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GEORGE CHURCH: We've come
to the fifth lecture,

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the first of a series, on
RNA and expression analysis.

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First, a quick review
of last week, and it

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has significant
connections this week,

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where we talked to the
topic of alignments

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and different algorithms for
obtaining pairwise alignments.

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In particular
dynamic programming,

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this led to an even
harder problem,

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which is multi-sequence
alignment, from which we

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will draw pretty heavily at
the beginning of the discussion

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today.

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And then, the issues
of getting the motifs,

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another topic we will touch
upon several times today,

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how you get-- once you have a
multi-sequence alignment, how

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this gives you either an
independent weight matrix where

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different positions are
independent or in a hidden

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Markov model where there is
some dependence between, say,

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adjacent nucleotides in a
simple sequence such as CG.

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So let us carry
over these thoughts

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about multi-sequence
alignment motifs

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and non independence of
positions in sequences

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to the next level higher.

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We will eventually
talk about protein

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three-dimensional structure.

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But a really beautiful
intermediate between proteins

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are the complexities
of protein structure

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and the simplicity of
double-stranded DNA

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is the folding of
RNAs because they're

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based on the same rules
of double-stranded DNA,

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but they have the
complicated structures

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of-- begin to have a complicated
structure of proteins.

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So we'll start with
this integration

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of multi-sequence alignment
of motifs with RNA structure,

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and then we'll switch to
tell about how these RNA

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structures play their
role by achieving

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different levels in the cell.

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In other words, we want
to start to introduce

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how we become quantitative about
the amounts and localization

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of RNAs in the cell.

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Some of the measures that we'll
be talking about and the tool--

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the computational tools
will be more appropriate

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for individual measures
and others will be more,

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what we call, genomics
grade, high throughput

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and high accuracy.

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And we have this--

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since this is a new
category of biological data,

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we have to address random
and systematic errors

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just as we did for
genotyping and sequence data.

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This is a new set of
them and a new set

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of solutions about the same
themes of random and systematic

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errors.

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And then we'll talk
about a particular set

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of interpretation
issues that lead

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to additional considerations.

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And we'll end on time
series data which

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will be a theme
that will connect

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this talk to much later
talks and systems biology

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where the ability to
connect with a time series

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will help establish
causality and connectivity.

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And we'll tie it to the
subject of RNA analysis

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by looking at
messenger RNA to k.

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Now slide three is a
reminder that we'll

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use in two different
contexts tonight.

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First, these are the bell
curves that you've seen,

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at least three of them
integrated before--

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the two discrete
binomial Poisson

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and the normal, which is
symmetric around the mean

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of 20, in this case.

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And just to connect to the
discussion from last time where

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we were asking what the
significance of a match

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of a single sequence
to a database might be,

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when you're asking for a match
of a single-sequence database,

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you're typically really
asking for the maximum match,

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or the maximum--

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the most extreme matches.

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And so when you
talk about extremes,

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when you're sampling
from a distribution,

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and you're looking for
the most extreme value

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for finite sampling
of that distribution,

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that tends to be not from the
normal distribution, which

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would be random sampling,
but from-- which

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is this middle magenta curve.

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But instead, it would be extreme
value distribution, which

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is this blue curve, which
you can see in this case,

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since we're looking
for extreme maximum,

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it's shifted slightly
to the right.

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And so you can see that it
comes inside of the other bell

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curves, on the
left-hand side, and goes

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outside, on the right-hand side.

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If we were looking for
extremely low values then

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it would've been
shifted to the left.

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And remember, all these
continuous functions go off

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to negative infinity
and positive infinity,

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although at
extremely low levels.

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And then that's the
extreme value distribution.

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Now in order to connect this
nucleotide sequence, which

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we've been seeing has these
wonderful Watson Crick base

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pairs that were
TNA, and so forth,

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is to this more complicated
tertiary structure.

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We're going to go
through an intermediate

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of secondary structure
where we really

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look at whether what kind
of base pairs can form.

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And I'm going to immediately
introduce some complexities

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so you don't get too
complacent right off the bat.

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Somewhere in this slide of
non-Watson-Crick base pairs

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is a Watson-Crick base pair.

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Take a moment to find it.

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Fine.

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OK.

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So since we haven't introduced
base pairs, it's going to--

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well, we've seen it twice
now in double-stranded DNA.

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Right in the middle
here are labeled

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A is an AU base pair,
which is Watson-Crick

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where the black dot
indicates the attachment

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to the ribose in RNA, or
to the oxyribose in DNA.

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And you'll find three
other AT base pairs.

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One right to the right
of it and two down below.

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And these four AT
base pairs are all

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different from one
another, most easily

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imagined in terms
of the orientation

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of the riboses, these black
dots, relative to one another.

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And they each have names.

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But the important thing
is that all of these

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are illustrated such
that they maintain

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the coplanarity of the bases.

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They typically maintain
one, or two, or even

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three hydrogen bonds.

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And the planarity allows
them to stack on base pairs

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below and above them,
just as you would

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in normal double-stranded DNA.

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But sometimes, the geometry
distorts the double helix

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enough that you
might get a penalty

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in the free energy in
the thermodynamic sense,

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or the kinetics, in a sense.

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Now here's another.

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So you can find almost--
you can basically

00:07:57.180 --> 00:07:59.010 align:middle line:84%
make one of these
base pairs for all

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of the possible combinations
of ACG and U in RNA.

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And all of them
will be coplanar,

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and they will have one
or more hydrogen bonds.

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Probably the most
stable and most commonly

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encountered in
otherwise normal RNA

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double helices is
a GU base pair.

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And you can see that this
has fairly similar geometry

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to the AU base pair, or for
that matter, the GC base pair.

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So let's see how these non
Watson-Crick base pairs appear.

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And this is the
transfer RNA that we

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saw a couple of slides
ago, spinning around

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in three dimensions.

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And the sequence
that was behind it

00:08:46.190 --> 00:08:49.700 align:middle line:84%
was the DNA sequence
that corresponds

00:08:49.700 --> 00:08:53.015 align:middle line:84%
to this unmodified RNA sequence
on the right-hand side.

00:08:53.015 --> 00:08:56.340 align:middle line:90%


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What we have-- you can think of
this as four fairly canonical

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Watson-Crick type double helices
for RNA double helices, which

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are slightly different from
the DNA double helices.

00:09:12.380 --> 00:09:16.940 align:middle line:84%
But in this-- so we have
seven base pairs, six of which

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are Watson-Crick in
the top stem loop,

00:09:20.690 --> 00:09:23.690 align:middle line:84%
starting at position number
one with the 5-prime end

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and ending position 72.

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So one and 72 is a GC base pair.

00:09:29.250 --> 00:09:31.760 align:middle line:84%
And you can see that
the anticodon where

00:09:31.760 --> 00:09:35.450 align:middle line:84%
it meets the messenger RNA is
at the bottom right-hand part

00:09:35.450 --> 00:09:36.950 align:middle line:90%
of the slide.

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And if you just look
at that loop and--

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you've got a seven-base loop
and a five-base pair anticodon

00:09:45.260 --> 00:09:46.250 align:middle line:90%
stem.

00:09:46.250 --> 00:09:47.310 align:middle line:90%
And so each of these--

00:09:47.310 --> 00:09:51.830 align:middle line:84%
so that each of these stems has
some distinguishing features,

00:09:51.830 --> 00:09:55.370 align:middle line:84%
a number of base pairs
ranges from four to seven.

00:09:55.370 --> 00:09:59.360 align:middle line:84%
You've got a GU base pair in
the middle of the top stem.

00:09:59.360 --> 00:10:02.000 align:middle line:84%
And you've got
little sequence boxes

00:10:02.000 --> 00:10:09.340 align:middle line:84%
which are fairly conserved,
such as this T psi CG The--

00:10:09.340 --> 00:10:13.510 align:middle line:84%
is-- actually, in its
original form is a UU CG.

00:10:13.510 --> 00:10:17.470 align:middle line:84%
And the T and the
psi, or pseudouridine,

00:10:17.470 --> 00:10:19.480 align:middle line:84%
are examples of modified
bases, which are shown

00:10:19.480 --> 00:10:21.110 align:middle line:90%
on the left side of the slide.

00:10:21.110 --> 00:10:23.320 align:middle line:84%
You can see there's
quite a number of them.

00:10:23.320 --> 00:10:27.340 align:middle line:84%
You can add a methyl
group of ch3 groups

00:10:27.340 --> 00:10:30.940 align:middle line:84%
to either of the bases, such
as one methyl group on G.

00:10:30.940 --> 00:10:33.640 align:middle line:84%
Or you can add them to the
riboses, such as the two

00:10:33.640 --> 00:10:38.170 align:middle line:84%
prime methyl groups, which can
go on any of the four bases

00:10:38.170 --> 00:10:41.350 align:middle line:84%
because it's modifying the
ribose which is generic.

00:10:41.350 --> 00:10:44.110 align:middle line:84%
Most of the other ones are
very specific to a base.

00:10:44.110 --> 00:10:46.630 align:middle line:84%
So for example, dihydrouridine
is a modification that

00:10:46.630 --> 00:10:49.210 align:middle line:90%
can only occur to uridines.

00:10:49.210 --> 00:10:52.285 align:middle line:84%
The pseudouridine--
similar thing.

00:10:52.285 --> 00:10:55.660 align:middle line:90%


00:10:55.660 --> 00:10:57.180 align:middle line:90%
And so on.

00:10:57.180 --> 00:10:59.640 align:middle line:84%
So each of these
requires an enzyme.

00:10:59.640 --> 00:11:02.970 align:middle line:84%
And we will highlight one of
the enzymes that's involved

00:11:02.970 --> 00:11:07.140 align:middle line:84%
in putting the methyl
groups onto the sugars,

00:11:07.140 --> 00:11:10.210 align:middle line:84%
the [? 0,2 ?] [? trimethyl ?]
in just a few slides.

00:11:10.210 --> 00:11:11.880 align:middle line:84%
But right now,
what we want to ask

00:11:11.880 --> 00:11:13.930 align:middle line:84%
is how did we get this
folding structure.

00:11:13.930 --> 00:11:15.930 align:middle line:84%
Now this is not the
three-dimensional structure.

00:11:15.930 --> 00:11:18.570 align:middle line:84%
This is the intermediate,
between the primary DNA

00:11:18.570 --> 00:11:21.738 align:middle line:84%
sequence and the fully
modified, fully folded

00:11:21.738 --> 00:11:24.030 align:middle line:84%
three-dimensional structure
that we saw spinning around

00:11:24.030 --> 00:11:25.450 align:middle line:90%
a couple slides ago.

00:11:25.450 --> 00:11:31.250 align:middle line:84%
So the first thing is the
way-- you can try folding

00:11:31.250 --> 00:11:36.170 align:middle line:84%
this, for you oppose
each base pair in turn

00:11:36.170 --> 00:11:38.540 align:middle line:90%
to look for possible matches.

00:11:38.540 --> 00:11:41.150 align:middle line:84%
And then, what we've
done historically--

00:11:41.150 --> 00:11:43.640 align:middle line:84%
this is in the
mid to late '60s--

00:11:43.640 --> 00:11:46.190 align:middle line:84%
was you take each new
transfer RNA sequence

00:11:46.190 --> 00:11:49.880 align:middle line:84%
and ask whether it
makes a decent fold

00:11:49.880 --> 00:11:52.280 align:middle line:84%
in this simple
planar representation

00:11:52.280 --> 00:11:54.320 align:middle line:84%
that's related to
the previous ones,

00:11:54.320 --> 00:11:57.260 align:middle line:84%
under the assumption,
the hope that there would

00:11:57.260 --> 00:12:01.040 align:middle line:84%
be some conservation, not
only of sequence of some

00:12:01.040 --> 00:12:05.600 align:middle line:84%
of these motifs like the PSI
CG, but also the way that it

00:12:05.600 --> 00:12:06.290 align:middle line:90%
folds up.

00:12:06.290 --> 00:12:08.600 align:middle line:84%
And you might even
hypothesize that maybe it

00:12:08.600 --> 00:12:11.180 align:middle line:84%
doesn't matter what the sequence
is in some of these stems.

00:12:11.180 --> 00:12:13.940 align:middle line:84%
What's important is that it's
capable of forming a stem,

00:12:13.940 --> 00:12:19.370 align:middle line:84%
that it is that position one is
complementary to position 72.

00:12:19.370 --> 00:12:22.010 align:middle line:84%
If position one were to
change from a G to an A,

00:12:22.010 --> 00:12:26.840 align:middle line:84%
then position 72 should
change from a C to a U.

00:12:26.840 --> 00:12:31.050 align:middle line:90%
So how do we formalize this?

00:12:31.050 --> 00:12:34.740 align:middle line:84%
How do we formalize the
process by which we generate

00:12:34.740 --> 00:12:36.420 align:middle line:84%
this so-called
cloverleaf structural

00:12:36.420 --> 00:12:43.670 align:middle line:84%
or any similar folding pattern
for small nucleic acids.

00:12:43.670 --> 00:12:46.880 align:middle line:84%
And what are the limitations
of those algorithms.

00:12:46.880 --> 00:12:49.310 align:middle line:84%
And these dotted
lines, you see, are

00:12:49.310 --> 00:12:51.470 align:middle line:84%
some of the non
Watson-Crick based pairs.

00:12:51.470 --> 00:12:52.820 align:middle line:90%
Some of them will stack.

00:12:52.820 --> 00:12:54.590 align:middle line:84%
Many of them-- some
of them will actually

00:12:54.590 --> 00:12:58.280 align:middle line:84%
form the hydrogen bonds of
the Watson-Crick based pair

00:12:58.280 --> 00:13:02.210 align:middle line:84%
but they won't otherwise have
the rest of the geometry.

00:13:02.210 --> 00:13:03.830 align:middle line:84%
And you can see
that some of these

00:13:03.830 --> 00:13:06.740 align:middle line:84%
will provide connections
between two loops which

00:13:06.740 --> 00:13:08.180 align:middle line:90%
are separated by stems.

00:13:08.180 --> 00:13:13.580 align:middle line:84%
And this kind of folding
back means that it's not

00:13:13.580 --> 00:13:18.170 align:middle line:90%
a simple set of helices.

00:13:18.170 --> 00:13:20.240 align:middle line:84%
So the way that
we formalize this

00:13:20.240 --> 00:13:24.980 align:middle line:84%
is we say that position
number one, if it's

00:13:24.980 --> 00:13:31.060 align:middle line:84%
bound to position number 72,
and the exact sequence maybe

00:13:31.060 --> 00:13:34.030 align:middle line:84%
isn't as important as their
ability to pair well another,

00:13:34.030 --> 00:13:37.150 align:middle line:84%
then you expect if you take a
large number of transfer RNAs

00:13:37.150 --> 00:13:40.420 align:middle line:84%
and do a multi-sequence
alignment, as we did last time,

00:13:40.420 --> 00:13:44.710 align:middle line:84%
then in that
multi-sequence alignment,

00:13:44.710 --> 00:13:48.610 align:middle line:84%
you expect that
when the G changes,

00:13:48.610 --> 00:13:49.600 align:middle line:90%
the C will change, too.

00:13:49.600 --> 00:13:51.100 align:middle line:90%
And that's called covariance.

00:13:51.100 --> 00:13:53.290 align:middle line:84%
And if you look at
the vertical axis,

00:13:53.290 --> 00:13:58.200 align:middle line:84%
the maximum that can be achieved
is the same kind of maximum

00:13:58.200 --> 00:14:01.440 align:middle line:84%
that we had in the
motifs last lecture.

00:14:01.440 --> 00:14:04.800 align:middle line:84%
The motifs, we've actually
had a couple of times.

00:14:04.800 --> 00:14:06.270 align:middle line:90%
It can get up to two bits.

00:14:06.270 --> 00:14:11.310 align:middle line:84%
Two bits is the full
scale for a base pair,

00:14:11.310 --> 00:14:14.130 align:middle line:84%
or base, which can have
four different values, A, C,

00:14:14.130 --> 00:14:16.740 align:middle line:84%
G, or T. And we're calling
this mutual information

00:14:16.740 --> 00:14:20.830 align:middle line:84%
if it has the same units, a
full scale of zero to two bits.

00:14:20.830 --> 00:14:25.140 align:middle line:84%
And so we see along the
horizontal axis, here--

00:14:25.140 --> 00:14:29.970 align:middle line:84%
call them positions I and J,
which range from one to 72,

00:14:29.970 --> 00:14:32.040 align:middle line:84%
which is the core part
of the transfer RNA.

00:14:32.040 --> 00:14:37.560 align:middle line:84%
The last four bases are added
by a specialized enzyme.

00:14:37.560 --> 00:14:40.200 align:middle line:84%
But position number
one and position 72

00:14:40.200 --> 00:14:41.910 align:middle line:84%
covariates
[? assume ?] this peak

00:14:41.910 --> 00:14:46.390 align:middle line:90%
in the far left-hand region.

00:14:46.390 --> 00:14:51.060 align:middle line:84%
In effect, there's seven
peaks in a row there

00:14:51.060 --> 00:14:56.430 align:middle line:84%
which correspond to the seven
stacked base pairs they covary.

00:14:56.430 --> 00:15:01.320 align:middle line:84%
Similarly, in the TC to UC stem
that we talked about a couple

00:15:01.320 --> 00:15:06.270 align:middle line:84%
of times there, that those
five nucleotides covary

00:15:06.270 --> 00:15:12.390 align:middle line:90%
as you would get in a stem.

00:15:12.390 --> 00:15:15.220 align:middle line:84%
The anti-codon stem
is another five.

00:15:15.220 --> 00:15:20.160 align:middle line:84%
And that D stem, so named after
the hydrourodine modifications

00:15:20.160 --> 00:15:21.690 align:middle line:90%
is four base pairs.

00:15:21.690 --> 00:15:23.280 align:middle line:84%
And the way that
this is derived--

00:15:23.280 --> 00:15:25.510 align:middle line:84%
and we're going to work
through this, an example,

00:15:25.510 --> 00:15:31.660 align:middle line:84%
in the next slide-- but just as
a labeling of this axis here,

00:15:31.660 --> 00:15:36.130 align:middle line:84%
the mutual information between
the Ith base and the jth base,

00:15:36.130 --> 00:15:39.430 align:middle line:84%
that is to see, for example,
between I equals 1 and J equals

00:15:39.430 --> 00:15:44.800 align:middle line:84%
72, is simply the sum of the
frequency of getting that

00:15:44.800 --> 00:15:46.960 align:middle line:90%
particular I, N, J--

00:15:46.960 --> 00:15:51.320 align:middle line:84%
F is the frequency
of getting, say,

00:15:51.320 --> 00:15:56.500 align:middle line:84%
a G as position one and
a C at position 72--

00:15:56.500 --> 00:15:58.453 align:middle line:90%
times the log base 2.

00:15:58.453 --> 00:16:00.370 align:middle line:84%
Remember, when we're
talking about information

00:16:00.370 --> 00:16:03.070 align:middle line:90%
content of nuclear--

00:16:03.070 --> 00:16:06.310 align:middle line:84%
or of information in
general, bits in a computer

00:16:06.310 --> 00:16:11.080 align:middle line:84%
or nucleotides in a sequence,
we do log base 2, and--

00:16:11.080 --> 00:16:12.830 align:middle line:84%
as introduced by
Shannon and others.

00:16:12.830 --> 00:16:15.830 align:middle line:84%
So now it's going to be the
log of that same frequency.

00:16:15.830 --> 00:16:19.420 align:middle line:84%
So the frequency of
getting that particular I

00:16:19.420 --> 00:16:23.170 align:middle line:84%
and that particular
J type of base

00:16:23.170 --> 00:16:28.450 align:middle line:84%
normalized now to how
frequently those two bases occur

00:16:28.450 --> 00:16:33.800 align:middle line:90%
throughout those positions.

00:16:33.800 --> 00:16:36.700 align:middle line:84%
In other words, you know
how often they co-occur

00:16:36.700 --> 00:16:38.660 align:middle line:90%
at those two positions.

00:16:38.660 --> 00:16:41.300 align:middle line:84%
Now, how often do they occur
independently of one another?

00:16:41.300 --> 00:16:43.790 align:middle line:84%
And that's what the
denominator is here.

00:16:43.790 --> 00:16:49.420 align:middle line:84%
So when you take this ratio, you
put it on a conventional scale,

00:16:49.420 --> 00:16:51.070 align:middle line:84%
and then you have
something that's

00:16:51.070 --> 00:16:53.560 align:middle line:84%
analogous to the P law
P of information theory.

00:16:53.560 --> 00:17:01.220 align:middle line:84%
And you sum over all
of the observed bases

00:17:01.220 --> 00:17:06.220 align:middle line:90%
at positions I and J.

00:17:06.220 --> 00:17:08.859 align:middle line:84%
And that that's for
a particular I and J,

00:17:08.859 --> 00:17:12.940 align:middle line:84%
you sum over all the X's that
occur at position, say, one

00:17:12.940 --> 00:17:14.170 align:middle line:90%
and 72.

00:17:14.170 --> 00:17:16.069 align:middle line:90%
And then you repeat that.

00:17:16.069 --> 00:17:21.530 align:middle line:84%
You can get this Nth of IJ
for every matrix element

00:17:21.530 --> 00:17:28.700 align:middle line:84%
going from one to 72 in a
symmetric square matrix.

00:17:28.700 --> 00:17:31.640 align:middle line:84%
So let's work through this
for two extreme examples.

00:17:31.640 --> 00:17:34.940 align:middle line:84%
The extreme case where
have perfect covariance

00:17:34.940 --> 00:17:39.350 align:middle line:84%
and the extreme case where
you have no real association.

00:17:39.350 --> 00:17:42.800 align:middle line:84%
So we're going to illustrate
this with a toy multi-sequence

00:17:42.800 --> 00:17:43.670 align:middle line:90%
alignment here.

00:17:43.670 --> 00:17:47.120 align:middle line:84%
This is just the same way we
did the multi-sequence alignment

00:17:47.120 --> 00:17:48.020 align:middle line:90%
in the last class.

00:17:48.020 --> 00:17:50.180 align:middle line:84%
Here there are no
insertions or deletions,

00:17:50.180 --> 00:17:51.590 align:middle line:90%
but it's the same thing.

00:17:51.590 --> 00:17:53.990 align:middle line:84%
You could derive a
weight matrix for this.

00:17:53.990 --> 00:17:56.570 align:middle line:84%
And you would see that the
first column-- the far left-hand

00:17:56.570 --> 00:18:00.740 align:middle line:84%
column, I equals one, has
all four possibilities,

00:18:00.740 --> 00:18:04.970 align:middle line:84%
and the so does the
rightmost column

00:18:04.970 --> 00:18:08.300 align:middle line:84%
of that multi-sequence
alignment J equals six.

00:18:08.300 --> 00:18:13.310 align:middle line:84%
And so let's calculate,
are these covarying

00:18:13.310 --> 00:18:19.210 align:middle line:84%
in this simple multi-sequence
alignment of four [INAUDIBLE]..

00:18:19.210 --> 00:18:21.940 align:middle line:84%
So we calculate the mutual
information for I equals one,

00:18:21.940 --> 00:18:25.420 align:middle line:90%
J equals six Nth of one sixth.

00:18:25.420 --> 00:18:28.210 align:middle line:90%
It's going to be equal to sum.

00:18:28.210 --> 00:18:31.660 align:middle line:84%
The first term in the
sum is for the AU.

00:18:31.660 --> 00:18:34.600 align:middle line:84%
And then we're going to
walk through the CG, GC, UA.

00:18:34.600 --> 00:18:36.940 align:middle line:84%
So there will be four
terms in the sum.

00:18:36.940 --> 00:18:40.270 align:middle line:84%
Each of the terms will have,
coincidentally in this case,

00:18:40.270 --> 00:18:43.720 align:middle line:84%
have the same frequency for
that particular pairing of AU.

00:18:43.720 --> 00:18:45.350 align:middle line:84%
And remember this
is not a base pair.

00:18:45.350 --> 00:18:47.290 align:middle line:84%
This is a covariant
pair of nucleotides

00:18:47.290 --> 00:18:49.207 align:middle line:84%
that could have been
anywhere in the sequence.

00:18:49.207 --> 00:18:51.475 align:middle line:84%
We happen to pick the
first and the last base.

00:18:51.475 --> 00:18:54.040 align:middle line:90%


00:18:54.040 --> 00:18:55.780 align:middle line:84%
So they all have
the same frequency.

00:18:55.780 --> 00:18:57.070 align:middle line:90%
That frequency is 1/4.

00:18:57.070 --> 00:18:59.470 align:middle line:84%
So the AU occurs
one quarter of the

00:18:59.470 --> 00:19:01.580 align:middle line:84%
for sequences in the
multi-sequence alignment,

00:19:01.580 --> 00:19:02.890 align:middle line:90%
so that's one quarter.

00:19:02.890 --> 00:19:07.570 align:middle line:84%
And then, remember it's the same
frequency inside the logarithm,

00:19:07.570 --> 00:19:09.640 align:middle line:84%
but now in the
denominator, we're

00:19:09.640 --> 00:19:12.100 align:middle line:84%
going to normalize
it to the frequency

00:19:12.100 --> 00:19:16.090 align:middle line:84%
that the A occurs in the I
equals one position, which

00:19:16.090 --> 00:19:17.800 align:middle line:84%
is one quarter, and
the frequency that U

00:19:17.800 --> 00:19:20.770 align:middle line:84%
occurs in the J equals six
position, which is one quarter.

00:19:20.770 --> 00:19:25.090 align:middle line:84%
So that's one quarter over
one quarter squared, or four.

00:19:25.090 --> 00:19:30.400 align:middle line:84%
So 0.25 times log base to a
of four is going to be two.

00:19:30.400 --> 00:19:39.910 align:middle line:84%
And 0.25 times two
is going to be 0.5.

00:19:39.910 --> 00:19:43.150 align:middle line:90%
And that's the first term.

00:19:43.150 --> 00:19:45.130 align:middle line:90%
That's for the AU pairing.

00:19:45.130 --> 00:19:46.870 align:middle line:84%
If you go down through
all four terms,

00:19:46.870 --> 00:19:49.990 align:middle line:84%
they all end up
being the same form.

00:19:49.990 --> 00:19:54.070 align:middle line:84%
The frequency is always going
to be 0.25 for the pair and 0.25

00:19:54.070 --> 00:19:55.720 align:middle line:84%
for each of the
individual bases.

00:19:55.720 --> 00:19:59.290 align:middle line:84%
So you end up with four of
those, four examples of those

00:19:59.290 --> 00:20:01.360 align:middle line:90%
for each of the four cases.

00:20:01.360 --> 00:20:04.930 align:middle line:90%
And so four times 0.5 is two.

00:20:04.930 --> 00:20:07.330 align:middle line:84%
So that's consistent,
hopefully, with what

00:20:07.330 --> 00:20:09.880 align:middle line:84%
you would have expected
for perfect covariance.

00:20:09.880 --> 00:20:11.560 align:middle line:84%
You're getting the
full information

00:20:11.560 --> 00:20:15.250 align:middle line:84%
content, the full
range of two bits,

00:20:15.250 --> 00:20:16.610 align:middle line:90%
and so that's what we achieved.

00:20:16.610 --> 00:20:22.030 align:middle line:84%
So now, as a controller is
just further gratification

00:20:22.030 --> 00:20:24.700 align:middle line:84%
that we actually
understand this,

00:20:24.700 --> 00:20:27.250 align:middle line:84%
as we're working through
the example of comparing

00:20:27.250 --> 00:20:31.450 align:middle line:84%
I equals 1 with J equals
2, so the two far columns.

00:20:31.450 --> 00:20:33.970 align:middle line:84%
And here, you're
familiar with I of 1.

00:20:33.970 --> 00:20:37.330 align:middle line:84%
J equals 2 is always
C, and so it's not

00:20:37.330 --> 00:20:42.650 align:middle line:84%
covarying with the first column
as in the previous example.

00:20:42.650 --> 00:20:46.460 align:middle line:84%
So let's just work
through it the same way.

00:20:46.460 --> 00:20:51.250 align:middle line:84%
So the first term in
the series is 0.25 again

00:20:51.250 --> 00:20:59.840 align:middle line:84%
because the AC pair, not
base pair, but pair of bases,

00:20:59.840 --> 00:21:02.560 align:middle line:84%
occurs only once in the four
of the multi-sequence alignment

00:21:02.560 --> 00:21:04.040 align:middle line:90%
so that's 0.25.

00:21:04.040 --> 00:21:07.520 align:middle line:84%
Then you have the logarithm
base two of that same 0.25

00:21:07.520 --> 00:21:11.930 align:middle line:84%
now normalized to the
frequency of the A

00:21:11.930 --> 00:21:16.100 align:middle line:84%
in its column, the one
column, which is 0.25.

00:21:16.100 --> 00:21:19.940 align:middle line:84%
And the C in the J equals
2 column, which is--

00:21:19.940 --> 00:21:22.370 align:middle line:84%
it's always there as
unity, so it's one.

00:21:22.370 --> 00:21:24.200 align:middle line:84%
So now that's the
big change here,

00:21:24.200 --> 00:21:27.350 align:middle line:84%
is instead of having 0.25 in
both of the denominator terms,

00:21:27.350 --> 00:21:29.240 align:middle line:90%
it's now 0.25 times one.

00:21:29.240 --> 00:21:33.950 align:middle line:84%
It's now it's 0.25 over 0.25,
so you have the log base

00:21:33.950 --> 00:21:36.680 align:middle line:90%
2 of one, which will be zero.

00:21:36.680 --> 00:21:38.400 align:middle line:84%
And that zeros out
the whole term.

00:21:38.400 --> 00:21:41.570 align:middle line:84%
And so you have mutual
information of zero,

00:21:41.570 --> 00:21:44.810 align:middle line:84%
as you would expect from
this particular toy example

00:21:44.810 --> 00:21:48.558 align:middle line:84%
where columns one and
two do not covary.

00:21:48.558 --> 00:21:51.225 align:middle line:84%
And so this is the same formulas
that was in the previous slide.

00:21:51.225 --> 00:21:55.380 align:middle line:84%
And a generalization of the
one that we walked through term

00:21:55.380 --> 00:21:56.530 align:middle line:90%
by term.

00:21:56.530 --> 00:22:03.120 align:middle line:84%
And here's the
reference for that.

00:22:03.120 --> 00:22:06.800 align:middle line:84%
So now how do we go-- so
that was-- we've taken now

00:22:06.800 --> 00:22:09.530 align:middle line:84%
hundreds, possibly
thousands, of transfer RNAs.

00:22:09.530 --> 00:22:11.180 align:middle line:84%
We've done a
multi-sequence alignment.

00:22:11.180 --> 00:22:15.620 align:middle line:84%
We've produced that
mutual information pattern

00:22:15.620 --> 00:22:18.170 align:middle line:84%
that we saw before
with the one by 72--

00:22:18.170 --> 00:22:21.830 align:middle line:84%
one to 72 by one
to 72 comparison

00:22:21.830 --> 00:22:26.810 align:middle line:84%
where you got the spikes at
each of the double helices.

00:22:26.810 --> 00:22:31.670 align:middle line:84%
Now how do we turn that
into more general practice.

00:22:31.670 --> 00:22:38.497 align:middle line:84%
How do we generate
secondary structures

00:22:38.497 --> 00:22:40.080 align:middle line:84%
which are kind of
at this intermediate

00:22:40.080 --> 00:22:42.455 align:middle line:84%
in between the primary sequence
and the three-dimensional

00:22:42.455 --> 00:22:49.530 align:middle line:84%
structure using a particular
class of experimental data

00:22:49.530 --> 00:22:52.290 align:middle line:90%
combined with the sequence data.

00:22:52.290 --> 00:22:54.660 align:middle line:84%
This does not
necessarily require

00:22:54.660 --> 00:23:00.690 align:middle line:84%
the large set of line
sequences, but it obviously

00:23:00.690 --> 00:23:01.500 align:middle line:90%
benefits from it.

00:23:01.500 --> 00:23:03.570 align:middle line:84%
You could do a
secondary structure

00:23:03.570 --> 00:23:08.550 align:middle line:84%
for each element in the
aligned sequence in order to--

00:23:08.550 --> 00:23:12.900 align:middle line:84%
and use the mutual
information, if you have it.

00:23:12.900 --> 00:23:16.800 align:middle line:84%
But let's just talk about
just the simple application

00:23:16.800 --> 00:23:19.320 align:middle line:84%
of these thermodynamic
parameters to the prediction

00:23:19.320 --> 00:23:20.370 align:middle line:90%
of secondary structure.

00:23:20.370 --> 00:23:22.110 align:middle line:84%
And what are our
expectations before we

00:23:22.110 --> 00:23:23.160 align:middle line:90%
go through the algorithm.

00:23:23.160 --> 00:23:25.080 align:middle line:90%
How good is it?

00:23:25.080 --> 00:23:30.810 align:middle line:84%
In this fairly close to
state-of-the-art paper,

00:23:30.810 --> 00:23:36.395 align:middle line:84%
looking through over 700
generated structures,

00:23:36.395 --> 00:23:36.895 align:middle line:90%
they have--

00:23:36.895 --> 00:23:39.830 align:middle line:90%


00:23:39.830 --> 00:23:43.580 align:middle line:84%
in each set, it
contains one structure

00:23:43.580 --> 00:23:48.670 align:middle line:84%
that, on average, has 86%
of its known base pairs.

00:23:48.670 --> 00:23:50.580 align:middle line:84%
That's not saying
that it's necessarily

00:23:50.580 --> 00:23:54.270 align:middle line:84%
identified as the top,
the best, structure.

00:23:54.270 --> 00:23:56.850 align:middle line:84%
It's saying that it has one
structure by the criterion

00:23:56.850 --> 00:23:57.810 align:middle line:90%
that they're using.

00:23:57.810 --> 00:24:00.450 align:middle line:90%
This as a weak self praise.

00:24:00.450 --> 00:24:03.350 align:middle line:90%


00:24:03.350 --> 00:24:05.600 align:middle line:84%
But let's walk through
how that works.

00:24:05.600 --> 00:24:08.330 align:middle line:84%
When someone says
that they're going

00:24:08.330 --> 00:24:13.900 align:middle line:84%
to predict a secondary
structure or a three-dimensional

00:24:13.900 --> 00:24:16.800 align:middle line:84%
structure from a
primary sequence,

00:24:16.800 --> 00:24:20.760 align:middle line:84%
more or less, from scratch,
they really typically

00:24:20.760 --> 00:24:25.170 align:middle line:84%
mean that there's going to be a
variety of other chemical data

00:24:25.170 --> 00:24:28.260 align:middle line:84%
that they take into account,
but it will be generic data.

00:24:28.260 --> 00:24:30.390 align:middle line:84%
It will not be
specific chemical data

00:24:30.390 --> 00:24:31.920 align:middle line:90%
for this particular molecule.

00:24:31.920 --> 00:24:34.050 align:middle line:84%
And the generic
data, in this case,

00:24:34.050 --> 00:24:40.730 align:middle line:84%
are measurements of the
thermodynamics of melting

00:24:40.730 --> 00:24:45.080 align:middle line:84%
of model
oligonucleotides, usually

00:24:45.080 --> 00:24:48.260 align:middle line:84%
large amounts of them, monitored
spectral photometrically.

00:24:48.260 --> 00:24:53.870 align:middle line:84%
And from the temperatures
of melting, basically,

00:24:53.870 --> 00:24:58.610 align:middle line:84%
at equilibrium where you're
getting half melted structures,

00:24:58.610 --> 00:25:01.490 align:middle line:84%
you can determine
the free energies

00:25:01.490 --> 00:25:04.100 align:middle line:84%
where the negative free
energies are the desirable ones,

00:25:04.100 --> 00:25:07.220 align:middle line:84%
the ones that are likely
to happen if you let

00:25:07.220 --> 00:25:10.200 align:middle line:90%
the system go to equilibrium.

00:25:10.200 --> 00:25:14.030 align:middle line:84%
And this is a kind of
interesting application

00:25:14.030 --> 00:25:16.790 align:middle line:84%
of the free energies
for nucleic acids.

00:25:16.790 --> 00:25:21.140 align:middle line:84%
Here, the algorithm
that one uses

00:25:21.140 --> 00:25:26.370 align:middle line:84%
is concerned mostly
with adjacent base

00:25:26.370 --> 00:25:27.940 align:middle line:90%
pairs of base pairs.

00:25:27.940 --> 00:25:31.380 align:middle line:84%
So it's not a base
pair, as you might

00:25:31.380 --> 00:25:36.150 align:middle line:84%
think that the hydrogen bonds
that determine the Watson-Crick

00:25:36.150 --> 00:25:38.820 align:middle line:84%
and non Watson-Crick base
pairs would dominate.

00:25:38.820 --> 00:25:41.310 align:middle line:84%
Instead, it's the stacking
interactions that dominate.

00:25:41.310 --> 00:25:43.680 align:middle line:84%
And since it's the stacking
interactions that dominate,

00:25:43.680 --> 00:25:46.740 align:middle line:84%
the hydrogen bonds are basically
exchanging a water hydrogen

00:25:46.740 --> 00:25:49.330 align:middle line:84%
bond for a base
pair hydrogen bond.

00:25:49.330 --> 00:25:51.820 align:middle line:84%
It looks very specific but
in terms of free energy,

00:25:51.820 --> 00:25:52.810 align:middle line:90%
it's fairly weak.

00:25:52.810 --> 00:25:56.020 align:middle line:84%
The free energy is determined
more by the stacking

00:25:56.020 --> 00:25:59.080 align:middle line:84%
of pi orbitals as
depending on the geometry

00:25:59.080 --> 00:26:01.240 align:middle line:84%
that you get, say,
when you have a GC--

00:26:01.240 --> 00:26:03.640 align:middle line:84%
a CG base on top
of an AU base pair

00:26:03.640 --> 00:26:05.920 align:middle line:84%
here at the bottom
of this helix.

00:26:05.920 --> 00:26:11.940 align:middle line:84%
And that stack, it gives you
a -2.1 kilocalories per mole.

00:26:11.940 --> 00:26:14.430 align:middle line:84%
All the units on this are
kilocalories per mole.

00:26:14.430 --> 00:26:18.090 align:middle line:84%
And by going along and
taking each of these stacks

00:26:18.090 --> 00:26:20.640 align:middle line:84%
a pair of base pairs is
what you're measuring.

00:26:20.640 --> 00:26:24.520 align:middle line:84%
You can get all the
negative free energy

00:26:24.520 --> 00:26:25.680 align:middle line:90%
so they're stacking.

00:26:25.680 --> 00:26:27.930 align:middle line:84%
Then you have some
penalties, some things

00:26:27.930 --> 00:26:31.020 align:middle line:84%
that are less favorable, that
would not happen spontaneously

00:26:31.020 --> 00:26:34.320 align:middle line:84%
if they did not have
these mitigating negative

00:26:34.320 --> 00:26:36.330 align:middle line:84%
free energies already
accumulated, which would

00:26:36.330 --> 00:26:39.630 align:middle line:90%
be the loop and the bulge here.

00:26:39.630 --> 00:26:42.450 align:middle line:84%
The base pairs on either
side of that bulge

00:26:42.450 --> 00:26:43.960 align:middle line:90%
will stack up on one another.

00:26:43.960 --> 00:26:48.660 align:middle line:84%
And that bulge will kind of
flip out of the, otherwise,

00:26:48.660 --> 00:26:50.130 align:middle line:90%
regular double helix.

00:26:50.130 --> 00:26:53.175 align:middle line:84%
Similarly, bases at the
end have a slight penalty.

00:26:53.175 --> 00:26:55.920 align:middle line:90%


00:26:55.920 --> 00:26:57.330 align:middle line:84%
And so then you
can add it all up

00:26:57.330 --> 00:26:58.913 align:middle line:84%
and you can calculate
it overall delta

00:26:58.913 --> 00:27:00.558 align:middle line:90%
G for the entire structure.

00:27:00.558 --> 00:27:02.100 align:middle line:84%
And if you do enough
of these things,

00:27:02.100 --> 00:27:03.600 align:middle line:84%
you can get a feeling
for which ones

00:27:03.600 --> 00:27:07.845 align:middle line:84%
are likely to be
occurring in your RNAs.

00:27:07.845 --> 00:27:10.600 align:middle line:90%


00:27:10.600 --> 00:27:14.560 align:middle line:84%
Now this should
trigger in your mind,

00:27:14.560 --> 00:27:24.720 align:middle line:84%
as the third example we've had
where the conceit of a motif

00:27:24.720 --> 00:27:29.610 align:middle line:84%
analysis, that you can do
a multi-sequence alignment

00:27:29.610 --> 00:27:32.430 align:middle line:84%
and each column and
multi-sequence alignment

00:27:32.430 --> 00:27:33.250 align:middle line:90%
is independent.

00:27:33.250 --> 00:27:36.120 align:middle line:84%
This is the third example
where that's not true.

00:27:36.120 --> 00:27:42.000 align:middle line:84%
We have here the three
energies are dependent on pairs

00:27:42.000 --> 00:27:43.560 align:middle line:90%
of base pairs.

00:27:43.560 --> 00:27:49.980 align:middle line:84%
The previous examples were
the very distant connections

00:27:49.980 --> 00:27:52.440 align:middle line:84%
that you can get in
folding up a transfer RNA.

00:27:52.440 --> 00:27:57.460 align:middle line:84%
And the earlier example
was the CG dinucleotides.

00:27:57.460 --> 00:27:59.532 align:middle line:84%
The assumption of
independence of columns

00:27:59.532 --> 00:28:01.740 align:middle line:84%
in a multi-sequence alignment
is a very powerful one.

00:28:01.740 --> 00:28:03.323 align:middle line:84%
I don't want to
undermine it too much.

00:28:03.323 --> 00:28:06.600 align:middle line:84%
But it doesn't hurt you to
have three examples this early

00:28:06.600 --> 00:28:09.100 align:middle line:90%
on in the course.

00:28:09.100 --> 00:28:11.695 align:middle line:84%
Question the
independence of columns

00:28:11.695 --> 00:28:15.020 align:middle line:84%
in multi-sequence alignments--
very important thing

00:28:15.020 --> 00:28:15.520 align:middle line:90%
to question.

00:28:15.520 --> 00:28:17.862 align:middle line:84%
We've got mutual
information theory

00:28:17.862 --> 00:28:19.570 align:middle line:84%
that we had a couple
of slides ago as one

00:28:19.570 --> 00:28:21.653 align:middle line:84%
of the most powerful ways
of questioning that when

00:28:21.653 --> 00:28:23.430 align:middle line:90%
you see it.

00:28:23.430 --> 00:28:32.950 align:middle line:84%
Now, that's the way that
this particular base

00:28:32.950 --> 00:28:36.020 align:middle line:84%
pairing, that we see
here, is one example--

00:28:36.020 --> 00:28:43.720 align:middle line:84%
now you could take each of these
and shift the right-hand half

00:28:43.720 --> 00:28:46.720 align:middle line:84%
of the molecule relative to
the left-hand by one base pair.

00:28:46.720 --> 00:28:51.080 align:middle line:84%
That would give you
a much poorer set

00:28:51.080 --> 00:28:57.200 align:middle line:84%
of energies and much, much
more bulges and more--

00:28:57.200 --> 00:28:58.700 align:middle line:90%
longer loops and so forth.

00:28:58.700 --> 00:29:02.090 align:middle line:84%
And you end up with
a poor delta G.

00:29:02.090 --> 00:29:04.400 align:middle line:84%
And what you can
do is you can rank

00:29:04.400 --> 00:29:11.090 align:middle line:84%
and do one of these
maximum-value searches

00:29:11.090 --> 00:29:12.530 align:middle line:90%
by going through that.

00:29:12.530 --> 00:29:14.990 align:middle line:84%
This should trigger
in your mind this

00:29:14.990 --> 00:29:18.170 align:middle line:84%
is another way of thinking
about that search.

00:29:18.170 --> 00:29:22.670 align:middle line:84%
You take the entire sequence,
whether it's transfer RNA,

00:29:22.670 --> 00:29:26.570 align:middle line:84%
or in this case, a 400
nucleic acid sequence,

00:29:26.570 --> 00:29:31.610 align:middle line:84%
and you draw lines between
every base where you

00:29:31.610 --> 00:29:33.380 align:middle line:90%
have a favorable free energy.

00:29:33.380 --> 00:29:36.920 align:middle line:84%
And you look for a set
of lines which do not

00:29:36.920 --> 00:29:42.960 align:middle line:84%
overlap one another,
because these

00:29:42.960 --> 00:29:45.780 align:middle line:84%
would represent short
sequences of local--

00:29:45.780 --> 00:29:48.000 align:middle line:84%
you can think of this
as a local sequence

00:29:48.000 --> 00:29:53.730 align:middle line:84%
alignment between one
half of the nucleic acid

00:29:53.730 --> 00:29:55.140 align:middle line:90%
and the other half.

00:29:55.140 --> 00:29:57.960 align:middle line:84%
Now this is not a sequence
identity, remember,

00:29:57.960 --> 00:29:59.640 align:middle line:84%
this is a sequence
complementarity.

00:29:59.640 --> 00:30:02.400 align:middle line:84%
That is to say, a
reverse complement

00:30:02.400 --> 00:30:07.380 align:middle line:84%
where complement means you've
substituted As for Us and Cs

00:30:07.380 --> 00:30:08.310 align:middle line:90%
for Gs.

00:30:08.310 --> 00:30:10.720 align:middle line:90%
So you're looking for--

00:30:10.720 --> 00:30:13.362 align:middle line:84%
but in many other
ways, this is analogous

00:30:13.362 --> 00:30:14.820 align:middle line:84%
to the dynamic
programming where we

00:30:14.820 --> 00:30:17.520 align:middle line:84%
took two independent sequences
and slid them along one

00:30:17.520 --> 00:30:20.700 align:middle line:84%
another and allowed for
insertions and deletions.

00:30:20.700 --> 00:30:23.100 align:middle line:84%
In that-- in the dynamic
equilibrium before,

00:30:23.100 --> 00:30:26.220 align:middle line:84%
we did that formally, all
possible such slippages

00:30:26.220 --> 00:30:30.820 align:middle line:84%
by setting them as the
two axes of a table

00:30:30.820 --> 00:30:34.860 align:middle line:84%
and then filled in the
squares for all the matches.

00:30:34.860 --> 00:30:38.760 align:middle line:84%
Here, we would fill in the
squares, not for the matches,

00:30:38.760 --> 00:30:42.510 align:middle line:84%
but for the free
energy of the stacking

00:30:42.510 --> 00:30:45.120 align:middle line:90%
for these short subsequences.

00:30:45.120 --> 00:30:48.120 align:middle line:84%
Now the reason that
they don't cross over,

00:30:48.120 --> 00:30:51.540 align:middle line:84%
and the reason for this
little note in the lower

00:30:51.540 --> 00:30:53.760 align:middle line:84%
left-hand corner
of slide 11, that

00:30:53.760 --> 00:30:55.470 align:middle line:90%
does not handle pseudo knots.

00:30:55.470 --> 00:30:57.990 align:middle line:84%
Psuedo knots we'll
explain in the next--

00:30:57.990 --> 00:31:00.120 align:middle line:84%
we'll show graphic
examples in the next slide.

00:31:00.120 --> 00:31:01.770 align:middle line:84%
But it basically
means that if you

00:31:01.770 --> 00:31:04.560 align:middle line:84%
allow such sequences
to occur willy-nilly

00:31:04.560 --> 00:31:09.660 align:middle line:84%
throughout the sequence,
then you'll get these tangles

00:31:09.660 --> 00:31:13.522 align:middle line:84%
that for a while
people weren't sure

00:31:13.522 --> 00:31:14.730 align:middle line:90%
whether they occurred or not.

00:31:14.730 --> 00:31:17.730 align:middle line:84%
The one or two non
Watson-Crick base pairs

00:31:17.730 --> 00:31:21.270 align:middle line:84%
that you might find connecting
up tRNA in these tangles

00:31:21.270 --> 00:31:23.610 align:middle line:84%
were not considered
long stretches

00:31:23.610 --> 00:31:25.380 align:middle line:90%
that would connect loops.

00:31:25.380 --> 00:31:26.880 align:middle line:84%
But since then,
they've been proven

00:31:26.880 --> 00:31:29.130 align:middle line:84%
to be of great
biological significance.

00:31:29.130 --> 00:31:31.560 align:middle line:84%
In any case, to do this
without the pseudo knots,

00:31:31.560 --> 00:31:35.250 align:middle line:84%
without allowing any crosses
is still a challenging problem.

00:31:35.250 --> 00:31:38.370 align:middle line:84%
It's basically the
dynamic programming

00:31:38.370 --> 00:31:43.080 align:middle line:84%
where N is the length of the
primary sequence then takes

00:31:43.080 --> 00:31:46.980 align:middle line:84%
on the order of N squared and
compute time and space in order

00:31:46.980 --> 00:31:56.610 align:middle line:84%
to figure out all the possible
pairings that can occur.

00:31:56.610 --> 00:31:58.760 align:middle line:84%
And then you go through
and you rank them,

00:31:58.760 --> 00:32:00.440 align:middle line:84%
which one gives the
best free energy,

00:32:00.440 --> 00:32:04.040 align:middle line:84%
and then you do the trace back
and you get the top scores

00:32:04.040 --> 00:32:06.610 align:middle line:90%
for that molecule.

00:32:06.610 --> 00:32:08.440 align:middle line:84%
Now let's talk
about pseudo notes.

00:32:08.440 --> 00:32:12.700 align:middle line:84%
We excluded that, but
now we'll reinvite it.

00:32:12.700 --> 00:32:17.980 align:middle line:84%
We had those little ones,
a couple of base pairs

00:32:17.980 --> 00:32:18.940 align:middle line:90%
in the transfer RNA.

00:32:18.940 --> 00:32:22.530 align:middle line:84%
But a much more dramatic one
we alluded to in the second

00:32:22.530 --> 00:32:23.030 align:middle line:90%
lecture.

00:32:23.030 --> 00:32:24.640 align:middle line:84%
We talked about
the genetic code.

00:32:24.640 --> 00:32:29.020 align:middle line:84%
And in order to introduce you to
exceptions to the genetic code,

00:32:29.020 --> 00:32:31.900 align:middle line:84%
I gave an example
where the ribosome

00:32:31.900 --> 00:32:34.120 align:middle line:84%
jumped over 50 base
pairs if presented

00:32:34.120 --> 00:32:35.470 align:middle line:90%
with the right context.

00:32:35.470 --> 00:32:38.350 align:middle line:84%
It didn't follow the
normal code of having

00:32:38.350 --> 00:32:40.270 align:middle line:84%
a triplet and
another triplet right

00:32:40.270 --> 00:32:42.190 align:middle line:90%
in a row with no punctuation.

00:32:42.190 --> 00:32:45.970 align:middle line:84%
Here we had the
punctuation that required,

00:32:45.970 --> 00:32:48.310 align:middle line:84%
what may have slipped by
at the time, a pseudo knot.

00:32:48.310 --> 00:32:52.630 align:middle line:84%
And this is an example of once
such pseudo knot in the best

00:32:52.630 --> 00:32:56.290 align:middle line:84%
that we can do of a two
dimensional schematic.

00:32:56.290 --> 00:32:58.510 align:middle line:84%
And then something
slightly better where

00:32:58.510 --> 00:33:02.020 align:middle line:84%
we have a more three-dimensional
and another three-dimensional

00:33:02.020 --> 00:33:02.770 align:middle line:90%
view of this.

00:33:02.770 --> 00:33:05.470 align:middle line:84%
And this is the RNA
pseudo knot, which

00:33:05.470 --> 00:33:07.630 align:middle line:84%
is-- one of them, which
is responsible for frame

00:33:07.630 --> 00:33:11.060 align:middle line:84%
shifting in the-- that
breaks this genetic code.

00:33:11.060 --> 00:33:13.360 align:middle line:84%
And so let's just
follow how this goes.

00:33:13.360 --> 00:33:15.610 align:middle line:84%
You've got basically
a normal helix here

00:33:15.610 --> 00:33:18.390 align:middle line:84%
at the bottom starting at the
five prime in position one

00:33:18.390 --> 00:33:19.750 align:middle line:90%
to seven.

00:33:19.750 --> 00:33:23.380 align:middle line:84%
It would go through a
normal five-base-- sorry--

00:33:23.380 --> 00:33:26.200 align:middle line:84%
six-base loop, from
eight to 13, and then

00:33:26.200 --> 00:33:29.110 align:middle line:90%
finish the stem 14 through 18.

00:33:29.110 --> 00:33:33.490 align:middle line:84%
That would be a normal stem
loop where the loop is six long,

00:33:33.490 --> 00:33:34.690 align:middle line:90%
eight to 13.

00:33:34.690 --> 00:33:37.450 align:middle line:84%
But at the end of eighteen,
you have this little green loop

00:33:37.450 --> 00:33:41.830 align:middle line:84%
that goes back and now makes
a nice perfect four base

00:33:41.830 --> 00:33:48.410 align:middle line:90%
Watson-Crick stem.

00:33:48.410 --> 00:33:50.970 align:middle line:84%
Now in the middle of what
would have been a loop--

00:33:50.970 --> 00:33:54.980 align:middle line:84%
and so this fold back is what
we meant by a pseudo knot,

00:33:54.980 --> 00:33:56.480 align:middle line:84%
and what would have
been represented

00:33:56.480 --> 00:33:59.420 align:middle line:84%
by a crossover of those red
lines in the previous slide--

00:33:59.420 --> 00:34:02.580 align:middle line:84%
something that makes it
much harder to compute.

00:34:02.580 --> 00:34:05.990 align:middle line:84%
In fact, it makes it so much
harder, in the next slide,

00:34:05.990 --> 00:34:09.230 align:middle line:84%
that it goes up from an
order of N squared, which

00:34:09.230 --> 00:34:11.900 align:middle line:84%
is your typical
dynamic programming

00:34:11.900 --> 00:34:18.000 align:middle line:84%
in a pairwise alignment to order
in sixth in CPU time and order

00:34:18.000 --> 00:34:20.882 align:middle line:84%
into the fourth
power in memory space

00:34:20.882 --> 00:34:22.590 align:middle line:84%
that you need to set
aside for storing up

00:34:22.590 --> 00:34:25.440 align:middle line:84%
the table of
possible pseudo knots

00:34:25.440 --> 00:34:27.750 align:middle line:84%
that can occur in the
context of the otherwise

00:34:27.750 --> 00:34:32.760 align:middle line:84%
normal circle with the
non-overlapping connections.

00:34:32.760 --> 00:34:41.610 align:middle line:84%
This is a relatively recent
innovation where a dynamic--

00:34:41.610 --> 00:34:43.500 align:middle line:84%
it's still a dynamic
programming algorithm,

00:34:43.500 --> 00:34:47.699 align:middle line:84%
it just has more
possibilities, more complex--

00:34:47.699 --> 00:34:50.670 align:middle line:90%
higher algorithmic complexity.

00:34:50.670 --> 00:34:53.130 align:middle line:84%
And the combination of
the biological discovery

00:34:53.130 --> 00:34:56.010 align:middle line:84%
to pseudo knots are important
for frame shifting a variety

00:34:56.010 --> 00:34:57.930 align:middle line:90%
of other biological phenomenon.

00:34:57.930 --> 00:35:02.130 align:middle line:84%
And the now three-dimensional
structure and now an algorithm

00:35:02.130 --> 00:35:05.160 align:middle line:84%
puts pseudo knots well
within the sort of things

00:35:05.160 --> 00:35:07.820 align:middle line:84%
that you should
feel comfortable.

00:35:07.820 --> 00:35:10.060 align:middle line:84%
Now we're going to go
back to hidden Markov

00:35:10.060 --> 00:35:13.480 align:middle line:84%
models in a slightly
more complicated context

00:35:13.480 --> 00:35:16.040 align:middle line:84%
here, that we take the
simplest one we could,

00:35:16.040 --> 00:35:22.740 align:middle line:84%
which was a dinucleotide,
simple, unfolded straight DNA.

00:35:22.740 --> 00:35:25.810 align:middle line:84%
And the part that was
hidden, as you will recall,

00:35:25.810 --> 00:35:29.285 align:middle line:84%
was whether the the CG
dinucleotides-- or sorry--

00:35:29.285 --> 00:35:30.660 align:middle line:84%
the dinucleotides,
which could be

00:35:30.660 --> 00:35:34.650 align:middle line:84%
any of the possible
dinucleotides,

00:35:34.650 --> 00:35:38.880 align:middle line:84%
including AA, CG, and so on,
whether it was present in a CG

00:35:38.880 --> 00:35:41.800 align:middle line:84%
island, or whether it was in
a region of the chromosome

00:35:41.800 --> 00:35:43.830 align:middle line:84%
which was likely to
have CGs, or whether it

00:35:43.830 --> 00:35:51.060 align:middle line:84%
was in a CG ocean which was
low in CG dinucleotide content.

00:35:51.060 --> 00:35:53.160 align:middle line:84%
So the hidden part
was the plus-minus

00:35:53.160 --> 00:35:55.290 align:middle line:84%
whether it was in
an island or not.

00:35:55.290 --> 00:35:58.710 align:middle line:84%
Now what we're going to do now
is take this and transfer this

00:35:58.710 --> 00:36:03.660 align:middle line:84%
over to the kinds of motifs
we are finding in RNAs,

00:36:03.660 --> 00:36:06.240 align:middle line:84%
like transfer RNA and
another class of RNA,

00:36:06.240 --> 00:36:11.160 align:middle line:84%
and say OK, now, whether it's
the hidden part of the Markov

00:36:11.160 --> 00:36:12.865 align:middle line:84%
model is these
transition probabilities.

00:36:12.865 --> 00:36:15.240 align:middle line:84%
The hidden part is whether
it's in a particular secondary

00:36:15.240 --> 00:36:18.030 align:middle line:84%
structure or not, not whether
it's in an island or not,

00:36:18.030 --> 00:36:20.650 align:middle line:90%
but a secondary structure.

00:36:20.650 --> 00:36:22.492 align:middle line:84%
In this particular
case we're going

00:36:22.492 --> 00:36:23.950 align:middle line:84%
to talk about is
a very interesting

00:36:23.950 --> 00:36:33.150 align:middle line:84%
biological illustration where
the hidden Markov models will

00:36:33.150 --> 00:36:36.720 align:middle line:84%
be modeling these boxes, these
motifs, that are involved

00:36:36.720 --> 00:36:41.650 align:middle line:84%
in base pairing or
recognition that

00:36:41.650 --> 00:36:44.486 align:middle line:84%
forms the secondary
structure of--

00:36:44.486 --> 00:36:48.300 align:middle line:84%
if it's necessary for
guiding a particular enzyme.

00:36:48.300 --> 00:36:52.380 align:middle line:84%
Now, remember we had all these
modified bases that we used,

00:36:52.380 --> 00:36:53.850 align:middle line:90%
that we saw in transfer RNA.

00:36:53.850 --> 00:36:56.160 align:middle line:84%
Some of those are simple
protein interactions

00:36:56.160 --> 00:36:58.710 align:middle line:84%
with the transfer RNA that adds
a methyl group here or there.

00:36:58.710 --> 00:37:01.560 align:middle line:84%
It turns out that all of
the methyl groups, the O2

00:37:01.560 --> 00:37:07.850 align:middle line:84%
prime methyl groups, these are
on the sugar of the ribose.

00:37:07.850 --> 00:37:13.970 align:middle line:84%
In ribosomal RNA, a few, just
a small number of a few dozen

00:37:13.970 --> 00:37:20.150 align:middle line:84%
of the ribosomes in this
multikilobase ribosomal RNA

00:37:20.150 --> 00:37:21.890 align:middle line:90%
are methylated O2 position.

00:37:21.890 --> 00:37:23.975 align:middle line:84%
How does the enzyme
know, or the enzymes,

00:37:23.975 --> 00:37:26.540 align:middle line:90%
know to get exactly those bases?

00:37:26.540 --> 00:37:35.470 align:middle line:84%
The way it knows is it doesn't
use pure protein brute force

00:37:35.470 --> 00:37:38.710 align:middle line:84%
to make a complimentary surface
of protein nucleic acid.

00:37:38.710 --> 00:37:43.890 align:middle line:84%
It actually uses this
elegance of base pairing

00:37:43.890 --> 00:37:45.420 align:middle line:90%
to make a guide sequence.

00:37:45.420 --> 00:37:47.970 align:middle line:84%
And so what it's
looking for is--

00:37:47.970 --> 00:37:53.070 align:middle line:84%
the protein cooperates with a
small RNA, so-called snow RNA,

00:37:53.070 --> 00:37:57.120 align:middle line:84%
or small nucleolar
RNA, to find a place

00:37:57.120 --> 00:37:59.550 align:middle line:84%
where the snow will
recognize the place that you

00:37:59.550 --> 00:38:00.390 align:middle line:90%
want to methylate.

00:38:00.390 --> 00:38:03.990 align:middle line:84%
And then the protein
methylates the base

00:38:03.990 --> 00:38:06.360 align:middle line:84%
in the middle of
that guide sequence.

00:38:06.360 --> 00:38:14.140 align:middle line:84%
So then the game, the
computational biology game,

00:38:14.140 --> 00:38:17.260 align:middle line:84%
that these authors
played was how can we

00:38:17.260 --> 00:38:21.790 align:middle line:84%
find all the small
RNAs, the snow RNAs,

00:38:21.790 --> 00:38:29.380 align:middle line:84%
present in a genome when we very
little about that the genome?

00:38:29.380 --> 00:38:31.480 align:middle line:84%
What they knew was they
knew the genome sequence.

00:38:31.480 --> 00:38:32.530 align:middle line:90%
This is for yeast.

00:38:32.530 --> 00:38:37.450 align:middle line:84%
They had a few examples
of snow RNAs in humans--

00:38:37.450 --> 00:38:39.010 align:middle line:90%
almost none in yeast.

00:38:39.010 --> 00:38:42.310 align:middle line:84%
They had the subsequence of
the ribosomal RNA, of course.

00:38:42.310 --> 00:38:47.140 align:middle line:84%
And they could--
what they wanted

00:38:47.140 --> 00:38:51.460 align:middle line:84%
to do then is ask where in the
genome do we have little guide

00:38:51.460 --> 00:38:55.330 align:middle line:84%
sequences flanked by some
of these other motifs

00:38:55.330 --> 00:39:00.520 align:middle line:84%
and characteristics like a
base pair, 4-8 base pair stem,

00:39:00.520 --> 00:39:02.347 align:middle line:84%
that will match
the ribosomal RNA.

00:39:02.347 --> 00:39:04.180 align:middle line:84%
So you basically march
along the algorithms,

00:39:04.180 --> 00:39:06.520 align:middle line:84%
you march along the ribosomal
RNA looking for matches

00:39:06.520 --> 00:39:07.820 align:middle line:90%
elsewhere in the genome.

00:39:07.820 --> 00:39:10.237 align:middle line:84%
And then ask whether those
matches elsewhere in the genome

00:39:10.237 --> 00:39:13.305 align:middle line:84%
have some of these other
contexts, features.

00:39:13.305 --> 00:39:15.805 align:middle line:84%
You can see this is going to
be a more complicated algorithm

00:39:15.805 --> 00:39:18.920 align:middle line:90%
than just looking for CGs.

00:39:18.920 --> 00:39:22.360 align:middle line:90%
So this is how it works.

00:39:22.360 --> 00:39:28.840 align:middle line:84%
That stem that we had
is now item number one.

00:39:28.840 --> 00:39:32.410 align:middle line:84%
The various boxes which
were basically sequences

00:39:32.410 --> 00:39:36.410 align:middle line:84%
are now turned into ungapped
hidden Markov models.

00:39:36.410 --> 00:39:39.610 align:middle line:84%
The hidden part of it
is whether it is present

00:39:39.610 --> 00:39:45.130 align:middle line:84%
or not in the context that
adds up to this guide sequence.

00:39:45.130 --> 00:39:48.520 align:middle line:84%
The guide sequence itself is
a hidden Markov model which

00:39:48.520 --> 00:39:53.990 align:middle line:84%
has to be an imperfect,
probably imperfect, duplex

00:39:53.990 --> 00:39:56.510 align:middle line:90%
with the ribosomal RNA.

00:39:56.510 --> 00:39:59.810 align:middle line:90%
So that's how that's modeled.

00:39:59.810 --> 00:40:01.910 align:middle line:84%
The most complicated
is that terminal

00:40:01.910 --> 00:40:04.700 align:middle line:84%
stem number one, which
is a so-called Stochastic

00:40:04.700 --> 00:40:05.930 align:middle line:90%
Context-Free Grammar.

00:40:05.930 --> 00:40:08.630 align:middle line:90%
That's what the SCFG stands for.

00:40:08.630 --> 00:40:11.570 align:middle line:84%
And that just means that
it is even less constrained

00:40:11.570 --> 00:40:12.470 align:middle line:90%
than the HMM.

00:40:12.470 --> 00:40:15.170 align:middle line:84%
The HMM is less constrained
than a simple motif,

00:40:15.170 --> 00:40:17.930 align:middle line:84%
which is less constrained than,
say, a consensus sequence.

00:40:17.930 --> 00:40:21.500 align:middle line:84%
It is constrained, it has
the grammar, if you will,

00:40:21.500 --> 00:40:24.470 align:middle line:84%
or the particular rules
for the base pairing

00:40:24.470 --> 00:40:26.990 align:middle line:84%
that have to occur
over a certain region

00:40:26.990 --> 00:40:29.780 align:middle line:84%
in a certain part of
this putative snow RNA.

00:40:29.780 --> 00:40:31.700 align:middle line:84%
So anyway, you apply
each of these criteria

00:40:31.700 --> 00:40:33.810 align:middle line:84%
and you have transition
probabilities

00:40:33.810 --> 00:40:37.080 align:middle line:84%
which come in from a learning
set, such as the human snow

00:40:37.080 --> 00:40:37.610 align:middle line:90%
RNAs.

00:40:37.610 --> 00:40:39.193 align:middle line:84%
You have a learning
set that tells you

00:40:39.193 --> 00:40:41.210 align:middle line:84%
what these transition
probabilities will be.

00:40:41.210 --> 00:40:43.970 align:middle line:84%
And you and you now apply this
to the entire yeast genome,

00:40:43.970 --> 00:40:46.610 align:middle line:84%
and you get a bunch of
candidates, snow RNA

00:40:46.610 --> 00:40:47.780 align:middle line:90%
encoding genes.

00:40:47.780 --> 00:40:50.450 align:middle line:84%
Now you can't use things
like the long open reading

00:40:50.450 --> 00:40:52.800 align:middle line:84%
frames that you normally
would use for finding genes.

00:40:52.800 --> 00:40:54.800 align:middle line:90%
So this is a very valuable tool.

00:40:54.800 --> 00:40:57.080 align:middle line:84%
But now how do you
convince yourself

00:40:57.080 --> 00:41:03.920 align:middle line:84%
that this is a gene, that this
actually encodes a snow RNA,

00:41:03.920 --> 00:41:07.160 align:middle line:84%
and that those are
responsible for guiding

00:41:07.160 --> 00:41:11.300 align:middle line:84%
the methylation at particular
positions in the ribosomal RNA.

00:41:11.300 --> 00:41:14.550 align:middle line:90%
The way you do that is--

00:41:14.550 --> 00:41:16.770 align:middle line:84%
well, before we get
to how you do that,

00:41:16.770 --> 00:41:20.190 align:middle line:84%
we want to ask how does
this algorithm perform

00:41:20.190 --> 00:41:21.540 align:middle line:90%
relative to other--

00:41:21.540 --> 00:41:23.130 align:middle line:84%
the few other
algorithms there are

00:41:23.130 --> 00:41:26.260 align:middle line:84%
for finding genes which
do not encode proteins.

00:41:26.260 --> 00:41:30.750 align:middle line:84%
And the first of these actually
dates well before 1991.

00:41:30.750 --> 00:41:33.510 align:middle line:84%
But there were ways of looking
for transfer RNAs in sequence.

00:41:33.510 --> 00:41:36.090 align:middle line:84%
They would use everything we
know about transfer RNAs--

00:41:36.090 --> 00:41:38.130 align:middle line:84%
the little boxes
that are conserved

00:41:38.130 --> 00:41:41.340 align:middle line:84%
as sequences, the regions
that are conserved only--

00:41:41.340 --> 00:41:45.660 align:middle line:84%
not as sequences, but as base
pairing potential, et cetera.

00:41:45.660 --> 00:41:48.090 align:middle line:90%
The loop lengths look--

00:41:48.090 --> 00:41:49.020 align:middle line:90%
are constrained.

00:41:49.020 --> 00:41:52.650 align:middle line:84%
All the constraints that
you can muster back in '91

00:41:52.650 --> 00:41:53.580 align:middle line:90%
were applied.

00:41:53.580 --> 00:41:55.800 align:middle line:90%
And it was fairly slow.

00:41:55.800 --> 00:42:01.590 align:middle line:84%
It would only do 400 base pairs
of genome chunk per second.

00:42:01.590 --> 00:42:05.580 align:middle line:84%
And when you have genomes on
the order of many mega bases,

00:42:05.580 --> 00:42:07.050 align:middle line:90%
this is slow.

00:42:07.050 --> 00:42:11.865 align:middle line:84%
And it had-- it missed about
5% of the true positives.

00:42:11.865 --> 00:42:13.590 align:middle line:90%
It had 95%.

00:42:13.590 --> 00:42:17.280 align:middle line:84%
And false positives sounds
impressive-- only 10

00:42:17.280 --> 00:42:18.180 align:middle line:90%
to the minus 6.

00:42:18.180 --> 00:42:20.370 align:middle line:84%
But when you think of
a double stranded--

00:42:20.370 --> 00:42:26.380 align:middle line:84%
both strands of E. coli
being about 10 million bases,

00:42:26.380 --> 00:42:28.750 align:middle line:84%
then this is about
four false positives.

00:42:28.750 --> 00:42:31.540 align:middle line:84%
And bigger genomes, of
course, would be even a larger

00:42:31.540 --> 00:42:33.160 align:middle line:90%
number in an absolute scale.

00:42:33.160 --> 00:42:39.130 align:middle line:84%
So then, six years later, the
speed is now 100 times faster.

00:42:39.130 --> 00:42:42.370 align:middle line:84%
You're now only missing 0.5%
of the true positives instead

00:42:42.370 --> 00:42:43.420 align:middle line:90%
of 5%.

00:42:43.420 --> 00:42:47.000 align:middle line:84%
And the false positives
is now vanishingly small.

00:42:47.000 --> 00:42:52.828 align:middle line:84%
So very often you can
just arbitrarily trade off

00:42:52.828 --> 00:42:54.370 align:middle line:84%
the number of true
positives you miss

00:42:54.370 --> 00:42:55.787 align:middle line:84%
with the number
of false positives

00:42:55.787 --> 00:42:57.490 align:middle line:90%
you get and make one--

00:42:57.490 --> 00:42:58.910 align:middle line:90%
take one advantage of the other.

00:42:58.910 --> 00:43:00.550 align:middle line:84%
But here, it was a
win-win situation.

00:43:00.550 --> 00:43:03.110 align:middle line:84%
They both went in a
favorable direction.

00:43:03.110 --> 00:43:06.470 align:middle line:84%
So how do the snow
RNAs compare with that?

00:43:06.470 --> 00:43:08.190 align:middle line:90%
Here, another two years passed.

00:43:08.190 --> 00:43:10.710 align:middle line:84%
We have the snow RNAs
are just starting out.

00:43:10.710 --> 00:43:15.170 align:middle line:84%
They have, probably, a little
better than 93% true positives.

00:43:15.170 --> 00:43:17.000 align:middle line:84%
This is not as good
as transfer RNAs.

00:43:17.000 --> 00:43:23.720 align:middle line:84%
This may be-- this may
improve or it may not.

00:43:23.720 --> 00:43:28.030 align:middle line:84%
The false positive
rate is acceptable.

00:43:28.030 --> 00:43:31.960 align:middle line:84%
So then the question becomes,
how do you track down--

00:43:31.960 --> 00:43:33.340 align:middle line:84%
after you track
down these genes,

00:43:33.340 --> 00:43:37.390 align:middle line:84%
how do you then prove that
they do what you think they do,

00:43:37.390 --> 00:43:40.300 align:middle line:84%
that they actually are
responsible for methylating

00:43:40.300 --> 00:43:44.220 align:middle line:84%
the riboses or the
bases in question?

00:43:44.220 --> 00:43:50.960 align:middle line:84%
So it turns out that
the technology we set up

00:43:50.960 --> 00:43:53.150 align:middle line:84%
in the sequencing and
genotyping lecture

00:43:53.150 --> 00:43:59.510 align:middle line:84%
where you extend with
DNA polymerase a primer

00:43:59.510 --> 00:44:02.360 align:middle line:84%
on a template so the primer
binds to the template

00:44:02.360 --> 00:44:05.270 align:middle line:84%
and you extend by
either many base pairs,

00:44:05.270 --> 00:44:07.610 align:middle line:84%
as in the conventional
dideoxy sequencing,

00:44:07.610 --> 00:44:11.090 align:middle line:84%
or one or two base pairs
in some of the more

00:44:11.090 --> 00:44:16.200 align:middle line:84%
up-and-coming
genotyping methods.

00:44:16.200 --> 00:44:19.860 align:middle line:84%
Those extension methods, those
DNA polymerase-based extension

00:44:19.860 --> 00:44:26.160 align:middle line:84%
methods will stall when you
run into this particular kind

00:44:26.160 --> 00:44:29.880 align:middle line:84%
of modified base where a
bulky group is introduced

00:44:29.880 --> 00:44:34.217 align:middle line:84%
onto the two prime position
of the ribose on the template.

00:44:34.217 --> 00:44:36.550 align:middle line:84%
So you're extending the primer,
sitting on the template,

00:44:36.550 --> 00:44:37.890 align:middle line:90%
and it will stall here.

00:44:37.890 --> 00:44:40.800 align:middle line:84%
And it stalls more when you
decrease the concentration

00:44:40.800 --> 00:44:44.910 align:middle line:84%
of the deoxynucleotide
triphosphates in the extension

00:44:44.910 --> 00:44:45.610 align:middle line:90%
reaction.

00:44:45.610 --> 00:44:46.650 align:middle line:84%
So that's what
these little wedges

00:44:46.650 --> 00:44:48.510 align:middle line:84%
mean at the top of
each of these columns.

00:44:48.510 --> 00:44:53.310 align:middle line:84%
They've done an extension with
all four triphosphates present,

00:44:53.310 --> 00:44:55.110 align:middle line:84%
either in high
amounts at the big end

00:44:55.110 --> 00:44:57.600 align:middle line:84%
of the wedge or low amounts in
the small ends of the wedge.

00:44:57.600 --> 00:45:00.150 align:middle line:84%
And to tell where you are
in the sequence-- this

00:45:00.150 --> 00:45:01.680 align:middle line:84%
is what using
reverse transcriptase

00:45:01.680 --> 00:45:05.370 align:middle line:84%
polymerase on a
ribosomal RNA template--

00:45:05.370 --> 00:45:06.990 align:middle line:84%
to find out where
you are, you do

00:45:06.990 --> 00:45:09.250 align:middle line:84%
this dideoxy, which is
basically the conventional DNA

00:45:09.250 --> 00:45:09.750 align:middle line:90%
sequencing.

00:45:09.750 --> 00:45:12.055 align:middle line:84%
Where you terminate,
it either is used Us,

00:45:12.055 --> 00:45:13.305 align:middle line:90%
Gs, Cs, or As in the template.

00:45:13.305 --> 00:45:15.932 align:middle line:90%


00:45:15.932 --> 00:45:17.265 align:middle line:90%
This allows you to get oriented.

00:45:17.265 --> 00:45:20.370 align:middle line:84%
And basically, your sequencing
on the far left-hand

00:45:20.370 --> 00:45:21.390 align:middle line:90%
set of lanes.

00:45:21.390 --> 00:45:25.440 align:middle line:84%
And these pause
sites our present,

00:45:25.440 --> 00:45:29.460 align:middle line:84%
say, the wild-type is
the first pair of lanes

00:45:29.460 --> 00:45:33.480 align:middle line:84%
next to the sequence lanes
on the left-hand side

00:45:33.480 --> 00:45:34.480 align:middle line:90%
of this display.

00:45:34.480 --> 00:45:38.070 align:middle line:84%
And you can see there's a
pause at every single known

00:45:38.070 --> 00:45:39.300 align:middle line:90%
methylated base.

00:45:39.300 --> 00:45:44.040 align:middle line:84%
You can determine methylated
bases by other methods as well.

00:45:44.040 --> 00:45:47.850 align:middle line:84%
But so now then, the
computational biology

00:45:47.850 --> 00:45:50.550 align:middle line:90%
predicted a set of snow genes.

00:45:50.550 --> 00:45:53.820 align:middle line:84%
In fact, ultimately, all of
the snow genes in the yeast

00:45:53.820 --> 00:45:57.390 align:middle line:84%
genome we think, explaining all
of the methyl groups, at least.

00:45:57.390 --> 00:46:00.540 align:middle line:84%
And one by one, these
were knocked out cleanly

00:46:00.540 --> 00:46:03.648 align:middle line:84%
so that there's no gene there
anymore for the small RNA.

00:46:03.648 --> 00:46:05.190 align:middle line:84%
And then you ask,
well, how does this

00:46:05.190 --> 00:46:07.710 align:middle line:84%
affect the methylation as
detected by this extension

00:46:07.710 --> 00:46:08.340 align:middle line:90%
assay?

00:46:08.340 --> 00:46:12.760 align:middle line:84%
And if you look on the far
right-hand side for deleted

00:46:12.760 --> 00:46:17.040 align:middle line:84%
number 40, and you can
see that position number

00:46:17.040 --> 00:46:21.330 align:middle line:84%
596, near the bottom,
circled in red, which

00:46:21.330 --> 00:46:23.730 align:middle line:84%
is present in the wild type
and all the other mutants,

00:46:23.730 --> 00:46:26.680 align:middle line:84%
is absent from that
particular mutant number 40.

00:46:26.680 --> 00:46:28.350 align:middle line:90%
So there's no pause there.

00:46:28.350 --> 00:46:30.480 align:middle line:84%
One infers there's
no methylation.

00:46:30.480 --> 00:46:34.050 align:middle line:84%
And that was the specific
site that that snow RNA guide

00:46:34.050 --> 00:46:36.810 align:middle line:90%
sequence was predicted to bind.

00:46:36.810 --> 00:46:40.110 align:middle line:84%
It's aligned with the
position in the guide

00:46:40.110 --> 00:46:44.790 align:middle line:84%
where you expect there to
be a methylation occurring.

00:46:44.790 --> 00:46:47.700 align:middle line:84%
And you can see in each lane
there's a different circled

00:46:47.700 --> 00:46:51.780 align:middle line:90%
red missing black pause site.

00:46:51.780 --> 00:46:57.490 align:middle line:84%
And until we get to
the one in the middle,

00:46:57.490 --> 00:47:00.250 align:middle line:84%
Newton numbers for
snow RNA number 60--

00:47:00.250 --> 00:47:03.880 align:middle line:84%
and here's actually two
missing bands in the same lane.

00:47:03.880 --> 00:47:06.520 align:middle line:84%
And how that can occur,
there's two different ways

00:47:06.520 --> 00:47:08.920 align:middle line:90%
that a snow RNA can--

00:47:08.920 --> 00:47:11.200 align:middle line:84%
knocking out a single
gene, a single snow RNA

00:47:11.200 --> 00:47:14.120 align:middle line:84%
can have an effect on two
different methyl groups.

00:47:14.120 --> 00:47:21.340 align:middle line:84%
One is if the guide sequence
can bind to two different places

00:47:21.340 --> 00:47:22.510 align:middle line:90%
in the ribosomal RNA.

00:47:22.510 --> 00:47:25.270 align:middle line:84%
And the other is if there
are two guides sequences

00:47:25.270 --> 00:47:26.620 align:middle line:90%
within the same snow RNA.

00:47:26.620 --> 00:47:31.340 align:middle line:90%


00:47:31.340 --> 00:47:35.610 align:middle line:84%
So now that we have at
least some grounding

00:47:35.610 --> 00:47:40.200 align:middle line:84%
in the kind of structures
that can occur, now

00:47:40.200 --> 00:47:43.020 align:middle line:84%
we're going to
ask how we monitor

00:47:43.020 --> 00:47:47.010 align:middle line:84%
and measure the amounts
of these structures

00:47:47.010 --> 00:47:50.150 align:middle line:90%
in biological systems.

00:47:50.150 --> 00:47:53.450 align:middle line:84%
And we will also see how these
structures impact the methods

00:47:53.450 --> 00:47:58.240 align:middle line:84%
that we use for the
quantitation of the structures.

00:47:58.240 --> 00:48:07.740 align:middle line:84%
So we have choices of
molecule that we're

00:48:07.740 --> 00:48:10.230 align:middle line:84%
going to measure
when we're monitoring

00:48:10.230 --> 00:48:12.510 align:middle line:84%
the various molecules
in the cell.

00:48:12.510 --> 00:48:14.160 align:middle line:90%
Why are we focusing on RNA?

00:48:14.160 --> 00:48:18.390 align:middle line:84%
Well, part of it is because of
its nice structural continuity

00:48:18.390 --> 00:48:21.390 align:middle line:84%
between the simple DNA and
the very complicated proteins.

00:48:21.390 --> 00:48:25.470 align:middle line:84%
But the other is that if we
want to study different points

00:48:25.470 --> 00:48:28.812 align:middle line:84%
in the regulatory and
metabolic networks

00:48:28.812 --> 00:48:31.020 align:middle line:84%
that we'll be talking about
at the end of this course

00:48:31.020 --> 00:48:36.530 align:middle line:84%
having to do with systems
biology, if we choose--

00:48:36.530 --> 00:48:40.310 align:middle line:84%
we want-- every part of
it is subject to some kind

00:48:40.310 --> 00:48:41.180 align:middle line:90%
of control.

00:48:41.180 --> 00:48:44.240 align:middle line:84%
Transcriptional control is
one of the early stages.

00:48:44.240 --> 00:48:46.820 align:middle line:84%
And then there are many stages
subsequence to that lead

00:48:46.820 --> 00:48:50.480 align:middle line:84%
to the protein and
ultimate phenotypes that

00:48:50.480 --> 00:48:52.820 align:middle line:84%
result in proliferation
of the species.

00:48:52.820 --> 00:48:55.310 align:middle line:84%
If you want to look at
transcriptional control,

00:48:55.310 --> 00:48:59.360 align:middle line:84%
it would not do well
to study protein

00:48:59.360 --> 00:49:02.510 align:middle line:84%
because the closest thing
to transcriptional control

00:49:02.510 --> 00:49:05.840 align:middle line:84%
that you can measure
is the RNA products.

00:49:05.840 --> 00:49:08.540 align:middle line:84%
You can study the
transcriptional control itself

00:49:08.540 --> 00:49:11.210 align:middle line:84%
directly, as well, by studying
the DNA protein interactions.

00:49:11.210 --> 00:49:14.450 align:middle line:84%
But if you want to measure,
a defusible molecule RNA

00:49:14.450 --> 00:49:15.690 align:middle line:90%
is the thing to do.

00:49:15.690 --> 00:49:18.770 align:middle line:84%
And there are multiple
different methods

00:49:18.770 --> 00:49:22.100 align:middle line:84%
for getting at a co-regulated
set of genes, co-regulated

00:49:22.100 --> 00:49:24.290 align:middle line:90%
at the transcriptional level.

00:49:24.290 --> 00:49:26.990 align:middle line:90%
We'll illustrate a few here.

00:49:26.990 --> 00:49:28.850 align:middle line:84%
And why do we need
multiple methods?

00:49:28.850 --> 00:49:31.820 align:middle line:84%
Well, we've talked about
random and systematic errors.

00:49:31.820 --> 00:49:37.230 align:middle line:84%
Random errors you can compensate
by repeating the experiment.

00:49:37.230 --> 00:49:39.307 align:middle line:84%
The random errors will
average out, ultimately.

00:49:39.307 --> 00:49:41.640 align:middle line:84%
Systematic errors will happen
the same way over and over

00:49:41.640 --> 00:49:41.980 align:middle line:90%
again.

00:49:41.980 --> 00:49:43.813 align:middle line:84%
So you want to have
something out of the box

00:49:43.813 --> 00:49:47.190 align:middle line:84%
to allow you to check
it, or to model it,

00:49:47.190 --> 00:49:51.000 align:middle line:84%
or to allow you
to do integration,

00:49:51.000 --> 00:49:54.160 align:middle line:84%
as you might want to have
in complicated systems.

00:49:54.160 --> 00:49:57.180 align:middle line:84%
So here, just to start us
thinking about integration

00:49:57.180 --> 00:50:00.750 align:middle line:84%
and checking different ways
of getting transcriptional

00:50:00.750 --> 00:50:05.760 align:middle line:84%
co-regulation,
let's think about--

00:50:05.760 --> 00:50:09.150 align:middle line:84%
if you look through all
the proteins that occur,

00:50:09.150 --> 00:50:13.080 align:middle line:84%
you will find proteins that
occur together, frequently,

00:50:13.080 --> 00:50:17.610 align:middle line:84%
as either as fusions or
as separate proteins.

00:50:17.610 --> 00:50:21.240 align:middle line:84%
Where in operands, they'll
occur as coding regions

00:50:21.240 --> 00:50:23.580 align:middle line:84%
that are clustered
together in some species

00:50:23.580 --> 00:50:27.350 align:middle line:84%
or maybe less clustered
in other species.

00:50:27.350 --> 00:50:31.840 align:middle line:84%
When we have metabolic pathways
where a small molecule will

00:50:31.840 --> 00:50:34.480 align:middle line:90%
be shared by--

00:50:34.480 --> 00:50:38.000 align:middle line:84%
as the product of one will
be the substrate of another,

00:50:38.000 --> 00:50:43.910 align:middle line:84%
and so on, you'll have this
chain of events as in the lower

00:50:43.910 --> 00:50:45.350 align:middle line:90%
left-hand corner.

00:50:45.350 --> 00:50:54.250 align:middle line:84%
And these sets of enzymes that
need to be working together,

00:50:54.250 --> 00:50:55.420 align:middle line:90%
need to be co-expressed.

00:50:55.420 --> 00:50:59.290 align:middle line:84%
They need to come up
together and go down together

00:50:59.290 --> 00:51:00.430 align:middle line:90%
when they're not needed.

00:51:00.430 --> 00:51:02.620 align:middle line:84%
They need to come up when
they're suddenly needed.

00:51:02.620 --> 00:51:05.920 align:middle line:84%
And so, you might have an entire
pathway, or a set of pathways,

00:51:05.920 --> 00:51:07.120 align:middle line:90%
that are co-expressed.

00:51:07.120 --> 00:51:11.200 align:middle line:84%
And one way to do that is to
cluster them in the genome.

00:51:11.200 --> 00:51:13.840 align:middle line:84%
When they are co-expressed,
you will sometimes

00:51:13.840 --> 00:51:18.250 align:middle line:84%
find upstream of them,
motifs, such as this.

00:51:18.250 --> 00:51:23.170 align:middle line:84%
Again, here's the two bits
for the vertical scale,

00:51:23.170 --> 00:51:26.650 align:middle line:90%
where this might be enriched.

00:51:26.650 --> 00:51:29.020 align:middle line:84%
And so this would be
another indication-- so

00:51:29.020 --> 00:51:32.290 align:middle line:84%
when you find these
in front of genes,

00:51:32.290 --> 00:51:35.670 align:middle line:84%
you might expect them
to be co-regulated.

00:51:35.670 --> 00:51:39.990 align:middle line:84%
When you find a set of proteins
that are consistently together

00:51:39.990 --> 00:51:42.420 align:middle line:84%
in different organisms,
so-called phylogenetic

00:51:42.420 --> 00:51:47.490 align:middle line:84%
profiles, you will find that
this set of proteins that is

00:51:47.490 --> 00:51:51.150 align:middle line:84%
involved in a common enzymatic
pathway, metabolic pathway,

00:51:51.150 --> 00:51:56.105 align:middle line:84%
are not only co-regulated
and found together but in--

00:51:56.105 --> 00:51:57.480 align:middle line:84%
along the chromosome,
but they're

00:51:57.480 --> 00:52:00.300 align:middle line:84%
found together when you go
through many different species.

00:52:00.300 --> 00:52:03.850 align:middle line:84%
They will be deleted
or inserted as a block,

00:52:03.850 --> 00:52:05.850 align:middle line:84%
or they'll be found
scattered around the genome.

00:52:05.850 --> 00:52:08.910 align:middle line:84%
But you'll find that
when one disappears,

00:52:08.910 --> 00:52:12.030 align:middle line:84%
they all disappear, in general,
statistically speaking.

00:52:12.030 --> 00:52:14.610 align:middle line:84%
It's this phylogenetic
co-occurrence

00:52:14.610 --> 00:52:16.900 align:middle line:84%
is another clue that
you might expect

00:52:16.900 --> 00:52:20.190 align:middle line:84%
them to be co-regulated in those
genomes in which there they

00:52:20.190 --> 00:52:22.180 align:middle line:90%
do co-occur.

00:52:22.180 --> 00:52:25.030 align:middle line:84%
Anyway, and
microarrays will be--

00:52:25.030 --> 00:52:27.190 align:middle line:84%
and variations on that
theme will be the main thing

00:52:27.190 --> 00:52:28.217 align:middle line:90%
that we'll talk about.

00:52:28.217 --> 00:52:29.800 align:middle line:84%
But I wanted to put
it in the context.

00:52:29.800 --> 00:52:35.390 align:middle line:84%
And I'll just expand on
one of these at the bottom

00:52:35.390 --> 00:52:40.980 align:middle line:90%
here in slide 22.

00:52:40.980 --> 00:52:44.070 align:middle line:84%
This is an algorithm
for reconstructing

00:52:44.070 --> 00:52:49.440 align:middle line:84%
likely combinations
where in some organisms

00:52:49.440 --> 00:52:52.650 align:middle line:84%
you might have the entire
biosynthetic pathway

00:52:52.650 --> 00:52:58.170 align:middle line:84%
as a series of genes which
encode one by one, all

00:52:58.170 --> 00:53:00.120 align:middle line:84%
the proteins in this
case that are involved

00:53:00.120 --> 00:53:05.380 align:middle line:84%
in purine biosynthesis
from simpler molecules.

00:53:05.380 --> 00:53:07.360 align:middle line:84%
But in other
organisms, you might

00:53:07.360 --> 00:53:09.790 align:middle line:84%
have them scattered
all over the genome,

00:53:09.790 --> 00:53:11.590 align:middle line:90%
but they might be co-regulated.

00:53:11.590 --> 00:53:13.970 align:middle line:84%
Their RNAs might go
up and down together.

00:53:13.970 --> 00:53:17.080 align:middle line:84%
And so, if you look
at enough genomes,

00:53:17.080 --> 00:53:23.170 align:middle line:84%
you can reconstruct the
likely combination of enzymes.

00:53:23.170 --> 00:53:25.710 align:middle line:90%
And here's how it might work.

00:53:25.710 --> 00:53:27.935 align:middle line:84%
In any one of these,
for example, E. coli,

00:53:27.935 --> 00:53:30.310 align:middle line:84%
you might see that they're
scattered about-- a pair here,

00:53:30.310 --> 00:53:31.020 align:middle line:90%
and a pair there.

00:53:31.020 --> 00:53:32.983 align:middle line:90%
Singletons don't help much.

00:53:32.983 --> 00:53:34.650 align:middle line:84%
But if you take all
the pairs from a lot

00:53:34.650 --> 00:53:40.260 align:middle line:84%
of different organisms, you
can reconstruct this network

00:53:40.260 --> 00:53:44.260 align:middle line:84%
where you say,
oh, this gene will

00:53:44.260 --> 00:53:47.890 align:middle line:84%
call L, Q, Y, C-- all
these are probably

00:53:47.890 --> 00:53:49.330 align:middle line:90%
involved in the same process.

00:53:49.330 --> 00:53:51.668 align:middle line:84%
If you get a hint for
what any one of them does,

00:53:51.668 --> 00:53:53.835 align:middle line:84%
say, one of them is involved
in purine biosynthesis,

00:53:53.835 --> 00:53:55.420 align:middle line:84%
so then you find
that they all are.

00:53:55.420 --> 00:53:59.870 align:middle line:84%
And if you guess they might
be co-regulated very tightly.

00:53:59.870 --> 00:54:01.840 align:middle line:84%
So now let's figure
out how we actually

00:54:01.840 --> 00:54:05.840 align:middle line:84%
measure that they're
co-regulated very tightly.

00:54:05.840 --> 00:54:08.510 align:middle line:90%
And the way we can do that--

00:54:08.510 --> 00:54:12.170 align:middle line:84%
as we do that, whatever
method we use, we want to ask

00:54:12.170 --> 00:54:15.200 align:middle line:84%
are we interested in
ratios, relative changes,

00:54:15.200 --> 00:54:17.090 align:middle line:84%
or are we interested
in absolute values?

00:54:17.090 --> 00:54:20.210 align:middle line:84%
There are various
things that we can

00:54:20.210 --> 00:54:21.800 align:middle line:84%
do with absolute
amounts that are

00:54:21.800 --> 00:54:24.460 align:middle line:90%
very hard to do with ratios.

00:54:24.460 --> 00:54:28.380 align:middle line:84%
In particular, if
we want to ask,

00:54:28.380 --> 00:54:34.170 align:middle line:84%
is a particular protein level
high because its translation is

00:54:34.170 --> 00:54:37.680 align:middle line:84%
efficient or is it high because
its transcription is efficient,

00:54:37.680 --> 00:54:41.910 align:middle line:84%
if you find that it's
full of abundant codons

00:54:41.910 --> 00:54:46.170 align:middle line:84%
as if it wants to be efficiently
translated, is it also

00:54:46.170 --> 00:54:48.570 align:middle line:84%
have a high-level
promoter as if it wants

00:54:48.570 --> 00:54:51.240 align:middle line:90%
to be transcriptionally active?

00:54:51.240 --> 00:54:54.630 align:middle line:84%
These sorts of
questions really benefit

00:54:54.630 --> 00:54:58.470 align:middle line:84%
from having absolute
amounts, meaning

00:54:58.470 --> 00:55:00.400 align:middle line:84%
so many molecules
of RNA per cell,

00:55:00.400 --> 00:55:02.550 align:middle line:84%
so many molecules
of protein per cell.

00:55:02.550 --> 00:55:04.920 align:middle line:84%
But we get that to
direct causality,

00:55:04.920 --> 00:55:06.990 align:middle line:90%
we want to get at the motifs.

00:55:06.990 --> 00:55:09.960 align:middle line:84%
This would be one of the
objectives of doing the RNA

00:55:09.960 --> 00:55:14.280 align:middle line:84%
quantitation, to allow
us to cluster RNAs that

00:55:14.280 --> 00:55:17.430 align:middle line:84%
are co-expressed, and then
to start looking for motifs

00:55:17.430 --> 00:55:19.140 align:middle line:90%
and direct causality.

00:55:19.140 --> 00:55:21.540 align:middle line:84%
Another thing that we might
want to do is to classify.

00:55:21.540 --> 00:55:26.250 align:middle line:84%
We can ask whether small
molecules or mutations,

00:55:26.250 --> 00:55:30.060 align:middle line:84%
such as occur in cancers,
cause enough of a signature

00:55:30.060 --> 00:55:36.110 align:middle line:84%
that you can then use as to say,
OK, this self state that we see

00:55:36.110 --> 00:55:40.010 align:middle line:84%
is a recognizable small molecule
effect, or stress effect,

00:55:40.010 --> 00:55:41.585 align:middle line:90%
or mutational effect, cancer.

00:55:41.585 --> 00:55:44.280 align:middle line:90%


00:55:44.280 --> 00:55:51.420 align:middle line:84%
Now, when we-- we
will be talking

00:55:51.420 --> 00:55:55.170 align:middle line:84%
about microarray
and related methods,

00:55:55.170 --> 00:56:00.390 align:middle line:84%
but I want you to question the
advantages and disadvantages

00:56:00.390 --> 00:56:01.410 align:middle line:90%
of these methods.

00:56:01.410 --> 00:56:05.100 align:middle line:84%
And so I'll compare
it to a number--

00:56:05.100 --> 00:56:08.460 align:middle line:84%
but let's start with the most
dramatic comparison, which

00:56:08.460 --> 00:56:11.370 align:middle line:90%
is with in situ hybridization.

00:56:11.370 --> 00:56:15.930 align:middle line:84%
So in array hybridization
you'll have tens of thousands

00:56:15.930 --> 00:56:21.325 align:middle line:84%
of different gene probes
mobilized on a solid surface.

00:56:21.325 --> 00:56:23.900 align:middle line:90%


00:56:23.900 --> 00:56:29.530 align:middle line:84%
And you'll label up the RNA from
a mixture of different cells--

00:56:29.530 --> 00:56:33.070 align:middle line:84%
different mixture of
different RNAs within a cell.

00:56:33.070 --> 00:56:34.750 align:middle line:84%
But you'll be able
to ask questions

00:56:34.750 --> 00:56:36.670 align:middle line:90%
about 10,000 genes at a time.

00:56:36.670 --> 00:56:39.070 align:middle line:84%
In an in situ experiment,
it's the other way around.

00:56:39.070 --> 00:56:43.690 align:middle line:84%
You take a cell in it's
fairly natural environment,

00:56:43.690 --> 00:56:46.930 align:middle line:84%
usually fixed, but
fixed with maintaining

00:56:46.930 --> 00:56:49.990 align:middle line:90%
the spatial aspects.

00:56:49.990 --> 00:56:53.430 align:middle line:84%
Then, if you look
within the cell,

00:56:53.430 --> 00:56:56.460 align:middle line:84%
with a single gene at
a time, or maybe two

00:56:56.460 --> 00:56:59.560 align:middle line:84%
or three at a time, a very small
number, not tens of thousands,

00:56:59.560 --> 00:57:03.177 align:middle line:84%
you can look to see whether
the RNA is uniformly

00:57:03.177 --> 00:57:05.760 align:middle line:84%
spread throughout the cell and
uniformly spread throughout all

00:57:05.760 --> 00:57:08.130 align:middle line:84%
the cells in the tissue,
or in, say, you've

00:57:08.130 --> 00:57:12.010 align:middle line:84%
got a mixed population
of yeast cells, whatever.

00:57:12.010 --> 00:57:14.940 align:middle line:84%
And you can find cases
in the literature

00:57:14.940 --> 00:57:17.970 align:middle line:84%
where it is not uniformly
present in all the cells

00:57:17.970 --> 00:57:19.680 align:middle line:84%
and not even uniformly
within a cell.

00:57:19.680 --> 00:57:23.280 align:middle line:84%
Here is one of the more
dramatic cases where

00:57:23.280 --> 00:57:28.710 align:middle line:84%
the two X chromosomes in
mammals behave differently

00:57:28.710 --> 00:57:30.180 align:middle line:90%
from one another.

00:57:30.180 --> 00:57:35.070 align:middle line:84%
The female mammals
will have one RNA--

00:57:35.070 --> 00:57:38.640 align:middle line:84%
one chromosome expressing most
of its RNAs at normal levels,

00:57:38.640 --> 00:57:41.550 align:middle line:84%
and the other chromosome
expressing almost no RNAs.

00:57:41.550 --> 00:57:44.670 align:middle line:84%
It is expressing at least
one RNA, and that RNA is--

00:57:44.670 --> 00:57:52.860 align:middle line:84%
which is XIST and it's
covering that whole chromosome

00:57:52.860 --> 00:57:54.720 align:middle line:84%
or is localized over
that chromosome and not

00:57:54.720 --> 00:57:55.720 align:middle line:90%
the rest of the cell.

00:57:55.720 --> 00:57:58.890 align:middle line:84%
So this is an extreme
case of localization

00:57:58.890 --> 00:58:01.890 align:middle line:84%
that you can monitor
with microscopic methods,

00:58:01.890 --> 00:58:04.170 align:middle line:90%
fluorescent microscopic methods.

00:58:04.170 --> 00:58:07.830 align:middle line:84%
Instead, we'll-- keep this in
the back of your mind as you

00:58:07.830 --> 00:58:12.780 align:middle line:84%
look through the microarray
and other experiments where

00:58:12.780 --> 00:58:16.590 align:middle line:84%
you're mushing together a
variety of cells that might be

00:58:16.590 --> 00:58:18.540 align:middle line:84%
in different stages
of the cell cycle,

00:58:18.540 --> 00:58:20.530 align:middle line:84%
might have slightly
different environments,

00:58:20.530 --> 00:58:22.830 align:middle line:84%
and even within
the cell, the RNA--

00:58:22.830 --> 00:58:25.680 align:middle line:84%
you're losing the information
about the RNA localization.

00:58:25.680 --> 00:58:28.270 align:middle line:90%


00:58:28.270 --> 00:58:37.030 align:middle line:84%
Let's take a short break and
then come back and connect on--

00:58:37.030 --> 00:58:41.530 align:middle line:84%
finish up in situ hybridization,
and connect to other methods

00:58:41.530 --> 00:58:44.160 align:middle line:90%
for quantitation of RNA.

00:58:44.160 --> 00:58:45.000 align:middle line:90%