:51:25.030 --> 00:51:27.910 align:middle line:84%
because after all, what
we wanted to see here is,

00:51:27.910 --> 00:51:31.880 align:middle line:84%
is there a relation between
pressure and partial pressures?

00:51:31.880 --> 00:51:34.520 align:middle line:84%
And here is the result.
So I put in evidence,

00:51:34.520 --> 00:51:38.630 align:middle line:84%
I solve this expression
for the total pressure,

00:51:38.630 --> 00:51:42.670 align:middle line:84%
and here is how it depends
on the partial pressures.

00:51:42.670 --> 00:51:45.490 align:middle line:90%
It's all over.

00:51:45.490 --> 00:51:57.470 align:middle line:84%
However, if I make these three
assumptions, you see this?

00:51:57.470 --> 00:52:03.380 align:middle line:84%
The first assumption kills
these terms in parentheses.

00:52:03.380 --> 00:52:07.580 align:middle line:84%
The second assumption
kills this other term.

00:52:07.580 --> 00:52:13.970 align:middle line:84%
The third assumption, and note
here that this is not a mistake,

00:52:13.970 --> 00:52:16.300 align:middle line:84%
here, there is no
summation sign.

00:52:16.300 --> 00:52:20.730 align:middle line:90%


00:52:20.730 --> 00:52:25.210 align:middle line:84%
So if this holds, then
we'll discuss what it means.

00:52:25.210 --> 00:52:30.810 align:middle line:84%
But if this holds, it means
that inside this summation,

00:52:30.810 --> 00:52:39.490 align:middle line:84%
every time I see ni times
vii, I can put capital V,

00:52:39.490 --> 00:52:41.960 align:middle line:90%
which doesn't depend on i.

00:52:41.960 --> 00:52:43.390 align:middle line:90%
It doesn't have a subscript.

00:52:43.390 --> 00:52:46.270 align:middle line:84%
So it goes outside
of the summation

00:52:46.270 --> 00:52:49.720 align:middle line:84%
and it cancels with the
V in the denominator.

00:52:49.720 --> 00:52:52.540 align:middle line:84%
And then what I'm left
with in the summation

00:52:52.540 --> 00:52:54.670 align:middle line:90%
is just the partial pressures.

00:52:54.670 --> 00:52:59.680 align:middle line:84%
So I finally get that the
pressure, if these three

00:52:59.680 --> 00:53:06.670 align:middle line:84%
assumptions are together,
all holding, the pressure

00:53:06.670 --> 00:53:08.660 align:middle line:84%
is equal to the sum of
the partial pressures.

00:53:08.660 --> 00:53:10.310 align:middle line:90%
And this is Dalton's law.

00:53:10.310 --> 00:53:17.430 align:middle line:90%


00:53:17.430 --> 00:53:27.950 align:middle line:84%
Let's see how we could
interpret those conditions that

00:53:27.950 --> 00:53:29.935 align:middle line:84%
define the ideal
Gibbs-Dalton behavior.

00:53:29.935 --> 00:53:32.570 align:middle line:90%


00:53:32.570 --> 00:53:36.420 align:middle line:84%
Essentially, it says that
I can see the mixture,

00:53:36.420 --> 00:53:40.880 align:middle line:84%
or at least I can model the
properties of the mixture,

00:53:40.880 --> 00:53:47.540 align:middle line:84%
as the model, as the properties
of a composite system in which I

00:53:47.540 --> 00:53:54.950 align:middle line:84%
have the pure components living
each one in the same volume

00:53:54.950 --> 00:53:59.570 align:middle line:84%
of the mixture, so
boxes of the same size,

00:53:59.570 --> 00:54:05.755 align:middle line:84%
at the same temperature and
at the partial pressure.

00:54:05.755 --> 00:54:08.890 align:middle line:90%


00:54:08.890 --> 00:54:18.020 align:middle line:84%
OK, then in these conditions,
this is the specific--

00:54:18.020 --> 00:54:20.480 align:middle line:84%
they have a specific
energy since they are pure.

00:54:20.480 --> 00:54:21.980 align:middle line:84%
For example, this
is component, say,

00:54:21.980 --> 00:54:25.790 align:middle line:84%
component i has a
specific energy, which

00:54:25.790 --> 00:54:28.850 align:middle line:84%
is u double i
evaluated at T and pii

00:54:28.850 --> 00:54:33.230 align:middle line:84%
because here it is at
the partial pressure.

00:54:33.230 --> 00:54:35.750 align:middle line:90%
The same for the entropy.

00:54:35.750 --> 00:54:49.400 align:middle line:84%
And now, if I use the fact
that energy and entropy are

00:54:49.400 --> 00:55:00.553 align:middle line:84%
additive properties, the energy
of this one is n1 times u11.

00:55:00.553 --> 00:55:03.770 align:middle line:90%


00:55:03.770 --> 00:55:08.270 align:middle line:90%
And so I sum up ni times uii.

00:55:08.270 --> 00:55:13.940 align:middle line:84%
And that gives me
the properties,

00:55:13.940 --> 00:55:15.300 align:middle line:90%
the property of the mixture.

00:55:15.300 --> 00:55:19.400 align:middle line:90%
So sum of ni times uii.

00:55:19.400 --> 00:55:26.570 align:middle line:84%
So that's-- this last equation
is the defining equation

00:55:26.570 --> 00:55:29.900 align:middle line:90%
for ideal Gibbs-Dalton behavior.

00:55:29.900 --> 00:55:32.510 align:middle line:84%
The first one here
I have added also

00:55:32.510 --> 00:55:36.780 align:middle line:84%
the general expression,
which is valid always,

00:55:36.780 --> 00:55:43.880 align:middle line:84%
which gives the property in
terms of the partial properties.

00:55:43.880 --> 00:55:45.220 align:middle line:90%
It's the same for the entropy.

00:55:45.220 --> 00:55:46.450 align:middle line:90%
So it's additive.

00:55:46.450 --> 00:55:48.750 align:middle line:90%
So I can view this.

00:55:48.750 --> 00:55:52.575 align:middle line:84%
And instead-- and here, I've
used the fact that each--

00:55:52.575 --> 00:55:55.320 align:middle line:90%


00:55:55.320 --> 00:55:58.440 align:middle line:84%
you see here, I could also
write the specific volume

00:55:58.440 --> 00:56:03.780 align:middle line:84%
of the constituent being
at the partial pressure.

00:56:03.780 --> 00:56:06.430 align:middle line:90%
And the fact that it--

00:56:06.430 --> 00:56:09.130 align:middle line:84%
that in the same amount of
the mixture, it occupies,

00:56:09.130 --> 00:56:15.480 align:middle line:84%
the same volume of the mixture
is the sort of interpretation

00:56:15.480 --> 00:56:16.520 align:middle line:90%
of this formula here.

00:56:16.520 --> 00:56:20.080 align:middle line:90%


00:56:20.080 --> 00:56:29.080 align:middle line:84%
It also goes together
with the idea

00:56:29.080 --> 00:56:33.130 align:middle line:84%
that in the gas limit,
when molecules live

00:56:33.130 --> 00:56:39.700 align:middle line:84%
far apart from one another in
either this or the Lennard-Jones

00:56:39.700 --> 00:56:43.783 align:middle line:84%
kind of potential, if they're
on average, they live here.

00:56:43.783 --> 00:56:50.080 align:middle line:90%


00:56:50.080 --> 00:56:56.320 align:middle line:84%
Essentially, they stay in-- they
occupy the volume of the mixture

00:56:56.320 --> 00:57:00.060 align:middle line:84%
as if they were by themselves,
each molecule by itself.

00:57:00.060 --> 00:57:04.360 align:middle line:90%


00:57:04.360 --> 00:57:08.350 align:middle line:90%
And that's why we have--

00:57:08.350 --> 00:57:10.990 align:middle line:84%
they obey the ideal
gas law, which

00:57:10.990 --> 00:57:16.380 align:middle line:84%
is valid for the single
molecule in a box

00:57:16.380 --> 00:57:18.430 align:middle line:90%
even if I have many box--

00:57:18.430 --> 00:57:20.260 align:middle line:90%
many particles in that box.

00:57:20.260 --> 00:57:25.060 align:middle line:84%
But it is as if each one
uses the box by itself.

00:57:25.060 --> 00:57:27.970 align:middle line:84%
It doesn't recognize on average,
the presence of the other,

00:57:27.970 --> 00:57:33.210 align:middle line:84%
even though it does continuously
collide with the other.

00:57:33.210 --> 00:57:38.130 align:middle line:90%
But the time that it takes--

00:57:38.130 --> 00:57:43.050 align:middle line:84%
that the collision--
and so that--

00:57:43.050 --> 00:57:44.550 align:middle line:90%
it lasts.

00:57:44.550 --> 00:57:46.680 align:middle line:84%
The time that the
collision lasts

00:57:46.680 --> 00:57:49.740 align:middle line:84%
is very short with respect
to the rest of the time

00:57:49.740 --> 00:57:53.940 align:middle line:84%
that the particle
moves freely in space

00:57:53.940 --> 00:57:58.600 align:middle line:84%
before encountering the other
molecule for the next collision.

00:57:58.600 --> 00:58:01.330 align:middle line:90%


00:58:01.330 --> 00:58:07.780 align:middle line:84%
So that's the ideal
Gibbs-Dalton behavior.

00:58:07.780 --> 00:58:10.510 align:middle line:84%
And if we apply
it now, we haven't

00:58:10.510 --> 00:58:11.970 align:middle line:90%
assumed yet the ideal gas.

00:58:11.970 --> 00:58:14.670 align:middle line:90%


00:58:14.670 --> 00:58:16.990 align:middle line:84%
So now, if we in
addition to those,

00:58:16.990 --> 00:58:26.090 align:middle line:84%
we also assume that each
pure substance behaves

00:58:26.090 --> 00:58:29.630 align:middle line:84%
as an ideal gas, so
it obeys the equation

00:58:29.630 --> 00:58:34.640 align:middle line:84%
of state of an ideal gas in
the full range of pressures

00:58:34.640 --> 00:58:39.740 align:middle line:84%
from the partial pressure to the
total pressure of the mixture,

00:58:39.740 --> 00:58:42.670 align:middle line:84%
I shouldn't call it total, to
the pressure of the mixture.

00:58:42.670 --> 00:58:45.440 align:middle line:90%


00:58:45.440 --> 00:58:48.590 align:middle line:84%
So I can write the
equation of state

00:58:48.590 --> 00:58:54.650 align:middle line:84%
for the gas pV equals RT
both at partial pressure

00:58:54.650 --> 00:58:56.380 align:middle line:84%
and at the pressure
of the mixture.

00:58:56.380 --> 00:59:00.910 align:middle line:90%


00:59:00.910 --> 00:59:09.035 align:middle line:84%
Then you see from assumption
three, which is this,

00:59:09.035 --> 00:59:17.180 align:middle line:84%
I substitute this,
obtain this result.

00:59:17.180 --> 00:59:20.005 align:middle line:84%
So I obtain the partial
pressure written this way.

00:59:20.005 --> 00:59:23.440 align:middle line:90%


00:59:23.440 --> 00:59:29.890 align:middle line:84%
Now, I'm using what we proved
in the Gibbs-Dalton theorem,

00:59:29.890 --> 00:59:36.460 align:middle line:84%
about the Dalton law that
the pressure of the mixture

00:59:36.460 --> 00:59:38.720 align:middle line:84%
is the sum of the
partial pressures.

00:59:38.720 --> 00:59:42.480 align:middle line:84%
So take the sum
of these ones, see

00:59:42.480 --> 00:59:47.270 align:middle line:84%
RT and V do not have subscripts,
so they go out of the summation.

00:59:47.270 --> 00:59:49.390 align:middle line:84%
I'm left with the
sum of the n's,

00:59:49.390 --> 00:59:55.450 align:middle line:84%
which is just the total n of
the particles in the mixture.

00:59:55.450 --> 00:59:58.600 align:middle line:90%
So here, what do I get?

00:59:58.600 --> 01:00:01.700 align:middle line:90%
That pV equals nRT.

01:00:01.700 --> 01:00:09.640 align:middle line:84%
So it means that also the
mixture behaves as an ideal gas.

01:00:09.640 --> 01:00:14.630 align:middle line:84%
So what this proves is that
an ideal Gibbs-Dalton mixture

01:00:14.630 --> 01:00:19.490 align:middle line:84%
of ideal gases
obeys the equation

01:00:19.490 --> 01:00:21.380 align:middle line:90%
of state of an ideal gas.

01:00:21.380 --> 01:00:23.065 align:middle line:90%
So it is an ideal gas itself.

01:00:23.065 --> 01:00:25.910 align:middle line:90%


01:00:25.910 --> 01:00:37.400 align:middle line:84%
And the other important result
is that if you extract RT over V

01:00:37.400 --> 01:00:39.770 align:middle line:84%
from here, you see
that you can write it

01:00:39.770 --> 01:00:43.760 align:middle line:84%
as partial pressure
over the amount.

01:00:43.760 --> 01:00:47.810 align:middle line:84%
And RT over V from
here, it's the pressure

01:00:47.810 --> 01:00:49.970 align:middle line:90%
over the total amount.

01:00:49.970 --> 01:00:56.900 align:middle line:84%
So that's-- essentially you
combine these two and you obtain

01:00:56.900 --> 01:01:01.100 align:middle line:84%
that the ratio of the partial
pressure to the total pressure

01:01:01.100 --> 01:01:06.410 align:middle line:84%
is equal to the ratio of the
individual amount with the total

01:01:06.410 --> 01:01:10.300 align:middle line:84%
amount, which is
the mole fraction.

01:01:10.300 --> 01:01:13.300 align:middle line:84%
In other words, the
partial pressure

01:01:13.300 --> 01:01:17.860 align:middle line:84%
is given by the mole
fraction of that constituent

01:01:17.860 --> 01:01:22.325 align:middle line:84%
times the pressure
of the mixture.

01:01:22.325 --> 01:01:26.720 align:middle line:90%


01:01:26.720 --> 01:01:37.160 align:middle line:84%
And this relation, if we
put it in this relation

01:01:37.160 --> 01:01:42.560 align:middle line:84%
that we have derived
before, so pii over p

01:01:42.560 --> 01:01:51.320 align:middle line:84%
becomes in the limit of
a Gibbs-Dalton mixture.

01:01:51.320 --> 01:01:54.450 align:middle line:90%
That is the mole fraction.

01:01:54.450 --> 01:01:59.050 align:middle line:84%
So this is RT the logarithm
of the mole fraction.

01:01:59.050 --> 01:02:06.210 align:middle line:90%


01:02:06.210 --> 01:02:08.150 align:middle line:84%
And this is a very
important relation.

01:02:08.150 --> 01:02:12.230 align:middle line:90%


01:02:12.230 --> 01:02:15.185 align:middle line:84%
It gives the chemical
potential of one constituent

01:02:15.185 --> 01:02:16.640 align:middle line:90%
in the mixture.

01:02:16.640 --> 01:02:21.690 align:middle line:84%
In terms of the chemical
potential that it has,

01:02:21.690 --> 01:02:24.920 align:middle line:84%
when it is a pure substance,
at the same temperature

01:02:24.920 --> 01:02:27.530 align:middle line:90%
and pressure of the mixture.

01:02:27.530 --> 01:02:32.660 align:middle line:84%
Plus RT, the log of
its mole fraction,

01:02:32.660 --> 01:02:36.565 align:middle line:84%
of the mole fraction with which
it appears in the mixture.

01:02:36.565 --> 01:02:41.330 align:middle line:90%


01:02:41.330 --> 01:02:46.200 align:middle line:84%
So it doesn't depend on
other things of the mixture.

01:02:46.200 --> 01:02:54.070 align:middle line:84%
For example, what are the other
components, or how many they

01:02:54.070 --> 01:03:00.070 align:middle line:84%
are except that all we need
is to know what fraction

01:03:00.070 --> 01:03:03.650 align:middle line:84%
our component occupies
in the mixture.

01:03:03.650 --> 01:03:11.300 align:middle line:90%


01:03:11.300 --> 01:03:28.250 align:middle line:84%
OK, the first few
lines of this slide

01:03:28.250 --> 01:03:34.970 align:middle line:84%
are just a cut and
paste from the previous.

01:03:34.970 --> 01:03:38.930 align:middle line:84%
But here, we add
some other items.

01:03:38.930 --> 01:03:42.330 align:middle line:84%
For example, we
compute the entropy--

01:03:42.330 --> 01:03:48.950 align:middle line:84%
the partial entropy of the
component in the mixture,

01:03:48.950 --> 01:03:53.000 align:middle line:84%
as you remember,
is this derivative.

01:03:53.000 --> 01:04:04.330 align:middle line:84%
It is equal to the
pure component entropy

01:04:04.330 --> 01:04:09.130 align:middle line:90%
plus a term that in--

01:04:09.130 --> 01:04:13.300 align:middle line:84%
when we define the entropy of
mixing at the beginning today,

01:04:13.300 --> 01:04:18.250 align:middle line:90%
this is delta si mix.

01:04:18.250 --> 01:04:24.790 align:middle line:84%
But if we-- since now, for
this ideal gas mixture of ideal

01:04:24.790 --> 01:04:27.430 align:middle line:84%
gases, we have the expression
for the chemical potential

01:04:27.430 --> 01:04:29.470 align:middle line:90%
in terms of--

01:04:29.470 --> 01:04:34.060 align:middle line:84%
explicitly here, taking the
derivative with respect to T,

01:04:34.060 --> 01:04:39.640 align:middle line:84%
we see leaves just R
times the log of y.

01:04:39.640 --> 01:04:44.290 align:middle line:84%
And since there is a minus sign
here, this is minus R log of y.

01:04:44.290 --> 01:04:47.720 align:middle line:84%
Essentially, this-- and
we'll return to this later,

01:04:47.720 --> 01:04:56.890 align:middle line:84%
but this says that the entropy
of isothermobaric mixing

01:04:56.890 --> 01:05:03.740 align:middle line:84%
of that molecule is equal
to minus R log of y.

01:05:03.740 --> 01:05:12.610 align:middle line:90%


01:05:12.610 --> 01:05:24.320 align:middle line:84%
And this is also equal to the
pure component entropy evaluated

01:05:24.320 --> 01:05:27.230 align:middle line:90%
at pii.

01:05:27.230 --> 01:05:45.360 align:middle line:84%
This is because you
remember for a gas,

01:05:45.360 --> 01:05:54.540 align:middle line:84%
for an ideal gas, if I evaluate
the difference in the entropy

01:05:54.540 --> 01:06:02.150 align:middle line:84%
at different temperature and
pressure, OK, this is equal to--

01:06:02.150 --> 01:06:04.700 align:middle line:90%


01:06:04.700 --> 01:06:05.900 align:middle line:90%
and this is the perfect--

01:06:05.900 --> 01:06:08.540 align:middle line:84%
let's suppose it's
a perfect gas.

01:06:08.540 --> 01:06:16.790 align:middle line:84%
It's T2 over T1 minus
R log p2 over p1.

01:06:16.790 --> 01:06:26.180 align:middle line:84%
So in this relation
here, we have s evaluated

01:06:26.180 --> 01:06:48.920 align:middle line:90%
at pii minus s evaluated at p.

01:06:48.920 --> 01:06:50.190 align:middle line:90%
Same temperature.

01:06:50.190 --> 01:06:53.190 align:middle line:84%
So this doesn't give
any contribution.

01:06:53.190 --> 01:06:59.000 align:middle line:84%
So I'm left with minus
R log of pii over p.

01:06:59.000 --> 01:07:06.490 align:middle line:84%
But that, in our limit of ideal
mixture, is the mole fraction.

01:07:06.490 --> 01:07:09.320 align:middle line:90%


01:07:09.320 --> 01:07:14.000 align:middle line:84%
So hopefully, what I've
written on the board

01:07:14.000 --> 01:07:16.340 align:middle line:90%
is this relation here.

01:07:16.340 --> 01:07:19.195 align:middle line:84%
That's to justify
this equal sign.

01:07:19.195 --> 01:07:23.090 align:middle line:90%


01:07:23.090 --> 01:07:28.400 align:middle line:84%
We can also compute
the partial volume,

01:07:28.400 --> 01:07:33.515 align:middle line:84%
taking the derivative of
this with respect to p

01:07:33.515 --> 01:07:36.920 align:middle line:84%
and you see that since this
last term doesn't have pressure,

01:07:36.920 --> 01:07:40.880 align:middle line:84%
I just pick up something
from the derivative

01:07:40.880 --> 01:07:42.920 align:middle line:84%
of the chemical potential
of the pure component.

01:07:42.920 --> 01:07:46.240 align:middle line:90%
And that's the specific volume.

01:07:46.240 --> 01:07:49.440 align:middle line:90%


01:07:49.440 --> 01:07:53.400 align:middle line:84%
So here, we see that there
is no volume of mixing.

01:07:53.400 --> 01:07:55.290 align:middle line:90%
There is no iso--

01:07:55.290 --> 01:08:04.230 align:middle line:84%
the delta-- essentially, we
are proving that delta vi mix

01:08:04.230 --> 01:08:07.080 align:middle line:84%
for a Gibbs-Dalton
mixture of ideal gases

01:08:07.080 --> 01:08:10.810 align:middle line:90%
and so on is equal to 0.

01:08:10.810 --> 01:08:16.180 align:middle line:84%
Up here, we proved that
this is equal to delta si

01:08:16.180 --> 01:08:20.400 align:middle line:84%
mix for a Gibbs-Dalton
mixture of ideal gases.

01:08:20.400 --> 01:08:23.390 align:middle line:90%


01:08:23.390 --> 01:08:25.606 align:middle line:84%
I should write it
because otherwise--

01:08:25.606 --> 01:08:40.174 align:middle line:90%


01:08:40.174 --> 01:08:43.160 align:middle line:90%
The same for the enthalpy.

01:08:43.160 --> 01:08:50.210 align:middle line:84%
Remember that derivative that I
emphasized this morning earlier,

01:08:50.210 --> 01:08:53.960 align:middle line:84%
if I take the expression for the
chemical potential divided by T

01:08:53.960 --> 01:08:59.790 align:middle line:84%
and take the derivative
with respect to 1 over t,

01:08:59.790 --> 01:09:02.910 align:middle line:84%
OK, well, if I
divide this by T, it

01:09:02.910 --> 01:09:04.899 align:middle line:84%
becomes independent
of temperature.

01:09:04.899 --> 01:09:06.899 align:middle line:84%
So when I take the
derivative with respect

01:09:06.899 --> 01:09:10.170 align:middle line:84%
to any function of temperature,
it doesn't contribute anything.

01:09:10.170 --> 01:09:17.910 align:middle line:84%
So that means that the partial
enthalpy is related just

01:09:17.910 --> 01:09:26.270 align:middle line:84%
to the specific enthalpy of
the gas, which here also, I

01:09:26.270 --> 01:09:30.740 align:middle line:84%
removed the pressure dependence,
because for an ideal gas,

01:09:30.740 --> 01:09:35.250 align:middle line:84%
the enthalpy depends
only on temperature.

01:09:35.250 --> 01:09:38.410 align:middle line:90%
And similarly for the--

01:09:38.410 --> 01:09:47.020 align:middle line:84%
so that also proves that
also delta h mix equals 0.

01:09:47.020 --> 01:09:53.100 align:middle line:90%


01:09:53.100 --> 01:09:56.290 align:middle line:84%
And remember what
these properties are.

01:09:56.290 --> 01:09:57.870 align:middle line:84%
These are the things
that I measure

01:09:57.870 --> 01:10:01.430 align:middle line:84%
when I add a little bit of
a substance to my mixture.

01:10:01.430 --> 01:10:08.795 align:middle line:84%
If I do it with an ideal mixture
of ideal gases, those are 0.

01:10:08.795 --> 01:10:13.810 align:middle line:90%


01:10:13.810 --> 01:10:21.640 align:middle line:84%
We can also prove for a gas,
for this kind of mixture,

01:10:21.640 --> 01:10:31.440 align:middle line:84%
the so-called Amagat law
of additive volumes, which

01:10:31.440 --> 01:10:34.830 align:middle line:90%
can be interpreted this way.

01:10:34.830 --> 01:10:46.532 align:middle line:84%
Suppose I take my
pure components

01:10:46.532 --> 01:10:51.860 align:middle line:84%
that you remember from when we
interpreted the mixture before,

01:10:51.860 --> 01:10:55.420 align:middle line:84%
if they are at the
partial pressure,

01:10:55.420 --> 01:10:59.200 align:middle line:84%
they occupy the entire
volume of the mixture.

01:10:59.200 --> 01:11:05.950 align:middle line:84%
But if I squeeze them from the
partial pressure to the pressure

01:11:05.950 --> 01:11:09.880 align:middle line:84%
of the mixture, they are going
to occupy a volume, which

01:11:09.880 --> 01:11:17.290 align:middle line:84%
is called the proper volume, V
prime, which see, this is not--

01:11:17.290 --> 01:11:20.630 align:middle line:84%
So this is the
volume they occupy

01:11:20.630 --> 01:11:23.540 align:middle line:84%
at the same temperature
and pressure of the mixture

01:11:23.540 --> 01:11:24.475 align:middle line:90%
when pure.

01:11:24.475 --> 01:11:28.581 align:middle line:90%


01:11:28.581 --> 01:11:31.070 align:middle line:84%
And I do the same
for all of them.

01:11:31.070 --> 01:11:34.900 align:middle line:84%
So they are all squeezed at the
same pressure of the mixture.

01:11:34.900 --> 01:11:38.860 align:middle line:84%
Well, it turns out that
the sum of these volumes

01:11:38.860 --> 01:11:42.195 align:middle line:84%
is equal to the
volume of the mixture.

01:11:42.195 --> 01:11:49.051 align:middle line:90%


01:11:49.051 --> 01:11:52.785 align:middle line:84%
And that is Amagat's
law of additive volumes.

01:11:52.785 --> 01:12:05.680 align:middle line:90%


01:12:05.680 --> 01:12:11.990 align:middle line:84%
OK, so now, let's
apply for example,

01:12:11.990 --> 01:12:17.060 align:middle line:84%
for an important example,
what we have seen.

01:12:17.060 --> 01:12:21.790 align:middle line:84%
So we want to compute
the so-called--

01:12:21.790 --> 01:12:24.490 align:middle line:84%
the bottom line
here is a formula

01:12:24.490 --> 01:12:31.580 align:middle line:84%
that we call the entropy of
spontaneous mixing, which

01:12:31.580 --> 01:12:36.380 align:middle line:84%
is actually going to be
an isothermobaric mixing.

01:12:36.380 --> 01:12:38.930 align:middle line:84%
So the idea here
is that we start

01:12:38.930 --> 01:12:44.720 align:middle line:84%
with a container,
which is isolated

01:12:44.720 --> 01:12:46.585 align:middle line:90%
so it doesn't experience any--

01:12:46.585 --> 01:12:49.250 align:middle line:90%


01:12:49.250 --> 01:12:54.500 align:middle line:84%
there is no heat bath, no
thermal reservoir, no contact

01:12:54.500 --> 01:12:56.010 align:middle line:90%
with thermal reservoirs.

01:12:56.010 --> 01:12:58.280 align:middle line:90%
It's just isolated.

01:12:58.280 --> 01:13:04.250 align:middle line:84%
And I have my r constituents
all in mutual equilibrium

01:13:04.250 --> 01:13:05.960 align:middle line:84%
at the same temperature
and pressure

01:13:05.960 --> 01:13:10.970 align:middle line:84%
because these partitions that
separate them are movable,

01:13:10.970 --> 01:13:15.770 align:middle line:84%
and therefore allow exchanges
of volume and energy.

01:13:15.770 --> 01:13:17.810 align:middle line:84%
So the conditions for
mutual equilibrium

01:13:17.810 --> 01:13:23.960 align:middle line:84%
is equality of temperature
and equality of pressure.

01:13:23.960 --> 01:13:32.420 align:middle line:84%
Then, I make those partitions,
those moving partitions,

01:13:32.420 --> 01:13:33.166 align:middle line:90%
disappear.

01:13:33.166 --> 01:13:38.700 align:middle line:90%


01:13:38.700 --> 01:13:44.340 align:middle line:84%
As you know, since we are
within the simple-system model,

01:13:44.340 --> 01:13:53.100 align:middle line:84%
taking the partition away
doesn't change the properties

01:13:53.100 --> 01:13:56.850 align:middle line:90%
of any of the properties.

01:13:56.850 --> 01:14:00.360 align:middle line:84%
And the moment I
do that removal,

01:14:00.360 --> 01:14:03.986 align:middle line:84%
the particles are
still separated.

01:14:03.986 --> 01:14:07.040 align:middle line:90%


01:14:07.040 --> 01:14:24.330 align:middle line:84%
So the particles--
which start from here.

01:14:24.330 --> 01:14:27.166 align:middle line:84%
And my system is the
system with the partitions.

01:14:27.166 --> 01:14:30.560 align:middle line:90%


01:14:30.560 --> 01:14:36.720 align:middle line:84%
When I remove the partitions,
the stable equilibrium state,

01:14:36.720 --> 01:14:40.320 align:middle line:84%
and the new system-- there
is a new system because I've

01:14:40.320 --> 01:14:44.070 align:middle line:84%
changed the internal
structure, it

01:14:44.070 --> 01:14:50.060 align:middle line:84%
has a new curve for the
stable equilibrium states.

01:14:50.060 --> 01:14:57.590 align:middle line:90%


01:14:57.590 --> 01:15:01.670 align:middle line:84%
And the moment I have
removed the partitions

01:15:01.670 --> 01:15:06.200 align:middle line:84%
and the properties haven't
changed, this state here,

01:15:06.200 --> 01:15:07.976 align:middle line:90%
which is--

01:15:07.976 --> 01:15:10.920 align:middle line:84%
which was a stable equilibrium
state with the partitions,

01:15:10.920 --> 01:15:14.300 align:middle line:84%
becomes a non-equilibrium state
with respect to the system

01:15:14.300 --> 01:15:16.190 align:middle line:90%
without partitions.

01:15:16.190 --> 01:15:22.070 align:middle line:84%
And the system will tend
to evolve spontaneously

01:15:22.070 --> 01:15:26.140 align:middle line:84%
towards a new equilibrium, which
is going to be the mixture.

01:15:26.140 --> 01:15:29.860 align:middle line:90%


01:15:29.860 --> 01:15:31.750 align:middle line:90%
The particles will mix.

01:15:31.750 --> 01:15:36.610 align:middle line:84%
And each one of
them, if you think

01:15:36.610 --> 01:15:39.320 align:middle line:84%
in terms of the single
particle contribution,

01:15:39.320 --> 01:15:47.190 align:middle line:84%
each particle here was
squeezed to a small volume.

01:15:47.190 --> 01:15:50.860 align:middle line:84%
And now, it sees the
entire volume available.

01:15:50.860 --> 01:15:53.340 align:middle line:90%
So it expands.

01:15:53.340 --> 01:15:55.780 align:middle line:84%
And the same for the particles
here, and the same for

01:15:55.780 --> 01:15:56.710 align:middle line:90%
particles there.

01:15:56.710 --> 01:16:00.690 align:middle line:84%
So each one experiences
a spontaneous expansion.

01:16:00.690 --> 01:16:07.620 align:middle line:84%
It's like if you take
the single particle view,

01:16:07.620 --> 01:16:16.150 align:middle line:84%
so say particle one,
and here, I have vacuum,

01:16:16.150 --> 01:16:21.730 align:middle line:84%
OK, I remove the
partition and the particle

01:16:21.730 --> 01:16:25.410 align:middle line:84%
now fills the entire volume
and fills the entire volume.

01:16:25.410 --> 01:16:28.530 align:middle line:84%
There is no more vacuum,
because at the beginning,

01:16:28.530 --> 01:16:33.810 align:middle line:84%
I had zero probability of
finding my particles here,

01:16:33.810 --> 01:16:38.460 align:middle line:84%
and probability 1
of finding it there.

01:16:38.460 --> 01:16:43.050 align:middle line:84%
When I remove the partition,
the particle is still one.

01:16:43.050 --> 01:16:45.540 align:middle line:84%
But now, I have an
even probability

01:16:45.540 --> 01:16:47.020 align:middle line:90%
of finding it everywhere.

01:16:47.020 --> 01:16:50.670 align:middle line:90%


01:16:50.670 --> 01:17:00.360 align:middle line:84%
OK, so for the moment,
we want to describe

01:17:00.360 --> 01:17:04.110 align:middle line:90%
that spontaneous process.

01:17:04.110 --> 01:17:08.590 align:middle line:84%
And so we want to
analyze our process here.

01:17:08.590 --> 01:17:11.290 align:middle line:84%
We have a final state
and an initial state.

01:17:11.290 --> 01:17:13.890 align:middle line:84%
And the tools are, as
usual, the energy balance

01:17:13.890 --> 01:17:15.310 align:middle line:90%
and the entropy balance.

01:17:15.310 --> 01:17:17.437 align:middle line:84%
Plus the auxiliary
balances that are

01:17:17.437 --> 01:17:23.370 align:middle line:84%
the balance for the volume,
the balance for the amounts

01:17:23.370 --> 01:17:24.760 align:middle line:90%
of the constituents.

01:17:24.760 --> 01:17:28.140 align:middle line:90%


01:17:28.140 --> 01:17:32.310 align:middle line:84%
So I need to write the various
ingredients of those balance

01:17:32.310 --> 01:17:36.580 align:middle line:84%
equations, which are the
expressions for the energy,

01:17:36.580 --> 01:17:40.590 align:middle line:84%
the volume, and the entropy
in the initial state,

01:17:40.590 --> 01:17:42.730 align:middle line:90%
and in the final state.

01:17:42.730 --> 01:17:47.880 align:middle line:84%
I've called this
final state B prime.

01:17:47.880 --> 01:17:51.360 align:middle line:84%
And I call that final
temperature T prime and pressure

01:17:51.360 --> 01:17:51.860 align:middle line:90%
p prime.

01:17:51.860 --> 01:17:55.670 align:middle line:90%


01:17:55.670 --> 01:17:58.430 align:middle line:84%
For the initial
state, things are

01:17:58.430 --> 01:18:03.480 align:middle line:84%
easy because the
components are separate.

01:18:03.480 --> 01:18:08.930 align:middle line:84%
So these are-- this
is just a composite

01:18:08.930 --> 01:18:13.670 align:middle line:90%
of separate substances.

01:18:13.670 --> 01:18:16.850 align:middle line:84%
We know how to compute
properties of pure substances.

01:18:16.850 --> 01:18:23.690 align:middle line:84%
And here in particular, they
are ideal gases, even simpler.

01:18:23.690 --> 01:18:27.440 align:middle line:84%
And so we simply have
to use additivity

01:18:27.440 --> 01:18:35.050 align:middle line:84%
for energy, for
volume, and for entropy

01:18:35.050 --> 01:18:39.610 align:middle line:84%
and sum up the energy
of each one of them.

01:18:39.610 --> 01:18:44.590 align:middle line:84%
Since u is the specific energy,
the energy of this system

01:18:44.590 --> 01:18:48.190 align:middle line:84%
is obtained by the specific
energy times the amount.

01:18:48.190 --> 01:18:51.588 align:middle line:84%
And then I sum, and
that's the additivity.

01:18:51.588 --> 01:18:53.505 align:middle line:84%
And the same for volume,
the same for entropy.

01:18:53.505 --> 01:18:57.180 align:middle line:90%


01:18:57.180 --> 01:19:09.150 align:middle line:84%
In the final state,
in the final state,

01:19:09.150 --> 01:19:12.770 align:middle line:84%
things are not as simple
because it's a mixture.

01:19:12.770 --> 01:19:15.300 align:middle line:90%


01:19:15.300 --> 01:19:19.710 align:middle line:84%
So we have to take a model
for mixture behavior.

01:19:19.710 --> 01:19:23.850 align:middle line:84%
So here, we are going to
adopt the Gibbs-Dalton--

01:19:23.850 --> 01:19:27.190 align:middle line:84%
ideal Gibbs-Dalton mixture
model for this state.

01:19:27.190 --> 01:19:31.970 align:middle line:90%


01:19:31.970 --> 01:19:35.330 align:middle line:84%
Therefore, the energy
for the mixture

01:19:35.330 --> 01:19:41.660 align:middle line:84%
is equal to the sum
weighted by the amounts

01:19:41.660 --> 01:19:51.050 align:middle line:84%
of the specific properties of
the pure components evaluated

01:19:51.050 --> 01:19:55.280 align:middle line:84%
at the temperature and
the partial pressure.

01:19:55.280 --> 01:20:00.410 align:middle line:84%
So here in principle, I
should have written comma pii.

01:20:00.410 --> 01:20:06.600 align:middle line:84%
But I didn't because I
remember that for an ideal gas,

01:20:06.600 --> 01:20:09.750 align:middle line:84%
the energy is a function
only of temperature.

01:20:09.750 --> 01:20:15.860 align:middle line:84%
So that dependence isn't
there because if you remember,

01:20:15.860 --> 01:20:20.270 align:middle line:90%
the u is equal to cv dT.

01:20:20.270 --> 01:20:25.650 align:middle line:84%
And for an ideal gas, there is
nothing, no pressure dependence.

01:20:25.650 --> 01:20:28.580 align:middle line:84%
And here, we are
talking about something

01:20:28.580 --> 01:20:31.150 align:middle line:84%
that holds for each of
the pure substances.

01:20:31.150 --> 01:20:38.950 align:middle line:90%


01:20:38.950 --> 01:20:46.230 align:middle line:84%
Then, we can use
the relation for--

01:20:46.230 --> 01:20:50.410 align:middle line:84%
this is Amagat's
relation, or you

01:20:50.410 --> 01:20:52.935 align:middle line:84%
can use, in any case,
the equation of state.

01:20:52.935 --> 01:20:57.290 align:middle line:90%


01:20:57.290 --> 01:21:01.730 align:middle line:84%
And we already proved
that V is equal to--

01:21:01.730 --> 01:21:07.940 align:middle line:84%
that the mixture of ideal gases
under the Gibbs-Dalton model

01:21:07.940 --> 01:21:09.780 align:middle line:90%
behaves itself as an ideal gas.

01:21:09.780 --> 01:21:15.050 align:middle line:84%
So there is the relation,
equation of state pV

01:21:15.050 --> 01:21:19.680 align:middle line:84%
equals nRT for the
entire mixture.

01:21:19.680 --> 01:21:22.220 align:middle line:90%
And that's what we use here.

01:21:22.220 --> 01:21:26.780 align:middle line:84%
And then for the
entropy, the entropy

01:21:26.780 --> 01:21:31.130 align:middle line:84%
is the sum of the entropies of
the specific entropies evaluated

01:21:31.130 --> 01:21:34.460 align:middle line:90%
at the partial pressures.

01:21:34.460 --> 01:21:40.410 align:middle line:84%
Now, the entropy does
depend on pressure.

01:21:40.410 --> 01:21:46.330 align:middle line:84%
So I did leave the
partial pressure

01:21:46.330 --> 01:21:52.210 align:middle line:84%
that the components
have in the final state.

01:21:52.210 --> 01:21:53.650 align:middle line:84%
So these are just
the ingredients

01:21:53.650 --> 01:21:54.820 align:middle line:90%
of the balance equations.

01:21:54.820 --> 01:21:56.860 align:middle line:84%
Now, I make the
balanced equation.

01:21:56.860 --> 01:22:02.980 align:middle line:84%
The balanced equation, when the
system is completely isolated

01:22:02.980 --> 01:22:05.590 align:middle line:90%
is that the energy is conserved.

01:22:05.590 --> 01:22:11.720 align:middle line:84%
So U final minus U
initial is equal to 0.

01:22:11.720 --> 01:22:17.630 align:middle line:84%
So I have U final, I have
U initial, I subtract them.

01:22:17.630 --> 01:22:22.800 align:middle line:84%
I can put this under
the same summation.

01:22:22.800 --> 01:22:25.970 align:middle line:84%
Then, I remember
this equation here.

01:22:25.970 --> 01:22:28.950 align:middle line:90%


01:22:28.950 --> 01:22:43.610 align:middle line:84%
And so for each of the
constituents, I can write that--

01:22:43.610 --> 01:22:49.400 align:middle line:84%
integrate from T to T
prime, this difference,

01:22:49.400 --> 01:22:52.040 align:middle line:84%
so this is the integral
from T to T prime of cv.

01:22:52.040 --> 01:22:53.735 align:middle line:84%
And here, there
should be a cvii.

01:22:53.735 --> 01:22:59.100 align:middle line:90%


01:22:59.100 --> 01:23:00.900 align:middle line:90%
OK, OK.

01:23:00.900 --> 01:23:05.020 align:middle line:84%
So this integral has
to be equal to 0.

01:23:05.020 --> 01:23:08.530 align:middle line:84%
Now, when can that
be equal to 0?

01:23:08.530 --> 01:23:11.020 align:middle line:84%
Now, here, we have to
remember a few things,

01:23:11.020 --> 01:23:19.860 align:middle line:84%
that for each pure substance,
the specific heats are

01:23:19.860 --> 01:23:23.430 align:middle line:84%
non-negative, are
greater than 0.

01:23:23.430 --> 01:23:26.910 align:middle line:84%
We proved it because they are
related to the second derivative

01:23:26.910 --> 01:23:28.330 align:middle line:90%
of the fundamental relations.

01:23:28.330 --> 01:23:32.180 align:middle line:84%
They are related to
this concavity here.

01:23:32.180 --> 01:23:35.830 align:middle line:90%


01:23:35.830 --> 01:23:41.050 align:middle line:84%
So we have an integral
of positive quantities,

01:23:41.050 --> 01:23:44.710 align:middle line:84%
of a positive function,
weighted and then

01:23:44.710 --> 01:23:47.620 align:middle line:84%
multiplied by positive numbers
because the amounts can only

01:23:47.620 --> 01:23:48.710 align:middle line:90%
be positive, of course.

01:23:48.710 --> 01:23:52.750 align:middle line:90%
It cannot be a negative amount.

01:23:52.750 --> 01:23:55.270 align:middle line:84%
So you can view
this as an integral

01:23:55.270 --> 01:24:00.430 align:middle line:84%
of a function, an
integral from, say,

01:24:00.430 --> 01:24:09.220 align:middle line:84%
x1 to x2 of a function
that has to be equal to 0,

01:24:09.220 --> 01:24:15.660 align:middle line:90%
while this function is positive.

01:24:15.660 --> 01:24:21.780 align:middle line:84%
So here is a function,
positive, and the integral

01:24:21.780 --> 01:24:27.570 align:middle line:84%
is equal to this
area from x1 to x2.

01:24:27.570 --> 01:24:31.240 align:middle line:84%
So if the function is positive
and I want the integral to be 0,

01:24:31.240 --> 01:24:35.790 align:middle line:84%
the only way is that the
interval of integration

01:24:35.790 --> 01:24:37.620 align:middle line:90%
must be 0.

01:24:37.620 --> 01:24:42.630 align:middle line:84%
So that implies that this
integral is equal to 0 only

01:24:42.630 --> 01:24:46.170 align:middle line:90%
when x2 is equal to x1.

01:24:46.170 --> 01:24:50.490 align:middle line:84%
So that proves that
the final temperature

01:24:50.490 --> 01:24:52.600 align:middle line:84%
must be equal to the
initial temperature.

01:24:52.600 --> 01:24:55.500 align:middle line:90%


01:24:55.500 --> 01:24:59.610 align:middle line:84%
We've no need to make
any assumptions of what

01:24:59.610 --> 01:25:02.070 align:middle line:84%
these functions
are, whether they

01:25:02.070 --> 01:25:05.950 align:middle line:84%
are functions of whether
they are constant or not.

01:25:05.950 --> 01:25:09.970 align:middle line:84%
They can be functions, arbitrary
functions of temperature,

01:25:09.970 --> 01:25:17.200 align:middle line:90%
still get the same result.

01:25:17.200 --> 01:25:24.220 align:middle line:84%
Then, if I make the volume
balance equation, here

01:25:24.220 --> 01:25:30.820 align:middle line:84%
is another mistake,
this is a V, not a U.

01:25:30.820 --> 01:25:35.900 align:middle line:84%
So the final volume, since we
are in the same overall box,

01:25:35.900 --> 01:25:38.180 align:middle line:84%
final volume is equal
to initial volume.

01:25:38.180 --> 01:25:40.810 align:middle line:90%
So V-- these two are equal.

01:25:40.810 --> 01:25:43.960 align:middle line:84%
If I look at this
relation here, it

01:25:43.960 --> 01:25:48.430 align:middle line:84%
says that if I put them
equal, it says that T over p

01:25:48.430 --> 01:25:51.610 align:middle line:84%
is equal to T
prime over p prime.

01:25:51.610 --> 01:25:53.620 align:middle line:84%
So that means that
if we just proved

01:25:53.620 --> 01:25:56.200 align:middle line:84%
that T prime is equal to T,
so the final temperature is

01:25:56.200 --> 01:25:59.050 align:middle line:84%
equal to the initial,
the volume balance

01:25:59.050 --> 01:26:02.020 align:middle line:84%
implies that also
the final pressure is

01:26:02.020 --> 01:26:02.910 align:middle line:90%
equal to the initial.

01:26:02.910 --> 01:26:08.250 align:middle line:90%


01:26:08.250 --> 01:26:14.180 align:middle line:84%
So spontaneous mixing with these
conditions is isothermobaric.

01:26:14.180 --> 01:26:19.910 align:middle line:90%


01:26:19.910 --> 01:26:22.435 align:middle line:84%
Different story is for
the entropy balance.

01:26:22.435 --> 01:26:27.510 align:middle line:90%


01:26:27.510 --> 01:26:33.000 align:middle line:84%
The entropy balance is written
here with another little mistake

01:26:33.000 --> 01:26:37.170 align:middle line:84%
because this should be a
capital S. So the final entropy

01:26:37.170 --> 01:26:39.023 align:middle line:90%
minus the initial entropy.

01:26:39.023 --> 01:26:42.630 align:middle line:90%


01:26:42.630 --> 01:26:44.390 align:middle line:90%
There are no interactions.

01:26:44.390 --> 01:26:47.250 align:middle line:90%
So there is no entropy transfer.

01:26:47.250 --> 01:26:49.860 align:middle line:90%
There are no heat interactions.

01:26:49.860 --> 01:26:54.370 align:middle line:84%
But there can be entropy
produced by irreversibility.

01:26:54.370 --> 01:27:01.160 align:middle line:90%


01:27:01.160 --> 01:27:03.230 align:middle line:90%
So we rewrite this.

01:27:03.230 --> 01:27:06.995 align:middle line:84%
So S here is equal
to SB minus SA.

01:27:06.995 --> 01:27:10.900 align:middle line:90%
And I have the terms here.

01:27:10.900 --> 01:27:14.290 align:middle line:90%
So I substitute.

01:27:14.290 --> 01:27:20.290 align:middle line:84%
Now, I realize that
this we can also write--

01:27:20.290 --> 01:27:23.145 align:middle line:84%
well, actually, it's
this expression here.

01:27:23.145 --> 01:27:26.320 align:middle line:90%


01:27:26.320 --> 01:27:28.580 align:middle line:90%
I don't have to re-prove it.

01:27:28.580 --> 01:27:30.550 align:middle line:90%
It's written here.

01:27:30.550 --> 01:27:33.280 align:middle line:84%
This difference is
equal to minus R log

01:27:33.280 --> 01:27:36.580 align:middle line:84%
y, which is also--
is interpreted

01:27:36.580 --> 01:27:41.290 align:middle line:84%
as the entropy of
isothermobaric mixing.

01:27:41.290 --> 01:27:48.190 align:middle line:84%
And therefore, the-- if I take
R, the minus sign, outside

01:27:48.190 --> 01:27:51.070 align:middle line:84%
of the summation, I take
also the total amount

01:27:51.070 --> 01:27:52.630 align:middle line:90%
out of the summation.

01:27:52.630 --> 01:27:57.880 align:middle line:84%
Then, I'm left inside with the
mole fraction times the log

01:27:57.880 --> 01:27:58.755 align:middle line:90%
of the mole fraction.

01:27:58.755 --> 01:28:03.040 align:middle line:90%


01:28:03.040 --> 01:28:11.260 align:middle line:84%
Now, at first sight, one would
be worried about the minus sign

01:28:11.260 --> 01:28:19.090 align:middle line:84%
because we know that the entropy
produced by irreversibility

01:28:19.090 --> 01:28:21.570 align:middle line:84%
cannot be negative,
must be positive.

01:28:21.570 --> 01:28:25.240 align:middle line:84%
But if you look at
this function y log

01:28:25.240 --> 01:28:33.880 align:middle line:84%
y, the function in the
interval between 0 and 1,

01:28:33.880 --> 01:28:37.840 align:middle line:84%
the function y log y
does something like that.

01:28:37.840 --> 01:28:43.186 align:middle line:90%


01:28:43.186 --> 01:28:45.620 align:middle line:90%
Versus y.

01:28:45.620 --> 01:28:47.690 align:middle line:90%
So it's negative.

01:28:47.690 --> 01:28:52.250 align:middle line:90%
So minus y log y is positive.

01:28:52.250 --> 01:28:53.380 align:middle line:90%
And we are safe.

01:28:53.380 --> 01:29:02.210 align:middle line:84%
That means for any reasonable,
in other words, possible values

01:29:02.210 --> 01:29:05.870 align:middle line:84%
of the mole fractions,
which of course can go only

01:29:05.870 --> 01:29:12.210 align:middle line:84%
between 0 and 1, that
function is non-negative.

01:29:12.210 --> 01:29:17.710 align:middle line:84%
But it also says that there
is entropy production.

01:29:17.710 --> 01:29:20.730 align:middle line:84%
So the process is
irreversible as we

01:29:20.730 --> 01:29:25.140 align:middle line:84%
have anticipated by
looking at the energy

01:29:25.140 --> 01:29:26.783 align:middle line:90%
versus entropy graphs.

01:29:26.783 --> 01:29:34.790 align:middle line:90%


01:29:34.790 --> 01:29:36.985 align:middle line:84%
And this is called
the entropy of mixing.

01:29:36.985 --> 01:29:44.220 align:middle line:90%


01:29:44.220 --> 01:29:51.610 align:middle line:84%
Now, so if I look at that
graph, immediately, I also

01:29:51.610 --> 01:29:58.480 align:middle line:84%
realize that I could
have done better.

01:29:58.480 --> 01:30:03.300 align:middle line:84%
In other words, we could have
done the mixing reversibly

01:30:03.300 --> 01:30:15.300 align:middle line:84%
because if instead of going
this way, I go this way,

01:30:15.300 --> 01:30:19.270 align:middle line:90%
I do not generate entropy.

01:30:19.270 --> 01:30:20.870 align:middle line:90%
And I extract some work.

01:30:20.870 --> 01:30:23.390 align:middle line:90%


01:30:23.390 --> 01:30:26.470 align:middle line:84%
So this is what we call
the adiabatic availability

01:30:26.470 --> 01:30:29.470 align:middle line:84%
of the state that is
achieved the moment I

01:30:29.470 --> 01:30:30.760 align:middle line:90%
remove the partitions.

01:30:30.760 --> 01:30:33.730 align:middle line:84%
That non-equilibrium state
has adiabatic availability

01:30:33.730 --> 01:30:36.220 align:middle line:84%
if I am quick enough,
or smart enough,

01:30:36.220 --> 01:30:39.830 align:middle line:90%
to do whatever needs to be done.

01:30:39.830 --> 01:30:44.590 align:middle line:84%
And we'll see how we
could do it in a moment.

01:30:44.590 --> 01:30:46.065 align:middle line:90%
We could extract some work.

01:30:46.065 --> 01:30:52.400 align:middle line:90%


01:30:52.400 --> 01:30:58.170 align:middle line:84%
So here is the calculation of
that adiabatic availability.

01:30:58.170 --> 01:31:04.010 align:middle line:90%


01:31:04.010 --> 01:31:13.460 align:middle line:84%
Now, the final state,
OK, what we just derived

01:31:13.460 --> 01:31:17.630 align:middle line:84%
is that if we mix this
way, the final state

01:31:17.630 --> 01:31:22.760 align:middle line:84%
has the same temperature
and pressure.

01:31:22.760 --> 01:31:27.740 align:middle line:84%
Clearly, if we go down and we
have extracted some energy,

01:31:27.740 --> 01:31:33.530 align:middle line:84%
the final state here will have
a smaller temperature, which

01:31:33.530 --> 01:31:34.945 align:middle line:90%
we call it T double prime.

01:31:34.945 --> 01:31:42.000 align:middle line:90%


01:31:42.000 --> 01:31:43.360 align:middle line:90%
And how do we measure it?

01:31:43.360 --> 01:31:46.830 align:middle line:90%
How do we do the computation?

01:31:46.830 --> 01:31:50.650 align:middle line:84%
Well, we start-- the
previous computation,

01:31:50.650 --> 01:31:52.290 align:middle line:84%
we started from
the energy balance

01:31:52.290 --> 01:31:55.890 align:middle line:84%
setting that final energy
is equal to initial energy.

01:31:55.890 --> 01:31:58.080 align:middle line:90%
That determines the temperature.

01:31:58.080 --> 01:32:01.080 align:middle line:84%
Now, we start from
the entropy balance

01:32:01.080 --> 01:32:03.720 align:middle line:84%
because for a reversible
process because we

01:32:03.720 --> 01:32:05.980 align:middle line:84%
want to extract the
adiabatic availability,

01:32:05.980 --> 01:32:08.140 align:middle line:84%
so that's a reversible
weight process.

01:32:08.140 --> 01:32:10.800 align:middle line:90%
The entropy stays constant.

01:32:10.800 --> 01:32:14.380 align:middle line:84%
We apply equality of
final and initial entropy.

01:32:14.380 --> 01:32:16.295 align:middle line:84%
And so we start from
the entropy balance.

01:32:16.295 --> 01:32:31.170 align:middle line:90%


01:32:31.170 --> 01:32:33.820 align:middle line:84%
Yeah, here is the
entropy balance.

01:32:33.820 --> 01:32:36.815 align:middle line:84%
S final minus S
initial equals 0.

01:32:36.815 --> 01:32:39.420 align:middle line:90%


01:32:39.420 --> 01:32:44.300 align:middle line:84%
So we write it this way
with the double primes.

01:32:44.300 --> 01:32:47.670 align:middle line:90%


01:32:47.670 --> 01:32:55.725 align:middle line:84%
And then this difference
here, we can--

01:32:55.725 --> 01:32:59.980 align:middle line:90%


01:32:59.980 --> 01:33:08.920 align:middle line:84%
yeah, it's evaluated in this
line because, OK, T double prime

01:33:08.920 --> 01:33:12.610 align:middle line:84%
is the final temperature
that we have.

01:33:12.610 --> 01:33:16.840 align:middle line:84%
p double prime double i
is the partial pressure

01:33:16.840 --> 01:33:20.890 align:middle line:84%
that the components will
have in that new final state.

01:33:20.890 --> 01:33:23.650 align:middle line:84%
So that partial
pressure is going

01:33:23.650 --> 01:33:28.090 align:middle line:84%
to be equal to
the mole fraction.

01:33:28.090 --> 01:33:31.660 align:middle line:84%
So that partial pressure will
be equal to the mole fraction

01:33:31.660 --> 01:33:35.670 align:middle line:84%
times the final
pressure p double prime.

01:33:35.670 --> 01:33:38.180 align:middle line:90%


01:33:38.180 --> 01:33:49.930 align:middle line:84%
But if we remember, if we
remember the question of--

01:33:49.930 --> 01:33:56.380 align:middle line:84%
if we look at the volume
balance, which is written here,

01:33:56.380 --> 01:34:02.035 align:middle line:84%
p double prime over T double
prime is equal to p over T.

01:34:02.035 --> 01:34:10.490 align:middle line:84%
So I can think of p double
prime, p double prime,

01:34:10.490 --> 01:34:13.850 align:middle line:90%
as what is it?

01:34:13.850 --> 01:34:17.500 align:middle line:90%


01:34:17.500 --> 01:34:27.416 align:middle line:84%
As p times T double
prime over T.

01:34:27.416 --> 01:34:35.710 align:middle line:84%
And that's why I am
writing this here.

01:34:35.710 --> 01:34:44.660 align:middle line:84%
Then I apply the relation
for how the entropy depends

01:34:44.660 --> 01:34:47.770 align:middle line:90%
on temperature and pressure.

01:34:47.770 --> 01:34:50.360 align:middle line:84%
Here, we also have a
temperature dependence.

01:34:50.360 --> 01:34:53.470 align:middle line:84%
So we also have the
cp log contribution

01:34:53.470 --> 01:34:57.760 align:middle line:84%
of the ratio of temperatures
minus R, the log

01:34:57.760 --> 01:34:59.960 align:middle line:90%
of the ratio of the pressures.

01:34:59.960 --> 01:35:02.600 align:middle line:90%


01:35:02.600 --> 01:35:07.160 align:middle line:84%
OK, then I can
split this logarithm

01:35:07.160 --> 01:35:08.885 align:middle line:84%
as being the logarithm
of the product,

01:35:08.885 --> 01:35:11.790 align:middle line:84%
so it's going to be the
sum of the logarithms.

01:35:11.790 --> 01:35:15.570 align:middle line:84%
So I take the
minus R log y here.

01:35:15.570 --> 01:35:18.740 align:middle line:84%
And then I combine the
log of T double prime

01:35:18.740 --> 01:35:22.940 align:middle line:84%
that appears from this
part and from that part.

01:35:22.940 --> 01:35:26.370 align:middle line:84%
It gets multiplied
by cv minus R,

01:35:26.370 --> 01:35:28.675 align:middle line:84%
but by the Mayer
relation that's cv.

01:35:28.675 --> 01:35:34.680 align:middle line:90%


01:35:34.680 --> 01:35:37.870 align:middle line:84%
OK, so we finally
have this expression.

01:35:37.870 --> 01:35:39.995 align:middle line:84%
We can put it in
the entropy balance.

01:35:39.995 --> 01:35:46.760 align:middle line:90%


01:35:46.760 --> 01:35:57.560 align:middle line:84%
Now, I see here that I could
define an average-specific heat

01:35:57.560 --> 01:36:03.560 align:middle line:84%
at constant volume of
the mixture as being--

01:36:03.560 --> 01:36:08.815 align:middle line:84%
the weighted as being
this summation here.

01:36:08.815 --> 01:36:12.462 align:middle line:90%


01:36:12.462 --> 01:36:18.990 align:middle line:84%
And then I recognize this final
term, which is very close.

01:36:18.990 --> 01:36:23.790 align:middle line:84%
I mean, it's exactly what we
called the entropy of mixing.

01:36:23.790 --> 01:36:25.980 align:middle line:90%
But in any case, by setting--

01:36:25.980 --> 01:36:30.090 align:middle line:84%
since this has to be equal
to 0 by the entropy balance,

01:36:30.090 --> 01:36:33.090 align:middle line:84%
this gives me an
expression-- a way

01:36:33.090 --> 01:36:38.660 align:middle line:84%
to calculate T double prime,
the final temperature.

01:36:38.660 --> 01:36:46.940 align:middle line:84%
And this is the result. Now, the
fact that these functions are

01:36:46.940 --> 01:36:54.000 align:middle line:84%
negative, so e to a negative
number is less than 1,

01:36:54.000 --> 01:36:57.600 align:middle line:84%
shows that, of course,
as we expected,

01:36:57.600 --> 01:36:59.550 align:middle line:84%
the final temperature
will be less

01:36:59.550 --> 01:37:01.210 align:middle line:90%
than the initial temperature.

01:37:01.210 --> 01:37:03.910 align:middle line:90%


01:37:03.910 --> 01:37:07.190 align:middle line:84%
And now that we have
the final temperature,

01:37:07.190 --> 01:37:10.100 align:middle line:84%
we can perform the
energy balance.

01:37:10.100 --> 01:37:13.600 align:middle line:84%
Now, the energy balance here,
since the system is not isolated

01:37:13.600 --> 01:37:17.980 align:middle line:84%
anymore, because we have lifted
the weight in a weight process,

01:37:17.980 --> 01:37:21.280 align:middle line:84%
we have extracted the
adiabatic availability.

01:37:21.280 --> 01:37:25.450 align:middle line:84%
So the energy
given to the weight

01:37:25.450 --> 01:37:27.580 align:middle line:84%
is equal to the difference
between the initial

01:37:27.580 --> 01:37:30.045 align:middle line:90%
and the final energy.

01:37:30.045 --> 01:37:33.110 align:middle line:90%


01:37:33.110 --> 01:37:36.650 align:middle line:84%
So by substituting these
ingredients that we calculated

01:37:36.650 --> 01:37:43.490 align:middle line:84%
up there and using the
same-- the specific heat

01:37:43.490 --> 01:37:46.280 align:middle line:84%
at constant volume, and then
the fact that the summation

01:37:46.280 --> 01:37:56.180 align:middle line:84%
we defined as sort of an average
mixing mixture, specific heat

01:37:56.180 --> 01:37:57.055 align:middle line:90%
at constant volume.

01:37:57.055 --> 01:37:59.640 align:middle line:90%


01:37:59.640 --> 01:38:01.500 align:middle line:84%
And we substitute
T double prime.

01:38:01.500 --> 01:38:05.100 align:middle line:84%
And you compute the value for
the adiabatic availability.

01:38:05.100 --> 01:38:11.150 align:middle line:84%
So we see that this
represents this work.

01:38:11.150 --> 01:38:16.230 align:middle line:90%


01:38:16.230 --> 01:38:21.910 align:middle line:84%
Just to show you how we could
actually do it with a picture,

01:38:21.910 --> 01:38:23.590 align:middle line:84%
so we conclude, we
have one minute.

01:38:23.590 --> 01:38:26.340 align:middle line:90%


01:38:26.340 --> 01:38:27.790 align:middle line:90%
How can we do that?

01:38:27.790 --> 01:38:30.200 align:middle line:84%
Can we actually
separate a mixture?

01:38:30.200 --> 01:38:35.080 align:middle line:90%


01:38:35.080 --> 01:38:42.910 align:middle line:84%
Remember, the problem here
with the single particle,

01:38:42.910 --> 01:38:47.840 align:middle line:84%
if I have a single particle
there, and I have vacuum,

01:38:47.840 --> 01:38:51.100 align:middle line:84%
and I have this-- and instead
of removing the piston,

01:38:51.100 --> 01:39:03.250 align:middle line:84%
I can just have it move
rightward while connected

01:39:03.250 --> 01:39:05.740 align:middle line:90%
through a pulley to a weight.

01:39:05.740 --> 01:39:10.080 align:middle line:84%
And the pressure of the particle
will push it to the right.

01:39:10.080 --> 01:39:13.350 align:middle line:84%
Therefore, the particle
will do work and lift.

01:39:13.350 --> 01:39:16.550 align:middle line:90%


01:39:16.550 --> 01:39:19.850 align:middle line:84%
And similarly, if I
have this other particle

01:39:19.850 --> 01:39:23.540 align:middle line:84%
on the other different
particle on the other side,

01:39:23.540 --> 01:39:28.640 align:middle line:84%
say, suppose I have a
particle of different kind

01:39:28.640 --> 01:39:31.500 align:middle line:84%
that is confined,
that's separated,

01:39:31.500 --> 01:39:33.590 align:middle line:90%
and it's on the other side.

01:39:33.590 --> 01:39:38.240 align:middle line:84%
Also here, I can do
the same and have

01:39:38.240 --> 01:39:41.840 align:middle line:84%
the pressure of the
particle, or the particles.

01:39:41.840 --> 01:39:46.160 align:middle line:84%
Doesn't really matter because
each one acts by itself.

01:39:46.160 --> 01:39:50.120 align:middle line:90%
So that pulls this this way.

01:39:50.120 --> 01:39:53.880 align:middle line:84%
And when you have the
presence of both particles,

01:39:53.880 --> 01:39:55.290 align:middle line:84%
you have to do it
more carefully.

01:39:55.290 --> 01:40:00.120 align:middle line:84%
Instead of having an
impermeable piston,

01:40:00.120 --> 01:40:05.270 align:middle line:84%
you have to use semi-permeable
membranes so that when this one

01:40:05.270 --> 01:40:09.145 align:middle line:90%
moves to the right, it will--

01:40:09.145 --> 01:40:12.230 align:middle line:90%


01:40:12.230 --> 01:40:17.870 align:middle line:84%
so this one allows
the black particles

01:40:17.870 --> 01:40:21.290 align:middle line:90%
to freely move in and out.

01:40:21.290 --> 01:40:26.480 align:middle line:84%
And then it feels only the
pressure of the gray particles

01:40:26.480 --> 01:40:28.260 align:middle line:90%
until you move to the right.

01:40:28.260 --> 01:40:32.450 align:middle line:84%
And this other
membrane, instead, is--

01:40:32.450 --> 01:40:36.200 align:middle line:84%
allows the gray particles
through, and instead,

01:40:36.200 --> 01:40:39.110 align:middle line:84%
feels the pressure of
the black particles.

01:40:39.110 --> 01:40:44.430 align:middle line:84%
OK, so when you're done, and
if you've done it reversibly,

01:40:44.430 --> 01:40:49.680 align:middle line:84%
you have extracted this
adiabatic availability.

01:40:49.680 --> 01:40:53.020 align:middle line:84%
So I think we have
to stop here today.

01:40:53.020 --> 01:40:58.000 align:middle line:90%