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MICHAEL SCOTT ASATO CUTHBERT:
Hello, computational

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music analysts.

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I'm going to talk a little bit
today about some topics that

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are not in themselves
essentially

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computational although
having a computer

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helps but are really
about the intersection

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of mathematical and
quantitative thinking

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with music analysis, music
theory, and musicology

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or the study of music history.

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And these are some of
the things that I've

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done in my own
research that I hope

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will make you think about some
ways that data analysis can go

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beyond the score and
tell us something more

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about the history of music.

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When I'm not doing
computational music analysis,

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my other job is as a
medieval music researcher,

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and one of the
certainties I was always

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taught about medieval music
is that we've lost most of it.

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We've lost so much of it,
and it's just incredible

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how much we have.

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In fact, most people always said
that the music that survives

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is just the tip of the iceberg.

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It was first said by a very
important medieval historian--

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musicologist Nino
Pirrotta, but this term

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was picked up from on by
dozens of other people.

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And so when we think
about what's lost,

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it could be a number of
manuscripts that's lost

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or it could be things that were
lost because they were never

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written down and
we've forgotten them,

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but if we want to think about
even the things that were once

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written down on songs that
were once written down,

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the pieces that were once
written down, how many of them

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do we no longer have
any copy of at all?

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What is the tip of the iceberg?

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Is it 90%?

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That's what a lot of people say
the visible part of the iceberg

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is.

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Is it 99% lost?

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99.9% lost, or as 1%--

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basically everything.

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So I'll call that 99.9999%.

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My friend and former
teacher, Sean Gallagher

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once asked me, hey,
would there be any way--

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you're a math guy-- to prove
this, to show that it's true.

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And I immediately said, no,
there's no way we could do this.

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Then I thought a little
bit more and realized

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there are people who look at
how things get lost and stuff.

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Later on I found
this great article

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on what happens in
peer-to-peer song sharing

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when you just start
disconnecting lots of computers

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from the network as happened
during the crackdown on Napster

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and things like that.

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And they showed that
as you go from--

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if you have a 100,000
computers on a network,

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you might have 5 million songs.

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But if the network gets down
to maybe 10,000 or 15,000

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computers, you only lose
about half the songs.

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So that was interesting to me.

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That was a little
bit counterintuitive

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that you could really lose
a lot of nodes on a network

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and not lose a lot
of the content there.

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And I thought, well,
computers might

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be something like
medieval manuscripts

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that we lose a bunch, but
maybe we still have the songs.

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So I wrote two articles
about this topic.

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First is what I'm really
going to be talking about now.

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It's an article called
"Tipping the Iceberg"

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in a journal called Musica
Disciplina and another,

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it's a little bit
harder to find.

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It's called Monks, Manuscripts,
and Other Peer-to-Peer Song

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Sharing Networks
of the Middle Ages.

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It's a great book that the
University of Pennsylvania

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helped publish called
Cantus Scriptus--

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Technologies of Medieval Song.

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I like the idea of technology
existing throughout history.

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Anyhow so one of
the ways that we

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could do this is just look
at all the records of missing

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pieces and see how
many of them we have.

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And that's sarcastic,
but there are things that

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exist in the world like this--

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there's a manuscript,
it's actually

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only I think two or
four pages survive now

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that was owned by the
Duchess of Trémouille.

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So it's often called the
Trémouille manuscript.

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It's in the National
Library of Paris now.

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And if you look at
this manuscript, what--

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we only have a
couple pages of it,

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but we have the entire
index, the table of contents

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that tells you what the
names of the pieces are

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and what page they
would have been

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on in the original manuscript.

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So we can look at-- well, we
don't have this manuscript,

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but how many of
these pieces do we--

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have we lost?

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So we can see that
I've marked here,

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these are all the
pieces that were pretty

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sure we don't have copies of.

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And here's all the
pieces that we're pretty

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sure we do have copies of.

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And there's some pieces
that we can't really

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be sure they're parts
of medieval music

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traditions like the mass
that have these somewhat

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generic names like credo or
something, like if we saw,

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oh, we lost symphony.

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Well, whose symphony,
things like that.

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So when we overlay
these two together,

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we see that actually those that
survive really outrank those

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that don't.

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So in this particular index,
we have 114 compositions

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that of which 109 are
identifiable and 68% of them

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seem to survive.

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Or another thing
that I looked at

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was this collection of
sonnets by cool but second

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tier Italian poet
named Prodenzani.

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And one of the things
that makes a lot of people

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think he's second tier is he
throws in a lot of his songs

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just lists of things-- lists
of all the food they eat-- ate,

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lists of all the dances
they danced that day,

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and in this particular case,
a list of all the songs

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that were sung.

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That begins at the top of--

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nice for where we're
about to be in the year

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with the violin,
viola, something.

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They made all the may songs
like "Rosetta Che Non Cambi Mai

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Colore," "The Rose That
Never Changes Its Colors,"

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"Je Sui Nafres Tam Fort, Dolce
Sapore," et cetera, et cetera.

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We can basically figure out
which ones of these things

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are titles of songs, and then
we can see how many of them

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we know.

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So "Rosetta Che Non Cambi Mai
Colore" is a song that survives.

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So is "Je Sui Nafres Tam Fort."

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But some of them like
toward the bottom,

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"Costei Sarebbe
Bella in Paradiso,"

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we don't know that song.

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So we can look over, and, again,
we can see how many of them

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survive, how many of
them don't survive.

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And then these
other four, where--

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we can argue about, but there's
songs with similar titles.

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Are they just being
misquoted or are they same

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or is this really a
song, things like that.

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So these are the two
proportions that it could be.

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So depending on what we
look at, there's somewhere

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between 16 and 17 compositions,
and three to seven of them

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are lost.

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And 10 to 12 survive.

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So that's about 59% to 75%
of the songs here survive.

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If we look at all of the
sonnets in this collection

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by Prodenzani, there's 59
identifiable compositions,

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and 40 of them survive.

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So that's 71%

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So here's two
pieces of evidence,

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both from textual sources, to
try to see how much survives

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or how much doesn't.

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But can we do better?

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One of the things
I thought of was

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that there are people who
spend a lot of time trying

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to count things that are
difficult to count because you

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can't capture them all.

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There the animal
population in biologists,

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they are people who go out, and
they can't capture every deer

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in a forest.

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So what do they do?

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They might go out-- here's
one way that they do it.

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They might go out
at a certain point

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and go and capture
all the deer they

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can capture in a couple days.

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Maybe it's-- let's
say it's 10, 10 deer.

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And they go, and they tag the
deer in some way or something.

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Somehow they-- so they can
recognize the same deer again.

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Then maybe they let a
month go by or something,

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not too long but
more-- enough time

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that animals can move
around and stuff.

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And then they go out, and they
capture deer for a day again.

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And let's say they
capture 10 deer again.

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The point is, the second
time they do a capture--

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this is called capture
recapture methods--

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the second time they do it, they
look to see how many of the deer

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that we captured
the second time did

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we also capture the first time?

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If you think about it,
if you go into a forest

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and you walked around pretty
randomly or something and you--

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all of the deer or
nine out of the 10 deer

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that you capture
the first time you

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see the same ones, the
second time, you might think,

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wow, we've seen almost all
the deer in the forest.

00:10:12.790 --> 00:10:15.695 align:middle line:90%


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On the other hand, let's say you
capture 10 deer and none of them

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that you captured the
second time had the tags.

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You'd be like, wow, I know
I've seen 20 deer here,

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but law of averages suggests
there's a lot more than 20 deer.

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And, in fact, there's
formulas that can-- you can--

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that people do with
this type of thing.

00:10:41.570 --> 00:10:44.420 align:middle line:84%
So I tried to figure
out what would

00:10:44.420 --> 00:10:47.060 align:middle line:90%
be the equivalent in music.

00:10:47.060 --> 00:10:54.340 align:middle line:84%
And so I started to think, let's
go and look at some equations

00:10:54.340 --> 00:10:56.380 align:middle line:90%
we might make.

00:10:56.380 --> 00:10:59.330 align:middle line:90%
If we had the number of pieces--

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if we knew the number of
pieces that originally existed

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and we multiplied
by the probability

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that any given piece
would be missing,

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we would know the total
number of missing pieces.

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That's fantastic.

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That is a very hard equation.

00:11:17.840 --> 00:11:22.160 align:middle line:84%
It's very hard to argue against,
but it's completely useless.

00:11:22.160 --> 00:11:24.740 align:middle line:84%
We don't know the number
of pieces originally.

00:11:24.740 --> 00:11:26.710 align:middle line:84%
We don't know the
probability that any given

00:11:26.710 --> 00:11:28.550 align:middle line:90%
piece would be missing.

00:11:28.550 --> 00:11:31.370 align:middle line:84%
And therefore we don't know
how many missing pieces are.

00:11:31.370 --> 00:11:37.060 align:middle line:84%
So one equation, three unknowns,
we don't know any of them.

00:11:37.060 --> 00:11:42.640 align:middle line:84%
But we can think through
some of the things here.

00:11:42.640 --> 00:11:46.580 align:middle line:84%
I'm going to go through a
quicker version of this,

00:11:46.580 --> 00:11:51.040 align:middle line:84%
but I have elsewhere-- well, I
have in my article a little bit

00:11:51.040 --> 00:11:54.460 align:middle line:84%
deeper version that
talks about all the un--

00:11:54.460 --> 00:11:56.390 align:middle line:84%
the assumptions that
could be in play.

00:11:56.390 --> 00:12:00.190 align:middle line:84%
But let's start with how can
we figure out the probability

00:12:00.190 --> 00:12:02.030 align:middle line:84%
that we're missing
a given piece.

00:12:02.030 --> 00:12:09.790 align:middle line:84%
Well, here's one model, and
it's kind of a bad assumption

00:12:09.790 --> 00:12:10.640 align:middle line:90%
maybe to start with.

00:12:10.640 --> 00:12:12.820 align:middle line:90%
But here's one model.

00:12:12.820 --> 00:12:17.860 align:middle line:84%
What if there's just
medieval scribes had baskets

00:12:17.860 --> 00:12:19.910 align:middle line:90%
of pieces, just all the pieces.

00:12:19.910 --> 00:12:22.368 align:middle line:84%
They knew them all their head,
there's something like that,

00:12:22.368 --> 00:12:24.160 align:middle line:84%
and they randomly
chose ones that they

00:12:24.160 --> 00:12:25.460 align:middle line:90%
were going to write down.

00:12:25.460 --> 00:12:28.930 align:middle line:84%
Well, then the probability
that a given piece

00:12:28.930 --> 00:12:31.270 align:middle line:84%
would be in a
particular manuscript

00:12:31.270 --> 00:12:35.620 align:middle line:84%
is approximately the
proportion of all

00:12:35.620 --> 00:12:37.130 align:middle line:90%
of the pieces in the manuscript.

00:12:37.130 --> 00:12:39.460 align:middle line:84%
That is, if R sub I is
the number of pieces

00:12:39.460 --> 00:12:42.220 align:middle line:84%
in the manuscript and N is
the total number of pieces

00:12:42.220 --> 00:12:44.550 align:middle line:84%
originally copied, then we
would know the probability

00:12:44.550 --> 00:12:48.420 align:middle line:84%
that a piece would be in a
given manuscript or songbook.

00:12:48.420 --> 00:12:50.880 align:middle line:84%
It's not exactly that
number because you

00:12:50.880 --> 00:12:55.020 align:middle line:84%
don't do duplication,
but it's pretty close.

00:12:55.020 --> 00:12:58.942 align:middle line:84%
It's actually the people have
argued against me that, well,

00:12:58.942 --> 00:13:00.400 align:middle line:84%
you have to correct
for that error,

00:13:00.400 --> 00:13:05.040 align:middle line:84%
but you only have to correct for
the probability of duplication

00:13:05.040 --> 00:13:07.740 align:middle line:84%
if the number of pieces
in that manuscript

00:13:07.740 --> 00:13:12.450 align:middle line:84%
is close to some major
percentage of the total number

00:13:12.450 --> 00:13:13.660 align:middle line:90%
of pieces originally copied.

00:13:13.660 --> 00:13:16.570 align:middle line:90%
So that's already getting that.

00:13:16.570 --> 00:13:18.057 align:middle line:84%
Anyhow so this is
the probability

00:13:18.057 --> 00:13:20.140 align:middle line:84%
that a given piece would
be in a given manuscript.

00:13:20.140 --> 00:13:22.920 align:middle line:84%
From here, we can
work out what's

00:13:22.920 --> 00:13:25.570 align:middle line:84%
the probability the piece is
not in a given manuscript.

00:13:25.570 --> 00:13:28.450 align:middle line:84%
And we just subtract
that from one.

00:13:28.450 --> 00:13:28.950 align:middle line:90%
Great.

00:13:28.950 --> 00:13:31.170 align:middle line:90%
So that's pretty good.

00:13:31.170 --> 00:13:34.510 align:middle line:84%
Now let's say you have two
independent manuscripts.

00:13:34.510 --> 00:13:36.350 align:middle line:84%
They're being copied
in different places,

00:13:36.350 --> 00:13:38.350 align:middle line:84%
different people, whatever,
something like that.

00:13:38.350 --> 00:13:40.600 align:middle line:84%
What would be the probability
that the piece would not

00:13:40.600 --> 00:13:43.600 align:middle line:84%
be in any of these
two manuscripts.

00:13:43.600 --> 00:13:46.230 align:middle line:84%
And so you just
multiply the probability

00:13:46.230 --> 00:13:49.660 align:middle line:84%
that it wouldn't be in one
manuscript and not in the other,

00:13:49.660 --> 00:13:51.960 align:middle line:84%
and so R sub 1 and
R sub 2, they're

00:13:51.960 --> 00:13:54.935 align:middle line:84%
going to depend on how many
pieces are in the manuscript.

00:13:54.935 --> 00:13:56.310 align:middle line:84%
But this would be
the probability

00:13:56.310 --> 00:14:00.420 align:middle line:84%
that some piece existing
or not would be in--

00:14:00.420 --> 00:14:03.630 align:middle line:84%
would not be in any
of two manuscripts.

00:14:03.630 --> 00:14:07.200 align:middle line:84%
So there's about 85 surviving
medieval manuscripts

00:14:07.200 --> 00:14:11.370 align:middle line:84%
in the period I'm most
interested in, Italy from

00:14:11.370 --> 00:14:16.770 align:middle line:84%
1370-1420 just after the Black
Death and during the time

00:14:16.770 --> 00:14:18.580 align:middle line:90%
of the Great Papal Schism.

00:14:18.580 --> 00:14:21.090 align:middle line:84%
So there's about 85 of
these manuscripts, so what's

00:14:21.090 --> 00:14:23.130 align:middle line:84%
the probability that any
given piece would not

00:14:23.130 --> 00:14:27.150 align:middle line:84%
be in any of the 85
surviving manuscripts?

00:14:27.150 --> 00:14:29.210 align:middle line:84%
And it looks
something like this.

00:14:29.210 --> 00:14:32.910 align:middle line:90%


00:14:32.910 --> 00:14:40.210 align:middle line:84%
So this is something that
it's a big long number,

00:14:40.210 --> 00:14:43.760 align:middle line:84%
but you can see that right
at the very end, this--

00:14:43.760 --> 00:14:48.550 align:middle line:84%
whatever this works out to is
the equal to the probability

00:14:48.550 --> 00:14:49.800 align:middle line:90%
that a piece would be missing.

00:14:49.800 --> 00:14:53.430 align:middle line:84%
Because if a piece is not in any
of the surviving manuscripts,

00:14:53.430 --> 00:14:56.490 align:middle line:90%
then it's missing to us today.

00:14:56.490 --> 00:15:00.110 align:middle line:84%
So this is great, but we
know all these r numbers

00:15:00.110 --> 00:15:02.780 align:middle line:84%
because they're simply the
number of pieces in a manuscript

00:15:02.780 --> 00:15:06.050 align:middle line:90%
today, not in originally.

00:15:06.050 --> 00:15:09.200 align:middle line:84%
So we can take this,
and we can go back

00:15:09.200 --> 00:15:11.810 align:middle line:84%
to our original equation
with three unknowns

00:15:11.810 --> 00:15:18.600 align:middle line:84%
and substitute it into
for that P of m place.

00:15:18.600 --> 00:15:22.760 align:middle line:84%
So we can see that now we have
one equation and two unknowns.

00:15:22.760 --> 00:15:25.700 align:middle line:84%
It's still a pretty
honking equation,

00:15:25.700 --> 00:15:27.390 align:middle line:90%
but, well, that's good.

00:15:27.390 --> 00:15:29.970 align:middle line:84%
One equation, two unknowns,
still too many unknowns.

00:15:29.970 --> 00:15:31.640 align:middle line:84%
We need two equations
at least if we're

00:15:31.640 --> 00:15:33.300 align:middle line:90%
going to do two unknowns.

00:15:33.300 --> 00:15:36.830 align:middle line:84%
But we can look at this
last answer, this m.

00:15:36.830 --> 00:15:40.070 align:middle line:84%
What are the total
number of missing pieces.

00:15:40.070 --> 00:15:42.700 align:middle line:84%
Well, the total number
of missing pieces

00:15:42.700 --> 00:15:46.100 align:middle line:84%
is just the number of pieces
that originally existed,

00:15:46.100 --> 00:15:50.420 align:middle line:84%
which we don't know, minus the
number of pieces that survive,

00:15:50.420 --> 00:15:51.350 align:middle line:90%
which we do know.

00:15:51.350 --> 00:15:53.590 align:middle line:84%
If we have a pretty good
catalog of everything

00:15:53.590 --> 00:15:56.800 align:middle line:84%
that survives today, then
we can figure that out.

00:15:56.800 --> 00:15:59.950 align:middle line:84%
So now we go back, and we see
that we have actually just

00:15:59.950 --> 00:16:02.650 align:middle line:90%
one equation and one unknown.

00:16:02.650 --> 00:16:05.020 align:middle line:90%
It's a pretty big equation.

00:16:05.020 --> 00:16:07.780 align:middle line:84%
In fact, a lot of the literature
that I was reading from

00:16:07.780 --> 00:16:12.250 align:middle line:84%
the '60s and '70s and '80s was
about you can't possibly solve

00:16:12.250 --> 00:16:16.210 align:middle line:84%
an equation of this
dimensionality exactly.

00:16:16.210 --> 00:16:18.550 align:middle line:84%
So here's all the
sophisticated math

00:16:18.550 --> 00:16:25.010 align:middle line:84%
that we can do to try
to approximate it.

00:16:25.010 --> 00:16:29.090 align:middle line:84%
But, in fact, nowadays
it's pretty simple.

00:16:29.090 --> 00:16:31.570 align:middle line:84%
What we can do is we can
try different numbers

00:16:31.570 --> 00:16:36.550 align:middle line:84%
for N, the number of original
pieces, starting from one more

00:16:36.550 --> 00:16:39.050 align:middle line:84%
than the number of surviving
pieces or something.

00:16:39.050 --> 00:16:42.880 align:middle line:84%
Try all these numbers into
here until the left side

00:16:42.880 --> 00:16:45.850 align:middle line:84%
and the right side
approximately balance.

00:16:45.850 --> 00:16:47.390 align:middle line:84%
And we can do that
with computers.

00:16:47.390 --> 00:16:53.400 align:middle line:84%
So when I did this, it's-- this
is an article I think like 13,

00:16:53.400 --> 00:16:57.830 align:middle line:84%
14 years old, it's
before Python was big.

00:16:57.830 --> 00:17:02.140 align:middle line:84%
So I used Perl, and I
just did find N, find

00:17:02.140 --> 00:17:04.310 align:middle line:84%
the hypothetical total
number of manuscripts

00:17:04.310 --> 00:17:07.430 align:middle line:84%
given all the things that we
know, and so on and so on.

00:17:07.430 --> 00:17:15.440 align:middle line:84%
And we're able for each
of four different genres--

00:17:15.440 --> 00:17:16.940 align:middle line:84%
these are different
types of music--

00:17:16.940 --> 00:17:20.829 align:middle line:84%
we're able to figure out
what percentage of the pieces

00:17:20.829 --> 00:17:23.150 align:middle line:90%
are probably missing.

00:17:23.150 --> 00:17:24.880 align:middle line:90%
These are-- I'm--

00:17:24.880 --> 00:17:26.260 align:middle line:90%
there's error bars on this.

00:17:26.260 --> 00:17:28.960 align:middle line:84%
It's rough guesses,
but we can see

00:17:28.960 --> 00:17:35.140 align:middle line:84%
that the percentage of missing
pieces may be in only one--

00:17:35.140 --> 00:17:37.650 align:middle line:84%
in only one of the
genres is it predicted

00:17:37.650 --> 00:17:42.490 align:middle line:84%
to be more than the number
of total number of pieces

00:17:42.490 --> 00:17:43.990 align:middle line:84%
than the number of
surviving pieces.

00:17:43.990 --> 00:17:46.270 align:middle line:84%
And, in fact, for
some of these genres,

00:17:46.270 --> 00:17:49.025 align:middle line:84%
we predict that, hey, we
have almost everything there.

00:17:49.025 --> 00:17:52.260 align:middle line:90%


00:17:52.260 --> 00:17:56.020 align:middle line:84%
So one of the things
we can look at,

00:17:56.020 --> 00:17:58.710 align:middle line:84%
instead of saying how many
pieces were once copied

00:17:58.710 --> 00:18:04.800 align:middle line:84%
but no longer exist, we can take
that total number and say, wow,

00:18:04.800 --> 00:18:07.490 align:middle line:84%
maybe we have all
but 25% of them.

00:18:07.490 --> 00:18:11.940 align:middle line:90%


00:18:11.940 --> 00:18:15.030 align:middle line:84%
Now there were a lot of
assumptions that went into that.

00:18:15.030 --> 00:18:17.400 align:middle line:84%
Scribes are collecting
things randomly and so on

00:18:17.400 --> 00:18:19.290 align:middle line:84%
and so forth and
that there's not

00:18:19.290 --> 00:18:22.210 align:middle line:84%
pieces that are more popular
than each other and so on.

00:18:22.210 --> 00:18:24.220 align:middle line:84%
And so in the
article that I wrote,

00:18:24.220 --> 00:18:27.540 align:middle line:84%
there's ways that you can
compensate for this and ways

00:18:27.540 --> 00:18:28.660 align:middle line:90%
that we can test.

00:18:28.660 --> 00:18:33.060 align:middle line:84%
For instance, we can hold out
10% of the manuscripts at random

00:18:33.060 --> 00:18:40.450 align:middle line:84%
and then say not just how many
pieces would we expect to--

00:18:40.450 --> 00:18:41.980 align:middle line:90%
would we expect were lost.

00:18:41.980 --> 00:18:45.660 align:middle line:84%
But if we gained 10 more
manuscripts, how many more

00:18:45.660 --> 00:18:49.600 align:middle line:84%
pieces would we expect to have
that we didn't know already

00:18:49.600 --> 00:18:52.060 align:middle line:90%
and then we can look at?

00:18:52.060 --> 00:18:54.730 align:middle line:84%
Now put those 10
manuscripts back and voila.

00:18:54.730 --> 00:18:55.315 align:middle line:90%
I think

00:18:55.315 --> 00:18:56.940 align:middle line:84%
I can't remember off
the top of my head

00:18:56.940 --> 00:18:58.980 align:middle line:84%
right now, one of those
things I publish it

00:18:58.980 --> 00:19:01.350 align:middle line:84%
so I don't have
to remember, but I

00:19:01.350 --> 00:19:05.010 align:middle line:84%
think that the percentage
of pieces that were lost I

00:19:05.010 --> 00:19:09.550 align:middle line:84%
think it was within
10% of something or--

00:19:09.550 --> 00:19:12.360 align:middle line:84%
so these models were
pretty, pretty good.

00:19:12.360 --> 00:19:14.790 align:middle line:84%
So we can use this
mathematical thinking and just

00:19:14.790 --> 00:19:17.550 align:middle line:84%
a little bit of
programming to answer

00:19:17.550 --> 00:19:20.310 align:middle line:84%
questions that were
thought to be completely

00:19:20.310 --> 00:19:23.220 align:middle line:90%
unanswerable in history.

00:19:23.220 --> 00:19:24.770 align:middle line:90%
Thanks.

00:19:24.770 --> 00:19:35.000 align:middle line:90%