WEBVTT

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[SQUEAKING]

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[RUSTLING]

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[CLICKING]

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PROFESSOR: On Friday, we had
a very almost philosophical

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lecture.

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And the second law
can get like that.

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It gets sometimes a little
bit head in the clouds.

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So today is going to
be pretty mathematical.

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But, actually, it's
very practical.

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We're going to start moving from
this very highfalutin concept

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of the second law
towards useful equations

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that we can use, things that
we can use to make predictions.

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So I'm going to tell you
about thermodynamic potentials

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and equilibrium.

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And I'm going to start
off just by listing them.

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These are going to be presented
without proof or motivation

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[INAUDIBLE] we'll discuss.

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So the first one is what
we already know now.

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For fixed U entropy
is max at equilibrium.

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So you already know that.

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But there are others.

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There are other conditions
and other potentials.

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So for fixed entropy and
volume, the internal energy U

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is minimum at equilibrium.

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So this is a condition
that you encounter

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in your introductory
physics classes.

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They don't really state that,
but that's the condition.

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Is there ever really a
way to fix the entropy?

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Is there a way?

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How can we fix the entropy?

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There's no entropy reservoir.

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We can't connect the system
to an entropy reservoir

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like we can with a pressure
reservoir or a temperature

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reservoir.

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So I'll tell you-- it's
a little bit of an aside.

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But the only way to fix
entropy is to be at 0 Kelvin.

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When you're at absolute
zero, there's no entropy.

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So the physicists
like it that way.

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But for the rest of us,
it's not terribly useful.

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For fixed S and P, new
term here, the enthalpy H

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equals U plus PV is
minimized at equilibrium.

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OK.

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So that's enthalpy.

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This condition, minimum
enthalpy and equilibrium,

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is not terribly useful.

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But the enthalpy is useful.

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It's a useful thing.

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And one of the problems
on the current p set

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is making connection
between enthalpy

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and the heat of a process.

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Sometimes those terms
enthalpy and heat

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are actually used
interchangeably.

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That's not strictly
correct, but you'll see why.

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More perfect
temperature and volume--

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so now we're getting a
little more practical,

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fixed temperature.

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That's something
we know how to do.

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We all have thermostats.

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That's what your
thermostat does.

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The Helmholtz, F equals U
minus TS is min at equilibrium.

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So I'll tell you, we
spent almost no time

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at all on Helmholtz
in this class

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because fixed temperature and
volume are much less practical

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and useful than fixed
temperature and pressure

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for materials processing.

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However, in other
disciplines, especially

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in semiconductors and
semiconductor physics,

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it's the Helmholtz
free energy that

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matters because your device is
typically operated at a fixed

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temperature, and
your electrons are

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confined in the volume of
the semiconductor device.

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So if we were to do
things like calculate

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the theoretical limiting
efficiency of a solar cell,

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we'd be worrying
about Helmholtz.

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But as it is, you almost never
hear us discuss that at all

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in the rest of the class.

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This is the one that
matters, perfect temperature

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and pressure.

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Anybody know what's the relevant
potential for these conditions?

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Who's read ahead?

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AUDIENCE: Gibbs free energy.

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PROFESSOR: Gibbs, right.

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So this is the one that
matters for material science.

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And one way to see the
rest of this class,

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actually the rest of
the term, is we're

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just calculating the Gibbs
for different scenarios.

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And we're doing price
shopping for Gibbs, I call it.

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We calculate the Gibbs free
energy for different scenarios.

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And we choose the lowest
one as the equilibrium case.

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So that is thermodynamic
potentials.

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Now these are presented
without proof.

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It's not worth the
time here to motivate

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each and every one of those.

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On the piece that
you're going to convince

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yourselves that given
this, then this.

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So one of the exercises
is going through a form

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of proof of this.

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And that's useful because
Gibbs is the one we care about.

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Now I have to make some
mathematical asides because

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without this, my math
note, a lot of what comes

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is kind of weird and confusing.

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So in 3.020, state functions and
state variables are functions

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of at most three independent
variables and both stay

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independent variables.

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And this is where
that comes from.

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It comes from-- sorry,
this pen is kind of smushy.

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It doesn't come from nowhere.

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It comes from the
combined statement.

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So it comes from
physical reasoning.

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dU equals TdS minus PdV plus mu.

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Yeah.

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This implies the existence
of a state function.

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U is a function of S, V, and N.

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This is a critical link here.

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If you write down a
differential form,

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we're going to learn
how to identify

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the independent variables,
the coefficients,

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and the dependent variable.

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And the existence of
this differential form

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implies a state function.

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Now, in most cases, we may
never know this, but can--

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we can still use this.

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That is, we may never know
the closed form of the state

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function.

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But we can still use
its differential form.

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In fact, outside of the
ideal gas situation,

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we almost never write down any
state functions in this class.

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You can't find a complete
state function for something

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useful like a
high-entropy alloy.

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It doesn't exist.

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It's too complicated.

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So a corollary of this is that
thermodynamic potentials have

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what I'll call natural
independent variables, which

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we will see aplenty
in the case of Gibbs.

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So for example, entropy is a
function of energy and volume.

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If you remember, at
equilibrium, entropy

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was max for fixed
energy and fixed volume.

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That tells you that those
are its natural variables.

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At equilibrium, internal
energy was maximum

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for fixed entropy and volume.

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Those are its natural variables.

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Enthalpy was equilibrium
for a minimum at equilibrium

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for fixed entropy and pressure.

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Those are its natural variables.

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For Helmholtz, its
natural variables

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are T and V. And for Gibbs, its
natural variables are T and P.

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Before you ding me
here, I'm not writing

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the ends for compactness.

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So everything is also a function
of the size of a system.

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I'm just leaving that off
to keep the lines short.

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One more note.

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Where on Earth does
this stuff come from?

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When I learned thermo,
these potentials

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were just told to me the
way I just told them to you.

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And I think in the back
of my mind, I said,

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where does that come from?

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And then I forgot the question.

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And I didn't come
back to it for years.

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It does come from somewhere.

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The potentials are related
by a change of variables

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via Legendre transforms.

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So this is something we don't
have time for in this class,

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and probably I wouldn't be
able to teach very well anyway.

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This is the math concept.

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And so for those of
you who have seen

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Legendre transforms in your
math classes, that's great.

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For those of you
who are curious,

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you can start with a wiki entry.

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We're not going to
cover it in detail.

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You can think of it as just
one more type of a transform,

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like a Fourier transform
or Laplace transform.

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Fourier transform, for example,
changes your natural variables

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from time to frequency.

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That's an example.

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Legendre transform will change
natural variables, for example,

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from U as a function of S and V
to H as a function of S and P,

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exchanging V for P.
And if you'll remember,

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H equals U plus PV.

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And this comes from somewhere.

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This is all beyond--

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this is beyond 020.

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I just want you to know
it comes from somewhere.

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It comes from somewhere.

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For most of the class,
you can just memorize.

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Try a bit a little more.

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Let's start with the
combined statement.

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dU equals T dS
minus PdV plus mu.

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I'll let this be a
multi-component system.

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So I'll keep the labels there.

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Somebody please remind me, what
are the independent variables

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in this differential form?

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AUDIENCE: S, V, and I.

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PROFESSOR: Correct.

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Those are the
independent variables.

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The other things we call--

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having fun with color today.

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The other things we
call coefficients.

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So the coefficients describe how
the dependent variable varies

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with the independent variables.

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And we can write down by
inspection coefficient

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relations.

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And here they are.

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dU dS.

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DU dS at fixed volume and fixed
particle number equals what?

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What is partial U by S?

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You can pick it off of--

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AUDIENCE: p?

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PROFESSOR: Yep, you just
look at the equation.

00:15:42.803 --> 00:15:44.460 align:middle line:90%
Put the terms apart.

00:15:44.460 --> 00:15:46.060 align:middle line:90%
And pick these off.

00:15:46.060 --> 00:15:54.850 align:middle line:84%
dU dV at fixed entropy and
particle number equals minus p.

00:15:54.850 --> 00:16:06.000 align:middle line:84%
And dU d Ni at fixed entropy
and volume and particle number J

00:16:06.000 --> 00:16:10.540 align:middle line:90%
not equal to i equals mu i.

00:16:10.540 --> 00:16:11.600 align:middle line:90%
Where's your coefficient?

00:16:11.600 --> 00:16:14.910 align:middle line:90%


00:16:14.910 --> 00:16:15.960 align:middle line:90%
Good call.

00:16:15.960 --> 00:16:18.510 align:middle line:84%
You can them O. I just
picked partial differentials.

00:16:18.510 --> 00:16:21.820 align:middle line:84%
But they're called
coefficient relations.

00:16:21.820 --> 00:16:24.520 align:middle line:84%
A lot of problem
solving in thermo

00:16:24.520 --> 00:16:28.419 align:middle line:84%
comes down to calculating
these coefficients.

00:16:28.419 --> 00:16:32.730 align:middle line:90%


00:16:32.730 --> 00:16:36.621 align:middle line:84%
The whole chapter,
actually, in--

00:16:36.621 --> 00:16:39.390 align:middle line:90%
get to chapter 10 of the book.

00:16:39.390 --> 00:16:41.070 align:middle line:84%
The most useful
chapter is chapter 4.

00:16:41.070 --> 00:16:42.900 align:middle line:84%
If you read only one
chapter of this book,

00:16:42.900 --> 00:16:47.810 align:middle line:84%
pick chapter 4 because
it contains all

00:16:47.810 --> 00:16:49.730 align:middle line:84%
that we need to
actually solve problems.

00:16:49.730 --> 00:16:51.920 align:middle line:84%
To actually solve
problems, you just

00:16:51.920 --> 00:16:53.630 align:middle line:90%
have to understand chapter 4.

00:16:53.630 --> 00:16:54.440 align:middle line:90%
And I say just.

00:16:54.440 --> 00:16:56.480 align:middle line:84%
It's actually one of
the hairier chapters.

00:16:56.480 --> 00:16:57.320 align:middle line:90%
But there it is.

00:16:57.320 --> 00:16:59.300 align:middle line:84%
And it's all about these
coefficient relations

00:16:59.300 --> 00:17:02.600 align:middle line:84%
and identifying
independent variables

00:17:02.600 --> 00:17:03.920 align:middle line:90%
and calculating coefficients.

00:17:03.920 --> 00:17:05.210 align:middle line:90%
So let's see how to do that.

00:17:05.210 --> 00:17:07.780 align:middle line:90%


00:17:07.780 --> 00:17:10.480 align:middle line:84%
I wouldn't have called
this a strategy.

00:17:10.480 --> 00:17:11.829 align:middle line:90%
I think it's a little funny.

00:17:11.829 --> 00:17:14.140 align:middle line:84%
Besides, it's a
tactic, not a strategy.

00:17:14.140 --> 00:17:16.119 align:middle line:84%
But that's what it's
called in DeHoff.

00:17:16.119 --> 00:17:17.109 align:middle line:90%
So I'll stick with it.

00:17:17.109 --> 00:17:21.550 align:middle line:84%
The general strategy
for deriving

00:17:21.550 --> 00:17:28.010 align:middle line:90%
thermodynamic relations.

00:17:28.010 --> 00:17:32.020 align:middle line:90%


00:17:32.020 --> 00:17:34.195 align:middle line:84%
This is really best
illustrated by an example.

00:17:34.195 --> 00:17:35.570 align:middle line:84%
So that's what
we're going to do.

00:17:35.570 --> 00:17:43.190 align:middle line:84%
Here is the general problem,
the general problem statement.

00:17:43.190 --> 00:17:50.230 align:middle line:90%


00:17:50.230 --> 00:18:06.220 align:middle line:84%
Given a dependent
state variable Z,

00:18:06.220 --> 00:18:23.080 align:middle line:84%
independent state variables
x and y, calculate--

00:18:23.080 --> 00:18:26.020 align:middle line:90%
so this is a word problem--

00:18:26.020 --> 00:18:30.124 align:middle line:90%
delta V for a given process.

00:18:30.124 --> 00:18:35.820 align:middle line:90%


00:18:35.820 --> 00:18:37.010 align:middle line:90%
So this is like--

00:18:37.010 --> 00:18:42.620 align:middle line:84%
probably half of all thermo
problems boil down to something

00:18:42.620 --> 00:18:44.198 align:middle line:90%
like this.

00:18:44.198 --> 00:18:46.490 align:middle line:84%
There's some kind of state
variable, which you identify

00:18:46.490 --> 00:18:47.880 align:middle line:90%
through the problem statement.

00:18:47.880 --> 00:18:49.422 align:middle line:84%
There are some
independent variables,

00:18:49.422 --> 00:18:51.048 align:middle line:90%
which usually you're not told.

00:18:51.048 --> 00:18:53.090 align:middle line:84%
You figure them out through
the problem statement

00:18:53.090 --> 00:18:54.830 align:middle line:90%
or the situation in hand.

00:18:54.830 --> 00:18:57.450 align:middle line:84%
And you want to calculate the
change for a given process.

00:18:57.450 --> 00:18:59.520 align:middle line:84%
So what example
are we going to do?

00:18:59.520 --> 00:19:01.182 align:middle line:90%
Example.

00:19:01.182 --> 00:19:23.370 align:middle line:84%
Calculate delta V for a process
involving a change of pressure

00:19:23.370 --> 00:19:34.510 align:middle line:84%
at fixed entropy,
which is also is

00:19:34.510 --> 00:19:40.320 align:middle line:90%
a reversible adiabatic process.

00:19:40.320 --> 00:19:46.730 align:middle line:90%


00:19:46.730 --> 00:19:50.220 align:middle line:84%
This is helpful,
remembering that

00:19:50.220 --> 00:19:56.580 align:middle line:84%
fixed entropy and
reversible adiabatic

00:19:56.580 --> 00:19:58.138 align:middle line:90%
processes are related.

00:19:58.138 --> 00:19:59.055 align:middle line:90%
That's really helpful.

00:19:59.055 --> 00:20:03.290 align:middle line:90%


00:20:03.290 --> 00:20:05.450 align:middle line:84%
So now I'm going to step
through this example.

00:20:05.450 --> 00:20:10.730 align:middle line:90%


00:20:10.730 --> 00:20:16.827 align:middle line:84%
We want to write down the
differential for the change

00:20:16.827 --> 00:20:17.910 align:middle line:90%
in the dependent variable.

00:20:17.910 --> 00:20:20.700 align:middle line:90%


00:20:20.700 --> 00:20:28.090 align:middle line:84%
And this is going to depend
on some coefficient times dP

00:20:28.090 --> 00:20:33.020 align:middle line:90%
plus some coefficient times dS.

00:20:33.020 --> 00:20:36.540 align:middle line:90%


00:20:36.540 --> 00:20:39.060 align:middle line:90%
And our job is to find--

00:20:39.060 --> 00:20:50.850 align:middle line:90%


00:20:50.850 --> 00:20:55.110 align:middle line:84%
we want to find
those coefficients,

00:20:55.110 --> 00:20:56.670 align:middle line:90%
and then integrate--

00:20:56.670 --> 00:21:07.940 align:middle line:90%


00:21:07.940 --> 00:21:10.230 align:middle line:90%
this is the approach.

00:21:10.230 --> 00:21:12.390 align:middle line:84%
Once you find
these coefficients,

00:21:12.390 --> 00:21:17.125 align:middle line:84%
then you can integrate this
term, which for fixed entropy

00:21:17.125 --> 00:21:18.750 align:middle line:84%
gives you the thing
you're looking for,

00:21:18.750 --> 00:21:20.237 align:middle line:90%
which is the change in volume.

00:21:20.237 --> 00:21:21.320 align:middle line:90%
That's what we need to do.

00:21:21.320 --> 00:21:25.000 align:middle line:90%


00:21:25.000 --> 00:21:28.750 align:middle line:84%
Questions before I go
on to actually do that?

00:21:28.750 --> 00:21:29.250 align:middle line:90%
OK.

00:21:29.250 --> 00:21:32.370 align:middle line:90%


00:21:32.370 --> 00:21:34.440 align:middle line:90%
Then we're going to start.

00:21:34.440 --> 00:21:41.792 align:middle line:84%
1-- we're going to write
the exact differential.

00:21:41.792 --> 00:21:45.950 align:middle line:90%


00:21:45.950 --> 00:21:47.870 align:middle line:90%
Rewriting what we did.

00:21:47.870 --> 00:21:53.820 align:middle line:90%
dV equals x dP plus Y dS.

00:21:53.820 --> 00:21:58.110 align:middle line:90%


00:21:58.110 --> 00:22:03.650 align:middle line:90%
x equals dV dP at s.

00:22:03.650 --> 00:22:09.820 align:middle line:90%
Y equals dV dS at p.

00:22:09.820 --> 00:22:11.580 align:middle line:90%
OK, good.

00:22:11.580 --> 00:22:18.780 align:middle line:84%
Then, we're going to do
a change of variables.

00:22:18.780 --> 00:22:21.820 align:middle line:90%


00:22:21.820 --> 00:22:26.790 align:middle line:84%
There's a really useful
reference, DeHoff table 4.5.

00:22:26.790 --> 00:22:42.415 align:middle line:84%
To express dP and dS
in terms of dP and dT.

00:22:42.415 --> 00:22:48.020 align:middle line:90%


00:22:48.020 --> 00:22:51.170 align:middle line:84%
DeHoff chooses P and T because
it's a materials science text.

00:22:51.170 --> 00:22:53.300 align:middle line:84%
Another text might have
chosen a different two.

00:22:53.300 --> 00:22:55.880 align:middle line:90%
You can choose any two.

00:22:55.880 --> 00:22:59.830 align:middle line:84%
So we're going to
look up in table 4.5.

00:22:59.830 --> 00:23:08.660 align:middle line:84%
And it has the coefficients
for every state variable

00:23:08.660 --> 00:23:11.780 align:middle line:90%
as a function of dP and dT.

00:23:11.780 --> 00:23:14.210 align:middle line:90%
So here, this is trivial.

00:23:14.210 --> 00:23:19.280 align:middle line:84%
There's going to be no-- this
is 0 because dP equals dP.

00:23:19.280 --> 00:23:20.900 align:middle line:90%
That's trivial.

00:23:20.900 --> 00:23:22.582 align:middle line:90%
The entropy is nontrivial.

00:23:22.582 --> 00:23:25.040 align:middle line:84%
We could derive this, but we're
not going to take the time.

00:23:25.040 --> 00:23:27.800 align:middle line:84%
We're just going to
copy it from the table.

00:23:27.800 --> 00:23:32.330 align:middle line:84%
It happens to be equal to
Cp over temperature times dT

00:23:32.330 --> 00:23:35.780 align:middle line:90%
minus V alpha dP.

00:23:35.780 --> 00:23:39.440 align:middle line:90%


00:23:39.440 --> 00:23:40.950 align:middle line:90%
That's not obvious to me.

00:23:40.950 --> 00:23:42.530 align:middle line:90%
I have to think about it.

00:23:42.530 --> 00:23:45.170 align:middle line:84%
This I could figure out if I
thought about it long enough.

00:23:45.170 --> 00:23:47.128 align:middle line:84%
This, it doesn't
make sense to me.

00:23:47.128 --> 00:23:48.170 align:middle line:90%
I just have to derive it.

00:23:48.170 --> 00:23:50.380 align:middle line:84%
But you don't have to
derive it or think about it.

00:23:50.380 --> 00:23:51.630 align:middle line:90%
It's right there in the table.

00:23:51.630 --> 00:23:55.820 align:middle line:84%
So here is pressure
and entropy written now

00:23:55.820 --> 00:23:59.613 align:middle line:84%
as dependent variables,
dependent on temperature

00:23:59.613 --> 00:24:00.155 align:middle line:90%
and pressure.

00:24:00.155 --> 00:24:03.600 align:middle line:90%


00:24:03.600 --> 00:24:06.870 align:middle line:84%
So we're going to combine
now, and we get the following.

00:24:06.870 --> 00:24:11.435 align:middle line:90%
dV equals x-- then we combine--

00:24:11.435 --> 00:24:16.400 align:middle line:90%


00:24:16.400 --> 00:24:20.320 align:middle line:90%
--equals dP-- that's easy--

00:24:20.320 --> 00:24:22.210 align:middle line:90%
plus Y. What's Cs?

00:24:22.210 --> 00:24:29.020 align:middle line:84%
Cs equals Cp over T
dT minus V alpha dP.

00:24:29.020 --> 00:24:32.950 align:middle line:90%


00:24:32.950 --> 00:24:36.820 align:middle line:84%
I just plugged in, substituted,
substituted for dS here.

00:24:36.820 --> 00:24:40.877 align:middle line:90%


00:24:40.877 --> 00:24:41.960 align:middle line:90%
So that's the second step.

00:24:41.960 --> 00:24:44.640 align:middle line:90%


00:24:44.640 --> 00:24:46.190 align:middle line:90%
Then I'm going to collect terms.

00:24:46.190 --> 00:24:48.050 align:middle line:90%
The third step-- collect terms.

00:24:48.050 --> 00:24:52.260 align:middle line:90%


00:24:52.260 --> 00:24:52.860 align:middle line:90%
Collect terms.

00:24:52.860 --> 00:24:53.860 align:middle line:90%
So I have the following.

00:24:53.860 --> 00:25:09.470 align:middle line:84%
I have dV equals Y tP over
temperature dT plus X minus YV

00:25:09.470 --> 00:25:11.350 align:middle line:90%
alpha dP.

00:25:11.350 --> 00:25:18.178 align:middle line:90%


00:25:18.178 --> 00:25:20.900 align:middle line:84%
I still don't have X and Y. I
still don't know what they are.

00:25:20.900 --> 00:25:24.210 align:middle line:90%


00:25:24.210 --> 00:25:35.490 align:middle line:84%
But I can say by inspection,
dV dT at fixed pressure

00:25:35.490 --> 00:25:40.050 align:middle line:84%
equals Y Cp over T.
That's this coefficient.

00:25:40.050 --> 00:25:43.700 align:middle line:90%


00:25:43.700 --> 00:25:48.830 align:middle line:84%
dV by temperature at fixed
pressure is that coefficient.

00:25:48.830 --> 00:25:57.450 align:middle line:84%
And dV dP at fixed temperature
equals this coefficient, X

00:25:57.450 --> 00:26:00.675 align:middle line:90%
minus YV alpha.

00:26:00.675 --> 00:26:15.020 align:middle line:90%


00:26:15.020 --> 00:26:16.760 align:middle line:84%
We get the coefficients
by inspection.

00:26:16.760 --> 00:26:19.930 align:middle line:90%


00:26:19.930 --> 00:26:30.710 align:middle line:84%
The fourth step is you compare
to the known coefficients,

00:26:30.710 --> 00:26:34.580 align:middle line:90%
again referring to table 4.5.

00:26:34.580 --> 00:26:38.300 align:middle line:84%
So in table 4.5, you will
find the differential form

00:26:38.300 --> 00:26:41.670 align:middle line:84%
of volume written as a function
of temperature and pressure.

00:26:41.670 --> 00:26:43.070 align:middle line:90%
And this is what you'll find.

00:26:43.070 --> 00:26:48.470 align:middle line:90%
V alpha dT minus V beta dP.

00:26:48.470 --> 00:26:53.400 align:middle line:90%


00:26:53.400 --> 00:26:56.920 align:middle line:90%
So here's the thing.

00:26:56.920 --> 00:27:03.800 align:middle line:84%
This coefficient and this
thing have to be equal.

00:27:03.800 --> 00:27:07.660 align:middle line:84%
And this thing and
this thing have

00:27:07.660 --> 00:27:12.070 align:middle line:84%
to be equal because they're both
the same mathematical objects.

00:27:12.070 --> 00:27:14.027 align:middle line:90%
They are these partials.

00:27:14.027 --> 00:27:16.360 align:middle line:84%
I always say if it walks like
a duck, talks like a duck,

00:27:16.360 --> 00:27:18.250 align:middle line:90%
it's the same thing.

00:27:18.250 --> 00:27:20.082 align:middle line:84%
Compare the known
coefficients and equate.

00:27:20.082 --> 00:27:22.988 align:middle line:90%


00:27:22.988 --> 00:27:24.030 align:middle line:90%
So we're going to equate.

00:27:24.030 --> 00:27:25.155 align:middle line:90%
We're going to equate them.

00:27:25.155 --> 00:27:30.880 align:middle line:84%
And we're to get the following.
dV dT at fixed pressure--

00:27:30.880 --> 00:27:32.850 align:middle line:90%
well, that was this--

00:27:32.850 --> 00:27:36.060 align:middle line:90%
equals Y Cp over T--

00:27:36.060 --> 00:27:37.920 align:middle line:90%
but it's also this--

00:27:37.920 --> 00:27:40.050 align:middle line:90%
equals V alpha.

00:27:40.050 --> 00:27:48.380 align:middle line:84%
And dV dP at fixed
temperature equals this.

00:27:48.380 --> 00:27:51.590 align:middle line:90%
X minus Y V alpha.

00:27:51.590 --> 00:27:53.480 align:middle line:90%
But it's also this.

00:27:53.480 --> 00:27:56.910 align:middle line:90%
It goes minus V beta.

00:27:56.910 --> 00:27:58.940 align:middle line:90%
So now, we have our answer.

00:27:58.940 --> 00:27:59.900 align:middle line:90%
How?

00:27:59.900 --> 00:28:02.360 align:middle line:84%
We have a system
of two equations

00:28:02.360 --> 00:28:07.430 align:middle line:84%
and two unknowns, X and Y. Two
equations and two unknowns.

00:28:07.430 --> 00:28:08.315 align:middle line:90%
So now you can solve.

00:28:08.315 --> 00:28:11.310 align:middle line:90%


00:28:11.310 --> 00:28:13.775 align:middle line:90%
5-- solve for unknowns.

00:28:13.775 --> 00:28:21.660 align:middle line:90%


00:28:21.660 --> 00:28:25.350 align:middle line:84%
I'll spare you the algebra
there because it's pretty easy.

00:28:25.350 --> 00:28:31.960 align:middle line:90%
Solving for Y V alpha T over Cp.

00:28:31.960 --> 00:28:36.510 align:middle line:84%
And solving for X
equals V squared alpha

00:28:36.510 --> 00:28:45.160 align:middle line:90%
squared T over Cp minus V beta.

00:28:45.160 --> 00:28:48.040 align:middle line:84%
And these are complicated
and nonobvious.

00:28:48.040 --> 00:28:50.290 align:middle line:84%
That's why you need a
tactic, set of tactics,

00:28:50.290 --> 00:28:51.207 align:middle line:90%
to get to the answers.

00:28:51.207 --> 00:28:52.707 align:middle line:84%
Because if you
follow this approach,

00:28:52.707 --> 00:28:54.280 align:middle line:84%
you will always get
the right answer

00:28:54.280 --> 00:28:57.410 align:middle line:84%
even if it doesn't
make sense to you.

00:28:57.410 --> 00:28:59.290 align:middle line:90%
So here's the final answer.

00:28:59.290 --> 00:29:02.770 align:middle line:84%
dV equals V squared
alpha squared

00:29:02.770 --> 00:29:14.390 align:middle line:84%
T over a Cp minus
V beta times dP

00:29:14.390 --> 00:29:21.560 align:middle line:90%
plus V alpha T over Cp times dS.

00:29:21.560 --> 00:29:23.180 align:middle line:84%
This is the thing
we were looking for.

00:29:23.180 --> 00:29:27.730 align:middle line:90%


00:29:27.730 --> 00:29:30.660 align:middle line:90%
That's it.

00:29:30.660 --> 00:29:55.610 align:middle line:84%
We integrate this to find
change delta V for given delta P

00:29:55.610 --> 00:29:58.680 align:middle line:90%
at fixed entropy.

00:29:58.680 --> 00:30:04.330 align:middle line:90%


00:30:04.330 --> 00:30:05.830 align:middle line:90%
Again, this is mechanics.

00:30:05.830 --> 00:30:07.480 align:middle line:84%
This will work for
you even if you

00:30:07.480 --> 00:30:10.370 align:middle line:84%
don't have a physical
intuition for every step.

00:30:10.370 --> 00:30:13.660 align:middle line:90%
This strategy works.

00:30:13.660 --> 00:30:15.010 align:middle line:90%
Question.

00:30:15.010 --> 00:30:18.190 align:middle line:84%
For a real material,
when you are--

00:30:18.190 --> 00:30:20.420 align:middle line:90%
this is very realistic.

00:30:20.420 --> 00:30:22.690 align:middle line:84%
I mean, now we go from
multivariable calculus

00:30:22.690 --> 00:30:24.400 align:middle line:90%
to money on the line.

00:30:24.400 --> 00:30:29.650 align:middle line:84%
You are calculating the
effect of a pressure change

00:30:29.650 --> 00:30:31.780 align:middle line:90%
on the volume of components.

00:30:31.780 --> 00:30:34.330 align:middle line:84%
Let's say you're going to
send this into outer space.

00:30:34.330 --> 00:30:37.285 align:middle line:84%
And you have a system
made out of components.

00:30:37.285 --> 00:30:39.160 align:middle line:84%
And the components are
made out of materials.

00:30:39.160 --> 00:30:41.243 align:middle line:84%
And you want to make sure
that the pressure change

00:30:41.243 --> 00:30:44.980 align:middle line:84%
that your device experience
isn't going to cause the thing

00:30:44.980 --> 00:30:46.900 align:middle line:90%
to fall apart.

00:30:46.900 --> 00:30:48.120 align:middle line:90%
So now this matters a lot.

00:30:48.120 --> 00:30:50.790 align:middle line:84%
You need to know how
to do that calculation.

00:30:50.790 --> 00:30:51.720 align:middle line:90%
Here's how.

00:30:51.720 --> 00:30:52.440 align:middle line:90%
Question.

00:30:52.440 --> 00:30:55.371 align:middle line:90%
Where are you going to get this?

00:30:55.371 --> 00:30:57.150 align:middle line:90%
This is the integrant.

00:30:57.150 --> 00:30:59.220 align:middle line:84%
How are you going to
evaluate the integrant?

00:30:59.220 --> 00:31:02.685 align:middle line:90%


00:31:02.685 --> 00:31:04.310 align:middle line:84%
How are you're probably
going to end up

00:31:04.310 --> 00:31:07.383 align:middle line:84%
evaluating the integrant when
you're working at SpaceX,

00:31:07.383 --> 00:31:09.050 align:middle line:84%
and you need the
answer in five minutes?

00:31:09.050 --> 00:31:16.760 align:middle line:90%


00:31:16.760 --> 00:31:18.050 align:middle line:90%
Let me set up a straw man.

00:31:18.050 --> 00:31:20.600 align:middle line:84%
Are you going to do density
functional theory calculations

00:31:20.600 --> 00:31:23.960 align:middle line:84%
to calculate the thermal
expansion coefficient,

00:31:23.960 --> 00:31:27.200 align:middle line:84%
and specific heat, and
volume, and compressibility

00:31:27.200 --> 00:31:28.940 align:middle line:84%
for your material
from first principles?

00:31:28.940 --> 00:31:32.080 align:middle line:90%


00:31:32.080 --> 00:31:34.360 align:middle line:84%
AUDIENCE: You're going to
probably look at databases.

00:31:34.360 --> 00:31:35.110 align:middle line:90%
PROFESSOR: Databases.

00:31:35.110 --> 00:31:35.610 align:middle line:90%
Thanks.

00:31:35.610 --> 00:31:36.813 align:middle line:90%
That's my favorite word.

00:31:36.813 --> 00:31:38.230 align:middle line:84%
You're going to
look at databases.

00:31:38.230 --> 00:31:39.640 align:middle line:90%
This stuff is in databases.

00:31:39.640 --> 00:31:44.422 align:middle line:84%
You're going to parameterize
what you need using databases.

00:31:44.422 --> 00:31:45.630 align:middle line:90%
You're going to plug that in.

00:31:45.630 --> 00:31:47.550 align:middle line:84%
And you're going to do
this integral numerically.

00:31:47.550 --> 00:31:49.175 align:middle line:84%
The computer is going
to do it for you.

00:31:49.175 --> 00:31:51.600 align:middle line:84%
You're going to make sure you
have good sources of data.

00:31:51.600 --> 00:31:54.142 align:middle line:84%
You're going to make sure the
data is inputted correctly.

00:31:54.142 --> 00:31:56.100 align:middle line:84%
You're going to make sure
your units are right.

00:31:56.100 --> 00:31:57.960 align:middle line:84%
And then the computer is
going to do this for you

00:31:57.960 --> 00:31:59.190 align:middle line:90%
as a numerical integration.

00:31:59.190 --> 00:32:02.520 align:middle line:84%
That's how it works
in the real world.

00:32:02.520 --> 00:32:06.825 align:middle line:84%
So this hairy-looking challenge
is why we hammer on this stuff

00:32:06.825 --> 00:32:07.940 align:middle line:90%
in 020.

00:32:07.940 --> 00:32:09.802 align:middle line:90%
And they make you talk to the--

00:32:09.802 --> 00:32:11.730 align:middle line:84%
you get to meet the
librarians and such

00:32:11.730 --> 00:32:15.630 align:middle line:84%
because being able to go from
those data resources to answers

00:32:15.630 --> 00:32:17.410 align:middle line:90%
is really an important skill.

00:32:17.410 --> 00:32:20.220 align:middle line:90%
It's really an important skill.

00:32:20.220 --> 00:32:23.350 align:middle line:84%
There is one case where you
don't need to do any of that.

00:32:23.350 --> 00:32:26.370 align:middle line:84%
And we'll discuss this a
little more next lecture.

00:32:26.370 --> 00:32:30.567 align:middle line:84%
And you can work this out on
your own if you're curious.

00:32:30.567 --> 00:32:32.400 align:middle line:84%
It's also worked out
plenty in the textbook.

00:32:32.400 --> 00:32:38.100 align:middle line:84%
For an ideal gas, as with
many things, it simplifies.

00:32:38.100 --> 00:32:40.950 align:middle line:84%
So you don't need any
databases to evaluate

00:32:40.950 --> 00:32:41.970 align:middle line:90%
this for an ideal gas.

00:32:41.970 --> 00:32:43.680 align:middle line:90%
It simplifies to the following.

00:32:43.680 --> 00:32:54.790 align:middle line:84%
X equals minus V over P
times Cp minus R or Cp

00:32:54.790 --> 00:33:02.140 align:middle line:84%
is also equal to V
over P Cv over Cp.

00:33:02.140 --> 00:33:09.900 align:middle line:84%
And this leads to an expression,
which before we just gave you.

00:33:09.900 --> 00:33:20.020 align:middle line:84%
P final over P initial equals
V initial over V final.

00:33:20.020 --> 00:33:21.640 align:middle line:90%
This is where that comes from.

00:33:21.640 --> 00:33:24.730 align:middle line:84%
And if you use this expression
for adiabatic process

00:33:24.730 --> 00:33:26.410 align:middle line:84%
for an ideal gas,
it comes from this.

00:33:26.410 --> 00:33:30.480 align:middle line:90%


00:33:30.480 --> 00:33:32.673 align:middle line:84%
So I'm not going to take
time to derive that now.

00:33:32.673 --> 00:33:34.340 align:middle line:84%
It's kind of an
interesting calculation.

00:33:34.340 --> 00:33:37.490 align:middle line:84%
You can just evaluate
all this stuff.

00:33:37.490 --> 00:33:42.690 align:middle line:84%
And I'll just mention that
in p set 2, in p set 2,

00:33:42.690 --> 00:33:45.000 align:middle line:84%
you're doing a
related problem, which

00:33:45.000 --> 00:33:49.310 align:middle line:84%
is you're calculating
change in Gibbs free energy

00:33:49.310 --> 00:33:53.870 align:middle line:84%
with current
pressure and entropy.

00:33:53.870 --> 00:33:58.160 align:middle line:84%
So we just did volume
with pressure and entropy.

00:33:58.160 --> 00:34:00.050 align:middle line:84%
And in p set 2, you're
going to do Gibbs

00:34:00.050 --> 00:34:01.550 align:middle line:90%
with pressure and entropy.

00:34:01.550 --> 00:34:04.640 align:middle line:84%
But the overall what they
call the general strategy

00:34:04.640 --> 00:34:05.390 align:middle line:90%
is the same.

00:34:05.390 --> 00:34:14.172 align:middle line:90%


00:34:14.172 --> 00:34:15.630 align:middle line:84%
So for the remaining
minutes, we're

00:34:15.630 --> 00:34:16.770 align:middle line:84%
going to get a
little bit specific

00:34:16.770 --> 00:34:18.430 align:middle line:84%
and talk about
Gibbs free strategy.

00:34:18.430 --> 00:34:25.850 align:middle line:90%


00:34:25.850 --> 00:34:27.440 align:middle line:90%
Let's talk about equilibrium--

00:34:27.440 --> 00:34:40.739 align:middle line:90%


00:34:40.739 --> 00:34:43.000 align:middle line:90%
fixed pressure and temperature.

00:34:43.000 --> 00:34:45.090 align:middle line:84%
So now we're
reprocessing materials.

00:34:45.090 --> 00:34:52.590 align:middle line:84%
Gibbs free energy equals U
plus PV minus TS is minimized.

00:34:52.590 --> 00:34:59.600 align:middle line:90%


00:34:59.600 --> 00:35:02.370 align:middle line:84%
Let's play with a
differential form, dG.

00:35:02.370 --> 00:35:15.160 align:middle line:84%
So I'm going to use the
chain rule. dG [AUDIO OUT] dS

00:35:15.160 --> 00:35:19.210 align:middle line:90%
minus S dT.

00:35:19.210 --> 00:35:20.985 align:middle line:90%
And that was just chain rule.

00:35:20.985 --> 00:35:30.020 align:middle line:90%


00:35:30.020 --> 00:35:33.400 align:middle line:84%
And now, I can use the
combined statement.

00:35:33.400 --> 00:35:43.565 align:middle line:84%
dU equals TdS minus PdV
plus mu of i dN of i.

00:35:43.565 --> 00:35:50.320 align:middle line:90%
That is all dU.

00:35:50.320 --> 00:35:51.700 align:middle line:90%
I carry the rest of the terms.

00:35:51.700 --> 00:36:01.390 align:middle line:84%
Plus PdV plus VdP
minus TdS minus S dT.

00:36:01.390 --> 00:36:03.376 align:middle line:84%
So here I use
combined statement.

00:36:03.376 --> 00:36:14.070 align:middle line:90%


00:36:14.070 --> 00:36:16.010 align:middle line:84%
And I'm going to see a
bunch of things cancel.

00:36:16.010 --> 00:36:17.800 align:middle line:84%
I'm going to see a
bunch of things cancel.

00:36:17.800 --> 00:36:21.170 align:middle line:90%
So we have TdS cancels TdS.

00:36:21.170 --> 00:36:25.780 align:middle line:90%


00:36:25.780 --> 00:36:27.490 align:middle line:90%
Minus PdV cancels PdV.

00:36:27.490 --> 00:36:30.050 align:middle line:90%


00:36:30.050 --> 00:36:31.610 align:middle line:84%
And so this simplifies
a little bit.

00:36:31.610 --> 00:36:32.960 align:middle line:90%
And I get the following.

00:36:32.960 --> 00:36:45.600 align:middle line:84%
Equals minus SdT plus
VdP plus mu i dN of i.

00:36:45.600 --> 00:36:46.290 align:middle line:90%
Good.

00:36:46.290 --> 00:36:48.420 align:middle line:84%
This is what we wanted
because I told you

00:36:48.420 --> 00:36:53.040 align:middle line:84%
the natural variables for Gibbs
were temperature, pressure,

00:36:53.040 --> 00:36:54.730 align:middle line:90%
and particle number.

00:36:54.730 --> 00:36:56.250 align:middle line:90%
And that's what we get.

00:36:56.250 --> 00:36:57.960 align:middle line:84%
That's what the
calculus gives us.

00:36:57.960 --> 00:37:01.425 align:middle line:90%


00:37:01.425 --> 00:37:03.050 align:middle line:84%
So there's a little
clue there into how

00:37:03.050 --> 00:37:04.880 align:middle line:90%
the Legendre transform works.

00:37:04.880 --> 00:37:06.600 align:middle line:90%
But again, we won't go there.

00:37:06.600 --> 00:37:23.620 align:middle line:84%
So the independent variables
are T, P, and N sub i.

00:37:23.620 --> 00:37:26.490 align:middle line:90%
And what are the coefficients?

00:37:26.490 --> 00:37:27.150 align:middle line:90%
Somebody?

00:37:27.150 --> 00:37:27.650 align:middle line:90%
Please?

00:37:27.650 --> 00:37:33.970 align:middle line:90%


00:37:33.970 --> 00:37:36.092 align:middle line:90%
AUDIENCE: S, V, and mu of i.

00:37:36.092 --> 00:37:36.800 align:middle line:90%
PROFESSOR: Right.

00:37:36.800 --> 00:37:42.770 align:middle line:90%
Minus S, V, and mu of i.

00:37:42.770 --> 00:37:45.770 align:middle line:90%
I'll make a note here.

00:37:45.770 --> 00:37:54.108 align:middle line:84%
A lot of times, in this class,
I use implicit summation.

00:37:54.108 --> 00:37:55.400 align:middle line:90%
You probably picked up on that.

00:37:55.400 --> 00:38:03.860 align:middle line:84%
But this implies
i, mu of i, and i.

00:38:03.860 --> 00:38:06.860 align:middle line:84%
It's just a little
bit more compact.

00:38:06.860 --> 00:38:08.838 align:middle line:84%
There's no i index on
the left-hand side.

00:38:08.838 --> 00:38:11.130 align:middle line:84%
So that means it has to
resolve on the right-hand side.

00:38:11.130 --> 00:38:13.490 align:middle line:90%
So you implicitly sum.

00:38:13.490 --> 00:38:24.160 align:middle line:84%
And by inspection, by
inspection, minus S

00:38:24.160 --> 00:38:29.800 align:middle line:84%
describes the change of
Gibbs with temperature

00:38:29.800 --> 00:38:36.170 align:middle line:84%
at fixed pressure
and particle number.

00:38:36.170 --> 00:38:40.670 align:middle line:84%
Volume describes
the change of Gibbs

00:38:40.670 --> 00:38:44.240 align:middle line:84%
with pressure at fixed
temperature and particle

00:38:44.240 --> 00:38:45.240 align:middle line:90%
number.

00:38:45.240 --> 00:38:47.510 align:middle line:84%
And finally, our favorite--
chemical potential

00:38:47.510 --> 00:38:52.070 align:middle line:84%
describes the change of
Gibbs with particle number i

00:38:52.070 --> 00:38:55.340 align:middle line:84%
have fixed temperature,
pressure, and particles

00:38:55.340 --> 00:38:58.109 align:middle line:90%
j not equal to i.

00:38:58.109 --> 00:39:02.890 align:middle line:90%


00:39:02.890 --> 00:39:04.890 align:middle line:84%
So already, we can say
something about the slope

00:39:04.890 --> 00:39:07.590 align:middle line:90%
of these things.

00:39:07.590 --> 00:39:09.780 align:middle line:90%
On a slope of--

00:39:09.780 --> 00:39:10.290 align:middle line:90%
let's see.

00:39:10.290 --> 00:39:12.980 align:middle line:90%


00:39:12.980 --> 00:39:15.980 align:middle line:90%
Here's pressure.

00:39:15.980 --> 00:39:17.900 align:middle line:90%
And here's Gibbs free energy.

00:39:17.900 --> 00:39:21.875 align:middle line:84%
And we're fixing temperature
and particle number.

00:39:21.875 --> 00:39:25.300 align:middle line:90%


00:39:25.300 --> 00:39:26.972 align:middle line:90%
What's the slope?

00:39:26.972 --> 00:39:27.680 align:middle line:90%
What's the slope?

00:39:27.680 --> 00:39:28.910 align:middle line:90%
Is it positive or negative?

00:39:28.910 --> 00:39:34.265 align:middle line:84%
Gibbs versus pressure for
fixed temperature and particle

00:39:34.265 --> 00:39:34.940 align:middle line:90%
number.

00:39:34.940 --> 00:39:45.020 align:middle line:90%


00:39:45.020 --> 00:39:46.070 align:middle line:90%
AUDIENCE: It's positive.

00:39:46.070 --> 00:39:48.320 align:middle line:84%
PROFESSOR: Positive because
volume is always positive.

00:39:48.320 --> 00:39:50.750 align:middle line:90%
Can't have negative volume.

00:39:50.750 --> 00:39:52.747 align:middle line:90%
So that's good.

00:39:52.747 --> 00:39:54.830 align:middle line:84%
Being able to pick off the
slope and the curvature

00:39:54.830 --> 00:39:56.580 align:middle line:84%
of these things
is really useful.

00:39:56.580 --> 00:39:58.610 align:middle line:84%
It's really, really
useful, as you'll see.

00:39:58.610 --> 00:39:59.310 align:middle line:90%
What about this?

00:39:59.310 --> 00:40:02.980 align:middle line:90%
What about temperature?

00:40:02.980 --> 00:40:07.630 align:middle line:84%
Change of Gibbs with temperature
for fixed pressure and particle

00:40:07.630 --> 00:40:09.300 align:middle line:90%
number.

00:40:09.300 --> 00:40:10.760 align:middle line:90%
AUDIENCE: Negative.

00:40:10.760 --> 00:40:13.190 align:middle line:84%
PROFESSOR: Yeah, it's negative
because entropy is strictly

00:40:13.190 --> 00:40:13.890 align:middle line:90%
positive.

00:40:13.890 --> 00:40:15.770 align:middle line:84%
So negative entropy
is strictly negative.

00:40:15.770 --> 00:40:18.620 align:middle line:90%


00:40:18.620 --> 00:40:22.630 align:middle line:84%
You got to think
about these slopes.

00:40:22.630 --> 00:40:25.000 align:middle line:84%
If Gibbs free energy
increases when we squeeze,

00:40:25.000 --> 00:40:27.308 align:middle line:90%
that's related to the enthalpy.

00:40:27.308 --> 00:40:28.600 align:middle line:90%
That's related to the enthalpy.

00:40:28.600 --> 00:40:32.500 align:middle line:84%
When we squeeze something, we're
increasing the energy content

00:40:32.500 --> 00:40:34.375 align:middle line:84%
of all the bonds that
make up that thing.

00:40:34.375 --> 00:40:36.980 align:middle line:90%


00:40:36.980 --> 00:40:40.130 align:middle line:84%
When we squeeze something, we're
increasing the entropy content

00:40:40.130 --> 00:40:43.440 align:middle line:84%
of all the bonds that
make up that thing.

00:40:43.440 --> 00:40:46.115 align:middle line:84%
So this is Gibbs free energy
getting higher as we squeeze.

00:40:46.115 --> 00:40:50.110 align:middle line:90%


00:40:50.110 --> 00:40:52.600 align:middle line:84%
When we heat something,
Gibbs decreases.

00:40:52.600 --> 00:40:57.445 align:middle line:84%
When we heat something,
we're increasing the entropy.

00:40:57.445 --> 00:41:01.530 align:middle line:84%
We're Increasing the
amount of mixedupness.

00:41:01.530 --> 00:41:07.050 align:middle line:84%
And Gibbs depends
negatively with entropy.

00:41:07.050 --> 00:41:09.490 align:middle line:90%
Well see this in many examples.

00:41:09.490 --> 00:41:11.697 align:middle line:84%
So up with pressure,
down with temperature.

00:41:11.697 --> 00:41:17.603 align:middle line:90%


00:41:17.603 --> 00:41:19.520 align:middle line:84%
What about conditions
that we're interrupting?

00:41:19.520 --> 00:41:26.700 align:middle line:84%
At fixed temperature T, at
fixed temperature and pressure,

00:41:26.700 --> 00:41:29.010 align:middle line:90%
dT equals 0.

00:41:29.010 --> 00:41:30.760 align:middle line:90%
That's pretty easy.

00:41:30.760 --> 00:41:32.985 align:middle line:90%
And dP equals 0.

00:41:32.985 --> 00:41:36.110 align:middle line:90%


00:41:36.110 --> 00:41:48.950 align:middle line:84%
That means the equilibrium,
the equilibrium condition,

00:41:48.950 --> 00:42:02.720 align:middle line:84%
reduces to dG equals minus SdT
plus VdP plus mu of i dN of i.

00:42:02.720 --> 00:42:04.670 align:middle line:90%
And we're holding that fixed.

00:42:04.670 --> 00:42:07.360 align:middle line:90%
And we're holding that fixed.

00:42:07.360 --> 00:42:10.510 align:middle line:84%
That means it basically
reduces to this--

00:42:10.510 --> 00:42:19.777 align:middle line:84%
equals 0 because G is
min at equilibrium.

00:42:19.777 --> 00:42:21.360 align:middle line:84%
So if you think back
to calculus, when

00:42:21.360 --> 00:42:24.630 align:middle line:90%
you would calculate extrema.

00:42:24.630 --> 00:42:27.330 align:middle line:84%
The extrema positions
of a function

00:42:27.330 --> 00:42:29.550 align:middle line:90%
are where its slope is 0.

00:42:29.550 --> 00:42:32.410 align:middle line:90%


00:42:32.410 --> 00:42:34.930 align:middle line:84%
So equilibrium condition
is that the change of Gibbs

00:42:34.930 --> 00:42:37.480 align:middle line:90%
with particle number i is 0.

00:42:37.480 --> 00:42:41.490 align:middle line:90%


00:42:41.490 --> 00:42:42.990 align:middle line:84%
So for most of the
cases of interest

00:42:42.990 --> 00:42:44.820 align:middle line:84%
to us as practicing
materials scientists,

00:42:44.820 --> 00:42:51.755 align:middle line:84%
that is multi-component,
heterogeneous systems.

00:42:51.755 --> 00:43:00.560 align:middle line:90%


00:43:00.560 --> 00:43:20.710 align:middle line:84%
This becomes dG sum over i
component k dN i component k.

00:43:20.710 --> 00:43:23.000 align:middle line:84%
I'm introducing a
new notation here.

00:43:23.000 --> 00:43:29.305 align:middle line:90%
Superscript labels phases.

00:43:29.305 --> 00:43:35.930 align:middle line:90%


00:43:35.930 --> 00:43:42.440 align:middle line:84%
And the subscript
labels components.

00:43:42.440 --> 00:43:51.350 align:middle line:90%


00:43:51.350 --> 00:43:53.860 align:middle line:84%
So now we can picture
something in our minds.

00:43:53.860 --> 00:43:57.580 align:middle line:84%
We have a phase boundary
here, two phases.

00:43:57.580 --> 00:44:02.530 align:middle line:84%
And each phase has
two components.

00:44:02.530 --> 00:44:14.737 align:middle line:90%


00:44:14.737 --> 00:44:16.320 align:middle line:84%
This was a purple-rich
phase, and this

00:44:16.320 --> 00:44:19.680 align:middle line:90%
was an orange-rich phase.

00:44:19.680 --> 00:44:22.200 align:middle line:84%
And evaluating the
equilibrium condition

00:44:22.200 --> 00:44:26.880 align:middle line:84%
is going to come down to knowing
how the components can exchange

00:44:26.880 --> 00:44:30.390 align:middle line:84%
between phases and what
the effect of that exchange

00:44:30.390 --> 00:44:33.420 align:middle line:90%
is on the chemical potential.

00:44:33.420 --> 00:44:34.368 align:middle line:90%
Let me write that out.

00:44:34.368 --> 00:45:21.760 align:middle line:90%


00:45:21.760 --> 00:45:24.088 align:middle line:84%
What determines whether
or not components can

00:45:24.088 --> 00:45:25.255 align:middle line:90%
exchange between the phases?

00:45:25.255 --> 00:45:28.400 align:middle line:90%


00:45:28.400 --> 00:45:29.810 align:middle line:90%
It's the boundary.

00:45:29.810 --> 00:45:31.790 align:middle line:84%
The property of the
boundary tells us

00:45:31.790 --> 00:45:34.970 align:middle line:84%
what components can
exchange between phases.

00:45:34.970 --> 00:45:36.710 align:middle line:90%
And that can be engineered.

00:45:36.710 --> 00:45:39.890 align:middle line:84%
So there's a lot of engineering
around choosing boundaries

00:45:39.890 --> 00:45:42.410 align:middle line:84%
to get the desired
equilibrium condition.

00:45:42.410 --> 00:45:45.340 align:middle line:90%


00:45:45.340 --> 00:45:48.160 align:middle line:84%
But much of what comes
later in this class

00:45:48.160 --> 00:46:06.317 align:middle line:84%
is calculating
composition dependence,

00:46:06.317 --> 00:46:08.650 align:middle line:84%
calculating the composition
dependence of those chemical

00:46:08.650 --> 00:46:09.820 align:middle line:90%
potentials.

00:46:09.820 --> 00:46:11.200 align:middle line:84%
And we're going
to develop models

00:46:11.200 --> 00:46:13.940 align:middle line:84%
for that and graphical
tools for that,

00:46:13.940 --> 00:46:16.090 align:middle line:84%
finally leading to
binary phase diagrams.

00:46:16.090 --> 00:46:23.500 align:middle line:90%


00:46:23.500 --> 00:46:24.250 align:middle line:90%
One last note.

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Going to do one last note
about independent variables,

00:46:38.110 --> 00:46:39.940 align:middle line:90%
sometimes called natural.

00:46:39.940 --> 00:46:50.160 align:middle line:90%


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If a state variable is
regulated, regulated,

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what does that mean?

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Controlled.

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Regulations are controls.

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If you go to a
McMaster-Carr, you

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can buy a regulator
for pressure.

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If you go to Home
Depot, you can get

00:47:17.710 --> 00:47:18.877 align:middle line:90%
a regulator for temperature.

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We call it a thermostat.

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And those things that you
would buy have analogs in--

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not the real world, but in R&D
and materials science, as well.

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If a state variable
is regulated--

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that's why I'm using that
term, because it will help you

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in the future.

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If it's regulated, then
it must be independent.

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So choosing your
independent variables

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is one of the major intellectual
challenges of thermo.

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It helps even know that that's
the challenge you're facing.

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Knowing that that's the
challenge you're facing,

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it gives you a good start.

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Identifying independent
and dependent variables

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from the problem at hand,
that's key to success.

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So for example, if
the problem statement

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says something about
fixed pressure,

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then you need to choose pressure
as an independent variable.

00:48:56.450 --> 00:49:02.500 align:middle line:90%


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If the problem says adiabatic,
you need to choose what?

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What should be your independent
variable if the problem

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statement said adiabatic?

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What should be one of your
two independent variables?

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AUDIENCE: Entropy.

00:49:22.880 --> 00:49:23.922 align:middle line:90%
PROFESSOR: Yeah, entropy.

00:49:23.922 --> 00:49:26.970 align:middle line:90%


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And if the problem statement
says in a thermal bath,

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then you need to
choose temperature

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as one of your independent
variables and so on.

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So this is like a key
for turning problems

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that you encounter
on problem sets

00:49:51.730 --> 00:49:56.130 align:middle line:84%
or in the real world into things
you can solve using thermo.

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