1 00:00:03,540 --> 00:00:07,150 We consider the work done by a gravitational force, which 2 00:00:07,150 --> 00:00:08,070 was path-independent. 3 00:00:08,070 --> 00:00:12,444 Now let's generalize that to any force between two points, 4 00:00:12,444 --> 00:00:20,460 i, and another point, f, that if the work done 5 00:00:20,460 --> 00:00:23,550 going from the initial point to the final point-- 6 00:00:23,550 --> 00:00:28,680 this is path-independent-- then we call this 7 00:00:28,680 --> 00:00:33,802 force a conservative force. 8 00:00:38,934 --> 00:00:40,350 There are many conservative forces 9 00:00:40,350 --> 00:00:42,600 that we'll analyze in this class. 10 00:00:42,600 --> 00:00:45,540 Examples will be the inverse square, electric force, 11 00:00:45,540 --> 00:00:47,250 or the gravitational force. 12 00:00:47,250 --> 00:00:49,504 We've already seen gravitational force. 13 00:00:49,504 --> 00:00:51,420 Near the surface of the Earth is conservative. 14 00:00:51,420 --> 00:00:53,880 Spring forces are other examples of conservative forces. 15 00:00:53,880 --> 00:00:56,820 But let's look a little bit in detail. 16 00:00:56,820 --> 00:01:01,020 Suppose we call this path 1 and we 17 00:01:01,020 --> 00:01:05,000 consider a second path, path 2. 18 00:01:05,000 --> 00:01:07,590 Then a property of conservative forces 19 00:01:07,590 --> 00:01:11,740 is that the work done is independent of that path. 20 00:01:11,740 --> 00:01:15,720 So if we total up the work from the initial 21 00:01:15,720 --> 00:01:22,560 to final on path 1 of f dot ds. 22 00:01:22,560 --> 00:01:25,590 And then we go from the final point 23 00:01:25,590 --> 00:01:31,800 to the initial point on path 2 of f dot ds. 24 00:01:31,800 --> 00:01:35,550 Then because these intervals are independent of the path, 25 00:01:35,550 --> 00:01:40,229 and all we've done is shifted the endpoints, we get 0. 26 00:01:40,229 --> 00:01:41,850 And that's the statement. 27 00:01:41,850 --> 00:01:46,620 And we'll write w conservative here for conservative forces. 28 00:01:46,620 --> 00:01:49,500 So we're going to call this force conservative 29 00:01:49,500 --> 00:01:51,090 if it's path-independent. 30 00:01:51,090 --> 00:01:53,310 So what we have here is the statement 31 00:01:53,310 --> 00:01:56,550 that the work done by a conservative force. 32 00:01:56,550 --> 00:02:00,120 Now what we'll do here, is indicate a circle 33 00:02:00,120 --> 00:02:02,640 by a closed path. 34 00:02:02,640 --> 00:02:07,350 The work done by conservative force on a closed path is zero. 35 00:02:07,350 --> 00:02:09,490 What does a closed path look like? 36 00:02:09,490 --> 00:02:13,470 Well, remember, what we did was we went from 1, but then 37 00:02:13,470 --> 00:02:15,840 instead of going in this direction, 38 00:02:15,840 --> 00:02:19,680 we came back on path to, from the final, 39 00:02:19,680 --> 00:02:21,120 to the initial point. 40 00:02:21,120 --> 00:02:22,950 And if the force is conservative, 41 00:02:22,950 --> 00:02:26,120 the work done around a closed path is 0.