1 00:00:04,730 --> 00:00:06,912 MARKUS KLUTE: Welcome back to 8.701. 2 00:00:06,912 --> 00:00:10,040 So again, we have now all tools in place 3 00:00:10,040 --> 00:00:13,180 to do a next round of cross-section calculations. 4 00:00:13,180 --> 00:00:16,170 We have seen how to set up a matrix element. 5 00:00:16,170 --> 00:00:20,100 We have seen how to build spin average or to treat the spin, 6 00:00:20,100 --> 00:00:22,010 and then specifically to calculate 7 00:00:22,010 --> 00:00:26,960 spin average amplitudes using [INAUDIBLE].. 8 00:00:26,960 --> 00:00:30,620 All right, I'm not saying that this is all easy now, 9 00:00:30,620 --> 00:00:33,020 but you have seen all necessarily 10 00:00:33,020 --> 00:00:37,410 elements to calculate a cross-section for QED process. 11 00:00:37,410 --> 00:00:38,630 So let's summarize. 12 00:00:38,630 --> 00:00:45,730 So we have seen that we can set up some matrix element using 13 00:00:45,730 --> 00:00:47,780 Feynman rules for QED. 14 00:00:47,780 --> 00:00:53,970 We have seen how to set up the spin average matrix element 15 00:00:53,970 --> 00:00:55,890 squared using the traces. 16 00:00:55,890 --> 00:00:58,590 Now we would have to evaluate the traces in order 17 00:00:58,590 --> 00:01:02,140 to derive this formula here. 18 00:01:02,140 --> 00:01:05,550 So I'll spare you a precise discussion of this step here, 19 00:01:05,550 --> 00:01:11,730 but you can actually follow this quite straightforwardly. 20 00:01:11,730 --> 00:01:14,370 Let me just step back a little bit before we proceed. 21 00:01:14,370 --> 00:01:17,220 My goal for the class is not to have you calculate 22 00:01:17,220 --> 00:01:20,340 all kinds of cross-section processes, 23 00:01:20,340 --> 00:01:23,220 but to understand how you would do it, 24 00:01:23,220 --> 00:01:25,440 for the purpose of really understanding 25 00:01:25,440 --> 00:01:29,340 where dependencies come from and where this kind of calculation 26 00:01:29,340 --> 00:01:31,000 has its limitations. 27 00:01:31,000 --> 00:01:33,660 The first part is you want to see 28 00:01:33,660 --> 00:01:38,420 what is the dependencies on the couplings involved. 29 00:01:38,420 --> 00:01:40,440 You see this g squared, for example. 30 00:01:40,440 --> 00:01:42,300 That's a rather important effect. 31 00:01:42,300 --> 00:01:44,910 You also want to see, so Fermi's this golden rule, 32 00:01:44,910 --> 00:01:48,210 how we get actually into the cross-section from the matrix 33 00:01:48,210 --> 00:01:50,500 element calculation. 34 00:01:50,500 --> 00:01:52,860 So if you ever had to calculate a matrix element, 35 00:01:52,860 --> 00:01:56,640 am I going to ask you to do this once, maybe twice, 36 00:01:56,640 --> 00:01:59,190 as part of the homework set. 37 00:01:59,190 --> 00:02:02,880 I encourage you to open the book, follow the rules, 38 00:02:02,880 --> 00:02:07,200 look up tricks, how to work with traces. 39 00:02:07,200 --> 00:02:09,690 And then you should get to a reasonable solution 40 00:02:09,690 --> 00:02:11,009 in a reasonable amount of time. 41 00:02:14,130 --> 00:02:16,430 But here for the purpose of this discussion, 42 00:02:16,430 --> 00:02:19,580 we want to just have a look at a few specific cases 43 00:02:19,580 --> 00:02:21,890 where we make assumptions and simplifications 44 00:02:21,890 --> 00:02:23,520 to the discussion. 45 00:02:23,520 --> 00:02:26,850 So the first one is called Mott scattering. 46 00:02:26,850 --> 00:02:30,822 So here, again, we are at this example of a spin-half particle 47 00:02:30,822 --> 00:02:32,405 scattering with a spin-half particle-- 48 00:02:32,405 --> 00:02:36,710 a different spin-half particle, so an exchange of a photon. 49 00:02:36,710 --> 00:02:39,890 So we used the example of an electron-muon scattering, 50 00:02:39,890 --> 00:02:43,160 but this muon here could also be a proton or any other nuclei 51 00:02:43,160 --> 00:02:44,930 we spin off. 52 00:02:44,930 --> 00:02:48,710 The assumption for Mott scattering we are using 53 00:02:48,710 --> 00:02:51,260 is that the mass of this particle, the muon, 54 00:02:51,260 --> 00:02:53,870 is much heavier than the mass of the electron. 55 00:02:53,870 --> 00:02:58,970 And that's true the muon 200 times heavier than an electron. 56 00:02:58,970 --> 00:03:00,800 A proton is even heavier. 57 00:03:00,800 --> 00:03:04,145 Any heavier nuclei of this feels even heavier than this. 58 00:03:04,145 --> 00:03:06,590 In Mott scattering, we also make the assumption 59 00:03:06,590 --> 00:03:08,570 that the momenta involved are lower 60 00:03:08,570 --> 00:03:10,310 than the mass of the heavy particle 61 00:03:10,310 --> 00:03:15,080 and that the recoil of the heavy nuclei, or the muon, 62 00:03:15,080 --> 00:03:17,300 can be neglected. 63 00:03:17,300 --> 00:03:23,090 If we do that, we can then write the differential cross-section 64 00:03:23,090 --> 00:03:26,270 using Fermi's golden rule as a spin average matrix 65 00:03:26,270 --> 00:03:29,920 element squared divided by 2 pi M squared. 66 00:03:29,920 --> 00:03:31,490 OK. 67 00:03:31,490 --> 00:03:36,840 If you then use this kinematic information, 68 00:03:36,840 --> 00:03:39,690 you basically start from this matrix element here. 69 00:03:39,690 --> 00:03:43,020 And then you use those vectors, those four vectors, 70 00:03:43,020 --> 00:03:45,850 for your momentum of the first, second, third, 71 00:03:45,850 --> 00:03:48,240 and fourth particle. 72 00:03:48,240 --> 00:03:51,750 You find that many of the vectors are simplifying to ME. 73 00:03:51,750 --> 00:03:53,970 So p2 times p3 is ME. 74 00:03:53,970 --> 00:03:55,650 And so are many of the others. 75 00:03:55,650 --> 00:03:57,390 And there is a few important factors. 76 00:03:57,390 --> 00:04:02,790 For example, p1 minus p3 squared is minus 4p squared sine 77 00:04:02,790 --> 00:04:04,500 squared theta half. 78 00:04:04,500 --> 00:04:08,250 And similarly, p1 times p3. 79 00:04:08,250 --> 00:04:10,800 So you put this all in-- 80 00:04:10,800 --> 00:04:12,900 again, starting from this very formula we 81 00:04:12,900 --> 00:04:15,180 just had discussed before-- 82 00:04:15,180 --> 00:04:17,220 and you put all the simplifications 83 00:04:17,220 --> 00:04:21,300 and you get this matrix element, which already that 84 00:04:21,300 --> 00:04:22,790 looks much more manageable. 85 00:04:22,790 --> 00:04:24,540 There's an M squared, there's a p squared, 86 00:04:24,540 --> 00:04:27,960 there's a cosine squared theta half term, 87 00:04:27,960 --> 00:04:32,670 and some factor which depends on the moment times the mass. 88 00:04:32,670 --> 00:04:35,070 And if you then add this to Fermi's golden rule, 89 00:04:35,070 --> 00:04:37,770 you find this equation for your Mott scattering. 90 00:04:37,770 --> 00:04:40,590 Again, this is the scattering of two 91 00:04:40,590 --> 00:04:44,040 different spin-half particles where one is much heavier. 92 00:04:44,040 --> 00:04:45,730 The outgoing momenta are small. 93 00:04:45,730 --> 00:04:50,070 And the recoil of the heavier particles can be neglected. 94 00:04:50,070 --> 00:04:51,960 So this Mott's formula describes, 95 00:04:51,960 --> 00:04:54,570 for example, the Coulomb scattering, so the scattering 96 00:04:54,570 --> 00:04:59,080 this photon on the electric charge of a nuclei. 97 00:04:59,080 --> 00:05:02,260 And the scattering particle is not too heavy and not too 98 00:05:02,260 --> 00:05:05,320 energetic, like an electron. 99 00:05:05,320 --> 00:05:07,910 We also assume that everything involved here is point-like. 100 00:05:07,910 --> 00:05:13,390 We haven't had any discussion on the charge distribution 101 00:05:13,390 --> 00:05:14,740 of the nuclei or anything. 102 00:05:14,740 --> 00:05:18,370 We assume that this is a point-like particle. 103 00:05:18,370 --> 00:05:21,370 OK, we can further discuss now the case 104 00:05:21,370 --> 00:05:24,460 where the initial state particles are non-relativistic. 105 00:05:24,460 --> 00:05:26,980 So here our momentum formulas simplify. 106 00:05:26,980 --> 00:05:31,480 This is simply M squared, p amplitudes is 2ME. 107 00:05:31,480 --> 00:05:34,930 And alpha is q1 times q2. 108 00:05:37,660 --> 00:05:39,520 Those are the electric charges. 109 00:05:39,520 --> 00:05:41,860 And so then our differential cross-section 110 00:05:41,860 --> 00:05:44,980 further simplifies to something you've already seen. 111 00:05:44,980 --> 00:05:48,490 The Lorentzian cross-section is equal to q1 times 112 00:05:48,490 --> 00:05:51,650 q2 divided by 4 times the energy sine 113 00:05:51,650 --> 00:05:53,080 squared theta half squared. 114 00:05:53,080 --> 00:05:57,730 And we have seen that as already the Rutherford scattering 115 00:05:57,730 --> 00:06:00,310 cross-section when we discussed cross-section measurements 116 00:06:00,310 --> 00:06:02,840 in a geometrical kind of thing. 117 00:06:02,840 --> 00:06:07,660 So this closes a loop here in our cross-section discussion 118 00:06:07,660 --> 00:06:10,250 how we can think about those things. 119 00:06:10,250 --> 00:06:12,160 The Rutherford cross-section is nothing else 120 00:06:12,160 --> 00:06:17,140 but a big billiard ball being hit by a small billiard ball 121 00:06:17,140 --> 00:06:21,820 and looking at how the cross-section differentially 122 00:06:21,820 --> 00:06:26,000 kind of evolves out this setup. 123 00:06:26,000 --> 00:06:29,600 All right, in this sequence we have a little bit more 124 00:06:29,600 --> 00:06:30,600 of a discussion. 125 00:06:30,600 --> 00:06:33,710 What happens now if we induce higher-order terms 126 00:06:33,710 --> 00:06:36,830 and how can we think about those solutions? 127 00:06:36,830 --> 00:06:39,515 And then have two extra lectures and where 128 00:06:39,515 --> 00:06:42,680 we go back and discuss spin, and also 129 00:06:42,680 --> 00:06:47,140 how we can actually understand this in a Lagrangian setup.