WEBVTT

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[SQUEAKING]

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[RUSTLING]

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[CLICKING]

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RAFAEL JARAMILLO: And
all right, so let's go,

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ideal gas processes.

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How to motivate this?

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It's not just that
we like ideal gases

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because they have a
simple equation of state.

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What we're going to see
in a couple of lectures

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is that the process
of mixing ideal gases

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is a model for the process
of mixing real materials.

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So in case you're wondering
why are we spending

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all this time on gases--

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and ideal gases,
for that matter--

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there is a material
science motivation for it.

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OK.

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Let's start with reversible
adiabatic expansion.

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You looked at this a little
bit at the last lecture.

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I want to look at it some more
because it is really important.

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Reversible adiabatic expansion.

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So what to choose for
independent variables?

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So this thought exercise
again, you have a problem,

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you want to calculate
something about that process.

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What are you going to choose
for independent variables?

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Well, adiabatic means no heat.

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And we said it's reversible.

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So what does that mean?

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Is anything fixed?

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And what does that
imply we should use

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for an independent variable?

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AUDIENCE: Pressure
and temperature.

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RAFAEL JARAMILLO: So
here's a rule of thumb.

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If something is fixed,
meaning constant,

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then it's independent.

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Let's call this stubborn.

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If something is
fixed or constant,

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you can also say it's stubborn.

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Something that's
stubborn is independent.

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So what is a state
variable, which is fixed,

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for a adiabatic
reversible process?

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AUDIENCE: Would it be entropy?

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RAFAEL JARAMILLO:
Entropy, right.

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This is a process
for dS equals 0,

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which means we need to use x
as an independent variable.

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If something stubborn,
it's independent.

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All right.

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And I said expansion.

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So you could say P or V change.

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Let's use P. So these are going
to be our independent variables

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here, S and P.

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So we want to find the equation
of state that describes,

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let's say, temperature
as a function of entropy

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and pressure.

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Just for example,
let's say the problem

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asked, calculate the
temperature change

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for a reversible adiabatic
process moving from pressure 1

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to pressure 2,
something like that.

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So that would be a useful
equation of state to find.

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All right.

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So now this is going
to be more practice

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on the general strategy.

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That's really one of the
reasons I'm doing this here.

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So you see this.

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Use general strategy
to find dT equals--

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let's say M dS plus
N dP, where M and N

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are the unknown coefficients.

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So then we substitute in.

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We do a change of variables.

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We change from S and P to T
and P, as we did the last time.

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Pardon me.

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Minus V alpha dP plus NdP.

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Change-- that's a
change of variables.

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And then we gather terms.

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Just gathering terms.

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Then we can say by inspection,
M Cp over T equals 1.

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Why is that?

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dT has to equal dT.

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So this got to be equal 1.

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This has to be equal to 1.

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And so it's equal--

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M equals T over Cp.

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All right.

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And likewise, if we have T
as an independent variable--

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dependent, sorry-- and the two
independent variables here are

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T and P--

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it's kind of silly--

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this thing has to be 0.

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dT has to be equal
to dT, end of story.

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So N minus MV alpha equals 0.

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And so N equals
TV alpha over Cp.

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All right, so these
are the coefficients

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that we were looking for.

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I did this more quickly
than I did it on Monday.

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Again, there's lots more
examples in the book,

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but this is the
general strategy.

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So we found our
coefficients there.

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That's what we were looking for.

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Now we can plug in.

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We can use properties
of the ideal gas.

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What are some properties
of ideal gases?

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V equals RT over P. Let's
just keep the number of moles

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equals 1 first because it's
easier that way and also

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because I did this
thing where I used

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N and M, because the
textbook does it that way.

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I don't like to do it
that way because N is also

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the number of moles.

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So we're going to just
pretend I didn't do that.

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All right.

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And alpha equals
1/T. We calculated

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on that first or second day.

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And another result,
which you're probably

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familiar with from the book--

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we haven't explicitly
mentioned in class--

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which is that Cp equals 5/2 R
for a monatomic gas, monatomic.

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All right.

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So now we can calculate the
thing which we are looking for.

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dT at fixed entropy equals
dT dP at fixed entropy dP.

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And this we have from
the previous board.

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That's what our general
strategy gave us.

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TV alpha over Cp dP.

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And we can plug in stuff from
the ideal gas-- equals TRT Cp

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TP.

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All right.

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We're using ideal
gas properties there.

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And we're going to simplify
R over Cp T/P dP equals--

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you can also say 2/5 T/P dP.

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I'm writing off the edge there.

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Sorry about that.

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I can separate variables.

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This is a separable
differential equation.

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This is a separable
differential equation.

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There's dT.

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There's dP.

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There's T. There's
P. It's separable.

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Separate and integrate.

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DT over T equals R
over Cp dP over p.

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Integrate that, and I get
T final over T initial

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equals P final over
P initial R over Cp.

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So I gave you this in the
P set and in a lecture

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a couple of lectures ago.

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And then on Monday, we
did something like this.

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We used the general
strategy, and we reduced it

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to the case of ideal gases.

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And then today, we just
went a little farther

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because we went a little faster.

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And we actually
derived an expression

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for the adiabatic reversible
expansion of an ideal gas.

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So we've kind of seen
the same thing now

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at three different levels.

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And this is just one
expression which you'll find.

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If you look up on Wikipedia
ideal gas adiabatic process,

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you'll find several expressions.

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They're all equivalent.

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There are alternative forms.

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There are alternative forms for
adiabatic of the original IG.

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PV to gamma equals constant.

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That's an alternative form.

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TV to the gamma minus
1 equals constant.

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These are simply
related by [INAUDIBLE]..

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It does use the ideal
gas equation of state.

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You can get from
one to the other.

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Here again, gamma equals the
ratio of Cp over Cv, which

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we know is greater than
1 for physical reasons

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we've discussed before.

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Or if you want, P
final over P initial

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equals V initial over V final.

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I think we've seen that already.

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So these are all equivalent.

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These are all the same thing.

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And we know that we have--

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on a VP plot, if
we have isotherms,

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the adiabat is going to
be something steeper.

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So if these are isotherms,
this is the adiabat.

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Right.

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OK.

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So we've seen this before.

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There's an interesting
alternative derivation

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of this that does not
use the general strategy.

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I think it's interesting.

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You should check it out.

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DeHoff section is--

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I wrote this down--

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4.2.4.

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He uses the fact that
for an ideal gas,

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the internal energy depends
only on temperature.

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And you can also start from this
expression and derive these.

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So if you're interested,
let's do that.

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Let's do that.

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dQ equals 0 alternative.

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Alternatively, dQ equals 0.

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That means that dU equals work--

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because there's no Q--

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equals minus PdV.

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All right.

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Previous-- we're
going to use that.

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And we will use both of these
combined, substituting Cv dT

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equals minus p dV
equals minus RT V dV.

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Again, separate and integrate.

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00:14:59.860 --> 00:15:03.760 align:middle line:84%
We got-- well, this
is separable, right?

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Cv dT over T equals--

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minus R dV over V. And
we can integrate that,

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and we get T final
over T initial

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equals V initial over
V final R over Cv--

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which, again, is the same thing.

00:15:30.410 --> 00:15:33.400 align:middle line:84%
So we're dancing around
the same thing here.

00:15:33.400 --> 00:15:34.070 align:middle line:90%
Good.

00:15:34.070 --> 00:15:34.570 align:middle line:90%
OK.

00:15:34.570 --> 00:15:37.300 align:middle line:90%


00:15:37.300 --> 00:15:39.650 align:middle line:84%
So by now, you've probably
had more than enough

00:15:39.650 --> 00:15:45.050 align:middle line:84%
of reversible adiabatic
expansion of an ideal gas.

00:15:45.050 --> 00:15:46.670 align:middle line:90%
Let's do isothermal expansion.

00:15:46.670 --> 00:16:03.100 align:middle line:90%


00:16:03.100 --> 00:16:03.600 align:middle line:90%
All right.

00:16:03.600 --> 00:16:07.710 align:middle line:84%
Isothermal expansion--
this is our second one.

00:16:07.710 --> 00:16:14.320 align:middle line:84%
Here, same question I asked
in the beginning, what to use

00:16:14.320 --> 00:16:16.060 align:middle line:90%
four independent variables?

00:16:16.060 --> 00:16:24.235 align:middle line:90%


00:16:24.235 --> 00:16:26.110 align:middle line:84%
What should we use for
independent variables?

00:16:26.110 --> 00:16:33.200 align:middle line:90%


00:16:33.200 --> 00:16:36.140 align:middle line:84%
AUDIENCE: Temperature and
then either pressure or volume

00:16:36.140 --> 00:16:36.950 align:middle line:90%
again.

00:16:36.950 --> 00:16:39.990 align:middle line:84%
RAFAEL JARAMILLO:
Good, thank you.

00:16:39.990 --> 00:16:45.330 align:middle line:90%
Isothermal dT equals 0.

00:16:45.330 --> 00:16:49.660 align:middle line:84%
That means you use T.
Temperature is stubborn.

00:16:49.660 --> 00:16:51.610 align:middle line:90%
It's independent.

00:16:51.610 --> 00:16:54.720 align:middle line:84%
And expansion, you're
going to control something.

00:16:54.720 --> 00:16:56.250 align:middle line:84%
Something that's
controlled sounds

00:16:56.250 --> 00:17:01.390 align:middle line:84%
like it should be an
independent variable expansion.

00:17:01.390 --> 00:17:05.594 align:middle line:84%
So we're going to-- in
this case, we use pressure.

00:17:05.594 --> 00:17:11.510 align:middle line:84%
We could use volume,
but we'll use pressure.

00:17:11.510 --> 00:17:12.690 align:middle line:90%
All right.

00:17:12.690 --> 00:17:22.770 align:middle line:84%
And what I want to do now is
find the equation of state

00:17:22.770 --> 00:17:28.713 align:middle line:84%
Gibbs free energy
T and P. So this

00:17:28.713 --> 00:17:30.630 align:middle line:84%
is an example where--
let's say someone said--

00:17:30.630 --> 00:17:33.000 align:middle line:84%
or your problem
statement boil down to,

00:17:33.000 --> 00:17:34.768 align:middle line:84%
we have an isothermal
expansion and we

00:17:34.768 --> 00:17:36.810 align:middle line:84%
want to calculate the
change of Gibbs free energy

00:17:36.810 --> 00:17:40.250 align:middle line:84%
for some process going from
pressure 1 to pressure 2.

00:17:40.250 --> 00:17:42.770 align:middle line:84%
That's a very common
scenario that you'll find.

00:17:42.770 --> 00:17:45.900 align:middle line:84%
To do this calculation
is very, very common.

00:17:45.900 --> 00:17:49.120 align:middle line:90%
So let's see how to do it.

00:17:49.120 --> 00:17:52.180 align:middle line:84%
We want to find a change,
so we want to use calculus.

00:17:52.180 --> 00:17:57.420 align:middle line:84%
So let's use the proper
differential form.

00:17:57.420 --> 00:18:04.230 align:middle line:90%


00:18:04.230 --> 00:18:12.420 align:middle line:84%
dG equals-- well dG equals
minus SdT plus P dV.

00:18:12.420 --> 00:18:14.580 align:middle line:90%
That, we know.

00:18:14.580 --> 00:18:17.310 align:middle line:84%
But we also said
this was isothermal.

00:18:17.310 --> 00:18:20.670 align:middle line:90%


00:18:20.670 --> 00:18:24.898 align:middle line:90%
So this is really pretty simple.

00:18:24.898 --> 00:18:26.565 align:middle line:84%
It's a single-variable
calculus problem.

00:18:26.565 --> 00:18:29.058 align:middle line:90%


00:18:29.058 --> 00:18:30.600 align:middle line:84%
I point this out
over and over again,

00:18:30.600 --> 00:18:32.780 align:middle line:84%
so forgive me for
pointing out again.

00:18:32.780 --> 00:18:35.750 align:middle line:84%
This is why if something is
stubborn or something is fixed,

00:18:35.750 --> 00:18:37.460 align:middle line:90%
it's independent.

00:18:37.460 --> 00:18:40.820 align:middle line:84%
Not only does that make sense,
it also makes your life easier.

00:18:40.820 --> 00:18:43.743 align:middle line:84%
When you have
multivariable calculus

00:18:43.743 --> 00:18:45.410 align:middle line:84%
and you have an
opportunity to reduce it

00:18:45.410 --> 00:18:48.240 align:middle line:84%
to single-variable calculus, you
should take that opportunity.

00:18:48.240 --> 00:18:49.380 align:middle line:90%
So here's an example.

00:18:49.380 --> 00:18:52.640 align:middle line:84%
If you have two terms
on the right-hand side

00:18:52.640 --> 00:18:56.690 align:middle line:84%
and you can set one of them
to 0, the math gets easier.

00:18:56.690 --> 00:18:59.320 align:middle line:84%
That's why a correct choice
of independent variables

00:18:59.320 --> 00:19:00.890 align:middle line:90%
is so important.

00:19:00.890 --> 00:19:02.440 align:middle line:90%
This boils is way down here.

00:19:02.440 --> 00:19:08.945 align:middle line:84%
PdV for an ideal
gas is RT P dP--

00:19:08.945 --> 00:19:10.900 align:middle line:90%
wait, I'm sorry.

00:19:10.900 --> 00:19:11.800 align:middle line:90%
No one called me out.

00:19:11.800 --> 00:19:15.940 align:middle line:90%


00:19:15.940 --> 00:19:16.440 align:middle line:90%
Right.

00:19:16.440 --> 00:19:19.310 align:middle line:90%


00:19:19.310 --> 00:19:22.160 align:middle line:84%
Gibbs free energy, independent
variables are T and P.

00:19:22.160 --> 00:19:25.170 align:middle line:84%
And I get to ignore half
of the right-hand side.

00:19:25.170 --> 00:19:26.930 align:middle line:90%
So things simplify.

00:19:26.930 --> 00:19:31.970 align:middle line:84%
And this is pretty
easy integral.

00:19:31.970 --> 00:19:40.110 align:middle line:84%
So dG equals G final
minus G initial--

00:19:40.110 --> 00:19:43.380 align:middle line:90%
we'll call that delta G--

00:19:43.380 --> 00:19:50.880 align:middle line:84%
equals RT plug P
final over P initial.

00:19:50.880 --> 00:19:56.800 align:middle line:90%


00:19:56.800 --> 00:20:01.870 align:middle line:84%
The math is easy when we
set the problem up right.

00:20:01.870 --> 00:20:07.420 align:middle line:84%
I'm going to put two
boxes around this.

00:20:07.420 --> 00:20:09.970 align:middle line:84%
The math-- oh it's like a--
it's a Christmas equation.

00:20:09.970 --> 00:20:12.970 align:middle line:84%
The math you just
saw is very easy,

00:20:12.970 --> 00:20:16.510 align:middle line:84%
but this is something which
will stick in your mind.

00:20:16.510 --> 00:20:20.350 align:middle line:84%
Because you will see expressions
like this in other classes

00:20:20.350 --> 00:20:22.370 align:middle line:90%
over and over and over again.

00:20:22.370 --> 00:20:25.750 align:middle line:84%
So, for example, if you
do electrochemistry,

00:20:25.750 --> 00:20:31.100 align:middle line:84%
this equation sets the
voltage of your device,

00:20:31.100 --> 00:20:33.280 align:middle line:90%
be it a reactor or a battery.

00:20:33.280 --> 00:20:36.990 align:middle line:84%
This is called the Nernst
equation in another context.

00:20:36.990 --> 00:20:40.440 align:middle line:84%
If you do chemical engineering
and you calculate change

00:20:40.440 --> 00:20:42.510 align:middle line:90%
in chemical potential with

00:20:42.510 --> 00:20:44.948 align:middle line:84%
fugacity-- we're not going to
use that word in this class

00:20:44.948 --> 00:20:45.990 align:middle line:90%
because this is course 3.

00:20:45.990 --> 00:20:47.820 align:middle line:84%
But if you're in course 10,
it's like fugacity this,

00:20:47.820 --> 00:20:50.340 align:middle line:84%
fugacity that-- you're going
to have log of fugacities,

00:20:50.340 --> 00:20:52.782 align:middle line:84%
and it's going to be
the same equation--

00:20:52.782 --> 00:20:53.740 align:middle line:90%
and so forth and so on.

00:20:53.740 --> 00:20:55.440 align:middle line:84%
This is really
foundational, so that's

00:20:55.440 --> 00:20:57.315 align:middle line:90%
why I put it in two colors.

00:20:57.315 --> 00:20:59.190 align:middle line:84%
AUDIENCE: Sorry, right
have a quick question.

00:20:59.190 --> 00:21:03.840 align:middle line:84%
Are we assuming that we're
using molar volume here?

00:21:03.840 --> 00:21:08.580 align:middle line:84%
RAFAEL JARAMILLO: I've
kept N equals 1 moles.

00:21:08.580 --> 00:21:11.900 align:middle line:90%
N equals 1 for simplicity here.

00:21:11.900 --> 00:21:12.900 align:middle line:90%
AUDIENCE: OK, thank you.

00:21:12.900 --> 00:21:15.180 align:middle line:90%
RAFAEL JARAMILLO: Yeah.

00:21:15.180 --> 00:21:17.820 align:middle line:90%
So thanks for clarifying.

00:21:17.820 --> 00:21:18.330 align:middle line:90%
Yeah, sure.

00:21:18.330 --> 00:21:20.030 align:middle line:84%
It's molar volume
because it's 1 moles.

00:21:20.030 --> 00:21:21.780 align:middle line:84%
I just didn't want to
carry an extra term.

00:21:21.780 --> 00:21:23.710 align:middle line:84%
If you wanted to, you
could put an N there.

00:21:23.710 --> 00:21:26.590 align:middle line:84%
And then you have an N there,
and that would be fine.

00:21:26.590 --> 00:21:28.890 align:middle line:90%
So let me we put a go to N here.

00:21:28.890 --> 00:21:31.290 align:middle line:84%
Here's an N, and you
can put an N there.

00:21:31.290 --> 00:21:33.620 align:middle line:84%
And everything else is
the same, same thing.

00:21:33.620 --> 00:21:39.110 align:middle line:90%


00:21:39.110 --> 00:21:39.610 align:middle line:90%
Good.

00:21:39.610 --> 00:21:43.850 align:middle line:90%


00:21:43.850 --> 00:21:44.640 align:middle line:90%
All right.

00:21:44.640 --> 00:21:46.700 align:middle line:84%
Now, again, I don't
expect you to have

00:21:46.700 --> 00:21:49.095 align:middle line:84%
the skies part and the
angels singing now,

00:21:49.095 --> 00:21:51.720 align:middle line:84%
because we haven't gotten to the
usefulness of this expression.

00:21:51.720 --> 00:21:53.178 align:middle line:84%
But I want it to
lodge in your mind

00:21:53.178 --> 00:21:56.240 align:middle line:84%
because we're going to come
back to this over and over.

00:21:56.240 --> 00:22:04.020 align:middle line:84%
All right, let's talk about
another ideal gas process,

00:22:04.020 --> 00:22:10.900 align:middle line:90%
adiabatic free expansion.

00:22:10.900 --> 00:22:14.470 align:middle line:90%


00:22:14.470 --> 00:22:18.202 align:middle line:84%
So this is a little bit of a
kooky example when you first

00:22:18.202 --> 00:22:19.785 align:middle line:84%
see it, if you haven't
seen it before.

00:22:19.785 --> 00:22:22.820 align:middle line:90%


00:22:22.820 --> 00:22:24.012 align:middle line:90%
So just bear with me.

00:22:24.012 --> 00:22:24.970 align:middle line:90%
So here's what we have.

00:22:24.970 --> 00:22:26.290 align:middle line:90%
Here's the situation.

00:22:26.290 --> 00:22:32.390 align:middle line:90%


00:22:32.390 --> 00:22:34.772 align:middle line:90%
We're going to have a piston.

00:22:34.772 --> 00:22:36.105 align:middle line:90%
So we're going to have a piston.

00:22:36.105 --> 00:22:45.840 align:middle line:90%


00:22:45.840 --> 00:22:53.190 align:middle line:84%
And this is a cylinder, and
it's thermally insulated.

00:22:53.190 --> 00:22:54.570 align:middle line:90%
So I'm drawing insulation.

00:22:54.570 --> 00:23:02.930 align:middle line:90%


00:23:02.930 --> 00:23:06.060 align:middle line:90%
Insulated.

00:23:06.060 --> 00:23:08.240 align:middle line:84%
Pardon me, that's not
very clear-- insulated.

00:23:08.240 --> 00:23:11.960 align:middle line:90%
And let's make the gas orange.

00:23:11.960 --> 00:23:18.800 align:middle line:90%


00:23:18.800 --> 00:23:20.390 align:middle line:90%
Simple picture, right?

00:23:20.390 --> 00:23:23.930 align:middle line:84%
So what we're going
to do is we're

00:23:23.930 --> 00:23:39.070 align:middle line:84%
going to withdraw the
piston instantaneously,

00:23:39.070 --> 00:23:43.870 align:middle line:84%
instantaneously, so much
faster than the gas molecules

00:23:43.870 --> 00:23:51.240 align:middle line:84%
can move, definitely much faster
than their sound velocity.

00:23:51.240 --> 00:23:54.690 align:middle line:84%
I made it bigger by accident,
didn't mean to do that.

00:23:54.690 --> 00:23:57.600 align:middle line:84%
Here's the original
position of the piston.

00:23:57.600 --> 00:24:00.325 align:middle line:84%
And I'm going to pull
it back very quickly.

00:24:00.325 --> 00:24:01.575 align:middle line:90%
So it's now going to sit here.

00:24:01.575 --> 00:24:09.817 align:middle line:90%


00:24:09.817 --> 00:24:10.525 align:middle line:90%
The same picture.

00:24:10.525 --> 00:24:21.160 align:middle line:90%


00:24:21.160 --> 00:24:27.950 align:middle line:84%
And the point is that at T
equals 0-- let's call it at--

00:24:27.950 --> 00:24:30.800 align:middle line:84%
instantaneously, none
of the gas molecules

00:24:30.800 --> 00:24:32.622 align:middle line:90%
have had time to move anywhere.

00:24:32.622 --> 00:24:35.280 align:middle line:90%


00:24:35.280 --> 00:24:38.180 align:middle line:84%
So the gas molecules are
occupying the space here.

00:24:38.180 --> 00:24:45.330 align:middle line:84%
And in the space evacuated by
the piston, we have a vacuum.

00:24:45.330 --> 00:24:47.860 align:middle line:90%


00:24:47.860 --> 00:24:49.110 align:middle line:90%
So that's the setup.

00:24:49.110 --> 00:24:50.580 align:middle line:84%
Like I said, it's
a little kooky.

00:24:50.580 --> 00:24:53.700 align:middle line:84%
There are actual, useful,
real-world scenarios

00:24:53.700 --> 00:24:55.350 align:middle line:90%
that approximate this.

00:24:55.350 --> 00:24:58.920 align:middle line:84%
But for now, it's just
a thought experiment.

00:24:58.920 --> 00:24:59.420 align:middle line:90%
All right.

00:24:59.420 --> 00:25:03.125 align:middle line:84%
So what's going to happen
spontaneously next?

00:25:03.125 --> 00:25:06.330 align:middle line:90%


00:25:06.330 --> 00:25:09.090 align:middle line:84%
Gas will spontaneously
do something.

00:25:09.090 --> 00:25:15.902 align:middle line:90%


00:25:15.902 --> 00:25:16.610 align:middle line:90%
AUDIENCE: Expand?

00:25:16.610 --> 00:25:18.027 align:middle line:84%
AUDIENCE: Diffuse
into the vacuum?

00:25:18.027 --> 00:25:21.560 align:middle line:90%


00:25:21.560 --> 00:25:28.005 align:middle line:84%
RAFAEL JARAMILLO: Freely
expand into the free volume.

00:25:28.005 --> 00:25:31.910 align:middle line:90%


00:25:31.910 --> 00:25:35.300 align:middle line:84%
It's kind of spontaneous to
expand into the free volume.

00:25:35.300 --> 00:25:41.190 align:middle line:84%
And this word spontaneously
in thermodynamics

00:25:41.190 --> 00:25:43.200 align:middle line:90%
it also means irreversibly.

00:25:43.200 --> 00:25:47.920 align:middle line:90%


00:25:47.920 --> 00:25:50.580 align:middle line:84%
So when you see one, I want
you to think of the other.

00:25:50.580 --> 00:25:53.220 align:middle line:84%
If you remember, we did this
with the baby book, right?

00:25:53.220 --> 00:25:57.290 align:middle line:84%
This was the baby
book from as well.

00:25:57.290 --> 00:26:00.410 align:middle line:84%
This gets beyond 0.2.0,
but somebody said diffuse.

00:26:00.410 --> 00:26:04.040 align:middle line:84%
The process here would
be initially something

00:26:04.040 --> 00:26:06.030 align:middle line:90%
that's super diffusive.

00:26:06.030 --> 00:26:10.140 align:middle line:84%
Because initially, the molecules
that are moving to the right

00:26:10.140 --> 00:26:13.410 align:middle line:84%
encounter no collisions with any
molecules coming from the left

00:26:13.410 --> 00:26:15.300 align:middle line:84%
or coming from the right,
moving to the left.

00:26:15.300 --> 00:26:17.280 align:middle line:84%
So you can imagine
almost, like, a shock wave

00:26:17.280 --> 00:26:20.820 align:middle line:84%
of expansion, followed by a
diffusive mixing process--

00:26:20.820 --> 00:26:23.590 align:middle line:84%
so anyway, again, just because
somebody mentioned diffusion.

00:26:23.590 --> 00:26:24.465 align:middle line:90%
So this is the setup.

00:26:24.465 --> 00:26:28.560 align:middle line:90%


00:26:28.560 --> 00:26:29.060 align:middle line:90%
All right.

00:26:29.060 --> 00:26:30.260 align:middle line:90%
You got that picture?

00:26:30.260 --> 00:26:32.380 align:middle line:84%
So let's calculate something
about that process.

00:26:32.380 --> 00:26:41.160 align:middle line:84%
Let's calculate the work and
heat during free expansion.

00:26:41.160 --> 00:26:45.560 align:middle line:90%


00:26:45.560 --> 00:26:46.460 align:middle line:90%
Start with the work.

00:26:46.460 --> 00:26:49.370 align:middle line:90%


00:26:49.370 --> 00:26:56.630 align:middle line:84%
Work equals minus dV
times P. And here's

00:26:56.630 --> 00:27:05.800 align:middle line:84%
the sort of kooky thing which
we tell you, but it's true.

00:27:05.800 --> 00:27:07.540 align:middle line:84%
The pressure of
the expansion is 0

00:27:07.540 --> 00:27:15.726 align:middle line:84%
because the gas is
expanding into--

00:27:15.726 --> 00:27:19.980 align:middle line:84%
or, here, better
say-- against vacuum.

00:27:19.980 --> 00:27:25.170 align:middle line:90%


00:27:25.170 --> 00:27:28.530 align:middle line:84%
So the gas is doing no
work in order to expand.

00:27:28.530 --> 00:27:30.000 align:middle line:90%
There's nothing pushing back.

00:27:30.000 --> 00:27:33.280 align:middle line:90%


00:27:33.280 --> 00:27:35.150 align:middle line:90%
So work equals 0.

00:27:35.150 --> 00:27:38.180 align:middle line:90%


00:27:38.180 --> 00:27:41.120 align:middle line:90%
What about heat?

00:27:41.120 --> 00:27:43.220 align:middle line:84%
AUDIENCE: I have a quick
question about homework.

00:27:43.220 --> 00:27:44.178 align:middle line:90%
RAFAEL JARAMILLO: Yeah.

00:27:44.178 --> 00:27:48.930 align:middle line:84%
AUDIENCE: So since it's like
an integral dV and the volume,

00:27:48.930 --> 00:27:50.335 align:middle line:90%
isn't the volume changing?

00:27:50.335 --> 00:27:50.760 align:middle line:84%
RAFAEL JARAMILLO:
Volume's changing.

00:27:50.760 --> 00:27:52.218 align:middle line:84%
AUDIENCE: So, like,
mathematically,

00:27:52.218 --> 00:27:53.360 align:middle line:90%
how would it work out to 0?

00:27:53.360 --> 00:27:54.860 align:middle line:84%
RAFAEL JARAMILLO:
The pressure is 0.

00:27:54.860 --> 00:27:55.900 align:middle line:90%
AUDIENCE: Is it the pressure?

00:27:55.900 --> 00:27:56.240 align:middle line:90%
Oh, I see.

00:27:56.240 --> 00:27:56.750 align:middle line:90%
Sorry.

00:27:56.750 --> 00:27:58.880 align:middle line:84%
RAFAEL JARAMILLO:
If you think about--

00:27:58.880 --> 00:28:03.890 align:middle line:84%
work comes back to energy,
which is forced by distance.

00:28:03.890 --> 00:28:05.490 align:middle line:90%
Go way back to the beginning.

00:28:05.490 --> 00:28:09.477 align:middle line:84%
So if you're pushing
something, something's

00:28:09.477 --> 00:28:10.310 align:middle line:90%
pushing back, right?

00:28:10.310 --> 00:28:12.620 align:middle line:84%
That's Newton's third law
or something like that.

00:28:12.620 --> 00:28:17.300 align:middle line:84%
If nothing's pushing
back, there's no work.

00:28:17.300 --> 00:28:19.060 align:middle line:90%
So that's one reason it's free.

00:28:19.060 --> 00:28:21.370 align:middle line:84%
I mean, this term free
expansion is as old as the hill,

00:28:21.370 --> 00:28:24.515 align:middle line:84%
so I'm not going to change the
term even though sometimes I

00:28:24.515 --> 00:28:25.390 align:middle line:90%
think it's confusing.

00:28:25.390 --> 00:28:28.820 align:middle line:84%
But that's one way to think
of the meaning of free.

00:28:28.820 --> 00:28:30.320 align:middle line:90%
The expansion comes for free.

00:28:30.320 --> 00:28:33.370 align:middle line:84%
You don't have to do any
work to move into that space.

00:28:33.370 --> 00:28:33.870 align:middle line:90%
All right.

00:28:33.870 --> 00:28:35.910 align:middle line:84%
So dV here is finite,
but the pressure

00:28:35.910 --> 00:28:39.130 align:middle line:84%
is 0, the pressure
during the expansion.

00:28:39.130 --> 00:28:42.880 align:middle line:84%
And heat Q equals 0 because
I said it was adiabatic.

00:28:42.880 --> 00:28:50.920 align:middle line:84%
So the change of energy during
adiabatic free expansion,

00:28:50.920 --> 00:29:03.680 align:middle line:84%
this implies dT equals
0 for ideal gas.

00:29:03.680 --> 00:29:04.400 align:middle line:90%
Right?

00:29:04.400 --> 00:29:07.670 align:middle line:84%
For an ideal gas, remember
temperature and energy

00:29:07.670 --> 00:29:10.720 align:middle line:90%
are one to one.

00:29:10.720 --> 00:29:13.890 align:middle line:84%
So if there's no
change of energy,

00:29:13.890 --> 00:29:17.920 align:middle line:84%
there's no change
of temperature.

00:29:17.920 --> 00:29:18.580 align:middle line:90%
OK.

00:29:18.580 --> 00:29:21.760 align:middle line:90%
Let's keep talking about this.

00:29:21.760 --> 00:29:39.750 align:middle line:84%
Adiabatic free expansion
is spontaneous,

00:29:39.750 --> 00:29:46.195 align:middle line:84%
so delta entropy
has to be positive.

00:29:46.195 --> 00:29:47.570 align:middle line:84%
That goes back a
couple lectures.

00:29:47.570 --> 00:29:48.830 align:middle line:90%
It's spontaneous.

00:29:48.830 --> 00:29:50.752 align:middle line:84%
That means that it has
to change the entropy,

00:29:50.752 --> 00:29:51.835 align:middle line:90%
has to change the entropy.

00:29:51.835 --> 00:29:56.060 align:middle line:84%
And it has to change it
with a positive sign.

00:29:56.060 --> 00:29:59.130 align:middle line:90%
How do we calculate--

00:29:59.130 --> 00:30:05.340 align:middle line:90%
how to calculate delta S?

00:30:05.340 --> 00:30:06.420 align:middle line:90%
How do we calculate it?

00:30:06.420 --> 00:30:12.360 align:middle line:90%


00:30:12.360 --> 00:30:22.811 align:middle line:84%
We want to find a differential
form and integrate.

00:30:22.811 --> 00:30:26.960 align:middle line:90%


00:30:26.960 --> 00:30:35.370 align:middle line:84%
dS equals-- delta S equals
dS equals something.

00:30:35.370 --> 00:30:35.870 align:middle line:90%
All right.

00:30:35.870 --> 00:30:38.960 align:middle line:84%
So here's one of the first
cases where we're going to,

00:30:38.960 --> 00:30:41.600 align:middle line:84%
in this class, see
how we can calculate

00:30:41.600 --> 00:30:45.140 align:middle line:84%
the results of
processes using thermo

00:30:45.140 --> 00:30:48.930 align:middle line:84%
even if we can't calculate the
specific processes themselves.

00:30:48.930 --> 00:30:50.910 align:middle line:84%
So we have this
spontaneous process,

00:30:50.910 --> 00:30:55.678 align:middle line:84%
which involves this nutty
expansion into a vacuum,

00:30:55.678 --> 00:30:56.720 align:middle line:90%
takes place very quickly.

00:30:56.720 --> 00:30:59.275 align:middle line:90%


00:30:59.275 --> 00:31:00.650 align:middle line:84%
That doesn't sound
like something

00:31:00.650 --> 00:31:01.700 align:middle line:90%
we know how to calculate.

00:31:01.700 --> 00:31:04.550 align:middle line:84%
We can't use PV equals nRT
because during that process,

00:31:04.550 --> 00:31:07.650 align:middle line:84%
the system is not
at equilibrium.

00:31:07.650 --> 00:31:09.200 align:middle line:84%
So the challenge
is, can we think

00:31:09.200 --> 00:31:14.820 align:middle line:84%
of an equivalent
reversible process that

00:31:14.820 --> 00:31:16.185 align:middle line:90%
brings us to the same endpoint?

00:31:16.185 --> 00:31:27.990 align:middle line:90%


00:31:27.990 --> 00:31:38.860 align:middle line:84%
Reversible process with same
initial and final states.

00:31:38.860 --> 00:31:41.380 align:middle line:90%


00:31:41.380 --> 00:31:47.290 align:middle line:84%
So we're going to
have start, end.

00:31:47.290 --> 00:31:49.390 align:middle line:84%
And we have this free
expansion process,

00:31:49.390 --> 00:31:51.015 align:middle line:84%
which I'll draw as
being kind of nutty.

00:31:51.015 --> 00:31:57.400 align:middle line:90%


00:31:57.400 --> 00:32:02.930 align:middle line:84%
And we want to come up
with a reversible process

00:32:02.930 --> 00:32:05.550 align:middle line:84%
with the same starting
and ending points.

00:32:05.550 --> 00:32:09.030 align:middle line:84%
Because if we can do that,
we can calculate delta S.

00:32:09.030 --> 00:32:11.280 align:middle line:84%
And we'll know it's
the same, regardless

00:32:11.280 --> 00:32:14.520 align:middle line:84%
of whether I take this
path or that path.

00:32:14.520 --> 00:32:16.940 align:middle line:84%
So let's imagine a
reversible process.

00:32:16.940 --> 00:32:18.540 align:middle line:84%
What do we know
about this process?

00:32:18.540 --> 00:32:23.240 align:middle line:90%
We know that delta T equals 0.

00:32:23.240 --> 00:32:25.780 align:middle line:90%


00:32:25.780 --> 00:32:27.850 align:middle line:90%
We know that delta T equals 0.

00:32:27.850 --> 00:32:29.560 align:middle line:90%
So let's consider isothermal.

00:32:29.560 --> 00:32:42.190 align:middle line:90%


00:32:42.190 --> 00:32:45.220 align:middle line:84%
As before, isothermal process,
no change in temperature.

00:32:45.220 --> 00:32:48.170 align:middle line:84%
We're going to use T as
an independent variable.

00:32:48.170 --> 00:32:49.270 align:middle line:90%
We'll do expansion.

00:32:49.270 --> 00:32:55.050 align:middle line:90%


00:32:55.050 --> 00:32:56.460 align:middle line:90%
Let's use volume this time.

00:32:56.460 --> 00:33:00.870 align:middle line:90%


00:33:00.870 --> 00:33:02.520 align:middle line:90%
Isothermal expansion.

00:33:02.520 --> 00:33:11.480 align:middle line:90%


00:33:11.480 --> 00:33:14.080 align:middle line:84%
So this isn't saying that
the adiabatic free expansion

00:33:14.080 --> 00:33:15.730 align:middle line:84%
is the same as
isothermal expansion.

00:33:15.730 --> 00:33:21.960 align:middle line:84%
But if I want to calculate
a change in state variables,

00:33:21.960 --> 00:33:24.480 align:middle line:84%
I can use this path
instead of this path.

00:33:24.480 --> 00:33:31.040 align:middle line:90%


00:33:31.040 --> 00:33:32.000 align:middle line:90%
OK.

00:33:32.000 --> 00:33:34.170 align:middle line:90%
So does anybody want to--

00:33:34.170 --> 00:33:34.670 align:middle line:90%
let's see.

00:33:34.670 --> 00:33:39.290 align:middle line:90%
I have some-- let's see.

00:33:39.290 --> 00:33:42.030 align:middle line:84%
I want to pause here before
we do that calculation.

00:33:42.030 --> 00:33:44.030 align:middle line:84%
I'm going to pause here
before that calculation.

00:33:44.030 --> 00:33:46.790 align:middle line:90%


00:33:46.790 --> 00:33:49.208 align:middle line:90%
Because that was a lot of stuff.

00:33:49.208 --> 00:33:50.750 align:middle line:84%
I'll take questions
before moving on.

00:33:50.750 --> 00:33:56.170 align:middle line:90%


00:33:56.170 --> 00:33:57.970 align:middle line:84%
AUDIENCE: Can you go
back and explain again

00:33:57.970 --> 00:34:01.222 align:middle line:90%
why heat equals 0?

00:34:01.222 --> 00:34:02.680 align:middle line:84%
RAFAEL JARAMILLO:
For this process?

00:34:02.680 --> 00:34:03.762 align:middle line:90%
AUDIENCE: Yes.

00:34:03.762 --> 00:34:04.720 align:middle line:90%
RAFAEL JARAMILLO: Yeah.

00:34:04.720 --> 00:34:09.319 align:middle line:90%
And part of this is--

00:34:09.319 --> 00:34:13.852 align:middle line:90%


00:34:13.852 --> 00:34:14.810 align:middle line:90%
shoot, I was about to--

00:34:14.810 --> 00:34:20.040 align:middle line:90%


00:34:20.040 --> 00:34:22.120 align:middle line:84%
just the way the
problem was set up.

00:34:22.120 --> 00:34:26.250 align:middle line:84%
So I told you the setup
is a little bit kooky.

00:34:26.250 --> 00:34:28.214 align:middle line:84%
I'm imagining a
thermally-insulated piston.

00:34:28.214 --> 00:34:31.150 align:middle line:90%


00:34:31.150 --> 00:34:36.310 align:middle line:84%
So a thermally-insulated piston,
it's in the title, adiabatic.

00:34:36.310 --> 00:34:39.310 align:middle line:84%
So thermal insulation,
heat equals 0.

00:34:39.310 --> 00:34:45.139 align:middle line:84%
So for that process, for
that process, work equals 0,

00:34:45.139 --> 00:34:46.040 align:middle line:90%
and heat equals 0.

00:34:46.040 --> 00:34:50.635 align:middle line:90%


00:34:50.635 --> 00:34:52.510 align:middle line:84%
Remember, those are
process variables, right?

00:34:52.510 --> 00:34:55.179 align:middle line:84%
So that means that
a different process

00:34:55.179 --> 00:34:57.850 align:middle line:84%
might have different
process variables that

00:34:57.850 --> 00:35:01.580 align:middle line:84%
still go between the
same start and end state.

00:35:01.580 --> 00:35:08.654 align:middle line:90%


00:35:08.654 --> 00:35:11.550 align:middle line:84%
So I'm going to
calculate delta S next,

00:35:11.550 --> 00:35:13.520 align:middle line:84%
but I want to gather
more questions.

00:35:13.520 --> 00:35:17.160 align:middle line:90%


00:35:17.160 --> 00:35:19.040 align:middle line:84%
AUDIENCE: So for
isothermal expansion,

00:35:19.040 --> 00:35:22.910 align:middle line:84%
previously, you had used P
as your independent variable.

00:35:22.910 --> 00:35:25.880 align:middle line:84%
Is there a reason why
you're changing it to V now?

00:35:25.880 --> 00:35:27.820 align:middle line:84%
Or is there a way
that we should--

00:35:27.820 --> 00:35:29.403 align:middle line:84%
RAFAEL JARAMILLO:
It's about the same.

00:35:29.403 --> 00:35:35.930 align:middle line:84%
For ideal gas, of
course, PV equals RT.

00:35:35.930 --> 00:35:39.050 align:middle line:84%
For ideal gas with N
equals 1, PV equals RT.

00:35:39.050 --> 00:35:44.310 align:middle line:84%
And for isothermal processes,
this is just a constant.

00:35:44.310 --> 00:35:46.520 align:middle line:84%
So you can always swap
P and V. They just

00:35:46.520 --> 00:35:48.693 align:middle line:84%
end up being the
inverse of each other.

00:35:48.693 --> 00:35:49.360 align:middle line:90%
AUDIENCE: I see.

00:35:49.360 --> 00:35:50.110 align:middle line:90%
OK, thank you.

00:35:50.110 --> 00:35:51.230 align:middle line:84%
RAFAEL JARAMILLO:
That's always easy.

00:35:51.230 --> 00:35:53.397 align:middle line:84%
I just did this because
before, I did the other way,

00:35:53.397 --> 00:35:55.660 align:middle line:90%
and just see it both ways.

00:35:55.660 --> 00:35:59.968 align:middle line:90%


00:35:59.968 --> 00:36:01.510 align:middle line:84%
AUDIENCE: I have a
question-- sorry--

00:36:01.510 --> 00:36:05.200 align:middle line:84%
going back to the reversible
adiabatic expansion.

00:36:05.200 --> 00:36:08.830 align:middle line:84%
And you mentioned the
step by inspection.

00:36:08.830 --> 00:36:12.940 align:middle line:84%
And that was when we identified
the variables M and N. Would

00:36:12.940 --> 00:36:15.940 align:middle line:84%
you mind clarifying
how you got to there?

00:36:15.940 --> 00:36:17.320 align:middle line:90%
RAFAEL JARAMILLO: Sure.

00:36:17.320 --> 00:36:20.648 align:middle line:90%
So that was back here, right?

00:36:20.648 --> 00:36:21.440 align:middle line:90%
That was back here?

00:36:21.440 --> 00:36:21.980 align:middle line:90%
AUDIENCE: Yes.

00:36:21.980 --> 00:36:22.938 align:middle line:90%
RAFAEL JARAMILLO: Yeah.

00:36:22.938 --> 00:36:35.420 align:middle line:84%
So let's talk about
coefficients, coefficients.

00:36:35.420 --> 00:36:41.495 align:middle line:84%
I'll ask you, tell me, what
is dT at fixed pressure?

00:36:41.495 --> 00:36:45.200 align:middle line:90%


00:36:45.200 --> 00:36:47.152 align:middle line:84%
Obviously, that's 1, but
forget about the fact

00:36:47.152 --> 00:36:48.110 align:middle line:90%
that you know that's 1.

00:36:48.110 --> 00:36:49.580 align:middle line:90%
Just pick it off of this line.

00:36:49.580 --> 00:36:51.015 align:middle line:90%
What is dT dT at fixed pressure?

00:36:51.015 --> 00:37:02.888 align:middle line:90%


00:37:02.888 --> 00:37:03.680 align:middle line:90%
I'm glad you asked.

00:37:03.680 --> 00:37:08.087 align:middle line:84%
Because this is a very common
mental exercise in thermal,

00:37:08.087 --> 00:37:10.670 align:middle line:84%
and maybe you're less familiar
with it coming into this class.

00:37:10.670 --> 00:37:13.460 align:middle line:84%
All right, differential
form, dependent variable,

00:37:13.460 --> 00:37:15.830 align:middle line:84%
independent variable,
coefficients.

00:37:15.830 --> 00:37:18.600 align:middle line:84%
The coefficients are the
partial differentials.

00:37:18.600 --> 00:37:23.240 align:middle line:84%
So dT and fixed pressure
is this coefficient.

00:37:23.240 --> 00:37:28.170 align:middle line:90%


00:37:28.170 --> 00:37:37.050 align:middle line:84%
Likewise, dT dP at
fixed temperature

00:37:37.050 --> 00:37:40.275 align:middle line:90%
equals N minus MV alpha.

00:37:40.275 --> 00:37:45.000 align:middle line:90%


00:37:45.000 --> 00:37:48.660 align:middle line:84%
Now, this is sort of silly in
some sense, a silly example.

00:37:48.660 --> 00:37:49.620 align:middle line:90%
I mean, it's useful.

00:37:49.620 --> 00:37:51.510 align:middle line:90%
The result is useful.

00:37:51.510 --> 00:37:59.010 align:middle line:84%
It's a little bit of a silly
example because dT has to be 1.

00:37:59.010 --> 00:38:01.440 align:middle line:84%
You don't need to go to
table 4.5 in DeHoff for that.

00:38:01.440 --> 00:38:03.720 align:middle line:84%
You can just go ahead
and say that's 1.

00:38:03.720 --> 00:38:05.548 align:middle line:84%
And dT dP at fixed
temperature, what's

00:38:05.548 --> 00:38:07.215 align:middle line:84%
the dT when temperature
is not changing?

00:38:07.215 --> 00:38:11.910 align:middle line:90%


00:38:11.910 --> 00:38:13.380 align:middle line:90%
AUDIENCE: Oh, that would be 0.

00:38:13.380 --> 00:38:14.880 align:middle line:84%
RAFAEL JARAMILLO:
Has to be 0, yeah.

00:38:14.880 --> 00:38:18.030 align:middle line:84%
So what we have here is we have
a system of equations, right?

00:38:18.030 --> 00:38:22.035 align:middle line:84%
We have two equations
and two unknowns.

00:38:22.035 --> 00:38:24.123 align:middle line:90%


00:38:24.123 --> 00:38:25.540 align:middle line:84%
And that's what
I'm doing here, is

00:38:25.540 --> 00:38:27.457 align:middle line:84%
I'm solving for those
two unknowns given those

00:38:27.457 --> 00:38:28.500 align:middle line:90%
two equations.

00:38:28.500 --> 00:38:30.250 align:middle line:84%
The example that you're
doing in the P set

00:38:30.250 --> 00:38:33.910 align:middle line:90%
is a little bit less--

00:38:33.910 --> 00:38:38.140 align:middle line:84%
I don't want to call
this silly, but it

00:38:38.140 --> 00:38:41.860 align:middle line:84%
does require that you look up
the coefficients in table 4.5.

00:38:41.860 --> 00:38:44.500 align:middle line:84%
It's not as immediately
apparent what

00:38:44.500 --> 00:38:47.890 align:middle line:84%
these should be in the problem
you're working on the P set.

00:38:47.890 --> 00:38:49.510 align:middle line:84%
But that's what I
meant by inspection.

00:38:49.510 --> 00:38:51.302 align:middle line:84%
It means you look at
the differential form,

00:38:51.302 --> 00:38:56.170 align:middle line:84%
you pick off the
partial differentials,

00:38:56.170 --> 00:38:59.110 align:middle line:84%
and you equate them to
what you know them to be.

00:38:59.110 --> 00:39:00.700 align:middle line:90%
In this case, it's 1 and 0.

00:39:00.700 --> 00:39:05.128 align:middle line:90%


00:39:05.128 --> 00:39:06.420 align:middle line:90%
AUDIENCE: OK, that makes sense.

00:39:06.420 --> 00:39:07.290 align:middle line:90%
Thank you so much.

00:39:07.290 --> 00:39:08.990 align:middle line:90%
RAFAEL JARAMILLO: Yeah, thanks.

00:39:08.990 --> 00:39:16.540 align:middle line:84%
So to finish here, coefficients,
coefficients, those

00:39:16.540 --> 00:39:17.530 align:middle line:90%
are coefficients.

00:39:17.530 --> 00:39:21.200 align:middle line:90%


00:39:21.200 --> 00:39:22.790 align:middle line:84%
Let me calculate the
change in entropy

00:39:22.790 --> 00:39:26.720 align:middle line:84%
here, because I think that
it's another example of using

00:39:26.720 --> 00:39:28.610 align:middle line:90%
these differential forms.

00:39:28.610 --> 00:39:30.390 align:middle line:84%
And so maybe it
will help right now.

00:39:30.390 --> 00:39:33.785 align:middle line:84%
So let me give you let
me give you something.

00:39:33.785 --> 00:39:37.040 align:middle line:90%


00:39:37.040 --> 00:39:43.170 align:middle line:84%
We have T and V, and I
want to calculate delta S.

00:39:43.170 --> 00:39:52.940 align:middle line:90%
So I need to integrate dS--

00:39:52.940 --> 00:39:53.440 align:middle line:90%
sorry.

00:39:53.440 --> 00:40:02.610 align:middle line:84%
I need to integrate dS,
which is going to be dS d--

00:40:02.610 --> 00:40:05.050 align:middle line:84%
no change in
temperature-- so dV, dS

00:40:05.050 --> 00:40:10.248 align:middle line:90%
dV at fixed temperature dV.

00:40:10.248 --> 00:40:11.790 align:middle line:84%
This is the thing
I need to integrate

00:40:11.790 --> 00:40:14.640 align:middle line:84%
to get my answer,
which means I need

00:40:14.640 --> 00:40:16.600 align:middle line:90%
to be able to write this down.

00:40:16.600 --> 00:40:18.420 align:middle line:84%
I need to know what
is this coefficient.

00:40:18.420 --> 00:40:21.270 align:middle line:90%


00:40:21.270 --> 00:40:22.990 align:middle line:90%
That's what I need to know.

00:40:22.990 --> 00:40:24.870 align:middle line:84%
So the implied
differential form here

00:40:24.870 --> 00:40:34.980 align:middle line:84%
is dS equals dS dV at fixed
temperature dV plus dS as dT

00:40:34.980 --> 00:40:36.960 align:middle line:90%
at fixed volume dT.

00:40:36.960 --> 00:40:41.442 align:middle line:90%


00:40:41.442 --> 00:40:42.900 align:middle line:84%
I'm going to skip
a couple of steps

00:40:42.900 --> 00:40:45.270 align:middle line:84%
here because we have
8 minutes remaining.

00:40:45.270 --> 00:40:49.850 align:middle line:84%
So I'm going to use
the general strategy--

00:40:49.850 --> 00:40:51.800 align:middle line:84%
or I think this
particular case is also

00:40:51.800 --> 00:40:54.380 align:middle line:84%
just worked in the book, so
I could also go look it up.

00:40:54.380 --> 00:40:58.820 align:middle line:84%
And I get dS equals-- and
we have to copy this--

00:40:58.820 --> 00:41:07.616 align:middle line:84%
Cp over T minus V alpha
squared over beta.

00:41:07.616 --> 00:41:10.460 align:middle line:84%
A lot of times, again, these
coefficients are non-obvious.

00:41:10.460 --> 00:41:12.290 align:middle line:84%
You just have to
trust that you're

00:41:12.290 --> 00:41:15.780 align:middle line:84%
doing the process correctly
and use the result. OK.

00:41:15.780 --> 00:41:18.320 align:middle line:84%
So this happens to
be what you get.

00:41:18.320 --> 00:41:22.640 align:middle line:90%


00:41:22.640 --> 00:41:26.030 align:middle line:90%
So for dT equals 0--

00:41:26.030 --> 00:41:30.537 align:middle line:84%
again, good choice of an
independent variable because I

00:41:30.537 --> 00:41:32.120 align:middle line:84%
get to ignore half
the right-hand side

00:41:32.120 --> 00:41:34.010 align:middle line:90%
of the equation.

00:41:34.010 --> 00:41:42.490 align:middle line:84%
For dT equals 0, dS
equals alpha over beta dV.

00:41:42.490 --> 00:41:47.070 align:middle line:90%


00:41:47.070 --> 00:42:00.670 align:middle line:84%
For an ideal gas, we have alpha
equals 1/T. Beta equals 1/P.

00:42:00.670 --> 00:42:05.680 align:middle line:90%
dS equals P over T dV--

00:42:05.680 --> 00:42:16.440 align:middle line:90%


00:42:16.440 --> 00:42:20.650 align:middle line:84%
again, using ideal
gas equation of state.

00:42:20.650 --> 00:42:24.340 align:middle line:84%
So this is pretty
simple in the end.

00:42:24.340 --> 00:42:27.515 align:middle line:90%
I can integrate dS.

00:42:27.515 --> 00:42:30.050 align:middle line:90%


00:42:30.050 --> 00:42:37.310 align:middle line:84%
It's going to be the
integral by dV of R/V

00:42:37.310 --> 00:42:46.550 align:middle line:84%
equals simply R
log V2 over V1 dS.

00:42:46.550 --> 00:42:48.068 align:middle line:90%
This is my answer.

00:42:48.068 --> 00:42:49.610 align:middle line:84%
This is the answer
I was looking for,

00:42:49.610 --> 00:42:59.340 align:middle line:84%
the change of entropy for a
reversible process isothermal

00:42:59.340 --> 00:43:00.240 align:middle line:90%
expansion.

00:43:00.240 --> 00:43:10.630 align:middle line:90%


00:43:10.630 --> 00:43:13.310 align:middle line:90%
And here's an important thing.

00:43:13.310 --> 00:43:15.040 align:middle line:90%
It's greater than 0.

00:43:15.040 --> 00:43:16.675 align:middle line:90%
So what does this mean?

00:43:16.675 --> 00:43:23.310 align:middle line:90%


00:43:23.310 --> 00:43:42.640 align:middle line:84%
If I start with my gas molecules
here in vacuum on the right,

00:43:42.640 --> 00:43:54.950 align:middle line:84%
spontaneous process is going
to bring me to gas molecules

00:43:54.950 --> 00:43:55.901 align:middle line:90%
everywhere.

00:43:55.901 --> 00:44:01.130 align:middle line:90%


00:44:01.130 --> 00:44:09.740 align:middle line:84%
V2 over V1 greater than
1, delta S greater than 0.

00:44:09.740 --> 00:44:11.450 align:middle line:90%
Spontaneous entropy generation.

00:44:11.450 --> 00:44:18.180 align:middle line:90%


00:44:18.180 --> 00:44:20.640 align:middle line:84%
What happens if I tried to
run this movie backwards?

00:44:20.640 --> 00:44:24.090 align:middle line:90%


00:44:24.090 --> 00:44:29.430 align:middle line:84%
If I ran this movie
backwards, everything

00:44:29.430 --> 00:44:32.670 align:middle line:84%
would be the same in
terms of the calculation,

00:44:32.670 --> 00:44:34.980 align:middle line:84%
except V2 and V1
would be switched.

00:44:34.980 --> 00:44:38.150 align:middle line:84%
The final volume
would be smaller

00:44:38.150 --> 00:44:39.350 align:middle line:90%
than the initial volume.

00:44:39.350 --> 00:44:45.090 align:middle line:90%


00:44:45.090 --> 00:44:47.210 align:middle line:84%
So the change of entropy
would be negative.

00:44:47.210 --> 00:44:54.110 align:middle line:90%


00:44:54.110 --> 00:44:58.510 align:middle line:84%
So it's our experience that
you won't spontaneously

00:44:58.510 --> 00:45:02.260 align:middle line:84%
have the gas molecules
uniformly distributed in the box

00:45:02.260 --> 00:45:03.850 align:middle line:84%
and then going
through a situation

00:45:03.850 --> 00:45:06.280 align:middle line:84%
where they leave a vacuum
on the right-hand side.

00:45:06.280 --> 00:45:07.780 align:middle line:90%
That's not our experience.

00:45:07.780 --> 00:45:12.620 align:middle line:90%


00:45:12.620 --> 00:45:22.630 align:middle line:84%
Here's uniform gas
molecules going to--

00:45:22.630 --> 00:45:24.790 align:middle line:84%
that red pen is
causing trouble here--

00:45:24.790 --> 00:45:25.950 align:middle line:90%
going to a situation.

00:45:25.950 --> 00:45:30.540 align:middle line:90%


00:45:30.540 --> 00:45:36.490 align:middle line:84%
But they segregated themselves
spontaneously on one side.

00:45:36.490 --> 00:45:40.840 align:middle line:90%


00:45:40.840 --> 00:45:45.230 align:middle line:84%
We know this would never
happen spontaneously.

00:45:45.230 --> 00:45:48.230 align:middle line:84%
Again, this sort of goes back
to the baby book we discussed.

00:45:48.230 --> 00:45:51.500 align:middle line:84%
This happens spontaneously, this
doesn't happen spontaneously.

00:45:51.500 --> 00:45:54.890 align:middle line:84%
Now we have some
math to support that.

00:45:54.890 --> 00:45:56.910 align:middle line:84%
We have something
called the second law.

00:45:56.910 --> 00:45:58.760 align:middle line:84%
We know that
spontaneously, entropy

00:45:58.760 --> 00:46:01.530 align:middle line:84%
has to always increase
or stay the same.

00:46:01.530 --> 00:46:03.590 align:middle line:90%
It can never decrease.

00:46:03.590 --> 00:46:06.280 align:middle line:84%
And now the math of
this backs us up.

00:46:06.280 --> 00:46:10.450 align:middle line:84%
In this case, over
here, we have V2 over V1

00:46:10.450 --> 00:46:12.580 align:middle line:90%
would be less than 1.

00:46:12.580 --> 00:46:17.520 align:middle line:84%
And delta S would
be less than 0.

00:46:17.520 --> 00:46:19.550 align:middle line:90%
So that doesn't happen.

00:46:19.550 --> 00:46:23.000 align:middle line:90%