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Express the square of the area of a parallelogram with sides v and w in terms of dot products. Solution:The area of a parallelogram is the length of its base multiplied
by its altitude. If we consider the vector v as its
base, then its altitude will be the length of w multiplied
by the sine of the angle between v and w. The
square of this area will then be the square of the length
of v multiplied by the square of the length of w,
multiplied by by the square of the sine of the angle between
them. The result then consists of two terms: The first is just the product of the squares of the sides, which is (v, v) * (w, w). The second which must be subtracted, can be identified as (v, w) * (w, v), and our answer is AREA of PARALLELOGRAM SQUARED = (v, v) * (w, w) - (v, w) * (w, v) |