1 00:00:10,707 --> 00:00:12,540 STUDENT: Let's talk about the Mohr's Circle, 2 00:00:12,540 --> 00:00:14,430 an important tool in materials science 3 00:00:14,430 --> 00:00:17,860 and mechanical engineering. 4 00:00:17,860 --> 00:00:20,812 What is Mohr's Circle, and what does it do? 5 00:00:20,812 --> 00:00:22,270 Assume you have a rod, and you want 6 00:00:22,270 --> 00:00:23,960 to break it with your hands. 7 00:00:23,960 --> 00:00:26,330 What can you do about it? 8 00:00:26,330 --> 00:00:29,830 You can pull it, compress it, or twist it. 9 00:00:29,830 --> 00:00:31,590 Each of these will induce a stress 10 00:00:31,590 --> 00:00:34,190 in the rod in a different way. 11 00:00:34,190 --> 00:00:37,390 And the Mohr's Circle helps you analyze this. 12 00:00:37,390 --> 00:00:40,120 Mohr's Circle is a graphical tool, a visual way 13 00:00:40,120 --> 00:00:44,530 to see how to go from one state of stress to another. 14 00:00:44,530 --> 00:00:46,420 Usually you are given a state of stress 15 00:00:46,420 --> 00:00:49,580 that you calculated from using stress equations. 16 00:00:49,580 --> 00:00:51,520 Then you want to find a state of stress 17 00:00:51,520 --> 00:00:54,700 at a new angle of orientation, or principal 18 00:00:54,700 --> 00:00:58,750 stresses at that orientation, or the maximum in-plane shear 19 00:00:58,750 --> 00:01:00,400 stresses. 20 00:01:00,400 --> 00:01:02,200 And Mohr's Circle allows you to draw 21 00:01:02,200 --> 00:01:04,750 this representative element to visualize 22 00:01:04,750 --> 00:01:06,010 the calculations for you. 23 00:01:10,920 --> 00:01:13,530 Now, let's derive the Mohr's Circle. 24 00:01:13,530 --> 00:01:15,830 So now we take a look at the piece of material 25 00:01:15,830 --> 00:01:20,690 that we cut from the rod that we're trying to break. 26 00:01:20,690 --> 00:01:25,460 And originally we had this coordinate system. 27 00:01:25,460 --> 00:01:28,340 And we have some stresses, where the signals 28 00:01:28,340 --> 00:01:31,010 represent the normal stress and the tiles 29 00:01:31,010 --> 00:01:33,090 represent the shear stress. 30 00:01:33,090 --> 00:01:35,330 So we draw this representative pair 31 00:01:35,330 --> 00:01:38,060 of stresses for convenience. 32 00:01:43,570 --> 00:01:48,550 And then we want to analyze the stresses 33 00:01:48,550 --> 00:01:51,560 of this cross-section area. 34 00:01:51,560 --> 00:01:56,560 So what we do is, we need to rotate the coordinate system 35 00:01:56,560 --> 00:02:01,660 so that x-axis would line up with the unit normal vector 36 00:02:01,660 --> 00:02:06,280 to this cross-sectional area. 37 00:02:06,280 --> 00:02:10,600 And then the y-axis would be rotated to this direction, 38 00:02:10,600 --> 00:02:16,042 and would be lined up with the n prime unit vector shown here. 39 00:02:20,470 --> 00:02:24,410 So this is done by rotating this coordinate system by an angle 40 00:02:24,410 --> 00:02:28,170 theta counterclockwise. 41 00:02:28,170 --> 00:02:33,230 Then we can obtain the unit normal vector in matrix form. 42 00:02:33,230 --> 00:02:36,350 And that is just cosine theta and sine theta. 43 00:02:36,350 --> 00:02:40,490 And similarly, the n prime vector, that's just negative 44 00:02:40,490 --> 00:02:43,340 sine theta and cosine theta. 45 00:02:43,340 --> 00:02:47,570 So we can now get the stress tensor 46 00:02:47,570 --> 00:02:51,440 by taking the dot product of the stresses 47 00:02:51,440 --> 00:02:55,660 in the x-direction with the unit normal vector, and the dot 48 00:02:55,660 --> 00:02:59,780 project of stresses in the y-direction with the unit 49 00:02:59,780 --> 00:03:01,860 normal vector. 50 00:03:01,860 --> 00:03:05,000 So now we can write out the normal stress 51 00:03:05,000 --> 00:03:07,700 in the new coordinate system by just 52 00:03:07,700 --> 00:03:11,480 taking the dot product of the stress tensor 53 00:03:11,480 --> 00:03:13,850 with the unit normal vector. 54 00:03:13,850 --> 00:03:18,590 And similarly, we can find the shear stress 55 00:03:18,590 --> 00:03:21,290 in the new coordinate system by taking 56 00:03:21,290 --> 00:03:25,055 the dot product of the stress tensor with the n prime. 57 00:03:27,740 --> 00:03:30,890 And we can do these complicated calculations 58 00:03:30,890 --> 00:03:33,530 on Mathematica, which I will show you right now. 59 00:03:36,520 --> 00:03:40,290 So I've already typed in these vectors into Mathematica. 60 00:03:40,290 --> 00:03:46,440 And n represents the unit normal vector, and np is just n prime, 61 00:03:46,440 --> 00:03:49,830 and t is the stress tensor. 62 00:03:49,830 --> 00:03:53,250 So we want to find the normal stress 63 00:03:53,250 --> 00:03:55,770 in the new coordinate system, sigma prime. 64 00:03:55,770 --> 00:04:00,160 And that is just dotting t with n. 65 00:04:00,160 --> 00:04:04,530 And we get this simplified version. 66 00:04:04,530 --> 00:04:05,385 That. 67 00:04:05,385 --> 00:04:07,930 So that's our sigma prime. 68 00:04:07,930 --> 00:04:11,430 Then we want to find our tau prime. 69 00:04:11,430 --> 00:04:18,029 And that is just t dotted with np. 70 00:04:18,029 --> 00:04:21,089 Again, we want to find the simplified version. 71 00:04:21,089 --> 00:04:22,560 So that's that. 72 00:04:22,560 --> 00:04:25,710 And don't worry about this thetas and 2 thetas. 73 00:04:25,710 --> 00:04:29,260 We'll use trig identities to change them. 74 00:04:29,260 --> 00:04:31,480 So here's our trig identities. 75 00:04:31,480 --> 00:04:33,170 And we just plug them back in. 76 00:04:33,170 --> 00:04:39,130 And we obtain these two equations for our new stresses. 77 00:04:39,130 --> 00:04:41,820 Then we move all the terms containing 78 00:04:41,820 --> 00:04:44,190 2 theta to the right side of the equations, 79 00:04:44,190 --> 00:04:47,220 and all the rest of the terms to the left side of the equations. 80 00:04:47,220 --> 00:04:50,190 And we square both sides of the equations 81 00:04:50,190 --> 00:04:53,850 to get equation 1 and equation 2, as shown here. 82 00:04:57,700 --> 00:05:03,330 We add equation 1 and equation 2, and some terms cancel. 83 00:05:03,330 --> 00:05:08,140 Finally, we get this really clean equation shown here. 84 00:05:08,140 --> 00:05:10,470 Now look closely to this equation. 85 00:05:10,470 --> 00:05:12,570 What form of equation does it look like? 86 00:05:15,990 --> 00:05:17,490 You might have guessed that it looks 87 00:05:17,490 --> 00:05:21,970 like the equation of a circle, and you're absolutely right. 88 00:05:21,970 --> 00:05:24,270 This is exactly how Mohr's Circle is derived. 89 00:05:26,820 --> 00:05:29,820 We can compare the equation with the equation of a circle, 90 00:05:29,820 --> 00:05:33,060 and we see that Mohr's Circle is centered at the coordinates 91 00:05:33,060 --> 00:05:36,960 sigma x plus sigma y over 2, 0. 92 00:05:36,960 --> 00:05:41,190 And sigma x plus sigma y over 2 is the average normal stress 93 00:05:41,190 --> 00:05:43,570 in the old coordinate system. 94 00:05:43,570 --> 00:05:46,010 We can also obtain the radius of Mohr's Circle. 95 00:05:50,160 --> 00:05:53,500 Now let me draw this Mohr's Circle for you. 96 00:05:53,500 --> 00:05:56,230 So we go back to our old coordinate system 97 00:05:56,230 --> 00:06:00,310 with some calculated stresses. 98 00:06:00,310 --> 00:06:06,820 And then we need to construct this new coordinate system 99 00:06:06,820 --> 00:06:11,080 to draw this Mohr's Circle on. 100 00:06:11,080 --> 00:06:17,260 I take the positive x-direction as the plus sigma 101 00:06:17,260 --> 00:06:23,890 and the negative y-direction as plus tau, just by convention. 102 00:06:23,890 --> 00:06:25,630 Then, in order to draw the circle, 103 00:06:25,630 --> 00:06:30,220 we take a pair of normal stress and shear stress 104 00:06:30,220 --> 00:06:35,470 and we plot their values as the coordinates 105 00:06:35,470 --> 00:06:38,950 in our coordinate system. 106 00:06:38,950 --> 00:06:41,590 So we find a dot, and it's represented 107 00:06:41,590 --> 00:06:45,490 by sigma x and tau xy. 108 00:06:45,490 --> 00:06:49,000 Then, by our previous equations that we derived, 109 00:06:49,000 --> 00:06:52,480 we can find the center of the circle, which is 110 00:06:52,480 --> 00:06:58,180 located at sigma average and 0. 111 00:06:58,180 --> 00:07:05,890 And sigma average is just sigma x plus sigma y over 2. 112 00:07:05,890 --> 00:07:11,920 Then we find its values, and we plot that on our sigma axes. 113 00:07:14,630 --> 00:07:17,190 That's just our center of the circle. 114 00:07:17,190 --> 00:07:20,690 Then we connect these two dots that we drew, 115 00:07:20,690 --> 00:07:24,170 and that's just the radius of the circle. 116 00:07:24,170 --> 00:07:27,380 Now we can draw this circle, since we know its center 117 00:07:27,380 --> 00:07:31,130 and a dot on its circumference. 118 00:07:31,130 --> 00:07:35,570 We can now confirm the equation for the radius of the circle 119 00:07:35,570 --> 00:07:39,800 by doing some geometry here. 120 00:07:39,800 --> 00:07:46,510 So, this length is just sigma average. 121 00:07:46,510 --> 00:07:50,470 And then we have another length that's just sigma x. 122 00:07:50,470 --> 00:07:52,450 And the difference between these lengths 123 00:07:52,450 --> 00:07:59,540 is just sigma x minus sigma average. 124 00:07:59,540 --> 00:08:02,600 Then this line right here is simply tau xy. 125 00:08:06,270 --> 00:08:09,720 And by looking at this right triangle 126 00:08:09,720 --> 00:08:12,060 and using Pythagoras' Theorem, we 127 00:08:12,060 --> 00:08:17,460 can obtain the radius of the circle, which is written here 128 00:08:17,460 --> 00:08:18,870 under the square root. 129 00:08:21,380 --> 00:08:24,570 Actually, it confirms our original equation 130 00:08:24,570 --> 00:08:28,750 for obtaining the radius r of Mohr's Circle. 131 00:08:28,750 --> 00:08:33,330 So Mohr's Circle is very useful for visualizing the stresses 132 00:08:33,330 --> 00:08:36,179 on the material. 133 00:08:36,179 --> 00:08:39,150 So we can, just by doing simple geometry, 134 00:08:39,150 --> 00:08:43,210 find the values for its principal stresses. 135 00:08:43,210 --> 00:08:45,920 So in green, you can see on the circle, 136 00:08:45,920 --> 00:08:48,470 there is the maximum normal stress 137 00:08:48,470 --> 00:08:49,710 and minimum normal stress. 138 00:08:49,710 --> 00:08:53,370 And now, in red, I'm labeling the minimum 139 00:08:53,370 --> 00:08:57,200 and maximum shear stresses.