WEBVTT

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[SQUEAKING]

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[RUSTLING]

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[CLICKING]

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PROFESSOR: So what
I'd like to do today

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is talk about an
entirely different class

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of switching power converter
than we've talked about before.

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And we are going to--

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we are going to look at-- for
this class and next class,

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we're going to talk about
switched capacitor converters.

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And that's Principles of
Power Electronics chapter six.

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Most converters introduce
magnetics in them.

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They have some magnetic
component in them.

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Why do you want it?

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Why do you want, say, an
inductor or an inductive energy

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storage element
in your converter?

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That's because if I put a
voltage difference across it,

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from, say, an input voltage
or an output voltage or two

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voltages, the inductor
can instantaneously

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take that energy difference,
absorb the voltage difference,

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absorb energy, then
we can recover later.

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And that's the
principle we operate on.

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And that's why almost
all of these converters

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use magnetics or something that
acts like a magnetic component.

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On the other hand,
sometimes, you

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can get away without
any magnetic components,

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without any inductors
in your circuit.

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And why might you
want to do that?

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Well, because if
you look at things

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that are on the scale of
my thumb or something,

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some small element,
the energy density

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you can achieve with a
capacitor is orders of magnitude

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higher than the
energy density you

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can achieve with a
magnetic component

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at similar efficiencies
and energy storage levels.

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So capacitors are just
extremely highly energy dense.

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So if I happen to have an
application where I can get away

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with only capacitive
energy storage,

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you can build a much smaller,
more efficient converter.

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But that application
space is limited.

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And we're going to get into why.

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So switch capacitor
converters are essentially--

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to come back to their
definition-- are essentially

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converters where I process all
my energy using capacitors.

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And so I have
capacitors and switches

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to do the energy throughput.

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I've brought a couple
of examples with these.

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These are both kind
of prototype designs.

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This one is a very small
power, low power one.

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You'll see much of
it on the front,

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and it has some energy storage
capacitors on the back.

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This is another overall
circuit, and this part over here

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is a switch capacitor
converter of a certain type.

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So just to illustrate
what we're talking about,

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you can take a look at these.

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And so in order to illustrate
their strengths and weaknesses,

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let's look at the
simplest switch capacitor

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converter I can think of.

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And this is sometimes known as
a 2-to-1 step-down converter,

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although we'll come back
to why people call it that,

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but what its tradeoffs are.

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So here's the idea.

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Suppose I had some
input voltage from which

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I'm going to draw power, and I'm
going to have a capacitor here.

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And this capacitor is my
energy transfer capacitor.

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So here c, ic, and vc.

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So, in this example
I'm going to do,

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this element is
where I'm storing

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the energy in the
intermediate form

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to do this energy processing.

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So I'll have switches.

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And then I will have
delivered to some output.

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And I'm going to call
this c big-- this

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is like my filter capacitor.

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And then, here, I have
some output current.

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This is the load current.

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And this is v out.

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So I'm going to have these two
capacitors, these two switches,

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and these are
phase one switches.

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Then I'm going to put
two more switches in.

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I'm going to call these
phase two switches.

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So here's one,
one, and two, two.

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And the idea here
is that we're going

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to alternately take the
switches that are labeled 1

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and close them together.

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And then, at some other
point in the cycle,

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we're going to
open those switches

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and close the switches that
are labeled 2 together.

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And what you're
going to see-- one

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of the characteristics of
switched capacitor converters,

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they tend to have
a lot of switches.

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And, in fact, if you want
high conversion ratios,

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they have lots of switches
and lots of capacitors.

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We'll talk about that
a little bit more.

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So this beast in the
box here, if you will--

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I don't know, you can
include the output capacitor,

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I suppose--

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is the simplest switch capacitor
or converter I can think of.

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To analyze it, let
me just simplify it.

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I'm going to think about this as
a really big output capacitor.

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So for the moment, let
me just replace them

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with a voltage source v out.

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So for my analysis, I'm going
to simplify this just a little,

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and I'll say we have
an input voltage v in.

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Here's my capacitor vc,
ic, c, my two switches.

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I'm just going to replace this
with an output voltage, v out.

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And then I'm going to have this
is switch 1, switch 1, switch

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2, and switch 2.

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And this is the circuit
we're going to analyze.

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So in state 1, I basically
have these two switches closed.

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So in state 1, the
converter looks like this--

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v in.

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Our first switch
is going to be on.

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I'll call that R switch.

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Then I'm going to
have my capacitor.

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And then I'm going to
have my second switch.

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And then that's going
to go to the output.

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And in my second
state, state 2--

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the input's now going
to be disconnected.

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But I am going to connect my
capacitor through a resistor

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to the output, like this.

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Any questions about the
two switch configurations?

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Let's just, for
simplicity, assume

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I'm going to flop back
and forth at 50% duty

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cycle between these two
states, although we'll see,

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in some cases, the
duty cycle matters.

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In some cases it doesn't.

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All right, any questions?

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Yeah?

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AUDIENCE: So in
this case, we can't

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deal with [INAUDIBLE] switches.

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We have to think
about the [INAUDIBLE].

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PROFESSOR: It helps to think
about the parasitic resistance

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because we were going to
worry about how much energy we

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dissipate in the switches.

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But if I let the switch
resistances go to 0,

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the answer doesn't
change, actually.

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So, yeah, we'll come
back to that point.

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So let's think about this
now in order to analyze this.

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What I'd like to
do is focus on--

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here, I have v in.

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Here's v in.

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Let me talk about the
current i in going into v in.

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And here, I have v out.

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And here's i out.

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And then I have vc and ic.

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I guess I should have drawn
this on the main circuit.

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So this is v in, i in, v
out, i out, and vc, ic.

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And what I would like to
do is track the charge

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flowing through this converter.

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which is going to
let me understand

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what its conversion ratio is.

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And analyzing any switch
capacitor converter more or less

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comes down to the
process I'm following.

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There are ways that
we can organize

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it to do the general case.

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But let's just think
about this case.

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And what I'm going
to think about

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is let's suppose that
when I close the switches

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and I have some
switch resistances,

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the values don't matter.

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But let's ask what does the
final voltage of the capacitor

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end up at?

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So at the end of
state 1, what I'm

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going to assume for
my first analysis--

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and this is what's known as
the slow switching limit--

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is that I close my
switches, and this capacitor

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charges to some final value
and then stops charging.

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So what would be the final value
of the capacitor in this state

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1?

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So vc at the-- and
state 1 at the end.

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What voltage would vc charge to?

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Has to be v in minus v out.

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And in state 2, at the
end, correspondingly, vc

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has to go to v out.

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So the idea is if I looked
at what vc was going to do,

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it's going to start off
when I enter state 1--

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or [INAUDIBLE] state 2
I'm going to be at v out.

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I'm going to flip my
switches, and then vc

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is going to charge
to v in minus v out.

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And I'm going to
switch my switches.

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Then, vc is going to discharge
in this case back to v out

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and it's going to repeat.

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That makes sense to everybody?

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So I'm assuming-- and this
is the slow switching limit--

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that what my capacitor voltage
is going to do versus time--

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if this is state 1
and this is state 2,

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I'm going to basically--
my capacitor is

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going to charge from v out
up to v in minus v out.

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And then it's going to
charge from v in minus v

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out, down to v
out, and it's going

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to do something like this
with some Rc time constant.

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And so I'm just assuming--
so this is going to--

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at the end of state 1, it's
going to v in minus v out.

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And then, in the next
state, in state 2,

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it's going to charge to v out.

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So my only assumption is
I'm going to-- each cycle,

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I'm going to charge up,
I'm going to charge down,

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and I'm going to
finish the charging.

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I'm going to let
this Rc time constant

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go to where he's fully charged.

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So let's think about
how much charge

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I transfer in each component.

00:12:47.210 --> 00:12:55.260 align:middle line:90%
In state 1, what do I have?

00:12:55.260 --> 00:12:59.420 align:middle line:90%
Delta qc in state 1--

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the amount of charge that
gets put onto the capacitor

00:13:03.410 --> 00:13:04.380 align:middle line:90%
in state 1.

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Well, what's that going to be?

00:13:05.630 --> 00:13:07.220 align:middle line:90%
That's going to be equal to--

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delta q is c delta
v, which is going

00:13:13.700 --> 00:13:18.510 align:middle line:84%
to be c times the change
in voltage across state 1.

00:13:18.510 --> 00:13:21.800 align:middle line:84%
He's starting at v out, and he's
going up to v in minus v out.

00:13:21.800 --> 00:13:26.510 align:middle line:84%
So it's going to be v in minus
v out minus v out is going to be

00:13:26.510 --> 00:13:30.060 align:middle line:90%
c times v in minus 2 v out.

00:13:30.060 --> 00:13:32.840 align:middle line:90%


00:13:32.840 --> 00:13:39.500 align:middle line:84%
So that's how much charge
gets put on to this capacitor

00:13:39.500 --> 00:13:44.070 align:middle line:84%
during state 1 in
periodic steady state.

00:13:44.070 --> 00:13:45.840 align:middle line:90%
Any questions about that?

00:13:45.840 --> 00:13:48.460 align:middle line:84%
Because the rest of the analysis
proceeds just like this.

00:13:48.460 --> 00:13:53.350 align:middle line:84%
So I want to make sure people
get what I'm calculating.

00:13:53.350 --> 00:13:56.542 align:middle line:84%
NPSS-- I charge and
discharge between two points.

00:13:56.542 --> 00:13:58.000 align:middle line:84%
And I'm just saying
how much charge

00:13:58.000 --> 00:14:02.110 align:middle line:84%
went on to the capacitor
in state 1, and that's it.

00:14:02.110 --> 00:14:10.970 align:middle line:84%
Well, how much charge went
into the input in state 1?

00:14:10.970 --> 00:14:14.150 align:middle line:84%
Well, the way I've defined
it here, the input--

00:14:14.150 --> 00:14:17.000 align:middle line:84%
and I've defined here
because the general analysis

00:14:17.000 --> 00:14:18.470 align:middle line:90%
tend to do it this way--

00:14:18.470 --> 00:14:20.717 align:middle line:84%
is the current going
in the capacitor

00:14:20.717 --> 00:14:22.550 align:middle line:84%
is exactly the opposite
of the current going

00:14:22.550 --> 00:14:23.790 align:middle line:90%
into the input in state 1.

00:14:23.790 --> 00:14:27.440 align:middle line:84%
So the current-- the
charge into the input

00:14:27.440 --> 00:14:28.690 align:middle line:90%
just has to be the opposite.

00:14:28.690 --> 00:14:35.270 align:middle line:84%
This is going to be minus
c v in minus 2 v out.

00:14:35.270 --> 00:14:39.950 align:middle line:84%
And likewise, the charge that
got transferred into the output

00:14:39.950 --> 00:14:43.310 align:middle line:84%
during state 1 is exactly
equal to the charge

00:14:43.310 --> 00:14:45.780 align:middle line:84%
in the capacity that
transferred onto the capacitor.

00:14:45.780 --> 00:14:53.600 align:middle line:84%
And I get delta q out in state
1 is equal to c v in minus 2

00:14:53.600 --> 00:14:54.180 align:middle line:90%
v out.

00:14:54.180 --> 00:14:57.230 align:middle line:90%


00:14:57.230 --> 00:15:00.510 align:middle line:84%
Does that make
sense to everybody?

00:15:00.510 --> 00:15:03.890 align:middle line:90%
Any questions?

00:15:03.890 --> 00:15:05.440 align:middle line:90%
Let's think about state 2.

00:15:05.440 --> 00:15:11.950 align:middle line:90%


00:15:11.950 --> 00:15:16.930 align:middle line:84%
Delta q c-- how much charge
goes on the capacitor in state 2

00:15:16.930 --> 00:15:19.670 align:middle line:90%
is equal to c delta v?

00:15:19.670 --> 00:15:22.960 align:middle line:84%
Well, in state 2, I started
at v in minus v out,

00:15:22.960 --> 00:15:24.550 align:middle line:90%
and I ended at v out.

00:15:24.550 --> 00:15:27.700 align:middle line:84%
So it's going to be
v in minus v out,

00:15:27.700 --> 00:15:31.490 align:middle line:84%
minus v out is what
I'm going to get.

00:15:31.490 --> 00:15:40.975 align:middle line:84%
But keep in mind that
I could write this--

00:15:40.975 --> 00:15:44.800 align:middle line:90%


00:15:44.800 --> 00:15:46.300 align:middle line:84%
the charge that's
going to-- he's

00:15:46.300 --> 00:15:50.690 align:middle line:84%
going to end up at v out
minus v in minus v out.

00:15:50.690 --> 00:15:53.120 align:middle line:84%
So it's v out minus
v in minus v out.

00:15:53.120 --> 00:15:56.020 align:middle line:90%
It's 2 v out minus v in times c.

00:15:56.020 --> 00:16:06.820 align:middle line:84%
But I could write that as minus
c times v in minus 2 v out.

00:16:06.820 --> 00:16:09.482 align:middle line:84%
And the reason I'm going
to write-- first of all,

00:16:09.482 --> 00:16:10.940 align:middle line:84%
does everybody get
what I just did?

00:16:10.940 --> 00:16:16.450 align:middle line:84%
All I did was I just expressed
it as a with a minus sign

00:16:16.450 --> 00:16:16.950 align:middle line:90%
out here.

00:16:16.950 --> 00:16:18.325 align:middle line:84%
I pulled the minus
sign out here.

00:16:18.325 --> 00:16:19.970 align:middle line:84%
Why did I pull the
minus sign out here?

00:16:19.970 --> 00:16:24.580 align:middle line:84%
Because I want to emphasize
that this is going

00:16:24.580 --> 00:16:26.800 align:middle line:90%
to be a negative net charge.

00:16:26.800 --> 00:16:30.190 align:middle line:84%
Or another way I ought to
think about it is, look,

00:16:30.190 --> 00:16:33.910 align:middle line:84%
I'm running this converter
back and forth between state 1

00:16:33.910 --> 00:16:35.930 align:middle line:84%
and state 2 in
periodic steady state.

00:16:35.930 --> 00:16:39.880 align:middle line:84%
What is the net
charge that I'm going

00:16:39.880 --> 00:16:42.010 align:middle line:84%
to transfer through
the capacitor

00:16:42.010 --> 00:16:45.010 align:middle line:90%
in periodic steady state?

00:16:45.010 --> 00:16:46.540 align:middle line:90%
0.

00:16:46.540 --> 00:16:51.850 align:middle line:84%
So that means that delta q
c 1 is a charge transferred

00:16:51.850 --> 00:16:54.975 align:middle line:84%
onto the capacitor in
state 1 plus delta q, c 2,

00:16:54.975 --> 00:16:57.100 align:middle line:84%
the charge transfer onto
the capacitor in state 2--

00:16:57.100 --> 00:16:58.400 align:middle line:90%
better add to 0.

00:16:58.400 --> 00:17:00.760 align:middle line:84%
And you can see that it
does if I write it this way.

00:17:00.760 --> 00:17:05.089 align:middle line:84%
It's c v in minus 2 v out plus
minus c v in minus 2 v out.

00:17:05.089 --> 00:17:06.339 align:middle line:90%
So they add to 0.

00:17:06.339 --> 00:17:08.440 align:middle line:84%
So indeed, if I
made the assumption

00:17:08.440 --> 00:17:11.800 align:middle line:84%
that it's charged to its
initial and final states,

00:17:11.800 --> 00:17:15.130 align:middle line:84%
this does satisfy the periodic
steady state requirements

00:17:15.130 --> 00:17:16.910 align:middle line:90%
on the capacitor.

00:17:16.910 --> 00:17:20.220 align:middle line:90%
Any questions about that?

00:17:20.220 --> 00:17:21.599 align:middle line:90%
So let's just say--

00:17:21.599 --> 00:17:27.110 align:middle line:84%
what happens-- what's
delta q in in state 2?

00:17:27.110 --> 00:17:30.420 align:middle line:90%


00:17:30.420 --> 00:17:31.505 align:middle line:90%
Anybody tell me that?

00:17:31.505 --> 00:17:34.700 align:middle line:90%


00:17:34.700 --> 00:17:36.500 align:middle line:90%
This is v in.

00:17:36.500 --> 00:17:38.450 align:middle line:90%
This is i in.

00:17:38.450 --> 00:17:43.870 align:middle line:84%
How much charge is transferred
into the input in state 2?

00:17:43.870 --> 00:17:44.710 align:middle line:90%
AUDIENCE: None.

00:17:44.710 --> 00:17:48.670 align:middle line:84%
PROFESSOR: 0-- no charge
transferred in the input.

00:17:48.670 --> 00:17:55.630 align:middle line:84%
How much charge is transferred
to the output in state 2?

00:17:55.630 --> 00:17:58.280 align:middle line:90%


00:17:58.280 --> 00:18:04.190 align:middle line:84%
Well, this is-- let's be
careful about signs here--

00:18:04.190 --> 00:18:05.430 align:middle line:90%
here's v out.

00:18:05.430 --> 00:18:07.070 align:middle line:90%
Here's i out.

00:18:07.070 --> 00:18:11.180 align:middle line:84%
The negative of the
capacitor current

00:18:11.180 --> 00:18:12.510 align:middle line:90%
is going into the output.

00:18:12.510 --> 00:18:14.840 align:middle line:84%
So whatever charge went
into the capacitor,

00:18:14.840 --> 00:18:17.400 align:middle line:84%
the negative of that charge
went into the output.

00:18:17.400 --> 00:18:25.800 align:middle line:84%
So delta q out 2 must be
positive c v in minus 2 v out.

00:18:25.800 --> 00:18:28.840 align:middle line:90%


00:18:28.840 --> 00:18:32.490 align:middle line:84%
Does that make
sense to everybody?

00:18:32.490 --> 00:18:36.090 align:middle line:90%
So what is the--

00:18:36.090 --> 00:18:39.390 align:middle line:84%
we know that the net
total charge transferred

00:18:39.390 --> 00:18:42.480 align:middle line:84%
on this energy storage capacitor
in periodic steady state better

00:18:42.480 --> 00:18:43.500 align:middle line:90%
be 0.

00:18:43.500 --> 00:18:46.210 align:middle line:84%
But that's not true of
the input or the output.

00:18:46.210 --> 00:18:49.770 align:middle line:84%
So why don't we just
find out what that is?

00:18:49.770 --> 00:19:02.880 align:middle line:84%
We could then write delta q in
is equal to q in state 1 plus

00:19:02.880 --> 00:19:07.890 align:middle line:84%
delta q in in state 2 And
if I just add those up,

00:19:07.890 --> 00:19:15.330 align:middle line:84%
that's going to be 2
c v in minus 2 v out.

00:19:15.330 --> 00:19:21.660 align:middle line:84%
And delta q out is going
to be equal to delta q

00:19:21.660 --> 00:19:28.060 align:middle line:84%
out in state 1 and
delta q out in state 2.

00:19:28.060 --> 00:19:36.430 align:middle line:84%
And if I add those up, it's
going to be minus c v in minus 2

00:19:36.430 --> 00:19:38.860 align:middle line:90%
v out.

00:19:38.860 --> 00:19:44.750 align:middle line:84%
Now what's the current
at the input on average?

00:19:44.750 --> 00:19:45.635 align:middle line:90%
Yeah?

00:19:45.635 --> 00:19:50.480 align:middle line:84%
AUDIENCE: Are these
flipped, [INAUDIBLE]?

00:19:50.480 --> 00:19:52.215 align:middle line:90%
PROFESSOR: Yes, thank you.

00:19:52.215 --> 00:19:54.780 align:middle line:90%


00:19:54.780 --> 00:19:57.040 align:middle line:90%
How did I do that?

00:19:57.040 --> 00:20:00.015 align:middle line:84%
Well, it's easier
to do it this way.

00:20:00.015 --> 00:20:04.450 align:middle line:90%


00:20:04.450 --> 00:20:05.560 align:middle line:90%
Thank you.

00:20:05.560 --> 00:20:07.930 align:middle line:90%
Somebody's watching.

00:20:07.930 --> 00:20:13.840 align:middle line:84%
So we have our input
and output net charge.

00:20:13.840 --> 00:20:17.170 align:middle line:84%
If I wanted to talk about
the average current going

00:20:17.170 --> 00:20:21.790 align:middle line:84%
to the input or the output
averaged over a cycle, really,

00:20:21.790 --> 00:20:24.670 align:middle line:84%
it's the charge
divided by the period,

00:20:24.670 --> 00:20:28.080 align:middle line:84%
or equivalently the charge
times the switching frequency.

00:20:28.080 --> 00:20:31.750 align:middle line:84%
So the local average
or the average

00:20:31.750 --> 00:20:35.170 align:middle line:84%
in periodic steady state,
I could infer from this

00:20:35.170 --> 00:20:46.510 align:middle line:84%
is that i in is equal to c
times the switching frequency--

00:20:46.510 --> 00:20:48.160 align:middle line:90%
that's 1 over the period--

00:20:48.160 --> 00:20:52.420 align:middle line:90%
times v in minus 2 v out.

00:20:52.420 --> 00:20:55.420 align:middle line:90%


00:20:55.420 --> 00:20:57.560 align:middle line:84%
And I should put
my minus sign here.

00:20:57.560 --> 00:21:01.930 align:middle line:84%
And that's this is the
current going into the input.

00:21:01.930 --> 00:21:10.150 align:middle line:84%
And likewise, i out is equal to
2 c f switch times v in minus 2

00:21:10.150 --> 00:21:12.760 align:middle line:90%
v out.

00:21:12.760 --> 00:21:17.620 align:middle line:84%
So if you look at this,
the magnitude of i

00:21:17.620 --> 00:21:23.270 align:middle line:84%
out is equal to 2 times
the magnitude of i in.

00:21:23.270 --> 00:21:25.930 align:middle line:90%


00:21:25.930 --> 00:21:27.050 align:middle line:90%
Why?

00:21:27.050 --> 00:21:29.380 align:middle line:84%
Because what happens
is, essentially--

00:21:29.380 --> 00:21:32.300 align:middle line:84%
and what's the deal
with the minus sign?

00:21:32.300 --> 00:21:33.970 align:middle line:84%
The minus sign is
because I chose

00:21:33.970 --> 00:21:35.870 align:middle line:90%
to define i in going this way.

00:21:35.870 --> 00:21:38.500 align:middle line:84%
Had I defined it
going this way, I'd

00:21:38.500 --> 00:21:41.290 align:middle line:84%
have i out is equal
to twice i in.

00:21:41.290 --> 00:21:43.340 align:middle line:84%
But let's just worry
about the magnitudes here.

00:21:43.340 --> 00:21:44.930 align:middle line:90%
So what's going on?

00:21:44.930 --> 00:21:47.320 align:middle line:84%
In the first part
of the cycle, I

00:21:47.320 --> 00:21:50.230 align:middle line:84%
dump a certain amount of charge
from the input to the output

00:21:50.230 --> 00:21:51.380 align:middle line:90%
through the capacitor.

00:21:51.380 --> 00:21:53.400 align:middle line:90%
I charge the capacitor up.

00:21:53.400 --> 00:21:55.320 align:middle line:90%
So that's some amount of charge.

00:21:55.320 --> 00:21:58.410 align:middle line:84%
In the second part of
the cycle, this capacitor

00:21:58.410 --> 00:22:01.710 align:middle line:84%
then dumps that same amount of
charge into the output again.

00:22:01.710 --> 00:22:03.640 align:middle line:84%
So the output gets twice
the amount of charge

00:22:03.640 --> 00:22:05.320 align:middle line:90%
as the input over the cycle.

00:22:05.320 --> 00:22:08.360 align:middle line:84%
And then I go back to the
next cycle and I repeat.

00:22:08.360 --> 00:22:12.740 align:middle line:84%
So whatever the current
coming in from--

00:22:12.740 --> 00:22:14.840 align:middle line:84%
coming into the
converter from the input

00:22:14.840 --> 00:22:16.850 align:middle line:84%
is exactly half
the current going

00:22:16.850 --> 00:22:21.680 align:middle line:84%
to the output by periodic
steady state and charge balance

00:22:21.680 --> 00:22:23.620 align:middle line:90%
on the capacitor.

00:22:23.620 --> 00:22:25.755 align:middle line:90%
Any questions about that?

00:22:25.755 --> 00:22:28.500 align:middle line:90%


00:22:28.500 --> 00:22:32.130 align:middle line:84%
I should say that this is the
defining feature of a switch

00:22:32.130 --> 00:22:34.030 align:middle line:90%
capacitor converter.

00:22:34.030 --> 00:22:39.130 align:middle line:84%
You will always have some
rational relationship--

00:22:39.130 --> 00:22:41.760 align:middle line:84%
"rational" meaning
an actual fraction--

00:22:41.760 --> 00:22:44.610 align:middle line:84%
relating the current from
the input to the current

00:22:44.610 --> 00:22:45.220 align:middle line:90%
on the output.

00:22:45.220 --> 00:22:45.720 align:middle line:90%
Why?

00:22:45.720 --> 00:22:48.065 align:middle line:84%
Because this is a
very simple converter.

00:22:48.065 --> 00:22:50.190 align:middle line:84%
We've got one capacitor
that we're flipping around,

00:22:50.190 --> 00:22:53.250 align:middle line:84%
but generally, you're going to
be taking energy, storing charge

00:22:53.250 --> 00:22:56.230 align:middle line:84%
from the input, doing something,
and throwing it to the output.

00:22:56.230 --> 00:23:01.880 align:middle line:84%
And those are always going to
be related in some rational way.

00:23:01.880 --> 00:23:06.650 align:middle line:84%
So that's what the core
thing that a switch capacitor

00:23:06.650 --> 00:23:08.420 align:middle line:84%
converter do-- is
by charge balance

00:23:08.420 --> 00:23:11.720 align:middle line:84%
is going to give you some
concurrent conversion

00:23:11.720 --> 00:23:13.610 align:middle line:84%
ratio between the
input and the output

00:23:13.610 --> 00:23:17.335 align:middle line:84%
that's fixed by the topology
and the switching sequence.

00:23:17.335 --> 00:23:26.790 align:middle line:90%


00:23:26.790 --> 00:23:29.700 align:middle line:90%
What else can we say about this?

00:23:29.700 --> 00:23:35.290 align:middle line:84%
Well, look at this
relationship here.

00:23:35.290 --> 00:23:38.145 align:middle line:84%
First of all, any questions
about what got me to that?

00:23:38.145 --> 00:23:41.000 align:middle line:90%


00:23:41.000 --> 00:23:41.510 align:middle line:90%
Yeah?

00:23:41.510 --> 00:23:43.853 align:middle line:84%
AUDIENCE: Is this
assuming a 50% duty cycle?

00:23:43.853 --> 00:23:45.270 align:middle line:84%
PROFESSOR: That's
a good question.

00:23:45.270 --> 00:23:50.210 align:middle line:84%
So long as the intervals
are such that I

00:23:50.210 --> 00:23:53.960 align:middle line:84%
fully charge and fully
discharge in each subinterval,

00:23:53.960 --> 00:23:56.270 align:middle line:84%
in state 1 and state 2,
the actual duty ratio

00:23:56.270 --> 00:23:59.300 align:middle line:84%
doesn't matter in this
mode of operation.

00:23:59.300 --> 00:24:01.850 align:middle line:84%
So the only thing
I've assumed is

00:24:01.850 --> 00:24:04.670 align:middle line:84%
that I'm waiting long enough
or in state 1 for the capacitor

00:24:04.670 --> 00:24:06.090 align:middle line:90%
to get to its final voltage.

00:24:06.090 --> 00:24:08.330 align:middle line:84%
And I'm waiting long enough
in state 2 for the pastor

00:24:08.330 --> 00:24:09.597 align:middle line:90%
to get to its final voltage.

00:24:09.597 --> 00:24:11.180 align:middle line:84%
And as long as I've
waited long enough

00:24:11.180 --> 00:24:14.000 align:middle line:84%
in both states, what the actual
fraction of bond times are

00:24:14.000 --> 00:24:16.250 align:middle line:90%
doesn't matter.

00:24:16.250 --> 00:24:17.890 align:middle line:90%
We'll come back to that shortly.

00:24:17.890 --> 00:24:18.570 align:middle line:90%
Yeah?

00:24:18.570 --> 00:24:19.820 align:middle line:90%
AUDIENCE: I've got a question.

00:24:19.820 --> 00:24:23.045 align:middle line:84%
This mode is called the slow
switching [INAUDIBLE], right?

00:24:23.045 --> 00:24:23.670 align:middle line:90%
PROFESSOR: Yes.

00:24:23.670 --> 00:24:28.565 align:middle line:84%
AUDIENCE: And is that why we
didn't include the [INAUDIBLE],

00:24:28.565 --> 00:24:29.390 align:middle line:90%
like effect--

00:24:29.390 --> 00:24:35.090 align:middle line:84%
or those switches there are
represented as resistors,

00:24:35.090 --> 00:24:40.520 align:middle line:84%
so like the charge
doesn't [INAUDIBLE]?

00:24:40.520 --> 00:24:41.810 align:middle line:90%
PROFESSOR: Well, no, it does.

00:24:41.810 --> 00:24:44.560 align:middle line:90%
We've included the resistance.

00:24:44.560 --> 00:24:49.780 align:middle line:84%
All I've said is the
only thing you really

00:24:49.780 --> 00:24:54.340 align:middle line:84%
need to know in this is
where did the capacitor start

00:24:54.340 --> 00:24:56.720 align:middle line:84%
in terms of its voltage
and where did it end?

00:24:56.720 --> 00:25:00.190 align:middle line:84%
And if you know that, then
how much charge went into it.

00:25:00.190 --> 00:25:04.910 align:middle line:84%
So we have actually included
the effect of the resistances.

00:25:04.910 --> 00:25:06.600 align:middle line:90%
It's those Rc charging things.

00:25:06.600 --> 00:25:08.750 align:middle line:84%
If the resistances
get small, I just

00:25:08.750 --> 00:25:11.960 align:middle line:90%
make those Rc charging shorter.

00:25:11.960 --> 00:25:13.430 align:middle line:90%
AUDIENCE: I see, thanks.

00:25:13.430 --> 00:25:16.970 align:middle line:84%
But wouldn't on-state
and off-state voltages

00:25:16.970 --> 00:25:21.020 align:middle line:84%
change, like wouldn't there
be potential differences

00:25:21.020 --> 00:25:22.010 align:middle line:90%
across the resistors?

00:25:22.010 --> 00:25:27.320 align:middle line:84%
PROFESSOR: Well, if I've assumed
that the capacitor is fully

00:25:27.320 --> 00:25:31.430 align:middle line:84%
charged, the voltage across this
resistor went to 0 by the end.

00:25:31.430 --> 00:25:34.860 align:middle line:84%
So the only assumption I've
made is this capacitor charges.

00:25:34.860 --> 00:25:36.570 align:middle line:84%
Once the capacitor
current goes to 0,

00:25:36.570 --> 00:25:39.430 align:middle line:90%
these voltage drops go to 0.

00:25:39.430 --> 00:25:41.190 align:middle line:84%
We'll relax that
assumption shortly.

00:25:41.190 --> 00:25:43.760 align:middle line:90%


00:25:43.760 --> 00:25:46.130 align:middle line:84%
So let me start from
this relationship,

00:25:46.130 --> 00:25:48.890 align:middle line:84%
and let me see if
I can give you what

00:25:48.890 --> 00:25:50.610 align:middle line:90%
the voltage relationship is.

00:25:50.610 --> 00:25:54.260 align:middle line:84%
I've told you here, this
is the current relationship

00:25:54.260 --> 00:25:55.670 align:middle line:90%
of the converter.

00:25:55.670 --> 00:25:59.900 align:middle line:84%
That's the fundamental thing
that this converter does.

00:25:59.900 --> 00:26:03.020 align:middle line:84%
Well, how are the input
and output voltage related?

00:26:03.020 --> 00:26:05.720 align:middle line:90%
Well, that's by this guy here.

00:26:05.720 --> 00:26:08.220 align:middle line:90%
And I can rearrange this.

00:26:08.220 --> 00:26:11.870 align:middle line:84%
So all I could do is
maybe solve for v out.

00:26:11.870 --> 00:26:14.300 align:middle line:84%
And if I solve this
equation for v out,

00:26:14.300 --> 00:26:23.510 align:middle line:84%
what I'm going to get is v out
is equal to 1/2 of v in minus 1

00:26:23.510 --> 00:26:30.265 align:middle line:90%
over 4 f switch c times i out.

00:26:30.265 --> 00:26:32.810 align:middle line:90%


00:26:32.810 --> 00:26:35.965 align:middle line:84%
This is an equivalent
statement as this.

00:26:35.965 --> 00:26:40.442 align:middle line:90%


00:26:40.442 --> 00:26:45.600 align:middle line:84%
So what does that mean
as in a practical matter?

00:26:45.600 --> 00:26:50.280 align:middle line:84%
Well, let me create for you
an equivalent circuit which

00:26:50.280 --> 00:26:59.940 align:middle line:84%
does this same thing, So I
told you, this is my converter.

00:26:59.940 --> 00:27:01.950 align:middle line:84%
If I wanted a
periodic steady state

00:27:01.950 --> 00:27:05.210 align:middle line:84%
model for what this thing does,
I have some input voltage.

00:27:05.210 --> 00:27:10.470 align:middle line:90%


00:27:10.470 --> 00:27:15.510 align:middle line:84%
And then I have some load
current connected to it

00:27:15.510 --> 00:27:17.310 align:middle line:90%
that I'm going to call i out.

00:27:17.310 --> 00:27:19.690 align:middle line:84%
What is the relationship
between what's in there?

00:27:19.690 --> 00:27:21.250 align:middle line:90%
It's defined by this.

00:27:21.250 --> 00:27:23.820 align:middle line:84%
Well, here's a
circuit that gives you

00:27:23.820 --> 00:27:25.440 align:middle line:90%
this same relationship.

00:27:25.440 --> 00:27:32.840 align:middle line:84%
If I had an ideal
2-to-1 transformer,

00:27:32.840 --> 00:27:36.590 align:middle line:84%
if this is v in, this
voltage would be half v

00:27:36.590 --> 00:27:40.880 align:middle line:84%
in because that's what
the transformer does.

00:27:40.880 --> 00:27:45.110 align:middle line:84%
And then I would have
an equivalent resistance

00:27:45.110 --> 00:27:48.650 align:middle line:84%
that would give me a voltage
drop that was i out times 1

00:27:48.650 --> 00:27:50.040 align:middle line:90%
over 4 f switch.

00:27:50.040 --> 00:27:55.520 align:middle line:84%
So I'd have an equivalent
resistance of 1 over 4

00:27:55.520 --> 00:27:59.070 align:middle line:90%
f switch c.

00:27:59.070 --> 00:28:01.090 align:middle line:84%
And I could put this
whole thing in a box.

00:28:01.090 --> 00:28:05.110 align:middle line:90%


00:28:05.110 --> 00:28:10.060 align:middle line:84%
And this is a DC
equivalent model

00:28:10.060 --> 00:28:12.040 align:middle line:90%
for how this thing behaves.

00:28:12.040 --> 00:28:15.045 align:middle line:90%
In other words, this is v out.

00:28:15.045 --> 00:28:18.040 align:middle line:90%


00:28:18.040 --> 00:28:20.770 align:middle line:84%
So this gives me the right
relationships between v

00:28:20.770 --> 00:28:22.660 align:middle line:90%
and v out.

00:28:22.660 --> 00:28:32.290 align:middle line:84%
v out is half v in
minus the voltage drop

00:28:32.290 --> 00:28:36.400 align:middle line:84%
across this which is i
out over 4 c f switch.

00:28:36.400 --> 00:28:40.360 align:middle line:84%
Likewise, if I have a current
coming i out this way,

00:28:40.360 --> 00:28:43.510 align:middle line:84%
the current this way through
the ideal transformer

00:28:43.510 --> 00:28:45.700 align:middle line:84%
is going to be
exactly half of that.

00:28:45.700 --> 00:28:50.510 align:middle line:84%
And that means the current
this way is minus 1/2 i out.

00:28:50.510 --> 00:28:53.980 align:middle line:84%
So this model in
yellow here precisely

00:28:53.980 --> 00:28:58.723 align:middle line:84%
captures the average circuit
behavior of this system.

00:28:58.723 --> 00:29:00.140 align:middle line:84%
Does that make
sense to everybody?

00:29:00.140 --> 00:29:02.710 align:middle line:90%


00:29:02.710 --> 00:29:05.740 align:middle line:90%
Now this is this converter.

00:29:05.740 --> 00:29:08.860 align:middle line:84%
Any other switch capacitor
converter I want to model,

00:29:08.860 --> 00:29:15.970 align:middle line:84%
you can model likewise as some
ideal transformer relationship.

00:29:15.970 --> 00:29:18.920 align:middle line:84%
This gives me my current
conversion ratio.

00:29:18.920 --> 00:29:21.580 align:middle line:84%
The input and the
output current are

00:29:21.580 --> 00:29:26.650 align:middle line:84%
related by the ideal transformer
and then a voltage drop that's

00:29:26.650 --> 00:29:31.690 align:middle line:84%
related by some equivalent
resistance that's

00:29:31.690 --> 00:29:34.420 align:middle line:84%
related to the energy transfer
capacitors and the switching

00:29:34.420 --> 00:29:36.010 align:middle line:90%
frequency.

00:29:36.010 --> 00:29:38.680 align:middle line:84%
So the details will vary,
but this model really

00:29:38.680 --> 00:29:41.380 align:middle line:90%
captures what's going on.

00:29:41.380 --> 00:29:45.220 align:middle line:84%
Now if I said, well,
what's a what's an--

00:29:45.220 --> 00:29:47.440 align:middle line:84%
if I wanted to just look
back from the output

00:29:47.440 --> 00:29:49.810 align:middle line:84%
and get Thevenin equivalent
looking backwards,

00:29:49.810 --> 00:29:51.730 align:middle line:90%
all I would see is--

00:29:51.730 --> 00:29:54.220 align:middle line:84%
another way to think
about this is one half v

00:29:54.220 --> 00:29:57.670 align:middle line:90%
in as a Thevenin voltage.

00:29:57.670 --> 00:30:04.330 align:middle line:84%
And a Thevenin resistance would
be Req is equal to 1 over 4

00:30:04.330 --> 00:30:07.420 align:middle line:90%
f switch c.

00:30:07.420 --> 00:30:10.360 align:middle line:84%
This is a Thevenin
equivalent model

00:30:10.360 --> 00:30:13.300 align:middle line:84%
looking back into the
switch capacitor converter

00:30:13.300 --> 00:30:15.710 align:middle line:90%
from at least a DC.

00:30:15.710 --> 00:30:17.630 align:middle line:90%
This is legitimate.

00:30:17.630 --> 00:30:21.510 align:middle line:84%
Does that make
sense to everybody?

00:30:21.510 --> 00:30:27.570 align:middle line:84%
Now we could say, what's the
efficiency of the converter?

00:30:27.570 --> 00:30:40.050 align:middle line:84%
Well, the efficiency is
equal to v out i out divided

00:30:40.050 --> 00:30:44.890 align:middle line:90%
by v in or minus v in i in.

00:30:44.890 --> 00:30:55.140 align:middle line:84%
And since i out is
twice minus i in,

00:30:55.140 --> 00:31:03.195 align:middle line:84%
this would be equal to
2 times v out over v in.

00:31:03.195 --> 00:31:06.920 align:middle line:90%


00:31:06.920 --> 00:31:13.360 align:middle line:84%
And we have an expression
for v out right here.

00:31:13.360 --> 00:31:20.110 align:middle line:84%
I could write this as also
equal to v out over 1/2 v in.

00:31:20.110 --> 00:31:24.280 align:middle line:84%
So to the extent that v out
is smaller than half v in,

00:31:24.280 --> 00:31:26.450 align:middle line:90%
the efficiency is less than 1.

00:31:26.450 --> 00:31:29.770 align:middle line:84%
Well, we can see that
the output is smaller

00:31:29.770 --> 00:31:33.960 align:middle line:84%
than half v in by whatever
drop is across this resistor.

00:31:33.960 --> 00:31:38.770 align:middle line:84%
So this model is actually
useful for calculating--

00:31:38.770 --> 00:31:41.670 align:middle line:84%
this model is actually useful
for calculating efficiency

00:31:41.670 --> 00:31:42.660 align:middle line:90%
as well.

00:31:42.660 --> 00:31:44.560 align:middle line:90%
And I could rewrite that.

00:31:44.560 --> 00:31:47.295 align:middle line:84%
If I plug that in,
what I would get is--

00:31:47.295 --> 00:31:50.280 align:middle line:90%


00:31:50.280 --> 00:31:56.070 align:middle line:84%
I could rewrite this as the
efficiency simply is equal to 1

00:31:56.070 --> 00:32:03.906 align:middle line:84%
minus i out times
Req over 1/2 v in.

00:32:03.906 --> 00:32:06.620 align:middle line:90%


00:32:06.620 --> 00:32:11.300 align:middle line:84%
This is just illustrating if
my load current goes to 0,

00:32:11.300 --> 00:32:15.480 align:middle line:90%
the efficiency then goes to 1.

00:32:15.480 --> 00:32:19.860 align:middle line:84%
If my load current gets really
big, the output droops down.

00:32:19.860 --> 00:32:23.670 align:middle line:84%
As my output gets really big,
I get a bigger and bigger drop

00:32:23.670 --> 00:32:26.850 align:middle line:84%
across this equivalent
resistor, and my efficiency

00:32:26.850 --> 00:32:29.170 align:middle line:90%
starts to decline.

00:32:29.170 --> 00:32:30.700 align:middle line:90%
Does that make sense, everybody?

00:32:30.700 --> 00:32:33.640 align:middle line:84%
Now, when I'm saying
this, what losses

00:32:33.640 --> 00:32:35.930 align:middle line:84%
am I counting when I'm
calculating this efficiency?

00:32:35.930 --> 00:32:39.460 align:middle line:84%
The losses I'm counting
are essentially

00:32:39.460 --> 00:32:43.570 align:middle line:84%
the resistor losses, the losses
in the switch resistances

00:32:43.570 --> 00:32:46.510 align:middle line:84%
and in the capacitor, like any
parasitics in the capacitor.

00:32:46.510 --> 00:32:53.300 align:middle line:84%
It's what we would call
capacitor charging loss.

00:32:53.300 --> 00:32:57.290 align:middle line:84%
So the only loss
I'm not counting--

00:32:57.290 --> 00:32:59.930 align:middle line:84%
if these switch have gate
drives and the gate drive--

00:32:59.930 --> 00:33:02.060 align:middle line:84%
gate capacitance [INAUDIBLE]
charge and discharge

00:33:02.060 --> 00:33:04.760 align:middle line:84%
or other losses like that
are internal to the switches,

00:33:04.760 --> 00:33:09.050 align:middle line:84%
but the loss associated with
the switches delivering current

00:33:09.050 --> 00:33:11.907 align:middle line:84%
through to charge the capacitor
and discharge the capacitor.

00:33:11.907 --> 00:33:14.240 align:middle line:84%
Now it doesn't matter-- you
notice the switch resistance

00:33:14.240 --> 00:33:15.407 align:middle line:90%
isn't even in here anywhere.

00:33:15.407 --> 00:33:18.770 align:middle line:84%
It doesn't really matter what
the switch resistance is.

00:33:18.770 --> 00:33:22.010 align:middle line:84%
The only constraint
I have is that I

00:33:22.010 --> 00:33:25.700 align:middle line:84%
have to finish charging
and discharging.

00:33:25.700 --> 00:33:28.100 align:middle line:90%
And that's just because of--

00:33:28.100 --> 00:33:30.950 align:middle line:84%
you can do this by
basically charging methods

00:33:30.950 --> 00:33:32.700 align:middle line:90%
to find out the efficiency.

00:33:32.700 --> 00:33:36.485 align:middle line:90%


00:33:36.485 --> 00:33:37.860 align:middle line:84%
AUDIENCE: Could
you say it again,

00:33:37.860 --> 00:33:39.750 align:middle line:84%
where the power is
being dissipated?

00:33:39.750 --> 00:33:44.130 align:middle line:84%
PROFESSOR: The power is
being dissipated in--

00:33:44.130 --> 00:33:48.030 align:middle line:90%
if the only elements--

00:33:48.030 --> 00:33:49.650 align:middle line:84%
I mean, the power
is being dissipated

00:33:49.650 --> 00:33:55.030 align:middle line:84%
in any parasitic resistance in
the charge and discharge path.

00:33:55.030 --> 00:33:59.590 align:middle line:84%
So if I turn the switch on, it
has some voltage drop across it,

00:33:59.590 --> 00:34:02.260 align:middle line:84%
or if the capacitor has
some parasitic resistance,

00:34:02.260 --> 00:34:07.498 align:middle line:90%
it loses some energy in that.

00:34:07.498 --> 00:34:09.040 align:middle line:84%
You say, well, what
happens if I make

00:34:09.040 --> 00:34:10.940 align:middle line:90%
my switch resistance go to 0?

00:34:10.940 --> 00:34:14.139 align:middle line:84%
Well, all that happens is
that the peak charging current

00:34:14.139 --> 00:34:16.429 align:middle line:90%
gets higher.

00:34:16.429 --> 00:34:19.460 align:middle line:90%
And it goes for a shorter time.

00:34:19.460 --> 00:34:21.826 align:middle line:84%
And the total loss
is the same thing.

00:34:21.826 --> 00:34:23.159 align:middle line:90%
So mathematically, it works out.

00:34:23.159 --> 00:34:25.260 align:middle line:84%
The actual value of the
resistance doesn't matter.

00:34:25.260 --> 00:34:27.052 align:middle line:84%
It doesn't even matter
if the resistance is

00:34:27.052 --> 00:34:30.780 align:middle line:84%
linear or nonlinear, but
you get the same net loss.

00:34:30.780 --> 00:34:33.440 align:middle line:84%
So it's basically
the loss that I

00:34:33.440 --> 00:34:36.883 align:middle line:84%
incur in putting the
charge on the capacitor

00:34:36.883 --> 00:34:39.050 align:middle line:84%
and then taking the charge
back off to the capacitor

00:34:39.050 --> 00:34:42.730 align:middle line:84%
to the output-- that's
the loss that's included.

00:34:42.730 --> 00:34:43.420 align:middle line:90%
Yeah?

00:34:43.420 --> 00:34:45.820 align:middle line:84%
AUDIENCE: So if you use a
smaller capacitor, which

00:34:45.820 --> 00:34:47.560 align:middle line:84%
takes less time to
charge your charge,

00:34:47.560 --> 00:34:50.290 align:middle line:90%
can you see smaller losses?

00:34:50.290 --> 00:34:53.980 align:middle line:84%
PROFESSOR: Ah, so if I
wanted to reduce my losses,

00:34:53.980 --> 00:34:57.450 align:middle line:84%
let's go back and look at my
efficiency characteristic.

00:34:57.450 --> 00:35:00.740 align:middle line:84%
If I want smaller losses,
I should make Req small.

00:35:00.740 --> 00:35:05.140 align:middle line:84%
To make R equivalent small,
I should make either c

00:35:05.140 --> 00:35:08.670 align:middle line:90%
big or switching frequency big.

00:35:08.670 --> 00:35:10.080 align:middle line:90%
And the notion is--

00:35:10.080 --> 00:35:13.150 align:middle line:84%
and we'll come back to this and
we'll look at this next class--

00:35:13.150 --> 00:35:15.580 align:middle line:84%
it comes down to the amount
I'm charging and discharging

00:35:15.580 --> 00:35:16.080 align:middle line:90%
the parser.

00:35:16.080 --> 00:35:19.380 align:middle line:84%
When I charge the capacitor over
a small, tiny delta voltage,

00:35:19.380 --> 00:35:21.580 align:middle line:84%
I don't lose much
energy in doing it.

00:35:21.580 --> 00:35:23.940 align:middle line:84%
And so if I want
lower loss, it's

00:35:23.940 --> 00:35:25.720 align:middle line:84%
a very great insight
on your part.

00:35:25.720 --> 00:35:27.387 align:middle line:84%
But if I want lower
loss, I want to make

00:35:27.387 --> 00:35:29.570 align:middle line:84%
the capacitor
bigger, not smaller

00:35:29.570 --> 00:35:31.170 align:middle line:90%
for a given load current.

00:35:31.170 --> 00:35:33.800 align:middle line:90%


00:35:33.800 --> 00:35:39.650 align:middle line:84%
So this model-- in
fact, if I wanted,

00:35:39.650 --> 00:35:41.390 align:middle line:84%
if I put a resistive
load on here,

00:35:41.390 --> 00:35:43.610 align:middle line:84%
the efficiency is exactly
just the efficiency

00:35:43.610 --> 00:35:45.320 align:middle line:90%
of a voltage divider.

00:35:45.320 --> 00:35:49.530 align:middle line:90%
So this is a very good model.

00:35:49.530 --> 00:35:53.120 align:middle line:84%
And the only thing that would
vary if I model any other switch

00:35:53.120 --> 00:35:57.320 align:middle line:84%
capacitor converter would
be this transformer ratio,

00:35:57.320 --> 00:36:00.320 align:middle line:84%
which relates to that perfect
current conversion ratio

00:36:00.320 --> 00:36:03.680 align:middle line:84%
we calculated, and what the
exact value of this output

00:36:03.680 --> 00:36:07.550 align:middle line:84%
resistance would look like,
which is, again dictated

00:36:07.550 --> 00:36:10.220 align:middle line:90%
by the losses.

00:36:10.220 --> 00:36:11.190 align:middle line:90%
Questions?

00:36:11.190 --> 00:36:14.850 align:middle line:90%


00:36:14.850 --> 00:36:24.400 align:middle line:84%
So let's think about what
other case I might consider.

00:36:24.400 --> 00:36:26.730 align:middle line:84%
We said, OK, suppose I
want to-- and by the way,

00:36:26.730 --> 00:36:28.480 align:middle line:90%
why do we like these converters?

00:36:28.480 --> 00:36:30.060 align:middle line:84%
Because they can
be hyperefficient.

00:36:30.060 --> 00:36:35.050 align:middle line:84%
If I go buy a really
big capacitor here

00:36:35.050 --> 00:36:38.500 align:middle line:84%
or I switch really fast,
this equivalent resistance

00:36:38.500 --> 00:36:39.940 align:middle line:90%
can be very small.

00:36:39.940 --> 00:36:44.480 align:middle line:84%
And I can get an almost perfect
2-to-1 voltage conversion.

00:36:44.480 --> 00:36:50.750 align:middle line:84%
And, in fact, people would call
this thing a 2-to-1 step-down

00:36:50.750 --> 00:36:52.380 align:middle line:90%
switch capacitor converter.

00:36:52.380 --> 00:36:52.880 align:middle line:90%
Why?

00:36:52.880 --> 00:36:55.670 align:middle line:84%
Because they're
thinking of the voltage.

00:36:55.670 --> 00:36:58.670 align:middle line:84%
Ideally speaking, if I make
this resistance really small,

00:36:58.670 --> 00:37:03.050 align:middle line:84%
I'm really just doing like
an ideal transformer 2-to-1.

00:37:03.050 --> 00:37:05.730 align:middle line:84%
And so people would
call that a 2-to-1.

00:37:05.730 --> 00:37:09.110 align:middle line:84%
On the other hand, it's
only approximately 2-to-1

00:37:09.110 --> 00:37:10.350 align:middle line:90%
because this is not 0.

00:37:10.350 --> 00:37:12.840 align:middle line:84%
This is some finite
value of resistance.

00:37:12.840 --> 00:37:17.570 align:middle line:84%
What it is, is a 1-to-2
current converter--

00:37:17.570 --> 00:37:19.080 align:middle line:90%
switch capacitor or converter.

00:37:19.080 --> 00:37:22.580 align:middle line:84%
And that relationship
is precise.

00:37:22.580 --> 00:37:25.440 align:middle line:90%
So what should people call this?

00:37:25.440 --> 00:37:27.620 align:middle line:84%
They should call this a
1-to-2 current conversion--

00:37:27.620 --> 00:37:29.250 align:middle line:90%
switch capacitor converter.

00:37:29.250 --> 00:37:30.630 align:middle line:84%
But that's not
what they call it.

00:37:30.630 --> 00:37:33.005 align:middle line:84%
They call it a 2-to-1 voltage
converter because everybody

00:37:33.005 --> 00:37:34.280 align:middle line:90%
likes to think about voltages.

00:37:34.280 --> 00:37:36.440 align:middle line:84%
So it's just you're stuck
with the-- you're stuck

00:37:36.440 --> 00:37:41.240 align:middle line:84%
with what people call things,
but maybe it's not fair.

00:37:41.240 --> 00:37:51.480 align:middle line:84%
So what do I get if I wanted
to go up in performance?

00:37:51.480 --> 00:37:53.450 align:middle line:90%
Suppose I want--

00:37:53.450 --> 00:37:56.270 align:middle line:84%
I should say, when would I
want to use a switch capacitor

00:37:56.270 --> 00:37:56.863 align:middle line:90%
converter?

00:37:56.863 --> 00:37:58.280 align:middle line:84%
I'd want to use a
switch capacitor

00:37:58.280 --> 00:38:04.730 align:middle line:84%
converter-- for example, I have
5 volts and I need 2.5 volts.

00:38:04.730 --> 00:38:07.880 align:middle line:90%
I want exactly half the voltage.

00:38:07.880 --> 00:38:10.405 align:middle line:84%
Then, to the extent
that I can make

00:38:10.405 --> 00:38:11.780 align:middle line:84%
this equivalent
resistance small,

00:38:11.780 --> 00:38:13.940 align:middle line:90%
this is a great converter.

00:38:13.940 --> 00:38:15.620 align:middle line:84%
On the other hand,
I wouldn't want

00:38:15.620 --> 00:38:18.920 align:middle line:84%
to use this converter when
my input voltage was 5 volts

00:38:18.920 --> 00:38:21.500 align:middle line:84%
and my output
voltage was 2 volts,

00:38:21.500 --> 00:38:26.690 align:middle line:84%
because then my efficiency
would be 2 over 2.5,

00:38:26.690 --> 00:38:28.100 align:middle line:90%
which isn't that high.

00:38:28.100 --> 00:38:31.970 align:middle line:84%
So switch capacitors
or converters

00:38:31.970 --> 00:38:34.730 align:middle line:84%
are very efficient when
your voltage conversion

00:38:34.730 --> 00:38:36.710 align:middle line:84%
ratio is very close
to the inverse

00:38:36.710 --> 00:38:39.590 align:middle line:84%
of your intrinsic
current conversion ratio.

00:38:39.590 --> 00:38:42.990 align:middle line:84%
And then their efficiency droops
down outside of that range.

00:38:42.990 --> 00:38:46.550 align:middle line:84%
Sometimes, actually, people use
this and vary this equivalent

00:38:46.550 --> 00:38:48.440 align:middle line:84%
resistor to give yourself
a linear regulator

00:38:48.440 --> 00:38:49.500 align:middle line:90%
kind of action too.

00:38:49.500 --> 00:38:52.160 align:middle line:84%
So instead of linear
regulating down from v in,

00:38:52.160 --> 00:38:54.320 align:middle line:84%
you linear regulate
down from half v in,

00:38:54.320 --> 00:38:55.920 align:middle line:84%
so you get an
advantage that way.

00:38:55.920 --> 00:38:58.513 align:middle line:84%
But if you want to talk about
pure switch mode operation,

00:38:58.513 --> 00:39:00.430 align:middle line:84%
you're usually trying
to make this very small.

00:39:00.430 --> 00:39:03.020 align:middle line:90%


00:39:03.020 --> 00:39:04.520 align:middle line:90%
How do I make that small?

00:39:04.520 --> 00:39:09.000 align:middle line:84%
I either get big capacitors
or I switch fast.

00:39:09.000 --> 00:39:12.750 align:middle line:84%
Now there's an
exception to what I said

00:39:12.750 --> 00:39:15.070 align:middle line:90%
or a limit to what I said.

00:39:15.070 --> 00:39:22.110 align:middle line:84%
This operation is all in
what I've been calling

00:39:22.110 --> 00:39:24.240 align:middle line:90%
the slow switching limit.

00:39:24.240 --> 00:39:28.740 align:middle line:84%
This limit right
here, where I'm fully

00:39:28.740 --> 00:39:33.587 align:middle line:84%
charging and fully
discharging, suppose

00:39:33.587 --> 00:39:34.920 align:middle line:90%
I want to get higher efficiency.

00:39:34.920 --> 00:39:38.580 align:middle line:84%
And I'm forgetting about gate
losses and capacitor discharge

00:39:38.580 --> 00:39:40.390 align:middle line:84%
losses and stuff
inside the switches.

00:39:40.390 --> 00:39:42.880 align:middle line:84%
I'm just talking about the
charge transfer losses.

00:39:42.880 --> 00:39:45.520 align:middle line:84%
I can switch faster
and faster and faster.

00:39:45.520 --> 00:39:48.390 align:middle line:84%
That output resistance keeps
drooping, keeps getting smaller,

00:39:48.390 --> 00:39:49.710 align:middle line:90%
and that's better.

00:39:49.710 --> 00:39:51.990 align:middle line:84%
But eventually, I
get to the point

00:39:51.990 --> 00:39:54.600 align:middle line:84%
where if I increase my
switching frequency--

00:39:54.600 --> 00:39:58.080 align:middle line:84%
suppose I just keep
each time period half,

00:39:58.080 --> 00:39:59.670 align:middle line:84%
that this time period
is going to get

00:39:59.670 --> 00:40:04.200 align:middle line:84%
so short that my capacitor
doesn't fully charge up.

00:40:04.200 --> 00:40:06.250 align:middle line:84%
And he doesn't
fully charge down.

00:40:06.250 --> 00:40:10.020 align:middle line:84%
If I keep pushing my
switching frequency up enough,

00:40:10.020 --> 00:40:12.090 align:middle line:84%
I'm going to violate the
assumption under which I

00:40:12.090 --> 00:40:13.306 align:middle line:90%
did this analysis.

00:40:13.306 --> 00:40:16.750 align:middle line:90%


00:40:16.750 --> 00:40:20.590 align:middle line:84%
The extreme limit of
that is the capacitor

00:40:20.590 --> 00:40:24.160 align:middle line:84%
sitting close to some
voltage, and he only

00:40:24.160 --> 00:40:26.640 align:middle line:90%
charges up and down a little.

00:40:26.640 --> 00:40:31.830 align:middle line:84%
So, in other words, suppose I
made my time scale really short,

00:40:31.830 --> 00:40:33.450 align:middle line:90%
and I will have--

00:40:33.450 --> 00:40:36.300 align:middle line:84%
here's state 1 and
here's state 2.

00:40:36.300 --> 00:40:42.260 align:middle line:84%
And, in state 1,
he just does this.

00:40:42.260 --> 00:40:49.980 align:middle line:84%
He charges a tiny bit, which is
part of a much bigger charge.

00:40:49.980 --> 00:40:55.460 align:middle line:84%
And then to state 2, he
discharges just a tiny bit,

00:40:55.460 --> 00:40:59.480 align:middle line:84%
which is part of a much
longer time charge,

00:40:59.480 --> 00:41:02.620 align:middle line:84%
So I can almost think in
the fast-switching limit--

00:41:02.620 --> 00:41:09.230 align:middle line:90%


00:41:09.230 --> 00:41:13.880 align:middle line:90%
vc is almost constant.

00:41:13.880 --> 00:41:17.070 align:middle line:84%
I don't have enough time to
charge up or down substantially.

00:41:17.070 --> 00:41:21.140 align:middle line:84%
The delta voltage I get is
nowhere near the full swing.

00:41:21.140 --> 00:41:24.530 align:middle line:84%
And I can just start to
think about the capacitor

00:41:24.530 --> 00:41:27.640 align:middle line:90%
as being a constant voltage.

00:41:27.640 --> 00:41:29.525 align:middle line:84%
But it's a special
constant voltage because,

00:41:29.525 --> 00:41:31.900 align:middle line:84%
nonetheless, if I'm going to
be in periodic steady state,

00:41:31.900 --> 00:41:35.500 align:middle line:84%
however much he charges in
the first state must balance

00:41:35.500 --> 00:41:38.120 align:middle line:84%
the amount of discharges
in the second state

00:41:38.120 --> 00:41:43.420 align:middle line:84%
that I haven't gotten
around that kind of rule.

00:41:43.420 --> 00:41:47.530 align:middle line:84%
But nonetheless, we can think
about this fast switching limit

00:41:47.530 --> 00:41:50.270 align:middle line:84%
as the capacitor voltage
almost becoming constant.

00:41:50.270 --> 00:41:54.550 align:middle line:84%
So let's think about what would
a converter do in the fast

00:41:54.550 --> 00:42:02.870 align:middle line:84%
switching limit in
the FSL in state--

00:42:02.870 --> 00:42:04.720 align:middle line:90%
so let me just think about--

00:42:04.720 --> 00:42:09.400 align:middle line:84%
I'm going to now mentally
replace this capacitor

00:42:09.400 --> 00:42:14.110 align:middle line:90%
with just a fixed voltage, vc.

00:42:14.110 --> 00:42:16.690 align:middle line:84%
And in this other
state, he's also

00:42:16.690 --> 00:42:19.420 align:middle line:90%
going to be a fixed voltage vc.

00:42:19.420 --> 00:42:21.820 align:middle line:84%
And the only thing I
need is the net charge

00:42:21.820 --> 00:42:24.130 align:middle line:84%
that goes into vc
over a cycle to be 0.

00:42:24.130 --> 00:42:29.395 align:middle line:84%
So how much charge do
I transfer in state 1?

00:42:29.395 --> 00:42:34.220 align:middle line:90%


00:42:34.220 --> 00:42:39.325 align:middle line:84%
And I'm going to do FSL
with 50% duty ratio.

00:42:39.325 --> 00:42:44.480 align:middle line:90%


00:42:44.480 --> 00:42:46.760 align:middle line:84%
In other words, I'm going
to assume that in state 1,

00:42:46.760 --> 00:42:48.290 align:middle line:90%
I spend half a period.

00:42:48.290 --> 00:42:52.430 align:middle line:84%
In state 2, I'm going to
spend half a period because

00:42:52.430 --> 00:42:55.970 align:middle line:84%
in the FSL, the fast switching
limit, how much time I

00:42:55.970 --> 00:42:58.385 align:middle line:84%
spend in the two
adjacent states matters.

00:42:58.385 --> 00:43:00.260 align:middle line:84%
But let's just assume
I'm going to spend half

00:43:00.260 --> 00:43:02.570 align:middle line:84%
in each state for
purposes of this analysis.

00:43:02.570 --> 00:43:08.120 align:middle line:84%
So in state 1, what do
I get for delta qc 1?

00:43:08.120 --> 00:43:14.150 align:middle line:84%
Well, delta qc 1 is
going to be what?

00:43:14.150 --> 00:43:17.720 align:middle line:84%
I'm going to say, all right,
if he's a constant voltage,

00:43:17.720 --> 00:43:20.390 align:middle line:84%
I'm going to get
a current that's

00:43:20.390 --> 00:43:26.480 align:middle line:84%
going to be v in minus vc minus
v out divided by 2 R switch.

00:43:26.480 --> 00:43:28.700 align:middle line:90%
That's the current in state 1.

00:43:28.700 --> 00:43:37.400 align:middle line:84%
So that's going to be v in
minus vc minus v out divided

00:43:37.400 --> 00:43:39.920 align:middle line:90%
by 2 R switch.

00:43:39.920 --> 00:43:42.370 align:middle line:84%
And that's going to
happen for how long?

00:43:42.370 --> 00:43:45.060 align:middle line:84%
That's going to
happen for one half t.

00:43:45.060 --> 00:43:50.700 align:middle line:84%
Or I could write that
as 1 over 2 f switch,

00:43:50.700 --> 00:43:52.760 align:middle line:90%
This is times half a period.

00:43:52.760 --> 00:43:55.560 align:middle line:90%


00:43:55.560 --> 00:44:00.310 align:middle line:90%
What is delta q in 1 look like?

00:44:00.310 --> 00:44:05.100 align:middle line:84%
That's just going to
be minus delta qc 1.

00:44:05.100 --> 00:44:08.980 align:middle line:84%
And what's delta
q in 2 look like?

00:44:08.980 --> 00:44:14.880 align:middle line:84%
That's just going to
be equal to delta qc 1.

00:44:14.880 --> 00:44:16.590 align:middle line:84%
In other words,
all I'm saying is

00:44:16.590 --> 00:44:19.473 align:middle line:84%
that here, the input
got the negative

00:44:19.473 --> 00:44:21.390 align:middle line:84%
of the charge of the
capacitor, and the output

00:44:21.390 --> 00:44:25.530 align:middle line:84%
got the charge that went
through the capacitor.

00:44:25.530 --> 00:44:26.770 align:middle line:90%
Makes sense to everybody?

00:44:26.770 --> 00:44:30.050 align:middle line:90%


00:44:30.050 --> 00:44:45.560 align:middle line:84%
If I do this for state 2, what
I'm going to get is delta qc 2

00:44:45.560 --> 00:44:47.330 align:middle line:90%
is simply going to be what?

00:44:47.330 --> 00:44:55.020 align:middle line:84%
It's going to be v out
minus vc over 2 R switch.

00:44:55.020 --> 00:45:01.880 align:middle line:84%
Or it's going to be v out
minus vc over 2 R switch

00:45:01.880 --> 00:45:13.100 align:middle line:84%
is going to be minus vc minus
v out over 2 R switch times

00:45:13.100 --> 00:45:16.450 align:middle line:90%
1 over 2 f switch.

00:45:16.450 --> 00:45:21.860 align:middle line:90%
Delta q in 2 is going to be 0.

00:45:21.860 --> 00:45:27.830 align:middle line:84%
And delta q out 2 is going to be
equal to the negative of this,

00:45:27.830 --> 00:45:32.970 align:middle line:84%
which is going to
be minus delta qc 1.

00:45:32.970 --> 00:45:36.750 align:middle line:90%
Does that make sense, everybody?

00:45:36.750 --> 00:45:40.090 align:middle line:90%
AUDIENCE: [INAUDIBLE]

00:45:40.090 --> 00:45:40.945 align:middle line:90%


00:45:40.945 --> 00:45:41.570 align:middle line:90%
PROFESSOR: Yes.

00:45:41.570 --> 00:45:48.937 align:middle line:90%


00:45:48.937 --> 00:45:50.270 align:middle line:90%
That's what happens when I rush.

00:45:50.270 --> 00:45:50.840 align:middle line:90%
Thank you.

00:45:50.840 --> 00:45:53.910 align:middle line:90%


00:45:53.910 --> 00:45:56.710 align:middle line:84%
What constraint do
I get off of this?

00:45:56.710 --> 00:46:02.370 align:middle line:84%
Well, what I need is delta
qc of 1 plus delta qc of 2

00:46:02.370 --> 00:46:05.130 align:middle line:90%
have to add up to 0.

00:46:05.130 --> 00:46:09.450 align:middle line:84%
I mean, that's a constraint
for periodic steady state.

00:46:09.450 --> 00:46:20.700 align:middle line:84%
So what I get is for PSS,
what I get is delta qc of 1

00:46:20.700 --> 00:46:27.420 align:middle line:84%
plus delta qc 2 is equal
to 0, which gives me--

00:46:27.420 --> 00:46:30.510 align:middle line:84%
I can ignore the 1 over
4 f switch R switch.

00:46:30.510 --> 00:46:32.670 align:middle line:84%
That gives me v in
minus vc minus v

00:46:32.670 --> 00:46:52.260 align:middle line:84%
out plus v out minus vc plus
v out minus vc is equal to 0.

00:46:52.260 --> 00:46:58.910 align:middle line:84%
And what this gives me is that
vc is going to be half v in.

00:46:58.910 --> 00:47:03.360 align:middle line:90%


00:47:03.360 --> 00:47:05.340 align:middle line:84%
So in periodic steady
state, I'm going

00:47:05.340 --> 00:47:07.050 align:middle line:84%
to be charging
discharging the capacitor,

00:47:07.050 --> 00:47:11.030 align:middle line:84%
but he's going to sit at an
average value of half v in.

00:47:11.030 --> 00:47:16.382 align:middle line:84%
I can then go and plug
this value back in--

00:47:16.382 --> 00:47:18.090 align:middle line:84%
and I'm kind of running
out of time here.

00:47:18.090 --> 00:47:23.040 align:middle line:84%
I can go plug this back in
and find q out 1 and q in 1.

00:47:23.040 --> 00:47:27.530 align:middle line:84%
I can do the same
game I do over here.

00:47:27.530 --> 00:47:34.640 align:middle line:84%
And if you do that
calculation, it's pretty easy.

00:47:34.640 --> 00:47:37.730 align:middle line:84%
I can calculate i out
as being the sum of q 1

00:47:37.730 --> 00:47:39.000 align:middle line:90%
and q in and q out.

00:47:39.000 --> 00:47:50.890 align:middle line:84%
And what I get is v out is equal
to 1/2 v in minus 2 R switch i

00:47:50.890 --> 00:47:51.390 align:middle line:90%
out.

00:47:51.390 --> 00:47:54.080 align:middle line:90%


00:47:54.080 --> 00:48:01.100 align:middle line:84%
So it's of the exact same
format that I had up here.

00:48:01.100 --> 00:48:05.800 align:middle line:90%
So here, I get this in the SSL.

00:48:05.800 --> 00:48:08.480 align:middle line:90%


00:48:08.480 --> 00:48:14.335 align:middle line:90%
And in the FSL--

00:48:14.335 --> 00:48:17.360 align:middle line:84%
I think should use
a different color--

00:48:17.360 --> 00:48:18.263 align:middle line:90%
in the FSL.

00:48:18.263 --> 00:48:21.740 align:middle line:90%


00:48:21.740 --> 00:48:27.710 align:middle line:84%
Req is simply equal
to 2 R switch.

00:48:27.710 --> 00:48:30.650 align:middle line:84%
Well, that actually kind
of feels good in some sense

00:48:30.650 --> 00:48:34.010 align:middle line:84%
because if you think about it,
in either of these two states,

00:48:34.010 --> 00:48:38.440 align:middle line:84%
I'm always dumping current
through two switches.

00:48:38.440 --> 00:48:41.930 align:middle line:90%


00:48:41.930 --> 00:48:45.200 align:middle line:84%
So half the time I'm doing
in this configuration, half

00:48:45.200 --> 00:48:48.290 align:middle line:84%
the time in that configuration,
but if I think of a capacitor

00:48:48.290 --> 00:48:54.060 align:middle line:84%
current as being of a plus and
minus square wave of current,

00:48:54.060 --> 00:48:56.640 align:middle line:84%
the input current is
constant coming here,

00:48:56.640 --> 00:48:57.660 align:middle line:90%
and the output current--

00:48:57.660 --> 00:48:59.970 align:middle line:84%
I'm sorry, the input current
is a pulse square root.

00:48:59.970 --> 00:49:03.180 align:middle line:84%
The output current
is kind of constant.

00:49:03.180 --> 00:49:06.168 align:middle line:84%
But the point is I'm
always putting my charging

00:49:06.168 --> 00:49:08.460 align:middle line:84%
and discharging current
through two switch resistances,

00:49:08.460 --> 00:49:11.040 align:middle line:84%
so it's not maybe
surprising that I

00:49:11.040 --> 00:49:13.320 align:middle line:84%
get down to this
equivalent resistance

00:49:13.320 --> 00:49:16.480 align:middle line:90%
being two switch resistances.

00:49:16.480 --> 00:49:20.290 align:middle line:84%
So what happens in the real
world is if I have a switch

00:49:20.290 --> 00:49:23.080 align:middle line:84%
capacitor converter
and I say I'm

00:49:23.080 --> 00:49:30.550 align:middle line:84%
going to have this model for its
behavior, all I'm going to get

00:49:30.550 --> 00:49:37.450 align:middle line:84%
is if I plotted R equivalent
on a log scale versus switching

00:49:37.450 --> 00:49:41.170 align:middle line:84%
frequency on a log scale,
what I'm going to get

00:49:41.170 --> 00:49:44.410 align:middle line:84%
is something that
falls linearly.

00:49:44.410 --> 00:49:49.030 align:middle line:90%
This is 1 over 4 c f switch.

00:49:49.030 --> 00:49:54.460 align:middle line:84%
And then he's going to have
some minimum value, which

00:49:54.460 --> 00:49:55.945 align:middle line:90%
is 2 R switch.

00:49:55.945 --> 00:49:58.480 align:middle line:90%


00:49:58.480 --> 00:50:00.700 align:middle line:84%
And the actual value
you're going to get

00:50:00.700 --> 00:50:04.680 align:middle line:84%
is going to do
something like this.

00:50:04.680 --> 00:50:07.490 align:middle line:90%


00:50:07.490 --> 00:50:10.940 align:middle line:84%
So there's kind of some limiting
efficiency you can get to.

00:50:10.940 --> 00:50:13.810 align:middle line:84%
Well, if I'm charging through
two switches all the time,

00:50:13.810 --> 00:50:16.610 align:middle line:84%
I got to eat the on-state
loss of those switches.

00:50:16.610 --> 00:50:19.420 align:middle line:84%
I mean, I can't have
100% efficiency.

00:50:19.420 --> 00:50:21.670 align:middle line:84%
But if I'm using 10
milliohm switches,

00:50:21.670 --> 00:50:22.940 align:middle line:90%
maybe that's pretty damn low.

00:50:22.940 --> 00:50:28.210 align:middle line:84%
So essentially, what
I would tend to do

00:50:28.210 --> 00:50:31.750 align:middle line:84%
is keep turning up the
switching frequency

00:50:31.750 --> 00:50:34.570 align:middle line:84%
until I get down to this
regime where turning it up

00:50:34.570 --> 00:50:37.420 align:middle line:84%
any more doesn't
reduce my output

00:50:37.420 --> 00:50:40.925 align:middle line:84%
resistance because, at that
point, there are other losses,

00:50:40.925 --> 00:50:42.550 align:middle line:84%
like gate drive losses
and stuff, which

00:50:42.550 --> 00:50:44.060 align:middle line:90%
get worse with frequency.

00:50:44.060 --> 00:50:45.622 align:middle line:84%
So I ought to just
go high enough

00:50:45.622 --> 00:50:47.330 align:middle line:84%
that I can get to very
high efficiencies.

00:50:47.330 --> 00:50:49.960 align:middle line:84%
And the result of
this is if what

00:50:49.960 --> 00:50:54.490 align:middle line:84%
I want is a fixed conversion
ratio close to this,

00:50:54.490 --> 00:50:59.140 align:middle line:84%
I can get extraordinarily high
efficiencies in power densities.

00:50:59.140 --> 00:51:02.560 align:middle line:84%
If I deviate the voltage
conversion ratio away from that,

00:51:02.560 --> 00:51:04.160 align:middle line:84%
then the efficiency
starts to droop.

00:51:04.160 --> 00:51:06.850 align:middle line:84%
But for what they're good at,
switch capacitor converters

00:51:06.850 --> 00:51:08.390 align:middle line:90%
are very hard to beat.

00:51:08.390 --> 00:51:10.780 align:middle line:84%
And if I was to come back
and analyze any other switch

00:51:10.780 --> 00:51:12.850 align:middle line:84%
capacitor converter,
it's the same deal.

00:51:12.850 --> 00:51:14.920 align:middle line:84%
It's some charge
transfer analysis

00:51:14.920 --> 00:51:16.520 align:middle line:84%
through the
different capacitors.

00:51:16.520 --> 00:51:19.510 align:middle line:84%
And I use charge balance,
and you can work that out

00:51:19.510 --> 00:51:24.132 align:middle line:84%
to being a current conversion
ratio and then some equivalent

00:51:24.132 --> 00:51:26.590 align:middle line:84%
resistance with a slow switching
limit and a fast switching

00:51:26.590 --> 00:51:27.090 align:middle line:90%
limit.

00:51:27.090 --> 00:51:29.410 align:middle line:90%


00:51:29.410 --> 00:51:31.190 align:middle line:84%
We'll take this up
again next class.

00:51:31.190 --> 00:51:34.400 align:middle line:84%
But are there any
final questions?

00:51:34.400 --> 00:51:34.937 align:middle line:90%
Yeah?

00:51:34.937 --> 00:51:36.770 align:middle line:84%
AUDIENCE: Now that
you're switching quickly,

00:51:36.770 --> 00:51:40.760 align:middle line:84%
can the duty ratio change
the conversion ratio?

00:51:40.760 --> 00:51:45.230 align:middle line:84%
PROFESSOR: Well, yes, but
only through the action

00:51:45.230 --> 00:51:49.130 align:middle line:84%
of essentially what
this resistance is.

00:51:49.130 --> 00:51:51.410 align:middle line:90%
So you can make the--

00:51:51.410 --> 00:51:53.450 align:middle line:84%
for any given converter,
there's a duty ratio

00:51:53.450 --> 00:51:55.970 align:middle line:84%
that will give you the
lowest output resistance.

00:51:55.970 --> 00:51:57.740 align:middle line:84%
Even in slow
switching limit, you

00:51:57.740 --> 00:52:01.160 align:middle line:84%
can change the conversion
ratio, but you're doing it

00:52:01.160 --> 00:52:02.520 align:middle line:90%
through a resistive drop.

00:52:02.520 --> 00:52:04.970 align:middle line:84%
It's sort of like you have
an ideal transformer and then

00:52:04.970 --> 00:52:06.510 align:middle line:84%
a linear regulator
kind of thing.

00:52:06.510 --> 00:52:10.460 align:middle line:84%
So you can always use
switching frequency and fast

00:52:10.460 --> 00:52:14.630 align:middle line:84%
switching limit duty ratio to
change the conversion ratio,

00:52:14.630 --> 00:52:17.976 align:middle line:84%
but not in a perfectly
efficient sense--

00:52:17.976 --> 00:52:20.282 align:middle line:84%
for the voltage
conversion ratio.

00:52:20.282 --> 00:52:20.990 align:middle line:90%
All right, great.

00:52:20.990 --> 00:52:23.640 align:middle line:90%
We'll pick this up next class.

00:52:23.640 --> 00:52:26.000 align:middle line:90%