#Programming for the Puzzled -- Srini Devadas
#You Will All Conform
#Input is a vector of F's and B's, in terms of forwards and backwards caps
#Output is a set of commands (printed out) to get either all F's or all B's
#Fewest commands are the goal
caps = ['F', 'F', 'B', 'B', 'B', 'F', 'B', 'B', 'B', 'F', 'F', 'B', 'F' ]
cap2 = ['F', 'F', 'B', 'B', 'B', 'F', 'B', 'B', 'B', 'F', 'F', 'F', 'F' ]
def pleaseConform(caps):
#Initialization
start = 0
forward = 0
backward = 0
intervals = []
#Determine intervals where caps are on in the same direction
for i in range(len(caps)):
if caps[start] != caps[i]:
# each interval is a tuple with 3 elements (start, end, type)
intervals.append((start, i - 1, caps[start]))
if caps[start] == 'F':
forward += 1
else:
backward += 1
start = i
#Need to add the last interval after for loop completes execution
intervals.append((start, len(caps) - 1, caps[start]))
if caps[start] == 'F':
forward += 1
else:
backward += 1
## print (intervals)
## print (forward, backward)
if forward < backward:
flip = 'F'
else:
flip = 'B'
for t in intervals:
if t[2] == flip:
#Exercise: if t[0] == t[1] change the printing!
if t[0] == t[1]:
print ('Person at position', t[0], 'flip your cap!')
else:
print ('People in positions', t[0], 'through', t[1], 'flip your caps!')
pleaseConform(caps)
##pleaseConform(cap2)