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Suppose we have a curve, C that is defined by an equation,
G(x, y) = 0, and we seek an extremal value of F(x, y) among
points restricted to lie on this curve. At any point q on C, we are free to move while staying on
C only in the direction of the tangent line to the curve.
Our condition above for an extremum then tells us that for
q to be an extremum of F, F must have 0 derivative in the
direction of the tangent, t, to the curve defined by
G. This means that the gradient of F must be perpendicular to
t. But the gradient of G is perpendicular to t
as well, so that in two dimensions the gradient of F and the
gradient of G must be parallel, for F to have an extremum
on G. There are two standard ways to express this condition. The second method is called that of
"Lagrange Multipliers", and the constant c is such
a multiplier. If you write out the three equations defined by G = ax2+bx2
-1 =0, i(F
- cG)
= 0 and j(F
- cG)
= 0, you may solve them for x, y and c, and arrive at the
same solutions previously obtained. Again, computing second derivatives (or examining values of F) must be used to determine the local and/or global maxima and minima. Exercises:14.1 Do this for some parametrically defined curve. 14.2 Suppose we want to maximize the volume of a vertically oriented cylinder give a fixed value q for the surface area of its sides and its top (but not its bottom). What radius and height should it have? |