WEBVTT

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[SQUEAKING]

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[RUSTLING]

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[CLICKING]

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BRYNMOR CHAPMAN: Hello.

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Can people hear me?

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[SIDE CONVERSATION]

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Hello?

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[SIDE CONVERSATION]

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Getting some thumbs up.

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[SIDE CONVERSATION]

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OK.

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Why don't we get started?

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Hello, everybody.

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I'm Brynmor.

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If you've been
coming to lecture,

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you've already
met Erik and Zach.

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I'm the third instructor
for this course.

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Today, we are going to
switch gears a little bit.

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So we're going to move
on from state machines.

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And we're going to start a new
unit on algorithmic analysis.

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So we'll be looking at that
until the end of next week.

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This lecture is going
to be about sums.

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OK.

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So sums are quite useful.

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As I hinted at a
moment ago, they're

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good for algorithmic analysis.

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You'll use everything in this
unit quite a bit if you take

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6.1210 or any other
algorithms course.

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They're also useful for things
like probability, counting,

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machine learning-- everything's
useful for machine learning

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nowadays--

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recurrences and a
bunch of other things.

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So let's start with an example.

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OK.

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Has anybody here
ever won the lottery?

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Hands.

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Nobody?

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Really?

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Oh.

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Come on, guys.

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OK.

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Well, does anybody
know how it works?

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So if you win $1
million in the lottery,

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it turns out you don't actually
get a check for $1 million

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in the MAIL.

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Or you do, but it won't cash.

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It actually comes
in installments.

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OK.

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So imagine you get $50,000
now and $50,000 next year

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and so on for the next 20 years.

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So in total, it ends up being
$1 million in some sense.

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Right?

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But does it have the same value?

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Who would prefer to have
$1 million right now?

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Lots of hands.

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Who would prefer to
have the installments,

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$50,000 per year for 20 years?

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Well, a few hands.

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Can I get some reasons?

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AUDIENCE: So you don't
waste it all at once.

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BRYNMOR CHAPMAN: Oh,
that's an excellent reason.

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Supposed to be.

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Anybody else?

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A reason either way.

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Yeah?

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AUDIENCE: Inflation
would make [INAUDIBLE].

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BRYNMOR CHAPMAN: Sorry?

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AUDIENCE: Inflation will make
the installments less valuable.

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BRYNMOR CHAPMAN: Yeah.

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OK.

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So that's an argument for
getting the million dollars

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right now.

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Right?

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The $50,000 you get in 20 years,
if a gallon of milk costs $4

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today and $10 in 20 years,
that $50,000 isn't going to go

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so far.

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So at least in terms
of the actual buying

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power of the money, you'd really
prefer to have that $1 million

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right now because money now
is more valuable than money

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in the future, inflation
or, relatedly, you

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can invest this money
and it'll end up

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being more worth
more in 20 years.

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So this is exactly how
a loan works, right?

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You get a lump
sump of money now.

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And you pay it back
in installments.

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And you account for interest.

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So this is what's
known as an annuity.

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So for an annuity, we're going
to make some fairly simplified

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assumptions.

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We're going to assume
a fixed interest rate.

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Let's call it p.

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So as an example,
the Federal Reserve

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says that interest rate
right now is about 5.33%

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So let's just take that
as a working example,

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or at least that's what it was
at the beginning of the week.

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I haven't checked it today.

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And we're going to get m
dollars every year for n years.

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So in the example that we were
just looking at, m is 50k,

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n is 20 years, and we've got
this interest rate p, 5.33%.

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OK.

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So what does this mean about
the value of money over time?

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Well $1 now, if we get this
$1 now, it's going to be worth

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or it's equivalent
to getting 1 plus p

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dollars one year from now.

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Does that make
sense to everybody?

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If I take my $1 now
and I invest it,

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I'll end up with
$1.05 in a year.

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OK.

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Or in two years, it'll be 1
plus p squared or, in k years,

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it'll be 1 plus p to the k.

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Conversely, what if I get
that dollar in 10 years?

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How much is that worth
in today's money?

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Anybody?

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Hand.

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No?

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Are we still asleep?

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Too early in the morning?

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OK.

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Well, conversely, if I
get my dollar in 10 years,

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it's going to be worth 1
divided by 1 plus p to the 10th.

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Does that make
sense to everybody?

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Yes, no, kind of, thumbs up?

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A few thumbs up.

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OK.

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Good.

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I'll take it.

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OK.

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So basically, what's going on
is we're getting m dollars now,

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m dollars in one year, m
dollars in two years, OK,

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dot, dot, dot, up to n years.

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And we'd like to figure out what
the equivalent value is today.

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So this m dollars now, now
this is worth m dollars today.

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OK.

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This m dollars in one year
is going to be worth--

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whoops-- m times 1
plus p to the minus 1.

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OK.

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This m dollars in two years is
going to be m times 1 plus p

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to the minus 2, et cetera.

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And the m dollars that we get in
n years is going to be m times 1

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plus p to the minus n.

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I guess this is
n minus 1, right?

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Yeah.

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We're starting at 0 years.

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Does that make
sense to everybody?

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So what is the total value?

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The total equivalent
value in today's money?

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OK.

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We'd like this in a closed form.

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So right now we've kind of got--

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we're trying to
sum all of this up.

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Right.

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But it's not a very
nice expression.

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OK.

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We'd like a closed
form, something

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that you can put into one of
those old-fashioned calculators

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if you've ever seen
it, those things

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that you hold in your hand
and push the buttons on it?

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No.

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Oh, yeah.

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There are some old
souls in the audience.

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OK.

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But yeah.

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We don't want any ellipses
like this or sigma notation

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or anything like that.

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We just want a nice,
clean expression

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that you can put
into a calculator.

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So how can we go
about computing it?

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Any ideas?

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What if we were to replace
this 1 plus p with an x?

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Would that make it any easier?

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So we've got m plus mx
plus mx squared plus mx

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to the n minus 1.

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Are people happier
with this expression?

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Getting some nods.

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OK.

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What is it?

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Anybody remember?

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00:09:16.250 --> 00:09:17.090 align:middle line:90%
Yeah?

00:09:17.090 --> 00:09:18.506 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:09:18.506 --> 00:09:19.920 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:09:19.920 --> 00:09:21.450 align:middle line:90%
It's a geometric series.

00:09:21.450 --> 00:09:23.242 align:middle line:90%
OK.

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So this is going to
be m times 1 minus x.

00:09:31.610 --> 00:09:33.830 align:middle line:90%
Oops.

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n over 1 minus x.

00:09:36.325 --> 00:09:41.272 align:middle line:90%


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So we knew this
expression already.

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How could we check it?

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Or how did you check it?

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I believe you already have.

00:09:51.500 --> 00:09:52.910 align:middle line:90%
Yeah?

00:09:52.910 --> 00:09:55.190 align:middle line:84%
AUDIENCE: Are you sure
that's the [iNAUDIBLE]?

00:09:55.190 --> 00:09:59.157 align:middle line:90%


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BRYNMOR CHAPMAN: Oh.

00:09:59.990 --> 00:10:03.350 align:middle line:90%


00:10:03.350 --> 00:10:04.030 align:middle line:90%
Thank you.

00:10:04.030 --> 00:10:14.310 align:middle line:90%


00:10:14.310 --> 00:10:14.810 align:middle line:90%
Yeah.

00:10:14.810 --> 00:10:20.230 align:middle line:90%


00:10:20.230 --> 00:10:20.730 align:middle line:90%
Yep.

00:10:20.730 --> 00:10:21.272 align:middle line:90%
You're right.

00:10:21.272 --> 00:10:22.340 align:middle line:90%
Thank you.

00:10:22.340 --> 00:10:24.777 align:middle line:90%
So how could you prove this?

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Or how would I have
failed to prove it

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if I tried to do it just now?

00:10:28.440 --> 00:10:28.940 align:middle line:90%
Yeah?

00:10:28.940 --> 00:10:30.084 align:middle line:90%
AUDIENCE: Subtract it?

00:10:30.084 --> 00:10:31.001 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:10:31.001 --> 00:10:40.630 align:middle line:90%


00:10:40.630 --> 00:10:42.490 align:middle line:90%
OK?

00:10:42.490 --> 00:10:46.280 align:middle line:84%
So this is what we call
the guess and check method.

00:10:46.280 --> 00:10:52.510 align:middle line:84%
So if we've got a sum
like this, and we know

00:10:52.510 --> 00:10:56.680 align:middle line:84%
or we can reasonably guess
a nice closed form for it,

00:10:56.680 --> 00:10:59.620 align:middle line:84%
then we can prove
it by induction.

00:10:59.620 --> 00:11:02.090 align:middle line:90%
That's fairly straightforward.

00:11:02.090 --> 00:11:06.100 align:middle line:84%
The hard part is figuring out
what that closed form should be.

00:11:06.100 --> 00:11:09.310 align:middle line:90%


00:11:09.310 --> 00:11:12.100 align:middle line:84%
And in this case,
the inductive step

00:11:12.100 --> 00:11:15.820 align:middle line:84%
reduces to some fairly simple
algebra as you already saw,

00:11:15.820 --> 00:11:16.820 align:middle line:90%
I think in recitation.

00:11:16.820 --> 00:11:18.100 align:middle line:90%
Is that right?

00:11:18.100 --> 00:11:20.830 align:middle line:90%
Rec 02 maybe?

00:11:20.830 --> 00:11:21.430 align:middle line:90%
Yeah.

00:11:21.430 --> 00:11:22.490 align:middle line:90%
Yes.

00:11:22.490 --> 00:11:23.540 align:middle line:90%
Thumbs up from Zach.

00:11:23.540 --> 00:11:26.110 align:middle line:84%
Even if you don't
remember, Zach does.

00:11:26.110 --> 00:11:27.490 align:middle line:90%
[LAUGHS]

00:11:27.490 --> 00:11:31.480 align:middle line:90%


00:11:31.480 --> 00:11:35.200 align:middle line:84%
So how might we discover this
closed form if we didn't already

00:11:35.200 --> 00:11:36.910 align:middle line:90%
know it, though?

00:11:36.910 --> 00:11:37.590 align:middle line:90%
Any ideas?

00:11:37.590 --> 00:11:43.450 align:middle line:90%


00:11:43.450 --> 00:11:46.300 align:middle line:90%
Yeah?

00:11:46.300 --> 00:11:49.570 align:middle line:84%
AUDIENCE: Multiply the
series by [INAUDIBLE].

00:11:49.570 --> 00:11:52.600 align:middle line:90%
BRYNMOR CHAPMAN: Yeah, exactly.

00:11:52.600 --> 00:11:55.875 align:middle line:84%
So this is what we call
the perturbation method.

00:11:55.875 --> 00:12:09.070 align:middle line:90%


00:12:09.070 --> 00:12:13.690 align:middle line:84%
So the answer was if we
multiply this entire thing by x

00:12:13.690 --> 00:12:17.650 align:middle line:84%
and subtract it, then
things will cancel.

00:12:17.650 --> 00:12:23.440 align:middle line:84%
So this is one example of what
we call the perturbation method.

00:12:23.440 --> 00:12:25.090 align:middle line:90%
This is something that--

00:12:25.090 --> 00:12:27.790 align:middle line:84%
does anybody know
the story of Gauss

00:12:27.790 --> 00:12:29.420 align:middle line:84%
in the kindergarten
or first grade

00:12:29.420 --> 00:12:34.853 align:middle line:84%
when he was given a massive sum
to evaluate by his teacher and 3

00:12:34.853 --> 00:12:37.520 align:middle line:84%
seconds, he gave the teacher his
answer and the teacher is like,

00:12:37.520 --> 00:12:38.103 align:middle line:90%
what the hell?

00:12:38.103 --> 00:12:39.580 align:middle line:90%
No, go back to your seat.

00:12:39.580 --> 00:12:40.290 align:middle line:90%
OK.

00:12:40.290 --> 00:12:40.790 align:middle line:90%
Yeah.

00:12:40.790 --> 00:12:42.770 align:middle line:84%
So perturbation
method in action.

00:12:42.770 --> 00:12:47.400 align:middle line:84%
So Gauss was asked to
evaluate 1 plus 2 plus--

00:12:47.400 --> 00:12:50.620 align:middle line:90%


00:12:50.620 --> 00:12:52.100 align:middle line:90%
I think the story was 100.

00:12:52.100 --> 00:12:53.410 align:middle line:90%
Not actually sure.

00:12:53.410 --> 00:12:59.140 align:middle line:84%
And Gauss observed that if you
take this series and perturb it

00:12:59.140 --> 00:13:09.160 align:middle line:84%
a little bit, so in this case
flip it around, and then add

00:13:09.160 --> 00:13:12.200 align:middle line:84%
them together, you end up
with something very nice.

00:13:12.200 --> 00:13:12.700 align:middle line:90%
Right?

00:13:12.700 --> 00:13:25.420 align:middle line:90%


00:13:25.420 --> 00:13:30.370 align:middle line:84%
So he's got two
copies of this sum.

00:13:30.370 --> 00:13:34.050 align:middle line:84%
So two S is equal to
this thing, which means

00:13:34.050 --> 00:13:37.355 align:middle line:90%
that S should be equal to that.

00:13:37.355 --> 00:13:40.050 align:middle line:90%


00:13:40.050 --> 00:13:41.620 align:middle line:90%
So fairly straightforward.

00:13:41.620 --> 00:13:44.390 align:middle line:84%
We can do the same thing with
this geometric series here.

00:13:44.390 --> 00:13:50.220 align:middle line:90%


00:13:50.220 --> 00:13:52.840 align:middle line:84%
So for simplicity, I'm
going to drop the m.

00:13:52.840 --> 00:13:59.820 align:middle line:84%
So if instead we have s
equals 1 plus x plus x squared

00:13:59.820 --> 00:14:04.830 align:middle line:84%
plus x to the n minus 1,
and here your colleague

00:14:04.830 --> 00:14:07.170 align:middle line:84%
said that we should
multiply this by x.

00:14:07.170 --> 00:14:09.780 align:middle line:90%
So Sx equals--

00:14:09.780 --> 00:14:11.380 align:middle line:84%
I'm going to shift
everything over

00:14:11.380 --> 00:14:14.000 align:middle line:84%
so that it's a little bit
easier to see what's going on.

00:14:14.000 --> 00:14:22.420 align:middle line:90%


00:14:22.420 --> 00:14:24.300 align:middle line:84%
And now this time
instead of adding them,

00:14:24.300 --> 00:14:25.633 align:middle line:90%
we're going to want to subtract.

00:14:25.633 --> 00:14:27.840 align:middle line:90%


00:14:27.840 --> 00:14:32.670 align:middle line:84%
This 1 doesn't have
anything to subtract.

00:14:32.670 --> 00:14:36.210 align:middle line:84%
And now here we've
got plus x minus x

00:14:36.210 --> 00:14:38.050 align:middle line:90%
plus x squared minus x squared.

00:14:38.050 --> 00:14:45.580 align:middle line:84%
So everything is going to
cancel until we get to the end.

00:14:45.580 --> 00:14:49.050 align:middle line:84%
And here we've got
minus x to the n.

00:14:49.050 --> 00:14:55.200 align:middle line:84%
So now we've got S
minus xS is equal to 1

00:14:55.200 --> 00:15:01.470 align:middle line:84%
minus x to the n which
means that S is 1 minus x

00:15:01.470 --> 00:15:04.355 align:middle line:90%
to the n over 1 minus x.

00:15:04.355 --> 00:15:08.045 align:middle line:90%


00:15:08.045 --> 00:15:12.660 align:middle line:84%
So if we didn't know the
formula for a geometric series

00:15:12.660 --> 00:15:15.930 align:middle line:84%
off the top of our heads,
which I clearly didn't, we

00:15:15.930 --> 00:15:18.210 align:middle line:84%
could derive it
like this and then

00:15:18.210 --> 00:15:19.920 align:middle line:90%
we can check it by induction.

00:15:19.920 --> 00:15:22.150 align:middle line:84%
Does that make
sense to everybody?

00:15:22.150 --> 00:15:31.860 align:middle line:90%


00:15:31.860 --> 00:15:36.720 align:middle line:84%
So if we go back to our
annuity example, we had--

00:15:36.720 --> 00:15:41.010 align:middle line:90%
so m was 50k.

00:15:41.010 --> 00:15:46.050 align:middle line:90%
n is 20 years.

00:15:46.050 --> 00:15:55.614 align:middle line:84%
p was 0.0533 which means
that our x here was--

00:15:55.614 --> 00:15:57.320 align:middle line:90%
was it 1 over 1 minus p?

00:15:57.320 --> 00:16:01.200 align:middle line:90%


00:16:01.200 --> 00:16:05.750 align:middle line:90%
1 over 1 plus p.

00:16:05.750 --> 00:16:10.260 align:middle line:90%


00:16:10.260 --> 00:16:14.880 align:middle line:84%
So if we plug this in, it
turns out that the value

00:16:14.880 --> 00:16:24.852 align:middle line:84%
of our annuity is
actually about 638,000.

00:16:24.852 --> 00:16:28.963 align:middle line:84%
So it's not just less
than the $1 million

00:16:28.963 --> 00:16:29.880 align:middle line:90%
that we were promised.

00:16:29.880 --> 00:16:31.414 align:middle line:90%
It's like substantially less.

00:16:31.414 --> 00:16:31.914 align:middle line:90%
Right?

00:16:31.914 --> 00:16:39.320 align:middle line:90%


00:16:39.320 --> 00:16:41.760 align:middle line:84%
What if we took an even
more extreme example?

00:16:41.760 --> 00:16:44.940 align:middle line:84%
Like suppose instead of
$50,000 per year for 20 years,

00:16:44.940 --> 00:16:48.050 align:middle line:84%
we got $1 per year
for million years.

00:16:48.050 --> 00:16:50.420 align:middle line:84%
For simplicity, let's
just say it's forever.

00:16:50.420 --> 00:16:54.680 align:middle line:84%
So suppose we get $1 forever,
like every year forever.

00:16:54.680 --> 00:16:55.795 align:middle line:90%
How much is that worth?

00:16:55.795 --> 00:17:03.020 align:middle line:90%


00:17:03.020 --> 00:17:05.750 align:middle line:90%
Half a million, 100,000?

00:17:05.750 --> 00:17:07.434 align:middle line:90%
Yeah?

00:17:07.434 --> 00:17:08.253 align:middle line:90%
AUDIENCE: $20.

00:17:08.253 --> 00:17:09.170 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:17:09.170 --> 00:17:09.670 align:middle line:90%
About $20.

00:17:09.670 --> 00:17:12.170 align:middle line:90%


00:17:12.170 --> 00:17:15.510 align:middle line:84%
So this x to the
n just goes to 0.

00:17:15.510 --> 00:17:21.480 align:middle line:84%
Turns out that if we have
m equals 1, n is infinity.

00:17:21.480 --> 00:17:24.079 align:middle line:90%
Same p as we had before.

00:17:24.079 --> 00:17:25.609 align:middle line:90%
It's about 20.

00:17:25.609 --> 00:17:29.720 align:middle line:84%
So it might be a little
bit counterintuitive

00:17:29.720 --> 00:17:35.780 align:middle line:84%
that getting money,
like, forever, it still

00:17:35.780 --> 00:17:39.890 align:middle line:90%
has finite value, right?

00:17:39.890 --> 00:17:43.830 align:middle line:84%
But yeah, I don't know,
maybe if you think about it,

00:17:43.830 --> 00:17:48.290 align:middle line:90%
it kind of makes sense.

00:17:48.290 --> 00:17:51.800 align:middle line:84%
Like that money that
you're getting like n years

00:17:51.800 --> 00:17:54.155 align:middle line:90%
from now, who cares?

00:17:54.155 --> 00:17:56.280 align:middle line:84%
You're not even going to
be alive to use it, right?

00:17:56.280 --> 00:17:58.370 align:middle line:84%
So maybe it also
kind of makes sense

00:17:58.370 --> 00:18:01.465 align:middle line:90%
that it's not worth very much.

00:18:01.465 --> 00:18:04.100 align:middle line:90%


00:18:04.100 --> 00:18:07.430 align:middle line:84%
And in the real world,
there are actually

00:18:07.430 --> 00:18:09.540 align:middle line:90%
perpetual annuities like this.

00:18:09.540 --> 00:18:11.960 align:middle line:90%
They do exist.

00:18:11.960 --> 00:18:15.950 align:middle line:84%
I believe there is a surviving
one issued by a Dutch water

00:18:15.950 --> 00:18:20.180 align:middle line:90%
company in the 17th century.

00:18:20.180 --> 00:18:23.850 align:middle line:84%
I think they issued five
that are still around today.

00:18:23.850 --> 00:18:29.180 align:middle line:84%
And one was acquired
by Yale in, let's see,

00:18:29.180 --> 00:18:33.390 align:middle line:84%
maybe 30 odd years ago,
I think, for $24,000.

00:18:33.390 --> 00:18:38.780 align:middle line:84%
And it gets them about $12
annually so only worth it

00:18:38.780 --> 00:18:40.320 align:middle line:90%
for the historical value.

00:18:40.320 --> 00:18:42.625 align:middle line:90%
The money is a complete wash.

00:18:42.625 --> 00:18:49.331 align:middle line:90%


00:18:49.331 --> 00:18:53.660 align:middle line:84%
So are people reasonably happy
with the perturbation method?

00:18:53.660 --> 00:18:54.170 align:middle line:90%
Yeah?

00:18:54.170 --> 00:18:55.980 align:middle line:90%
Some thumbs up?

00:18:55.980 --> 00:18:56.480 align:middle line:90%
OK.

00:18:56.480 --> 00:18:59.990 align:middle line:84%
So Let's move on to a
slightly different method

00:18:59.990 --> 00:19:02.470 align:middle line:90%
for evaluating other sums.

00:19:02.470 --> 00:19:05.060 align:middle line:90%


00:19:05.060 --> 00:19:08.812 align:middle line:84%
So this is what's called
the ansatz method.

00:19:08.812 --> 00:19:10.680 align:middle line:90%
Am I spelling this correctly?

00:19:10.680 --> 00:19:11.200 align:middle line:90%
I hope so.

00:19:11.200 --> 00:19:17.630 align:middle line:90%


00:19:17.630 --> 00:19:19.790 align:middle line:84%
Or if you don't
like German, I think

00:19:19.790 --> 00:19:22.845 align:middle line:84%
it is, you could also just call
it the educated guess method.

00:19:22.845 --> 00:19:25.670 align:middle line:90%


00:19:25.670 --> 00:19:29.920 align:middle line:84%
So suppose we have
the following sum.

00:19:29.920 --> 00:19:38.650 align:middle line:84%
Sum from k equals 1
to n of k squared.

00:19:38.650 --> 00:19:40.930 align:middle line:90%
OK.

00:19:40.930 --> 00:19:44.240 align:middle line:84%
So first, does anybody
already know the answer?

00:19:44.240 --> 00:19:45.900 align:middle line:90%
What does the sum evaluate to?

00:19:45.900 --> 00:19:49.190 align:middle line:90%


00:19:49.190 --> 00:19:49.690 align:middle line:90%
Oh.

00:19:49.690 --> 00:19:50.120 align:middle line:90%
Nobody.

00:19:50.120 --> 00:19:50.620 align:middle line:90%
OK.

00:19:50.620 --> 00:19:54.250 align:middle line:84%
In that case, next question
is open to everyone.

00:19:54.250 --> 00:19:59.350 align:middle line:84%
Does anybody have any idea
what vaguely the solution

00:19:59.350 --> 00:20:00.120 align:middle line:90%
might look like?

00:20:00.120 --> 00:20:04.150 align:middle line:90%


00:20:04.150 --> 00:20:04.970 align:middle line:90%
Yeah?

00:20:04.970 --> 00:20:07.523 align:middle line:84%
AUDIENCE: It should
be some sort of cubic.

00:20:07.523 --> 00:20:08.440 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:20:08.440 --> 00:20:11.770 align:middle line:90%
It should be some sort of cubic.

00:20:11.770 --> 00:20:13.820 align:middle line:84%
We're summing up a
bunch of squares--

00:20:13.820 --> 00:20:16.480 align:middle line:90%
well, n squares.

00:20:16.480 --> 00:20:19.310 align:middle line:84%
A bunch of them are
about n squared.

00:20:19.310 --> 00:20:22.780 align:middle line:84%
And so we should get something
that's about n cubed.

00:20:22.780 --> 00:20:35.221 align:middle line:84%
So guess S is
approximately n cubed.

00:20:35.221 --> 00:20:36.730 align:middle line:84%
Now, it won't do
us too much good

00:20:36.730 --> 00:20:39.980 align:middle line:84%
to put that into our
guess and check method.

00:20:39.980 --> 00:20:41.093 align:middle line:90%
Yeah?

00:20:41.093 --> 00:20:44.051 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:20:44.051 --> 00:20:47.670 align:middle line:90%


00:20:47.670 --> 00:20:49.910 align:middle line:84%
BRYNMOR CHAPMAN:
Intuition, basically.

00:20:49.910 --> 00:20:52.960 align:middle line:90%


00:20:52.960 --> 00:20:58.960 align:middle line:84%
So one way you could think about
it is so half of these terms

00:20:58.960 --> 00:21:02.750 align:middle line:84%
are going to be larger
than n over 2 squared.

00:21:02.750 --> 00:21:07.060 align:middle line:84%
So that's one
fourth of n squared.

00:21:07.060 --> 00:21:08.902 align:middle line:90%
You've got n over 2 of those.

00:21:08.902 --> 00:21:10.360 align:middle line:84%
So you should have
something that's

00:21:10.360 --> 00:21:13.195 align:middle line:90%
at least one eighth of n cubed.

00:21:13.195 --> 00:21:14.070 align:middle line:90%
Does that make sense?

00:21:14.070 --> 00:21:17.860 align:middle line:90%


00:21:17.860 --> 00:21:19.520 align:middle line:84%
And then for an
upper bound, you've

00:21:19.520 --> 00:21:22.200 align:middle line:84%
got n terms which are
all at most n squared.

00:21:22.200 --> 00:21:24.500 align:middle line:84%
And so it's going to be
something between one eighth n

00:21:24.500 --> 00:21:27.590 align:middle line:90%
cubed and n cubed itself.

00:21:27.590 --> 00:21:29.900 align:middle line:90%
Does that make sense?

00:21:29.900 --> 00:21:31.850 align:middle line:84%
We're hinting at
something else that we'll

00:21:31.850 --> 00:21:34.430 align:middle line:90%
do a little bit later.

00:21:34.430 --> 00:21:39.800 align:middle line:84%
If you squint really hard, a sum
kind of looks like an integral.

00:21:39.800 --> 00:21:41.810 align:middle line:84%
So if you integrate
that, you're going

00:21:41.810 --> 00:21:43.820 align:middle line:84%
to get something that
looks like n cubed.

00:21:43.820 --> 00:21:44.900 align:middle line:90%
OK.

00:21:44.900 --> 00:21:46.370 align:middle line:90%
Another question?

00:21:46.370 --> 00:21:48.800 align:middle line:84%
AUDIENCE: Oh, my question was
just if you could write down

00:21:48.800 --> 00:21:51.788 align:middle line:84%
[INAUDIBLE] so that it's easier
to visualize, like some of them

00:21:51.788 --> 00:21:54.080 align:middle line:84%
are greater than n [INAUDIBLE]
squared and some of them

00:21:54.080 --> 00:21:54.800 align:middle line:90%
are less.

00:21:54.800 --> 00:21:55.940 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:21:55.940 --> 00:21:57.510 align:middle line:90%
We could do that if you like.

00:21:57.510 --> 00:22:03.680 align:middle line:84%
So we've got 1 plus 2
squared plus 3 squared

00:22:03.680 --> 00:22:14.216 align:middle line:84%
plus n over 2 squared plus
all the way up to n squared.

00:22:14.216 --> 00:22:20.610 align:middle line:84%
So these terms, plus or minus
1 term if it's even or odd,

00:22:20.610 --> 00:22:27.900 align:middle line:84%
so these are all greater than
or equal to n over 2 squared.

00:22:27.900 --> 00:22:31.230 align:middle line:84%
And we've got n over 2 of them
or n over 2 plus 1, or whatever.

00:22:31.230 --> 00:22:36.330 align:middle line:84%
So the sum is going
to be at least n

00:22:36.330 --> 00:22:44.850 align:middle line:84%
over 2 squared times n over
2 is one eighth n cubed.

00:22:44.850 --> 00:22:46.260 align:middle line:90%
OK.

00:22:46.260 --> 00:22:46.930 align:middle line:90%
Yeah?

00:22:46.930 --> 00:22:47.920 align:middle line:90%
Question.

00:22:47.920 --> 00:22:51.180 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:22:51.180 --> 00:22:57.937 align:middle line:90%


00:22:57.937 --> 00:22:58.770 align:middle line:90%
BRYNMOR CHAPMAN: Ah.

00:22:58.770 --> 00:22:59.270 align:middle line:90%
OK.

00:22:59.270 --> 00:23:03.870 align:middle line:84%
So we're getting a
more refined guess.

00:23:03.870 --> 00:23:07.860 align:middle line:84%
So actually, I would argue that
n cubed is already good enough

00:23:07.860 --> 00:23:11.580 align:middle line:90%
for what we're doing anyway.

00:23:11.580 --> 00:23:13.210 align:middle line:90%
And here's why.

00:23:13.210 --> 00:23:17.000 align:middle line:84%
So as we said, it's
not very precise.

00:23:17.000 --> 00:23:17.500 align:middle line:90%
Right?

00:23:17.500 --> 00:23:20.820 align:middle line:84%
We don't know, like you said,
the leading coefficient should

00:23:20.820 --> 00:23:23.430 align:middle line:90%
probably be 1/3.

00:23:23.430 --> 00:23:26.880 align:middle line:84%
But we're just going
to start from guessing

00:23:26.880 --> 00:23:28.980 align:middle line:90%
that it's a cubic of some sort.

00:23:28.980 --> 00:23:31.980 align:middle line:84%
We don't know anything
about the coefficients,

00:23:31.980 --> 00:23:34.205 align:middle line:84%
but it seems like
a reasonable guess.

00:23:34.205 --> 00:23:37.920 align:middle line:90%


00:23:37.920 --> 00:23:45.120 align:middle line:84%
So we're going to say that S
is equal to a times n cubed

00:23:45.120 --> 00:23:51.016 align:middle line:90%
plus bn squared plus cn plus d.

00:23:51.016 --> 00:23:53.555 align:middle line:90%


00:23:53.555 --> 00:23:55.180 align:middle line:84%
We're just going to
take that on faith,

00:23:55.180 --> 00:23:56.975 align:middle line:84%
assume it, and see
where it leads us.

00:23:56.975 --> 00:24:00.360 align:middle line:90%


00:24:00.360 --> 00:24:04.770 align:middle line:84%
So if we assume that,
what can we deduce?

00:24:04.770 --> 00:24:05.525 align:middle line:90%
Any ideas?

00:24:05.525 --> 00:24:10.410 align:middle line:90%


00:24:10.410 --> 00:24:12.000 align:middle line:84%
How might we go
about figuring out

00:24:12.000 --> 00:24:13.535 align:middle line:90%
what a, b, c, and d should be?

00:24:13.535 --> 00:24:25.200 align:middle line:90%


00:24:25.200 --> 00:24:29.250 align:middle line:84%
Well, what if we
look at, small n?

00:24:29.250 --> 00:24:31.640 align:middle line:90%
So if we have, say, n equals 0?

00:24:31.640 --> 00:24:34.350 align:middle line:90%


00:24:34.350 --> 00:24:36.140 align:middle line:84%
What happens if we
put in n equals 0?

00:24:36.140 --> 00:24:39.406 align:middle line:90%


00:24:39.406 --> 00:24:41.811 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:24:41.811 --> 00:24:43.920 align:middle line:90%
BRYNMOR CHAPMAN: Exactly.

00:24:43.920 --> 00:24:44.850 align:middle line:90%
OK.

00:24:44.850 --> 00:24:54.030 align:middle line:84%
So then we have a times 0 cubed
plus b times 0 squared plus c

00:24:54.030 --> 00:24:58.530 align:middle line:90%
times 0 plus d equals what?

00:24:58.530 --> 00:25:00.330 align:middle line:84%
What is the value
of our sum at 0?

00:25:00.330 --> 00:25:01.108 align:middle line:90%
AUDIENCE: 0.

00:25:01.108 --> 00:25:01.900 align:middle line:90%
BRYNMOR CHAPMAN: 0.

00:25:01.900 --> 00:25:02.100 align:middle line:90%
Yeah.

00:25:02.100 --> 00:25:03.575 align:middle line:90%
We've just got the empty sum.

00:25:03.575 --> 00:25:09.870 align:middle line:90%


00:25:09.870 --> 00:25:10.910 align:middle line:90%
What else can we do?

00:25:10.910 --> 00:25:16.970 align:middle line:90%


00:25:16.970 --> 00:25:18.500 align:middle line:84%
AUDIENCE: You plug
in n equals 1.

00:25:18.500 --> 00:25:19.417 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:25:19.417 --> 00:25:19.920 align:middle line:90%
n equals 1.

00:25:19.920 --> 00:25:22.910 align:middle line:84%
That seems like
another decent choice.

00:25:22.910 --> 00:25:25.670 align:middle line:84%
And so this time, we'll
end up with a plus

00:25:25.670 --> 00:25:31.340 align:middle line:90%
b plus c plus d equals what?

00:25:31.340 --> 00:25:34.188 align:middle line:84%
What's the value
of our sum there?

00:25:34.188 --> 00:25:35.000 align:middle line:90%
AUDIENCE: 1.

00:25:35.000 --> 00:25:35.792 align:middle line:90%
BRYNMOR CHAPMAN: 1.

00:25:35.792 --> 00:25:38.210 align:middle line:90%


00:25:38.210 --> 00:25:48.650 align:middle line:84%
And if we continue like this,
we get 8a plus 4b plus 2C plus d

00:25:48.650 --> 00:25:53.930 align:middle line:90%
equals 5, so 1 plus 4.

00:25:53.930 --> 00:25:54.868 align:middle line:90%
Question.

00:25:54.868 --> 00:25:57.307 align:middle line:84%
AUDIENCE: Do we have the
values of a, b, c, and d?

00:25:57.307 --> 00:25:58.140 align:middle line:90%
BRYNMOR CHAPMAN: No.

00:25:58.140 --> 00:25:59.670 align:middle line:84%
We're trying to
figure those out.

00:25:59.670 --> 00:26:04.580 align:middle line:84%
So we're just taking it on
faith that S has this form.

00:26:04.580 --> 00:26:07.922 align:middle line:84%
AUDIENCE: But if n equals
1 then we solve one.

00:26:07.922 --> 00:26:09.380 align:middle line:84%
BRYNMOR CHAPMAN:
So we already know

00:26:09.380 --> 00:26:12.620 align:middle line:84%
that because S was defined
as the sum of squares.

00:26:12.620 --> 00:26:16.740 align:middle line:84%
So if we sum up all of the
squares up to n equals 1,

00:26:16.740 --> 00:26:17.760 align:middle line:90%
we get 1.

00:26:17.760 --> 00:26:21.435 align:middle line:84%
If we sum them up to n
equals 2, we get 5, cetera.

00:26:21.435 --> 00:26:24.626 align:middle line:90%


00:26:24.626 --> 00:26:25.400 align:middle line:90%
Is this enough?

00:26:25.400 --> 00:26:31.386 align:middle line:90%


00:26:31.386 --> 00:26:32.386 align:middle line:90%
AUDIENCE: Need one more.

00:26:32.386 --> 00:26:33.303 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:26:33.303 --> 00:26:34.050 align:middle line:90%
We need one more.

00:26:34.050 --> 00:26:37.280 align:middle line:90%
So let's put in n equals 3.

00:26:37.280 --> 00:26:48.530 align:middle line:84%
Here we've got 27a plus 9b
plus 3c plus d equals 14.

00:26:48.530 --> 00:26:51.200 align:middle line:90%
Can I arithmetic at least?

00:26:51.200 --> 00:26:52.640 align:middle line:90%
I think I can arithmetic.

00:26:52.640 --> 00:26:54.120 align:middle line:90%
1 plus 4 plus 9.

00:26:54.120 --> 00:26:55.590 align:middle line:90%
That sounds like 14.

00:26:55.590 --> 00:26:56.090 align:middle line:90%
OK.

00:26:56.090 --> 00:27:01.700 align:middle line:84%
So now we've got a system
of four equations and four

00:27:01.700 --> 00:27:02.820 align:middle line:90%
variables.

00:27:02.820 --> 00:27:05.600 align:middle line:84%
So we should be
able to solve it.

00:27:05.600 --> 00:27:07.688 align:middle line:90%
OK.

00:27:07.688 --> 00:27:09.730 align:middle line:84%
Has anybody figured out
what the solution is yet?

00:27:09.730 --> 00:27:12.500 align:middle line:90%


00:27:12.500 --> 00:27:13.650 align:middle line:90%
Well, d equals 0.

00:27:13.650 --> 00:27:16.250 align:middle line:90%
That's an easy one.

00:27:16.250 --> 00:27:23.640 align:middle line:84%
I think it turns out to be
a equals 1/3, b equals 1/2,

00:27:23.640 --> 00:27:26.510 align:middle line:90%
c equals 1/6.

00:27:26.510 --> 00:27:27.235 align:middle line:90%
Is that right?

00:27:27.235 --> 00:27:30.350 align:middle line:90%


00:27:30.350 --> 00:27:34.180 align:middle line:84%
And yeah, d equals 0 because
we've got a bunch of zeros here.

00:27:34.180 --> 00:27:37.070 align:middle line:90%


00:27:37.070 --> 00:27:38.774 align:middle line:90%
OK.

00:27:38.774 --> 00:27:41.080 align:middle line:90%
So are we done?

00:27:41.080 --> 00:27:42.205 align:middle line:90%
Have we found our solution?

00:27:42.205 --> 00:27:48.800 align:middle line:90%


00:27:48.800 --> 00:27:49.460 align:middle line:90%
Yeah?

00:27:49.460 --> 00:27:50.923 align:middle line:84%
AUDIENCE: Got to
prove the values.

00:27:50.923 --> 00:27:51.840 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:27:51.840 --> 00:27:56.100 align:middle line:84%
So we've maybe found our
solution but we don't know.

00:27:56.100 --> 00:28:00.000 align:middle line:84%
We just pulled this out
of a hat and assumed it.

00:28:00.000 --> 00:28:03.260 align:middle line:84%
So we should actually
prove that this is correct.

00:28:03.260 --> 00:28:13.570 align:middle line:84%
So now we're going to take S
equals 1/3 n cubed plus 1/2 n

00:28:13.570 --> 00:28:18.880 align:middle line:84%
squared plus 1/6 n and use
that as our guess and go back

00:28:18.880 --> 00:28:21.710 align:middle line:84%
to the guess and check method
and prove this by induction.

00:28:21.710 --> 00:28:26.080 align:middle line:90%


00:28:26.080 --> 00:28:28.600 align:middle line:84%
We're actually going to
want strong induction.

00:28:28.600 --> 00:28:30.080 align:middle line:90%
These are our base cases.

00:28:30.080 --> 00:28:31.840 align:middle line:84%
We've already proven
that, essentially.

00:28:31.840 --> 00:28:35.320 align:middle line:84%
That's what we used to
derive a, b, c, and d.

00:28:35.320 --> 00:28:38.500 align:middle line:84%
And our inductive step is just
going to be a bunch of algebra.

00:28:38.500 --> 00:28:40.580 align:middle line:84%
So I'm not going to go
into that right now.

00:28:40.580 --> 00:28:46.600 align:middle line:84%
But yeah, if you're interested,
feel free to prove it.

00:28:46.600 --> 00:28:49.210 align:middle line:90%
OK.

00:28:49.210 --> 00:28:49.790 align:middle line:90%
Yeah.

00:28:49.790 --> 00:28:52.600 align:middle line:84%
And if it works,
we'll have a proof

00:28:52.600 --> 00:28:55.370 align:middle line:90%
that our formula was correct.

00:28:55.370 --> 00:28:58.750 align:middle line:84%
And if it doesn't, we go
back to the drawing board.

00:28:58.750 --> 00:29:00.890 align:middle line:84%
We know that this
form was wrong.

00:29:00.890 --> 00:29:04.210 align:middle line:84%
And so maybe we try and
figure out a different form

00:29:04.210 --> 00:29:07.420 align:middle line:90%
that our answer might take.

00:29:07.420 --> 00:29:09.550 align:middle line:90%
Does that make sense?

00:29:09.550 --> 00:29:10.800 align:middle line:90%
Are people happy with that?

00:29:10.800 --> 00:29:16.330 align:middle line:90%


00:29:16.330 --> 00:29:17.425 align:middle line:90%
Any questions?

00:29:17.425 --> 00:29:19.050 align:middle line:84%
Maybe I should phrase
it the other way.

00:29:19.050 --> 00:29:25.090 align:middle line:90%


00:29:25.090 --> 00:29:26.530 align:middle line:90%
AUDIENCE: What's your name?

00:29:26.530 --> 00:29:27.363 align:middle line:90%
BRYNMOR CHAPMAN: Oh.

00:29:27.363 --> 00:29:30.560 align:middle line:84%
I'm Brynmor, like the
Pennsylvania College.

00:29:30.560 --> 00:29:32.060 align:middle line:90%
Same word spelled differently.

00:29:32.060 --> 00:29:35.980 align:middle line:90%


00:29:35.980 --> 00:29:38.450 align:middle line:90%
I saw another hand over here.

00:29:38.450 --> 00:29:41.898 align:middle line:90%
Was that a question or a--

00:29:41.898 --> 00:29:44.920 align:middle line:84%
AUDIENCE: Your 1/3, 1/2, 1/6,
that's just like if you do

00:29:44.920 --> 00:29:45.923 align:middle line:90%
the algebra pretty much?

00:29:45.923 --> 00:29:46.840 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:29:46.840 --> 00:29:51.040 align:middle line:84%
So that's if you solve
this system of equations.

00:29:51.040 --> 00:29:52.400 align:middle line:90%
That's what comes out.

00:29:52.400 --> 00:29:54.610 align:middle line:84%
You could do
Gaussian elimination,

00:29:54.610 --> 00:29:57.057 align:middle line:84%
or invert the
matrix, or whatever.

00:29:57.057 --> 00:29:58.640 align:middle line:84%
AUDIENCE: But if you
didn't know that,

00:29:58.640 --> 00:30:01.407 align:middle line:84%
did you just know that because
it was on your notes or did you

00:30:01.407 --> 00:30:02.990 align:middle line:84%
have a way to figure
it out instantly,

00:30:02.990 --> 00:30:04.000 align:middle line:90%
like the way you just wrote it?

00:30:04.000 --> 00:30:05.000 align:middle line:90%
BRYNMOR CHAPMAN: Oh, no.

00:30:05.000 --> 00:30:06.957 align:middle line:90%
I'm not that good.

00:30:06.957 --> 00:30:07.790 align:middle line:90%
AUDIENCE: All right.

00:30:07.790 --> 00:30:08.610 align:middle line:90%
I'm just checking.

00:30:08.610 --> 00:30:10.360 align:middle line:84%
BRYNMOR CHAPMAN: Oh,
I mean, no, I totally

00:30:10.360 --> 00:30:12.250 align:middle line:90%
don't have it on my notes.

00:30:12.250 --> 00:30:13.420 align:middle line:90%
Yeah.

00:30:13.420 --> 00:30:14.000 align:middle line:90%
Yeah.

00:30:14.000 --> 00:30:14.505 align:middle line:90%
Question.

00:30:14.505 --> 00:30:15.880 align:middle line:84%
AUDIENCE: Is there
any particular

00:30:15.880 --> 00:30:19.342 align:middle line:84%
reason you chose this form
as your educated guess?

00:30:19.342 --> 00:30:22.043 align:middle line:90%
[INAUDIBLE]

00:30:22.043 --> 00:30:22.960 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:30:22.960 --> 00:30:28.180 align:middle line:84%
So as we were discussing
before we dove into it,

00:30:28.180 --> 00:30:30.040 align:middle line:84%
we think that it's
probably going

00:30:30.040 --> 00:30:33.760 align:middle line:90%
to look something like n cubed.

00:30:33.760 --> 00:30:36.830 align:middle line:84%
We don't know exactly
how close it is to that,

00:30:36.830 --> 00:30:39.100 align:middle line:84%
but it's kind of
reasonable to assume

00:30:39.100 --> 00:30:42.970 align:middle line:84%
that it's a polynomial
like a cubic polynomial.

00:30:42.970 --> 00:30:48.943 align:middle line:84%
So maybe we could have started
with something like this

00:30:48.943 --> 00:30:49.443 align:middle line:90%
instead.

00:30:49.443 --> 00:30:53.140 align:middle line:90%


00:30:53.140 --> 00:30:55.630 align:middle line:84%
Like maybe it's some
constant times n

00:30:55.630 --> 00:30:58.120 align:middle line:90%
cubed plus quadratic term.

00:30:58.120 --> 00:31:03.300 align:middle line:84%
And then the ansatz
method would have failed.

00:31:03.300 --> 00:31:05.877 align:middle line:84%
We would have ended up with
suspicious looking guess.

00:31:05.877 --> 00:31:07.710 align:middle line:84%
We would have tried to
prove it by induction

00:31:07.710 --> 00:31:10.560 align:middle line:90%
and it wouldn't have worked.

00:31:10.560 --> 00:31:19.130 align:middle line:84%
But yeah, as it turns out,
this is a reasonable guess.

00:31:19.130 --> 00:31:19.630 align:middle line:90%
Yeah?

00:31:19.630 --> 00:31:21.990 align:middle line:84%
AUDIENCE: If we don't
know if it's a bad guess,

00:31:21.990 --> 00:31:25.380 align:middle line:84%
and we try to prove
it by induction,

00:31:25.380 --> 00:31:27.040 align:middle line:84%
and we don't see
how to prove it,

00:31:27.040 --> 00:31:28.720 align:middle line:84%
how do we know that
means it's wrong?

00:31:28.720 --> 00:31:32.820 align:middle line:84%
What if we just didn't figure
out the right way to prove it?

00:31:32.820 --> 00:31:35.700 align:middle line:84%
BRYNMOR CHAPMAN: So the question
is if we have a bad guess,

00:31:35.700 --> 00:31:37.442 align:middle line:84%
and we can't prove
it by induction,

00:31:37.442 --> 00:31:39.150 align:middle line:84%
how do we know that
the guess is actually

00:31:39.150 --> 00:31:41.760 align:middle line:84%
wrong and not that
we're doing something

00:31:41.760 --> 00:31:44.100 align:middle line:90%
suspicious with the proof?

00:31:44.100 --> 00:31:46.710 align:middle line:90%
So that's a good question.

00:31:46.710 --> 00:31:50.790 align:middle line:84%
So maybe I should digress
here a little bit.

00:31:50.790 --> 00:31:54.930 align:middle line:84%
If you're trying to figure
out a proof or a disproof

00:31:54.930 --> 00:31:57.510 align:middle line:84%
for a statement that you're not
quite sure whether it's true

00:31:57.510 --> 00:32:01.050 align:middle line:84%
or not, often the thing
that you'll want to do

00:32:01.050 --> 00:32:03.310 align:middle line:90%
is attempt to prove it.

00:32:03.310 --> 00:32:06.312 align:middle line:84%
see where your proof
seems to be breaking, like

00:32:06.312 --> 00:32:07.770 align:middle line:84%
if you find a block,
like something

00:32:07.770 --> 00:32:10.170 align:middle line:84%
that you can't figure
out, and then try and use

00:32:10.170 --> 00:32:12.900 align:middle line:90%
that to generate a disproof.

00:32:12.900 --> 00:32:15.250 align:middle line:84%
And then you can
iterate on that.

00:32:15.250 --> 00:32:19.530 align:middle line:84%
And if your disproof
gets stuck somewhere,

00:32:19.530 --> 00:32:22.500 align:middle line:84%
maybe try and use that
block to try and come up

00:32:22.500 --> 00:32:23.850 align:middle line:90%
with a different proof.

00:32:23.850 --> 00:32:25.746 align:middle line:90%
OK?

00:32:25.746 --> 00:32:29.250 align:middle line:84%
And eventually,
hopefully, you'll

00:32:29.250 --> 00:32:31.710 align:middle line:84%
be able to come up
with one or the other.

00:32:31.710 --> 00:32:40.170 align:middle line:84%
So in this case, there's
a fairly clear path

00:32:40.170 --> 00:32:41.850 align:middle line:90%
towards a disproof.

00:32:41.850 --> 00:32:43.600 align:middle line:90%
Put in more numbers.

00:32:43.600 --> 00:32:46.310 align:middle line:90%
OK.

00:32:46.310 --> 00:32:49.280 align:middle line:90%
So we could try n equals 4.

00:32:49.280 --> 00:32:53.130 align:middle line:90%


00:32:53.130 --> 00:33:02.370 align:middle line:84%
Then we'd have 64a plus 16b
plus 4c plus d should be equal

00:33:02.370 --> 00:33:03.830 align:middle line:90%
to, what is it, 30?

00:33:03.830 --> 00:33:06.396 align:middle line:90%


00:33:06.396 --> 00:33:08.370 align:middle line:90%
So that's a decent sanity check.

00:33:08.370 --> 00:33:09.220 align:middle line:90%
Right?

00:33:09.220 --> 00:33:12.690 align:middle line:84%
Like if that doesn't work,
then we know that we've

00:33:12.690 --> 00:33:15.360 align:middle line:90%
screwed something up.

00:33:15.360 --> 00:33:16.780 align:middle line:84%
Does that make
sense to everybody?

00:33:16.780 --> 00:33:17.280 align:middle line:90%
Yeah.

00:33:17.280 --> 00:33:18.198 align:middle line:90%
Question?

00:33:18.198 --> 00:33:25.650 align:middle line:84%
AUDIENCE: [INAUDIBLE] How
did you decide that those

00:33:25.650 --> 00:33:26.860 align:middle line:90%
would be the base cases?

00:33:26.860 --> 00:33:28.920 align:middle line:90%
Is it just for simplicity sake?

00:33:28.920 --> 00:33:31.700 align:middle line:84%
BRYNMOR CHAPMAN: So that's
because we have four variables

00:33:31.700 --> 00:33:32.200 align:middle line:90%
here.

00:33:32.200 --> 00:33:33.970 align:middle line:90%
We've got a, b, c, and d.

00:33:33.970 --> 00:33:38.156 align:middle line:84%
So we needed four equations,
like four constraints.

00:33:38.156 --> 00:33:41.700 align:middle line:90%


00:33:41.700 --> 00:33:42.330 align:middle line:90%
Yeah.

00:33:42.330 --> 00:33:45.210 align:middle line:84%
Like we could equally well
have chosen like n equals 1,

00:33:45.210 --> 00:33:48.240 align:middle line:84%
n equals 2, n equals
5, n equals 100.

00:33:48.240 --> 00:33:50.110 align:middle line:84%
It would have given
us the correct answer.

00:33:50.110 --> 00:33:56.270 align:middle line:84%
It just would have taken
more complicated computation.

00:33:56.270 --> 00:33:56.779 align:middle line:90%
Yeah.

00:33:56.779 --> 00:33:57.446 align:middle line:90%
AUDIENCE: Sorry.

00:33:57.446 --> 00:34:01.323 align:middle line:84%
Will there ever be an n over
2 multiplier that works out

00:34:01.323 --> 00:34:06.020 align:middle line:90%
to be n over 2 [INAUDIBLE]?

00:34:06.020 --> 00:34:07.700 align:middle line:90%
BRYNMOR CHAPMAN: Oh, here.

00:34:07.700 --> 00:34:09.069 align:middle line:90%
Here you mean?

00:34:09.069 --> 00:34:09.949 align:middle line:90%
AUDIENCE: Yeah.

00:34:09.949 --> 00:34:11.967 align:middle line:84%
Or where the next
n over 2 would be.

00:34:11.967 --> 00:34:12.800 align:middle line:90%
BRYNMOR CHAPMAN: Oh.

00:34:12.800 --> 00:34:13.300 align:middle line:90%
OK.

00:34:13.300 --> 00:34:16.070 align:middle line:90%
So the squared term is--

00:34:16.070 --> 00:34:19.610 align:middle line:84%
right, because each of these
terms here is at least n over 2

00:34:19.610 --> 00:34:21.080 align:middle line:90%
squared.

00:34:21.080 --> 00:34:23.880 align:middle line:84%
The last term is because
there are n over 2 of them.

00:34:23.880 --> 00:34:27.080 align:middle line:84%
And we're trying to
evaluate the sum.

00:34:27.080 --> 00:34:29.270 align:middle line:84%
So we're summing up n
over 2 things that are all

00:34:29.270 --> 00:34:30.505 align:middle line:90%
at least n over 2 squared.

00:34:30.505 --> 00:34:34.040 align:middle line:90%


00:34:34.040 --> 00:34:36.600 align:middle line:84%
AUDIENCE: What about these 1
plus 2 squared plus 3 squared

00:34:36.600 --> 00:34:37.423 align:middle line:90%
[INAUDIBLE]?

00:34:37.423 --> 00:34:39.090 align:middle line:84%
BRYNMOR CHAPMAN:
They're are at least 0.

00:34:39.090 --> 00:34:40.020 align:middle line:90%
We don't care.

00:34:40.020 --> 00:34:41.480 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:34:41.480 --> 00:34:42.397 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:34:42.397 --> 00:34:48.020 align:middle line:90%


00:34:48.020 --> 00:34:53.150 align:middle line:84%
OK, are people reasonably
happy with this?

00:34:53.150 --> 00:34:54.710 align:middle line:90%
Yeah, OK.

00:34:54.710 --> 00:34:58.226 align:middle line:84%
So let's move on to
a third technique.

00:34:58.226 --> 00:35:14.360 align:middle line:90%


00:35:14.360 --> 00:35:20.790 align:middle line:84%
So sometimes, we're going to
end up with sums of sums--

00:35:20.790 --> 00:35:24.290 align:middle line:84%
nested summations which
we call double sums.

00:35:24.290 --> 00:35:28.770 align:middle line:84%
So for instance, what
if we had the following?

00:35:28.770 --> 00:35:39.140 align:middle line:84%
So I equals 1 to n of the sum
from j equals 1 to i of j.

00:35:39.140 --> 00:35:44.420 align:middle line:90%
So now, before we had--

00:35:44.420 --> 00:35:48.830 align:middle line:84%
the thing inside our sum was
this nice simple expression

00:35:48.830 --> 00:35:50.930 align:middle line:90%
k squared.

00:35:50.930 --> 00:35:55.550 align:middle line:84%
Now our summand is
itself a summation.

00:35:55.550 --> 00:35:56.700 align:middle line:90%
What can we do about that?

00:35:56.700 --> 00:35:58.325 align:middle line:84%
How would we evaluate
things like this?

00:35:58.325 --> 00:36:02.982 align:middle line:90%


00:36:02.982 --> 00:36:06.980 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:36:06.980 --> 00:36:08.840 align:middle line:84%
BRYNMOR CHAPMAN:
Yeah, so the answer

00:36:08.840 --> 00:36:13.190 align:middle line:84%
was to evaluate the inner sum
first, figure out a closed

00:36:13.190 --> 00:36:16.310 align:middle line:84%
form as a function
of i, and then we

00:36:16.310 --> 00:36:17.990 align:middle line:90%
can evaluate the outer sum.

00:36:17.990 --> 00:36:23.245 align:middle line:84%
So in this case, what
do we end up with?

00:36:23.245 --> 00:36:25.120 align:middle line:84%
What happens when we
evaluate this inner sum?

00:36:25.120 --> 00:36:32.060 align:middle line:90%


00:36:32.060 --> 00:36:34.358 align:middle line:84%
I claim that this is
something that we already

00:36:34.358 --> 00:36:36.400 align:middle line:84%
know how to do, something
that we've seen before.

00:36:36.400 --> 00:36:39.770 align:middle line:90%


00:36:39.770 --> 00:36:41.240 align:middle line:90%
Yeah?

00:36:41.240 --> 00:36:44.870 align:middle line:84%
AUDIENCE: i minus
i plus 1 over n?

00:36:44.870 --> 00:36:46.880 align:middle line:90%
BRYNMOR CHAPMAN: Yeah, exactly.

00:36:46.880 --> 00:36:53.140 align:middle line:84%
So this is the sum from i
equals 1 to n of i times i

00:36:53.140 --> 00:36:57.130 align:middle line:90%
plus 1, all divided by 2.

00:36:57.130 --> 00:37:02.450 align:middle line:84%
Now how could we
evaluate this sum?

00:37:02.450 --> 00:37:05.050 align:middle line:84%
This expression is a little bit
more complicated than the ones

00:37:05.050 --> 00:37:07.542 align:middle line:90%
that we had before.

00:37:07.542 --> 00:37:10.060 align:middle line:84%
is there a way that
we can simplify it?

00:37:10.060 --> 00:37:11.860 align:middle line:90%
Yeah?

00:37:11.860 --> 00:37:14.260 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:37:14.260 --> 00:37:18.010 align:middle line:90%


00:37:18.010 --> 00:37:20.920 align:middle line:84%
BRYNMOR CHAPMAN: Yeah, so
let's distribute this i

00:37:20.920 --> 00:37:22.660 align:middle line:90%
and then break the sum up.

00:37:22.660 --> 00:37:29.440 align:middle line:84%
So if we distribute
this, we end up

00:37:29.440 --> 00:37:35.830 align:middle line:84%
with i squared plus
i divided by 2.

00:37:35.830 --> 00:37:41.990 align:middle line:84%
And now we've got
a sum of a sum.

00:37:41.990 --> 00:37:44.296 align:middle line:84%
So we can split it into
two different summations.

00:37:44.296 --> 00:37:48.130 align:middle line:90%


00:37:48.130 --> 00:37:59.380 align:middle line:84%
i equals 1 to n i
squared plus sum of i.

00:37:59.380 --> 00:38:05.620 align:middle line:84%
So I've taken each of these
terms and split it into its own

00:38:05.620 --> 00:38:09.340 align:middle line:84%
sum and also pulled this
factor of 1/2 out in front.

00:38:09.340 --> 00:38:14.060 align:middle line:84%
So this is now something
that we know how to evaluate.

00:38:14.060 --> 00:38:16.390 align:middle line:90%
We just evaluated it.

00:38:16.390 --> 00:38:19.270 align:middle line:84%
This is also something
we know how to evaluate.

00:38:19.270 --> 00:38:20.910 align:middle line:90%
Also, we just evaluated it.

00:38:20.910 --> 00:38:23.920 align:middle line:90%


00:38:23.920 --> 00:38:28.940 align:middle line:84%
So this comes out to the
answer that we had there,

00:38:28.940 --> 00:38:51.160 align:middle line:84%
so 1/6 n cubed plus 1/4 n
squared plus 1/12 n plus 1/4

00:38:51.160 --> 00:38:54.970 align:middle line:90%
times n times n plus 1.

00:38:54.970 --> 00:39:01.190 align:middle line:84%
Does that make
sense to everybody?

00:39:01.190 --> 00:39:17.200 align:middle line:90%


00:39:17.200 --> 00:39:23.630 align:middle line:84%
Suppose instead we had something
similar but slightly different.

00:39:23.630 --> 00:39:29.080 align:middle line:90%


00:39:29.080 --> 00:39:36.955 align:middle line:84%
So sum from i equals 1 to
n, sum from j equals i to n.

00:39:36.955 --> 00:39:44.400 align:middle line:90%


00:39:44.400 --> 00:39:48.090 align:middle line:84%
So our inner sum now,
instead of going from 1 to i,

00:39:48.090 --> 00:39:49.650 align:middle line:90%
it's going from i to n.

00:39:49.650 --> 00:40:01.800 align:middle line:90%


00:40:01.800 --> 00:40:07.380 align:middle line:84%
Now we could evaluate this in
the same way as we just did.

00:40:07.380 --> 00:40:10.800 align:middle line:84%
But it turns out that there's
a slightly easier way.

00:40:10.800 --> 00:40:13.960 align:middle line:84%
We can exchange the
order of summation.

00:40:13.960 --> 00:40:33.390 align:middle line:90%


00:40:33.390 --> 00:40:37.620 align:middle line:84%
And what I mean by that is
that we want the outer sum

00:40:37.620 --> 00:40:41.730 align:middle line:84%
to be in terms of j and the
inner sum to be in terms of i.

00:40:41.730 --> 00:40:51.500 align:middle line:84%
So what are the
possible values of j?

00:40:51.500 --> 00:41:01.650 align:middle line:90%


00:41:01.650 --> 00:41:03.090 align:middle line:90%
So in our-- yes?

00:41:03.090 --> 00:41:07.440 align:middle line:90%


00:41:07.440 --> 00:41:08.850 align:middle line:90%
Yeah?

00:41:08.850 --> 00:41:10.080 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:41:10.080 --> 00:41:10.997 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:41:10.997 --> 00:41:15.610 align:middle line:90%


00:41:15.610 --> 00:41:20.770 align:middle line:84%
So if i equals 1 here,
j equals i, j equals 1.

00:41:20.770 --> 00:41:23.190 align:middle line:84%
So that's the
smallest value of j.

00:41:23.190 --> 00:41:27.330 align:middle line:90%
And j can clearly go up to n.

00:41:27.330 --> 00:41:37.650 align:middle line:90%


00:41:37.650 --> 00:41:39.875 align:middle line:84%
What are the bounds of
summation on our inner sum?

00:41:39.875 --> 00:41:45.360 align:middle line:90%


00:41:45.360 --> 00:41:46.670 align:middle line:90%
How would we compute this?

00:41:46.670 --> 00:41:53.490 align:middle line:90%


00:41:53.490 --> 00:41:57.810 align:middle line:84%
What constraints do we
have on i and k originally?

00:41:57.810 --> 00:42:04.650 align:middle line:90%


00:42:04.650 --> 00:42:07.830 align:middle line:84%
When we know that 1 is less
than or equal to i less than

00:42:07.830 --> 00:42:12.600 align:middle line:84%
or equal to n i less than
or equal to j less than

00:42:12.600 --> 00:42:13.260 align:middle line:90%
or equal to n.

00:42:13.260 --> 00:42:17.070 align:middle line:90%


00:42:17.070 --> 00:42:20.610 align:middle line:84%
So we could phrase
this as 1 less

00:42:20.610 --> 00:42:23.790 align:middle line:84%
than or equal to i less
than or equal to j less than

00:42:23.790 --> 00:42:24.485 align:middle line:90%
or equal to n.

00:42:24.485 --> 00:42:28.950 align:middle line:90%


00:42:28.950 --> 00:42:32.675 align:middle line:84%
And now we've got bounds
on i in terms of j.

00:42:32.675 --> 00:42:42.360 align:middle line:90%


00:42:42.360 --> 00:42:44.050 align:middle line:84%
Does that make
sense to everybody?

00:42:44.050 --> 00:42:46.920 align:middle line:90%


00:42:46.920 --> 00:42:52.260 align:middle line:84%
So we still want the sum over
the same set of pairs, i and j.

00:42:52.260 --> 00:42:54.340 align:middle line:84%
We're just expressing
it differently.

00:42:54.340 --> 00:42:57.870 align:middle line:90%


00:42:57.870 --> 00:42:59.375 align:middle line:90%
And now our sum n is the same.

00:42:59.375 --> 00:43:02.910 align:middle line:90%


00:43:02.910 --> 00:43:06.090 align:middle line:84%
Does it make sense to
everybody how we got this?

00:43:06.090 --> 00:43:07.260 align:middle line:90%
Yeah?

00:43:07.260 --> 00:43:09.424 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:43:09.424 --> 00:43:14.100 align:middle line:90%


00:43:14.100 --> 00:43:19.620 align:middle line:84%
BRYNMOR CHAPMAN: So this
just came from the bounds

00:43:19.620 --> 00:43:22.560 align:middle line:90%
on our inner sum.

00:43:22.560 --> 00:43:27.390 align:middle line:84%
We're saying that j should
range from i up to n.

00:43:27.390 --> 00:43:35.250 align:middle line:84%
And so then we just stick this
pair of inequalities in here.

00:43:35.250 --> 00:43:38.690 align:middle line:84%
Does that make
sense to everybody?

00:43:38.690 --> 00:43:42.260 align:middle line:84%
Are you reasonably
happy with this?

00:43:42.260 --> 00:43:46.910 align:middle line:84%
So now we've exchanged
the order of summation.

00:43:46.910 --> 00:43:52.670 align:middle line:84%
We've got j for our outer
sum, i for our inner sum.

00:43:52.670 --> 00:43:55.970 align:middle line:84%
And now we've got a
much simpler sum here

00:43:55.970 --> 00:43:58.130 align:middle line:90%
that we can easily evaluate.

00:43:58.130 --> 00:43:59.365 align:middle line:90%
What is our inner sum?

00:43:59.365 --> 00:44:08.857 align:middle line:90%


00:44:08.857 --> 00:44:09.690 align:middle line:90%
AUDIENCE: j squared.

00:44:09.690 --> 00:44:10.607 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:44:10.607 --> 00:44:20.630 align:middle line:90%


00:44:20.630 --> 00:44:27.020 align:middle line:84%
The sum end has no dependence
on the index of summation.

00:44:27.020 --> 00:44:28.830 align:middle line:90%
So we've just got j terms.

00:44:28.830 --> 00:44:30.110 align:middle line:90%
All of them are j.

00:44:30.110 --> 00:44:31.105 align:middle line:90%
So it's j squared.

00:44:31.105 --> 00:44:37.016 align:middle line:90%


00:44:37.016 --> 00:44:39.535 align:middle line:84%
And now this is just the
sum that we had before.

00:44:39.535 --> 00:44:56.150 align:middle line:90%


00:44:56.150 --> 00:44:57.690 align:middle line:84%
Does that make
sense to everybody?

00:44:57.690 --> 00:45:00.770 align:middle line:90%


00:45:00.770 --> 00:45:01.865 align:middle line:90%
Yeah?

00:45:01.865 --> 00:45:04.910 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:45:04.910 --> 00:45:11.330 align:middle line:90%


00:45:11.330 --> 00:45:16.928 align:middle line:90%
BRYNMOR CHAPMAN: This one here?

00:45:16.928 --> 00:45:19.916 align:middle line:90%


00:45:19.916 --> 00:45:23.130 align:middle line:84%
So that's just an expression
that you've already seen.

00:45:23.130 --> 00:45:25.280 align:middle line:84%
We've already seen how to
evaluate the sum from j

00:45:25.280 --> 00:45:28.550 align:middle line:90%
equals 1 to i of j.

00:45:28.550 --> 00:45:30.680 align:middle line:84%
So that's just
plugging in that closed

00:45:30.680 --> 00:45:32.875 align:middle line:90%
formula for that inner sum.

00:45:32.875 --> 00:45:42.500 align:middle line:90%


00:45:42.500 --> 00:45:44.125 align:middle line:84%
Are people reasonably
happy with this?

00:45:44.125 --> 00:45:46.850 align:middle line:90%


00:45:46.850 --> 00:45:48.023 align:middle line:90%
Yeah?

00:45:48.023 --> 00:45:51.105 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:45:51.105 --> 00:45:52.105 align:middle line:90%
BRYNMOR CHAPMAN: Did we?

00:45:52.105 --> 00:45:56.660 align:middle line:90%


00:45:56.660 --> 00:45:58.340 align:middle line:90%
Oh yeah, here-ish.

00:45:58.340 --> 00:46:00.890 align:middle line:90%


00:46:00.890 --> 00:46:15.950 align:middle line:84%
I mean, here it's the particular
example where n equals 100.

00:46:15.950 --> 00:46:19.750 align:middle line:84%
So why don't we move on to
the last topic for today?

00:46:19.750 --> 00:46:30.880 align:middle line:90%


00:46:30.880 --> 00:46:38.745 align:middle line:84%
So what happens if we
have the following sum?

00:46:38.745 --> 00:46:52.030 align:middle line:90%


00:46:52.030 --> 00:46:55.663 align:middle line:84%
Any idea how we might come up
with a closed form for this?

00:46:55.663 --> 00:46:57.330 align:middle line:84%
Does anybody already
know a closed form?

00:46:57.330 --> 00:47:01.100 align:middle line:90%


00:47:01.100 --> 00:47:01.600 align:middle line:90%
Nobody?

00:47:01.600 --> 00:47:02.822 align:middle line:90%
Really?

00:47:02.822 --> 00:47:04.530 align:middle line:84%
That's good because
it's an open problem.

00:47:04.530 --> 00:47:07.450 align:middle line:90%


00:47:07.450 --> 00:47:09.200 align:middle line:84%
Well, I suppose that
doesn't make it good.

00:47:09.200 --> 00:47:11.450 align:middle line:84%
If you have a closed form,
you could a paper about it.

00:47:11.450 --> 00:47:14.360 align:middle line:90%
That would be pretty exciting.

00:47:14.360 --> 00:47:19.070 align:middle line:84%
So it turns out that there isn't
any nice closed form for this,

00:47:19.070 --> 00:47:21.670 align:middle line:90%
as far as we know.

00:47:21.670 --> 00:47:25.645 align:middle line:84%
So does that mean we should
just-- hands in the air,

00:47:25.645 --> 00:47:26.145 align:middle line:90%
give up?

00:47:26.145 --> 00:47:30.110 align:middle line:90%


00:47:30.110 --> 00:47:31.450 align:middle line:90%
Getting some nods.

00:47:31.450 --> 00:47:36.940 align:middle line:84%
Yeah, I mean, I suppose that's
a question of philosophy.

00:47:36.940 --> 00:47:39.710 align:middle line:84%
But we can still say
something about it, right?

00:47:39.710 --> 00:47:44.080 align:middle line:84%
Maybe we don't need to know
exactly what this sum is.

00:47:44.080 --> 00:47:47.270 align:middle line:84%
But as long as we figure out
something, that's close enough,

00:47:47.270 --> 00:47:49.420 align:middle line:90%
maybe we're still happy.

00:47:49.420 --> 00:47:51.450 align:middle line:84%
So maybe we want
to approximate it.

00:47:51.450 --> 00:48:05.544 align:middle line:90%


00:48:05.544 --> 00:48:10.750 align:middle line:84%
So can anybody give me a
guess as to an approximation

00:48:10.750 --> 00:48:11.340 align:middle line:90%
for this sum?

00:48:11.340 --> 00:48:17.920 align:middle line:90%


00:48:17.920 --> 00:48:20.120 align:middle line:84%
AUDIENCE: So we were just
integrating that as well?

00:48:20.120 --> 00:48:23.515 align:middle line:90%
BRYNMOR CHAPMAN: Mm-hmm.

00:48:23.515 --> 00:48:27.880 align:middle line:84%
So the answer was, again, if we
squint really hard and pretend

00:48:27.880 --> 00:48:31.780 align:middle line:84%
that this is an integral,
maybe s is approximately equal

00:48:31.780 --> 00:48:39.670 align:middle line:84%
to the integral of root
x dx, say from 1 to n,

00:48:39.670 --> 00:48:50.920 align:middle line:84%
which is going to be
about 2/3 n to the 3/2.

00:48:50.920 --> 00:48:53.170 align:middle line:90%
Is that about right?

00:48:53.170 --> 00:48:55.480 align:middle line:84%
I swear I've done
calculus before.

00:48:55.480 --> 00:48:58.060 align:middle line:90%
It's been a while.

00:48:58.060 --> 00:49:05.180 align:middle line:84%
So the question then becomes,
how close is that approximation?

00:49:05.180 --> 00:49:08.410 align:middle line:90%


00:49:08.410 --> 00:49:11.740 align:middle line:84%
Do we think we're
within a factor of 2?

00:49:11.740 --> 00:49:15.890 align:middle line:84%
Do you think we're
off by n by root n?

00:49:15.890 --> 00:49:19.000 align:middle line:90%
Off by 1 maybe?

00:49:19.000 --> 00:49:21.973 align:middle line:90%
It's not entirely clear.

00:49:21.973 --> 00:49:28.380 align:middle line:84%
So in order to figure
this out, we're

00:49:28.380 --> 00:49:30.635 align:middle line:84%
going to use what we
call the integral method.

00:49:30.635 --> 00:49:34.560 align:middle line:90%


00:49:34.560 --> 00:49:42.480 align:middle line:84%
So give me a moment
to draw this.

00:49:42.480 --> 00:49:48.210 align:middle line:84%
And redux looks a
little bit like that

00:49:48.210 --> 00:49:49.370 align:middle line:90%
if you squint really hard.

00:49:49.370 --> 00:49:57.990 align:middle line:90%


00:49:57.990 --> 00:50:08.960 align:middle line:84%
So suppose we have a weakly
increasing function of x.

00:50:08.960 --> 00:50:18.180 align:middle line:90%


00:50:18.180 --> 00:50:22.445 align:middle line:84%
So root x is indeed weakly
increasing, so that'll work.

00:50:22.445 --> 00:50:25.320 align:middle line:90%


00:50:25.320 --> 00:50:29.030 align:middle line:84%
Now, recall Riemann sums
from integral calculus.

00:50:29.030 --> 00:50:32.310 align:middle line:90%


00:50:32.310 --> 00:50:33.490 align:middle line:90%
No post-traumatic stress?

00:50:33.490 --> 00:50:35.130 align:middle line:90%
Are we OK?

00:50:35.130 --> 00:50:43.250 align:middle line:84%
So how could we approximate
the integral of f of x?

00:50:43.250 --> 00:50:48.660 align:middle line:90%


00:50:48.660 --> 00:50:50.190 align:middle line:90%
Yeah?

00:50:50.190 --> 00:50:53.310 align:middle line:84%
AUDIENCE: [INAUDIBLE] the
right hand [INAUDIBLE].

00:50:53.310 --> 00:50:54.270 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:50:54.270 --> 00:51:02.070 align:middle line:84%
So if we've got 1, 2,
3, 4, dot, dot, dot,

00:51:02.070 --> 00:51:06.425 align:middle line:84%
we can draw a bunch of
rectangles, like this.

00:51:06.425 --> 00:51:11.730 align:middle line:90%


00:51:11.730 --> 00:51:15.155 align:middle line:90%
And this step function here--

00:51:15.155 --> 00:51:18.432 align:middle line:90%


00:51:18.432 --> 00:51:20.390 align:middle line:84%
actually, maybe I should
get a different color.

00:51:20.390 --> 00:51:42.772 align:middle line:90%


00:51:42.772 --> 00:51:44.480 align:middle line:84%
For completeness,
maybe I should do that.

00:51:44.480 --> 00:51:51.600 align:middle line:90%


00:51:51.600 --> 00:51:55.200 align:middle line:84%
So this step function
here that I've

00:51:55.200 --> 00:51:57.900 align:middle line:90%
drawn is f of the floor of x.

00:51:57.900 --> 00:52:01.350 align:middle line:90%
f is weakly increasing.

00:52:01.350 --> 00:52:06.670 align:middle line:84%
So that means floor of x is
an under approximation for x.

00:52:06.670 --> 00:52:11.540 align:middle line:84%
So f of floor of x is an under
approximation for f of x.

00:52:11.540 --> 00:52:17.340 align:middle line:90%


00:52:17.340 --> 00:52:22.840 align:middle line:84%
Now what happens if we
integrate this step function?

00:52:22.840 --> 00:52:35.870 align:middle line:90%


00:52:35.870 --> 00:52:50.780 align:middle line:84%
What is the integral from
1 to n of f of floor of x?

00:52:50.780 --> 00:52:51.440 align:middle line:90%
Yeah?

00:52:51.440 --> 00:52:53.092 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:52:53.092 --> 00:52:54.050 align:middle line:90%
BRYNMOR CHAPMAN: Sorry?

00:52:54.050 --> 00:52:56.522 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:52:56.522 --> 00:52:57.522 align:middle line:90%
BRYNMOR CHAPMAN: Almost.

00:52:57.522 --> 00:53:05.630 align:middle line:90%


00:53:05.630 --> 00:53:09.110 align:middle line:90%
So in this case, it actually--

00:53:09.110 --> 00:53:10.450 align:middle line:90%
does it turn out to be s?

00:53:10.450 --> 00:53:13.195 align:middle line:90%


00:53:13.195 --> 00:53:15.560 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:53:15.560 --> 00:53:17.310 align:middle line:90%
BRYNMOR CHAPMAN: Yeah, exactly.

00:53:17.310 --> 00:53:19.910 align:middle line:90%
We're missing a term here.

00:53:19.910 --> 00:53:28.160 align:middle line:84%
So we can break this
into n minus 1 integrals.

00:53:28.160 --> 00:53:32.390 align:middle line:84%
We've got an interval
of width n minus 1.

00:53:32.390 --> 00:53:37.970 align:middle line:84%
This is constant on each of
those width-1 subintervals.

00:53:37.970 --> 00:53:42.230 align:middle line:84%
So we can break it apart into
a whole bunch of rectangles.

00:53:42.230 --> 00:53:50.540 align:middle line:84%
So this is going to be the sum
from i equals 1 to n minus 1

00:53:50.540 --> 00:53:55.160 align:middle line:90%
of f of i.

00:53:55.160 --> 00:53:57.890 align:middle line:84%
Does that make
sense to everybody?

00:53:57.890 --> 00:54:02.510 align:middle line:84%
So we've got
intervals of width 1.

00:54:02.510 --> 00:54:06.420 align:middle line:84%
Our function is constant
on each of those intervals.

00:54:06.420 --> 00:54:12.410 align:middle line:84%
And it's equal to the left-hand
side of that interval.

00:54:12.410 --> 00:54:16.490 align:middle line:84%
Does that make
sense to everybody.

00:54:16.490 --> 00:54:23.170 align:middle line:84%
And this is just going
to be s minus f of n.

00:54:23.170 --> 00:54:32.960 align:middle line:90%


00:54:32.960 --> 00:54:34.210 align:middle line:90%
Sorry?

00:54:34.210 --> 00:54:36.680 align:middle line:84%
AUDIENCE: Why is n
minus 1 the [INAUDIBLE]?

00:54:36.680 --> 00:54:39.320 align:middle line:84%
BRYNMOR CHAPMAN: So the question
is, why are we using n minus 1

00:54:39.320 --> 00:54:40.820 align:middle line:90%
as the bound here?

00:54:40.820 --> 00:54:47.630 align:middle line:84%
So that's because the width
of this interval is n minus 1.

00:54:47.630 --> 00:54:52.820 align:middle line:84%
We're splitting into n minus
1 intervals of width 1.

00:54:52.820 --> 00:55:01.730 align:middle line:84%
So for instance, if we went
up to, say, n equals 5.

00:55:01.730 --> 00:55:07.190 align:middle line:84%
So if we were trying to sum f
of 1, f of 2, f of 3, f of 4,

00:55:07.190 --> 00:55:13.480 align:middle line:84%
f of 5, we would then want
to compare to this integral

00:55:13.480 --> 00:55:22.450 align:middle line:84%
here, so the
integral from 1 to 5.

00:55:22.450 --> 00:55:24.546 align:middle line:90%
And this gives us 4 rectangles.

00:55:24.546 --> 00:55:27.730 align:middle line:90%


00:55:27.730 --> 00:55:34.490 align:middle line:84%
We've got the integral from 1 to
2 from 2 to 3, 3 to 4, 4 to 5.

00:55:34.490 --> 00:55:43.330 align:middle line:84%
And the integral, say, from 2 to
3 has width 1 and height f of 2.

00:55:43.330 --> 00:55:51.940 align:middle line:84%
So maybe we could phrase
this as 1 times f of i.

00:55:51.940 --> 00:55:52.860 align:middle line:90%
Does that make sense?

00:55:52.860 --> 00:56:06.370 align:middle line:90%


00:56:06.370 --> 00:56:08.530 align:middle line:84%
So we've got an
underapproximation

00:56:08.530 --> 00:56:10.330 align:middle line:90%
for our integral now.

00:56:10.330 --> 00:56:15.160 align:middle line:84%
So I haven't actually
written the integral.

00:56:15.160 --> 00:56:24.030 align:middle line:84%
So let's let i equal the
integral from 1 to n f of x dx.

00:56:24.030 --> 00:56:27.318 align:middle line:90%


00:56:27.318 --> 00:56:33.650 align:middle line:84%
So we said that this function
here underapproximates f.

00:56:33.650 --> 00:56:38.860 align:middle line:84%
So this integral
under approximates i.

00:56:38.860 --> 00:56:43.090 align:middle line:84%
So that tells us that
i is greater than

00:56:43.090 --> 00:56:47.230 align:middle line:90%
or equal to s minus f of n.

00:56:47.230 --> 00:56:51.580 align:middle line:90%


00:56:51.580 --> 00:56:55.270 align:middle line:84%
Now equivalently, we could
phrase this as a bound on s

00:56:55.270 --> 00:56:58.330 align:middle line:84%
in terms of i because s
was what we originally

00:56:58.330 --> 00:57:01.420 align:middle line:90%
wanted to figure out.

00:57:01.420 --> 00:57:04.870 align:middle line:84%
So instead, we could write
this as s is less than

00:57:04.870 --> 00:57:10.555 align:middle line:90%
or equal to i plus f of n.

00:57:10.555 --> 00:57:11.430 align:middle line:90%
Does that make sense?

00:57:11.430 --> 00:57:23.980 align:middle line:90%


00:57:23.980 --> 00:57:29.176 align:middle line:84%
What if, instead,
we overapproximated?

00:57:29.176 --> 00:57:38.920 align:middle line:90%


00:57:38.920 --> 00:57:45.585 align:middle line:84%
So now we've got f
of the ceiling of x.

00:57:45.585 --> 00:57:56.350 align:middle line:90%


00:57:56.350 --> 00:57:58.060 align:middle line:84%
So the new step
function that I've just

00:57:58.060 --> 00:58:03.890 align:middle line:84%
drawn in green is
f of ceiling of x,

00:58:03.890 --> 00:58:08.970 align:middle line:84%
which is an
overapproximation for f of x.

00:58:08.970 --> 00:58:15.000 align:middle line:84%
So if we integrate it
the integral from 1 to n

00:58:15.000 --> 00:58:23.960 align:middle line:84%
of f of ceiling of x dx should
be greater than or equal to i.

00:58:23.960 --> 00:58:28.050 align:middle line:90%


00:58:28.050 --> 00:58:35.340 align:middle line:84%
Now, doing exactly the same
thing as we had before,

00:58:35.340 --> 00:58:36.575 align:middle line:90%
what is this integral?

00:58:36.575 --> 00:58:46.170 align:middle line:90%


00:58:46.170 --> 00:58:47.580 align:middle line:90%
Yeah?

00:58:47.580 --> 00:58:49.818 align:middle line:84%
AUDIENCE: Sum from
2 to n of f of i?

00:58:49.818 --> 00:58:50.735 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

00:58:50.735 --> 00:58:53.265 align:middle line:90%


00:58:53.265 --> 00:58:59.370 align:middle line:84%
So sum from i equals
2 to n of f of i--

00:58:59.370 --> 00:59:07.985 align:middle line:84%
say times 1-- and this
is just s minus f of 1.

00:59:07.985 --> 00:59:14.070 align:middle line:90%


00:59:14.070 --> 00:59:19.680 align:middle line:90%
So s minus f of 1 is at least i.

00:59:19.680 --> 00:59:27.840 align:middle line:84%
Once again, we can rephrase this
as a bound on s in terms of i.

00:59:27.840 --> 00:59:39.020 align:middle line:84%
So s is greater than or
equal to i plus f of 1.

00:59:39.020 --> 00:59:53.490 align:middle line:90%


00:59:53.490 --> 00:59:56.050 align:middle line:84%
So does that make
sense to everybody?

00:59:56.050 --> 01:00:02.520 align:middle line:90%


01:00:02.520 --> 01:00:12.150 align:middle line:84%
So putting these together now,
we have i plus f of 1 less than

01:00:12.150 --> 01:00:18.180 align:middle line:84%
or equal to s less than
or equal to i plus f of n.

01:00:18.180 --> 01:00:25.860 align:middle line:90%


01:00:25.860 --> 01:00:29.460 align:middle line:84%
So this is what we call the
integral bound for increasing

01:00:29.460 --> 01:00:30.460 align:middle line:90%
functions.

01:00:30.460 --> 01:01:03.512 align:middle line:90%


01:01:03.512 --> 01:01:05.095 align:middle line:84%
Are people reasonably
happy with this?

01:01:05.095 --> 01:01:07.800 align:middle line:90%


01:01:07.800 --> 01:01:12.410 align:middle line:84%
So if we go back to our original
question where f of x equals

01:01:12.410 --> 01:01:15.535 align:middle line:84%
root x, what are
the bounds we get?

01:01:15.535 --> 01:01:18.050 align:middle line:90%


01:01:18.050 --> 01:01:19.420 align:middle line:90%
What is i first?

01:01:19.420 --> 01:01:25.130 align:middle line:90%


01:01:25.130 --> 01:01:27.330 align:middle line:84%
It wasn't quite what
I wrote down before.

01:01:27.330 --> 01:01:28.290 align:middle line:90%
Yeah?

01:01:28.290 --> 01:01:30.610 align:middle line:90%
AUDIENCE: [INAUDIBLE]

01:01:30.610 --> 01:01:31.370 align:middle line:90%


01:01:31.370 --> 01:01:32.910 align:middle line:84%
BRYNMOR CHAPMAN:
It is from 1 to n.

01:01:32.910 --> 01:01:37.910 align:middle line:84%
Remember what I wrote originally
was a 2/3 n to the 3/2,

01:01:37.910 --> 01:01:40.630 align:middle line:84%
which is, I believe, the
integral from 0 to n.

01:01:40.630 --> 01:01:43.190 align:middle line:90%


01:01:43.190 --> 01:01:50.930 align:middle line:84%
So what we actually have here
is i equals the integral from 1

01:01:50.930 --> 01:02:05.030 align:middle line:84%
to n of x to the 1/2 dx, which
is equal to 2/3 x to the 3/2

01:02:05.030 --> 01:02:15.860 align:middle line:84%
evaluated at 1 and n, which
is going to be 2/3 times n

01:02:15.860 --> 01:02:23.980 align:middle line:84%
to the 3/2 minus 1, so
almost what we had before.

01:02:23.980 --> 01:02:28.640 align:middle line:90%


01:02:28.640 --> 01:02:35.570 align:middle line:84%
So our lower bound, then,
is this value plus f of 1.

01:02:35.570 --> 01:02:37.440 align:middle line:90%
f of 1 is just root 1.

01:02:37.440 --> 01:02:40.100 align:middle line:90%
It's 1.

01:02:40.100 --> 01:02:44.360 align:middle line:84%
And our upper bound
is i plus root n.

01:02:44.360 --> 01:02:47.240 align:middle line:90%


01:02:47.240 --> 01:02:51.920 align:middle line:84%
So it turns out that 2/3 n
to the 3/2 is a pretty good

01:02:51.920 --> 01:02:54.210 align:middle line:90%
approximation.

01:02:54.210 --> 01:03:00.370 align:middle line:84%
It's going to be a little bit
larger than that but not much.

01:03:00.370 --> 01:03:05.360 align:middle line:84%
We're going to be within
an additive root n.

01:03:05.360 --> 01:03:12.040 align:middle line:84%
And given that our approximation
is the cube of that,

01:03:12.040 --> 01:03:15.570 align:middle line:90%
that's actually pretty good.

01:03:15.570 --> 01:03:19.793 align:middle line:84%
Does that make
sense to everybody?

01:03:19.793 --> 01:03:21.335 align:middle line:84%
Everybody reasonably
happy with that?

01:03:21.335 --> 01:03:49.560 align:middle line:90%


01:03:49.560 --> 01:03:56.650 align:middle line:84%
What if, instead, we had s
equals sum from i equals 1 to n

01:03:56.650 --> 01:03:58.650 align:middle line:90%
of, say, 1 over i?

01:03:58.650 --> 01:04:04.948 align:middle line:90%


01:04:04.948 --> 01:04:06.615 align:middle line:84%
Can we apply our
integral bound to this?

01:04:06.615 --> 01:04:12.100 align:middle line:90%


01:04:12.100 --> 01:04:15.280 align:middle line:90%
Who thinks yes?

01:04:15.280 --> 01:04:17.860 align:middle line:90%
Who thinks no?

01:04:17.860 --> 01:04:21.380 align:middle line:84%
Can anybody explain why
in either direction?

01:04:21.380 --> 01:04:21.880 align:middle line:90%
Yeah?

01:04:21.880 --> 01:04:25.120 align:middle line:90%


01:04:25.120 --> 01:04:30.680 align:middle line:84%
AUDIENCE: [INAUDIBLE] but
it's going to be [INAUDIBLE],

01:04:30.680 --> 01:04:33.370 align:middle line:84%
but after 1, it's going to
be a convergent [INAUDIBLE]

01:04:33.370 --> 01:04:36.550 align:middle line:90%
between 1 and 0.

01:04:36.550 --> 01:04:41.020 align:middle line:84%
BRYNMOR CHAPMAN: So
the answer was after 1,

01:04:41.020 --> 01:04:42.293 align:middle line:90%
it's going to converge.

01:04:42.293 --> 01:04:44.920 align:middle line:90%


01:04:44.920 --> 01:04:46.230 align:middle line:90%
I would dispute that.

01:04:46.230 --> 01:04:49.630 align:middle line:90%


01:04:49.630 --> 01:04:51.370 align:middle line:90%
Yeah?

01:04:51.370 --> 01:04:53.290 align:middle line:84%
AUDIENCE: If I recall
correctly, the integral

01:04:53.290 --> 01:04:55.990 align:middle line:90%
is natural log [INAUDIBLE].

01:04:55.990 --> 01:05:00.100 align:middle line:90%


01:05:00.100 --> 01:05:02.500 align:middle line:84%
BRYNMOR CHAPMAN:
OK, fair enough.

01:05:02.500 --> 01:05:04.725 align:middle line:84%
So even if we could
apply the integral bound,

01:05:04.725 --> 01:05:05.850 align:middle line:90%
it may not get us very far.

01:05:05.850 --> 01:05:09.730 align:middle line:90%


01:05:09.730 --> 01:05:11.510 align:middle line:84%
I think there's a
bigger problem here.

01:05:11.510 --> 01:05:12.040 align:middle line:90%
Yeah?

01:05:12.040 --> 01:05:13.470 align:middle line:90%
AUDIENCE: [INAUDIBLE]

01:05:13.470 --> 01:05:14.720 align:middle line:90%
BRYNMOR CHAPMAN: That's right.

01:05:14.720 --> 01:05:19.000 align:middle line:84%
So remember that our
assumption was that f

01:05:19.000 --> 01:05:21.310 align:middle line:90%
should be weakly increasing.

01:05:21.310 --> 01:05:25.220 align:middle line:84%
1 over i is not,
or 1 over x is not.

01:05:25.220 --> 01:05:25.780 align:middle line:90%
Yeah?

01:05:25.780 --> 01:05:31.840 align:middle line:84%
AUDIENCE: Well, at least it's
weakly decreasing [INAUDIBLE].

01:05:31.840 --> 01:05:34.960 align:middle line:84%
BRYNMOR CHAPMAN: So
the observation here

01:05:34.960 --> 01:05:39.640 align:middle line:84%
is that if we take f
of x equals 1 over x,

01:05:39.640 --> 01:05:41.216 align:middle line:90%
this is weakly decreasing.

01:05:41.216 --> 01:05:48.160 align:middle line:90%


01:05:48.160 --> 01:05:52.390 align:middle line:90%
So we can do something similar.

01:05:52.390 --> 01:05:54.140 align:middle line:90%
What exactly are we going to do?

01:05:54.140 --> 01:06:10.380 align:middle line:84%
Well, let's take g of x to be
equal to f of n plus 1 minus x.

01:06:10.380 --> 01:06:15.040 align:middle line:90%


01:06:15.040 --> 01:06:19.455 align:middle line:90%
Now what do we know about g?

01:06:19.455 --> 01:06:34.360 align:middle line:90%


01:06:34.360 --> 01:06:37.870 align:middle line:84%
So basically, what
we've done here,

01:06:37.870 --> 01:06:41.180 align:middle line:84%
we are essentially
negating the argument.

01:06:41.180 --> 01:06:45.200 align:middle line:84%
So we're kind of
flipping it horizontally.

01:06:45.200 --> 01:06:48.430 align:middle line:84%
We started with a weakly
decreasing function.

01:06:48.430 --> 01:06:50.627 align:middle line:84%
So when we flip it
like this, we're

01:06:50.627 --> 01:06:52.710 align:middle line:84%
going to end up with a
weakly increasing function.

01:06:52.710 --> 01:07:05.710 align:middle line:90%


01:07:05.710 --> 01:07:06.700 align:middle line:90%
Yeah?

01:07:06.700 --> 01:07:07.910 align:middle line:90%
AUDIENCE: [INAUDIBLE]

01:07:07.910 --> 01:07:12.700 align:middle line:90%


01:07:12.700 --> 01:07:14.950 align:middle line:84%
BRYNMOR CHAPMAN: So are you
worried about the n plus 1

01:07:14.950 --> 01:07:16.425 align:middle line:90%
as opposed to the n?

01:07:16.425 --> 01:07:17.800 align:middle line:84%
AUDIENCE: Yeah,
I'm just confused

01:07:17.800 --> 01:07:21.165 align:middle line:84%
on why you can't do that
or how that flips it.

01:07:21.165 --> 01:07:22.540 align:middle line:84%
BRYNMOR CHAPMAN:
So basically, we

01:07:22.540 --> 01:07:27.070 align:middle line:84%
are mapping 1 to
n and vice versa.

01:07:27.070 --> 01:07:29.230 align:middle line:84%
And then everything
in between should just

01:07:29.230 --> 01:07:31.660 align:middle line:90%
interpolate linearly.

01:07:31.660 --> 01:07:36.020 align:middle line:84%
So if we put 1 into here,
we end up with f of n.

01:07:36.020 --> 01:07:38.710 align:middle line:84%
If we put n into here,
we end up with f of 1.

01:07:38.710 --> 01:07:40.210 align:middle line:90%
Does that make sense?

01:07:40.210 --> 01:07:42.070 align:middle line:84%
So the question
is, why do we have

01:07:42.070 --> 01:07:45.670 align:middle line:84%
the n plus 1 there instead
of just an n or a minus x

01:07:45.670 --> 01:07:49.890 align:middle line:84%
or something like that,
which kind of gets

01:07:49.890 --> 01:07:53.285 align:middle line:84%
into the next question--
what is s in terms of g?

01:07:53.285 --> 01:08:12.090 align:middle line:90%


01:08:12.090 --> 01:08:16.529 align:middle line:84%
So maybe it would be better
to write it using ellipses

01:08:16.529 --> 01:08:18.569 align:middle line:90%
instead of sigma notation.

01:08:18.569 --> 01:08:24.479 align:middle line:84%
So we defined it as
f of 1 plus f of 2,

01:08:24.479 --> 01:08:28.234 align:middle line:90%
plus dot, dot, dot plus f of n.

01:08:28.234 --> 01:08:31.170 align:middle line:90%


01:08:31.170 --> 01:08:35.074 align:middle line:84%
Now how can we rewrite
this in terms of g?

01:08:35.074 --> 01:08:40.740 align:middle line:90%


01:08:40.740 --> 01:08:42.870 align:middle line:84%
AUDIENCE: p over n
plus p over n minus 1.

01:08:42.870 --> 01:08:43.787 align:middle line:90%
BRYNMOR CHAPMAN: Yeah.

01:08:43.787 --> 01:08:54.029 align:middle line:90%


01:08:54.029 --> 01:08:58.630 align:middle line:84%
So this is actually equal
to the sum of g of i--

01:08:58.630 --> 01:08:59.464 align:middle line:90%
same bounds.

01:08:59.464 --> 01:09:03.090 align:middle line:90%


01:09:03.090 --> 01:09:10.625 align:middle line:90%
So now what can we do?

01:09:10.625 --> 01:09:17.694 align:middle line:90%


01:09:17.694 --> 01:09:19.140 align:middle line:90%
AUDIENCE: [INAUDIBLE]

01:09:19.140 --> 01:09:21.270 align:middle line:84%
BRYNMOR CHAPMAN:
Yeah, g satisfies

01:09:21.270 --> 01:09:26.010 align:middle line:84%
all of the requirements that we
needed for our integral bound.

01:09:26.010 --> 01:09:30.300 align:middle line:84%
So we can apply the integral
bound now to g instead of

01:09:30.300 --> 01:09:31.410 align:middle line:90%
to our original f.

01:09:31.410 --> 01:09:33.960 align:middle line:90%


01:09:33.960 --> 01:09:46.310 align:middle line:84%
So now we know that i plus g
of 1 less than or equal to s

01:09:46.310 --> 01:09:51.740 align:middle line:84%
less than or equal
to i plus g of n.

01:09:51.740 --> 01:09:57.350 align:middle line:84%
So the integral is
exactly the same.

01:09:57.350 --> 01:09:59.310 align:middle line:90%
We've just flipped it.

01:09:59.310 --> 01:10:03.200 align:middle line:84%
But the area under it
is going to be the same.

01:10:03.200 --> 01:10:05.430 align:middle line:90%
And what is this g of 1?

01:10:05.430 --> 01:10:08.605 align:middle line:84%
Well, this g of
1 is just f of n.

01:10:08.605 --> 01:10:12.980 align:middle line:90%


01:10:12.980 --> 01:10:14.965 align:middle line:90%
g of n is just f of 1.

01:10:14.965 --> 01:10:24.886 align:middle line:90%


01:10:24.886 --> 01:10:29.800 align:middle line:84%
So this is the integral bound
for weakly decreasing f.

01:10:29.800 --> 01:10:40.040 align:middle line:90%


01:10:40.040 --> 01:10:41.610 align:middle line:84%
Does that make
sense to everybody?

01:10:41.610 --> 01:10:46.100 align:middle line:90%


01:10:46.100 --> 01:10:47.256 align:middle line:90%
Yeah?

01:10:47.256 --> 01:10:49.400 align:middle line:84%
AUDIENCE: Could this also
[INAUDIBLE] a negative

01:10:49.400 --> 01:10:50.260 align:middle line:90%
[INAUDIBLE]?

01:10:50.260 --> 01:10:53.480 align:middle line:90%


01:10:53.480 --> 01:10:55.390 align:middle line:84%
BRYNMOR CHAPMAN:
Strictly speaking--

01:10:55.390 --> 01:10:58.610 align:middle line:90%


01:10:58.610 --> 01:11:01.769 align:middle line:84%
AUDIENCE: Do we need it to
be positive or negative?

01:11:01.769 --> 01:11:07.520 align:middle line:90%


01:11:07.520 --> 01:11:10.070 align:middle line:84%
BRYNMOR CHAPMAN: So you
end up with a slightly

01:11:10.070 --> 01:11:19.000 align:middle line:84%
different problem if you
just negate it, which is--

01:11:19.000 --> 01:11:23.120 align:middle line:90%


01:11:23.120 --> 01:11:26.690 align:middle line:84%
well, I'll hint
at it in a moment.

01:11:26.690 --> 01:11:32.200 align:middle line:84%
What happens if you take
limits as n goes to infinity?

01:11:32.200 --> 01:11:34.160 align:middle line:90%
AUDIENCE: [INAUDIBLE]

01:11:34.160 --> 01:11:35.360 align:middle line:90%
BRYNMOR CHAPMAN: Pardon?

01:11:35.360 --> 01:11:38.540 align:middle line:84%
AUDIENCE: Oh, it's
n goes to infinity.

01:11:38.540 --> 01:11:41.630 align:middle line:84%
BRYNMOR CHAPMAN:
Yeah, so you have to--

01:11:41.630 --> 01:11:45.300 align:middle line:84%
you can do that, but you'd
have to adjust for it,

01:11:45.300 --> 01:11:48.500 align:middle line:84%
and it doesn't work quite
as nicely with the limits.

01:11:48.500 --> 01:11:51.170 align:middle line:84%
So the answer is, strictly
speaking, yes, you

01:11:51.170 --> 01:11:55.310 align:middle line:90%
could negate it if you want to.

01:11:55.310 --> 01:11:59.165 align:middle line:90%
But flipping it, and--

01:11:59.165 --> 01:12:04.730 align:middle line:90%


01:12:04.730 --> 01:12:06.630 align:middle line:84%
I personally find it
easier to think about.

01:12:06.630 --> 01:12:13.320 align:middle line:90%


01:12:13.320 --> 01:12:17.930 align:middle line:84%
So that was the idea, to
negate f instead of x.

01:12:17.930 --> 01:12:24.530 align:middle line:84%
But segue into the
last thing-- we've

01:12:24.530 --> 01:12:27.090 align:middle line:84%
got a couple of minutes,
or eight minutes.

01:12:27.090 --> 01:12:27.655 align:middle line:90%
Oh, nice.

01:12:27.655 --> 01:12:30.350 align:middle line:90%


01:12:30.350 --> 01:12:38.570 align:middle line:84%
So what about s equals sum
from I equals 1 to infinity of,

01:12:38.570 --> 01:12:40.510 align:middle line:90%
let's say--

01:12:40.510 --> 01:12:42.490 align:middle line:84%
because as somebody
pointed out, we do not

01:12:42.490 --> 01:12:44.360 align:middle line:90%
want to be working with logs.

01:12:44.360 --> 01:12:47.250 align:middle line:90%
So let's say 1 over i squared.

01:12:47.250 --> 01:12:51.400 align:middle line:90%


01:12:51.400 --> 01:12:59.490 align:middle line:84%
So how could we evaluate
this infinite sum?

01:12:59.490 --> 01:13:14.380 align:middle line:90%


01:13:14.380 --> 01:13:17.520 align:middle line:84%
Well, we can basically do
what we were just doing right.

01:13:17.520 --> 01:13:21.220 align:middle line:90%


01:13:21.220 --> 01:13:23.530 align:middle line:84%
Well, does anybody
remember how we actually

01:13:23.530 --> 01:13:25.605 align:middle line:90%
define what an infinite sum is?

01:13:25.605 --> 01:13:29.800 align:middle line:90%


01:13:29.800 --> 01:13:32.235 align:middle line:84%
It's just going to be a
limit of partial sums.

01:13:32.235 --> 01:13:43.300 align:middle line:90%


01:13:43.300 --> 01:13:52.540 align:middle line:84%
Now all of these, we
know how to evaluate.

01:13:52.540 --> 01:14:02.740 align:middle line:84%
So each of these,
if we take i sub

01:14:02.740 --> 01:14:09.490 align:middle line:84%
n to be equal to the integral
from 1 to n of 1 over i

01:14:09.490 --> 01:14:10.780 align:middle line:90%
squared--

01:14:10.780 --> 01:14:14.180 align:middle line:90%
sorry, 1 over x squared dx--

01:14:14.180 --> 01:14:16.780 align:middle line:90%


01:14:16.780 --> 01:14:18.615 align:middle line:90%
what is this integral?

01:14:18.615 --> 01:14:53.200 align:middle line:90%


01:14:53.200 --> 01:14:54.920 align:middle line:90%
Anybody want to evaluate that?

01:14:54.920 --> 01:14:57.730 align:middle line:90%
No, we don't like calculus?

01:14:57.730 --> 01:14:58.250 align:middle line:90%
Me too.

01:14:58.250 --> 01:14:59.542 align:middle line:90%
That's why I'm asking for help.

01:14:59.542 --> 01:15:00.301 align:middle line:90%
Yeah?

01:15:00.301 --> 01:15:03.130 align:middle line:90%
AUDIENCE: [INAUDIBLE]

01:15:03.130 --> 01:15:06.225 align:middle line:84%
BRYNMOR CHAPMAN: Yeah,
1 minus 1 over n.

01:15:06.225 --> 01:15:10.090 align:middle line:90%


01:15:10.090 --> 01:15:11.480 align:middle line:90%
Why are you laughing at me?

01:15:11.480 --> 01:15:13.210 align:middle line:90%
That's so rude.

01:15:13.210 --> 01:15:15.580 align:middle line:90%
Oh, come on, guys.

01:15:15.580 --> 01:15:18.290 align:middle line:84%
So we know what these
partial sums are,

01:15:18.290 --> 01:15:21.670 align:middle line:84%
or we have approximations
for these partial sums.

01:15:21.670 --> 01:15:27.023 align:middle line:84%
So the partial sum s sub n is
going to be bounded on one side

01:15:27.023 --> 01:15:27.523 align:middle line:90%
by--

01:15:27.523 --> 01:15:31.383 align:middle line:90%


01:15:31.383 --> 01:15:32.925 align:middle line:84%
oops, why don't I
write it like this?

01:15:32.925 --> 01:15:36.090 align:middle line:90%


01:15:36.090 --> 01:15:42.000 align:middle line:84%
So i sub n plus f of n
less than or equal to s

01:15:42.000 --> 01:15:47.070 align:middle line:84%
sub n less than or equal
to i sub n plus f of 1.

01:15:47.070 --> 01:15:54.335 align:middle line:84%
Now what happens
when we take limits?

01:15:54.335 --> 01:15:57.390 align:middle line:90%


01:15:57.390 --> 01:16:02.050 align:middle line:84%
So weak inequalities
are preserved by limits.

01:16:02.050 --> 01:16:15.060 align:middle line:84%
So the limit of i sub n plus f
of n is going to be less than

01:16:15.060 --> 01:16:20.940 align:middle line:84%
or equal to s, less
than or equal to limit

01:16:20.940 --> 01:16:24.725 align:middle line:90%
of i sub n plus f of 1.

01:16:24.725 --> 01:16:37.661 align:middle line:90%


01:16:37.661 --> 01:16:38.930 align:middle line:90%
Now what does the limit do?

01:16:38.930 --> 01:16:46.680 align:middle line:90%


01:16:46.680 --> 01:16:48.280 align:middle line:90%
Well, we can separate these.

01:16:48.280 --> 01:16:50.345 align:middle line:90%
What's the limit of i sub n?

01:16:50.345 --> 01:16:54.510 align:middle line:90%


01:16:54.510 --> 01:16:57.090 align:middle line:90%
Yeah?

01:16:57.090 --> 01:16:59.730 align:middle line:84%
AUDIENCE: 1 minus
infinity or [INAUDIBLE].

01:16:59.730 --> 01:17:03.840 align:middle line:84%
BRYNMOR CHAPMAN: 1 minus 1
divided by infinity, basically.

01:17:03.840 --> 01:17:09.570 align:middle line:84%
So as n goes to infinity,
this 1 over n term disappears.

01:17:09.570 --> 01:17:15.570 align:middle line:84%
So this part is
just going to be 1.

01:17:15.570 --> 01:17:17.375 align:middle line:90%
What's the limit of f of n?

01:17:17.375 --> 01:17:21.630 align:middle line:90%


01:17:21.630 --> 01:17:23.130 align:middle line:90%
Yeah?

01:17:23.130 --> 01:17:24.630 align:middle line:90%
AUDIENCE: [INAUDIBLE]

01:17:24.630 --> 01:17:26.626 align:middle line:90%
BRYNMOR CHAPMAN: Also infinity.

01:17:26.626 --> 01:17:27.600 align:middle line:90%
AUDIENCE: It's also 0.

01:17:27.600 --> 01:17:29.040 align:middle line:90%
BRYNMOR CHAPMAN: Yeah, 0.

01:17:29.040 --> 01:17:33.360 align:middle line:90%


01:17:33.360 --> 01:17:35.190 align:middle line:84%
Less than or equal
to s less than

01:17:35.190 --> 01:17:39.600 align:middle line:84%
or equal to-- we just
established that this is 1.

01:17:39.600 --> 01:17:40.520 align:middle line:90%
What's f of 1?

01:17:40.520 --> 01:17:43.360 align:middle line:90%


01:17:43.360 --> 01:17:43.860 align:middle line:90%
1.

01:17:43.860 --> 01:17:49.470 align:middle line:90%


01:17:49.470 --> 01:17:53.083 align:middle line:90%
So we have an approximation.

01:17:53.083 --> 01:17:53.750 align:middle line:90%
It's a good one.

01:17:53.750 --> 01:17:59.910 align:middle line:90%


01:17:59.910 --> 01:18:01.870 align:middle line:84%
I'm seeing some people
like, yeah, good enough,

01:18:01.870 --> 01:18:03.540 align:middle line:90%
let's just go home.

01:18:03.540 --> 01:18:07.560 align:middle line:84%
Some people like, what the hell,
we're off by a factor of 2.

01:18:07.560 --> 01:18:12.672 align:middle line:84%
Yeah, it's between 1
and 2-- not so great.

01:18:12.672 --> 01:18:14.255 align:middle line:84%
Any ideas how we
could make it better?

01:18:14.255 --> 01:18:21.090 align:middle line:90%


01:18:21.090 --> 01:18:22.880 align:middle line:84%
How can we make our
bounds more precise?

01:18:22.880 --> 01:18:38.060 align:middle line:90%


01:18:38.060 --> 01:18:40.470 align:middle line:84%
Maybe if we go back
to the picture,

01:18:40.470 --> 01:18:42.820 align:middle line:84%
it'll be a little
bit easier to see.

01:18:42.820 --> 01:18:54.980 align:middle line:90%


01:18:54.980 --> 01:18:57.590 align:middle line:84%
This lack of precision
is coming from the fact

01:18:57.590 --> 01:19:02.540 align:middle line:84%
that we're looking at the
difference between these two

01:19:02.540 --> 01:19:04.110 align:middle line:90%
step functions.

01:19:04.110 --> 01:19:09.740 align:middle line:84%
So the farther apart they are,
the worse our approximation

01:19:09.740 --> 01:19:10.910 align:middle line:90%
is going to be.

01:19:10.910 --> 01:19:18.020 align:middle line:84%
So if we just forget
about the first few terms,

01:19:18.020 --> 01:19:22.730 align:middle line:84%
compute those exactly, and
then just approximate the rest,

01:19:22.730 --> 01:19:26.090 align:middle line:84%
we're going to end up
with a more precise bound.

01:19:26.090 --> 01:19:43.190 align:middle line:84%
So if, instead, we say, s equals
1 plus 1/4 plus 1/9 plus the sum

01:19:43.190 --> 01:19:53.755 align:middle line:84%
from i equals 1 to infinity
of 1 over i plus 3 squared--

01:19:53.755 --> 01:19:58.910 align:middle line:90%


01:19:58.910 --> 01:20:00.085 align:middle line:90%
sorry, it's a bit crowded.

01:20:00.085 --> 01:20:06.420 align:middle line:90%


01:20:06.420 --> 01:20:08.350 align:middle line:84%
Now, what happens if we
approximate this sum?

01:20:08.350 --> 01:20:19.520 align:middle line:90%


01:20:19.520 --> 01:20:20.770 align:middle line:90%
How close are we going to get?

01:20:20.770 --> 01:20:56.300 align:middle line:90%


01:20:56.300 --> 01:21:04.820 align:middle line:84%
Well, our error term,
remember, was just

01:21:04.820 --> 01:21:08.570 align:middle line:90%
the first term in our series.

01:21:08.570 --> 01:21:14.960 align:middle line:84%
We are going to be between the
integral and the integral plus

01:21:14.960 --> 01:21:17.840 align:middle line:90%
the first term.

01:21:17.840 --> 01:21:23.860 align:middle line:84%
Here, the first term
is much smaller.

01:21:23.860 --> 01:21:26.530 align:middle line:90%
So this time, we've got--

01:21:26.530 --> 01:21:27.440 align:middle line:90%
what is it?

01:21:27.440 --> 01:21:30.010 align:middle line:90%
1 over 16.

01:21:30.010 --> 01:21:35.090 align:middle line:84%
So instead of being
between i and i plus 1,

01:21:35.090 --> 01:21:42.310 align:middle line:84%
we're now between i and i plus
1 over 16 for a different i--

01:21:42.310 --> 01:21:43.540 align:middle line:90%
same i?

01:21:43.540 --> 01:21:44.810 align:middle line:90%
No, different i.

01:21:44.810 --> 01:21:49.180 align:middle line:90%


01:21:49.180 --> 01:21:51.610 align:middle line:84%
Does that make
sense to everybody?

01:21:51.610 --> 01:21:53.330 align:middle line:84%
So if you want a
better approximation,

01:21:53.330 --> 01:21:55.540 align:middle line:84%
just strip some
terms of the front

01:21:55.540 --> 01:22:01.630 align:middle line:84%
and approximate the tail of the
sum instead of the entire thing.

01:22:01.630 --> 01:22:05.200 align:middle line:84%
So that's all we
have time for today.

01:22:05.200 --> 01:22:05.980 align:middle line:90%
Let's see.

01:22:05.980 --> 01:22:08.110 align:middle line:84%
I'm not sure if we
we'll see you next week.

01:22:08.110 --> 01:22:09.830 align:middle line:90%
Somebody will see you next week.

01:22:09.830 --> 01:22:12.910 align:middle line:90%
Zach we'll see you next week.

01:22:12.910 --> 01:22:14.930 align:middle line:84%
Feel free to come up if
you have any questions.

01:22:14.930 --> 01:22:16.590 align:middle line:90%
Yeah?

01:22:16.590 --> 01:22:21.000 align:middle line:90%