1 00:00:03,410 --> 00:00:05,330 Let's consider a two dimensional motion. 2 00:00:05,330 --> 00:00:09,080 Suppose we have something like projectile motion. 3 00:00:09,080 --> 00:00:10,940 And we have an object moving. 4 00:00:10,940 --> 00:00:15,620 Let's now describe how we can describe this motion 5 00:00:15,620 --> 00:00:16,866 with vectors. 6 00:00:16,866 --> 00:00:18,240 So the first thing we always want 7 00:00:18,240 --> 00:00:20,410 to do, and let's remind ourselves of the steps, 8 00:00:20,410 --> 00:00:23,216 is we want to choose a coordinate system. 9 00:00:23,216 --> 00:00:25,090 Now what does a coordinate system consist of? 10 00:00:25,090 --> 00:00:27,150 It consists of an origin. 11 00:00:27,150 --> 00:00:28,530 It consists of two axes. 12 00:00:28,530 --> 00:00:31,370 In this case, we'll identify the positive direction 13 00:00:31,370 --> 00:00:34,620 for each axis as plus x and plus y. 14 00:00:34,620 --> 00:00:37,760 And at every single point in space-- 15 00:00:37,760 --> 00:00:42,330 so if we had any arbitrary point P here-- let's call this P1. 16 00:00:42,330 --> 00:00:47,570 We have a choice of unit vectors, i-hat 1 and j-hat 1. 17 00:00:47,570 --> 00:00:49,570 Now, what makes Cartesian coordinates 18 00:00:49,570 --> 00:00:53,210 unique is that no matter what point we're at, 19 00:00:53,210 --> 00:00:55,450 the unit vectors are all the same. 20 00:00:55,450 --> 00:00:58,370 So we could erase all these indices 21 00:00:58,370 --> 00:01:00,430 for that particular point and just 22 00:01:00,430 --> 00:01:04,819 have an abstract set of unit vectors, i-hat and j-hat. 23 00:01:04,819 --> 00:01:07,770 Now normally what we'll do is we'll just put those off 24 00:01:07,770 --> 00:01:09,610 to the side. 25 00:01:09,610 --> 00:01:12,940 So in our Cartesian coordinates, we now 26 00:01:12,940 --> 00:01:15,650 want to define the position vector. 27 00:01:15,650 --> 00:01:17,410 And the position vector is a vector 28 00:01:17,410 --> 00:01:20,310 from the origin to where the object is. 29 00:01:20,310 --> 00:01:22,700 So we'll write that position vector. 30 00:01:22,700 --> 00:01:24,910 We'll denote it by r of t. 31 00:01:24,910 --> 00:01:27,650 Because as this object moves along its trajectory 32 00:01:27,650 --> 00:01:29,700 that position vector is changing. 33 00:01:29,700 --> 00:01:32,680 And we'll write down r of t in terms 34 00:01:32,680 --> 00:01:39,509 of two coordinate functions, x of t and y of t. 35 00:01:39,509 --> 00:01:44,030 And so our vector-- position vector of the object r of t 36 00:01:44,030 --> 00:01:51,259 is equal to x of t, i-hat plus y of t, j-hat. 37 00:01:51,259 --> 00:01:54,470 And one of our main goals is to figure out 38 00:01:54,470 --> 00:01:59,300 what these position functions are for the motion of objects. 39 00:01:59,300 --> 00:02:02,050 So this is how we describe an object 40 00:02:02,050 --> 00:02:04,120 in a Cartesian coordinate system, 41 00:02:04,120 --> 00:02:06,720 undergoing two dimensional motion. 42 00:02:06,720 --> 00:02:09,180 What we want to analyze next is what 43 00:02:09,180 --> 00:02:11,820 is the velocity of that object.