1 00:00:03,360 --> 00:00:05,970 We now would like to explore the concept of potential energy 2 00:00:05,970 --> 00:00:07,860 difference for a conservative force. 3 00:00:07,860 --> 00:00:10,090 Let's consider the following case. 4 00:00:10,090 --> 00:00:13,200 Suppose you have an object of mass m 5 00:00:13,200 --> 00:00:17,700 and it's located at a certain height y i initial. 6 00:00:17,700 --> 00:00:21,120 And so this is our initial state. 7 00:00:21,120 --> 00:00:24,870 And we would like to move this object upwards. 8 00:00:24,870 --> 00:00:27,930 So it goes up to a height y final. 9 00:00:27,930 --> 00:00:30,770 This is our final state. 10 00:00:30,770 --> 00:00:32,340 And in our initial state, we might 11 00:00:32,340 --> 00:00:35,250 have some initial velocity. 12 00:00:35,250 --> 00:00:39,486 And then the final state might have some final speed. 13 00:00:39,486 --> 00:00:40,860 And what we'd like to do now is-- 14 00:00:40,860 --> 00:00:45,330 we know that if there is a gravitational force, mg, 15 00:00:45,330 --> 00:00:47,880 acting downwards, that this gravitational force is 16 00:00:47,880 --> 00:00:49,780 a conservative force. 17 00:00:49,780 --> 00:00:52,860 And now what I'd like to do is-- because the force is 18 00:00:52,860 --> 00:00:56,130 conservative, it doesn't depend on the path 19 00:00:56,130 --> 00:00:58,860 that our object goes to the final state. 20 00:00:58,860 --> 00:01:00,570 It just depends on the parameters 21 00:01:00,570 --> 00:01:03,550 that describe the initial and the final states. 22 00:01:03,550 --> 00:01:07,020 In fact, we'll see it only depends on the initial height 23 00:01:07,020 --> 00:01:08,530 and the final height. 24 00:01:08,530 --> 00:01:12,000 So what I'd like to do is define a potential energy difference 25 00:01:12,000 --> 00:01:13,630 in the following way. 26 00:01:13,630 --> 00:01:19,800 So as a definition, the potential energy difference 27 00:01:19,800 --> 00:01:23,310 between these two points is given 28 00:01:23,310 --> 00:01:28,830 by the negative of the work done by the gravitational force 29 00:01:28,830 --> 00:01:32,910 in going from the initial state to the final state. 30 00:01:32,910 --> 00:01:37,440 Notice this negative sign. 31 00:01:37,440 --> 00:01:40,800 Because the gravitational force here, Fg 32 00:01:40,800 --> 00:01:46,530 is minus mg j hat-- where we're taking j hat up-- 33 00:01:46,530 --> 00:01:48,720 we've seen that this is an example 34 00:01:48,720 --> 00:01:49,979 of a conservative force. 35 00:01:53,250 --> 00:01:55,590 And it doesn't matter how we went from the initial 36 00:01:55,590 --> 00:01:56,970 to the final states. 37 00:01:56,970 --> 00:02:00,540 So we can generalize this idea for potential energy. 38 00:02:00,540 --> 00:02:03,600 But first, let's just remind ourselves of the calculation. 39 00:02:03,600 --> 00:02:05,640 When we did this calculation before, 40 00:02:05,640 --> 00:02:10,889 we had u final minus u final initial equals a negative sign 41 00:02:10,889 --> 00:02:12,210 in the definition. 42 00:02:12,210 --> 00:02:15,990 And when we calculated the work done by the conservative force, 43 00:02:15,990 --> 00:02:21,050 we had negative mg y final minus y initial. 44 00:02:21,050 --> 00:02:22,430 Notice the two minus signs. 45 00:02:22,430 --> 00:02:27,510 So we get mg y final minus y initial. 46 00:02:27,510 --> 00:02:30,570 Now, many times people talk about changes 47 00:02:30,570 --> 00:02:32,050 in potential energy. 48 00:02:32,050 --> 00:02:37,320 So when I write delta u, I mean precisely the potential energy 49 00:02:37,320 --> 00:02:39,180 at the final state minus potential energy 50 00:02:39,180 --> 00:02:42,010 of the initial state-- the change in potential energy. 51 00:02:42,010 --> 00:02:47,520 And that's equal to mg times the change in the displacement. 52 00:02:47,520 --> 00:02:49,800 And so we see here for this example, 53 00:02:49,800 --> 00:02:53,190 that if delta y is positive, that 54 00:02:53,190 --> 00:02:56,680 implies that the potential energy is increasing. 55 00:02:56,680 --> 00:02:59,220 Now let's connect that to our definition. 56 00:02:59,220 --> 00:03:01,770 Why is the potential energy increasing 57 00:03:01,770 --> 00:03:03,240 when we raise something? 58 00:03:03,240 --> 00:03:07,050 Well, the gravitational force points downwards. 59 00:03:07,050 --> 00:03:08,860 The displacement is upwards. 60 00:03:08,860 --> 00:03:11,040 So the work done is negative. 61 00:03:11,040 --> 00:03:13,950 And another minus sign means the change in potential energy 62 00:03:13,950 --> 00:03:15,300 is positive. 63 00:03:15,300 --> 00:03:20,730 If the object is moving with no change in height, 64 00:03:20,730 --> 00:03:24,390 that tells us that the potential energy is change is zero. 65 00:03:24,390 --> 00:03:27,210 And finally, if delta y is less than zero, 66 00:03:27,210 --> 00:03:30,730 that implies that the change in potential energy is negative. 67 00:03:30,730 --> 00:03:33,340 Now again let's examine this case. 68 00:03:33,340 --> 00:03:37,290 If we were actually lowering an object, dropping it down. 69 00:03:37,290 --> 00:03:39,360 The object moved downward from the initial state 70 00:03:39,360 --> 00:03:41,475 to a final state, the gravitational force 71 00:03:41,475 --> 00:03:44,070 is downward, the displacement is downward, 72 00:03:44,070 --> 00:03:46,829 the integral is positive, the extra minus sign 73 00:03:46,829 --> 00:03:48,810 corresponds to the change of potential energy 74 00:03:48,810 --> 00:03:50,900 being negative.