1 00:00:04,610 --> 00:00:07,420 MARKUS KLUTE: All right, so welcome back to 8.801. 2 00:00:07,420 --> 00:00:10,720 We'll continue our discussion on Feynman calculus. 3 00:00:10,720 --> 00:00:14,200 And here we dive into toy theory. 4 00:00:14,200 --> 00:00:16,390 So this theory is a toy. 5 00:00:16,390 --> 00:00:20,710 And it's just an example to illustrate Feynman rules. 6 00:00:20,710 --> 00:00:23,370 What we do, the simplification we employ here 7 00:00:23,370 --> 00:00:26,260 is leaving out the spin of the particle involved. 8 00:00:26,260 --> 00:00:31,430 We consider the spin, we add another algebraic complication 9 00:00:31,430 --> 00:00:33,072 which is quite now confusing. 10 00:00:33,072 --> 00:00:34,280 So we leave this out for now. 11 00:00:34,280 --> 00:00:36,250 We come back later to this. 12 00:00:36,250 --> 00:00:38,950 So we're supposed to have three kinds of particles involved 13 00:00:38,950 --> 00:00:41,770 here-- particle A, B, and C. And so we 14 00:00:41,770 --> 00:00:45,280 can have a primary vertex where these all three particle are 15 00:00:45,280 --> 00:00:47,840 interacting like shown here. 16 00:00:47,840 --> 00:00:54,970 So particle A, might decay into particle B and C. 17 00:00:54,970 --> 00:00:56,950 You can assume that particle A is heavier 18 00:00:56,950 --> 00:01:01,510 than the sum of B and C, so this is schematically allowed. 19 00:01:01,510 --> 00:01:05,840 We might also have corrections involved here as shown here. 20 00:01:05,840 --> 00:01:08,230 And what we'd be interested in is now, for example, 21 00:01:08,230 --> 00:01:12,480 calculating the lifetime of this particle A. 22 00:01:12,480 --> 00:01:15,990 We might do this just for this primitive vertex. 23 00:01:15,990 --> 00:01:20,370 Or we might do this for this complicated set of corrections. 24 00:01:20,370 --> 00:01:24,030 We might also be interested in calculating scattering 25 00:01:24,030 --> 00:01:26,670 processes where particle A is scattered with particle A 26 00:01:26,670 --> 00:01:29,460 and produces particle B and particle B. 27 00:01:29,460 --> 00:01:33,220 Or we scatter particle A with particle B and so on. 28 00:01:33,220 --> 00:01:36,250 So in this theory, at the end of the lecture, 29 00:01:36,250 --> 00:01:39,450 we have all tools in hand to calculate this. 30 00:01:39,450 --> 00:01:42,660 No worries-- I will not leave you alone with this. 31 00:01:42,660 --> 00:01:45,240 This lecture, we go through the recipe. 32 00:01:45,240 --> 00:01:48,400 And then later on we'll see how we actually apply this. 33 00:01:48,400 --> 00:01:50,680 So let's look at this recipe. 34 00:01:50,680 --> 00:01:52,800 So the recipe has a number of steps. 35 00:01:52,800 --> 00:01:57,210 And the key is to just follow those steps in order 36 00:01:57,210 --> 00:01:59,940 to get to the desired result. 37 00:01:59,940 --> 00:02:02,670 The first step is to label incoming and outgoing 38 00:02:02,670 --> 00:02:04,560 four-momenta of particles. 39 00:02:04,560 --> 00:02:09,600 We label them with p1, p2, and up to pn. 40 00:02:09,600 --> 00:02:12,520 We also want to label all internal momenta. 41 00:02:12,520 --> 00:02:14,850 So we have an internal line, then we 42 00:02:14,850 --> 00:02:19,920 want to label this internal momenta with q1, q2, and so on. 43 00:02:19,920 --> 00:02:21,840 We want to add arrows to each line 44 00:02:21,840 --> 00:02:25,650 to keep track of what is a positive direction, as we 45 00:02:25,650 --> 00:02:29,040 discussed before, particles might travel backwards in time. 46 00:02:29,040 --> 00:02:31,080 Those are typically antiparticles. 47 00:02:31,080 --> 00:02:34,530 And for those we, have to make sure that we correctly 48 00:02:34,530 --> 00:02:37,170 account for the momenta. 49 00:02:37,170 --> 00:02:42,170 For each vertex, we have a factor. 50 00:02:42,170 --> 00:02:45,170 We write this factor minus ig, where 51 00:02:45,170 --> 00:02:47,100 g is the coupling constant. 52 00:02:47,100 --> 00:02:48,740 So this is a measure of the strength 53 00:02:48,740 --> 00:02:51,540 of the interaction involved. 54 00:02:51,540 --> 00:02:52,790 Then we have a propagator. 55 00:02:52,790 --> 00:02:55,580 So for each internal line, the internal lines 56 00:02:55,580 --> 00:02:56,990 are also called propagator. 57 00:02:56,990 --> 00:03:02,360 We write down a factor, i over qj squared minus mj 58 00:03:02,360 --> 00:03:03,890 squared t squared. 59 00:03:03,890 --> 00:03:08,710 Note that qj squared doesn't have 60 00:03:08,710 --> 00:03:12,280 to be mj squared c squared, meaning that the parity can 61 00:03:12,280 --> 00:03:15,980 be off shell, off mass shell. 62 00:03:15,980 --> 00:03:18,573 You also see that there is a complication in the integral 63 00:03:18,573 --> 00:03:20,740 when you actually have those vectors being the same. 64 00:03:24,740 --> 00:03:27,320 You want to make sure that energy and momentum is 65 00:03:27,320 --> 00:03:28,080 conserved. 66 00:03:28,080 --> 00:03:34,790 So for each vertex, you write down a delta function 67 00:03:34,790 --> 00:03:35,670 with the conditions. 68 00:03:35,670 --> 00:03:39,770 This is for this three vertex where momentum of the first one 69 00:03:39,770 --> 00:03:42,950 plus the second plus the third is equal to 0. 70 00:03:42,950 --> 00:03:46,580 Only then the value of the delta function is 1. 71 00:03:46,580 --> 00:03:48,710 Remember, there's a minus sign somewhere, 72 00:03:48,710 --> 00:03:53,630 most likely here for this k1 value. 73 00:03:53,630 --> 00:03:56,550 Then you want to integrate overall internal momenta. 74 00:03:56,550 --> 00:04:00,530 So for each internal line, we write a factor-- 75 00:04:00,530 --> 00:04:04,070 1 over 2 pi to the fourth power. 76 00:04:04,070 --> 00:04:06,980 d4 is on your momenta. 77 00:04:06,980 --> 00:04:11,690 And then, this all will result in a delta function, 78 00:04:11,690 --> 00:04:13,670 which you just eliminate. 79 00:04:13,670 --> 00:04:17,089 And you do that by multiplying it. 80 00:04:17,089 --> 00:04:20,810 You erase this delta function and you replace it 81 00:04:20,810 --> 00:04:23,090 by a factor i. 82 00:04:23,090 --> 00:04:24,830 So this seems like very confusing. 83 00:04:24,830 --> 00:04:27,110 Why do you add delta functions first, and then 84 00:04:27,110 --> 00:04:28,460 you erase them later? 85 00:04:28,460 --> 00:04:38,350 Note in Fermi's golden rule, we use 86 00:04:38,350 --> 00:04:40,430 the squared of the amplitude. 87 00:04:40,430 --> 00:04:42,790 And you also saw that the [? phase-based ?] factors 88 00:04:42,790 --> 00:04:48,160 already have this kind of delta functions included. 89 00:04:48,160 --> 00:04:50,710 So we get out of the complications that we 90 00:04:50,710 --> 00:04:53,650 don't really know what to square of the delta function is 91 00:04:53,650 --> 00:04:58,570 by erasing, by adding the i and then keeping track 92 00:04:58,570 --> 00:05:03,580 of the momentum conservation, this conservation here when we 93 00:05:03,580 --> 00:05:05,230 apply the [? phase-based ?] factor. 94 00:05:05,230 --> 00:05:09,940 And then, voila, you just calculated a matrix element. 95 00:05:09,940 --> 00:05:12,370 All right, so those are the rules. 96 00:05:12,370 --> 00:05:16,740 Now the key is to practice how to apply them. 97 00:05:16,740 --> 00:05:19,670 So what we do next is to practice using this toy 98 00:05:19,670 --> 00:05:23,060 experiment in how to calculate the matrix element, 99 00:05:23,060 --> 00:05:26,970 the [? phase ?] base, and the z decay rates and cross sections. 100 00:05:26,970 --> 00:05:30,750 And then as a following step, we will see how this all unfolds. 101 00:05:30,750 --> 00:05:32,510 Then we have a real series, like QED, 102 00:05:32,510 --> 00:05:36,910 like the weak interaction and the strong interaction.