1 00:00:07,010 --> 00:00:10,220 MARKUS KLUTE: Welcome back to Special Relativity, 8.20. 2 00:00:10,220 --> 00:00:13,250 In this section, we're going to talk about proper velocity. 3 00:00:13,250 --> 00:00:17,330 We have seen already concepts of proper time and proper length 4 00:00:17,330 --> 00:00:20,930 as the time and the space as seen 5 00:00:20,930 --> 00:00:24,170 in the object's own reference frame. 6 00:00:24,170 --> 00:00:26,600 So now we want to try to find something similar 7 00:00:26,600 --> 00:00:29,420 for velocities, as we have seen the Lorentz 8 00:00:29,420 --> 00:00:32,150 transformation applied to velocities 9 00:00:32,150 --> 00:00:34,370 of a quite difficult form. 10 00:00:34,370 --> 00:00:37,220 As a reminder, velocity is given as a change 11 00:00:37,220 --> 00:00:39,830 in space of a change in time. 12 00:00:39,830 --> 00:00:44,542 We have seen the Lorentz transformation of a velocity x 13 00:00:44,542 --> 00:00:47,000 in a reference frame which is boosted in the same direction 14 00:00:47,000 --> 00:00:48,050 x. 15 00:00:48,050 --> 00:00:52,620 And you see that this new velocity x prime 16 00:00:52,620 --> 00:00:55,350 is given by new x minus v. So there's 17 00:00:55,350 --> 00:00:57,740 a velocity addition going on, which 18 00:00:57,740 --> 00:01:03,290 is corrected then by this factor 1 minus uxv over c squared. 19 00:01:03,290 --> 00:01:08,540 You've also seen that even so, the boost is in x direction. 20 00:01:08,540 --> 00:01:12,140 There's also modification of the velocity in y direction 21 00:01:12,140 --> 00:01:13,890 and in z direction. 22 00:01:13,890 --> 00:01:14,390 OK? 23 00:01:14,390 --> 00:01:17,270 So you see that basically, there is this-- 24 00:01:19,810 --> 00:01:23,570 the velocity itself is corrected with this new factor. 25 00:01:23,570 --> 00:01:26,390 Note here that there is a special case 26 00:01:26,390 --> 00:01:29,300 in which the direct-- the velocity in x direction 27 00:01:29,300 --> 00:01:30,680 is equal to 0. 28 00:01:30,680 --> 00:01:33,620 Think about this object being in its own rest frame, 29 00:01:33,620 --> 00:01:38,310 again, where the velocity in the booth direction is 0. 30 00:01:38,310 --> 00:01:40,710 You see that both equations simplify 31 00:01:40,710 --> 00:01:46,470 for ux prime that would be simply equal to minus v, 32 00:01:46,470 --> 00:01:54,420 where uy prime would be uy prime and uv prime would be uv. 33 00:01:54,420 --> 00:01:58,170 So let's try to get at it. 34 00:01:58,170 --> 00:02:02,850 Let's try to express velocities in terms of the proper time, 35 00:02:02,850 --> 00:02:07,360 at the time as it ticks in the object reference frame. 36 00:02:07,360 --> 00:02:10,979 So we have seen that the time is given by gamma times 37 00:02:10,979 --> 00:02:13,440 the time in the rest frame or time in the proper-- 38 00:02:13,440 --> 00:02:15,750 times gamma times the proper time. 39 00:02:15,750 --> 00:02:19,350 Note here that we have two different gamma 40 00:02:19,350 --> 00:02:20,760 factors to play with. 41 00:02:20,760 --> 00:02:24,840 One is a gamma factor of the Lorentz transformation. 42 00:02:24,840 --> 00:02:28,980 And this gamma here is the gamma using 43 00:02:28,980 --> 00:02:32,440 the speed of the object in a specific reference frame. 44 00:02:32,440 --> 00:02:36,270 So this is the gamma which is a gamma factor which 45 00:02:36,270 --> 00:02:41,660 is a gamma of v of the velocity or the speed of the object. 46 00:02:41,660 --> 00:02:44,680 And now we can just simply define proper velocity 47 00:02:44,680 --> 00:02:49,640 if I use this vector eta here, which is a four vector, which 48 00:02:49,640 --> 00:02:54,880 is the derivative of the spatial component with the proper time. 49 00:02:54,880 --> 00:02:58,320 And when we do this, you find this relatively simple solution 50 00:02:58,320 --> 00:03:02,880 of gamma times c for the 0's component, gamma times ux, 51 00:03:02,880 --> 00:03:11,570 gamma times uy, and gamma times uz for the last component. 52 00:03:11,570 --> 00:03:16,460 So the question now is, we defined this new velocity 53 00:03:16,460 --> 00:03:19,800 of an object where the time of the object 54 00:03:19,800 --> 00:03:22,880 ticks in its own reference frame using 55 00:03:22,880 --> 00:03:25,440 this property as proper time. 56 00:03:25,440 --> 00:03:26,490 OK? 57 00:03:26,490 --> 00:03:28,860 If we now try a Lorentz transformation on this, 58 00:03:28,860 --> 00:03:32,910 we can simply apply the matrix for Lorentz transformation 59 00:03:32,910 --> 00:03:35,370 on this four vector and find the solution here. 60 00:03:38,900 --> 00:03:43,160 You can see that this is consistent by doing 61 00:03:43,160 --> 00:03:48,680 this with the original components in this proper time 62 00:03:48,680 --> 00:03:49,180 as well. 63 00:03:49,180 --> 00:03:52,440 You see that those actually are a consistent answer. 64 00:03:52,440 --> 00:03:54,590 It makes a lot of sense.