1 00:00:03,290 --> 00:00:05,480 We will now introduce a new kinematic quantity 2 00:00:05,480 --> 00:00:07,260 called angular momentum. 3 00:00:07,260 --> 00:00:08,960 Angular momentum will be very useful 4 00:00:08,960 --> 00:00:10,910 when we describe the rotation and objects. 5 00:00:10,910 --> 00:00:14,250 In particular, how will it be related to torque. 6 00:00:14,250 --> 00:00:16,110 Now, what is angular momentum? 7 00:00:16,110 --> 00:00:18,740 Suppose we have an object of mass m. 8 00:00:18,740 --> 00:00:21,380 And it's moving in this direction. 9 00:00:21,380 --> 00:00:23,140 And it has momentum p. 10 00:00:23,140 --> 00:00:24,510 Remember, p equals mv. 11 00:00:27,050 --> 00:00:30,770 Angular momentum is always defined about some point. 12 00:00:30,770 --> 00:00:34,310 So suppose we choose a point s, and I wanted 13 00:00:34,310 --> 00:00:36,020 to find the angular momentum about 14 00:00:36,020 --> 00:00:39,180 s due to this motion of the object. 15 00:00:39,180 --> 00:00:42,920 And the way it's defined is I'll draw a vector from the point 16 00:00:42,920 --> 00:00:45,410 s to where the object is. 17 00:00:45,410 --> 00:00:51,320 And our definition of angular momentum about s is equal-- 18 00:00:51,320 --> 00:00:53,690 this is three lines for our definition-- 19 00:00:53,690 --> 00:00:57,950 it's the vector cross product of the vector rs. 20 00:00:57,950 --> 00:01:00,650 We have the vector p. 21 00:01:00,650 --> 00:01:04,890 Now, how do we define the direction of this vector? 22 00:01:04,890 --> 00:01:07,400 Well, the way we do that for any vector 23 00:01:07,400 --> 00:01:09,860 product is we take the two vectors 24 00:01:09,860 --> 00:01:11,820 and we put them tail to tail. 25 00:01:11,820 --> 00:01:15,080 So let's start off by drawing the vector 26 00:01:15,080 --> 00:01:19,560 rs in that direction. 27 00:01:19,560 --> 00:01:22,070 And now when you take a cross product, 28 00:01:22,070 --> 00:01:25,160 we draw an arrow from the first vector to the second one. 29 00:01:25,160 --> 00:01:28,400 Remember, cross in vector products are the same thing. 30 00:01:28,400 --> 00:01:30,800 And now we want to use our right hand 31 00:01:30,800 --> 00:01:34,259 rule to get the direction of the angular momentum. 32 00:01:34,259 --> 00:01:36,170 So we curl our fingers. 33 00:01:36,170 --> 00:01:38,420 And notice in this case, it's pointing 34 00:01:38,420 --> 00:01:41,150 into the plane of the figure. 35 00:01:41,150 --> 00:01:45,620 And so the direction of the angular momentum about s 36 00:01:45,620 --> 00:01:51,170 is given into the plane of the figure in our light board. 37 00:01:51,170 --> 00:01:53,479 Now, we'll learn how to calculate this cross product 38 00:01:53,479 --> 00:01:54,470 in detail. 39 00:01:54,470 --> 00:01:56,810 But suppose we have our vectors which 40 00:01:56,810 --> 00:01:59,300 are in a slightly different arrangement 41 00:01:59,300 --> 00:02:01,400 as seen in this figure here. 42 00:02:01,400 --> 00:02:05,570 Well, what we see is with the vector p and the vector rs, 43 00:02:05,570 --> 00:02:08,180 we still use our right hand rule to calculate 44 00:02:08,180 --> 00:02:09,978 the direction of Ls. 45 00:02:09,978 --> 00:02:12,860 Notice, whenever you have a vector cross product, 46 00:02:12,860 --> 00:02:17,150 that the vector Ls is perpendicular to both 47 00:02:17,150 --> 00:02:23,840 the vectors rs and is perpendicular to the vector p. 48 00:02:23,840 --> 00:02:26,150 And you can see in both of these examples 49 00:02:26,150 --> 00:02:29,420 that the angular momentum is perpendicular to the plane 50 00:02:29,420 --> 00:02:33,826 formed by the vectors rs and p.