1 00:00:03,510 --> 00:00:09,660 We would like to now apply the momentum principle 2 00:00:09,660 --> 00:00:12,750 to examples of recoil. 3 00:00:12,750 --> 00:00:16,750 So recall that the momentum principle 4 00:00:16,750 --> 00:00:20,670 is that the external force causes the momentum 5 00:00:20,670 --> 00:00:23,860 of the system to change. 6 00:00:23,860 --> 00:00:25,680 Now, this is a vector equation. 7 00:00:25,680 --> 00:00:29,250 So for example, if the external force in the x direction 8 00:00:29,250 --> 00:00:34,010 is 0, then the momentum of the system in the x direction, 9 00:00:34,010 --> 00:00:36,310 let's say, the final momentum will be 10 00:00:36,310 --> 00:00:40,780 equal to the initial momentum. 11 00:00:40,780 --> 00:00:43,310 I would like to now apply the momentum principle 12 00:00:43,310 --> 00:00:46,780 to an example of recoil. 13 00:00:46,780 --> 00:00:50,430 In our recoil example, we have a person jumping off a cart. 14 00:00:50,430 --> 00:00:57,490 So let's just look at how this example can work 15 00:00:57,490 --> 00:00:59,950 if we draw momentum diagrams. 16 00:00:59,950 --> 00:01:04,720 So suppose we choose a ground frame. 17 00:01:04,720 --> 00:01:09,530 And in that ground frame, we have a cart and a person. 18 00:01:09,530 --> 00:01:11,490 A person is standing on the cart. 19 00:01:11,490 --> 00:01:14,380 And this is t initial. 20 00:01:14,380 --> 00:01:18,670 And here, they are at rest. 21 00:01:18,670 --> 00:01:21,860 Now, the person we're going to assume to jump horizontally 22 00:01:21,860 --> 00:01:24,330 off the cart, and the cart will recoil 23 00:01:24,330 --> 00:01:26,000 in the opposite direction. 24 00:01:26,000 --> 00:01:30,600 So after the jump, we can describe this picture. 25 00:01:30,600 --> 00:01:33,000 The person is moving with the velocity, 26 00:01:33,000 --> 00:01:35,051 v. The cart is moving with vc. 27 00:01:35,051 --> 00:01:41,009 And the person has jumped with the velocity vp. 28 00:01:41,009 --> 00:01:46,200 Now, suppose I choose a different reference frame. 29 00:01:46,200 --> 00:01:47,860 That instead of choosing a ground 30 00:01:47,860 --> 00:02:00,700 frame, as a reference frame moving with the velocity vc. 31 00:02:00,700 --> 00:02:05,900 You can imagine that maybe I have a car here 32 00:02:05,900 --> 00:02:09,690 and you're inside that car moving with velocity vc, 33 00:02:09,690 --> 00:02:12,460 and you're looking at this picture. 34 00:02:12,460 --> 00:02:15,520 Then, what would our momentum diagrams look like? 35 00:02:15,520 --> 00:02:17,870 Well, if I'm moving in a car this way 36 00:02:17,870 --> 00:02:21,390 and in the ground frame the initial picture 37 00:02:21,390 --> 00:02:23,820 is the person in the cart is at rest. 38 00:02:23,820 --> 00:02:25,740 Then, in my moving frame, it actually 39 00:02:25,740 --> 00:02:28,370 looks as if the cart and the person 40 00:02:28,370 --> 00:02:30,870 are moving in the opposite direction. 41 00:02:30,870 --> 00:02:33,950 So let's write that this way. 42 00:02:33,950 --> 00:02:37,970 Here's the initial picture, t initial. 43 00:02:37,970 --> 00:02:41,250 And in this frame, the person and the cart 44 00:02:41,250 --> 00:02:44,980 are moving with vc minus vc. 45 00:02:44,980 --> 00:02:47,450 I put an arrow here to indicate that it's 46 00:02:47,450 --> 00:02:50,320 opposite the direction of vc there. 47 00:02:50,320 --> 00:02:54,079 But their velocity is minus the velocity 48 00:02:54,079 --> 00:02:55,630 of the reference frame. 49 00:02:55,630 --> 00:03:00,790 After the jump-- so here's the person now. 50 00:03:00,790 --> 00:03:04,160 The cart is at rest, why? 51 00:03:04,160 --> 00:03:07,700 Because we're in the reference frame moving with vc. 52 00:03:07,700 --> 00:03:10,500 So if you're in a car and you're moving at the same speed 53 00:03:10,500 --> 00:03:12,960 that the cart has with the ground frame, 54 00:03:12,960 --> 00:03:17,840 then in your frame, this cart looks like it's at rest. 55 00:03:17,840 --> 00:03:19,930 What about the person jumping off? 56 00:03:19,930 --> 00:03:22,970 Well, let's write it this way. 57 00:03:22,970 --> 00:03:24,050 So this is the velocity. 58 00:03:24,050 --> 00:03:26,630 I'm going to use a symbol, u. 59 00:03:26,630 --> 00:03:30,260 Now, u-- this is what do we mean by that. 60 00:03:30,260 --> 00:03:38,950 This is the velocity of the person in the moving 61 00:03:38,950 --> 00:03:47,240 frame that's moving with velocity vc-- that's 62 00:03:47,240 --> 00:03:49,770 the velocity of the person as seen by a car. 63 00:03:49,770 --> 00:03:56,640 Sometimes we call this the velocity of the person 64 00:03:56,640 --> 00:04:03,030 relative to the cart. 65 00:04:03,030 --> 00:04:06,550 What does that word relative to the cart mean? 66 00:04:06,550 --> 00:04:09,020 Well, you can see in this picture. 67 00:04:09,020 --> 00:04:11,060 In this moving frame, the cart is at rest, 68 00:04:11,060 --> 00:04:13,890 and the person jumps with the speed u velocity 69 00:04:13,890 --> 00:04:16,760 u relative to the cart. 70 00:04:16,760 --> 00:04:20,654 So these are momentum diagrams for a ground frame 71 00:04:20,654 --> 00:04:22,280 in which the person in the cart started 72 00:04:22,280 --> 00:04:24,800 at rest, the person jumps off. 73 00:04:24,800 --> 00:04:27,060 I can put an arrow here, but it's really 74 00:04:27,060 --> 00:04:28,790 information is in that vector. 75 00:04:28,790 --> 00:04:30,550 The cart is moving. 76 00:04:30,550 --> 00:04:33,790 In a frame moving with the velocity of the cart, 77 00:04:33,790 --> 00:04:37,780 then what does my picture looks like? 78 00:04:37,780 --> 00:04:39,550 Well, the cart and the person initially 79 00:04:39,550 --> 00:04:42,960 are moving opposite directions. 80 00:04:42,960 --> 00:04:44,274 Again, you're moving this way. 81 00:04:44,274 --> 00:04:45,940 The cart looks like it's moving that way 82 00:04:45,940 --> 00:04:47,900 if you're inside the car. 83 00:04:47,900 --> 00:04:52,110 And the final state, person, cart is at rest 84 00:04:52,110 --> 00:04:55,590 and the person is jumping with the velocity u 85 00:04:55,590 --> 00:04:57,540 relative to the cart. 86 00:04:57,540 --> 00:05:01,140 Now, our question now is how do we relate 87 00:05:01,140 --> 00:05:05,460 these two velocities, u and vp? 88 00:05:05,460 --> 00:05:07,260 What are u and vp? 89 00:05:07,260 --> 00:05:10,310 vp is the velocity of the person in the ground frame. 90 00:05:10,310 --> 00:05:14,140 And u is the velocity of the person in the moving frame. 91 00:05:14,140 --> 00:05:16,410 Well, we've already seen our equation 92 00:05:16,410 --> 00:05:18,970 for how to get velocities in different frames. 93 00:05:18,970 --> 00:05:23,530 We have that vp equals the relative velocity of the two 94 00:05:23,530 --> 00:05:27,140 frames plus the velocity in the moving frame. 95 00:05:27,140 --> 00:05:33,570 So what we have is, this is the velocity of the person-- 96 00:05:33,570 --> 00:05:40,600 let me just clean that up-- of the person in the ground frame. 97 00:05:45,130 --> 00:05:48,490 v is the relative velocity of the two frames. 98 00:05:48,490 --> 00:05:52,130 So here we have that v is the velocity of the cart, 99 00:05:52,130 --> 00:05:55,290 because you're in a frame moving with vc with respect 100 00:05:55,290 --> 00:05:56,530 to the ground. 101 00:05:56,530 --> 00:06:08,010 And u is the velocity of the person in the moving frame. 102 00:06:11,590 --> 00:06:16,440 So this is how we can show the same type of interaction 103 00:06:16,440 --> 00:06:18,980 in two different reference frames. 104 00:06:18,980 --> 00:06:22,790 Next, we'll figure out what these velocities are.