1 00:00:03,420 --> 00:00:07,090 When a wheel is rolling without slipping, as we saw before, 2 00:00:07,090 --> 00:00:13,690 that the contact point here, the contact point 3 00:00:13,690 --> 00:00:21,380 is instantaneously at rest. 4 00:00:21,380 --> 00:00:25,880 Now, if the wheel is rolling on a surface with friction, 5 00:00:25,880 --> 00:00:31,550 then it's possible that we may have a static friction force. 6 00:00:31,550 --> 00:00:40,800 So there could be static friction may act. 7 00:00:40,800 --> 00:00:42,990 However, static fiction is always 8 00:00:42,990 --> 00:00:45,430 depends on the circumstances. 9 00:00:45,430 --> 00:00:48,340 Now let's just consider two cases. 10 00:00:48,340 --> 00:00:51,330 Suppose here's a wheel, Vcm. 11 00:00:51,330 --> 00:00:55,560 This is a horizontal surface. 12 00:00:55,560 --> 00:00:59,280 And in that case, the static friction, 13 00:00:59,280 --> 00:01:01,470 if the wheel is rolling with velocity V, 14 00:01:01,470 --> 00:01:05,280 in this case f static is 0. 15 00:01:05,280 --> 00:01:07,350 And because of that, the wheel will 16 00:01:07,350 --> 00:01:12,090 roll without any friction, which is an idealization. 17 00:01:12,090 --> 00:01:15,300 There's other types of friction called rolling resistance, air 18 00:01:15,300 --> 00:01:17,880 resistance, et cetera, which will slow the wheel down. 19 00:01:17,880 --> 00:01:21,660 But in a perfect hard wheel, idealized wheel in a vacuum, 20 00:01:21,660 --> 00:01:23,460 it will keep on rolling. 21 00:01:23,460 --> 00:01:28,230 However, if a wheel is going down an incline plane 22 00:01:28,230 --> 00:01:32,610 and it wants to maintain the rolling without slipping 23 00:01:32,610 --> 00:01:34,390 condition-- 24 00:01:34,390 --> 00:01:37,710 so here we have Vcm. 25 00:01:37,710 --> 00:01:40,180 And it has some angular speed-- 26 00:01:40,180 --> 00:01:42,870 we have to be careful because in this case 27 00:01:42,870 --> 00:01:47,940 if we differentiate Acm is our alpha. 28 00:01:47,940 --> 00:01:51,750 So what is making the wheel spin faster? 29 00:01:51,750 --> 00:01:59,700 It has a non-zero, angular acceleration. 30 00:01:59,700 --> 00:02:03,540 And if we looked at the forces acting on the wheel, 31 00:02:03,540 --> 00:02:06,230 then we have a normal force. 32 00:02:06,230 --> 00:02:11,009 We have gravity acting at the center of mass. 33 00:02:11,009 --> 00:02:15,300 And we also have static friction. 34 00:02:15,300 --> 00:02:22,340 And it's precisely the static friction 35 00:02:22,340 --> 00:02:30,460 that is producing a torque about the center of mass. 36 00:02:35,270 --> 00:02:38,300 And that torque about the center of mass 37 00:02:38,300 --> 00:02:41,790 will produce an angular acceleration. 38 00:02:41,790 --> 00:02:44,450 So in order for the wheel to continue 39 00:02:44,450 --> 00:02:46,550 rolling without slipping, it must 40 00:02:46,550 --> 00:02:48,410 have both a linear acceleration, which 41 00:02:48,410 --> 00:02:52,295 comes from gravitational force component going down 42 00:02:52,295 --> 00:02:57,320 an inclined plane minus the friction plus the alpha 43 00:02:57,320 --> 00:02:59,750 is coming from the torque. 44 00:02:59,750 --> 00:03:01,970 And so this side, if we wrote it as a vector 45 00:03:01,970 --> 00:03:05,060 equation, the torque about the center of mass 46 00:03:05,060 --> 00:03:09,300 would be the vector from-- 47 00:03:09,300 --> 00:03:14,770 let's right this is r cm to where 48 00:03:14,770 --> 00:03:17,170 the static friction is acting. 49 00:03:17,170 --> 00:03:23,050 So that's the vector r cm F static cross f static. 50 00:03:23,050 --> 00:03:27,490 So in this case, f static is non-zero. 51 00:03:27,490 --> 00:03:31,540 So there are many circumstances in which static friction can 52 00:03:31,540 --> 00:03:37,060 vary between a zero value, some possible value, 53 00:03:37,060 --> 00:03:38,829 and some maximum value. 54 00:03:38,829 --> 00:03:41,650 And here we see one more example. 55 00:03:41,650 --> 00:03:45,880 In order for the wheel to continue to accelerate down 56 00:03:45,880 --> 00:03:48,310 the inclined plane and roll without slipping 57 00:03:48,310 --> 00:03:51,340 that the static friction must produce a torque 58 00:03:51,340 --> 00:03:54,160 that causes the angular acceleration. 59 00:03:54,160 --> 00:03:57,280 And so we see that static friction 60 00:03:57,280 --> 00:04:03,447 depends on the other constraints in the problem.