WEBVTT

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RAFAEL JARAMILLO:
All right, so today

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is the last lecture
of new material.

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We're going to talk about
reactions between gases

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and condensed phases.

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So we're going to
talk about that,

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and then, we'll make it
specific to oxidation.

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And then, on Friday, I'll do
an extended practice problem,

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I suppose, on reactions between
gases and condensed phases.

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So in general, some reaction--

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I'm going to write this
really generally. aA

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plus bB going to cC plus dD.

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And these are not
just for ideal gases.

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So the last time we've seen
reaction like this in 020,

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it's been for ideal
gases reacting.

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And we're going to
move away from that

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and do this more generally.

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So let me just
quickly remind you

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of how we get to the
action coefficient.

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We have a general expression
for the change in Gibbs

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free energy with these
unconstrained internal

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variables, and we can re-express
this in terms of the reaction

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extent, remembering
that DNI over

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mu I is a constant for
all I reaction extent.

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I don't need to have an I there.

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Just xe.

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And reminding us that mu of
I, the chemical potential

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of a given species is its
reference chemical potential

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plus [INAUDIBLE] activity.

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So this is still
completely general.

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We take that expression and
we write d of g equals--

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let's see, mu of I not mu
of I plus rt log a of I

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to the power mu of I.
And this is all times dt.

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And this is d G0 plus RT log
product a of I mu of I. Again,

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whole thing times dt.

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And of course, this
is 0 at equilibrium,

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because at equilibrium, Gibbs
free energy is optimized.

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So the coefficient is 0,
and we get, at equilibrium,

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this product, a of
I mu of I, which

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we call the equilibrium
constant, equals e to the minus

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delta G0 over RT.

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So that's just a reminder.

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But this is why I wanted to
take three minutes for that

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because we're going to make this
specific to metal oxidation.

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That's what we're doing.

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So equilibrium
constant for metal.

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And what you're going to find
is that it simplifies a lot.

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So that's good.

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Metal oxidation.

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As we started the
last lecture, we

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have some metal reacting
with a modal of oxygen gas

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going to MzO2.

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Remember, z here has
to do with the fact

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that we don't know what the
oxidation state of that metal

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is.

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So potassium would be
1, iron has a couple

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of different oxidation states.

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Copper would be 1 or 2--

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so there's different
oxidation states.

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So this is to do this generally.

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So all right, now, we're
going to write the equilibrium

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constant for this reaction.

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So we have the activity
of the oxide MzO2.

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Sorry, the writing is getting
a little bit small there.

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The activity of the
oxide over the activity

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of the metal to the
power of z times

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is the activity of O2 gas.

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The products of the numerator,
reactants, and the denominator.

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The metal is z modal of metal.

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So we have that activity
to the power of z.

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And straightforward
to write down.

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Everyone with me so far?

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All right, this oxidation
reaction at equilibrium.

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We're going to
come back to that.

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This is the metal and oxygen
and the oxide all coexisting

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at equilibrium.

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And now come the approximations.

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We're going to treat
O2 as-- how are we

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going to treat oxygen, anybody?

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How will we model oxygen?

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AUDIENCE: Constant pressure?

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[INAUDIBLE] question.

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RAFAEL JARAMILLO: Not constant
pressure, but we have a--

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AUDIENCE: It's a gas.

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RAFAEL JARAMILLO: --as
a-- what kind of gas?

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AUDIENCE: Ideal gas.

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Ideal?

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RAFAEL JARAMILLO: Yeah, because
it's the only model for gases

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that we know.

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[INAUDIBLE] So an ideal gas--
the activity of an ideal gas

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is just as partial pressure
by atmosphere for 1 atmosphere

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reference statement.

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Good.

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That's easy.

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And we're going to assume that
condensed phases are pure.

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That's big.

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If we assume the condensed
phases are pure, that's

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equivalent to saying that their
composition is unchanging,

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all right?

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That's saying that this metal
does not dissolve any oxygen,

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and it's saying that
this oxide is what?

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What kind of a compound is
always at fixed stoichiometry?

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AUDIENCE: Like, perfect crystal?

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RAFAEL JARAMILLO: Sorry?

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AUDIENCE: The perfect crystal?

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RAFAEL JARAMILLO: No,
well, not perfect.

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No, not a perfect
crystal, actually.

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Be something else.

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We learned this
just two days ago.

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AUDIENCE: [INAUDIBLE] ?

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RAFAEL JARAMILLO: Mm, yes.

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It's a pure oxide, meaning
that stoichiometry is ideal.

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It's a line compound.

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It doesn't deviate from that.

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So if we can assume the
condensed phases are pure,

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what is the activity
of a pure phase?

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We've got to think back.

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What's the activity of a
component in its reference

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statement?

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AUDIENCE: 1?

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RAFAEL JARAMILLO: Right.

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Thanks, that's
recalling material

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from the middle of the semester,
so it goes back a little bit,

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but the activity of the material
in its reference date is 1.

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So now, I have some really
handy approximations.

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The activity of oxygen gas.

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We're treating it
like an ideal gas,

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so it's just Po2 by atmosphere.

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And the activity of the metal
and the activity of the oxide

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are both 1.

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So it's equivalent to assuming
that there's vanishing oxygen

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solubility in the metal and that
the oxide is a line compound.

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So with those approximations,
we have the equilibrium

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constant is Po2 by
atmosphere, so minus 1,

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and this is going to be equal
to the E minus delta G0 over RT.

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So you see this
simplified quite a lot.

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Simplified quite a lot.

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All right, I want to share some
slides on binary metal oxygen

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systems to convince
you that they do

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tend to be pair of materials.

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So let's look here.

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I grabbed a couple.

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OK, so here's the
tin oxygen system.

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And you could see
that an oxygen--

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well, it's just a gas here.

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Tin down here is a metal
until it becomes a liquid.

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In the liquid phase, it
dissolves some oxygen.

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You can see that the
liquid phase here

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has a solution region.

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So you can dissolve
oxygen in liquid tin,

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but what about in solid tin?

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I know oxygen is off.

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So you see solid tin will just
coexist with this line compound

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tin oxide.

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So this is what
we're talking about,

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a line compound of
an oxide and a metal

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that doesn't
dissolve any oxygen.

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Here's another example,
copper oxygen. Again, copper.

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It's written here
as a parentheses

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as if it's a solid solution,
but really, there's

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vanishingly small oxygen
dissolution and copper.

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There's some.

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There's some, but
it's so small as to be

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invisible on this part.

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I'll tell you that when
you're making a component

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for cryogenics or for
space applications,

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you want oxygen-free copper.

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You can buy it from
McMaster, and you want it,

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because oxygen is
magnetic when it freezes,

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and so a lot of times you
want non-magnetic copper.

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So you have to get
oxygen-free copper,

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but it's there at the
parts per million level.

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It doesn't show up
at all on the spot.

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So again, oxygen not
dissolving in copper and these

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oxides being line compounds.

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Here's more examples.

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This is a little
counter example.

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This is manganese.

00:11:45.340 --> 00:11:47.215 align:middle line:84%
Manganese actually does
dissolve some oxygen.

00:11:47.215 --> 00:11:50.973 align:middle line:84%
So you see it dissolves
1% or 2% of oxygen.

00:11:50.973 --> 00:11:52.390 align:middle line:84%
So maybe the
activity of manganese

00:11:52.390 --> 00:11:54.400 align:middle line:90%
should be not quite 1.

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Maybe it should be 0.99.

00:11:58.300 --> 00:12:01.120 align:middle line:84%
And making these oxide similarly
to not quite long compounds.

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They have some solid
solution region,

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so that's a counterexample.

00:12:05.350 --> 00:12:08.720 align:middle line:90%


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Another example a
titanium oxide oxygen

00:12:11.480 --> 00:12:16.350 align:middle line:84%
system is titanium
dissolves a lot of oxygen.

00:12:16.350 --> 00:12:18.320 align:middle line:84%
So this is an even
counter counterexample.

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This is a titanium,
so funny system.

00:12:20.180 --> 00:12:23.780 align:middle line:84%
It dissolves a lot of
oxygen into solid titanium,

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but its oxides here
are line compounds.

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So what to make of it?

00:12:33.230 --> 00:12:36.088 align:middle line:84%
It's good to understand
where the approximations are

00:12:36.088 --> 00:12:37.130 align:middle line:90%
and where they might not.

00:12:37.130 --> 00:12:39.885 align:middle line:90%


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Questions on these
faith diagrams

00:12:41.260 --> 00:12:44.000 align:middle line:90%
before I go back to the board?

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AUDIENCE: Does
this dissolving all

00:12:46.280 --> 00:12:49.085 align:middle line:84%
owe to the molecule or
just oxygen in general?

00:12:49.085 --> 00:12:50.960 align:middle line:84%
RAFAEL JARAMILLO: I'm
sorry, I didn't quite--

00:12:50.960 --> 00:12:52.490 align:middle line:90%
could you repeat?

00:12:52.490 --> 00:12:54.200 align:middle line:84%
AUDIENCE: Going back
to the solution,

00:12:54.200 --> 00:12:58.010 align:middle line:84%
is this like dissolving
oxygen as auto form

00:12:58.010 --> 00:13:00.440 align:middle line:90%
or other forms of oxygen?

00:13:00.440 --> 00:13:03.310 align:middle line:84%
RAFAEL JARAMILLO: It almost
certainly disassociate.

00:13:03.310 --> 00:13:06.030 align:middle line:84%
So this would be
dissolving oxygen atoms.

00:13:06.030 --> 00:13:09.560 align:middle line:84%
Well, I mean, how do you
dissolve oxygen atoms?

00:13:09.560 --> 00:13:12.560 align:middle line:84%
You expose the
material to oxygen gas,

00:13:12.560 --> 00:13:15.980 align:middle line:84%
and there's some catalytic
process by which the oxygen

00:13:15.980 --> 00:13:19.400 align:middle line:84%
gas splits into oxygen atoms
at the surface and the oxygen

00:13:19.400 --> 00:13:21.680 align:middle line:90%
atoms diffuse into the metal.

00:13:21.680 --> 00:13:26.680 align:middle line:84%
It's almost certainly not
dissolving O2 molecules.

00:13:26.680 --> 00:13:29.380 align:middle line:84%
Metals that do
dissolve oxygen are

00:13:29.380 --> 00:13:34.540 align:middle line:84%
the basis for a lot of
interesting technologies,

00:13:34.540 --> 00:13:36.320 align:middle line:90%
but we won't have time for that.

00:13:36.320 --> 00:13:39.072 align:middle line:90%
So let's move back to--

00:13:39.072 --> 00:13:40.780 align:middle line:84%
sorry, any other
questions on these phase

00:13:40.780 --> 00:13:43.750 align:middle line:84%
diagrams and interpreting
them or applications

00:13:43.750 --> 00:13:45.220 align:middle line:90%
and so forth before I move back?

00:13:45.220 --> 00:13:47.730 align:middle line:90%


00:13:47.730 --> 00:13:50.310 align:middle line:84%
All right, so we have this
really simple expression

00:13:50.310 --> 00:13:52.350 align:middle line:84%
for the equilibrium
constant, and now we

00:13:52.350 --> 00:14:02.200 align:middle line:84%
want to evaluate delta G0
equals delta H0 minus T delta

00:14:02.200 --> 00:14:05.320 align:middle line:90%
S0 for metal oxidation.

00:14:05.320 --> 00:14:10.477 align:middle line:90%


00:14:10.477 --> 00:14:11.810 align:middle line:90%
So we're going to evaluate that.

00:14:11.810 --> 00:14:13.393 align:middle line:84%
So we're going to
start with enthalpy.

00:14:13.393 --> 00:14:18.490 align:middle line:90%


00:14:18.490 --> 00:14:23.860 align:middle line:84%
Enthalpy delta H0
equals delta H0--

00:14:23.860 --> 00:14:32.290 align:middle line:84%
let's say 298 plus
298 temperature D--

00:14:32.290 --> 00:14:35.780 align:middle line:84%
temperature and you can have
a delta Cp for the reaction.

00:14:35.780 --> 00:14:39.042 align:middle line:84%
So this is general,
but here's the--

00:14:39.042 --> 00:14:41.000 align:middle line:84%
and you know what's coming
is an approximation.

00:14:41.000 --> 00:14:53.270 align:middle line:84%
So I'm going to tell you for
most metal oxides, delta H0--

00:14:53.270 --> 00:14:57.190 align:middle line:90%
let's say 298-- is large.

00:14:57.190 --> 00:14:59.710 align:middle line:90%


00:14:59.710 --> 00:15:02.080 align:middle line:90%
These are energetic reactions.

00:15:02.080 --> 00:15:06.670 align:middle line:84%
Why would the enthalpy of
formation of an oxide be large?

00:15:06.670 --> 00:15:09.430 align:middle line:84%
Does somebody have the sense
for why that should be?

00:15:09.430 --> 00:15:11.905 align:middle line:90%


00:15:11.905 --> 00:15:12.780 align:middle line:90%
I'll give you a hint.

00:15:12.780 --> 00:15:15.290 align:middle line:90%
It's large negative.

00:15:15.290 --> 00:15:17.851 align:middle line:84%
It's large in the
negative direction.

00:15:17.851 --> 00:15:22.930 align:middle line:90%


00:15:22.930 --> 00:15:24.780 align:middle line:84%
What reaction are we
talking about here?

00:15:24.780 --> 00:15:28.550 align:middle line:90%


00:15:28.550 --> 00:15:29.383 align:middle line:90%
AUDIENCE: Oxidation?

00:15:29.383 --> 00:15:30.550 align:middle line:90%
RAFAEL JARAMILLO: Oxidation.

00:15:30.550 --> 00:15:32.870 align:middle line:84%
So what kind of reaction is
an oxidation reaction other

00:15:32.870 --> 00:15:35.078 align:middle line:84%
than just-- you could say
it's an oxidation reaction,

00:15:35.078 --> 00:15:36.350 align:middle line:90%
but what's actually happening?

00:15:36.350 --> 00:15:38.540 align:middle line:84%
Maybe somebody who
hasn't replied yet today.

00:15:38.540 --> 00:15:40.760 align:middle line:84%
What's happening
on the atomic level

00:15:40.760 --> 00:15:42.230 align:middle line:90%
during an oxidation reaction?

00:15:42.230 --> 00:15:45.040 align:middle line:90%


00:15:45.040 --> 00:15:47.350 align:middle line:84%
AUDIENCE: Does it include
a favorable transfer

00:15:47.350 --> 00:15:48.222 align:middle line:90%
of electrons?

00:15:48.222 --> 00:15:49.180 align:middle line:90%
RAFAEL JARAMILLO: Yeah.

00:15:49.180 --> 00:15:52.180 align:middle line:90%
Yeah, this is due to--

00:15:52.180 --> 00:15:53.710 align:middle line:90%
so thank you to the two of you.

00:15:53.710 --> 00:16:14.880 align:middle line:84%
Due to exothermic nature of
electron transfer during metal

00:16:14.880 --> 00:16:17.940 align:middle line:90%
oxygen bond formation.

00:16:17.940 --> 00:16:22.420 align:middle line:90%


00:16:22.420 --> 00:16:24.750 align:middle line:90%
And I could--

00:16:24.750 --> 00:16:26.440 align:middle line:90%
I get to ionic.

00:16:26.440 --> 00:16:28.180 align:middle line:90%
So it's an ionic bond formation.

00:16:28.180 --> 00:16:30.110 align:middle line:84%
You have very
electronegative element,

00:16:30.110 --> 00:16:32.800 align:middle line:84%
and that's oxygen, and less
electronegative elements,

00:16:32.800 --> 00:16:33.790 align:middle line:90%
those are metals.

00:16:33.790 --> 00:16:38.230 align:middle line:84%
And that bonding mechanism
is electron transfer,

00:16:38.230 --> 00:16:40.120 align:middle line:90%
and it's very exothermic.

00:16:40.120 --> 00:16:43.990 align:middle line:84%
So as a result, delta H's tend
to be very large and negative.

00:16:43.990 --> 00:16:49.820 align:middle line:84%
And this allows us to
neglect temp dependence.

00:16:49.820 --> 00:16:55.440 align:middle line:90%


00:16:55.440 --> 00:16:56.790 align:middle line:90%
Neglect temp dependence.

00:16:56.790 --> 00:17:02.900 align:middle line:90%


00:17:02.900 --> 00:17:05.630 align:middle line:84%
We'll just say
that it's whatever

00:17:05.630 --> 00:17:09.349 align:middle line:84%
it is at 298, because that's
a convenient reference point.

00:17:09.349 --> 00:17:10.520 align:middle line:90%
And these are tabulated.

00:17:10.520 --> 00:17:12.890 align:middle line:84%
The enthalpy of
oxidation reactions

00:17:12.890 --> 00:17:16.650 align:middle line:84%
at standard condition,
those are tabulated.

00:17:16.650 --> 00:17:19.176 align:middle line:84%
So that takes care
of the enthalpy.

00:17:19.176 --> 00:17:20.134 align:middle line:90%
What about the entropy?

00:17:20.134 --> 00:17:27.130 align:middle line:90%


00:17:27.130 --> 00:17:34.920 align:middle line:84%
Entropy delta S is delta S at
some reference temperature,

00:17:34.920 --> 00:17:37.205 align:middle line:90%
298 plus integral.

00:17:37.205 --> 00:17:45.710 align:middle line:90%


00:17:45.710 --> 00:17:48.350 align:middle line:84%
OK, so who knows-- who
has a guess on what

00:17:48.350 --> 00:17:49.100 align:middle line:90%
we're going to do?

00:17:49.100 --> 00:17:51.190 align:middle line:84%
We're going to
approximate this as what?

00:17:51.190 --> 00:17:56.135 align:middle line:90%


00:17:56.135 --> 00:17:57.210 align:middle line:90%
What am I looking for?

00:17:57.210 --> 00:18:00.790 align:middle line:84%
I want to justify
what approximation.

00:18:00.790 --> 00:18:03.460 align:middle line:84%
AUDIENCE: Aren't entropy
values usually much smaller?

00:18:03.460 --> 00:18:06.900 align:middle line:84%
So if the enthalpy is already
so big, we could assume entropy

00:18:06.900 --> 00:18:08.490 align:middle line:90%
is 0?

00:18:08.490 --> 00:18:09.520 align:middle line:90%
RAFAEL JARAMILLO: I see.

00:18:09.520 --> 00:18:14.180 align:middle line:84%
So you're right that entropy
values tend to be much smaller,

00:18:14.180 --> 00:18:16.498 align:middle line:84%
but the thing is they're
multiplied by temperature.

00:18:16.498 --> 00:18:19.040 align:middle line:84%
So they do matter quite a lot,
because the temperature number

00:18:19.040 --> 00:18:21.040 align:middle line:90%
can get large.

00:18:21.040 --> 00:18:24.550 align:middle line:84%
So we're not we're not going
to neglect it completely,

00:18:24.550 --> 00:18:25.960 align:middle line:90%
but I'll tell you--

00:18:25.960 --> 00:18:27.110 align:middle line:90%
I'm sorry?

00:18:27.110 --> 00:18:29.110 align:middle line:84%
AUDIENCE: Neglecting its
temperature dependence?

00:18:29.110 --> 00:18:29.680 align:middle line:84%
RAFAEL JARAMILLO:
Yeah, we're going

00:18:29.680 --> 00:18:31.600 align:middle line:84%
to neglect its
temperature dependence.

00:18:31.600 --> 00:18:36.620 align:middle line:84%
So I'm going to write
this before I write this.

00:18:36.620 --> 00:18:38.430 align:middle line:84%
It's just the why
we get to do that.

00:18:38.430 --> 00:18:43.940 align:middle line:84%
So let me write neglect
the temperature dependence,

00:18:43.940 --> 00:18:46.820 align:middle line:84%
and now, somebody
please tell me why

00:18:46.820 --> 00:18:50.005 align:middle line:90%
we might be able to do this?

00:18:50.005 --> 00:18:52.630 align:middle line:84%
And it's not just that we really
like to make our lives easier.

00:18:52.630 --> 00:18:55.810 align:middle line:84%
It turns out to be a really good
approximation in many cases.

00:18:55.810 --> 00:18:57.655 align:middle line:84%
What about this
oxidation reaction?

00:18:57.655 --> 00:19:00.270 align:middle line:90%


00:19:00.270 --> 00:19:02.625 align:middle line:84%
What's the dominant
entropy change?

00:19:02.625 --> 00:19:05.950 align:middle line:90%


00:19:05.950 --> 00:19:12.483 align:middle line:84%
What's the dominant
contribution to delta S?

00:19:12.483 --> 00:19:14.650 align:middle line:84%
AUDIENCE: Could it be when
the phase change happens?

00:19:14.650 --> 00:19:17.112 align:middle line:84%
So when the temperature
is constant?

00:19:17.112 --> 00:19:19.320 align:middle line:84%
RAFAEL JARAMILLO: The phase
change meaning from metal

00:19:19.320 --> 00:19:21.300 align:middle line:90%
to metal oxide?

00:19:21.300 --> 00:19:22.683 align:middle line:90%
AUDIENCE: Yeah.

00:19:22.683 --> 00:19:24.350 align:middle line:84%
RAFAEL JARAMILLO:
That's true, but maybe

00:19:24.350 --> 00:19:26.360 align:middle line:90%
tell me what part of that?

00:19:26.360 --> 00:19:31.420 align:middle line:90%


00:19:31.420 --> 00:19:33.375 align:middle line:84%
AUDIENCE: [INAUDIBLE]
condense it?

00:19:33.375 --> 00:19:34.750 align:middle line:84%
RAFAEL JARAMILLO:
Yes, thank you.

00:19:34.750 --> 00:19:36.220 align:middle line:90%
That's what I'm looking for.

00:19:36.220 --> 00:19:38.937 align:middle line:84%
The reaction entropy
is dominated by--

00:19:38.937 --> 00:19:41.020 align:middle line:84%
I didn't see who said that,
but thank you so much.

00:19:41.020 --> 00:19:51.890 align:middle line:84%
By condensation of
O2 from the gas.

00:19:51.890 --> 00:19:52.790 align:middle line:90%
That's it.

00:19:52.790 --> 00:19:55.310 align:middle line:90%
So here's metal.

00:19:55.310 --> 00:20:04.640 align:middle line:84%
There's a chunk of metal,
and then I have O2 gas.

00:20:04.640 --> 00:20:08.120 align:middle line:84%
Gas is very high
entropy, as you know.

00:20:08.120 --> 00:20:09.890 align:middle line:90%
O2.

00:20:09.890 --> 00:20:15.470 align:middle line:84%
And this reaction pulls
the oxygen out of the gas

00:20:15.470 --> 00:20:19.520 align:middle line:90%
and makes a metal oxide.

00:20:19.520 --> 00:20:23.480 align:middle line:84%
So the reactants have
much, much higher entropy

00:20:23.480 --> 00:20:25.730 align:middle line:84%
than the products,
simply due to the fact

00:20:25.730 --> 00:20:27.890 align:middle line:84%
that the reactants
included a mode of gas

00:20:27.890 --> 00:20:31.040 align:middle line:84%
and the products
don't include any gas.

00:20:31.040 --> 00:20:35.890 align:middle line:84%
And in almost all
cases, that change

00:20:35.890 --> 00:20:39.370 align:middle line:90%
dominates the reaction entropy.

00:20:39.370 --> 00:20:45.650 align:middle line:84%
And since we're modeling
oxygen as an ideal gas,

00:20:45.650 --> 00:20:48.110 align:middle line:84%
the entropy of this gas is
temperature independent.

00:20:48.110 --> 00:20:50.580 align:middle line:90%
It's configuration entropy.

00:20:50.580 --> 00:20:52.880 align:middle line:84%
It's the thing
we've been talking

00:20:52.880 --> 00:20:55.130 align:middle line:84%
about pretty much the
whole semester, which

00:20:55.130 --> 00:21:00.680 align:middle line:84%
is the entropy of randomly
configured gas molecules.

00:21:00.680 --> 00:21:01.180 align:middle line:90%
Good.

00:21:01.180 --> 00:21:01.680 align:middle line:90%
Thank you.

00:21:01.680 --> 00:21:04.390 align:middle line:84%
So now we have waved our
hands, although we've

00:21:04.390 --> 00:21:05.437 align:middle line:90%
done it scientifically.

00:21:05.437 --> 00:21:07.270 align:middle line:84%
Scientifically waving
of hands has happened,

00:21:07.270 --> 00:21:09.730 align:middle line:84%
and we figured out that we
can neglect the temperature

00:21:09.730 --> 00:21:12.520 align:middle line:84%
dependence of the enthalpy and
we can neglect the temperature

00:21:12.520 --> 00:21:14.170 align:middle line:84%
dependence of the
entropy, and this

00:21:14.170 --> 00:21:17.530 align:middle line:84%
is going to make our lives even
easier than they already were.

00:21:17.530 --> 00:21:22.080 align:middle line:90%
We can solve for this thing.

00:21:22.080 --> 00:21:25.290 align:middle line:84%
We can solve for that
oxygen partial pressure.

00:21:25.290 --> 00:21:35.280 align:middle line:84%
PO2 by atmosphere equals
e the delta H0 over RT.

00:21:35.280 --> 00:21:40.240 align:middle line:84%
e the minus delta
S0 over R. This

00:21:40.240 --> 00:22:00.600 align:middle line:84%
is the oxygen pressure at
which a metal and its oxide

00:22:00.600 --> 00:22:05.621 align:middle line:90%
coexist at equilibrium.

00:22:05.621 --> 00:22:13.510 align:middle line:90%


00:22:13.510 --> 00:22:14.885 align:middle line:84%
All right, so
you've got a metal.

00:22:14.885 --> 00:22:18.470 align:middle line:90%


00:22:18.470 --> 00:22:24.400 align:middle line:84%
They've got it's oxide, and this
is the oxygen partial pressure,

00:22:24.400 --> 00:22:25.620 align:middle line:90%
so there's some oxygen here.

00:22:25.620 --> 00:22:31.420 align:middle line:90%


00:22:31.420 --> 00:22:32.980 align:middle line:84%
This is the oxygen
partial pressure

00:22:32.980 --> 00:22:38.220 align:middle line:84%
at which this kind of
situation is that equilibrium.

00:22:38.220 --> 00:22:48.800 align:middle line:90%


00:22:48.800 --> 00:22:52.460 align:middle line:84%
What happens if the oxygen
partial pressure is higher

00:22:52.460 --> 00:22:53.730 align:middle line:90%
than the equilibrium value?

00:22:53.730 --> 00:22:59.360 align:middle line:84%
What do you think happens
spontaneously in this system?

00:22:59.360 --> 00:23:01.012 align:middle line:90%
Think Le Chatelier's principle.

00:23:01.012 --> 00:23:02.720 align:middle line:84%
I have the system in
equilibrium and then

00:23:02.720 --> 00:23:04.280 align:middle line:90%
I shove more oxygen gas in.

00:23:04.280 --> 00:23:06.350 align:middle line:84%
I increase the oxygen
partial pressure.

00:23:06.350 --> 00:23:07.640 align:middle line:90%
What do you expect to happen?

00:23:07.640 --> 00:23:10.780 align:middle line:90%
How will the system respond?

00:23:10.780 --> 00:23:12.737 align:middle line:84%
AUDIENCE:
Spontaneously oxidized?

00:23:12.737 --> 00:23:14.070 align:middle line:90%
RAFAEL JARAMILLO: One more time.

00:23:14.070 --> 00:23:14.960 align:middle line:84%
I'm sorry, I didn't
quite hear that.

00:23:14.960 --> 00:23:16.520 align:middle line:84%
AUDIENCE:
Spontaneously oxidized?

00:23:16.520 --> 00:23:17.900 align:middle line:84%
RAFAEL JARAMILLO:
Yes, fantastic.

00:23:17.900 --> 00:23:21.360 align:middle line:90%
Metal spontaneously.

00:23:21.360 --> 00:23:28.380 align:middle line:90%


00:23:28.380 --> 00:23:31.370 align:middle line:84%
So you're going to have
spontaneous conversion of more

00:23:31.370 --> 00:23:32.720 align:middle line:90%
metal into oxide.

00:23:32.720 --> 00:23:35.780 align:middle line:84%
We've already established
that the oxygen can't

00:23:35.780 --> 00:23:37.313 align:middle line:84%
dissolve in the
metal and the oxygen

00:23:37.313 --> 00:23:38.480 align:middle line:90%
can't dissolve in the oxide.

00:23:38.480 --> 00:23:40.490 align:middle line:84%
They're pure components,
so all we can do

00:23:40.490 --> 00:23:44.090 align:middle line:84%
is convert metal to oxide,
metal to oxide, metal to oxide.

00:23:44.090 --> 00:23:44.690 align:middle line:90%
Excellent.

00:23:44.690 --> 00:23:45.230 align:middle line:90%
Thank you.

00:23:45.230 --> 00:23:46.706 align:middle line:90%
What about at lower?

00:23:46.706 --> 00:23:50.087 align:middle line:90%


00:23:50.087 --> 00:23:52.160 align:middle line:84%
At lower oxygen
pressure pressure?

00:23:52.160 --> 00:23:54.680 align:middle line:84%
If we're below this
value, what do we

00:23:54.680 --> 00:23:58.062 align:middle line:90%
expect to happen spontaneously?

00:23:58.062 --> 00:24:00.270 align:middle line:84%
AUDIENCE: We will see the
reverse reaction happening.

00:24:00.270 --> 00:24:03.062 align:middle line:90%
So more O2 gas will form?

00:24:03.062 --> 00:24:06.030 align:middle line:84%
RAFAEL JARAMILLO:
How does it form?

00:24:06.030 --> 00:24:09.000 align:middle line:84%
AUDIENCE: Through the
oxide decomposing back

00:24:09.000 --> 00:24:11.598 align:middle line:90%
into a metal and O2 gas.

00:24:11.598 --> 00:24:13.140 align:middle line:84%
RAFAEL JARAMILLO:
Exactly, thank you.

00:24:13.140 --> 00:24:15.140 align:middle line:84%
I'm going to use this
term the oxide is reduced,

00:24:15.140 --> 00:24:18.720 align:middle line:84%
but your expression of
spontaneously decomposing

00:24:18.720 --> 00:24:20.830 align:middle line:90%
is exactly the right thing.

00:24:20.830 --> 00:24:25.350 align:middle line:84%
So if we pull down the oxygen
pressure below the equilibrium

00:24:25.350 --> 00:24:28.860 align:middle line:84%
value, the system will
respond by converting oxide

00:24:28.860 --> 00:24:30.790 align:middle line:90%
into metal and oxygen gas.

00:24:30.790 --> 00:24:33.120 align:middle line:84%
And you can think of this
in terms of Le Chatelier.

00:24:33.120 --> 00:24:35.250 align:middle line:84%
If I add more oxygen,
the system will

00:24:35.250 --> 00:24:39.900 align:middle line:84%
try to counteract that by
condensing the oxygen into more

00:24:39.900 --> 00:24:43.230 align:middle line:84%
oxide, so it'll take more
metal, convert it into oxide

00:24:43.230 --> 00:24:48.360 align:middle line:84%
by pulling some of my extra
oxygen out of the atmosphere.

00:24:48.360 --> 00:24:50.880 align:middle line:84%
If I pull down the
oxygen pressure,

00:24:50.880 --> 00:24:54.060 align:middle line:84%
the system will try to
counteract that by giving off

00:24:54.060 --> 00:24:56.190 align:middle line:90%
more oxygen gas from the oxide.

00:24:56.190 --> 00:25:00.990 align:middle line:84%
The oxide will decompose into
more oxygen gas and more metal.

00:25:00.990 --> 00:25:03.750 align:middle line:90%
That's right.

00:25:03.750 --> 00:25:05.650 align:middle line:90%
So that's what happens.

00:25:05.650 --> 00:25:09.560 align:middle line:84%
So for example, let's
imagine Ti oxidizing.

00:25:09.560 --> 00:25:12.750 align:middle line:90%


00:25:12.750 --> 00:25:14.730 align:middle line:90%
That's a nice reaction.

00:25:14.730 --> 00:25:19.700 align:middle line:90%
At 298 Kelvin, I looked it up.

00:25:19.700 --> 00:25:23.300 align:middle line:90%
The PO2 at this equilibrium is--

00:25:23.300 --> 00:25:25.220 align:middle line:90%
anybody have a guess?

00:25:25.220 --> 00:25:26.120 align:middle line:90%
Forget the guess.

00:25:26.120 --> 00:25:28.610 align:middle line:90%
It's completely naive.

00:25:28.610 --> 00:25:34.720 align:middle line:90%
10 to the minus 150 atmospheres.

00:25:34.720 --> 00:25:39.370 align:middle line:84%
A completely silly,
make believe number.

00:25:39.370 --> 00:25:40.360 align:middle line:90%
It's 0.

00:25:40.360 --> 00:25:40.860 align:middle line:90%
It's 0.

00:25:40.860 --> 00:25:42.237 align:middle line:90%
It might as well be 0.

00:25:42.237 --> 00:25:43.945 align:middle line:84%
What does that mean
about titanium metal?

00:25:43.945 --> 00:25:48.420 align:middle line:90%


00:25:48.420 --> 00:25:50.782 align:middle line:84%
AUDIENCE: It's very
favorable for it to oxidize.

00:25:50.782 --> 00:25:52.740 align:middle line:84%
RAFAEL JARAMILLO: Very
favorable with oxidized.

00:25:52.740 --> 00:25:55.710 align:middle line:84%
Titanium metal, if
you see it in the air,

00:25:55.710 --> 00:25:59.010 align:middle line:84%
will actually be titanium
metal with a thin layer

00:25:59.010 --> 00:26:01.950 align:middle line:84%
of its own native
oxide on top of it.

00:26:01.950 --> 00:26:03.810 align:middle line:84%
Because if you were
to remove the oxide

00:26:03.810 --> 00:26:06.060 align:middle line:84%
and wait a split
second, the oxide

00:26:06.060 --> 00:26:09.920 align:middle line:90%
would spontaneously reform.

00:26:09.920 --> 00:26:13.330 align:middle line:84%
And so this spontaneous
oxide formation process

00:26:13.330 --> 00:26:16.670 align:middle line:84%
is really important
for a lot of reasons.

00:26:16.670 --> 00:26:18.520 align:middle line:84%
It's important for
microelectronics,

00:26:18.520 --> 00:26:20.350 align:middle line:84%
it's important for
stainless steel.

00:26:20.350 --> 00:26:22.630 align:middle line:84%
That's how stainless
steel remains stainless.

00:26:22.630 --> 00:26:25.570 align:middle line:84%
You have spontaneous
formation of a passive rating,

00:26:25.570 --> 00:26:28.150 align:middle line:84%
or you can think of it
as a protecting oxide

00:26:28.150 --> 00:26:32.410 align:middle line:84%
layer and the engineering of
those materials continues.

00:26:32.410 --> 00:26:34.030 align:middle line:90%
It's all interesting stuff.

00:26:34.030 --> 00:26:38.855 align:middle line:84%
All right, so that is enough to
take us to Richardson Ellingham

00:26:38.855 --> 00:26:39.355 align:middle line:90%
diagrams.

00:26:39.355 --> 00:26:52.560 align:middle line:90%


00:26:52.560 --> 00:26:54.733 align:middle line:90%
So we're going to do this.

00:26:54.733 --> 00:26:56.400 align:middle line:84%
I can't really motivate
this, because it

00:26:56.400 --> 00:26:58.350 align:middle line:84%
sounds kind of random
what we're going to do.

00:26:58.350 --> 00:27:00.848 align:middle line:84%
So I'm just going to tell you
what it is, and at the end

00:27:00.848 --> 00:27:01.890 align:middle line:90%
tell you why it's useful.

00:27:01.890 --> 00:27:06.410 align:middle line:90%


00:27:06.410 --> 00:27:09.190 align:middle line:84%
We're going to plot delta G0
as a function of temperature

00:27:09.190 --> 00:27:11.110 align:middle line:90%
for metal oxidation reactions.

00:27:11.110 --> 00:27:15.200 align:middle line:90%


00:27:15.200 --> 00:27:17.280 align:middle line:90%
As you know, it's like this.

00:27:17.280 --> 00:27:20.010 align:middle line:84%
And so this is a
pretty simple thing.

00:27:20.010 --> 00:27:28.620 align:middle line:84%
This is a line with slope minus
delta S0 and intercept delta

00:27:28.620 --> 00:27:30.710 align:middle line:90%
H0.

00:27:30.710 --> 00:27:36.945 align:middle line:84%
This is a really,
really simple line.

00:27:36.945 --> 00:27:39.880 align:middle line:90%


00:27:39.880 --> 00:27:40.930 align:middle line:90%
So here's is temperature.

00:27:40.930 --> 00:27:42.290 align:middle line:90%
Let's see in Kelvin.

00:27:42.290 --> 00:27:44.380 align:middle line:90%
Here's 0, here's 0.

00:27:44.380 --> 00:27:49.790 align:middle line:84%
Here's delta G0,
and we have line.

00:27:49.790 --> 00:27:55.770 align:middle line:84%
We have a line, the
slope, and an intercept.

00:27:55.770 --> 00:28:00.120 align:middle line:90%
Slope, intercept.

00:28:00.120 --> 00:28:02.830 align:middle line:90%


00:28:02.830 --> 00:28:06.760 align:middle line:84%
That is a Richardson
Ellingham diagram.

00:28:06.760 --> 00:28:09.610 align:middle line:90%
Now, why did we do that?

00:28:09.610 --> 00:28:11.930 align:middle line:90%
A couple of reasons.

00:28:11.930 --> 00:28:18.280 align:middle line:84%
Let's start by talking
about the PO2 scale.

00:28:18.280 --> 00:28:19.540 align:middle line:90%
What's that?

00:28:19.540 --> 00:28:27.400 align:middle line:84%
The equilibrium constant is PO2
by atmosphere to the minus 1,

00:28:27.400 --> 00:28:32.080 align:middle line:84%
which is equal to e to
the minus G0 over RT.

00:28:32.080 --> 00:28:37.180 align:middle line:84%
So I'm just going to rearrange
that and write delta G0 equals

00:28:37.180 --> 00:28:42.670 align:middle line:90%
RT log PO2 by atmosphere.

00:28:42.670 --> 00:28:45.590 align:middle line:90%


00:28:45.590 --> 00:28:59.110 align:middle line:84%
This is a line on delta
G0 by t plot with slope

00:28:59.110 --> 00:29:06.970 align:middle line:90%
our log, PO2 and 0 intercepts.

00:29:06.970 --> 00:29:16.570 align:middle line:90%


00:29:16.570 --> 00:29:17.690 align:middle line:90%
Let's draw that.

00:29:17.690 --> 00:29:24.650 align:middle line:90%


00:29:24.650 --> 00:29:28.160 align:middle line:84%
All right, here is
temperature in Kelvin.

00:29:28.160 --> 00:29:30.200 align:middle line:90%
0 is 0.

00:29:30.200 --> 00:29:33.260 align:middle line:90%
Here's delta G0.

00:29:33.260 --> 00:29:43.080 align:middle line:84%
I'll draw the oxidation
of a given metal

00:29:43.080 --> 00:29:47.920 align:middle line:90%
just to have something on there.

00:29:47.920 --> 00:29:51.520 align:middle line:84%
And now, I'm going to draw
these two contours, right?

00:29:51.520 --> 00:29:54.550 align:middle line:84%
Delta G0 equals RT log
PO2 over atmosphere.

00:29:54.550 --> 00:29:56.560 align:middle line:84%
So I'm going to draw
a series of lines

00:29:56.560 --> 00:29:58.960 align:middle line:84%
all with 0 intercepts
in varying slope.

00:29:58.960 --> 00:30:10.210 align:middle line:90%


00:30:10.210 --> 00:30:12.900 align:middle line:84%
So there's a series of lines
with 0 intercept and varying

00:30:12.900 --> 00:30:13.890 align:middle line:90%
slope.

00:30:13.890 --> 00:30:23.045 align:middle line:84%
And as I move in this
direction, I'm increasing PO2.

00:30:23.045 --> 00:30:26.850 align:middle line:90%


00:30:26.850 --> 00:30:30.500 align:middle line:84%
So that's what a Richardson
Ellingham plot is.

00:30:30.500 --> 00:30:32.780 align:middle line:84%
Now, I get to tell
you why it's useful.

00:30:32.780 --> 00:30:35.180 align:middle line:84%
All right, so if I rush
through the explanation what

00:30:35.180 --> 00:30:37.430 align:middle line:84%
it is, because it's just like,
I have to tell you what it is.

00:30:37.430 --> 00:30:39.097 align:middle line:84%
But now, I can show
you why it's useful.

00:30:39.097 --> 00:30:42.060 align:middle line:90%


00:30:42.060 --> 00:30:48.780 align:middle line:90%
So why is this useful?

00:30:48.780 --> 00:30:53.170 align:middle line:90%


00:30:53.170 --> 00:30:55.980 align:middle line:84%
It's useful for
materials processing.

00:30:55.980 --> 00:31:03.460 align:middle line:90%


00:31:03.460 --> 00:31:05.460 align:middle line:90%
Let me illustrate that.

00:31:05.460 --> 00:31:13.460 align:middle line:84%
Let's consider two
metals, and I pick these

00:31:13.460 --> 00:31:16.580 align:middle line:84%
just because they appear
nicely separate on the plot.

00:31:16.580 --> 00:31:22.050 align:middle line:90%
Let's consider tin in manganese.

00:31:22.050 --> 00:31:24.930 align:middle line:90%


00:31:24.930 --> 00:31:28.650 align:middle line:84%
If I look up the
Richard Ellingham

00:31:28.650 --> 00:31:31.660 align:middle line:84%
diagram for tin and
manganese, I could do that,

00:31:31.660 --> 00:31:36.570 align:middle line:84%
but I'll just draw qualitatively
what it looks like.

00:31:36.570 --> 00:31:39.300 align:middle line:90%
It's temperature in Kelvin.

00:31:39.300 --> 00:31:41.400 align:middle line:90%
It's delta G0.

00:31:41.400 --> 00:31:53.380 align:middle line:84%
And I'm just here to tell you
that the tin line sits well

00:31:53.380 --> 00:31:58.430 align:middle line:90%
above the manganese line.

00:31:58.430 --> 00:32:02.570 align:middle line:84%
So that's just a fact
about these metals.

00:32:02.570 --> 00:32:10.730 align:middle line:84%
This here is tin plus
O2 going to tin O2.

00:32:10.730 --> 00:32:19.130 align:middle line:84%
That's what that is, and
this is 2 manganese plus O2

00:32:19.130 --> 00:32:21.830 align:middle line:90%
going to 2 manganese oxide.

00:32:21.830 --> 00:32:26.050 align:middle line:90%


00:32:26.050 --> 00:32:29.050 align:middle line:90%
And here are my PO2 contours.

00:32:29.050 --> 00:32:37.940 align:middle line:90%


00:32:37.940 --> 00:32:41.340 align:middle line:90%
What is this plot telling me?

00:32:41.340 --> 00:32:45.765 align:middle line:84%
It's telling me
that, at a given--

00:32:45.765 --> 00:32:55.750 align:middle line:90%


00:32:55.750 --> 00:32:58.360 align:middle line:84%
I have a typo on my scan
lecture notes, I'm sorry.

00:32:58.360 --> 00:33:03.410 align:middle line:84%
At a given temp at
any given temperature,

00:33:03.410 --> 00:33:13.470 align:middle line:84%
PO2 for the manganese
oxidation reaction

00:33:13.470 --> 00:33:22.970 align:middle line:84%
is lower than for the
tin oxidation reaction.

00:33:22.970 --> 00:33:29.740 align:middle line:90%


00:33:29.740 --> 00:33:31.690 align:middle line:90%
That's a useful fact.

00:33:31.690 --> 00:33:32.530 align:middle line:90%
How do I see that?

00:33:32.530 --> 00:33:42.530 align:middle line:84%
Let's say at a
given temperature,

00:33:42.530 --> 00:33:46.260 align:middle line:90%
let's see that temperature here.

00:33:46.260 --> 00:33:50.340 align:middle line:84%
I have this point on
the tin oxidation line.

00:33:50.340 --> 00:33:53.760 align:middle line:90%


00:33:53.760 --> 00:34:00.070 align:middle line:84%
And this point on the
manganese oxidation line.

00:34:00.070 --> 00:34:09.320 align:middle line:84%
Well, the PO2 contour that runs
through the manganese oxidation

00:34:09.320 --> 00:34:12.260 align:middle line:84%
line intercepting
of that temperature

00:34:12.260 --> 00:34:14.750 align:middle line:84%
corresponds to a
lower partial pressure

00:34:14.750 --> 00:34:18.650 align:middle line:84%
than the PO2 contour that runs
through the tin oxidation line

00:34:18.650 --> 00:34:20.840 align:middle line:90%
for that given temperature.

00:34:20.840 --> 00:34:27.440 align:middle line:84%
Again, at its given temperature,
the PO2 partial pressure

00:34:27.440 --> 00:34:33.260 align:middle line:84%
contour for manganese oxidation
is a lower partial pressure

00:34:33.260 --> 00:34:35.510 align:middle line:84%
than the contour
for tin oxidation.

00:34:35.510 --> 00:34:39.100 align:middle line:90%


00:34:39.100 --> 00:34:40.880 align:middle line:90%
What does that mean?

00:34:40.880 --> 00:34:50.139 align:middle line:84%
Manganese metal will
reduce tin oxide.

00:34:50.139 --> 00:34:51.630 align:middle line:84%
So if you were to
put tin oxide--

00:34:51.630 --> 00:34:54.750 align:middle line:84%
let's say an ore into a
furnace in the presence

00:34:54.750 --> 00:34:59.870 align:middle line:84%
of manganese metal
and heat it up,

00:34:59.870 --> 00:35:03.620 align:middle line:84%
the manganese will
convert to manganese oxide

00:35:03.620 --> 00:35:06.950 align:middle line:84%
and then tin oxide will
convert to tin metal.

00:35:06.950 --> 00:35:08.390 align:middle line:90%
Why is that?

00:35:08.390 --> 00:35:25.680 align:middle line:84%
Manganese has higher affinity
for oxygen than does tin.

00:35:25.680 --> 00:35:31.820 align:middle line:84%
Or saying the same thing,
the enthalpy of oxidation

00:35:31.820 --> 00:35:43.110 align:middle line:84%
is more negative for
manganese oxidation

00:35:43.110 --> 00:35:47.100 align:middle line:90%
than for tin oxidation.

00:35:47.100 --> 00:35:50.520 align:middle line:90%


00:35:50.520 --> 00:35:53.880 align:middle line:84%
So you can see that
from the plots.

00:35:53.880 --> 00:35:56.790 align:middle line:84%
The intercept of these
plots is delta H. So

00:35:56.790 --> 00:35:59.810 align:middle line:84%
you can see the intercepts
for the manganese oxidation--

00:35:59.810 --> 00:36:02.250 align:middle line:90%
that's at this point down here--

00:36:02.250 --> 00:36:03.510 align:middle line:90%
is lower.

00:36:03.510 --> 00:36:04.620 align:middle line:90%
Let me extend these lines.

00:36:04.620 --> 00:36:11.968 align:middle line:90%


00:36:11.968 --> 00:36:14.010 align:middle line:84%
The intercept of the
manganese oxidation reaction

00:36:14.010 --> 00:36:16.427 align:middle line:84%
is lower than the intercept
of the tin oxidation reaction.

00:36:16.427 --> 00:36:19.780 align:middle line:90%


00:36:19.780 --> 00:36:23.530 align:middle line:84%
The enthalpy of manganese
oxidation is more negative.

00:36:23.530 --> 00:36:27.100 align:middle line:84%
Or if we are speaking a
little bit colloquially,

00:36:27.100 --> 00:36:33.710 align:middle line:90%
manganese metal pulls--

00:36:33.710 --> 00:36:42.295 align:middle line:84%
in quotation marks--
oxygen out of tin oxide.

00:36:42.295 --> 00:36:47.610 align:middle line:90%


00:36:47.610 --> 00:36:50.460 align:middle line:84%
So everything I
just wrote, these

00:36:50.460 --> 00:37:02.765 align:middle line:84%
are all saying the same thing
about metal oxygen bonds.

00:37:02.765 --> 00:37:06.180 align:middle line:90%


00:37:06.180 --> 00:37:09.150 align:middle line:84%
All right, these are all
equivalent statements.

00:37:09.150 --> 00:37:12.510 align:middle line:84%
They're just ways of
interpreting metal oxygen

00:37:12.510 --> 00:37:17.730 align:middle line:84%
bonding and the implications of
that for materials processing.

00:37:17.730 --> 00:37:19.680 align:middle line:84%
If you're going to be
processing manganese

00:37:19.680 --> 00:37:22.230 align:middle line:84%
in the presence of
tin, you need to know

00:37:22.230 --> 00:37:25.710 align:middle line:84%
which one is going to have
a higher PO2 at equilibrium

00:37:25.710 --> 00:37:29.290 align:middle line:84%
for oxidation, because it's
going to determine your process

00:37:29.290 --> 00:37:29.790 align:middle line:90%
outcome.

00:37:29.790 --> 00:37:35.990 align:middle line:90%


00:37:35.990 --> 00:37:40.050 align:middle line:84%
I want to share with you some
pictures of Ellingham diagrams.

00:37:40.050 --> 00:37:44.040 align:middle line:84%
So there's lots of Ellingham
diagrams out there.

00:37:44.040 --> 00:37:47.870 align:middle line:84%
Here is one representation
that's a little busy,

00:37:47.870 --> 00:37:49.520 align:middle line:84%
but you can see
lots of things here.

00:37:49.520 --> 00:37:53.120 align:middle line:84%
You can see many metals
which are all represented.

00:37:53.120 --> 00:37:54.620 align:middle line:90%
Let me grab my laser pointer.

00:37:54.620 --> 00:37:56.780 align:middle line:84%
Sometimes the laser
pointer is stubborn.

00:37:56.780 --> 00:37:57.935 align:middle line:90%
So here's iron.

00:37:57.935 --> 00:38:00.470 align:middle line:90%


00:38:00.470 --> 00:38:03.440 align:middle line:84%
Oxidation reaction is a
nickel reaction copper.

00:38:03.440 --> 00:38:08.820 align:middle line:84%
As you move down, you're
going to metals that have

00:38:08.820 --> 00:38:10.740 align:middle line:90%
higher affinity for oxygen.

00:38:10.740 --> 00:38:15.450 align:middle line:84%
So copper is sometimes
considered noble.

00:38:15.450 --> 00:38:18.590 align:middle line:84%
So it doesn't readily
form an oxide.

00:38:18.590 --> 00:38:20.630 align:middle line:84%
You remember we talked
about roof flashing.

00:38:20.630 --> 00:38:23.210 align:middle line:84%
It takes a long time
for it to turn green.

00:38:23.210 --> 00:38:24.445 align:middle line:90%
As opposed to calcium, right?

00:38:24.445 --> 00:38:25.820 align:middle line:84%
If you have calcium
metal around,

00:38:25.820 --> 00:38:27.320 align:middle line:84%
you should look
out, because it's

00:38:27.320 --> 00:38:30.290 align:middle line:90%
going to explosively oxidize.

00:38:30.290 --> 00:38:32.630 align:middle line:84%
So down here, you have
calcium, magnesium.

00:38:32.630 --> 00:38:33.470 align:middle line:90%
Aluminum.

00:38:33.470 --> 00:38:36.500 align:middle line:84%
Aluminum is a very energetic
oxidation reaction,

00:38:36.500 --> 00:38:38.907 align:middle line:84%
but we know it forms
a passivating oxide.

00:38:38.907 --> 00:38:41.240 align:middle line:84%
So you don't have exploding
aluminum all over the place.

00:38:41.240 --> 00:38:44.120 align:middle line:84%
You have almost
instantaneous formation

00:38:44.120 --> 00:38:46.610 align:middle line:84%
of aluminum oxide on
the surface of aluminum.

00:38:46.610 --> 00:38:48.530 align:middle line:84%
Titanium silicon
manganese chromium.

00:38:48.530 --> 00:38:53.990 align:middle line:84%
So this is a limited Richardson
diagram, Ellingham diagram,

00:38:53.990 --> 00:38:57.200 align:middle line:84%
because it only shows
about a dozen or so metals.

00:38:57.200 --> 00:39:00.200 align:middle line:84%
Of course, you can get
very, very busy plots.

00:39:00.200 --> 00:39:06.320 align:middle line:84%
I want to point out one more
thing, which is the PO2 scale.

00:39:06.320 --> 00:39:08.890 align:middle line:90%
PO2.

00:39:08.890 --> 00:39:11.260 align:middle line:84%
And you see it's a
series of numbers

00:39:11.260 --> 00:39:19.750 align:middle line:84%
running from 1 atmosphere to 0
to the minus 200 atmospheres.

00:39:19.750 --> 00:39:22.390 align:middle line:84%
And each of these numbers
has a little tick mark,

00:39:22.390 --> 00:39:25.270 align:middle line:84%
and the tick marks all
point towards the origin.

00:39:25.270 --> 00:39:28.990 align:middle line:84%
You see these tick marks,
they're at different angles.

00:39:28.990 --> 00:39:30.310 align:middle line:90%
Why is that?

00:39:30.310 --> 00:39:32.350 align:middle line:84%
Because it's asking
you to imagine

00:39:32.350 --> 00:39:35.710 align:middle line:84%
a series of straight lines
connecting the origin to those

00:39:35.710 --> 00:39:37.580 align:middle line:90%
values.

00:39:37.580 --> 00:39:40.980 align:middle line:84%
Those series of straight lines
connecting the origin to--

00:39:40.980 --> 00:39:42.590 align:middle line:90%
I've never done this before.

00:39:42.590 --> 00:39:43.740 align:middle line:90%
I draw the line.

00:39:43.740 --> 00:39:45.370 align:middle line:90%
So here is-- oh, there we go.

00:39:45.370 --> 00:39:45.930 align:middle line:90%
Look at that.

00:39:45.930 --> 00:39:49.880 align:middle line:84%
So this would be a line of 10
to the minus 50 atmospheres

00:39:49.880 --> 00:39:53.590 align:middle line:84%
of oxygen. So for
example, you might

00:39:53.590 --> 00:40:03.480 align:middle line:84%
say that zinc and its oxide
are equilibrium at 400 degrees

00:40:03.480 --> 00:40:08.253 align:middle line:84%
C and 10 to the minus 50
atmospheres of oxygen.

00:40:08.253 --> 00:40:09.920 align:middle line:84%
That would be one way
to read this plot.

00:40:09.920 --> 00:40:15.950 align:middle line:90%


00:40:15.950 --> 00:40:18.550 align:middle line:84%
And you also see that
the delta H of formation

00:40:18.550 --> 00:40:21.250 align:middle line:84%
here is correlated to
the electronegativity.

00:40:21.250 --> 00:40:25.060 align:middle line:84%
So this idea that metal oxygen
bond formation is energetic,

00:40:25.060 --> 00:40:29.700 align:middle line:84%
well, we know that, but
it's more energetic for less

00:40:29.700 --> 00:40:30.705 align:middle line:90%
electronegative metals.

00:40:30.705 --> 00:40:33.830 align:middle line:90%


00:40:33.830 --> 00:40:38.690 align:middle line:84%
So we expect noble metals
like silver and copper

00:40:38.690 --> 00:40:40.670 align:middle line:90%
to be fairly electronegative.

00:40:40.670 --> 00:40:44.240 align:middle line:84%
They like their
electrons, 1.9, 1.93.

00:40:44.240 --> 00:40:47.330 align:middle line:84%
And we expect alkaline,
alkaline Earth metals--

00:40:47.330 --> 00:40:50.060 align:middle line:90%
let's say alkaline earth--

00:40:50.060 --> 00:40:51.110 align:middle line:90%
alkali metals.

00:40:51.110 --> 00:40:53.790 align:middle line:84%
Alkaline Earth metals
like magnesium, right?

00:40:53.790 --> 00:40:56.840 align:middle line:84%
They are happy to give up
their electrons to oxygen.

00:40:56.840 --> 00:40:59.090 align:middle line:84%
And that has a lower
electronegativity

00:40:59.090 --> 00:41:00.275 align:middle line:90%
calcium is down here at 1.

00:41:00.275 --> 00:41:03.030 align:middle line:90%


00:41:03.030 --> 00:41:05.042 align:middle line:84%
So there's some
solid chemistry here.

00:41:05.042 --> 00:41:06.750 align:middle line:84%
There's one more thing
I want to tell you

00:41:06.750 --> 00:41:14.470 align:middle line:84%
about Ellingham diagrams,
and that is the effect

00:41:14.470 --> 00:41:15.610 align:middle line:90%
of phase transitions.

00:41:15.610 --> 00:41:26.520 align:middle line:90%


00:41:26.520 --> 00:41:37.590 align:middle line:84%
So let's consider melting
of metal or its oxide.

00:41:37.590 --> 00:41:42.420 align:middle line:84%
Metal's metal--
oxide's also metal--

00:41:42.420 --> 00:41:57.040 align:middle line:84%
causes-- it causes discrete
jumps in those values.

00:41:57.040 --> 00:42:06.080 align:middle line:84%
So for example, let's
consider solid metal

00:42:06.080 --> 00:42:12.390 align:middle line:90%
plus O2 going to MO2 solid.

00:42:12.390 --> 00:42:13.860 align:middle line:90%
Reaction one.

00:42:13.860 --> 00:42:18.220 align:middle line:90%
This says standard entropy 1.

00:42:18.220 --> 00:42:18.920 align:middle line:90%
It's negative.

00:42:18.920 --> 00:42:22.180 align:middle line:84%
It's negative, because
we're pulling oxygen gas out

00:42:22.180 --> 00:42:24.760 align:middle line:90%
of the gas, right?

00:42:24.760 --> 00:42:26.240 align:middle line:90%
Solids.

00:42:26.240 --> 00:42:26.740 align:middle line:90%
Solids.

00:42:26.740 --> 00:42:29.560 align:middle line:90%


00:42:29.560 --> 00:42:47.720 align:middle line:84%
Now, consider case where metal
melts at lower temp than MO2.

00:42:47.720 --> 00:42:49.290 align:middle line:84%
So metals have a
lower melting point,

00:42:49.290 --> 00:42:52.520 align:middle line:84%
which is true for
most but all oxides.

00:42:52.520 --> 00:43:02.910 align:middle line:84%
And raise the temp until
then the metal solid

00:43:02.910 --> 00:43:04.055 align:middle line:90%
becomes liquid metal.

00:43:04.055 --> 00:43:05.430 align:middle line:84%
So that's what
we're going to do.

00:43:05.430 --> 00:43:08.160 align:middle line:84%
We're going to consider
that, and now we're

00:43:08.160 --> 00:43:12.090 align:middle line:84%
going to consider the oxidation
again, except now we're

00:43:12.090 --> 00:43:13.410 align:middle line:90%
oxidizing liquid metal.

00:43:13.410 --> 00:43:17.760 align:middle line:90%


00:43:17.760 --> 00:43:22.140 align:middle line:84%
So the oxide is still solid
but the metal is now liquid.

00:43:22.140 --> 00:43:30.780 align:middle line:84%
And we'll call this reaction
to have delta S02 Well, we

00:43:30.780 --> 00:43:39.640 align:middle line:84%
know that the liquid
metal has higher

00:43:39.640 --> 00:43:45.280 align:middle line:90%
entropy than solid metal.

00:43:45.280 --> 00:43:48.680 align:middle line:90%


00:43:48.680 --> 00:43:50.460 align:middle line:90%
We know that.

00:43:50.460 --> 00:43:56.350 align:middle line:84%
So what that means
is that delta S02 is

00:43:56.350 --> 00:44:01.030 align:middle line:84%
going to be smaller
than delta S01,

00:44:01.030 --> 00:44:02.380 align:middle line:90%
and they're all less than 0.

00:44:02.380 --> 00:44:05.750 align:middle line:90%


00:44:05.750 --> 00:44:10.840 align:middle line:84%
In other words, it's going
to be even more negative.

00:44:10.840 --> 00:44:21.000 align:middle line:90%


00:44:21.000 --> 00:44:23.220 align:middle line:84%
On a plot, it looks
like as follows.

00:44:23.220 --> 00:44:30.880 align:middle line:90%


00:44:30.880 --> 00:44:32.830 align:middle line:90%
There's temperature.

00:44:32.830 --> 00:44:41.520 align:middle line:84%
This is delta G0, and we
have a kink in the plot.

00:44:41.520 --> 00:44:44.410 align:middle line:84%
The kink happens at
the melting point.

00:44:44.410 --> 00:44:53.103 align:middle line:84%
So here is metal melting
at that temperature.

00:44:53.103 --> 00:45:00.500 align:middle line:90%


00:45:00.500 --> 00:45:04.150 align:middle line:84%
The lower curve is a
solid oxidation reaction--

00:45:04.150 --> 00:45:10.920 align:middle line:90%


00:45:10.920 --> 00:45:14.730 align:middle line:90%
solid metal oxidation.

00:45:14.730 --> 00:45:16.860 align:middle line:84%
The upward curve is
liquid metal oxidation.

00:45:16.860 --> 00:45:29.260 align:middle line:90%


00:45:29.260 --> 00:45:37.410 align:middle line:84%
This intercept is delta H0
for solid metal oxidation,

00:45:37.410 --> 00:45:43.960 align:middle line:84%
and this intercept is delta
H0 for liquid metal oxidation.

00:45:43.960 --> 00:45:51.430 align:middle line:90%


00:45:51.430 --> 00:45:53.790 align:middle line:84%
So let's go back
to some real plots.

00:45:53.790 --> 00:45:57.190 align:middle line:90%


00:45:57.190 --> 00:45:59.080 align:middle line:84%
So now we can
understand why there

00:45:59.080 --> 00:46:01.480 align:middle line:90%
are break points in these.

00:46:01.480 --> 00:46:04.300 align:middle line:84%
There are break points
in these curves,

00:46:04.300 --> 00:46:11.550 align:middle line:84%
because at these transition
points, the standard enthalpy

00:46:11.550 --> 00:46:14.820 align:middle line:84%
and entropy of these
reactions changes.

00:46:14.820 --> 00:46:18.230 align:middle line:84%
So this melting point
here of aluminum,

00:46:18.230 --> 00:46:19.800 align:middle line:84%
it changes the
slope very slightly.

00:46:19.800 --> 00:46:21.180 align:middle line:90%
You can't really see it.

00:46:21.180 --> 00:46:23.400 align:middle line:84%
You can't really see it,
but there is a slope change.

00:46:23.400 --> 00:46:26.870 align:middle line:84%
Then up here, the
aluminum boils.

00:46:26.870 --> 00:46:32.290 align:middle line:84%
So there's another
break in the slope.

00:46:32.290 --> 00:46:33.355 align:middle line:90%
Here, manganese melts.

00:46:33.355 --> 00:46:36.570 align:middle line:90%


00:46:36.570 --> 00:46:38.880 align:middle line:90%
Here, the manganese melts.

00:46:38.880 --> 00:46:44.120 align:middle line:90%
Here, zinc melts and zinc boils.

00:46:44.120 --> 00:46:45.270 align:middle line:90%
So forth and so on.

00:46:45.270 --> 00:46:50.150 align:middle line:84%
And if you want to
really lose your mind,

00:46:50.150 --> 00:46:58.440 align:middle line:84%
you can look at more
complete Ellingham diagrams.

00:46:58.440 --> 00:47:01.140 align:middle line:84%
So this is posted
on the website.

00:47:01.140 --> 00:47:05.100 align:middle line:84%
And this is a very, very, very
thorough Ellingham diagram

00:47:05.100 --> 00:47:08.040 align:middle line:84%
now with so many
elements and melting

00:47:08.040 --> 00:47:10.740 align:middle line:84%
points and boiling
points and so forth.

00:47:10.740 --> 00:47:12.270 align:middle line:84%
And you can start
to look at these

00:47:12.270 --> 00:47:14.670 align:middle line:84%
and learn what the melting
points and the boiling points

00:47:14.670 --> 00:47:16.410 align:middle line:84%
of the metals and
the oxides are,

00:47:16.410 --> 00:47:19.080 align:middle line:84%
and you can see how they change
the slope of these curves.

00:47:19.080 --> 00:47:21.900 align:middle line:84%
There are cases where the
slope actually dips downward

00:47:21.900 --> 00:47:23.130 align:middle line:90%
for a little while.

00:47:23.130 --> 00:47:28.990 align:middle line:84%
That's typically a melting
point of an oxide and so forth.

00:47:28.990 --> 00:47:32.713 align:middle line:84%
And if you really like to
explore this a little more,

00:47:32.713 --> 00:47:33.880 align:middle line:90%
which I encourage you to do.

00:47:33.880 --> 00:47:36.030 align:middle line:90%
It's a nice way to learn.

00:47:36.030 --> 00:47:41.102 align:middle line:84%
Go to DoITPoMS page
with Ellingham diagrams.

00:47:41.102 --> 00:47:42.810 align:middle line:84%
For those of you who
don't know DoITPoMS,

00:47:42.810 --> 00:47:43.920 align:middle line:90%
you should know DoITPoMS.

00:47:43.920 --> 00:47:49.750 align:middle line:84%
It's a really excellent resource
for learning material science

00:47:49.750 --> 00:47:50.500 align:middle line:90%
concepts.

00:47:50.500 --> 00:47:55.500 align:middle line:84%
It's maintained by
University of Cambridge,

00:47:55.500 --> 00:47:57.000 align:middle line:84%
and it's a nice
complement to things

00:47:57.000 --> 00:47:59.400 align:middle line:90%
like OpenCourseWare and MIT.

00:47:59.400 --> 00:48:01.980 align:middle line:90%


00:48:01.980 --> 00:48:03.930 align:middle line:84%
Let me share that
just to show you

00:48:03.930 --> 00:48:11.440 align:middle line:84%
where you might go to play
with this a little more,

00:48:11.440 --> 00:48:12.880 align:middle line:90%
get a feel for it.

00:48:12.880 --> 00:48:20.770 align:middle line:84%
So here is the DoITPoMS
page for Ellingham diagrams,

00:48:20.770 --> 00:48:24.630 align:middle line:84%
and if you click
on oxides, there's

00:48:24.630 --> 00:48:25.630 align:middle line:90%
a whole bunch of oxides.

00:48:25.630 --> 00:48:28.255 align:middle line:84%
And so let's go at
random cobalt oxide.

00:48:28.255 --> 00:48:29.990 align:middle line:90%
See Ellingham diagram.

00:48:29.990 --> 00:48:35.320 align:middle line:84%
So it now shows you Ellingham
diagrams for cobalt for its two

00:48:35.320 --> 00:48:37.120 align:middle line:90%
different oxidation states.

00:48:37.120 --> 00:48:41.500 align:middle line:84%
And it will give you data,
you can mouse around,

00:48:41.500 --> 00:48:43.932 align:middle line:90%
get the actual numbers.

00:48:43.932 --> 00:48:44.890 align:middle line:90%
Change the temperature.

00:48:44.890 --> 00:48:47.530 align:middle line:84%
It gives you free energy
information, and so forth.

00:48:47.530 --> 00:48:50.110 align:middle line:90%
And it's a nice learning tool.

00:48:50.110 --> 00:48:56.460 align:middle line:84%
So now I will call it a
day and stop recording.

00:48:56.460 --> 00:49:05.000 align:middle line:90%